Hessian sufficiency for bordered Hessian

合集下载

高三英语文章公平正义单选题50题

高三英语文章公平正义单选题50题

高三英语文章公平正义单选题50题1.Fairness, justice and equality are important concepts. In a just society, people are treated equally and have access to the same opportunities. What is the main difference between fairness and justice?A.Fairness emphasizes equal treatment, while justice emphasizes moral rightness.B.Fairness emphasizes moral rightness, while justice emphasizes equal treatment.C.Fairness and justice have no difference.D.Fairness is only for the rich, while justice is only for the poor.答案:A。

公平(fairness)强调平等对待,而正义(justice)强调道德上的正确性。

2.In history, many people fought for justice. Which of the following is most closely related to justice?A.WealthB.PowerwD.Fame答案:C。

在历史上,许多人都为正义而战。

法律(Law)与正义最为密切相关,因为法律旨在维护公平正义。

3.What does equality mean in the context of fairness and justice?A.Everyone has the same amount of money.B.Everyone has the same opportunities and rights.C.Everyone has the same job.D.Everyone has the same hobbies.答案:B。

2024年沪教版英语小学三年级上学期模拟试卷及答案指导

2024年沪教版英语小学三年级上学期模拟试卷及答案指导

2024年沪教版英语小学三年级上学期模拟试卷及答案指导一、听力部分(本大题有12小题,每小题2分,共24分)1.Question:What is the girl's favorite color?Options:A.RedB.BlueC.GreenD.YellowAnswer:B.BlueExplanation:In the recording,the girl says,“My favorite color is blue because it reminds me of the sky.”This clearly indicates that her favorite color is blue,making option B the correct choice.2.Question:Where is the boy going after school?Options:A.To the libraryB.To the parkC.To the supermarketD.To his friend's houseAnswer:D.To his friend's houseExplanation:The boy mentions in the recording,“After school,I am going to my friend's house to play video games.”This statement directly answers the question, making option D the correct answer.The other options are not mentioned in the context provided.Note:Ensure to listen attentively to the recordings as the details are crucial for selecting the correct answers.3 、Listen to the dialogue and choose the correct answer.Dialogue:Teacher:“What did you do yesterday,Tom?”Tom:“I went to the park with my family.We had a picnic and played some games.”Question:What did Tom do yesterday?A)He went to the zo0.B)He had a picnic in the park.C)He stayed at home.Answer:BExplanation:In the dialogue,Tom clearly states that he went to the park with his family and had a picnic.Therefore,option B is the correct answer.4 、Listen to the short story and answer the question.Story:“Yesterday,it was sunny and warm.Lisa and her friends decided to go swimming in the lake.They had a lot of fun and stayed there until sunset.”Question:What was the weather like yesterday?A)It was rainy.B)It was sunny.C)It was cold.Answer:BExplanation:The story mentions that it was sunny and warm yesterday,which directly corresponds to option B.Therefore,option B is the correct answer.5.Listen to the dialogue between a teacher and a student.Choose the correct answer.Dialogue:Teacher:“What did you do yesterday,Tom?”Tom:“I visited my grandparents in the countryside.”Question:Where did Tom go yesterday?A)To the parkB)To the countrysideC)To the museumAnswer:B)To the countrysideExplanation:In the dialogue,Tom clearly states that he visited his grandparents in the countryside.Therefore,option B is the correct answer.6.Listen to the short story and answer the question.Story:Sara loves animals.She has a dog named Max and a cat named Luna.Every morning, she feeds them and takes Max for a walk.Yesterday,Sara found a bird with a hurt wing.She took care of the bird and it flew away the next day.Question:What did Sara do for the bird?A)She took it to the vet.B)She fed it and took care of it.C)She let it fly away immediately.Answer:B)She fed it and took care of it.Explanation:The story mentions that Sara found a bird with a hurt wing and took care of it until it flew away the next day.This indicates that she fed it and looked after it,making option B the correct choice.7.Listen to the dialogue and choose the correct answer.Dialogue:Speaker 1: “What did you do yesterday,Tom?”Speaker 2:“I went to the park with my family.We had a picnic and played some games.”Question:Where did Tom go yesterday?A)To the zo0B)To the parkC)To the museumD)To the beachAnswer:BExplanation:The dialogue clearly states that Tom went to the park with his family.The other options(zoo,museum,beach)are not mentioned,making B the correct choice.8.Listen to the short story and answer the question.Story:“Last weekend,Sarah decided to bake a cake for her mother's birthday.She gathered all the ingredients and followed the recipe carefully.After an hour, the cake was ready and it looked delicious.Her mother was very happy and thanked Sarah for the wonderful surprise.”Question:Why did Sarah bake a cake?A)For her own birthdayB)For her friend's birthdayC)For her mother's birthdayD)For a school eventAnswer:CExplanation:The story explains that Sarah baked a cake specifically for her mother's birthday.The other options (her own birthday,friend's birthday, school event)are not mentioned in the context,making C the correct answer.9 、Instructions:Listen to the dialogue between a teacher and a student. Then answer the question.Audio Script:Teacher:“Hello,Tim.How was your weekend?”Student:“Hi,Mrs.Smith.My weekend was great!I visited my grandparents and we went to the zo0.”Question:What did Tim do over the weekend?A)He stayed at home.B)He visited his grandparents.C)He went to the park.D)He played video games.Answer:B)He visited his grandparents.Explanation:In the dialogue,Tim clearly states that he visited his grandparents and they went to the zoo.This directly corresponds to option B.10 、Instructions:Listen to the short story and then answer the question. Audio Script:“Last Saturday,Lisa and her family went to the beach.They brought their sunscreen,beach balls,and a picnic basket.They played in the water,built a sandcastle,and had a delicious lunch.It was a sunny and fun day!”Question:What did Lisa and her family do at the beach?A)They went swimming.B)They built a sandcastle.C)They had a picnic.D)All of the above.Answer:D)All of the above.Explanation:The story mentions that Lisa and her family played in the water (implying swimming),built a sandcastle,and had a delicious lunch(a picnic). Therefore,all the activities listed in the options were done by them,makingD the correct answer.11.Question:Listen to the short dialogue and choose the correct answer. Audio:“Excuse me,where is the library?”It's on the second floor,next to the cafeteria.”0ptions:A.The library is on the first floor.B.The library is on the second floor.C.The library is next to the gym.D.The library is on the third floor.Answer:BExplanation:The dialogue clearly states that the library is on the second floor, making option B the correct choice.Options A,C,and D are incorrect as they do not match the information given in the dialogue.12.Question:Listen to the passage and answer the question.Audio:“Tom loves animals.He has a dog named Max,a cat named Lily,and a bird named Sky.Every morning,he feeds them and takes Max for a walk in the park. In the evening,he plays with Lily and talks to Sky.”Question:Which animal does Tom take for a walk?Options:A.The catB.The dogC.The birdD.All of themAnswer:BExplanation:The passage mentions that Tom takes Max,his dog,for a walk in the park every morning.Therefore,option B is the correct answer.Options A, C,and D are incorrect as they do not accurately reflect the information provided in the passage.二、选择题(本大题有12小题,每小题2分,共24分)1、Which word is the opposite of “happy”?A)SadB)AngryC)ExcitedD)JoyfulExplanation:The word “happy”means feeling or showing pleasure or contentment.The opposite of this emotion is “sad,”which means feeling or showing sorrow.Options B,C,and D are not direct opposites of “happy.”“Angry”refers to feeling or showing anger,“excited”means feeling or showing enthusiasm,and“joyful”is similar to“happy,”meaning full of joy.2 、Choose the correct form of the verb to complete the sentence:“She t o the store every day.”A)goB)goesC)goingD)goneAnswer:BExplanation:The correct form of the verb to use here is“goes.”This is because the subject“She”is third-person singular,and in the present simple tense,verbs must end in“-s”or“-es”for third-person singular subjects. “Go”is the base form and is incorrect in this context.“Going”is the present participle form,used wit h“am,” “is,”or“are.” “Gone” is the past participle form,used with“have”or “has.”Therefore,“goes”is the appropriate choice to complete the sentence correctly.3 、What is the correct plural form of“child”?A)childsB)childesD)childerenAnswer:CExplanation:The plural form of“child”is “children,”whic h is an irregular plural form.It does not follow the regular rule of adding“-s”or “-es”to the end of the word.4 、Choose the correct sentence:A)She go to school by bus.B)She goes to school by bus.C)She go school by bus.D)She goes to the school by bus.Answer:BExplanation:The correct sentence is“She goes to school by bus.”In this sentence,“goes”is the correct form of the verb“to go”for the third person singular(she),and“to school”is the correct prepositional phrase indicating the destination.Option D is incorrect because“the”is not needed before “school” in this context.5.What is the correct plural form of the word“child”?A)childsB)childesC)childrenD)childerenAnswer:CExplanation:The correct plural form of the word“child”is“children.”This is an irregular plural form and does not follow the typical rule of adding “s” to make a word plural.6.Choose the correct sentence:A)She go to school by bus.B)She goes to school by bus.C)She go to the school by bus.D)She goes to the school by bus.Answer:BExplanation:The correct sentence is “She goes to school by bus.”In this sentence,“goes”is the correct form of the verb“to go”for the third person singular(she).Additionally,“school”is used without the definite article “the”when referring to the general concept of going to school.7.What is the correct plural form of the wor d “child”?A)childsB)childesC)childrenD)childerenAnswer:CExplanation:The correct plural form of“child”is“children.”This is an irregular plural form and does not follow the standard rule of adding“s”to make a noun plural.8.Which sentence is correct?A)She have a cat.B)He has a dog.C)They has two birds.D)We have a car.Answer:DExplanation:The correct sentence is“We have a car.”In English,the verb “have”is used with the pronouns“I,” “you,” “we,”and“they,”while“has” is used with the pronouns “he,” “she,”and “it.”Therefore, options A,B,and C are incorrect due to the improper use of“have”and“has.”Option D correctly uses “have”with the pronoun “we.”9 、Which word is the opposite of“happy”?A)SadB)AngryC)ExcitedD)JoyfulAnswer:AExplanation:The word “happy”means feeling or showing pleasure or contentment.The opposite of this feeling is “sad,”which means feeling or showing sorrow.“Angry”and“excited”are different emotions,and“joyful”is a synonym of “happy.”10、What is the correct plural form of“child”?A)ChildsB)ChildrenC)ChildesD)ChilderenAnswer:BExplanation:The plural form of “child”is “children.”This is an irregular plural form and does not follow the common rule of adding “s”to make a noun plural.“Childs,” “Childes,”and“Childeren”are incorrect forms.11.Which word is the opposite of“happy”?A)SadB)AngryC)ExcitedD)JoyfulAnswer:AExplanation:The word “happy”means feeling or s howing pleasure or contentment.The opposite of this emotion is “sad,”which means feeling or showing sorrow.Options B,C,and D are not direct opposites of “happy”; “angry”is another emotion,“excited”is similar to happy,and“joyful”is a synonym of happy.12.What is the correct plural form of the word“child”?A)ChildsB)ChildrenC)ChildesD)ChilderenAnswer:BExplanation:The plural form of the word“child”is “children.”This is an irregular plural form and does not follow the usual rule of adding“s”or“es”to the end of the word.Options A,C,and D are incorrect as they are not the correct plural forms of“child.”三、完型填空(10分)Read the passage carefully and fill in the blanks with the correct words from the options given.Once upon a time,there was a little girl named Lily.She lived in a small village near a beautiful forest.Every day,she walked to school with her friends. One day,while walking through the forest,they heard a strange sound.Curious, they decided to (1) i t.As they moved closer,they saw a small bird with a broken wing.It was crying for help.Lily felt(2) for the bird and wanted to help it.She gently picked it up and wrapped its wing with a piece of cloth from her dress.Her friends helped her find a safe place to put the bird.They decided to take care of it until it got better.Every day,they brought food and water for the bird.Slowly,the bird started to (3)After a few weeks,the bird's wing healed completely.It was time for the bird to return to the forest.Lily and her friends were sad to see it go,but they were happy that they had helped it.The bird flew away,chirping happily.Lily learned that even a small act of kindness can make a big (4) From that day on,Lily and her friends always looked out for animals in need. They knew that helping others was a great way to make the world a better place. The forest seemed to thank them with its beautiful (5) e very day.Options:(A)follow(B)sorry(C)improve(D)difference(E)soundsAnswers:(1)A(2)B(3)C(4)D(5)EExplanation:1.follow-They decided to follow the sound to see where it was coming from.2.sorry -Lily felt sorry for the bird because it was hurt.3.improve-The bird started to improve as they took care of it.4.difference -Lily learned that her kindness made a big difference.5.sounds -The forest thanked them with its beautiful sounds every day.四、阅读理解(26分)Part IV:Reading ComprehensionPassage:Tom is a third-grade student.He loves going to school because he has many friends there.Every morning,Tom wakes up early,eats breakfast,and then goes to school with his backpack.His favorite subject is math because he enjoys solving problems.After school,Tom often plays soccer with his friends in the park.On weekends,he likes to read books and help his parents with chores.Tom’s dream is to become a scientist when he grows up.Questions:1.What grade is Tom in?A.First gradeB.Second gradeC.Third gradeD.Fourth grade2.What is Tom's favorite subject?A.MathB.ScienceC.EnglishD.History3.What does Tom like to do on weekends?A.Play video gamesB.Read books and help with choresC.Watch TV all dayD.Go swimmingAnswers:1.C2.A3.B五、写作题(16分)Part V:WritingInstructions:Write a short paragraph about your favorite holiday.Include the name of the holiday,when it is celebrated,what you usually do on that day,and why you enjoy it so much.Your paragraph should be at least 50 words but no more than 100 words.Example:My Favorite HolidayMy favorite holiday is Christmas,which is celebrated on December 25th.On this day,my family decorates a beautiful tree with lights and ornaments.We exchange gifts and enjoy a big feast with delicious food like turkey and pie.I love Christmas because it brings everyone together,and the atmosphere is filled with joy and happiness.Analysis:1.Introduction:The paragraph starts with a clear statement about the favorite holiday,“My favorite holiday is Christmas.”2.Date of Celebration:It provides the specific date when the holiday is celebrated,“which is celebrated on December 25th.”3.Activities:It describes the activities done on that day,such as decorating the tree,exchanging gifts,and enjoying a feast.4.Reason for Enjoyment:It explains why the holiday is enjoyable, highlighting the togetherness and joyful atmosphere.5.Word Count:The paragraph meets the word count requirement,being concise yet informative.This structure ensures that all the key elements of the prompt are addressed, making the response coherent and well-organized.。

【2019年整理】matlab学习-求最小值

【2019年整理】matlab学习-求最小值

[转]matlab学习-求最小值2007-08-25 21:391.有约束的一元函数的最小值单变量函数求最小值的标准形式为min f(x) sub.to x1<x<x2在MA TLAB5.x中使用fmin函数求其最小值。

函数fminbnd格式x = fminbnd(fun,x1,x2) %返回自变量x在区间上函数fun取最小值时x值,fun 为目标函数的表达式字符串或MATLAB自定义函数的函数柄。

x = fminbnd(fun,x1,x2,options) % options为指定优化参数选项[x,fval] = fminbnd(…) % f val为目标函数的最小值[x,fval,exitflag] = fminbnd(…) %xitflag为终止迭代的条件[x,fval,exitflag,output] = fminbnd(…) % output为优化信息说明若参数exitflag>0,表示函数收敛于x,若exitflag=0,表示超过函数估计值或迭代的最大数字,exitflag<0表示函数不收敛于x;若参数output=iterations表示迭代次数,output=funccount表示函数赋值次数,output=algorithm表示所使用的算法。

例5-3 在[0,5]上求下面函数的最小值f(x)=(x-3)^2-1解:先自定义函数:在MATLAB编辑器中建立M文件为:function f = myfun(x)f = (x-3).^2- 1;保存为myfun.m,然后在命令窗口键入命令:>> x=fminbnd(@myfun,0,5)则结果显示为:x =32.无约束多元函数最小值多元函数最小值的标准形式为min f(x)其中:x为向量,如在MA TLAB5.x中使用fmins求其最小值。

命令利用函数fminsearch求无约束多元函数最小值函数fminsearch格式x = fminsearch(fun,x0) %x0为初始点,fun为目标函数的表达式字符串或MATLAB 自定义函数的函数柄。

hessian函数

hessian函数

hessian函数Hessian函数是一个具有连续的二阶偏导数的多元实函数f(x1,x2,…,xn),它是由德国数学家Hessian所发明的,因此得名。

Hessian函数在数理统计学和机器学习领域中经常被使用,因为它是用来求解目标函数的二阶信息的一种方法,包括计算梯度和海森矩阵以及确定局部极小值和鞍点。

一般而言,二阶梯度算子是被定义在一个函数f(x,y)上的一个算子,它包含函数的二阶偏导数。

由于Hessian函数是对实函数进行二阶梯度的一个推广,因此,它是由一个方阵组成的,其中每个元素都是函数的二阶偏导数。

Hessian函数的定义如下:(adsbygoogle = window.adsbygoogle || []).push({});H(f)(x) =\begin{pmatrix}\frac{\partial ^2 f}{\partial x_1^2} & \frac{\partial ^2 f}{ \partial x_1 \partial x_2} & \cdots & \frac{\partial ^2 f}{\partial x_1 \partial x_n}\\\vdots & \vdots & \ddots & \vdots \\通常,人们用H(f)(x)表示函数f(x)在点x的海森矩阵。

Hessian函数可以用来定义一个向量的牛顿方向,该向量是与点x的梯度相反的方向,其大小可以通过f(x)的海森矩阵H(f)(x)来确定。

因此,在点x处的牛顿方向可以表示为:d_N(x)=-H(f)(x)^{-1} \nabla f(x)在这个方程中,d_N(x)是函数f(x)在点x处的牛顿方向,\nabla f(x)是函数在这一点处的梯度,而H(f)(x)^{-1}是函数在该点的海森矩阵的逆矩阵。

在机器学习领域中,计算Hessian函数的目标是确定一个函数的局部最小值和鞍点。

八年级英语议论文论证方法单选题40题

八年级英语议论文论证方法单选题40题

八年级英语议论文论证方法单选题40题1. In the essay, the author mentions a story about a famous scientist to support his idea. This is an example of _____.A.analogyB.exampleparisonD.metaphor答案:B。

本题主要考查论证方法的辨析。

选项A“analogy”是类比;选项B“example”是举例;选项C“comparison”是比较;选项D“metaphor”是隐喻。

文中提到一个关于著名科学家的故事来支持观点,这是举例论证。

2. The writer uses the experience of his own life to prove his point. This kind of method is called _____.A.personal storyB.example givingC.case studyD.reference答案:B。

选项A“personal story”个人故事范围较窄;选项B“example giving”举例;选项C“case study”案例分析;选项D“reference”参考。

作者用自己的生活经历来证明观点,这是举例论证。

3. The author cites several historical events to strengthen his argument. What is this method?A.citing factsB.giving examplesC.making comparisonsing analogies答案:B。

选项A“citing facts”引用事实,历史事件可以作为例子,所以是举例论证;选项B“giving examples”举例;选项C“making comparisons”比较;选项D“using analogies”使用类比。

h因子 约翰·赫希提出的一种评价学术成就的方法

h因子 约翰·赫希提出的一种评价学术成就的方法

h因子约翰·赫希提出的一种评价学术成就的方法H因子是由美国科学家约翰赫希(JohnE.Hirsch)于2005年首次提出的一种衡量一个研究人员学术成就的度量标准,也被称为Hirsch指数(h-index)。

H因子是一种基于文章引用次数的指标,可以用来衡量一个学者的学术影响力,被认为是最能衡量科学家学术影响力的指标。

H因子的理论基础H因子基于一个简单的理论:科学家的学术贡献应当与其文章所获得的引用次数成正比。

H因子衡量了科学家在其学术领域里累积的发表文章的影响力和成就,通过统计每位研究者论文被引用的次数,以评价学者的研究成果。

H因子的计算方法H因子衡量学者的文章引用次数,计算方法如下:1.索某位研究者的所有发表的文章,并统计它们的总引用次数;2.照文章的引用次数,从高到低排列所有文章;3.排序后的文章列表中,选取文章的编号,此编号即为研究者的H因子;4. 例如,如果一位研究者发表了20篇文章,其中有10篇文章引用次数超过10次,而其他文章引用次数少于10次,那么该研究者的H因子为10。

H因子的重要性H因子作为一种评价学者学术影响力的方法,迅速被任何人喜欢和接受。

它不仅能反映学者一段时间内的研究成果,还能反映出学者长期以来的学术积累和工作情况。

它比其他指标更能体现学术贡献的真实情况。

H因子的优缺点H因子的准确性备受质疑,它也有很多缺点,其中最严重的一个缺点是,它只能反映一个学者在过去发表的文章的影响力,而不能反映未来发表的文章可能有多大的影响力。

另外,H因子不能反映一篇文章在学术界的不同领域的影响力,也忽略了一些具有重要意义的文章,它只考虑文章的引用次数,而忽略文章质量的影响。

结论H因子是一种衡量学者学术影响力的常用指标,它可以有效反映学者积累的学术成果,但也有一些缺点,不能完全反映学者的学术影响力。

因此,在评估学者学术成就时,应多结合其他指标,更加客观准确地评估学者学术成就。

Hessian正则化Logistic回归模型

Hessian正则化Logistic回归模型

1 引 言 随着数码相机 、电脑硬件 、互联 网以及机器学习等技
术的不断发展 ,百万甚至千万 的图像 的获取及处理成 为 可能 ,进而大数 据量的图像分类研 究受 到广泛关注 。然 而大数据量 的图像标 注需要耗费 大量 的人力物力财 力 , 而 半 监 督 学 习 (Semi.Supervised Learning,SSL)f l ̄够 在 少量标 记样本 情况 下 同时利用大 量未标 记样本 来构造 有效 的学习模型 ,进而提升分类性能 ,因而成为图像分 类 中的研究热点。 目前常用的半监督 学习方法大多基于流 形假 设 ,例 如 SamT.Roweis在文 [2]提 出的 局部 线性 嵌
中国石 油大学 信息与控制工程学院 ,山东 青岛 266580 College of Information and Control Engineering,China University of Petroleum ,Qingdao,Shangdong 266580,China
LIU Hongli,LIU W eifeng,WANG Yanjiang,et a1.Hessian regularized Logistic regression·Computer Engineering and Applications,2016,52(5):236-240.
Abstract:The Sem i Supervised Learning(SSL)method of Laplacian regularization opens a bright avenue by studying the classif ication problem of a large number of im ages.However,Laplacian m ethod biases the classification function toward a constant function and possibly results in poor generalization.So the Hessian regularized Logistic Regression(HesLR) m ethod for im age classification is proposed.Hessian regularization can well predict the data points beyond the boundary of the dom ain.Extensive experim ents on the M IR Flickr dataset validate the effectiveness of the proposed m ethod by com paring it w ith baseline algorithm s,including SVM ,the Logistic regression m ethod and the Laplacian regularized Logistic

德语概况

德语概况

德语概况德语使用分布图。

德语(Deutsch)是德国、奥地利的官方语言,也是瑞士的4种官方语言之一(官方语还包括其他三种语言:法语、意大利语和罗曼什语)。

它属于印欧语系下日耳曼语族下的西日耳曼语。

德语共同标准语的形成可以追溯到德意志时代马丁·路德(Martin Luther)的圣经翻译。

把德语当作母语的有1亿多人(总计约为1.1亿)。

此外,中国的上海、北京、天津、俄罗斯和罗马尼亚等国的德国移民区以及美国的宾夕法尼亚州等地也有少数人使用德语。

发音: [d???t?]使用国家及地区德国、奥地利、瑞士、列支敦士登和其他37个国家区域西欧使用人数 1.25亿(9.5千万为母语,3千万为第二语言)排名: 11语系印欧语系日尔曼语族西日尔曼语支高地德语德语作为官方语言德国、奥地利、瑞士、比利时、列支敦士登、卢森堡、欧盟;作为地方性官方语言的:丹麦、意大利、波兰、法国。

(在1990年前的纳米比亚是官方语言)德语字母德语翻译|德文翻译|德语翻译公司|德语口译Aa(Ää)BbCcDdEeFfGgHhIiJjKkLlMmNnOo(Öö)PpQqRrSs(ß)TtUu(Üü)VvWwXxYyZz其中 Aa、Ee、Ii、Oo、Uu 以及三个变体字母 Ää、Öö、Üü为元音字母。

其他为辅音字母。

德语分类德语德语分为高地德语(Hochdeutsch)和低地德语(Plattdeutsch)。

高地德语是共同语,它采用了低地德语的某些发音规则,低地德语听上去更象英语和荷兰语。

通用的书面语以高地德语为准。

各方言之间的差异很大。

高地德语和低地德语的语言分界线大致从德国西北部的亚琛起,向东经过莱茵河畔的本拉特、卡塞尔、马格德堡直到奥得河畔的浮斯腾堡,这条线以南是高地德语,以北是低地德语。

高地德语(Hochdeutsch)是西日耳曼语(Westgermanisch),主要通用于德国(Deutschland)、奥地利(Oesterreich)、列支敦士登(Lichtenstein)、瑞士(Schweiz)和卢森堡(Luxemburg),也用于一些临近的地区,是现代德语的主体。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

Res. Lett. Inf. Math. Sci., 2005, Vol. 8, pp 189-196 189Available online at /research/letters/Hessian sufficiency for bordered HessianE RIC I KSOON I MDepartment of Economics, College of Business and Economics,University of Hawaii at Hilo, USAeim@We show that the second–order condition for strict local extrema in both constrained andunconstrained optimization problems can be expressed solely in terms of principal minorsof the (Lagrengean) Hessian. This approach unifies the determinantal tests in the sense thatthe second-order condition can be always given solely in terms of Hessian matrix.1 IntroductionIn the theory of constrained optimization, we use the bordered Hessian determinantalcriterion to test whether an objective function has an extremun at a critical point.However, the required signs of the minors in the case of the constrained optimizationare quite different from those in the case without constraints, which is somewhatconfusing. In this paper, we show that when the constraints are twice differentiable wedo not need the bordered Hessian at all for determinantal test. We only need the(Lagrangian) Hessian matrix for the determinantal test for both unconstrained andconstrained optimization problems. This saves the unnecessary switching from theHessian matrix to the bordered Hessian matrix for determinantal test for the second-order sufficient condition when the optimization problem is subject to constraints..2 DiscussionTo set the stage, first we formally state the standard constrained optimization problemand the second-order sufficient condition, then address the issue of unified signrequirements for the second-order condition for optimization.Let :S φ→\ be a real-valued function defined on a set S in , anda vector function defined on S . Let c be an interior point of S andlet be a point in . Define the Lagrangian function n \:(m g S m n →<\)A m \:S ψ→\ by the equation)()()(x g x x A ′−=φψ, (1)190 E.I. Im where )(x φ and both are twice differentiable at c , the )(x g n m × Jacobian matrixhas a full row rank m . Then, the sufficient first- and second-order conditions for)(c Dg )(x φ to have a strict local minimum (maximum) at c are respectively (Magnus andNeudecker, pp.135-318 for example):0)();(==dx c Dg dx c d ψ and for all , (2)0)(=c g n dx ℜ∈0)();(2>′=dx c H x d dx c d ψψ for all 0≠dx satisfying 0);(=dx c dg . (3)where , and D and H are respective notations for Jacobian andHessian operators.∑=−≡mm i i i c Hg H H )(λφψThe components of the second-order condition in (3) can be consolidated into one asfollows. Partitioning dx and conformably as )(c Dg B n m ≡×)(′′′=−m n m x d x d dx # and, we can rewrite )()(,m n m m B B c g D −=#0)(=c dg in the second order condition:0)(),(,=+==−−m n m n m m m dx B dx B dx c Dg dx c dgfrom which .(4) m n m n m m m dx B B dx −−−−=,1Incorporating (4) into (3), two components of the second-order condition are nowconsolidated into one:)0(0),(2<>′′=−−m n m n dx Q H Q x d dx c d ψψ for 0≠dxwhere , or, equivalently )(1,′′−=−−−m n m m n mI B B Q #)0(0)()(<>′≡ΩQ c H Q c ψ. (5)The strict inequality holds if and only if the signs of the principal minors ofadhere to:)(c Ω0>Ωk for strict local minima;0)1(>Ω−k k for strict maxima ( k = m+1, m +2, …, n -m ) (6)where ; in which kk k E c E ′Ω=Ω)(())(0k n k k k I E −×=# and k k E Q Q ′=.In practice, however, we test for the sign definiteness of the second-order condition,using the determinantal criterion based on the bordered Hessian matrix:0)()1(>−c H r m ψ for strict local minima;0)()1(>−c H r r ψ for strict local maxima, ),...,1(n m r += (7)where: ()⎥⎦⎤⎢⎣⎡′=×××r r m r m m m r c H B B c H )(0)(ψψ (8)Hessian sufficiency for bordered Hessian191defines the principal submatrices of bordered Hessian of order r m +of the borderedHessian matrix of order :n m +⎥⎦⎤⎢⎣⎡′=×××)(0)(c H B B c H n m n m m m ψψ (9) in which denotes the first r columns of r m B ×)(c g D B n m ≡×However, the sufficient second-order condition for a strict local optimum can bestated purely in terms of principal minors of )(c H ψ instead of those of the borderedHessian as discussed in the following section.3 Hessian Sufficiency for Bordered HessianIn the Hessian alternative to the bordered-Hessian, it is essential to note that there is arank condition implicit in the first-order condition, which is not needed in the borderedHessian approach. To make the point, re-express the first part of first-order condition in(2) in variable form for further differentiation:. for all n m n m dx −−∈\0)();(==dx x D dx x d ψψDifferential of this first-order condition at c x =, with (4) incorporated, can be writtenas:dx c H x d dx c d )(),(2ψψ′=0)(=Ω′=−−m n m ndx c x d for all (10)m n m n dx −−ℜ∈†Though Equation (10) contains the Hessian matrix, it is not the second-order condition.It is in essence the first-order condition in quadratic form which facilitates identifying auseful property of Q c H Q )(ψ′ associated with a strict local critical point.Suppose that . Then, 0n m dx −≠0)(=Ω−m n dx c for all (11)0≠−m n dxSince 0≠−m n dx , Ω must be singular, hence )(c Ω=Ω (therefore c ) depends onwhich violates the assumption that c is a strict local critical point. Therefore, shouldbe nonsingular, which in turn implies m n dx −Ω0=−m n dx . Hence, a lemma can be stated withoutproof:LEMMA : Let c be a strict local critical point for the optimization problem (1). Then,Q c H Q c )()(ψ′≡Ωis nonsingular.H † Note that if is linear, )(x g ψ does not depend on x , therefore c . This is exactly the reason whyis assumed to be twice differentiable. However, a linear constraint is technically twicedifferentiable when squared. Hence, our approach applies to both linear and nonlinear constraints.)(x g192 E.I. Im Having established formally that is nonsingular if c is a strict local critical point,we are now ready to restate the second-order sufficient condition in (5) solely in term ofthe (Lagrangian) Hessian instead of bordered Hessian as follows.)(c ΩTHEOREM (General Sufficient Condition): If )(c H ψ is nonnegative definite(nonpositive definite) where c is a strict critical point x , )(c ψ is a strict minimum(maximum), and m n c H Rank −≥))((ψProof : Since is a strict critical point, c Q c H Q c )()(ψ′=Ω is nonsingular (thereforeof full rank) in view of the Lemma. If )(c H ψ is nonnegative definite, it has a full-rankfactorization: T T c H ′=)(ψ where T is of full column rank. Hence, we can rewritewhich is nonnegative definite. Since )()()(Q T Q T c ′′′=Ω)(c Ω is both non-singular andnonnegative definite, which implies that 0)(>Ωc )(c ψ is a strict local maximum. Theproof for a strict local maximum is similar. The second part of the theorem can beproved as follows. implies 0)(>Ωc m n c H Rank −≥))((ψ: Since, m n c Rank −=Ω))((m n Q T Rank −=′)(. However, since byassumption, m n Q Rank −=)(m n T Rank −≥)( from which follows m n c H Rank −≥))((ψ. )QEDCOROLLARY (Special Sufficient Condition): If )(c H ψ is positive definite(negative definite) where c is a strict local critical point, )(c ψis a strict minimum(maximum), and n c (H Rank =))(ψ.‡Proof : Since positive definiteness (negative definiteness) is a special case ofnonnegativity (nonpositivity), the corollary follows from the theorem as a trivial case.Since definite matrices are of full rank, n c H Rank =))((ψ. QED4 An ExampleSolve the problem (Magnus & Neudecker, pp. 138-139)22),()()(w v x Min Max w v x +==φsubject to .322=++w vw vThen, the Lagrangian function will be: ,)3()(2222−++−+=w vw v w v x A ψ ‡The special sufficient condition has been known and noted in a number of places (e.g., Hal R. Varian(p. 498)), but not the general sufficient condition.Hessian sufficiency for bordered Hessian193and the first-order conditions are:3;022;02222=++=−−=−−w vw v w v w w v v A A A A .Solving the first-order conditions for control variable vector ),(w v x =, we have threestrict local stationary points: 321,,c c c x = are defined respectively as)1,1(),(111−−==w v c , )3,3(),(222−==w v c , and )3,3(),(333−==w v c .The corresponding Lagrangian multipliers are, respectively, 3/21=A , , and. The (Lagrangian) Hessian and bordered Hessian are, respectively:22=A 23=A.222222220)(;2222)(⎥⎥⎥⎦⎤⎢⎢⎢⎣⎡−−+−−+++=⎥⎦⎤⎢⎣⎡−−−−=λλλλψλλλλψw v w v w v w v x H x H Now, we check the sign behavior of all minors, not just the leading minors, of )(x H ψat each of the three critical points to see whether we have a local minimum or maximumor neither in view of the Lemma.Minors of )(1c H ψ for the first stationary point are: 0~;03/2)3/2(22~21=>=−=M M .)(1c H ψ is positive semi-definite of rank 1, hence, in view of the Theorem, the firstcritical point is a strict local minimum.Corresponding principal minors of )(2c H ψ and )(3c H ψ are identical:0~;02~21=<−=M M .Both )(2c H ψ and )(3c H ψ are negative semi-definite of rank 1, thus in light of theTheorem )(x φ has two strict local maxima.(The same conclusion is arrived for each critical point by way of the bordereddeterminantal criterion in Magnus and Neudecker).5 Linear Constraints as Twice DifferentiablesTypical linear constraints can be transformed into twice differentiables by squaring thelinear constraints. Therefore, the Hessian alternative to bordered Hessian applies to all194 E.I. Im constraints in general. This can be illustrated by a simple example in Chiang andWainwright (Example 2, p. 360):Find the extremum ofvw z = subject to 6=+w v . (I)The Hessian and bordered Hessian matrices are respectively:.011101110)(;0110)(⎥⎥⎥⎦⎤⎢⎢⎢⎣⎡=⎥⎦⎤⎢⎣⎡=x H x H ψψThe determinant of bordered Hessian is positive: 02)(>=x H ψ which meets the signrequirement for a strict local maximum, whereas the leading principal minors of Hessian are: 01)(2;0)(1<−==x H x H ψψ which do not meet the sign requirements for a local maximum. Clearly, the Hessian approach fails to identify the localmaximum. The reason is that theorem is applicable only when the constraint is twicedifferentiable.This problem can reformulated using the squared constraint asvw z = subject to or . (II)226)(=+w v 36222=++w vw vThen, the Lagrangian function for (II) will be: , andthe first-order conditions are:)362()(22−++−=w vw v vw x A ψ362;022;02222=++=−−=−−w vw v w v v w v w A A A A .The Lagrangian Hessian then will be:.221)(2212)(2)(2)(20)(;221212)(⎥⎥⎥⎦⎤⎢⎢⎢⎣⎡−−+−−−+−+−+−=⎥⎦⎤⎢⎣⎡−−−−=A A A A A A A A w v w v w v w v x H x H ψψSolving the first-order conditions for control vector ),(w v x =, we have two strict localcritical points:)3,3(),(1==w v c and )3,3(),(2−−==w v c and 4/1=A for both critical points.Hessian sufficiency for bordered Hessian195However, since does not satisfy the original constraint, it will be out ofconsideration. At 2c )3,3(),(1==w v c ,⎥⎦⎤⎢⎣⎡−−=⎥⎦⎤⎢⎣⎡−−−−=2/12/12/12/1221212)(1A A A A c H ψ for which: 0~;02/1~21=<−=M M)(c H ψ is negative semi-definite of rank 1, hence, in view of the Theorem, the firstcritical point is a strict local maximum, which is exactly the same results as would beproduced if we used the bordered Hessian determinantal rule to Problem (II).The Hessian Approach to Problem I breaks down for the simple reason that theconstraint is not twice differentiable as required by the Theorem, but it works forProblem II since the constraint are converted into a twice differentiable.6 ConclusionIn this paper, we have shown that the conventional second-order sufficient condition forconstrained optimization in terms of minors of bordered Hessian can be recastalternatively in terms of minors of Hessian matrix, making it possible to represent thesecond-order condition in general all in terms of minors of the Hessian matrix. Thistheoretical result dispels the misconception that borders in the bordered Hessian matrixhave some bearings on the second-order condition. Furthermore, the second-ordercondition based on Hessian matrix is more convenient in practice than the borderedHessian since finding minors of Hessian is less cumbersome than those of borderedHessian. Practitioners of the determinantal tests in optimization theory find it a bitconfusing to use the minors of Hessian for constrained optimization problems butminors of bordered Hessian for unconstrained problems. Finally, the theorem seeminglyapplicable only to the optimization problems with twice differentiable constraintsindeed applies to problems with linear constraints, therefore applicable in general.APPENDIXAs shown in Magnus and Neudecker ( p.55),k k m r m T x H Ω−=−2)1()()1(ψ )...,,2,1;(m n k k m r −=+= (A1)where (nonsingular) is defined as: . (A2) k T ⎟⎟⎠⎞⎜⎜⎝⎛=×××k mk k m m m k I B B T 0196 E.I. Im From (A1) for readily follows: m n k −=m n m n n m T x H −−Ω=−2)()1(ψ. (A.3)It is clear from (A.3) that 0≠Ωif and only if 0)(≠x H ψ, or equivalently Ω is nonsingular if and only if )(x H ψ is nonsingular. Note that )(x H H n ψψ= andwhich is obvious from the context.m n −Ω=ΩReferencesChiang A. and K. Wainwright (2005). Fundamental Methods of MathematicalEconmics . Fourth Edition. McGraw-Hill, New York.Magnus, J. R. and H. Neudecker (1998). Matrix Differential Calculus withApplications in Statistics and Econometrics . Revised Edition. Wiley, New York.Varian, H. R. (2001). Microeconomic Analysis . Norton & Company, New York.。

相关文档
最新文档