限时训练(1)
限时训练1
高三物理限时训练一班别_______________ 姓名_________________ 座号____________________ 1. 下列关于速度的说法正确的是： ( )A ．速度是描述物体位置变化的物理量B ．速度方向就是物体运动的方向C ．位移方向和速度方向一定相同D ．平均速度的大小就是平均速率2．某人爬山，从山脚爬上山顶，然后又从原路返回到山脚，上山的平均速率为v 1，下山的平均速率为v 2，则往返的平均速度的大小和平均速率是( )A.v 1＋v 22， v 1＋v 22B.v 1－v 22， v 1－v 22C ．0，v 1－v 2v 1＋v 2 D ．0， 2v 1v 2v 1＋v 23．一艘船以恒定的速率，往返于上、下游两码头之间．如果以时间t 1和t 2分别表示水的流速较小和较大时船往返一次所需的时间，那么，两时间的长短关系为( )A ．t 1＝t 2B ．t 1>t 2C ．t 1<t 2D ．条件不足，不能判断4．下表是四种交通工具的速度改变情况，下列说法正确的是( )A.C ．③的速度变化最快 D ．④的末速度最大，但加速度最小 5.一个质点做运动方向不变的直线运动，加速度的方向始终与速度方向相同，但加速度的大小逐渐减小直至为零，在此过程中( )A.速度逐渐减小，当加速度减小到零时，速度达到最小B.速度逐渐增大，当加速度减小到零时，速度达到最大C.位移逐渐增大，当加速度减小到零时，位移将不再增加D.位移逐渐减小，当减速度减小到零时，位移达到最小6．一物体做匀变速直线运动，初速度为15 m/s ，方向向东，第5 s 末的速度为10m/s ，方向向西，则第几秒开始物体向西运动（ ）A ．第2sB ．第4sC ．第9sD ．第15s7． 2008年9月25日晚21点10分，我国在九泉卫星发射中心将我国自行研制的“神舟7号”宇宙飞船成功地送上太空，飞船绕地球飞行一圈时间为90分钟．则( )A ．“21点10分”和“90分钟”前者表示“时刻”后者表示“时间”B ．卫星绕地球飞行一圈，它的位移和路程都为零C ．卫星绕地球飞行一圈平均速度为零，但它在每一时刻的瞬时速度都不为零D ．地面卫星控制中心在对飞船进行飞行姿态调整时可以将飞船看作质点8.一质点做匀加速直线运动，第三秒内的位移2m，第四秒内的位移是2.5m，以下说法中正确的是（）A．这两秒内平均速度是2.25m/s B．第三秒末即时速度是2.50m/sC．质点的加速度是0.125m/s2 D．质点的加速度是0.5m/s29. 一辆汽车从原点O由静止出发沿x轴做直线运动，为研究汽车的运动而记下它的各时刻(1)(3)汽车在第4秒内的平均速度为多大？10．一辆汽车沿平直公路从甲站开往乙站，起动加速度为2m/s2，加速行驶5秒，后匀速行驶2分钟，然后刹车，滑行50m，正好到达乙站，求汽车从甲站到乙站的平均速度？解析：(1)v 2＝3m/s (2)a ＝Δv ＝4－23－1m/s 2＝1m/s 2(3)Δx 4＝3.5m ，t ＝1s ，v 4＝Δx 4t 4＝3.5m/s.解析：起动阶段行驶位移为： s 1=2121at ……（1） 匀速行驶的速度为： v = at 1 ……（2） 匀速行驶的位移为： s 2 =vt 2 ……（3） 刹车段的时间为： s 3 =32t v……（4） 汽车从甲站到乙站的平均速度为：v =s m s m s m t t t s s s /44.9/1351275/10120550120025321321==++++=++++。
2020高考英语江苏专用版考前冲刺5周限时练辑：限时训练(一) Word版含解析
限时训练(一)Ⅰ.单项填空1.Without the wise leadership of the Party，it hard to achieve the GDP growth target for 2022.A.would have beenB.would beC.wereD.had been答案 B解析考查虚拟语气。
句意为：要是没有党的英明领导，很难实现2022年国内生产总值增长的目标。
此处without短语相当于虚拟条件句，根据题干中的“2022”判断是对将来的虚拟，主句用would＋do的形式，故B项正确。
2.Parents’top priority is to help their kids develop the ability to show in their choices of friends.binationB.admirationC.inspirationD.discrimination答案 D解析考查名词词义辨析。
combination结合；admiration钦佩；inspiration灵感；discrimination 区别，识别。
句意为：父母的首要任务是帮助他们的孩子发展在选择朋友时的识别能力。
根据句意可知D项正确。
3.As Emerson puts it，we travel the world over to find the beautiful，we must carry it with us or we find it not.A.unlessB.untilC.thoughD.because答案 C解析考查连词词义辨析。
句意为：如爱默生所言，我们环游世界是为了寻找美，但是我们必须与美同行才能发现它。
unless除非；until直到；though尽管；because因为。
根据句意可知，这里表示一种让步关系，故选C。
4.I felt like giving up.I probably ，but my Dad whispered，“Come on! You can make it.”A.would haveB.wouldC.shouldD.should have答案 A解析考查过去将来时。
中档题规范限时训练(1)
„14 分
A
∵ AC 平面 AB1D ， OD 平面 AB1D ， 1 ∴ A1C ∥平面 AB1D ． （2） M 为 CC1 的中点． 证明如下： ∵在正三棱柱 ABC A1B1C1 中， BC BB1 ，∴四边形
B1
„„„6 分 „„„7 分
O B D C M C1
BCC1B1 是正方形．
1 π 当且仅当 ＝3tanB 时，B＝ 取“＝”号． tanB 6 又 A－B∈(－ π π π π ， )，则 A－B 的最大值为 ，此时 A＝ ． 2 2 6 3
π 所以，当 A－B 的最大时，A＝ ． 3 2． （1）证明：连接 A1 B ，交 AB1 于点 O , 连接 OD . ∵ O 、 D 分别是 A1 B 、 BC 的中点， ∴ A1C ∥ OD ． „„„3 分
BC CD ， sin CDB sin B
a CD ，∴ CD sin( 45 ) sin 45
a 2 sin( 45 )
„„„„4 分
1 2a 2 cos ∴ S BC CD sin BCD ， 0 90 „„6 分（其中范围 1 分） 2 4 sin( 45 )
S A D 图（1） B
C A 图（2）
B
2
亭湖高级中学 2015 届高三
中档题规范限时训练（1）答案
π π 1 1.解 (1)a·c＝ 3cosA－sinA＝2cos(A＋ )＝1，则 cos(A＋ )＝ ．„„„3 分 6 6 2 π π 7π π π π 因为 A∈(0，π )，则 A＋ ∈( ， )，则 A＋ ＝ ，则 A＝ ． 6 6 6 6 3 6 „„7 分
(2)因为 a//b，所以 3cosA· 3sinB＝sinA·cosB，则 tanA＝3tanB． „9 分 由于 A、B 为三角形内角，则 A、B 只能均为锐角，即 tanA＞0，tanB＞0． tan(A－B) ＝ tanA－tanB 2tanB ＝ 2 ＝ 1＋tanA·tanB 1＋3tan B 2 1 ＋ 3tanB tanB 2 3 ≤ ＝ ， 2 3 3 „12 分
【练习】2021届高三英语下学期限时训练一有详解
高三英语限时训练一总分65分第一部分：阅读理解（共两节，满分30分）第一节（共7个小题：每小题2.5分，满分17.5分）AWhat do the random, scribbled(潦草的)drawings crowding the margins(页边空白)of most high school students’ papers mean? When a student is caught doodling(乱画)in class, he will probably be criticized for daydreaming. But doodling while listening can help with remembering details, rather than implying that the mind is wandering, according to a study published in the scientific journal Applied Cognitive Psychology.In an experiment conducted b y the Medical Research Council’s Cognition and Brain Sciences Unit in Cambridge,40 subjects were asked to listen to a two-minute tape giving several names of people and places. Half of the participants were asked to shade in shapes on a piece of paper at the same time, without paying attention to neatness, while the rest were given no such instructions. After the tape had finished, all participants in the study were asked to recall the names of people and places. The doodlers recalled on average 7.5 names of people and places, compared to only 5.8 by the non-doodlers.“If someone is doing a boring task, like listening to a dull telephone conversation, they may start to daydream.” said study researcher, Professor Jackie Andrade, of the School of Psychology, U niversity of Plymouth. “Daydreaming distracts them from the task, resulting in poorer performance. A simple task, like doodling, may be enough tostop daydreaming without affecting performance on the main task.”“In psychology, tests of memory or attention will often use a second task to selectively block a particular mental process. If that process is important for the main task, then performance will be weakened. But my research suggests that in everyday life doodling may be something we do because it helps to keep us on track with a boring task, rather than being an unnecessary distraction(分心)that we should try to resist doing.” said Andrade.Dan Ware, a social study teacher, used to consider doodling a distraction from learning, but after teaching kids with all personality types he learned scribbling away during lectures helps certain students remember more information. “In my first few years of teaching, I thought, ‘Well, this kid isn’t paying attention. He’s daydreaming.’ But I had some really powerful experiences with students and came to understand in many cases that was their way of focusing, and those students were probably paying more attention than other students.” Ware said.1. What do we know about the participants involved in the experiment?A. Some were asked to note down the information neatly.B. Some were asked to memorize the names they would hear.C. Some were instructed to listen to the tape with full attention.D. Some were instructed to make random drawings on paper.2. Which of the following will both Jackie Andrade and Dan Ware agree with?A. Doodling helps some people focus.B. Doodling makes a dull task interesting.C. Students who doodle perform poorly.D. Students who doodle lack concentration.3. What is the best title of the text?A. Daydreaming Can Sharpen Study SkillsB. Doodling Can Help Memory RecallC. A Wandering Mind Improves ProductivityD. Distractions Harm Academic PerformanceBShyness is the cause of much unhappiness for a great many people. Shy people are anxious and self-conscious; that is, they are concerned about their own appearance and actions too much. Negative thoughts are constantly occurring in their minds: What kind of impression am I making? Do they like me? Do I sound stupid? Am I wearing unattractive clothes?It is obvious that such uncomfortable feelings must affect people unfavorably. A person’s self-concept is reflected in the way he or she behaves and the way a person behaves affects other people’s reactions. In general, the way people think about themselves has a deep effect on all areas of their lives.Shy people, who have low respect, are likely to be passive and easily influenced by others. They need faith that they are doing ＂the right thing＂. Shy people are very sensitive to criticism. It makes them feel inferior(自卑). They also find it difficult to be pleased by praises because they believe they are unworthy of praise. A shy person may respond to a praise with a statement like this one: ＂You’re just saying that to make me feel good. I kn ow it’s not true.＂It is clear that, while self-awareness is a healthy quality, overdoing it is harmful.Can shyness be completely got rid of, or at least reduced? Fortunately, people can overcome shyness with determination since shyness goes hand in hand with lack ofself-respect. It is important for people to accept their weaknesses as well as their strengths. Each one of us has his or her own characteristics. We are interested in our own personal ways. The better we understand ourselves, the easier it becomes to live up to our chances for a rich and successful life.4. The first paragraph is mainly about ____________. .A. the cause of shynessB. the effect of shyness on peopleC. the feelings of shy peopleD. the questions in the minds of shy people5. According to the writer, self-awareness is ____________.A. harmful to peopleB. a weak point of peopleC. the cause of unhappinessD. a good characteristic6. What is the shy people’s reaction to praise?A. They are pleased by it. B They feel it is not true.C. They are very sensitive to it.D. They feel they are worthy of it.7. We can learn from the passage that shyness ____________.A. blocks our chances for a successful lifeB. helps us to live up to our full developmentC. enables us to understand ourselves betterD. has nothing to do with lack of self-respect第二节七选五（共5小题，每小题2.5分，满分12.5分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，选项中有两项为多余选项。
2021届江苏省常州市金沙高级中学高三下学期限时训练(一)英语试题(解析版)
江苏省常州市金沙高级中学2021届高三下学期限时训练（一）英语试题第一部分：阅读理解（共两节，满分30分）第一节（共7个小题：每小题2.5分，满分17.5分）AWhat do the random, scribbled(潦草的)drawings crowding the margins(页边空白)of most high school students’ papers mean? When a student is caught doodling(乱画)in class, he will probably be criticized for daydreaming. But doodling while listening can help with remembering details, rather than implying that the mind is wandering, according to a study published in the scientific journal Applied Cognitive Psychology.In an experiment conducted by the Medical Research Council’s Cognition and Brain Sciences Unit in Cambridge,40 subjects were asked to listen to a two-minute tape giving several names of people and places. Half of the participants were asked to shade in shapes on a piece of paper at the same time, without paying attention to neatness, while the rest were given no such instructions. After the tape had finished, all participants in the study were asked to recall the names of people and places. The doodlers recalled on average 7.5 names of people and places, compared to only 5.8 by the non-doodlers.“If someone is doing a boring task, like listening to a dull telephone conversation, they may start to daydream.” said study researcher, Professor Jackie Andrade, of the School of P sychology, University of Plymouth. “Daydreaming distracts them from the task, resulting in poorer performance. A simple task, like doodling, may be enough to stop daydreaming without affecting performance on the main task.”“In psychology, tests of memory or attention will often use a second task to selectively block a particular mental process. If that process is important for the main task, then performance will be weakened. But my research suggests that in everyday life doodling may be something we do because it helps to keep us on track with a boring task, rather than being an unnecessary distraction(分心)that we should try to resist doing.” said Andrade.Dan Ware, a social study teacher, used to consider doodling a distraction from learning, butafter teaching kids with all personality types he learned scribbling away during lectures helps certain students remember more information. “In my first few years of teaching, I thought, ‘Well, this kid isn’t paying attention. He’s daydreaming.’ But I had some real ly powerful experiences with students and came to understand in many cases that was their way of focusing, and those students were probably paying more attention than other students.” Ware said.1. What do we know about the participants involved in the experiment?A. Some were asked to note down the information neatly.B. Some were asked to memorize the names they would hear.C. Some were instructed to listen to the tape with full attention.D. Some were instructed to make random drawings on paper.2. Which of the following will both Jackie Andrade and Dan Ware agree with?A. Doodling helps some people focus.B. Doodling makes a dull task interesting.C. Students who doodle perform poorly.D. Students who doodle lack concentration.3. What is the best title of the text?A. Daydreaming Can Sharpen Study SkillsB. Doodling Can Help Memory RecallC. A Wandering Mind Improves ProductivityD. Distractions Harm Academic PerformanceBShyness is the cause of much unhappiness for a great many people. Shy people are anxious and self-conscious; that is, they are concerned about their own appearance and actions too much. Negative thoughts are constantly occurring in their minds: What kind of impression am I making? Do they like me? Do I sound stupid? Am I wearing unattractive clothes?It is obvious that such uncomfortable feelings must affect people unfavorably. A person’s self-concept is reflected in the way he or she behaves and the way a person behaves affects other people’s reactions. In general, the way p eople think about themselves has a deep effect on all areas of their lives.Shy people, who have low respect, are likely to be passive and easily influenced by others. They need faith that they are doing ＂the right thing＂. Shy people are very sensitive to criticism. It makes them feel inferior(自卑). They also find it difficult to be pleased by praises because they believe they are unworthy of praise. A shy person may respond to a praise with a statement like this one: ＂You’re just saying that to make me feel good. I know it’s not true.＂It is clear that,. while self-awareness is a healthy quality, overdoing it is harmful.Can shyness be completely got rid of, or at least reduced? Fortunately, people can overcomeshyness with determination since shyness goes hand in hand with lack of self-respect. It isimportant for people to accept their weaknesses as well as their strengths. Each one of us has hisor her own characteristics. We are interested in our own personal ways. The better we understandourselves, the easier it becomes to live up to our chances for a rich and successful life.4. The first paragraph is mainly about ____________.A. the cause of shynessB. the effect of shyness on peopleC. the feelings of shy peopleD. the questions in the minds of shy people5. According to the writer, self-awareness is ____________.A. harmful to peopleB. a weak point of peopleC. the cause of unhappinessD. a good characteristic6. What is the shy people’s reaction to praise?A. They are pleased by it. B They feel it is not true.C. They are very sensitive to it.D. They feel they are worthy of it.7. We can learn from the passage that shyness ____________.A. blocks our chances for a successful lifeB. helps us to live up to our full developmentC. enables us to understand ourselves betterD. has nothing to do with lack of self-respect第二节（共5小题，每小题2.5分，满分12.5分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，选项中有两项为多余选项。
高一上学期语文 限时训练 一含答案
高一语文第一次限时训练一、客观题1．下列词语中加点字的读音，完全正确的一项是（）A．彷（páng）徨青荇（xìng）遒劲（jìn）颓圮（qǐ）B．长篙（gāo）漫溯（sù）青苔（tāi）火钵（bō）C．愤懑（mǎn）冰屑（xuè）麦糟（zāo）叱（chì）骂D．袒露（lù）隽（juàn）永碣（jié）石忸怩（ní）2．下列词语中，没有错别字的一组是（）A．凄婉漂泊褒扬击浊扬清B．斑斓笙萧抨击剑拔驽张C．榆阴气概瓦菲意气风发D．讴歌扭扣寥廓天伦之乐3．下列句子中，成语使用恰当的一句是（）A．袁弘表示，世上没有天生或是一蹴而就的坏人，自己会在饰演的这一版本的杨康中加深刻画其心理变化的过程，将其内心的迷茫和矛盾展现出来。
B．中日双方首脑同时以更加明确清晰的语言表示，解决东海共同开发问题倚马可待，现在剩下的可能就是技术层面或者事务层面的问题了。
C．日本捕鲸者不顾国际社会谴责，把非法捕捉到的鲸鱼屠宰、清洗、销售，以牟取暴利，血腥的一幕令人惨不忍睹。
D．房地产市场对宏观调控“免疫”，更深层的原因是市场制度存在重大的制度缺陷，若不从制度改革入手釜底抽薪，恐怕再多的“组合拳”和“重拳”都难以“拳拳到肉”。
4．下列各句中，没有语病的一句是（）A．由于这种思想上的局限性，使得韩愈的文体改革运动仅仅以模仿先秦诸子的散文为目标，而不能像先秦诸子和司马迁那样以接近人民口语为目标来创造新的散文。
B．这种如鱼得水似的悠闲，让后世的学者在感叹中国人融入西方社会的艰难时，不得不叹服徐志摩是“最适应西方生活的中国文人”。
C．在这一时期，毛泽东同志在长沙组织了湖南学生联合会、新民学会，开办了平民夜校、文化书社和湖南自修大学，参加了反对袁世凯称帝，领导了驱逐张敬尧等军阀。
D．行政处罚在程序上的公正、合理与否，将直接影响行政处罚的内容的有效和成立。
限时训练,判卷分析卷的好处
限时训练,判卷分析卷的好处一、限时训练的好处（1）限时训练可以促使更好地完成任务，有一定的紧张感，成绩往往会比没有紧张感要高，但切记也不要太紧张。
（2）主要是一种模拟，培养题感，控制时间，学会取舍。
（3）能加强训练效果，能把握时间，掌握主动。
二、判卷分析卷的好处（1）第一：知识上的查漏补缺。
所谓查漏补缺，就是找到在知识学习上的薄弱环节，及时采取有效措施进行补充完善，让知识的吸收全面化、系统化、有效化。
有效巩固薄弱知识，可以通过多种方式来做。
比如说，英语学科可以制作单词卡片，暑假辅导老师建议：自己用稍硬一些的纸制作成便于携带的卡片，然后将英语单词写在卡片上，这样可以做到随时记忆难记的单词，提高记忆效率。
还可以建立各个学科的“错题集”，尤其是瘸腿学科，也可以将老师讲过的一些典型的、思路巧妙的、对自己有所启发、让自己有所领悟的例题，整理上去，但要记住，平时要及时整理和总结，多看、多思、多问！这样可以快速弥补知识上的漏洞。
一本或数本“错题集”记满以后，可以再重新整理，自己会做的可以删去，不会做的可以保留，如此反复，直至完全掌握！（2）第二：注重学习方法和习惯的调整。
其实考试不仅仅是考察知识的掌握程度，也在一定程度上检验学习方法或某方面的能力。
暑假辅导老师指出：通过考试也常常反映出来容易粗心、做题方法不对、不会审题、检查等方面的不足，弥补这些不足对学习来说也是很重要的。
读题千万不能走马观花、一目十行，更不能大意；要一个字一个字地去读，去体会，去分析。
无论是平时还是考试，我们都需要找到自己在学习方法或习惯方面的不足，及时纠正。
暑假辅导老师提示我们：而大的考试就是一次很好的机遇，因为考试中只有全身心投入，尽全力发挥，才能够客观地反映出问题，比如学习不够踏实认真，容易浮躁特别是看到自己会做的题目沾沾自喜，容易掉以轻心，最终失分。
这些问题背后反映的就是学习习惯与态度的问题，我们要想有针对性地解决，需要在平时注意培养良好的习惯。
高三数学复习限时训练卷1
高三文科数学 限时训练卷１（湖南）班次：_______姓名：_________考号：________8_____{6,8}___________9______9____________10_______6____________**********************************************************************一、选择题：1.复数z=i ·(1+i)(i 为虚数单位)在复平面上对应的点位于A .第一象限B .第二象限C .第三象限D .第四象限2.“1＜x ＜2”是“x ＜2”成立的A.充分不必要条件B.必要不充分条件C.充分必要条件D.既不充分也不必要条件3.某工厂甲、乙、丙三个车间生产了同一种产品，数量分别为120件，80件，60件。
为了解它们的产品质量是否存在显著差异，用分层抽样方法抽取了一个容量为n 的样本进行调查，其中从丙车间的产品中抽取了3件，则n=A .9B .10C .12D .134.已知f （x ）是奇函数，g （x ）是偶函数，且f （－1）+g （1）=2，f （1）+g （－1）=4，则g （1）等于A .4B .3C .2D .15.在锐角∆ABC 中，角A ，B 所对的边长分别为a ，b. 若2asinB=3b ，则角A 等于A .3πB .4πC .6π D .12π 6.函数f （x ）=㏑x 的图像与函数g （x ）=x 2-4x+4的图像的交点个数为A.0B.1C.2D.37.已知正方体的棱长为1，其俯视图是一个面积为1的正方形，侧视图是一个面积A ．B.1二、填空题：８.已知集合{2,3,6,8},{2,3},{2,6,8}U A B ===,则()U C A B ⋂=_____________ ９.执行如图1所示的程序框图，如果输入a=1,b=2,则输出的a 的值为______１０.若变量x,y 满足约束条件28,04,03,x y x y +≤⎧⎪≤≤⎨⎪≤≤⎩则x+y 的最大值为________。
高三英语晚自习限时训练 (1)
高三英语晚自习限时训练【3月31日晚限制：不超过65-70分钟】一、六选四阅读1. Complete the following passage by using the sentences given below. Each sentences can be used only once. Note that there are two more sentences than you need.Can just one person make a difference? You bet! In a community every person counts, and getting involved is not difficult. Take stock of your own talents and interests. Don't wait for someone else to act first. Take the initiative! Once you see what you can accomplish, you'll want to keep going.Here are just a few ways to make a difference in your community. How many more ways can you come up with?Clean up the community. People often throw litter in places where there is already litter. And the problem only becomes worse until someone gets fed up and does something. Could your neighborhood use a cleanup? Neighborhood cleanups are often sponsored by local businesses or schools. But if your community doesn't have a cleanup program, get together with friends to organize one. You could pick up garbage in a larger area twice a year, or you could clean a smaller area every few months.Include the isolated. Do you know anyone who is housebound? Almost all neighborhoods have a few people who have to stay at their homes. These people are often elderly and unable to leave their homes to perform simple tasks. By letting them "borrow" your legs and eyes, you can make them feel included. You can run errands for them like shopping or paying bills. They might like you to read to them if their eyesight is failing. Governments provide some of the services these people need, but programs cannot give them friendship; that's what communities are for!Reading clubs are popular all over Europe and North America. Members might read at home to prepare for discussion, or they might read aloud to each other and talk about what they just read. Either way, a book or article can spark lively discussion and this often challenges people to take action.A. Cleaning your community will have a positive effect on others in society.B. They find a need or an issue you really care about.C. But they belong to the community, too.D. Living in a clean neighborhood will be its own reward.E. Don't hesitate to take part in the community's activity.F. Round up some readers.二、语法填空阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。
高一限时训练1定稿
高一化学限时训练（一）一、单项选择题1．在盛放浓硫酸的试剂瓶的标签上应印有下列警示标记中的2．某同学用托盘天平称量锌粒24.4g（1g以下用游码），他把锌粒放在右盘，砝码放在左盘，实际质量为A．24.4g B．25.5g C．23.6g D．24g3. 下列实验操作中正确的是A.手持试管给试管里的物质加热B.将鼻孔凑到集气瓶口闻气体的气味C.酒精灯的火焰可以用嘴吹灭D.一般用药匙或镊子取用固体药品4. 下列仪器用酒精灯加热时，需垫石棉网的是①烧杯②坩埚③锥形瓶④蒸发皿⑤试管⑥烧瓶A．②④⑤B．①②⑥C．③④⑥D．①③⑥5．下列分离或提纯混合物的方法正确的是A．在除去生石灰中的石灰石时，加水后进行过滤B．用过滤的方法除去碘水中的碘C．用乙醇萃取碘水中的碘D．用溶解过滤蒸发的方法除去固体BaCl2中的BaSO4 6．有人从市场上购得一瓶“纯净水”，喝过之后感觉有点苦涩味，怀疑是由深层地下水冒充的伪劣产品。
已知地下水含Ca2+、Mg2+等离子，家庭中的下列物品可用于验证他的推测的是A．纯碱B．食盐C．食醋D．食糖7．对下列实验过程的评价，正确的是A．某固体中加入稀盐酸，产生了无色气体，证明该固体中一定含有碳酸盐B．某溶液中滴加BaCl2溶液，生成白色沉淀，证明一定含有SO42-C．某无色溶液滴入紫色石蕊试液显红色，该溶液一定显碱性D．验证烧碱溶液中是否含有Cl-，先加稀硝酸除去OH-，再加入AgNO3溶液，有白色沉淀，证明含Cl-8．过滤后的食盐水仍含有可溶性的CaCl2、MgCl2、Na2SO4等杂质，通过如下几个实验步骤，可制得纯净的食盐水：①加入稍过量的Na2CO3溶液；②加入稍过量的NaOH溶液；③加入稍过量的BaCl2 溶液；④滴入稀盐酸至无气泡产生；⑤过滤。
正确的操作顺序是A．③②①⑤④B．①②③⑤④C．②③①④⑤D．③⑤②①④9．提纯含有少量硝酸钡杂质的硝酸钾溶液，可以使用的方法为A．加入过量碳酸钠溶液，过滤，除去沉淀，溶液中补加适量硝酸B．加入过量硫酸钾溶液，过滤，除去沉淀，溶液中补加适量硝酸C．加入过量硫酸钠溶液，过滤，除去沉淀，溶液中补加适量硝酸D．加入过量碳酸钾溶液，过滤，除去沉淀，溶液中补加适量硝酸10．实验室进行过滤和蒸发时，都要用到的仪器是A．烧杯B．玻璃棒C．蒸发皿D．酒精灯11. 某溶液中含有较大量的Cl－、 2CO、OH3-种阴离子，如果只取一次该溶液就能够分别将3种阴离3子依次检验出来，下列实验操作顺序中，正确的是①滴加Mg(NO3)2溶液；②过滤；③滴加AgNO3溶液；④滴加Ba(NO3)2溶液A．①②④②③B．④②①②③C．①②③②④D．④②③②①12. 下列实验操作中错误的是A．用规格为10 mL的量筒量取6 mL的液体B．用药匙或者纸槽把粉末状药品送入试管的底部C．过滤时玻璃棒的末端应轻轻靠在三层的滤纸上D．如果没有试管夹，可以临时手持试管给固体或液体加热13．进行过滤操作应选用的一组仪器是A．玻璃棒、滤纸、烧瓶、漏斗、铁架台B．滤纸、烧杯、试管夹、漏斗、玻璃棒C．漏斗、玻璃棒、烧杯、铁架台、滤纸D．烧杯、酒精灯、试管、铁架台、漏斗二、非选择题14．粗食盐中除含有钙离子、镁离子、硫酸根离子等可溶性杂质外，还含有泥砂等不溶性杂质。
- 1、下载文档前请自行甄别文档内容的完整性，平台不提供额外的编辑、内容补充、找答案等附加服务。
- 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
- 3、如文档侵犯您的权益，请联系客服反馈,我们会尽快为您处理(人工客服工作时间：9:00-18:30)。
限时训练（一）一、 选择题：本大题共12小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1.已知集合{}220P x x x =--…，(){}2log 11Q x x =-…，则()PQ =R ð（ ）.A. ()2,3B. (][),13,-∞-+∞C. (]2,3D. (](),13,-∞-+∞2.若i 为虚数单位，则复数3i 11i-+的模是（ ）. A.5 B. 22 C. 5 D.23.设等差数列{}n a 的前n 项和为n S ，若24924a a a ++=，则9S =（ ）. A. 36 B. 72 C. 144 D. 704. 已知四棱锥P ABCD -的三视图如图所示，则四棱锥P ABCD -的四个侧面中的最大面积为（ ）.A. 3B. 25C. 6D. 85.若连续抛掷两次骰子得到的点数分别为m ，n ，则点(),P m n 在直线4x y +=上的概率是（ ）. A.13 B. 14 C. 16 D. 1126.某程序框图如图所示，执行该程序.若输入24P =，则输出S 的值为（ ）. A. 30 B. 15 C. 45 D. 60222433侧视图俯视图正视图7.已知向量()1,2x =a ，()4,x =-b ，则“2x =”是“⊥a b ”的（ ）.A.充分不必要条件B.必要不充分条件C.充要条件D. 既不充分也不必要条件 8.已知圆222410x y x y ++-+=关于直线()220,ax by a b -+=∈R 对称.则ab 的取值范围是（ ）.A. 10,4⎛⎤ ⎥⎝⎦B. 1,04⎡⎫-⎪⎢⎣⎭C. 1,4⎛⎤-∞ ⎥⎝⎦D. 1,4⎡⎫-+∞⎪⎢⎣⎭9.已知点(),P x y 满足0201x y x y x -⎧⎪-⎨⎪⎩………时，若不等式2x y M +…恒成立，则M 的最小值为（ ）.A. 0B. 1C. 2D. 310.已知正四棱锥的侧棱与底面边长都为32，则这个四棱锥的外接球的表面积为（ ）. A. 12π B. 16π C. 32π D. 36π 11.已知数列{}n a 满足：112a =，前n 项和n S 为()2*n n S n a n =∈N ，则n a 为（ ）. A. ()1n n + B.()11n n + C. ()2n n + D. ()12n n +12.若函数()()[)21,0,131,1,ax x f x ax x ⎧-∈⎪=⎨-∈+∞⎪⎩和()2log g x x =使不等式()()0f x g x ⋅…， 对()0,x ∈+∞恒成立，则实数a 的取值范围是（ ）.A. 31,2⎡⎤⎢⎥⎣⎦B. 10,2⎡⎤⎢⎥⎣⎦C. 11,32⎡⎤⎢⎥⎣⎦D. []0,1n=1,S=0输入P 开始S<P ?S =S+3n n =n +1输出S结束否是二、填空题：本大题共四小题，每小题5分，共20分，把答案填在题中的横线上. 13.设0a >，0b >.若lg a 与lg b 的等差中项为0，则11a b+的最小值是 . 14.已知函数()2211x x f x x ++=+，若()23f a =，则()f a -= . 15.已知双曲线2216436x y -=的焦点为1F ，2F ，点P 在双曲线上，且1260F PF ∠=，则12F PF △的面积为 . 16.给出下列四个命题：①在频率分布直方图中，各个小矩形对应的纵坐标读数之和为1.②某商店售出甲种产品350件，乙种产品150件，为了了解产品的使用满意情况，用分层抽样法从这两种产品中抽取一个容量为n 的样本，已知甲种产品抽到7件，则样本容量n 为10.③学校随意安排甲、乙、丙3位老师在五一节假期间值班.每人值1天，则甲排在乙前的概率为13.④已知函数()21log ,,22f x x x ⎡⎤=∈⎢⎥⎣⎦，若在区间1,22⎡⎤⎢⎥⎣⎦上随机取一点，则使()00f x …的概率为23.其中正确的命题序号为 .限时训练（一）答案部分一、选择题 二、填空题13. 2 14.4315. 363 16. ②④ 解析部分1.解析 解法一：对于P ，解不等式220x x --…，得{}12P x x=-剟.对于Q ，解不等式组1012x x ->⎧⎨-⎩…，得{}13Q x x =<…，可得(){}23R P Q x x =<…ð.故选C.解法二（特殊值检验法）：观察选项，因为1Q -∉，所以排除B ，D 选项. 又因为3P ∉，则3P ∈R ð，且3Q ∈，所以排除A 选项.故选C.2.解析 解法一（模的性质）：22223i 13i 1311051i 1i 211--+====+++.故选A. 解法二（除法公式）：由()()()()3i 11i 3i 124i12i 1i 1i 1i 2---+===+++-，则模为22125+=. 故选A.3.解析 解法一：设公差为d ，则由24924a a a ++=， 得()()()1113824a d a d a d +++++=，即131224a d +=. 所以148a d +=，即58a =.所以()199599722a a S a+⨯===.故选B.解法二：因为()2491591955552324a a a a a a a a a a a a ++=++=++=+==，得58a =.所以95972S a ==. 故选B.题号 1 2 3 4 5 6 7 8 9 10 11 12 答案CABCDAACDDBC4.解析 由几何体的三视图，画出其立体图形P ABCD -，如图所示.由题可知，顶点P 在底面上的投影是边CD 的中点，底面是边长为4AB =，2BC =的矩形.PCD △的高为22325-=，所以侧面PCD △的面积为145252⨯⨯=.两个侧面PAD △，PBC △的面积相等为12332⨯⨯=. 侧面PAB △的面积为()22145262⨯⨯+=.所以四个侧面中的最大面积为6.故选C.5.解析 由题意知(),m n 的取值情况有()1,1，()1,2，…，()1,6；()2,1，()2,2，…，()2,6；…；()6,1，()6,2，…，()6,6，共36种情况.而满足点(),P m n 在直线4x y +=上的取值情况有()1,3，()2,2，()3,1共3种情况.故所求概率313612P ==.故选D. 6.解析 由程序框图可知逐次循环结果分别为：①3S =，2n =；②9S =，3n =；③18S =，4n =；④30S =，5n =； 当第④次循环后3024S P =>=，此时结束循环.从而输出30S =.故选A. 评注 如果P 的值很大，则要找到S 与循环次数n 的关系即()312n n S +=. 7.解析 ⊥a b 的充要条件是0⋅a b =，则有2420x -=，解得2x =±. 故“2x =”是“⊥a b ”充分不必要条件.故选A.8.解析 由已知得圆的标准方程为()()22124x y ++-=， 则圆心为()1,2-.又因为对称轴经过圆心，D C BAP243322所以把圆心坐标()1,2-代入所给对称轴方程得2220a b --+=，即1a b +=. 从而()()21ab a a a a a =-=-+∈R ，由二次函数的性质，可得1,4ab ⎛⎤∈-∞ ⎥⎝⎦.故选C.9.解析 画出满足不等式组的可行域，如图中阴影部分所示，作出直线0:20l x y +=，平移0l .由图可知，当直线1:2l z x y =+经过点D 时，z 取得最大值为2113⨯+=，所以只需要3M …，所以M 的最小值为3.故选D.10.解析 依题意作图，如图所示.由32AB BC CD DA PA PB PC PD ========，可得3PO DO CO AO BO =====，即底面的中心就是外接球的球心.则球的半径为3R =，可得该球的表面积为224π4π336πS R ==⨯=.故选D.11.解析 由已知，当2n …时，()22111n n n n n a S S n a n a --=-=--，则()()22111n n n a n a --=-，即1211211n n n n n n a a a n n n-----==⋅=++312311n n n n a n n n ----⋅⋅=+-323232O DC BAP13D Ol 1l 0x-2y=0x-y=0x=1yx112332111543n n n a n n n ---⋅⋅⋅⋅⋅⋅+-， 又因为112a =，则有()11n a n n =+.当1n =时也符合上式， 所以()()*11n a n n n =∈+N .故选B. 12.解析 ①当()0,1x ∈时， ()2log 0g x x =<.则由()()0f x g x ⋅…，得()210f x ax =-…，所以12a x…. 又因为()0,1x ∈，所以12a …. ②当[)1,x ∈+∞时，()2log 0g x x =….则由()()0f x g x ⋅…，得()310f x ax =-…，所以13a x…. 又因为[)1,x ∈+∞，所以max1133x⎛⎫= ⎪⎝⎭. 要使13a x …恒成立，需13a …. 综合①②，得所求a 的取值范围是11,32⎡⎤⎢⎥⎣⎦.故选C.13.解析 依题意有()()11lg lg lg 022a b ab +==， 则1ab =.从而111122a b a b+⋅=…. 当且仅当1a b ==时取等号.所以11a b+的最小值为2. 14.解析 因为()211x f x x =++，令()21xg x x =+，则()g x 为奇函数.所以当()()213f a g a =+=时，()13g a =-， 从而()()1f a g a -=+-=()1g a -=14133⎛⎫--=⎪⎝⎭. 15.解析 由2216436x y -=，可知8a =，6b =，所以2210c a b =+=. 解法一：由题意作图，如图所示.由正弦定理得12121sin 602F PF S r r =△. 又由余弦定理得，()22212122cos 602r r r r c +-=① 由双曲线的定义得，122r r a -=.由12216r r a -==，得()221216r r -=，2212122256r r rr +-=，所以2212122562r r rr +=+②联立式①，式②得12121256224002r r r r +-⨯=，则12144rr =. 所以121314436322F PF S =⨯⨯=△. 解法二：设2PF x =，由双曲线的定义可得116PF x =+.又1260F PF ∠=，由余弦定理得()()22216201cos602162x x x x ++-==⋅⋅+，解得8413x =-+. 所以()()12184138413sin 603632PF F S =⨯-+⨯+⨯=△.yxr2r 1OF 2F 1P评注 本题作为填空题，可直接利用122363633tan23F PF b S θ===△. 16.解析 对于①，在频率分布直方图中，各个小矩形的面积之和为1，而不是纵坐标读数之和为1，①错；对于②，用分层抽样有7350350150n =+，解得10n =,②对； 对于③，由于甲在乙前和乙在甲前的机会一样，则为12. 也可以列出所有可能情况共6种，易知甲在乙前有3种，则概率为12，③错； 对于④，由函数()00f x …，得20log 0x …，解得[]01,2x ∈.又由函数()f x 的定义域为1,22⎡⎫⎪⎢⎣⎭，故()00f x …的概率为2121322-=-，④对. 综上可知正确的命题为②④.。