2018年陕西省高三质量检测题(一)

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陕西省2018年高三教学质量检测试题(一)理数试题+Word版含答案

陕西省2018年高三教学质量检测试题(一)理数试题+Word版含答案

2018年陕西省高三教学质量检测试题(一)数学(理)第Ⅰ卷(选择题 共60分)一、选择题(本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.设集合2{|90}A x x =-<,{|}B x x N =∈,则A B I 中元素的个数( )A .0B .1C .2D .32.欧拉公式cos sin ix e x i x =+(i 为虚数单位)是由瑞士著名数学家欧拉发现的,它将指数函数的定义域扩大到复数,建立了三角函数和指数函数的关系,它在复变函数理论里非常重要,被誉为“数学中的天桥”,根据欧拉公式可知,2i e 表示的复数在复平面中位于( )A .第一象限B .第二象限C .第三象限D .第四象限3.已知命题:p 对任意x R ∈,总有20x >;:q “1x >”是“2x >”的充分不必要条件,则下列命题为真命题的是( )A .p q ∧B .p q ⌝∧⌝C .p q ⌝∧D .p q ∧⌝4.已知等差数列{}n a 的前n 项和为n S ,且3512a a =g ,20a =.若10a >,则20S =( )A .420B .340 420 D .-3405.设x R ∈,定义符号函数1,0sgn 0,01,0x x x x >⎧⎪==⎨⎪-<⎩,则函数()||sgn f x x x =的图像大致是( )A .B . C.D .6.将2名教师、4名学生分成2个小组,分别安排到甲、乙两地参加社会实践活动,每个小组由1名教师和2名学生组成,不同的安排方案共有( )A .12种B .10种 C.9种 D .8种7.若变量,x y 满足约束条件120y x y x y ≤⎧⎪+≥⎨⎪--≤⎩,则2z x y =-的最大值为( ) A .4 B .3 C.2 D .18.已知ABC ∆与BCD ∆均为正三角形,且4AB =.若平面ABC 与平面BCD 垂直,且异面直线AB 和CD 所成角为θ,则cos θ=( )A .1515 C. 14- D .149.运行如图所示的程序框图,设输出数据构成的集合为A ,从集合A 中任取一个元素a ,则函数a y x =,[0,)x ∈+∞是增函数的概率为( )A .47B .45 C. 35 D .3410.已知P 为ABC ∆所在平面内一点,0AB PB PC ++=u u u r u u u r u u u r ,||||||2AB PB PC ===u u u r u u u r u u u r ,则ABC ∆的面积等于( )A 3B .2333.4311.过双曲线22221(0,0)x y a b a b-=>>的右焦点F 作圆222x y a +=的切线FM (切点为M ),交y 轴于点P .若M 为线段FP 的中点,则双曲线的离心率是( )A 2B 3 C.2 D 512.若函数2()ln f x ax x x =--存在极值,且这些极值的和不小于4ln2+,则a 的取值范围为( )A .[2,)+∞B .[22,)+∞ C. [23,)+∞ D .[4,)+∞第Ⅱ卷(非选择题 共90分)二、填空题(本大题共4小题,每小题,每小题5分,共20分)13.若直线20x y c -+=是抛物线24x y =的一条切线,则c = .14.若函数()f x ax b =+,[4,]x a a ∈-的图像关于原点对称,则函数()a g x bx x =+,[4,1]x ∈--的值域为 . 15.在《九章算术》中,将四个面都为直角三角形的三棱锥称之为鳖臑( ).已知在鳖臑M ABC -中,MA ⊥平面ABC ,2MA AB BC ===,则该鳖臑的外接球的表面积为 .16.已知ABC ∆的内角,,A B C 的对边分别是,,a b c ,且222()a b c +-(cos cos )a B b A ⋅+abc =,若2a b +=,则c 的取值范围为 .三、解答题(本大题分必考题和选择题两部分,满分70分.解答应写出文字说明、证明过程或演算过程)(一)必考题(共5小题,每小题12分,共60分)17.已知在递增等差数列{}n a 中,12a =,3a 是1a 和9a 的等比中项.(1)求数列{}n a 的通项公式;(2)若1(1)n n b n a =+,n S 为数列{}n b 的前n 项和,求100S 的值.18.如图,四棱柱1111ABCD A B C D -的底面ABCD 是菱形,AC BD O =I ,1AO ⊥底面ABCD ,2AB =,13AA =.(Ⅰ)证明:平面1ACO ⊥平面11BB D D ; (Ⅱ)若60BAD ∠=︒,求二面角1B OB C --的余弦值.19.随着资本市场的强势进入,互联网共享单车“忽如一夜春风来”,遍布了一二线城市的大街小巷.为了解共享单车在A 市的使用情况,某调查机构借助网络进行了问卷调查,并从参与调查的网友中随机抽取了200人进行抽样分析,得到下表(单位:人):(Ⅰ)根据以上数据,能否在犯错误的概率不超过0.15的前提下认为A 市使用共享单车情况与年龄有关?(Ⅱ)①现从所抽取的30岁以上的网民中,按“经常使用”与“偶尔或不用”这两种类型进行分层抽样抽取10人,然后,再从这10人中随机选出3人赠送优惠券,求选出的3人中至少有2人经常使用共享单车的概率.②将频率视为概率,从A 市所有参与调查的网民中随机抽取10人赠送礼品,记其中经常使用共享单车的人数为X ,求X 的数学期望和方差. 参考公式:22()()()()()n ad bc K a b c d a c b d -=++++,其中n a b c d =+++. 参考数据:20.已知椭圆22221(0)x y a b a b+=>>的左右焦点分别为1F 和2F ,由4个点(,)M a b -,(,)N a b ,2F 和1F 面积为. (Ⅰ)求椭圆的方程;(Ⅱ)过点1F 的直线和椭圆交于两点,A B ,求2F AB ∆面积的最大值.21.设函数()ln k f x x x=+,k R ∈. (Ⅰ)若曲线()y f x =在点(,())e f e 处的切线与直线20x -=垂直,求()f x 的单调递减区间和极小值(其中e 为自然对数的底数); (Ⅱ)若对任何120x x >>,1212()()f x f x x x -<-恒成立,求k 的取值范围. 请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分.22.选修4-4:坐标系与参数方程在平面直角坐标系xOy 中,已知曲线C 的参数方程为cos sin x t y αα=⎧⎨=⎩,(0,t α>为参数).以坐标原点O 为极点,x 轴的正半轴为极轴,取相同的长度单位建立极坐标系,直线l 的极坐标方程为sin()34πθ+=. (Ⅰ)当1t =时,求曲线C 上的点到直线l 的距离的最大值; (Ⅱ)若曲线C 上的所有点都在直线l 的下方,求实数t 的取值范围.23.选修4-5:不等式选讲已知函数()|21||1|f x x x =-++.(Ⅰ)解不等式()3f x ≤.(Ⅱ)记函数()()|1|g x f x x =++的值域为M ,若t M ∈,证明2313t t t+≥+.试卷答案一、选择题1-5 6-10 11、12:二、填空题134 14. 1-- 15. 12π 16.[2,]2[1,2)三、解答题17.解:(Ⅰ)由{}n a 为等差数列,设公差为d ,则1(1)n a a n d =+-. ∵3a 是1a 和9a 的等比中项,∴2319a a a =,即2(22)2(28)d d +=+,解之,得0d =(舍),或2d =. ∴1(1)2n a a n d n =+-=. (Ⅱ)11111()(1)2(1)21n n b n a n n n n ===-+++. 12100n S b b b =+++=L 111111(1)2223100101-+-++-L 1150(1)2101101=-=. 18.(Ⅰ)证明:∵1AO ⊥平面ABCD ,BD ⊂平面ABCD ,∴1AO BD ⊥. ∵ABCD 是菱形,∴CO BD ⊥.∵1AO CO O =I ,∴BD ⊥平面1A CO . ∵BD ⊂平面11BB D D ,∴平面1ACO ⊥平面11BB D D . (Ⅱ)∵1AO ⊥平面ABCD ,CO BD ⊥,以O 为原点,OB u u u r ,OC u u u r ,1OA uuu r 方向为,,x y z 轴正方向建立如图所示空间直角坐标系.∵2AB =,13AA =,60BAD ∠=︒,∴1OB OD ==,3OA OC ==22116OA AA OA -. 则(1,0,0)B ,3,0)C ,(0,3,0)A -,16)A , ∴113,6)BB AA ==u u u r u u u r ,113,6)OB OB BB ++=u u u u r u u u r u u u r .设平面1OBB 的法向量为(,,)n x y z =r ,∵(1,0,0)OB =u u u r,1OB =u u u u r ,∴00x x =⎧⎪⎨=⎪⎩.令y =,得1)n =-r .同理可求得平面1OCB的法向量为1)m =-u r .∴cos ,n m <>=r u r . 19.解:(Ⅰ)由列联表可知,22200(70406030) 2.19813070100100K ⨯⨯-⨯=≈⨯⨯⨯. ∵2.198 2.072>,∴能在犯错误的概率不超过0.15的前提下认为A 市使用共享单车情况与年龄有关.(Ⅱ)①依题意,可知所抽取的10名30岁以上网民中,经常使用共享单车的有60106100⨯=(人), 偶尔或不用共享单车的有40104100⨯=(人). 则选出的3人中至少2人经常使用共享单车的概率为21364633101023C C C P C C =+=. ②由22⨯列联表,可知抽到经常使用共享单位的频率为1301320020=, 将频率视为概率,即从A 市市民中任意抽取1人, 恰好抽到经常使用共享单车的市民的概率为1320. 由题意得13(10,)20X B :,∴1313()10202E X =⨯=;13791()10202040D X =⨯⨯=. 20.解:(Ⅰ)由条件,得b ==3a c +=. 又223a c -=,解得2a =,1c =.∴椭圆的方程22143x y +=. (Ⅱ)显然,直线的斜率不能为0, 设直线方程为1x my =-,直线与椭圆交于11(,)A x y ,22(,)B x y , 联立方程221431x y x my ⎧+=⎪⎨⎪=-⎩,消去x 得,22(34)690m y my +--=. ∵直线过椭圆内的点,无论m 为何值,直线和椭圆总相交. ∴122634m y y m +=+,122934y y m =-+. ∴21212121||||||2F AB S F F y y y y ∆=-=-===令211t m =+≥,设1()9f t t t =+,易知1(0,)3t ∈时,函数()f t 单调递减,1(,)3t ∈+∞函数单调递增, ∴当211t m =+=,设0m =时,min 10()9f t =,2F AB S ∆的最大值为3. 21.解:(Ⅰ)由条件得21'()(0)k f x x x x =->, ∵曲线()y f x =在点(,())e f e 处的切线与直线20x -=垂直, ∴此切线的斜率为0,即'()0f e =,有210k e x -=,得k e =. ∴221'()(0)e x e f x x x x x-=-=>,由'()0f x <得0x e <<,由'()0f x >得x e >. ∴()f x 在(0,)e 上单调递减,在(,)e +∞上单调递增. 当x e =时,()f x 取得极小值()ln 2e f e e e =+=. 故()f x 的单调递减区间(0,)e ,极小值为2. (Ⅱ)条件等价于对任意120x x >>,1122()()f x x f x x -<-恒成立, 设()()ln (0)k h x f x x x x x x=-=+->,则()h x 在(0,)+∞上单调递减. ∴21'()10k h x x x=--≤在(0,)+∞上恒成立. 得2211()(0)24k x x x x ≥-+=--+>恒成立. ∴14k ≥(对14k =,'()0h x =仅在12x =时成立). 故k 的取值范围是1[,)4+∞. 22.解:(Ⅰ)直线l 的直角坐标方程为30x y +-=,曲线22:1C x y +=. ∴曲线C 为圆,且圆心O 到直线l的距离2d =.∴曲线C 上的点到直线l的距离的最大值为12+.(Ⅱ)∵曲线C 上的所有点均在直线l 的下方, ∴对R α∀∈,有cos sin 30t αα+-<恒成立.)3αϕ-<(其中1tan tϕ=)恒成立.3<. 又0t >,∴解得0t <<∴实数t的取值范围为. 23.解:(Ⅰ)依题意,得3,11()2,1213,2x x f x x x x x ⎧⎪-≤-⎪⎪=--<<⎨⎪⎪≥⎪⎩, 于是得1()333x f x x ≤-⎧≤⇔⎨-≤⎩,或11223x x ⎧-<<⎪⎨⎪-≤⎩,或1233x x ⎧≥⎪⎨⎪≤⎩, 解得11x -≤≤.即不等式()3f x ≤的解集为{|11}x x -≤≤. (Ⅱ)()()|1|g x f x x =++=|21||22||2122|3x x x x -++≥---=,当且仅当(21)(22)0x x -+≤时,取等号,∴[3,)M =+∞. 原不等式等价于2331t t t-+- 22233(3)(1)t t t t t t t-+--+==. ∵t M ∈,∴30t -≥,210t +>. ∴2(3)(1)0t t t -+≥. ∴2313t t t +≥+.。

2018年陕西省高三质量检查试题(一)数学理B (1)

2018年陕西省高三质量检查试题(一)数学理B (1)

数学(理)一、选择题(共12小题,每小题5分,共60分) 1.已知集合2{|9}A x x =<,{|}B x x =∈N ,则AB 中元素的个数( )A.3B.2C.1D.03.已知命题:p 对任意x ∈R ,总有20x >;:q “1x >”是“2x >”的充分不必要条件,则下列命题为真命题的是( )A.p q ∧B.p q ∧⌝C.p q ⌝∧⌝D.p q ⌝∧4.已知等差数列{}n a 的前n 项和为n S ,且3512a a ⋅=,20a =,若10a >,则20S =( )A.420-B.340-C.420D.3405.设x ∈R ,定义符号函数1,0sgn 0,01,0x x x x >⎧⎪==⎨⎪-<⎩,则函数()||sgn f x x x =的图像大致是( )7.若变量x ,y 满足约束条件1020y x y x y ⎧⎪+⎨⎪--⎩≤≥≤,则2z x y =-的最大值为( )A.1B.2C.3D.411.过双曲线22221x y a b-=(0a >,0b >)的右焦点F 作圆222x y a +=的切线FM (切点为M ),交y 轴于点P 。

若M 为线段FP 的中点,则双曲线的离心率是( )B.2二、填空题(本大题共4小题,每小题5分,共20分)13.若直线20x y c -+=是抛物线24x y =的一条切线,则c = 。

16.已知ABC △的内角A 、B 、C 的对边分别是a 、b 、c ,且222()(cos cos )a b c a B b A abc +++=。

若2a b +=,则c 的取值范围为 。

三、解答题(本大题分必考题和选考题两部分,满分70分) (一)必考题(共5小题,每小题12分,共60分)17.(12分)已知在递增等差数列{}n a 中,12a =,3a 是1a 和9a 的等比中项。

⑴求数列{}n a 的通项公式; 。

陕西省西安市长安区2018届高三教学质量检测理科综合物理试题

陕西省西安市长安区2018届高三教学质量检测理科综合物理试题

5.16
5.04
4.94
4.83
4.71
4.59
4.46
改装表A读数I/mA
20
40
60
80
100
120
140
160
难度:0.4 组卷:3080 题型:实验题 更新:2014/6/21
图所示,水平桌面距地面高h=0.80m,桌面上放置两个小物块A、B,物块B置于桌面右边缘,物块A与物块B相距s=2.0m,两物块 质量mA、mB均为0.10 kg.现使物块A以速度v0=5.0m/s向物块B运动,并与物块B发生正碰,碰撞时间极短,碰后物块B水平飞出,落到 水平地面的位置与桌面右边缘的水平距离x=0.80 m.已知物块A与桌面间的动摩擦因数μ=0.40,重力加速度g取10m/s2,物块A和B均可 视为质点,不计空气阻力.求:
A.小球带负电 B.小球运动的轨迹是一条抛物线 C.洛伦兹力对小球做正功 D.要保持试管匀速运动,拉力F应逐渐增大
难度:0.65 组卷:186 题型:多选题 更新:2018/2/9
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16 . 如图所示,一个三棱镜的截面为等腰直角ΔABC,腰长为a,∠A=90°。一束细光线沿此截面所在平面且平行于BC边的方向射到AB边 上的中点,光进入核镜后直接射到AC边上,并刚好能发生全反射。试求:
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2018高考高三英语第一次质量预测试卷附答案及命题意图说明

2018高考高三英语第一次质量预测试卷附答案及命题意图说明

高中毕业年级第一次质量预测英语试题卷【试卷综述】本套试卷试题遵循考试大纲要求,体现了新课程理念。

阅读理解题材广泛、信息量大,选材现代化、生活化、突出趣味性。

内容涉及学校生活、现代科技、猎狐行动和体育精神等方面。

完型填空考察学生对语义、语境、语篇的深层次理解,并在掌握文章主旨大意、正确理解上下文语境线索的基础上审题。

总之,本套试卷没有偏、难、怪题,将语言知识点融入到具体语境中进行考察。

本试卷分为第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

第Ⅰ卷包括第一、二部分和第三部分的第一节,第Ⅱ卷包括第三部分的第二节和第四部分。

考试时间120分钟,满分150分(听力成绩算作参考分)。

考生应首先阅读答题卡上的文字信息,然后在答题卡上作答,在试卷上作答无效。

第Ⅰ卷第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面五段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What's Mark doing when the call comes in?A. Leaving his office.B. Talking with a secretary. B. Making a long distance call.2. What does the man advise the woman to do?A. Talk to her friend.B. Just get the money back.C. Keep a friendship with her friend..3. Why is the woman having a hard time?A. Her children eat a lot.B. Food costs more.C. She has to feed her children.4. What will the man do this weekend?A. Go to visit Mary.B. Go for a picnic.C. Work in his garden.5. What did the woman expect to do?A. Take charge of sales.B. Change to another department.C. Become the new manager.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

西安市2018届高三第质量检测理科综合试题+含答案

西安市2018届高三第质量检测理科综合试题+含答案

绝密★启用前长安一中2018届高三第十五模拟测试试卷理科综合(考试时间:150分钟试卷满分:300分)注意事项:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答第Ⅰ卷时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦干净后,再选涂其他答案标号。

写在本试卷上无效。

3.回答第Ⅱ卷时,将答案写在答题卡上。

写在本试卷上无效。

4.考试结束后,将本试卷和答题卡一并交回。

相对原子质量:H-1O-16N-14Cl-35.5Al-27Cu-64Fe-56Ag-108第Ⅰ卷一、选择题:本题共13个小题,每小题6分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

1.下列有关细胞器的叙述,正确的是()A.溶酶体中的水解酶对细胞自身结构不起作用B.病毒蛋白质外壳的合成离不开自身的核糖体C.液泡内细胞液的浓度升高导致植物细胞质壁分离D.叶绿体中的基粒和类囊体扩展了捕获光能的膜面积2.下列有关细胞代谢的叙述中正确的是()A.可利用氧化无机物产生的能量来合成有机物的微生物都是原核生物B.人体成熟的红细胞不能合成酶,但需要ATP,因此进行不需要酶的呼吸作用C.CO2可直接被[H]还原,再经过一系列的变化形成糖类D.进行光合作用的细胞中的色素种类都不相同3.下列是生物学中一系列有关“一定”的说法,其中完全正确的一项是()①人体细胞内C02的生成一定在细胞器中进行②种群的基因库一定随个体的死亡而逐渐变小直至消失③染色体中DNA的脱氧核苷酸序列改变一定会引起遗传性状的改变④在真核细胞增殖的过程中,一定会发生DNA含量变化和细胞质的分裂⑤类比推理法得出的结论不一定正确,但假说-演绎法得出的结论一定正确⑥某生物的测交后代中只有两种表现型且比例为1:1,则此生物一定只含一对等位基因⑦某生物的测交后代中只有两种表现型且比例为1:1,则此生物一定产生两种比值相等的配子A.①②③⑤⑥B.④⑤⑥⑦C.①④⑤⑦D.①⑤⑥4.反义RNA是指与mRNA或其他RNA互补的小分子RNA,当其与特定基因的mRNA互补结合时,可阻断该基因的表达。

2018陕西省高三教学质量检测试题(一)文科综合答案

2018陕西省高三教学质量检测试题(一)文科综合答案

2018年陕西省高三教学质量检测试题(一)参考答案及评分标准文科综合第Ⅰ卷(选择题 共140分)说明:本题包括35小题,每小题4分,共140分。

试卷类型:犃题号123456789101112答案CDBADCBCABAC题号131415161718192021222324答案DACABDCCADBB题号2526272829303132333435答案DCACBDDDBAB试卷类型:犅题号123456789101112答案BACCADDBDCBA题号131415161718192021222324答案BDDCACBDBBCD题号2526272829303132333435答案CADBAAABCBD第Ⅱ卷(非选择题 共160分)说明:第36~42题为必考题,计135分;43~46题为选考题,计25分。

36.(24分)(1)加那利群岛位于亚热带海洋,受海洋影响,最热月均温不会太高,最冷月均温不会太低,气温年较差较小;(4分)冬季受西风带控制,降水较多。

(2分)(2)欧洲大陆第三纪晚期受到冰川活动侵袭,古地中海亚热带植物区系在该群岛得以保留;(2分)各岛自然环境不同,加剧了外来植物的演变;(2分)群岛内多山地,垂直地域分异明显;受人类活动干扰较小等。

(2分)(3)可提高香蕉废料利用率;有利于节省矿物能源;可增加劳动力就业;可减少废料对环境的污染等。

(4分)(4)赞成。

(2分)加那利群岛是非洲、欧洲、美洲间来往轮船的重要燃料供应站,石油市场需求量大;在当地开发石油可以减少对进口石油的严重依赖;有利于促进当地经济的发展;有利于当地居民的就业等。

(答3点即得6分)不赞成。

(2分)加那利群岛距离非洲主要产油国近,方便进口石油;位于西亚至欧洲的石油运输线附近,便于石油的运进;沿岸有优良的港口,海运便利;当地开发石油易对环境造成破坏且不利于旅游业、渔业的发展。

(答3点即得6分)37.(22分)(1)位于阳坡,光照充足;(2分)位于山坡,排水条件好;(2分)海拔较高,夏季气温低,气候温和湿润。

《首发》陕西省西安市长安区2018届高三上学期质量检测大联考(一)数学(理)试题Word版含答案

《首发》陕西省西安市长安区2018届高三上学期质量检测大联考(一)数学(理)试题Word版含答案

2018届高三质量检测同一大联考数学(理)联考试卷(一)第Ⅰ卷一、选择题(本大题共12个小题,每小题5分,共60分,在每小题给出的四个选项中,只有一项是符合题目要求的)1、设集合22{|40},{|log 1}A x x x B x x =-<=>,则A B =A .(2,4)B .(0,2)C .(1,4)D .(0,4)2、若命题:2,2p k k Z πϕπ=+∈,命题():sin()(0)q f x wx w ϕ=+≠是偶函数,则p 是q 的A .充要条件B .充分不必要条件C .必要不充分条件D .既不充分也不必要条件3、已知函数()24,[,5]f x x x x m =-+∈的值域是[5,4]-,则实数m 的取值范围是 A .(,1)-∞- B .(1,2]- C .[1,2]- D .[2,5]4、已知()lg ,0,0x x x f x a b x ->⎧=⎨+≤⎩且(0)2,(1)4f f =-=,则((2))f f -=A .-1B .2C .3D .-35、下列命题中,真命题是A .220001,sin ()cos ()333x x x R ∃∈+= B .(0,),sin cos x x x π∀∈> C .2000,2x R x x ∃∈+=- D .(0,),1x x e x ∀∈+∞>+6、若x A ∈,则1A x ∈,就称A 是伙伴关系集合,集合11{1,0,,,2,3}23M =-的所有非空子集中具有伙伴关系的集合的个数是A .31B .7C .3D .17、若2)4n x dx π=+,则2()n y y+的展开式中常数项为 A .8 B .16 C .24 D .608、把函数sin()6y x π=+的图象上个点的横坐标缩短到原来的12(纵坐标不变),再将图象向右平移3π个单位,那么所得图象的一个对称中心为A .(,0)2π-B .(,0)2πC .(,0)8πD .(,0)4π9、执行如图所示的程序框图,如果输入3,2a b ==,那么输出a 的值为A .16B .256C .3log 626D .656110、已知直线0(0)x y k k +-=>与圆224x y +=交于不同的两点,,A B O 是坐标原点,且有43OA OB AB +≥,那么k 的取值范围是A .)+∞B .)+∞C .D .11、设α为锐角,若1cos()63πα+=-,则sin(2)12πα+的值为A .725B .818C .50-D .5 12、已知定义在R 上的函数()f x 满足()(3)f x f x -=-,在区间3[0,]2上是增函数,且函数(3)y f x =-为奇函数,则A .()31(84)(13)f f f -<<B .()(84)(13)31f f f <<-C .()13(84)(31)f f f <<-D .()31(13)(84)f f f -<<第Ⅱ卷二、填空题:本大题共4小题,每小题5分,共20分,把答案填在答题卷的横线上..13、一个正方体消去一个角所得的几何体的三视图如图所示(图中三个四边形都是边长为3的正方形),则该几何体外接球的表面积为14、曲线12y x=+,直线1,x x e ==和x 轴所围成的区域的 面积是15、已知ABC ∆中角C 为直角,D 是边BC 上一点,M 是AD 上一点, 且1,CD DBM DMB CAB =∠=∠=∠ ,则MA =16、已知函数()2(24)23,3,a x a x t f x x x x t-+-≤⎧=⎨-+>⎩,无论t 去何值,函数()f x 在区间(,)-∞+∞上总是不单调,则a 的取值范围是三、解答题:本大题共6小题,满分70分,解答应写出文字说明、证明过程或演算步骤(一)必考题,共60分17、(本小题满分10分)设函数()2sin()2cos 366x x f x πππ=--. (1)试说明()y f x =的图象由函数3y x π=的图象经过怎样的变化得到?并求()f x 的单调区间;(2)若函数()y g x =与()y f x =的图象关于直线2x =对称,当[0,1]x ∈时,求函数()y g x =的最值.18、(本小题满分12分)已知定义在区间(0,)+∞上的函数()f x 满足1212()()()f x x f x f x ⋅=+,且当1x >时,()0f x >.(1)求()1f 的值;(2)证明:()f x 为单调增函数;(3)若1()15f =-,求()f x 在1[,125]25上的最值.19、(本小题满分12分)已知数列{}n a 的前n 项和为n S ,且满足112,420(2,)n n a S S n n N +-=--=≥∈. (1)求数列{}n a 的通项公式;(2)令2log ,n n n b a T =为{}n b 前n 项和,求证:112nk n T =<∑.20、(本小题满分12分)某单位N 名员工参加“社区低碳你我他”活动,他们的年龄在25岁至50岁之间,按年龄分组:第1组[)25,30,第2组[)30,35,第3组[)35,40,第4组[)40,45,第5组[]45,50,得到的频率分布图如图所示,下表是年龄的频率分布表.(1)现要从年龄较小的第1,2,3组中用分层抽样的方法抽取6人,则年龄第1,2,3组人数分别是多少?(2)在(1)的条件下,从这6中随机抽取2参加社区宣传交流活动,X 表示第3组中抽取的人数,求X 的分布列和期望值21、(本小题满分12分)已知函数()1xx e f x xe =+ . (1)求()f x 的单调区间;(2)当0x >时,()21(0)1f x a ax >≥+,求a 的取值范围.请考生在第(22)、(23)题中任选一题作答,如果多做,则按所做的第一题记分,作答时用2B 铅笔在答题卡上把所选题目的题号涂黑,把答案填在答题卡上.22、(本小题满分10分) 选修4-4 坐标系与参数方程已知函数()32f x x ax bx c =+++,曲线()y f x =在点1x =-处的切线为:550l x y +-=,若23x =时,()y f x =有极值. (1)求,,a b c 的值;(2)求()y f x =在[3,2]-上的最大值和最小值.23、(本小题满分10分))选修4-5 不等式选讲 已知函数()f x x a =-.(1)若不等式()4f x ≤的解集为[1,7]-,求实数a 的值;(2)在(1)的条件下,若0x R ∈,使得00()(5)4f x f x m ++<,求实数m 的取值范围.。

陕西省西安市2018届高三理综第三次质量检测 精品推荐

陕西省西安市2018届高三理综第三次质量检测  精品推荐

2018年西安市高三年级第三次质量检测试题理科综合第I卷(选择题共126分)一、选择题:本题共13小题,共78分,每小题6分,在每小题列出的四个选项中,只有一项是符合题目要求的。

1.下列有关著名科学家通过研究取得重要理论成果的叙述,不正确的是A.孟德尔根据多年对豌豆等植物性状遗传的研究,通过假说演绎的方法提示了遗传学的两条基本规律。

B.摩尔根通过对果蝇眼色性状遗传的分析,证明了孟德尔遗传定律的正确性。

C.萨顿将看不见的基因与看得见的染色体的行为进行类比,提出基因在染色体上,并且与染色体行为存在着明显的平行关系。

D.沃森和克里克通过构建物理模型,得出了DNA分子的双螺旋结构,对解释生物性状的稳定性遗传提供了坚实的物质基础和理论依据。

2.用某种大小相似的绿色植物轮藻叶片分组进行光合作用实验:已知实验前叶片质量相等,在不同温度下分别暗处理1h,测其质量变化,立即光照1h(光照强度相同),再测其质量变化。

得到如下结果:据表分析,以下说法正确的是A.光照时,第二、三组轮藻光合作用产生的氧气量相等B.光照时,第二组轮藻光合作用强度等于呼吸作用强度C.光照时,第四组轮藻光合作用合成的有机物总量为11mgD.该轮藻进行光合作用的最适温度是27°C3.下图表示染色体、DNA、基因三者之间的关系,关于三者之间关系叙述错误的是A.每条染色体上含有1个或2个DNA分子,DNA分子上含有多个基因B.才能复制、分离和传递,且三者行为一致C.三者都是生物细胞内的遗传物质D.在生物的传宗接代中,染色体的行为决定着DNA和基因的行为4.图中的A、B、C表示3个自然条件有差异的地区,地区间黑线表示存在一定的地理隔离。

A地区某个体由于机会开始分布到B、C地区,并逐渐形成两个新物种,③中的甲、乙、丙分别表示3个种群。

下列相关说法正确的是A .上述过程说明地理隔离是新物种形成的必要条件B .甲、乙两个种群的基因库存在着明显的差异,不能进行基因交流C .乙、丙两个种群存在生殖隔离,但两种群的基因频率不同D .甲、丙种群存在地理隔离,并且两个各群基因库组成完全不同5.2018年4月5日,山西王家岭煤矿,由于透水事件被困的153名矿工有115名奇迹般获救,并有显著的生命特征。

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2018年陕西省高三质量检测题(一)英语本试题共12页,满分150分,考试时间120分钟。

(命题人:王海峰)第一部分听力(共两节,满分30分)做题时,先把答案标在试卷上。

录音内容结束后,你将有两分钟时间将试卷上的答案转涂到答题卡上。

第一节(共5小题,每小题1.5,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the T-shirt?A.$19.15B. $18.7C. $13.57答案是C。

1. What has happened to the bike?A. It has broken down.B. She changed the brake.C. She has just repaired it.2. What does the man like best?A. Poems.B. Camping.C. Basketball.After all that’s my favorite.3. What does Tom plan to do next week?A. To make a robotB. To enter a competition.C. To surprise the woman.4. What’s the man probably going to eat?A. Fried dishes.B. Hot pot.C. Local snack.5. How is Janet probably feeling now?A. Stressed.B. Confused.C. Disappointed.1. A. 旨在考查考生简单分析推理的能力。

见The chain’s broken. (0.75)2. C. 旨在考查考生简单分析推理的能力。

见Maybe I’ll go to the basketball. (0.70)3. B. 旨在考查考生简单分析推理的能力。

见It’s for the competitio n next week.(0.70)4. C. 旨在考查考生理解并确认事实性信息的能力。

本题有两个干扰信息,分别是fried dishes 和hot pot,但男方却说but maybe we should try some local snack.(0.65)5. A. 旨在考查考生理解对话、分析判断说话者心情的能力。

The deadline is tomorrow. But I haven’t finished even half of it.(0.60)第二节(共15小题,每题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6. What time is it now?A. 1:45.B. 2:10.C. 2:15.6. A. 本题旨在考查考生7. What will the man do?A. He’ll work on a project.B. He’ll see Linda in the library.C. He’ll meet with Professor Smith.听第7段材料,回答第8至第10题。

8. What are the speakers talking about?A. Having guests this weekend.B. Going out for sightseeing.C. Moving into a new house.9. What is the relationship between the speakers?A. Neighbors.B. Husband and wife.C. Host and visitor.10. What will the man do tomorrow?A. Work in his garden.B. Have a barbecue.C. Do some shopping. 听第8段材料,回答第11至13题。

11. What did the woman plan to do at first?A. Read at home.B. Borrow a book.C. Go to the cinema.12. How are they going to the opera?A. Take a bus.B. Drive a car.C. Take a taxi.13. What do you learn about the woman?A. She has little interest in reading.B. She hates going out on weekends.C. She is crazy about classic opera.听第9段材料,回答第14至17题。

14. How does Carrie feel about her job?A. It is quite OK.B. It is unpleasant.C. It is not bad.15. Why does the man want to give up his present work?A. His colleagues aren’t friendly.B. He’s got too low a wage.C. He’s lost interest in his work.16. What seems to be Andrew's future plan?A. To learn to speak Spanish.B. To start a travel business.C. To find a new job in Spain.17.What is the relationship between Carrie and Andrew?A. Good friends.B.Fellow workers.C. Travel companions.听第10段材料,回答第17至20题。

18. How do students enter the library?A. With a library account.B. With a student card.C. With a password.19. What kind of books have to be returned within one week?A. Books liked by a lot of people.B. Books borrowed by local residents.C. Books published recently.20. What will the speaker do next?A. Tell the students where to get bottled water.B. Take the students on a campus tour.C. Show the students around the library.第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C、D)中选出最佳选项,并在答题卡上将该项涂黑。

AThe Electricity workers’strike has been going on for three days. Below are some statements about the strike.Mr. Mike Smith:I t wasn’t an easy decision, but we have been asking for a reasonable wage for years. Now at last people are beginning to listen to us. We’re only asking for a 25 percent increase in our wages. It’s a pity so many people have to be inconvenienced by our strike. but please don’t blame us. Blame the government for refusing our claim.Mr. Tom Brown:It’s totally unreasonable to demand so much money when we are trying desperately to stop the prices going up. If wages go up, so do prices. If we give in to them, all the other unions would want more, with the inevitable result that the crisis would become uncontrollable. We offer them a 10 percent increase. And that’salready too much. My stand at the strike is to persuade the Union to see the reason.Mr. Bob Davis:Everybody will be hurt by this strike, including the electricity workers themselves. The economy will be destroyed and many people will lose their jobs. Already people are saying that the big unions have too much power and shouldn’t be allowed to strike. Of course the electricity workers want to get more money. don’t we all?Miss Stater:Let’s face it. It’s neither here nor there. The electricity workers are in a strong position. Perhaps we can’t do anything about it. What I say is: let them have their 250 dollars so we can return to work. I mean, the government wastes the taxpayers’money all the time on unimportant things. How can anyone say 250 dollars is “too much”? Pop singers get more. Nurses get less. It’s just one of those things.21. Who is most likely to be employed in electricity industry?A. Mr. Mike SmithB. Mr. Tom BrownC. Mr. Bob DavisD. Miss Stater22. The underlined word most probably means _______.A. avoidableB. inspiringC. automaticD. sensitive23. We can learn from the texts that ________.A. the electricity workers won’t achieve their goalB. the government won’t meet the workers’ demandC. the strike caused little trouble for the societyD. the workers got little support from the societyBLate last year, I needed to transport some furn iture from our house to my son’s flat in central London. I should have paid a man to do it, but foolishly confident in my driving ability, I decided to hire a lorry and drive it myself.Moving the lorry backward in my yard, I crashed into a small shed, causing permanent damage. Fortunately I owned the shed. I loaded up the furniture and set out. By now it was rush hour. My nerves broke down, as I drove the huge lorry through the streets nervously.At last I arrived at Charlotte Street and found an available parking space. I moved the lorry into it only to notice three people at a pavement cafe waving to me.I got out, trembling violently, like one who has just finished a stormy Atlantic crossing. “You’ve hit the car parked behind you,” they said. I examined the car. There were white scratches on its front face. It bore a disabled sign. So, now I was a bad driver and a bad man. Under the severe look of the three, I left an apologetic note on the damaged car’s wingscreen, giving my phone number.I unloaded the furniture, dripping the sweat. wanting only to escape from the monster, I drove it back to its base at Edgware. On arrival, the boss told me I must fill it up with petrol before returning it. “Just charge me,” I cried, still shaking with fear. He stared at me with understanding. No doubt he’d witnessed others in this state before. “How about I drive you to a petrol station, you fill up, and I drive her back?” he asked.He danced the great through the traffic so carefully that it would have shamed me if I had not been so grateful.24. The man felt it _______ to have delivered the furniture himself.A. gratefulB. proudC. confidentD. regretful25. The man trembled violently because _______.A. the lorry was too difficult to driveB. he caused a terrible traffic accidentC. he was afraid to see the three menD. the furniture was too heavy for him26. The man said he was a bad man most probably because _____.A. he shouldn’t have driven the lorry himselfB. he made the traffic accident on purposeC. he shouldn’t cause trouble for the disabledD. he parked the big lorry on the pavement27. The writer intended to suggest that ________.A. it was thrilling to drive a lorryB. being too confident is foolishC. it was hard to avoid accidentsD. the bass was expert in drivingCIt’s easy to keep your ag eing brain as quick as it was in college. Log on to a website full of brain games or download the right apps, and within 20 minutes you’llbe doing your part to sharpen your memory and slow the decline of your mental functions. At least that’s what the companies behind this booming industry would have you believe. But is it true?Concrete proof about the benefits of brain games is hard to come by, experts say, when it comes to measurably improving aspects of mental fitness, like having a good memory. “People would really love to believe you could do something like this and make your brain better, but t here’s just no solid evidence.” Says Randall W. Engle, a primary investigator at the Attention and Working Memory Lab at the Georgia Institute of Technology.That’s not to say brain games are without benefit. Experts say these kinds of mental exercises can change your brain. The brain changes with just about everything you do, including mental training exercises. But numerous studies have shown that brain game lack what researchers call “transfer.” In other words, repeating a game over and over again teaches you how to play the game and get better at it but your brain ageing won’t necessarily come to a stop.“It’s like, you walk through fresh snow, you leave a trace. If you walk the same route again, the trace gets deeper and deeper,” says Ursula Staudinger, director of the Butler Columbia Ageing Center at Columbia University. The fact that structural changes occur does not imply that in general this brain has become more capable. It has become more capable of doing exactly the tasks it was practicing.28. We can infer from the first paragraph that _______.A. brain games improve the memoryB. brain ageing actually can be quitC. people don’t believe brain gamesD. the author doubt the effect of brain games.29. What does Engle think of the functions of brain games?A. They really make difference.B. Their effects still need proving.C. People like to be led by the noseD. people don’t believe the effects.30. The underlined word most probably means _______.A. stopping the brain ageingB. having the brain working.C. making the brain more active.D. speeding up the brain’s ageing.31. Which can be the best title of the passage?A. Games Stop Brain AgingB. Unavoidable Brain Aging.C. Games’ Roles Need Proving.D. Games Improve Your Brain.DCulture shock occurs when people have been suddenly thrown into a new culture. Newcomers may be anxious because they don’t speak the language. Neither do they know the customs or understand the people’s behavior in daily life.Quite often the visitor find that “yes”may not always mean “yes”, that friendliness does not necessarily mean friendship, or that statements that appear to be serious are really intended as jokes. the foreigners may be unsure as when to shake hands, when to start conversations, or how to approach a stranger. The idea of culture shock helps explain feeling of puzzlement and confusion.Language problems do not account for all the setback that people feel. When one has lost everything that was once familiar, such as understanding a transportation system, knowing how to register for university classes, or knowing how to make friends, difficulties in coping with the new society may arise.When an individual enters a strange culture, he or she feels like a fish out of water. Newcomers feel at times that they do not belong to the culture and feel deserted by the native members of the culture. When this happens, visitors may want to reject everything about the new environment and may glorify and sing their own praises of the positive aspects of their own culture. On the other side, more visitors may sneeze at their native country by rejecting its value and instead choosing to approve of the value of the new country. This may occur as an attempt to accept the new culture in order to be taken in by the people in it.32. What do people feel when they are abruptly in a new culture?A. Excited.B. Delighted.C. Upset.D. Depressed.33. We can infer from the second paragraph that _______.A. it’s impossible to get used to a new cultureB. people feel confused due to culture shockC. foreigners often don’t mean what they sayD. most foreigners are usually quite humorous34. The biggest barrier people often meet with in a new country is _____.A. the languageB. the transportationC. the environmentD. the puzzlement35. Which of the following can help one be taken by a new country?A. To do what he is used to.B. To follow the native culture.C. To reject the new culture.D. To keep his own customs.第二节(共5小题,每小题2分,满分10分)根据短文内容,从短文后的选项中选出能选出能填入空白处的最佳选项。

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