广东省汕头市金山中学2019届高三上学期9月月考英语答题卡
广东省汕头市金山中学、广州六中、佛山一中、中山一中2024届高三上学期四校期中联考试题英语含答案解析

2024届高三级11月四校联考英语试题佛山市第一中学、广州市第六中学汕头市金山中学、中山市第一中学试卷总分:120分考试时间:120分钟注意事项:1. 答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
本次考试采用特殊编排考号,请考生正确填涂。
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写在本试卷上无效。
第一部分阅读(共两节,满分50分)第一节(共15小题,每小题2.5分,满分37.5分)阅读下面短文,从每题所给的A、B、C和D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
ABEST BODY FITNESSAbout usYou don’t want just a gym membership. You want a membership that means something. And that means you need support, expert help and a community.Best Body Fitness isn’t just a gym: it’s full-service fitness membership made for you. Here’s how it works:STEP ONE: Your assessmentWe begin with an assessment session. This is a chance for you to see what we do at Best Body. Our assessment plans are no-cost and no-risk. We’ll also make a training plan specifically for you. STEP TWO: Your trainingWhen you decide to become a Best Body member, we show you what to do, how to do it and why you are doing it. After a few sessions with an expert private trainer you will feel comfortable working out on your own.STEP THREE: Your membershipMembership works on a month-to-month basis. There are no sign-up fees and no cancellation fees. Start and stop whenever you want. And the best part? Our fees are the most competitive in the whole downtown area.STEP FOUR: Your communityAt Best Body Fitness, we see everyone as part of a big team. And when you work with a team, you can do great things. Join any of our specialized classes, led by expert trainers. Come to our nutrition classes. Participate in our regular social events. Everything is included in your fee.Finally, we want to share with you some reasons why our members say that they have chosen us over any other fitness centre in the city.It’s so EASYEasy to start, stop, cancel or refund a membership.Easy to access ―we’re open 24/7, we never close.Easy results ― our trainers and equipment give you success, fast.Come and visit us for a personal tour!21. What can one do in the second step?A. Have a full assessment.B. Work with a team.C. Learn from the private trainer.D. Make a training plan.22. If you become a member of this gym, you can ________.A. get refund when you cancel your membershipB. get expert training but you need to pay extra feeC. go to the gym only from 6:00 am to 10:00 pmD. go to the gym only from Monday to Saturday23. What do you think the above passage is?A. A story book.B. A science magazine.C. A TV show.D. An advertisement.BIt’s perhaps the world’s most famous underwater att raction that remained in film and in legend: the Titanic. But now experts say the ocean liner, once a wonder of the high seas, is falling to pieces.Capt. Alfred McLaren, the scientist who in July led the most recent expedition to the ship’s underwater grave, said his team saw clear signs of the accelerating damage of the wreck (残骸). There was damage likely caused by rust and sea life, and the captain’s cabin had collapsed.“I was absolutely astonished,” McLaren said.Worse still, the fallen mast (桅杆) that crushed the ship’s deck is believed by many to be the result of an unapproved salvage (打捞) operation. “It was almost depressing to see how quickly she was getting worse,” McLaren says. “I would be really surprised if there’s very much standing upfrom the bottom, two decades from now.”Ed Kamuda, who runs the Titanic Historical Society in Springfield, Mass., says adventure tourists ― who pay $36,000 each to visit the wreck ― are also contributing to the destruction of it.“This is something I expected. I just didn’t expect it to happen so quickly,” Kamuda said. “People are going down just as an ego trip to say ‘I was there.’ All this takes a fare on the ship.”The Titanic has sat at the bottom of the Atlantic since it sank after hitting an iceberg on its maiden voyage on April 14, 1912. More than 1,500 people died that night. The ship came to rest at the bottom of the freezing North Atlantic, more than 2 miles beneath the waves. The wreck was discovered in 1985, and since then it has been repeatedly visited by treasure hunters.But still some scientists say those divers, and other thrill seekers are not necessarily to blame for the Titanic’s current problems.Capt. Craig McLean of the National Oceanic and Atmospheric Administration went on an expedition to the Titanic in June as part of a government study that is monitoring the condition of the ship. He says it’s unclear what part of the damage is from Mother Nature and which is from human nature.“It’s too early and there isn’t enough evidence to put our fingers on anything,” McLean said.Regardless, most agree there’s little that can be done for this most famous of wrecks. And soon, the mighty Titanic could well be lost again.24.McLaren expected that in twenty years _______.A.Only a minor part of the wreck would remain as it isB.The wreck would be getting worse at a faster speedC.Only salvage operation with the purpose of research would be approvedD.The wreck would be completely destroyed by unapproved treasure hunters25.What is the tourist’s purpose of visiting the w reck, according to Kamuda?A.To contribute to the breaking down of the Titanic.B.To help finance the preservation of the Titanic.C.To satisfy their curiosity and adventurousness.D.To better understand the history of the Titanic.26.Craig McLean is one of the scientists who believe _______.A.Visitors should not be prohibited from the Titanic and other famous wrecksB.The influence of the thrill seekers on the wreck will finally be determinedC.The government should contribute more to the monitoring of the TitanicD.The damage of the Titanic is not necessarily attributed to the adventure tourists27.The author is most likely to agree that the future of the Titanic is _______.A.promisingB. discouragingC. controllableD. vagueCIn department stores and closets all over the world, they are waiting. Their outward appearance seems rather appealing because they come in a variety of styles, patterns, materials, and colors. But they are eventually the biggest deception (欺骗) that exists in the fashion industry today. What are they? They are high heels ― a woman’s worst enemy (whether she knows it or not). High heel shoes are the downfall of modern society. Fashion myths have led women to believe that they are more beautiful or stylish for wearing heels, but in reality, heels succeed in creating short as well as long term troubles. Women should fight the high heel industry by refusing to use or purchase them in order to save the world from unnecessary physical and psychological suffering.For the sake of fairness, it must be noted that there is a positive side to high heels. First, heels are excellent for aerating lawns (草坪通气). Anyone who has ever worn heels on grass knows what I am talking about. A simple trip around the yard in a pair of those babies gets rid of all the need to call for a lawn care specialist, and provides the perfect-sized holes to give any lawn oxygen without all those messy blocks of dirt lying around. Second, heels are quite functional for defending against potential enemies, who can easily be scared away by threatening them with a pair of these sharp, deadly fashion items.Regardless of such practical uses for heels, the fact remains that wearing high heels is harmful to one’s physical health. Talk to any podiatrist (足病医生), and you will hear that the majority of their business comes from high-heel-wearing women. High heels are known to cause problems such as deformed feet and torn toenails. The risk of severe back problems and twisted or broken ankles is three times higher for a high heel wearer than for a flat shoe wearer. Wearing heels also creates the threat of getting a heel caught in a narrow sidewalk gap and being thrown to the ground ― possibly breaking a nose, back, or neck. And of course, after wearing heels for a day, any woman knows she can look forward to a night of pain as she tries to comfort her aching feet.28. Women don’t take the disadvantages of high heels too seriously because of _______.A. their attempt to show off their statusB. the rich variety of high heel stylesC. their wish to improve their appearanceD. the multi-functional use of high heels29. What’s the author’s tone in presenting the positive sides of high heel shoes?A. ironicB. favorableC. sympatheticD. objective30. The writer uses “those babies” (Paragraph 2) to refer to high heels _______.A. to show their fragile characteristicB. to show women’s affection for themC. to emphasize their small sizeD. to indicate their trendy appearance31. It can be inferred from the passage that women should _______.A. refuse to buy the products of the fashion industryB. go to a podiatrist regularly for adviceC. avoid following fashion too closelyD. see through the very nature of fashion mythsDCarried by the wind, dust particles (微粒) from places such as the Sahara Desert can float halfway around the world before settling to the ground. As the plastics abandoned by humans break down into tiny pieces in the environment, they, too, travel through the atmosphere. Now scientists are a step closer to understanding how these microplastics travel in the globe ― both locally and on long-distance flights.Researchers spent more than a year collecting microplastics from 11 national parks and wilderness areas in the western U.S. They examined the particles that settled on dry days and those that fell along with rain or snow. In addition to making clear how microplastics move around, the results, published on Thursday in Science, reveal the seriousness of the problem: more than 1 million kilograms of microplastics ― the weight of 120 million to 300 million plastic water bottles ― fall on protected lands in the country’s western region each year.The new findings add to scientists’ concern over microplastic pollution’s potential impacts o n the environment and human health. “We’re not supposed to breathe in this material,” says Steve Allen, a microplastics researcher at the University of Strathclyde in Scotland, who was not involved in the new study. Plastics in the environment “carry all s orts of pesticides (农药), heavy metals and all the other chemicals that we’ve made over time,” he adds. “They’re going to carry them directly into our lungs.”Since their discovery in oceans in the 1970s, microplastics ― which can be as large as a grain of rice or smaller than a particle of dust ― have been found nearly everywhere researchers have looked: in cities, in Arctic snow, on remote mountaintops. Their presence in areas distant from the place where human live has pointed to them being carried by winds.32.What do the scientists further understand now?A. Why Sahara Desert is expanding to the south of Africa.B. How plastic particles travel on the wind.C. Why it is hard for plastics to break down.D. How dust particles are spreading through the wind.33. What do we know about the new study?A. The results showed the amount of microplastics is huge.B. Researchers collected microplastics across the U.S.C. Researchers focused on plastic particles in dry days.D. Numerous plastic water bottles were found each year.34. What does Steve Allen say about plastics?A. They should be recycled.B. They do harm to weather.C. They can be used to make all sorts of pesticides.D. They carry harmful chemicals to human lungs.35. What would be the best title for the passage?A. Dust Particles Is Harmful to Our LungsB. The Environment Is Threatened by PlasticsC. Microplastics Are Falling from the SkyD. Microplastics Do Harm to Health第二节(共5小题,每小题2.5分,满分12.5分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。
2019届广东省汕头市金山中学高三上学期9月月考试题 语文

2019届广东省汕头市金山中学高三上学期9月月考试题语文(2018.9)本试题满分150分,考试时间150分钟。
★祝你考试顺利★注意事项:1、考试范围:高考考查范围。
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一、现代文阅读(36分)(一)论述类文本阅读(本题共3小题,9分)阅读下面的文字,完成1—3题。
①中国传统文化历来重视诚信教育。
孔子将道德教育置于教育的基础和核心地位,并高度重视诚信教育。
“子以四教:文、行、忠、信”(《论语·述而》),其中的“信”是指传统道德教育的重要内容,教育学生“主忠信”(《论语·学而》),即以诚信教育为主。
②古人的诚信教育首先是在家庭里从蒙学开始,从婴幼儿抓起,以胎教、父范母仪,生活日用及讲故事等多种形式实现诚信教化。
婴幼儿善模仿,父母是儿童的第一任老师,中国古代的父范母仪,特别强调家长对儿童的示范教育。
父母长辈常以讲故事的形式对儿童进行诚信教育。
中国古代的诚信故事俯拾即是,如商鞅立木、季札赠剑、管鲍之谊、范式守信等等;也有不少因不守信用而败德坏身甚至亡国的故事,如周幽王烽火戏诸候,颇具警戒作用。
2019-2020学年汕头市金山中学南区学校高三英语上学期期末考试试题及答案

2019-2020学年汕头市金山中学南区学校高三英语上学期期末考试试题及答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AThis online course is designed to provide you with work-ready skills including responding to job advertisements,writing application letters and resumes(简历)and developing inter-view skills.What topics will it cover?● The recruitment(招聘)and selection process● The job application● Planning for the interview● Developing interview skillsWhat will you achieve?By the end of the course,you'll be able to...● Assess the recruitment and selection process from an employer's point of view● Interpret an advertisement,job description and selection criteria correctly● Model a well-written job application● Plan for a job interviewWho is the course for?While this course appeals to trainees and graduates,it also applies to job seekersin the broader community looking to increasing their confidence and success rate when applying for work.Who develops the course?Central Queensland University.It is Australia's leading regional university.Our courses are designed alongside industry andmany include hands-on learning experiences and project-based learning.Our commitment to making real-world knowledge and skills accessible to all has seen us being awarded global recognition.1. What will students learn if they take the online course?A. The way to write a resume.B. The way to put an advertisement.C. The skills of talking with others.D. The skills of improving reading.2. Who is the online course intended for?A. Trainers.B. Interviewers.C. Job seekers.D. College students.3. Which ofthe following best describes the online course?A Cheap. B. Practical. C. Long-standing. D. World-class.BAfter a year at sea, 16-year-old Laura Dekker can finally say, “Missionaccomplished!” Last month, she finished a daring trip around the world aboard her 38-foot boat, Guppy. Dekker, who is from theNetherlands, traveled more than 30,000 miles all by herself. She is the youngest person ever to sail around the globe alone.Dekker had wanted to lake on this challenge when she was even younger. She first tried to set sail at the age of 13, but a court in theNetherlandsstopped her. They said that she was too young to make such a risky trip by herself. But Dekker insisted she had the navigation skills and patience of an adult sailor.She finally took off on January 20, 2011. During her trip, Dekker battled loneliness, storms, and worries about pirates. But she also got to surf, scuba dive, and started a new hobby: playing the flute. Although Dekker didn’t spend all of her time at sea—she stopped at ports along the way—she did spend her 16lh birthday on the open ocean. To celebrate, she ate doughnuts for breakfast.But Dekker didn’t sail into the record books. Guinness World Records and the World Sailing Speed Record Council no longer recognize records for “youngest” sailors. They dropped the category in 2009 to discourage children fromattempting such dangerous feats (壮举). But that didn’t stop Dekker,who was born on a yacht during a seven-year world voyage undertaken by her parents.Dekker doesn’t mind that she won’t hold an official record. She says it was a personal goal, and she is happy she achieved it.“I am not disappointed at all that Guinness World Record won’t recognize my attempt.” Dekker wrote on her website. “I did not start on my trip to achieve any record…I did it just for myself.”4. Dekker wasn’t allowed to sail at the age of 13 because .A. people were concerned about her safetyB.she didn’t learn any sailing skills wellC. she had to continue her study at schoolD. she didn’t have enough patience for long trips5. What does the underlined word “accomplished” in Paragraph 1 mean?A. Failed.B. Completed.C. Continued.D. Started.6. In 2009 records for youngest sailors were canceled in order to .A. set a higher sailing standard for teen sailorsB. stop children entering Guinness World RecordsC. encourage parents to sail with their childrenD. prevent children making dangerous attempts7. What could be the best title for this passage?A. A New Guinness World Record in SailingB. A New Sailing Standard for Teen SailorsC. A Teen Girl Sailing Alone Aroundthe WorldD. The Youngest Sailor in Guinness World RecordsCHave you ever been on social media and seen your favorite celebrity talking about a product? These promotions might not be totally random, and are actually seen as a vital part of the marketing process. The question is: How do social media influencers ‘influence’ what you buy?Human desire for status and making friends, combined with our need to belong to a group, makes us receptive to being ‘socially influenced’. Companies often use that desire to have a similar lifestyle to a celebrity we admire to sell or launch a product. So, what do these promotions actually do?Firstly, they can be used to build brand awareness. A social media influencer should have a strong understanding of the platform they operate on, and therefore can create appealing content that not only sticks to the brand image, but sparks their followers’ interests in a product they might never have seen before.Secondly, influencers can improve a company or product’s relationship with their customer base. According to InMoment’s 2018 US Retail CX Trends Report on customer loyalty, 77% of buyers have been brand loyal for more than ten years. This is also true of 60% of millennials. A popular celebrity can target key customers and talk or blog about a product, which can create an instant and lasting bond with them.Lastly, influencers can improve customer buying habits with seemingly ‘unbiased opinions’. We are more likely to respond to ‘peer recommendation’ than traditional ads, meaning the fact we see an influencer as a ‘friend’ can make us less likely to be doubtful about what we are seeing.So, the next time you see a celebrity talking about a product, you might want to consider that this could be acarefully worked-out marketing strategy designed to target your core needs. If you find yourself examining a product you’ve seen on social media, you may well have been influenced.8. Why do companies invite celebrities to launch products?A. Because celebrities can improve the companies’ public images.B. Because consumers like to share similarity with celebrities.C. Because celebrities want to make more money.D. Because consumers can make friends with celebrities.9. According to the passage, which strategy is often used by influencers?A. Setting up operation platforms.B. Sending gifts to customers.C. Improving relationship with the company.D. Taking advantage of their popularity.10. To customers, the recommendations of influencers seem to be ________.A. offensiveB. subjectiveC. objectiveD. misleading11. The passage is mainly about ________.A. how social media make adsB. how social media influence our lifestyleC. how social influencers affect our buyingD. how celebrities earn fameDA dog spentthe lastfour years of his life waitingat a crossroad in the Thai city ofKhon Kaenas if waiting for someone. People originally thought the dog had been abandoned, but then realized that he looked healthy, so people asked around about him. It turned out that the dog had indeed been spending most of his time around that crossroad, but a woman had been coming round regularly to bring him food and water.One day, while photographing the dog everyone called Leo, a reporter met the woman who had been taking care of him. She had come to drop off some food. After learning the story about the dog and the woman, the reporter decided to share the story on social media. The post soonwent viraland the photos of Leo got shared hundreds of times. And the photos reached the eyes of Leo’s former old owner.Nang Noi Sittisarn, a 64-year-old woman fromThailand’sRoiEtProvince, almost had a heart attack when her daughter showed her a photo of the beloved dog named BonBon she had lost during a car trip. When she learned that he had been waiting for her in the same spot for the last four years,her heart melted(融化).Auntie Noi told her daughter to drive her to where the dog was waiting. When she got there and called his name. BonBon,the poor dog started wiggling(扭动)his tailand came to her,but when she tried to take him home with her, he was unwilling to follow. She didn’ t want to force the dog to come with her so she agreed to leave himwith his new master. However, she and her daughter will come to visit him regularly.12.Why did the dog look healthy after separation from his former owner?A. He walked around the crossroad constantly.B. He was kept at a woman’s home all the time.C. A local reporter brought him food and water.D. A woman looked after him on a regular basis.13. What does the underlined phrase “went viral” in paragraph 2 probably mean?A. Changed surprisingly.B. Spread quickly.C. Appeared gradually.D. Fell directly.14. How did Nang Noi Sittisam feel about the dog's waiting for her?A. Shocked.B. Regretful.C. Touched.D. Proud.15. What can we mainly learn from the story about the dog?A. Unbelievable success is worth waiting for.B. We should adjust ourselves to environments.C. We need to learn to be faithful and thankful.D. No one knows the result until the last minute第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。
2019届广东省汕头市金山中学高三(上)9月月考数学(文科)试题(解析版)

2019届广东省汕头市金山中学高三(上)9月月考数学(文科)试题数学 注意事项: 1.答题前,先将自己的姓名、准考证号填写在试题卷和答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。
2.选择题的作答:每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑,写在试题卷、草稿纸和答题卡上的非答题区域均无效。
3.非选择题的作答:用签字笔直接答在答题卡上对应的答题区域内。
写在试题卷、草稿纸和答题卡上的非答题区域均无效。
4.考试结束后,请将本试题卷和答题卡一并上交。
一、单选题 1.设全集 ,集合 , ,则 等于 A . B . C . D . 2.已知平面向量 , ,则向量 的模是 A . B . C . D .5 3.下列命题正确的是 A .命题“若 ,则 ”的逆否命题为真命题 B .命题“若 ,则 ”的逆命题为真命题 C .命题“ , ”的否定是“ ” D .“ ”是“ ”的充分不必要条件 4.设{a n }是有正数组成的等比数列, 为其前n 项和。
已知, ,则 A . B . C . D . 5.若函数 为奇函数,则 A . B . C .0 D .2 6.从装有大小材质完全相同的3个红球和3个黑球的不透明口袋中,随机摸出两个小球,则两个小球同色的概率是 此卷只装订不密封 班级 姓名 准考证号 考场号 座位号A.B.C.D.7.已知p为直线上的点,过点p作圆O:的切线,切点为M,N,若,则这样的点p有A.0个B.1个C.2个D.无数个8.某几何体的三视图如图所示,若图中小正方形的边长均为1,则该几何体的体积是A.B.C.D.9.已知函数的周期为,当时,方程恰有两个不同的实数解,,则A.2 B.1 C.D.10.运行如图所示的程序框图,若输出的S的值为480,则判断框中可以填A.B.C.D.11.已知函数,若曲线上存在点使得,则实数a的取值范围是A.B.C.D.12.在四面体ABCD中,,,底面ABC,的面积是6,若该四面体的顶点均在球O的表面上,则球O的表面积是A.B.C.D.13.函数的图象可能是下面的图象______填序号二、填空题14.复数z满足,则复数z的共轭复数______.15.已知实数x,y满足约束条件则的最大值等于______.16.是P为双曲线:上的点,,分别为C的左、右焦点,且,与y轴交于Q点,O为坐标原点,若四边形有内切圆,则C的离心率为______.三、解答题17.在中,内角A,B,C的对边分别为a,b,c,且.求A;若,且的面积为,求的周长.18.如图,三棱柱中,,平面.证明:平面平面;若,,求点到平面的距离.19.已知经销某种商品的电商在任何一个销售季度内,每售出1吨该商品可获利润万元,未售出的商品,每1吨亏损万元根据往年的销售经验,得到一个销售季度内市场需求量的频率分布直方图如图所示已知电商为下一个销售季度筹备了130吨该商品现以单位:吨,表示下一个销售季度的市场需求量,单位:万元表示该电商下一个销售季度内经销该商品获得的利润.Ⅰ根据频率分布直方图,估计一个销售季度内市场需求量x的平均数与中位数的大小;Ⅱ根据直方图估计利润T不少于57万元的概率.20.已知抛物线E:的焦点为F,为x轴上的点.过点P作直线l与E相切,求切线l的方程;如果存在过点F的直线与抛物线交于A,B两点,且直线PA与PB的倾斜角互补,求实数a的取值范围.21.已知函数,.求函数的单调递增区间;若,,且,,,求实数a的取值范围.22.已知圆C的极坐标方程为,直线l的参数方程为为参数,点A的极坐标为,设直线l与圆C交于点P、Q两点.写出圆C的直角坐标方程;求的值.23.已知函数.解不等式;若关于x的不等式只有一个正整数解,求实数a的取值范围.2019届广东省汕头市金山中学高三(上)9月月考数学(文科)试题数学答案参考答案1.C【解析】由A中的不等式变形得:2x>1=20,得到x>0,即A=(0,+∞),∵全集U=R,∴∁U A=(﹣∞,0],由B中的不等式变形得:﹣ ≤x﹣ ≤ ,即﹣ ≤x≤ ,∴B=[﹣1,5],则(∁U A)∩B=[﹣1,0].故选:C.2.C【解析】因为向量,,,,故选C.3.A【解析】对于A,原命题为真命题,∴逆否命题为真命题,故正确;对于B,逆命题为“若,则”,当时不成立,故错误;对于C,命题“”的否定是“”,故错误;对于D,由得到,∴“”是“”的必要不充分条件,故错误,故选:A4.【解析】5.D【解析】【分析】求出的值,从而求出的值即可.【详解】设,则,故,故时,,由,故,故选:D.【点睛】本题考查了函数求值问题,考查函数的奇偶性问题,是一道基础题.6.C【解析】记个红球分别为,个黑球分别为,则随机取出两个小球共有种可能:,其中两个小球同色共有种可能,,根据古典概型概率公式可得所求概率为,故选C.【方法点睛】本题主要考查古典概型概率公式的应用,属于难题,利用古典概型概率公式求概率时,找准基本事件个数是解题的关键,基本亊件的探求方法有(1)枚举法:适合给定的基本事件个数较少且易一一列举出的;(2)树状图法:适合于较为复杂的问题中的基本亊件的探求.在找基本事件个数时,一定要按顺序逐个写出:先,…. ,再,…..依次….… 这样才能避免多写、漏写现象的发生.7.B【解析】连接,则四边形为正方形,因为圆的半径为,,原点(圆心)到直线距离为符合条件的只有一个,故选B.8.B【解析】该几何体是直三棱柱和半圆锥的组合体,其中三棱柱的高为2,底面是高和底边均为4的等腰三角形,圆锥的高为4,底面半径为2,则其体积为,.故选:B点睛:由三视图画出直观图的步骤和思考方法:1、首先看俯视图,根据俯视图画出几何体地面的直观图;2、观察正视图和侧视图找到几何体前、后、左、右的高度;3、画出整体,然后再根据三视图进行调整.9.B【解析】函数,由周期,可得,,,且的对称轴为,方程恰有两个不同的实数解,,则,故选B.10.B【解析】执行一次,,执行第2次,,执行第3次,,执行第4次,,执行第5次,,执行第6次,,执行第7次,跳出循环,因此判断框应填,故选B.11.B【解析】因为曲线在上递增,所以曲线上存在点,可知,由,可得,而在上单调递减,,故选B.12.D【解析】四面体 与球 的位置关系如图所示,设 为 的中点, 为 外接球的圆心,因为 , ,由余弦定理可得,由正弦定理可得 由勾股定理可得 ,又, ,在四边形 中, , ,计算可得 + = ,则球 的表面积是 = ,故选D.【方法点晴】本题主要考查球的性质及圆内接三角形的性质、正弦定理与余弦定理法应用及球的表面积公式,属于难题.球内接多面体问题是将多面体和旋转体相结合的题型,既能考查旋转体的对称形又能考查多面体的各种位置关系,做题过程中主要注意以下两点:①多面体每个面都分别在一个圆面上,圆心是多边形外接圆圆心;②注意运用性质 .13.C【解析】因为,所以函数 的图象关于点(2,0)对称,排除A ,B 。
广东省汕头市金山中学2018_2019学年高一英语上学期10月月考试题201901080230

广东省汕头市金山中学2018-2019学年高一英语上学期10月月考试题第一卷选择题部分(满分95分)第一部分英语知识运用 (共二节,满分55分)第一节单项填空 (共25小题;每小题1分,满分25分)从每题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
1. I am tired _____ the partner I have been working with; he is too hard aperson______.A. with; to get along withB. from; to be got along withC. of; to get along withD. of; getting along with2. They became good friends during the war, and since then their lifelongfriendship has______ tests oflife and death.A. looked throughB. cleared upC. stood upD.gone through3. The engine of the ship was out of order and the bad weather ____ thehelplessness of the crew at sea.A. calmed downB. set downC. added toD. added4. ___________ with any danger, you should keep ___________.A. Facing; quietB. Facing; stillC. Faced; calmD.Faced; silent5. It’s not until mid-night ______ the baby stopped crying.A. whenB. thatC. whichD. while6. ---What do you think of my article, professor?---The former part is well written but _____ part is just so so.A. the laterB. the lastC. the latestD. thelatter7. You won’t be able to make ________ of a word until you know all the _____of it.A. use; usesB. usage; usagesC. use; usagesD.usage; uses8. Judging from her _________, I guess she must come from the West of America.A. voiceB. soundC. noiseD. accent9. We won’t give up ___________ we should fail 100 times.A. as ifB. evenC. ifD. even if10. Many questions __________ at the meeting, but he answered none.A. raisedB. roseC. came upD.came about11. While _____ the dog, you should take care not to _______; otherwise, itwill be dangerous to others.A. walked; get looseB. walks; be looseC. walking; get it looseD. walk; run loose12. That guy caught________ in the exam once cheated me _______ my money.A. cheated…ofB. cheating…outC. cheating…ofD.cheated…out13. There is no _________swimming pool in this school and the students oftengo to swim _________.A. indoor; outdoorsB. indoors; outdoorsC. indoor; outdoorD.indoors; outdoor14. While the hostess was getting me _______ into a tiny but clean room, herhusband tried to prepare some food for me.A. settleB. settlingC. settledD. besettled15. It was the first time that she ______________ gone to the summer camp inShanghai, so her parents were concerned __________ her safety.A. had; aboutB. had; withC. has; withD.has; about16. __________ let him have a rest, we suggest he______________ off the meetinguntil next Monday.A. In order to; putB. In order to; puttingC. So as to; putD. Soas to; putting17. It was the training ____________ he had as a teenager _________ made himsuch a good engineer.A. that; thatB. what; thatC. that; whoD. that;which18. The roof fell ____________he had time to dash into the room to save hisbaby.A. beforeB. after C, until D. unless19. There is ______ is called Mr. Smith in our workshop.A. no such man asB. no such a man asC. no such manD. no sucha man that20. With our knowledge _________ on knowledge, we can make a contribution tosociety.A. basedB. is on the basis ofC. being basedD.basing21. Before Sam can repair his bicycle, he must know why it does not work. Forexample, he must ______ the parts that are wrong.A. retellB. correctC. determineD.decide22. Challenges may _________ as stepping-stones towards success.A. useB. serveC. meanD. aim23. He ignored his family, so he was always the _________ person his son waswilling to ask for help.A. firstB. lastC. rightD. very24. Set out ahead of time, _______you are much less likely to miss the bus.A. orB. andC. beforeD. if25. Being ________ in a language will take years, but learning to get by takes_______.A. frequent; a lot moreB. fluent; a lot moreC. fluent; a lot lessD.frequent ; a lot less第二节完形填空(共20小题;每小题1.5分,满分30分)阅读下面短文,掌握其段落大意,然后从每题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
广东省汕头市金山中学2019届高三上学期9月月考试题数学(文)Word版含答案

2019届高三第一学期文科数学月考考试、选择题:本大题共 12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项 是符合题目要求的•1.设全集错误!未找到引用源。
,集合错误!未找到引用源。
,错误!未找到引用源。
,则错误! 未找到引用源。
等于A .错误!未找到引用源。
B .错误!未找到引用源。
C .错误!未找到引用源。
D . [0, 5]2. 已知平面向量 , 心二m ,则向量 的模是A. B. .. C. . D.3. 卜列命题正确的是A. 命题"若J. J;,则m y :】.:”的逆否命题为真命题B. 命题“若 ,则 .”的逆命题为真命题 C •命题“…,”的否定是“ •,”D.”是“心十①-江”的充分不必要条件 4.设{a n }是由正数组成的等比数列,Sn 为其前n 项和,已知a ?a 4 = 1, S 3 = 7 ,则S 5等于A. B. C. D.:个红球和■■个黑球的不透明口袋中,随机摸出两个小球,则两个 小球同色的概率是2 12 1 A. B.C.D.32537. 已知P 为直线汽〔:上的点,过点P 作圆 …「-的切线,切点为I ,,若 H --尤 则这样的点P 有A.个B. I 个C. •个D. 无数个8. 某几何体的三视图如图所示,若图中小正方形的边长均为A. 31 415C.33 5. 若函数I :-:;17 22_X -23X < ag(x)h x > 0 为奇函数,则 K -6.从装有大小材质完全相同的 ,则该几何体的体积是CB D否A■出$C 13 14 1532 8•: DA.B32 16A. DC.,则 A. B.C. -iD.9.已知函数 f(x) =2 .3sin X cos —X 2cos 2 X -1( :,0)2 2 210.运行如图所示的程序框图,若输出的S 的值为480,则判断框中可以填 A . i 60 B . i 70 C、填空题(每题 5分,满分20分,将答案填在答题纸上)2 2是 为双曲线C : x 2 与=1(a, b 0)上的点,, 分别为 的左、右焦点,且[时,方程in 恰有两个不同的实数解i 80 Di 9011.已知函数:.-.1 ,- 2-. ■,若曲线■' .. |上存在点 使得,'' =,则实数 的取值范围是12.在四面体 丄:、.「中, " = , V-底面注, 的表面积是 复数 满足:J '■ : <■/ -',则复数 的共轭复数已知实数,满足约束条件2x-y < x-3y+ 5 > 0,A.:怕."- |>: } : <■:<B. (-cc,e 3-9) U (e + 3,十«?)二丨」一的面积是,若该四面体的顶点均在球的表面上,则球开孙则 的最大值是5=200 b i-10兀 m,,与轴交于点,为坐标原点,若四边形.有内切圆,贝y 的离心率为(1)(2) (3)(4)三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17. (12 分)在冲,内角,卜:,的对边分别为,卜,,且'■■■I ■ ■(1)求;(2)若,且;七二的面积为..,求區匸三二的周长.18. (12 分)如图,三棱柱:任二二f 中,•上匚八-乂,平面.(1)证明:平面忆三〕.平面;(2)若卞―,];;求点至呼面一乂的距离.B19. (12分)已知经销某种商品的电商在任何一个销售季度内,每售出】吨该商品可获利润万元,未售出的商品,每】吨亏损J三万元•根据往年的销售经验,得到一个销售季度内市场需求量的频率分布直方图,如下图所示.已知电商为下一个销售季度筹备了丄2□吨该商品.现以x (单位:吨,100 ■: X “ 150)表示下一个销售季度的市场需求量,T (单位:万元)表示该电商下一个销售季度内经销该商品获得的利润.(I)根据频率分布直方图,估计一个销售季度内市场需求量x的平均数与中位数的大小; (n)根据直方图估计利润T不少于57万元的概率•频車/组距\oo 110 120130 M020. (12分)已知抛物线E:x2=4y的焦点为F , P(a,0)为x轴上的点.(1)过点P作直线I与E相切,求切线I的方程;(2)如果存在过点F的直线「与抛物线交于A, B两点,且直线PA与PB的倾斜角互补,求实数a的取值范围.21. (12 分)已知函数f(x)=(x-2)e x, x (0, ::) •(1)求函数f(x)的单调递增区间;(2)若g(x)二f (x) 2e x-ax2, h(x) = x,且-x1, x20,::, g(xj-h(xj Hg(x2) - h(x2)丨0,求实数a的取值范围.请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分 选修4-4 :坐标系与参数方程i 3 Xt 22. (10分)已知圆C 的极坐标方程为亍=2cosv ,直线I 的参数方程为 22( t 为参1 1 y t I2 2(I )写出圆C 的直角坐标方程;(II )求 | AP| | AQ| 的值.选修4-5 :不等式选讲 23. (10 分)已知函数■: -'■: I .(1) 解不等式;(2) 若关于 的不等式只有一个正整数解,求实数的取值范围高三月考文数参考答案一、 选择题CCAAD CBBBB BD 、填空题三、解答案• sinCccsB 十 sinBcosC = 2sinAc0sA.•.•II :.;yr..'.:- ■.数),点A 的极坐标为设直线I 与圆C 交于点P,Q ;13、仁③ 14、815、2 16、( 3)17、TI •••—(2)T _ "的面积为.' .、,•. I;.' r.2 4兀由一儿及:I、十”甕m得.斤…!,「+:::.又i •:打「•丨•:一j.故其周长为.18、(1)证明:•••平面W.':• •川I I 平面厶二笃A-.又 '平面/:亡£,.・.平面. 平面.(2)解法一:取的中点,连接.A[% = A[C,.・.A]D 丄AC.又平面止三7 •平面,且交线为.,则、|一平面••••;】!平面容•二,■,•四边形' '|为菱形,.兰4.-'-.又:耳七;,••••—、二是边长为正三角形,•.:.设点至序面&E二的距离为.. I p2^3 \贝则、I、;严’.j 山:::丫. - 广.■〔I?:.所以点到平面二的距离为•:.19、(I)估计一个销售季度内市场需求量工的平均数为x = 105 x 0,1 ■+ 115 x 0,2 十125 x 03 十135 x 0,25 十145 x 0.15 = 126,5 (吨)设所求中位数为k,由直方图建立方程:0.01 10 0.02 10 - (k -120) 0.03=0.5解得 k =120126.73即估计一个销售季度内市场需求量工的中位数为126.7。
广东省汕头市金山中学2019届高三(上)9月月考数学(文科)试卷 Word版含解析
努力的你,未来可期!2019届广东省汕头市金山中学 高三(上)9月月考数学(文科)试题数学注意事项:1.答题前,先将自己的姓名、准考证号填写在试题卷和答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。
2.选择题的作答:每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑,写在试题卷、草稿纸和答题卡上的非答题区域均无效。
3.非选择题的作答:用签字笔直接答在答题卡上对应的答题区域内。
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一、单选题1.设全集U =R ,集合A ={x|2x>1},B ={x||x −2|≤3},则(∁U A)∩B 等于 A .[−1,0) B .(0,5] C .[−1,0] D .[0,5] 2.已知平面向量AB ⃗⃗⃗⃗⃗ =(1,2),AC ⃗⃗⃗⃗⃗ =(3,4),则向量CB ⃗⃗⃗⃗⃗ 的模是 A .√2 B .√5 C .2√2 D .5 3.下列命题正确的是A .命题“若α=β,则sinα=sinβ”的逆否命题为真命题B .命题“若a <b ,则ac 2≤bc 2”的逆命题为真命题C .命题“∀x >0,5x >0”的否定是“∃x 0≤0,5x 0≤0”D .“x <−1”是“ln(x +2)<0”的充分不必要条件4.设{a n }是有正数组成的等比数列,S n 为其前n 项和。
已知,S 3=7,则S 5=A .152B .314C .334D .1725.若函数f(x)={g(x),x >02−x −2,x<0为奇函数,则f(g(2))= A .−2 B .−1 C .0 D .26.从装有大小材质完全相同的3个红球和3个黑球的不透明口袋中,随机摸出两个小球,则两个小球同色的概率是A .23 B .12 C .25 D .137.已知p 为直线x +y −2=0上的点,过点p 作圆O :x 2+y 2=1的切线,切点为M ,N ,若∠MPN =90∘,则这样的点p 有A .0个B .1个C .2个D .无数个8.某几何体的三视图如图所示,若图中小正方形的边长均为1,则该几何体的体积是A .16+163π B .16+83π C .323+83π D .323+163π9.已知函数f(x)=2√3sin ωx 2cosωx 2+2cos 2ωx 2−1(ω>0)的周期为π,当x ∈[0,π2]时,方程f(x)=m 恰有两个不同的实数解x 1,x 2,则f(x 1+x 2)=A .2B .1C .−1D .−210.运行如图所示的程序框图,若输出的S 的值为480,则判断框中可以填A .i >60B .i >70C .i >80D .i >9011.已知函数f(x)=e −x −2x −a ,若曲线y =x 3+x +1(x ∈[−1,1])上存在点(x 0,y 0)使得f(y 0)=y 0,则实数a 的取值范围是A .(−∞,e −3−9]∪[e +3,+∞)B .[e −3−9,e +3]C .(e −3−9,e 2+6)D .(−∞,e −3−9)∪(e +3,+∞)此卷只装订不密封班级 姓名 准考证号 考场号 座位号12.在四面体ABCD中,AB=AC=2√3,BC=6,AD⊥底面ABC,△DBC的面积是6,若该四面体的顶点均在球O的表面上,则球O的表面积是A.24πB.32πC.46πD.49π13.函数f(x)=ln(x2−4x+4)(x−2)3的图象可能是下面的图象______(填序号)二、填空题14.复数z满足(1−2i)z=7+i,则复数z的共轭复数z=______.15.已知实数x,y满足约束条件{2x−y≤0x−3y+5≥0y≥1则z=(12)x+y−2的最大值等于______.16.是P为双曲线C:x2a2−y2b2=1(a,b>0)上的点,F1,F2分别为C的左、右焦点,且PF2⊥F1F2,PF1与y轴交于Q点,O为坐标原点,若四边形OF2PQ有内切圆,则C的离心率为______.三、解答题17.在△ABC中,内角A,B,C的对边分别为a,b,c,且ccosB+bcosC=2acosA.(1)求A;(2)若a=2,且△ABC的面积为√3,求△ABC的周长.18.如图,三棱柱ABC−A1B1C1中,∠BCA=90∘,AC1⊥平面A1BC.(1)证明:平面ABC⊥平面ACC1A1;(2)若BC=AC=2,A1A=A1C,求点B1到平面A1BC的距离.19.已知经销某种商品的电商在任何一个销售季度内,每售出1吨该商品可获利润0.5万元,未售出的商品,每1吨亏损0.3万元.根据往年的销售经验,得到一个销售季度内市场需求量的频率分布直方图如图所示.已知电商为下一个销售季度筹备了130吨该商品.现以x(单位:吨,100≤x≤150)表示下一个销售季度的市场需求量,T(单位:万元)表示该电商下一个销售季度内经销该商品获得的利润.(Ⅰ)根据频率分布直方图,估计一个销售季度内市场需求量x的平均数与中位数的大小;(Ⅱ)根据直方图估计利润T不少于57万元的概率.20.已知抛物线E:x2=4y的焦点为F,P(a,0)为x轴上的点.(1)过点P作直线l与E相切,求切线l的方程;(2)如果存在过点F的直线l′与抛物线交于A,B两点,且直线PA与PB的倾斜角互补,求实数a的取值范围.21.已知函数f(x)=(x−2)e x,x∈(0,+∞).(1)求函数f(x)的单调递增区间;(2)若g(x)=f(x)+2e x−ax2,ℎ(x)=x,且∀x1,x2,[g(x1)−ℎ(x1)][g(x2)−ℎ(x2)]>0,求实数a的取值范围.22.已知圆C的极坐标方程为ρ=2cosθ,直线l的参数方程为{x=12+√32ty=12+12t(t为参数),点A的极坐标为(√22,π4),设直线l与圆C交于点P、Q两点.(1)写出圆C的直角坐标方程;(2)求|AP|⋅|AQ|的值.23.已知函数f(x)=|x+2|−2|x−1|.(1)解不等式f(x)≤1;(2)若关于x的不等式f(x)>ax只有一个正整数解,求实数a的取值范围.2019届广东省汕头市金山中学 高三(上)9月月考数学(文科)试题数学 答 案参考答案 1.C 【解析】由A 中的不等式变形得:2x >1=20,得到x >0,即A=(0,+∞), ∵全集U=R ,∴∁U A=(﹣∞,0],由B 中的不等式变形得:﹣3≤x ﹣2≤3,即﹣1≤x≤5, ∴B=[﹣1,5],则(∁U A )∩B=[﹣1,0]. 故选:C . 2.C 【解析】因为向量AB ⃗⃗⃗⃗⃗ =(1,2),AC ⃗⃗⃗⃗⃗ =(3,4),∴CB ⃗⃗⃗⃗⃗ =AB ⃗⃗⃗⃗⃗ −AC ⃗⃗⃗⃗⃗ =(1,2)−(3,4)=(−2,−2),∴|CB ⃗⃗⃗⃗⃗ |=2√2,故选C.3.A 【解析】对于A ,原命题为真命题,∴逆否命题为真命题,故正确;对于B,逆命题为“若ac 2≤bc 2,则a <b ”,当c =0时不成立,故错误; 对于C ,命题“∀x >0,5x >0”的否定是“∃x 0>0,5x 0≤0”,故错误;对于D ,由ln (x +2)<0得到−2<x <1,∴“x <−1”是“ln (x +2)<0”的必要不充分条件,故错误,故选:A4. 【解析】 5.D 【解析】 【分析】求出g(2)的值,从而求出f(g(2))的值即可. 【详解】设x >0,则−x <0, 故f(−x)=2x −2=−f(x), 故x >0时,f(x)=2−2x , 由g(2)=f(2)=2−4=−2, 故f(g(2))=f(−2)=−f(2)=2, 故选:D . 【点睛】本题考查了函数求值问题,考查函数的奇偶性问题,是一道基础题. 6.C 【解析】记3个红球分别为a,b,c ,3个黑球分别为x,y,z ,则随机取出两个小球共有15种可能:ab,ac,ax,ay,az,bc,bx,by,bz,cx,cy,cz,xy,xz,yz ,其中两个小球同色共有6种可能,ab,ac,bc,xy,xz,yz ,根据古典概型概率公式可得所求概率为615=25,故选C.【方法点睛】本题主要考查古典概型概率公式的应用,属于难题,利用古典概型概率公式求概率时,找准基本事件个数是解题的关键,基本亊件的探求方法有 (1)枚举法:适合给定的基本事件个数较少且易一一列举出的;(2)树状图法:适合于较为复杂的问题中的基本亊件的探求.在找基本事件个数时,一定要按顺序逐个写出:先(A 1,B 1),(A 1,B 2)…. (A 1,B n ),再(A 2,B 1),(A 2,B 2)…..(A 2,B n )依次(A 3,B 1) (A 3,B 2)….(A 3,B n )… 这样才能避免多写、漏写现象的发生.7.B 【解析】连接OM,ON ,则∠MPN =∠ONP =∠OMP =90∘,∴四边形OMPN 为正方形,因为圆的半径为1,∴|OP |=√2,∵原点(圆心)O 到直线x +y −2=0距离为√2,∴符合条件的P 只有一个,故选B.8.B 【解析】该几何体是直三棱柱和半圆锥的组合体,其中三棱柱的高为2,底面是高和底边均为4的等腰三角形,圆锥的高为4,底面半径为2,则其体积为V =12×4×4×2+12×13×π×4×4,=16+83π.故选:B点睛:由三视图画出直观图的步骤和思考方法:1、首先看俯视图,根据俯视图画出几何体地面的直观图;2、观察正视图和侧视图找到几何体前、后、左、右的高度;3、画出整体,然后再根据三视图进行调整.9.B【解析】函数f (x )=2√3sinωx 2cosωx 2+2cos 2ωx 2−1 =√3sinωx +cosωx =2sin (ωx +π6),由周期T =2πω=π,可得ω=2,∴f (x )=2sin (2x +π6),∵x ∈[0,π2],∴π6≤2x +π6≤7π6,∴−1≤f (x )≤2,且f (x )的对称轴为x =π6,∵方程f (x )=m 恰有两个不同的实数解x 1,x 2,∴x 1+x 2=π3,则f (x 1+x 2)=f (π3)=2sin (2π3+π6)=2sin 5π6=1,故选B.10.B 【解析】执行一次,S =200+10,i =20,执行第2次,S =200+10+20,i =30,执行第3次,S =200+10+20+30,i =40,执行第4次,S =260+40,i =50,执行第5次,S =300+50,i =60,执行第6次,S =350+60,i =70,执行第7次,S =410+70,i =80跳出循环,因此判断框应填i >70,故选B.11.B 【解析】因为曲线y =x 3+x +1在(x ∈[−1,1])上递增,所以曲线y =x 3+x +1(x ∈[−1,1])上存在点(x 0,y 0), 可知y 0∈[−1,3],由f (y 0)=y 0,可得y 0=e −y 0−2y 0−a,∴a =e −y 0−3y 0,而a =e −y 0−3y 0在[−1,3]上单调递减,∴a ∈[e −3−9,e +3],故选B.12.D 【解析】四面体ABCD 与球O 的位置关系如图所示,设E 为BC 的中点,O 1为ΔABC 外接球的圆心,因为AB =AC =2√3,BC =6,由余弦定理可得∠BAC =2π3,由正弦定理可得2AO 1=√32=4√3,AO 1=2√3由勾股定理可得AE =√3,又S ΔDBC =12×DE ×BC =6,∴DE =2,∴AD =√DE 2−AE 2=√4−3=1,在四边形OO 1AD 中,OO 1//AD,∠OO 1A =90∘,OA =OD ,计算可得R 2=OA 2=(2√3)2+(12)2=494,则球O 的表面积是4π×494=49π,故选D.【方法点晴】本题主要考查球的性质及圆内接三角形的性质、正弦定理与余弦定理法应用及球的表面积公式,属于难题.球内接多面体问题是将多面体和旋转体相结合的题型,既能考查旋转体的对称形又能考查多面体的各种位置关系,做题过程中主要注意以下两点:①多面体每个面都分别在一个圆面上,圆心是多边形外接圆圆心;②注意运用性质R 2=r 2+OO 12.13.C 【解析】 因为f (x )=ln (x 2−4x+4)(x−2)3=ln (x−2)2(x−2)3,所以函数f (x )的图象关于点(2,0)对称,排除A ,B 。
【全国名校】2019届广东省汕头市金山中学高三(上)9月月考数学(文科)试题(解析版)
2019届广东省汕头市金山中学 高三(上)9月月考数学(文科)试题数学注意事项:1.答题前,先将自己的姓名、准考证号填写在试题卷和答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。
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一、单选题1.设全集 ,集合, ,则 等于 A . B . C . D . 2.已知平面向量, ,则向量 的模是 A . B . C . D .5 3.下列命题正确的是A .命题“若 ,则 ”的逆否命题为真命题B .命题“若 ,则 ”的逆命题为真命题C .命题“ , ”的否定是“ ”D .“ ”是“ ”的充分不必要条件4.设{a n }是有正数组成的等比数列, 为其前n 项和。
已知, ,则A .B .C .D .5.若函数为奇函数,则 A . B . C .0 D .26.从装有大小材质完全相同的3个红球和3个黑球的不透明口袋中,随机摸出两个小球,则两个小球同色的概率是A .B .C .D .7.已知p 为直线 上的点,过点p 作圆O : 的切线,切点为M ,N ,若 ,则这样的点p 有A .0个B .1个C .2个D .无数个8.某几何体的三视图如图所示,若图中小正方形的边长均为1,则该几何体的体积是A .B .C .D .9.已知函数的周期为 ,当时,方程恰有两个不同的实数解 , ,则A .2B .1C .D .10.运行如图所示的程序框图,若输出的S 的值为480,则判断框中可以填A .B .C .D .11.已知函数 ,若曲线 上存在点 使得 ,则实数a 的取值范围是A .B .C .D .此卷只装订不密封班级 姓名 准考证号 考场号 座位号12.在四面体ABCD中,,,底面ABC,的面积是6,若该四面体的顶点均在球O的表面上,则球O的表面积是A.B.C.D.13.函数的图象可能是下面的图象______填序号二、填空题14.复数z满足,则复数z的共轭复数______.15.已知实数x,y满足约束条件则的最大值等于______.16.是P为双曲线:上的点,,分别为C的左、右焦点,且,与y轴交于Q点,O为坐标原点,若四边形有内切圆,则C的离心率为______.三、解答题17.在中,内角A,B,C的对边分别为a,b,c,且.求A;若,且的面积为,求的周长.18.如图,三棱柱中,,平面.证明:平面平面;若,,求点到平面的距离.19.已知经销某种商品的电商在任何一个销售季度内,每售出1吨该商品可获利润万元,未售出的商品,每1吨亏损万元根据往年的销售经验,得到一个销售季度内市场需求量的频率分布直方图如图所示已知电商为下一个销售季度筹备了130吨该商品现以单位:吨,表示下一个销售季度的市场需求量,单位:万元表示该电商下一个销售季度内经销该商品获得的利润.Ⅰ根据频率分布直方图,估计一个销售季度内市场需求量x的平均数与中位数的大小;Ⅱ根据直方图估计利润T不少于57万元的概率.20.已知抛物线E:的焦点为F,为x轴上的点.过点P作直线l与E相切,求切线l的方程;如果存在过点F的直线与抛物线交于A,B两点,且直线PA与PB的倾斜角互补,求实数a的取值范围.21.已知函数,.求函数的单调递增区间;若,,且,,,求实数a的取值范围.22.已知圆C的极坐标方程为,直线l的参数方程为为参数,点A的极坐标为,设直线l与圆C交于点P、Q两点.写出圆C的直角坐标方程;求的值.23.已知函数.解不等式;若关于x的不等式只有一个正整数解,求实数a的取值范围.2019届广东省汕头市金山中学高三(上)9月月考数学(文科)试题数学答案参考答案1.C【解析】由A中的不等式变形得:2x>1=20,得到x>0,即A=(0,+∞),∵全集U=R,∴∁U A=(﹣∞,0],由B中的不等式变形得:﹣ ≤x﹣ ≤ ,即﹣ ≤x≤ ,∴B=[﹣1,5],则(∁U A)∩B=[﹣1,0].故选:C.2.C【解析】因为向量,,,,故选C.3.A【解析】对于A,原命题为真命题,∴逆否命题为真命题,故正确;对于B,逆命题为“若,则”,当时不成立,故错误;对于C,命题“”的否定是“”,故错误;对于D,由得到,∴“”是“”的必要不充分条件,故错误,故选:A4.【解析】5.D【解析】【分析】求出的值,从而求出的值即可.【详解】设,则,故,故时,,由,故,故选:D.【点睛】本题考查了函数求值问题,考查函数的奇偶性问题,是一道基础题.6.C【解析】记个红球分别为,个黑球分别为,则随机取出两个小球共有种可能:,其中两个小球同色共有种可能,,根据古典概型概率公式可得所求概率为,故选C.【方法点睛】本题主要考查古典概型概率公式的应用,属于难题,利用古典概型概率公式求概率时,找准基本事件个数是解题的关键,基本亊件的探求方法有(1)枚举法:适合给定的基本事件个数较少且易一一列举出的;(2)树状图法:适合于较为复杂的问题中的基本亊件的探求.在找基本事件个数时,一定要按顺序逐个写出:先,…. ,再,…..依次….… 这样才能避免多写、漏写现象的发生.7.B【解析】连接,则四边形为正方形,因为圆的半径为,,原点(圆心)到直线距离为符合条件的只有一个,故选B.8.B【解析】该几何体是直三棱柱和半圆锥的组合体,其中三棱柱的高为2,底面是高和底边均为4的等腰三角形,圆锥的高为4,底面半径为2,则其体积为,.故选:B点睛:由三视图画出直观图的步骤和思考方法:1、首先看俯视图,根据俯视图画出几何体地面的直观图;2、观察正视图和侧视图找到几何体前、后、左、右的高度;3、画出整体,然后再根据三视图进行调整.9.B【解析】函数,由周期,可得,,,且的对称轴为,方程恰有两个不同的实数解,,则,故选B.10.B【解析】执行一次,,执行第2次,,执行第3次,,执行第4次,,执行第5次,,执行第6次,,执行第7次,跳出循环,因此判断框应填,故选B.11.B【解析】因为曲线在上递增,所以曲线上存在点,可知,由,可得,而在上单调递减,,故选B.12.D【解析】四面体与球的位置关系如图所示,设为的中点,为外接球的圆心,因为,,由余弦定理可得,由正弦定理可得由勾股定理可得,又,,在四边形中,,,计算可得+=,则球的表面积是=,故选D.【方法点晴】本题主要考查球的性质及圆内接三角形的性质、正弦定理与余弦定理法应用及球的表面积公式,属于难题.球内接多面体问题是将多面体和旋转体相结合的题型,既能考查旋转体的对称形又能考查多面体的各种位置关系,做题过程中主要注意以下两点:①多面体每个面都分别在一个圆面上,圆心是多边形外接圆圆心;②注意运用性质.13.C【解析】因为,所以函数的图象关于点(2,0)对称,排除A,B。
广东省汕头市金山中学高三英语上学期期中试题
广东省汕头市金山中学2019届高三英语上学期期中试题本试卷分选择题和非选择题两部分,满分135(120×1.125)分,考试用时120分钟。
注意事项:1.答卷前,考生务必分别将答题卷上的姓名、考试号用黑色字迹的签字笔填写,用2B铅笔将考试号对应的信息点涂黑。
2.选择题每小题选出答案后,用2B铅笔把答题卡上对应题目选项的答案信息点涂黑,如需改动,用橡皮擦干净后,再选涂其他答案,答案不能答在试卷上。
第一部分阅读理解(每题2分,满分40分)第一节(共15题, 每题2分,满分30分)阅读下列四篇短文,从每题所给的A、B、C、D四个选项中,选出最佳选项,并把答题卡上对应题目的答案标号涂黑。
ABest Western Ilford HotelBest Western Ilford is just 20 minutes away from Central London via subway or train, putting you within touching distance of all that the capital has to offer!It is a 3-star hotel, offering luxury as well as comfort. From the stylish, convenient setting to the latest multi-media facilities, we’re well co nnected in more ways than one!Our multi-lingual (多语言的) staff will do everything they can to make your stay as memorable as possible and you might pick up some handy new phrases along the way! If you want to see the sights and get the most out of London while you’re here, they’ll be happy to recomme nd the city’s best bits, and tell you the best way to get there too.Even though near central London, there’s more countryside s cenery near the hotel. Just minutes away, you can enjoy the beautiful Epping Forest and ride a horse along the famous Centenary Walk path. The English lakes and gardens in the nearby Valentines Park are simply stunning(极好的), and thepopular Fairlop Waters is perfect for birdwatchers!● Location:3-5 Argyle Road, Ilford, England, IG1 3BH, United Kingdom● Getting there:Nearest motorway: M11, Ja406, 2.4kilometresNearest train station: Ilford, 0.8 kilometresNearest tube station: Gants Hill, 70 kilometresNearest airport: London City, 4.5 kilometres● Meeting, Confe rences and EventsThe meeting and conferences facilities at the Best Western Ilford are second to none. We can cater for business meetings, training sessions, seminars and product launches, so be our guest!● For your reference:Twenty-Four Hour Service. No Lift. Hotel does not sell alcohol; however, soft drinks are available.1. What do we know about the staff in Best Western Ilford Hotel?A. They will communicate with you only in English.B. They can show you around Central London freely.C. They can teach you English for days free of charge.D. They do everything they can for you and offer best service.2. Which of the following places is the farthest away from the hotel?A. Argyle Road.B. Epping Forest.C. Gants Hill.D. Valentines Park.3. What is the purpose of the last paragraph of the text?A. To draw your special attention.B. To introduce their best service.C. To advertise the soft drinks.D. To tell about the hotel’s history.BThat cold January night, I was growing sick of my life in San Francisco. There I was, walking home at one in the morning after a tiring practice at the theater. With opening night only a week away, I was still learning my lines. I was having trouble dealing with my part-time job at the bank and my acting at night at the same time. As I walked, I thought seriously about giving up both acting and San Francisco. City life had become too much for me.As I walked down empty streets under tall buildings, I felt very small and cold. I began running, both to keep warm and to keep away any possible robbers. Very few people were still out except a few sad-looking homeless people under blankets.About a block from my apartment, I heard a sound behind me. I turnedquickly, half expecting to see someone with a knife or a gun. The street was empty. All I saw was a shining streetlight. Still, the noise had made me nervous, so I started to run faster. Not until I reached my apartment building and unlocked the door did I realize what the noise had been. It had been my wallet falling to the sidewalk.Suddenly I wasn’t cold or tired anymore. I ra n out of the door and back to where I’d heard the noise. Although I searched the sidewalk anxiously for fifteen minutes, my wallet was nowhere to be found.Just as I was about to give up the search, I heard the garbage truck pull up to the sidewalk next to me. When a voice called from th e inside, “Alisa Camacho?” I thought I was dreaming. How could this man know my name? The door opened, and out jumped a small red-haired man with an amused look in his eyes. “Is this what you’re looking for?” he asked, holding up a small square shape.It was nearly 3 a. m. by the tim e I got into bed. I wouldn’t get much sleep that night, but I had got my wallet back. I also had got back some enjoyment of city life. I realized tha t the city couldn’t be a bad place as long as people were willing to help each other.4. How did the writer feel when she was walking home after work?A. Cold and sickB. Lucky and hopefulC. Satisfied and cheerfulD. Disappointed and helpless5. From the first paragraph, we learn that the writer was busy_____.A. solving her problem at the bankB. taking part in various city activitiesC. learning acting in an evening schoolD. preparing for the first night show6. On her way home the writer_____A. lost her wallet unknowinglyB. was stopped by a garbage truck driverC. was robbed of her wallet by a man with a knifeD. found some homeless people following her7. From the text, we can infer that the writer_____A. would stop working at nightB. would stay on in San FranciscoC. would make friends with the manD. would give up her job at the bankCThere is an old Chinese proverb that states “One Ge neration plants the trees; another gets the shade,” and this is how it sho uld be with mothers and daughters. The relationship between a mother and daughter is sometimesconfusing. If close, the relationship can be similar to friendship. However, the mother and daughter relationship has unique characteristics that distinguish it from a friendship. These characteristics include a hierarchy (等级) of responsibility and unconditional love, which preclude mothers and daughters from being best friends.Marina, 27 years old, says, "I love spending time with my mom, but I wouldn't consider her my best friend. Best friends don't pay for your wedding. Best friends don't remind you how they carried you in their body and gave you life! Best friends don't tell you how wise they are because they have been alive at least 20 years longer than you.” This doesn't mean that the mother and daughter relationship can't be very close and satisfying.While some adult relationships are still troubled, many find them to be extremely rewarding. This generation of mothers and adult daughters has a lot in common which increases the likelihood of shared companionship. Mothers and daughters have always shared the common experience of being homemakers, responsible for maintaining and passing on family values and traditions. Today contemporary mothers and daughters also share the experience of the workforce and technology, which may bring them even closer together.Best friends may or may not continue to be best friends, but for better or worse, the mother and daughter relationship is permanent, even if for some unfortunate reason they aren't speaking. The mother and child relationship is closer than any other. There is not an equal relationship. Daughters should not feel responsible for their mother's emotional well-being. It isn’t that they don't care deeply about their mothers. It's just that they shouldn't be burdened with their mother's well being.The mother and daughter relationship is a relationship that is not replaceable by any other. Mothers never stop being mothers, which includes frequently wanting to protect their daughters and often feeling responsible for their happiness. Mother always "trumps"(王牌) friend.8. The underlined word “preclude” in Paragraph 1 probab ly means “_________”.A. differB. preventC. benefitD. change9. What do we know from the passage?A. The mother and daughter relationship can be replaced by a best friend.B. A mother’s love brings her and her daughter a close friendship.C. The mother and daughter relationship goes beyond best fri ends’ friendship.D. Marina has a troubled relationship with her mother.10.The author proves his statements mainly by _________.A. listing dataB. giving explanationsC. quoting sayingsD. making examples11. What is the best title for the passage?A. How to be a good mother and daughter?B. Who is a mother’s best friend?C. Mother or friend?D. Can a mother be a d aughter’s best friend?DBeing sociable looks like a good way to add years to your life. Relationships with family, friends, neighbours, even pets, will all do the trick, but the biggest longevity(长寿) boost seems to come from marriage or an equivalent relationship. The effect was first noted in 1858 by William Farr, who wrote that widows and widowers(鳏夫) were at a much higher risk of dying than their married peers. Studies since then suggest that marriage could add as much as seven years to a man’s life and two to a woman’s. The effect holds for all causes of death, whether illness, accident or self-harm.Even if the odds are stacked against you (the conditions are not favourable), marriage can more than compensate. Linda Waite of the University of Chicago has found that a married older man with heart disease can expect to live nearly four years longer than an unmarried man with a healthy heart. Likewise, a married man who smokes more than a pack a day is likely to live as l ong as a divorced man who doesn’t smoke. There’s a flip side, however, as partners are more likely to become ill or die in the couple of years follo wing their spouse’s death, a nd caring for a spouse with mental disorder can leave you with some of the same severe problems. Even so, the odds favour marriage. In a 30-year study of more than 10,000 people, Nicholas Christakis of Harvard Medical School describes how all kinds of social networks have similar effects.So how does it work? The effects are complex, affected by socio-economic factors, health-service provision, emotional support and other more physiological mechanisms(机制). For example, social contact can boost development of the brain and immune system, leading to better health and less chance of depression later in life. People in supportive relationships may handle stress better. Then there are the psychological benefits of a supportive partner.A life partner, children and good friends are all recommended if you aim to live to 100.The best social network is still being mapped out, but Christakis says: “People are interconnected, so their hea lth is interconnected.”12. Which one of the following is TRUE according to the passage?A. The married men live seven years longer than the unmarried.B. Marriage can help make up for ill health,C. The unmarried are more likely to have heart disease than the married old men.D. Unmarried people are likely to suffer in later life13. It can be inferred from the contex t that the “flip side” in Pa ragraph 2 refers to________.A. the disadvantages of being marriedB. The emotional problems arising from marriageC. The responsibility of taking care of one’s famil yD. The consequence of a broken marriage14. What does the author say about social networks?A. They contribute a great deal to longevity.B. They help develop people’s c ommunity spirit.C. They provide timely support for those in need.D. They help relieve people of the ir life’s burden15. What can be inferred from the last paragraph?A. It’s important that we d evelop a social network when young.B. To stay healthy, one should have a proper social network.C. Getting a divorce means risking a reduced life span.D. We should share our social networks with each other.第二节(共5小题;每小题2分;满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项;选项中有两项为多余选项。
2018-2019学年广东省汕头市金山中学高三(上)9月月考数学试卷(文科)-(解析版)
2018-2019学年广东省汕头市金山中学高三(上)9月月考数学试卷(文科)一、选择题(本大题共12小题,共60.0分)1. 设全集,集合,,则等于A. B. C. D.【答案】C【解析】解:由A中的不等式变形得:,得到,即,全集,,由B中的不等式变形得:,即,,则.故选:C.分别求出A与B中不等式的解集确定出A与B,根据全集求出A的补集,找出A补集与B的交集即可.此题考查了交、并、补集的混合运算,熟练掌握各自的定义是解本题的关键.2. 已知平面向量,,则向量的模是A. B. C. D. 5【答案】C【解析】解:向量,,向量,.故选:C.根据平面向量的坐标运算与线性表示,求出向量的坐标与模长.本题考查了平面向量的坐标运算与线性表示以及模长公式的应用问题.3. 下列命题正确的是A. 命题“若,则”的逆否命题为真命题B. 命题“若,则”的逆命题为真命题C. 命题“,”的否定是“”D. “”是“”的充分不必要条件【答案】A【解析】解:根据题意,依次分析选项:对于A,“若,则”为真命题,则其逆否命题也为真命题,A正确;对于B,命题“若,则”的逆命题为若,则,当时,该命题为假命题;B错误;对于C,命题“,”的否定是“,,C错误;对于D,”是“”的既不充分也不必要条件,D错误;故选:A.根据题意,依次分析选项,综合即可得答案.本题考查命题真假的判定,涉及知识点比较多,要掌握涉及的知识点.4. 设是有正数组成的等比数列,为其前n项和已知,,则A. B. C. D. 【答案】B【解析】解:由,得,所以,又,解得,即.所以,所以.故选:B.先由等比中项的性质求得,再利用等比数列的通项求出公比q及首项,最后根据等比数列前n项和公式求得.本题考查等比中项的性质、等比数列的通项公式及前n项和公式.5. 若函数为奇函数,则A. B. C. 0 D. 2【答案】D【解析】解:设,则,故,故时,,由,故,故选:D.求出的值,从而求出的值即可.本题考查了函数求值问题,考查函数的奇偶性问题,是一道基础题.6. 从装有大小材质完全相同的3个红球和3个黑球的不透明口袋中,随机摸出两个小球,则两个小球同色的概率是A. B. C. D.【答案】C【解析】解:从装有大小材质完全相同的3个红球和3个黑球的不透明口袋中,随机摸出两个小球,基本事件总数,两个小球同色包含的基本事件个数,两个小球同色的概率是.故选:C.随机摸出两个小球,基本事件总数,两个小球同色包含的基本事件个数,由此能求出两个小球同色的概率.本题考查概率的求法,考查古典概型、排列组合等基础知识,考查运算求解能力,考查函数与方程思想,是基础题.7. 已知p为直线上的点,过点p作圆O:的切线,切点为M,N,若,则这样的点p有A. 0个B. 1个C. 2个D. 无数个【答案】B【解析】解:圆O : 圆的半径为1,圆的圆心 到直线 的距离为: ,垂足就是P ,满足p 为直线 上的点,过点p 作圆O : 的切线,切点为M ,N ,若 , 所以P 只有一个. 故选:B .求出圆的圆心到直线的距离,然后判断选项即可.本题考查直线与圆的位置关系的综合应用,考查转化思想以及计算能力.8. 某几何体的三视图如图所示,若图中小正方形的边长均为1,则该几何体的体积是A.B.C.D.【答案】B【解析】解:根据三视图得知:该几何体是由一个三棱柱和一个半个圆锥构成. 故: ,,.故选:B .直接把三视图进行复原,进一步求出几何体的体积. 本题考查的知识要点:三视图的应用. 9.已知函数的周期为 ,当时,方程 恰有两个不同的实数解 , ,则 A. 2 B. 1 C. D.【答案】B【解析】解:由,得 .作出函数 在上的图象如图:由图可知,,.故选:B .降幂,再由辅助角公式化简函数解析式,作出图象,数形结合求得 ,则答案可求.本题主要考查三角恒等变换,正弦函数的周期性和单调性,正弦函数的图象特征,属于中档题.10. 运行如图所示的程序框图,若输出的S 的值为480,则判断框中可以填A. B. C. D. 【答案】B 【解析】解:第一次循环后, , ,应不满足输出条件; 第二次循环后, , ,应不满足输出条件; 第三次循环后, , ,应不满足输出条件; 第四次循环后, , ,应不满足输出条件;第五次循环后,,,应不满足输出条件;第六次循环后,,,应不满足输出条件;第七次循环后,,,应满足输出条件;故判断框中条件可以是,故选:B.由已知中的程序框图可知:该程序的功能是利用循环结构计算并输出变量S的值,模拟程序的运行过程,分析循环中各变量值的变化情况,可得答案.本题考查的知识点是程序框图,当循环的次数不多,或有规律时,常采用模拟循环的方法解答.11. 已知函数,若曲线上存在点使得,则实数a的取值范围是A. B.C. D.【答案】B【解析】解:在上是增函数,.由可得,令,显然为减函数,的最小值为,最大值为.的范围是.故选:B.根据单调性求出的范围,再根据分离参数得出a关于的函数,求出此函数的值域即可得出a 的范围.本题考查了函数单调性的判断与最值计算,属于中档题.12. 在四面体ABCD中,,,底面ABC,的面积是6,若该四面体的顶点均在球O的表面上,则球O的表面积是A.B.C.D.【答案】D【解析】解:取CD的中点E,连结AE,DE,在四面体ABCD中,平面BCA,,,,的面积是6,,,设底面ABC的外接圆的圆心为G,可得外接圆半径.作交AB的中垂线HO于O,O为外接球的中心,半径为.可得:,即四面体ABCD外接球的表面积为:.故选:D.取CD的中点E,连结AE,DE,作出外接球的球心,求出半径,即可求出表面积.本题考查球的内接体知识,考查空间想象能力,确定球的球心与半径是解题的关键二、填空题(本大题共4小题,共20.0分)13. 复数z满足,则复数z的共轭复数______.【答案】【解析】解:,.共轭复数.故答案为:先将z利用复数除法的运算法则,化成代数形式,再求其共轭复数.本题考查复数除法的运算法则,共轭复数的概念及求解复数除法的关键是分子分母同乘以分母的共轭复数,实现分母实数化.14. 已知实数x,y满足约束条件则的最大值等于______.【答案】8【解析】解:作图易知可行域为一个三角形,验证知在点时,取得最小值,最大是8,故答案为:8.先根据约束条件画出可行域,欲求的最大值,即要求的最小值,再利用几何意义求最值,分析可得表示直线在y轴上的截距,只需求出可行域直线在y轴上的截距最小值即可.本题考查线性规划问题,难度较小目标函数有唯一最优解是我们最常见的问题,这类问题一般要分三步:画出可行域、求出关键点、定出最优解.15. 是P为双曲线:上的点,,分别为C的左、右焦点,且,与y轴交于Q点,O为坐标原点,若四边形有内切圆,则C的离心率为______.【答案】2【解析】解:,,,直线的方程为,即,四边形的内切圆的圆心为,半径为,到直线的距离,化简得:,令可得,又,,..故答案为:2.求出圆的圆心、半径和直线的方程,根据切线的性质列方程求出a,b,c的关系,得出离心率.本题考查了双曲线的性质,直线与圆的位置关系,属于中档题.16. 函数的图象可能是下面的图象______填序号【答案】【解析】解:由.令,则转化为,可得为奇函数,排除,当时,,图象在x轴的下方.故答案:.利用换元法,结合奇偶性,带入特殊点即可选出答案.本题考查了函数图象变换,是基础题.三、解答题(本大题共7小题,共70分)17. 在中,内角A,B,C的对边分别为a,b,c,且.求A;若,且的面积为,求的周长.【答案】解:,.,.,,,.的面积为,,.由,及,得,.又,.故其周长为6.【解析】由已知利用正弦定理,两角和的正弦函数公式,三角形内角和定理可得结合,可求,进而可求A的值.由已知利用三角形面积公式可求利用余弦定理可求,联立解得b,c的值即可得解.本题主要考查了正弦定理,两角和的正弦函数公式,三角形内角和定理,三角形面积公式,余弦定理在解三角形中的综合应用,考查了转化思想和方程思想,属于中档题.18. 如图,三棱柱中,,平面.证明:平面平面;若,,求点到平面的距离.【答案】证明:平面,.,,平面.又平面ABC,平面平面.解:取AC的中点D,连接D.,.又平面平面,且交线为AC,则平面ABC.平面,,四边形为菱形,.又,是边长为2正三角形,..设点到平面的距离为h.则.又,.所以点到平面的距离为.【解析】证明,推出平面然后证明平面平面.取AC的中点D,连接D.推出平面设点到平面的距离为通过.求解点到平面的距离即可.本题考查直线与平面垂直的判断定理的应用点线面距离的求法,考查空间想象能力以及计算能力.19. 已知经销某种商品的电商在任何一个销售季度内,每售出1吨该商品可获利润万元,未售出的商品,每1吨亏损万元根据往年的销售经验,得到一个销售季度内市场需求量的频率分布直方图如图所示已知电商为下一个销售季度筹备了130吨该商品现以单位:吨,表示下一个销售季度的市场需求量,单位:万元表示该电商下一个销售季度内经销该商品获得的利润.Ⅰ根据频率分布直方图,估计一个销售季度内市场需求量x的平均数与中位数的大小;Ⅱ根据直方图估计利润T不少于57万元的概率.【答案】解:Ⅰ估计一个销售季度内市场需求量x的平均数为吨;分由频率分布直方图易知,由于时,对应的频率为,而时,对应的频率为,因此一个销售季度内市场需求量x的中位数应属于区间,分于是估计中位数应为吨;分Ⅱ当时,;分当时,,分所以,,分根据频率分布直方图以及Ⅰ知,当时,由,解得,分当时,由,所以,利润T不少于57万元当且仅当,分于是由频率分布直方图可知市场需求的频率为,所以下一个销售季度的利润T不少于57万元的概率估计值为分【解析】Ⅰ根据频率分布直方图计算平均数与中位数即可;Ⅱ写出利润函数,利用函数求利润T不少于57万元的x取值,计算对应的频率值即为概率估计值.本题考查了频率分布直方图以及平均数、中位数的计算问题,也考查了利用频率估计概率的应用问题,是中档题.20. 已知抛物线E:的焦点为F,为x轴上的点.过点P作直线l与E相切,求切线l的方程;如果存在过点F的直线与抛物线交于A,B两点,且直线PA与PB的倾斜角互补,求实数a的取值范围.【答案】解:设切点为,则.点处的切线方程为.过点P,,解得或.当时,切线l的方程为,当时,切线l的方程为.设直线的方程为,代入得.设,,则,.由已知得,即,.把代入得,当时,显然成立,当时,方程有解,,解得,且.综上,.【解析】设切点为,求出导函数,然后求解切线方程即可.设直线的方程为,代入得设,,则,利用直线PA与PB的倾斜角互补,列出方程,转化求解即可.本题考查函数与导数的应用,切线方程以及直线与抛物线是位置关系的综合应用,考查转化思想以及计算能力.21. 已知函数,.求函数的单调递增区间;若,,且,,,求实数a 的取值范围.【答案】解:依题意,,令0'/>,解得,故函数的单调递增区间为.当,对任意的,都有;当时,对任意的,都有;故对恒成立,或对恒成立,而,设函数,.则对恒成立,或对恒成立,,当时,,,0'/>恒成立,在上单调递增,,故在上恒成立,符合题意.当时,令,得,令,得,故在上单调递减,所以,而,设函数,,则,令,则(a(1,+∞))'/>恒成立,在上单调递增,φ{{'}}(1)=e-2 > 0'/>恒成立,在上单调递增,恒成立,即,而,不合题意.综上,故实数a的取值范围为.【解析】首先求得导函数,然后利用导函数的符号确定原函数的单调性即可;结合函数的性质分类讨论和两种情况即可求得实数a的取值范围.本题考查导函数研究函数的单调性,分类讨论的数学思想等,重点考查学生对基础概念的理解和计算能力,属于中等题.22. 已知圆C的极坐标方程为,直线l的参数方程为为参数,点A的极坐标为,设直线l与圆C交于点P、Q两点.写出圆C的直角坐标方程;求的值.【答案】解:圆C的极坐标方程为即,即,表示以为圆心、半径等于1的圆.点A的直角坐标为,点A在直线为参数上.把直线的参数方程代入曲线C的方程可得.由韦达定理可得,根据参数的几何意义可得.【解析】根据直角坐标和极坐标的互化公式、,把圆C的极坐标方程化为直角坐标方程.由题意可得点A在直线为参数上,把直线的参数方程代入曲线C的方程可得由韦达定理可得,根据参数的几何意义可得的值.本题主要考查把极坐标方程、参数方程化为直角坐标方程的方法,参数的几何意义,属于基础题.23. 已知函数.解不等式;若关于x的不等式只有一个正整数解,求实数a的取值范围.【答案】解:当时,,解得,;当时,,解得,;当时,,解得,.综上,不等式的解集为或.作出函数与的图象,由图象可知当时,不等式只有一个正整数解,.【解析】化简函数为分段函数,通过x的范围转化求解不等式的解集即可.利用函数的图象,转化求解即可.本题考查函数的图象的应用,不等式恒成立,绝对值不等式的解法,考查数形结合以及转化思想以及计算能力.。
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2019届汕头金山9月月考
广东省汕头市金山中学2019届高三上学期9月月考英语答题卡
班级_____________ 姓名______________学号_______________ 总分_________________
第二节 语法填空(共10小题;每小题1.5分,满分15分)
阅读下面材料,在空白处填入适当的内容(1个单词)或括号内单词的正确形式。
41.__________________________42.____________________________43.__________________________
44.__________________________45.____________________________46. __________________________
47. ______________________________________ 48. ____________________________________
49. ______________________________________ 50. ____________________________________
第三部分: 写作(共两节;满分35分)
第一节 短文改错 (共10分,每处1分)
假定英语课上英语老师要求同桌之间互相修改作文,请你修改你同桌的以下作文。文中共有10处
语错误,每句中最多有两处。错误涉及一个单词的增加、删除或修改。
删除:把多余的词用斜线(\)划掉。
增加:在缺词处加一个漏字符号(∧),并在该词下面写出该加的词。
修改:在错的词下划一横线,在该词下面写出修改后的词。
注意:1.每处错误及修改均仅限一词。
2.只允许修改10处,多者(从11处起)不计分。
On Thanksgiving morning, I got up early to run in a race. It was just above freezing. So every runner was
jumping around trying to stay warmly.
By the roadside was a man wrapping in a blanket. He was obviously homeless and most people pretended
not see him. I went over and talked with him. We talked about all sort of things. It always hurts to see someone
going through so a rough time. He didn’t ask me for anything, and I wanted to do something for him. I gave him
all the cash which I had. At the first he didn’t want to accept it but I insisted. Then he said something surprised.
He said,’’ This has been so nice. Thank you. I hadn’t really talked to anybody for a long time.” It was he who