Hermitian operators and convex functions

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协同(r,(h,m))-凸函数的Hermite-Hadamard型积分不等式

协同(r,(h,m))-凸函数的Hermite-Hadamard型积分不等式

则称 f 为 I 上的 (h, m) -凸函数。
M. P. Gill 等人在文[4]中引进了“r-凸函数”的等价形式
定义 2:设 I ⊆ 为区间,实数 r ∈ ,函数 f : I → =+ (0, +∞) ,若对任意的点 x, y ∈ I 和任意的 λ ∈[0,1] ,有
( )
f

x
( a, c )
+
f
(b,c) +
f
(a, d
)+
f
(b, d ) ,
其中 L (u, v) 为对数平均,且
= Ψ f (∆)
1 4
L
(
f
( a, c ) ,
f
(b, c ))
+
L
(
f
(a,
d
),
f
(b, d
))
+
L
(
f
(a,
c),
f
(a,
d
))
+
L
(
f
(b,
c),
f
(b,
d
) ) .
定理 1 [பைடு நூலகம்] 设函数 f : [a,b] ⊆ → + 为对数凸函数,且 a < b ,则
b
1 −
a
b
∫a
f
(
x)
dx

L
(
f
(a),
f
(b)),
其中 L (u, v) 为对数平均数。
定理 2 [4] 设一元函数 f : [a,b] ⊆ → + 为 r-凸函数,且 a < b , r ∈ ,若 f ∈ L1 ([a, b]) ,则

代数英语

代数英语

(0,2) 插值||(0,2) interpolation0#||zero-sharp; 读作零井或零开。

0+||zero-dagger; 读作零正。

1-因子||1-factor3-流形||3-manifold; 又称“三维流形”。

AIC准则||AIC criterion, Akaike information criterionAp 权||Ap-weightA稳定性||A-stability, absolute stabilityA最优设计||A-optimal designBCH 码||BCH code, Bose-Chaudhuri-Hocquenghem codeBIC准则||BIC criterion, Bayesian modification of the AICBMOA函数||analytic function of bounded mean oscillation; 全称“有界平均振动解析函数”。

BMO鞅||BMO martingaleBSD猜想||Birch and Swinnerton-Dyer conjecture; 全称“伯奇与斯温纳顿-戴尔猜想”。

B样条||B-splineC*代数||C*-algebra; 读作“C星代数”。

C0 类函数||function of class C0; 又称“连续函数类”。

CA T准则||CAT criterion, criterion for autoregressiveCM域||CM fieldCN 群||CN-groupCW 复形的同调||homology of CW complexCW复形||CW complexCW复形的同伦群||homotopy group of CW complexesCW剖分||CW decompositionCn 类函数||function of class Cn; 又称“n次连续可微函数类”。

Cp统计量||Cp-statisticC。

物理学专业英语

物理学专业英语

华中师范大学物理学院物理学专业英语仅供内部学习参考!2014一、课程的任务和教学目的通过学习《物理学专业英语》,学生将掌握物理学领域使用频率较高的专业词汇和表达方法,进而具备基本的阅读理解物理学专业文献的能力。

通过分析《物理学专业英语》课程教材中的范文,学生还将从英语角度理解物理学中个学科的研究内容和主要思想,提高学生的专业英语能力和了解物理学研究前沿的能力。

培养专业英语阅读能力,了解科技英语的特点,提高专业外语的阅读质量和阅读速度;掌握一定量的本专业英文词汇,基本达到能够独立完成一般性本专业外文资料的阅读;达到一定的笔译水平。

要求译文通顺、准确和专业化。

要求译文通顺、准确和专业化。

二、课程内容课程内容包括以下章节:物理学、经典力学、热力学、电磁学、光学、原子物理、统计力学、量子力学和狭义相对论三、基本要求1.充分利用课内时间保证充足的阅读量(约1200~1500词/学时),要求正确理解原文。

2.泛读适量课外相关英文读物,要求基本理解原文主要内容。

3.掌握基本专业词汇(不少于200词)。

4.应具有流利阅读、翻译及赏析专业英语文献,并能简单地进行写作的能力。

四、参考书目录1 Physics 物理学 (1)Introduction to physics (1)Classical and modern physics (2)Research fields (4)V ocabulary (7)2 Classical mechanics 经典力学 (10)Introduction (10)Description of classical mechanics (10)Momentum and collisions (14)Angular momentum (15)V ocabulary (16)3 Thermodynamics 热力学 (18)Introduction (18)Laws of thermodynamics (21)System models (22)Thermodynamic processes (27)Scope of thermodynamics (29)V ocabulary (30)4 Electromagnetism 电磁学 (33)Introduction (33)Electrostatics (33)Magnetostatics (35)Electromagnetic induction (40)V ocabulary (43)5 Optics 光学 (45)Introduction (45)Geometrical optics (45)Physical optics (47)Polarization (50)V ocabulary (51)6 Atomic physics 原子物理 (52)Introduction (52)Electronic configuration (52)Excitation and ionization (56)V ocabulary (59)7 Statistical mechanics 统计力学 (60)Overview (60)Fundamentals (60)Statistical ensembles (63)V ocabulary (65)8 Quantum mechanics 量子力学 (67)Introduction (67)Mathematical formulations (68)Quantization (71)Wave-particle duality (72)Quantum entanglement (75)V ocabulary (77)9 Special relativity 狭义相对论 (79)Introduction (79)Relativity of simultaneity (80)Lorentz transformations (80)Time dilation and length contraction (81)Mass-energy equivalence (82)Relativistic energy-momentum relation (86)V ocabulary (89)正文标记说明:蓝色Arial字体(例如energy):已知的专业词汇蓝色Arial字体加下划线(例如electromagnetism):新学的专业词汇黑色Times New Roman字体加下划线(例如postulate):新学的普通词汇1 Physics 物理学1 Physics 物理学Introduction to physicsPhysics is a part of natural philosophy and a natural science that involves the study of matter and its motion through space and time, along with related concepts such as energy and force. More broadly, it is the general analysis of nature, conducted in order to understand how the universe behaves.Physics is one of the oldest academic disciplines, perhaps the oldest through its inclusion of astronomy. Over the last two millennia, physics was a part of natural philosophy along with chemistry, certain branches of mathematics, and biology, but during the Scientific Revolution in the 17th century, the natural sciences emerged as unique research programs in their own right. Physics intersects with many interdisciplinary areas of research, such as biophysics and quantum chemistry,and the boundaries of physics are not rigidly defined. New ideas in physics often explain the fundamental mechanisms of other sciences, while opening new avenues of research in areas such as mathematics and philosophy.Physics also makes significant contributions through advances in new technologies that arise from theoretical breakthroughs. For example, advances in the understanding of electromagnetism or nuclear physics led directly to the development of new products which have dramatically transformed modern-day society, such as television, computers, domestic appliances, and nuclear weapons; advances in thermodynamics led to the development of industrialization; and advances in mechanics inspired the development of calculus.Core theoriesThough physics deals with a wide variety of systems, certain theories are used by all physicists. Each of these theories were experimentally tested numerous times and found correct as an approximation of nature (within a certain domain of validity).For instance, the theory of classical mechanics accurately describes the motion of objects, provided they are much larger than atoms and moving at much less than the speed of light. These theories continue to be areas of active research, and a remarkable aspect of classical mechanics known as chaos was discovered in the 20th century, three centuries after the original formulation of classical mechanics by Isaac Newton (1642–1727) 【艾萨克·牛顿】.University PhysicsThese central theories are important tools for research into more specialized topics, and any physicist, regardless of his or her specialization, is expected to be literate in them. These include classical mechanics, quantum mechanics, thermodynamics and statistical mechanics, electromagnetism, and special relativity.Classical and modern physicsClassical mechanicsClassical physics includes the traditional branches and topics that were recognized and well-developed before the beginning of the 20th century—classical mechanics, acoustics, optics, thermodynamics, and electromagnetism.Classical mechanics is concerned with bodies acted on by forces and bodies in motion and may be divided into statics (study of the forces on a body or bodies at rest), kinematics (study of motion without regard to its causes), and dynamics (study of motion and the forces that affect it); mechanics may also be divided into solid mechanics and fluid mechanics (known together as continuum mechanics), the latter including such branches as hydrostatics, hydrodynamics, aerodynamics, and pneumatics.Acoustics is the study of how sound is produced, controlled, transmitted and received. Important modern branches of acoustics include ultrasonics, the study of sound waves of very high frequency beyond the range of human hearing; bioacoustics the physics of animal calls and hearing, and electroacoustics, the manipulation of audible sound waves using electronics.Optics, the study of light, is concerned not only with visible light but also with infrared and ultraviolet radiation, which exhibit all of the phenomena of visible light except visibility, e.g., reflection, refraction, interference, diffraction, dispersion, and polarization of light.Heat is a form of energy, the internal energy possessed by the particles of which a substance is composed; thermodynamics deals with the relationships between heat and other forms of energy.Electricity and magnetism have been studied as a single branch of physics since the intimate connection between them was discovered in the early 19th century; an electric current gives rise to a magnetic field and a changing magnetic field induces an electric current. Electrostatics deals with electric charges at rest, electrodynamics with moving charges, and magnetostatics with magnetic poles at rest.Modern PhysicsClassical physics is generally concerned with matter and energy on the normal scale of1 Physics 物理学observation, while much of modern physics is concerned with the behavior of matter and energy under extreme conditions or on the very large or very small scale.For example, atomic and nuclear physics studies matter on the smallest scale at which chemical elements can be identified.The physics of elementary particles is on an even smaller scale, as it is concerned with the most basic units of matter; this branch of physics is also known as high-energy physics because of the extremely high energies necessary to produce many types of particles in large particle accelerators. On this scale, ordinary, commonsense notions of space, time, matter, and energy are no longer valid.The two chief theories of modern physics present a different picture of the concepts of space, time, and matter from that presented by classical physics.Quantum theory is concerned with the discrete, rather than continuous, nature of many phenomena at the atomic and subatomic level, and with the complementary aspects of particles and waves in the description of such phenomena.The theory of relativity is concerned with the description of phenomena that take place in a frame of reference that is in motion with respect to an observer; the special theory of relativity is concerned with relative uniform motion in a straight line and the general theory of relativity with accelerated motion and its connection with gravitation.Both quantum theory and the theory of relativity find applications in all areas of modern physics.Difference between classical and modern physicsWhile physics aims to discover universal laws, its theories lie in explicit domains of applicability. Loosely speaking, the laws of classical physics accurately describe systems whose important length scales are greater than the atomic scale and whose motions are much slower than the speed of light. Outside of this domain, observations do not match their predictions.Albert Einstein【阿尔伯特·爱因斯坦】contributed the framework of special relativity, which replaced notions of absolute time and space with space-time and allowed an accurate description of systems whose components have speeds approaching the speed of light.Max Planck【普朗克】, Erwin Schrödinger【薛定谔】, and others introduced quantum mechanics, a probabilistic notion of particles and interactions that allowed an accurate description of atomic and subatomic scales.Later, quantum field theory unified quantum mechanics and special relativity.General relativity allowed for a dynamical, curved space-time, with which highly massiveUniversity Physicssystems and the large-scale structure of the universe can be well-described. General relativity has not yet been unified with the other fundamental descriptions; several candidate theories of quantum gravity are being developed.Research fieldsContemporary research in physics can be broadly divided into condensed matter physics; atomic, molecular, and optical physics; particle physics; astrophysics; geophysics and biophysics. Some physics departments also support research in Physics education.Since the 20th century, the individual fields of physics have become increasingly specialized, and today most physicists work in a single field for their entire careers. "Universalists" such as Albert Einstein (1879–1955) and Lev Landau (1908–1968)【列夫·朗道】, who worked in multiple fields of physics, are now very rare.Condensed matter physicsCondensed matter physics is the field of physics that deals with the macroscopic physical properties of matter. In particular, it is concerned with the "condensed" phases that appear whenever the number of particles in a system is extremely large and the interactions between them are strong.The most familiar examples of condensed phases are solids and liquids, which arise from the bonding by way of the electromagnetic force between atoms. More exotic condensed phases include the super-fluid and the Bose–Einstein condensate found in certain atomic systems at very low temperature, the superconducting phase exhibited by conduction electrons in certain materials,and the ferromagnetic and antiferromagnetic phases of spins on atomic lattices.Condensed matter physics is by far the largest field of contemporary physics.Historically, condensed matter physics grew out of solid-state physics, which is now considered one of its main subfields. The term condensed matter physics was apparently coined by Philip Anderson when he renamed his research group—previously solid-state theory—in 1967. In 1978, the Division of Solid State Physics of the American Physical Society was renamed as the Division of Condensed Matter Physics.Condensed matter physics has a large overlap with chemistry, materials science, nanotechnology and engineering.Atomic, molecular and optical physicsAtomic, molecular, and optical physics (AMO) is the study of matter–matter and light–matter interactions on the scale of single atoms and molecules.1 Physics 物理学The three areas are grouped together because of their interrelationships, the similarity of methods used, and the commonality of the energy scales that are relevant. All three areas include both classical, semi-classical and quantum treatments; they can treat their subject from a microscopic view (in contrast to a macroscopic view).Atomic physics studies the electron shells of atoms. Current research focuses on activities in quantum control, cooling and trapping of atoms and ions, low-temperature collision dynamics and the effects of electron correlation on structure and dynamics. Atomic physics is influenced by the nucleus (see, e.g., hyperfine splitting), but intra-nuclear phenomena such as fission and fusion are considered part of high-energy physics.Molecular physics focuses on multi-atomic structures and their internal and external interactions with matter and light.Optical physics is distinct from optics in that it tends to focus not on the control of classical light fields by macroscopic objects, but on the fundamental properties of optical fields and their interactions with matter in the microscopic realm.High-energy physics (particle physics) and nuclear physicsParticle physics is the study of the elementary constituents of matter and energy, and the interactions between them.In addition, particle physicists design and develop the high energy accelerators,detectors, and computer programs necessary for this research. The field is also called "high-energy physics" because many elementary particles do not occur naturally, but are created only during high-energy collisions of other particles.Currently, the interactions of elementary particles and fields are described by the Standard Model.●The model accounts for the 12 known particles of matter (quarks and leptons) thatinteract via the strong, weak, and electromagnetic fundamental forces.●Dynamics are described in terms of matter particles exchanging gauge bosons (gluons,W and Z bosons, and photons, respectively).●The Standard Model also predicts a particle known as the Higgs boson. In July 2012CERN, the European laboratory for particle physics, announced the detection of a particle consistent with the Higgs boson.Nuclear Physics is the field of physics that studies the constituents and interactions of atomic nuclei. The most commonly known applications of nuclear physics are nuclear power generation and nuclear weapons technology, but the research has provided application in many fields, including those in nuclear medicine and magnetic resonance imaging, ion implantation in materials engineering, and radiocarbon dating in geology and archaeology.University PhysicsAstrophysics and Physical CosmologyAstrophysics and astronomy are the application of the theories and methods of physics to the study of stellar structure, stellar evolution, the origin of the solar system, and related problems of cosmology. Because astrophysics is a broad subject, astrophysicists typically apply many disciplines of physics, including mechanics, electromagnetism, statistical mechanics, thermodynamics, quantum mechanics, relativity, nuclear and particle physics, and atomic and molecular physics.The discovery by Karl Jansky in 1931 that radio signals were emitted by celestial bodies initiated the science of radio astronomy. Most recently, the frontiers of astronomy have been expanded by space exploration. Perturbations and interference from the earth's atmosphere make space-based observations necessary for infrared, ultraviolet, gamma-ray, and X-ray astronomy.Physical cosmology is the study of the formation and evolution of the universe on its largest scales. Albert Einstein's theory of relativity plays a central role in all modern cosmological theories. In the early 20th century, Hubble's discovery that the universe was expanding, as shown by the Hubble diagram, prompted rival explanations known as the steady state universe and the Big Bang.The Big Bang was confirmed by the success of Big Bang nucleo-synthesis and the discovery of the cosmic microwave background in 1964. The Big Bang model rests on two theoretical pillars: Albert Einstein's general relativity and the cosmological principle (On a sufficiently large scale, the properties of the Universe are the same for all observers). Cosmologists have recently established the ΛCDM model (the standard model of Big Bang cosmology) of the evolution of the universe, which includes cosmic inflation, dark energy and dark matter.Current research frontiersIn condensed matter physics, an important unsolved theoretical problem is that of high-temperature superconductivity. Many condensed matter experiments are aiming to fabricate workable spintronics and quantum computers.In particle physics, the first pieces of experimental evidence for physics beyond the Standard Model have begun to appear. Foremost among these are indications that neutrinos have non-zero mass. These experimental results appear to have solved the long-standing solar neutrino problem, and the physics of massive neutrinos remains an area of active theoretical and experimental research. Particle accelerators have begun probing energy scales in the TeV range, in which experimentalists are hoping to find evidence for the super-symmetric particles, after discovery of the Higgs boson.Theoretical attempts to unify quantum mechanics and general relativity into a single theory1 Physics 物理学of quantum gravity, a program ongoing for over half a century, have not yet been decisively resolved. The current leading candidates are M-theory, superstring theory and loop quantum gravity.Many astronomical and cosmological phenomena have yet to be satisfactorily explained, including the existence of ultra-high energy cosmic rays, the baryon asymmetry, the acceleration of the universe and the anomalous rotation rates of galaxies.Although much progress has been made in high-energy, quantum, and astronomical physics, many everyday phenomena involving complexity, chaos, or turbulence are still poorly understood. Complex problems that seem like they could be solved by a clever application of dynamics and mechanics remain unsolved; examples include the formation of sand-piles, nodes in trickling water, the shape of water droplets, mechanisms of surface tension catastrophes, and self-sorting in shaken heterogeneous collections.These complex phenomena have received growing attention since the 1970s for several reasons, including the availability of modern mathematical methods and computers, which enabled complex systems to be modeled in new ways. Complex physics has become part of increasingly interdisciplinary research, as exemplified by the study of turbulence in aerodynamics and the observation of pattern formation in biological systems.Vocabulary★natural science 自然科学academic disciplines 学科astronomy 天文学in their own right 凭他们本身的实力intersects相交,交叉interdisciplinary交叉学科的,跨学科的★quantum 量子的theoretical breakthroughs 理论突破★electromagnetism 电磁学dramatically显著地★thermodynamics热力学★calculus微积分validity★classical mechanics 经典力学chaos 混沌literate 学者★quantum mechanics量子力学★thermodynamics and statistical mechanics热力学与统计物理★special relativity狭义相对论is concerned with 关注,讨论,考虑acoustics 声学★optics 光学statics静力学at rest 静息kinematics运动学★dynamics动力学ultrasonics超声学manipulation 操作,处理,使用University Physicsinfrared红外ultraviolet紫外radiation辐射reflection 反射refraction 折射★interference 干涉★diffraction 衍射dispersion散射★polarization 极化,偏振internal energy 内能Electricity电性Magnetism 磁性intimate 亲密的induces 诱导,感应scale尺度★elementary particles基本粒子★high-energy physics 高能物理particle accelerators 粒子加速器valid 有效的,正当的★discrete离散的continuous 连续的complementary 互补的★frame of reference 参照系★the special theory of relativity 狭义相对论★general theory of relativity 广义相对论gravitation 重力,万有引力explicit 详细的,清楚的★quantum field theory 量子场论★condensed matter physics凝聚态物理astrophysics天体物理geophysics地球物理Universalist博学多才者★Macroscopic宏观Exotic奇异的★Superconducting 超导Ferromagnetic铁磁质Antiferromagnetic 反铁磁质★Spin自旋Lattice 晶格,点阵,网格★Society社会,学会★microscopic微观的hyperfine splitting超精细分裂fission分裂,裂变fusion熔合,聚变constituents成分,组分accelerators加速器detectors 检测器★quarks夸克lepton 轻子gauge bosons规范玻色子gluons胶子★Higgs boson希格斯玻色子CERN欧洲核子研究中心★Magnetic Resonance Imaging磁共振成像,核磁共振ion implantation 离子注入radiocarbon dating放射性碳年代测定法geology地质学archaeology考古学stellar 恒星cosmology宇宙论celestial bodies 天体Hubble diagram 哈勃图Rival竞争的★Big Bang大爆炸nucleo-synthesis核聚合,核合成pillar支柱cosmological principle宇宙学原理ΛCDM modelΛ-冷暗物质模型cosmic inflation宇宙膨胀1 Physics 物理学fabricate制造,建造spintronics自旋电子元件,自旋电子学★neutrinos 中微子superstring 超弦baryon重子turbulence湍流,扰动,骚动catastrophes突变,灾变,灾难heterogeneous collections异质性集合pattern formation模式形成University Physics2 Classical mechanics 经典力学IntroductionIn physics, classical mechanics is one of the two major sub-fields of mechanics, which is concerned with the set of physical laws describing the motion of bodies under the action of a system of forces. The study of the motion of bodies is an ancient one, making classical mechanics one of the oldest and largest subjects in science, engineering and technology.Classical mechanics describes the motion of macroscopic objects, from projectiles to parts of machinery, as well as astronomical objects, such as spacecraft, planets, stars, and galaxies. Besides this, many specializations within the subject deal with gases, liquids, solids, and other specific sub-topics.Classical mechanics provides extremely accurate results as long as the domain of study is restricted to large objects and the speeds involved do not approach the speed of light. When the objects being dealt with become sufficiently small, it becomes necessary to introduce the other major sub-field of mechanics, quantum mechanics, which reconciles the macroscopic laws of physics with the atomic nature of matter and handles the wave–particle duality of atoms and molecules. In the case of high velocity objects approaching the speed of light, classical mechanics is enhanced by special relativity. General relativity unifies special relativity with Newton's law of universal gravitation, allowing physicists to handle gravitation at a deeper level.The initial stage in the development of classical mechanics is often referred to as Newtonian mechanics, and is associated with the physical concepts employed by and the mathematical methods invented by Newton himself, in parallel with Leibniz【莱布尼兹】, and others.Later, more abstract and general methods were developed, leading to reformulations of classical mechanics known as Lagrangian mechanics and Hamiltonian mechanics. These advances were largely made in the 18th and 19th centuries, and they extend substantially beyond Newton's work, particularly through their use of analytical mechanics. Ultimately, the mathematics developed for these were central to the creation of quantum mechanics.Description of classical mechanicsThe following introduces the basic concepts of classical mechanics. For simplicity, it often2 Classical mechanics 经典力学models real-world objects as point particles, objects with negligible size. The motion of a point particle is characterized by a small number of parameters: its position, mass, and the forces applied to it.In reality, the kind of objects that classical mechanics can describe always have a non-zero size. (The physics of very small particles, such as the electron, is more accurately described by quantum mechanics). Objects with non-zero size have more complicated behavior than hypothetical point particles, because of the additional degrees of freedom—for example, a baseball can spin while it is moving. However, the results for point particles can be used to study such objects by treating them as composite objects, made up of a large number of interacting point particles. The center of mass of a composite object behaves like a point particle.Classical mechanics uses common-sense notions of how matter and forces exist and interact. It assumes that matter and energy have definite, knowable attributes such as where an object is in space and its speed. It also assumes that objects may be directly influenced only by their immediate surroundings, known as the principle of locality.In quantum mechanics objects may have unknowable position or velocity, or instantaneously interact with other objects at a distance.Position and its derivativesThe position of a point particle is defined with respect to an arbitrary fixed reference point, O, in space, usually accompanied by a coordinate system, with the reference point located at the origin of the coordinate system. It is defined as the vector r from O to the particle.In general, the point particle need not be stationary relative to O, so r is a function of t, the time elapsed since an arbitrary initial time.In pre-Einstein relativity (known as Galilean relativity), time is considered an absolute, i.e., the time interval between any given pair of events is the same for all observers. In addition to relying on absolute time, classical mechanics assumes Euclidean geometry for the structure of space.Velocity and speedThe velocity, or the rate of change of position with time, is defined as the derivative of the position with respect to time. In classical mechanics, velocities are directly additive and subtractive as vector quantities; they must be dealt with using vector analysis.When both objects are moving in the same direction, the difference can be given in terms of speed only by ignoring direction.University PhysicsAccelerationThe acceleration , or rate of change of velocity, is the derivative of the velocity with respect to time (the second derivative of the position with respect to time).Acceleration can arise from a change with time of the magnitude of the velocity or of the direction of the velocity or both . If only the magnitude v of the velocity decreases, this is sometimes referred to as deceleration , but generally any change in the velocity with time, including deceleration, is simply referred to as acceleration.Inertial frames of referenceWhile the position and velocity and acceleration of a particle can be referred to any observer in any state of motion, classical mechanics assumes the existence of a special family of reference frames in terms of which the mechanical laws of nature take a comparatively simple form. These special reference frames are called inertial frames .An inertial frame is such that when an object without any force interactions (an idealized situation) is viewed from it, it appears either to be at rest or in a state of uniform motion in a straight line. This is the fundamental definition of an inertial frame. They are characterized by the requirement that all forces entering the observer's physical laws originate in identifiable sources (charges, gravitational bodies, and so forth).A non-inertial reference frame is one accelerating with respect to an inertial one, and in such a non-inertial frame a particle is subject to acceleration by fictitious forces that enter the equations of motion solely as a result of its accelerated motion, and do not originate in identifiable sources. These fictitious forces are in addition to the real forces recognized in an inertial frame.A key concept of inertial frames is the method for identifying them. For practical purposes, reference frames that are un-accelerated with respect to the distant stars are regarded as good approximations to inertial frames.Forces; Newton's second lawNewton was the first to mathematically express the relationship between force and momentum . Some physicists interpret Newton's second law of motion as a definition of force and mass, while others consider it a fundamental postulate, a law of nature. Either interpretation has the same mathematical consequences, historically known as "Newton's Second Law":a m t v m t p F ===d )(d d dThe quantity m v is called the (canonical ) momentum . The net force on a particle is thus equal to rate of change of momentum of the particle with time.So long as the force acting on a particle is known, Newton's second law is sufficient to。

泛函微分方程-泛函微分方程

泛函微分方程-泛函微分方程

泛函微分方程是指除了理想的情形以外,任何具有反馈的动力系统总是存在滞后现象;用传统的常微分方程去描述物理系统只是一种近似,而且是有条件的,这就需要考虑带有各种滞后量的微分方程,诸如微分差分方程,各种具有复杂偏差变元的微分方程,有滞后量的积分微分方程,等等。

泛函微分方程是这一类方程的概括和抽象。

最早的泛函微分方程来自1750年L.欧拉提出的几何问题:求一曲线使之与其渐缩线相似。

这种曲线便满足一个特殊的泛函微分方程,此后不断从各个学科中提出这类问题。

到20世纪40年代为止,主要是研究微分差分方程的解析解。

50年代开始探讨稳定性理论,1959年H.H.克拉索夫斯基在函数空间之间建立解映射,从而确立了滞后型泛函微分方程。

70年代初,J.黑尔与A.克鲁兹分离出一类广泛的中立型方程。

1978年赫尔与加藤敏夫共同奠立了具有无穷滞后的泛函微分方程。

以后又有对其他类型的中立型泛函微分方程的研究。

给定实数r≥0,区间【-r,0】到n维实(或复)线性空间R n的连续映射全体记为C(【-r,0】,R n),简记为C,C中元素φ的范数取为则C 为巴拿赫空间且具有一致收敛拓扑。

若t0∈R,A≥0,且x∈C(【t0-r,t0+A】,R n),则对任何t∈【t0,t0+A】,记x t(θ)=x(t+θ)(-r ≤θ≤0),显然x t∈C。

若D吇R×C,给定映射ƒ:D→R n,则(1)叫做D上的滞后型泛函微分方程,记为RFDE(ƒ)。

(1)中为右导数。

若存在t0∈R,A >0 使得,(t,x t)∈D,且当)时x(t)满足(1),则称x(t)为(1)之解。

若t0∈R ,φ∈C 给定,且x(t;t0,φ)为(1)之解。

则当时称x为过 (t0,φ)的解。

由此可以建立两种解映射:及。

而且一般地说解空间是无穷维的。

当r=0时(1)退化为常微分方程,解映射为,解空间是有限维的。

二者截然不同,通常解的存在惟一性,稳定性,周期解的存在性都不等价。

A New Approach for Filtering Nonlinear Systems

A New Approach for Filtering Nonlinear Systems

computational overhead as the number of calculations demanded for the generation of the Jacobian and the predictions of state estimate and covariance are large. In this paper we describe a new approach to generalising the Kalman filter to systems with nonlinear state transition and observation models. In Section 2 we describe the basic filtering problem and the notation used in this paper. In Section 3 we describe the new filter. The fourth section presents a summary of the theoretical analysis of the performance of the new filter against that of the EKF. In Section 5 we demonstrate the new filter in a highly nonlinear application and we conclude with a discussion of the implications of this new filter1
Tቤተ መጻሕፍቲ ባይዱ
= = =
δij Q(i), δij R(i), 0, ∀i, j.
(3) (4) (5)

ROHM Solution Simulator用户指南说明书

ROHM Solution Simulator用户指南说明书

User’s Guide ROHM Solution SimulatorAutomotive High Precision & Input/Output Rail-to-Rail CMOS Operational Amplifiers (Dual Op-Amps) TLR2377YFVM-C –Non-inverting Amplifier (Sine Wave Input) – Transient Response sim This circuit simulates the transient response to sine wave input with non-inverting amplifier configured Op-Amps. You can observe the output voltage and how faithfully the sine wave input voltage is reproduced. You can customize the parameters of the components shown in blue, such as VSOURCE, or peripheral components, and simulate the non-inverting amplifier with the desired operating condition.You can simulate the circuit in the published application note: Operational amplifier, Comparator (Tutorial). [JP] [EN] [CN] [KR] General CautionsCaution 1: The values from the simulation results are not guaranteed. Please use these results as a guide for your design.Caution 2: These model characteristics are specifically at Ta=25°C. Thus, the simulation result with temperature variances may significantly differ from the result with the one done at actual application board (actual measurement).Caution 3: Please refer to the Application note of Op-Amps for details of the technical information.Caution 4: The characteristics may change depending on the actual board design and ROHM strongly recommend to double check those characteristics with actual board where the chips will be mounted on.1 Simulation SchematicFigure 1. Simulation Schematic2 How to simulateThe simulation settings, such as parameter sweep or convergence options,are configurable from the ‘Simulation Settings’ shown in Figure 2, and Table1 shows the default setup of the simulation.In case of simulation convergence issue, you can change advancedoptions to solve. The temperature is set to 27 °C in the default statement in‘Manual Options’. You can modify it.Figure 2. Simulation Settings and execution Table 1.Simulation settings default setupParameters Default NoteSimulation Type Time-Domain Do not change Simulation TypeEnd Time 300 µs -Advanced options Balanced - Time Resolution Enhancement Convergence Assist-Manual Options .temp 27 - SimulationSettingsSimulate3Simulation ConditionsTable 2. List of the simulation condition parametersInstanceNameType ParametersDefaultValue Variable Range Units Min Max VSOURCE Voltage Source Frequency 10k 10 10M Hz Peak_voltage 0.5 0 5.5V Initial_phase0 free ° DC_offset2.5 0 5.5V DF0.0 fixed 1/s AC_magnitude 0.0 fixed V AC_phase 0.0 fixed ° VDD Voltage SourceFor Op-AmpVoltage_level5 2.5(Note1) 5.5(Note1)V AC_magnitude0.0 fixed V AC_phase 0.0 fixed ° VREF Voltage Source Voltage_level2.5 VSS VDDV AC_magnitude0.0 fixed V AC_phase0.0fixed°(Note 1) Set it to the guaranteed operating range of the Op-Amps.3.1 VSOURCE parameter setupFigure 3 shows how the VSOURCE parameters correspond to the VIN stimulus waveform.Figure 3. VSOURCE parameters and its waveform4 Op-Amp modelTable 3 shows the model pin function implemented. Note that the Op-Amp model is the behavior model for its input/output characteristics, and no protection circuits or the functions not related to the purpose are not implemented.Table 3. Op-Amp model pins used for the simulationPin Name Description+INNon-inverting input -INInverting input VDDPositive power supply VSSNegative power supply / Ground OUTOutputInitial_phaseDC_offsetPeak_voltage1/FrequencyVOVIN5 Peripheral Components5.1 Bill of MaterialTable 4 shows the list of components used in the simulation schematic. Each of the capacitors has the parameters of equivalent circuit shown below. The default values of equivalent components are set to zero except for the ESR ofC. You can modify the values of each component.Table 4. List of capacitors used in the simulation circuitType Instance Name Default Value Variable RangeUnits Min MaxResistor R2_1 10k 1k 1M ΩR2_2 10k 1k 1M ΩRL2 10k 1k 1M, NC ΩCapacitor C2_1 10 10 100 pF CL2 10 free, NC pF5.2 Capacitor Equivalent Circuits(a) Property editor (b) Equivalent circuitFigure 4. Capacitor property editor and equivalent circuitThe default value of ESR is 0.01 Ω.(Note 2) These parameters can take any positive value or zero in simulation but it does not guarantee the operation of the IC in any condition. Refer to the datasheet to determine adequate value of parameters.6 Recommended Products6.1 Op-AmpTLR2377YFVM-C : Automotive High Precision & Input/Output Rail-to-Rail CMOS Operational Amplifier (DualOp-Amp). [JP] [EN] [CN] [KR] [TW] [DE]TLR377YG-C : Automotive High Precision & Input/Output Rail-to-Rail CMOS Operational Amplifier. [JP] [EN] [CN] [KR] [TW] [DE]LMR1802G-LB : Low Noise, Low Input Offset Voltage CMOS Operational Amplifier. [JP] [EN] [CN] [KR] [TW] [DE] Technical Articles and Tools can be found in the Design Resources on the product web page.NoticeROHM Customer Support System/contact/Thank you for your accessing to ROHM product informations.More detail product informations and catalogs are available, please contact us.N o t e sThe information contained herein is subject to change without notice.Before you use our Products, please contact our sales representative and verify the latest specifica-tions :Although ROHM is continuously working to improve product reliability and quality, semicon-ductors can break down and malfunction due to various factors.Therefore, in order to prevent personal injury or fire arising from failure, please take safety measures such as complying with the derating characteristics, implementing redundant and fire prevention designs, and utilizing backups and fail-safe procedures. ROHM shall have no responsibility for any damages arising out of the use of our Poducts beyond the rating specified by ROHM.Examples of application circuits, circuit constants and any other information contained herein areprovided only to illustrate the standard usage and operations of the Products. The peripheral conditions must be taken into account when designing circuits for mass production.The technical information specified herein is intended only to show the typical functions of andexamples of application circuits for the Products. ROHM does not grant you, explicitly or implicitly, any license to use or exercise intellectual property or other rights held by ROHM or any other parties. ROHM shall have no responsibility whatsoever for any dispute arising out of the use of such technical information.The Products specified in this document are not designed to be radiation tolerant.For use of our Products in applications requiring a high degree of reliability (as exemplifiedbelow), please contact and consult with a ROHM representative : transportation equipment (i.e. cars, ships, trains), primary communication equipment, traffic lights, fire/crime prevention, safety equipment, medical systems, servers, solar cells, and power transmission systems.Do not use our Products in applications requiring extremely high reliability, such as aerospaceequipment, nuclear power control systems, and submarine repeaters.ROHM shall have no responsibility for any damages or injury arising from non-compliance withthe recommended usage conditions and specifications contained herein.ROHM has used reasonable care to ensur e the accuracy of the information contained in thisdocument. However, ROHM does not warrants that such information is error-free, and ROHM shall have no responsibility for any damages arising from any inaccuracy or misprint of such information.Please use the Products in accordance with any applicable environmental laws and regulations,such as the RoHS Directive. For more details, including RoHS compatibility, please contact a ROHM sales office. ROHM shall have no responsibility for any damages or losses resulting non-compliance with any applicable laws or regulations.W hen providing our Products and technologies contained in this document to other countries,you must abide by the procedures and provisions stipulated in all applicable export laws and regulations, including without limitation the US Export Administration Regulations and the Foreign Exchange and Foreign Trade Act.This document, in part or in whole, may not be reprinted or reproduced without prior consent ofROHM.1) 2)3)4)5)6)7)8)9)10)11)12)13)。

《2024年无穷维Hamilton算子的拟谱》范文

《2024年无穷维Hamilton算子的拟谱》范文

《无穷维Hamilton算子的拟谱》篇一摘要:本文旨在探讨无穷维Hamilton算子的拟谱问题。

首先,我们将介绍Hamilton算子的基本概念及其在物理和数学领域的重要性。

随后,我们将阐述拟谱方法的基本原理和在处理无穷维系统中的优势。

最后,我们将详细描述我们的研究方法和结果,以及这些结果对无穷维系统理论和相关领域研究的潜在贡献。

一、引言Hamilton算子是一种广泛应用于量子力学、光学、电磁学等领域的数学工具。

在处理具有无穷维度的系统时,Hamilton算子的谱问题变得尤为重要。

然而,由于无穷维系统的复杂性,直接求解其谱往往面临巨大挑战。

因此,寻求有效的拟谱方法成为研究的关键。

二、Hamilton算子的基本概念Hamilton算子是一种描述系统动力学的算子,具有特定的形式和性质。

在量子力学中,它描述了粒子的能量和动量关系。

在光学和电磁学中,它用于描述光场或电磁场的演化。

由于系统的复杂性,Hamilton算子往往具有无穷维度,使得其谱的求解变得困难。

三、拟谱方法的基本原理及优势拟谱方法是一种用于处理无穷维系统的数学方法。

它通过将系统在一定的近似空间中进行展开,将原本复杂的无穷维问题转化为有限维问题进行处理。

这种方法在处理具有复杂相互作用的系统时具有显著优势,能够有效地降低问题的复杂度。

四、无穷维Hamilton算子的拟谱研究针对无穷维Hamilton算子的拟谱问题,我们采用了一种基于拟谱方法的解决方案。

首先,我们选择了一个合适的近似空间,将Hamilton算子在这个空间中进行展开。

然后,我们利用数值方法求解展开后的有限维问题,得到Hamilton算子的近似谱。

最后,我们通过分析近似谱的性质,了解原系统的动力学特性。

五、研究方法与结果我们采用了一种基于多项式展开的拟谱方法。

首先,我们选择了一组合适的多项式基函数作为近似空间的基底。

然后,我们将Hamilton算子在这组基底上进行展开,得到一个有限维的矩阵表示。

量子化学课程习题及标准答案

量子化学课程习题及标准答案

量子化学习题及标准答案Chapter 011. A certain one-particle,one-dimensional system has/2bmx ibt e ae --=ψ,where a and b are constants and m is theparticle ’s mass. Find thepotential-energy function V for thissystem. (Hint : Use the time-dependentSchrodinger equation.)Solution :As (x,t) is known, we canderive the corresponding derivatives. ⎪⎪⎩⎪⎪⎨⎧ψ+ψ-=∂ψ∂ψ-=∂ψ∂⇒=ψ--222222/42),(),(),(2 x m b bm xt x ib t t x e ae t x bmx ibtAccording to time-dependentSchroedinger equation,substituting into the derivatives, weget222),(mx b t x V =2. At a certain instant of time, aone-particle, one-dimensional systemhas bx xe b /||2/13)/2(-=ψ, where b = 3.000 nm. If ameasurement of x is made at this time inthe system, find the probability thatthe result (a) lies between 0.9000 nm and0.9001 nm (treat this interval asinfinitesimal); (b) lies between 0 and2 nm (use the table of integrals, ifnecessary). (c) For what value of x isthe probability density a minimum?(There is no need to use calculus toanswer this.) (d) Verify that ψ isnormalized. 222(,)(,)2x t x t V i t m x∂ψ∂ψ=-+∂∂Solution :a) The probability of findingan particle in a space between x and x+dx is given by6/223210*29.32--==ψ=dx e x b dx P b x b) 0753.02910*20/223==⎰--dx e x bP b x c) Clearly, the minimum of probabilitydensity is at x=0, where the probabilitydensity vanishes. d)4220/223/223/2232===ψ=⎰⎰⎰⎰+∞-+∞∞--+∞∞--+∞∞-dx e x b dx e x b dx e x b dx P b x b x b x3. A one-particle, one-dimensionalsystem has the state function2222/4/16/4/12)/32)((cos )/2)((sin c x c x xe c at e c at --+=ψππwhere a is a constant and c = 2.000 Å.If the particle ’s position is measuredat t = 0, estimate the probability thatthe result will lie between 2.000 Å and2.001 Å.Solution :when t=0, the wavefunction is simplified as441610*158.2)32(),(22--==ψc x xec t x πChapter 021. Consider an electron in a one-dimensional box of length2.000Åwith the left end of the box at x = 0.(a) Suppose we have one million of these systems, each in the n= 1 state, and we measure the x coordinate of the electron in each system. About how many times will the electron be found between 0.600 Åand 0.601 Å? Consider the interval to be infinitesimal. Hint: Check whether your calculator is set to degrees or radians.(b) Suppose we have a large number of these systems, each in the n =1 state, and we measure the x coordinate of the electron in each system and find the electron between 0.700 Å and 0.701 Å in 126 of the measurements. In about how many measurements will the electron be found between 1.000 Å and 1.001 Å? Solution: a) In a 1D box, the energyand wave-function of a micro-system are given by)sin(2,22222x ln l ml n E πψπ== therefore, the probability density offinding the electron between 0.600 and0.601 Å is65510*545.6)(sin 242⇒==-dx x ln l P πb) From the definition of probability,the probability of finding an electron between x and x+dx is given bydx x l n l P )(sin 22π= As the number of measurements of findingthe electron between 0.700 and 0.701 Å is known, the number of system is1(sin 22*158712158712001.0)7.02*1(sin 2212612622=⇒===πP P N2. When a particle of mass 9.1*10-28 g ina certain one-dimensional box goes from the n = 5 level to the n = 2 level, itemits a photon of frequency 6.0*1014 s -1.Find the length of the box. Solution.lml h n n ml n n E lower up lower up 36222222222110*26646.18)(2)(-=-=-=∆ π3. An electron in a stationary state of a one-dimensional box of length 0.300 nmemits a photon of frequency 5.05*1015 s -1.Find the initial and final quantum numbers for this transition. Solution:2,388)(2)(22222222222===-⇒=-=-=∆lower upper lower up lower up lower up n n n n hv ml h n n ml n n E π4. For the particle in a one-dimensional box of length l , we could have put the coordinate origin at the center of the box. Find the wave functions and energylevels for this choice of origin.Solution: The wavefunction for a particle in a one-dimernsional box can be written as)2()2()(x mE BSin x mE ACos x+=ψ If the coordinate origin is defined at the center of the box, the boundary conditions are given as2()22(0)(2()22(0)(22mE BSin l mE ACos x mE BSin l mE ACos x l x lx +⇒=-⇒==-= ψψ Combining Eq1 with Eq2, we get)4(,0)22()3(,0)22(Eq l mE BSin Eq l mE ACos ==Eq3 leads to A=0, or )22(l mE Cos =0. We willdiscuss both situations in the following section.If A=0, B must be non-zero number otherwise the wavefunction vanishes.2220)22(02mlh n E n l mE l mE Sin B π=⇒=⇒=⇒≠If A ≠08)12()21(220)22(00)22(0)22(0222mlh n E n l mE l mE Cos B l mE Sin l mE Cos A ψπ⇒+=⇒+=⇒==⇒≠⇒=⇒≠5. For an electron in a certain rectangular well with a depth of 20.0 eV, the lowest energy lies 3.00 eV above the bottom of the well. Find the width of this well. Hint : Use tanθ = sin θ/cos θ Solution : For the particle in a certainrectangular well, the E fulfill with)2sin()2()2cos()(21010l mE V E l mE E E V ---=- Substituting into the V and E, we get1010011110*64.22)7954.0(7954.022)(2)2()2()2(-----=⇒+-=⇒+-=⇒-=--==lowest l mEn l n l mE V E E E V l mE Tan l mE Cos l mE Sin ππChapter 03 1. If A ˆf (x ) = 3x 2f (x ) + 2xd f /dx , givean expression for Aˆ. Solution :Extracting f(x) from the known equationleads to the expression of Adx d x x A 23ˆ2+=2. (a) Show that (Aˆ+Bˆ)2= (Bˆ+Aˆ)2for any two operators. (b) Under what conditionsis (A ˆ+B ˆ)2 equal to A ˆ2+2A ˆB ˆ+B ˆ2?Solution:a)2222ˆ()ˆˆ)(ˆˆ(ˆˆˆˆˆˆˆˆˆˆˆ)ˆˆ)(ˆˆ()ˆˆ(B A B A BA B A A B B A B B A A B A B A B A =++=+++=+++=++=+ b)B AA B A B B A A B A ˆˆ2ˆˆˆˆˆˆˆ)ˆˆ(2222++=+++=+If and only if A and B commute, (Aˆ+Bˆ)2equals to A ˆ2+2A ˆB ˆ+B ˆ2 3. If A ˆ = d 2/dx 2 and B ˆ = x 2, find (a) A ˆB ˆx 3; (b) B ˆA ˆx 3; (c) AˆB ˆf (x ); (d)B ˆA ˆf (x )Solution:a)3522320ˆˆx x dxd x B A == b)3322236ˆˆx x dxd x x A B == c))()(4)(2)]()(2[)]([)(ˆˆ2222222x f dxd x x f dx d x x f x f dxd x x xf dx d x f x dx d x f B A ++=+==d))()()(ˆˆ222222x f dxd x x f dx d x x f A B ==4. Classify these operators as linear ornonlinear: (a) 3x 2d 2/dx 2; (b) ( )2; (c) ∫dx ; (d) exp; (e) ∑=n x 1.Solution:Linear operator is subject to the following condition.f A c cf Ag A f A g f A ˆ)(ˆˆˆ)(ˆ=+=+ a) Linearb) Nonlinear c) Linear d) Nonlinear e) Linear5. The Laplace transform operator Lˆ is defined by⎰∞-=0)()(ˆdx x f e x f L px(a) Is L ˆ linear? (b) Evaluate L ˆ(1). (c)Evaluate L ˆe ax , assuming that p >a .Solution:a) L is a linear operatorb),1)1(ˆ0>==⎰∞-p p dx e L px c)pdx e dx e e e L x a p ax px ax ===⎰⎰∞--∞-)(ˆ0)(06. We define the translation operator hTˆ by hT ˆf (x ) = f (x + h ). (a) Is hT ˆ a linear operator? (b) Evaluate(2ˆ3ˆ121+-T T )x 2.Solution:a) The translation operator is linear operator2212212121(2ˆ3ˆ)2ˆ3ˆ(x x x T x T x T T +=+-=+-7. Evaluate the commutators (a) [xˆ,xp ˆ]; (b) [x ˆ,2ˆxp ]; (c) [x ˆ,y p ˆ]; (d) [x ˆ, ),,(ˆz y x V ]; (e)[xˆ,H ˆ]; (f) [z y x ˆˆˆ, 2ˆxp ]. Solution:a)i xx x x i x x i p xx =∂∂--∂∂-=∂∂-=)ˆ1ˆ(],ˆ[]ˆ,ˆ[b)xp i p p x p x p p xx x x x x x∂∂==+=222ˆ2)ˆ]ˆ,ˆ[]ˆ,ˆ[ˆ(]ˆ,ˆ[c)0)ˆˆ(],ˆ[]ˆ,ˆ[=∂∂-∂∂-=∂∂-=yx y x i y x i p xy0ˆ),,(ˆ),,(ˆˆ)],,(ˆ,ˆ[=-=x z y x V z y x V x z y x V xe)mxT x V T x H x ==+=21,ˆ[]ˆ,ˆ[]ˆˆ,ˆ[]ˆ,ˆ[f)xz y p z y xx∂∂=ˆˆ2]ˆ,ˆˆˆ[22Chapter 041:The one-dimensional harmonic-oscillator is at its first excited state and its wavefunction is given as)21exp()()(2)(24/14/31x x x βπβψ-=please evaluate the expectation values(average values) of kinetic energy (T), potential energy (V) and the total energy.Answer: 1) First of all, check the normalization property of the wavefunction.2) Evaluate the expectationvalue of kinetic energy.3) Evaluate the expectation valueof potential energy4) Total Energy = T + V 2. The one-dimensional harmonic-oscillator Hamiltonian is2222ˆ22ˆˆxm v mp H xπ+= The raising and lowering operators forthis problem are defined as]ˆ2ˆ[)2(1ˆ2/1x ivm p m A x π+=+, ]ˆ2ˆ[)2(1ˆ2/1x ivm p m A x π-=-Show thathv H A A 21ˆˆˆ-=-+, hv HA A21ˆˆˆ+=+-, hv A A-=-+]ˆ,ˆ[ ++=A hv A H ˆ]ˆ,ˆ[, ---=A hv A Hˆ]ˆ,ˆ[ Show that +Aˆ and -A ˆ are indeed ladder operators and that the eigenvalues are spaced at intervals of hv . Since both the kinetic energy and the potential energy are nonnegative, we expect the energy eigenvalues to be nonnegative. Hence there must be a state of minimum energy. Operate on the wave function for thisstate first with -A ˆ and then with +Aˆ and show that the lowest energy eigenvalueis hv 21. Finally, conclude that hvn E )21(+=, n = 0, 1, 2, …Answer:1) Write down the definition of operatordx di px -=ˆ2) Expand the operators in full form.]2[21]2[2122ˆ222222vmxi dx di mA vmxi dx d i mA mx v dx d m H πππ--=+-=+-=-+ 3) Evaluate the correspondingcombination of operators]22][2[21ˆ4222[21]2[2]2[2[21]2[21]22[ˆ21ˆ2122]4222[21]]2[2]2[[21]2[21]2[2121ˆ2122]42[21]4222[21]]2[2]2[[21]2[21]2[21222222332222222333222222222222222222222222222222222222222222222mx v dx d m vmxi dx d i mH A v dx d i mx v dx d ix v dx d i v dxd m i m vmxi dx d i mx v vmxi dx d i dxd m m vmxi dx d i mmx v dx d m A H hv H hv mx v dx d m x m v dxd vmx dx d x vm vm dx d m vmxi dxd i vmxi vmxi dx d i dx d i m vmxi dx d i mvmxi dx d i m A A hv H hv mx v dx d m x m v vm dxd m x m v dxd vmx dx d x vm vm dx d m vmxi dxd i vmxi vmxi dx d i dx d i m vmxi dx d i mvmxi dx d i m A A πππππππππππππππππππππππππππππππππ+-+-=+---=+-++--=+-+-=+=++-=+-++-=+--+--=+---=-=-+-=+--=++---=--+---=--+-=+++--++++=+-=+-=+-=-hvA vmxi m dx d i m hv vmxi m hv dxd i m hv mxi v dx d i v m H A A H ]22121[]221[]21[]42[21ˆˆ222ππππIn the same manner, we can get---=-hvA H A A H ˆˆ 4) Substituting the above communicatorsinto the Schroeidnger equation, we getψψψψψψψψψψψψ------++++++-=-=-=+=+=+==A hv E hvA E A hvA H A A H A hv E hvA E A hvA H A A H E H)(]ˆ[ˆ)(]ˆ[ˆˆThis shows that +Aˆ and -A ˆ are indeed ladder operators and that theeigenvalues are spaced at intervals ofhv . 5) Suppose that is the eigenfunctionwith the lowest eigenvalue. ψψlowest E H =ˆAccording to the definition of A_operator, we haveψψ---=A hv E A H )(ˆ As is the eigenfunction with thelowest eigenvalue, the above equation isfulfilled if and only if 0=-ψAOperating on the wave function for thisstate first with -Aˆ and then with +A ˆ leads to ψψψψhv H hv H A A 21ˆ]21ˆ[0=⇒-==-+Therefore, the lowest energy is 1/2 hv.3,2,1,0,)(21ˆ=+=n hv n H ψψChapter 051. For the ground state of theone-dimensional harmonic oscillator,compute the standard deviations x andp x and check that the uncertaintyprinciple is obeyed.Answer:1) The ground state wavefunction of theone-dimensional harmonic oscillator isgiven by2214141)(x e ααπψ--=2) The standard deviations x and p xare defined as222x x x -=∆222)∆∆-=p(p∆)(pThe product of x and p is given by2422122 ==∙=∆∆ααp xIt shows that the uncertainty principleis obeyed.2. (a) Show that the three commutationrelations [x L ˆ,y L ˆ] = z L i ˆ , [y L ˆ,z L ˆ] = x L i ˆ , [z L ˆ,x Lˆ] = y Li ˆ are equivalent to the single relation L L Lˆˆˆ i =⨯ (b) Find [2ˆx L ,y L ˆ] Answer:1): zy x y x z x z y z y x y x x z z y x y y x z x x z y z z y y z x z z y x y z x y x z y x z y x z y x L i L L L i L L L i L L k L j L i L i k L L j L L i L L k L L L L j L L L L i L L L L i L L j L L i L L k L L j L L k L L k L j L i L k L j L i L L L k L j L i L L ===⇒++=++=-+-+-=-++--=++⨯++=⨯++=],[],[],[)(],[],[],[)()()()()(ˆˆˆ2):)()()(],[],[],[2x z z x xz z x x y x y x x y x L L L L i L L i L i L L L L L L L L L +=+=+=3. Calculate the possible angles betweenL and the z axis for l = 2.Answer:The possible angles between L and thez axis are equivalent the angles betweenL and L z . Hence, the angles are given by:Lm Cos L z ==+=θ6)12(2 ︒︒︒︒=7.144,10.114,00.90,91.65,26.35θ 4. Complete this equation:m l m l z Y m Y L 333ˆChapter 061. Explain why each of the following integrals must be zero, where the functions are hydrogenlike wave functions: (a) <2p 1|z L ˆ|3p -1>; (b) <3p 0|z L ˆ|3p 0>Answer:Both 3p -1 and 3p 0 are eigenfunctions of L z , with eigenvalues of -1 and 0, respectively. Therefore, the above integrals can be simplified asa) due to orthogonalization properties of eigenfunctions03|213ˆ21111=-=--p p p L p z b) 02. Use parity to find which of the following integrals must be zero: (a)<2s |x |2p x >; (b) <2s |x 2|2p x >; (c)<2p y |x |2p x >. The functions in these integrals are hydrogenlike wave functions.Answer:1) b) and c) must be zero.3. For a hydrogen atom in a p state, the possible outcomes of a measurement of L z are – ħ, 0, and ħ. For each of the following wave functions, give the probabilities of each of these three results: (a)z p 2ψ; (b) y p 2ψ; (c) 12p ψ. Then find <L z > for each of these three wave functions.Answer:a) 022p p z ψψ=, therefore, the probabilities are: 0%, 100%, 0% )(2111222-+=p p p x ψψψ, the probabilities are 50%, 0%, 50%.12p ψ,the probabilities are 100%, 0%, 0% b) 0,0,14. A measurement yields 21/2ħ for themagnitude of a particle’s orbital angular momentum. If L x is now measured,what are the possible outcomes?Answer:1): Since the wavefunction is the eigenfunction of L2, a measurement of the magnitude of the orbital angular momentum should be+LLL=)1⇒21 (=,The possible outcomes when measure L x are-1, 0, 1Chapter 071. Which of the following operators areHermitian: d /dx , i (d /dx ), 4d 2/dx 2,i (d 2/d x 2)?Answer :An operator in one-D space is Hermitianif⎰⎰=dx A dx A **)ˆ(ˆψψψψ a)⎰⎰⎰⎰-=-=-=∞∞-dx dx d dx dx d dx dx d dx dxd *****)(ψψψψψψψψψψ b)⎰⎰⎰⎰=-=-=∞∞-dx dx d i dx d i dx dx d i i dx dx d i ****)(ψψψψψψψψψψc)⎰⎰⎰⎰⎰=+-=-=-=∞∞-∞∞-dxdxddxddxddxdxddxddxddxddxddxdxdψψψψψψψψψψψψψ2*22****22*44 444 44This operator can be written as a product of 1D kinetic operator and a constant. Hence, it’s Hermitian.d) As the third operator is Hermitian, this operator is not Hermitian.2. If Aˆ and Bˆ are Hermitian operators, prove that their product AˆBˆ is Hermitian if and only if Aˆ and Bˆcommute. (b) If Aˆ and Bˆ are Hermitian,prove that 1/2(A ˆB ˆ+B ˆA ˆ) is Hermitian. (c)Is x px ˆˆHermitian? (d) Is 1/2(x p x ˆˆ+x p xˆˆ) Hermitian?Answer:1)If operator A and B commute , we have⎰=-⇒=-⇒=0])ˆˆˆˆ[(0ˆˆˆˆˆˆˆˆˆ*τψψd A B B AA B B A A B B A ⎰⎰⎰=⇒=-⇒τψψτψψτψψd A B d B A d A B B A ***]ˆˆ[]ˆˆ[0])ˆˆˆˆ[( Operator A and B are Hermitian, we have⎰⎰⎰==⇒τψψτψψτψψd B A d B A d A B ˆˆ)ˆ()ˆ(]ˆˆ[***Therefore, when A and B commute, thefollowing equation fulfills. Namely, ABis also Hermitian.⎰⎰=τψψτψψd B A d B A ˆˆ]ˆˆ[** 2)]ˆˆˆˆ[21)]ˆˆˆˆ(21[***⎰⎰⎰+=+τψψτψψτψψd A B d B A d A B B AOperator A and B are Hermitian, we get⎰⎰⎰⎰⎰⎰⎰+=+⇒+=+=+τψψτψψτψψτψψτψψτψψτψψd A B B A d A B B A d B A A B d B A d A B d A B d B A *******])ˆˆˆˆ(21[)ˆˆˆˆ(21])ˆˆˆˆ(21[)ˆˆ()ˆˆ([21]ˆˆˆˆ[21The above equation shows that theoperator 1/2[AB+BA] is Hermitian.c) xp x is not Hermitian since both x andpx are Hermitian and do not commute.d) YesChapter 081. Apply the variation function cr e -=φtothe hydrogen atom; choose the parameterc to minimize the variational integral,and calculate the percent error in theground-state energy.Solution :1) The requirement of the variationfunction being a well-behaved functionrequires that c must be a positivenumber.2) check the normalization of the variation function.322*)(c d d Sin dr r e d cr πϕθθτφφ==⎰⎰⎰⎰- 3) The variation integral equals to)2(214])2[(2)1(21()121(ˆ32223*32*32*3**-=-∂∂+∂∂-=-∇-=-∇-==⎰⎰⎰⎰⎰⎰--c c c dr r e rr r e c d r c c d r c d d H w cr cr τφφπφπτφφπτφφτφφ4) The minimum of the variation integral is 21101-=⇒=⇒=-=∂∂w c c c w5) The percent error in the ground stateis 0%2. If the normalized variation functionx l 2/13)/3(=φ for 0 ≤ x ≤ l is applied tothe particle-in-a-one-dimensional-boxproblem, one finds that the variationintegral equals zero, which is less thanthe true ground-state energy. What is wrong?Solution:The correct trail variation function must be subject to the same boundary condition of the given problem. For the particle in a 1D box problem, the correct wavefunction must equal to zero at x=0 and x=l. However, the trial variation function x l 2/13)/3(=φ does not fulfill these requirement. The variation integral based on this incorrect variation function does not make any sense.3. Application of the variation function 2cx e -=φ(where c is a variationparameter) to a problem with V = af (x), where a is a positive constant and f (x ) is a certain function of x , gives thevariation integral as W = c ħ2/2m+15a /64c 3. Find the minimum value of Wfor this variation function.Solution:23434123434141min 4141413272598.03)25(23)25(0)64152(m a m a w m a c dc c a m c d c w ==⇒±=⇒=+=∂∂4. In 1971 a paper was published that applied the normalized variationfunction N exp(-br 2a 02-cr /a 0) to thehydrogen atom and stated that minimization of the variation integral with respect to the parameters b and c yielded an energy 0.7% above the true ground-state energy for infinite nuclear mass. Without doing any calculations, state why this result must be wrong. Solution:From the evaluation of exercise 1, we know that the variation function exp(-cr) gives no error in the ground state of hydrogen atom. This function is a special case of the normalized variationfunction N exp(-br 2a 02-cr /a 0) when bequals to zero. Therefore, adopting the normalized variation function as a trial variation function should also have no error in the ground state energy for hydrogen atom.5. Prove that, for a system with anondegenerate ground state, 0*ˆE d H >⎰τφφ, ifφ is any normalized, well-behaved function that is not equal to the true ground-state wave function. (E 0 is thelowest-energy eigenvalue of H ˆ) Solution:As the eigenfunctions of the Hermitian operator H form a complete set, any well-behaved function which is subjectto the same boundary condition can be expanded as a linear combination of the eigenfunction of the Hermitian operator, namely,∑∞==0i i i c ψφ, where i s are eigenfunctions of Hermitian operator H, c i s are constant.The expectation valueof with respect to the Hermitian operator is0201020201020020*00**00*0*0*ˆˆ)(ˆE c E E c E c c E c E c E c c E c cH c c d c H c d H i i i i i i i i i i i i i ij j j j i i i j j i i j j j i i i ==+>+======∑∑∑∑∑∑∑⎰∑∑⎰∑∑⎰∞=∞=∞=∞=∞=∞=∞=∞=∞=∞=∞=δψψτψψτφφChapter 09, 101. For the anharmonic oscillator with Hamiltonian43222212ˆdx cx kx dx d m H +++-= , evaluate E (1) for the first excited state, taking the unperturbed system as the harmonic oscillator.Solution:The wavefunction of the first excited state of the harmonic oscillator is241312)4(x xe απαψ-=Hence, the first order correct to energy of the first excited state is given by6213422134134324131'*1415)4()4()4)(()4(ˆ222απαπαπαπαψψαααd dx e x d dx x d e x xe x d x c xe dx H x x x ==∙=∙+∙=---⎰⎰⎰⎰2. Consider the one-particle, one-dimensional system withpotential-energyV = V 0 for l x l 4341<<, V = 0 for l x 410≤≤ and l x l ≤≤43and V = ∞ elsewhere, where V 0 = 22/ml .Treat the system as a perturbed particle in a box. (a) Find the first-order energy correction for the general stationary state with quantum number n . (b) Find the first-order correction to the wave function of the stationary state with quantum number n .Solution:The wavefunction of a particle in 1D box is given by)(2)0(x ln Sin l n πψ= Take this as unperturbed wavefunction, and the perturbation H ’ is given by V. a) The first-order energy correction forn is])23[]2[(224]2[4[2)()(2)()(2ˆ00004341)0('*)0()1(πππππππππψψn Sin n Sin n V V n S n Sin l l V dx V x l n Sin x l n Sin l dx x ln VSin x l n Sin l dx H E l ln n -+=-+====⎰⎰⎰b) The first correction to the wavefunction is given by)0()0()0()0()0()1(2)0()0(222)0('(818mn m mn nm n mn n E E H n E E ml h n E ψψψψ∑∞≠-==-⇒=3. For an anharmonic oscillator with3222212ˆcx kx dx d m H ++-= , take 'ˆH as cx 3. (a) Find E (1) for the state with quantum number v .(b) Find E (2) for the state with quantumnumber v . You will need the following integral:3,'2/13)0(3)0('2/)1[(3]8/)3)(2)(1[(||++++++>=<v v v v v v v v x αδαψψ1,'2/38/)2)(1([)2/(3---++v v v v v v αδα Solution: a) As the potential of the unperturbed is a even function, the eigenfunctions of the unperturbed system are either even or odd. The perturbation is an odd function with respect to x. Hence, thefirst order energy correction is zero.b) The second order energy correction is given by)51212(8]38)2)(1(838)1(338)3)(2)(1([()2(3)21(38)3)(2)(1((''2323333332)0()0(1,2/31,2/33,32)0()0(2)0(3)0()0()0()0()0()0()0()2(++-=--++-++-+++=-+++++++=-=-=∑∑∑∞≠-++∞≠∞≠n n hvc hvn n n hv n hv n hv n n n c E E n n n n n n n c E E cx E E H H E n m mn n n n n n n n m mn m n n m m n m n nm n αααααδαδαδαψψψψψψ4. Calculate the angle that the spin vector S makes with the z axis for an electron with spin function α.Solution:For an electron, both S and S z equal to one half. The magnitude of S is74.54]31[23)1(===+=ArcCos S S S θ5. (a) Show that 12ˆP and 23ˆP do not commutewith each other. (b) Show that 12ˆPand 23ˆP commute when they are applied to antisymmetric functions. Solution:a) Set the wavefunction to be)1()3()2()2()1()3(321321φφφφφφ≠b) When the function is antisymmetric, we haveψψψψψψψ2312121223231223ˆˆ)(ˆˆˆ)(ˆˆˆP P P P P P P P =-=-==-=-=6. Which of the following functions are (a) symmetric? (b) antisymmetric?(1) )2()1()2()1(ααg f ; (2) )]2()1()2()1()[2()1(αββα-f f ;(3) )3()2()1()3()2()1(βββf f f ; (4) )(21r r a e --;(5) )]1()2()2()1()][2()1()2()1([βαβα--f g g f ; (6) )(21221r r a e r +-. Solution:(2) is antisymmetric(3), (5) and (6) are symmetricChapter 11, 131. How many electrons can be put in each of the following: (a) a shell with principal quantum number n ; (b) a subshell with quantum numbers n and l ; (c) an orbital; (d) a spin-orbital? Solution:a) 2n 2, b) 2*(2l+1), c) 2, d) 12. Give the possible values of the total-angular-momentum quantum number J that result from the addition of angular momentum with quantum numbers (a) 3/2 and 4; (b) 2, 3, and 1/2 Solution:Coupling between two angular momentums with quantum number j 1 and j 2 gives the possible quantum number J of the total angular momentum as:2121j j J j j +<<-a) The possible values are 11/2, 9/2, 7/2,5/2b) The possible values are:11/2, 9/2, 9/2, 7/2, 7/2, 5/2, 5/2, 3/2, 3/2, 1/23. Find the terms that arise from each of the following electron configurations: (a) 1s22s22p63s23p5g; (b) 1s22s22p3p3d (c) 1s22s22p24dSolution:As fully-filled sub-shells do not contribution the total orbital and spin angular momentum, we can ignore the electrons in these sub-shells while considering the atomic terms. Hence, a) The atomic terms can be:3H, 1H, 3G, 1G, 3F, 1Fb) The atomic terms can be:4G, 2G, 4F, 2F, 4D, 2D, 4P, 2P, 4S, 2S4F 2F, 4D, 2D, 4P, 2P4D, 2D, 4P, 2P, 4S, 2Sc) The atomic terms can be:。

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4
It remains to check that (6) entails λ2j −1 (f (AE )) ≤ λj (f (A)E ). This follows from the forthcoming elementary observation. Proposition 1.2. Let X , Y be Hermitians such that UY U∗ + V Y V ∗ X≤ 2 for some unitaries U , V . Then, for j = 1, 2, . . . , λ2j −1 (X ) ≤ λj (Y ). 2
Abstract. We establish several convexity results for Hermitian matrices. For instance: Let A, B be Hermitian and let f be a convex function. If X and Y stands for f ({A + B }/2) and {f (A) + f (B )}/2 respectively, then there exist unitaries U , V such that UY U∗ + V Y V ∗ . 2 This is nothing but the matrix version of the scalar convexity inequality X≤ f a+b 2 ≤ f (a) + f (b) . 2
As a consequence we get, λ2j −1 (X ) ≤ λj (Y ), where λj (·) are the eigenvalues arranged in decreasing order. Keywords: Hermitian operators, eigenvalues, operator inequalities, Jensen’s inequality Mathematical subjects classification: 47A30 47A63
∗ 0 U0 . 0 V0∗
Besides we note that, still in respect with the decomposition E = E ′ ⊕ E ′′ , f (A)E ′ 0 So, letting U= we get f (AE ) ≤ U f (A)E U ∗ + V f (A)E V ∗ . 2 (6) U0 0 0 V0 and V = U0 0 0 − V0 0 f (A)E ′′ = 1 2 I 0 f (A)E 0 I I 0 I 0 + f (A)E 0 I 0 −I I 0 0 −I .
When f is convex and monotone, we showed [2] that (2) can be extended to an operator inequality: There exists a unitary U such that f A+B 2 ≤U·
1Байду номын сангаас
f (A) + f (B ) · U∗ 2
Hermitian operators and convex functions
arXiv:math/0601318v2 [math.OA] 16 Jan 2006
Jean-Christophe Bourin E-mail: bourinjc@club-internet.fr Universit´ e de Cergy-Pontoise, d´ ept. de Math´ ematiques 2 rue Adolphe Chauvin, 95302 Pontoise, France
Introduction
The main aim of this paper is to give a matrix version of the scalar inequality f a+b 2 ≤ f (a) + f (b) 2 (1)
for convex functions f on the real line. Capital letters A, B . . . Z mean n-by-n complex matrices, or operators on a finite dimensional Hilbert space H; I stands for the identity. When A is positive semidefinite, resp. positive definite, we write A ≥ 0, resp. A > 0. A classical matrix version of (1) is von Neuman’s Trace Inequality: For Hermitians A, B , Tr f A+B 2 ≤ Tr f (A) + f (B ) 2 (2)
1. Compressions
Our substitute to (4) for general convex functions (on the real line) is: Theorem 1.1. Let A be Hermitian, let E be a subspace and let f be a convex function. Then, there exist unitaries U , V on E such that U f (A)E U ∗ + V f (A)E V ∗ . f (AE ) ≤ 2 Consequently, for j = 1, 2, . . . , λ2j −1 (f (AE )) ≤ λj (f (A)E ).
3
Proof. We may find spectral subspaces E ′ and E ′′ for AE and a real r such that (i) E = E ′ ⊕ E ′′ , (ii) the spectrum of AE ′ lies on (−∞, r ] and the spectrum of AE ′′ lies on [r, ∞), (iii) f is monotone both on (−∞, r ] and [r, ∞). Let k be an integer, 1 ≤ k ≤ dim E ′ . There exists a spectral subspace F ⊂ E ′ for AE ′ (hence for f (AE ′ )), dim F = k, such that λk [f (AE ′ )] =
(3)
2
We also established similar inequalities involving more general convex combinations. These inequalities are equivalent to an inequality for compressions. Recall that given an operator Z and a subspace E with corresponding orthoprojection E , the compression of Z onto E , denoted by ZE , is the restriction of EZ to E . Inequality (3) can be derived from: For every Hermitian A, subspace E and monotone convex function f , there exists a unitary operator U on E such that f (AE ) ≤ U f (A)E U ∗ . (4) Inequalities (3) and (4) are equivalent to inequalities for eigenvalues. For instance (4) can be rephrased as λj (f (AE )) ≤ λj (f (A)E ), j = 1, 2, . . . where λj (·), j = 1, 2, . . . are the eigenvalues arranged in decreasing order and counted with their multiplicities. Having proved an inequality such as (3) for monotone convex functions, it remains to search counterparts for general convex functions. We derived from (3) the following result for even convex functions f : Given Hermitians A, B , there exist unitaries U , V such that U f (A)U ∗ + V f (B )V ∗ A+B . (5) ≤ f 2 2 This generalizes a wellknown inequality for the absolute value, |A + B | ≤ U |A|U ∗ + V |B |V ∗ We do not know whether (5) is valid for all convex functions. In Section 1 we present a counterpart of (4) for all convex functions. This will enable us to give, in Section 2, a quite natural counterpart of (3) for all convex functions. Though (3) can be proven independently of (4) -and the same for the counterparts-, we have the feeling that in the case of general convex functions, the approach via compressions is more illuminating.
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