初三模考1

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模考试卷

模考试卷

盐城市初级中学初三模拟考试第Ⅰ卷(选择题,共60 分)一、单项选择(共15小题;每小题1分,计15分)从A、B、C、D四个选项中选出一个可以填入句中空白处的最佳答案。

( ) 1. —My son always goes to school without having ______ breakfast.—It is ______ unhealthy habit. You must ask him to change it.A. /; anB. /; aC. the; anD. the; a( ) 2. —________is a boat ticket for children?—How old is your child? It’s free for kids under three years old.A. How longB. How muchC. How oftenD. How soon ( ) 3. The libraries in your school are nicer than_______ in ours.A. thatB. onesC. thoseD. them( ) 4. Ya'an earthquake happened_______ the morning_______ April 20, 2013.A. on, onB. in, inC. on, ofD. in, of( ) 5. —Did you ride your bicycles to the beach yesterday?—Yeah. we had!A. What funB. What a funC. How funD. How funny ( ) 6. The price of the house is too ______. I am afraid I can’t afford it.A. cheapB. expensiveC. lowD. high( ) 7. Travelers on planes_______ carry knives because it is against the rules.A. needn'tB. couldn'tC. won'tD. mustn't ( ) 8. I was so tired after a day of hard work that I could ______ move any longer.A. reallyB. nearlyC. simplyD. hardly( ) 9. --Drugs have done great harm to some people and their families.--Quite true, so we should ________ them.A. keep away fromB. look down onC. get on withD. take care of ( ) 10. ---Your grandfather is always full of_______. Do you know the secret?---Well, he takes exercise every morning and keeps healthy diets.A. forceB. powerC. energyD. strength ( ) 11. ---How can I improve my reading?---I think the most important is to ______ a good habit of reading.A. developB. showC. makeD. take( ) 12. —They speak perfect English. How long have they learnt it?—______ they were seven years old.A. SinceB. WhenC. AfterD. Until( ) 13. —Could you tell me ______?—Sure. We will meet at the school gate.A. when we will meet tomorrow morningB. where we will meet tomorrow morningC. when shall we meet tomorrow morningD. where shall we meet tomorrow morning ( ) 14. --Do you mind my parking here? The parking lot is full.--______. Look at the sign! It says, ―No Parking!‖A. You’d better notB. No, I don’t mindC. It doesn’t matterD. Yes, go ahead ( ) 15. Which of the following sentences is an opinion?A. Four people in Jiangsu died in early April because of H7N9 bird flu infections.B. China’s star swimmer Sun Yang won the first prize on April 1st at the National SwimmingChampionships.C. People think Peng Liyuan, wife of President Xi Jinping, will draw great attention from people bothat home and abroad.D. It is reported that many college students have volunteered to serve in the 2014 Nanjing YOG..二、完形填空(共15小题;每小题1分,计15分)阅读下面短文,掌握其大意,然后从各题所给的四个选项中选出一个最佳答案。

浙江省九年级中考模拟考试一语文考试卷(解析版)(初三)中考模拟.doc

浙江省九年级中考模拟考试一语文考试卷(解析版)(初三)中考模拟.doc

浙江省九年级中考模拟考试一语文考试卷(解析版)(初三)中考模拟姓名:_____________ 年级:____________ 学号:______________一、xx 题 (每空xx 分,共xx 分) 【题文】下面加点汉字注音全部正确的是( )A. 迸溅(pèng) 啜泣(chuò) 骸骨(hái) 溯流(shù)B. 收敛(Iiǎn) 佳肴(yáo) 卓越(chuó) 匀称(chèn)C. 掣拳(chè) 旷野(kuàng) 澄澈(chéng) 庇护(bì)D. 孪生(luán) 哪吒(né) 陛下(bì) 附和(hé)【答案】C【解析】此题考查学生对字音的掌握情况,这就要求在学生平时的学习中注意字音的识记和积累,特别是形近字、多音字,这样才能轻松应对该题型。

A 应为迸溅(bèng) 溯流( sù ) B 应为卓越( zhuó ) D 应为 附和( hè ) C 正确。

故选C 。

【题文】古诗文名句默“一切景语皆情语”,一切环境描写的文字都是作者表情寄意的载体。

徜徉于文学海洋,情景交融的佳句比比皆是:①杜甫《登楼》中“锦江春色来天地,______________________。

”以浩大的气势描绘祖国山河壮美,表达对民族历史的追怀。

②王维《使至塞上》“_________,_________。

”描绘了塞外大漠苍凉雄浑之壮美。

③陆游的《卜算子·咏梅》用“_________________,只有香如故。

”写梅花即使遭遇摧折也坚持自己操守。

④常建《题破山寺后禅院》中“___________________,_______________________。

”则表现美学中的曲折美、层次美。

⑤白居易《钱塘湖春行》中,“______________,_______________ 。

初三第一模考试卷语文试卷

初三第一模考试卷语文试卷

一、选择题(每小题2分,共20分)1. 下列词语中字形完全正确的一项是()A. 瞒哄B. 漫步C. 沮丧D. 沉默2. 下列句子中,没有语病的一项是()A. 这场演讲比赛,他虽然得了第一名,但是并不骄傲。

B. 通过这次活动,我们深深感受到了团队合作的重要性。

C. 我们要努力学习,争取早日实现自己的梦想。

D. 在这次考试中,他因为粗心大意,导致成绩一落千丈。

3. 下列词语中,加点字注音完全正确的一项是()A. 潜伏(qián)B. 咄咄逼人(duō)C. 碧螺春(luó)D. 翠绿(cuì)4. 下列句子中,修辞手法使用不恰当的一项是()A. 星星点点的灯光,像无数只眼睛在黑夜中闪烁。

B. 那山峰上,云雾缭绕,宛如仙境。

C. 这座城市的夜晚,犹如一幅色彩斑斓的画卷。

D. 小明的学习成绩像过山车一样,时而上升,时而下降。

5. 下列文学常识表述错误的一项是()A. 《红楼梦》的作者是曹雪芹。

B. 《三国演义》的作者是罗贯中。

C. 《西游记》的作者是吴承恩。

D. 《水浒传》的作者是施耐庵。

6. 下列名言警句中,不属于诸葛亮的是()A. 非淡泊无以明志,非宁静无以致远。

B. 读书破万卷,下笔如有神。

C. 天行健,君子以自强不息。

D. 知之者不如好之者,好之者不如乐之者。

7. 下列诗句中,意境优美的一项是()A. 春风又绿江南岸,明月何时照我还?B. 独在异乡为异客,每逢佳节倍思亲。

C. 春风得意马蹄疾,一日看尽长安花。

D. 会当凌绝顶,一览众山小。

8. 下列对联中,上联与下联意思连贯的一项是()A. 上联:山青水秀风光好;下联:鸟语花香景色新。

B. 上联:月满西楼人倚栏;下联:风吹长亭马蹄疾。

C. 上联:书山有路勤为径;下联:学海无涯苦作舟。

D. 上联:雨打梨花深闭门;下联:闲看落花渐欲销。

二、填空题(每空2分,共20分)9. 下列词语中,加点字注音完全正确的一项是_________。

2022-2023学年九年级中考模拟检测(一) (物理)(含答案解析)235331

2022-2023学年九年级中考模拟检测(一) (物理)(含答案解析)235331

2022-2023学年九年级中考模拟检测(一) (物理)试卷考试总分:115 分 考试时间: 120 分钟学校:__________ 班级:__________ 姓名:__________ 考号:__________一、 选择题 (本题共计 7 小题 ,每题 5 分 ,共计35分 )1. 电子车票,也称“无纸化”车票,乘客网上购票后,直接通过“刷身份证”或“扫手机”即可顺利进站。

如图甲所示是乘客通过“刷身份证”进站时的情景,将身份证靠近检验口,机器感应电路中就会产生电流,从而识别乘客身份。

下图中能说明这一原理的是( ) A. B. C. D.2. 如图所示,三个直径不同的塑料管、、连接在一起(管直径最大,管直径最小),然后与吹风机相通。

当吹风机吹气时,将三个气体压强传感器分别放入管内,将传感器与计算机相连,从计算机上就可以读出三个位置气体的压强值。

图中显示器所显示的是“压强-时间”图象,则下列说法中正确的是( )a b c a cA.塑料管中气体流速最快,气体压强最大,对应图中曲线B.塑料管中气体流速最慢,气体压强最大,对应图中曲线C.吹风过程中,三节管中的气体流速相同D.=时,吹风机不工作,、、三个塑料管中气体压强传感器测量的是大气压强3. 下列事例中,利用惯性的是( )A. 跳远运动员起跳前要助跑B. 守门员用力抓住飞来的足球C. 运动员撑杆跳高时把撑杆压弯D. 运动员游泳时向后划水4. 生活中处处有物理知识,下列说法中正确的是( )A.防疫中最普遍采用的方法是测人体体温,“体温枪”是利用紫外线测体温B.雷电天气总是先看到闪电后听到雷声,是因为在空气中光速大于声速C.体操运动员上器械前在手上涂防滑粉,是为了减小手与器械之间的摩擦力D.在火车站,人必须站在站台安全线外的区域候车,是因为流体流速大的地方压强大5. 如图所示是物理兴趣小组同学设计的太阳能路灯。

图中,甲和乙一个是太阳能电池板,一个是路灯,为光敏电阻,其电阻大小与光照强度关系如图所示;白天太阳能电池板为蓄电池充电,夜晚蓄电池为电灯供电。

2022-2023学年九年级中考模拟检测(一) (数学)(含答案)090216

2022-2023学年九年级中考模拟检测(一) (数学)(含答案)090216

2022-2023学年九年级中考模拟检测(一) (数学)试卷考试总分:115 分 考试时间: 120 分钟学校:__________ 班级:__________ 姓名:__________ 考号:__________一、 选择题 (本题共计 10 小题 ,每题 5 分 ,共计50分 )1. 在数,,,中,最小的数是( )A.B.C.D.2. 下列运算正确的是( )A.B.C.D. 3.如图所示的主视图对应的几何体是( ) A. B. C.D.4. 新冠疫情在我国得到了很好地控制,可至今仍在海外肆虐,截止年月底,海外累计确诊人,用科学记数法可表示为(精确到千万位)( )A.B.C.D.−3−203−3−23=(−)a 43a 7⋅=−(−a)5a 5a 10=6(2ab)3a 3b 3a +=a 2a 3202151289242291289242290.13×1091.3×1081.29×10312.9×1075. 在同一平面内有条直线,若,,,,…,,则下列结论正确的是 A.B.C.D.6. 若数据:,,,,的平均数为,则这组数中的( )A.中位数为B.众数为C.=D.中位数为7. 关于的一元二次方程有两个实数根,则实数的取值范围是( )A.B.且C.D.且8.已知的斜边,一条直角边,分别以以下三边所在直线为轴旋转一周所得几何体的表面积最大的为( )A.B.C.D.不确定9. 如图,直线上有三个正方形,,,若,的面积分别为和,则的面积为( )A.B.C.D.10. 已知二次函数的图象如图所示,对称轴为直线.且经过点,有位学生写出了以下五个结论:;方程的两根是,;;当时,随的增大而减小;.则以上结论中不正确的有( )100⊥a 1a 2⊥a 2a 3⊥a 3a 4⊥a 4a 5⊥a 99a 100()//a 1a 100⊥a 2a 98//a 1a 99//a 49a 5022x 34333x 3xx (mx−2)x−1=0m m≥−1m≥−1m≠0m>−1m>−1m≠0Rt △ABC AB =5AC =3ABACBCl a b c a c 511b 681655y =a +bx+c x 2x =1(3,0)(1)ac >0(2)a +bx+c =0x 2=−1x 1=3x 2(3)2a −b =0(4)x >1y x (5)3a +2b +c >0A.个B.个C.个D.个二、 填空题 (本题共计 4 小题 ,每题 5 分 ,共计20分 )11. 使代数式有意义的的取值范围是________.12. 因式分解:________.13. 如图,在平面直角坐标系中,的顶点在轴正半轴上,在上,=,点,在反比例函数的图象上,的面积等于,则=________.14. 如图,在中,,,,是的中点,点在边上,将沿翻折,使得点落在点处,当时,则________.三、 解答题 (本题共计 9 小题 ,每题 5 分 ,共计45分 )15. 计算:.16. 甲乙两个施工队在六安(六盘水-安顺)城际高铁施工中,每天甲队比乙队多铺设米钢轨,甲队铺设天的距离刚好等于乙队铺设天的距离,求出甲乙两施工队每天各铺设多少米? 17. 如图,水平放置在平面直角坐标系中,点、的坐标分别为、,点在函数的图象上.(1)求函数的表达式;(2)求点的坐标;(3)将沿轴正方向平移个单位后,判断点能否落在函数的图象上,请说明理由.12341x−8−−−−−√x 16−4=x 2xOy △OAB B x C AB AC 2BC A C y =(x >0)k x△OAB 12k Rt △ABC ∠C =90∘AB =10AC =8D AC E AB △ADE DE A A ′E ⊥AB A ′A =A ′+(−|1−|−2cos 8–√13)−22–√45∘10056▱ABCD A D (−2,5)(0,1)B(3,5)y =(k >0)k xy =k xC ▱ABCD x 10C y =(k >0)k x18. 观察以下等式:第个等式:,第个等式:,第个等式:,第个等式:,按照以上规律,解决下列问题:写出第个等式:________.写出你猜想的第个等式:________(用含的等式表示),并证明.19. 如图,在一笔直的海岸线上有,两个观测站,在的正东方向,.有一艘小船在点处,从测得小船在北偏西的方向,从测得小船在北偏东的方向.求点到海岸线的距离;小船从点处沿射线的方向航行一段时间后,到达点处,此时,从测得小船在北偏西的方向.求点与点之间的距离.(上述两小题的结果都保留根号) 20. 在平面直角坐标系中,的半径为.给出如下定义:记线段的中点为,当点不在上时,平移线段,使点落在上,得到线段(,分别为点,的对应点)线段长度的最小值称为线段到的“平移距离”.(1)已知点的坐标为,点在轴上.①若点与原点重合,则线段到的“平移距离”为________;②若线段到的“平移距离”为,则点的坐标为________;(2)若点,都在直线=上,且=,记线段到的“平移距离”为,求的最小值;(3)若点的坐标为,且=,记线段到的“平移距离”为,直接写出的取值范围. 21. 某校为了解学生对“新冠肺炎”及防护知识掌握情况,对全校学生进行新冠肺炎及防护知识测试,试卷满分分.随机抽取了部分学生的测试成绩进行分析,按,,,四个等级进行统计,并将统计结果绘制了如下两幅不完整的统计图.(说明:测试成绩取整数,级:分分;级:分分;级:分分;级:分以下).1−=2×1+122122−=2×2+132223−=2×3+142324−=2×4+15242⋯(1)5(2)n n A B A B AB =4km P A 60∘B 45∘(1)P (2)P AP C B 15∘C B xOy ⊙O 1AB M M ⊙O AB M ⊙O A B ′′A ′B ′A B AA ′AB ⊙O A (−1,0)B x B O AB ⊙O AB ⊙O 2B A B y x+4AB 2AB ⊙O d 1d 1A (3,4)AB 2AB ⊙O d 2d 2100A B C D A 90∼100B 80∼89C 70∼79D 70学校共调查了________名学生.补全条形图.级在扇形图中的圆心角是________.全校一共有人,估计有多少人对“新冠肺炎”及防护知识掌握能达到分及以上?在抽样的等级学生中每人成绩不同,随机抽取两名学生进行“新冠肺炎”及防护知识的强化学习,用列表或者画树状图求出恰好抽中成绩最后的两名学生的概率. 22. 如图,抛物线经过轴上的点和点及轴上的点,经过,两点的直线为 .求抛物线的解析式;点从出发,在线段上以每秒个单位的速度向运动,同时点从出发,在线段上以每秒个单位的速度向运动.当其中一个点到达终点时,另一点也停止运动.设运动时间为秒,求为何值时, 的面积最大并求出最大值;过点作于点,过抛物线上一动点(不与点,重合)作直线的平行线交直线于点.若点,,,为顶点的四边形是平行四边形,求点的横坐标.23.如图,四边形是正方形,是边上的一点,是边的中点,且平分试探究,,之间的数量关系,并说明理由;若,求线段的长.(1)C (2)240090(3)D y =a +bx−5(a ≠0)x 2x A(1,0)B(5,0)y C B C y =kx+b(k ≠0)(1)(2)P A AB 1B E B BC 2C t t △PBE (3)A AM ⊥BC M N B C AM BC Q A M N Q N ABCD M BC E CD AE ∠DAM.(1)AM AD MC (2)AD =4MC参考答案与试题解析2022-2023学年九年级中考模拟检测(一) (数学)试卷一、 选择题 (本题共计 10 小题 ,每题 5 分 ,共计50分 )1.【答案】A【考点】实数大小比较【解析】将这几个实数按照从小到大的顺序排列,即可求解.【解答】解:由于,故最小的为.故选2.【答案】B【考点】同底数幂的乘法幂的乘方与积的乘方合并同类项【解析】利用同底数幂的乘法,同底数幂的乘法,合并同类项的法则,逐一检验.【解答】解:, ,本选项错误;,,本选项正确;,,本选项错误;,与不是同类项,不能合并,本选项错误.故选.3.【答案】B【考点】简单几何体的三视图【解析】根据主视图是在正面内得到的由前向后观察物体的视图,逐一判断即可.−3<−2<0<3−3A.A =−(−)a 43a 12B ⋅=−(−a)5a 5a 10C =8(2ab)3a 3b 3D a a 2B【解答】解:、主视图如图所示:、主视图如图所示:、主视图如图所示:、主视图如图所示:故选.4.【答案】B【考点】科学记数法--表示较大的数科学记数法与有效数字【解析】此题暂无解析【解答】解:.故选.5.【答案】C【考点】平行线的判定【解析】可以画图寻找规律,,,,…,奇数的平行;,,,…,偶数的也平行,但,,,,…,根据规律进行判断.【解答】解:如图,,,,,奇数的直线平行;,,,,偶数的直线也平行,,,故错误;A B C D B 128924229=1.28924229×≈1.3×10−810−8B a 1a 3a 5a 2a 4a 6⊥a 1a 2⊥a 2a 3⊥a 3a 4⊥a 4a 5a 1a 3a 5⋯a 2a 4a 6⋯A ⊥a 1a 100A,,故错误;,,故错误;故选.6.【答案】A【考点】中位数算术平均数众数【解析】根据平均数的定义可以先求出的值,进而就可以确定这组数的中位数和众数即可得到正确的选项.【解答】根据平均数的定义可知,==,这组数按照从小到大排列是:,,,,,这组数据从小到大的顺序排列后,处于中间位置的数是,由中位数的定义和众数的定义可知,这组数据的中位数是,众数是和.7.【答案】B【考点】根的判别式一元二次方程的定义【解析】由关于的一元二次方程有两个实数根,根据一元二次方程的定义和根的判别式的意义可得且,即,两个不等式的公共解即为的取值范围.【解答】解:∵关于的一元二次方程有两个实数根,即有两个实数根,∴且,即,解得,且,∴的取值范围为且.故选.8.【答案】B【考点】圆锥的全面积圆锥的计算【解析】B //a 2a 98B D ⊥a 49a 50DC x x 3×5−2−2−3−44223443324x m −2x−1=0x 2m≠0△≥0(−2−4⋅m ⋅(−1)≥0)2m x (mx−2)x−1=0m −2x−1=0x 2m≠0△≥0(−2−4⋅m ⋅(−1)≥0)2m≥−1m≠0m m≥−1m≠0B此题暂无解析【解答】解:根据题意可知,当以,为轴旋转时得到的几何体为圆锥,以为轴旋转得到的图形可看做两个底面相同的圆锥底面并在一起的图形.故当以为轴得到的几何体表面积为:,当以为轴得到的几何体表面积为:,当以为轴时,得到的圆锥底面半径等于:,故得到的几何体表面积为:.综上,当以为轴时得到的表面积最大.故选.9.【答案】C【考点】正方形的性质全等三角形的判定全等三角形的性质勾股定理【解析】根据已知及全等三角形的判定可得到,从而得到的面积的面积的面积.【解答】解:如图,∵,,∴.∵,,在和中,∴,∴,∴根据勾股定理的几何意义,的面积的面积的面积,AC BC AB AC π+πrl=16π+20π=36πr 2BC π+πrl=9π+15π=24πr 2AB r =3×45πr(+)=⋅(3+4)⋅π=πl 1l 2125845AC B △ABC ≅△CDE b =a +c ∠ACB+∠ECD =90∘∠DEC +∠ECD =90∘∠ACB =∠DEC ∠ABC =∠CDE AC =CE △ABC △CDE ∠ABC =∠CDE,∠ACB =∠CED,AC =CE,△ABC ≅△CDE(AAS)BC =DE b =a +c∴的面积的面积的面积.故选.10.【答案】B【考点】抛物线与x 轴的交点二次函数图象上点的坐标特征二次函数图象与系数的关系【解析】由函数图象可得抛物线开口向下,得到小于,又抛物线与轴的交点在轴正半轴,得到大于,进而得到与异号,根据两数相乘积为负得到小于,错误;由抛物线的对称轴为直线,得到对称轴右边随的增大而减小,对称轴左边随的增大而增大,故时,随的增大而减小,正确;由抛物线的对称轴为,利用对称轴公式得到,错误;由抛物线与轴的交点为及对称轴为,利用对称性得到抛物线与轴另一个交点为,进而得到方程的两根分别为和,正确;由于时对应的函数图象在轴上,得到,然后把代入即可得到,由,则,得出,正确.【解答】解:由二次函数的图象可得:抛物线开口向下,即,抛物线与轴的交点在轴正半轴,即,∴,错误;由函数图象可得:当时,随的增大而减小,故正确;∵对称轴为直线,∴,即,错误;由图象可得抛物线与轴的一个交点为,又对称轴为直线,抛物线与轴的另一个交点为,则方程的两根是,,正确.由于时,,∴,把代入即可得到,由,则,得出,正确.综上所知错误的有两个.故选.二、 填空题 (本题共计 4 小题 ,每题 5 分 ,共计20分 )11.【答案】【考点】分式有意义、无意义的条件二次根式有意义的条件【解析】此题暂无解析【解答】b =a +c =5+11=16C a 0y y c 0a c ac 0(1)x =1y x y x x >1y x (4)x =12a +b =0(3)x (3,0)x =1x (−1,0)a +bx+c =0x 2−13(2)x =3x 9a +3b +c =0b =−2a 3a +c =0a <0b >03a +2b +c >0(5)y =a +bx+c x 2a <0y y c >0ac <0(1)x >1y x (4)x =1−=1b 2a 2a +b =0(3)x (3,0)x =1x (−1,0)a +bx+c =0x 2=−1x 1=3x 2(2)x =3y =09a +3b +c =0b =−2a 3a +c =0a <0b >03a +2b +c >0(5)(1)(3)B x >8解:由题意知:解得.故答案为:.12.【答案】【考点】因式分解-运用公式法因式分解-提公因式法【解析】此题暂无解析【解答】解:.故答案为:.13.【答案】【考点】反比例函数系数k 的几何意义【解析】过点作于点,过点作于点,设,所以=,=,根据题意求出点的坐标为,由于点,在反比例函数的图象上,从而列出方程:=,解出的值即可求出的值.【解答】过点作于点,过点作于点,设∴=,=,∵,=,∴==,∵=,∴,∴=,∴=,∴===,∴点的坐标为,由于点,在反比例函数的图象上,∴=,∴解得:=,∴==,{x−8≥0,≠0,x−8−−−−−√x >8x >84(2x+1)(2x−1)16−4=4(4−1)=4(2x+1)(2x−1)x 2x 24(2x+1)(2x−1)6C CD ⊥OB D A AE ⊥OB E C(x,y)CD y OD x A (3x−,3y)16y A C y =(x >0)k x (3x−)⋅3y 16yxy xy k C CD ⊥OB D A AE ⊥OB E C(x,y)CD y OD x CD//AE AC 2BC AE 3CD 3y OB ⋅AE 1212OB =8y BD OB−OD =−x 8y DE 2BD =−2x 16y OE OD−DE x−(−2x)16y 3x−16y A (3x−,3y)16y A C y =(x >0)k x (3x−)⋅3y 16yxy xy 6k xy 614.【答案】或【考点】翻折变换(折叠问题)相似三角形的性质与判定【解析】分两种情形分别求解,作于,连接.想办法求出,利用等腰直角三角形的性质求出即可.【解答】解:①如图,作于,连接,在中,,∵,,∴,∴,∴,∴,,∵,∴,由翻折不变性可知,,∴,∴,∴,②如图,作于,当时,与①同理可得,.故答案为:或.三、 解答题 (本题共计 9 小题 ,每题 5 分 ,共计45分 )15.【答案】原式282–√542–√5DF ⊥AB F AA'AE AA'DF ⊥AB F AA ′Rt △ACB BC ==6A −A B 2C 2−−−−−−−−−−√∠DAF =∠BAC ∠AFD =∠C =90∘△AFD ∽△ACB ==DF BC AD AB AF AC ==DF 6410AF 8DF =125AF =165E ⊥AB A ′∠AE =A ′90∘∠AED =45∘EF =DF =125AE =E =+=A ′125165285A =A ′282–√5DF ⊥AB F E ⊥AB A ′AE =−=16512545A =AE =A ′2–√42–√5282–√542–√5=2+9−(−1)−2×2–√2–√2–√2=2+9−+1−–√–√–√.【考点】特殊角的三角函数值负整数指数幂实数的运算【解析】直接利用特殊角的三角函数值以及负整数指数幂的性质、绝对值的性质、二次根式的性质分别化简得出答案.【解答】原式.16.【答案】解:设甲队每天铺设米,乙队每天铺设米,由题可得解得答:甲队每天铺设米,乙队每天铺设米.【考点】二元一次方程组的应用——其他问题【解析】此题暂无解析【解答】解:设甲队每天铺设米,乙队每天铺设米,由题可得解得答:甲队每天铺设米,乙队每天铺设米.17.【答案】把点代入,∴==,∴反比例函数解析式为;∵四边形为平行四边形,∴=,,∵点、的坐标分别为、,点,∴==,∴=,∴点坐标为;点落在函数的图象上.理由如下:=2+9−+1−2–√2–√2–√=10=2+9−(−1)−2×2–√2–√2–√2=2+9−+1−2–√2–√2–√=10x y { x−y =100,5x =6y,{ x =600,y =500,600500x y { x−y =100,5x =6y,{ x =600,y =500,600500B(3,5)y =(k >0)k x k 3×515y =15x ABCD AB CD AB//CD A D (−2,5)(0,1)B(3,5)AB 3+25CD 5C (5,1)C y =(k >0)k x把点沿轴正方向平移个单位后得到对应点的坐标为,而=时,,∴点落在函数的图象上.【考点】反比例函数图象上点的坐标特征待定系数法求反比例函数解析式平行四边形的性质坐标与图形变化-平移【解析】(1)把点坐标代入中得到的值,从而得到反比例函数解析式;(2)利用平行四边形的性质得到==,,然后写出点坐标;(3)利用点平移的坐标规律得到点沿轴正方向平移个单位后得到对应点的坐标为,然后根据反比例函数图象上点的坐标特征可判断点落在函数的图象上.【解答】把点代入,∴==,∴反比例函数解析式为;∵四边形为平行四边形,∴=,,∵点、的坐标分别为、,点,∴==,∴=,∴点坐标为;点落在函数的图象上.理由如下:把点沿轴正方向平移个单位后得到对应点的坐标为,而=时,,∴点落在函数的图象上.18.【答案】猜想的第个等式:.故答案为:.证明:∵左边右边,∴等式成立.【考点】规律型:数字的变化类【解析】暂无暂无【解答】解:∵第个等式:,(5,1)x 10(15,1)x 15y ==115x C y =(k >0)k x B y =(k >0)k x k AB CD 5AB//CD C (5,1)x 10(15,1)C y =(k >0)k x B(3,5)y =(k >0)k x k 3×515y =15x ABCD AB CD AB//CD A D (−2,5)(0,1)B(3,5)AB 3+25CD 5C (5,1)C y =(k >0)k x (5,1)x 10(15,1)x 15y ==115x C y =(k >0)k x −=2×5+16252(2)n −=2n+1(n+1)2n 2−=2n+1(n+1)2n 2=(n+1+n)(n+1−n)=2n+1=(1)1−=2×1+12212−=2×2+122第个等式:,第个等式:,第个等式:,∴第个等式:.故答案为:.猜想的第个等式:.故答案为:.证明:∵左边右边,∴等式成立.19.【答案】解:如图,过点作于点.设.在中,,,∴.在中,,,∴.∵,即,解得.∴点到海岸线的距离为.如图,过点作于点.则.在中,,,∴.∵,∴.在中,,,∴.∴点与点之间的距离大约为.【考点】解直角三角形的应用-方向角问题【解析】(1)过点作于点,设,先解,用含的代数式表示,再解,用含的代数式表示,然后根据,列出关于的方程,解方程即可;(2)过点作于点,先解,得出,再解,得出.【解答】解:如图,过点作于点.2−=2×2+132223−=2×3+142324−=2×4+152425−=2×5+16252−=2×5+16252(2)n −=2n+1(n+1)2n 2−=2n+1(n+1)2n 2=(n+1+n)(n+1−n)=2n+1=(1)P PD ⊥AB D PD =xkm Rt △PBD ∠BDP =90∘∠PBD =−=90∘45∘45∘BD =PD =xkm Rt △PAD ∠ADP =90∘∠PAD =−=90∘60∘30∘AD =PD =xkm 3–√3–√BD+AD =AB x+x =43–√x =2−23–√P (2−2)km 3–√(2)B BF ⊥AC F ∠ABC =105∘Rt △ABF ∠AFB =90∘∠BAF =30∘BF =AB =2km12∠ABC =105∘∠C =−∠BAC −∠ABC =180∘45∘Rt △BCF ∠BFC =90∘∠C =45∘BC =BF =2km 2–√2–√C B 2km 2–√P PD ⊥AB D PD =xkm Rt △PBD x BD Rt △PAD x AD BD+AD =AB x B BF ⊥AC F Rt △ABF BF =AB =2km12Rt △BCF BC =BF =2km 2–√2–√(1)P PD ⊥AB D设.在中,,,∴.在中,,,∴.∵,即,解得.∴点到海岸线的距离为.如图,过点作于点.则.在中,,,∴.∵,∴.在中,,,∴.∴点与点之间的距离大约为.20.【答案】,或如图中,设直线=,交轴于,,,交于.∵=,=,∴===,∵==,∴=,观察图像可知,当的中点与重合时,最小值==.即=.如图中,由题意,PD =xkm Rt △PBD ∠BDP =90∘∠PBD =−=90∘45∘45∘BD =PD =xkm Rt △PAD ∠ADP =90∘∠PAD =−=90∘60∘30∘AD =PD =xkm 3–√3–√BD+AD =AB x+x =43–√x =2−23–√P (2−2)km 3–√(2)B BF ⊥AC F ∠ABC =105∘Rt △ABF ∠AFB =90∘∠BAF =30∘BF =AB =2km12∠ABC =105∘∠C =−∠BAC −∠ABC =180∘45∘Rt △BCF ∠BFC =90∘∠C =45∘BC =BF =2km 2–√2–√C B 2km 2–√B(−5,0)(7,0)6y y E 5)0)⊙O K OE 4OF 5EF 5S △OEF ×OE×OF OH AB M H OH−OK d 46的最小值===,的最大值===,∴.【考点】圆的综合题【解析】此题暂无解析【解答】此题暂无解答21.【答案】,(人),所以该校有人对“新冠肺炎”及防护知识掌握能达到分及以上.设四人为,成绩最后两名为,画树状图有由图可知,共有种情况,其中是的有两种,所以.答:恰好抽中成绩最后的两名学生的概率为.【考点】用样本估计总体列表法与树状图法频数(率)分布直方图扇形统计图【解析】用级人数除以它所占的百分比得到调查的总人数;用乘以样本中级人数所占的百分比即可.【解答】d 2PQ 5−63d 2PR 7+168≤≤6d 24072(2)2400×=48084048090(3)P,Q,M,N M,N 12M,N P =1616(1)B (2)2400A解:(人),所以该企业员工中参加本次安全生产知识测试共有人;级人数(人),级在扇形图中的圆心角,条形统计图为:故答案为:;.(人),所以该校有人对“新冠肺炎”及防护知识掌握能达到分及以上.设四人为,成绩最后两名为,画树状图有由图可知,共有种情况,其中是的有两种,所以.答:恰好抽中成绩最后的两名学生的概率为.22.【答案】解:∵点,在上,∴∴,∴抛物线解析式: .由题意,得,由知, ,∴点到的高为,∴ .当时,的面积最大,最大值为 .由知,所在直线为:,根据题意知:;设,分种情况进行讨论:①当为对角线时,解得:或(舍去). ②当为对角线时,解得 或 ③当为对角线时解得:或(舍去). 综上所述,若点,,,为顶点的四边形是平行四边形,点的横坐标为:或或 .(1)20÷50%=4040C =40−8−20−4=8C =×=840360∘72∘4072(2)2400×=48084048090(3)P,Q,M,N M,N 12M,N P =1616(1)B A y =a +bx−5x 2{a +b −5=0,25a +5b −5=0,a =−1,b =6y =−+6x−5x 2(2)PB =4−t,BE =2t (1)∠OBC =45∘P BC h BP sin =(4−t)45∘2–√2=BE ⋅h =×(4−t)×2t S △PBE 12122–√2=−+2(0<t ≤)2–√2(t−2)22–√52–√2t =2△PBE 22–√(3)(1)BC y =x−5A(1,0),M(3,−2)N (m,−+6m−5),Q(n,n−5)m 23AM {1+3=m+n ,0−2=−+6m−5+n−5,m 2{m=4,n =0{m=1,n =3AN {1+m=n+3,−2+n−5=−+6m−5,m 2 m=,5+41−−√2n =1+41−−√2 m=,5−41−−√2n =.1−41−−√2AQ {1+n =3+m ,n−5=−+6n−5−2,m 2{m=4,n =6{m=1,n =3A M N Q N 45+41−−√25−41−−√2【考点】待定系数法求二次函数解析式二次函数综合题【解析】(1)∵点、在上,∴,∴,∴抛物线解析式: .(2)由题意,得:∴ ,由(1)知, ,∴点到的高为,∴ .当时,的面积最大,最大值为 .(3)由①知,所在直线为:,根据题意知:;设,分种情况进行讨论:(1)当为对角线时,,解得:或(舍去). (2)当为对角线时,解得 或 . (3)当为对角线时,解得:或(舍去). 综上所述,若点、、、为顶点的四边形是平行四边形,点的横坐标为:或或 .【解答】解:∵点,在上,∴∴,∴抛物线解析式: .由题意,得,由知, ,∴点到的高为,∴ .当时,的面积最大,最大值为 .由知,所在直线为:,根据题意知:;设,分种情况进行讨论:①当为对角线时,解得:或(舍去). B A y =a +bx−5x 2{a +b −5=025a +5b −5=0a =−1,b =6y =−+6x−5x 2PB =4−t,BE =2t∠OBC =45∘P BC h BP sin =(4−t)45∘2–√2=BE ⋅h =×(4−t)×2=−+2(0<t ≤)S △PBE 12122–√22–√2(1−2)22–√52–√2t =2△PBE 22–√BC y =x−5A(1,0),M(3,−2)N (m,−+6m−5),Q(n,n−5)m 23AM {1+3=m+n 0−2=−+6m−5+n−5m 2{m=4n =0{m=1n =3AN {1+m=n+3−2+n−5=−+6m−5m 2 m=5+41−−√2n =1+41−−√2 m=5−41−−√2n =12AQ {1+n =3+m n−5=−+6n−5−2m 2{m=4n =6{m=1n =3A M N Q N 45+41−−√25−41−−√2(1)B A y =a +bx−5x 2{a +b −5=0,25a +5b −5=0,a =−1,b =6y =−+6x−5x 2(2)PB =4−t,BE =2t (1)∠OBC =45∘P BC h BP sin =(4−t)45∘2–√2=BE ⋅h =×(4−t)×2t S △PBE 12122–√2=−+2(0<t ≤)2–√2(t−2)22–√52–√2t =2△PBE 22–√(3)(1)BC y =x−5A(1,0),M(3,−2)N (m,−+6m−5),Q(n,n−5)m 23AM {1+3=m+n ,0−2=−+6m−5+n−5,m 2{m=4,n =0{m=1,n =3②当为对角线时,解得 或 ③当为对角线时解得:或(舍去). 综上所述,若点,,,为顶点的四边形是平行四边形,点的横坐标为:或或 .23.【答案】解:.理由:如图,分别延长,相交于点.∵四边形是正方形,∴,∴,∵是边的中点,∴,∵,,,∴(),∴,∵平分,∴,∴,即.∵四边形是正方形,∴,,设,则,.∵在中, ,∴,解得,∴.【考点】全等三角形的性质与判定正方形的性质勾股定理角平分线的性质【解析】无无【解答】解:.理由:如图,分别延长,相交于点.AN {1+m=n+3,−2+n−5=−+6m−5,m 2 m=,5+41−−√2n =1+41−−√2 m=,5−41−−√2n =.1−41−−√2AQ {1+n =3+m ,n−5=−+6n−5−2,m 2{m=4,n =6{m=1,n =3A M N Q N 45+41−−√25−41−−√2(1)AM =AD+MC AE BC F ABCD AD//BC ∠DAE =∠F E CD ED =EC ∠DAE =∠F ∠DEA =∠FEC ED =EC △ADE ≅△FCE AAS AD =CF AE ∠DAM ∠DAE =∠MAE =∠F AM =MF =CF +MC =AD+MC AM =AD+MC (2)ABCD AB =BC =AD =4∠B =90∘MC =x BM =4−x AM =AD+MC =4+xRt △ABM A +B =A B 2M 2M 2+=42(4−x)2(4+x)2x =1MC =1(1)AM =AD+MC AE BC F∵四边形是正方形,∴,∴,∵是边的中点,∴,∵,,,∴(),∴,∵平分,∴,∴,即.∵四边形是正方形,∴,,设,则,.∵在中, ,∴,解得,∴.ABCD AD//BC ∠DAE =∠F E CD ED =EC ∠DAE =∠F ∠DEA =∠FEC ED =EC △ADE ≅△FCE AAS AD =CF AE ∠DAM ∠DAE =∠MAE =∠F AM =MF =CF +MC =AD+MC AM =AD+MC (2)ABCD AB =BC =AD =4∠B =90∘MC =x BM =4−x AM =AD+MC =4+x Rt △ABM A +B =A B 2M 2M 2+=42(4−x)2(4+x)2x =1MC =1。

精品解析:2023年陕西省西安市交通大学附属中学九年级第一次模考数学试题(解析版)

精品解析:2023年陕西省西安市交通大学附属中学九年级第一次模考数学试题(解析版)
【分析】由于一次函数 与反比例函数 在同一平面直角坐标系内的图象没有交点,则说明 无解.
【详解】解:令 ,变形得: ,
∵图象有交点,
∴ 有解,
∴ ,
解得: .
故答案为: .
【点睛】此题运用了方程组的知识和一元二次方程根的判别式的有关内容,注意函数图像的交点问题和对应一元二次方程的根的关系.
13.如图,在矩形 中, , ,点 为线段 的中点,动点 从点 出发,沿 的方向在 和 上运动,将矩形沿 折叠,点 的对应点为 ,当点 恰好落在矩形的对角线上时,点 运动的距离为________.
【分析】根据对角线互相垂直的矩形是正方形即可求解.
【详解】解:添加条件 ,能使矩形 成为正方形,A、C、D选项都是矩形的性质,都不符合题意,
故选:B.
【点睛】本题考查了正方形的判定,矩形的性质,掌握以上知识是解题的关键.
5.四边形不具稳定性,四条边长都确定的四边形.当内角的大小发生变化时.其形状也随之改变.如图,改变正方形 的内角,使正方形 变为菱形 ,如果 ,那么菱形 与正方形 的面积之比是( )
初三数学(一)
一、选择题(共8小题,每小题3分,共24分)
1. 的倒数是()
A.3B. C. D.1
【答案】B
【解析】
【分析】根据倒数的概念即可得到答案.
【详解】解: 的倒数是﹣3,
故选:B.
【点睛】本题考查的是一个数的倒数,解题的关键是掌握倒数的概念:两个数乘积为1,则这两个数互为倒数.
2.如图,将三角尺的直角顶点放在直尺的一边上, , ,则 的度数等于()
A. B. C. D.1
【答案】A
【解析】
【分析】过D'作D'M⊥AB于M,求出正方形ABCD的面积=AB2,再由含30°角的直角三角形的性质得AM= AD',D'M= AM= AD',然后求出菱形ABCD的面积=AB×D'M= AB2,即可求解.

北京六中学2024-2025学年初三第一次模考语文试题含解析

北京六中学2024-2025学年初三第一次模考语文试题含解析

北京六中学2024-2025学年初三第一次模考语文试题注意事项:1.答卷前,考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。

用2B铅笔将试卷类型(B)填涂在答题卡相应位置上。

将条形码粘贴在答题卡右上角"条形码粘贴处"。

2.作答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案。

答案不能答在试题卷上。

3.非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新答案;不准使用铅笔和涂改液。

不按以上要求作答无效。

4.考生必须保证答题卡的整洁。

考试结束后,请将本试卷和答题卡一并交回。

一、积累1.下列句子中没有语病的一项是()A.2014年我国多地又出现了感染H7N9型禽流感疫情,为了防止这种病毒再蔓延,我国政府采取了强有力的应对措施。

B.作为一档新兴的电视节目,《我是歌手》目前最重要的当务之急就是扬长避短,带给观众更为持久的音乐享受和情境感受。

C.为了保障学生安全和健康成长,教育部门大力开展各种形式的安全教育,打造浓郁的安全教育氛围,努力使校园安全工作落实到位。

D.最近十年间,我国造林6000余万公顷,人工林面积位居世界第一,但是土地沙漠化、植被覆盖率和森林病虫害等依然十分严重,令人担忧。

2.下列有关文学、文化常识表述不正确...的一项是()A.《左传》相传是春秋时期左丘明所作,是根据鲁史写的编年体史书,记载了春秋各国的政治、军事、外交等方面的大事。

《曹刿论战》出自该书。

B.“表”是古代的一种文体,通常借某一事物说明道理。

我们学过的这种体裁的文章有诸葛亮的《出师表》。

C.朱自清,字佩弦,江苏扬州人,著名诗人、学者、散文家。

我们学过的课文《春》、《绿》《背影》都是他的作品。

D.小店开张之际,热忱欢迎广大顾客朋友光临,我们将努力为大家营造一个良好的购物环境。

九年级第一次模拟考试(数学)试卷含答案

九年级第一次模拟考试(数学)试卷含答案

九年级第一次模拟考试(数学)(考试总分:120 分)一、单选题(本题共计7小题,总分21分)1.(3分)如如,如如如如如如如如如如如如如( )A.-1B.-1.5C.-4.2D.-32.(3分)如如如如“如如如如”如如如如如如如如如如如如如( )A.B.C.D.3.(3分)如如如如如如如x5如如( )A.x10÷x2B.(x2)3C.x2⋅x3D.x6−x4.(3分)如图,在Rt△ABC中,∠ACB=90∘,AB=5,AC=3,把Rt△ABC沿直线BC如如如如3如如如如如如如△A′B′C′,则四边形ABC′A′如如如如( )A.15B.18C.20D.225.(3分)如如如如如如如如如如如如如如如如如如如如如如如如,如如如如如如如如如如5如如如如如,如如如如如如如如8如如如如如,如如如如如如如如11如如如如如,…,如如如如如如如如,如如如如如如如如如如如如如如( )A.96B.92C.90D.936.(3分)如图,四边形ABCD 内接于⊙O,AB ^=AD ^,连接BD ,若∠DCE =50∘,则∠ABD 如如如如( )A.50∘B.60∘C.65∘D.70∘7.(3分)已知二次函数y =(x −m)(x −1)(1≤m ≤2),若函数图象过(a,b)和(a +6,b)两点,则a 如如如如如如( )A.−2≤a≤−32B.−2≤a≤−1C.−3≤a≤−32D.0≤a≤2二、解答题(本题共计13小题,总分81分)8.(3分)已知正比例函数y=(2m−6)x如如如如如如(x0,y0),如x0y0<0,则m如如如如如如( )A.m>3B.m>13C.m<13D.m<39.(5分)如如:(√6+√23)×√3+(−8)0−|√2−2|.10.(5分)如如如如如:{4(x−1)≥x+2 2x+13>x−1.11.(5分)如如如(mm+3−2mm−3)÷mm2−9,如如如-3,0,1,3如如如如如如如如如如如如.12.(5分)如图,点P为∠AOB内一定点,过点P作PD⊥OA于点D,请用尺规作图法在OB上求作一点Q,使得∠AOB与∠DPQ如如.(如如如如如如,如如如如)13.(6分)如图,在▱ABCD中,E、F为对角线AC上两点,且BE//DF,如如如如如如如如如如如如如,如如如.14.(6分)如如如如如如如如如如100如如,如如如如如如如如如如,如如如如如如如如如如,如如如如如如如如如“如如如如如如如如如如”如如如如如如如如如如,如如如如如如如如如如,如如如如如如如如如如如如如如“如如如如”如如如如如:如如如如如如如如如如如如如,如如如如如如如如如如20如如如如5如如如如如如如,如如如如:如如如如:90 91 89 89 90 98 90 97 95 9898 97 95 88 90 97 95 90 95 88(1)如如如如如如,如如如如如如如如如.如如如如如如如:如如如如:如如如如如如如如如如如如如如如如如如(如如如如如如如如如:(2)如如如如如如,如如如如如如如如如如如如如如如30%如如如“如如如如”如如如如,如如如如如如如如如如如如如如如,如如如如如.15.(6分)如如如如如如如如如“如如如如如”(如如),如如如如如如如如如如如如,如如如如如如如如如如,如如如如如如如如如如如如如“如如如如如”如如如如如如如,如如如如如如如如如如如如如如如,如如如如如如如如如如如如如如,如如如如如如:(1)如如如如如如如如如如如,如_____小组的数据无法算出“天下第一灯”的高度AB;(2)如如如如如如如如如如如如如如如如如,如如“如如如如如”如如如AB.(如如如如:sin⁡37∘≈0.60,cos⁡37∘≈0.80,tan⁡37∘≈0.75)16.(6分)如如如如如如如如如如如如如“如如如如”,如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如如,如如如如如如如如如如如如如如如如如如如如如如如如,如如如如如如如如如如,如如如如如如如如如如如如如如如如如如如如如如如如如如如如,如如如如如如如如如如如如如如如如如如如如如如,如如如如:如如如,如如如如如如如如如如如如如如如如如如如如如如如如(如如如如如如如如如如如),如如如如如如如如如如如如如如如如(如如如),如如如如如如如如如如如如如如如如如如如如如如如如如如.(1)"如如如如如如如如如”如如如如如__________如如;(如“如如”如“如如如”如"如如”)(2)如如如如如如如如如,如如如如如如如如如如如如如如如如“如如如如”如如如.17.(7分)小王计划从某批发市场批量购买A,B两种仿古秦兵马俑工艺品摆件,已知A种摆件的批发价比B种摆件的批发价每个少5元,且用400元购买的A种摆件数量与用500元购买的B如如如如如如如.(1)求A,B如如如如如如如如如如如?(2)如如如如如如如如如如如如如如如如如如8如如如,如如如如如如50如,如如如如如如如如如如如如按需购买100个仿古秦兵马俑工艺品摆件,共用了y元,设A种摆件购买了x个,请求出y与x之间的函数关系式.若小王共用了1930元,则他购买A,B如如如如如如如如?18.(8分)如图,在△ABC中,∠ACB=90∘,边AB与⊙O相切于点D,CD是⊙O的直径,AC交⊙O于E,连接BE交CD于P,交⊙O于F,连接DF.(1)求证:∠ABC=∠EFD;(2)若AD=2,CD=√6,求BD如如.19.(9分)如图,在平面直角坐标系中,抛物线L:y=−x2+bx+c的图象与x轴的一个交点为A(−3,0),顶点B如如如如如-1.(1)求抛物线L如如如如如如;(2)点P为坐标轴上一点,将抛物线L绕点P如如180∘如如如如如如L′,且A,B的对应点分别为C,D,当以A,B,C,D为顶点的四边形是矩形时,请求出符合条件的点P如如.20.(10分)如如如如1.如图如,在△ABC中,AB=AC=2,∠A=120∘如如SΔABC=__________;2.如图如,在△ABC中AB的垂直平分线交BC于D,交AB于点M,AC的垂直平分线交BC于E,交AC于N,N,∠DAE=20∘,BC=6,求∠BAC的度数及△ADE如如如;如如如如3.如图如,某农场主欲规划出一个如图所示的矩形田地ABCD其中BC=0.4km,点P在边AD 上,E,F为BC边上两点(包括端点),在△PEF如如如如如如如如如,如如如如如如如如如如如,如如△PEF的三边铺设围栏,围栏总长为0.6km(即△PEF的周长为0.6km),围栏PE与PF如如如如60∘(即∠EPF=60∘),为了尽可能多的种植农作物,要求矩形ABCD的面积尽可能的大请问能否设计出一个面积尽可能大又满足要求的矩形ABCD田地?若能,求出矩形ABCD如如如如如如,如如如,如如如如如.三、填空题(本题共计6小题,总分18分)21.(3分)如如如如如如如如如5,如如如如如如_____.22.(3分)因式分解:mx2−2mx+m=__________.23.(3分)如图,EC,BD是正五边形ABCDE如如如如,如∠1如如如如_____.24.(3分)如如2021如3如如如如如如如如如如如如1如如如,5如如如如如如如如如如如如1.21如如如,如3如如如5如如,如如如如如如如如如如如如如如如如如如如如如_____.的图象交于A(1,m),B(−2,n)两点,点C(2,t) 25.(3分)直线y=2x+b与反比例函数y=kx也在该反比例函数的图象上,则m,n,t如如如如如如__________.(如“ < "如如)26.(3分)如图,已知正方形ABCD中,AB=6,点E是边AD的中点,点P是边CD上的动点,点Q 是正方形内一动点,且满足∠BQC=90∘,则PE+PQ如如如如如__________.答案一、单选题(本题共计7小题,总分21分)1.(3分)如如如如A2.(3分)如如如如C3.(3分)如如如如D4.(3分)如如如如C5.(3分)如如如如D6.(3分)如如如如B7.(3分)如如如如C二、解答题(本题共计13小题,总分81分)8.(3分)如如如如A9.(5分)如如如如5√2−1如如如如如如=3√2+√2+1−(2−√2)=4√2+1−2+√2=5√2−1 10.(5分)【答案】2≤x<4【解析】解不等式4(x−1)≥x+2,得x≥2,如如如如2x+13>x−1,得x<4,则不等式组的解集为2≤x<4.·11.(5分)如如如如-10如如如如如如=[m(m−3)(m+3)(m−3)−2m(m+3)(m+3)(m−3)]⋅(m+3)(m−3)m=m[(m−3)−2(m+3)](m+3)(m−3)⋅(m+3)(m−3)m=(m−3)−2(m+3)=m−3−2m−6=−m−9,当m=−3,0,3如,如如如如如如,如如;当m=1如,如如=-1-9=-10.12.(5分)【答案】解:点Q如如如如:如:如如如如如如如如如如如如如如如如;如如如如如如如如如如如13.(6分)【答案】解:一对全等三角形为:△ADF≌△CBE(或△ADC≌△CBA,△DFC≌△BEA);证明:如四边形ABCD如如如如如如,如AD=BC,∠DAC=∠BCA,如BE//DF,如∠DFC=∠BEA,如∠AFD=∠BEC,如△ADF≌△CBE(AAS).如:如如如如如如如如如如如如如如如如如如如.·14.(6分)(1)5如3; 93如93如(2)如如如如如如如如如如如如如如如97如;如如如如:如20×30%=6如如如如如如如如如如如如如如如如如97如.15.(6分)未找到试题答案16.(6分)(1)如如;(2)如如如如:如如20如如如如如如如,如如如如如如如如如如如如如如如“如如如如”如如如如8如,如P(如如如如如如如如如如如如如如如“如如如如”)=820=25,如:如如2如如如如如如如如如如,如如如如如如如如如如如如3如;如如如如如如,如如如如如如如如如如如如如如如如如如如如如;如如2如如如如如如如如如如如如20如如如如如如,如如如如如如,如如如.17.(7分)(1)20;25;【解析】设A种摆件的单价为a元/个,则种摆件的单价为(a+5)如/如,如如如如,如如400a =500a+5,解得a=20,如a+5=25,如A,B如如如如如如如如如如20如/如如25如/如.(2)30;70.【解析】根据题意,可得y=50+0.8×[20x+25(100−x)]=50+0.8×[2500−5x] =−4x+2050,可得1930=−4x+2050,解得x=30,如小王购买A,B如如如如如如如30如如70如.18.(8分)(1)证明:∵AB与⊙O相切,CD是⊙O如如如,如CD⊥AB,如∠CDB=90∘,即∠ABC+∠BCD=90∘,如∠ACB=90∘,如∠ECD+∠BCD=90∘,如∠ABC=∠ECD,如∠ECD=∠EFD,如∠ABC=∠EFD.(2)由1知∠ACD=∠ABC,又如∠ADC=∠BDC=90∘,如△ACD∽△CBD,如CD AD =BDCD,如√62=√6如如BD=3.19.(9分)(1)y=−x2−2x+3;如如如如如−b2a=−1,如b=2a=−2,将A(−3,0),代入y=−x2−2x+c得:0=−9+6+c如解得:c=3如如抛物线L的函数表达式为:y=−x2−2x+3如(2)(0,1),(2,0) .【解析】由y=−x2−2x+3=−(x+1)2+4得点B如如如(−1,4)如由抛物线L如L′关于坐标轴上一点P对称,可得PA=PC,PB=PD如如以A,B,C,D如如如如如如如如如如如如如,由矩形的中心对称性知:PB=PA时,四边形ABCD如如如.如当点P在y轴上时,令点P坐标为(0,y)如如PB2=(−1)2+(4−y)2,PA2=(−3)2+y2如∴(−1)2+(4−y)2=(−3)2+y2如如y=1如如P1(0,1),如当点P在x轴上时,令点P坐标为(x,0)如如PB2=(−1)2+(4−y)2,PA2=(−3)2+y2,如(−1)2+(4−y)2=(−3)2+y 2,∴x =2,如P 2(2,0),综上所述满足题意的P 如如如如(0,1),(2,0).20.(10分)如如如如1.√32.∵DM 如如如AB如如如如如如,如DA =DB ,如∠B =∠DAB ,同理AE =CE,∠C =∠EAC ,如∠B +∠DAB +∠C +∠EAC +∠DAE =180∘,如∠DAB +∠EAC =80∘,如∠BAC =100∘,∵DA =DB,AE =CE ,如△ADE 如如如=AD +DE +AE =BD +DE +EC =BC =6;3.如图,延长FE 至M,使得EM =PE ,延长EF 至N ,使得FN =PF ,则MN 的长等于ΔPEF 的周长,即MN =0.6,则∠BMN +∠PNM =180∘−∠EPF 2=180∘−60∘2=60∘,如∠MPN =180∘−(∠PMN +∠PNM)=120∘,连接PM,PN ,作△PMN 的外接圆⊙O 过点O 作OG ⊥MN 于G,延长OG 交⊙O 如P ′,如P 作PH ⊥MN 于H ,分别连接OP,OM,ON ,则∠MON =2(180∘−∠MPN)=120∘,如OG ⊥BC ,如∠NOG =12∠MON =60∘,CN =12MN =0.3, 在RtΔOGN 中,ON =GN sin⁡∠NOG =0.3sin⁡60∘=√35,OG =√310, 如OG +PH ≤OP,∴√310+PH ≤√35, 解得PH ≤√310,如当点P 如如P ′重合时,PH 如如如如如√310, ∵PH =AB,∴PH 取得最大值时矩形ABCD 如如如如如,S 矩形ABCD 最大=BC ⋅PH 最大=0.4×√310=√325,如矩形ABCD 如如如如如如如如,如如如如√325km 2. 三、 填空题 (本题共计6小题,总分18分)21.(3分)如如如如±√522.(3分)【答案】m(x −1)223.(3分)如如如如7224.(3分)如如如如 10%25.(3分)【答案】n<t<m26.(3分)如如如如6√2−3。

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单项选择:20分()1.Let's look at the bag. Can you see _____“s”on the corner of_____ bag?A. a, aB. a, theC. an, aD. an, the()2.________ it is today!A. What fine weatherB. What a fine weatherC. How a fine weatherD. How fine a weather()3.Some people like to stay at home, but ________ like to go to the cinema.A. anotherB. otherC. othersD. other one()4.Have you ever seen ________ big panda before?A. a suchB. such aC. so aD. a so()5.-- _______ do you write to your parents?-- Once a month.A. How longB. How soonC. How oftenD. How far()6.He knows _________ English ________ French. But he’s very good at Japanese.A. either; orB. both; andC. neither; norD. either; nor ()7.–Oh, it’s raining heavily.-- Pl ease don’t leave ________ it stops.A. whenB. afterC. sinceD. until()8.– I called you last night but no one answered the phone.-- I ________ dinner with my friends in the restaurant.A. haveB. hadC. was havingD. have had()9. If you have lost a library book, you have to _________it.A. find outB. look afterC. pay forD. take care()10..The train _________ for twenty minutes.A. leftB. has leftC. is leavingD. has been away()11.Miss Li is one of _______ in our school.A. a popular teacherB. more popular teacherC. most popular teacherD. the most popular teachers ()12.–What’s the weather like tomorrow?-- The radio says it is going to be even ______.A. badB. worstC. badlyD. worse()13.The math problem is so hard that ________ students can work it out.A. a fewB. a littleC. manyD. few()14.The nurse told the children the sun ______ in the east.A. risesB. roseC. will riseD. has risen()15.If it ________ tomorro w we’ll go to the park.A. will not rainB. doesn’t rainC. is not rainingD. didn’t rain ()16. Tom has been in the factory _________he left school.A. whenB. sinceC. as soon asD. whether()17. I don't like winter because it’s ________cold.A. too muchB. far moreC. much tooD. much more()18. A talk on Chinese history __________in the school hall next Monday.A. be givenB. has been givenC. will be givenD. will give ()19.Study hard, _______ you will fall behind the others.A. andB. but c. or D. though()20.Mr. King didn’t know _______ yesterday evening.A. when does his son come backB. when his son comes backC. when did his son come homeD. when his son came home 完形填空:Everyone likes gifts. Some little kid think they don’t get enough gifts. Some old people think they get ______ (21) gifts. Different people like different ______ (22) gifts. Some presents are never too small. A little child may give his mother a leaf from a tree . It makes her _______(23).Gift giving is different in different countries. In Japan, people _______ (24) give special gifts. But they are not expensive. Later, the same gift may _____ (25) away to _______ (26) . Many people will not give big gifts to someone else. They will _______ (27) a park bench or a tree to help remember a person. In the USA, some people ask their families and friends ______ (28) money to charity rather than _______ (29) them gifts. In Sweden, doing something for someone is the best gift. People don’t need to spend too much money. Instead, _______ (30)a meal is enough.( )21. A. too much B. much too C. too many D. many too ( )22.A. kind of B, kinds of C. a kind D. a kind of ( )23.A. sad B.happily C. happy Dexciting( )24.A. sometimes B. some times C. some time D. sometime ( )25.A. be giving B. be given C. to give D. give( )26.A. someone other B. else someone C. someone else D.other someone( )27.A. spend B. take C. cost D. pay for( )28.A. give B. giving C. to give D. given( )29. A. buy B. to buy C. buying D. bought( )30.A. make B. making C. made D. makes阅读理解AMany students in China are learning English. Some of these students are small children. Others are teenagers(十几岁的青少年). Many are adults. Some learn at school, others study by themselves. A few learn English language (语言)over the radio, on television, or in films. One must work hard to learn another language.Why do all these people want to learn English? It is difficult to answer that question. Many boys and girls learn English at school because it is one of their subjects. They study their own language and maths and English ... Some people learn English because it is useful for their work. Many people often learn English for their higher sutdies, because at college or university(大学) some of their books are in English. Other people learn English because they want to read newspaper and magazines in English.( )31. Many students in China are learning English, aren't they? ____.A. Y es, they aren'tB. No, they areC. Y es, they areD. No, they aren't( )32. If one wants to learn another language well, he must ____.A. learn at schoolB. study by himselfC. work hardD. study hard( )33. The sentence "It is difficult to answer that question" means ____.A. that question is not difficult to answerB. that question is difficult to answer itC. it is difficultly to answer that questionD. it is hard to answer that question( )34. "Their own language" means ____.A. ChineseB. EnglishC. FrenchD. Japanese( )35. What's the Chinese of "study by themselves"?A. 和他们一起学习B. 自学C. 向他们学习D. 通过学习B( )36.Fei Junlong and Nie Haisheng traveled in outer space for ______ days.A.twoB.sixC.sevenD.eight( )37.Y ao Ming is a basketball player in ______ now.A.GermanyB.CanadaC.AmericaD.England( )38.The ______ was born in 1833.A. scientistB.singerC.astronautD.writer ( )39.The Story of My life is the name of a ______ .A.sportB.songC. book play( )40.Which of the following is true?A. Helen Keller couldn’t see, but could hearB.Jay Chou is from Shanghai, China.C.Alfred Nobel was a Swedish man.D.Y ao Ming ’mother is a teacher.CEveryone likes living in a clean and comfortant environment. If the envionment(环境) are bad, it will affect(影响)our body, and make us not feel well. Sometimes we may be terribly ill. At that time we don’t want to work, and we have to stay in bed and rest at home. So the envrionment is very important to us.It’s germs that makes us ill. There are germs everywhere, They are very small and you can’t find them with your own eyes, but you can see them with a microscope(显微镜)They are very small and there may be hundreds of them on a very small thing, Germs can always be found in dirty water. When we look at dirty water under the microscope, we shall see them in it. Germs can also be found in air and dust(灰尘). If you cut your finger, some of the dust from the floor may go into it, and you will have much pain in it. Sometimes the germs will go into all of your boby, and you will have pain everywhere.To keep us healthy, we should try to our best to make our environment become cleaner and tidier. This needs us to act together.( )41.The writer tell us that________.A. we like working when we are illB. germs can’t live in the water.C. we can’t feel ill if the environment is bad.D. we feel well when the environment is good.( )42.Germs are________.A. very small things that you can’t see with your eyes.B. the things that don’t effect people.C. the things that you can find with your eyes.D. the things that are very big.( )43. Where can germs be found? They can be found_________.A. on the small thingB. in air and dustC. only in dirty waterD. everywhere( )44.How will you feel if germs go into the finger that is cut?A. I will feel nothing.B. I won’t mind.C. I will feel tense.D. I will feel painful.( )45. From the passage we know that________.A. environment doesn’t affect our lifeB. we don’t need to improve our environmentC. germs may make us illD. if the environment is better, germs will be more.DClose your eyes for a minute and imagine what life would be like if you couldn’t see. Imagine having to read this page, not with your eyes but with your fingers. How do you feel, then?With medical knowledge and skills today, two-thirds of theworld’s 42 million blind people should not have to suffer (受苦). Unluckily, rich countries have this knowledge, but developing countries do not.ORBIS is an international charitable organization (慈善组织). Its goal is to help fight blindness all over the world. Inside a DC-8 airplane, there is a teaching hospital with television room and classroom. Doctors are taught the latest technology of helping the blind get sight again here. ORBIS is always trying to keep a closer relation among countries.ORBIS helps those developing countries by providing sight-saving training. It has taught over 35,000 doctors and nurses. They continue to treat thousands of blind people every year. They have travelled around the earth 3 times, visited 76 countries and treated over 20,000 blind people. They need your help to continue their work and free people from blindness.For just $38, you can help one person see; for $380 you can bring sight to 10 people; $1,300 helps train a doctor new skills; and for $13,000 you can provide a training program for a group of doctors who can make thousands of blind people see again. Y our love can help them open their eyes to the world.46题判断正误(“T”表示正确,“F”表示错误);47 题完成句子;48~49题简略回答,50题英译汉。

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