Ch3-2-Data Link
计算机网络CH3 数据链路层.ppt

R3 网络层 链路层 物理层
H2
应用层 运输层 网络层 链路层 物理层
课件制作人:谢希仁
3.1 使用点对点信道的数据Байду номын сангаас路层
3.1.1 数据链路和帧
链路(link)是一条无源的点到点的物理线 路段,中间没有任何其他的交换结点。
一条链路只是一条通路的一个组成部分。
数据链路(data link) 除了物理线路外,还必须 有通信协议来控制这些数据的传输。若把实现 这些协议的硬件和软件加到链路上,就构成了 数据链路。
计算机网络(第 5 版)
第 3 章 数据链路层
课件制作人:谢希仁
第 3 章 数据链路层
3.1 使用点对点信道的数据链路层 3.1.1 数据链路和帧 3.1.2 三个基本问题
3.2 点对点协议 PPP 3.2.1 PPP 协议的特点 3.2.2 PPP 协议的帧格式 3.2.3 PPP 协议的工作状态
误码率与信噪比有很大的关系。如果提高信噪 比,就可以使误码率减小。
为了保证数据传输的可靠性,在计算机网络传 输数据时,必须采用各种差错检测措施。
课件制作人:谢希仁
循环冗余检验的原理
在数据链路层传送的帧中,广泛使用了循环冗余 检验 CRC (Cyclic Redundancy Check)的检错技 术。
3.5 扩展的以太网 3.5.1 在物理层扩展以太网 3.5.2 在数据链路层扩展以太网
3.6 高速以太网 3.6.1 100BASE-T 以太网 3.6.2 吉比特以太网 3.6.3 10 吉比特以太网 3.6.4 使用高速以太网进行宽带接入
3.7 其他类型的高速局域网接口
课件制作人:谢希仁
第一次课
课件制作人:谢希仁
DATALINK RS232C RS530转换器RSCV-S 说明书

RS232C/RS530转换器RSCV-S用户手册大连菱科数据通信技术有限公司目录第一章前言 (1)1-1概要 (1)1-2特征 (1)1-3何谓RS530 (1)1-4 连接构成图 (2)1-5 用户登记 (3)1-6 商品包装 (3)第二章物理说明 (4)2-1 说明 (4)2-2 内部构成图 (5)2-3 外观图 (6)2-4 直流电源外观图 (7)第三章运行说明 (8)3-1 RS232C连接器 (8)3-2 RS530接口 (9)3-3 RS530侧的控制信号线 (10)3-4 [RSCV-S]相互连接 (12)售后服务 (13)第一章前言1-1 概要非常感谢您购买[RSCV-S]。
[RSCV-S] 是日本DATA-LINK公司研制的RS232C 和RS530 信号转换器,连接不同规格的通信的连接器形状的接口。
第一章叙述的是特征,使用环境部分;第二章叙述的是尺寸、构成、消耗电流等物理说明;第三章叙述的是连接,使用等运行说明。
1-2 特征l实现RS232C到RS422信号电平的转换;l最大通信速率:115200bps;l使用2个[RSCV-S],可以把RS232C机器间的最大通信距离延长至1200米;l RS232C侧的接口为Dsub25针式插座(DCE)。
可直接连接到个人电脑、工作站、终端机器等RS232C 端口(DTE)来使用;l变换RS232C 侧数据线的TXD/RXD,控制信号线的RTS/CTS,DTR/DSR 共计6线;l RS530 侧的连接器接口是Dsub25 管脚插孔;l[RSCV-S]的供电方法为,:①可选的直流电源(形式:AD-150T)②通过RS232C 端口的9 管脚供电。
1-3 何谓RS530RS530是定义数据终端装置(DTE)和数据回路终端装置(DCE)之间的机械接口特性的25管脚连接器规格,是EIA在1987年3月研发的。
其特性与RS422相同。
也就是说,RS530是把RS422的特性规格化到Dsub25管脚的。
(题)数据结构复习题

(题)数据结构复习题Ch3链表一、选择题(共18题,11道算法设计题)1、设单链表中结点的结构为(data, link)。
已知指针q所指结点是指针p所指结点的直接前驱,若在*q与*p之间插入结点*s,则应执行下列哪一个操作?(1) s->link = p->link; p->link = s;(3) p->link = s->link; s->link = p;Key:(2)2、设单链表中结点的结构为(data, link)。
已知指针p所指结点不是尾结点,若在*p之后插入结点*s,则应执行下列哪一个操作?(1) s->link = p;p->link = s;(2) s->link = p->link;p->link = s;(4) p->link = s;s->link = p;(2) q->link = s; s->link = p;(4) p->link = s; s->link = q;(3) s->link = p->link; p = s;Key:(2)3、设单链表中结点的结构为(data, link)。
若想摘除结点*p的直接后继,则应执行下列哪一个操作?(2) p = p->link; p->link = p->link->link;(4) p = p->link->link;(1) p->link = p->link->link;(3) p->link = p->link;Key:(1)4、设单循环链表中结点的结构为(data, link),且rear是指向非空的带表头结点的单循环链表的尾结点的指针。
若想删除链表第一个结点,则应执行下列哪一个操作?(1) s = rear; rear = rear->link; free(s);(2) rear = rear->link;free(rear);(3) rear = rear->link->link; free(rear);(4) s = rear->link->link; rear->link->link = s->link; free(s);1Key:(4)5、设双向循环链表中结点的结构为(data, prior, next),且不带表头结点。
Datalink V2 固件升级指南(CAN)说明书

Datalink Firmware Upgrade Guide(CAN)Tools:Datalink V2 Type-C CableTIPS:1. Please power Datalink by USB port only.2. The ESC requires power supply in the upgrade process. The details will show below.3. It supports upgrading only one ESC at the same time, using the ''-CH1 CL1 +'' port.4. The yellow cable is GND, the middle one cable is CH, and the green cable is CL. No need to connect the positive pole cable. If the colors of your ESC's cables are different with this, please check the cable definition on the user manual.5. Whether the black and white cable is plugged in or not will not affect the upgrade.6. If the LED light flashes red, it is abnormal. Please try to upgrade the firmware of Datalink, or contact our after-sales service.Software:Tips:Select ''CAN->ESC(FAST) '' mode, click OK, and then click ''Communication Settings''.Tips:After scanning, power on your ESC. Then click Stop, the ESC informations will be displayed on the screen. That means the communication succeeded.Tips:Click out the drop-down list at ''Available version'', select the firmware version that you want and click ''Update''Tips:Waiting for the upgrade complete.Tips:After the upgrade is completed, repeat the steps as page 8 to check whether the upgrade is successful or not. If upgrade failed by powering off by accident during upgrading or other cases, please try all upgrade steps again.。
半导体FAB常用单词

半导体FAB常用单词◎ A开头的单字◎1. Abort 取消操作2. Abnormal 异常3. Acetic Acid(CH3COOH)醋酸4. Acetone(CH3COCH3)丙酮5. Acid 酸6. Add 增加7. Adjust 调整8. Air Shower 洁净走道9. Alignment 对准10. Alloy 合金11. Aluminum(Al)铝12. Ammonia(NH4OH)氢氧化胺(俗称:氨水)13. Analysis 分析 m~H14. AR 氩气15. Automation 自动化◎ B开头的单字◎1. Bake 烘烤2. Bank 暂存3. Barcode 条形码4. Batch 整批5. BHLD 被工程师或客户Bank Hold短时间内不会Run的货6. Blue Tape 蓝膜7. Boat 石英晶舟8. Bottom 底部9. Breakdown Voltage 击穿电压10. Broken 破片;损坏11. Buffer 生产暂存区12. Buffer Chemical 缓冲液◎ C开头的单字◎1. Calibration 校正;调整2. Camera 照相机;摄影机3. Cancel 清除4. Candela(cd)烛光5. Cart 手推车6. Cassette 晶舟7. Certify 技能认证8. Chamber 反应室9. Charge 电荷10. Chipping 崩裂11. Chip Suction Pen 真空吸笔12. Chip Transfer - m(Machine) 翻转机13. Clean Bench 清洗台14. Clean Room 洁净室15. Cleaning 清洗 IF16. Cleaning Sequence 清洗程序17. Clear 清除18. Coat 涂布19. Coater 上光阻机台20. Coating 上光阻;涂布上整个表面21. Completed 结束;完成22. Confirm 确认23. Contact 接触24. Contamination 污染25. Control Wafer(C/W)控片26. Controller 控制器27. Cooling Water 冷却水28. Crucible,Pot 坩埚29. Curing 烘烤30. Customer 客户31. CVD(Chemical Vapor Deposition) 化学汽相沉积32. Cycle Time 生产周期◎ D开头的单字◎1. Daily Monitor 每日检测2. Data 资料;数据3. Date 日期4. Defect 缺点;缺陷5. Defocus 散焦;无法聚焦6. Del(Delete) 清除;删除7. Delay 延迟8. Department 部门9. Deposition(DEP)沉积10. Develop 显影11. Developer 显影器;显影液12. Die,Chip 晶粒(台);芯片(陆)13. DI Water 去离子水14. Dicing 切割15. Down 当机16. Drain 泄出17. Dry Etching 干蚀刻18. Dry Pump 干式(无油封)的真空泵19. Dummy Wafer(D/W)挡片◎ E开头的单字◎1. E/R(Etching Rate) 蚀刻率2. Emergency Stop 紧急停止3. EMO 紧急停止按钮4. Endpoint 终点值5. Engineer 工程师6. Epi –wafer 磊晶片(台);外延片(陆)7. Equipment 机台;设备8. Error Message 错误讯息9. Etching 蚀刻10. Evaporation 蒸镀11. Exhaust 抽出;抽风管;排(废)气12. Expanding Machine 扩张机13. Exposure 曝光;曝光量◎ F开头的单字◎1. FAC 厂务2. Facility 厂务水电气系统3. Film 薄膜4. Focus 聚焦;焦距5. Forward Current 顺向电流6. Forward Voltage(Vf)顺向电压7. FQC 最终检验员8. Furnace 炉管◎ G开头的单字◎1. Gallium(Ga)镓2. GOR(General Operation Rule) 厂区操作规则3. Group 群组◎ H开头的单字◎1. Handle 处理2. High Current 高电流3. Highlight 强调4. High Vacuum 高真空5. High Voltage 高电压6. History 歴史7. HMDS 界面活性剂8. Hold 扣留;暂停9. Hold Date 留置日期10. Hold Reason 留置原因11. Hold User 留置者12. Hot Run 很急件13. Hydrochloric Acid(HCL)盐酸14. Hydrofluoric Acid(HF)氢氟酸15. Hydrogen Peroxide(H2O2)双氧水◎ I开头的单字◎1. Idle 休息2. Initial 初始状态3. Inspection 检验4. IPA(Isopropyl Acetone) 异丙醇5. IPQC 制程检验员6. IQC 进料检验员7. Item 项目8. Iv Test Iv测试◎ J开头的单字◎1. Job 工作2. Job – Name 程序名称代号◎ K开头的单字◎1. Key Lock 功能键;指令键2. Keyboard 键盘◎ L开头的单字◎1. Leak 泄漏2. LHLD 被Hold住的货(Hold在上一站)3. Light Emitting Diode(LED)发光二极体4. Link 连结;线5. Lithography 微影6. Log 记录7. Lost 机台是清空的,无人操作机台或机台没在Run货8. Lot 批货9. Lot History Information 批货历史资料10. Lot -ID 批货编号11. Lot Information 批货信息12. Lot Note 批货批注13. Lot Note Information 批货批注信息14. Lot Owner 货主15. Lot Position 批货位置16. Lot Process Status 批货生产状态17. Lot Status 批货状态18. LPHL 被工程师Hold在当站,请依Lot Note Call工程师或执行Run Card19. Luminous Intensity(Iv)光的强度(单位:cd,mcd)◎ M开头的单字◎1. Maintain 维护2. Maintenance 维修;保护3. Manufacture 制造4. Mark 记号5. Mask 光罩6. Merge 合并7. Metal 金属8. Microscope 显微镜;实体显微镜9. Misalign 对偏10. Missing Lot 失踪批货11. Miss operation(MO)错误操作12. Multi 多重的◎ N开头的单字◎1. Native Oxide Layer 自然氧化层2. NHLD 因下一站机台正在Run货或无法Run货而设的Hold(Hold在下一站)3. Nitric Acid(NHO3)硝酸4. Nitride 氮化物5. Nitrogen(N)氮6. Normal Lot 普通货7. Notavailable 不可用的;无效的8. Notch 缺角9. Nozzle 喷嘴◎ O开头的单字◎1. OCAP (Out Of Control Action 异常状况处理计划Plan)2. Off-line 不与计算机联机;间接参与生产的人员3. OI(Operation Instruction) 操作准则4. On-line 与计算机联机;直接参与生产的人员5. Operation 操作6. Operation Cancel 操作中止;取消操作7. Operation Complete 操作完成8. Operation Number(OP.NO.)操作步骤编号9. Operation Procedure 操作流程10. Operation Start 操作开始11. Operation Start Cancel 取消"操作开始"12. OPI(Operator Interface) 操作接口13. Optical Aligner 光对准曝光机14. OQC 出货检验员15. Out Of Control(OOC)超出控制规格16. Out Of Spec(OOS)超出规格17. Outgassing 指附着于固体表面的气体因压力降低或热量而升华18. Oven 烤箱;炉子19. Over Etching 过度蚀刻20. Over Q-Time 超过限制时间21. Owner 负责人22. Oxide 氧化物◎ P开头的单字◎1. Parameter 参数2. Part Number 型号3. Particle 微粒子4. Passivation 护层5. Password 密码6. Pattern 图案7. Pattern Shift 图案偏移8. Peeling 剥皮;剥离9. Phosphorus(P)磷10. Phosphorus Acid(H3PO4)磷酸11. Photo 黄光12. Photolithographic Patterning 微影图案13. Photo Resist(PR)光阻;光阻液14. Photo Resist Stripper 去光阻液15. Physical Vapor Deposition(PVD) 物理汽相沉积16. Piece 片数;张数17. Plasma 电浆18. PM(Preventive Maintenance) 机台定期例行保养19. PN(Production Notice) 制造通报20. PN Junction PN结21. Post Exposure Bake 曝光后烘烤22. POD 晶片专用盒(Run货専用)23. Port 港口;舱门24. Press 压;按下25. Pressure 压力26. Priority 优先次序27. Probe 探针28. Probe Area 探索区29. Probe Card 探针卡30. Process 制程31. Product 产品32. Program 程序33. Pump Down 抽真空34. Pure Water 纯水35. Purge 清除36. Push 推动◎ Q开头的单字◎1. Q-Time 限制的时数2. Quality 品质3. Quaternary Compound 四元化合物;季化合物◎ R开头的单字◎1. Range 范围2. Rapid Thermal Processing(RTP) 快速高温处理3. Rate 速率4. Recipe 处方;程序5. Recipe ID 程序名称6. Reclaim 回收改造;外送研磨7. Record 记录8. Recover 排除;复原9. Recover Runcard 异常流程卡10. Recover Wafers 回收晶片11. Recycle 循环;再制造12. Reject 拒绝13. Release 释放;放行14. Reset 重新启动;重设15. Resistance 电阻16. Reticle 光罩17. Reverse Current(Ir)逆向电流18. Rework 重做;重工19. RHLD 机台Alarm造成货被Hold住20. Robot 机械手臂21. Rough Vacuuming 粗抽22. Route 路径;途程23. Route ID 程序编号24. RS 表面电阻25. RTA 快速热处理26. Rule 规则27. Run 执行28. Runcard(R/C)流程卡29. Rush 急件◎ S开头的单字◎1. Sapphire 蓝宝石2. Scan 扫描3. Scan Fail 扫描失效4. Scan Speed 扫描速度5. Scattering 散射6. Scrap 报废7. Scratch 刮伤8. Scrubber 刷洗器;清扫夫9. Search 搜寻10. SEMI 半自动11. Sensor 感应器12. Sequence 顺序13. Service 服务14. Set 设定15. Shift 位移;班别16. Shut Down 停机17. Sign 签名18. Signal 讯号19. Signal Tower 讯号灯20. Silicon(Si)矽(硅)21. Single 单一22. Size 尺寸;型23. Skill 技能24. Skip 跳过;跳站25. Slot ID 晶片摆放位置26. Slurry 研磨液27. Sodium Hydroxide(NaOH)氢氧化钠28. SOLID/Solid 固体29. Solvent 溶剂;缓和剂30. Sort 分类31. Sorter 排序机台32. SPC(Statistical Process Control) 统计制程管制33. Spec(Specification) 规格34. Spin Dryer 旋干机35. Split 分开;部份;分批36. Stage 站别;层次37. Status 状态38. Step 步骤39. Stress 应力40. Strip 去除41. Substrate 基板42. Sulferic Acid(H2SO4)硫酸43. Summary 摘要44. Super Hot Run(SH)超级急件45. Supervisor 督导者(课长)46. Supplier 供货商47. Supply 供给48. Support 支援49. Surface Contamination 表面污染50. Switch 按钮;开关51. System 系统◎ T开头的单字◎1. Tag 显示器2. Tank 槽3. Tape 胶带4. Target 目标5. TC(Thermal Couple) 热电偶(用以量测物体温度)6. TE(Technician) 技术员7. Technology 技术8. TECN(Temporary Engineer) 临时工程变更通知单(Change Notice)9. Telephone 电话10. Temp(Temperature) 温度11. Terminal 终端机12. Terminate 终止13. Ternary Compound 三元化合物14. Testing 测试部门15. Thallium(Tl)鉈16. Thermionic Filament 热电子灯丝17. Thin Film(T/F)薄膜18. Thin Film Deposition 薄膜沉积19. Thickness(THK)厚度20. Thickness Uniformity 厚度的均匀度21. Throttle 节流阀22. Throughput 生产速度23. Tilt 倾斜24. Timeout 时限已到25. Title 标题26. Tool ID 机台编号27. Tool Name 机台名称28. Tools 工具29. Track in/out 入/出帐30. Training 训练31. Transfer 晶片传送;翻转32. Transport 输送33. Tray 指High Current上放Cassette的基座(有三个)34. Trend 趋势35. Trolley 推车36. Trouble 麻烦;异常;问题37. Trouble Over 故障结束38. Tune 调机39. Tuning 调机中40. Turbo Pump 分子涡轮真空泵41. Turn Rate(T/R)晶片周转率42. Twist 晶片旋转角度43. Type 类型;型态◎ U开头的单字◎1. Ultrasonic Cleaner (Supersonic超音波清洗机cleaner)2. Underdeveloped 显影不良3. Under – Etching 蚀刻不足4. Uniformity(U%)均匀度5. Unit 单位6. Unload 收货7. Unlock 开关放松8. Update 更改9. Use 使用10. User ID 使用者编号11. User Name 使用者名称◎ V开头的单字◎1. Vacuum(VAC.)真空2. Vacuum Evaporator 真空蒸镀机3. Vacuum Gauge 真空压力计4. Vacuum Pump 真空泵5. Valve 阀6. Vapor 蒸气7. Vender(Vendor) 厂商8. Vent 泄漏9. Venting 破真空10. Verify 确认11. Vf Test Vf测试12. Vf Tester Vf测试机13. View Angle 视角;发光角度(单位:deg)14. Voltage(V)电压◎ W开头的单字◎1. Wafer 晶片(台);外延片(陆)2. Wafer Actual Output 实际晶片产3. Wafer ID(#) 刻号(#)4. Wafer Out 晶片产出量5. Wafer Pcs(Pieces) 晶片片数6. Wafer Stage 晶片承载台7. Waste Chemicals Collection 废液回收箱8. WAT(Wafer Accept Test) 晶片接收侦测9. Water Mark 水痕10. Wet Etching 湿蚀刻11. Wet Etching System 湿蚀刻系统12. Wheel High Current上固定晶片旋转植入的轮盘13. White Tape 白膜14. Whole Dicing 全切15. Width 宽度16. WIP Lot List 在制品的批货清单◎ X开头的单字◎1. X-ray X射线◎ Y开头的单字◎1.Yield 良率◎ Z开头的单字◎1. Zero 零层2. Zoom(Zoom In/Zoom Out) 调整自由焦距镜头。
ch3

整个网络只有一个广播域,给网络带来不便和不安全。 使用路由器,受到接口限制,广播域分离不是太好 使用交换机
实现VLAN的机制 首先,在一台未设置任何VLAN的二层交换机上,任何广播帧都会被转 发给除接收端口外的所有其他端口(Flooding)。
交换机
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4
广播帧
交换机收到广 播帧后,转发 到除接收端口 外的其他所有 端口。
VLAN间的通信也需要路由器 提供中继服务,这被称作 “VLAN间路由”。VLAN间 路由,可以使用普通的路由器, 也可以使用三层交换机。
访问链接 访问链接,指的是“只属于一个VLAN,且仅向该VLAN转发数据帧” 的端口。在大多数情况下,访问链接所连的是客户机。 通常设置VLAN的顺序是: 生成VLAN 设定访问链接(决定各端口属于哪一个VLAN) 设定访问链接的手法,可以是事先固定的、也可以是根据所连的计算 机而动态改变设定。前者被称为“静态VLAN”、后者自然就是“动态 VLAN”了。
动态VLAN 另一方面,动态VLAN则是根据每个端口所连的 计算机,随时改变端口所属的VLAN。这就可以 避免上述的更改设定之类的操作。动态VLAN可 以大致分为3类: 基于MAC地址的VLAN(MAC Based VLAN) 基于子网的VLAN(Subnet Based VLAN) 基于用户的VLAN(User Based VLAN)
VLAN
Mr Song
为什么需要VLAN
什么是VLAN? VLAN(Virtual LAN),翻译成中文是“虚拟局域网”。 LAN 广播域,指的是广播帧(目标MAC地址全部为1)所能传 递到的范围,亦即能够直接通信的范围。严格地说,并不 仅仅是广播帧,多播帧(Multicast Frame)和目标不明的 单播帧(Unknown Unicast Frame)也能在同一个广播域 中畅行无阻。
Joint_Slot_Scheduling_and_Power_Allocation_in_Clus
LetterJoint Slot Scheduling and Power Allocation in ClusteredUnderwater Acoustic Sensor NetworksZhi-Xin Liu, Xiao-Cao Jin, Yuan-Ai Xie, and Yi YangDear Editor,This letter deals with the joint slot scheduling and power alloca-tion in clustered underwater acoustic sensor networks (UASNs),based on the known clustering and routing information, to maximize the network’s energy efficiency (EE). Based on the block coordi-nated decent (BCD) method, the formulated mixed-integer non-con-vex problem is alternatively optimized by leveraging the Kuhn-Munkres algorithm, the Dinkelbach’s method and the successive con-vex approximation (SCA) technique. Numerical results show that the proposed scheme has a better performance in maximizing EE com-pared to the separate optimization methods.Recently, the interest in the research and development of underwa-ter medium access control (MAC) protocol is growing due to its potentially large impact on the network throughput. However, the focus of many previous works is at the MAC layer only, which may lead to inefficiency in utilizing the network resources [1]. To obtain a better network performance, the approach of cross-layer design has been considered. In [1], Shi and Fapojuwo proposed a cross-layer optimization scheme to the scheduling problem in clustered UASNs.However, power allocation and slot scheduling were separately designed in [1], which cannot guarantee a global optimum solution.In [2], a power control strategy was introduced to achieve the mini-mum-frame-length slot scheduling. However, EE, as a non-negligi-ble aspect of network performance, is not being considered in [2].In this letter, we formulate a joint slot scheduling and power allo-cation optimization problem to maximize the network’s EE in clus-tered UASNs. The formulated problem with coupled variables is non-convex and mixed-integer, which is challenging to be solved.We propose an efficient iterative algorithm to solve it. Numerical results demonstrate the effectiveness of our proposed algorithm.N ≜{1,2,...,N }K ≜{1,2,...,K }M ≜{1,2,...,M }Problem statement: A clustered UASN with N sensor nodes grouped into K clusters is considered in this article, with the sets and . Sensor nodes’ operation time in a frame consists of M equal and length-fixed time slots with the index set . The sensor nodes send carriers at the same frequency. The half-duplex (HD) mode and the decode-and-for-ward (DF) mode are adopted for data relaying. The data packet length is assumed equal to the length of the time slot. Since packet collisions occur at the receiver but not the sender, we optimize the slot scheduling from the perspective of signal arrival time. As shown in Fig. 1, packets are scheduled to reach the destination at specific time slots. To avoid collisions, the arriving packets cannot overlap with each other as shown in the example of the packets at the sink from CH1, CH2 and CH3 in Fig. 1.z n =(M ,[t ,1])∈R M ×1M −1We use the sparse vector (which means the t -th element is 1 and the rest elements are 0) to represent the scheduling indicator, i.e., the t -th time slot is assigned to node n to Z ≜{z 1,z 2,...,z N }p n P ≜{p 1,p 2,...,p N }B log 2(1+γn )γn deliver data. Then the slot scheduling of the overall network can beexpressed by the set . The allocated transmission power of node n is denoted as , with the corresponding set of the overall network . By Shannon’s law, the achiev-able link rate of node n to its receiver can be given by R n =, where B is the bandwidth, and is the signal-to-interference-and-noise ratio (SINR) at the receiver of node n , which can be written asg nn n N 0(f )where is the link’s channel gain from node to the receiver of node n , is the power spectral density (p.s.d.) ofthe ambient noises at the receiver (refer to [3]), and binary variablen n n ∈N tionships between node n and node , where .We regard the links connecting to the sink (i.e., sea surface buoy node) directly as the bottleneck links, then the EE maximization˙KK Q k ≜{1,2,...,Q k }C (z k )k ∈˙Kγth NR th T p C 1C 2C 3C 4M min M max C 5C 6z k i ,j where is the set of the links connecting to the sinkdirectly, is the remaining part of after removing the cluster con-taining the sink, is the set of cluster members (CMs) in k -th cluster, represents the set of time slots occupiedby the cluster head (CH) to transmit data, is the required SINR threshold for each link, is the required threshold of net-work rate for the entire network, and is a constant integer. is the transmission power constraint. is the SINR constraint to ensure that the signals can be correctly demoduled as shown in the example of CH3 in Fig. 1. indicates that the output link rate of CH k is restrained by the rate of its subnetwork, which ensures that the links connecting to the sink directly are the bottleneck links. is the integer constraint of M ranging from to . is the required minimum network rate constraint. denotes is a binary variable, which is set as 1 when the j -th time slot is occupied by theCorresponding author: Zhi-Xin Liu.Citation: Z.-X. Liu, X.-C. Jin, Y.-A. Xie, and Y. Yang, “Joint slot scheduling and power allocation in clustered underwater acoustic sensor networks,” IEEE/CAA J. Autom. Sinica , vol. 10, no. 6, pp. 1501–1503, Jun.2023.The authors are with the School of Electrical Engineering, Yanshan University, Qinhuangdao 066004, China (e-mail:Color versions of one or more of the figures in this paper are available online at .Digital Object Identifier 10.1109/JAS.2022.106031CH1CH2CH2CH1CH3CH3Slot1Signal packetInterference packetSlot2Slot3Slot4Slot5SinkFig. 1. Receiver-synchronized slot scheduling table.C 7C 8C 9C 10i -th CM of the k -th cluster. denotes that each time slot accommo-dates at most one node in a cluster, which is given to avoid packetcollisions. denotes that each node is assigned one and only onetime slot to deliver data in a frame. denotes that the HD mode is adopted, thus CHs could not transmit and receive data simultane-ously as shown in the example of CH1 in Fig. 1. is the con-straint for CHs to ensure that frames will not affect each other.P Z C 2C 3C 5P Z Problem solution: The optimization problem (3) is a non-convex and mixed-integer optimization problem, which cannot be solved directly due to the challenge that the variables M , and are always coupled with each other in , , and the objective function. To tackle the coupled variables, firstly, the exhaustive search method is adopted to solve the variable M , then a BCD-based alternating optimization method is utilized to decouple and .P Z∗Given the , and M , sensors’ optimal slot scheduling solution Q k M Q k M each node is assigned one and only one slot to deliver data and each slot accommodates at most one node in a cluster, the slot scheduling problem in a cluster can be modeled as a weighted matching prob-lem for a bipartite graph, in which the CMs in the k -th cluster and the M time slots can be partitioned into two independent and disjoint sets and such that every edge connects a node in to a time slot in . The weight of the edge is defined as the network rate. Then problem (4) can be solved by the Kuhn-Munkres algorithm proposed in [4]. The process, that optimizing the slot scheduling of a cluster while keeping the other clusters unchangeable, continues until all the clusters are optimized. After a round of optimization, if the network rate is improved, another optimization round will be performed until the network rate no longer increases.C 2Although any two nodes in the same cluster have no mutual inter-ference, it still should be noted that a node in other clusters may be interfered by multi nodes in the optimization cluster. That means the optimal matching obtained by the Kuhn-Munkres algorithm may unsatisfy . For solving this problem, Criterion 1 is proposed to search for the eligible slot scheduling scheme.B B B Criterion 1: Supposing node A is the node unsatisfying the SINR constraint, firstly, we find its interference nodes (called set ) who belong to the optimization cluster. Then, we sort set in descending order in terms of the interference intensity to node A to find the node having the largest interference to node A (called node C). If nodeC has more than one available time slot, the previous assigned slot is forbidden to be assigned to node C. Otherwise, other nodes’ time slot will be checked and forbidden in same fashion unless there are no more time slot that can be forbidden in .Z P∗Given the and , sensors’ optimal transmission power solution can be optimized by solving the following problem:C 3C 5P C 3R k ∀k ∈˙K R k =B log 2A k −B log 2H k A k =p k g kk +∑∀k k ∈N δk (z k )p k g kk +N 0(f )B H k =∑∀k k ∈N δk (z k )p k g kk +N 0(f )B ∑i v i ≥∏i (v i /θi )θiv i ≥0θi >0∑i θi =1∑v objective function and the constraints and with respect to .To obtain a convex upper bound of the left-hand side (LHS) of ,we note that , , can be rewritten as , where , and. Making use of the deformation of arithmetic-geometric mean inequality, which states thatwith , and (the equality happensRk =B log 2A k −B f (P )R k ≤R k ,∀k ∈K ˜pn =ln p n ∀p n ∈P Letting , we have . And the equality happens when (7) holds. Letting , , it isC 3To obtain a concave lower bound of the right-hand side (RHS) of , the logarithmic approximation method used in [5] is adopted.ˇRl ,∀l ∈L ,R l ,∀l ∈L ,C 5˜pn =ln p n ∀p n ∈P of in the objective function and . Substitut-ing the undesired terms in (5) with the upper or lower boundsobtained above, and letting , , problem (5) can be12N ˜Ptional function with a concave numerator and a convex denominatorin terms of the transmission power , and the constraints are all con-vex. Therefore, we can exploit the Dinkelbach’s method [6] to trans-form it into the equivalent convex problemP The optimal solution of problem (5) can be obtained by solving the equivalent convex problem (13) iteratively, which can be tackled with existing optimization tools like CVX. The pseudocode of the optimization process in terms of sensors’ transmission power is shown in Algorithm 1.The pseudocode of the BCD-based alternating optimization algo-rithm is shown in Algorithm 2, in which two variable blocks are opti-mized alteratively corresponding to the two optimization subprob-lems (i.e., the slot scheduling subproblem and the power allocation subproblem) in each iteration of the alternating optimization process.f =10B =2P max =Simulation results: We consider a 10 km × 10 km × 200 m area,where N = 30 underwater sensor nodes deployed randomly at differ-ent sea depths are divided K clusters. We assume that the sensors are stationary, and the data in each sensor’s buffer is always sufficient.We take the carrier frequency kHz, kHz and 2 W.P 0Z 0For assessing the performance of the proposed alternating-opti-mization-based joint slot scheduling and power allocation algorithm (denoted as AO), we present three other schemes as contrasts, which include two kinds of separate optimization methods and the power allocation scheme and the slot scheduling scheme obtained by the proposed CMS-MAC algorithm in [2]. The two separate opti-mization methods are summarized as follows:Algorithm 1 Power Control Algorithm Based on the SCA Technique andthe Dinkelbach’s Methodτεt ←−0˜P{t }←−{ln p 1,ln p 2,...,ln p N }P 1: Set the maximum number of iterations and the maximum tolerance .Initialize iteration index and , where is the input powers;2: repeath ←−0˜P {h }temp←−˜P {t }3: Initialize iteration index and ;η{t }EE ˜P{t }4: Compute with given ;5: repeat αl =γl (˜P {h }temp )1+γl (˜P {h }temp )βl =ln1+γl (˜P {h }temp )γαl l(˜P {h }temp ) ∀l ∈L αq =γq (˜P {h }temp )1+γq (˜P {h }temp )βq =ln 1+γq (˜P {h }temp )γαq q (˜P {h }temp) ∀q ∈Q k ∀k ∈˙K θk ∀k k ∈N θN ∀k ∈˙K˜P {h }temp 6: Compute , , , , , , , and compute ,, , by (7) with given ;η{t }EE Z ˜P {h +1}temp7: Solve (13) with the given and , and obtain the optimal ;h ←−h +18: Update ;˜P h temp ˜P ∗temp 9: until converge to the optimal solution ;˜P{t +1}←−˜P ∗temp 10: ;t ←−t +111: Update ; f (η{t −1}EE )<ε,or t ≥τ12: until ;P ∗={e ˜p{t }1,e ˜p {t }2,...,e ˜p {t }N }13: Obtain the optimal solution ;Algorithm 2 Alternating-Optimization-Based Joint Time Slot Scheduling and Power Allocation AlgorithmM min M max P 0Z 0M min 1: Obtain the low bound and the upper bound of M , and the power allocation solution and the slot scheduling scheme under by the algorithm proposed in [2];ε2: Set the maximum tolerance ;M =M min ;M ≤M max ;M ++3: for do l ←04: Initialize iteration index ;Z {l }M ←Z 0P {l }M ←P 05: Initialize , and ;6: repeatP {l }M Z {l }M Z {l +1}M 7: Solve (4) with the given and by the Kuhn-Munkres algo-rithm, and obtain the optimal slot scheduling ;P {l }M Z {l +1}M P {l +1}M 8: Solve (5) with the given and by Algorithm (1), and obtainthe optimal power allocation ;l ←−l +19: Update ;10: until the increment of ηEE is smaller than ε;η∗M Z {l }M P {l }M 11: Obtain the optimal network EE , and the optimal solution and ;12: endη∗M ∗=Max {η∗M min ,η∗M min +1,...,η∗M max }13: Let ;M ∗Z {l }M ∗P {l }M ∗14: Return the optimal solution , and ;Z 01) Optimal power allocation with fixed slot scheduling (denoted as OPA_FSS): With the fixed slot scheduling scheme , the transmis-sion powers are optimized by Algorithm 1.P 02) Optimal slot scheduling with fixed power allocation (denoted as OSS_FPA): With the fixed power allocation scheme , the slotscheduling of all of sensors are optimized by the slot schedulingalgorithm proposed above.The corresponding comparison results are shown in Fig. 2. It can be observed that the proposed AO shows the best performance. The reason is that slot scheduling and power allocation may be influ-enced by each other, thus it is unreasonable to fix one of them and then solve another. For the proposed AO, slot scheduling and power allocation could be solved in an alternating way, which leads to bet-ter solutions. Furthermore, it can be found that AO achieves signifi-cant EE gains compared to CMS-MAC algorithm.(a)(b)K SINR (dB)2500E E (b i t s /H z /J )E E (b i t s /H z /J )200015001000500γth Fig. 2. Comparisons of EE. (a) for different clustering numbers with = 10dB; (b) for different SINR constraints with K = 7.Conclusion: In this letter, an EE maximization problem withcross-layer design is considered in clustered UASNs. To tackle the non-convex and mixed-integer optimization problem, a BCD-based iterative algorithm is proposed. Numerical results show that the pro-posed joint optimization scheme achieves significant EE gains com-pared to the separate optimization methods.Acknowledgment: This work was supported by the National Natu-ral Science Foundation of China (62273298, 61873223), the Natural Science Foundation of Hebei Province (F2019203095), and Provin-cial Key Laboratory Performance Subsidy Project (22567612H).ReferencesL. Shi and A. O. Fapojuwo, “TDMA scheduling with optimized energy efficiency and minimum delay in clustered wireless sensor networks,”IEEE. Trans. Mob. Comput., vol. 9, no. 7, pp. 927–940, 2010.[1]W. Bai, H. Wang, X. Shen, and R. Zhao, “Link scheduling method for underwater acoustic sensor networks based on correlation matrix,” IEEE Sens. J., vol. 16, no. 11, pp. 4015–4022, 2016.[2]M. Stojanovic, “On the relationship between capacity and distance in an underwater acoustic communication channel,” SIGMOBILE put. Commun. Rev., vol. 11, no. 4, pp. 34–43, 2007.[3]F. Xing, H. Yin, Z. Shen, and V. C. M. Leung, “Joint relay assignment and power allocation for multiuser multirelay networks over underwater wireless optical channels,” IEEE Internet Things J., vol. 7, no. 10, pp. 9688–9701, 2020.[4]Z. Liu, Y. Xie, Y. Yuan, K. Ma, K. Y. Chan, and X. Guan, “Robust power control for clustering-based vehicle-to-vehicle communication,”IEEE Syst. J., vol. 14, no. 2, pp. 2557–2568, 2020.[5]J.-P. Crouzeix and J. A. Ferland, “Algorithms for generalized fractional programming,” Mathematical Programming , vol. 52, no. 1, pp. 191–207,1991.[6]LIU et al .: JOINT SLOT SCHEDULING AND POWER ALLOCATION IN CLUSTERED UASNS 1503。
计算机网络CH3练习题
2、网桥的工作原理和特点是什么?网桥与转发器以 及以太网交换机有何异同?
网桥从其端口接收网段上传输的帧。每收到一个帧就先暂存在其缓冲器 中。若此帧未出错,且目的 MAC 地址属于另一个网段,则通过查找转发表, 将收到的帧送往相应的端口转发出去,但不改变转发帧的源地址,它不会 把自己的地址写到帧的地址字段中。若该帧出错则丢弃之。仅在一个网段 中的帧不会转发,不会引起广播风暴。网桥是通过内部端口管理程序和网 桥协议来完成上述操作的。 网桥与转发器都是网段互联设备,但工作在不同的协议层次上,转发器 是物理层互联设备,网桥是MAC层互联设备。转发器在转发一个帧时,不 对传输媒体进行检测,但网桥在转发一个帧前,必须执行CAMA/CD算法, 如发送过程中出现碰撞,就必须停止发送和进行退避。 以太网交换机实质上就是一个多端口网桥,但网桥的端口较少,一般只 有 2~4个,而以太网交换机通常都有十几个以上的端口。以太网交换机的 每个端口都可以直接与主机相连,还可以工作在全双工方式下。而普通网 桥的端口只是连接到局域网上,转发时延较大。在使用以太网交换机的情 况下,当主机需要通信时,交换机能同时连接许多对端口,可以使每一对 相互通信的计算机都像独占通信媒体那样进行无碰撞的数据传输。以太网 交换机由于使用了专用的交换芯片结精构品 ,交换速度较快。
帧的传输时延≧帧的传播时延
所以帧的传输时延必须大于等于10us,即 最小帧长=1Gbps×10us=10000b=1250B
所以最小帧长为1250B
精品
课堂练习2
• 假设为以太网设计一种新的传输介质。这 种新的传输介质允许任意两个端系统之间 最多有6个转发器。每个网段的最大传播延 迟为20us。新介质将工作在10Mbps。请问 最小的帧长度是多少?
R qtl书籍的数据集:qtlbook包说明书
Package‘qtlbook’October13,2022Version0.18-8Date2019-06-28Title Datasets for the R/qtl BookAuthor Karl W Broman[aut,cre](<https:///0000-0002-4914-6671>)Maintainer Karl W Broman<***************>Description Datasets for the book,A Guide to QTL Mapping with R/qtl.Broman and Sen(2009)<doi:10.1007/978-0-387-92125-9>.Depends R(>=2.10.1)Suggests qtlLicense GPL-3URL /book,https:///kbroman/qtlbookBugReports https:///kbroman/qtlbook/issuesEncoding UTF-8RoxygenNote6.1.1NeedsCompilation noRepository CRANDate/Publication2019-06-2814:50:03UTCR topics documented:ch3a (2)ch3b (3)ch3c (4)gutlength (5)iron (6)myocard (7)nf1 (8)ovar (9)trout (10)Index1212ch3a ch3a Data with a phenotype errorDescriptionAnonymous data with a phenotype error and a pair of individuals with very similar phenotypes.Usagech3aFormatAn object of class cross.See qtl::read.cross()for details.DetailsA backcross with234individuals,each withfive phenotypes and typed at166markers.SourceKarl W Broman,<***************>ReferencesBroman,K.W.and Sen,S.(2009)A Guide to QTL Mapping with R/qtl.Springer,New York.See Alsoch3b,ch3cExamplesdata(ch3a)#phenotype problempairs(ch3a$pheno)ch3a$pheno[ch3a$pheno[,4]==0,]#individual159#individuals with similar genotypeslibrary(qtl)cg<-comparegeno(ch3a)hist(cg,breaks=200)max(cg[cg<1])which(cg==max(cg[cg<1]),arr.ind=TRUE)ch3b3 ch3b Data with bad markersDescriptionAnonymous data with markers showing severe segregation distortion.Usagech3bFormatAn object of class cross.See qtl::read.cross()for details.DetailsAn intercross with144individuals,each with one phenotype and typed at145markers.SourceKarl W Broman,<***************>ReferencesBroman,K.W.and Sen,S.(2009)A Guide to QTL Mapping with R/qtl.Springer,New York.See Alsoch3a,ch3cExamplesdata(ch3b)library(qtl)thetab<-geno.table(ch3b)plot(-log10(thetab[,ncol(thetab)]),ylab=expression(-log[10](P)))thetab[thetab[,ncol(thetab)]<1e-6,]4ch3c ch3c Data with misplaced markersDescriptionAnonymous data with markers out of place.Usagech3cFormatAn object of class cross.See qtl::read.cross()for details.DetailsAn intercross with100individuals,each with one real phenotype and typed at108markers.SourceKarl W Broman,<***************>ReferencesBroman,K.W.and Sen,S.(2009)A Guide to QTL Mapping with R/qtl.Springer,New York.See Alsoch3a,ch3bExamplesdata(ch3c)library(qtl)ch3c<-est.rf(ch3c)plotRF(ch3c,chr=c(1,7,12,13,15))gutlength5 gutlength Gut length intercross dataDescriptionData from a mouse intercross experiment on gut length,including both sexes.All individuals carry the Sox10Dom mutation.UsagegutlengthFormatAn object of class cross.See qtl::read.cross()for details.DetailsA mouse intercross between C3HeBFeJ(C3)and C57BL/6J(B6),with one F1parent carrying theSox10Dom mutation.There are1068mice from reciprocal intercrosses.Over2000mice were generated,but only those individuals heterozygous at Sox10Dom were genotyped and included in the data set.Sox10is on chromosome15,and so that chromosome exhibits an unusual segregation pattern.Some mice received the mutation from their mother and some from their father.The primary phenotype here is gut length(in cm).The phenotype cross indicates the cross used to generate an animal.SourceE.Michelle Southard-Smith,Division of Genetic Medicine,Department of Medicine,VanderbiltUniversity School of Medicine,<**************************************>ReferencesOwens,S.E.,Broman,K.W.,Wiltshire,T.,Elmore,J.B.,Bradley,K.M.,Smith,J.R.and Southard-Smith,E.M.(2005)Genome-wide linkage identifies novel modifier loci of aganglionosis in the Sox10Dom model of Hirschsprung disease.Hum.Mol.Genet.14,1549–1558.Broman,K.W.,Sen,’S,Owens,S.E.,Manichaikul,A.,Southard-Smith,E.M.and Churchill G.A.(2006)The X chromosome in quantitative trait locus mapping.Genetics174,2151–2158.See Alsoiron,myocard,nf1,ovar,trout6ironExamplesdata(gutlength)library(qtl)plot(gutlength)iron Iron levels intercross dataDescriptionData from a mouse intercross experiment(using the C57BL/6J/Ola and SWR/Ola strains)on basal iron levels in the liver and spleen.UsageironFormatAn object of class cross.See qtl::read.cross()for details.DetailsAn intercross with284individuals(including both sexes and both cross directions),each with mea-sures of iron(inµg/g)in the liver and spleen.SourceAndrew G.Smith,MRC Toxicology Unit,<**********.uk>ReferencesGrant,G.G.,Robinson,S.W.,Edwards,R.E.,Clothier,B.,Davies,R.,Judah,D.J.,Broman,K.W.and Smith,A.G.(2006)Multiple polymorphic loci determine basal hepatic and splenic iron status in mice.Hepatology44,174–185.See Alsolink{gutlength},link{myocard},link{nf1},link{ovar},link{trout}Examplesdata(iron)library(qtl)plot(iron)myocard7 myocard Myocarditis intercross dataDescriptionData from a mouse intercross experiment on myocarditis.UsagemyocardFormatAn object of class cross.See qtl::read.cross()for details.DetailsAn intercross between the H-2s congenic mice A.SW and B10.S,with296individuals(including both sexes).The mice were injected with purified murine cardiac myosin,and the area of infiltrated myocardium in heart sections was measured.The phenotype is the percent myocarditis.SourceNoel R.Rose,Department of Pathology,Johns Hopkins University,<*******************.edu>ReferencesGuler,M.L,Ligons,D.L.,Wang,Y.,Bianco,M.,Broman,K.W.and Rose,N.R.(2005)Two autoimmune diabetes loci influencing T cell apoptosis control susceptibility to experimental au-toimmune myocarditis.J.Immunol.174:2167–2173.See Alsolink{gutlength},link{iron},link{nf1}link{ovar},link{trout}Examplesdata(myocard)library(qtl)plot(myocard)8nf1 nf1Neurofibromatosis type1backcross dataDescriptionData from a backcross experiment on neurofibromatosis type I.All individuals carry the NPcis mutation,received either from their mother or from their father.Usagenf1FormatAn object of class cross.See qtl::read.cross()for details.DetailsBackcrosses(C57BL/6J x A/J)x C57BL/6J and C57BL/6J x(A/J x C57BL/6J)with a total of 254individuals.Individuals received the NPcis mutation from either their mother or their father (indicated by the phenotype from.mom.The major phenotype,affected indicates whether the mice were affected(1)or unaffected(0)with neurofibromatosis type1.ReferencesReilly,K.M.,Broman,K.W.,Bronson,R.T.,Tsang,S.,Loisel,D.A.,Christy,E.S.,Sun,Z., Diehl,J.,Munroe,D.J.and Tuskan,R.G.(2006)An imprinted locus epistatically influences Nstr1 and Nstr2to control resistance to nerve sheath tumors in a neurofibromatosis type1mouse model.Cancer Research66,62–68.#’@source Karlyne Reilly,Mouse Cancer Genetics Program,National Cancer Institute at Frederick,<*******************>See Alsolink{gutlength}link{iron},link{myocard},link{ovar},link{trout}Examplesdata(nf1)library(qtl)plot(nf1)ovar9 ovar Interspecific backcross in DrosophilaDescriptionData on ovariole number in a backcross between D.simulans and D.sechellia;the majority ofindividuals were selected to be recombinant in the region of a putative QTL on chromosome3.UsageovarFormatAn object of class cross.See qtl::read.cross()for details.DetailsThe data come from an interspecific Drosophila backcross.D.simulans was crossed to D.sechellia,and the F1hybrid was crossed back to D.simulans.The phenotype of interest was ovariole number in females(a measure offitness).Phenotypes on1and on2are the ovariole counts in the left and right gonads.The phenotype onm is the average ofthe two counts;for many individuals,the ovariole count for one of two gonads was missing,and soonm is missing.In an initial cross of402individuals,383had complete phenotype data.Initial genotyping focusedon94individuals with extreme phenotype.To increase the resolution of a major QTL identified on chromosome3,a second cross of approxi-mately7000flies was performed,though only1050individuals showing a recombination event be-tween two morphological markers,st(bright red eyes)and e(dark brown body),were phenotypedand genotyped;1038had complete phenotype data.The aim was to oversample recombinants ofthe region of the QTL.There are genotype data for24markers on3chromosomes.(The fourth chromosome had onemarker,but showed no effect and is not included in these data.)The phenotype cross indicates whether an individual came from thefirst or second cross.Alleles"I"and"E"refer to D.simulans and D.sechellia,respectively.SourceVirginie Orgogozo,Department of Ecology and Evolutionary Biology,Princeton University,<ogozo@normaleReferencesOrgogozo,V.,Broman,K.W.and Stern,D.L.(2006)High-resolution QTL mapping reveals signepistasis controlling ovariole number between two Drosophila species.Genetics173,197–205.10troutSee Alsolink{gutlength},link{iron},link{myocard},link{nf1},link{trout}Examplesdata(ovar)library(qtl)plot(ovar)trout Rainbow trout doubled haploid dataDescriptionData from doubled haploid individuals derived from a cross between Oregon State University(OSU) and Clearwater(CW)River rainbow trout clonal lines.UsagetroutFormatAn object of class cross.See qtl::read.cross()for details.DetailsDoubled haploid individuals were produced from a cross between Oregon State University(OSU) and Clearwater(CW)river rainbow trout(Oncorhynchus mykiss)clonal lines.Eggs from one of eight outbred females,two from Troutlodge(TL)and six from Spokane(SP),were irradiated to destroy maternal nuclear DNA and fertilized with sperm from a single F1male.Thefirst embryonic cleavage was blocked by heat shock to restore diploidy.There are a total of554individuals,with between8and168individuals from each of the eight females.The primary phenotype is time to hatch(tth).An additional"phenotype",female,indicates ma-ternal cytoplasmic environment(the source of the egg).There are genotype data on171markers on28linkage groups.The linkage groups are named as in Nichols et al.(2002),though a pair of markers are assigned to linkage group"un",as they don’t connect to any of the linkage groups in Nichols et al.(2002).Note that the data have cross type"dh"(for doubled haploids);in R/qtl they are treated just like a backcross,except that genotypes are referred to as the homozygotes.SourceKrista M.Nichols,Department of Biological Sciences,Purdue University,<*******************>trout11ReferencesNichols,K.M.,Broman,K.W.,Sundin,K.,Young,J.M.,Wheeler,P.A.and Thorgaard,G.H.(2007)Quantitative trait loci by maternal cytoplasmic environment interaction for development rate in Oncorhynchus mykiss.Genetics175,335–347.Nichols,K.M.,Young,W.P.,Danzmann,R.G.,Robison,B.D.,Rexroad,C.,Noakes,M.,Phillips, R.B.,Bentzen,P.,Spies,I.,Knudsen,K.,Allendorf,F.W.,Cunningham,B.M.,Brunelli,J.,Zhang,H.,Ristow,S.,Drew,R.,Brown,K.H.,Wheeler,P.A.and Thrgaard,G.H.(2002)A consolidatedlinkage map for rainbow trout(Oncorhynchus mykiss).Animal Genetics34,102–115.See Alsolink{gutlength},link{iron},link{myocard},link{nf1},link{ovar}Examplesdata(trout)library(qtl)plot(trout)Index∗datasetsch3a,2ch3b,3ch3c,4gutlength,5iron,6myocard,7nf1,8ovar,9trout,10ch3a,2,3,4ch3b,2,3,4ch3c,2,3,4gutlength,5iron,5,6myocard,5,7nf1,5,8ovar,5,9qtl::read.cross(),2–10trout,5,1012。
网络营销英文版题库带答案练习题复习题Ch3-(13)
CHAPTER FIFTEENCUSTOMER RELATIONSHIP MANAGEMENTMultiple Choice1.Which of the following represents a major shift in current marketing practice?a.From high fixed costs to low fixed costsb.From mass marketing to individualized marketingc.From focusing on a small base of customers to focusing on acquiring many newcustomersd.All of the above(b; Difficult; LO1; Analytic Skills)2. A firm using relationship marketing focuses on ________.a.market shareb.wallet sharec.time shared.relationship share(b; Easy; LO1; Analytic Skills)panies can use relationship marketing techniques to build relationships with________.a.customersb.employeesteral partnersd.all of the above(d; Moderate; LO1; Analytic Skills)4.Which of the following is a facet of customer relationship management (CRM)?a.customer serviceb.sales force automationc.marketing automationd.all of the above(d; Moderate; LO1; Analytic Skills)5.Social CRM means that companies must interact with customers ________.a.on the customer’s termsb.based on company datac.based on company strategyd.based on company desires(a; Difficult; LO3; Use of Information Technology)6.In order to keep customers from viewing their communications as spam, the firm shouldbuild relationships by ________.a.offering promotionsb.purchasing new consumer lists periodicallying consumer information to build more precise target profilesd.rewarding customers for giving out their friend’s e-mail addresses(c; Difficult; LO1; Analytic Skills)7.Which of the following is referred to as level one of relationship marketing?a.Marketers learn the names and needs of customersb.Marketers create solid solutions to customer problemsc.Marketers build a financial bond with customers by using pricing strategiesd.Marketers stimulate social interaction with customers(c; Difficult; LO2; Analytic Skills)8.Which of the following is an advantage of connecting customers with supply chainbusinesses?a.all companies will share transaction data so inventories can be kept lowb.customer service reps will have up-to-the-minute inventory information and be ableto help consumers more immediatelyc.upstream firms can use data to design products that better meet consumer needsd.all of the above(d; Moderate; LO3; Analytic Skills)9.As more companies integrate customer relationship management (CRM) and supply chainmanagement (SCM) activities ________.a.they will experience an increase in variable costsb.they will slightly less able to learn how to create value throughout the supply chainc.they will become more responsive to individual customer needsd.all of the above(c; Difficult; LO3; Analytic Skills)10.If two or more companies were to link their intranet networks for the purpose of sharinginformation, then they would have a(n) ________.a.supply chainb.extranetc.ethernetd.internet(b; Easy; LO4; Analytic Skills)panies obtain transactional, behavioral, and interaction data about prospects,business customers, and end customers through ________.a.personal disclosureb.automated tracking of the sales forcec.website activityd.all of the above(d; Moderate; LO1; Analytic Skills)12.CRM allows companies to leverage their resources by investing more in the ________customers.a.averageb.least profitablec.most lucratived.none of the above(c; Moderate; LO5; Analytic Skills)13.When everyone in the company who touches the customer understands all aspects of thecustomer’s relationship with the company, this is regarded as ________.a.owning the customer’s total experienceb.streamlining business processes that impact the customerc.having a 360-degree view of the customer relationshipd.fostering community(c; Difficult; LO3; Analytic Skills)14.Important tools that aid firms in customizing products to groups of customers orindividuals include ________ strategies that reside o n the company’s w eb and e-mailservers, and ________ strategies that are initiated by internet users.a.push; pullb.pull; pushc.marketing; brochurewared.marketing; inquiry(a; Moderate; LO4; Analytic Skills)ing _________ firms can develop customized web pages based on visitor behavior.a.Web log analysisb.ongoing e-mailc.client-side toolsd.agents(a; Difficult; LO4; Analytic Skills)16.________ allows marketers to monitor users’ online behavior and make instantaneousand/or automatic adjustments to online promotional offers and web content.a.Collaborative filteringb.Real-time profilingc.An agentd.E-mail communication(b; Difficult; LO4; Analytic Skills)17.Through real-time chat, forums, and email postings at its website, companies are able to________.a.aggregate data used to design marketing mixes that meet user needsb.build communityc.learn about productsd.all of the above(d; Moderate; LO4; Analytic Skills)18.Software agents such as shopping agents and search engines ________.a.scour the internet for terms matching the users’ search criteriae web portals to access partner informationc.are forms of experiential marketingd.match user input to databases and return customized information(d; Difficult; LO4; Analytic Skills)19.Individualized web portals are most often used to build relationships in the ________.a.B2C marketb.B2B marketc.B2G marketd.G2C market(b; Difficult; LO1; Analytic Skills)20.All of the following are metrics used to assess the internet’s value in delivering CRMexcept ________.a.lifetime value (LTV)b.cost savingsc.employee satisfactiond.customer satisfaction(c; Difficult; LO5; Analytic Skills)True/False21.Most businesses spend more money acquiring new customers than they spend keepingcurrent customers.a.Trueb.False(a; Easy; LO1; Analytic Skills)22.Customer service occurs only post-purchase when customers have questions orcomplaints.a.Trueb.False(b; Easy; LO1; Analytic Skills)23.Most customers would prefer to be brand disloyal in favor of finding the lowest price foreach purchase, so marketers must entice them into loyalty through special offers.a.Trueb.False(b; Difficult; LO1; Analytic Skills)24.One important tenet of CRM is that it is better to attract, retain, and grow customers thanto focus only on customer acquisition.a.Trueb.False(a; Moderate; LO1; Analytic Skills)25.Social CRM does not retain any of the tenets of CRM 1.0.a.Trueb.False(b; Difficult; LO3; Analytic Skills)26.Permission marketing dictates that customers will be pleased to receive e-mail for whichthey have opted-in.a.Trueb.False(a; Moderate; LO4; Analytic Skills)27.Lively and useful chat and forums increase repeat site visits and stickiness.a.Trueb.False(a; Easy; LO4; Analytic Skills)28.Post-transaction customer service is an important part of the customer care life cycle.a.Trueb.False(a; Easy; LO5; Analytic Skills)29.No matter how good a company may be at retaining customers, new customer acquisitionis still an important activity.a.Trueb.False(a; Moderate; LO5; Analytic Skills)31.Personalization involves ways that marketers individualize in an impersonal, computernetworked environment.a.Trueb.False(a; Easy; LO4; Analytic Skills)32.Unlike SCM, CRM activities usually refer to back-end operations.a.Trueb.False(b; Moderate; LO1; Analytic Skills)Essay Questions33.Why are the three pillars of relationship management?▪Customer relationship management (CRM)▪Customer experience management (CEM)▪Customer collaboration management (CCM)(Easy; LO2; Analytic Skills)34.Why is it important to implement CRM effectively and efficiently? In what ways can afirm ensure that their use of CRM is both effective and efficient?▪Many companies that invest in CRM software lose money on the investment.▪Companies need to focus on CRM applications to ensure effectiveness and efficiency▪Vision of CRM that fits with the company culture, is bought into by management, and fits with the firm’s brands and value propositions.▪CRM Strategy▪CEM - Valued Customer experience▪CCM – Organization-and-Customer Collaboration▪CRM Processes▪CRM Information▪CRM Technology▪CRM Metrics(Difficult; LO2; Analytic Skills)35. Discuss the major principles behind Social CRM (CRM 2.0), and contrast it with CRM 1.0.▪Social CRM (CRM 2.0) retains all the tenets of CRM 1.0. However, it adds social media technology and customer collaborative conversations to the process.▪Social CRM means that companies must interact with customers on their terms, and not based solely on the company’s data, strategy and desire.▪Social CRM extends CRM 1.0, but does not replace it; in CRM 1.0, customers would forward e-mails to friends or talk in business meetings about products.▪Social CRM added more conversation among customers due to social media and gave companies many additional media for building long-term customer relationships andsales.(Difficult; LO3; Use of Information Technology)36.What is the difference between push strategies and pull strategies used by firms thatcustomize products to customers? Your answer should include an example of each.▪Push strategies are marketing efforts initiated by (internet) companies. The firms are “pushing” customized information down the channel to customers.▪Pull strategies are customer initiated requests to retailers which ultimately get passed onto producers that make the branded products purchased by customers.(Moderate; LO4; Analytic Skills)37.The text notes that relationship marketing is practiced on three levels. Describe each ofthe three levels from the lowest to the highest.▪Level one is financial. Differentiation is based on pricing▪Level two is stimulating social interaction- ongoing personal communication or community building and aggressive pricing.▪Level three is creating and selling a structural solution to customer problems. At this point the customer is buying a solution or benefit from the firm, which resultsin strong bonds between customer(s) and the firm that serves them.(Moderate; LO2; Analytic Skills)38.Explain what is meant by CRM-SCM Integration. What are the advantages of thisintegration for internet companies?▪CRM - customer relationship management, which is the “front-end” connection between the customer and the firm. It includes all touch points with thecustomer, marketing efforts, customer service▪SCM - Supply Chain Management, which is the back-end connection between the firm and its suppliers.▪Integration ties the customer to suppliers.▪Advantages for internet companies include lower levels of inventory needed on hand, firms use the data to design products that better meet customer needs, andcustomer service representatives have current information to better servecustomers.▪Firms become more responsive to individual customer needs.(Moderate; LO1; Analytic Skills)39.Give an example of a time when you experienced some aspect of CRM via the internet.Did this experience represent a CRM success or failure in your mind? Why?▪ suggesting products based on previous orders is a success in CRM on the internet. They personalize/customize automatically the web sitebased on a customer buying patterns, live or past browsing patterns, and/orprojected preferences based on similar customers’ past purchases.(Moderate; LO2; Analytic Skills)。
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Sliding Window Protocol
ACK received Current Sequence Number
ACK sent
Window for Expected Frame
(c) After the first frame has been received. (d) After the first acknowledgement has been received.
One-Bit Sliding Window Protocol
Abnormal Case
A
B
Expect ACK 0, get ACK 1 Send B0 again!
Expect ACK 0, get ACK 1 Send A0 again! ACK 0 Disregard B0 (received before) Send A1 (A0 is acknowledged) Send A1 again Disregard A0 Send B1
7
Stop-and-Wait ARQ Software Coding
s.kind = data;
What if the event = “time_out” ?
8
Stop-and-Wait ARQ: The Receiver
1. At start, sequence number is 0 2. The receiver waits until event = frame_arrival 3. Receive the frame from the physical layer
Timer
4
Stop-and-Wait ARQ: Lost ACK
S is the current frame being sent
R is the current frame to receive
Importance of numbering
5
Delayed ACK & Lost Frame
S is the current frame being sent
15
One-Bit Sliding Window Protocol
A
B
One-bit = 2 sequence numbers (0 and 1) Window size is one.
Piggybacking but not pipelining (It is stop & wait) The notation is (seq, ack, info) An asterisk indicates where a network layer accepts a packet
Send B1 again
Every frame is sent twice!
Sliding Window Protocol
Use of Sliding Window 1. Sender: to hold the frames that have been sent, but are not acknowledged. Unacknowledged frames are caused by pipelining and piggybacking (in this case, if no data is sent from the receiver, then no ACK is sent as well) 2. Receiver: to hold unordered frames so that they can be reassembled in order and therefore no resend is necessary
Chapter 3
The Data Link Layer
(Part 2)
CSCI-345/EENG 480 Dr. Sunan Han, NYIT
1
Protocol 3: Stop-and-Wait ARQ
(Automatic Repeat reQuest)
A flow and error control mechanism for noisy channel The sending device keeps a copy of the last frame transmitted until it receives an acknowledgement (ACK)
2
Stop-and-Wait ARQ: Normal Operation
S is the current frame being sent
R is the current frame to receive
The sender will not send the next piece of data until it is sure that the current one is correctly received Sequence number necessary to check for duplicated packets
18
Sliding Window Protocol: The Sender
Window Size = 8 Frames from network layer
3 4 5 6 7 0 1
– Retransmits lost/damaged frame or lost/delayed ACK
Timer is introduced: expired response = frame loss ACK sent for frames received correctly Frame sequence numbers are 0 and 1 only
11
Protocol 4: Sliding Window Protocol
The sequence number of a frame is stored in the header in binary: if the number of bits in the header is m then the sequence number goes from 0 to 2m – 1 Sliding Window: Acknowledged (ACKed) frames are removed from the window and new frames are added into the window to maintain the window size
a) If sequence number (seq) is correct, send info to the network layer. Then send an ack frame to the sender, and invert sequence number (0 to 1 or 1 to 0) b) If seq is not correct, send the correct sequence number to the sender in an ack frame c) Go to step 2
a) If event = frame_arrivel and ack# is correct, then invert the sequence number (0 to 1 or 1 to 0) and go to step 2 b) If event = time_out or ack# is not correct, go to step 5
If it is the expected frame, frame_expected = unchanged! Meaning sending an ACK of the expected frame
10
Protocol 4: Sliding Window Protocol
Sequence number: each frame is assigned a sequence number, 0, 1, 2, 3, ... Window: set of sequence numbers for frames that are allowed to be sent without acknowledgment
3
Stop-and-Wait ARQ: Lost Frame
A timer is set each time a frame is sent
When ACK not received for the time set in the timer, the same frame will be resent
பைடு நூலகம்
R is the current frame to receive
I
I
R=0 S=0
Importance of ACK numbering
6
Stop-and-Wait ARQ: The Sender
1. The start sequence number is 0 2. The sender obtain the packet from network layer and put the packet into the info field of a frame 3. Assign the sequence number in the seq field 4. Assign “Data” in the kind field 5. Send the current frame to the physical layer 6. Start the timer: it starts to tick, … 7. Wait for “event”
12
Sliding Window Protocol
Current Sequence Number Current Frame on Hold