2014东城二模试题及答案word版

合集下载

北京市东城区2014年中学考试二模英语精彩试题word版

北京市东城区2014年中学考试二模英语精彩试题word版

实用文档学年第二学期综合练习(二)2013—2014 北京市东城区英语初三2014.6_____________ 姓名_____________ 考号学校_____________ 班级_____________ 120 分钟。

120 分,考试时间考12 1.本试卷共页,满分2生.在试卷和答题卡上准确填写学校名称、姓名和考号。

须3.试题答案一律填涂或书写在答题卡上,在试卷上作答无效。

2B 铅笔作答,其他试题用黑色字迹签字笔作答。

4.在答题卡上,选择题用知5.考试结束,请将本试卷和答题卡一并交回。

听力理解(共26 分)一、听对话,从下面各题所给的A、B、C 三幅图片中选择与对话内容相符的图片。

每段对话你将听两遍。

(共4 分,每小题1 分)1.A. B. C.2.A. B. C.3.大全.实用文档B. A.4.C.A. B.三个选项中选择C B、二、听对话或独白,根据对话或独白的内容,从下面各题所给的A、分)1 最佳选项。

每段对话或独白你将听两遍。

(共12 分,每小题6 小题。

请听一段对话,完成第5 至第5.What food does the man want to have?C. A cake. B. A pizza. A. A hamburger.6.How much does the man pay?C. $9. B. $8. A. $7.8 小题。

请听一段对话,完成第7 至第s trouble?'7.What's the man 'A. He cant find his way.'B. He doesnt have any money.t know how to buy a ticket.'C. He doesn大全.实用文档8.Where are the speakers?A. In a science museum.B. At a train station.C. At a movietheatre.请听一段对话,完成第9 至第10 小题。

2014年高三二模数学(文)北京市东城区试题Word版带解析

2014年高三二模数学(文)北京市东城区试题Word版带解析

知识点;函数与导数-------函数--------函数的定义域与值域
难度系数:2
第 4页 共 15页
(10)已知平面向量 a (1, 2) , b (2, m) ,且 a ∥ b ,则 b

解析: a
∥b

1 2
2 m
m
4
b
4 16 2 5
知识点:平面向量------------平面向量基本定理及坐标表示-----平面向量的坐标运算
2
知识点:解析几何--------直线-------两直线的位置关系
难度系数:3
(8)对任意实数
a
,b
定义运算“⊙”:a
b
b, a b a, a b
1, 1,

f
(x)
(x2
1)
(4
x)
k

若函数 f (x) 的图象与 x 轴恰有三个交点,则 k 的取值范围是
(A) (2,1)
(B) [0,1]
知识点; 推理与证明、数系的扩充与复数---------推理与证明---------直接证明与间接 证明; 数列----------数列综合; 难度系数:4
y1
2, y2
4 k 2 2
2
3
知识点;解析几何----------圆锥曲线------------抛物线
难度系数:3
(14)在棱长为1的正方体 ABCD A1B1C1D1 中,点 P 是正方体棱上一点(不包括棱的端
点), PA PC1 m , ①若 m 2 ,则满足条件的点 P 的个数为________;
(A)第一象限
(B)第二象限
(C)第三象限
(D)第四象限

北京东城高三二模试卷与解析

北京东城高三二模试卷与解析

东城区2014届高三二模理综化学试题2014.5可能用到的相对原子质量:H 1 O 16 S 326.下列说法正确的是A.钙和氮均为人体所需的微量元素B.二氧化硅是太阳能电池的主要材料C.油脂和蛋白质均属于高分子化合物D.明矾与水作用能生成有吸附性的物质答案:D解析:A.钙和氮均为人体所需的常量元素,错误;B.二氧化硅主要做光导材料,硅单质才是太阳能电池的主要材料,错;C.油脂不属于高分子化合物,错;D.明矾与水作用能生成有吸附性的Al(OH)3胶体,正确。

7. 右图是制备和研究乙炔的性质实验装置图。

下列说法不.正确..的是A.制备乙炔的反应原理是CaC2+2H2O Ca(OH) 2+C2H2↑B. c的作用是除去影响后续实验的杂质C. d中的有机产物与AgNO3溶液混合能产生沉淀D. e中的现象说明乙炔能被高锰酸钾酸性溶液氧化答案:C解析:A.制备乙炔可用电石(CaC2)与饱和食盐水反应,其方程式为:CaC2+2H2O Ca(OH)+C2H2↑,正确;因反应后所得气体中还有H2S等杂质,需用硫酸铜溶液除去,B正确;2C. d中的有机产物为溴代烃,取少量卤代烃于试管中,加NaOH溶液,振荡静置,待分层后,取上层水溶液,加入另一支盛有稀硝酸的溶液中,然后加入几滴AgNO3溶液,才能看到淡黄色沉淀,错误;D. 乙炔通入e中,高锰酸钾酸性溶液褪色,是因为高锰酸钾酸性溶液被乙炔还原,正确。

8. 下列离子方程式不正确...的是A. 向AgCl悬浊液中加入Na2S溶液:2AgCl +S2- == Ag2S+ 2Cl-B. 向NaHCO3溶液中加入NaOH溶液:HCO3-+OH- == CO32-+ H2OC. 向Ba(OH)2溶液中加入稀H2SO4:Ba2+ + OH- + H+ + SO42- == BaSO4↓+ H2OD. 向Cu粉中加入过量的浓HNO3:Cu+4H+ +2 NO3-== Cu2++2NO2↑+2H2O答案:C解析:A. 正确,溶解度:AgCl>Ag2S ,向AgCl悬浊液中加入Na2S溶液能生成Ag2S;B. 正确;C. 错误,向Ba(OH)2溶液中加入稀H2SO4:Ba2+ + 2OH- + 2H+ + SO42-= BaSO4↓+ 2H2O;D. 正确。

2014东城区中考数学二模

2014东城区中考数学二模

2014东城区中考数学二模一、选择题(本题共32分,每小题4分)下面各题均有四个选项,其中只有一个是符合题意的.1.(4分)如果a与﹣3互为相反数,那么a等于()A.3 B.﹣3 C.D.2.(4分)2014年3月21日上午,我国新型导弹驱逐舰昆明舰举行入列仪式,正式加入人民海军战斗序列.昆明舰采用柴燃交替动力,配备2台QC208燃气轮机,单台功率37500马力.数据37500用科学记数表示为()A.3.75×104 B.37.5×103 C.0.375×105D.3.75×1033.(4分)下列运算中,正确的是()A.a2+a3=a5B.a6÷a3=a2C.(a4)2=a6D.a2•a3=a54.(4分)同时抛掷两枚质地均匀的正方体骰子1次,下列事件中是不可能事件的是()A.朝上的点数之和为13B.朝上的点数之和为12C.朝上的点数之和为2D.朝上的点数之和小于35.(4分)本学期的五次数学单元练习中,甲、乙两位同学的平均成绩一样,方差分别为1.2,0.5,由此可知()A.甲比乙的成绩稳定B.甲乙两人的成绩一样稳定C.乙比甲的成绩稳定D.无法确定谁的成绩更稳定6.(4分)如图,已知⊙O是正方形ABCD的外接圆,点E是弧AD上任意一点,则∠BEC的度数为()A.30°B.45°C.60°D.90°7.(4分)已知一个菱形的周长是20cm,两条对角线的比是4:3,则这个菱形的面积是()A.12cm2B.24cm2C.48cm2D.96cm28.(4分)矩形ABCD中,AD=8cm,AB=6cm.动点E从点C开始沿边CB向点B以2cm/s的速度运动,动点F从点C同时出发沿边CD向点D以1cm/s的速度运动至点D停止.如图可得到矩形CFHE,设运动时间为x(单位:s),此时矩形ABCD去掉矩形CFHE后剩余部分的面积为y(单位:cm2),则y与x之间的函数关系用图象表示大致是下图中的()A.B.C.D.二、填空题(本题共16分,每小题4分)9.(4分)使得二次根式有意义的x的取值范围是.10.(4分)如图,在△ABC中,∠C=90°,点D在AC上,将△BCD沿BD翻折,点C落在斜边AB上,若AC=12cm,DC=5cm,则sinA=.11.(4分)如图,三个小正方形的边长都为1,则图中阴影部分面积的和是(结果保留π).12.(4分)如图,矩形BCDE的各边分别平行于x轴或y轴,物体甲和物体乙由点A(2,0)同时出发,沿矩形BCDE 的边作环绕运动,物体甲按逆时针方向以1个单位/秒匀速运动,物体乙按顺时针方向以2个单位/秒匀速运动,则两个物体运动后的第2次相遇地点坐标是;第2014次相遇地点的坐标是.三、解答题(本题共30分,每小题5分)13.(5分)计算:.14.(5分)解方程:x2﹣10x+8=0.15.(5分)如图,已知,EC=AC,∠BCE=∠DCA,∠A=∠E;求证:BC=DC.16.(5分)已知2x+y=4,求[(x﹣y)2﹣(x+y)2+y(2x﹣y)]÷(﹣2y)的值.17.(5分)甲、乙两公司各为“希望工程”捐款20000元.已知乙公司比甲公司人均多捐20元,且乙公司的人数比甲公司的人数少20%.问甲、乙两公司人均捐款各为多少元?18.(5分)如图,在直角坐标系中,O为原点.点A在第一象限,它的纵坐标是横坐标的3倍,反比例函数y=的图象经过点A.(1)求点A的坐标;(2)如果经过点A的一次函数图象与y轴的正半轴交于点B,且OB=AB,求这个一次函数的解析式.四、解答题(本题共20分,每小题5分)19.(5分)在平行四边形ABCD中,AB=6,AD=9,∠BAD的平分线交BC于点E,交DC的延长线于点F,BG⊥AE 于点G,,求△EFC的周长.20.(5分)图①表示的是某综合商场今年1~5月的商品各月销售总额的情况,图②表示的是商场服装部各月销售额占商场当月销售总额的百分比情况,观察图①、图②,解答下列问题:(1)来自商场财务部的数据报告表明,商场1~5月的商品销售总额一共是410万元,请你根据这一信息将图①中的统计图补充完整;(2)商场服装部5月份的销售额是多少万元?(3)小刚观察图②后认为,5月份商场服装部的销售额比4月份减少了.你同意他的看法吗?请说明理由.21.(5分)如图,在△ABC中,AB=AC,AE是角平分线,BM平分∠ABC交AE于点M,经过B、M两点的⊙O交BC于点G,交AB于点F,FB恰为⊙O的直径.(1)判断AE与⊙O的位置关系,并说明理由;(2)当BC=4,AC=3CE时,求⊙O的半径.22.(5分)我们曾学过“两点之间线段最短”的知识,常可利用它来解决两条线段和最小的相关问题,下面是大家非常熟悉的一道习题:如图1,已知,A,B在直线l的同一侧,在l上求作一点,使得PA+PB最小.我们只要作点B关于l的对称点B′,(如图2所示)根据对称性可知,PB=PB′.因此,求AP+BP最小就相当于求AP+PB′最小,显然当A、P、B′在一条直线上时AP+PB′最小,因此连接AB′,与直线l的交点,就是要求的点P.有很多问题都可用类似的方法去思考解决.探究:(1)如图3,正方形ABCD的边长为2,E为BC的中点,P是BD上一动点.连结EP,CP,则EP+CP的最小值是;(2)如图4,A是锐角MON内部任意一点,在∠MON的两边OM,ON上各求作一点B,C,组成△ABC,使△ABC 周长最小;(不写作法,保留作图痕迹)(3)如图5,平面直角坐标系中有两点A(6,4)、B(4,6),在y轴上找一点C,在x轴上找一点D,使得四边形ABCD的周长最小,则点C的坐标应该是,点D的坐标应该是.五.解答题(本题共22分,第23题7分,第24题7分,第25题8分)23.(7分)已知:关于x的一元二次方程mx2+(m﹣3)x﹣3=0.(1)求证:无论m取何值,此方程总有两个实数根;(2)设抛物线y=mx2+(m﹣3)x﹣3,证明:此函数图象一定过x轴,y轴上的两个定点(设x轴上的定点为点A,y轴上的定点为点C);(3)设此函数的图象与x轴的另一交点为B,当△ABC为锐角三角形时,求m的取值范围.24.(7分)如图,等腰Rt△ABC中,∠ACB=90°,AC=BC=4,P是AC边上一动点,由A向C运动(与A、C不重合),Q是CB延长线上一点,与点P同时以相同的速度由B向CB延长线方向运动(Q不与B重合),过P作PE⊥AB于E,连接PQ交AB于D.(1)当∠BQD=30°时,求AP的长;(2)当运动过程中线段ED的长是否发生变化?如果不变,求出线段ED的长;如果变化请说明理由;(3)在整个运动过程中,设AP为x,BD为y,求y关于x的函数关系式,并求出当△BDQ为等腰三角形时BD的值.25.(8分)定义:对于数轴上的任意两点A,B分别表示数x1,x2,用|x1﹣x2|表示他们之间的距离;对于平面直角坐标系中的任意两点A(x1,y1),B(x2,y2)我们把|x1﹣x2|+|y1﹣y2|叫做A,B两点之间的直角距离,记作d(A,B).(1)已知O为坐标原点,若点P坐标为(﹣1,3),则d(O,P)=;(2)已知C是直线上y=x+2的一个动点,①若D(1,0),求点C与点D的直角距离的最小值;②若E是以原点O为圆心,1为半径的圆上的一个动点,请直接写出点C与点E的直角距离的最小值.参考答案与试题解析一、选择题(本题共32分,每小题4分)下面各题均有四个选项,其中只有一个是符合题意的.1.【解答】由题意,得:a+(﹣3)=0,解得a=3.故选A.2.【解答】:37500=3.75×104,故选:A.3.【解答】A、a2与a3不是同类项,不能合并,故本选项错误;B、a6÷a3=a3,故本选项错误;C、(a4)2=a8,故本选项错误;D、a2•a3=a5,故本选项正确.故选D.4.【解答】根据同时抛掷两枚质地均匀的正方体骰子1次,每个骰子上的数字最大是6,故朝上的点数之和最大为12,所以,朝上的点数之和为13是不可能事件,故选:A.5.【解答】∵甲的方差是1.2,乙的方差是0.5,1.2>0.5,∴乙比甲的成绩稳定;故选C.6.【解答】连接OB,OC,∵⊙O是正方形ABCD的外接圆,∴∠BOC=90°,∴∠BEC=∠BOC=45°.故选B.7.【解答】设菱形的对角线分别为8x和6x,已知菱形的周长为20cm,故菱形的边长为5cm,根据菱形的性质可知,菱形的对角线互相垂直平分,即可知(4x)2+(3x)2=25,解得x=1,故菱形的对角线分别为8cm和6cm,所以菱形的面积=×8×6=24cm2,故选B.8.【解答】此题在读懂题意的基础上,分两种情况讨论:当x≤4时,y=6×8﹣(x•2x)=﹣2x2+48,此时函数的图象为抛物线的一部分,它的最上点抛物线的顶点(0,48),最下点为(4,16);当4<x≤6时,点E停留在B点处,故y=48﹣8x=﹣8x+48,此时函数的图象为直线y=﹣8x+48的一部分,它的最上点可以为(4,16),它的最下点为(6,0).结合四个选项的图象知选A项.故选:A.二、填空题(本题共16分,每小题4分)9.【解答】根据题意得,2x+1≥0,解得x≥﹣.故答案为:x≥﹣.10.【解答】如图,过D作DE⊥AB于点E,∵△BCD沿BD翻折,点C落在斜边AB上,∴∠ABD=∠CBD,又∵∠C=90,∴DE=DC,∵DC=5cm,∴DE=5cm,∵AC=12cm,∴AD=12﹣5=7cm,∴在Rt△AED中,sinA==.故答案为:.11.【解答】根据图示知,∠1+∠2=180°﹣90°﹣45°=45°,∵∠ABC+∠ADC=180°,∴图中阴影部分的圆心角的和是90°+90°﹣∠1﹣∠2=135°,∴阴影部分的面积应为:S==.故答案是:.12.【解答】由题意可得:矩形的边长为4和2,因为物体乙是物体甲的速度的2倍,时间相同,物体甲与物体乙的路程比为1:2,由题意知:①第一次相遇物体甲与物体乙行的路程和为12×1,物体甲行的路程为12×=4,物体乙行的路程为12×=8,在BC边相遇;②第二次相遇物体甲与物体乙行的路程和为12×2,物体甲行的路程为12×2×=8,物体乙行的路程为12×2×=16,在DE边相遇;此时相遇点的坐标为:(﹣1,﹣1),③第三次相遇物体甲与物体乙行的路程和为12×3,物体甲行的路程为12×3×=12,物体乙行的路程为12×3×=24,在A点相遇;…此时甲乙回到原出发点,则每相遇三次,两点回到出发点,∵2014÷3=671…1,故两个物体运动后的第2014次相遇地点的是:第一次相遇地点,即物体甲行的路程为12×1×=4,物体乙行的路程为12×1×=8;此时相遇点F的坐标为:(﹣1,1),故答案为:(﹣1,﹣1);(﹣1,1).三、解答题(本题共30分,每小题5分)13.【解答】原式=2﹣1+2﹣=1+.14.【解答】由原方程,得x2﹣10x=﹣8,配方,得x2﹣10x+25=﹣8+25,整理,得(x﹣5)2=17,解得x1=5+,x2=5﹣.15.【解答】证明:∵∠BCE=∠DCA,∴∠BCE+∠ACE=∠DCA+∠ACE,即∠ACB=∠ECD,在△ABC和△EDC中,,∴△ABC≌△EDC(ASA),∴BC=DC.16.【解答】∵2x+y=4,∴x+y=2,∴原式=[x2﹣2xy+y2﹣x2﹣2xy﹣y2+2xy﹣y2]÷(﹣2y)=(﹣2xy﹣y2)÷(﹣2y)=x+y=2.17.【解答】设甲公司人均捐款x元,则乙公司人均捐款x+20元,根据题意得:(1﹣20%)=解得:x=80经检验x=80是原方程的根,故x+20=80+20=100元,答:甲公司人均捐款80元,乙公司人均捐款100元.18.【解答】(1)由题意,设点A的坐标为(a,3a),a>0,∵点A在反比例函数y=的图象上,得:3a=,解得a1=2,a2=﹣2,经检验a1=2,a2=﹣2是原方程的根,但a2=﹣2不符合题意,舍去,∴点A的坐标为(2,6);(2)设点B的坐标为(0,m),∵m>0,OB=AB,∴在Rt△ABC中,根据勾股定理得:AB2=BC2+AC2,即m2=(6﹣m)2+2 2,解得m=,经检验m=是原方程的根,∴点B的坐标为(0,),设一次函数的解析式为y=kx+,由于这个一次函数图象过点A(2,6),∴6=2k+,解得k=,∴所求一次函数的解析式为y=x+.四、解答题(本题共20分,每小题5分)19.【解答】∵四边形ABCD为平行四边形,∴AB∥CD,AD∥BC,∴∠BAE=∠AFD,∠DAF=∠AEB,∵AF为∠BAD的角平分线,∴∠BAE=∠EAD,∴∠AFD=∠EAD,∠BAE=∠AEB,∠CEF=∠CFE,∴△ABE,△ADF,△CEF都是等腰三角形,又∵AB=6,AD=9,∴AB=BE=6,AD=DF=9,∴CE=CF=3.∵BG⊥AE,BG=4,由勾股定理可得:AG==2,∴AE=4,∵AB∥CD,∴△ABE∽△FCE.∴==,∴EF=2,∴△EFC的周长=EF+FC+CE=8.20.【解答】(1)410﹣(100+90+65+80)=410﹣335=75;如图:(2)商场服装部5月份的销售额是80万元×16%=12.8万元;(3)4月和5月的销售额分别是75万元和80万元,服装销售额各占当月的17%和16%,则为75×17%=12.75万元,80×16%=12.8万元,故小刚的说法是错误的.21.【解答】(1)AE与⊙O相切.理由如下:连接OM,则OM=OB,∴∠OMB=∠OBM.∵BM平分∠ABC,∴∠OBM=∠EBM.∴∠OMB=∠EBM.∴OM∥BC.∴∠AMO=∠AEB.在△ABC中,AB=AC,AE是角平分线,∴AE⊥BC.∴∠AEB=90°.∴∠AMO=90°.∴OM⊥AE.∴AE与⊙O相切;(2)在△ABC中,AB=AC,AE是角平分线,∴BE=BC,∠ABC=∠C.∵BC=4,cosC=,∴BE=2,cos∠ABC=.在△ABE中,∠AEB=90°,∴.设⊙O的半径为r,则AO=6﹣r.∵OM∥BC,∴△AOM∽△ABE.∴.∴.解得:r=∴⊙O的半径为.22.【解答】(1)连接AE,则EP+CP的最小值=AE==.(2)如图所示:点B,C即为所求作的点;(3)作点B关于y轴的对称点B',作A关于x轴的对称点A’,则B'的坐标是(﹣4,6),A'的对称点是(6,﹣4).设直线A'B'的解析式是y=kx+b,根据题意得:,解得:,则直线的解析式是:y=﹣x+2,令x=0,解得:y=2,则C的坐标是(0,2);令y=0,解得:x=2,则D的坐标是(2,0).故答案是:(0,2),(2,0).五.解答题(本题共22分,第23题7分,第24题7分,第25题8分)23.【解答】(1)△=(m﹣3)2+12m=(m+3)2∵(m+3)2≥0∴无论m取何值,此方程总有两个实数根.(2)由公式法:∴x1=﹣1,x2=,∴此函数图象一定过x轴,y轴上的两个定点,分别为A(﹣1,0),C(0,﹣3).(3)由(2)可知抛物线开口向上,且过点A(﹣1,0),C(0,﹣3)和B(,0).观察图象,当m<0时,△ABC为钝角三角形,不符合题意.当m>0时,可知若∠ACB=90°时,可证△AOC∽△COB.∴.∴|OC|2=|OA|•|OB|.∴32=1×|OB|.∴OB=9.即B(9,0).∴当时,△ABC为锐角三角形.即当m>时,△ABC为锐角三角形.24.【解答】(1)∵∠ACB=90°,AC=BC=4,设AP为x,∴PC=4﹣x,CQ=4+x.∵∠BQD=30°,∴CQ=PC.∴4+x=(4﹣x).解得x=8﹣4.(2)当点P,Q运动时,线段DE的长度不会改变.理由如下:作QF⊥AB,交直线AB的延长线于点F,∵PE⊥AB于E,∴∠DFQ=∠AEP=90°,∵点P,Q做匀速运动且速度相同,∴AP=BQ.∵△ABC是等腰直角三角形,∴可证PE=QF=AE=BF.在△PDE和△QDF中,,∴△PDE≌△QDF(AAS),∴DE=DF.∴DE=AB.又∵AC=BC=4,∴AB=4,∴DE=2,∴当点P,Q运动时,线段DE的长度不会改变.(3)∵AP=x,BD=y,∴AE=x,∵AB=AE+DE+BD,∵4=x+2+y,即y=﹣x+2(0<x<4),当△BDQ为等腰三角形时,x=y,∴x=4﹣4,即BD的值为4﹣4.25.【解答】(1)d(O,P)=|0+1|+|3﹣0|=1+3=4,故答案为4;(2)①设C点坐标为(x,x+2),d(C,D)=|x﹣1|+|x+2﹣0|=|x﹣1|+|x+2|,当x>1时,d(C,D)=x﹣1+x+2=2x+1>3,当﹣2≤x≤1时,d(C,D)=1﹣x+x+2=3,当x<﹣2时,d(C,D)=1﹣x﹣x﹣2=﹣2x﹣1>3,所以点C与点D的直角距离的最小值为3;②点C与点E的直角距离的最小值为2﹣.。

2014东城二模

2014东城二模

15.作者是如何做到把对母亲的感情写得真挚深切,十 分感人的?试举例分析。(不超过150字)(7分)
• 作者运用想像、议论等手法将对母亲感情 写得真挚深切,十分感人。 • 第9段,通过想像妈妈如果真的去参加研讨 会时将有的得体表现,由衷地表达了作者 对母亲善良的理解。 • 又以“相比之下,这个沉默而微笑的老人 并不丢人。在妈妈眼里,职位、专业、学 历、名气都可有可无,因此她穿行无羁” 的议论,深情赞美了母亲敢于超越世俗偏 见的勇气。
(共2分)
19. 请在第⑤段横线处填上一句话,阐明《朱子 家训》中的话与本段论点之间的联系。(3分)
虽然“一粥一饭”,“半丝半缕”微 不足道,但仍然凝聚着人们辛勤的劳动 汗水,是需要珍惜的劳动成果。
20.简要分析文章的论证过程。(3分)
议论文(立论)结构
一、中心论点\论题 (解释中心论点中的关键词) 二、多角度论证 方法:事实论证 事理论证(名言) 比喻论证 对比论证 三、指出方法\号召\提出论点
⑤但这个看似低调谦恭的阿姨,也有吃了熊心豹 子胆的时候,且这个时候出现得无比不合时宜。 \\“文革”之初,他们被造反派揪出来,挂了牌 子押上批斗会。\\可杨季康对“天兵天将”的推 第⑤段作者将杨绛先生在文革时, 推搡搡公然进行了反抗,而且怒目而视。这还了 公然反抗造反派批斗,与别人的 得!在批斗会上,那么多党内老资格的革命干部, 服服帖帖作对比,突出了她敢于 哪个不是服服帖帖?于是盛怒之下的造反派对她 维护自己尊严的勇气,写出了作 狠加惩罚,给她剃了个阴阳头。 \\我第一次惊奇 地感到季康先生性格中的凛然。 \\要知道,“牛 者的钦佩之情。 棚”里有不少从火线上转业过来的老战士,没有 一个敢于如此维护自己被践踏了的尊严。
2014东城二模

2014北京东城高三二模英语试卷和解析

2014北京东城高三二模英语试卷和解析

北京市东城区2013—2014学年度高三第二学期综合练习(二)英语试题第二部分:英语知识运用(共两节, 满分45分)第一节:单项填空(共15小题,每小题1分,满分15分)从A、B、C、D四个选项中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。

21.I have watched a number of movies recently,______ none of them have impressed me.A.but B.or C.so D.for答案:A解析过程:近来我看了许多电影,但是没有一个给我留下了深刻的印象。

根据两句之间的关系是转折关系,故答案选A。

22.The best way ______ how to drive a car is to practice with a driving instructor.A.learnt B.learningC.to learn D.to be learnt答案:C解析过程:固定句型:the best way to do sth /the best way of doing sth做某事最好的方法.故答案选A. 23.—Do you have any plan for this Sunday?—Yes, I ______ shopping with my friends.A.go B.am goingC.went D.have gone答案:B解析过程:--周日你有什么计划吗?---我打算和朋友去购物。

进行时表按计划,安排近期要发生的动作故答案选B。

24.It is believed ______ children should learn to be responsible from the very beginning.A.why B.howC.when D.that答案:D解析过程:it 是形式主语,真正的主语是后面的that 从句,从句中that 不能省略。

2014北京东城高考二模数学理(含答案)

2014北京东城高考二模数学理(含答案)

东城区2013-2014学年第二学期综合练习(二)高三数学 (理科)第一部分(选择题 共40分)一、选择题共8小题,每小题5分,共40分.在每小题列出的四个选项中,选出符合题目要求的一项. (1)设集合{12}A x x =∈+≥R ,集合{2,1,0,1,2}B =--,则AB =( ).A .{2}B .{1,2}C .{0,1,2}D .{1,0,1,2}-(2)在复平面内,复数32i 1i--对应的点位于( ). A .第一象限 B .第二象限 C .第三象限 D .第四象限(3)已知一个算法的程序框图如图所示,当输出的结果为0时,输入的x 值为( ).A .2或2-B .1-或2-C .1或2-D .2或1-(4)如果实数x ,y 满足条件10,10,10,x y x y y -+≥⎧⎪++≤⎨⎪+≥⎩则2z x y =-的最大值为( ).A .3-B .1-C .0D .1(5)设n S 为等差数列{}n a 的前n 项和,若11a =,公差2d =,236n n S S +-=,则n =( ). A .5 B .6C .7D .8(6)6个人站成一排,其中甲、乙必须站在两端,且丙、丁相邻,则不同站法的种数为( ).A .12B .18C .24D .36(7)若直线1,x t y a t=+⎧⎨=-⎩(t 为参数)被圆22cos 22sin x y =+⎧⎨=+⎩αα(α为参数)所截的弦长为22,则a 的值为( ).A .1 或5B .1- 或5C .1 或5-D .1- 或5-(8)对任意实数a ,b 定义运算“⊙”:,1,,1,b a b ab a a b -⎧=⎨-<⎩…设2()(1)(4)f x x x k =-++,若函数()f x 的图象与x 轴恰有三个交点,则k 的取值范围是( ).A .(2,1)-B .[0,1]C .[2,0)-D .[2,1)-第二部分(非选择题 共110分)二、填空题共6小题,每小题5分,共30分. (9)已知tan =2α,那么cos 2=α .(10)已知平面向量a ,b ,若3=a ,13-=a b ,6⋅=a b ,则=b ;向量a ,b 夹角的大小为 .(11)在区间[0,6]上随机取两个实数x ,y ,则事件“26x y +…”的概率为_________.(12)如图所示,PA 与圆O 相切于A ,直线PO 交圆O 于B ,C 两点,AD BC ⊥,垂足为D ,且D 是OC 的中点,若6PA =,则PC = .(13)若直线(1)(0)y k x k =+>与抛物线24y x =相交于A ,B 两点,且A ,B 两点在抛物线的准线上的射影分别是M ,N ,若2BN AM =,则k 的值是 .A BCPD O·(14)在棱长为1的正方体1111ABCD A BC D -中,点P 是正方体棱上一点(不包括棱的端点),1PA PC m +=,①若2m =,则满足条件的点P 的个数为________;②若满足1PA PC m +=的点P 的个数为6,则m 的取值范围是________. 三、解答题共6小题,共80分.解答应写出文字说明,演算步骤或证明过程. (15)(本小题共13分)已知函数2()sin 3sin sin()2f x x x x π=++.(Ⅰ)求()12f π的值; (Ⅱ)当[0,]2x π∈时,求函数()f x 的最大值和最小值.(16)(本小题共13分)“你低碳了吗?”这是某市为倡导建设资源节约型社会而发布的公益广告里的一句话.活动组织者为了解这则广告的宣传效果,随机抽取了100名年龄段在[10,20),[20,30),,[50,60)的市民进行问卷调查,由此得到样本的频率分布直方图如图所示. (Ⅰ)求随机抽取的市民中年龄段在[30,40)的人数;(Ⅱ)从不小于40岁的人中按年龄段分层抽样的方法随机抽取8人,求[50,60)年龄段抽取的人数; (Ⅲ)从按(Ⅱ)中方式得到的8人中再抽取3人作为本次活动的获奖者,记X 为年龄在[50,60)年龄段的人数,求X 的分布列及数学期望.0.020 0.02510 20 30 40 50 60 0.015 0.005频率 组距(17)(本小题共14分)如图,四棱锥E ABCD -中,平面EAD ⊥平面ABCD ,DC //AB ,BC CD ⊥,EA ED ⊥,且4AB =,2BC CD EA ED ====.(I )求证:BD ⊥平面ADE ;(II )求BE 和平面CDE 所成角的正弦值;(III )在线段CE 上是否存在一点F 使得平面BDF ⊥平面CDE ,请说明理由.DCBEA(18)(本小题共13分)已知0a >,函数2()21axf x a x =++,()ln g x a x x a =-+. (Ⅰ)求函数()f x 的单调区间;(Ⅱ)求证:对于任意的12,(0,e)x x ∈,都有12()()f x g x >.(19)(本小题共13分)已知椭圆22221x ya b+=的一个焦点为(2,0)F,且离心率为63.(Ⅰ)求椭圆方程;(Ⅱ)斜率为k的直线l过点F,且与椭圆交于,A B两点,P为直线3x=上的一点,若△ABP为等边三角形,求直线l的方程.(20)(本小题共14分)设a 是一个自然数,()f a 是a 的各位数字的平方和,定义数列{}n a :1a 是自然数,1()n n a f a -=(*n ∈N ,2n ≥).(Ⅰ)求(99)f ,(2014)f ; (Ⅱ)若1100a ≥,求证:12a a >;(Ⅲ)当11000a <时,求证:存在*m ∈N ,使得32m m a a =.东城区2013-2014学年第二学期综合练习(二)高三数学参考答案及评分标准 (理科)一、选择题(本大题共8小题,每小题5分,共40分) (1)B (2)A (3)C (4)D (5)D (6)C (7)A (8)D 二、填空题(本大题共6小题,每小题5分,共30分) (9)35- (10)4 60(11)14(12)23 (13)223(14)6 (3,5) 注:两个空的填空题第一个空填对得3分,第二个空填对得2分. 三、解答题(共6小题,共80分) (15)(共13分)解:(Ⅰ)2()sin 3sin sin()2f x x x x π=++2sin 3sin cos x x x =+ 1cos 23sin 222x x -=+ 311sin 2cos 2222x x =-+ 1sin(2)62x π=-+. 所以1()122f π=. …………………7分 (Ⅱ)当[0,]2x π∈时,52666x πππ-≤-≤. 所以,当266x ππ-=-时,即0x =时,函数()f x 取得最小值0; 当262x ππ-=时,即3x π=时,函数()f x 取得最大值32.…………………13分(16)(共13分)解:(Ⅰ)110(0.0200.0250.0150.005)0.35-⨯+++=,1000.35⨯=,即随机抽取的市民中年龄段在[30,40)的人数为35.………………………4分 (Ⅱ)1000.1515⨯=,1000.055⨯=,所以85220⨯=, 即抽取的8人中[50,60)年龄段抽取的人数为2. ……………………7分(Ⅲ)X 的所有可能取值为0,1,2.36385(0)14C P X C ===;12263815(1)28C C P X C ===; 2126383(2)28C C P X C ===.所以X 的分布列为X 0 1 2P514 1528 328X 的数学期望为515330121428284EX =⨯+⨯+⨯=.………………………13分 (17)(共14分)解:(I )由BC CD ⊥,2BC CD==.,可得22BD =.由EA ED ⊥,且2EA ED ==, 可得22AD =. 又4AB =. 所以BD AD ⊥.又平面EAD ⊥平面ABCD , 平面ADE平面ABCD AD =,BD ⊂平面ABCD ,所以BD ⊥平面ADE . ……………5分 (II )如图建立空间直角坐标系D xyz -,则(0,0,0)D ,(0,22,0)B ,(2,2,0)C -,(2,0,2)E ,(2,22,2)BE =-,(2,0,2)DE =,(2,2,0)DC =-.D B ACEzxy设(,,)x y z =n 是平面CDE 的一个法向量,则0DE ⋅=n ,0DC ⋅=n ,即0,0.x z x y +=⎧⎨-+=⎩ 令1x =,则(1,1,1)=-n .设直线BE 与平面CDE 所成的角为α, 则|||2222|2sin |cos ,|3||||233BE BE BE ⋅--=<>===⋅⋅αn n n . 所以BE 和平面CDE 所成的角的正弦值23. ……………10分 (III )设CF CE =λ,[0,1]λ∈.(2,2,0)DC =-,(22,2,2)CE =-,(0,22,0)DB =.则2(21,1,)DF DC CF DC CE =+=+=--+λλλλ.设(,,)x'y'z'=m 是平面BEF 一个法向量,则0EB ⋅=n ,0EF ⋅=n ,即0,(21)(1)0.y'x'y'z'=⎧⎨-+-++=⎩λλλ 令1x'=,则21(1,0,)λλ-=-m .若平面BEF ⊥平面CDE ,则0⋅=m n ,即2110λλ-+=,1[0,1]3λ=∈. 所以,在线段CE 上存在一点F 使得平面BEF ⊥平面CDE .……………14分(18)(共13分)解:(Ⅰ)函数()f x 的定义域为R ,()()()()()()a x a x x f x x x --+'==++2222211111, 因为0a >,所以,当1x <-,或1x >时,'()0f x <;当11x -<<时,'()0f x >.所以,()f x 的单调递增区间为(,)-11,单调递减区间为(,)-∞-1,(,)+∞1.……6分(Ⅱ)因为()f x 在区间(,)01上单调递增,在区间(,e)1上单调递减,又()f a =02,e (e)e a f a a =+>+2221, 所以,当(,e)x ∈0时,()f x a >2.由()ln g x a x x a =-+,可得'()1a a x g x x x-=-=. 所以当e a ≥时,函数()g x 在区间(0,e)上是增函数,所以,当(,e)x ∈0时,()(e)g x g a e a <=-<22.所以,当(,e)x ∈0时,对于任意的12,(0,e)x x ∈,都有1()2f x a >,2()2g x a <,所以12()()f x g x >. 当0e a <<时,函数()g x 在区间(0,)a 上是增函数,在区间(,e)a 上是减函数, 所以,当(,e)x ∈0时,()()ln g x g a a a a ≤=<2.所以,当(,e)x ∈0时,对于任意的12,(0,e)x x ∈,都有1()2f x a >,2()2g x a <,所以12()()f x g x >. 综上,对于任意的12,(0,e)x x ∈,都有12()()f x g x >. ……………13分(19)(共13分)解(Ⅰ)依题意有2c =,63c a =. 可得26a =,22b =.故椭圆方程为22162x y +=. ………………………………………………5分 (Ⅱ)直线l 的方程为(2)y k x =-.联立方程组22(2),1.62y k x x y =-⎧⎪⎨+=⎪⎩ 消去y 并整理得2222(31)121260k x k x k +-+-=.设11(,)A x y ,22(,)B x y . 故21221231k x x k +=+,212212631k x x k -=+. 则2221212121(1)[()4]AB k x x k x x x x =+-=++-2226(1)31k k +=+. 设AB 的中点为00(,)M x y .可得202631k x k =+,02231k y k =-+. 直线MP 的斜率为1k-,又 3P x =, 所以220222113(1)1(31)P k k MP x x k k k ++=+⋅-=⋅+. 当△ABP 为正三角形时,32MP AB =, 可得22222213(1)326(1)(31)231k k k k k k +++⋅=⋅++, 解得1k =±.即直线l 的方程为20x y --=,或20x y +-=.………………………………13分(20)(共14分)解:(Ⅰ)22(99)99162f =+=;2222(2014)201421f =+++=. ………………5分(Ⅱ)假设1a 是一个n 位数(3n ≥),那么可以设1221132110101010n n n n a b b b b b ---=⋅+⋅++⋅+⋅+,其中09i b ≤≤且i b ∈N (1i n ≤≤),且0n b ≠.由21()a f a =可得,2222221321n n a b b b b b -=+++++.1221211332111(10)(10)(10)(10)(1),n n n n n n a a b b b b b b b b b b -----=-+-++-+-+- 所以11211(10)(1)n n n a a b b b b --≥---.因为0n b ≠,所以1(10)99n n n b b --≥.而11(1)72b b -≤,所以120a a ->,即12a a >. ………………9分(Ⅲ)由11000a <,即1999a ≤,可知2222999243a ≤++=.同理999n a ≤,可知2221999243n a +≤++=.由数学归纳法知,对任意*n ∈N ,有999n a ≤.即对任意*n ∈N ,有{1,2,3,,999}n a ∈.因此,存在,*p q ∈N (p q <),有p q a a =.则11p q a a ++=,22p q a a ++=,…,11q q q p a a -+--=,可得对任意*n ∈N ,n p ≥,有n q p n a a +-=.设q p T -=,即对任意n p ≥,有n T n a a +=.若T p ≥,取m T =,2n m =,则有32m m a a =.若T p <,由n T n a a +=,可得n pT n a a +=,取m pT =,2n m =,则有32m m a a =. ………………14分。

2014北京市东城区高考语文二模试题(附答案)

2014北京市东城区高考语文二模试题(附答案)

北京市东城区2014年高三5月统一练习(二模)语文2014.5.本试卷共8页,150分。

考试时间150分钟。

考生务必将答案答在答题卡上,在试卷上作答无效。

考试结束后,将本试卷和答题卡一并交回。

一、本大题共8小题,共17分。

阅读下面的文字,完成1—5题。

从前的孩子认字,全凭记忆。

如今的孩子读书,先学注音符号,这是一大改革。

本来是先有语言,后有文.字。

我们的文字不是拼音的,虽然其中一部分是形声字,究竟无法看字即能读出声音,或是发音即能写出文字。

注音符号(比反切.高明多了)是帮助把语言文字合而为一的一种工具,对于儿童读书实在是无比的方便。

我们中国的文字不是没有严密的体系,所谓六书即是一套提纲挈领的理论,虽然号称“小学”,小学生谁能理解其中的道理? 我们中国的语言文字,说难不难,说易不易。

瑞典汉学家高本汉说过这样一段话:北京语实在是一种最可怜的方言,总共只.有四百二十个音缀.;普通的语词不下有四千个,这四千多个的语词,统须支配于四百二十个音缀当中。

同音语词的增进,使听者受了极大的困难,于此也可以想见了……这是外国人对外国人所说的话,我们中国儿童国语娴熟,四声准确,并不觉得北京语“可怜”。

我们的困难不在语言,在语言与文字之间的不易勾通。

所以读书从注音符号开始,这方法是绝对正确的。

(取材于梁实秋《从开蒙说起》)1.“反切”是中国传统的一种注音方法。

用两个汉字合起来为一个汉字注音,有时单称反或切,所使用的两个汉字,前者取其声母,后者取其韵母,声母韵母相碰撞组合,产生出被注音汉字的读音。

文中加点字注音不正确...的一项是(2分)A.文,无分切B.切,千结切C.只,诸氏切D.缀,尺过切2.形声字是用表义的形旁和表音的声旁合起来构成的字。

下列词语中加点字全都是形声字的一项是(2分)A.广袤.振聋.发聩邂逅.缠绵悱.恻B.尘.寰肝肠寸.断发酵.风声鹤唳.C.忖.度川.流不息福祉.比.比皆是D.癖.好刨.根问底步.履甘.之如饴3.根据语境,文中黑体字词语使用不正确...的一项是(2分)A.合而为一 B.提纲挈领 C.娴熟 D. 勾通4.“所谓六书”中“六书”指的是(2分)A.风、雅、颂、赋、比、兴B.《诗》《书》《礼》《易》《乐》《春秋》C.象形、指事、会意、形声、转注、假借D.篆书、隶书、魏书、草书、行书、楷书5.在文中横线处填入下列语句,衔接最恰当的一项是(2分)①之后的陈独秀又编了一部《小学识字读本》,是文字学方面一部杰出的大作,但是显然不是适合小学识字的读本。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

北京市东城区2013—2014学年度第二学期高三综合练习(二)英语试卷2014.5本试卷共12页,共150分。

考试时长120分钟。

考生务必将答案写在答卷纸上,在试卷上作答无效。

考试结束后,将本试卷和答题纸一并交回。

第一部分:听力理解(共三节,30分)第一节(共5小题;每小题1.5分,共7.5分)听下面5段对话。

每段对话后有一道小题,从每题所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你将有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话你将听一遍。

1. Which place is the woman looking for?A. A post office.B. The Art Gallery.C. The National Museum.2. When will the men go to see the doctor?A. On Monday.B. On Tuesday.C. On Wednesday.3. Where are the two speakers?A. In a library.B. In a bookstore.C. At a supermarket.4. What‟s the man probably doing?A. Studying.B. Taking a test.C. Listening to music.5. Why is the announcement made?A. To advertise a red car.B. To warn the visitors of the fire. D. To ask a driver to move the car. 第二节(共10小题,每小题1.5分,共15分)听下面4段对话。

每段对话后有几道小题,从每题所给的A、B、C三个选项中选出最佳选项。

听每段对话前,你将有5秒钟时间阅读每小题,听完后,美小题将给出5秒钟的作答时间。

每段对话你将听两遍。

听完第6段材料,回答第6至7小题。

6. How old is the woman‟s aunt?A. 30.B. 50.C. 62.7. Who collects stamps?A. The woman‟s auntB. The man‟s fatherC. The man.听第7段材料,回答第8至9题。

8. Where is the woman?A. In her office.B. At the airport.C. At the restaurant.9. What time will the two speakers probably meet?A. At 11:00 a.m.B. At 11:30 a.m.C. At 2:00 p.m.听完第8段材料,回答第10至12题。

10. What attracts the man?A. Visiting different places by ship.B. Staying at a hotel by the seaside.C. Spending the holiday at home.11. How does the man like the vacation last year?A. Expensive.B. Boring.C. Interesting.12. What‟s the possible relationship between the two speakers?A. Husband and wife.B. Travel agent and customer.C. Newspaper editor and reader.听第9段材料,回答第13至15题。

13. What is the woman?A. Travel agent.B. Air hostess.C. Hotel manager.14. What will the man first do when he arrives?A. Rent a car.B. Book a hotel.C. Find the driver.15. How long will the man stay in London?A. 3 days.B. 4 days.C. 5 days.第三节(共5小题,每小题1.5分,共7.5分)听下面一段对话,完成第16至20题,每小题仅填写一个词。

听对话前,你将有20秒钟的时间阅读试题,听完后你将有60秒钟的作答时间。

这段对话你将听两遍。

第二部分:知识运用(共两节,45分)第一节单项填空(共15小题,每小题1分,共15分)21. I have watched a number of movies recently, none of them have impressed me.A. butB. orC. soD. for22. The best way how to drive a car is to practice with a driving instructor.A. learntB. learningC. to learnD. to be learnt23. ---Do you have any plan for this Sunday? ---Yes. I shopping with my friends.A. goB. am goingC. wentD. have gone24. It is believed children should learn to be responsible from the very beginning.A. whyB. howC. whenD. that25. a new house is impossible for the young couple because they haven‟t saved enough money.A. BuyB. BuyingC. BoughtD. Having bought26. The cinema ten years ago when we first moved to this town.A. builtB. has builtC. was builtD. would be built27. My sister has a habit of keeping a diary and writes down happens every day.A. howB. whenC. whichD. what28. Every book from the library should be returned on time.A. borrowB. to borrowC. borrowingD. borrowed29. ---Hi, Jack. You look a bit fat now. ---Yes. I five pounds recently.A. am putting onB. will put onC. have put onD. had put on30. You‟d better not ride the bicycle on snowy days; you fall.A. mustB. mightC. have toD. ought to31. Milk will turn sour soon on hot days it is stored in the refrigerator.A. sinceB. untilC. becauseD. unless32. There was an excited expression his face when he heard the good news.A. ofB. onC. atD. over33. Drivers must stop when the traffic lights red.A. turnB. will turnC. turnedD. were turning34. Teaching is a difficult job requires great skill and patience.A. whichB. whereC. whoD. why35. If you had told him the truth, he so angry now.A. isn‟tB. wasn‟tC. wouldn‟t beD. wouldn‟t have been第二节完形填空(共20小题,每小题1.5题,共30分)When I was thirteen, one day my mom told my family that she had to tell us something. So my dad, my brother and I all sat down on the sofa to begin the discussion. You could feel the 36 atmosphere of the room. It was 37 that something was wrong. Then my mom told us that she had been diagnosed (诊断)with a very serious disease. That was when we all had a moment of 38 and cried.After that my mom started the 39 and had to travel to the hospital every day. after a week, she began to lose her 40 and so she shaved it all off. My mom would always wear bright-colored scarves and after a while 41 to buy a wig(假发).Along with losing her hair she loses all her nails.42 , I had never seen a desperate look in my mom‟s eye. I remember one day I went with my mom to the hospital. When we were 43 for her to receive the treatment, we kept telling jokes. We both burst out 44 from time to time. everyone in the waiting room was so 45 , while we were in the middle of the room, chatting 46 . Neither of us cared 47 people thought of us.After about a year of the treatment, and all the 48 , one day my mom said she wanted to tell us something important. As my mom was about to speak, a smile 49 on her face. At that moment I knew that it was going to be something very 50 . She told us that she had recovered! At that moment I 51 down in tears. They were tears of joy. At that moment for the first time in a very long time I had a feeling that everything was going to be 52 .Now two years has passed and my mom is 53 of the disease. I am so happy that I have my mom with me every step of they way. My mom 54 me to value every moment in my life and to remain 55 through thick or thin. She has taught me so much and continues to teach me more.36. A. tense B. calm C. friendly D. cold37. A. necessary B. common C. obvious D. strange38. A. regret B. anger C. sorrow D. hesitation39. A. appointment B. treatment C. operation D. observation40. A. hair B. weight C. energy D. hope41. A. liked B. offered C. decided D. afforded42. A. Therefore B. However C. Besides D. Finally43. A. arranging B. waiting C. wishing D. preparing44. A. crying B. quarreling C. talking D. laughing45. A. down B. over C. out D. off46. A. nervously B. curiously C. happily D. gently47. A. why B. when C. where D. what48. A. pain B. failure C. advice D. love49. A. turned B. formed C. changed D. burst50. A. attractive B. active C. exciting D. amusing51. A. came B. looked C. bent D. broke52. A. fair B. clear C. ready D. fine53. A. free B. afraid C. aware D. sure54. A. asked B. taught C. persuaded D. admitted55. A. determined B. modest C. independent D. positive第三部分:阅读理解(共两节,40分)第一节(共15小题,每小题2分,共30分)A56. What does the underlined part “ Congenital Heart Defct” refer to?A. An activityB. A diseaseC. A programD. A disability57. Children aged 5 can take part in .A. Camp Bon CoeurB. Girls‟ Summer CampC. Kidcam Summer CampD. Tulane University Ripples Camp58. Children taking part in Ripples Camp will .A. have the chance to try cookingB. stay in the camp for two weeksC. meet kids from across the worldD. have different camp places to choose fromBGift IdeaThe other day I was shopping for Grandma when I realized I had no gift ideas at all. It was not a birthday gift or anything like that. It was simply sorts of a hero gift. That is how we do things in my family. We don‟t really give gifts for special occasions. Instead, we occasionally just give presents to each other tell other people that we are thinking about them.That was why I wanted a gift for Grandma. Bu it was like my imagination had dried up. I have gone through all of the gift ideas in previous years, fruits, wines, cheeses, little handmade crafts, and anything else that you can give to a grandmother. I had even given her gift watches, and CDs. What else was there?I have always found gift ideas for men a little bit easier than for women, because for men, you canalways get the usual things, such as video games, power tools and things like that. With a woman‟s gift idea, however, you have to know more about her. You cannot just get someone a book or a CD. You have to know all about her taste in movies, music, and literature.My grandmother likes to read a lot, but what she likes is always pretty popular. I didn‟t want to get her a book that she might not like, but I was running out of time. I needed a gift idea for this weekend and went to visit her. After all, I hadn‟t seen her for a long time. I wanted to give her a gift so she would not feel ignored.Finally, I came up with the perfect gift idea, I made a collection of all the stories I had written in the past year. It wasn‟t a typical gift idea like a bunch of flowers, but it rally worked in the situation. You see, I am a writer and my grandma has always been my fan. Anyway, I had been learning about bookbinding recently, and had pretty much mastered the art. I figured that I would add a little bit of handmade artwork to the stories, bind it altogether, and give it to her. It took hours to complete, but it was well worth the effort. She absolutely loved it.59. The writer chose a gift for Grandma to .A. celebrate a special family occasionB. please her during a weekend visitC. congratulate her on her birthdayD. beg her pardon for ignoring her60. What gift did the writer finally decide to give his grandma?A. Gift watchesB. A bunch of flowersC. Artwork made by handD. Stories written by himself61. How does the writer feel about giving gifts to women?A. InterestingB. ChallengingC. Time-wastingD. Popular62. We can learn from the passage that .A. the writer is a successful novelistB. most people are particular about giftsC. the writer‟s grandma has a good taste in artD. the writers family will give gifts on regular daysCDogs already guide blind and disabled people and now they are to be trained to help people with dementia. The idea developed by some university students will now be put into practice by Scotland Medical Center. The research is meaningful, for there are $ 70,000 people in Britain who have dementia and by 2021 this is expected to rise to one million.Dementia can make people confuse night and day or forget basic things such as washing or drinking enough water. The dogs would be trained to help to guide them through the day. Joyce Gray from Scotland Medical Center said, “People in the early stages of dementia are still able to live a relatively normal life, and dogs help them to maintain routine.” For example, people with memory loss will tend to forget to medicine. “but if a dog presents them with a bag with pills in it, there‟s a greater chance of them taking it.” Ms Gray also said dogs were perfectly suited to remind their owners to eat. “Dogs have an ability to say …it‟s my feeding time‟, so there would be a note in the cupboard next to the dog‟s food reminding the dog‟s owner to eat too.”The dog would also encourage the owner to take tem out for walks. “It gives a reason for the owner to go out into the community.” Ms. Gray said, “We did a test with an elderly person walking down the high street on his own. Then we gave him a dog on a lead and he did the exact same walk. The time people would come up to him, chatting or smiling and making eye contact. We hope we‟d see this with people with dementia too.”There is one more advantage of using the pets as companions. Since conversation can be increasingly confusing for people with dementia, dogs can give them a sense of silent support and companionship. Ms. Gray said, “We have found that people may forget familiar faces but not pets. People light up when they see animals. There is a speechless bond between the dog and its owner.”63. What‟s the common symptom of dementia?A. Going hungryB. Feeling lonelyC. Forgetting thingsD. Waking up at night64. According to Ms. Gray, after feeding the pet, the owner may .A. do some washingB. take his medicineC. have something to eatD. go out to walk the dog65. For people with dementia, pets can .A. give them wordless helpB. contribute to their recoveryC. help them to recognize people‟s facesD. ensure them to gain support from other people66. What‟s the best title for the passage?A. Guide Dogs for the MindB. Pets, Faithful CompanionsC. Mental Support for the DisabledD. Dementia, a Curable DiseaseDInteractive Home-security SystemsTarik Celebi, who lives in San Francisco suburb, takes his home-security system with him to work, to dinner, just about anywhere. By his cell phone, he “arms” his home-security alarm from his car before he leaves for work. During his workday, he gets e-mail alerts every time his front door opens, even though he‟s miles away. If the door opens at an unusual time—say middy when no none should be coming or going—he can order a 30-second video clip(片断)from the camera that watches the door. If it‟s just his mother-in-law getting a package delivery, no worries.Celebi is one of the first users of the latest interactive home security systems. In addition to sounding alarms when the house is broken into and notifying homeowners or police, as traditional systems do, the interactive systems give users new ways to remotely control their systems and their home environment. Different from traditional home-security alarms, which homeowners typically have to press buttons on a keypad to turn on before they leave their homes, the interactive systems enable consumers to arm and disarm systems from smartphones, iPads and PCs, no matter where they are.Most traditional systems are set up to sound an alarm if doors or windows are opened. The interactive systems give homeowners more options. For example, users can elect when they want to be notified. They might want an e-mail or a text every time a door is opened, or only during the hours of 3 to 4 p.m., when kids come home from school. Like Celebi, they can add cameras and get video clips when doors open. That could be helpful in making sure kids aren‟t bringing friends home when they‟re not supposed to.Nationwide, about 20% of homes have traditional home-security systems. About half stop using them because they tire of the trouble. Being able to arm systems even while dashing to the subway or while at work will increase their usage of the new interactive systems. Although the new functions add costs to home security, the interactive systems are believed to push home-security systems‟ usage rates closer to30%, which would be a big movement for an industry that‟s been largely stuck at 20% for the past decade. “We all know it‟s going to get bigger, though we don‟t know how long it‟s going to take,” Eric Taylor, an officer from San Francisco Security Department says.67. What may Celebi first do if his front door opens at a wrong time when he is away?A. Inform the policeB. Call his mother-in-lawC. Arm the security alarmD. Observe through video68. The interactive systems enable the user to .A. improve his home environment remotelyB. lock his house‟s door while he is miles awayC. operate the home-security systems at any placeD. sound the alarm and inform the police at the same time69. What‟s the advantage of the interactive systems over the traditional ones?A. They are cheaperB. They are easier to set upC. They can give quicker reactionD. They have more ways to inform the users70. What is the last paragraph mainly about?A. The importance of security industryB. The functions of the interactive alarmsC. The popularity of home-security systemsD. The market potential of the interactive systems第二节(共5小题,每小题2分,共10分)根据短文内容,从短文后的七个选项中选出能填入空白处的最佳选项,选项中有两项为多余选项。

相关文档
最新文档