Additive Reverses of the Continuous Triangle Inequality for Bochner Integral of Vector-Valu

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HVPZT 三通道电压放大器说明书

HVPZT 三通道电压放大器说明书

HVPZT Piezo Amplifier, 3 ChannelsE-463࡯3 Independent Channels ࡯3 x 6 W Peak Power ࡯3 LED Voltage Displays࡯Output Voltage Range 0 to -1500 VE-463.00E-463, frequency response with various PZT loads. Values shown are capacitance in nF , measured in actual PZT.the input range between 0 V to +10 V and -6.66 V to 3.33 V (see page 6-52). Three 31/2-digit LED displays show the output voltage of each individual channel. For frequency response with selected HVPZTs, see graph below.For computer-controlled clo-sed-loop positioning electron-ics, refer to the E-500 system starting on page 6-18.Technical DataModels E-463.00Function Power amplifier Channels3Maximum output power 6 W / channel (see page 6-52)Peak output current <5 ms 4 mA / channel Average output current >5 ms 2 mA / channel Current limitation Short-circuit proof Voltage gain-150 ±1PolarityNegative Control input voltage 0 to +10 V Output voltage 0 to -1500 VDC-offset setting 0 to -1000 V at output with 10-turn pot.Input impedance 1 M ΩDisplay3 x 31/2-digits, LED Control input sockets 3 x BNCPZT voltage output sockets 3 x LEMO ERA.0A.250.CTL Dimensions 236 x 88 x 273 mm + handles (see page 6-10) Weight4.3 kgOperating voltage90-120 / 220-240 VAC, 50-60 Hz (linear P/S)The E-463.00 is a bench-top piezo driver for high-voltage PZTs. It contains three inde-pendent low-noise, 4-quadrant amplifiers that can output and sink a peak current of 4 mA and an average current of 3 mA each. The E-463.00 can be oper-ated in two ways:I. Manual Control:Output voltage for each chan-nel can be set by a 10-turn DC-offset potentiometer in the range of 0 to -1000 V.II. External Control:Output voltage is controlled by an analog signal applied to the BN C inputs, ranging from 0 to 10 V. Multiplying by the gain factor of -150, an output volt-age range of 0 to -1500 V re-sults. The DC-offset potentiom-eter adds a DC bias to the input,allowing continuous shifting of6-40© P I 1998-2005. S u b j e c t t o c h a n g e w /o n o t i c e . C a t 118 05/09.17。

数学专业英语 第2章课后答案

数学专业英语 第2章课后答案

2.12.比:ratio 比例:proportion 利率:interest rate 速率:speed 除:divide 除法:division 商:quotient 同类量:like quantity 项:term 线段:line segment 角:angle 长度:length 宽:width高度:height 维数:dimension 单位:unit 分数:fraction 百分数:percentage3.(1)一条线段和一个角的比没有意义,他们不是相同类型的量.(2)比较式通过说明一个量是另一个量的多少倍做出的,并且这两个量必须依据相同的单位.(5)为了解一个方程,我们必须移项,直到未知项独自处在方程的一边,这样就可以使它等于另一边的某量.4.(1)Measuring the length of a desk, is actually comparing the length of the desk to that of a ruler.(3)Ratio is different from the measurement, it has no units. The ratio of the length and the width of the same book does not vary when the measurement unit changes.(5)60 percent of students in a school are female students, which mean that 60 students out of every 100 students are female students.2.22.初等几何:elementary geometry 三角学:trigonometry 余弦定理:Law of cosines 勾股定理/毕达哥拉斯定理:Gou-Gu theorem/Pythagoras theorem 角:angle 锐角:acute angle 直角:right angle 同终边的角:conterminal angles 仰角:angle of elevation 俯角:angle of depression 全等:congruence 夹角:included angle 三角形:triangle 三角函数:trigonometric function直角边:leg 斜边:hypotenuse 对边:opposite side 临边:adjacent side 始边:initial side 解三角形:solve a triangle 互相依赖:mutually dependent 表示成:be denoted as 定义为:be defined as3.(1)Trigonometric function of the acute angle shows the mutually dependent relations between each sides and acute angle of the right triangle.(3)If two sides and the included angle of an oblique triangle areknown, then the unknown sides and angles can be found by using the law of cosines.(5)Knowing the length of two sides and the measure of the included angle can determine the shape and size of the triangle. In other words, the two triangles made by these data are congruent.4.(1)如果一个角的顶点在一个笛卡尔坐标系的原点并且它的始边沿着x轴正方向,这个角被称为处于标准位置.(3)仰角和俯角是以一条以水平线为参考位置来测量的,如果正被观测的物体在观测者的上方,那么由水平线和视线所形成的角叫做仰角.如果正被观测的物体在观测者的下方,那么由水平线和视线所形成的的角叫做俯角.(5)如果我们知道一个三角形的两条边的长度和对着其中一条边的角度,我们如何解这个三角形呢?这个问题有一点困难来回答,因为所给的信息可能确定两个三角形,一个三角形或者一个也确定不了.2.32.素数:prime 合数:composite 质因数:prime factor/prime divisor 公倍数:common multiple 正素因子: positive prime divisor 除法算式:division equation 最大公因数:greatest common divisor(G.C.D) 最小公倍数: lowest common multiple(L.C.M) 整除:divide by 整除性:divisibility 过程:process 证明:proof 分类:classification 剩余:remainder辗转相除法:Euclidean algorithm 有限集:finite set 无限的:infinitely 可数的countable 终止:terminate 与矛盾:contrary to3.(1)We need to study by which integers an integer is divisible, that is , what factor it has. Specially, it is sometime required that an integer is expressed as the product of its prime factors.(3)The number 1 is neither a prime nor a composite number;A composite number in addition to being divisible by 1 and itself, can also be divisible by some prime number.(5)The number of the primes bounded above by any given finite integer N can be found by using the method of the sieve Eratosthenes.4.(1)数论中一个重要的问题是哥德巴赫猜想,它是关于偶数作为两个奇素数和的表示.(3)一个数,形如2p-1的素数被称为梅森素数.求出5个这样的数.(5)任意给定的整数m和素数p,p的仅有的正因子是p和1,因此仅有的可能的p和m的正公因子是p和1.因此,我们有结论:如果p是一个素数,m是任意整数,那么p整除m,要么(p,m)=1.2.42.集:set 子集:subset 真子集:proper subset 全集:universe 补集:complement 抽象集:abstract set 并集:union 交集:intersection 元素:element/member 组成:comprise/constitute包含:contain 术语:terminology 概念:concept 上有界:bounded above 上界:upper bound 最小的上界:least upper bound 完备性公理:completeness axiom3.(1)Set theory has become one of the common theoretical foundation and the important tools in many branches of mathematics.(3)Set S itself is the improper subset of S; if set T is a subset of S but not S, then T is called a proper subset of S.(5)The subset T of set S can often be denoted by {x}, that is, T consists of those elements x for which P(x) holds.(7)This example makes the following question become clear, that is, why may two straight lines in the space neither intersect nor parallel.4.(1)设N是所有自然数的集合,如果S是所有偶数的集合,那么它在N中的补集是所有奇数的集合.(3)一个非空集合S称为由上界的,如果存在一个数c具有属性:x<=c对于所有S中的x.这样一个数字c被称为S的上界.(5)从任意两个对象x和y,我们可以形成序列(x,y),它被称为一个有序对,除非x=y,否则它当然不同于(y,x).如果S和T是任意集合,我们用S*T表示所有有序对(x,y),其中x术语S,y属于T.在R.笛卡尔展示了如何通过实轴和它自己的笛卡尔积来描述平面的点之后,集合S*T被称为S和T的笛卡尔积.2.52.竖直线:vertical line 水平线:horizontal line 数对:pairs of numbers 有序对:ordered pairs 纵坐标:ordinate 横坐标:abscissas 一一对应:one-to-one 对应点:corresponding points圆锥曲线:conic sections 非空图形:non vacuous graph 直立圆锥:right circular cone 定值角:constant angle 母线:generating line 双曲线:hyperbola 抛物线:parabola 椭圆:ellipse退化的:degenerate 非退化的:nondegenerate任意的:arbitrarily 相容的:consistent 在几何上:geometrically 二次方程:quadratic equation 判别式:discriminant 行列式:determinant3.(1)In the planar rectangular coordinate system, one can set up aone-to-one correspondence between points and ordered pairs of numbers and also a one-to-one correspondence between conic sections and quadratic equation.(3)The symbol can be used to denote the set of ordered pairs(x,y)such that the ordinate is equal to the cube of the abscissa.(5)According to the values of the discriminate,the non-degenerate graph of Equation (iii) maybe known to be a parabola, a hyperbolaor an ellipse.4.(1)在例1,我们既用了图形,也用了代数的代入法解一个方程组(其中一个方程式二次的,另一个是线性的)。

金融数学中英文专业词汇对照

金融数学中英文专业词汇对照

金融数学中英文专业词汇对照accumulation function 累积函数American-style option 美式期权amortization method 分期偿还法annuity 年金annuity-due 期初付年金annuity-immediate 期末付年金arbitrage 套利at-the-money option 平价期权base amount 基价base points 基点bear spreads 熊市差价Bermudan-style option 百慕大期权binomial tree 二叉树bond 债券bond with coupons 附息债券box spread 盒式差价brownian motion 布朗运动bull spreads 牛市差价butterfly spreads 蝶式差价buyer 买方call option 看涨期权callable bond 可赎回债券cash flow matching 现金流配比cash-and-carry arbitrage 正向套利Chicago mercantile exchange(CME)芝加哥商业交易所collar 衣领策略collar width 衣领宽度common stock 普通股compound increasing annuity 复递增年金compound interest 复利continuously payable annuity 连续支付年金continuously payable continuously decreasing annuity 连续支付连续递减的年金continuously payable continuously increasing annuity 连续支付连续递增的年金continuously payable decreasing annuity 连续支付的递减年金continuously payable increasing annuity 连续支付的递增年金continuously payable varying annuity 连续支付的变额年金convexity 凸度coupon 息票收入coupon rate 息票率decreasing annuity 递减年金decreasing annuity-due 期初付递减年金decreasing annuity-immediate 期末付递减年金delivery price 交割价格derivative instrument 衍生产品discount function 贴现函数duration 久期effective duration 有效久期effective rate of discount 实际贴现率effective rate of interest 实际利率equation of value 价值方程European-style option 欧式期权exercise price 执行价格face amount 面值fixed interest rate model 固定利率模型force of discount 贴现力force of interest 利息力forward contract 远期合约forward price 远期价格forward rate 远期利率forward rate agreements(FRA)远期利率协议forwards 远期full immunization 完全免疫future value 终值futures 期货futures contracts 期货合约futures price 期货价格hedging 套期保值immunization 免疫increasing annuity 递增年金increasing annuity-due 期初付递增年金increasing annuity-immediate 期末付递增年金initial margin 初始保证金interest 利息interest rate swaps 利率互换interest rate tree 利率树interest-sensitive cash flows 利率敏感型现金流internal rate of return 内涵报酬率in-the-money option 实值期权intrinsic value 内在价值investment year method 投资年度法Ito process 伊藤过程level annuity 等额年金London interbank offered rate 伦敦银行同业拆借利率long position 多头maintenance margin 维持保证金marking to market 盯市modified duration 修正久期mortgage 抵押贷款net present value 净现值nominal rate of discount 名义贴现率nominal rate of interest 名义利率offset 对冲平仓option 期权option price 期权价格out-of-the-money option 虚值期权outstanding balance 未偿还本金余额par yield curve 平价收益率曲线payoff 回收perpetuity 永续年金portfolio method 组合方法preferred stock 优先股premium 期权费premium amortization 溢价分摊present value 现值principle 本金prospective method 将来法pure discount bond 贴现债券put option 看跌期权ratio spread 比率差价redemption value 偿还值retrospective method 过去法reverse cash-and-carry arbitrage 反向套利risk-neutral probability 风险中性概率seller 卖方short position 空头short sale 卖空simple interest 单利sinking fund method 偿债基金法spot price 即期价格spot rate 即期利率spreads 差价stock 股票straddle 跨式策略strap 带式策略strip 条式策略swap 互换swap rate 互换利率term structure of interest rate 利率的期限结构time-weighted rate of return 时间加权收益率underlying asset 标的资产variance rate 方差率varying interest rate model 变动利率模型covered call 有担保的看涨期权covered put 有担保的看跌期权yield rate 收益率yield to maturity 到期收益率zero-cost collar 零成本衣领zero-coupon bond 零息债券。

兽医专业英语(扬州大学)lesson 11

兽医专业英语(扬州大学)lesson 11

Lesson Eleven Drug Interactions
•Ketamine[‘ketəmi:n] n. [药] 氯胺酮(一种麻醉剂 ) •Barbiturate[,bɑ:'bitjurət] n. [药] 巴比土酸盐;[药] 巴比妥酸盐 •Methylprednisolone[,meθilpred'nisələun] n. [药] 甲基强的松龙 •Succinate[‘sʌksineit] n. [有化]丁二酸盐;琥珀酸盐 •Calcium['kælsiəm] n. [化学] 钙 •Gluconate['ɡlu:kəneit] n. [有化] 葡糖酸盐 •Hydrolysis [hai‘drɔlisis] n. 水解作用 •Reduction [ri'dʌkʃən] n. 减少;下降;缩小 •Complexation [kɔmplek'seiʃ(ə)n] n. 络合;络合作用(complex的名词) •Precipitation [pri,sipi‘teiʃən] n. [化学] 沉淀;冰雹;坠落;鲁莽
In vivo drug interactions may result in diminished or enhanced drug effects, expression of a new or different effect, or perhaps no obvious pharmacodynamic change but altered pharmacokinetics that may not be clinically apparent. Some drug interactions are advantageous and are exploited (开发,开拓 ) in therapy. Many others ( drug interactions ) are potentially deleterious. A documented or potential drug interaction is rarely an absolute contraindication for concurrent administration and hence becomes a component of risk assessment in therapeutic decision making.

Analysis of top to bottom-$k$ shuffles

Analysis of top to bottom-$k$ shuffles

(n log n)/2, then T (Sn , qn,kn ) ∼ n log n;
(2) if kn ≥ cn with c ∈ (0, 1), then (3) if kn ≤ C , then
A(c)n log n ≤ T (Sn , qn,kn ) ≤ B (c)n2 log2 n; A(C )n3 ≤ T (Sn , qn,kn ) ≤ B (C )n3 log n; An3 log n ≤ T (Sn , qn,kn ) ≤ Bn3 log n.
1. Introduction. A deck of n cards can be shuffled by repeatedly removing the top card and inserting it uniformly at random back into the deck. A coupling argument shows that the total variation mixing time for this Markov chain is n log n (see, e.g., [1, 2, 12]). In fact, a detailed analysis yields a closed form expression for the distribution of this chain after any number of steps (see [3]). Here we analyze a class of walks that generalizes the top to random chain, namely, top to bottom-k shuffles. These shuffles are generated by moving the top card uniformly at random to any of the bottom kn positions of the deck. For kn = n, we recover the top to random walk. For kn = 2, this is the Rudvalis shuffle, and upper and lower bounds of order n3 log n have been shown by Hildebrand [9] and Wilson [15], respectively. More formally, let Sn be the permutation group, and let σ ∈ Sn denote an element of this group, interpreting σ (i) = j to mean that position i holds the card with label j . Fix n ≥ kn > 1, and denote a cycle permutation by σl = (1, 2, . . . , l), i + 1 for 1 ≤ i ≤ l − 1, σl (l) = 1, and σl (i) = i otherwise. Define the probability measure qn,kn on Sn by qn,kn (σ ) =

Single Variable Calculus_中国大学mooc课后章节答案期末考试题库2023年

Single Variable Calculus_中国大学mooc课后章节答案期末考试题库2023年

Single Variable Calculus_西北工业大学中国大学mooc课后章节答案期末考试题库2023年1.If f (x) and g (x) are differentiable on (a, b), 【图片】and f (x) > 0, g (x) > 0,x∈(a, b), then when x∈(a, b), we have答案:2.For what values of a and b will 【图片】be differentiable for all values of x?答案:a=-1/2, b=13.The evaluation of integral【图片】(where x>1) is答案:4.Find the derivative of【图片】答案:5.Find the centroid of a thin, flat plate covering the “triangular” region i n thefirst quadrant bounded by they-axis, the parabola【图片】, and the line【图片】.答案:6.If【图片】, find the limit of g(x) as x approaches the indicated value.答案:7.Find the derivative of the function below at x=0,【图片】答案:8.【图片】is答案:-1/329.If f (x) is continuous and F′(x) = f(x), then答案:10.Find the volume of the solid generated by revolving the region bounded bythe curve【图片】and the lines【图片】about【图片】.答案:11.The mean value【图片】that satisfies the Rolle’s Theorem on the function【图片】is答案:12.The critical number of 【图片】is ( )答案:0 and 213.Which statement is true?【图片】答案:A14.If【图片】,then【图片】答案:15.Evaluate【图片】.答案:16.The integtral of【图片】is答案:17.When x approaches infinity, the limit of【图片】is答案:18.The evaluation of integral【图片】is答案:19.If【图片】has continuous second-order derivative, and【图片】, then答案:20.Find the length of the enclosed loop【图片】shown here. The loop starts at【图片】and ends at【图片】.【图片】答案:21.The height of a body moving vertically is given by 【图片】, with s in metersand t in se conds. The body’s maximum height is ( )答案:22.If f (x) is increasing and f(x) > 0, then答案:23. A rock climber is about to haul up 100 N of equipment that has been hangingbeneath her on 40 m of rope that weighs 0.8 newton per meter. How much work will it take? (Hint: Solve for the rope and equipment separately, thenadd.)答案:24.The integral of【图片】is答案:25.Expand【图片】by partial function答案:26.Assume that u is a function of x and v is the derivative of u, then thederivative of arcsin(u) is答案:27.Find the center of mass of a thin plate covering the region bounded below bythe parabola 【图片】and above by the line 【图片】, if the density at the point 【图片】is 【图片】.答案:28.Find the limit【图片】答案:-129.Find the length of the curve【图片】, from【图片】 to【图片】.答案:53/630.Find the volume of the solid generated by revolving the regions bounded bythe curve 【图片】and line 【图片】about the x-axis.答案:31.Find the total area of the shaded region in the following picture.【图片】答案:4/332.The total area between the region 【图片】and the x-axis is答案:33.Which statement is NOT true?答案:34.Calculate【图片】答案:-135.The second derivative of the function y=secx is ( )答案:36.If gas in a cylinder is maintained at a constant temperature T, the pressure Pis related to the volume V by a formula of the form 【图片】in which a, b, n, and R are constants. Then【图片】答案:37.If【图片】then【图片】.答案:38.Calculate 【图片】The limit is ( )答案:139.Find the tangent to the folium of descartes 【图片】at the point (3,3)答案:x+y=640.Let 【图片】The tangent line to the graph of g(x) at (0,0) is ( ).答案:x-axis41.Find the derivative of the function below at x=0, 【图片】答案:It does not exist42.Find【图片】答案:43.The average value of 【图片】over theinterval [【图片】] is答案:44.Find the average rate of change of the function【图片】over the giveninterval [2,3]答案:1945.For【图片】 find the number【图片】 by using the two steps learned in 2.3.答案:0.0546.The linearization of the function 【图片】at x=1 is ( ).答案:47.If and only if x=ln(y),y=e^x.答案:正确48.Find the derivative of the function【图片】答案:49.Find the derivative of the function 【图片】It is ( )答案:50.If f (x) is an antiderivative of【图片】then【图片】答案:51.If f ′(x ) < 0, f ′′(x ) < 0, x∈(a, b), then the graph of f (x) on (a, b) is答案:decreasing and concave down.52.If【图片】, find【图片】.答案:753.At what points are the function【图片】 continuous?答案:Discontinuous at odd integer multiples of , but continuous at all other x.54.On what interval is the function 【图片】continuous?答案:55.On what interval is the function【图片】continuous?答案:56.【图片】【图片】and【图片】答案:0, 357.Suppose that the functionf(x)is second order continuous differentiable, and【图片】,【图片】. Therefore,【图片】答案:58.When x approaches 0, the limit of【图片】is答案:59.Find the area of the surface generated by revolving the curve 【图片】aboutthe x-axis to generate a solid.答案:60.Find the average rate of change of the function【图片】 over the giveninterval [0,2]答案:161.Find the limit of the function【图片】 and is the function continuous at thepoint being approached?答案:The limit is 0 and the function is continuous at62.The integral of [x/(x^2+1)]dx is答案:1/2[ln(x^2+1)]+C63.When x approaches 0, the limit of (1+3x)^(1/x) is答案:e^364.When x approaches infinity, the limit of x^(1/x) is答案:165.When x approaches infinity, for two functions f(x) and g(x), the limit off(x)/g(x) is infinity, and the limit of g(x)/f(x) is 0, thus a relationship between their growth rates can be said that答案:Function f(x) grouws faster than g(x).66. A function f is called a One-to-One function if it never takes on the same valuetwice.答案:正确67.The integtral of [e^(2x+1)]dx is答案:1/2[e^(2x+1)]+C68. A force of 2 N will stretch a rubber band 2 cm (0.02 m). Assuming thatHooke's Law applies, how far will a 4-N force stretch the rubber band?答案:4 cm69.Find the area of the surface generated by revolving the curve【图片】aboutthey-axis.答案:70.Which statement is true?答案:71.Which statement is false?答案:72.Find the integration formula of the solid volume generated by the curve 【图片】, the x-axis, and the line 【图片】revolved about the x-axis by the shell method.答案:73.Find the integration formula of the area of the region bounded above by thecurve 【图片】, below by the curve 【图片】, on the left by 【图片】, and on the right by 【图片】.答案:74.If 【图片】is continuous on [-1,1] and the average value is 2, then 【图片】答案:475. A cubic function is a polynomial of degree 3; that is, it has the form 【图片】,where a≠0. Then ( ) is false.答案:x=1 is critical number when the cubic function has only one criticalnumber.76.The graph of【图片】has ( )asymptotes.答案:377.If 【图片】then答案:78.The average value of【图片】on【图片】is答案:79.If f (x) is continuous on (−1, 1), and【图片】then答案:80.The derivative of the function【图片】 is答案:81.The function 【图片】has ( )答案:A. neither a local maximum nor a local minimum82.Find the derivative of function【图片】答案:83.Find y' , if【图片】答案:84.The derivative of 【图片】is( )答案:85.Let【图片】,Then【图片】答案:18x(x+1)86.At what points, is the function 【图片】continuous?答案:A. Discontinuous only when x= 3 or x= 187.Find the derivative of x(e^x).答案:e^x(x+1)88.The integral of (1/x)dx is答案:ln|x|+C89.Find the area of the surface generated by revolving the curve 【图片】aboutthe y-axis to generate a solid.答案:90.Find the length of the curve【图片】.答案:7ing the trapezoidal rule to estimate the integralwith n=4 steps【图片】答案:0.70500。

Multilayer feedforward networks with a nonpolynomial activation function can approximate an

Multilayer feedforward networks with a nonpolynomial activation function can approximate an

Center for Digital Economy Research Stern School of Business Working y different applications, with most papers reporting that they perform at least as good as their traditional competitors, e.g. linear discrimination models and Bayesian classifiers. This success has recently led several researchers to undertake a rigorous analysis of the mathematical properties that enable feedforward networks to perform well in the field. The motivation for this line of research was eloquently described by Hornik and his colleagues (1989) , as follows: "The apparent ability of sufficiently elaborate feedforward networks to approximate quit.e well nearly any function encountered in applications leads one to wonder about the ultimate capabilities of such networks. Are the successes observed to da.te reflective of some deep and fundamental approximation capabilities, or are they merely flukes, resulting from selective reporting and a. fortuitous choice of problems?" Previous research on the approximation capabilities of feedforward networks can be found in Carroll and Dickinson, le Cun (1987)

铅酸蓄电池常用专业词汇

铅酸蓄电池常用专业词汇

Short-Circuit Current 短路电流 (SCC) Shrinkage of 负极活性物 Negative Active 质收缩 Material Sintered Electrode SLI Battery Soaking Softening Spalling 烧结电极 汽车铅酸电 池 浸泡 软化 剥落
常用专业词汇
英 文 Accelerator Active Material Age Hardening Ambient Temperature Ampere Hour Ampere-Hour Capacity Ampere-Hour Efficiency Ampere-Hour Law Anode Apparent Density Automatic Charging Auxiliary Electrode Available Capacity Barton Oxide Barton Pot Battery Battery Discharge Indicator Battery Oxide Binder Blank Bolted Connector Boost Charge Boundary Layer C Rate Cadmium electrode Cadmium Reading Calomel Electrode Capacity Capacity Rating Capacity Retention Castability Casting Cation Cell Ceramic Cone Charge 中 文 固化剂 活性物质 时效硬化 环境温度 安时 安时容量 安时效率 安时定律 阳极 视比重 自动充电 辅助电极 可用容量 巴顿铅粉 巴顿炉 电池 电池放电指 示器 电池用铅粉 粘合剂 铅皮 连接条 冲击充电 边界层 小时率 镉电极 镉压 甘汞电极 容量 额定容量 容量保持率 浇铸性 铸造 阳离子 电池 陶瓷片 充电
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4
SEVER S. DRAGOMIR
If (2.3) and (2.4) hold true, then
b b b b b
f (t) dt =
a a
f (t) dt −
k (t) dt
a
e =
a
f (t) dt −
k (t) dt
a
and the equality holds true in (2.2). Conversely, if the equality holds in (2.2), then, obviously (2.3) is valid and we need only to prove (2.4). If f (t) − Re f (t) , e < k (t) for a.e. t ∈ [a, b] , then (2.5) holds as a strict inequality, implying that (2.2) also holds as a strict inequality. Therefore, if we assume that equality holds in (2.2), then we must have (2.7) It is well known that in Schwarz’s inequality x y ≥ Re x, y the equality holds iff there exists a λ ≥ 0 such that x = λy. Therefore, if we assume that the equality holds in all of (2.6), then there exists a λ ≥ 0 such that
b a
for a.e. t ∈ [a, b] , for a.e. t ∈ [a, b] ,
b
then we have the inequality √ 2 mM (1.12) M +m or, equivalently,
b
f (t) dt ≤
f (t) dt ,
a
b
(1.13)
0≤
a
f (t) dt −
b
(1.7)
for a.e. t ∈ [a, b] .b1 − ρ2b
a
f (t) dt ≤
b
f (t) dt ,
a
with equality if and only if (1.9)
a
f (t) dt =
1 − ρ2
f (t) dt
a
· e.
Corollary 2. Let e be a unit vector in H and M ≥ m > 0. If f ∈ L ([a, b] ; H ) is such that (1.10) or, equivalently, (1.11) Re M e − f (t) , f (t) − me ≥ 0 f (t) − 1 M +m e ≤ (M − m) 2 2
b b
(1.1)
a
f (x) dx ≤
a
|f (x)| dx,
and plays a fundamental role in Mathematical Analysis and its applications. It seems, see [5, p. 492], that the first reverse inequality for (1.1) was obtained by J. Karamata in his book from 1949, [3]:
a
+
a
k (t) dt.
By Schwarz’s inequality for e and
b
f (t) dt, we have
b b
(2.6)
Re
a
f (t) dt, e
≤ Re
b
f (t) dt, e
a

b
f (t) dt, e
a

f (t) dt
a
e =
a
f (t) dt .
Making use of (2.5) and (2.6), we deduce the desired inequality (2.2).
a
f (t) dt ≤
√ √ M− m M +m
2 b
f (t) dt .
a
ADDITIVE REVERSES OF THE CONTINUOUS TRIANGLE INEQUALITY
3
The equality holds in (2.11) (or in the second part of (2.12) if and only if √ b b 2 mM f (t) dt e. f (t) dt = M +m a a The main aim of this paper is to point out additive reverses for the continuous triangle inequality, namely, upper bounds for the nonnegative difference
b a b
f (t) dt −
f (t) dt
a
under various assumptions on the function f ∈ L ([a, b] ; H ) . Both the case for a unit vector e ∈ H and a family of orthonormal vectors {ei }i∈{1,...,n} are analysed. Applications for complex-valued Lebesgue integrable functions are given as well. 2. Some Additive Reverses for a Unit Vector The following result holds. Theorem 2. If f ∈ L ([a, b] ; H ) is such that there exists a vector e ∈ H, e = 1 and k : [a, b] → [0, ∞), a Lebesgue integrable function with (2.1) f (t) − Re f (t) , e ≤ k (t)
1
2
SEVER S. DRAGOMIR
In our previous work [2], we pointed out some continuous versions of Diaz and Metcalf reverses of the generalised triangle inequality. We mention here some results from [2] which may be compared with the new results obtained in Sections 2 and 3 below. Theorem 1. If f ∈ L ([a, b] ; H ) , the space of Bochner integrable functions defined on [a, b] and with values in the Hilbert space H, and there exists a constant K ≥ 1 and a vector e ∈ H, e = 1 such that f (t) ≤ K Re f (t) , e
1. Introduction Let f : [a, b] → K, K = C or R be a Lebesgue integrable function. The following inequality is the continuous version of the triangle inequality
Date : April 16, 2004. 2000 Mathematics Subject Classification. 46C05, 26D15, 26D10. Key words and phrases. Triangle inequality, Reverse inequality, Hilbert spaces, Bochner integral.
SEVER S. DRAGOMIR Abstract. Some additive reverses of the continuous triangle inequality for Bochner integral of vector-valued functions in Hilbert spaces are given. Applications for complex-valued functions are provided as well.
b b
(1.2) provided
cos θ
a
|f (x)| dx ≤
f (x) dx
a
|arg f (x)| ≤ θ, x ∈ [a, b] , where θ is a given angle in 0, π 2 . This integral inequality is the continuous version of a reverse inequality for the generalised triangle inequality
n n
(1.3) provided
cos θ
i=1
|zi | ≤
zi ,
i=1
a − θ ≤ arg (zi ) ≤ a + θ, for i ∈ {1, . . . , n} , where a ∈ R and θ ∈ 0, π 2 , which, as pointed out in [5, p. 492], was first discovered by M. Petrovich in 1917, [6], and, subsequently rediscovered by other authors, including J. Karamata [3, p. 300 – 301], H.S. Wilf [7], and in an equivalent form by M. Marden [4]. The first to consider the problem for sums in the general case of Hilbert and Banach spaces, were J.B. Diaz and F.T. Metcalf [1].
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