10单元测试

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Unit 10 单元测试卷-八年级英语上册(人教版)

Unit 10 单元测试卷-八年级英语上册(人教版)

Unit 10 If you go to the party, you'll have a great time!单元测试卷(解析版)时间:90分钟满分:100分一. 单项选择(每小题1分,共15分)从A.B.C.D四个选项中选择可以填入空白处的最佳答案。

1.We won't go to the Great Wall if it ___________ the day after tomorrow.A.won't rainB.is rainingC.rainsD.doesn't rain【答案】C【解析】句意:如果后天下雨,我们就不去长城了。

根据句意,故选C。

此题考查句子主将从现时态,要特别注意。

2.Don't ___________ jeans to the party.A.put onB.wearC.wearingD.dress【答案】B【解析】A. put on 穿上,动态(穿的动作);B. wear穿上,带上,静态;C. wearing 动名词(don't后接动词原形);D. dress给...穿上,宾语是人;句意:不要穿牛仔裤去晚会。

根据句意,故选B。

此题考查表示穿,戴动词辨析,较易选错项是put on。

3.I was ___________ tired to climb the mountain.A.a littleB.a bitC.muchD.too【答案】D【解析】A. a little 一些,一点;B. a bit一点点;C. much非常,很;D. too太,too...to..太...而不能...。

句意:我太累爬不了这座山。

根据句意,故选D。

要注意too...to...太...而不能...的特殊意义。

4.I ___________ to bed until my granny came back home.A.didn't goB.wentC.had goneD.have gone【答案】A【解析】A. didn't go 不能去,过去时态;B. went去,过去时态;C. had gone已经去了,过去完成时态;D. have gone已经去了,现在完成时态;根据句中“came”可知句子时态是过去时态;not... until固定句型,直到...才...;句意:直到我的奶奶回到家,我才去睡觉。

人教版英语八年级上册第10单元Unit10测试题及答案带听力材料

人教版英语八年级上册第10单元Unit10测试题及答案带听力材料

Unit10 If you go to the party, you'll have a great time!单元测试题一、听力(听力)(共20小题;共20分)一、听力选择(共20小题,计20分)(一)录音中有五个句子,每个句子听一遍,然后从每小题A、B、C中选出适合每个句子的答语。

1. A. I don't mind. B. A knife and fork. C. They like it.2. A. That's right. B. Yes, please. C. My pleasure.3. A. Advertising is everywhere.B. It only costs you 10 dollars.C. Some advertising can be misleading.4. A. Yes, he has. B. Yes, I have. C. Yes, we do.5. A. Yes, I like doing so.B. Yes, I'd like to.C. Please enjoy your meal.(二)录音中有五组对话,每组对话听一遍,然后从每小题A、B、C中选出能回答每个问题的正确答案。

6. What is the cat doing now?A. It is eating fish.B. It is catching a mouse.C. It is sleeping.7. What is the advantage of using e-mail English?A. It can save time and it is easy to use.B. It is easy to use and it can save money.C. It can save time and it is great fun.8. What does Martin think is the best award?A. Vacation.B. Money.C. Flowers.9. Why did Dave feel anxious at the party last night?A. Because he drank too much.B. Because the music was too loud and noisy.C. Because the party lasted too long.10. Where did the man leave his raincoat?A. On the train.B. On the bus.C. At school.(三)录音中有一段对话,听对话两遍,然后从每小题A、B、C中选出能回答每个问题的正确答案。

苏科版初中数学八年级下册《第10章 分式》单元测试卷

苏科版初中数学八年级下册《第10章 分式》单元测试卷

苏科新版八年级下学期《第10章分式》单元测试卷一.选择题(共21小题)1.下列各式中,分式的个数是().A.2B.3C.4D.52.使分式有意义的x的取值范围是()A.x≠1B.x≠2C.x≠1且x≠2D.x可为任何数3.若分式的值为0,则x的值是()A.±3B.﹣3C.3D.04.已知﹣=5,则分式的值为()A.1B.5C.D.5.一件工作,甲单独完成需要a天,乙单独完成需要b天,如果甲、乙二人合作,那么每天的工作效率是()A.a+b B.+C.D.6.不改变分式的值,使分子、分母的最高次项的系数都为正,正确的变形是()A.B.C.D.7.化简的结果是()A.1B.C.D.08.若=﹣,则a﹣2b的值是()A.﹣6B.6C.﹣2D.29.下列分式中,最简分式是()A.B.C.D.10.张萌将分式进行通分,则这两个分式的最简公分母为()A.2(x+y)(x﹣y)B.4(x+y)(x﹣y)C.(x+y)(x﹣y)D.4(x+y)211.计算(a2b)3•的结果是()A.a5b5B.a4b5C.ab5D.a5b612.已知,则的值为()A.1B.0C.﹣1D.﹣213.张阿姨,李阿姨到农贸市场买大米,第一次,张阿姨买了100千克大米,李阿姨买了100元的大米;第二次,张阿姨还是买了100千克大米,李阿姨还是买了100元的大米.下列说法正确的是()A.如果米价下降张阿姨买的合算B.如果米价上涨张阿姨买的合算C.无论米价怎样变化李阿姨买的合算D.无法判断谁买的合算14.已知+=3,则代数式的值为()A.3B.﹣2C.﹣D.﹣15.下列方程是分式方程的是()A.B.C.x2﹣1=3D.2x+1=3x 16.若关于x的分式方程无解,则m的值为()A.﹣1.5B.1C.﹣1.5或2D.﹣0.5或﹣1.5 17.方程=的解是()A.﹣B.C.﹣D.18.用换元法解方程,若设=y,则原方程可化为()A.y2﹣7y+6=0B.y2+6y﹣7=0C.6y2﹣7y+1=0D.6y2+7y+1=0 19.若分式方程有增根,则a的值是()A.﹣2B.0C.2D.0或﹣2 20.小明坐滴滴打车前去火车高铁站,小明可以选择两条不同路线:路线A的全程是25千米,但交通比较拥堵,路线B的全程比路线A的全程多7千米,但平均车速比走路线A时能提高60%,若走路线B的全程能比走路线A少用15分钟.若设走路线A时的平均速度为x千米/小时,根据题意,可列分式方程()A.=15B.=15C.=D.21.甲志愿者计划用若干个工作日完成社区的某项工作,从第三个工作日起,乙志愿者加盟此项工作,且甲、乙两人工效相同,结果提前3天完成任务,则甲志愿者计划完成此项工作的天数是()A.8B.7C.6D.5二.解答题(共7小题)22.下面是售货员与小明的对话:根据对话内容解答下列问题:(1)A、B两种文具的单价各是多少元?(2)若购买A、B两种文具共20件,其中A种文具的数量少于B种文具的数量,且购买总费用不超过260元,共有几种购买方案.23.两列火车分别行驶在两平行的轨道上,其中快车车长100米,慢车车长150米,当两车相向而行时,快车驶过慢车某个窗口(快车车头到达窗口某一点至车尾离开这一点)所用的时间为5秒.(1)求两车的速度之和及两车相向而行时慢车驶过快车某个窗口(慢车车头到达窗口某一点至车尾离开这一点)所用的时间;(2)如果两车同向而行,慢车的速度不小于8米/秒,快车从后面追赶慢车,那么从快车的车头赶上慢车的车尾开始到快车的车尾离开慢车的车头所需时间至少为多少秒?24.某工厂计划生产一种创新产品,若生产一件这种产品需A种原料1.2千克、B种原料1千克.已知A种原料每千克的价格比B种原料每千克的价格多10元.(1)为使每件产品的成本价不超过34元,那么购入的B种原料每千克的价格最高不超过多少元?(2)将这种产品投放市场批发销售一段时间后,为拓展销路又开展了零售业务,每件产品的零售价比批发价多30元.现用10000元通过批发价购买该产品的件数与用16000元通过零售价购买该产品的件数相同,那么这种产品的批发价是多少元?25.济南在创建全国文明城市的进程中,高新区为美化城市环境,计划种植树木30000棵,由于志愿者的加入,实际每天植树比原计划多20%.结果提前10天完成任务,求原计划每天植树多少棵.26.在某校举办的2012年秋季运动会结束之后,学校需要为参加运动会的同学们发纪念品.小王负责到某商场买某种纪念品,该商场规定:一次性购买该纪念品200个以上可以按折扣价出售;购买200个以下(包括200个)只能按原价出售.小王若按照原计划的数量购买纪念品,只能按原价付款,共需要1050元;若多买35个,则按折扣价付款,恰好共需1050元.设小王按原计划购买纪念品x个.(1)求x的范围;(2)如果按原价购买5个纪念品与按打折价购买6个纪念品的钱数相同,那么小王原计划购买多少个纪念品?27.一项工程,甲队单独完成比乙队单独完成需少用9天,甲队单独做3天的工作乙队单独做需要4天,(1)甲、乙两队单独完成此项工程各需几天?(2)该项工程先由甲、乙两队合作,再由甲队单独完成,若完成此项工程不超过18天,甲乙两队至少合作几天?28.今年我区的葡萄喜获丰收,葡萄一上市,水果店的王老板用2400元购进一批葡萄,很快售完;老板又用5000元购进第二批葡萄,所购件数是第一批的2倍,但进价比第一批每件多了5元.(1)第一批葡萄每件进价多少元?(2)王老板以每件150元的价格销售第二批葡萄,售出80%后,为了尽快售完,决定打折促销,要使第二批葡萄的销售利润不少于640元,剩余的葡萄每件售价最少打几折?(利润=售价﹣进价)苏科新版八年级下学期《第10章分式》单元测试卷参考答案与试题解析一.选择题(共21小题)1.下列各式中,分式的个数是().A.2B.3C.4D.5【分析】判断分式的依据是看代数式的分母中是否含有字母,如果含有字母则是分式,如果不含有字母则不是分式.【解答】解:,的分母中均不含有字母,因此它们是整式,而不是分式;a+的分子不是整式,因此不是分式.,,的分母中含有字母,因此是分式.故选:B.【点评】本题考查了分式的定义:如果A、B表示两个整式,并且B中含有字母,那么式子叫做分式,A叫做分式的分子,B叫做分式的分母.注意π不是字母,是常数,所以不是分式,是整式.2.使分式有意义的x的取值范围是()A.x≠1B.x≠2C.x≠1且x≠2D.x可为任何数【分析】分式有意义的条件是分母≠0,即x2﹣3x+2≠0,解得x.【解答】解:∵x2﹣3x+2≠0即(x﹣1)(x﹣2)≠0,∴x﹣1≠0且x﹣2≠0,∴x≠1且x≠2.故选:C.【点评】本题考查的是分式有意义的条件:当分母不为0时,分式有意义.3.若分式的值为0,则x的值是()A.±3B.﹣3C.3D.0【分析】分式的值等于零,分子等于零,且分母不等于零.【解答】解:依题意,得x2﹣9=0且x+3≠0,解得,x=3.故选:C.【点评】本题考查了分式的值为零的条件.若分式的值为零,需同时具备两个条件:(1)分子为0;(2)分母不为0.这两个条件缺一不可.4.已知﹣=5,则分式的值为()A.1B.5C.D.【分析】已知等式左边通分并利用同分母分式的减法法则变形,整理后代入原式计算即可得到结果.【解答】解:已知等式整理得:=5,即x﹣y=﹣5xy,则原式===1,故选:A.【点评】此题考查了分式的值,熟练掌握运算法则是解本题的关键.5.一件工作,甲单独完成需要a天,乙单独完成需要b天,如果甲、乙二人合作,那么每天的工作效率是()A.a+b B.+C.D.【分析】合作的工作效率=甲的工作效率+乙的工作效率,据此可得.【解答】解:∵甲单独完成需要a天,乙单独完成需要b天,∴甲的工效为,乙的工效为,∴甲、乙二人合作每天的工作效率是+,故选:B.【点评】本题主要考查列代数式,解题的关键是熟练掌握工程问题中关于合作的工作效率的相等关系.6.不改变分式的值,使分子、分母的最高次项的系数都为正,正确的变形是()A.B.C.D.【分析】首先判断出分式的分子、分母的最高次项的系数分别为﹣1、﹣5,它们都是负数;然后根据分式的基本性质,把分式的分子、分母同时乘以﹣1,使分子、分母的最高次项的系数都为正即可.【解答】解:==∴不改变分式的值,使分子、分母的最高次项的系数都为正,正确的变形是.故选:C.【点评】此题主要考查了分式的基本性质的应用,要熟练掌握,解答此题的关键是要明确:分式的分子与分母同乘(或除以)一个不等于0的整式,分式的值不变.7.化简的结果是()A.1B.C.D.0【分析】将分子利用平方差公式分解因式,再进一步计算可得.【解答】解:原式=====1,故选:A.【点评】本题主要考查约分,解题的关键是掌握平方差公式分解因式和约分的定义.8.若=﹣,则a﹣2b的值是()A.﹣6B.6C.﹣2D.2【分析】先去分母,得4x=(a﹣b)x+(﹣2a﹣2b),再根据对应相等求出a、b 的值,代入计算即可.【解答】解:化简得,4x=(a﹣b)x+(﹣2a﹣2b),∴a﹣b=4,﹣2a﹣2b=0,解得a=2,b=﹣2,∴a﹣2b=2﹣2×(﹣2)=6,故选:B.【点评】本题考查了通分以及解二元一次方程组,是基础知识要熟练掌握.9.下列分式中,最简分式是()A.B.C.D.【分析】根据最简分式的定义对各选项逐一判断即可得.【解答】解:A、==,不符合题意;B、==,不符合题意;C、是最简分式,符合题意;D、==,不符合题意;故选:C.【点评】本题主要考查最简分式,解题的关键是掌握一个分式的分子与分母没有公因式时,叫最简分式.10.张萌将分式进行通分,则这两个分式的最简公分母为()A.2(x+y)(x﹣y)B.4(x+y)(x﹣y)C.(x+y)(x﹣y)D.4(x+y)2【分析】确定最简公分母的方法是:(1)取各分母系数的最小公倍数;(2)凡单独出现的字母连同它的指数作为最简公分母的一个因式;(3)同底数幂取次数最高的,得到的因式的积就是最简公分母.【解答】解:分式的分母分别是2x+2y=2(x+y)、4x﹣4y=4(x ﹣y),故最简公分母是4(x+y)(x﹣y).故选:B.【点评】本题考查了最简公分母的定义及求法.通常取各分母系数的最小公倍数与字母因式的最高次幂的积作公分母,这样的公分母叫做最简公分母.一般方法:①如果各分母都是单项式,那么最简公分母就是各系数的最小公倍数,相同字母的最高次幂,所有不同字母都写在积里.②如果各分母都是多项式,就可以将各个分母因式分解,取各分母数字系数的最小公倍数,凡出现的字母(或含字母的整式)为底数的幂的因式都要取最高次幂.11.计算(a2b)3•的结果是()A.a5b5B.a4b5C.ab5D.a5b6【分析】根据积的乘方等于乘方的积,分式的乘法,可得答案.【解答】解:原式=a6b3•=a5b5,故选:A.【点评】本题考查了分式的乘除法,熟记法则并根据法则计算是解题关键.12.已知,则的值为()A.1B.0C.﹣1D.﹣2【分析】解决本题首先将已知条件转化为最简形式,再把所求分式通分、代值即可.本题考查了分式的加减运算.【解答】解:把已知+=去分母,得(a+b)2=ab,即a2+b2=﹣ab∴+===﹣1.故选C.【点评】分式中的一些特殊求值题并非是一味的化简,代入,求值.许多问题还需运用到常见的数学思想,如化归思想(即转化)、整体思想等,了解这些数学解题思想对于解题技巧的丰富与提高有一定帮助.13.张阿姨,李阿姨到农贸市场买大米,第一次,张阿姨买了100千克大米,李阿姨买了100元的大米;第二次,张阿姨还是买了100千克大米,李阿姨还是买了100元的大米.下列说法正确的是()A.如果米价下降张阿姨买的合算B.如果米价上涨张阿姨买的合算C.无论米价怎样变化李阿姨买的合算D.无法判断谁买的合算【分析】先设第一次大米的单价为a,第二次大米的单价为b,分别计算两人两次所卖大米的平均单价,求出单价,再比较两者的差,根据结果来比较大小.【解答】解:设第一次大米的单价为a,第二次大米的单价为b,张阿姨两次购买的平均单价为,李阿姨两次购买的平均单价为则﹣=≥0.所以无论米价怎样变化都是李阿姨买的合算.故选:C.【点评】本题考查了分式的混合运算,解题的关键是求出两人两次所买大米的平均单价,再比较单价的大小.14.已知+=3,则代数式的值为()A.3B.﹣2C.﹣D.﹣【分析】已知等式左边通分并利用同分母分式的加法法则计算,整理得到a+2b =6ab,代入原式计算即可得到结果.【解答】解:+==3,即a+2b=6ab,则原式===﹣,故选:D.【点评】此题考查了分式的化简求值,熟练掌握运算法则是解本题的关键.15.下列方程是分式方程的是()A.B.C.x2﹣1=3D.2x+1=3x【分析】依据分式方程的定义进行判断即可.【解答】解:A、﹣=0是一元一次方程,故A错误;B、=﹣2是分式方程,故B正确;C、x2﹣1=3是一元二次方程,故C错误;D、2x+1=3x是一元一次方程,故D错误.故选:B.【点评】本题主要考查的是分式方程的定义,熟练掌握分式方程的定义是解题的关键.16.若关于x的分式方程无解,则m的值为()A.﹣1.5B.1C.﹣1.5或2D.﹣0.5或﹣1.5【分析】去分母得出方程①(2m+x)x﹣x(x﹣3)=2(x﹣3),分为两种情况:①根据方程无解得出x=0或x=3,分别把x=0或x=3代入方程①,求出m;②求出当2m+1=0时,方程也无解,即可得出答案.【解答】解:方程两边都乘以x(x﹣3)得:(2m+x)x﹣x(x﹣3)=2(x﹣3),即(2m+1)x=﹣6,分两种情况考虑:①∵当2m+1=0时,此方程无解,∴此时m=﹣0.5,②∵关于x的分式方程无解,∴x=0或x﹣3=0,即x=0,x=3,当x=0时,代入①得:(2m+0)×0﹣0×(0﹣3)=2(0﹣3),解得:此方程无解;当x=3时,代入①得:(2m+3)×3﹣3(3﹣3)=2(3﹣3),解得:m=﹣1.5,∴m的值是﹣0.5或﹣1.5,故选:D.【点评】本题考查了对分式方程的解的理解和运用,关键是求出分式方程无解时的x的值,题目比较好,难度也适中.17.方程=的解是()A.﹣B.C.﹣D.【分析】根据解分式方程的步骤:①去分母;②求出整式方程的解;③检验;④得出结论解答可得.【解答】解:两边都乘以2(x+2),得:2(2x﹣1)=x+2,解得:x=,当x=时,2(x+2)≠0,所以x=是分式方程的解,故选:D.【点评】本题主要考查解分式方程,解题的关键是掌握解分式方程的步骤:①去分母;②求出整式方程的解;③检验;④得出结论.18.用换元法解方程,若设=y,则原方程可化为()A.y2﹣7y+6=0B.y2+6y﹣7=0C.6y2﹣7y+1=0D.6y2+7y+1=0【分析】观察方程的两个分式具备的关系,若设=y,则原方程另一个分式为6×.可用换元法转化为关于y的方程.去分母、整理即可.【解答】解:把=y代入原方程得:y+6×=7,方程两边同乘以y整理得:y2﹣7y+6=0.故选:A.【点评】换元法解分式方程时常用方法之一,它能够把一些分式方程化繁为简,化难为易,对此应注意总结能用换元法解的分式方程的特点,寻找解题技巧.19.若分式方程有增根,则a的值是()A.﹣2B.0C.2D.0或﹣2【分析】增根是分式方程化为整式方程后产生的使分式方程的分母为0的根.把增根代入化为整式方程的方程即可求出未知字母的值.【解答】解:方程两边都乘(x+a)(x﹣2),得x+a+3(x﹣2)(x+a)=(a﹣x)(x﹣2),∵原方程有增根,∴最简公分母(a+x)(x﹣2)=0,∴增根是x=2或﹣a,当x=2时,方程化为:2+a=0,解得:a=﹣2;当x=﹣a时,方程化为﹣a+a=2a(﹣a﹣2),即a(a+2)=0,解得:a=0或﹣2.当a=﹣2时,原方程可化为+3=,化为整式方程得,1+3(x﹣2)=﹣x﹣2,即:x=,不存在增根,故不符合题意,当a=0时,原方程可化为,化为整式方程得,x+3x(x﹣2)=﹣x(x﹣2),解得x=或x=0,此时,有增根为x=0,∴a=0符合题意,故选:B.【点评】增根确定后可按如下步骤进行:①化分式方程为整式方程;②把增根代入整式方程即可求得相关字母的值.20.小明坐滴滴打车前去火车高铁站,小明可以选择两条不同路线:路线A的全程是25千米,但交通比较拥堵,路线B的全程比路线A的全程多7千米,但平均车速比走路线A时能提高60%,若走路线B的全程能比走路线A少用15分钟.若设走路线A时的平均速度为x千米/小时,根据题意,可列分式方程()A.=15B.=15C.=D.【分析】若设走路线A时的平均速度为x千米/小时,则走路线B时的平均速度为1.6x千米/小时,根据路线B的全程比路线A的全程多7千米,走路线B 的全程能比走路线A少用15分钟可列出方程.【解答】解:设走路线A时的平均速度为x千米/小时,根据题意,得﹣=.故选:D.【点评】本题考查了由实际问题抽象出分式方程,找到关键描述语,找到合适的等量关系是解决问题的关键.21.甲志愿者计划用若干个工作日完成社区的某项工作,从第三个工作日起,乙志愿者加盟此项工作,且甲、乙两人工效相同,结果提前3天完成任务,则甲志愿者计划完成此项工作的天数是()A.8B.7C.6D.5【分析】工效常用的等量关系是:工效×时间=工作总量,本题的等量关系为:甲工作量+乙工作量=1,根据从第三个工作日起,乙志愿者加盟此项工作,本题需注意甲比乙多做2天.【解答】解:方法1、设甲志愿者计划完成此项工作需x天,故甲的工效都为:,由于甲、乙两人工效相同,则乙的工效为甲前两个工作日完成了,剩余的工作量甲完成了,乙在甲工作两个工作日后完成了,则+=1,解得x=8,经检验,x=8是原方程的解.故选:A.方法2、设甲志愿者计划完成此项工作需a天,则一天完成工作总量的,由于甲、乙两人工效相同,则乙的一天完成工作总量的,甲实际工作了(a﹣3)天,乙比甲少工作两天,实际工作了(a﹣5)天,即用甲的工作量加乙的工作量=1,建立方程×(a﹣3)+×(a﹣5)=1,∴a=8,故选:A.【点评】本题主要考查分式方程的应用,还考查了工效×时间=工作总量这个等量关系.二.解答题(共7小题)22.下面是售货员与小明的对话:根据对话内容解答下列问题:(1)A、B两种文具的单价各是多少元?(2)若购买A、B两种文具共20件,其中A种文具的数量少于B种文具的数量,且购买总费用不超过260元,共有几种购买方案.【分析】(1)设A种文具的单价为x元,则B种文具单价为(25﹣x)元,根据用80元购买A种文具的数量是用120元购买B种文具的数量的2倍,列方程求解;(2)设学校购进A种文具a件,则购进B种文具(20﹣a)件,根据其中A种文具的数量少于B种文具的数量,且购买总费用不超过260元,列不等式求出a的取值范围,结合a为正整数,确定购买方案.【解答】解:(1)设A种文具的单价为x元,则B种文具单价为(25﹣x)元,由题意得,=,解得:x=10,经检验,x=10是分式方程的解,且符合题意,25﹣x=15答:种文具的单价为10元,则B种文具单价为15元;(2)设学校购进A种文具a件,则购进B种文具(20﹣a)件,由题意得,解得:8≤a<10,∵a是正整数,∴a为8或9∴共有两种购买方案.【点评】本题考查了分式方程和一元一次不等式的应用,解答本题的关键是读懂题意,设出未知数,找出合适的等量关系,列方程求解,注意检验.23.两列火车分别行驶在两平行的轨道上,其中快车车长100米,慢车车长150米,当两车相向而行时,快车驶过慢车某个窗口(快车车头到达窗口某一点至车尾离开这一点)所用的时间为5秒.(1)求两车的速度之和及两车相向而行时慢车驶过快车某个窗口(慢车车头到达窗口某一点至车尾离开这一点)所用的时间;(2)如果两车同向而行,慢车的速度不小于8米/秒,快车从后面追赶慢车,那么从快车的车头赶上慢车的车尾开始到快车的车尾离开慢车的车头所需时间至少为多少秒?【分析】(1)快车驶过慢车某个窗口等量关系为:两车的速度之和×所用时间=快车车长;慢车驶过快车某个窗口等量关系为:两车的速度之和×所用时间=慢车车长;(2)等量关系为:两车速度之差×时间=两车车长之和.【解答】解:(1)设快,慢车的速度分别为x米/秒,y米/秒.根据题意得x+y==20,即两车的速度之和为20米/秒;设慢车驶过快车某个窗口需用t1秒,根据题意得x+y=,∴t1=.即两车相向而行时,慢车驶过快车某个窗口所用时间为7.5秒.答:两车的速度之和为20米/秒,两车相向而行时,慢车驶过快车某个窗口所用时间为7.5秒;(2)所求的时间t2=,∴,依题意,当慢车的速度为8米/秒时,t2的值最小,t2=,∴t2的最小值为62.5秒.答:从快车的车头赶上慢车的车尾开始到快车的车尾离开慢车的车头所需时间至少为62.5秒.【点评】找到相应的等量关系是解决问题的关键;难点是得到相应的车速和路程.24.某工厂计划生产一种创新产品,若生产一件这种产品需A种原料1.2千克、B种原料1千克.已知A种原料每千克的价格比B种原料每千克的价格多10元.(1)为使每件产品的成本价不超过34元,那么购入的B种原料每千克的价格最高不超过多少元?(2)将这种产品投放市场批发销售一段时间后,为拓展销路又开展了零售业务,每件产品的零售价比批发价多30元.现用10000元通过批发价购买该产品的件数与用16000元通过零售价购买该产品的件数相同,那么这种产品的批发价是多少元?(1)设B种原料每千克的价格为x元,则A种原料每千克的价格为(x+10)【分析】元,根据每件产品的成本价不超过34元,即可得出关于x的一元一次不等式,解之取其中的最大值即可得出结论;(2)设这种产品的批发价为a元,则零售价为(a+30)元,根据数量=总价÷单价结合用10000元通过批发价购买该产品的件数与用16000元通过零售价购买该产品的件数相同,即可得出关于a的分式方程,解之经检验后即可得出结论.【解答】解:(1)设B种原料每千克的价格为x元,则A种原料每千克的价格为(x+10)元,根据题意得:1.2(x+10)+x≤34,解得:x≤10.答:购入B种原料每千克的价格最高不超过10元.(2)设这种产品的批发价为a元,则零售价为(a+30)元,根据题意得:=,解得:a=50,经检验,a=50是原方程的根,且符合实际.答:这种产品的批发价为50元.【点评】本题考查了分式方程的应用以及一元一次不等式的应用,解题的关键是:(1)根据各数量间的关系,正确列出一元一次不等式;(2)找准等量关系,正确列出分式方程.25.济南在创建全国文明城市的进程中,高新区为美化城市环境,计划种植树木30000棵,由于志愿者的加入,实际每天植树比原计划多20%.结果提前10天完成任务,求原计划每天植树多少棵.【分析】设原计划每天种树x棵,则实际每天栽树的棵数为(1+20%),根据题意可得,实际比计划少用10天,据此列方程求解.【解答】解:设原计划每天种树x棵,则实际每天栽树的棵数为(1+20%),由题意得,﹣=10,解得:x=500,经检验,x=500是原分式方程的解,且符合题意.答:原计划每天种树500棵.【点评】本题考查了分式方程的应用,解答本题的关键是读懂题意,设出未知数,找出合适的等量关系,列方程求解,注意检验.26.在某校举办的2012年秋季运动会结束之后,学校需要为参加运动会的同学们发纪念品.小王负责到某商场买某种纪念品,该商场规定:一次性购买该纪念品200个以上可以按折扣价出售;购买200个以下(包括200个)只能按原价出售.小王若按照原计划的数量购买纪念品,只能按原价付款,共需要1050元;若多买35个,则按折扣价付款,恰好共需1050元.设小王按原计划购买纪念品x个.(1)求x的范围;(2)如果按原价购买5个纪念品与按打折价购买6个纪念品的钱数相同,那么小王原计划购买多少个纪念品?【分析】(1)根据商场的规定确定出x的范围即可;(2)设小王原计划购买x个纪念品,根据按原价购买5个纪念品与按打折价购买6个纪念品的钱数相同列出分式方程,求出解即可得到结果.【解答】解:(1)根据题意得:0<x≤200,且x∈N;(2)设小王原计划购买x个纪念品,根据题意得:×5=×6,整理得:5x+175=6x,解得:x=175,经检验x=175是分式方程的解,且满足题意,则小王原计划购买175个纪念品.【点评】此题考查了分式方程的应用,弄清题中的等量关系“按原价购买5个纪念品与按打折价购买6个纪念品的钱数相同”是解本题的关键.27.一项工程,甲队单独完成比乙队单独完成需少用9天,甲队单独做3天的工作乙队单独做需要4天,(1)甲、乙两队单独完成此项工程各需几天?(2)该项工程先由甲、乙两队合作,再由甲队单独完成,若完成此项工程不超过18天,甲乙两队至少合作几天?【分析】(1)设甲队单独完成此项工程需x天,则乙队单独完成此项工程需(x+9)天,根据甲队单独做3天的工作乙队单独做需要4天,即可得出关于x的分式方程,解之经检验后即可得出结论;(2)设甲乙两队合作y天,根据完成此项工程不超过18天,即可得出关于y的一元一次不等式,解之即可得出y的取值范围,取其中的最小值即可得出结论.【解答】解:(1)设甲队单独完成此项工程需x天,则乙队单独完成此项工程需(x+9)天,根据题意得:=,解得:x=27,经检验,x=27是原方程的解,且符合题意,∴x+9=36.答:甲队单独完成此项工程需27天,乙队单独完成此项工程需36天.(2)设甲乙两队合作y天,根据题意得:+≥1,解得:y≥12.。

外研版七年级英语下册Module10单元综合测试题

外研版七年级英语下册Module10单元综合测试题

外研版七年级英语下册Module10单元综合测试题一、单项选择(每小题1. 5分, 共15分)1. It usually ________ Mum about half an hour to cook supper.A. paysB. takesC. spendsD. costs2. Last Tuesday morning we ________ at home.A. relaxB. relaxesC. relaxedD. relaxing3. —It's too late. I have to go now.—Oh, it's raining heavily outside. You'd better wait here ________ it stops.A. tillB. becauseC. butD. though4. They ________ Shanghai ________ a cold morning.A. arrived at; inB. arrived in; onC. got in; onD. got to; in5. —________ did it take to get there?—About two hours.A. What timeB. WhenC. How longD. How soon6. This news is so ________. I am ________ to hear it.A. excited; excitingB. exciting; excitedC. excited; excitedD. exciting; exciting7. —What do they ________ in the shop?—School things. Would you like to buy some?A. takeB. doC. sellD. say8. —________ you go to the cinema with last night?—My best friend Kate.A. Why didB. Where didC. Who doD. Who did9. Taiwan is ________ a beautiful island that ________ people in Guangdong go tovisit it every year.A. so; thousandsB. so; thousands ofC. such; two thousandsD. such; thousands of10. —I'm going to spend my summer holiday in Hawaii.—What a lucky boy! ________ And don't forget to send me a postcard.A. That sounds good.B. Have a good time!C. Good luck!D. Can I go with you?二、完形填空(每小题1分, 共10分)An artist went to a beautiful part of the country to go on a holiday and stayed with a farmer. Every day he went ________11 with his paints(颜料) and brushes and painted till evening. When it got ________12, he went back to the farm and had a good dinner ________13 he went to bed. At the end of his ________14 he wanted to pay the farmer, ________15 the farmer said, “No, I don't want money. But give me ________16 of your pictures. I will use up the money some day, but your picture will be here forever. ” The artist was very ________17 and thanked the farmer for saying so. The farmer smiled and answered, “Your picture can also give me a big help. I have a ________18in London. He wants to be ________19. He will come home ________20 month. I'll show him your picture, and he will not want to be an artist any more, I think. ”11. A. in B. out C. back D. at12. A. black B. white C. dark D. green13. A. before B. when C. after D. because14. A. birthday B. holiday C. weekday D. party15. A. and B. or C. but D. so16. A. one B. two C. some D. any17. A. angry B. happy C. sad D. good18. A. daughter B. sister C. son D. wife19. A. an artist B. a teacherC. a scientistD. a doctor20. A. last B. first C. next D. every三、阅读理解(每小题2分, 共10分)Jane went to Scotland for her holiday. Two days ago, she sent a letter and apostcard to her family.Jane said in her letter, “I visited a lot of places. How are you all? I miss you very much. I went to Edinburgh (爱丁堡) by train. I stayed there for three days and then I went to the mountains. I met a lot of young people there and now they are my friends.I also saw many famous lakes. I find that Scotland is more beautiful than England. And the restaurant is very nice. I'm having a wonderful time here now. ”21. Jane sent ________ to her family.A. a letterB. a postcardC. Both A and B.D. some presents22. In her letter Jane said ________.A. she met many young people in the mountainsB. she was in the mountains for three daysC. she went to the mountains three days ago with her motherD. she went to the mountains by plane23. Jane said that she ________.A. visited many lakesB. didn't visit any lakesC. visited some riversD. wasn't beautiful24. Jane thought that ________.A. England was more beautiful than ScotlandB. Scotland was more beautiful than EnglandC. England was smaller than ScotlandD. England was as beautiful as Scotland25. From Jane's letter we know that ________.A. she didn't like EnglandB. she didn't make any friendsC. she enjoyed herself very muchD. she didn't like the trip at all四、任务型阅读(每小题3分, 共15分)Peter often goes to the mountains (山) to take photos. Last Saturday morning,Peter put his camera in his bag and walked in a big mountain. He knew that he had to be not noisy, ________ the birds would fly away. He saw a yellow and blue bird sitting in a tree. Then the bird flew in front of Peter. How beautiful!He took a great photo. 然后他又拍了更多照片。

_第10章 分式 单元测试卷 2021-2022学年七年级数学沪教版(上海)上册(word 含答案)

_第10章 分式 单元测试卷 2021-2022学年七年级数学沪教版(上海)上册(word 含答案)

2021-2022学年沪教新版七年级上册数学《第10章分式》单元测试卷一.选择题1.下列各式:,其中分式共有()A.1个B.2个C.3个D.4个2.若分式无意义,则x的值为()A.3B.﹣3C.3或﹣3D.93.下列式子是分式的是()A.B.C.D.1+x4.下列式子:①,②,③,④,其中是分式的有()A.2个B.3个C.4个D.5个5.下列各式,,,,(x﹣y),中,分式的个数共有()A.2个B.3个C.4个D.5个6.能使分式的值为零的所有x的值是()A.x=2B.x=﹣2C.x=2或x=﹣2D.x=07.下列约分正确的是()A.B.C.D.8.当分式的值为0时,x的值为()A.0B.2C.0或2D.9.如果把分式中的x和y都扩大3倍,那么分式的值是()A.扩大3倍B.不变C.缩小3倍D.缩小6倍10.下列运算中正确的是()A.B.C.D.二.填空题11.已知,用x的代数式表示y,则y=.12.写出一个含有字母m,且m≠2的分式,这个分式可以是.13.下列各式:(1﹣x),,,+x,,其中是分式的有个.14.如果分式的值为0,则x的值是.15.下列各式:①;②;③;④;⑤;⑥;⑦﹣3x2,是分式的有,是整式的有.(只填序号)16.在有理式:﹣3x、、、、、中,分式有.17.使分式有意义的x的取值范围.18.已知m﹣n=2018,n﹣p=﹣2019,p﹣q=2021,则的值是.19.若把分式中的字母x和y同时增加3倍,分式的值将.20.约分:=;=.三.解答题21.当x为何值时,分式的值为0?22.当m为何值时,分式的值为0?23.当x取什么值时,下列各式的值等于零?(1);(2);(3).24.是否存在x的值,使得当a=4时,分式的值为0?25.已知,求的值.参考答案与试题解析一.选择题1.解:由题可得,分式有:,共1个,故选:A.2.解:∵分式无意义,∴x2﹣9=0,∴x=3且﹣3,故选:C.3.解:A.属于整式,不合题意;B.属于整式,不合题意;C.属于分式,符合题意;D.1+x属于整式,不合题意;故选:C.4.解:由题可得,属于分式的式子为:,,,共3个,故选:B.5.解:由题可得,是分式的有:,,(x﹣y),,共4个,故选:C.6.解:由题意得,解得x=﹣2.故选:B.7.解:A.=1,故本选项错误;B.=x4,故本选项错误;C.=,故本选项错误;D.,故本选项正确;故选:D.8.解:∵分式值为0,∴2x=0,解得:x=0.故选:A.9.解:∵如果把分式中的x和y都扩大了3倍,xy扩大到原来的9倍,x+y扩大的到原来的3倍,∴分式的值扩大3倍.故选:A.10.解:A、=x3,原计算错误,故此选项不符合题意;B、的分子分母没有公因式,不能约分,原计算错误,故此选项不符合题意;C、的分子分母没有公因式,不能约分,原计算错误,故此选项不符合题意;D、==,原计算正确,故此选项符合题意,故选:D.二.填空题11.解:xy﹣x=2y+1,(x﹣2)y=x+1y=,故答案为:.12.解:含有字母m,且m≠2的分式可以是,故答案为:(答案不唯一).13.解:(1﹣x),是多项式,属于整式;,是单项式,属于整式;,是多项式,属于整式;分式有+x,,共2个.故答案为:2.14.解:由题意得,x(x﹣2)=0,x﹣2≠0,解得,x=0,故答案为:0.15.解:②;④;⑦﹣3x2的分母中均不含有字母,因此它们是整式,而不是分式.①;③﹣;⑤;⑥分母中含有字母,因此是分式.故答案是:①、③、⑤、⑥,②、④、⑦.16.解:﹣3x、、、中,的分母中均不含有字母,因此它们是整式,而不是分式.、的分母中含有字母,因此是分式.故答案是:、.17.解:根据题意,得x﹣3≠0,解得x≠3,故答案为:x≠3.18.解:m﹣n=2018①,n﹣p=﹣2019②,p﹣q=2021③,①+②得:m﹣p=﹣1②+③得:n﹣q=2④①+④得:m﹣q=2020所以原式==﹣.故答案为﹣.19.解:中的字母x和y同时增加3倍,,故答案为:缩小.20.解:=;==;故答案为:,.三.解答题21.解:∵分式的值为0,∴,解得x=0且x≠3,∴x=0.∴当x=0时,分式的值为0.22.解:由题意得,m2﹣4=0,m2﹣m﹣6≠0,解得,m=2,则当m=2时,此分式的值为零.23.解:(1)由题意得,3x﹣1=0,2x+5≠0,解得,x=,则当x=时,此分式的值为零.(2)由题意得,x+2=0,解得,x=﹣2,则当x=﹣2时,此分式的值为零.(3)由题意得,|x|﹣2=0,x+2≠0,解得,x=2,则当x=2时,此分式的值为零.24.解:a=4时,a﹣x=4﹣x=0,x=4,a2﹣x2=42﹣42=0,分式无意义,∴不存在x的值,得当a=4时,分式的值为0.25.解:∵=,∴x≠0.x+=3,x2+2+=9,∴x2+=7.∴=x2+1+=8,∴=.。

人教版英语八上Unit 10 单元测试题(含答案)

人教版英语八上Unit 10 单元测试题(含答案)

Unit 10If you go to the party,you'll have a great time! Section A一、根据句意及汉语提示填写单词。

1.—Did your brother go to Central Park yesterday?—No.He _____________(待) at home.2.I think this ________________(主意) is the best.Do you agree with me?3.—Which bus should I ________(乘) if I go to the museum? —The No.336 bus.4.Mary and Linda are good friends.They go to school _________(一起) every day.5.—Does Bill always _________________ (戴) glasses when he reads?—Yes.Or he can't see the words clearly.二、用括号内所给单词的适当形式填空。

1.They planned _______________(have) the class party on Friday evening.2.The trousers in this store are much ____________(cheap) than those in that one.3.We will climb the mountain if it ____________________(not rain) this Sunday.4.Both Larry and Dennis are excellent ________________ (taxi) drivers.5.—What will you do if there is a fire? —I _______________(call) 119 for help.6. Please ask the children not ___________ (play) soccer in the street.7. John learned English by watching ___________ (video) in his free time.8. If Mr. Steen ___________ (come) to Beijing, he will visit the Great Wall first.9. My brother got a lot of nice ___________ (gift) at his eleventh birthday party.三、按要求完成句子,每空一词。

人教版八年级上册英语Unit 10 单元测试卷及答案

测试卷 ’Unit 10 If you go to the party, you’ll have a great time! 总分:150 分 时间:120 分钟第一卷听力部分(20 分) 一、听句子,选择你听到的单词或短语。

(共 5 分)A B C D E二、听句子,选择正确答案。

(共 5 分)三、6. A. That ’s g ood . B. Happy birthday . C. Cool.7. A. Sorry, I ’d love to. B. Sure, I ’d love to. C. How can I come? 8. A. Have a great time. B. T oo bad. C. I ’m going hiking. 9. A. Thanks. B. Not at all. C. All right. 10. A. That ’ good . B. What a pity . C. That ’s right!三、听对话及问题,选择正确答案。

(共 5 分)11. What clothes will the boy wear? A. Jeans. B. His school uniforms. C. His coat. 12. What will happen if they have their class meeting tomorrow? A. All the class will come. B. Most of the class will come. C. Most of the class won ’t come. 13. Does the boy want to go to college when he grows up? A. Yes, he does. B. No, he doesn ’t. C. W e don ’t know . 14. What will the boy have to go first? A. Go to the movies. B. Do his homework. C. Do nothing. 15. What should th e man do if he wants to be rich? A. He should be rich. B. He should work hard. C. He should help people in trouble.四、听短文,填空。

初三化学(九年级)第十、十一单元测试题

第十单元第十一单元测试题一、选择题(每小题只有一个选项符合题意,请把答案的序号填在下面的表格里,每小题3分,共42分)1、下列各组物质的名称、俗名、化学式表示同一物质的是( ) A 氢氧化钠、纯碱、NaOH B 氢氧化钙、生石灰、Ca (OH )2 C 氯化钠、食盐、NaCl D 碳酸氢钠、小苏打、Na 2CO 32、下列物质长期敞口放置于空气中,质量会减小的是( ) A 浓盐酸 B 浓硫酸 C 氢氧化钠固体 D 消石灰3、下列物质溶于水,能使无色酚酞试液变红的是( ) A 干冰 B 食醋 C 食盐 D 生石灰4、一些国家下在试用碳酸水浇灌某些植物,这样做不能起到的作用是( ) A 改良酸性土壤 B 促进植物的光合作用 C 提高作物的产量 D 改良碱性土壤5、下列两种不同PH 的溶液混合,有可能得到中性溶液的是( ) A PH==1 和PH==7 B PH==5 和PH==14 C PH==3 和PH==4 D PH==8 和PH==106、下列反应属于复分解反应的是( )A Fe+2HCl==FeCl 2+H 2B 2 KMnO 4===K 2MnO 4+MnO 2+O 2C CaO+H 2O==Ca (OH )2D Ca (OH )2+K 2CO 3==CaCO 3+2KOH7、小明在做酸的性质实验时,不小心将某酸滴到手上,下列正确的处理方法是( ) A 立即用大量水冲冼,再涂上硼酸溶液B 立即用大量水冲冼,再涂上3%-5%的碳酸氢钠溶液C 立即用大量水冲冼,再涂上3%-5%的氢氧化钠溶液D 立即用大量水冲冼,再涂上一些石灰水8、要检验仓库中的氢氧化钠是否变质,下列检方法不正确的是( ) A 取样品溶于水后加入酚酞试液 B 取样品溶于水后加入稀盐酸 C 取样品溶于水后加入氯化钙溶液 D 取样品溶于水后加入石灰水 9、下表列出了四种农作物生长最适宜的PH 范围:某同学测定得知,当地土壤的PH 接近于7。

小学-英语-科普版-五年级下册Lesson 10 单元测试卷

科普版五年级下册Lesson 10 单元测试卷一、将下列字母组成正确的单词。

1、将下列字母组成正确的单词。

(1)dtsna ______ (2)frboee ______(3)iaafrd ______ (4)eomseon ______(5)elsdudny ______二、选出下列单词中不同类的一项。

2、( )选出下列单词中不同类的一项。

A. whereB. whiteC. whenD. how3、( )选出下列单词中不同类的一项。

A. eveningB. morningC. afternoonD. skiing4、( )选出下列单词中不同类的一项。

A. usuallyB. footballC. skiingD. basketball5、( )选出下列单词中不同类的一项。

A. sportB. doC. musicD. picture6、( )选出下列单词中不同类的一项。

A. workerB. brotherC. fatherD. sister三、判断下列每组单词中画线部分的发音是(T)否(F)相同。

7、判断下列每组单词中画线部分的发音是(T)否(F)相同。

( ) lesson before( ) afternoon choose( ) at stand( ) exercise bedroom( ) some job四、选择填空。

8、( )Lily ______ to school on foot every morning.A. goB. goesC. went9、( )--What time is it?--It's ______ seven.A. aboutB. aC. the10、( )Let's go ______ see her.A. /B. to doC. and11、( )Does she do sports ______?A. tomorrowB. every dayC. yesterday12、( )Look ______ that boy!A. atB. onC. about五、为下列图片选择正确的短语。

七年级英语上册_Unit_10_Can_you_play_the_guitar单元检测(无答案)_人教新目标版

Unit 10 单元测试Ⅰ. 单项选择(15分)()1. My sister likes playing the guitar, but she can’t play ______.A. niceB. goodC. well()2. —Are you good ____ swimming?—Yes, and I think I can help kids ___ it.A. with; inB. with; withC. at; with()3. He wants ______ the English club.A. to joinB. to beC. be in()4. My father can’t play ______ basketball. He can play ______ piano.A. the; theB. /; theC. the; /()5. —Why do you want to ______ theEnglish club?Because Mr Li in the club is good ___ us.A. have; withB. join; withC. join; at()6. My brother doesn’t like playing basketball _______ watching TV.A. andB. butC. or()7. —Can you speak Chinese, Tom? —Yes, but only ______.A. lots ofB. manyC. a little()8. —_______ do you want to join? —The music club.A. What clubB. WhenC. What()9. Hi!Can I help you? __. I want to join the club.A. No, thanks a lotB. GreatC. Yes, please()10. —___? —He can do Chinese kung fu well.A. Can he do Chinese kung fuB. What can he doC. Does he want to join the Chinese kung fu club( )11. ---What can you do? ---I can _____.A. play the guitarB. play violinC. swimmingD. join the club( )12. ---Can Tom help kids _____ swimming?---Yes, can.A. xB. withC. forD. to( )13. ---___ do you want to join the chess club?---Because I like chess very much.A. WhoB. HowC. WhyD. What( )14. What is the first day of the week?A. MondayB. FridayC. SaturdayD. Sunday( )15. I can swim well.I want to join the ___ club.A musicB chessC swimming D、musicianⅡ.完形填空(10分)Ann is a middle school student. She has a sister 16 a brother. They are Helen and Paul. Ann and Helen can 17 . Ann can sing and play 18 well, but Helen 19 . Helen doesn’t like playing the instruments. She 20 chess, but she doesn’t play chess 21 Ann. Ann can’t play chess. Helen often plays with Paul, because Paul plays 22 very well. Paul can 23 play basketball well. And he is 24 the school basketball club. He often 25other students with basketball.()16. A. or B. but C. and()17. A. speak B. show C. dance()18. A. the guitar B. guitars C. guitar()19. A. can B. can’t C. don’t()20. A. has B. does C. likes()21. A. with B. for C. on()22. A. basketball B. chess C. games()23. A. also B. too C. only()24. A. of B. to C. in()25. A. plays B. joins C. helpsⅢ.阅读理解(10分)ATony and Anna are brother and sister. They are Americans. Tony likes sports very much. He can play soccer, basketball and volleyball. Anna likes music(音乐) very much. She can’t play ball games. But they both(两者都) like playing on computers.They like eggs, bread and milk for breakfast. For lunch, Anna likes eating vegetables and fruit, but Tony likes chicken and fish(鱼). They both like hamburgers. But they don’t like ice cream or dessert.根据短文内容,选择最佳答案。

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1 2010级2级起点 单元测试 读写教程第三册,第十单元测试卷 Part 1 Understanding Short Conversations (8%) Directions: In this section you'll hear 8 short conversations. Listen carefully and choose the best answer to the questions you hear. 1. A. She had paid more attention to her pronunciation. B. She doesn't make mistakes in her pronunciation. C. She didn't pay more attention to her pronunciation. D. She sometimes makes mistakes in her pronunciation. 2. A. He's afraid of crashing. B. He gets sick on planes. C. He misunderstood the woman. D. He dislikes traveling alone. 3. A. A person. B. A dog. C. A bird. D. A monkey. 4. A. 6:25. B. 7:30. C. 10:00. D. 12:00. 5. A. That they finish their assignment early. B. That they watch the clock carefully. C. That they be careful of their handwriting. D. That they wait a few minutes after class. 6. A. She suggests that the man go to hospital. B. She suggests that the man call Jack's family. C. She suggests that the man go back to Jack at once. D. She suggests that the man go and get a taxi. 7. A. $8.82. B. $9.20. C. $10.12. D. $11.00. 8. A. Mother and son. B. Father and daughter. C. Brother and sister. D. Boyfriend and girlfriend.

Part 2 Understanding Long Conversations (10%) 2

Directions: In this section you'll hear 2 long conversations. Listen carefully and choose the best answer to the questions you hear. Questions 9 to 13 are based on the same passage or dialog. 9. A. Foreign travel. B. Latin America. C. Airplanes. D. Disease. 10. A. 1. B. 20. C. 74. D. 250. 11. A. The disease had never been seen in Los Angeles. B. The food made people sick. C. People were not concerned enough about disease. D. Any dead disease may come back. 12. A. No one could explain it. B. It had never been seen in South America. C. The newspapers said it wasn't a problem. D. The disease was thought to have gone away. 13. A. Doctors. B. A lack of concern. C. Food. D. Travel. Questions 14 to 18 are based on the same passage or dialog. 14. A. The man's flights in space. B. The man's discoveries in space. C. America's space program. D. America's disasters. 15. A. 30. B. 3. C. 27. D. 2. 16. A. The man lost faith in the space program. B. The man reduced the number of space flights. C. The space program has had many accidents. D. The Challenger is the name of a spacecraft. 17. A. Space flights were stopped for two years. B. The space program wasn't the same. 3

C. The space program was reduced. D. People lost faith. 18. A. It should be stopped. B. It should be reduced. C. It costs too much. D. It has a good future. Part 3 Understanding Passages (10%) Directions: In this section you'll hear 2 passages. Listen carefully and choose the best answer to the questions you hear. Questions 19 to 23 are based on the same passage or dialog. 19. A. A storm. B. A plane disappearance. C. A flight to Alaska. D. The military. 20. A. To help a friend get elected. B. To search for a lost friend. C. To see Blue Mountain Pass. D. To become re-elected. 21. A. They would never want to stop the search. B. They would eventually find Penn. C. They would feel tired. D. They would conduct a professional search. 22. A. Penn's plane entering Blue Mountain Pass. B. A severe storm on the day of the flight. C. The radio from Penn's plane. D. The largest search in Alaska's history. 23. A. 325,000. B. 39. C. 3,600. D. 55. Questions 24 to 28 are based on the same passage or dialog. 24. A. New York and Washington D.C. B. The effects of a terrorist attack. C. The modern global society. D. The American media. 25. A. The September 11 attacks left an impact greater than any other event on the US. B. Defense and security agencies were created to confront terrorism. C. Terrorism has a greater impact outside of the country in which it happens. D. The terrorist attacks of September 11 were more terrible than any other.

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