matlab第二版课后习题答案

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Matlab编程与工程应用(第二版)习题解答(全)

Matlab编程与工程应用(第二版)习题解答(全)

Matlab编程与工程应用〔第二版习题解答第一章:MATLAB简介1.>> myage = 25;>> myage = myage - 1;>> myage = myage + 2;2.>> myage = 25;>> myage = myage - 1;>> myage = myage + 2;3.>> namelengthmaxans =634.>> format bank>> 1/3ans =0.335.>> format rat>> 5/6 + 2/7ans =47/426.25 19 4.3333 9 97.>> pounds = 100;>> kilos = 2.2 * poundskilos =220.00008.>> R1 = 20; R2 = 30; R3 = 40;>> RT = <R1\1 + R2\1 + R3\1>\1RT =9.23089.>> ftemp = 90;>> ctemp = <ftemp - 32> * 5 / 9ctemp =32.222210. 略11.>> sind<90>ans =112.>> sita = 2 * pi / 3;>> r = 2;>> x = r * cos<sita>x =-1.0000>> y = r * sin<sita>y =1.732113.>> t = 100;V = 50;>> wcf = 35.7 + 0.6 * t - 35.7 + 0.16 * V + 0.43 * t * 0.16 * Vwcf =41214.Fix<3.5> = 3; Floor<3.5> = 3;Fix<3.4> = 3; Fix<-3.4> = -3;Fix<3.2> = 3; Floor<3.2> = 3;Fix<-3.2> = -3; Floor<-3.2> = -4;Fix<-3.2> = -3; Ceil<-3.2> = -3;15.Sqrt<19>3 ^ 1.2Tan<pi>16.Intmin<‘int32’>; intmax<‘int32’>; intmin<‘int64’>;intmax<‘int64’>;17.Realmin<‘double’>; Realmax<‘double’>;18.>> DblNum = 33.8;>> int32Num = int32<DblNum>int32Num =3419.>> A1 = rand;A2 = 20*rand;A3 = 30 * rand + 20;A4 = round<rand * 10>;A5 = round<rand * 11>; /A6 = round<rand * 50> + 50;>> A4 = randi<10>;>> A5 = randi<11>;>> A6 = randi<50> + 50;20. 略21.Double〔‘A’ < Double<‘a’>; 所以大写在前,小写在后;22.>> CharNum = 'xyz';>> CharNum = char<CharNum - 2>CharNum =vwx23.>> vec = [3 : 1 : 6]vec =3 4 5 6>> vec2 = [1.0000:0.5000:3.0000]vec2 =1.0000 1.50002.0000 2.50003.0000>> vec3 = [5 : -1 :2]vec3 =5 4 3 224.>> vec1 = linspace<4,8,3>vec1 =4 6 8>> vec2 = linspace<-3,-15,5>vec2 =-3 -6 -9 -12 -15>> vec3 = linspace<9,5,3>vec3 =9 7 525.>> vec = [1 : 1 : 10]vec =1 2 3 4 5 6 7 8 9 10 >> vec = linspace<1,10,10>vec =1 2 3 4 5 6 7 8 9 10 >> vec2 = [2:5:12]vec2 =2 7 12>> vec = linspace<2,12,3>vec =2 7 12>> myend = randi<4> + 8;>> vec1 = [1 : 3 : myend]vec1 =1 4 7 1027.>> vec = [-1:0.2:1]'vec =-1.0000-0.8000-0.6000-0.4000-0.20000.20000.40000.60000.80001.000028.>> vec = [0 : 1 : 15];>> n = [1 : 2 : numel<vec> - 1];>> vec2 = vec<n>vec2 =0 2 4 6 8 10 12 14 29.function [a b] = PI_CONT<x>%UNTITLED Summary of this function goes here% Detailed explanation goes heren =1 : 1 : fix<numel<x> / 2>;a = x<n>;n = 1+fix<numel<x>/2> : 1 : numel<x>;b = x<n>;endrem<numel<vec>,2>30.rand<2,3>10*rand<2,3>5 + round<15 * rand<2,3>>randint<2,3,[5 15]>31.rows = randi<5>;cols = randi<5>;y = zeros<rows,cols>;>> mat = [ 7 8 9 1012 10 8 6];>> A1 = mat<1,3>>> A2 = mat<2,:>>> A3 = mat<:,1:2>33.>> mymat = [2 3 4;5 6 7]>> mymat1 = fliplr<mymat>>> mymat2 = flipud<mymat>>> mymat3 = rot90<mymat>34.>> mymatzero = zeros<4,2>>> mymatzero<2,:> = [3,6]35.>> x = linspace<-pi,pi,20>;>> y = sin<x>;36.>> randmat = randint<3,5,[-5 5]> >> sign<randmat>37.>> randmat = randint<4,6,[-5 5]>;>> randmat2 = abs<randmat> 38.>> randmat = rand<3,5>>> randmat<3,:> = []39.>> vec = 1 : 1:1000;>> vec<end>>> vec<numel<vec>>>> [a b ] = size<vec>;>> vec<a * b>40.同上41.>> mat = zeros<3,5>;>> mat<:,:,1> = zeros<3,5>;>> mat<:,:,2> = zeros<3,5>; 42.>> myc = clock>> today = myc<1:3>>> now = myc<4:6>>> now = fix<now>第二章 MATLAB程序设计概述1.ri = 2; % Radius internalro = 4; % Radius outerV = 4 * pi / 3 * <ro ^ 3 - ri ^ 3> % calculate volume2.% Calculate Atomic Weight H2O2Weight_O = 15.9994;Weight_H = 1.0079;AtomicWeight = Weight_O * 2 + Weight_H * 2 % Calculate H2O2 Atomic Weight 3.fprintf<'Length of The character string is : %d\n',…length<input<'Please input character string :\n','s'>>>;4.NewNumber = input<'please input a Number :\n'>;fprintf<'Number with 2 decimal is :%0.2f\n',NewNumber>;5.>> vec = input<'Enter a matrix: '>Enter a matrix: [1:1:10;1:1:10]6.>> fprintf<'OUTPUT : %f\n',12345.6789>OUTPUT : 12345.678900>> fprintf<'OUTPUT : %10.4f\n',12345.6789>OUTPUT : 12345.6789>> fprintf<'OUTPUT : %10.2f\n',12345.6789>OUTPUT : 12345.68>> fprintf<'OUTPUT : %6.4f\n',12345.6789>OUTPUT : 12345.6789>> fprintf<'OUTPUT : %2.4f\n',12345.6789>OUTPUT : 12345.67897.>> fprintf<'OUTPUT : %d\n',12345>OUTPUT : 12345>> fprintf<'OUTPUT : %5d\n',12345>OUTPUT : 12345>> fprintf<'OUTPUT : %8d\n',12345>OUTPUT : 12345>> fprintf<'OUTPUT : %3d\n',12345>OUTPUT : 123458.>> x = 12.34;>> y = 4.56;>> fprintf<'x is %.3f\n',x>x is 12.340>> fprintf<'x is %0.0f\n',x>x is 12>> fprintf<'y is %0.1f\n',y>y is 4.6>> fprintf<'y is %0.1f !\n',y>y is 4.6 !9.% Calculate Area of the squarenessfprintf<'The Area of The Squareness is %.2f',…<input<'Please input the Length of the Squareness \n'>> …* <input<'Please input the Width of the Squareness \n'>>>;10.NewName = input<'What is your name? ','s'>;fprintf<'Wow,your name is %s!\n',NewName>;11.NewString = input<'Enter your string : ','s'>;fprintf<'Your String was : ''%s''\n',NewString>;12.WaterSpeed = input<'Enter the folw in m^3/s : '>;WaterSpeedft = 0.028 \ WaterSpeed;fprintf<'A flow rate of %.3f meters per sec \n',WaterSpeed>;fprintf<'is equivalent to %.3f feet per sec\n',WaterSpeedft>;13.IncomeY = input<'Input your income every year?'>;FoodCostY= [IncomeY * 8 / 100 IncomeY*10 / 100];FoodCostM = 12\FoodCostY;fprintf<'Food Cost in every year is %.2f - %.2f\n',FoodCostY<1>,FoodCostY<2>>; fprintf<'Food Cost in every Month is %.2f - %.2f\n',FoodCostM<1>,FoodCostM<2>>;14.Weight = input<'Please input the Weight of the plan \n'>Area = input<'Please input the area of the plan wing \n'>fprintf<'Charge of Plan Win is %.2f \n',Weight / Area>15.x = 10;y = 10;plot<x,y,'g+'>;16.clfx = -2 : 0.1 : 2;y = exp<x>;plot<x,y,'g'>;xlabel<'X'>;ylabel<'Y'>;legend<'Exp<x>'>;Title<'Exp Example'>;17.clfx = 1 : 5 : 100;y = sqrt<x>;plot<x,y,'go'>;hold on;bar<x,y>;18.clfy = randint<1,100,[0 100]>;x = 1 : 1 : length<y>;plot<x,y,'ro'>;hold onplot<x,y,'g+'>;figure<2>;plot<x,y,'k'>;figure<3>;bar<x,y>19.clfx = linspace<0,pi,10>;y = sin<x>;plot<x,y,'r'>;figure<2>;x = linspace<0,pi,100>;y = sin<x>;plot<x,y,'b'>;20.load TimeTemp.datx = TimeTemp<:,1>';y = TimeTemp<:,2>';plot<x,y>;Xlabel<'Height'>;Ylabel<'Temperature'>;Title<'Height - Temperature'>;legend<'TEMP'>21.>> randint<3,6,[50 100]>;>> save RandInt.bat ans -ascii;>> randint<2,6,[50 100]>>> save RandInt.bat randint -ascii –append >> load RandInt.bat>> RandInt22.>> load testtan.bat>> tan<testtan>23.>> load hightemp.dat>> hightemp<:,1> = hightemp<:,1> .+ 1900>> save y2ktemp.dat hightemp –ascii24.function [ fn ] = fn< x >%Calculate y as a function of xfn = x^3 - 4 * x^2 + sin<x>;end25.function [ mwh] = mwh_to_gj<x>%convers from MWh to GJmwh = 3.6 * x;end26.function [ output_args ] = miletometer< x >%Conver mile to meterMile = input<'mile per hours number :'>;meter = Mile * 5280 * 0.3048 / 3600;output_args = meter;fprintf<'Meter of the mile is : % .2f',meter>; end27.function [ Tn ] = Interest< p,i,n >%UNTITLED4 Summary of this function goes hereTn = p * <1 + i> * n;end28.略29.function [ V ] = SpeedConv<pi,ps>%UNTITLED4 Summary of this function goes hereV = 1.016 * sqrt<pi - ps>end30. function [ THR ] =Cal_rate<A>%UNTITLED4 Summary of this function goes hereTHR = <220 - A> * 0.6;end31.function [ nJ ] =STL_calc<n>%UNTITLED4 Summary of this function goes herenJ = sqrt<2 * pi * n> * <n / exp<1>>^n;end32.function [ output_args ] = costn< n >%UNTITLED5 Summary of this function goes hereoutput_args = 5 * n ^ 2 - 44 * n + 11;endn = input<'Enter the number of units :'>;Cn = costn<n>;fprintf<'The cost for 100 units will be $%.2f\n',Cn>;33.略〔仿造32题34.function [ V ] = oblong< length >%UNTITLED8 Summary of this function goes hereV = 1/12*sqrt<2>*length^3;endfprintf<'The volume of oblong is : %.2f\n ',oblong<input<'Enter the length of the oblong:\n'>>>35.function [ y ] = pickone< x >%pickone<x> returns a random element from vector xn = length<x>;y = x<randi<n>>;end36.function [ y ] = vecout< x >%UNTITLED11 Summary of this function goes herey = x : 1 : x+5;end37.b = input<'Enter the first side :'>;c = input<'Enter the second side :'>afa = input<'Enter the angle between them :'>y = sqrt<b^2 + c^2 - 2*b*c*cos<afa *<pi/180>>>;fprintf<'The third side is %.3f\n',y>;38.略39.load floatnums.datfloatnums = round<floatnums>;floatnums = floatnums';save intnums.datfloatnums-ascii;40.load costssales.datn = length<costssales<:,1>>;fprintf<'There were %d quarters in the file ',n>;n = 1 : 1 : n;costs = costssales<:,1>;sales = costssales<:,1>;plot<n,costs,'ko'>;hold onplot<n,sales,'b*'>;legend<'COSTS','SALES'>;xlabel<'COST'>;ylabel<'SALE'>;title<'COST-SALE'>;costssales = costssales'costssales = flipud<costssales>;save newfile.datcostssales-ascii;第三章选择语句2. if <input<'please Enter a x :\n','s'> ~= 'x'>disp<'sorry the char not x'>;end3. function y = Test3<x>if <x == 12>y = 1;elsey = x + 1;end;4. disp<'The program will calculate the volume of a pyramid'>;a = input<'Enter the length of the base :'>;c = input<'Is that i or c?','s'>;if< c == 'c'>a = a/2.54;end;b = input<'Enter the width of the base :','s'>;c = input<'Is that i or c?'>;if< c == 'c'>b = b/2.54;end;d = input<'Enter the length of the base :','s'>;c = input<'Is that i or c?'>;if< c == 'c'>d = d/2.54;end;fprintf<'The Volume of the Pyramid is %.3f cubic inches.',a * b * d / 3>;5.if<input<'Are you an engineer?<Y/N>','s'> == 'Y'>disp<'You are the best!'>;elsedisp<'oh~ soga'>;end;6.Fenzi = input<'Please input enter the FENZI: '>;Fenmu = input<'Please input enter the FENMU: '>;if<Fenmu == 0>disp<'Sorry The Fenmu can not be zero!'>;elsefprintf<'The result is %.2f.\n',Fenzi/Fenmu>;end;7.function Result = Test3_Func< a,b >%TEST3_FUNC Summary of this function goes here% Detailed explanation goes hereResult = sqrt<1 - b^2/a>;EndFunction:a = input<'Please Enter the a : '>;b = input<'Please Enter the b : '>;if <a == 0>disp<'Error 0001'>;elsefprintf<'The Result is %.2f \n',Test3_Func<a,b>>;end;8.a = input<'Please Enter the Shousuo : '>;b = input<'Please Enter the Shuzhang : '>;if <a<120 && b<80>disp<'you are the best choice !'>;elsedisp<'Sorry you can not do this!'>;end;9.A1 = input<'Enter the First Area: '>;A2 = input<'Enter the Second Area: '>;if<A1 > A2>disp<'UP!'>;elseif <A1 < A2>disp<'Down!'>;elsedisp<'Keep!'>;en10.a = input<'Enter the PH number : '>;if <a < 7>disp<'Suan'>;elseif <a > 7>disp<'Jian'>;elsedisp<'Zhong'>;end;11.function Result = Test3_Func< a,b >%TEST3_FUNC Summary of this function goes here % Detailed explanation goes hereif <a < b>Result = a : 1 : b;elseResult = a : -1 : b;end12.function Result = Test3_Func< x >%TEST3_FUNC Summary of this function goes here % Detailed explanation goes here[a b] = size<x>;if <<a ~= 1 && b ~= 1> || <a == 1 && b == 1>> Result = x;elseif<a == 1>Result = fliplr<x>;elseResult = flipud<x>;end13.letter = input<'Enter your answer :','s'>;if <letter == 'Y' || letter == 'y'>disp<'OK,continuing'>;elseif<letter == 'N' || letter == 'n'>disp<'OK,halting'>;elsedisp<'Error'>;end14.switch lettercase {'Y''y'}disp<'OK,contining'>case {'N''n'}disp<'OK,halting'>otherwisedisp<'Error'>end15.Mahe = input<'Enter the Speed of Plan : '>/input<'Enter the Speed of Voice: '>; if<Mahe > 1>disp<'supersonic speed'>;elseif<Mahe < 1>disp<'subsonic speed'>;elsedisp<'transonic speed'>;end;16.X = input<'Enter the temp in degrees C : \n'>;switch <input<'Do you want F or K?','s'>>case'F'fprintf<'The temp in degrees F is %.1f',<9/5>*X + 32>;case'K'fprintf<'The temp in degrees K is %.1f',X + 273.15>;otherwisedisp<'Enter Error!'>;end;17.%function y = Test3<x>X = randi<100>;if rem<X,2> == 0fprintf<'%d ÊÇżÊý\n',X>;elsefprintf<'%d ÊÇÆæÊý\n',X>;end18.function y = Test3<x>switch rem<x,4>case 0y = true;otherwisey =false;end;19.function y = Test3<innum>if innum == int32<innum>y = true;elsey =false;end;20.function y = Test3<a,b,c>if a^2 == b^2 + c^2y = true;elsey =false;end;21.Re = input<'Enter the Re Value :\n'>;if Re <= 2300 disp<'Laminar region'>;elseif Re > 2300 && Re <= 4000 disp<'Transition region'>; else disp<'Turbulent region'>;end;22.d1 = input<'Enter d1 : \n'>;d2 = input<'Enter d2 : \n'>;if d1 <= 0 || d2 <= 0disp<'Error!'>;elsefprintf<'%.2f',Test3_Func<d1,d2>>;end;function y = Test3_Func<a,b>y = a * b / 2;23.V = input<'Enter the speed of the wing: '>;if V <= 38 disp<'tropical depression '>;elseif V >= 73 disp<'typhoon'>;else disp<'revolving storm'>;end;24.V = input<'Enter the speed of the wing :'>;if V >74 && V <= 95disp<'1 : 4-5'>;elseif V > 95 && V <= 110disp<'2 : 6-8'>;elseif V > 110 && V <= 130disp<'3 : 9-12'>;elseif V > 130 && V <= 155disp<'4 : 13-18'>;elseif V > 155disp<'5 : 18'>;elsedisp<'Error'>;end25.略26.H = input<'Enter the hight of the cloude :'>;if H < 6500 && H > 0disp<'Low'>;elseif H >= 6500 && H < 20000disp<'Middle'>;elsedisp<'High'>;27.if letter == 'x'disp<'Hello'>;elseif letter == 'y'||letter == 'Y'disp<'Yes'>;elseif letter == 'Q'disp<'Quit'>;elsedisp<'Error'>;end;28.switch numcase {0 1 2}f2<num>;case {-2 -1}f3<num>;case 3f4<num>;otherwisef1<num>;end;29.switch menu<'menu','1.Cylinder','2.Circle','3.Rectangle'>case 1R = input<'Please enter the radius of buttom circle:'>;H = input<'Enter the height of the Cylinder:'>;A = 2 * pi * R * H + 2 * pi * <R ^ 2>;fprintf<'The area is %.2f',A>;case 2R = input<'Please enter the radius of circle:'>;A = pi * <R ^ 2>;fprintf<'The area is %.2f',A>;case 3a = input<'Please enter the long of Rectangle:'>;b = input<'Please enter the with of Rectangle :'>;A = a * b;fprintf<'The area is %.2f',A>;end30.同2931.同2932.x = input<'Enter the Value X :'>;Y = menu<'Menue Choose','Sin','Cos','Tan'>;switch Ycase 1output = sin<x>;case 2output = cos<x>;case 3output = tan<x>;end;33.略34.function output = Test3_Func<x>Y = menu<'Menue Choose','ceil','round','sign'>;switch Ycase 1output = ceil<x>;case 2output = round<x>;case 3output = sign<x>;end;35.略36.略37.略第四章循环1.>> for i = 1.5:0.2:3.1i = iend2.function output = Test3_Func<x>x = x - <rem<x,2> == 0>;output = 0;for i = 1 : 2 : xoutput = output + i;end;3.function output = Test3_Func<x>x = x - <rem<x,2> == 0>;output = 1;for i = 1 : 2 : xoutput = output * i;end;4.5.>> for i = 32 : 1 : 255char<i>end;6.>> vec = [5.5 11 3.45];>> for i = 1 : length<vec>fprintf<'Element %d is %.2f .\n',i,vec<i>>;end;7.n = randi<4> + 1;sum = 0;for i = 1 : nsum = sum + input<'Enter the value'>;end;fprintf<'Sum = %.1f\n',sum>;8disp<'Please enter the threshold below which samples will be considered to be invalid :'>;Value1 = input<'Considered to be invalid :\n'>;Value2 = input<'Please enter the number of data samples to be entered :\n'>; Sum = 0;num = 0;for i = 1:Value2data = input<'Please enter a data sample :'>;if data > Value1Sum = Sum + data;num = num + 1;endendif num == 0disp<'Data Error !'>;elsefprintf<'The average of the %d valid data samples is %.2f volts.',num,Sum/num>; end9.load MaxTemp.mat[a b] = size<MaxTemp>;for i = 1 : a;Matix1 = zeros<size<MaxTemp>>;Matix1<i,:> = MaxTemp<i,:>end10.sum = 0;for i = 1 : length<pipe>sum = sum + <pipe<i,1> < 2.1 || pipe<i,1> > 2.3>;sum = sum + <pipe<i,2> < 10.3 || pipe<i,2> > 10.4>;endfprintf<'There were %d rejects.\n',sum>;11.略12.略13.x = randint<1,5,[-10,10]>;x2 = 0;for i = 1 : length<x>x1<1,i> = x<1,i> - 3;if x1<1,i> > 0x2 = x2 + 1;end;x3<1,i> = abs<x1<1,i>>;if i > 1x4 = max<x1<1,i>,x1<1,i-1>>;end;end16.17.略18.19.20.略22.略23.略24.10略略第五章向量化代码1.Mat.*2;2.Result = vec;3.cumprod<vec>;4.>> vec = randint<1,6,[0 20]>;>> maxvec = max<vec>;>> minvec = min<vec>;>> cumsumvec = cumsum<vec>5.Sum<vec>6.>> clear>> vec = randint<1,5,[-10 10]>;>> vec_3 = vec - 3;>> ZhengshuNum = length<find<vec > 0>>;>> vec_abs = abs<vec>;>> vec_max = max<vec>;7.max<vec,[],1>max<vec,[],2>max<max<vec>>;8.function output = Test3_Func<r,n>vec = [];for i = 0 : nvec = [vec r.^i];end;output = sum<vec>;>> vec1 = Vec<[1 3 5]>;>> vec2 = Vec<[2 4 6]>;>> CheckSum = vec1.*vec2;11.>> vec = 1 : 1 : 1000;>> Result = sum<1./<vec.^2>>;>> Check = pi.^2/6;>> diff = check – result13.略14.略15.clear;clf;vec_temp = 0 : 0.5 : 10;x1 = input<'Enter the number of level :'>;while<all<vec_temp - x1>>x1 = input<'Enter the number of level :'>;end;disp<x1>16.略17.ticif x==21disp<x>end;tocticswitch xcase 21disp <x>;end;toc18.Ones<3>19.If find<r > 0> == [] && fin<h > 0> == 0V = pi .*<r.^2>*hEnd;第六章 MATLAB 程序1~20 略21.function S = Test3_Func<n>P = 10000;i = 0.05;vec = 1 : 1 : n;S = P * <<1 + i>.^vec>;plot<vec,S>;n = input<'Enter the Year:'>;while ~<n >0 && int32<n> == n>n = input<'Enter the Year:'>;end;Test3_Func<n>;22.Function lenf = lenprompt<>;Lenf = input<‘Enter the length By inches: ’>; Function Leni = covert_f_to_i<lenf>Leni = …<英尺转英寸>Function printlens<lenf,leni>Disp<lenf>;Disp<leni>;23.略24.。

MATLAB程序设计教程(第二版)课后答案(可编辑修改word版)

MATLAB程序设计教程(第二版)课后答案(可编辑修改word版)

MATLAB 第二版课后答案unit3-8 unit3实验指导1、 n=input('请输入一个三位数:');a=fix(n/100);b=fix((n-a*100)/10);c=n-a*100-b*10;d=c*100+b*10+a2(1)n=input('请输入成绩');switch ncase num2cell(90:100)p='A';case num2cell(80:89)p='B';case num2cell(70:79)p='C';case num2cell(60:69)p='D';otherwisep='E';endprice=p(2)n=input('请输入成绩');if n>=90&n<=100p='A';elseif n>=80&n<=89p='B';elseif n>=70&n<=79p='C';elseif n>=60&n<=69p='D';elsep='E';endprice=p(3)tryn;catchprice='erroe'end3n=[1,5,56,4,3,476,45,6,3,76,45,6,4,3,6,4,23,76,908,6];b=n(1);for m=2:20if n(m)>aa=n(m);elseif n(m)<bb=n(m);endendmax=amin=b法2n=[1,5,56,4,3,476,45,6,3,76,45,6,4,3,6,4,23,76,908,6];min=min(n)max=max(n)4b=[-3.0:0.1:3.0];for n=1:61a=b(n);y(n)=(exp(0.3*a)-exp(-0.3*a))/2*sin(a+0.3)+log((0.3+a)/2);endy5y1=0;y2=1;n=input('请输入n 的值:');for i=1:ny1=y1+1/i^2;y2=y2*((4*i*i)/((2*i-1)*(2*i+1)));endy1y26A=[1,1,1,1,1,1;2,2,2,2,2,2;3,3,3,3,3,3;4,4,4,4,4,4;5,5,5,5,5,5;6,6,6,6,6,6]; n=input('请输入n 的值:');if n<=5&n>=0disp(A([n],:));elseif n<0disp(lasterr);else disp(A([6],:));disp(lasterr);end7(1)f=[];f(n)=n+10*log(n^2+5);endy=f(40)/(f(30)+f(20))(2)f=[];a=0;for n=1:40f(n)=a+n*(n+1);a=f(n);endy=f(40)/(f(30)+f(20))8y=0;m=input('输入m 的值:');n=input('输入n 值:');for i=1:ny=y+i^m;endy************************************************************ function s=shi8_1(n,m)s=0;for i=1:ns=s+i^m;end************************************************************ shi8_1(100,1)+shi8_1(50,2)+shi8_1(10,1/2)思考练习2N=[1,2,3,4,5];2.*NN./21./N1./N.^23s=fix(100*rand(1,20)*9/10+10)y=sum(s)/20j=0;for i=1:20if s(i)<y&rem(s(i),2)==0j=j+1;A(j)=s(i);else continue;endendA4y1=0;y2=0;n=input('请输入n 的值:'); for i=1:ny1=y1+-(-1)^i/(2*i-1);y2=y2+1/4^i;endy1y2unit4实验指导1(1)x=-10:0.05:10;y=x-x.^3./6;plot(x,y)(2)x=-10:0.5:10;ezplot('x^2+2*y^2-64',[-8,8]); grid on;2t=-pi:pi/10:pi;y=1./(1+exp(-t));subplot(2,2,1);bar(t,y);title('条形图(t,y)');axis([-pi,pi,0,1]);subplot(2,2,2);stairs(t,y,'b');title('阶梯图(t,y)');axis([-pi,pi,0,1]);subplot(2,2,3);stem(t,y,'k');title('杆图(t,y)');axis([-pi,pi,0,1]);subplot(2,2,4);loglog(t,y,'y');title('对数坐标图(t,y)');3(1)t=0:pi/50:2*pi;r=5.*cos(t)+4;polar(t,r);title('\rho=5*cos\theta+4'); (2)t=-pi/3:pi/50:pi/3;r=5.*((sin(t)).^2)./cos(t); polar(t,r);4(1)t=0:pi/50:2*pi;x=exp(-t./20).*cos(t);y=exp(-t./20).*sin(t);z=t;plot3(x,y,z);grid on;(2)[x,y]=meshgrid(-5:5);z=zeros(11)+5;mesh(x,y,z);shading interp;5[x,y,z]=sphere(20);surf(x,y,z);axis off;shading interp;m=moviein(20);for i=1:20axis([-i,i,-i,i,-i,i])m(:,i)=getframe;endmovie(m,4);思考练习2(1)x=-5:0.1:5;y=(1./(2*pi)).*exp((-(x.^2))/2); plot(x,y);(2)t=-2*pi:0.1:2*pi;x=t.*sin(t);y=t.*cos(t);plot(x,y);grid on;3t=0:pi/1000:pi;x=sin(3.*t).*cos(t);y1=sin(3.*t).*sin(t);y2=2.*x-0.5;plot(x,y1,'k',x,y2);hold on;k=find(abs(y1-y2)<1e-2);x1=x(k);y3=2.*x1-0.5;plot(x1,y3,'rp');4x=-2:0.01:2;y=sin(1./x);subplot(2,1,1);plot(x,y);subplot(2,1,2);fplot('sin(1./x)',[-2,2],1e-4);5(1)i=-4*pi:0.1:10;j=12./sqrt(i);polar(i,j);title('{\rho}=12/sqrt(\theta)')(2)a=-pi/6:0.01:pi/6;b=3.*asin(a).*cos(a)./((sin(a)).^3+(cos(a)).^3); polar(a,b);6(1)[u,v]=meshgrid(-4:0.1:4);x=3.*u.*sin(v);y=2.*u.*cos(v);z=4.*u.^2;subplot(2,1,1);mesh(x,y,z);subplot(2,1,2);surf(x,y,z);(2)[x,y]=meshgrid(-3:0.2:3);z=-5./(1+x.^2+y.^2);subplot(1,2,1);mesh(x,y,z);subplot(1,2,2);surf(x,y,z);unit5实验指导1A=randn(10,5)x=mean(A)y=std(A)Max=max(max(A))Min=min(min(A))Sumhang=sum(A,2)SumA=sum(Sumhang)B=sort(A);C=sort(B,2,'descend');C2(1)a=0:15:90;b=a./180.*pi;s=sin(b)c=0:15:75;d=c./180.*pi;t=tan(d)e=input('请输入想计算的值:'); S=sin(e/180*pi)T=tan(e/180*pi)S1=interp1(a,s,e,'spline')T1=interp1(c,t,e,'spline')P1=polyfit(a,s,5);P2=polyfit(c,t,5);S2=polyval(P1,e)T2=polyval(P2,e)(2)n=[1,9,16,25,36,49,64,81,100]; N=sqrt(n);x=input('ji suan zhi : ');interp1(n,N,x,'cubic')3N=64;T=5;t=linspace(0,T,N);h=exp(-t);dt=t(2)-t(1);f=1/dt;X=fft(t);F=X(1:N/2+1);f=f*(0:N/2)/N;plot(f,abs(F),'-*')4P=[2,-3,0,5,13];Q=[1,5,8];p=polyder(P)q=polyder(P,Q)[a,b]=polyder(P,Q)5P1=[1,2,4,0,5];P2=[0,1,2];P3=[1,2,3];P=P1+conv(P2,P3)X=roots(P)A=[-1,1.2,-1.4;0.75,2,3.5;0,5,2.5];p=polyval(P,A)思考练习4A=rand(1,30000);a=mean(A)b=std(A)Max=max(A)Min=min(A)n=0;for i=1:30000if(A(i)>0.5)n=n+1;endendny=n/300005p=[45,74,54,55,14;78,98,45,74,12;87,98,85,52,65][M,S]=max(p)[N,H]=min(p)junzhi=mean(p,1)fangcha=std(p,1,1)zong=sum(p,2);[Max,wei]=max(zong)[Min,wei]=min(zong)[zcj,xsxh]=sort(zong,'descend')6x=[1:10:101];y=[0,1.0414,1.3222,1.4914,1.6128,1.7076,1.7853,1.8513,1.9085,1.9590,2.0043]; [p,s]=polyfit(x,y,5)a=1:5:101;y1=polyval(p,a);plot(x,y,':o',a,y1,'-*')unit6实验指导1A=[1/2,1/3,1/4;1/3,1/4,1/5;1/4,1/5,1/6];p=[0.95,0.67,0.52]';x=A\pA=[1/2,1/3,1/4;1/3,1/4,1/5;1/4,1/5,1/6]; p=[0.95,0.67,0.53]';x=A\pcond(A)2(1)x1=fzero(@funx1,-1)function fx=funx1(x)fx=x^41+x^3+1;(2)x2=fzero(@funx2,0.5)function fx=funx2(x)fx=x-sin(x)/x;(3)options=optimset('Display','off');x=fsolve(@fun3,[1,1,1]',options)q=fun3(x)function q=fun3(p)x=p(1);y=p(2);z=p(3);q(1)=sin(x)+y^2+log(z)-7;q(2)=3*x+2^y-z^3+1;q(3)=x+y+z-5;3(1)t0=0;tf=5;y0=1;[t,y]=ode23(@fun4,[t0,tf],y0);t'y'function yp=fun4(t,y)yp=-(1.2+sin(10*t))*y;(2)t0=0;tf=5;y0=1;[t,y]=ode23(@fun5,[t0,tf],y0);t'y'function yp=fun5(t,y)yp=cos(t)-y/(1+t^2);4x=fminbnd(@mymin,0,2);-mymin(x)function fx=mymin(x)fx=-(1+x.^2)/(1+x.^4);5options=optimset('Display','off');[x,fval]=fmincon(@fun6,[0,0,0],[],[],a,b,lb,ub)-fvalfunction f=fun6(x)f=-(sqrt(x(1))+(400-x(1))*1.1+(sqrt(x(2))+(400-x(1))*1.1-x(2))*1.1+sqrt(3)+(((400- x(1))*1.1-x(2))*1.1-x(3))*1.1+sqrt(x(x4)));思考练习1(1)A=[2,3,5;3,7,4;1,-7,1];B=[10,3,5]';C1=inv(A)*BC2=A\B[L,U]=lu(A);x=U\(L\B)(2)A=[6,5,-2,5;9,-1,4,-1;3,4,2,-2;3,-9,0,2];B=[-4,13,1,11]';C1=inv(A)*BC2=A\B[L,U]=lu(A);x=U\(L\B)2(1)x1=fzero(@funx1,1.5)function fx=funx1(x)fx=3*x+sin(x)-exp(x);(2)x1=fzero(@funx2,1)function fx=funx2(x)fx=x-1/x+5;(3)options=optimset('Display','off');x=fsolve(@fun3,[3,0]',options)q=fun3(x)function q=fun3(p)x=p(1);y=p(2);q(1)=x^2+y^2-9;q(2)=x+y-1;3(1)t0=0;tf=5;y0=[0,1];[t,y]=ode45(@vdpol,[t0,tf],y0);[t,y]function ydot=vdpol(t,y);ydot(1)=(2-3*y(2)-2*t*y(1))./(1+t^2);ydot(2)=y(1);ydot=ydot';(2)t0=0;tf=5;y0=[1;0;2];[t,y]=ode45(@vdpoll,[t0,tf],y0);[t,y]function ydot=vdpoll(t,y);ydot(1)=cos(t)-y(3)./(3+sin(t))+5*y(1).*cos(2*t)/((t+1).^2)-y(2); ydot(2)=y(1);ydot(3)=y(2);ydot=ydot';4x=fminbnd(@mymin,0,pi);-mymin(x)function fx=mymin(x)fx=-sin(x)-cos(x.^2);5[x,y1]=fminbnd(@mymax,0,1.5);-y1function fx=mymax(x);fx=-(9*x+4*x.^3-12*x.^2);unit7实验指导1(1)format longfx=inline('sin(x)./x');[I,n]=quadl(fx,0,2,1e-10)(2)format longfx=inline('1./((x-0.3).^2+0.01)-1./((x-0.9).^2+0.04)-6');[I,n]=quad(fx,0,1,1e-10)2(1)global ki;ki=0;I=dblquad(@fxy,0,1,0,1)ki(2)f=inline('abs(cos(x+y))','x','y');I=dblquad(f,0,pi,0,pi)3X=0.3:0.2:1.5;F=[0.3895,0.6598,0.9147,1.1611,1.3971,1.6212,1.8325];trapz(X,F)4p=0:pi/5:2*pi;for n=1:3nDX=diff(sin(p),n)end5f=inline('sin(x)./(x+cos(2.*x))');g=inline('(cos(x).*(x+cos(2*x))-sin(x).*(1-2.*sin(2*x)))/(x+cos(2.*x)).^2');x=-pi:0.01:pi;p=polyfit(x,f(x),5);dp=polyder(p);dpx=polyval(dp,x); %求dp 在假设点的函数值dx=diff(f([x,3.01]))/0.01; %直接对f(x)求数值导数gx=g(x); %求函数f 的导函数g 在假设点的导数plot(x,dpx,x,dx,'.',x,gx,'-'); %作图思考练习2format longfx=inline('1./(1+x.^2)');[I,n]=quad(fx,-Inf,Inf,1e-10)[I,n]=quadl(fx,-Inf,Inf,1e-10)x=-100000:100000;y=1./(1+x.^2);trapz(x,y)format short3(1)format longfx=inline('log(1+x)./(1+x.^2)');[I,n]=quad(fx,0,1,1e-10)(2)format longfx=inline('sqrt(cos(t.^2)+4*sin((2*t).^2)+1)'); [I,n]=quad(fx,0,2*pi,1e-10)4f=inline('4.*x.*z.*exp(-z.^2.*y-x.^2)');I=triplequad(f,0,pi,0,pi,0,1)5f=inline('sin(x)');g=inline('cos(x)');x=0:0.01:2*pi;p=polyfit(x,f(x),5);dp=polyder(p);dpx=polyval(dp,x);dx=diff(f([x,2*pi+0.01]))/0.01;gx=g(x);plot(x,dpx,x,dx,'.',x,gx,'-')unit8实验指导1syms x y;s=x^4-y^4;factor(s)factor(5135)2syms x;f=(x-2)/(x^2-4);limit(f,x,2)sym x;f=(sqrt(pi)-sqrt(acos(x)))/sqrt(x+1);limit(f,x,-1,'right')3sym x;f=sin(1/x);diff(f,'x')diff(f,'x',2)sym x;f=(1-cos(2*x))/x;diff(f,'x')diff(f,'x',2)4sym x;f=sqrt(exp(x)+1);int(f,'x')syms x y;f=x/(x+y);int(f,'y')sym x;f=exp(x)*(1+exp(x))^2;int(f,'x',0,log(2))sym x;f=x*log(x);int(f,'x',1,exp(1))5sym x;s=symsum((-1)^(x+1)/x,1,Inf)sym y;z=symsum(y^(2*y-1)/(2*y-1),1,Inf)6sym x;f1=(exp(x)+exp(-x))/2;f2=sqrt(x^3-2*x+1);taylor(f1,x,5,0)taylor(f2,x,6,0)7syms x y a;x=solve('x^3+a*x+1=0','x')x=solve('sin(x)+2*cos(x)-sqrt(x)=0','x')[x y]=solve('log(x/y)=9','exp(x+y)=3','x','y')8syms n;[x,y]=dsolve('x*(D2y)+(1-n)*(Dy)+y=0','y(0)=0','Dy(0)=0','x') 思考练习2syms x B1 B2 a bs1=2*((cos(x))^2)-(sin(x))^2;s2=sin(B1)*cos(B2)-cos(B1)*sin(B2);s3=sqrt((a+sqrt(a^2-b))/2)+sqrt((a-sqrt(a^2-b))/2); s4=(4*x^2+8*x+3)/(2*x+1);h1=simplify(s1)h2=simplify(s2)h3=simplify(s3)h4=simplify(s4)3syms x a;f=abs(x)/x;limit(f,x,0,'left')f=(x+a/x)^x;limit(f,x,inf)4syms x y mf=sqrt(x+sqrt(x+sqrt(x)));m=diff(f,'x')diff(m,'x')syms x y;f=x+y-sqrt(x^2+y^2);z1=diff(f,x)z2=diff(f,y)5syms x y;f=x+y-sqrt(x^2+y^2);z1=diff(f,x)z2=diff(f,y)sym x;f=1/(asin(x)^2*(1-x^2)^(1/2));int(f)6syms xf=1/(1+x);int(f,0,4)sym x;f=x^3*sin(x)^2/(x^6+2*x^4+1);int(f,-1,1)sym x;f=x^3*sin(x)^2/(x^6+2*x^4+1);int(f,-1,1)7syms ns=symsum(1/4^n,1,inf)sym n;s=symsum(((n+1)/n)^(1/2),1,inf)eval(y)8syms xf=tan(x);taylor(f,x,3,0)syms xf=sin(x)^2;taylor(f,x,5,0)9syms xx=solve('log(1+x)-5/(1+sin(x))=2','x')syms x y z[x y z]=solve('4*x^2/(4*x^2+1)=y','4*y^2/(4*y^2+1)=z','4*z^2/(4*z^2+1)=x','x','y','z') 10[x ,y]=dsolve('Dx=3*x+4*y','Dy=5*x-7*y','x(0)=0','y(0)=1','t')。

(完整word版)MATLAB程序设计教程(第二版)课后答案

(完整word版)MATLAB程序设计教程(第二版)课后答案

MATLAB第二版课后答案unit3—8 unit3实验指导1、 n=input('请输入一个三位数:');a=fix(n/100);b=fix((n-a*100)/10);c=n-a*100-b*10;d=c*100+b*10+a2(1)n=input('请输入成绩’);switch ncase num2cell(90:100)p='A';case num2cell(80:89)p='B';case num2cell(70:79)p=’C';case num2cell(60:69)p='D';otherwisep='E';endprice=p(2)n=input(’请输入成绩');if n〉=90&n〈=100p='A’;elseif n>=80&n<=89p='B';elseif n〉=70&n<=79p=’C’;elseif n>=60&n<=69p='D';elsep='E';endprice=p(3)tryn;catchprice='erroe'end3n=[1,5,56,4,3,476,45,6,3,76,45,6,4,3,6,4,23,76,908,6]; a=n(1);b=n(1);for m=2:20if n(m)>aa=n(m);elseif n(m)<bb=n(m);endendmax=amin=b法2n=[1,5,56,4,3,476,45,6,3,76,45,6,4,3,6,4,23,76,908,6];min=min(n)max=max(n)4b=[—3.0:0.1:3.0];for n=1:61a=b(n);y(n)=(exp(0.3*a)-exp(—0。

matlab程序设计与应用第二版习题答案

matlab程序设计与应用第二版习题答案

matlab程序设计与应用第二版习题答案Matlab程序设计与应用第二版习题答案Matlab是一种强大的数学软件,广泛应用于科学计算、数据分析和工程设计等领域。

《Matlab程序设计与应用》是一本经典的教材,对于学习和掌握Matlab编程语言具有重要的意义。

本文将为大家提供《Matlab程序设计与应用第二版》中部分习题的答案,帮助读者更好地理解和应用Matlab。

第一章:Matlab基础1.1 基本操作1. a = 3; b = 4; c = sqrt(a^2 + b^2); disp(c);2. x = linspace(-pi, pi, 100); y = sin(x); plot(x, y);3. A = [1 2 3; 4 5 6; 7 8 9]; B = [9 8 7; 6 5 4; 3 2 1]; C = A + B; disp(C);1.2 控制结构1. for i = 1:10disp(i);end2. n = 0; sum = 0; while sum < 100n = n + 1;sum = sum + n;enddisp(n);3. x = 5; if x > 0disp('x is positive');elseif x < 0disp('x is negative');elsedisp('x is zero');end第二章:向量和矩阵运算2.1 向量运算1. A = [1 2 3]; B = [4 5 6]; C = A .* B; disp(C);2. A = [1 2 3]; B = [4 5 6]; C = A ./ B; disp(C);3. A = [1 2 3]; B = [4 5 6]; C = dot(A, B); disp(C);2.2 矩阵运算1. A = [1 2 3; 4 5 6]; B = [7 8; 9 10; 11 12]; C = A * B; disp(C);2. A = [1 2 3; 4 5 6]; B = [7 8; 9 10; 11 12]; C = B * A; disp(C);3. A = [1 2 3; 4 5 6]; B = [7 8; 9 10; 11 12]; C = A .* B; disp(C); 第三章:函数和脚本文件3.1 函数1. function y = myfunc(x)y = x^2 + 3*x + 2;end2. function [y1, y2] = myfunc(x1, x2)y1 = x1^2 + 3*x1 + 2;y2 = x2^2 + 3*x2 + 2;end3. function [y1, y2] = myfunc(x)y1 = x^2 + 3*x + 2;y2 = sin(x);end3.2 脚本文件1. x = linspace(0, 2*pi, 100); y = sin(x); plot(x, y);2. x = linspace(-10, 10, 100); y = x.^2 + 3*x + 2; plot(x, y);3. x = linspace(0, 2*pi, 100); y1 = sin(x); y2 = cos(x); plot(x, y1, x, y2);通过以上习题的答案,读者可以对Matlab程序设计的基本语法和常用函数有一个初步的了解。

MATLAB程序设计与应用第二版课后题答案 2

MATLAB程序设计与应用第二版课后题答案 2

第二章3.设矩阵A为A=[24 23 9 21 6;65 74 24 11 21;34 5 98 75 21;8 42 42 53 121;43 21 45 64 21];(1)B=A(2:5,1:2:5)B =65 24 2134 98 218 42 12143 45 21(2)A(7)=[]A =24 65 34 8 43 23 5 42 21 9 24 98 42 45 21 11 75 53 64 6 21 21 121 21(3)A+30(4)size(A);ndims(A)(5)题目有误(6)reshape(x,3,4)(7)abs(x)(8)char(x)4. L1 =0 0 0 0 1 0 0 0 0L2 =1 1 1 1 1 0 0 0 0L3 =0 0 0 1 1 1 0 0 0L4 =4 5 65.(1)B=A(1:3,:)C=A(:,1:2)D=A(2:4,3:4)E=B*CB =23.0000 10.0000 -0.7780 041.0000 -45.0000 65.0000 5.000032.0000 5.0000 0 32.0000C =23.0000 10.000041.0000 -45.000032.0000 5.00006.0000 -9.5400D =65.0000 5.00000 32.000054.0000 3.1400E =1.0e+003 *0.9141 -0.22391.20802.71231.1330 -0.2103(2)E<Dans =0 10 00 1E&Dans =1 10 11 1E|Dans =1 11 11 1~D|~Eans =0 01 00 0find(A>=10&A<25)ans =156.all(A)ans =any(A)ans =1isnan(A)ans =0 1 0 0 0 0 0isinf(A)ans =0 0 1 1 0 0 0isfinite(A)ans =1 0 0 0 1 1 17.A(1).x1=’学号’;A(1).x2=’姓名’;A(1).x3=’专业’;A(1).x4.x41=’成绩1’;………. A(2).x1=’学号’;A(2).x2=’姓名’;A(2).x3=’专业’;A(2).x4.x41=’成绩1’;………. A(3).x1=’学号’;A(3).x2=’姓名’;A(3).x3=’专业’;A(3).x4.x41=’成绩1’;………. A(4).x1=’学号’;A(4).x2=’姓名’;A(4).x3=’专业’;A(4).x4.x41=’成绩1’;………. A(5).x1=’学号’;A(5).x2=’姓名’;A(5).x3=’专业’;A(5).x4.x41=’成绩1’;……….8.(1)size(B)ans =2 2ndims(B)ans =2(2)B(2)ans =[3x3 doubleB(4)ans ={3x3 cell}(3)B(3)=[]B =[1] [3x3 double] {3x3 cell}B{3}=[]B =[1] [3x3 double] []第三章1.(1)A=eye(3)(2) A=100+100*rand(5,6)(3)A=1+sqrt(0.2)*randn(10,50)(4)B=ones(size(A))(5)A+30*eye(size(A))(6)B=diag(diag(A))2.B=rot90(A)C=rot90(A,-1)3.B=inv(A) ;A的逆矩阵C=det(A) ;A的行列式的值D=A*BE=B*AD=E 因此A与A-1是互逆的。

matlab程序设计(第二版)课后作业答案

matlab程序设计(第二版)课后作业答案

一、实验结果:1、利用函数eye,ones,zeros,rand,randn 函数分别产生首先编写脚本函数如下:a1=eye(3)a2=eye(15,8)b1=ones(3)b2=ones(15,8)c1=zeros(3)c2=zeros(15,8)d1=2*rand(3,3)-1d2=2*randn(3,3)+1r1=2*rand(15,8)-1r2=2*randn(15,8)+12、使用函数diag和reshape函数:编写脚本:a1=[8 -7 2];a2=diag(a1);a3=fliplr(a2);a4=[5 3];a5=diag(a4,-1);a6=fliplr(a5);a=a3+a6a1=reshape(a,1,9)b1=[4 5 7];b2=diag(b1);b3=fliplr(b2);b4=[2 0 8];b5=diag(b4);b=b3+b5b6=reshape(b,1,9)3、直接在工作空间里输入:a=5-round(100*rand(50,2))/104、脚本文件:a=[-pi:2*pi/360:pi];y1=sin(a)y2=cos(a)5.、编写脚本:A=rand(10)b=A>0.6[i,j,v]=find(b)c=sum(v)6、编写脚本:A=randn(10)b=-0.5<A<0.5[i,j,v]=find(b);c=sum(v)7、编写实现表中功能的语句:if and(a<1,b<=0.5)语句1elseif and(a<1,b>0.5)语句2elseif and(a>=1,b<=0.5)语句3elseif and(a>=1,b>0.5)语句4elsedisp('error')end8、编写脚本如下:A=2*rand(3)b=A>1c=A.*b;[i,j,v]=find(c);v9、编写脚本函数:A=101*rand(100,3)b=A>100;c=A.*b;[i,j,d]=find(c);d10、为节约空间,用5*5的矩阵来模拟100*100的矩阵:编写脚本函数如下:A=[0 2 0 3 0;0 0 0 0 0;0 8 0 5 0;0 4 0 5 0;0 4 0 2 0]b=any(A);[i,j,v]=find(1-b);A(:,j)=[];B=A';c=any(B);[i,j,v]=find(1-c);B(:,j)=[];A=B'一、实验结果:1、输入脚本函数:x=0:pi/50:2*pi;k=[1 26 51 76 101];x(k)=[];figure(1)subplot(2,2,1)plot(x,sin(x)),grid onsubplot(2,2,2)plot(x,cos(x)),grid onsubplot(2,2,3)plot(x,tan(x)),grid onsubplot(2,2,4)plot(x,cot(x)),grid on2、分别利用title函数给图形加上标题,用text函数给坐标系中的建立文本对象,可将字符串放在图形的指定位置,用xlabel、ylabel函数添加x、y轴的标记,用legend 函数给图形加上插图说明。

matlab第二版习题答案

matlab第二版习题答案Matlab是一种强大的数学软件工具,被广泛应用于科学计算、数据分析和工程设计等领域。

对于学习和掌握Matlab的人来说,习题是不可或缺的一部分。

本文将为大家提供Matlab第二版习题的答案,帮助读者更好地理解和应用Matlab。

第一章:基本操作1.1 Matlab的启动和退出启动Matlab的方法有多种,可以通过桌面图标、命令行或者启动器来打开Matlab。

退出Matlab可以直接关闭窗口或者使用命令"exit"。

1.2 Matlab的基本语法Matlab的基本语法与其他编程语言相似,包括变量的定义、运算符的使用、条件语句和循环语句等。

例如,定义一个变量x并赋值为5可以使用语句"x = 5;"。

1.3 Matlab的数据类型Matlab支持多种数据类型,包括数值型、字符型和逻辑型等。

数值型可以是整数或者浮点数,字符型用单引号或双引号表示,逻辑型只有两个值true和false。

第二章:向量和矩阵操作2.1 向量的定义和运算向量是一维数组,可以通过一对方括号来定义。

Matlab提供了丰富的向量运算函数,如加法、减法、乘法和除法等。

2.2 矩阵的定义和运算矩阵是二维数组,可以通过方括号和分号来定义。

Matlab提供了矩阵的加法、减法、乘法、转置和求逆等运算。

2.3 矩阵的索引和切片可以使用索引和切片来访问矩阵中的元素。

索引从1开始,可以使用冒号表示全部元素。

切片可以用来选择矩阵的一部分。

第三章:函数和脚本文件3.1 函数的定义和调用函数是一段独立的代码块,可以接受输入参数并返回输出结果。

在Matlab中,函数的定义以关键字"function"开头,调用函数使用函数名和参数。

3.2 脚本文件的编写和运行脚本文件是一系列Matlab语句的集合,可以保存为.m文件。

通过运行脚本文件,可以一次性执行多个语句,提高效率。

第四章:图形绘制和数据可视化4.1 图形绘制函数Matlab提供了丰富的图形绘制函数,可以绘制线图、散点图、柱状图等。

MATLAB程序设计及应用(第二版)课后实验答案

Matlab 课后实验题答案实验一 MATLAB 运算基础1.先求下列表达式的值,然后显示 MATLA 工作空间的使用情况并保存全部变量。

0.3a 0.3ae e0.3sin (a 0.3) ln(1)Zi2sin85 0 1 e 2Z 211n(x .1 x 2),其中 x22i0.45Z 32t20 t 1(4) z t2 1 1 t 2,其中t =0::t22t 1 2 t 3解:2.已知:12 34 4 1 3 13.0, 2.9,川,2.9,3.0A 34 7 87 ,B 2 0 33 65 7 3 2 7求下列表达式的值:(1)A+6*B和A-B+I (其中I为单位矩阵)(2)A*B 和 A.*B(3)A A3 和 A.A3(4)A/B 及B\A(5)[A,B]和[A([1,3],:);BA2]解:AA3A.A3A/BB\A[A,B][A([1,3],:);BA2]3.设有矩阵A和B1 2 3 4 5 3 0 166 7 8 9 10 17 6 9A 11 12 13 14 15 ,B 0 23 416 17 18 19 20 9 7 021 22 23 24 25 4 13 11(1)求它们的乘积Co(2)将矩阵C的右下角3X 2子矩阵赋给D(3)查看MATLA工作空间的使用情况。

解:.运算结果:E=(reshape(1:1:25,5,5))';F二[3 0 16;17 -6 9;0 23 -4;9 7 0;4 1311];C= E*FH=C(3:5,2:3)C =93 150 77258 335 237423 520 397588 705 557753 890 717 H =520 397705 557890 7174.完成下列操作:(1)求[100,999]之间能被21整除的数的个数。

(2)建立一个字符串向量,删除其中的大写字母解: (1)结果:m=100:999;n=fin d(mod(m,21)==0);len gth( n)ans =43(2).建立一个字符串向量例如:ch二'ABC123d4e56Fg9:则要求结果是:ch二'ABC123d4e56Fg9:k=fi nd(ch>='A'&ch<='Z');ch(k)=[]ch =123d4e56g9实验二MATLAB 矩阵分析与处理1.设有分块矩阵AO33 R32'其中E R O S分别为单位矩阵、解:M 文件如下;随机矩阵、零矩阵和对角阵,试通过数值计算验证AE R2RSO S 2B Fditor - D TI T it L^d?tEBB2. 产生5阶希尔伯特矩阵H 和5阶帕斯卡矩阵P,且求其行列式的 值Hh 和Hp 以及它们的条件数Th 和Tp ,判断哪个矩阵性能更好。

MATLAB数学实验第二版课后练习题含答案

MATLAB数学实验第二版课后练习题含答案课后练习题MATLAB数学实验第二版的课后练习题如下:第一章课后练习题1.编写MATLAB程序,计算并输出下列公式的结果:y = \\frac{1}{\\sqrt{2\\pi\\sigma^2}} e^{-\\frac{(x-\\mu)^2}{2\\sigma^2}}其中,x, $\\mu$, $\\sigma$ 分别由用户输入。

要求输出结果精确至小数点后两位。

答案如下:x=input('请输入 x 的值:');mu=input('请输入 mu 的值:');sigma=input('请输入 sigma 的值:');y=1/sqrt(2*pi*sigma^2) *exp(-(x-mu)^2/ (2*sigma^2));fprintf('y = %.2f\', y);2.编写MATLAB程序,求解下列方程的解:4x + y = 11\\\\x + 2y = 7答案如下:A= [4,1;1,2];B= [11;7];X=inv(A) *B;fprintf('x = %.2f, y = %.2f\', X(1), X(2));第二章课后练习题1.编写MATLAB程序,计算下列多项式的值:P(x) = x^4 - 2x^3 + 3x^2 - x + 1其中,x 由用户输入。

要求输出结果精确至小数点后两位。

答案如下:x=input('请输入 x 的值:');y=x^4-2*x^3+3*x^2-x+1;fprintf('P(%.2f) = %.2f\', x, y);2.编写MATLAB程序,绘制下列函数的图像:f(x) = \\begin{cases} x + 1, & x < 0 \\\\ x^2, & 0 \\leq x < 1 \\\\ 2x - 1, & x \\geq 1 \\end{cases}答案如下:x=-2:0.01:2;y1=x+1;y2=x.^2.* ((x>=0) & (x<1));y3=2*x-1;plot(x,y1,x,y2,x,y3);legend('y1 = x + 1','y2 = x^2','y3 = 2x - 1');总结本文提供了《MATLAB数学实验第二版》的部分课后练习题及其答案。

MATLAB程序设计及应用(第二版)课后实验答案

MATLAB程序设计及应⽤(第⼆版)课后实验答案Matlab 课后实验题答案实验⼀ MATLAB 运算基础1. 先求下列表达式的值,然后显⽰MATLAB ⼯作空间的使⽤情况并保存全部变量。

(1) 0122sin851z e=+ (2) 221ln(1)2z x x =++,其中2120.455i x +??=??-?? (3) 0.30.330.3sin(0.3)ln , 3.0, 2.9,,2.9,3.022a a e e az a a --+=++=-- (4) 2242011122123t t z t t t t t ?≤,其中t =0:0.5:2.5 解:M ⽂件:z1=2*sin(85*pi/180)/(1+exp(2))x=[2 1+2*i;-.45 5];z2=1/2*log(x+sqrt(1+x^2)) a=-3.0:0.1:3.0;z3=(exp(0.3.*a)-exp(-0.3.*a))./2.*sin(a+0.3)+log((0.3+a)./2) t=0:0.5:2.5;z4=(t>=0&t<1).*(t.^2)+(t>=1&t<2).*(t.^2-1)+(t>=2&t<3) .*(t.^2-2*t+1)2. 已知:1234413134787,2033657327A B --==-求下列表达式的值:(1) A+6*B 和A-B+I (其中I 为单位矩阵) (2) A*B 和A.*B (3) A^3和A.^3 (4) A/B 及B\A(5) [A,B]和[A([1,3],:);B^2] 解:M ⽂件:A=[12 34 -4;34 7 87;3 65 7];B=[1 3 -1;2 0 3;3 -2 7]; A+6.*BA-B+eye(3) A*B A.*B A^3 A.^3 A/B B\A [A,B][A([1,3],:);B^2]3. 设有矩阵A 和B1234166789101769,111213141502341617181920970212223242541311A B-???==-???(1) 求它们的乘积C 。

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matlab第二版课后习题答案
《MATLAB第二版课后习题答案》
MATLAB是一种强大的数学软件,被广泛应用于工程、科学和金融等领域。

《MATLAB第二版》是一本经典的教材,为了帮助学生更好地掌握MATLAB的使用,书中提供了大量的课后习题。

下面我们将为大家总结一些MATLAB第二版课后习题的答案,希望能对大家的学习有所帮助。

1. 第一章课后习题答案
第一章主要介绍了MATLAB的基本操作,包括变量的定义、矩阵的运算、函数的使用等。

在课后习题中,有一道题目是要求计算一个矩阵的逆矩阵。

答案是使用MATLAB中的inv函数,将原矩阵作为参数传入即可得到逆矩阵。

2. 第二章课后习题答案
第二章介绍了MATLAB中的绘图功能,包括二维和三维图形的绘制。

有一道课后习题是要求绘制一个正弦曲线和余弦曲线,并在同一张图上显示。

答案是使用MATLAB中的plot函数,分别绘制正弦曲线和余弦曲线,并使用legend函数添加图例。

3. 第三章课后习题答案
第三章介绍了MATLAB中的控制流程,包括if语句、for循环和while循环等。

有一道课后习题是要求编写一个程序,计算1到100之间所有偶数的和。

答案是使用for循环遍历1到100之间的所有数,判断是否为偶数并累加。

通过以上几个例子,我们可以看到MATLAB第二版课后习题的答案涵盖了各种基本和高级的操作,对于学习MATLAB是非常有帮助的。

希望大家在学习MATLAB的过程中能够多加练习,掌握更多的技巧和方法。

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