广东省惠州市第一中学2022-2023学年高一上学期期中考试英语试题
2024-2025学年广东省惠州市第一中学高一(上)期中物理试卷(含答案)

2024-2025学年广东省惠州市第一中学高一(上)期中物理试卷一、单选题:本大题共7小题,共28分。
1.篮球比赛中的击地传球是指持球者在传球时,为躲防守队员防守而将球击地后传给队友,如图所示,下列说法正确的是( )A. 篮球对水平地面的弹力方向斜向下B. 水平地面对篮球的弹力方向斜向上C. 水平地面受到的压力是由于篮球发生了形变而产生的D. 篮球受到水平地面的支持力是由于篮球发生了形变而产生的2.如图所示滑块A和B叠放在传送带上,B被轻绳连于墙上。
如果传送带逆时针转动,滑块A和B都相对地面静止,则下列说法正确的是( )A. 滑块A受到的静摩擦力水平向右B. 无论传送带的速度是多大,滑块A都不受摩擦力C. 滑块B受到的静摩擦力水平向左D. 传送带受到的摩擦力与滑块B受到的轻绳拉力是一对平衡力3.如图,用一根细线穿过杯柄,两手握住细线两端,提起水杯,保持静止状态.下列说法正确的是( )A. 当细线之间的夹角θ为90°时,细线的张力大小等于杯子的重力大小B. 细线的张力大小一定小于杯子的重力大小C. 只要人的力气足够大,就可以将细线拉至水平D. 逐渐增大细线之间的夹角θ,细线张力将逐渐变大4.电影中汽车从山崖上坠落的镜头常用缩微模型摄影的方法拍摄:如将汽车与山崖都制作成1:100缩微模型(即模型中所有景物的1cm相当于真实世界的1m)。
设电影放映时每1s播放的画面数(帧率,单位为帧/秒)恒为a。
为了让模型汽车坠崖的镜头达到以假乱真的视觉效果,则摄影机在拍摄电影时的( )A. 帧率应为aB. 帧率应为10aC. 帧率应为100aD. 帧率应为110a5.有人提出“加速度的变化率”的概念,基于你的理解,下列说法正确的是( )A. “加速度的变化率”的单位应是m/s2B. 加速度的变化率为零的运动是匀速直线运动C. 若加速度与速度同方向,如图所示的a−t图像,表示的是物体的速度在减小D. 如图所示的a−t图像,已知物体在t=0时速度为5m/s,若加速度与速度方向相反,则2s末的速度大小为2m/s6.一质点做匀减速直线运动时,速度变化Δv时发生位移x1,紧接着速度变化同样的Δv时发生位移x2,则该质点的加速度大小为( )A. (Δυ)2(1x1+1x2) B. (Δv)2(1x1−1x2) C. 2(Δυ)2x1−x2D. (Δυ)2x1−x27.一本书重约9N,正面朝上,共1001页。
广东省惠州市第一中学2024-2025学年高一上学期12月月考数学试题

广东省惠州市第一中学2024-2025学年高一上学期12月月考数学试题一、单选题1.若集合(){},2M x y x y y x =-+=,则()A .()3,1M -∈B .()1,3M -∈C .()1,2M-∈D .()2,1M-∈2.函数3log y x =的反函数为()y f x =,则()2f =()A .2B .3C .8D .93.“α是锐角”是“sin 0α>”成立的()A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件4.冷水坑皇家学院某同学用二分法求函数.()2log 2f x x x a =++零点的近似值时,确定零点所处的初始区间为()1,2,那么实数a 的取值范围为()A .()5,3--B .()5,2--C .()(),52,-∞--+∞D .()(),53,-∞-⋃-+∞5.已知tan 3α=,则sin cos αα=()A .310B .35C .310±D .35±6.已知函数()()()2233221log 3log 22f x x x a f b f c f ⎛⎫=-+=== ⎪⎝⎭,,,,则()A .c b a <<B .c a b <<C .a b c <<D .a c b<<7.函数()()21log 122xf x x =+-的图象关于()A .点()0,1对称B .直线1x =对称C .y 轴对称D .直线y x =对称8.已知实数x ,y 满足2log 4x x +=,342yy +=,则2x y +=()A .52B .3C .72D .4二、多选题9.已知角α的始边与x 轴的非负半轴重合,终边与单位圆交于点34,55P ⎛⎫⎪⎝⎭,则()A .35=cos αB .()4sin π5α-=-C .π4cos 25α⎛⎫+=-⎪⎝⎭D .()4tan π3α+=10.已知0a >,0b >,且1a b +=,则()A .ab 的最大值为14B .22a b +的最小值为12C的最大值为2D .1422a b a b+++的最小值为311.函数[]y x =被称为高斯函数,其中[x ]表示不超过x 的最大整数,如[2.1]3,[3.9]3,[4]4-=-==,已知函数()e e 2x xf x -+=,函数()e e 2x x g x --=,则()A .函数[()()]y f x g x =+的值域是自然数集NB .函数()()g x y f x ⎡⎤=⎢⎥⎢⎥⎣⎦的值域是{1,0,1}-C .函数()()1g x y x f x =+-有且只有一个零点D .函数()()2y f x g x =+的最小值是78三、填空题12.如图是某折扇的示意图,已知D 为OA 的中点,2OA =,2π3AOB ∠=,则此扇面部分(扇环ABCD )的面积是.13.写出一个同时具有下列性质①②③的幂函数() f x =.①对R x ∀∈,都有()()f x f x -=成立;②对()12,0,x x ∀∈+∞当12x x <时,都有()()12f x f x <成立;③对R x ∀∈,都有()0f x ≥,且0R x ∃∈使得()00f x =成立.14.已知函数()2221,0log ,0x x f x x x +⎧-≤⎪=⎨>⎪⎩,若关于x 的方程()()²40f x af x ⎡⎤++=⎣⎦有6个不同的实数根,则实数a 的取值范围是四、解答题15.已知sin ,cos θθ是方程250x x m -+=的两个实数根.(1)求m 的值:(2)若θ为第二象限角,求sin cos θθ-的值.16.为响应“湘商回归,返乡创业”的号召,某企业回永州投资特色农业,为了实现既定销售利润目标,准备制定一个激励销售人员的奖励方案:按销售利润进行奖励,总奖金额y (单位:万元)关于销售利润x (单位:万元)的函数的图象接近如图所示,现有以下三个函数模型供企业选择:①()0y kx b k =+>②()20xy k m k =⋅+>③()3log 303x y k n k ⎛⎫=++> ⎪⎝⎭(1)请你帮助该企业从中选择一个最合适的函数模型,并说明理由;(2)根据你在(1)中选择的函数模型,如果总奖金不少于6万元,则至少应完成销售利润多少万元?17.已知函数()f x 对,x y ∀∈R ,都有()()()f x y f x f y -=-且0x <时,()0f x >.(1)求()()11f f -+的值;(2)判断函数()f x 的单调性,并给出证明:(3)若()12f =-,求不等式()()1324f x f x -+-<的解集.18.已知函数()32.g x x x=-+(1)求不等式>0的解集;(2)令()().f xg x m =+(i )若函数有4个零点x x x x x x x x <<<₁,₂,₃,₄(₁₂₃₄),求证:9;x x x x =₁₂₃₄(ii )是否存在非零实数m ,使得函数在区间[],0a b a b <<()上的取值范围为22,?m m a b ⎡⎤⎢⎣⎦若存在,求出m 的取值范围;若不存在,请说明理由.19.给定正整数()2n n ≥,若集合{}12,,n A a a a M =⊆ ,且满足1212n n a a a a a a +++=⨯⨯⨯ ,则称集合A 为集合M 的n 元“和合集”.(1)判断集合{}1,2-是否为实数集R 的4元“和合集”,并说明理由.(2)若集合{},a b 为正实数集R +的2元“和合集”,证明:a ,b 中至少有一个大于2;(3)若集合A 是自然数集N 的n 元“和合集”,求集合A .。
广东省惠州市第五片区2022-2023学年七年级下学期期中语文试题 含答案

惠州市2022-2023学年第二学期期中考试七年级语文试题说明:1.全卷共6页,满分为130分,考试用时为120分钟。
2.答卷前,考生务必用黑色字迹的签字笔或钢笔在答题卡填写自己的准考证号、姓名、考场号、座位号。
用2B铅笔把对应该号码的标号涂黑。
3.选择题每小题选出答案后,用2B铅笔把答题卡上对应题目选项的答案信息点涂黑,如需改动,用橡皮擦干净后,再选涂其他答案,答案不能答在试题上。
4.非选择题必须用黑色字迹钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
5.考生务必保持答题卡的整洁。
一、基础(33分)1.根据课文用正楷默写古诗文。
(每空1分,默写满分为10分,书写分2分,共12分)(1)□□□□□□□,何人不起故园情。
(李白《春夜洛城闻笛》)(2)故园东望路漫漫,□□□□□□□。
(岑参《逢入京使》)(3)我们要用发展的目光去看待他人的进步,正如《孙权劝学》中所说的□□□□,□□□□□□。
(4)《木兰诗》中和“醉卧沙场君莫笑,古来征战几人回”有异曲同工之妙的句子是□□□□□,□□□□□。
《木兰诗》中描写木兰奔赴战场时矫健英姿的句子是:□□□□□,□□□□□。
(5)默写韩愈的《晚春》。
□□□□□□□,□□□□□□□。
□□□□□□□,□□□□□□□。
2.根据拼音写出相应的词语。
(4分)(1)我将用我的泪水,洗去她一切的wū huì()和耻辱。
(2)我似乎遇着了一个pī lì(),全体都震悚起来。
(3)因为实在太疲倦,一会儿就hān rán rùmèng()了。
(4)农村里有这么个风俗,dàtínɡ ɡuǎnɡ zhònɡ()之下,夫妇俩从不合坐一条板凳。
3.请选出下列句子中划线词语运用有误的一项()(3分)A.被誉为“最美司机”的吴斌,几十年如一日服务乘客,任劳任怨,在生命的最后时刻,顶着肋骨被撞断和肝脏破裂的剧痛,停稳汽车,保障了乘客的安全。
广东省惠州市第一中学教育集团2024-2025学年七年级上学期11月期中语文试题(无答案)

惠州一中教育集团2024—2025学年第一学期期中质量监测初一年级语文科试题本试卷共5页,21小题,满分120分。
考试用时120分钟。
注意事项:1. 答卷前,考生务必用黑色字迹的钢笔或签字笔将自己的准考证号、姓名、考场号和座位号填写在答题卡上。
用2B铅笔在“考场号”和“座位号”栏相应位置填涂自己的考场号和座位号。
2. 作答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案,答案不能答在试卷上。
3. 非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
4. 考生必须保持答题卡的整洁。
一、积累运用 (29分)1. 默写古诗文。
(共10分。
答对1空得1分,满分不超过10分)(1) 日月之行;若出其里。
(曹操《观沧海》)(2),随君直到夜郎西。
(李白《闻王昌龄左迁龙标遥有此寄》)(3)潮平两岸阔,。
,江春入旧年。
(王湾《次北固山下》)(4) 遥怜故园菊,。
(岑参《行军九日思长安故园》)(5) 正是江南好风景,。
(杜甫《江南逢李龟年》)(6),一夜征人尽望乡。
(李益《夜上受降城闻笛》)(7)《<论语>十二章》中孔子感叹时光易逝,以勉励自己和学生要珍惜时间求学的句子是:,。
点明“兴趣是最好的老师”的句子是:,。
阅读下面的文字,完成2-4题。
(9分)轻轻打开语文课本,美丽的四季迎面而来。
春风夏雨,秋霜冬雪,大自然生生不息,四时景物。
跟随朱自清的脚步来到生机勃勃的春天,鸟儿在繁花嫩叶中,唱着宛转动人的曲子,与轻风流水yìng hè着;聆听老舍的叙述,我们欣赏了天蓝地暖的济南冬景图。
通过老舍的《济南的冬天》,让我们感受到了冬天的温情;我们在刘湛秋笔下走过雨的四季,热烈而cūguǎng,让我们感受到他对大自然的。
广东省惠州市丰湖高级中学2022-2023学年高一下学期第一次段考物理试题

第二学期第一次段考高一物理试卷满分100分, 考试用时75分钟一、单项选择题:本题共7小题,每小题4分,共28分。
在每小题给出的四个选项中,只有一项符合题目要求。
1.从离地高0.8m 处,以初速度为1m/s 水平抛出一个小物块,不计空气阻力,则落地点到抛出点的水平距离为(g 取10m/s 2)( ) A .0.2mB .0.4mC .0.6mD .0.8m2.质量为25kg 的小孩坐在秋千上,小孩离系绳子的横梁2.5m 。
如果秋千摆到最低点时,小孩运动速度的大小是5m/s ,她对秋千板的压力是( ) A .500NB .100NC .1000ND .800N3.下列关于曲线运动的说法正确的是( ) A .曲线运动可以是变速运动也可以是匀速运动 B .曲线运动一定是变速运动 C .匀速圆周运动是匀速曲线运动 D .曲线运动受到的合外力可以为零4.如图所示,水平面上的小车向左运动,系在车后的轻绳绕过定滑轮,拉着质量为m 的物体上升。
若小车以v 1的速度做匀速直线运动,当车后的绳与水平方向的夹角为θ时,物体的速度为v 2,绳对物体的拉力为FT ,重力加速度为g ,则下列说法正确的是( ) A .物体做匀速运动且21v v = B .物体做加速运动且21cos v v θ= C .绳对物体的拉力为T F mg = D .绳对物体的拉力为T F mg <5.人造卫星A 、B 绕地球做匀速圆周运动,A 卫星的运动周期为2天,A 的轨道半径为B 的轨道半径的13,则B 卫星运行的周期大约是( ) A .3天 B .5天 C .10天 D .18天6.如图所示,自行车的大齿轮与小齿轮通过链条相连,而后轮与小齿轮绕共同的轴转动。
在自行车正常行驶时()A.后轮边缘点与小齿轮边缘点的线速度相等B.后轮边缘点与小齿轮边缘点的角速度相等C.大齿轮边缘点与后轮边缘点的线速度相等D.大齿轮边缘点与小齿轮边缘点的角速度相等7.有一个质量为4 kg的质点在xOy平面内运动,在x方向的速度图象和y方向的位移图象分别如图甲、乙所示.下列说法正确的是()A.质点做匀变速直线运动B.质点所受的合外力为22 NC.2 s时质点的速度为6 m/sD.零时刻质点的速度为5 m/s二、多项选择题:本题共4小题,每小题6分,共24分。
广东省惠州市第五中学2022-2023学年八年级下学期期末数学试题

.....如图,在▱ABCD中,对角线AC交于点O,下列式子中不一定成立的是A.43B8.一组数据3、2、4、5A.2BA.点N处B.点P处C.点二、填空题(本大题共5小题,每小题3分,共11.若菱形的两条对角线长分别为6和8,则该菱形的面积为12.甲、乙两个样本,甲的方差为0.102,乙的方差为答:.15.如图,正方形ABCD的边长为2,顺次连接正方形21.如图,已知DB∥AC,(1)求证:四边形DBCE (2)若要使四边形ADBE23.如图,矩形ABCD的对角线AC,BD相交于点O,将△COD沿CD所在直线折叠,得到△CED.(1)求证:四边形OCED是菱形;(2)若AB=2,当四边形OCED是正方形时,求OC的长;(3)若BD=3,∠ACD=30°,P是CD边上的动点,Q是CE边上的动点,求PE+PQ 的最小值.【点睛】本题考查菱形的性质,三角形面积,由三角形的面积得到菱形的面积DAC =△的面积BAC +△的面积是解题的关键.12.甲的波动比乙的波动大.【分析】根据方差的定义,方差越小数据越稳定,故可得到正确答案.【详解】解:根据方差的意义,甲样本的方差大于乙样本的方差,故甲的波动比乙的波动大.故答案:甲的波动比乙的波动大.【点睛】本题考查方差的意义.方差是用来衡量一组数据波动大小的量,方差越大,表明这组数据偏离平均数越大,即波动越大,数据越不稳定;反之,方差越小,表明这组数据分布比较集中,各数据偏离平均数越小,即波动越小,数据越稳定.13.4【分析】设BN x =,则由折叠的性质可得9DN AN x ==-,根据中点的定义可得3BD =,在Rt BND △中,根据勾股定理可得关于x 的方程,解方程即可求解.【详解】解:设BN x =,由折叠的性质可得9DN AN x ==-,D 是BC 的中点,3BD ∴=,在Rt BND △中,2223(9)x x +=-,解得4x =.故线段BN 的长为4.故答案为:4.【点睛】此题考查了翻折变换(折叠问题),折叠的性质,勾股定理,中点的定义以及方程思想,综合运用以上知识是解题的关键.14.−2a【分析】根据数轴表示数的方法得到a <0<b ,且|a |>b ,则原式=-(a +b )-(a -b ),然后去括号合并即可.【详解】解:∵a <0<b ,且|a |>b20.水的深度为12尺,这根芦苇的长度是13尺【分析】如图所示,根据题意可得5BC =,设AB x =,则1AC x =-,由勾股定理列方程求解即可得到答案.【详解】解:如图所示:由题意可知5BC =,设AB x =,则1AC x =-,由勾股定理可得222AC BC AB +=,即()22215x x -+=,226x ∴=,解得13x =,答:水的深度为12尺,这根芦苇的长度是13尺.【点睛】本题考查勾股定理解实际问题,读懂题意,构造直角三角形求解是解决问题的关键.21.(1)见解析;(2)△ABC 满足AB =BC 时,四边形DBEA 是矩形【分析】(1)根据EC =BD ,EC ∥BD 即可证明;(2)根据等腰三角形三线合一的性质得出∠BEA =90°,根据有一个角是直角的平行四边形是矩形推出即可.【详解】(1)∵E 是AC 中点,∴AE =EC ,∵DB =AE ,∴EC =BD又∵DB ∥AC ,∴四边形DECB 是平行四边形;(2)△ABC 满足AB =BC 时,四边形DBEA 是矩形,理由如下:∵DB =AE ,又∵DB ∥AC ,【点睛】本题主要考查了翻折变换的性质,勾股定理以及垂线最短等知识,熟练掌握翻折的性质和菱形的性质与判定是解题的关键。
广东省惠州市第一中学2024届九年级英语第一学期期末达标测试试题含解析
广东省惠州市第一中学2024届九年级英语第一学期期末达标测试试题请考生注意:1.请用2B铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
写在试题卷、草稿纸上均无效。
2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。
Ⅰ. 单项选择1、Both of them had the same opinion. They reached a(n) ______ quickly.A.organization B.victory C.situation D.agreement2、—Hi, mom, exciting news! I am the only one of the students who elected (当选) as president of the students’ union.—Oh, you are so lucky to get the honor and then work hard!A.were B.was C.are3、---_______I smoke here, Madam?---Sorry, you _______. Look at the sign.A.Could, couldn’t B.Can, couldn’tC.Could, can’ D.Must, needn’t4、---Do you know that Erhu is one of the most traditional in China?---Of course. Liu Tianhua, the of Erhu, was born and grew up in our hometown Jiangyin.A.instructions; pioneer B.instruments; pioneerC.instructions; inventor D.instruments; inventor5、Lucy and I are twin sisters and we have a lot ________ common.A.at B.in C.on D.to6、—Only those who have a lot in common can get along well.—________. Opposites sometimes attract.A.I hope so B.I think so C.I don't care D.I don't think so7、Do more exercise and ______ from sugar and fat food, then you’ll be fitter.A.send away B.stay away C.give away D.take away8、--Did you hear someone knocking at the door just now, Tom?--No, I _______ TV with my friend in my bedroom.A.was watching B.watched C.am watching D.watch9、—As we know, it’s difficult to live in the foreign country.—______ if you don’t understand the local language.A.Generally B.Naturally C.Exactly D.Especially10、It’s reported that people throw plastic bags along this street every day.A.hundred B.hundreds C.hundred of D.hundreds ofⅡ. 完形填空11、完形填空(共15小题,计15分)通读下面短文,掌握其大意,然后在各题所给的四个选项(A、B、C和D)中选出一个最佳选项。
广东省惠州市第一中学2023-2024学年七年级上学期期末考试数学试卷(含解析)
惠州一中2023-2024学年第一学期初一年级期末考试数学试题卷满分120分,考试用时为90分钟注意事项:1.答题前,考生务必用黑色字迹的签字笔或钢笔在答题卡上填写自己的学校、班级、姓名、考号.用2B 铅笔将对应该号码的标号涂黑.2.选择题每小题选出答案后,用2B 铅笔将答题卡上对应题目选项的答案信息点涂黑,如需改动,用橡皮擦擦干净后,再选涂其它答案,答案不能答在试题上.3.非选择题必须用黑色字迹的钢笔或签字笔作答、答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液.不按以上要求作答的答案无效.4.考生务必保持答题卡的整洁.考试结束时,将答题卡交回.一、单选题(每小题3分,共10小题)1.据科学研究表明,5G 移动通信技术的网络理论下载速度可达每秒1300000KB 以上.其中1300000用科学记数法表示为()A.51310⨯ B.61.310⨯ C.51.310⨯ D.71.310⨯答案:B解析:61300000 1.310=⨯.故选B .2.如图所示,几何体的左视图是()A. B. C. D.答案:A解析:解:从左边看,是一个矩形,矩形内部有两条横向的虚线.故选:A .3.下列方程中,是一元一次方程的是()A.0x = B.225x x -= C.34x y += D.120x -=答案:A解析:解:A 、0x =是一元一次方程,故A 符合题意;B 、225x x -=中未知数的最高次数是2,因此不是一元一次方程,故B 不符合题意;C 、34x y +=中含有2个未知数,因此不是一元一次方程,故C 不符合题意;D 、120x -=中1x是分式,因此不是一元一次方程,故D 不符合题意.故选:A .4.在实数11,0,0.3,3.1415926,4,20223--,π中,有理数的个数为()A.3B.4C.5D.6答案:D 解析:解:整数和分数统称为有理数,个数有11,0,0.3,3.1415926,4,20223--,共6个,故选:D5.下列运用等式的性质,变形不正确的是()A.若x y =,则55x y +=+ B.若a b =,则ac bc =C.若a b c c =,则a b = D.若x y =,则x y a a=答案:D【解析:解:A 、若x y =,则55x y +=+,正确,不合题意;B 、若a b =,则ac bc =,正确,不合题意;C 、若a b c c =,则a b =,正确,不合题意;D 、若x y =,0a ≠,则x y a a =,故此选项错误,符合题意;故选:D .6.下列说法正确的是()A.23xy -的系数是2-B.232a b 的次数是6次C.多项式2631x x -+是二次三项式D.21x x +-的常数项为1答案:C解析:解:A 、23xy -的系数是23-,原说法错误,选项错误;B 、232a b 的次数是4次,原说法错误,选项错误;C 、多项式2631x x -+是二次三项式,原说法正确,选项正确;D 、21x x +-的常数项为1-,原说法错误,选项错误,故选C .7.已知线段AB =5cm ,在直线AB 上画线段BC =2cm ,则AC 的长是()A.3cmB.7cmC.3cm 或7cmD.无法确定答案:C解析:解:∵在直线AB 上画线段BC ,∴AC 的长度有两种可能:①当C 在AB 之间,此时AC =AB -BC =5-2=3cm ;②当C 在线段AB 的延长线上,此时AC =AB +BC =5+2=7cm .故选C .8.如图,将一副三角尺按不同的位置摆放,下列摆放方式中a ∠与∠β互余的是()A.图①B.图②C.图③D.图④答案:A 解析:解:图①,∠α+∠β=180°﹣90°90,=°互余;图②,根据同角的余角相等,∠α=∠β;图③,根据等角的补角相等∠α=∠β;图④,∠α+∠β=180°,互补.故选A .9.如图所示,数轴上点A 、B 对应的有理数分别为a 、b ,下列说法正确的是()A.0ab > B.a b < C.0a b +> D.0a b -<答案:D 解析:解:由数轴可知0a b <<,且||||a b >,∴A 、0ab <,故此选项错误,不符合题意;B 、||||a b >,故此选项错误,不符合题意;C 、0a b +<,故此选项错误,不符合题意;D 、0a b -<,故此选项正确,符合题意;故选:D .10.小华在某月的日历上圈出相邻的四个数,算出这四个数字的和为36,那么这四个数在日历上位置的形式是()A. B. C. D.答案:D解析:试题分析:可设第一个数为x ,根据四个数字的和为36列出方程,即可求解.解:设第一个数为x ,根据已知:A 、由题意得x+x+6+x+7+x+8=36,则x=6.25不是整数,故本选项不可能.B 、由题意得x+x+1+x+2+x+8=36,则x=6.25不是整数,故本选项不可能.C 、由题意得x+x+1+x+8+x+9=36,则x=4.5不是整数,故本选项不可能.D 、由题意得x+x+1+x+7+x+8=36,则x=5,为正整数符合题意.故选D .考点:一元一次方程的应用.二、填空题(每小题3分,共5小题)11.2024-的相反数是______.答案:2024解析:解:2024-的相反数是2024,故答案为:2024.12若2230x y -++=(),则2x y +=________.答案:1解析:因为(x -2)2+|y +3|=0,所以x -2=0,y +3=0,解得x =2,y =-3,所以2x +y =2×2-3=1.故答案为1.13.已知1418∠=︒',244∠=︒,则1∠______2∠(比较大小).答案:<解析:解:由题意知,2444360'∠=︒=︒,∵4360418'<︒︒',∴12∠∠<,故答案为:<.14.观察一列数:1234,,,,24816…根据规律,请你写出第5个数是______.答案:532解析:解:由已知数列可知分子恰是自然数列,所以第5个数的分子为5,分母是比为2的等比数列,所以第5个数的分母为5232=,∴第5个数为:532,故答案为:532.15.某商场将一款品牌时装按标价打九折出售,可获利80%,若按标价打七折出售,可获利______%.答案:40解析:解:设按标价打七折出售,设可获利x ,再设成本为a 元,根据题意,得(10.8)(1)0.90.7a x a++=,解得x =0.4=40%.即按标价打七折出售,可获利40%.故答案为:40.三、解答题(每题8分,共3题)16.计算:(1)2211(10)2(4)2---+⨯+-;(2)1571(36)2612⎛⎫-+⨯- ⎪⎝⎭.答案:(1)26(2)45-小问1解析:解:2211(10)2(4)2---+⨯+-110116=-+++26=;小问2解析:解:1571(36)2612⎛⎫-+⨯- ⎪⎝⎭357(36)(36)(36)2612=⨯--⨯-+⨯-543021=-+-45=-.17.解方程:(1)5x -6=3x -4(2)123173x x -+-=答案:(1)x=1;(2)x=-3.解析:(1)5x -6=3x -4解:5x -3x =-4+62x =2x =1(2)123173x x -+-=解:()()3122173x x --=+3621721x x --=+6721213x x --=+-1339x -=3x =-18.先化简,再求值:()()232x y x y x --++,其中12x y =-=,.答案:5x y -,11-解析:解:()()232x y x y x--++2322x y x y x=---+5x y =-,当12x y =-=,时,原式15211=--⨯=-.四.解答题(每题9分,共3题)19.如图,已知线段a ,b ,其中AB =a .(1)用尺规作图法,在AB 延长线上,作一点C ,使得BC =b .(不写作法,保留作图痕迹);(2)在(1)的条件下,若a =2,b =1,AC 的中点为M ,求线段AM 的长.答案:(1)作图见解析(2)AM 的长为32小问1解析:解:如图,以B 为圆心,以b 为半径画弧与AB 延长线的交点为C ,BC 即为所求;小问2解析:解:∵2,1AB a BC b ====∴3AC AB BC =+=∵AC 的中点为M ∴1322AM AC ==∴AM 的长为32.20.列方程解应用题.某家具厂有60名工人,加工某种有一个桌面和四条桌腿的桌子,工人每天每人可以加工3个桌面或6个桌腿.分配多少工人加工桌面,多少工人加工桌腿,才能使每天生产的桌面和桌腿配套?答案:有20名工人加工桌面,40名工人加工桌腿解析:解:设有x 名工人加工桌面,则加工桌腿的有()60x -名,根据题意得,()43660x x ⨯=⨯-,解得:20x =,602040∴-=名,答:有20名工人加工桌面,40名工人加工桌腿.21.如图,直线AB ,CD 相交于点O ,OD 平分∠BOE ,OF 平分AOE ∠.(1)求DOF ∠的度数;(2)若:1:5AOC AOD ∠∠=,求EOF ∠的度数.答案:(1)90DOF ∠=︒;(2)60︒.小问1解析:解:∵OD 平分∠BOE ,OF 平分AOE ∠,∴12EOD BOE ∠=∠,12EOF AOE ∠=∠,∴()12EOD EOF BOE AOE ∠+∠=∠+∠,∴111809022DOF AOB ∠=∠=⨯︒=︒;【小问2解析:∵:1:5AOC AOD ∠∠=,180AOC AOD ∠+∠=︒,∴30AOC ∠=︒,∴30BOD AOC ∠=∠=︒,∵OD 平分∠BOE ,∴30BOD EOD ∠=∠=︒,由(1)得:∴90903060EOF EOD ∠=︒-∠=︒-︒=︒.五.解答题(每题12分,共2题)22.2023年12月28日晚,惠州一中南湖校区“悠悠南湖情,拳拳家国心”元旦文艺晚会在南湖畔上演.一中师生用歌声舞姿表达热爱寄托情怀,回首2023,逐梦2024.若1班和2班共有94名学生(其中1班人数多于2班人数,且1班人数不够90名),统一购买服装参加演出,下面是某服装厂给出的服装价格表:购买服装的套数1套—46套47套—90套91套及以上每套服装的价格60元50元40元如果两个班分别单独购买服装,一共应付5120元.(1)若两班联合起来购买服装,则比各自购买服装共可以节省多少元?(2)两个班各有多少名学生准备参加元旦演出?(3)如果1班有10名学生被调去参加合唱团的节目,不能参加班级演出,请你为这两个班设计一种最省钱的购买服装的方案.答案:(1)若两班联合起来购买服装,则比各自购买服装共可以节省1360元;(2)1班有52名学生准备参加元旦演出,2班有42名学生准备参加元旦演出;(3)联合一起买91套最省钱.小问1解析:解:512094401360-⨯=元,答:若两班联合起来购买服装,则比各自购买服装共可以节省1360元;小问2解析:解:设1班有x 名学生准备参加元旦演出,则2班有()94x -名学生准备参加元旦演出,1班人数多于2班人数,94x x ∴>-,解得:47x >,1班人数不够90名,4790x ∴<<,9447x ∴-<,由题意得:()5060945120x x +-=,解得:52x =,94945242x -=-=,答:1班有52名学生准备参加元旦演出,2班有42名学生准备参加元旦演出;小问3解析:解:由题意可知,1班有42名学生准备参加元旦演出,2班有42名学生准备参加元旦演出,共84人,联合一起买最省钱,若买84套,则需花费50844200⨯=元,若买91套,则需花费40913640⨯=元,36404200< ,∴联合一起买91套最省钱.23.如图,将一条数轴在原点O 和点B 处各折一下,得到一条“折线数轴”.图中点A 表示11-,点B 表示10,点C 表示18,我们称点A 和点C 在数轴上相距29个单位长度.动点P 从点A 出发,以2个单位长度/秒沿着“折线数轴”的正方向运动,从点O 运动到点B 期间速度变为原来的一半,之后立刻恢复原速;同时,动点Q 从点C 出发,以1个单位长度/秒的速度沿着数轴的负方向运动,从点B 运动到点O 期间速度变为原来的两倍,之后也立刻恢复原速.设运动时间为t 秒.问:(1)动点P 从点A 运动到点C 需要多少时间?(2)P 、Q 两点相遇时,求出相遇点M 所对应的数是多少;(3)求当t 为何值时,P 、Q 两点在数轴是相距的长度与Q 、B 两点在数轴上相距的长度相等.答案:(1)19.5秒(2)5(3)9.5或15.5小问1解析:解:由图可知:动点P 从点A 运动至C 分成三段,分别为AO OB BC 、、,AO 段时间为11 5.52=,OB 段时间为10101=,BC 段时间为842=,∴动点P 从点A 运动至C 点需要时间为5.510419.5++=(秒),答:动点P 从点A 运动至点C 需要19.5秒;小问2解析:解:由题可知,P 、Q 两点相遇在线段OB 上于M 处,设OM x =.则()112181102x x ÷+÷=÷+-÷,解得:5x =,∴M 所对应的数为5;小问3解析:P 、Q 两点相遇需11510.52+=秒.由图可知,当点Q 在线段BC 即即08t ≤≤时,PQ BQ >;当点Q 在线段BO 上且与P 相遇前,即810.5t <<时,由题意,得()()()10 5.52828t t t ----=-,解得9.5t =,符合题意;当点Q 在线段BO 上且与P 相遇后,即10.519t <≤时,显然当P 与B 重合时,PQ QB =,此时 5.51015.5t =+=.综上可知:t 的值为9.5或15.5.。
2023-2024学年广东省惠州市惠城区第一中学九年级英语第一学期期末联考模拟试题含解析
2023-2024学年广东省惠州市惠城区第一中学九年级英语第一学期期末联考模拟试题注意事项1.考试结束后,请将本试卷和答题卡一并交回.2.答题前,请务必将自己的姓名、准考证号用0.5毫米黑色墨水的签字笔填写在试卷及答题卡的规定位置.3.请认真核对监考员在答题卡上所粘贴的条形码上的姓名、准考证号与本人是否相符.4.作答选择题,必须用2B铅笔将答题卡上对应选项的方框涂满、涂黑;如需改动,请用橡皮擦干净后,再选涂其他答案.作答非选择题,必须用05毫米黑色墨水的签字笔在答题卡上的指定位置作答,在其他位置作答一律无效.5.如需作图,须用2B铅笔绘、写清楚,线条、符号等须加黑、加粗.Ⅰ. 单项选择1、Several _________ are talking under the tree. And their _____ are swimming in the lake.A.woman, children B.woman, childC.women, children D.women, child2、---QQ and Wechat have changed people’s life in ma ny ways.--- _____. We can use them to keep in touch and communicate with others more easily.A.Completely B.Exactly C.Probably D.Possibly3、Li Wei bought some school things online at the beginning of the new term, according to the information in the form below, he saved _______ in all.School thingsThe shop nearby ¥ 160 ¥ 30 ¥ 20 ¥ 80Online shop ¥ 140 ¥ 20 ¥ 15 ¥ 60A.¥ 55 B.¥ 235 C.¥ 2904、—Was his father very strict with him when he was at school?—Yes. He never praised him ________ he became one of the top students in his grade.A.after B.unless C.if D.when5、–What were you doing at eight last night?-- I in my office at that time.A.worked B.works C.was working6、—What should I do, doctor?—________ healthy, you should take more exercise.A.Keep B.To keepC.Keeping D.To keep out7、---Could you tell me the_______of making such tasty cakes?---Well,I just follow the instructions in the cookbook.A.time B.methodC.cost D.menu8、If it rains hard, we have to ______ the basketball match.A.cut offB.put offC.go offD.take off9、--The man I saw yesterday __________ around my house again.--Let’s call the police right now.A.was walking B.has walked C.is walking10、——Dad, must I finish my homework today?------No, you . You may do it tomorrow.A.needn’t B.mustn’t C.don’t D.won’tⅡ. 完形填空11、There was once a greedy(贪婪的) dog. It got a piece of 1 in his mouth. He was going to 2 it at home by himself. When he was 3 on a bridge, he looked down and saw a dog in the 4 . That dog looked at him and he had a piece of meat in his mouth, too. The dog 5 there was another dog in the river. So he said to himself, “I want to eat his meat. I must make him run 6 from here and get the meat in his mouth, then I can have 7 pieces of meat.” He opened his mouth and 8 at the dog in the river. But the meat in his mouth went down into the river. The dog was so 9 , so he jumped into the river and wanted to 10 the other dog. Of course, the greedy dog got nothing in the end.1.A.cake B.bread C.meat D.food2.A.cook B.put C.eat D.cut3.A.walking B.running C.dancing D.looking4.A.tree B.river C.pool D.lake5.A.looked B.told C.watched D.thought6.A.away B.out C.down D.up7.A.one B.two C.three D.no8.A.cried B.barked C.shouted D.looked9.A.nervous B.happy C.surprised D.angry10.A.run B.see C.find D.catchⅢ. 语法填空12、At the age of fifteen, I met 1.Australia teacher. He taught us English. One day, he wrote an English poem 2.the blackboard and asked us the meaning. There was a long silence. 3.(unlucky),the teacher4.(choose) me to answer the questions. I said in a low v5.,“Sorry, I don’t know.”That’s always my reply to difficult qustions.To my surprise, he spent the rest of the class 6.(explain) my answer. He said “I don’t know is a wrong answer.”Y ou should at least have some ideas about the questions, no matter how difficult it is. It doesn’t mean that you don’t know. It means that you are not 7.(confidence), and you are afraid of making 8.(mistake).” I was shocked by 9.(he) words. He was right. From then on, I said goodbye to the wrong answer“I don’t know”,b10.any answers was better than that one. Now I always try my best to find a proper answer.Ⅳ. 阅读理解A13、The Internet, mobile phones and iPads are part of our lives now. Technology is greatly affecting all ways of our lives, from the ways we work to the ways we play. And it even causes a number of social problems such as cloning humans. We have had lots of technology and it has changed our lives a lot. There is no doubt that humans will continue to use more and more technology. Here are some examples of modern technology that will change our ideas and will affect our lives greatly.Global positioning system(GPS)——It’s a system th at uses radio signals from satellites to show exact information. It tells you where the user is on the earth in all weather conditions. It’s made up of three parts:satellites, control equipments on land and receivers.Space Technology——Russian and American scientists have worked together for the international Space Station(ISS) for a long time. They hope the ISS will provide a long-lasting lab. Such a lab will bring humans limitless advantage. It’s even hoped that one day space technology will take hum ans to their new housed in space.Underwater Robot——Hercules is kind of underwater robot with some high technology equipments. It will be used to search for ancient ships which were destroyed into the deep sea during their journey long ago.The world is c hanging so quickly that it’s hard for us to catch up with all the new inventions because they seem to come out every month. It’s important for us to learn about new technology and the role that it plays in our lives. So we should be willing to accept modern technology, or we will fall behind the times.根据短文内容,选择最佳答案。
广东省惠州市惠阳高级中学2022-2023学年数学七年级第一学期期末经典试题含解析
2022-2023学年七上数学期末模拟试卷请考生注意:1.请用2B 铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
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一、选择题(每小题3分,共30分)1.如图是一个简单的运算程序,如果输入的x 值为﹣2,则输出的结果为( )A .6B .﹣6C .14D .﹣142.多项式2x 3﹣10x 2+4x ﹣1与多项式3x 3﹣4x ﹣5x 2+3相加,合并后不含的项是( )A .三次项B .二次项C .一次项D .常数项3.在下列变形中,正确的是( )A .若420x -=,则5x =B .若37322x x +=-,则32327x x +=+C .若()2105x x x -+=,则2105x x x --=D .若1224x x +-=,则()212x x -=- 4.下列各组数相等的一组是 ( )A .∣-3∣和-(-3)B .-1-(-4)和-3C .2(3)-和 23-D .21()3-和19- 5.一些相同的房间需要粉刷墙面.一天3名一级技工去粉刷8个房间,结果其中有50m 2墙面未来得及粉刷;同样时间内5名二级技工粉刷了10个房间之外,还多粉刷了另外的40m 2墙面,每名一级技工比二级技工一天多粉刷10m 2墙面,设每个房间需要粉刷的墙面面积为xm 2,则下列的方程正确的是( )A .3505(10)40810--+=x x B .3505(10)40810+--=x x C .850104035+-=x x +10 D .850104035-+=x x +10 6.近年来,中国高铁发展迅速,高铁技术不断走出国门,成为展示我国实力的新名片.现在中国高速铁路营运里程已达到35000公里,继续高居世界第一.将35000用科学记数法表示应为( )A .3.5×104B .35×103C .3.5×103D .0.35×1057.如图,过A 点的一次函数的图象与正比例函数y=2x 的图象相交于点B ,则这个一次函数的解析式是( )A .y=2x+3B .y=x ﹣3C .y=2x ﹣3D .y=﹣x+38.下列变形不正确的是( )A .1122x x x x +-=---B .b a a b c c--+=- C .a b a b m m -+-=- D .22112323x x x x--=--- 9.若2320a a --=,则2526a a +-( )A .2B .1C .-2D .-110.数x 、y 在数轴上对应点如图所示,则化简|x+y|﹣|y ﹣x|的结果是( )A .0B .2xC .2yD .2x ﹣2y二、填空题(本大题共有6小题,每小题3分,共18分)11.如果一个多项式与另一多项式223m m -+的和是多项式231m m +-,则这个多项式是_________.12.如图,AOB ∠=___________.13.若(x+m )(x+3)中不含x 的一次项,则m 的值为__.14.如图,直线AB 与CD 相交于点O ,射线OM 是∠AOC 的平分线,如果∠BOC =110°,那么∠AOM =______°.15.已知点()3,21A a --与点(),3B b -关于x 轴对称,那么点(),P a b 关于y 轴的对称点P '的坐标为__________.16.已知线段6AB cm =,点C 在直线AB 上,2BC cm =,点D 为线段AC 的中点,则线段DB 的长为 _____________cm .三、解下列各题(本大题共8小题,共72分)17.(8分)一个由若干小正方形堆成的几何体,它从正面看和从左面看的图形如图1所示.()1这个几何体可以是图2中甲,乙,丙中的______;()2这个几何体最多由______个小正方体堆成,最少由______个小正方体堆成;()3请在图3中用阴影部分画出符合最少情况时的一个从上面往下看得到的图形.18.(8分)某体育场的环行跑道长400米,甲、乙同时从同一起点分别以一定的速度练习长跑,如果反向而行,那么他们每隔32秒相遇一次.如果同向而行,那么每隔160秒乙就追上甲一次.甲、乙的速度分别是多少?19.(8分)如图,点A D C F 、、、在同一条直线上,,,AD CF AB DE BC EF ===.(1)请说明ABC DEF △≌△;(2)BC 与EF 平行吗?为什么?20.(8分)同学们,今天我们来学习一个新知识,形如ab c d 的式子叫做二阶行列式,它的运算法则用公式表示为:a bcad bc d =-,利用此法则解决以下问题:(1)仿照上面的解释,计算出23- 14的结果;(2)依此法则化简23- 32ab a b a b ab-+--的结果; (3)如果51x + 34x =,那么x 的值为多少?21.(8分)解下列方程(1) 2x ﹣(x+10)=6x (2)2211632x x x -+--=+; 22.(10分)2018年元旦期间,某商场打出促销广告,如下表所示:(1)用代数式表示(所填结果需化简)设一次性购买的物品原价是x 元,当原价x 超过200元但不超过500元时,实际付款为 _________元;当原价x 超过500元时,实际付款为 元;(2)若甲购物时一次性付款490元,则所购物品的原价是多少元?(3)若乙分两次购物,两次所购物品的原价之和为1000元(第二次所购物品的原价高于第一次),两次实际付款共894元,则乙两次购物时,所购物品的原价分别是多少元?23.(10分)点A 在数轴上对应的数为a ,点B 对应的数为b ,且a 、b 满足22(3)0a b ++-=.(1)求点A 、B 所表示的数;(2)点C 在数轴上对应的数为x ,且x 是方程27213x x -=+的解. ①求线段BC 的长;②在数轴上是否存在点P ,使PA +PB =BC ?若存在,求出点P 对应的数;若不存在,请说明理由.24.(12分)以直线AB上一点O为端点作射线OC,将一块直角三角板的直角顶点放在O处(注:∠DOE=90°).(1)如图①,若直角三角板DOE的一边OD放在射线OB上,且∠BOC=60°,求∠COE的度数;(2)如图②,将三板DOE绕O逆时针转动到某个位置时,若恰好满足5∠COD=∠AOE,且∠BOC=60°,求∠BOD 的度数;(3)如图③,将直角三角板DOE绕点O逆时针方向转动到某个位置,若OE恰好平分∠AOC,请说明OD所在射线是∠BOC的平分线.参考答案一、选择题(每小题3分,共30分)1、C【分析】根据图示列出算式,继而计算可得.【详解】解:根据题意可列算式[(-2)-5]×(-2)=(-7)×(-2)=14,故选:C.【点睛】本题主要考查有理数的混合运算,解题的关键是熟练掌握有理数的混合运算顺序和运算法则.2、C【分析】把两式相加,合并同类项得5x3﹣15x2+2,结果不含一次项.【详解】解:2x3﹣10x2+4x﹣1+3x3﹣4x﹣5x2+3=5x3﹣15x2+2,则多项式2x3﹣10x2+4x﹣1与多项式3x3﹣4x﹣5x2+3相加,合并后不含的项是一次项.故选C.【点睛】本题主要考查整式的加法运算,涉及到多项式的定义知识点.3、C【分析】根据等式的基本性质及去括号法则进行判断即可.【详解】若420x -=,则5x =-,故A 错误;若37322x x +=-,则32327x x +=-,故B 错误;若()2105x x x -+=,则2105x x x --=,故C 正确; 若1224x x +-=,则()212x x +=-,故D 错误. 故选:C【点睛】本题考查的是解一元一次方程,掌握等式的基本性质及去括号法则是关键.4、A【解析】A 选项:|-3|=3,-(-3)=3,故这两个数相等;B 选项:-1-(-4)=-1+4=3,故这两个数不相等;C 选项:()23-=9和23-=-9,故这两个数不相等; D 选项:213⎛⎫- ⎪⎝⎭=19和19-,故这两个数不相等; 故选A.5、D 【解析】由题意易得:每名一级技工每天可粉刷的面积为:8503x -m 2,每名二级技工每天可粉刷的面积为:10405x +m 2,根据每名一级技工比二级技工一天多粉刷10m 2,可得方程: 85010401035x x -+=+. 故选D.6、A【分析】根据科学记数法的定义直接求解即可.把一个数表示成a 与10的n 次幂相乘的形式(1≤|a|<10,n 为整数),这种记数法叫做科学记数法.【详解】解:∵435000 3.510=⨯∴将35000用科学记数法表示应为43.510⨯.故选:A.【点睛】本题考查的知识点是科学记数法的定义,表示时关键要正确确定a 的值以及n 的值.在确定n 的值时,看该数是大于或等于1还是小于1.当该数大于或等于1时,n 为它的整数位数减1;当该数小于1时,-n 为它第一个有效数字前0的个数(含小数点前的1个0).7、D【解析】试题分析:∵B 点在正比例函数y=2x 的图象上,横坐标为1,∴y=2×1=2,∴B (1,2),设一次函数解析式为:y=kx+b ,∵过点A 的一次函数的图象过点A (0,1),与正比例函数y=2x 的图象相交于点B (1,2),∴可得出方程组3{2b k b =+=, 解得3{1b k ==-,则这个一次函数的解析式为y=﹣x+1.故选D .考点:1.待定系数法求一次函数解析式2.两条直线相交或平行问题.8、A【分析】答题首先清楚分式的基本性质,然后对各选项进行判断.【详解】解:A 、1122x x x x+--=---,故A 不正确; B 、b a a b c c--+=-,故B 正确; C 、a b a b m m -+-=-,故C 正确; D 、22112323x x x x--=---,故D 正确. 故答案为:A .【点睛】本题主要考查了分式的基本性质,掌握分式的基本性质是解题的关键.9、B【分析】先由条件得到232a a -=,再对所求式子进行变形,最后整体代入计算即可.【详解】由题可得:232a a -=,∴()225265235221a a a a +-=--=-⨯=,故选:B .【点睛】本题考查代数式求值,灵活运用添括号法则进行变形是解题关键.10、C【分析】先根据x 、y 在数轴上的位置判断出x 、y 的符号及绝对值的大小,再去括号,合并同类项即可.【详解】解:∵由图可知,y <0<x ,x >|y|,∴原式=x+y ﹣(x ﹣y )=x+y ﹣x+y=2y .故选C .二、填空题(本大题共有6小题,每小题3分,共18分)11、2234m m +-【分析】根据题意列出算式,利用整式的加减混合运算法则计算出结果.【详解】解:设这个多项式为A,则A=(3m 2+m-1)-(m 2-2m+3)=3m 2+m-1-m 2+2m-3=2m 2+3m-1,故答案为2m 2+3m-1.【点睛】本题考查了整式的加减运算,掌握整式的加减混合运算法则是解题的关键.12、107︒【分析】如图,根据题意可得∠AOE 的度数,然后根据角的和差计算即可.【详解】解:如图,∠AOE =90°-28°=62°,∴∠AOB =∠AOE +∠BOE =62°+45°=107°.故答案为:107°.【点睛】本题考查了方位角的概念和角的和差计算,属于基本题型,熟练掌握基本知识是解题关键.13、-1【分析】把式子展开,找到x 的一次项的所有系数,令其为2,可求出m 的值.【详解】解:∵(x+m )(x+1)=x 2+(m+1)x+1m ,又∵结果中不含x 的一次项,∴m+1=2,解得m=-1.【点睛】本题主要考查了多项式乘多项式的运算,注意当多项式中不含有哪一项时,即这一项的系数为2.14、35°【分析】根据∠AOC =180°-∠BOC ,根据射线OM 是∠AOC 的平分线,可得∠MOA =∠MOC =12∠AOC ,即可求出答案.【详解】∵射线OM 是∠AOC 的平分线,∴∠MOA =∠MOC =12∠AOC , ∵∠AOC =180°-∠BOC =180°-110°=70°,∴∠MOA =12∠AOC =35° 故答案为:35°.【点睛】本题考查了角平分线的性质和邻补角,求出∠AOC 的度数是解题关键.15、()2,3--【分析】先将a ,b 求出来,再根据对称性求出P '坐标即可.【详解】根据题意可得:﹣1=b ,2a -1=1.解得a =2,b =﹣1.P(2,﹣1)关于y 轴对称的点P '(﹣2,﹣1)故答案为: (﹣2,﹣1).【点睛】本题考查了关于坐标轴对称的点的坐标特征,熟练掌握是解题的关键.16、4或1【分析】分当点C 在线段AB 上和点C 在线段AB 的反向延长线上两种情况,根据线段中点的定义、结合图形进行计算即可.【详解】解:若点C 在AB 上,如图1所示,∵6AB cm =,2BC cm =∴AC=AB -BC=4cm∵点D 为线段AC 的中点,∴DC=12AC =1cm ∴DB=DC +BC=4cm ;若点C 在AB 的延长线上,如图1所示∵6AB cm =,2BC cm =∴AC=AB +BC=8cm∵点D 为线段AC 的中点,∴DC=12AC =4cm ∴DB=DC -BC=1cm ;故答案为:4或1.【点睛】本题考查的是两点间的距离的计算,灵活运用数形结合思想、掌握线段中点的定义是解题的关键.三、解下列各题(本大题共8小题,共72分)17、(1)甲,乙;(2)9,7;(3)答案见解析.【解析】()1依据甲和乙的主视图和左视图如图1所示,丙的左视图与图1不符,即可得到结论;()2若几何体的底层有6个小正方体,则几何体最多由9个小正方体组成;若几何体的底层有4个小正方体,则几何体最少由7个小正方体组成;()3依据几何体的底层有4个小正方体,几何体最少由7个小正方体组成,即可得到几何体的俯视图.【详解】()1图2中,甲和乙的主视图和左视图如图1所示,丙的左视图与图1不符,故答案为:甲,乙;()2由图1可得,若几何体的底层有6个小正方体,则几何体最多由9个小正方体组成;若几何体的底层有4个小正方体,则几何体最少由7个小正方体组成;故答案为:9,7;()3符合最少情况时,从上面往下看得到的图形如下:(答案不唯一)【点睛】本题考查了简单组合体的三视图,画简单组合体的三视图要循序渐进,通过仔细观察和想象,再画它的三视图.18、甲的速度是5米/秒,乙的速度是7.5米/秒【分析】设甲的速度是x 米/秒,乙的速度是y 米/秒,根据“如果反向而行,那么他们每隔32秒相遇一次.如果同向而行,那么每隔160秒乙就追上甲一次”,即可得出关于x ,y 的二元一次方程组,解之即可得出结论.【详解】设甲的速度是x 米/秒,乙的速度是y 米/秒,由题意得:()()32400160400x y y x ⎧+=⎪⎨-=⎪⎩解得 :57.5x y =⎧⎨=⎩ 答:甲的速度是5米/秒,乙的速度是7.5米/秒.【点睛】本题考查了二元一次方程组的应用,找准等量关系,正确列出二元一次方程组是解题的关键.19、(1)详见解析;(2)//BC EF ,理由详见解析.【分析】(1)根据线段的和差关系可得AC=DF ,利用SSS 即可证明△ABC ≌△DEF ;(2)根据全等三角形的性质可得∠ACB=∠F ,即可证明BC//EF .【详解】(1)∵AD=CF ,∴AD+CD=CF+CD ,即AC=DF ,在△ABC 和△DEF 中, AB CD BC CF AC DF=⎧⎪=⎨⎪=⎩,∴△ABC ≌△DEF .(2)//BC EF ,理由如下:由(1)可知,ABC DEF △≌△,∴F ACB∠=∠,∴//BC EF.【点睛】本题考查全等三角形的判定与性质及平行线的判定,熟练掌握判定定理是解题关键.20、(1)11(2)5a−b−ab(3)7 2【分析】(1)利用已知的新定义计算即可;(2)利用已知的新定义化简即可;(3)已知等式利用已知的新定义化简计算即可求出x的值.【详解】(1)23-14=2×4−1×(-3)=8+3 =11(2)23-32ab a ba b ab-+--=-2×(2a−b−ab)−3×(ab−3a+b)=-4a+2b+2ab−3ab+9a−3b =5a−b−ab(3)51x+34x=∴5x-3(x+1)=4 ∴5x−3x−3=4∴2x=7∴x=7 2【点睛】此题考查了解一元一次方程,以及有理数的混合运算,理解题中的新定义是解题的关键.21、(1)x=-2 ; (2)x=-2.25【解析】试题分析:按照解一元一次方程的步骤进行运算即可.()1()2106.x x x-+=2106,x x x--=2610,x x x --=510,x -=2.x =-()22211,632x x x -+--=+ ()()222631,x x x --+=+-224633,x x x ---=+-236342,x x x --=-++49.x -=2.25.x =-点睛:解一元一次方程得步骤:去分母,去括号,移项,合并同类项,把系数化为1.22、(1)0.9x ;0.8x+1;(2)51元;(3)第一次是440元,第二次是4元.【分析】(1)根据给出的优惠办法,用含x 的代数式表示出实际付款金额即可;(2)设甲所购物品的原价是y 元,先求出购买原价为10元商品时实际付款金额,比较后可得出y>10,结合(1)的结论即可得出关于y 的一元一次方程,解之即可得出结论;(3)由第二次所购物品的原价高于第一次,可得出第二次所购物品的原价超过10元且第一次所购物品的原价低于10元,设乙第一次所购物品的原价是z 元,则第二次所购物品的原价是(1000-z )元,分0<z≤200、200<z<10两种情况列出关于z 的一元一次方程,解之即可得出结论.【详解】解:(1)当200<x≤10时,实际付款0.9x 元;当x >10时,实际付款10×0.9+0.8(x ﹣10)=(0.8x+1)元. 故答案为0.9x ;0.8x+1.(2)设甲所购物品的原价是y 元,∵490>10×0.9=41, ∴y >10.根据题意得:0.8y+1=490,解得:y=51.答:甲所购物品的原价是51元.(3)∵第二次所购物品的原价高于第一次,∴第二次所购物品的原价超过10元,第一次所购物品的原价低于10元.设乙第一次所购物品的原价是z 元,则第二次所购物品的原价是(1000﹣z )元,①当0<z≤200时,有z+0.8(1000﹣z )+1=894,解得:z=220(舍去);②当200<z <10时,有0.9z+0.8(1000﹣z )+1=894,解得:z=440,∴1000﹣z=4.答:乙第一次所购物品的原价是440元,第二次所购物品的原价是4元.【点睛】考查,列代数式,代数式求值,一元一次方程的应用,读懂题目中的优惠方案是解题的关键.23、(1)点A ,B 所表示的数分别为﹣2,3;(2)①9;②存在;﹣4或1.【分析】(1)由()2230a b ++-=,可得:a +2=0且b ﹣3=0,再解方程可得结论;(2)①先解方程27213x x -=+,再利用数轴上两点间的距离公式可得答案;②设点P 表示的数为m ,所以2,3PA m PB m =+=-,再分三种情况讨论:当m <2-时,(﹣2﹣m )+(3﹣m )=9,当23m -≤≤时,239m m ++-=,当m >3时,+2+39m m -=,通过解方程可得答案.【详解】解:(1)∵()2230a b ++-=, ∴a +2=0且b ﹣3=0,解得a =﹣2,b =3,即点A ,B 所表示的数分别为﹣2,3;(2)① 27213x x -=+, 22163,x x ∴-=+424,x ∴=-解得x =﹣6,∴点C 表示的数为﹣6,∵点B 表示的数为3,∴BC =3﹣(﹣6)=3+6=9,即线段BC 的长为9;② 存在点P ,使PA +PB =BC ,理由如下:设点P 表示的数为m ,2,3,PA m PB m ∴=+=-当m <﹣2时,(﹣2﹣m )+(3﹣m )=9,解得m =﹣4,即当点P 表示的数为﹣4时,使得PA +PB =BC ;当﹣2≤m≤3时,2359m m ++-=≠,故当﹣2≤m≤3时,不存在点P 使得PA +PB =BC ;当m >3时,+2+39m m -=,解得m =1,即当点P 表示的数为1时,使得PA +PB =BC ;由上可得,点P 表示的数为﹣4或1时,使得PA +PB =BC .【点睛】本题考查的是非负数的性质,数轴上两点之间的距离,绝对值的化简,一元一次方程的解法与应用,分类讨论的数学思想,掌握利用分类讨论解决问题是解题的关键.24、 (1) 30°;(2) 65°;(3)见解析. 【解析】分析:(1)根据∠COE+∠DOC=90°求解即可;(2)根据∠BOC+∠COD+∠DOE+∠AOE=180°求解即可;(3)由OE 恰好平分∠AOC ,得∠AOE =∠COE ,再根据平角的定义得∠COE +∠COD=∠AOE +∠BOD =90°即可得证.详解:(1)∵∠DOE =90°,∠BOC =60°, ∴∠COE =∠DOE -∠BOC =30°. (2)设∠COD =x ,则∠AOE =5x.∵∠AOE +∠DOE +∠COD +∠BOC =180°,∠DOE =90°,∠BOC =60°, ∴5x +90°+x +60°=180°,解得x =5°,即∠COD =5°. ∴∠BOD =∠COD +∠BOC =5°+60°=65°. (3)∵OE 平分∠AOC ,∴∠AOE =∠COE.∵∠DOE =∠COE +∠COD =90°,∠AOE +∠DOE +∠BOD =180°, ∴∠AOE +∠BOD =90°,又∠AOE =∠COE ,∴∠COD =∠BOD ,即OD 所在射线是∠BOC 的平分线.点睛:本题主要考查了角平分线定义和角的计算,能根据图形和已知求出各个角的度数是解此题的关键.。
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广东省惠州市第一中学2022-2023学年高一上学期期中考试英语试题学校:___________姓名:___________班级:___________考号:___________一、阅读理解Boston is an excellent place for a family vacation. There are many different fun and educational activities that are sure to interest visitors of all ages.Explore the New England AquariumLocated on the waterfront on the north end of the city, the New England Aquarium draws visitors from around the northeast. This aquarium gives visitors the unique opportunity to pet sharks. The aquarium is home to many kinds of sea life, including dolphins, penguins and seals. With ticket prices at $24.95 for adults and $17.95 for children over the age of three, a visit to the aquarium is an affordable addition to any Boston family vacation.Visit Fenway ParkWhether or not you are a Red Sox fan, a visit to Fenway Park is an absolute must for any Boston family vacation. Baseball is the great American pastime, so if the Red Sox are playing while you are in the city, then you and your family might want to consider getting tickets, buying some hot dogs, and watching one of the best sports displays in the world.Play at the Boston Children’s MuseumIf you have young children in your family, then a Boston family vacation wouldn’t be complete without an afternoon at the Boston Children’s Museum. It is one of the best children’s museums in the nation. It features many different themed rooms, including bubble rooms, construction rooms, a climbing area, and play spaces for little ones who are not yet walking.Dine at Quincy MarketQuincy Market has long been thought of as the social center of the city of Boston. In fact, Quincy Market was the first public market in the entire Boston. At this marketplace you can shop in more than 100 stores and find the perfect souvenirs. It is also a great place to grab a quick and cheap lunch, dinner or snack.1.What can you do at the New England Aquarium?A.Buy souvenirs.B.Play with sharks.C.See polar bears.D.Watch cartoons.2.Which place will you go to if you go in for sports?A.Fenway Park.B.New England Aquarium.C.Quincy Market.D.Boston Children’s Museum.3.What is the text aimed at?A.Encouraging people to visit Boston for vacation.B.Comparing some famous attractions in Boston.C.Telling people what they can do in some places.D.Recommending several places for a family vacation.Marigi worked deep in a forest in Nigeria, a country on the western coast of Africa. He is a logger who cuts down trees using a knife. The forest where he worked is in the Ondo State in Southwest Nigeria. But many trees in that forest have been lost to too much logging.The 61-year-old father of two said that he could cut down over 15 trees anywhere in the forest,but he would be lucky to find only two now.“During the time of my father, we had big trees but sadly what we have now are just small trees and we don’t even allow them to grow tall enough before we cut them,” Marigi said.After cutting down the trees, Marigi puts markers on them to let other loggers know that he is the owner. The cut-down trees, or logs, are then transported(运输)by waterways and rivers to Nigeria’s biggest city, Lagos.Trees in Nigeria are cut down to open land for farming or to feed the energy need of a growing population. From 2001 to 2021, Nigeria has lost 1. 14 million hectares of tree cover.Months after cutting down the trees, Marigi returned to the forest to tie his 40 logs together so they could be transported. With other loggers, he paid for a boat to pull the logs through waterways from Ondo State to Lagos.They built simple houses on top of the logs to help protect themselves from the weather. Food was shared and they sang traditional songs to cheer themselves up. They did not sleep at night to make sure that the logs would not get away from the boat. The boat stopped at several places to pickup more loggers and their logs. A single boat can transport thousands of such logs.Marigi’s trip ended in Lagos where logs from Ondo State and other parts of the country came together. The logs were then cut and sold to users.4.What can we learn about his father according to Marigi?A.He took good care of the forest.B.He could cut down trees for free. C.He left small trees to later generations.D.He had plenty of big trees to cut. 5.How does Marigi show the ownership of the trees he cut down?A.By moving them to his house.B.By making signs on them.C.By putting them near waterways.D.By living on top of them.6.Why did Marigi go back into the forest?A.To collect his woods.B.To plant small trees.C.To look for big trees.D.To open land for farming.7.Why didn’t Marigi and his partners sleep at night?A.Their houses were too small to sleep in.B.They were busy with the woods for sale.C.They protected the woods from being lost.D.They needed to work together continuously.Home to large numbers of elephants, India has some of the strictest elephant protection laws in Asia. Elephants have been granted (给予) the highest level of legal protection for wildlife. Strict bans exist on poaching (偷猎), and trading them, with heavy fines and prison sentences of up to seven years.China had been making efforts to protect its small population of elephants since the 1980s. Local authorities in areas with elephants such as Xishuangbanna Dai Autonomous Prefecture in Yunnan Province, have not only made efforts to move human populations away from elephant habitats but have also worked with private insurance companies to insure farmers’ crops against damage caused by the animals. According to one report, the population of elephants in China nearly doubled between the 1980s and 2021 to about 300.While both India and China have made efforts to protect the elephant and some success had been achieved, danger still appears as conservation laws are often either flouted (轻视) or not implemented. Strengthening domestic (国内的) laws is not enough. The animals now face the much more dangerous threat of climate change which calls for united action by these two leading economies.There are many opportunities for cooperation between New Delhi and Beijing on elephant protection. These could potentially include: formation of a cooperative institute for research on elephant conservation; joint efforts on reforestation to ensure the expansion ofbuffer zones (缓冲区) between animal populations and human settlements; the training of local populations that live near elephant habitats and have traditional knowledge of harmonious living with elephants; formation of a joint resource fund for building care facilities and to achieve set targets to increase the population of elephants through careful breeding.By doing so, India and China would promote economic growth through an ecological path and responsible ecotourism in not just the two nations but in Asia at large. Such joint efforts would also lead to better relations between the two countries.8.What is a measure taken by China to protect elephants according to paragraph 2? A.Applying strict elephant protection laws.B.Resetting humans in other places.C.Growing crops to feed elephants.D.Building natural reserves.9.What made China and India work together to protect elephants?A.The threat of climate change.B.The need of economic growth.C.The focus on scientific research.D.The rapid development of tourism.10.How is paragraph 4 mainly developed?A.By listing examples.B.By stating arguments.C.By explaining numbers.D.By providing research results. 11.Which is the most suitable title for the text?A.Future for Asian elephantsB.A bridge of elephant protectionC.Why are elephants under threat?D.Can elephants and humans live together?Procrastination (拖延症) gets people into trouble--leaving tasks until the very last moment is a Pandora’ s box of anxiety, uncertainty, and panic, but it’s still a popular way of planning our time. The healthier opposite would be to get tasks done as soon as possible, right? Wrong. It’s called precrastination (提前症) and it can be just as unhealthy.Precrastination is not an uncommon phenomenon, driven by the desire to check thingsoff one’s to-do list, in order not to keep in mind those tasks which fill up headspace and become a source of stress. While this tendency might seem positive, it often leads to similar negative results as procrastination. In a 2014 study, college students were asked to carry a bucket (桶) to a finish line in the easiest way possible. They had two choices-- carry the bucket placed halfway down the path, or carry the bucket that was close to the finish line. To the researchers’ surprise, most of the participants chose the bucket closest to them and carried it for a longer time, other than the one closest to the finish line to save themselves some effort.Those college students chose to get started on a task earlier, even if it meant spending more energy in the longer term. And that’s the main problem with precrastination--it enables people to pay attention to urgent, easy-to-do tasks and get them out of the way quickly. But in doing so, people often leave important, more time-and-energy-consuming tasks for later, which they actually should have been saving their efforts for. Another shortcoming to precrastinating is the frenzy (疯狂) that accompanies the satisfaction of getting tasks done early. This hurried frenzy can replace careful planning and thought, ending in the rushed completion of a task often with mistakes.Compared to procrastinators’ low efficiency, hyper-diligence (过度勤奋) is commonly seen in precrastinators. However, the only practice that can actually help people better organize their tasks and lives is careful, strategic planning. Meanwhile, they should get better at saying no, and above all, keep in mind that quality is better than quantity.12.What do we know about precrastination according to the text?A.It’s as unhealthy as procrastination.B.It makes people try to think logically.C.It’s a popular way people use to plan their time.D.It encourages people to do several tasks at the same time.13.What did the researchers find about most participants in the 2014 study?A.They were difficult to satisfy.B.They failed to understand the lecture.C.They avoided carrying the heavier buckets.D.They chose to work hard rather than work cleverly.14.What might come with people’s precrastination?A.Their carelessness.B.Their low interest.C.Their overconfidence.D.Their unnecessary competition.15.What is the author’s suggestion for readers?A.Working at their own rate.B.Valuing quality over quantity.C.Trying to live a productive life.D.Weighing gains and losses wisely.二、七选五Inventing campfire stories for children is easier than you might think. Use these easy tips for telling campfire stories that will entertain and delight children of all ages.____16____When telling campfire stories to children, include a bunch of fun and strange names for the characters. If it is a humorous story, don’t be afraid to use silly things for names, like Snickers or Twix. If it is a scary story, you can use names like Mr. Blue Toes or Mrs. Scissor Arms.Include animal charactersCampfire stories are often the best when they include animals, especially ones that can be found in the woods. Ideas of animals to include are bears, mountain lions, deer, and squirrels. You try to make the bears gentle and the squirrels or deer the more aggressive (好斗的) ones. ____17____Take turnsNo one says that a campfire story has to be told by one person from beginning to end. Take turns. _____18_____This will often result in unforeseen twists and induce tons of laughter.Change your voiceDo not use a single voice when telling campfire stories to children. ____19____ Talk in different tones and use a different infliction for each character. Alternate(交替)between whispering and talking louder.Using these tips will make telling campfire stories fun and exciting. ____20____. Onceyou get going, the kids may beg for more stories, until your voice is sore(疼的). It will be well worth it.A.But be prepared.B.Use fun and strange namesC.Children like listening to stories very much.D.Just have fun and get creative.E.Good for children’s growing upF.One person tells a part of the story and the next person takes over.G.This will make even the best stories dull and uninteresting.三、完形填空Just a few months earlier, I would never have pictured myself acting in a play in front of two hundred people. If not for my___21___, Mrs. Sather, I might never have found that opportunity.In the first and second grade, I was extremely___22___. It just wasn’t in my personality to be very outgoing. I would escape in my writing. Mrs. Sather, always___23___me to write more. I think she was one of the first people to see my inner___24___.One day, she announced our class was going to___25___a play, a take-off on The Wizard of Oz. “I need someone to play the lead part of Dorothy.” A few excited hands were___26___. Mine, of course, was not one of them.After school, Mrs. Sather said to me,“ Dallas, I was___27___you didn’t raise your hand. You’ re good at memorizing things, and you have such a sweet personality. Perfect for Dorothy! I had you in___28___for Dorothy while writing the play! If you___29___don’t want to, though, I won’t make you. It’s your___30___.”I realized it was time to show the world who I really was. I___31___the role.Fast-forward through five months of ___32___, lines memorizing, and costume creating, we were ready.At the end of the play, when the___33___stood and applauded, I knew they were not just___34___for my performance that night, but for the performances that they knew would come in later years because of my new-found___35___.”21.A.partner B.teacher C.parent D.classmate22.A.shy B.weak C.curious D.admirable 23.A.contacted B.allowed C.encouraged D.cheated 24.A.drawback B.peace C.character D.strength 25.A.perform B.watch C.write D.enjoy 26.A.put down B.reached out C.put up D.drew back 27.A.excited B.amused C.afraid D.surprised 28.A.store B.mind C.memory D.comparison 29.A.firstly B.really C.finally D.natively 30.A.turn B.choice C.luck D.fault 31.A.accepted B.played C.created D.remembered 32.A.practicing B.learning C.observing D.communicating 33.A.student B.adult C.police D.audience 34.A.celebrating B.chatting C.cheering D.congratulating 35.A.skill B.confidence C.interest D.hobby四、用单词的适当形式完成短文阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。