重庆市部分区2020-2021学年高一英语下学期期末联考试题
2020-2021学年北京市延庆区高一(下)期末英语试卷
2020-2021学年北京市延庆区高一（下）期末英语试卷1.（填空题，15分）AKoshiba had a legendary life.When he was a kid,he dreamed of being a soldier or musician,but his dream was broken when his right hand was damaged by polio（小儿麻痹症）.While in the hospital,he read Adlbert Einstein's books and（1）___ （become）interested in physics.He never made it to the top of his physics class in high school,but went on to study at the University of Tokyo,then the University of Rochester,（2）___ he earned his PhD. "There are things in the world you can achieve despite poor academic records." Koshiba said.What（3）___ （count）most is adopting an active attitude toward studying.BZoos play an important role in the world for conservation and education.They are（4）___ （particular） important for endangered species.Many animals are critically（5）___ danger and may go extinct in the wild,but in zoos,they are going wrong.Many others are already extinct in the wild and only animals（6）___ are kept in zoos survive.Even those critics of zoos often recognize that it is better to have species preserved somewhere than lose them altogether,as animals held in zoos（7）___ （protect） from serious threat.C（8）___ （wear）different colors can affect how you feel and how others react to you,so it is important to consider this when deciding（9）___ to wear in the morning.If you want people to take you seriously,put on navy blue or black.Blue would also be helpful for an interview or oral examination because it relaxes you and makes you feel calm.Red gets you noticed by everyone and make you feel energetic,（10）___ be careful,as it can raise your heart rate and not everyone want this effect.So think carefully before you leave your house.2.（问答题，12分）阅读下面的短文，用方框所给短语替换划线部分。
2020-2021学年重庆市主城区六校高一下学期期末联考数学试题(解析版)
2020-2021学年重庆市主城区六校高一下学期期末联考数学试题一、单选题1．设()1i 2i z -=（i 是虚数单位），则z =（ ） A ．2 B ．5 C ．2 D ．5【答案】A【分析】利用分数的除法化简复数z ，利用复数的模长公式可求得结果. 【详解】由已知可得()()()()2121111i i ii i i i i i 1z +===+=-+--+，因此，()22112z =-+=.故选：A.2．已知(1,1)a =，(,1)b x =，()a a b ⊥+，则x =（ ） A ．1- B ．1C ．3D ．3-【答案】D【分析】利用向量垂直的坐标表示有(1)1210x +⨯+⨯=，即可求x . 【详解】由题设，(1,2)a b x +=+，又()a a b ⊥+， 所以(1)12130x x +⨯+⨯=+=，即3x =-. 故选：D3．如图，在棱长为2的正方体1111ABCD A B C D -中，E 为AB 的中点，则直线1EB 与1A D 所成角的余弦值为（ ）A 15B 10C 10D 6【答案】B【分析】连接1B C 、CE ，证明出11//A D B C ，可得出直线1EB 与1A D 所成角为1CB E ∠或其补角，计算出1B CE △三边边长，利用余弦定理可求得结果. 【详解】连接1B C 、CE ，如下图所示：在正方体1111ABCD A B C D -中，11//A B CD 且11A B CD =，则四边形11A B CD 为平行四边形， 所以，11//B C A D ，故直线1EB 与1A D 所成角为1CB E ∠或其补角，由勾股定理可得221122B C BB BC =+=2215B E CE BE CB ==+由余弦定理可得2221111110cos 2B C B E CE CB E B C B E +-∠==⋅因此，直线1EB 与1A D 10故选：B.4．已知a →是单位向量，a →与b →的夹角是3π，且7a b →→+=， 则b →=（ ）A ．12B ．1C 2D ．2【答案】D【分析】把7a b →→+=的两边同时平方化简即得解.【详解】解：由题7a b →→+=得2221+27,12||||72a ab b b b →→→→→→+=∴+⨯⨯+=所以2||+||60,||2b b b →→→-=∴=或||3b →=-（舍去）. 故选：D5．口袋中装有编号为①、②的2个红球和编号为①、②、③、④、⑤的5个黑球，小球除颜色、编号外形状大小完全相同，现从中取出1个小球，记事件A 为“取到的小球的编号为②”，事件B 为“取到的小球是黑球”，则下列说法正确的是（ ） A ．A 与B 互斥B ．A 与B 对立C ．6()7P A B +=D ．6()7P AB =【答案】C【分析】利用互斥事件、对立事件的意义判断A ，B ；利用古典概率求出(),(),()P A P B P AB 判断C ，D 作答.【详解】依题意，取到的小球为黑球且编号为②，事件A 与B 同时发生，则A 与B 不互斥，也不对立，A ，B 都不正确； 由古典概率得：2()7P A =，5()7P B =，1()7P AB =，于是得6()()()()7P A B P A P B P AB +=+-=，C 正确，D 不正确. 故选：C6．一个骑行爱好者从A 地出发向西骑行了2km 到达B 地，然后再由B 地向北偏西60︒骑行23km 到达C 地，再从C 地向南偏西30骑行了5km 到达D 地，则A 地到D 地的直线距离是（ ） A ．8 B ．37C ．33D ．5【答案】B【分析】根据给定信息作出图形，再利用三角形正弦定理、余弦定理计算作答. 【详解】如图，在ABC 中，150ABC ∠=，2,23AB BC ==，依题意，90BCD ∠=，在ABC 中，由余弦定理得：2232cos 41283272AC AB BC AB BC ABC +-⋅∠++⨯ 由正弦定理得：sin sin 27AB ABC ACB AC ∠∠==，在ACD △中，cos cos(90)sin 27ACD ACB ACB ∠=+∠=-∠=，由余弦定理得：2212cos 282522753727AD AC CD AC CD ACD =+-⋅∠++⨯⨯⨯=所以A 地到D 地的直线距离是37故选：B7．在正三棱锥S ABC -中，23SA =，3AB =，顶点S 在底面ABC 内的射影为O ，点D 、E 分别是棱AC 、BC 的中点，则下列说法错误的是（ ）A ．3SO =B ．SA BC ⊥C ．//DE 平面SABD ．3tan 6SEO ∠=【答案】D【分析】利用勾股定理可判断A 选项；利用线面垂直的性质可判断B 选项；利用线面平行的判定定理可判断C 选项；求出tan SEO ∠的值，可判断D 选项. 【详解】如下图所示：由已知O 为等边ABC 的中心，且SO ⊥平面ABC ，AO ⊂平面ABC ，则SA AO ⊥，由正弦定理可得32sin3AB AO π=223SO SA AO =-=，A 对；延长AO ，则直线AO 过点E ，因为ABC 为等边三角形，E 为BC 的中点，则AE BC ⊥， 因为SO ⊥平面ABC ，BC ⊂平面ABC ，则SO BC ⊥，SO AE O =，则BC ⊥平面SAO ，SA ⊂平面SAO ，故SA BC ⊥，B 对；D 、E 分别为AC 、BC 的中点，则//DE AB ，DE ⊄平面SAB ，AB 平面SAB ，所以，//DE 平面SAB ，C 对；连接SE ，因为O 为等边ABC 的中心，则132OE AO =3SO =，SO ⊥平面ABC ，OE ⊂平面ABC ，SO OE ∴⊥，所以，tan 33SO SEO OE ∠===D 错. 故选：D.8．奔驰定理：已知O 是ABC 内的一点，若BOC 、AOC △、AOB 的面积分别记为1S 、2S 、3S ，则1230S OA S OB S OC ⋅+⋅+⋅=．“奔驰定理”是平面向量中一个非常优美的结论，这个定理对应的图形与“奔驰”轿车的logo 很相似，故形象地称其为“奔驰定理”.如图，已知O 是ABC 的垂心，且240OA OB OC ++=，则cos B =( )A ．23B ．13C ．23D ．33【答案】A【分析】由O 是垂心，可得tan tan tan 0A OA B OB C OC ⋅+⋅+⋅=，结合240OA OB OC ++=可得tan :tan :tan 1:2:4A B C =，根据三角形内角和为π，结合正切的和差角公式即可求解.【详解】∵O 是ABC 的垂心，延长CO 交AB 与点P ，∴()()1211:::tan :tan 22S S OC BP OC AP BP AP OP POB OP AOP ∠∠⎛⎫⎛⎫=⋅⋅⋅⋅== ⎪ ⎪⎝⎭⎝⎭()()tan :tan tan :tan tan :tan BOC AOC A B A B ∠∠ππ==--=， 同理可得13:tan :tan S S A C =，∴1S ：23:tan :tan :tan S S A B C =， 又1230S OA S OB S OC ⋅+⋅+⋅=， ∴tan tan tan 0A OA B OB C OC ⋅+⋅+⋅=， 又240OA OB OC +⋅+⋅=， ∴tan :tan :tan 1:2:4A B C =，不妨设tan tan 2tan 4A k B k C k ===，，，其中0k ≠， ∵()()tan tan tan tan tan 1tan tan B CA B C B C B Cπ+⎡⎤=-+=-+=-⎣⎦-，∴24124k k k k k +=--⋅，解得78k =78k =当78k =-tan 0tan 0tan 0A B C <<<，，，则、、A B C 都是钝角，则A B C π++>，矛盾.故k =tan 0B ===>，∴B 是锐角，sin 0cos 0B B >>，，于是22sin cos 2sin cos 1B B B B ⎧=⎪⎨⎪+=⎩，解得cos 3B =. 故选：A. 二、多选题9．若复数123i z =+，21i z =-，其中i 是虚数单位，则下列说法正确的是（ ） A ．1z 在复平面内对应的点位于第四象限 B ．若()1R z a a +∈是纯虚数，那么2a =- C ．121i z z ⋅=-+D ．若1z 、2z 在复平面内对应的向量分别为OA 、OB （O 为坐标原点），则17AB =【答案】ABD【分析】利用复数的几何意义可判断AD 选项；利用复数的概念可判断B 选项；利用复数的乘法可判断C 选项.【详解】对于A 选项，123i z =-，则1z 在复平面内对应的点位于第四象限，A 对； 对于B 选项，()()123i R z a a a +=++∈为纯虚数，则20a +=，可得2a =-，B 对； 对于C 选项，()()1223i 1i 5i z z ⋅=+⋅-=+，C 错；对于D 选项，由已知可得()2,3OA =，()1,1OB =-，则()1,4AB OB OA =-=--， 所以，(AB =-=D 对.故选：ABD.10．随着互联网的发展，网上购物几乎成为了人们日常生活中不可或缺的一部分，这也使得快递行业市场规模呈现出爆发式的增长.渝北区的陈先生计划在家所在的小区内开一家菜鸟驿站，为了确定驿站规模的大小，他统计了隔壁小区的菜鸟驿站和小兵驿站一周的日收件量（单位：件），得到折线图如下，则下列说法正确的是（ ）A ．菜鸟驿站一周的日收件量的极差小于小兵驿站一周的日收件量的极差B ．菜鸟驿站星期三的日收件量小于小兵驿站星期六的日收件量C ．菜鸟驿站日收件量的平均值大于小兵驿站的日收件量的平均值D ．菜鸟驿站和小兵驿站的日收件量的方差分别记为21s 、22s ，则2212s s >【答案】ABC【分析】利用极差的定义可判断A 选项；利用折线图可判断B 选项；利用平均数公式可判断C 选项；利用方差公式可判断D 选项.【详解】对于A 选项，菜鸟驿站一周的日收件量的极差为20013070-=， 小兵驿站一周的日收件量的极差为16040120-=，所以，菜鸟驿站一周的日收件量的极差小于小兵驿站一周的日收件量的极差，A 对； 对于B 选项，菜鸟驿站星期三的日收件量为130，小兵驿站星期六的日收件量为160， 所以，菜鸟驿站星期三的日收件量小于小兵驿站星期六的日收件量，B 对； 对于C 选项，菜鸟驿站日收件量的平均值为160200130150160190180117077++++++=，小兵驿站的日收件量的平均值为50120804012016012069077++++++=，所以，菜鸟驿站日收件量的平均值大于小兵驿站的日收件量的平均值，C 对； 对于D 选项，22222221111701170117011701170117021602001301501801907777777s ⎡⎤⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫=⨯-+-+-+-+-+-⎢⎥⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎢⎥⎣⎦2480049=， 222222216906906906906903120508016040777777s ⎡⎤⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫=⨯-+-+-+-+-⎢⎥ ⎪ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎢⎥⎣⎦7900049=，所以，2212s s <，D 错.故选：ABC.11．已知,m l 是两条不重合的直线，,,αβγ是三个不重合的平面，则下列结论正确的是（ ）A ．若//m l ，//αβ，m 与α相交，则l 与β也相交B ．若αβ⊥，βγ⊥，则αγ⊥C ．若//αβ，m 与α所成角等于l 与β所成角，则//m lD ．若m α⊥，αβ⊥，m β⊄，则//m β 【答案】AD【分析】对于A 根据空间线面位置关系推理即可；对于B 根据题意判断两平面位置关系即可；对于C 根据题意判断两直线位置关系即可；对于D 根据空间线面关系直接推理即可.【详解】对于A ，因为//m l ，m 与α相交，所以l 与α相交，又因为//αβ，所以l 与β相交，故A 正确；对于B ，若αβ⊥，βγ⊥，则αγ⊥或α与γ相交，故B 错误；对于C ，若//αβ，m 与α所成角等于l 与β所成角，则//m l 或m 与l 相交或m 与l 异面，故C 错误；对于D ，若m α⊥，αβ⊥，则//m β或m β⊄，又因为m β⊄，则//m β，故D 正确. 故选:AD12．在ABC 中，内角,,A B C 所对的边分别为,,a b c ，ABC 的面积为S ．下列与ABC 有关的结论，正确的是（ ）A ．若3A π=，a =b =4B π=或34π B ．若ABC 为锐角三角形，则sin cos A B >C ．若R 为ABC 的外接圆半径，则24sin sin sin S R A B C =D ．若6C π=，22a c bc -=，则ABC 是直角三角形【答案】BD【分析】根据解三角形知识，对选项逐一判断【详解】对于A ，由正弦定理得sin sin a b A B=，解得sin B a b >，故4B π=，故A 错误对于B ，ABC 为锐角三角形，可知2A B π+>，则22A B ππ>>-，故sin sin()cos 2A B B π>-=，故B 正确对于C ，由正弦定理得2sin sin sin a b c R A B C===，21sin 2sin sin sin 2S ab C R A B C ==故C 错误 对于D ，6C π=，22a c bc -=，由余弦定理得2223c a b ab =+-化简后得3b c a +=又由正弦定理化简得sin sin 3sin 3sin()6B C A B π+==+ 化简后得1sin()32B π+=，可得2B π=，故D 正确故选：BD 三、填空题13．某大学为提高数学系学生的数学素养，开设了“数学在19世纪的发展”、“拓扑学”、“数学思想史”三门选修课程，要求数学系每位同学在大学一年级时选修1门，则甲乙两名同学选到不同课程的概率是__________. 【答案】23【分析】分别计算甲乙两名同学任意选两门课程和选到不同课程的方法数，由古典概型的概率公式即得解【详解】由题意，甲乙两名同学任意选两门课程共有339⨯=种不同的情形 若选到不同课程有326⨯=种情况由古典概型的概率公式，甲乙两名同学选到不同课程的概率为6293=故答案为：2314．已知一个圆锥的轴截面(过圆锥轴的一个截面)是一个等腰直角三角形，且圆锥的底面半径为1，则该圆锥的侧面积为__________. 【答案】2π【分析】作出图像，根据结合关系求圆锥母线长度，根据圆锥侧面积公式即可计算.【详解】如图所示，△ABC 为轴截面，圆锥母线长度为22112AB + 故圆锥侧面积为122ππ⨯. 2π﹒15．将一个边长为4的正三角形ABC 沿其中线BD 折成一个直二面角，则所得三棱锥A BCD -的外接球的体积为_________.【答案】2053π 【分析】由垂直关系可知所求外接球即为以,,BD CD AD 为长宽高的长方体的外接球，根据长方体外接球半径为体对角线的一半可求得外接球半径，由球的体积公式得到最终结果.【详解】由题意得：4AB BC ==，2AD CD ==，BD AD ⊥，CD BD ⊥，即BD ⊥平面ADC ；二面角A BD C --为直二面角，AD CD ∴⊥，则三棱锥A BCD -的外接球即为以,,BD CD AD 为长宽高的长方体的外接球， 又1643BD =-=∴三棱锥A BCD -的外接球半径222114412522R AD CD BD =++++ ∴三棱锥A BCD -的外接球体积342053V R π==. 205. 四、双空题16．已知在ABC 中，90C =∠，4CA =，3CB =，D 为BC 的中点，2AE EB =，CE 交AD 于F ，则CE AD ⋅=_______；若BF xBC yBA =+，则x y +=_______.【答案】 73- 350.6【分析】以C 为坐标原点可建立平面直角坐标系，利用2AE EB =可求得E 点坐标，根据数量积的坐标运算可求得CE AD ⋅；设()00,F x y ，根据,,C F E 三点共线和,,A F D 三点共线可构造方程组求得F 点坐标，根据向量坐标运算可求得x y +的值.【详解】以C 为坐标原点，,CB CA 为,x y 轴，可建立如图所示平面直角坐标系，则()0,0C ，()3,0B ，()0,4A ，3,02D ⎛⎫⎪⎝⎭，设(),E m n ，2AE EB =，()(),423,m n m n ∴-=--，6242m m n n =-⎧∴⎨-=-⎩，解得：243m n =⎧⎪⎨=⎪⎩， 42,3E ⎛⎫∴ ⎪⎝⎭，42,3CE ⎛⎫∴= ⎪⎝⎭，3,42AD ⎛⎫=- ⎪⎝⎭，()34724233CE AD ∴⋅=⨯+⨯-=-；设()00,F x y ，则()00,CF x y =，()00,4AF x y =-， ,,C F E 三点共线，CF CE λ∴=，即00243x y λλ=⎧⎪⎨=⎪⎩；,,A F D 三点共线，AF AD μ∴=，即003244x y μμ⎧=⎪⎨⎪-=-⎩，003244x y μμ⎧=⎪∴⎨⎪=-⎩，3224443μλμλ⎧=⎪⎪∴⎨⎪-=⎪⎩，解得：3545λμ⎧=⎪⎪⎨⎪=⎪⎩，68,55F ⎛⎫∴ ⎪⎝⎭，98,55BF ⎛⎫∴=- ⎪⎝⎭，又()3,0BC =-，()3,4BA =-，BF xBC yBA =+，9335x y ∴--=-，35x y ∴+=.故答案为：73-；35.【点睛】方法点睛：本题考查几何中的平面向量线性运算和数量积运算的求解问题，解决此类问题的基本方法有两个：1.建立平面直角坐标系，利用平面向量的坐标运算进行求解；2.利用转化法，将所求向量向已知向量进行转化，根据向量线性运算法则和数量积的运算律来进行求解. 五、解答题17．甲、乙两名篮球运动员进行投篮比赛，甲投篮命中的概率为23，乙投篮命中的概率为34，在每次投篮中，甲和乙投篮是否命中相互没有影响. (1)求甲乙各投篮一次，恰好有1人命中的概率； (2)求甲乙各投篮一次，至少有1人命中的概率. 【答案】(1)512； (2)1112. 【分析】（1）利用独立事件乘法公式及互斥事件加法求恰好有1人命中的概率； （2）首先求出两人都没有命中的概率，利用对立事件的概率求法即可得至少有1人命中的概率.【详解】(1)记“甲投篮命中”为A 事件，“乙投篮命中”为B 事件, 则2()3P A =，3()4P B =， 由甲和乙投篮是否命中相互没有影响，所以A 与B 互为独立事件， 那么，恰好有1人命中的概率P 21135P(AB)P(AB)343412=+=⨯+⨯=. (2)由（1），两人都没有命中的概率111()3412P AB =⨯=，所以，至少有1人命中的概率1P P(AB 112)11=-=. 18．在△ABC 中，内角A 、B 、C 的对边分别为a 、b 、c ，已知__________.（在以下这三个条件中任选一个填入上方的横线上作为已知条件，并解答下面两个问题，如果选择多个条件解答，按第一个解答计分）①sin cos b A B =；②cos cos 2cos a C c A b B +=；③b =（R 是锐角△ABC 的外接圆半径）. (1)求B ；(2)若b =△ABC △ABC 的周长. 【答案】(1)条件选择见解析，3B π=；(2)3【分析】（1）根据所选的条件，由正弦定理的边角关系、和角正弦公式，结合三角形的内角性质求B ；（2）由三角形面积公式可得2ac =，再由余弦定理有223a c ac +-=，即可求a c +，进而可得△ABC 的周长.【详解】(1)选择①，由sin cos b A B =，则sin sin cos B A A B ，又sin 0A >，所以sin 3cos B B =，则tan 3B =，由0B π<<，故3B π=.选择②，由cos cos 2cos a C c A b B +=，则sin cos sin cos 2sin cos A C C A B B +=， 所以sin()sin 2sin cos A C B B B +==，又sin 0B >，则1cos 2B =， 由0B π<<，故3B π=.选择③，由3b R =（R 是锐角△ABC 的外接圆半径）， 由正弦定理知：2sin b R B =，则3sin 2B =，由02B π<<，故3B π=.(2)由（1），133222ABCSac =⨯⨯=，则2ac =， 由余弦定理知：222222cos33b ac ac a c ac π=+-=+-=，所以2()33a c ac +-=，故2()9a c +=，即3a c +=， 则△ABC 的周长为33a b c ++=+.19．重庆市某报社发起了建党100周年主题征文活动，报社收到了来自社会各界的大量文章，打算从众多文章中选取60篇文章以专栏形式在报纸上发表，其参赛作者年龄集中在[15，65]之间，根据统计结果，作出频率分布直方图如图：(1)求频率分布直方图中m 的值，并根据频率分布直方图，求这60位作者年龄的样本平均数x （同一组数据用该区间的中点值作代表）和80%分位数（结果保留一位小数）； (2)为了展示不同年龄作者心中的党的形象，报社按照分层抽样的方法，计划从这60篇文章中抽出20篇最佳文章，并邀请相应作者参加座谈会.若从年龄在[15，35）的作者中选出2人作为代表发言，求这2人的年龄都在[25，35）的概率. 【答案】(1)0.035m =，样本平均数41.5x =岁，80%分位数为51.7 (2)310【分析】（1）利用概率之和为1求m ；利用同一组数据用该区间的中点值乘以频率求平均数；利用总体百分位数的估计计算80%分位数； （2）通过列举法求出概率即可.【详解】(1)频率分布直方图知：10(0.010.0150.030.01)1m ⨯++++=，0.035m ∴=, 样本平均数200.1300.15400.35500.3600.141.5x =⨯+⨯+⨯+⨯+⨯=岁， 参赛作者年龄的第80%分位数为80%60%2045104551.790%60%3-+⨯=+≈-(2)按分层抽样抽出的20篇最佳文章的作者，年龄落在[15,25）的有2人， 记为12,a a ，年龄落在[25,35）的有3人，记为123,,b b b ， 现从这5个人中选出2人作为代表发言，共有12111213212223121323,,,,,,,,,a a a b a b a b a b a b a b b b b b b b 10种情况，选出的2人年龄落在[25,35）的有121323,,b b b b b b 3种情况， 所以所求概率310P =. 20．如图所示，图（1）中的ABC 中，120ABC ∠=，2AB BC ==，D 是AC 的中点，现将ABD △沿BD 折起，使点A 到达点P 的位置，且满足PC PD =，得到如图（2）所示的三棱锥P BCD -，点O 、F 分别是棱CD 、PD 的中点，E 、G 分别在棱BD 、BC 上，满足14BE BD =， 14BG BC =.(1)求证：//EF 平面POG ；(2)求直线EF 与平面BCD 所成角的正弦值. 【答案】(1)证明见解析 21【分析】（1）构造平行四边形，利用线线平行推线面平行（2）借助（1）的结论，将问题转化为求与EF 平行的直线与平面BCD 所成的角【详解】(1)证明：在ABC ∆中，120,2ABC AB BC ∠===，1BD ∴=，23AC =D 是AC 的中点,3,AD CD BD AC ∴==⊥,在三棱锥P BCD -中，取PO 的中点H ,连接FH , O F 、分别是棱CD PD 、的中点，1//,2FH OD FH OD ∴=,连接,GH EF ,E G 、满足14BE BD =, 14BG BC = 11//,,42EG CD EG CD OD ∴==//,EG FH EG FH ∴=∴四边形FHGE 是平行四边形，//EF GH ∴EF ⊄平面POG ,GH ⊂平面POG//EF ∴平面POG(2)翻折前BD AC ⊥，翻折后，,,,BD AD BD CD AD CD D ⊥⊥=BD ∴⊥平面PCD ,PO ⊂平面PCD ,BD PO ∴⊥,PC PD CD ==，O 是中点,PO CD CD BD D ∴⊥=PO ∴⊥平面BCDHG ∴与平面BCD 的所成角为,HGO ∠//EF GHEF ∴与平面BCD 的所成角等于GH 与平面BCD 的所成角，221321,24HO PO GH EF DF DE ====+= 21sin HGO ∴∠=21．如图，在ABC 中，已知120BAC ∠=︒，24AB AC ==，，点D 在BC 上，且2BD DC =，点E 是AC 的中点，连接AD ，BE 相交于O 点.(1)求线段AD ，BE 的长； (2)求EOD ∠的余弦值. 【答案】(1)213AD =23BE =339【分析】（1）由22212BE BE AC AB ⎛⎫==- ⎪⎝⎭，22221()33AD AD AC AB ==+，根据向量数量积的运算即可求解；（2）由AD 与BE 的夹角即为EOD ∠，利用向量的夹角公式即可求解. 【详解】(1)解：由题意，2,22ACAB AE ===，120BAC ∠=︒， 又12BE AE AB AC AB =-=-， 所以2222222111cos 244BE BE AC AB AC AC AB AB AC AC AB BAC AB⎛⎫==-=-⋅+=-⋅∠+ ⎪⎝⎭12=，23BE ∴=3BE =22()33AD AB BD AB BC AB AC AB =+=+=+-=2133AC AB +22221()33AD AD AC AB ∴==+2222421142115222cos 933993399C BA AC AC AB AB A A AB C C AB =+⨯⨯⨯⋅+=+⨯⨯⨯⋅+=∠， 2133AD ∴=，即2133AD = (2)解：12BE AE AB AC AB =-=-， 211()()332AD BE AC AB AC AB ∴⋅=+-=22111323AC AC AB AB -⋅-=()221114426323⨯-⨯--⨯=，AD 与BE 的夹角即为EOD ∠， 6339cos 26213233AD BE EOD AD BE⋅∴∠===⨯. 22．如图，四棱柱1111ABCD A B C D -的底面ABCD 为菱形，60ABC ∠=︒，其中侧面11B BCC 为矩形，E F 、分别为11,BC B C 的中点，P 在线段AE 上，且满足:1:2AP PE =，过11B C 和点P 的平面交AB 于G ，交DC 于H .(1)证明：11//B C GH ； (2)证明：GH ⊥平面AEF ； (3)若12AB PF ==，且3EPF π∠=，求四棱锥11E GHC B -的体积.【答案】(1)证明见解析 (2)证明见解析 (3)288【分析】（1）由平面ABCD //平面1111D C B A 得到两条交线平行即可； （2）通过AE BC ⊥和EF BC ⊥证明BC ⊥面AEF 即可证明GH ⊥平面AEF ； （3）作出四棱锥的高，求出底面面积，利用体积公式计算即可. 【详解】(1)四棱柱1111ABCD A B C D -中，平面ABCD //平面1111D C B A ，设过11B C 和P 的平面为α，由题可知面ABCD GH α=，面111111A B C D B C α=，11B C ∴ //GH(2)由（1）得GH //11B C //BC ，连接AC ,ABCD 为菱形，60ABC ∠=,ABC ∴为等边三角形，E 为BC 中点，AE BC ∴⊥，又11B BCC 为矩形，1B B BC ∴⊥， ,E F 分别为1B B BC ，中点，所以EF //1B B ，EF BC ∴⊥，AE EF E ⋂=，BC ∴⊥面AEF ，GH ∴⊥面AEF(3)GH ⊂面11GHC B ，由（2）知GH ⊥面AEF ，∴面11GHC B ⊥面AEF ，面11GHC B 面AEF PF =，过E 做EM PF ⊥交PF 于M ，EM ∴⊥面11GHC B ， 在等边ABC 中，12AB =，3AE ∴=:1:2AP PE =,2433PE AE ∴==∴在Rt EMP 中， 3EPF π∠=，sin63EM PE π∴==，由（2）得BC ⊥面AEF ，PE ⊂面AEF ,BC PF ，∴四边形的高为12PF =，111212144GHC B S =⨯=，11161442883E GHC B V -=⨯⨯=.。
2020-2021学年新疆新和县高一下学期期末考试英语试题(解析版)
2020-2021学年新疆新和县高一下学期期末考试英语试题一、阅读理解（每题2分，共30分）APart-time Cleaning HelpAre you looking for a vacation job? Can you clean the house and cook? Then, I need you. The work is boring, but the pay is good. I need you from 2:00--5:00p.m., Monday to Saturday. Please come to the cleaning center or call Mrs. Johnson at 544-9968.A Fitness Camp for Overweight KidsAre you too fat? Can you run as fast as your classmates? Have you failed your P.E. examination?Our fitness camp can help you lose weight and get fit again. Come and join us! Please call Nathan at 475-2300.Next Wave Music StoreAfter 10 years of teaching the piano, David Smith has made his first CD! Come and meet him this weekend. Special presents for the first 50 people.Time: Sat. 7:00p.m. Call Marsha at 873-2059.1. ________ needs a cleaner.A. Mrs. JohnsonB. Marsha and NathanC. NathanD. Marsha2. In the fitness camp, you can________.A. clean the houseB. make a CDC. lose weightD. meet David Smith3. If you're the tenth to come to________ you can get a special present.A. the cleaning centerB. Next Fashion StoreC. the fitness campD. Next Wave Music Store【答案】1. A 2. C 3. D【解析】【分析】这是一篇应用文。
2020-2021学年广东省佛山市南海区高一下学期期末考试(南海统考)英语试题
2020-2021学年第二学期期末考试高一英语试题2021.7本试卷共10页，满分130分，考试时间120分钟。
【第一部分听说考试（已另外安排）】第二部分综合运用（共三节，满分45分）第一节课外阅读（共10小题：每小题2分，满分20分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项。
AThere is nothing like a hug from grandma.But that special gift has become much less common—and thus more valuable—over the last12months.Out of concern for the safety of their loved ones.many people have been waiting months and months for that priceless moment when they will get to see their grandparents again.For one little boy in Rose City,that reunion(团聚)finally happened!Kelsey recently posted a video of her3-year-old son John having a surprise gathering with his grandma,Nana Jane.Because of the epidemic(流行病),the pair hadn’t seen each other since Christmas2019—17long months ago.As Kelsey told a newspaper,"All he ever said was,'I wanna go to Nanas.I miss my Nan.’And it just breaks our heart.”The turning point came when Jane finally received her second dose of the COVID-19(疫苗)!Kelsey and Jane immediately got to planning.and Kelsey decided to take John playground after day care...where Nana Jane would be waiting!In a video,we can hear Kelsey say,"Go see her!"Then little John begins running toward his grandma before she throws her arms around him."I cry every time I see it,I do,"Jane said.It's enough to leave the audience in tears,too—not only out of joy for John and Nana Jane,but also out of excitement for the day when we will experience the same kind of reunion with our loved ones!1.What makes family reunions more valuable?A.Concerns about the safety of the vaccine.B.The slim chance of seeing each other again.C.Grandparents being easy targets for diseases.D.The fear of losing contact with family members.2.What made it possible for John and Jane to meet again?A Media reports of their story. B.Janes second dose of the vaccine.C.Kelseys video posted on the Internet.D.Drop in the number of epidemic cases.3.What can we infer about the audience according to the last paragraph?A.They have the same experience as John.B.The feelings of John are beyond their belief.C.They are expecting to see their families again.D.The separation of John and Jane breaks their heart.BEverywhere you look,people are looking at screens,and then half an hour has gone by before they realize it.Researchers at the University of Washington conducted in-depth interviews to learn why we can’t stop checking our phones.They found a series of reasons,common across age groups,that start and end habitual smartphone use. Hiniker and her team interviewed three groups of smartphone users:high school students,college students and adults who have graduated from college.The39interviewees were smartphone users in the Seattle area between the ages of 14and64.In general,interviewees had four common reasons for using their phones:■During unoccupied moments,like waiting for a friend to show up.■Before or during boring and repetitive tasks.■When in socially awkward situations.■When they are expecting a message.The group also had common reasons that ended their phone use:■Meeting competing needs from the real world,like meeting up with a friend or needing to drive somewhere.■Realizing that they had been on their phones for half an hour.■Coming across content they’d already seen.The team was surprised to find that the reasons were the same across age groups."This doesn't mean that teens use their phones the same way adults do.But I think this desire to turn back to your phone plays out the same way across all these groups.The high school students would say‘Anytime I have a dead moment,if I have one minute between classes I pull out my phone.'And the adults would say'Anytime I have one dead moment,if I have one minute between seeing patients at work.I pull out my phone.’”4.When is a man most likely to use his smartphone?A.When he is talking with a friend.B.When he is late for a friend’s party.C.When he is given a challenging task.D.When he is taking the lift with a stranger.5.What did the research find about the smartphone users of different ages?A.They liked to read the same thing again.B.They used smartphones in the same way.C.They used smartphones nonstop for a long time.D.They shared the same reasons for smartphone use.6.What is the best title for the passage?A.Influence of Smartphone Addiction.B.Ways to Stop Smartphone Addiction.C Difference in Smartphone Use across Age Groups. D.Research on the Strong Desire for Smartphone Use.CMichael Evans was standing in line waiting to pay his taxes(税),when he heard a disturbing sound ahead of him. An elderly woman at the window was crying and so was the cashier(出纳员)helping her.Then Evans learned why: the woman was informed she would lose her house if she couldn’t pay the tax.He also heard the woman tell the cashier that her daughter had recently died.Evans,a businessman who had just buried his father,couldn't stand the idea of this woman losing her home right after losing her child.He approached the window and said to the cashier,"I'll pay her taxes.”The two women were stunned.Their hopelessness turned to disbelief.Evans promised to go straight to the bank and come right back withthe money.And he did.But when he returned to the office,he asked someone else waiting in line to hand the check to the cashier.Evans was trying to slip away quietly.Obviously,he didn't want the attention.Of course,attention found him.It's not every day that someone pays a stranger’s high tax bill That said,Evans often finds himself on the giving end of charitable situations,though for years he went unrecognized for it.He is the president of a company which owns a variety of businesses,from restaurants to a mobile restroom company,most located in the inner city of Detroit.In2015,when he saw a story on the news about a local boy with a severe disease, Evans held an event to raise money at his restaurant to help pay for the boy's medical fee.He also gave away all the money the restaurant made that day to the boy's family.Why does Evans give so much to strangers?"Doing things with your money is better than putting it in the banks, "he says.As for paying for the elderly woman's taxes,he says he did it"for no other reason but to make sure the lady was in her house.”7.Why did Evans pay the woman’s tax?A.He felt pity for the woman.B.He was moved by the cashier.C.He didn't want the disturbance.D.He felt sorry for the cashier's mistake.8.What does the underlined word"stunned"in paragraph2mean?A.Satisfied.B.Thankful.C.Shocked.D.Thoughtful.9.What can we infer from paragraph4about Michael Evans?A.He is used to doing good deeds.B.He is well known for his charity work.C.He is president of a charity organization.D He is an important figure in social reforms.10.Which of the following words can best describe Evans?A.Kind and Brave.B.Generous and caring.C.creative and successful.D.Energetic and warm-hearted.第二节课内阅读（共5小题；每小题2分，满分10分）根据短文内容，把短文后的选项填入合适的空白处。
2020-2021学年河南省商开大联考高一下学期期末考试英语试题
商开大联考2020~2021学年下学期期末考试高一英语考生注意:1.本试卷分选择题和非选择题两部分。
满分150分,考试时间120分钟。
2.答题前,考生务必用直径0.5毫米黑色墨水签字笔将密封线内项目填写清楚。
3.考生作答时,请将答案答在答题卡上。
选择题每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;非选择题请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区域书写的答案无效,在试题卷、草稿纸上作答无效。
4.本卷命题范围:北师大版必修3~必修4。
第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.When will the concert begin?A.At7:30.B.At8:00.C.At8:30.2.What will the woman probably do on New Year's Day?A.Attend a party.B.See a house.C.Call the man,3.What's the relationship between the speakers?A.Partners.B.A couple.C.Neighbors.4.Where does the conversation most probably take place?A.At a lecture.B.At a wedding.C.At a meeting.5.What did the woman buy yesterday?A.Lots of food.B.A dress.C.Some books.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
重庆市七校2020-2021学年高一下学期期末联考语文试题+Word版含答案
2020—2021学年下期高2023级七校期末语文试题满分150分，考试时间150分钟。
注意事项：1．答题前，务必将自己的姓名、准考证号等填写在答题卷规定的位置上。
2．答选择题时，必须使用2B铅笔将答题卷上对应题目的答案标号涂黑。
3．答非选择题时，必须使用0.5毫米黑色签字笔，将答案书写在答题卷规定的位置上。
4．考试结束后，将答题卷交回。
一、现代文阅读（35分）（一）现代文阅读I(本题共5小题，19分)阅读下面的文字，完成1-5题。
材料一：据说古希腊的亚历山大大帝在东宫的时候，每听到他父王在外国打胜仗的消息，就要发愁，生怕全世界都给他老子征服了，自己这样一位英雄将来没有用武之地。
紧跟着伟大的诗歌创作时代而起来的诗人准有类似的感想。
当然，诗歌的世界是无边无际的，不过，前人占领的疆域愈广，继承者要开拓版图，就得配备更大的人力物力，出征得愈加辽远，否则他至多是个守成之主，不能算光大前业之君。
所以，前代诗歌的造诣不但是传给后人的产业，而在某种意义上也可以说向后人挑衅，挑他们来比赛，试试他们能不能后来居上、打破记录，或者异曲同工、别开生面。
假如后人没出息，接受不了这种挑衅，那么这笔遗产很容易贻祸子孙，养成了贪吃懒做的膏粱纨绔。
有唐诗作榜样是宋人的大幸，也是宋人的大不幸。
看了这个好榜样，宋代诗人就学了乖，会在技巧和语言方面精益求精；同时，有了这个好榜样，他们也偷起懒来，放纵了摹仿和依赖的惰性。
瞧不起宋诗的明人说它学唐诗而不像唐诗，这句话并不错，只是他们不懂这一点不像之处恰恰就是宋诗的创造性和价值所在。
明人学唐诗是学得来维肖而不维妙，像唐诗而又不是唐诗，缺乏个性，没有新意，因此博得“瞎盛唐诗”“赝古”“优孟衣冠”等等绰号。
宋人能够把唐人修筑的道路延长了，疏凿的河流加深了，可是不曾冒险开荒，没有去发现新天地。
用宋代文学批评的术语来说，凭借了唐诗，宋代作者在诗歌里“小结裹”方面有了很多发明和成功的尝试，譬如某一个意思写得比唐人透彻，某一个字眼或句法从唐人那里来而比他们工稳，然而在“大判断”或者艺术的整个方向上没有什么特著的转变，风格和意境虽不寄生在杜甫、韩愈、白居易或贾岛、姚合等人的身上，总多多少少落在他们的势力圈里。
山东省青岛(胶州市、黄岛区、平度区、城阳区)2020-2021学年高一下学期期末考试英语试题
2020—2021学年度第二学期第二学段模块检测高一英语试题（考试时间：120分钟试卷满分：150分）注意事项：1. 答卷前，考生务必将自己的姓名、考生号等填写在答题卡上。
2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
回答非选择题时，将答案写在答题卡上，写在本试卷上无效。
3.考试结束后，将答题卡交回。
第一部分：听力（共两节，满分30分）做题时，先将答案划在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What will the woman do this afternoon?A. Go to the park.B. Take pictures.C. Have a class.2. What is the main reason for the woman to buy a beach chair?A. She hates to get burned.B. She wants something to sit on.C. She needs to put her towels on it.3. What does the woman suggest the man do?A. Send a card.B. Use the Internet.C. Make a phone call.4. How much money will the man probably lend to the woman?A. $400.B. $300.C. $100.5. Why does the woman want fewer peppers in her food today?A. She feels too hot.B. She has a health problem.C. She doesn’t like spicy food.第二节: (共15小题：每小题1.5分，满分22.5分)听下面5段对话或独白。
2020-2021学年重庆市部分学校高一下学期期末联合检测数学试卷及答案
2020-2021学年重庆市部分学校高一下学期期末联合检测数学试题数学测试卷共4页.满分150分.考试时间120分钟. 注意事项：1. 答卷前，考生务必将自己的姓名、准考证号填写在答题卡上.2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑.如需改动，用橡皮擦干净后，再选涂其他答案标号.回答非选择题时，将答案写在答题卡上，写在本试卷上无效.3. 考试结束后，将本试卷和答题卡一并交回.一、选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的.1. 已知向量()2,1a =-，()4,b m =-，//a b ，则实数m =（ ） A. -4 B. -2 C. 2 D. 42. 已知复数z 满足210z iz +=，则z =（ ）A. 2i +B. 2i -C. 42i +D. 42i -3. 正方体1111ABCD A BC D -的六个面的对角线中与直线1AC 垂直的有（ ） A. 0条B. 3条C. 6条D. 12条4. 甲、乙、丙三位同学在学校举办的建党100周年党史知识竞赛活动中获得优胜奖，颁奖时甲、乙、丙三位同学随机站成一排，则甲乙两人恰好相邻而站的概率为（ ） A.16B.13C.12D.235. 为迎接北京2022年冬奥会，推广冰上运动，某班体育老师调查了全班同学对冰上运动项目的了解程度，调查结果分为三个等级：“不了解”“基本了解”和“非常了解”，其中等级为“基本了解”的人数比等级为“不了解”的人数多8人.接下来，该体育老师采用分层抽样的方法从全班同学中抽取部分同学参加冰壶运动的体验活动，参加体验活动的同学中对冰上运动项目“不了解”的有1人，“基本了解”的有3人，“非常了解”的有6人，那么该班全体同学中对冰上运动项目“非常了解”的人数为（ ） A. 10人B. 12人C. 18人D. 24人6. 已知运动员甲每次射击击中目标的概率为12，运动员乙每次射击击中目标的概率为13，若两人各射击一次，且两人是否击中目标相互独立，则恰有一人击中目标的概率是（ ） A.16B.13 C.12D.237. 已知四面体P ABC -中，PA ⊥平面ABC ，2PA AB ==，BC =，且3tan 2ABC ∠=，则四面体P ABC -的外接球的表面积为（ ） A. 15πB. 17πC. 18πD. 20π8. 在四边形ABCD 中，//AB CD ，120BAD ∠=︒，4AB =，2AD =，3CD =，E ，F 分别为BC ，CD 的中点，则FE AC ⋅=（ ） A. 92-B. -3C.52D.72二、选择题：本题共4小题，每小题5分，共20分.在每小题给出的选项中，有多项符合题目要求.全部选对的得5分，部分选对的得2分，有选错的得0分. 9. 下列说法正确的是（ ）A. 有两个面互相平行，其余各面都是平行四边形的几何体一定是棱柱B. 棱锥的侧面一定都是三角形C. 棱台各侧棱所在直线必交于一点D. 有两个面为矩形且相互平行，其余四个面均为等腰梯形的几何体一定是四棱台 10. 关于平面非零向量a ，b ，c ，下列说法错误的是（ ） A. 若0a b ⋅>，则a 与b 的夹角为锐角 B. 若()()a b c a b c ⋅⋅=⋅⋅，则//a c C. 若a b a c +>+，则b c >D. 若230a b c ++=，则()()//a c b c ++11. 已知非零复数1z ，2z 满足12z z R ∈，则（ ） A. 12z z =B. 12z z R ⋅∈C.12z R z ∈ D. 12z z R +∈12. 在长方体1111ABCD A BC D -中，2AB =，11AD AA ==，E 为棱AB 上的动点（不包含端点），则（ ）A. 四面体1E DCD -的体积恒为13B. 直线1D E 与平面11BCC B 所成角一定小于3πC. 存在点E 使得1//D E 平面11A BCD. 存在点E 使得11D E DB ⊥三、填空题：本题共4小题，每小题5分，共20分.13. 某工厂对一批产品的净重（单位：克）进行抽样调查得到样本数据：230，235，237，238，238，239，240，242，244，246，据此估计这批产品的第80百分位数为___________.14. 已知ABC △的面积为3，且6AB BC ⋅=，则B =__________.15. 如图，'''O A B △是OAB △在斜二测画法下的直观图，其中''''2O A O B ==，且''''O A O B ⊥，则OAB △的面积为___________.16. 在等边三角形ABC 中，2AD DB =，2DE EC =，P 为线段AE 上一点，且BP CA CD λ=+，则实数λ的值为___________.四、解答题：本题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤. 17. 已知2a =，3b =，()()2219a b a b +⋅-=-. （1）求向量a 与b 的夹角； （2）求2a b +.18. 某课外活动小组有三项不同的任务需要完成，已知每项任务均只分配给组员甲和组员乙中的一人，且每项任务的分配相互独立，根据两人的学习经历和个人能力知，这三项任务分配给组员甲的概率分别为12，13，34. （1）求组员甲至少分配到一项任务的概率；（2）设甲、乙两人分配到的任务数分别为x 项和y 项，求()P x y >.19. 在ABC △中，角A ，B ，C 的对边分别为a ，b ，c ，222222tan a b c B a c b--=+-. （1）求A ；（2）若34a =__________，求ABC △的周长.在①ABC △的面积为3，②417cos 17B =答.注：如果选择多个条件分别解答，按第一个解答计分.20. 在正方体1111ABCD A BC D -中，M ，N ，P 分别为11A D ，DC ，1CC 的中点.（1）求证：1//AC 平面DPB ； （2）求证：MN ⊥平面DPB .21. 如图，正四棱锥P ABCD -中，2AB PA ==，E 是棱AP 上靠近点P 的三等分点，F 是棱PC 的中点.（1）求异面直线BF 与PD 所成角的余弦值； （2）求四面体P EBF -的体积.22. 自疫情爆发以来，由于党和国家对抗疫工作的高度重视，在人民群众的不懈努力下，我国抗疫工作取得阶段性成功，国家经济很快得到复苏.在餐饮业恢复营业后，某快餐店统计了近100天内每日接待的顾客人数，将前50天的数据进行整理得到频率分布表和频率分布直方图如下. 组别 分组频数 频率 第1组 [)20,30 40.08 第2组 [)30,40a第3组 [)40,50 20 b第4组 [)50,600.32 第5组 [)60,704 0.08 合计501.00（1）求a ，b ，c 的值，并估计该快餐店在前50天内每日接待的顾客人数的平均数；（2）已知该快餐店在前50天内每日接待的顾客人数的方差为104，在后50天内每日接待的顾客人数的平均数为51、方差为100，估计这家快餐店这100天内每日接待的顾客人数的平均数和方差.重庆市部分学校2021年春高一（下）期末联合检测试卷 数学参考答案一、选择题 1-5：CDCDD6-8：CBD第8题提示：以A 为原点建立如图所示的坐标系， 则()2,3C ，()4,0B ，()1,3D -，33,2E ⎛⎫ ⎪ ⎪⎝⎭，1,32F ⎛⎫ ⎪⎝⎭， 53,22FE ⎛⎫=- ⎪ ⎪⎝⎭，()2,3AC =，72FE AC ⋅=，故D 正确.二、选择题9. BC 10. AC 11. BC 12. AB第9题提示：如左图，将两个平行六面体合在一起，可知A 错误；如右图，该几何体的上下底面是两个全等的矩形，两矩形平行，且上面矩形的长与下面矩形的宽对应平行，则四个侧面均为等腰梯形，但四条侧棱并不交于同一点，故D 错误.第10题提示：当a ，b 同向时，夹角为0，但0a b ⋅>，故A 错误；当0a b ⋅≠时，0b c ⋅≠，()//a b c c ⋅⋅，()//a b c a ⋅⋅，故//a c ，当0a b ⋅=时，0b c ⋅=，则a b ⊥，c b ⊥，故//a c ，故B 正确；若b a =，c a =-，则a b a c +>+，但b c =，故C 错误；由230a b c ++=可知()2a c b c +=-+，故()()//a c b c ++，即D 正确.第11题提示：取12z z i ==，则121z z R =-∈，但12z z ≠，122z z i R +=∉，故A 、D 均不正确； 设1z a bi =+，2z c di =+，则12()z z ac bd ad bc i =-++，由题知0ad bc +=， 故12()()()z z a bi c di ac bd ad bc i ac bd R ⋅=-⋅-=--+=-∈，故B 正确；112222z z z R z z =∈，故C 正确. 第12题提示：由//AB 平面1DCD 知，点E 到平面1DD C 的距离即为 直线AB 到平面1DD C 的距离AD ， 故111133E DD C DD C V S AD -=⋅=△，A 正确； ∵平面11//BCC B 平面11ADD A ，∴1D E 与平面11BCC B 所成角即为1D E 与平面11ADD A 所成角1ED A ∠，1tan 2)2ED A ∠=，∴13ED A π∠<，B 正确；∵1//D A BC ，∴1//D A 平面11A BC ，若1//D E 平面11A BC ，则平面1//D AE 平面11A BC ，则//AB 平面11A BC ，显然矛盾，故C 错误； ∵11D A A D ⊥，111D A A B ⊥，∴1D A ⊥平面11A B D ，∴11D A DB ⊥，若11D E DB ⊥，则1DB ⊥平面1D AE ，则1DB AB ⊥，即1DB DC ⊥，显然矛盾，故D 错误.三、填空题 13. 243 14.34π 15. 42 16. 43- 第15题提示：过'B 分别作'y ，'x 轴的平行线，且交'x ，'y 轴于点M ，N ， ∴'22O N =，'2O M =，∴在原坐标系xOy 中，点()2,42B -， 点()2,0A ，∴42OAB S =△.第16题提示：以A 为原点建立如图所示坐标系， 不妨设()6,0B ，由题知()4,0D ，(3,33C ，10,233E ⎛⎝， 由P 在AE 上，设33P m ⎛⎫ ⎪ ⎪⎝⎭，33BP m ⎛⎫=- ⎪ ⎪⎝⎭， (3,33CA =--，(1,33CD =-，∵BP CA CD λ=+，∴63m λ-=-，3333(1)5m λ=-+， 解得43λ=-.四、解答题17. 解：（1）由题知2223219a a b b -⋅-=-，2223cos 219a a b b θ-⋅-=-， 即818cos 1819θ--=-，1cos 2θ=，3πθ=； （2）222222444cos 4523a b a a b b a a b b π+=+⋅+=+⋅+=，∴252213a b +==.18. 解：（1）记事件A 为甲一项任务都没有被分配，则1131()11123412P A ⎛⎫⎛⎫⎛⎫=-⋅-⋅-= ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭， ∴组员甲至少分配到一项任务的概率为111()12P A -=； （2）满足x y >即3x =，0y =或2x =，1y =，三项任务的具体分配对象依次为：甲甲甲，甲甲乙，甲乙甲，乙甲甲，故所求概率11311112311313()23423423423424P x y >=⋅⋅+⋅⋅+⋅⋅+⋅⋅=. 19. 解：（1）由余弦定理2222cos b c a bc A +-=，2222cos a c b ac B +-=，∴2cos tan 2cos bc AB ac B-=，sin cos 0a B b A +=，故sin sin sin cos 0A B B A +=，∴tan 1A =-，34A π=；（2）由余弦定理222342a b c bc ==+（*） 若选①，1sin 32S bc A ==，62bc =*）式得2222b c +=， ∴222322b c b c bc +=++=，∴周长为23234+若选②，17sin B =sin sin b a B A =得2b =， 代入（*）式得32c =23234+20. 解：（1）设ACBD O =，则AC 中点为O ，∴1//OP AC ，又OP ⊆平面DPB ，∴1//AC 平面DPB ；（2）连接1D N ，在正方形11DCC D 中，∵N ，P 为DC ，1CC 中点. ∴1D N DP ⊥，又1MD ⊥平面11DCC D ，∴1MD DP ⊥， ∴DP ⊥平面1MD N ，∴DP MN ⊥，过M 作1MM AD ⊥于1M ，连接1M N ，则1MM ⊥平面ABCD ， 且1M 为AD 中点，∴1MM DB ⊥，1M N DB ⊥， ∴DB ⊥平面1MM N ，∴DB MN ⊥，∴MN ⊥平面DPB .21. 解：（1）取DC 中点M ，连接MF ，BM ，则//MF PD ， 故异面直线BF 与PD 所成角为MFB ∠或其补角，在MFB △中，1MF =，5MB PCB △中，3BF =∴2223cos 2623MF FB MB MFB MF FB +-∠===-⋅， ∴异面直线BF 与PD 3（2）连接AC ，取AC 中点O ，连接PO ，则PO ⊥底面ABCD ，∵222PA PO OA =+，∴2PO =14233P ABCD ABCD V S PO -=⋅=， 由题知11111sin sin 22326PEF PAC S PE PF APC PA PC APC S =⋅∠=⋅⋅∠=△△， ∴1126129B PEF B PAC P ABCD V V V ---===.22. 解：（1）由表可知第4组的频数为500.3216⨯=，∴504201646a =----=，200.4050b ==， 第2组的频率为60.1250=，0.120.01210c ==， 前50天内每日接待的顾客人数的平均数为：250.08350.12450.40550.32650.0847⨯+⨯+⨯+⨯+⨯=；（2）设前50天接待的顾客人数分别为1x ，2x ，…，50x ，后50天接待的顾客人数分别为1y ，2y ，…，50y ，则由（1）知前50天的平均数47x =，方差2104x s =，后50天的平均数51y =，方差2100y s =，故这100天的平均数为4750515049100⨯+⨯=，()()50502222215011112505050xi i i i s x x x x x x x x ==⎡⎤⎡⎤=-++-=-+⎢⎥⎢⎥⎣⎦⎣⎦∑∑505022221111250505050i i i i x x x x x x ==⎡⎤=-⋅+=-⎢⎥⎣⎦∑∑， 同理502221150y i i s y y ==-∑，这100天的方差25050505022211111100100i i i i i i i i x y s x y ====⎛⎫+ ⎪⎛⎫ ⎪=+- ⎪⎪⎝⎭ ⎪⎝⎭∑∑∑∑， 结合三式可得()2222221505050505050100100x y x y s s x s y ⎛⎫+=+++- ⎪⎝⎭()222222221111()1()1062222424x y x y x y x y s x s y s s +-=+++-=++=.。
重庆市渝北区、合川区、江北区等七区2020-2021学年高二下学期期末联考英语试题
重庆市渝北区、合川区、江北区等七区2020-2021学年高二下学期期末联考英语试题学校:___________姓名：___________班级：___________考号：___________一、阅读选择We work with Cambridge County Council's Participation Team to create opportunities for young people to visit the University and learn more about it. The following events are scheduled for the 2019/2020 academic year.SuperStar workshops12 workshops are planned for young people aged 7 to 11. These half-day visits will be held throughout the year, at times when young people are not at school. If participants complete 8 of the 12 workshops, they will be awarded the nationally recognized SuperStar Crest Award.Please note, workshops will only run if we have a sufficient number of attendees (usually around 3+ participants).Explore University DaysExplore University Days are for young people aged 12-15. Participants visit the University for two days and take part in a variety of university-related workshops, and other fun activities.Previous participants have joined in the following:• Visited the Sports Centre• Took part in a Neuroscience workshop• Enjoyed a two-course meal at a University CollegeDates will be confirmed in early December 2019, and a schedule for event will follow in the New Year.Events for post-16 studentsIf you are studying for your post-16 qualifications and are considering applying for Cambridge or would like to find out more about a specific subject, the following events might be for you:• University and College Open Days• Subject Masterclasses• Cambridge Science Festiv al1．What can the participants do in SuperStar workshops？A．To stay only half a day.B．To get a gift.C．To enjoy a free meal.D．To visit the Sports Centre.2．Which event is specially for applicants of Cambridge？A．SuperStar workshops.B．The Neuroscience workshop.C．Explore University Days.D．Events for post-16 students.3．The events in the passage most probably aim to .A．introduce some coursesB．advertise Cambridge UniversityC．enrich students’ spare time lifeD．promote children’s interest in touringThe 3D-printing industry is accelerating its efforts to help fight the new coronavirus and the disease it causes, COVID-19.On Tuesday, HP announced it’s working with those who bought its 3D printers to make medical face shields, hands-free door openers and an adjuster for face masks for medical staff who often must wear them for hours. It’s also testing “hospital-grade” face masks meeting the higher-end FFP3 (过滤式面罩) standard and parts for simple emergency ventilators (呼吸机) and it’s looking into nasal swabs to test for COVID-19 infection. HP also is offering free downloads of its 3D-printed medical equipment designs.Carbon, whose 3D printers are used to make everything from bicycle seats to teeth straighteners, said it plans to send face shield design s to its network of customers who’ve bought its 3D printers. Carbon co-founder and Executive Chairman Joseph DeSimone said on Monday the company expects to send the designs by early Tuesday.3D-printcr makers typically sell their products to others that actually do the 3D printing. One such customer, Ford, said Tuesday that it’s made 1,000 face shields and shipped them to Michigan hospitals, with plans to make 100,000 face shields a week. It is also working with 3M and General Electric on respirator masks and ventilator designs.The effort is one of several to apply 3D-printing technology to the fight againstcoronavirus. 3D printing isn’t as fast at churning out products as conventional mass production methods. But 3D printers are flexible and able to make many different parts anywhere there’s a printer and raw materials like the plastic resins Carbon printers use.Some 3D-printing efforts have focused on ventilators, which expected to be in short supply with a surge of COVID-19 patients suffering from respiratory (呼吸器官) problems. Also in short supply arc N95 masks that can be useful in reducing the likelihood a wearer will spread COVID-19 to others.Carbon’s DeSimone is cautious about the enthusiasm, though, saying that regulatory approval is important and that 3D-printcr enthusiasts shouldn’t be making components not intended for close human contact that might release unhealthy gases.4．What is the passage mainly about?A．An introduction about 3D-printing.B．The 3D-printing industry’s efforts to help fight C OVID-19.C．The products that 3D-printing makers sell.D．How 3D-printing makers produce medical equipment.5．HP announced to help its customers to make the following products exceptfor_____________.A．medical face shields B．hands-free door openersC．an adjuster for face masks D．emergency ventilators6．Which of the following is true according to the passage?A．Carbon’s company will finish its design after Tuesday.B．Ford has made 1,000 face shields end plans to make 10,000 more in a week.C．3D printers are more flexible than traditional mass production methods.D．Most 3D-printings focus on making ventilators and N95 because of their short supply. 7．What can be inferred from the last paragraph?A．3D-printing may release unhealthy gases.B．DeSimone is cautious about 3D-printing.C．Carbon’s company didn’t gain regulatory approval of making medical equipment.D．3D printers aren’t enthusiastic about making components designed for close human contact.Imagine that you’re the creator and show runner of the newest comedy show on television. Only it isn’t so popular yet, and your live Studio audience isn’t giving you the biglaughs the show deserves. Do you film the show all over again, hoping that this time the audience will laugh? Or is there another option for making a joke sound funnier than it was received?Sweeten(改善) the sound by adding a laugh track! “Sweetening,” or the addition of sound effects such as laughs, screams, and other audience-produced noises to the audio track of a TV show, has been used since the 1940s to produce the appearance, or rather the sound, of an engaged and entertained response to a show’s comedy. Laugh tracks came into existence as not only a solution, and sometimes replacement, for an unengaged live audience but also as a way to engage an at-home audience into a more-traditional, public, and theaterlike experience. Adding a laugh track to a television show makes the viewers at home feel much less like they’re sitting on a couch staring at the television screen and much more like they’re in a room full of laughing happy people to varying degrees of success.Though the art of sweetening has risen and fallen in popularity over the past 60 years, credit for its creation and continued use is owed to laugh-track pioneer and sound engineer Charles Douglass. Douglass was the first to develop, in 1953, a machine for producing “canned laughter”, accessible at the push of a button or pull of a lever (操纵杆). Despite being artificial, sensibly edited laugh tracks are found by television studios to bring about a positive audience response, as their use is usually accompanied by higher ratings and increased audience memory. Though some television audiences may disagree with the value of the laugh track, the cheerful and repetitive sound holds a permanent place in the history and future of television comedy. 8．The author uses the first paragraph to .A．introduce the topic “sweetening”B．seek solutions for the problemC．point out a way of making comediesD．arouse readers’ interest in comedies9．What effect does a laugh track produce?A．The creation of a show.B．Funnier sound in a show,C．More engaged live audienceD．Communication among TV viewers.10．What’s the author’s attitude towards the use of the laugh track?A．Doubtful. B．Positive.C．Neutral (中立的). D．Uncertain,11．What does the passage mainly talk about?A．The reason for using laugh tracks.B．The brief history of laugh tracks.C．The development of TV comedies.D．The way to improve television shows.You may think that creativity and artistic judgment are what sets humans apart from artificial intelligence (AI). Robots will be washing our windows long before they start creating masterpieces Right?Not necessarily. At Amper Music (), you can make the music you want based on mood, instrument, speed and length. You click “Render,” and boom! There’s your original piece, not only composed (作曲) but also “performed” and “mixed” by AI software.But something has kept bothering me: What happens in a world where effort and scarcity (稀缺) are no longer part of the definition of art? A mass-produced print of the Mona Lisa is worth less than the actual Leonardo painting. Why? Scarcity—there’s only one of the original. But Amper turns. professional-quality original piece of music every time you click “Render.” It puts us in a strange world where works of art are unique but require almost zero human effort to produce. Should anyone pay for these things? And if an artist puts AI masterpieces up for sale, what should the price be?Tha t’s not just a thought experiment either.Soon the question “What’s the value of AI artwork and music?” will start impacting flesh—and—blood consumers. It has already, in fact.Earlier, reporters discovered something suspicious (可疑的) about many playlists of Spotify—another online music service. According to the report, the composers and bands who wrote the songs appeared to be nonexistent. These playlists have names like Peaceful Piano and Ambient Chill—exactly the kind of music AI software is good at.Is Spotify using software to compose music to avoid paying fees to human musicians? The New York Times reported that the tracks with false names have been played 500 million times, which would ordinarily have cost Spotify $3 million in payments.But Spotify ha s firmly denied that the tracks in question were created by “fake” artists to avoid payments: while posted under pennames, they were written by actual people receivingactual money for work that they own. But the broader issue remains. Why couldn’t Spotify, or any music service, start using AI to produce free music to save itself money? Automation (自动化) is beginning to replace millions of human taxi drivers, truck drivers and fast-food workers. Why should artists and musicians be an exception to the same economics?Should there be anything in place—a union, a law---to stop that from happening? Or will we always value human-produced art and music more than machine-made stuff? Once we’ve answered those questions, we can settle the really big one: When an AI—composed song wins the Grammy, who will be awarded?12．What do we know from the example of Amper Music?A．It doesn’t need any human effort to compose music.B．It allows ordinary people to perform their own music.C．It makes a challenge to the traditional definition of art.D．It produces music works that are similar in styles.13．The underlined part in Paragraph 4 implies that ________.A．it is hard to tell AI artworks apart from human artworksB．people will be charged for AI art in the near futureC．people don’t know what price of AI art is reasonableD．the scarcity of AI artworks means it is one of a copy14．Spotify was covered in the media because ________.A．AI music can be performed free of chargeB．its musicians might not be paid fairlyC．playlists of its music did not actually existD．AI software has replaced human musicians15．The writing purpose of this passage is to ________.A．draw deserved attention to AI-made artworksB．warn against the immediate threat from Al artC．support the use of Al software in art creationD．solve misunderstandings about AI’s role in art二、七选五Shopping therapy （疗法）is the practice of using the shopping experience to help overcome depression or other emotional problems. 16．Actually, it really works.17．One of the most obvious things is the enjoyment people get from the items they buy. When people shop, they often buy things they really care about on some level. For example, when people come home with a new shirt or a new computer, they assume that the item is going to improve their lives in some way. This can help reduce many feelings of unhappiness.18．Some experts think humans are linked with the need to constantly achieve and fight for improvement. People make a decision to buy something, and then actually follow through this plan. This is one way people can take action to directly change their own lives for the better.People who don't actually have any money to buy things still benefit from shopping therapy. For them, simply browsing （浏览）can be a nice experience. That's because it helps them form future shopping plans. 19．The simple act of leaving home and spending time around other humans is another possible reason for the effectiveness of shopping therapy.20．Many people even use shopping as a specific social activity by bringing friends along with them and turning the process into a pleasant one.A．So why not shop until you start feeling better?B．So how do people benefit from shopping therapy?C．These plans offer great expectation and hope in their life.D．Many people shop for this reason without even realizing it.E.People can have the feeling of achievement after shopping.F.Many people have gone into debt due to shopping addiction.G.There is sometimes a sense of community in the shopping experience.三、完形填空Experts are warning about the risks of extreme fussy eating(挑食)after a teenager developed permanent sight loss after living on a diet of chips and crisps.Since leaving 21 school, the teen had been eating only French fries, Pringles and white bread, as well as a(n) 22 slice of ham or a sausage. At the age of 14, feeling tired and not well, he was diagnosed with vitamin B12 deficiency(缺乏)and was 23 supplements(补充剂), but he did not 24 the treatment or improve his poor diet. Three years later, he was taken to the Bristol Eye Hospital because of progressive 25 loss.Dr Denize Atan, who 26 him at the hospital, said, “The teenager explained thiseating disorder as a dislike of certain textures of food that he really could not 27 , and so chips and crisps were really the only types of food that he wanted and felt that he could eat.”28 in B12 as well as some other important vitamins and minerals, he was not over or underweight, but was 29 malnourished (lacking nutrition) from his food intake disorder. “He had lost minerals from his bone, which was really quite30 for a boy of his age.”In terms of his sight loss, he met the 31 for being registered blind. Dr Atan said, “He can’t drive and would find it really difficult to 32 , watch TV or recognize faces. He can walk around on his own, 33 , because he doesn’t lose peripheral( 周边的)vision.”The condition the young man has is treatable 34 diagnosed early. Left too long, however, the nerve fibers in the optic nerve die and the damage becomes 35 . Dr Atan said cases like this are thankfully uncommon, but that parents should 36 the potential harm that can be caused by picky eating, and seek expert help.Dr Atan said vegans(素食主义者)are also at increased risk of B12 deficiency-related sight problems if they do not replace what they can lack when 37 meat from their diet.“Multivitamin tablets can supplement a diet, but are not a(n) 38 for eating healthily. It’s much better to39 vitamins through a varied and balanced diet,” she said, adding that too much of certain vitamins, including vitamin A, can be 40 , “so you don’t want to overdo it”.21．A．vocational B．primary C．middle D．special 22．A．funny B．rigid C．occasional D．raw 23．A．forbidden B．denied C．prescribed D．offered 24．A．stick with B．cope with C．play with D．go with 25．A．diet B．sight C．weight D．wit 26．A．cured B．studied C．instructed D．treated 27．A．describe B．recognize C．tolerate D．receive 28．A．Abundant B．Lost C．Backward D．Lacking 29．A．severely B．scarcely C．seemingly D．sincerely 30．A．amusing B．normal C．shocking D．typical 31．A．situations B．criteria C．deadlines D．challenges 32．A．read B．sing C．dance D．laugh 33．A．even B．though C．still D．yet34．A．since B．unless C．after D．if 35．A．persistent B．periodic C．persevering D．permanent 36．A．wake up to B．live up to C．stand up to D．come up to 37．A．excluding B．separating C．including D．distinguishing 38．A．companion B．substitute C．suggestion D．explanation 39．A．take off B．take after C．take in D．take over 40．A．rewarding B．compulsory C．restrictive D．poisonous四、用单词的适当形式完成短文阅读下面短文，按照句子结构的语法性和上下文连贯的要求，在空格处填入一个适当的词或使用括号中词语的正确形式填空。
2020-2021学年重庆市七校高二下学期期末联考英语试题
期末考试试卷 1 重庆市七校2020-2021学年高二下学期期末联考英语试题 第一部分 听力（共两节，满分30分） 第一节（共5小题；每小题1.5分，满分7.5分） 听下面5段对话。每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 1. What fruit salad will the woman probably make? A. Apple. B. Banana. C. Grape. 2. Why is the woman upset? A. She dislikes art. B. She has to do many tasks. C. She doesn’t like her teacher. 3. How much money will the man send to the woman tomorrow? A. $500. B. $850. C. $1,000. 4. What is the woman doing? A. Organizing fun activities. B. Giving personal advice. C. Making a travel plan. 5. What are the speakers mainly discussing? A. Housework. B. The weather. C. Weekend activities. 第二节 听下面5段对话或独白。每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。每段对话或独白读两遍。 听第6段材料，回答第6、7题。 6. Which part of the woman’s body hurts? A. Her foot. B. Her ankle. C. Her head. 7. What does the man advise the woman to do? A. Use the ice as long as possible. B. Take the painkillers four times a day. C. Avoid walking too much for a couple of days. 听第7段材料，回答第8至10题。 8. At what time will the man arrive in Rome? A. 4:00 p.m. B. 5:20 p.m. C. 7:30 p.m. 9. Where will the man sit? A. Beside the washroom. 期末考试试卷 2 B. Close to the exit door. C. In the middle of the plane. 10. How will the man get his ticket? A. He will get it in person. B. It will be posted to his office. C. The woman will take it to him. 听第8段材料，回答第11至13题。 11.When will the woman give a presentation? A. In February. B. In March. C. In November. 12. How does the woman feel about her presentation? A. Satisfied. B. Confident. C. Nervous. 13. What do we know about the speakers? A. They met in San Francisco last year. B. They will host the conference together. C. They are quite familiar with each other. 听第9段材料，回答第14至16题。 14. What is the man’s opinion on the woman’s trouble? A. She should talk with her boss. B. She should solve her problem by herself. C. She should practice her communication skills. 15. What does the man suggest the woman do about the report? A. Get help from others. B. Ask to extend the deadline. C. Work overtime to finish it. 16. What is the probable relationship between the speakers? A. Husband and wife. B. Teacher and student. C. Colleagues. 听第10段材料，回答第17至20题。 17. What happened to the speaker? A. Her car broke down. B. Her car key was lost. C. She couldn’t find her way. 18. What did the speaker do before meeting the stranger? A. She stayed in her car. B. She sat by the road. C. She made a phone call. 19. How did the stranger help the speaker? 期末考试试卷 3 A. By calling for help. B. By driving her home. C. By accompanying her. 20. How did the speaker thank the stranger? A. She paid him some money. B. She expressed her gratitude. C. She treated him to dinner. 第二部分 阅读理解（共两节，满分50分） 第一节 (共15小题；每小题2.5分，满分37.5分)(改编) 阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。 A You haven’t truly visited a city until you’ve experienced its nightlife. Watching a big city like London gradually turn dark and darker into the night is a beautiful journey of time and light. So how about taking a historical evening walk and touching some of the nicest areas in central London? Let’s get started. 6:30 pm The walk starts on the Millennium Bridge. On the bridge, watch the scenic city across the River Thames with the skyscrapers gradually lighting up against the darkening skies. The Millennium Bridge has been featured in many London-based films, including Harry Potter, and the film Guardians of the Galaxy. 7:30 pm It’s getting dark. A fifteen-minute walk northwest from St Paul’s Cathedral takes you to the historic Borough Market. During the evenings, you find a lot of restaurants around the market. This is an excellent time to get your dinner. 9:00 pm The next stop is London Bridge. This is about 6 minutes’ walk from the Borough Market. As you join other onlookers and mentally go through the nursery school rhyme of “London Bridge is Falling Down”, you get lost again in history. Why does the song say London Bridge is falling and who is the fair lady? During the London city fire of 1897, London Bridge served an important role in fire control. It was one of the major structures that prevented the fire from crossing over to the other side of London. 11:30 pm London never sleeps; it’s a few minutes to midnight and everywhere is still filled with people moving around. About four minutes away from the Golden Jubilee Bridges is Trafalgar Square, our next stop. 12:00 am It’s been a beautiful evening, hasn’t it?
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最新 Word 可修改 欢迎下载 重庆市部分区 2020-2021 学年度第二学期期末联考 高一英语试题卷 注意事项： 1. 考试时间：150 分钟，满分：150 分。试题卷总页数：8 页。 2. 所有题目必须在答题卡上作答，在试题卷、草稿纸上答题无效。 3. 需要填涂的地方，一律用 2B 铅笔涂满涂黑。需要书写的地方一律用 0.5MM 签字笔。4．答题前，务必将自己的姓名、准考证号填写在答题卡规定的位置上。 5．考试结束后，将试题卷和答题卡一并交回。 第Ⅰ卷 第一部分 听力（共两节，满分 30 分） 第一节（共 5 小题，每小题 1.5 分，共计 7.5 分） 听下面 5 段对话。每段对话后有一个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 1. What will the man want to do? A. Open the window. B. Find another room. C. Go out with the woman. 2. When is the woman’s birthday? A. March 15th. B. March 11th. C. March 10th. 3. What does the man mean? A. John has some personal problems. B. The problem is common for young men. C. It’s not common for young men to leave home. 4. What is the man’s purpose? A. Get some change from Jane. B. Go and look for a payphone. C. Use Jane’s mobile phone. 5. What is the man’s opinion ? A. It was impossible for him to go to the party. B. Everybody was surprised by his appearance at the party. C. He had expected to go to the party for a long time. 第二节 （共 15 小题；每小题 1.5 分，满分 22.5 分） 听下面 5 段对话或独白。每段对话或独白后有几个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。听每段对话或独白前，你将有时间阅读各个小 题，每小题 5 秒钟；听完后，各小题给出 5 秒钟的作答时间。每段对话或独白读两遍。 听第 6 段材料，回答第 6 至 8 题。 6. Why does the woman want to go to the library? A. To return some books. B. To borrow some new books.
最新 Word 可修改 欢迎下载 C. To find some test papers.
最新 Word 可修改 欢迎下载 7. When does the library close? A. At 9:00. B. At 9:40. C. At 10:00. 8. What does the man ask the woman to do? A. He asks her to return some books for him. B. He asks her to borrow some books for him. C. He asks her to go to the library with him. 听第 7 段材料，回答第 9 至 11 题。 9. What was the man doing when the story happened? A. Sleeping. B. Swimming. C. Listening to the radio. 10. What happened to the little boy?
A. His eye was hurt by the sand. B. He couldn’t find his parents.
C. He fell into the water. 11. What did the man do after hearing someone shouting for help? A. He went on enjoying the music. B. He looked for the boy’s parents. C. He jumped into the water. 听第 8 段材料，回答第 12 至 14 题。 12. What is the probable relationship between the two speakers? A. Teacher and student. B. Husband and wife. C. Manager and secretary. 13. Where are the two speakers going? A. The airport. B. The railway station. C. The bus station. 14. Why do the speakers call Brenda? A. To ask her to change clothes. B. To ask her when Mother arrives. C. To ask her if she can go with them. 第 9 段材料，回答第 15 至 17 题。 15. Where is Mary going? A. Her home. B. The park. C. The zoo. 16. Why doesn’t Mary like walking through the street? A. It’s too cold. B. There are too many people. C. It isn’t interesting. 17. When does the conversation most likely take place?
最新 Word 可修改 欢迎下载 A. Late in the morning. B. In the late afternoon. C. Early in the morning. 听第 10 段材料，回答第 18 至 20 题。
最新 Word 可修改 欢迎下载 18. When did Grandma Moses turn to painting? A. At the age of 39. B. At the age of 76. C. At the age of 101. 19. What did Grandma Moses do before she became an artist? A. She sold other artists’ works in a shop. B. She worked on her farm. C. She taught at a school. 20. What is the story mainly about? A. A famous American artist. B. Making money from painting. C. Collecting paintings. 第二部分 阅读理解（共两节，满分 35 分） 第一节（共 10 小题，毎小题 2.5 分，共计 25 分） 阅读下列短文，从每小题后所给的四个选项（A、B、C 和 D）中，选出最佳选项，并在答题卡上将该项涂黑 A Here are five movies that are perfect for English learners. The Social Network (2010) Starring (主演) Jesse Eisenberg. Directed by David Fincher. Story: how Mark Zuckerberg founded Facebook. For learning English: Its natural conversation is enjoyable to listen to and easy to follow. The Remains of the Day (1993) Starring Anthony Hopkins and Emma Thompson. Directed by James Ivory. Story: a drama (戏剧) about the relationship between a butler (男管家) and a housekeeper in an English rich family. For learning English: The film is set in an English upper-class home in the 1930s, so the characters speak very formally. Before watching the film you could read the novel that the film is based on by Kazuo Ishiguro. Toy Story (1995) Starring the voices of Tom Hanks and Tim Allen. Directed by John Lasseter. Story: an animated (动画的) film about toys that come to life when children and adults aren’t around. For learning English: Animated films are usually aimed at children and this means the storylines are uncomplicated (简易的). Willy Wonka&the Chocolate Factory (1971) Starring Gene Wilder. Directed by Mel Stuart. Story: things go wrong when a group of kids get a free tour of Willy