2016松江二模答案解析
上海市徐汇区(金山、松江)2016年高三二模语文答案
2016年徐汇（松江、金山）区高三二模语文试卷〃参考答案一、阅读（80分）（一）18分1. C（2分）2. B（2分）3. ⑴迎合数码化⑵强调体验⑶艺术形式（表现）（3分）4. 更清晰地说明艺术品的价值与其价格之间的关系（2分）5. ⑴挂毯、铜版画等复制技术，使作品的原貌在传播过程中对受到折损。
⑵摄影技术从根本上改变了人们对绘画的传统要求，催生了现代主义艺术。
⑶数码复制技术影响了艺术品的价格，进而影响了艺术家和艺术品生存、发展的方式，导致创作方式的改变、艺术形式的变化。
⑷数码复制技术使得受众可以随意对艺术品进行剪辑、改动，使艺术品最终变得面目全非。
（4分）6.【答案示例】复制品进入观赏者的生活情境，使观赏者和艺术品距离更近，满足了大众对艺术的渴望；数码复制技术促进了艺术的多样性，使得欣赏者拥有了更多的选择；数码技术使得观赏者同时也可能参与到艺术创作的过程当中，通过对艺术品的改编，表达个人的感悟、评价、灵感，成为表达自我的手段等。
（5分）（二）18分7. 写出了作者远离尘嚣与自然逐渐接近的过程，也表现了他逐渐获得心灵慰藉的过程，引出下文在绝幽之处的草地上作者与自然的更深沉的沟通。
（3分）8. 从句式运用的角度：整句；从表现手法的角度：运用想象、修辞（比拟、比喻）。
写出作者与大地、海洋、天空、太阳在灵魂上的广泛而深入的沟通，也表现出自然的伟力与神奇。
表达灵动，富有感染力。
（4分）9. “吮吸”比“呼吸”更具力度，更贴切地表现出作者对生命力的热烈渴望与尽情吸收；“吮吸”多用于对液体的吸取，也与下文作者说从草叶、野花等身上汲取生命的滋养来生活更匹配；“吮吸”也是一种孩童的行为，更能表现出作者在大自然面前婴儿般的依恋。
（写出两点即可，3分）10. A（3分）11. 作者借助“祈祷”这一形式，通过与大地、阳光、天空、海洋等自然界在身体、灵魂两方面的接触和交流，从渴望接近自然以获取力量与慰藉，到释放心灵，进而追问灵魂的内在意义，再到从宇宙间获取对生命的认识，汲取生命的智慧与能量，达到与自然完全交融、物我两忘的境界，逐渐推进文意，展现了作者与自然在精神层面逐渐深入的契合，也表达了作者在自然面前的虔诚，对有“神性”的自然界的崇敬。
2016学年松江区初三化学二模试卷及参考答案-松江新城
2016学年松江区初中毕业生学业模拟考试初三理化试卷(完卷时间100分钟，满分150分）(2017.4)化学部分可能用到的相对原子质量：C-12 O-16 H-1 S-32 Cu-64 Zn-65六、选择题(共20分）27.属于物理性质的是A.延展性B.可燃性C.酸碱性D.氧化性28.蔗糖（C12H22O11）属于A.混合物B.氧化物C.单质D. 有机物29.NaNO2中氮元素的化合价是A. -3B. +3C. +4D. +530.化合价与俗名不一致的是A, CaO 熟石灰 B.NaCl 食盐 C. Na2CO3纯碱 D. NaOH 烧碱31.属于氧化物的是A.O2B.Ca(OH)2C.Na2CO3D.CO232.不属于盐类的氮肥是A. NH4NO3B.NH3ˑH2OC.NH4HCO3D.(NH4)2SO433.属于一元含氧酸的是A.盐酸（HCl）B.碳酸（H2CO3）C.硫酸（H2SO4）D.硝酸（HNO3）34.钠在二氧化碳中燃烧的化学方程式是该反应属于A.分解反应B.化合反应C.复分解反应D.置换反应35.实验操作正确的是36.含氧原子个数约为6.02×1023的物质是A.1molH2O2B.0.5molSO2C.4.4gCO2D.180mlH2O37.有关H2S的叙述正确的是A.H2S的摩尔质量是34gB.H2S中含有氢分子C.H2S中的元素呈化合态D.H2S中氢、硫元素的质量之比为2：138．物质的用途错误的是A. 氢氧化钙：治疗胃酸过多B. 干冰：人工降雨C. 稀有气体: 制作霓虹灯D. 食盐溶液39．不属于同素异形体的一组物质是A. 金刚石和碳60B. 红磷和白磷C. 冰和干冰D. 氧气和臭氧40. 除去物质中的杂质，正确的是41. 在滴有酚酞的氢氧化钠溶液中滴加稀盐酸，恰好中核的情况是A. 酸和碱的质量相等B. 酚酞变无色C. 酸和碱的物质的量相等D. 酸溶液与碱溶液的体积相等42. 正确的说法是A. 与碱反应生成盐和水的物质一定是酸B. 与盐酸反应放出气体的物质一定是碳酸盐C. 使酚酞试液变红的物质一定呈碱性D. 与氯化钡溶液反应生成不溶于稀硝酸的白色沉淀的物质一定含有硫酸根43.能证明X，Y，Z三种金属活动性是X >Y>Z的实验组合是A. ①③④B.②③④C. ①②④D. ①②③④44. 一定量的木炭和氧化铜固体混合物受热过程中，某变量y随加热时间的变化趋势如右图，其中纵坐标y表示A. 碳的质量B. 氧化铜的质量C. 二氧化碳的质量D. 固体中铜元素的质量分数45. 有氧化铁和氧化铜的混合物，其中氧元素的质量为1.6g。
2016年松江区初三二模化学试卷及参考答案
2016年松江区初中毕业生学业模拟考试理化试卷（满分150分，完卷时间100分钟）2016.4化学部分可能用到的相对原子质量：H-1 N-14 O-16 S-32 Cu-64 Zn-65 C-12六、选择题（共20分）27．属于化学变化的是A．汽油挥发B．水的电解C．胆矾研碎D．冰川融化28．俗称与化学式相对应的是A．水银—Ag B．干冰—H2O C．苛性钠—NaOH D．石碱—Na2CO3 29．属于纯净物的是A．食醋B．液氧C．空气D．石油30．氯元素的化合价为+5价的是A．HCl B．Cl2C．HClO3D．ClO231．酒精（C2H6O）属于A．混合物B．氧化物C．单质D．有机物32．属于复合肥的是A．(NH4)2SO4B．NH4HCO3C．NH4NO3D．KNO333．既具有可燃性又具有还原性的氧化物是A. CO B．CH4C．H2D．CO234．物质燃烧时，现象描述正确的是A．铁丝在空气中剧烈燃烧，火星四射B．镁条在空气中燃烧，发出耀眼的白光C．红磷在氧气中燃烧，生成浓厚的烟雾D．硫在氧气中燃烧，发出淡蓝色火焰35．实验操作错误的是A．滴加液体B．添加酒精C．加热液体D．放置试管36．右图是某反应的微观示意图，分析错误的是A ．该反应属于化合反应B ．每个生成物分子由3个原子构成C ．该反应中反应物的质量比为1:2D ．两种反应物均为单质37．互为同素异形体的物质一定具有相同的A ．物理性质B ．元素组成C ．微观结构D ．用途 38．水作氧化剂的反应是A ．C+H 2O H 2+CO B ．2H 2O 22H 2O+O 2 C ．H 2+CuOCu+H 2O D ．H 2O+CO 2H 2CO 339．能用于鉴别氢氧化钠溶液和稀盐酸的是A ．CuB ．H 2SO 4C ．Ba(NO 3)2D ．Cu(OH)2 40．说法正确的是A ．1 mol H 2SO 4含有6 mol 原子B ．18 g H 2O 中含有2 mol 氢C ．0.5 mol O 2中约含有6.02×1023个氧原子D ．1 mol 氮气的质量是14g 41．能达到目的实验是42．推理合理的是A ．某固体中加入稀硫酸，产生气泡，则该固体为活泼金属B ．某溶液中加入硫酸铜溶液，产生蓝色沉淀，则该溶液是氢氧化钠溶液C ．燃烧需要同时满足三个条件，则灭火也要同时控制这三个条件D ．某溶液进行焰色反应，火焰呈黄色，则该溶液中含有钠元素 43．物质间可以直接实现转化的是A ．Fe→Fe 2O 3→FeSO 4B ．HCl→CuCl 2→BaCl 2C ．NaOH→NaCl→Na 2CO 3D ．CO 2→H 2CO 3→CO 44．除去物质中的杂质（括号内是杂质），操作正确的是 MnO 2加热45．证明混合气体中含有CO2、H2、CO、H2O，通过试剂顺序正确的是①澄清石灰水②无水硫酸铜③氢氧化钠固体④灼热的氧化铜A．②①③④②①B．②③①④②①C．①②③④②①D．②①③④①②46．一定量的碳与氧化铜混合加热，反应前后测定装置I、II的质量如下。
2016年松江区初三二模语文试题(附答案)
2016年松江区初三二模语文试题（满分：150分，完成时间100分钟，在答题纸上完成）考生注意：1、本卷共26题。
2、请将所有答案做在答题纸的指定位置上，做在试卷上一律不得分。
一、文言文（39分）（一）默写（15分）1、蜂蝶纷纷过墙去，。
（《雨晴》）2、，浓睡不消残酒。
（《如梦令》）3、，白水绕东城。
（《送友人》）4、而吾蛇尚存，。
（《捕蛇者说》）5、未果，寻病终。
（《桃花源记》）(二）阅读下列诗句，完成第6-7题（4分）【甲】伫倚危楼风细细，望极春愁，黯黯生天际。
草色烟光残照里，无言谁会凭栏意。
【乙】自送别，心难舍，一点相思几时绝？凭栏袖拂杨花雪。
溪又斜，山又遮，人去也！6、甲、乙分别通过“”和“_ ”等词句表现“凭栏之久”，以此表达用情之深。
（2分)7、下列对诗句理解不正确的一项是（）（2分）A．两句所交代的时令都是春季。
B.都描绘了有情人离别时的场景。
C．甲的抒情方式委婉，而乙较直接。
D.两句中的景分别用来渲染气氛和层层设障。
(三）阅读下列选文，完成第8-10题（9分）泰山正南面有三谷。
中谷绕泰安城下，郦道元所谓环水也。
余始循以入，道少半，越中岭，复循西谷，遂至其巅。
古时登山，循东谷入，道有天门。
东谷者，古谓之天门溪水，余所不至也。
今所经中岭及山巅，崖限当道者，世皆谓之天门云。
道中迷雾冰滑，磴几不可登。
及既上，苍山负雪，明烛天南；望晚日照城郭，汶水、徂徠如画，而半山居雾若带然。
8、节选语段的作者是清朝派古文家 (姓名）。
（2分）9、解释下列句中加点词语。
（4分）(1)崖限当．道者（）（2)半山居．雾若带然（）10、下列对划线句理解错误的一项是（）（3分）A．描绘了泰山顶上时而日照时而迷雾的奇特气象。
B．“半山居雾若带然”一句从侧面表现了泰山之高。
C．“苍山负雪，明烛天南”表现了积雪的厚实白亮。
D．表达作者历尽艰险领略到美景后的兴奋畅快之情。
(四）阅读下文，完成第11-13题（12分）梁鸿家贫而尚节，博览无不通，而不为章句①。
上海市松江区2016届九年级4月质量调研(二模)物理试题及答案(word解析版)
初三物理第1页共9页松江区2015~2016年度第二学期初三质量调研理化试卷（满分150分考试时间100分钟）物理部分2016.4考生注意：1．本试卷物理部分含五个大题。
2．答题时，考生务必按答题要求在答题纸规定的位置上作答，在草稿纸，本试卷上答题一律无效。
一、选择题（16分）下列各题均只有一个正确选项，请将正确选项的代号用2B 铅笔填涂在答题纸的相应位置上，更改答案时，用橡皮擦去，重新填涂。
1．在下列各星球中，属于卫星的是A ．月球B ．地球C ．水星D ．太阳2．“闻其声而知其人”，这句话表明不同人发出的声音具有不同的A ．音调B ．音色C ．响度D ．频率3．小刚学习了磁的知识后，标出了下列四种情况下磁体的磁极（小磁针的黑端为N 极），如图1所示，其中正确的是4．下列现象中，用热传递方式改变物体内能的是A ．火车经过后，铁轨的温度升高B ．反复弯折后，铁丝的温度升高C ．铁锅烧热后，铁锅的温度升高D ．锯条锯木后，锯条的温度升高5．如图2所示，分别用F 1、F 2、F 3、F 4匀速提升同一重物，若不计滑轮本身的重力及摩擦，则A ．F 1＜F 2＜F 3＜F 4B ．F 1＞F 2＞F 3＞F 4C ．F 1＝F 2＝F 3＜F 4D ．F 1＝F 2＝F 3＞F 46．如图3所示，图3图2图1A BC D初三物理第2页共9页1224681002468t /秒甲车乙车图6跳水运动员站在跳板上静止不动，下列说法正确的是A ．跳板被压弯说明力可以改变物体的运动状态B ．运动员对跳板的压力和运动员所受的重力是一对平衡力C ．跳板对运动员的支持力和运动员对跳板的压力是一对平衡力D ．跳板对运动员的支持力和运动员所受的重力是一对平衡力7．如图4所示电路中，电源电压保持不变，当电键S 由断开到闭合时，则A ．电流表的示数变小，电压表的示数变小B ．电流表的示数变小，电压表的示数变大C ．电流表的示数不变，电压表的示数变小D ．电流表的示数不变，电压表的示数不变8．如图5所示，底面积不同的甲、乙圆柱形轻质容器，分别盛有密度为ρ甲、ρ乙两种液体，甲液体对容器底部的压强等于乙液体对容器底部的压强。
2016学年松江二模-试卷
松江区2016学年第二学期高三年级质量调研考试英语试卷考生注意：1．考试时间120分钟, 试卷满分150分。
2．本考试设试卷和答题纸两部分, 试卷共12页。
所有答题必须涂（选择题）或写（非选择题）在答题纸上, 做在试卷上一律不得分。
3．答题前, 务必在答题纸上填写准考证号和姓名。
I. Listening ComprehensionSection ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. At 12:30. B. At 13:00. C. At 13:30. D. At 14:00.2. A. In a hospital. B. In a police station.C. In a garage.D. In a post-office.3. A. Wash clothes. B. Clean the backyard.C. Sit in the backyard.D. Enjoy the tea.4. A. He doesn’t want to watch TV tonight. B. He prefers to watch the baseball game.C. He’d rather see the movie.D. He hasn’t decided what to watch tonight.5. A. How to check computer files. B. How to write computer programs.C. How to apply for a computer course.D. How to assemble a computer.6. A. She thinks it wrong to choose either of the books.B. She finds it difficult to choose one from the two books.C. She thinks either of the books will be Ok.D. She doesn’t like either of the two books.7. A. The application has been delayed for a week.B. The job has been offered to someone else.C. The man is not suitable for the position.D. The man lacks the relevant experience.8. A. Ambitious. B. Diligent. C. Aggressive. D. Considerate.9. A. She is strict with discipline. B. She has missed some lessons.C. She can’t give good lessons.D. She fails to behave herself.10. A. Working conditions should be improved for the employees.B. The employees should be satisfied with the present working conditions.C. He doesn’t think the employees should have the protest.D. He is doubtful about the effect of the employees’ action.Section BDirections: In Section B, you will hear two passages and a longer conversation, and you will be asked several questions on each of the passages and the conversation. The passages and conversation will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one is the best answer to the question you have heard.Questions 11 through 13 are based on the following news.11. A. A jewelry shop. B. Shops in the City Mall.C. A parked truck.D. A driver in the parking lot.12. A. Leave the truck together. B. Run back to the truck without helmets.C. Run back to the truck separately.D. Leave the truck without helmets.13. A. The truck was originally painted white.B. The truck had no registration plate.C. The truck disappeared from the parking lot.D. The truck was covered with silver material.Questions 14 through 16 are based on the following passage.14. A. In order to protect the weak and old ones.B. In order to show beautiful shape of them.C. In order to maintain physical strength.D. In order to keep teamwork spirit.15. A. How the birds decide the order of the group.B. How the birds decide the route of the group.C. How the birds decide the time of flying of the group.D. How the birds decide who takes charge of the group.16. A. Birds’ ability to keep order. B. Birds’ flying pattern as a team.C. Birds’ intention to migrate.D. Birds’ skills to tell directions.Questions 17 through 20 are based on the following conversation.17. A. Beautiful scenery in the countryside. B. Cross-country skiing.C. Dangers of winter sports.D. Pain and pleasure in sports.18. A. He can’t find good examples to illustrate his point.B. He can’t find a peaceful pl ace to do the assignment.C. He can’t decide whether to include the effort part of skiing.D. He doesn’t know how to describe the beautiful country scenery.19. A. New ideas come up as you write. B. Much time is spent on collecting data.C. It’s hard to find a proper topic.D. The writer’s point of view often changes.20. A. How to revise a paper in an academic manner.B. How to polish your arguments in a paper.C. How to tell the main ideas in a paper effectively.D. How to decide on relevant content for a paper.II. Grammar and VocabularySection ADirections:After reading the passage below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.One steamy July afternoon in central Arkansas, I was working on an important project in my home office. My trusty printer was busy producing an important report (21) ______ it simply stopped. After fifteen minutes of trying to repair, I decided to buy a new printer. Upon my return, my heart froze to see my house on fire.(22) ______ having spent much of my life writing, I was speechless when facing this situation. I was lost for adequate words (23) ______ (describe) the sick, sinking feeling of seeing my home, business, and belongings going up in flames along with photographs and memories (24) ______ (collect) over a lifetime. But the panic that filled my shocked heart in that awful moment was for the nine cats that shared my home after (25) ______ (rescue) from situations of ill-treatment and abandonment.Responding to an early security-system warning, the amazing firefighters arrived immediately, (26) ______ the chemical smoke had already caused deaths. I examined and kissed each cat goodbye, extremely grateful that they had passed gently, without injuries or burns.Only animal lovers really understand the unbelievable impact (27) ______ the loss of one beloved four-legged family member can have on your heart, mind and soul. The loss of so many dearly loved creatures sent me in great sorrow.After staying with a friend of mine for a couple of weeks, I was relocated to a furnished apartment. One evening, about a month after moving in, I (28) ______ (occupy) in writing a mystery novel, and at that time a ―meow‖ sounded from outside the apartment door. Was it my mind playing tricks again? More than once I had heard, seen or felt the brush of one of mydeparted furry roommates. The meow grew louder and more repetitive. Curious, I opened the door.Sitting on the doorstep was a kitten with a black coat and alert eyes. A neighbor (29) ______ (walk) by picked him up and began petting him. When I remarked how cute her kitten was, she explained that it had been born under a bridge and looked around for food. This kitty-loving neighbor was quick to offer an extra litter box if I was interested in giving him a home. My immediate reaction was: ―that’s all I need!‖ without hesitation she put the cute kitten down. I thanked her and closed the door, determined to just let him stay (30) ______ a real home could be found.Section BDirections: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.There are two basic ways to see growth: one as a product, the other as a process. People have generally viewed personal growth as a(n) 31 result or product that can easily be identified and measured. The worker who gets a promotion, the student whose grades improve, the foreigner who learns a new language-all these are examples of people who have measurable results to show for their efforts.By 32 , the process of personal growth is much more difficult to determine, since by definition it is a journey and not the specific signposts or landmarks along the way. The process is not the road itself, but rather the attitudes and feelings people have, their caution or courage, as we 33 new experiences and unexpected obstacles. In this process, the journey never really ends. There are always new ways to experience the world, new ideas to try, new challenges to accept.In order to grow, to travel new roads, people need to have a 34 to take risks. And we are supposed to be ready to face the 35 , and to accept the possibility that we may ―fail‖ at first. How we see ou rselves as we try a new way of being is essential to our ability to grow. Do we perceive ourselves as quick and curious? If so, then we tend to take more chances and to be more open to unfamiliar experiences. Do we think we’re 36 and shy? Then our 37 of shyness can cause us to hesitate, to move slowly, and not to take a step until we know the ground is safe. Do we think we’re slow to adapt to change or that we’re not smart enough to cope with a new challenge? Then we are likely to take a more38 role or not try at all.These feelings of insecurity and self-doubt are both unavoidable and necessary if we are to change and grow. We will 39 to grow, if we do not confront and overcome these internal fears and doubts, and if we protect ourselves too much. We become 40 inside a shell of our own making.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.To Apologize or Not to ApologizeWhy difficult?When we do wrong to someone we know, even not 41 , we are generally expected to apologize so as to improve the situation. But when we’re acting as leaders, the circumstances are 42 . The act of apology is carried out not merely at the level of the43 but also at the level of the institution. It is a performance in which every word or expression 44 ,as they become part of the public record. Refusing to apologize can be smart, or it can be stupid. So, readiness to apologize can be seen as a sign of strong character or as a sign of weakness.Why now?The question of whether leaders should apologize publicly has never been more 45 . During the last decade or so, the United States in particular has developed an apology culture—apologies of all kinds and for all sorts of wrongdoings are made far more 46 than before. More newspaper writers have written about the growing importance of 47 apologies. Meanwhile, more and more articles, advice columns, and radio and television programs have similarly dealt with the subject of 48 apologies. Although they are not carried out in the public place, we can’t neglect the importance of this performance.Why 49 ?Why do we apologize? Why do we ever put ourselves in situations likely to be difficult, embarrassing, and even risky? Leaders who apologize publicly could be an easy target for 50 . They are expected to appear strong and capable. And whenever they make public statements of any kind, their individual and institutional reputations are in danger. Clearly, then, leaders should not apologize often. For a leader to express apology, there needs to be a strong 51 . Leaders will publicly apologize if and when they think the costs of doing so are lower than the costs of not doing so.Why refuse?Why is it that leaders so often try every means to 52 apologies, even when a public apology seems to be in order? Their reasons can be individual or institutional. Because leaders are public figures, their apologies are likely to be personally uncomfortable and even 53 risky. Apologies can be signals for admitting mistakes and mistakes can be indication of job insecurity. Leaders may also be afraid that 54 of a mistake will damage or destroy the organization for which they are responsible. There can be good reasons for hanging tough (硬撑) in tough situations, as we shall see, but it is a high-risk 55 .41. A. immediately B. intentionally C. occasionally D. accidentally42. A. simple B. ridiculous C. abnormal D. different43. A. individual B. company C. family D. society44. A. conflicts B. matters C. appeals D. deceives45. A. urgent B. possible C. necessary D. simple46. A. interestedly B. patiently C. frequently D. hopefully47. A. faithful B. trusty C. immediate D. public48. A. sincere B. acceptable C. private D. positive49. A. bother B. reduce C. regret D. ignore50. A. promotion B. criticism C. appreciation D. identification51. A. personality B. will C. reason D. desire52. A. attempt B. involve C. commit D. avoid53. A. financially B. professionally C. academically D. physically54. A. avoidance B. admission C. involvement D. elimination55. A. fulfillment B. statement C. occupation D. strategySection BDirections: Read the following passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)If your in-box is currently reporting unread messages in the hundreds or thousands, you might have a hard time believing the news: e-mail is on the decline.At first thought, that might seem to be the case. The incoming generation, after all, doesn’t do e-mail. Oh, they might have an account. They use it only as we would use a fax machine: as a means to communicate with old-school folks like their parents or to fulfill the sign-up requirements of Web sites. They rarely check it, though.Today’s instant electronic memos—such as texting and Facebook and Twitter messages—are more direct, more concentrated, more efficient. They go without the salutation (称呼语) and the signoff (签收); we already know the ―to‖ and ―from.‖ Many corporations are moving to messaging networks for exactly that reason: more signal, less noise and less time. This trend is further evidence that store-and-forward systems such as e-mail and voicemail are outdated. Instead of my leaving you a lengthy message that you pick up later, I can now send you an easily-read message that you can read—and respond to—on the go.The coming of the mobile era is responsible for the decline of e-mail. Instant written messages bring great convince to people. They can deal with them at about any time: before a movie, in a taxi, waiting for lunch. An d because these messages are very brief, they’re suitable for smart phone typing.Does this mean e-mail is on its way to the dustbin of digital history? Not necessarily. E-mail still has certain advantages. On the other hand, tweets and texts feel ephemeral—you read them, then they’re gone, into an endless string, e-mail still feels like something you have and that you can file, search and return to later. It’s easy to imagine that it will continue tofeel more appropriate for formal communications: agreements, important news, longer explanations.So, e-mail won’t go away completely. Remember, we’ve been through a transition (过度) like this not so long ago: when e-mail was on the rise, people said that postal mail was dead. That’s not how it works. Postal ma il found its smaller market, and so will e-mail. New technology rarely replaces old one completely; it just adds new alternatives.56. What would the incoming generation like to do with their e-mail accounts?A. Contact close friends.B. Send long messages.C. Fill in some forms.D. Communicate with their colleagues.57. Which of the following is mainly discussed in paragraphs 3 and 4?A. The possible reasons behind the decline of e-mail.B. The likes and dislikes of the young generation.C. The rapid development of e-communication channels.D. Evidence about the uncertain future of easily-consumed messages.58. What does the underlined word ―ephemeral‖ in paragraph 5 mean?A. Automatically-sending.B. Randomly-written.C. Hardly- recognized.D. Shortly-appearing.59. According to the passage, which of the following statements is true?A. It’s too early to determine the decline of e-mail.B. E-mail has reasons to exist on its own advantages.C. E-mail, just like postal mail has come to its end.D. We should feel sorry for the decline of e-mail.(B)60. The Fox News review mentioned the first party scene in the film to ________.A. reveal the fact that Nick wants to know more about GatsbyB. show the version of Rhapsody in Blue matches the film wellC. prove that the director is good at combining visual and musicD. convince us that the first scene is perfectly shot by the director61. According to Time Magazine, what did Baz Luhrmann do to make the film a success?A. He adapted the story in the novel as he wished.B. He made the film more powerful than the book.C. He mixed his style with the elegance of the book.D. He changed the story to meet his own style.62. Which of the following can be used to describe Gatsby?A. Faithful and warm-hearted.B. Charming and professional.C. Selfish and charming.D. Mysterious and devoted.(C)The British Medical Journal recently featured a strong response to what was judged an inappropriately merciful reaction by a medical school to a student cheating in an examination. Although we have insufficient reliable data about the extent of this phenomenon, itsprevention, or its effective management, much can be concluded and acted upon on the basis of common sense.There is general agreement that there should be zero tolerance of cheating in a profession based on trust and one on which human lives depend. It is reasonable to assume that cheaters in medical school will be more likely than others to continue to act dishonestly with patients, colleagues, and government.The behaviours under question are multifactorial in origin. There are familial (家庭的), religious, and cultural values that are acquired long before medical school. For example, countries, cultures, and subcultures exist where bribes and dishonest behaviour are very normal. There are secondary schools in which neither staff nor students tolerate cheating and others where cheating is common; there are homes which cultivate young people with high standards of moral behaviour and others which leave moral training to the harmful influence of television and the market place.Medical schools reflect society and cannot be expected to remedy all the ills of a society. The selection process of medical students might be expected to favour applicants with positive moral behaviour. Medical schools should be the major focus of attention for cultivating future doctors with moral sensitivity. Unfortunately there are troubling data that suggest that during medical school the moral behaviour of medical students does not necessarily improve; indeed, moral development may actually stop or even regress (倒退).It is critical that the academic and clinical leaders of the institution set a personal example on moral behaviour. Medical schools must do something to make sure that their students are expected to be clear from day one. The development of a school’s culture of moral behaviour requires cooperation with the students in which they play an active role in its creation and developing. Moreover, the school’s examination system and general treatment of students must be fair. Finally, the treatment of infractions (违规) must be firm, fair, transparent (透明的).63. What does the author say about cheating in medical schools?A. Extensive research has been done about this phenomenon.B. We have sufficient data to prove that prevention is possible.C. We know that this phenomenon exists in every medical school.D. We still need more reliable data to know how serious it is.64. According to the author, it is important to prevent cheating in medical schools because________.A. The medical profession is based on trustB. There is zero tolerance of cheating in medicineC. The medical profession depends on the governmentD. Cheating exists extensively in medical schools65. Which of the following statements will the author probably agree with?A. Medical schools should make a less competitive environment for students.B. Outstanding people should create a set of moral standards to be followed.C. Medical students should be positive in creating and preserving moral behavior.D. We don’t know the cause-and-effect of the examination cheating in medical school.66. Which of the following can be implied from the passage?A. It makes little sense to talk about medical school student cheating in exams.B. Medical schools haven’t been doing well to help students devel op morally.C. Cheating in exams is tolerable outside of medical school circle.D. Elimination of exams helps cultivate healthier characters of medical school students.Section CDirections: Read the following passage carefully. Fill in each blank with a proper sentence given in the box. Each sentence can be used only once. Note that there are two more sentences than you need.The worst time to look for a job is when you feel desperate and must have a new one immediately. 67 If you are not in need of an immediate career change, here are ways you can improve your long-term career prospects today:Identify at least two different roles. You do not have to be qualified for these positions today, nor do they have to exist in your company. However, these roles should be related to your current skill set. They are career options that look interesting. 68 Pay close attention to what appeals to you, and write it down. This will give insight into your motivations and targets.Subscribe to a career specific magazine. Knowledge is power in the workplace. All businesses must stay relevant to their customers in order to win the competitions and increase revenue (收益). Reading about industry trends, advancements and success stories keeps youin touch with market conditions. This information allows you to see which companies and professionals are leading the pack. You can follow their examples in your own workplace.69Do exceptional work. In any role, there is a way to perform at your best. Look for ways to deliver a top performance. Show up early, be flexible to new assignments, have a positive attitude, cooperate with other departments, pay attention to the little details.Be professionally curious. Talk to people about their careers. Learn more about how success is measured in other roles, departments and companies. Ask people their thoughts on different industries. 70 People hire people. You never know what connections may be relevant when you start your next job search, so develop a habit of making good connections no matter where you go. Take the time to learn about others, and be helpful when you can.As in all things in life, getting in front of a difficult task early is always less stressful than reacting to a career surprise. Changing jobs is to be expected. No matter how secure you feel today, the time will come when either you or your employer decide it is time to change.IV. Summary WritingDirections: Read the following passage. Summarize the main idea and the main points of the passage in no more than 60 words. Use your own words as far as possible.There are various means consumers can do if they find that an item they bought is faulty or in some other way does not live up to the manufacturer’s claims. A simple and common method used by many consumers is to complain directly to the store manager. In general, the ―higher up‖ his or her complaint, the faster he or she can expec t it to be settled. In such a case, it is usually settled in the consumer’s favor, assuming he or she has a just claim.Consumers should complain in person whenever possible, but if they cannot get to the place of purchase, it is acceptable to phone or write the complaint in a letter.Complaining is usually most effective when it is done politely but firmly, and especially when the consumer can demonstrate what is wrong with the item in question. If this cannot be done, the consumer will succeed best by presenting specific information as to what is wrong, rather than by making general statements. For example, ―The left speaker does not work at all and the sound coming out of the right one is unclear‖ is better than ―This stereo does not work‖. The store ma nager may advice the consumer to write to the manufacturer. If so, the consumer should do this, stating the complaint as politely and firmly as possible. If a polite complaint does not achieve the desired result, the consumer can go to a step further. She or he can threaten to take the seller to court or report the seller to a private or public organization responsible for protecting consumer’s rights.V. TranslationDirections: Translate the following sentences into English, using the words given in the brackets.72. 看孩子们在沙滩上打排球很有趣。
2016年松江区初三二模语文试题和参考答案
2016年松江区初三二模语文试题一、文言文（39分）（一）默写（15分）1、蜂蝶纷纷过墙去，。
（《雨晴》）2、，浓睡不消残酒。
（《如梦令》）3、，白水绕东城。
（《送友人》）4、而吾蛇尚存，。
（《捕蛇者说》）5、未果，寻病终。
（《桃花源记》）（二）阅读下列诗句，完成第6-7题（4分）【甲】伫倚危楼风细细，望极春愁，黯黯生天际。
草色烟光残照里，无言谁会凭栏意。
【乙】自送别，心难舍，一点相思几时绝？凭栏袖拂杨花雪。
溪又斜，山又遮，人去也！6、甲、乙分别通过“”和“_ ”等词句表现“凭栏之久”，以此表达用情之深。
（2分)7、下列对诗句理解不正确的一项是（）（2分）A．两句所交代的时令都是春季。
B.都描绘了有情人离别时的场景。
C．甲的抒情方式委婉，而乙较直接。
D.两句中的景分别用来渲染气氛和层层设障。
（三）阅读下列选文，完成第8-10题（9分）泰山正南面有三谷。
中谷绕泰安城下，郦道元所谓环水也。
余始循以入，道少半，越中岭，复循西谷，遂至其巅。
古时登山，循东谷入，道有天门。
东谷者，古谓之天门溪水，余所不至也。
今所经中岭及山巅，崖限当道者，世皆谓之天门云。
道中迷雾冰滑，磴几不可登。
及既上，苍山负雪，明烛天南；望晚日照城郭，汶水、徂徠如画，而半山居雾若带然。
8、节选语段的作者是清朝派古文家(姓名）。
（2分）9、解释下列句中加点词语。
（4分）(1)崖限当道者（）（2)半山居雾若带然（）10、下列对划线句理解错误的一项是（）（3分）A描绘了泰山顶上时而日照时而迷雾的奇特气象。
B、“半山居雾若带然”一句从侧面表现了泰山之高。
C、“苍山负雪，明烛天南”表现了积雪的厚实白亮。
D、表达作者历尽艰险领略到美景后的兴奋畅快之情。
（四）阅读下文，完成第11-13题（12分）梁鸿家贫而尚节，博览无不通，而不为章句①。
学毕，乃牧豕②于上林苑中，曾误遗火，延及他舍。
鸿乃寻访烧者，问所去失，悉以豕偿之。
其主犹以为少。
鸿曰：“无他财，愿以身居作。
上海市徐汇区、金山区、松江区2016年高考数学二模试卷(文科) 含解析
2016年上海市徐汇区、金山区、松江区高考数学二模试卷（文科）一、填空题1．抛物线y2=4x的焦点坐标为．2．若集合A={x|3x+1＞0}，B=｛|x﹣1｜＜2}，则A∩B=．3．若=（3,2）是直线l的一个方向向量,则l的倾斜角的大小为(结果用反三角函数值表示）4．若复数z满足=﹣i,其中i为虚数单位,则= ．5．求值:= 弧度．6．已知=3,设=λ，则实数λ=．7．函数y=+的最小值为．8．试写出（x﹣）7的展开式中系数最大的项．9．已知三个球的表面积之比是1：2:3，则这三个球的体积之比为．10．已知实数x，y满足，则目标函数z=﹣x﹣y的最大值为．11．若不等式x2﹣5x+6＜0的解集为（a,b)，则= ．12．从集合A=｛1，2，3，4，5，6，7，8，9，10}中任取两个数，欲使取到的一个数大于k，另一个数小于k（其中k∈A）的概率为，则k= ．13．有一道解三角形的题因纸张破损有一个条件不清，具体如下:在△ABC中,已知，，求角A．经推断破损处的条件为三角形一边的长度，且答案提示A=60°，试将条件在横线处补全．14．定义在R上的奇函数f（x），当x≥0时，f（x）=则关于x的函数F（x）=f（x）﹣a（0＜a＜1）的所有零点之和为．二、选择题15．已知非零向量、，“函数为偶函数”是“”的( )A．充分非必要条件B．必要非充分条件C．充要条件 D．既非充分也非必要条件16．如图所示的几何体的左视图是（）A．B．C． D．17．函数y=的反函数是（)A．y= B．y=C．y= D．y=18．设x1、x2分别是关于x的方程x2+mx+m2﹣m=0的两个不相等的实数根,那么过两点A(x1，x12），B（x2，x22）的直线与圆（x﹣1）2+（y+1）2=1的位置关系是（）A．相离B．相切C．相交D．随m的变化而变化三、解答题19．在直三棱柱ABC﹣A1B1C1中，AB=AC=1,∠BAC=90°,且异面直线A1B与B1C1所成的角等于60°，设AA1=a．（1）求a的值；（2）求三棱锥B1﹣A1BC的体积．20．已知函数f(x）=2sinxcosx+2cos2x．（1）求函数f（x）的单调递增区间;（2)将函数y=f（x)图象向右平移个单位后，得到函数y=g(x）的图象,求方程g(x)=1的解．21．已知函数f（x)=|2x﹣a｜+a．(1）若不等式f（x)＜6的解集为（﹣1，3），求a的值；(2)在(1）的条件下，若存在x0∈R，使f（x0）≤t﹣f(﹣x0），求t的取值范围．22．已知椭圆C：+=1（a＞b＞0)的右焦点为F（1，0），且点P（1，）在椭圆上；(1）求椭圆C的标准方程；(2）当点P(x，y）在椭圆C上运动时，点Q（,)在曲线S上运动，求曲线S的轨迹方程,并指出该曲线是什么图形；（3）过椭圆C1:+=1上异于其顶点的任意一点Q作曲线S的两条切线，切点分别为M，N（M，N 不在坐标轴上），若直线MN在x轴，y轴的截距分别为m，n，试问：+是否为定值？若是，求出该定值,若不是,请说明理由．23．按照如下的规律构造数表:第一行是：2；第二行是：2+1，2+3：即3,5;第三行是:3+1，3+3，5+1，5+3，即：4,6，6，8,…（即从第二行起将上一行的数的每一项各加1写出，再各项再加3写出），若第n行所有的项的和为a n；23 54 6 6 85 7 7 9 7 9 9 11…(1）求a3，a4，a5；（2）试写出a n+1与a n的递推关系，并据此求出数列{a n}的通项公式;（3）设S n=++…+（n∈N*），求S n和S n 的值．2016年上海市徐汇区、金山区、松江区高考数学二模试卷（文科）参考答案与试题解析一、填空题1．抛物线y2=4x的焦点坐标为(1，0）．【考点】抛物线的简单性质．【分析】先确定焦点位置，即在x轴正半轴，再求出P的值，可得到焦点坐标．【解答】解：∵抛物线y2=4x是焦点在x轴正半轴的标准方程，p=2∴焦点坐标为：（1,0)故答案为：（1，0)2．若集合A={x｜3x+1＞0｝,B=｛|x﹣1｜＜2}，则A∩B=（﹣，3）．【考点】交集及其运算．【分析】求出集合的等价条件，根据集合的基本运算进行求解即可．【解答】解：A=｛x｜3x+1＞0}=｛x｜x＞﹣},B={|x﹣1|＜2｝={x｜﹣2＜x﹣1＜2}={x｜﹣1＜x＜3},则A∩B={x｜﹣＜x＜3}，故答案为：（﹣，3）．3．若=(3，2）是直线l的一个方向向量，则l的倾斜角的大小为arctan（结果用反三角函数值表示）【考点】直线的倾斜角．【分析】由直线l的一个方向向量求出直线的斜率,再由倾斜角的正切值等于斜率求解．【解答】解:∵直线l的一个方向向量为（3，2)，∴直线l的斜率为k=,设其倾斜角为α（0≤α＜π），由tanα=，得α=arctan．故答案为：arctan．4．若复数z满足=﹣i，其中i为虚数单位，则= 1﹣i ．【考点】复数代数形式的乘除运算．【分析】利用复数代数形式的乘除运算化简求得z，则可求．【解答】解：由=﹣i,得，∴．故答案为：1﹣i．5．求值:= 弧度．【考点】二阶矩阵；反三角函数的运用．【分析】利用二阶行列式展开法则由原式得到﹣2arctan,再利用反三角函数性质能求出结果．【解答】解:：=﹣2arctan=3×﹣2×=．故答案为:．6．已知=3,设=λ，则实数λ= 2 ．【考点】向量的线性运算性质及几何意义．【分析】可知,这样带入便可得到,从而便可得出λ的值．【解答】解：根据条件，=；∴λ=2．故答案为：2．7．函数y=+的最小值为．【考点】基本不等式．【分析】令=t，可得：y==g（t），利用导数研究函数的单调性即可得出．【解答】解：令=t，∴y==g（t),g′（t）=1﹣=＞0，∴函数g（t）在上单调递增,∴g(t）的最小值为:=．故答案为：．8．试写出（x﹣)7的展开式中系数最大的项．【考点】二项式系数的性质．【分析】T r+1=(﹣1）r x7﹣2r，r必须为偶数,分别令r=0,2，4，6，经过比较即可得出．【解答】解：T r+1=x7﹣r=（﹣1)r x7﹣2r，r必须为偶数，分别令r=0，2，4,6,其系数分别为：1,，，．经过比较可得：r=4时满足条件,T5=x﹣1=，故答案为：．9．已知三个球的表面积之比是1:2：3，则这三个球的体积之比为．【考点】球的体积和表面积．【分析】通过球的表面积之比求出半径之比，然后求出它们的体积之比即可．【解答】解：设三个球的半径为a，b，c,根据球的表面积公式得出4πa2：4πb2：4πc2=1：2：3，所以它们的半径之比为a:b：c=1：：．则它们的体积之比是a3：b3：c3=故答案为：10．已知实数x,y满足，则目标函数z=﹣x﹣y的最大值为．【考点】简单线性规划．【分析】由约束条件作出可行域，化目标函数为直线方程的斜截式，数形结合得到最优解，联立方程组求得最优解的坐标,代入目标函数得答案．【解答】解：由约束条件作出可行域如图，联立，解得A(﹣1，3)，化目标函数z=﹣x﹣y为y=﹣，由图可知,当直线y=﹣过A时，直线在y轴上的截距最小,z有最大值为．故答案为：．11．若不等式x2﹣5x+6＜0的解集为（a,b）,则= ．【考点】极限及其运算；一元二次不等式的解法．【分析】先解一元二次不等式，求得a,b的值，将其代入，分式同除3n，可求得极限值．【解答】解:不等式x2﹣5x+6＜0，解集为（2，3）∴a=2，b=3,====．故答案为：．12．从集合A={1，2,3，4，5,6，7,8，9,10}中任取两个数，欲使取到的一个数大于k，另一个数小于k（其中k∈A）的概率为，则k= 4或7 ．【考点】列举法计算基本事件数及事件发生的概率．【分析】由题意=，由此能求出结果．【解答】解：∵从集合A=｛1，2，3,4，5，6,7，8，9，10}中任取两个数，欲使取到的一个数大于k,另一个数小于k(其中k∈A）的概率为，∴=，解得k=4或k=7．故答案为：4或7．13．有一道解三角形的题因纸张破损有一个条件不清，具体如下：在△ABC中，已知，，求角A．经推断破损处的条件为三角形一边的长度,且答案提示A=60°，试将条件在横线处补全．【考点】正弦定理．【分析】要把横线处补全,就要把A的度数作为已知条件求c的值，由a，A和B的度数,根据正弦定理求出b的长,再由三角形的内角和定理求出C的度数,由a,b 及cosC,利用余弦定理即可求出c的长．【解答】解：根据正弦定理得：=，a=,sinB=,sinA=，所以b==，又C=180°﹣45°﹣60°=75°，所以cos75°=cos（45°+30°）=cos45°cos30°﹣sin45°sin30°=，所以c2=a2+b2﹣2abcosC=3+2﹣2×==,则c=．故答案为：14．定义在R上的奇函数f（x）,当x≥0时,f（x）=则关于x的函数F（x）=f（x）﹣a(0＜a＜1)的所有零点之和为1﹣2a．【考点】根的存在性及根的个数判断．【分析】由题意，作函数y=f（x）与y=a的图象，从而可得x1+x2=﹣6，x4+x5=6，x3=1﹣2a，从而解得．【解答】解：由题意，作函数y=f（x）与y=a的图象如下，结合图象,设函数F（x）=f（x)﹣a（0＜a＜1）的零点分别为x1，x2，x3，x4，x5，则x1+x2=﹣6，x4+x5=6，﹣log0.5（﹣x3+1）=a,x3=1﹣2a，故x1+x2+x3+x4+x5=﹣6+6+1﹣2a=1﹣2a，故答案为：1﹣2a．二、选择题15．已知非零向量、，“函数为偶函数”是“"的（）A．充分非必要条件B．必要非充分条件C．充要条件 D．既非充分也非必要条件【考点】必要条件、充分条件与充要条件的判断．【分析】已知非零向量、，根据f（﹣x)=f（x），求出向量、的关系，再利用必要条件和充分条件的定义进行判断．【解答】解：∵函数=（x）2+2+2•x，又f（x）为偶函数，f(﹣x）=f(x），∴f（﹣x）=（﹣x）2+2﹣2•x，∴f（﹣x）=f（x）,∴2•x=0,∴•=0，∴，若，则•=0，∴f（﹣x）=f（x),∴f(x）为偶函数,故选C．16．如图所示的几何体的左视图是（）A．B．C． D．【考点】简单空间图形的三视图．【分析】根据几何体中小正方体的排放位置进行判断．【解答】解：设几何体中小正方体的边长为1，∵几何体的高为3，宽为2，故左视图的高为3,长为2．∵几何体前排为单个小正方体，∴左视图的右侧为单个小正方形，故选B．17．函数y=的反函数是（）A．y= B．y=C．y= D．y=【考点】反函数．【分析】利用反函数的求法、分段函数的性质即可得出．【解答】解:∵y=,x≥0时,由y=2x，解得x=，把x与y互换可得：y=x；x＜0,由y=﹣x2，解得x=﹣，把x与y互换可得：y=．∴函数y=的反函数是y=．故选：B．18．设x1、x2分别是关于x的方程x2+mx+m2﹣m=0的两个不相等的实数根,那么过两点A(x1，x12），B（x2，x22）的直线与圆（x﹣1)2+（y+1）2=1的位置关系是（）A．相离B．相切C．相交D．随m的变化而变化【考点】直线与圆的位置关系．【分析】根据方程x2+mx+m2﹣m=0根的判别式大于0,算出0＜m＜,由根与系数的关系算出x1+x2=﹣m，x1x2=m2﹣m．再利用直线的斜率公式算出AB的斜率k=﹣m，利用中点坐标公式算出AB的中点为M（﹣m，﹣m2+m)，得出直线AB的方程为mx+y+m2﹣m=0．最后利用点到直线的距离公式,算出已知圆的圆心C到直线AB的距离大于圆C的半径,可得直线AB 与已知圆相离．【解答】解:∵x1、x2是关于x的方程x2+mx+m2﹣m=0的两个不相等的实数根，∴△=m2﹣4（m2﹣m）＞0，即0＜m＜，且x1+x2=﹣m，x1x2=m2﹣m，可得x12+x22=(x1+x2）2﹣2x1x2=﹣m2+2m，因此，直线AB的斜率k=x1+x2=﹣m，AB的中点为M((x1+x2），（x12+x22））,即M（﹣m，﹣m2+m）∴直线AB的方程为y﹣（﹣m2+m）=﹣m(x+m），化简得mx+y+m2﹣m=0又∵圆（x﹣1）2+（y+1）2=1的圆心坐标为C（1，﹣1），半径r=1，∴圆心C到直线AB的距离为d==，∵0＜m＜，可得d=＞1，∴圆心C到直线AB的距离大于圆C的半径，可得直线与圆的位置关系是相离．故选：A．三、解答题19．在直三棱柱ABC﹣A1B1C1中，AB=AC=1，∠BAC=90°，且异面直线A1B与B1C1所成的角等于60°，设AA1=a．(1)求a的值；(2）求三棱锥B1﹣A1BC的体积．【考点】棱柱、棱锥、棱台的体积；棱柱的结构特征．【分析】（1）以A为原点，AB为x轴，AC为y轴，AA1为z轴，建立空间直角坐标系，利用向量法能求出a．（2）由AC⊥平面A1B1B，利用等体积法能求出三棱锥B1﹣A1BC的体积．【解答】解:(1）以A为原点，AB为x轴，AC为y轴，AA1为z轴，建立空间直角坐标系，则A1（0，0,a），B（1，0，0)，B1（1,0，1）,C1（0，1，a），=（1，0，﹣a)，=（﹣1，1，a﹣1)，∴异面直线A1B与B1C1所成的角等于60°，∴cos60°===，由AA1=a＞0，解得a=1．（2）∵在直三棱柱ABC﹣A1B1C1中，AB=AC=1，∠BAC=90°,∴AC⊥平面A1B1B，∵AC=1,==，∴三棱锥B1﹣A1BC的体积===．20．已知函数f（x）=2sinxcosx+2cos2x．（1）求函数f（x)的单调递增区间；（2）将函数y=f(x）图象向右平移个单位后，得到函数y=g（x）的图象，求方程g(x)=1的解．【考点】二倍角的余弦；二倍角的正弦;函数y=Asin(ωx+φ）的图象变换．【分析】（1)把函数f（x）的解析式第一项利用二倍角的正弦函数公式化简，第二项利用二倍角的余弦函数公式化简，整理后再利用两角和与差的正弦函数公式化为一个角的正弦函数，由正弦函数的单调区间［2kπ﹣，2kπ+]（k∈Z），求出x的范围，即为函数f（x）的单调递增区间；（2）根据平移规律“左加右减”，由f(x）的解析式得到向右平移2个单位后的解析式g（x）,令g(x）=1，得到sin（2x﹣）=0,根据正弦函数的图象与性质即可求出x的值，即为方程g（x）=1的解．【解答】解:(1)函数f（x）=2sinxcosx+2cos2x=sin2x+cos2x+1=sin（2x+)+1，由2kπ﹣≤2x+≤2kπ+（k∈Z)得：kπ﹣≤x≤kπ+（k∈Z），则f（x）的单调递增区间是[kπ﹣，kπ+]（k∈Z）；（2）由已知得：g（x）=sin[2（x﹣）+]+1=sin(2x ﹣），由g（x）=1得：sin(2x﹣)=0,∴2x﹣=kπ（k∈Z），则x=+（k∈Z）．21．已知函数f（x)=|2x﹣a｜+a．（1）若不等式f(x）＜6的解集为（﹣1，3)，求a的值；(2）在(1）的条件下，若存在x0∈R，使f(x0）≤t﹣f(﹣x0），求t的取值范围．【考点】绝对值不等式的解法．【分析】(1)求得不等式f（x）＜6的解集为a﹣3≤x≤3,再根据不等式f（x)＜6的解集为（﹣1，3），可得a﹣3=﹣1，由此求得a的范围；（2)令g(x）=f（x）+f（﹣x)=｜2x﹣2|+｜2x+2|+4，求出g（x）的最小值，可得t的范围．【解答】解:（1）∵函数f(x）=｜2x﹣a|+a，不等式f（x）＜6的解集为（﹣1，3),∴｜2x﹣a|＜6﹣a 的解集为（﹣1,3)，由｜2x﹣a｜＜6﹣a，可得a﹣6＜2x+a＜6﹣a，求得a ﹣3≤x≤3，故有a﹣3=﹣1，a=2．（2）在（1）的条件下,f（x）=｜2x﹣2｜+2，令g（x)=f（x）+f(﹣x)=｜2x﹣2|+｜2x+2|+4=，故g（x)的最小值为8，故使f(x）≤t﹣f（﹣x）有解的实数a的范围为[8,+∞）．22．已知椭圆C:+=1(a＞b＞0）的右焦点为F（1，0）,且点P（1,）在椭圆上；(1）求椭圆C的标准方程;(2)当点P（x，y）在椭圆C上运动时,点Q（,）在曲线S上运动，求曲线S的轨迹方程，并指出该曲线是什么图形；（3)过椭圆C1:+=1上异于其顶点的任意一点Q作曲线S的两条切线，切点分别为M，N(M，N不在坐标轴上），若直线MN在x轴,y轴的截距分别为m,n，试问：+是否为定值?若是，求出该定值，若不是，请说明理由．【考点】椭圆的简单性质．【分析】(1）由焦点坐标确定出c的值,根据椭圆的性质列出a与b的方程，再将P点坐标代入椭圆方程列出关于a与b的方程，联立求出a与b的值，确定出椭圆方程即可．（2）由已知得，Q(，）,(0≤θ＜2π）,由此能求出曲线S的轨迹方程，并能指出该曲线是什么图形．（3）由题意：确定出C1的方程,设点P(x1，y1)，M（x2，y2），N（x3，y3），根据M，N不在坐标轴上，得到直线PM与直线OM斜率乘积为﹣1，确定出直线PM的方程，同理可得直线PN的方程，进而确定出直线MN 方程,求出直线MN与x轴，y轴截距m与n，即可确定出所求式子的值为定值．【解答】解：(1）∵椭圆C：的右焦点为F(1，0），且点P（1，）在椭圆C上；∴，解得a=2,b=，∴椭圆C的标准方程为．（2)∵点P（x，y）在椭圆C：上运动时,点Q（，）在曲线S上运动，∴，∴Q（，）,（0≤θ＜2π），∴曲线S的轨迹方程为，曲线S是以原点为圆心,以为半径的圆．（3）由题意：C1:+=1，设点P（x1，y1），M（x2，y2)，N（x3,y3)，∵M,N不在坐标轴上,∴k PM=﹣=﹣,∴直线PM的方程为y﹣y2=﹣(x﹣x2)，化简得:x2x+y2y=,①，同理可得直线PN的方程为x3x+y3y=，②，把P点的坐标代入①、②得，∴直线MN的方程为x1x+y1y=，令y=0,得m=，令x=0得n=，∴x1=,y1=，又点P在椭圆C1上,∴()2+3（)2=4,则+=为定值．23．按照如下的规律构造数表：第一行是:2;第二行是：2+1，2+3：即3，5；第三行是：3+1,3+3，5+1，5+3,即：4，6，6，8,…（即从第二行起将上一行的数的每一项各加1写出,再各项再加3写出）,若第n行所有的项的和为a n；23 54 6 6 85 7 7 9 7 9 9 11…（1）求a3,a4，a5；(2）试写出a n+1与a n的递推关系，并据此求出数列{a n}的通项公式;（3）设S n=++…+（n∈N＊），求S n和S n 的值．【考点】数列递推式；数列的极限；归纳推理．【分析】（1）直接代入计算即可；（2)通过观察可知a n+1=2a n+（1+3）•2n﹣1，进而两边同时除以2n+1，整理可得数列{｝是首项、公差均为1的等差数列，计算即得结论;（3）通过（2）裂项可知=4［﹣]，进而并项相加即得结论．【解答】解:（1）依题意，a3=4+6+6+8=24，a4=5+7+7+9+7+9+9+11=64，a5=6+8+8+10+8+10+10+12+8+10+10+12+10+12+12 +14=160；（2）∵从第二行起将上一行的数的每一项各加1写出，再各项再加3写出，∴a n+1=2a n+（1+3）•2n﹣1,即a n+1=2a n+2n+1,两边同时除以2n+1，得：=+1,又∵=1，∴=n，即a n=n•2n；（3）由（2）可知==4［﹣］，∴S n=++…+=4[﹣+﹣+…+﹣]=4［﹣]=2﹣（n∈N＊），∴S n=[2﹣]=2．2016年6月20日。
上海市松江区2016届九年级4月模拟考试二模语文试题PDF含答案
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(2021年整理)2016年松江区中考数学二模试卷及答案
(完整版)2016年松江区中考数学二模试卷及答案编辑整理：尊敬的读者朋友们：这里是精品文档编辑中心，本文档内容是由我和我的同事精心编辑整理后发布的，发布之前我们对文中内容进行仔细校对，但是难免会有疏漏的地方，但是任然希望（(完整版)2016年松江区中考数学二模试卷及答案）的内容能够给您的工作和学习带来便利。
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(完整版）2016年松江区中考数学二模试卷及答案编辑整理:张嬗雒老师尊敬的读者朋友们：这里是精品文档编辑中心,本文档内容是由我和我的同事精心编辑整理后发布到文库，发布之前我们对文中内容进行仔细校对，但是难免会有疏漏的地方，但是我们任然希望 (完整版)2016年松江区中考数学二模试卷及答案这篇文档能够给您的工作和学习带来便利.同时我们也真诚的希望收到您的建议和反馈到下面的留言区，这将是我们进步的源泉，前进的动力。
本文可编辑可修改，如果觉得对您有帮助请下载收藏以便随时查阅，最后祝您生活愉快业绩进步，以下为 <(完整版）2016年松江区中考数学二模试卷及答案〉这篇文档的全部内容.2016年松江区初中毕业生学业模拟考试数学试卷（满分150分，考试时间100分钟） 2016。
4考生注意：1．本试卷含三个大题，共25题;2．答题时,考生务必按答题要求在答题纸规定的位置上作答，在草稿纸、本试卷上答题一律无效；3．除第一、二大题外，其余各题如无特别说明，都必须在答题纸的相应位置上写出证明或计算的主要步骤．一、选择题:（本大题共6题，每题4分，满分24分) 1．下列各数是无理数的是（ ）A ．722； B． C ．9 ； D ．16． 2．下列式子中，属于最简二次根式的是（ ）AB ．8；C ．9； D3．在平面直角坐标系中,直线1y x =-经过（ ）A ．第一、二、三象限;B ．第一、二、四象限；C ．第一、三、四象限；D ．第二、三、四象限．4．某班一个小组7名同学的体育测试成绩（满分30分)依次为：27，29，27，25,27，30， 25,这组数据的中位数和众数分别是（ ）A ．27，25；B ．25,27；C ．27,27 ；D ．27，30．5. 如图，已知四边形ABCD 是平行四边形,要使它成为菱形，那么需要添加的条件可以是( ）A . AC ⊥BD ;B . AB =AC ； C 。
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上海学而思教研部出品
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上海学而思教研部出品
2016 年松江区数学二模解析
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a ( 2a − 3)
13
y1 < y2
y = x2 + 6 x + 9
18
14
15
19.6 万件
16
3 10
17
289 (1 − x ) = 256
2
y2 + y − 3 = 0
5 2
【18 题详解】 CD = BC = 5 ， DF = 3 ， CF = 4 AE DE 3 3 = = ⇒ AE = AD FG 4 2 ∴ BE =
5 2
A
D
F
E
B
三、 解答题：
C
19. （学而思教研部） 原式 = 9 + 1 − 2 + 1 + 2 = 11 20. （学而思教研部）
∴ ∠AMN =° 90 ， AP = MQ ⇒ 6 − 2 x = 5 − x ∴x= 1 ⇒ FM = 5
B
P H
M F G
Q C
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上海学而思教研部出品
②当 M 在 FE 延长线上时， Ⅰ当 ∠AMN =° 90 时，
AP = MQ ⇒ 2 x − 6 = 5 − x ⇒ x = 11 11 5 ⇒ FM = 3 3
AP MQ 6 − 2x 5 − x = ⇒ = PM QN 3+ x y − 2x
A E D N
= y
5 x 2 − 14 x − 15 ( 0 ≤ x ≤ 1) 2x − 6 ⑶①当 M 在线段 FE 上时 ∠AMN > ∠AME > ∠AFE > 45° ，或 ∠AMN > ∠AEF > 45°
GM GM 1 = = ． MD BD − MD 3
A
H O G BM E D F C
23.（学而思教研部） = 90° ⑴ ∠CAD + ∠ACD ∠ECB + ∠B = 90° ∠ACD = ∠B ⇒ ∠CAD = ∠ECB ⑵ CE ⊥ BE , BD = DC ∴ ∠DEB = ∠B ∠FDC 同理 ∠DFC = ∠FDC 又 ∠B = ∴ △EBD ∽△DCF ∴
Ⅱ当 ∠ANM =° 90 时 MK = JN = 8 ,设 AJ = NK = a ， KI= JH= 6 − a FI 1 5+a 1 4 = ⇒ = ⇒a= MI 2 8+6−a 2 3
19 5 3 Ⅲ当 ∠MAN =° 90 时， ∠ANM > 45° ，舍去
∴ FM =
综上所述， FM = 5 或
EB BD = ⇒ BD 2 = FC ⋅ BE DC CF
E
A
F
B
D
C
24. （学而思教研部） ⑴y= − x2 + 4 x + 5 ⑵ P ( 2 , 9) 过 P 作 PH ⊥ x 轴，交 AC 于 H ，则 H ( 2 , 3) ， PH = 6
S△ ACP = S△ PCH + S△ APH = 1 1 ( xA − xC ) ⋅ PH = × 5 × 6 = 15 2 2
12 = x1 4= x2 6 x + 2 y = , ⇒ 0 = ( x − y )( x − 2 y ) = y1 4= y2 3
21. （学而思教研部） 9 y x + 32 ⑴= 5 9 x + 32 ⇒ x = 40 ⑵ 105 = 5
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