2012年高考浙江卷自选模块试题及答案word

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2012年高考真题——自选模块理化生(浙江卷)word版

2012年高考真题——自选模块理化生(浙江卷)word版

2012年浙江高考自选模块试题题号:13 科目:物理“物理3-3”模块(10分)一定质量的理想气体,状态从A →B →C →D →A 的变化过程可用如图所示的P-V 图描述,图中P 1、P 2、V 1、V 2和V 3为已知量。

(1)气体状态从A 到B 是____过程(填“等容”、“等压”或“等温”);(2分)(2)状态从B 到C 的变化过程中,气体的温度_____(填“升高”、“不变”或“降低”;)(2分)(3)状态从C 到D 的变化过程中,气体___(填“吸热”或“放热”);(2分)(4)状态从A →B →C →D 的变化过程中,气体对外界所做的总功为____。

(4分)题号:14 科目:物理“物理3-5”模块(10分)一个静止的钚核23994pu 自发衰变成一个铀核23592U 和另一个原子核X ,并释放出一定的能量。

其核衰变方程为:2392359492Pu U X →+。

(1)方程中的“X ”核符号为_______;(3分)(2)钚核的质量为239.0522u ,铀核的质量为235.0439a ,X 核的质量为4.0026u ,已知1u 相当于931MeV ,则该衰变过程放出的能量是_____,MeV ;(3分)(3)假设钚核衰变释放出的能量全部转变为铀核的X 核的动能,则X 核与铀核的动能之比是_____。

(4分)题号:15 科目:化学《物质结构与性质》模块(1)可正确表示原子轨道的是: ① 。

A .2sB .2dC .3pzD .3f(2)写出基态镓(Ga )原子的电子排布式: ② 。

(3)下列物质变化,只与范德华力有关的是 ③ 。

A .干冰熔化B .乙酸汽化C .乙醇与丙酮混溶D .H C N O CH 3CH 3溶于水 E .碘溶于四氯化碳 F .石英熔融(4)下列物质中,只含有极性键的分子是 ④ ,既含离子键又含共价键的化合物是 ⑤ ,只存在σ键的分子是 ⑥ ,同时存在σ键和π键的分子是 ⑦ 。

2012年高考真题—(浙江卷)word详细答案解析版

2012年高考真题—(浙江卷)word详细答案解析版

2012·浙江卷(语文)一、语言文字运用(共24分,其中选择题每小题3分)1.[2012·浙江卷] 下列词语中加点的字,注音全都正确的一项是()A.昵.(nì)称质.(zhǐ)量衣钵.(bō) 因噎.(yē)废食B.刍(chú)议熟稔.(rěn)露.(lù)脸瘙.(sào)痒难忍C.奇葩.(pā) 笑靥.(yǎn)当.(dàng)真物阜.(fù)民丰D.绮.(qǐ)丽木讷.(nè)顷.(qǐng)刻入不敷.(fū)出1.D[解析] 本题考查考生识记现代汉语字音的能力。

题目中所涉及的都是常见字的读音,这些常见字在必修教材中都出现过,学生并不生疏。

如A项的“质(zhǐ)量”应为“质(zhì)量”;B项的“露(lù)脸”应为“露(lòu)脸”;C项的“笑靥(yǎn)”应为“笑靥(yè)”。

其中“露”字为多音字,所以考生在复习时要注意根据一个字在具体语境中的意义去判定它的读音。

2.[2012·浙江卷] 下列各句中,没有错别字的一项是()A.散文是倍受读者青睐的文体,古今中外的散文家凭借生花妙笔,写下了无数文采斐然、脍炙人口的名篇。

B.上课铃声过后,他才慌慌张张地冲进教室,“报告”声刚落,同学们轰堂大笑,原来他衣服的纽扣错位了。

C.毋庸讳言,得过且过、敷衍塞责的教师确实存在,但像“最美女教师”张丽莉那样爱生如子、恪尽职守的人,才是教师队伍中的主流。

D.作为领导干部,面对群众时需要很强的亲和力,只有贴近群众,和颜悦色而不是急言厉色,才能真正听到群众的心声。

2.C[解析] 本题考查考生识记并正确书写现代汉语常用规范汉字的能力,以及对同音字、形似字的辨析能力。

在语境中考查字形,既考查错别字,也考查近义词语的区别,比单纯考错别字,难度有所加大。

在语境中考查字形,还要根据前后语境来判断字形。

2012年高考浙江卷英语试题及答案word

2012年高考浙江卷英语试题及答案word

2012年浙江高考英语试题选择题部分(共80分)第一部分:英语知识运用(共两节,满分30分)第一节:单项填空(共20小题;每小题0.5分,满分10分)从A、B、C、D 四个选项中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。

1. ----- Is there anything else to discuss?------ _________, I guess.A. Not at allB. No ,that's allC. Yes , I 'm sureD. Yes , of course2. The development of industry has been _______ gradual process throughout ______human existence from stone tools to modern technology.A.不填;the B.the;a C.a;不填D.a;a3.No matter how bright a talker you are , there are times when it 's better ______ silent. A.remain B, be remaining C, having remained D, to remain4. I made a promise to myself _______ this year, my first year in high school , would be different. A, whether B, what C, that D, how5. Studying Wendy's menu , I found that many of the items are similar to ______ of McDonald's . A, those B, ones C, any D, all6. _______ all the animals I 've ever had ,those two dogs are the most sensitive to the spoken word..A. FromB. OfC. ForD. With7. Your _______ as a student will be excellent if you develop a habit of reflecting on how you learn.A, opinion B, growth C, performance D, character8. I think Tom, as the head of a big department, should either study regualrly or ______ his job. A, quits B, to quit C, quitting D, quit9. We live in an age ________ more information is available with great ease than ever before. A, why B, when C, to whom D, on which10. The research lacks ________ evidence ,and therefore , its conclusions are doubtful.A, solid B, fierce C, severe D, potential11. " It's such a nice place," Mother said as she sat at the table______ for customers.A, to be reserved B, having reserved C, reserving D, reserved12. According to scientists, our mental abilities begin to ___ from the age of 27 after reaching thehighest level at 22.A, differ B, shrink C, fail D, decline13. Peter had intended to take a job in business, but ______ that plan after the unpleasantexperience in Canada in 2010.A, had abandoned B, abandoned C, abandon D, will abandon14. Brown said he was by no means annoyed; _______ he was glad to be able make himself clearly understood.A, all in all B, for one thing C, on the contrary D, by the way15. Armed with the information you have gathered , you can ________ preparing your business plan. A, set out B, set about C, set off D, set up16. ----- Alvin , are you coming with us?------ I'd love to , but something unexpected __________.A, has come up B, was coming up C, had come up D, would come up17. Ellen was a painter of birds and nature, _______, for some reason , had withdrawn from all human society. A, which B, who C, where D, whom18. Mike was usually so careful, ________this time he made a small mistake.A, yet B, still C, even D, thus19. Had they known what was coming next, they ________ second thoughts.A, may have B, could have C, must have had D, might have had20. ----- I'm going to San Francisco for a couple of days .------ ________, I wish I could get away for a while.A. It doesn't matterB. Forget it.C. I really envy youD. I can't agree more第二节:完形填空(共20小题;每小题1分,满分20分)阅读下面短文,掌握其大意,然后从第21—40 各题所给的四个选项(A、B、C 和D)中,选出最佳选项,并在答题卷上将该项涂黑。

(完整word版)2012高考浙江文科数学试题及答案(高清版),推荐文档

(完整word版)2012高考浙江文科数学试题及答案(高清版),推荐文档

2012年普通高等学校夏季招生全国统一考试数学文史类(浙江卷)本试题卷分选择题和非选择题两部分.满分 150分,考试时间120分钟.选择题部分(共50分)参考公式: 球的表面积公式 s = 4 n 2球的体积公式 4 3V = T R 33其中R 表示球的半径 锥体的体积公式 1 V = Sh3其中S 表示锥体的底面积, 柱体的体积公式 V = Sh其中S 表示柱体的底面积, 台体的体积公式 V = 1h(S 1 + .S3 + S 2)3其中S 1, S 2分别表示台体的上、下底面积. h 表示台体的高如果事件A , B 互斥,那么P(A + B) = P(A)+ P(B)如果事件A 在一次试验中发生的概率是P ,那么n 次独立重复试验中事件A 恰好发生k次的概率 P n (k) = c n p k (1 - P)旷k (k = 0,1,2,…,n)一、选择题:本大题共 10小题,每小题5分,共50分.在每小题给出的四个选项中, 只有一项是符合题目要求的.1. 设全集 U = {123,4,5,6},集合 P = {1,2,3,4} , Q = {3,4,5},贝U P n u Q)=( )A . {1,2,3,4,6}B . {1,2,3,4,5}C . {1,2,5}D . {1,2}3 i2. 已知i 是虚数单位,则 ( )1 iA . 1-2iB . 2-iC . 2+ iD . 1 + 2i3.已知某三棱锥的三视图(单位:cm)如图所示,则该三棱锥的体积是( )h 表示锥体的咼h 表示柱体的高A .1 cm3B.2 cm3C.3 cm3D.6 cm34. 设a € R,则“ a = 1” 是“直线li: ax+ 2y—1 = 0 与直线I2: x + (a+ 1)y+ 4= 0 平行”的( )A .充分不必要条件B .必要不充分条件C.充分必要条件 D •既不充分也不必要条件5. 设I是直线,a, B是两个不同的平面,()A .若I // a, I // 贝U all 3B .若I // a, I 丄3,贝V a丄3C .若a丄3, I丄a, 贝V I丄3D .若a丄3, I / a ,贝V I丄36. 把函数y= cos2x+1 的图象上所有点的横坐标伸长到原来的 2 倍(纵坐标不变) 然后向左平移 1 个单位长度再向下平移 1 个单位长度得到的图象是( )7. 设a b 是两个非零向量( )A .若|a+ b|= |a|—|b| ,贝U a丄bB .若a丄b,则|a+ b|= |a|—|b|C. 若|a+ b|=|a|—|b| ,则存在实数入使得b =七D. 若存在实数入使得b= ,则|a + b|= |a|—|b|8. 如图中心均为原点O 的双曲线与椭圆有公共焦点M N 是双曲线的两顶点.若2M , O , N 将椭圆长轴四等分,则双曲线与椭圆的离心率的比值是A. 3 B . 2 C . ■ 3D . 29. 若正数x , y 满足x + 3y = 5xy ,则3x + 4y 的最小值是(24 28A.B .C . 5D . 65510 .设a >0, b >0, e 是自然对数的底数( )A .若 e a + 2a = e b + 3b ,贝U a >b B. 若 e a + 2a = e b + 3b ,贝V a v b C. 若 e a — 2a = e b — 3b ,则 a >b D. 若 e a — 2a = e b — 3b ,贝U av b非选择题部分(共100分)、填空题:本大题共 7小题,每小题4分,共28分.11.某个年级有男生560人,女生420人,用分层抽样的方法从该年级全体学生中抽取 一个容量为280的样本,则此样本中男生人数为 ______________________________________________ .12 .从边长为1的正方形的中心和顶点这五点中,随机 距离为迈的概率是13 .若某程序框图如图所示,则该程序运行后输出的值是(等可能)取两点,则该两点间的x y 10,x y 20,14 .设z= x+ 2y,其中实数x,y满足则z的取值范围x0,y0,uuu umr15. 在厶ABC 中,M 是BC 的中点,AM = 3, BC = 10,贝U AB AC ____________ .16. 设函数f(x)是定义在R上的周期为2的偶函数,当x€[ 0,1 ]时,f(x)= x+ 1,则f(3)217. ____________ 定义:曲线C上的点到直线I的距离的最小值称为曲线C到直线I的距离.已知曲线C1:y= x2+ a到直线I: y= x的距离等于曲线C2 : x2+ (y+ 4)2= 2到直线I: y= x的距离,贝y实数a= ___________ .三、解答题:本大题共5小题,共72分•解答应写出文字说明、证明过程或演算步骤.18. 在△ ABC 中,内角A,B,C 的对边分别为a,b,c,且bsinA = ■■. 3 acosB.(1) 求角B的大小;(2) 若b = 3,sinC= 2sinA,求a,c 的值.19. 已知数列{a n}的前n项和为S n,且3= 2n2+n,n € N*,数列{b n}满足a n = 4log2b n + 3,n € N*.(1)求a n,b n;⑵求数列{a n b n}的前n项和T n.20. 如图,在侧棱垂直底面的四棱柱ABCD —A1B1C1D1中,AD // BC ,AD丄AB, AB . 2,AD =2,BC=4,AA1=2,E是DD1的中点,F是平面B1C1E与直线AA1的交点.(1)证明:① EF // A1D1;②BA1丄平面B1C1EF ;⑵求BC1与平面B1C1EF所成的角的正弦值.21. 已知a € R,函数f(x)= 4x3—2ax+ a.(1) 求f(x)的单调区间;(2) 证明:当0W x w 1 时,f(x)+ |2 —a|>0.122. 如图,在直角坐标系xOy中,点P(1,-)到抛物线C:y2=2px(p> 0)的准线的距离25为三.点M(t,1)是C上的定点,A,B是C上的两动点,且线段AB被直线OM平分.4⑴求p, t的值;(2)求厶ABP面积的最大值.【自选模块】3. “数学史与不等式选讲”模块(10分)已知a€ R,设关于x的不等式|2x—a|+ |x+ 3|> 2x+ 4的解集为A.(1) 若a = 1,求A;(2) 若A = R,求a的取值范围.4. “矩阵与变换和坐标系与参数方程”模块(10分)x= 2 + tcos ,在直角坐标系xOy中,设倾斜角为a的直线I: _ (t为参数)与曲线C:y=V3+ tsinx=2cos ,(B为参数)相交于不同两点A, B .y= sinn(1) 若一,求线段AB中点M的坐标;3(2) 若|PA| |PB|= |0P|2,其中P(2,. 3),求直线I 的斜率.1. D 由已知得,-U Q = {1,2,6},所以P n C-U Q)= {1,2}.3 i (3 i)(1 i) 3+3i+i+i 2 2 4i2. D •/ 1 2i ,1 i (1 i)(1 i)2 2•••选 D .13. A 由三视图得,该三棱锥底面面积S= x 2 x 1= 1(cm2),高为3 cm,由体积公1 1 3式,得v= _ Sh= - x 1x 3 = 1(cm3).3 34. A l1与l2平行的充要条件为a(a+ 1)= 2 x 1且a x 4丰1 x (—1),可解得a = 1或a =—2,故a= 1是11 // l2的充分不必要条件.5. B A项中由I // a l // B不能确定a与B的位置关系,C项中由a丄B, I丄a可推出l // B或I B, D项由a丄B, l // a不能确定I与B的位置关系.6. A y= cos2x+ 1图象上所有点的横坐标伸长到原来的2倍得y i= cosx+ 1,再向左平移1个单位长度得y2 = cos(x+ 1)+ 1,再向下平移1个单位长度得y3= cos(x+ 1),故相应的图象为A项.7. C 由|a+ b|=|a|—|b|两边平方可得,|a|2+ 2a b + |b|2= |a|2-2|a||b|+ |b|2,即卩 a b=-ai|b|,所以cos < a, b>=- 1,即卩a与b反向,根据向量共线定理,知存在实数入使得b =?a.8. B 由题意可知椭圆的长轴长2a1是双曲线实轴长2a2的2倍,即a1= 2a2,而椭圆与双曲线有相同的焦点.c故离心率之比为a虫2.c a2a1.1 3 .9. C - x+ 3y = 5xy, - - 1 .5y 5x1 3••• 3x+ 4y= (3x+ 4y)x 1 = (3x+ 4y)5y 5x=空9 4 12y 13 2(3x 12y 55y 5 5 5x 5 ■. 5y5x3x 12v 1当且仅当,即x= 1, y —时等号成立.5y 5x 210. A 函数y= e x+ 2x为单调增函数,若e a+ 2a = e b+ 2b,则a= b;若e a+ 2a= e b+3b, • a> b.故选A .11. 答案:160解析:根据分层抽样的特点,此样本中男生人数为560280560 420212. 答案:-52解析:五点中任取两点的不同取法共有C5=10种,而两点之间距离为4 2故概率为一10 5113. 答案: -120解析:当i = 1 时,T = 1= 1,1当i = 2时,T1,当!1i = 3 时,T 231 r6,当i= 4160 .-的情况有42种,1丄时,T61当i = 5时,T1,当i = 6时,结束循环,输出T —.4245120120 14答案:[0, j :解析:不等式组表示的可行域如图阴影部分,结合图象知,0点,C 点分别使目标函数取得最小值、最大值,代入得最小值为 0,最大值为7.215. 答案:—16uur ULUT uuuu uuir UUUU uuun UUUU ULUU UULU UUUU LULT解析:AB -AC = (AM + MB )(・AM + MC )= AM + AM -MC + AM MB + LULT UUUT UUUU UULT UUUU UUUU UULT UULUMB MC = |AM |2 + ( MB + MC )AM + | MB ||MC |cos n — 25=— 16.…316. 答案:一2 3 311 f (¥) f(3 2) f( -)f(-)2 22 2…917.答案:一4物线y = x 2 + a 开口向上,所以 y = x 2 + a 与y = x + 2相切,可求得 a18.解:(1)由bsinA = ------- 3 acosB 及正弦定理si nA 得 sinB =、、3 cosB ,所以tanB = --3,所以B —.3 a c⑵由 sinC = 2sinA 及,得 c = 2a .si nA si nC由 b = 3 及余弦定理 b 2= a 2 + c 2— 2accosB ,解析: 4解析:x 2+ (y + 4)2= 2到直线y = x 的距离为 一-距离为、、2,而与y = x 平行且距离为.2的直线有两条,分别是、2 、、2,所以 y = x 2+ a 到 y = x 的y = x + 2 与 y = x — 2,而抛b si nB得9 = a2+ c2—ac.所以a , c 2、3 .19. 解:(1)由S n = 2n2+ n,得当n = 1 时,a1 = S1 = 3;当n >2 时,a n= S n—S n-1= 4n—1. 所以a n= 4n—1, n € N*.由4n— 1 = a n= 4log2b n+ 3,得b n= 2n—1, n € N*.(2)由(1)知a n b n= (4n—1) 2n—1, n€ N*.所以T n= 3+ 7 X 2 + 11X 22+…+ (4n—1) 2n —1,2T n= 3X 2+ 7 X 22+…- (4n —1) 2n,所以2T n —T n= (4n —1)2n—[ 3+ 4(2 + 22+…+ 2n —1):= (4n —5)2n+ 5. 故T n= (4n —5)2n+ 5, n€ N*.20. (1)证明:①因为C1B1//A1D1, C1B1 平面ADD 1A1,所以C1B1 //平面A1D1DA .又因为平面B1C1EF门平面A1D1DA=EF ,所以C1B1 //EF,所以A1D1 //EF .②因为BB1丄平面A1B1C1D1,所以BB1丄B1C1.又因为B1C1丄B1A1,所以B1C1丄平面ABB1A1, 所以B1C1丄BA1.在矩形ABB1A1 中,F 是AA1 的中点,tan/ A1B1F = tan/ AA1B =2 / AA1B,故BA1 丄B1F .所以BA1丄平面B1C1EF.⑵解:设BA1与B1F交点为H,连结C1H. (4n —5) 2n —1+,即 / A1B1F =由(1)知BA1丄平面B1C1EF ,所以/BC1H是BC1与面B1C1EF所成的角.在矩形AA1B1B 中,AB 、2 , AA1=2,得BH 4 .6 .在直角△ BHC1 中,BG 2 5 , BH4 "6,得 sin BGHBH 30BC 175由题意得 f'x) = 12x 2— 2a . f'x) > 0恒成立,此时f(x)的单调递增区间为(一 °° ,).此时函数f(x)的单调递增区间为(—m, J 6[和[^6, +m )单调递减区间为]t 6, 〕— ]•(2)证明:由于 0w x w 1,故当 a w 2 时,f(x) + |a — 2|= 4x 3— 2ax + 2> 4x 3— 4x + 2.当 a >2 时,f(x) + |a — 2|= 4x 3 + 2a(1 — x) — 2 > 4x 3 + 4(1 — x)— 2= 4疋一 4x + 2. 设 g(x) = 2x 3— 2x + 1,0W x w 1,273恵则 g 'x)= 6x — 2= 6(x — )(x +),33于是血4g(x)min= g (〒=1一可 >0所以当 0w x < 1 时,2x 3— 2x + 1>0. 故 f(x) + |a — 2|>4x 3— 4x + 2>0.2 pt 1,1p — 22.解:⑴由题意知 卫 §得 212 4' t 1.所以设线段AB 的中点为Q(m , m).所以BC i 与平面B i C i EF 所成角的正弦值是30 15当a > 0时, f'x) = 12(x- \ ;)(x +[;), 21. ⑴解:当a < 0时, 所以,⑵设 A (X 1, y 1), B(X 2, y 2),因为 OM 过AB 的中点,而且直线OM 的方程为x — y=0 ,由题意,设直线 AB 的斜率为k(k z 0).2y 1X \, ,由 2得(y i — y 2)(y i + y 2)=x i -x 2,故 k 2m = 1.y 2X 2,i所以直线AB 方程为y — m = (x - m),2m即 x — 2my + 2m 2— m = 0.2x 2my 2m m 0,由2y x,消去 x ,整理得 y 2— 2my + 2m 2— m = 0,所以 =4m — 4m 2>0, y i + y 2= 2m , y i y 2 = 2m 2— m . 从而 |AB=,.C ;2 ly i -y 2= 41 ~4m 2 V 4m~4m 2 . 设点P 到直线AB 的距离为d ,|i 2m 2m 21i 4m 2设厶ABP 的面积为S ,S = |AB | d = |i — 2(m — m 2)| -m m 2 . 2=4m — 4m 2 > 0,得 0v m v i .u =、m m 2, 0v u < *,贝U S = u(i — 2u 2).2i则 S'u)= i -6u 2.46i 由 S,u)= 0,得 u(0,;),62设 S(u)= u(i — 2u 2), 0v u <2故厶ABP 面积的最大值为3.解:⑴当x w — 3时,1当—3v x w时,原不等式化为 4 — x 》2x + 4,得—3v x w 0.21x 一时,原不等式化为 3x + 2>2x + 4,得x >2.2综上,A = {x|x w 0 或 x >2}⑵当 x w — 2 时,|2x — a| + |x + 3》0》2x + 4 成立. 当x >— 2时,|2x — a|+ x + 3= |2x — a| + |x + 3|》2x + 4,a 1得x 》a + 1或x3所以a + 1w — 2或a 1电」,得a w — 2.3综上,a 的取值范围为a w — 2.4.解:设直线I 上的点A , B 对应参数分别为t 1, t 2.将曲线C 的参数方程化为普通方2程—+ y 2= 1.4n(1)当 一时,设点M 对应参数为t o .3t t 28 12—2 ,所以,点M 的坐标为(一21313 x=2+tcos ,x 2l代入曲线C 的普通方程 一 + y 2= 1,得y = +3 tsi n4x 直线I 方程为21…■- (t 为参数),22x+ y 2= 1,得 13t 2+ 56t + 48= 0,4.3 代入曲线C 的普通方程则t o⑵将(cos2a+ 4sin2 a)t2+ (8,3 sin a+ 4coso)t+ 12= 0,… 12 2因为|FA| |P B|= |t1t2|= —2— , |OP|2= 7,cos 4sin所以一2cos 124s in2o7,得tan516由于=32cos a 2:/3 sin a—cos”> 0,故tan所以直线l的斜率为。

2012高考英语真题_浙江卷及答案(全word版)

2012高考英语真题_浙江卷及答案(全word版)

2012年浙江高考英语试题选择题部分,(共80分)第一部分:英语知识运用(共两节,满分30分)第一节:单项填空(共20小题;每小题0.5分,满分10分)从每题所给的A、B、C、D 四个选项中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑。

1. ----- Is there anything else to discuss?------ _________, I guess.A. Not at allB. No ,that‟s allC. Yes , I …m sureD. Yes , of course2. The development of industry has been _______ gradual process throughout______human existence from stone tools to modern technology.A, / , the B, the , a C, a, / D, a, a3. No matter how bright a talker you are , there are tim es when it …s better ______ silent.A, remain B, be remaining C, having remained D, to remain4. I made a promise to myself _______ this year, my first year in high school , would be different.A, whether B, what C, that D, how5. Studying Wendy‟s menu , I found that many of the items are similar to ______ of McDonald‟s .A, those B, ones C, any D, all6. _______ all the animals I …ve ever had ,those two dogs are the most sensitive to spoken word.A. FromB. OfC. ForD. With7. Your _______ as a student will be excellent if you develop a habit of reflecting on how you learn. A, opinion B, growth C, performance D, character8. I think Tom, as the head of a big department, should either study regualrly or ______ his job.A, quits B, to quit C, quitting D, quit9. We live in an age ________ more information is available with great ease than ever before.A, why B, when C, to whom D, on which10. The research lacks ________ evidence ,and therefore , its conclusions are doubtful. A, solid B, fierce C, severe D, potential11. “ It‟s such a nice place,” Mother said as she sat at the table______ for customers.A, to be reserved B, having reserved C, reserving D, reserved12. According to scientists, our mental abilities begin to ___ from the age of 27 after reaching the highest level at 22. A, differ B, shrink C, fail D, decline 13. Peter had intended to take a job in business, but ______ that plan after the unpleasant experience in Canada in 2010.A, had abandoned B, abandoned C, abandon D, will abandon14. Brown said he was by no means annoyed; _______ he was glad to be able make himself clearly understood.A, all in all B, for one thing C, on the contrary D, by the way15. Armed with the information you have gathered , you can ________ preparing your business plan. A, set out B, set about C, set off D, set up16. ----- Alvin , are you coming with us?------ I‟d love to , but something unexpected __________.A, has come up B, was coming up C, had come up D, would come up17. Ellen was a painter of birds and nature, _______, for some reason, had withdrawn from all human society. A, which B, who C, where D, whom18. Mike was usually so careful, ________this time he made a small mistake.A, yet B, still C, even D, thus19. Had they known what was coming next, they ________ second thoughts.A, may have B, could have C, must have had D, might have had20. ----- I‟m going to San Francisco for a coup le of days.------ ________, I wish I could get away for a while.A. It doesn‟t matterB. Forget it.C. I really envy youD. I can‟t agree more第二节:完形填空(共20小题;每小题1分,满分20分)阅读下面短文,掌握其大意,然后从第21—40 各题所给的四个选项(A、B、C 和D)中,选出最佳选项,并在答题卷上将该项涂黑。

2012年高考真题——英语(浙江卷)解析版

2012年高考真题——英语(浙江卷)解析版

2012年普通高等学校招生全国统一考试(浙江卷)英语选择题部分(共80分)第一部分英语知识运用第一节单项填空1. — Is there anything else to discuss?—_____________. I guess.A. Not at allB. No, that's allC. Yes, I'm sureD. Yea, of course1. 【考点】交际用语—征求意见或看法【答案】B【解析】根据句意:---还有其他事要讨论吗?---没有,就这么多(no, that’s all),我想。

故选答案B。

not at all 一点儿也不;yes, I’m sure是的,我确定;yes, of course是的,当然,均是答非所问,不合题意,故排除。

【难度】偏小2. The development of industry has been_______ gradual process throughout _______ human existence, from stone tools to modern technology.A. 不填, theB. the; aC. a; 不填D. a; a2. 【考点】冠词—零冠词和不定冠词【答案】C【解析】第一空process是可数名词,第一次出现一般用不定冠词,且此次表示“一个”的概念;第二空existence 是不可数名词,其此处表示抽象概念,故用零冠词。

【难度】中等3. No matter how bright a talker you are, there are times when it's better silent.A. remainB. be remainingC. having remainedD. to remain3. 【考点】非谓语—不定式【答案】D【解析】it做形式主语,真正的主语是后面的不定式:to remain silent. 可归结为句型:it is +形容词/名词+to do/that…。

2012年普通高等学校招生全国统一考试 理综(浙江卷)word版(含答案)

2012年普通高等学校招生全国统一考试 理综(浙江卷)word版(含答案)

2012年普通高等学校招生全国统一考试(浙江卷)理科综合选择题部分(必做,共87分)一、选择题(本题共17小题。

在每小题给出的四个选项中,只有一项是符合题目要求的)1.(2012·浙江理综,1)人体肝细胞内CO2分压和K+浓度高于细胞外,而O2分压和Na+浓度低于细胞外,上述四种物质中通过主动转运进入该细胞的是()。

A.CO2B.O2C.K+D.Na+C氧气、二氧化碳等气体小分子进出细胞的方式是自由扩散,A、B项错误。

细胞内的钾离子高于细胞外是逆浓度主动吸收,C项正确。

钠离子膜外高于膜内,进入细胞时是通过离子泵顺浓度梯度进行的,因此是被动运输,D项错误。

2.(2012·浙江理综,2)下列关于高等哺乳动物受精与胚胎发育的叙述,正确的是()。

A.绝大多数精卵细胞的识别具有物种特异性B.卵裂球细胞的体积随分裂次数增加而不断增大C.囊胚的滋养层细胞具有发育全能性D.原肠胚发育分化形成内外两个胚层A异种精子不能与卵细胞融合,因为精卵细胞表面有特异性相互识别的蛋白,A项正确。

卵裂球几乎不生长即迅速地进行下次分裂,卵裂球细胞的体积越来越小,B项错误。

滋养层将来发育成胎膜和胎盘,起营养辅助的功能,没有全能性,C项错误。

原肠胚发育分化形成外胚层、中胚层和内胚层三个胚层,D项错误。

3.(2012·浙江理综,3)不同浓度的生长素影响某植物乙烯生成和成熟叶片脱落的实验结果如图所示。

下列有关叙述正确的是()。

A.乙烯浓度越高脱落率越高B.脱落率随生长素和乙烯浓度增加而不断提高C.生长素和乙烯对叶片脱落的作用是相互对抗的D.生产上可喷施较高浓度生长素类似物降低脱落率D据图分析在一定范围内随乙烯和生长素浓度的逐渐增大脱落率先上升,但超过一定浓度后脱落率又逐渐降低,A、B、C三项错误,D项正确。

4.(2012·浙江理综,4)下列关于神经肌肉(肌肉指骨骼肌)接点及其相关结构和功能的叙述,正确的是()。

2012高考浙江高清卷(附答案)

2012高考浙江高清卷(附答案)

2012年普通高等学校招生全国统一考试浙江文科综合能力测试·地理部分Ⅰ选择题部分2011年11月28日至12月9日,联合国气候变化大会在南非东部海滨城市德班召开,大会重点关注了二氧化碳排放。

完成1-2题。

1.2009年我国政府提出,到2020年单位GDP二氧化碳排放比2005年下降40%~50%。

下列措施中有助于实现该目标的有①推广太阳能、核能②降低非化石能源占一次性能源消费的比重③增加森林面积④提高单位GDP能耗A.①②B.①③C.②③D.②④2.据下表分析,德班的气候类型是A.热带雨林气候B.热带草原气候C.热带季风气候D.地中海气候专家认为,欣赏旅游景观,尤其需要的是提升感受力和理解力。

完成3-4题。

“马穿山径菊初黄,信马悠悠野兴长。

万壑有声含晚籁,数峰无语立斜阳。

棠梨叶落胭脂色,荞麦花开白雪香。

何事吟余忽惆怅,村桥原树似吾乡。

”这是宋朝诗人王禹偁谪居陕西时,描述山村风景的《村行》。

3.下面四位同学对《村行》评论,哪些同学的说法是正确的?甲:“马穿山径菊初黄”中的“菊初黄”同时包含了由视觉、听觉感受到的景象;乙:“万壑有声含晚籁”中的“万壑”指的是遍布的黄土沟壑;丙:“荞麦花开白雪香”指的由视觉、嗅觉感到的春天景象;丁:“村桥原树似吾乡”是由视觉看到的景物,并引发的移情想象欣赏。

A.甲乙B.甲丙C.乙丁D.丙丁4.下列对地貌旅游资源所构成的岩石类型的表述,正确的是A.火山地貌景观的岩石构成是花岗岩B.丹霞地貌景观的岩石构成是流纹岩C.岩溶地貌景观的岩石构成是可溶性的沉积岩D.球状风化形成的山石景观的岩石构成是砂岩自2011年7月始,泰国发生了持续3个多月的洪涝灾害,多个全球知名IT企业在泰国设立的硬盘生产厂家在此灾害中遭受不同程度损毁,导致当年硬盘价格上涨。

完成5-6题。

20010002000国界线水域河流500等高线10°20°105°5.从气候与地形角度看,泰国洪涝灾害严重的原因有 ①热带季风气候,降水多且集中 ②热带雨林气候,终年多雨 ③中南部地势低平,积涝成灾 ④北部地势低洼,排水不畅 A.①③ B.②③ C.②④ D.①④6.全球知名IT 企业在泰国设立硬盘生产工厂,主要原因是该国 A.软件产业发达 B.国内市场广阔 C.运输条件优越 D.劳动力价格较低 读我国某区域示意图,完成7-8题。

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2012年浙江高考自选模块试题题号:01 科目:语文“中国古代诗歌散文欣赏”模块(10分)阅读下面的散文,然后回答问题。

吃野菜说清·龚鼎孳新雨后,绿芜如发,园蔬叶叶,青满畦径。

启扉视之,知一年春事又将烂漫矣,家人间撷作羹,劣得一饱。

野香拂拂,从匕箸间出,诚有如子瞻所谓饱霜雪之精、味含土膏①者。

独怜此物没蓬蒿中,与贫士为伍,寒窗一嚼,胜十日太牢②,甚不可进于达官贵人、钟鸣鼎食、芍药撰、朱砂羹之口。

今中原嗷嗷,道殣相望,雁粪榆皮,所在仰以为命。

甚且折骨解肢,与乌鸢争攫啄之利。

吁,可悲也!彼达官贵人日啖浓鲜,当翠袖,奉卮华茵,度梦时亦曾念及野人藜藿③不继无耶?昔人曰:民不可有此色,士大夫不可无此味。

知信哉!【注】①土膏:土地中的膏泽。

⑦太牢:古时祭祀用的猪、牛、羊,泛指美味佳肴。

③藜藿:野菜。

(1)结合全文,理解文中画线句子的含义。

(4分)(2)赏析这篇散文的写作特色。

(6分)题号:02 科目:语文“中国现代诗歌散文欣赏”模块(10分)阅读下面的诗歌,然后回答问题。

采采卷耳朱巧玲采采卷耳。

不盈顷筐嗟我怀人。

置彼周行——《诗经﹒周南﹒卷耳》用群山、河流和铁轨衡量我们之间的距离三千诗句,算不算长?我相信爱的辽阔一如采采卷耳覆盖每一寸肌肤细微的感觉你知道吗每当老虎从白雪里跃出我会获得释放,像蒲公英散落四方用地理和祖国容纳我们之间的落差每一棵树木都是升起的太阳每一只小兽都是可爱的孩子走在天穹下什么在呼唤我的名字我相信爱的自由一如采采卷耳当我抬头,那些洁白的云朵聚拢而来挡住了倾斜的光线(1)本诗以《诗经﹒周南﹒卷耳》为引子有什么作用?(4分)(2)从意象、手法、结构中选择一个方面,结合具体诗句进行赏析。

(6分)题号:03 科目:数学“数学史与不等式选讲”模块(10分)已知a R ∈,设关于x 的不等式2324x a x x -++≤+的解集为A ,(1)若a=1,求A;(2) 若A=R,求a 的取值范围。

题号:04 科目:数学“矩阵与变换和坐标系与参数方程”模块(10分)在直角坐标系xoy 中,以o 为极点,x 轴的正半轴为极轴建立极坐标系,抛物线M 的极坐标方程为24cos sin θρθ=, (1) 写出抛物线M 的直角坐标方程;(2) 如图,抛物线M 的弦BD 与CE 交于点)0,2(A ,且4DAE π∠=. 当42BD =时,求11AC AE+的值.题号:05 科目:英语阅读理解(分两节,共5小题:每小题2分,共10分)阅读下面的短文,并根据短文后的要求答题。

Some scientists believe that our brains may be hardwired(天生的)in ways that determine how happy we tend to be.Dr.Richard Davidson and his colleagues at the University of Wisconsin have found an area in the front part of the brain that controls positive feelings,optimism,and happiness.① ,Using functional MRI brain scans,they found that when mothers viewed photos of their babies. their brain activity increased greatly in this front brain region.② For generally cheerful people,happiness is associated with a personality type that emphasizes independence, self-respect,ability,and close relationships.____③___ people seek it through fancy vacations,expensive,jeaelry,or other material things,the excitement of these quick-fix satisfactions is generally short-lived.Sustained (持续的)contentment is more likely to result from healthy relationships and meaningful accomplishments.④ Many people who survived the 9/11 disaster but were close enough to experience the destruction first-hand were shocked at the beginning.but they eventually got a clearer idea about what is truly important in their lives-----family,friends and sustaining a purpose in life.Through hardship,people often become more aware of their own survival skills, emotionl strenght,and power to help others as well as to be helped.Nobody ’life is free of misfortune,but through hardship we can become more aware of little things we often forget to appreciate,and sometimes gain new positive ways of thingking and understangdings for the future.Dr.Ronnie Janoff-Bulman and collesgues at the University of Masschusetts have studied the way extreme life events-both positive and negative-may influence an individual ’s ability to enjoy sustained happiness and satisfaction.They tcompared the well-being of two groups: lettery winners and people who bad sudderly become disabled. Though the lottery winners experienced initial excitement following their new wealth ,in the long run many were no happier than the accident victims, in part became normal ,everyday pleasures now paled next to the thrill of winning the “big one .”In contrast, many of the people who because disabled learned to adjust to their new disabilities , and were eventuslly better able to appreciate small pleasures and accomplishments ,as compared with those who became rich overning in the study.第一节 根据短文内容,从A 、B 、C 、D 、和E 中选出最适合填入短文空白出的选项,并将序号及相应答案写在答题纸上,选项中有一项是对于选项。

A . Keeping positive attitude, like any other skill, can be learned.B . Research also shows that joyful individuals share certain charactristics and habitsC . Surprisingly, a tragedy or loss can sometimes set individuals on a path to sustained happinessD.His group studied one of the most powerful positive sets emotions-a mother’s feelings toward her newborn bady.E.Fortunately,even if there is some hardwiring that determines how happy we tend to be ,much of what determines our happiness is under own control第二节根据短文所给的信息,用一个完整的句子回答下面的问题,并将序号及相应答案写在答题纸上。

⑤How did Dr.Ronnie Janoff Bulman and his colleagues carry out their research?题号:06 科目:英语填空(共10小题;每小题1分,共10分)阅读下面的短文,在标有序号的空白处填入一个适当的词,或填入括号中所给单词的正确形式,并将序号及相应的答案写在答题纸上。

One night, when I was a teenager, my friends and I stole a goose from a lady who lived nearby. The next day we took it down by the river, near Dan’s farm, to cook it. The goose would need some salt, so I was elected to go into Dad’s bam(谷仓)for it. Even the salt didn’t help; we couldn’t keep the fire hot enough for the goose to get totally __①__(cook).Despite our poor results, we ate some of the goose. Then one day word came to me____②___the lady who owned the goose wanted to see me.“Rex,”he said,“Your mother is one of my 高考资源网est friends, and I know she would be saddened if I were to tell her that you stole my goose, You do not want to be know as a____③___, so this will be our little ___④__, if you promise me you’ll mever steal anything again.”Of course I promised.After I had teenagers myself, I would often visit the Goose Lady. And each time I thanked her for __⑤___(teach)me the lesson of a lifetime. Before she died, she told me that, long ago, my father had come to her and said be had seen me take salt. He__⑥__me back to the river and witnessed the goose being cooked. She said.“Your father thought, and I ___⑦___ with him, that the message of ‘You shall mot steal’would be more impressive if____⑧____ came from the lady you stole from___⑨ ___ than your parent.”My father had died, and I was sad that he had never told me of his role in the story. But now I can only be thankful for a father ___⑩___, even when I didn’t know it, was still watching out for me.题号:07 科目:思想政治“经济常识”模块(10分)司马迁在《史记﹒货殖列传》中指出:自有文字记载以来,人们追求自我利益的本性从未改变。

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