浙江省金华十校2013-2014学年高二语文下学期期末考试试题(扫描版)
浙江省金华十校2014届高三上学期期末调研考试数学(文)试题
金华十校2013-2014学年第一学期期末调研考试高三数学（文科）试题卷本试卷分第Ⅰ卷和第Ⅱ卷两部分.考试时间120分钟. 试卷总分为150分。
请考生按规定用笔将所有试题的答案涂、写在答题纸上.参考公式：球的表面积公式棱柱的体积公式S=4πR2 V=Sh球的体积公式其中S表示棱柱的底面积，h表示棱柱的高.V=43πR3 棱台的体积公式其中R表示球的半径V=13h(S1S2)棱锥的体积公式其中S1、S2表示棱台的上、下底面积，h表示棱V=13Sh 台的高.其中S表示棱锥的底面积，h表示棱锥的高. 如果事件A、B互斥，那么P(A+B)= P(A)+ P(B)第Ⅰ卷一、选择题：本大题共10小题，每小题5分，共50分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1. 已知集合M={x|x2-2x-3<0}，N={x| x≥1}，则M∩N=A.(3,+∞)B.(1,3)C.[1,3)D. (-1,+∞)2. 已知x∈R，i为虚数单位，若(1-i)(x+i)=1+i，则x的值等于A.0B.-1C.1D.23. “直线ax-y=0与直线x-ay=1平行”是“a=1”成立的A.充分不必要条件B.必要不充分条件C.充分必要条件D.既不充分也不必要条件4. 若m,n是两条不同的直线，α,β是两个不同的平面，则下列命题中正确的是A.α∥β, m⊂α, n⊂β⇒ m∥nB.α⊥β, n∥α, m⊥β⇒n⊥mC.m∥n, m⊥α⇒n⊥αD. m∥n, m∥α⇒ n∥α5. 执行如图所示的程序框图，输出的k 的值为A.4B.5C.6D.76. 下列函数中，在区间(0,+∞)内单调递减的是A.1y x x=-B. 2y x x =-C. ln y x x =-D.x y e x =- 7. 函数y =A sin(ωx +ϕ)（A >0,ω>0）在一个周期内的图象如图所示，则此函数的解析式是A ．2sin 24y x π⎛⎫=- ⎪⎝⎭B ．2sin 24y x π⎛⎫=+ ⎪⎝⎭C ．32sin 8y x π⎛⎫=+ ⎪⎝⎭D ．72sin 216x y π⎛⎫=+ ⎪⎝⎭8. 对于项数为m 的数列{a n }和{b n }，记b k 为a 1,a 2,…,a k (k =1,2,…,m )中的最小值。
浙江省金华十校2014届下学期高三年级4月高考模拟考试语文试卷 有答案
浙江省金华十校2014届下学期高三年级4月高考模拟考试语文试卷有答案注意：本卷共四大题，26小题。
满分l 50分，考试时间l 50分钟。
请考生按规定用笔将所有的答案写在答题纸上。
一、语言文字运用(共24分，其中选择题每小题3分)1．下列词语中加点的字，注音没有错误的一项是2．下列各句中，没有错别字的一项是A．福岛核泄漏事故发生以来，有关放射性污染和清理等方面的信息批露缺乏透明度，日本政府和相关企业的不断遮掩、欺瞒之举让本国民众和国际社会长期不安。
B．仰望夜空，总是会有不可名状的失落感涌上心头。
多么怀念幼时曾见的如金钢钻般闪耀的星辰，那些闪烁的光亮总能引起我们无限的遐想。
C．“十一”长假，杭州西湖出现“只见人头不见桥头"的画面，游客们涌人各大景区，万头攒动，磨肩接踵。
根据统计，2日当天游客量破天荒达到l。
万人次。
D．“土豪"称谓的流行，与其说是揶揄，不如说是焦虑。
焦虑的背后，则是物质日渐走向丰裕之后，对精神生活更上层楼的迷茫和向往。
3．下列各句中，加点的词语运用不正确的一项是A．近年来，空气污染加剧，影响了人们的日常生活和身体健康。
在过去的一年中，自年初至年末，由北向南，雾霾波及大半个中国。
B．等待的同时，各方传来的信息引起了人们各种猜测。
一天之后，马航客机失联一事似乎更加扣人心弦。
C．树立大国风范，涵养大国心态，让世界看到中国的开放、包容和自信，看到中国人民的团结、理性和智慧。
D．在陕西谢朝平事件、江西宜黄血拆事件中，微博狙击潜规则的表现可圈可点，对事件最终走向良性解决，几乎起到决定性的作用。
4．下列各句中，没有语病的一项是A．‘‘余额宝取消j’问题在新浪微博上被报道98700次、在百度新闻中被提及41900次，从而超越雾霾问题，位居热点话题榜首。
B．我们这个社会如果价值观迷失，是非不分、善恶不辨，即便逞强一时，也是高楼盖在沙滩上，最终难逃衰颓倒塌。
，C．浙江因水而兴，因水而生，因水而名，因水而美，从历史上的大禹治水，到今天的“五水共治”，文化内涵一脉相承，注重对生态环境的保护和利用。
高二下学期期末考试(语文)试题含答案
高二下学期期末考试（语文）（考试总分：150 分）一、现代文阅读（本题共计2小题，总分35分）1.（19分）阅读下面的文字,完成1~5题。
现代诗派因《现代》杂志而得名,其兴起的标志,是1932年在上海创刊的由施蛰存、杜衡主编的《现代》杂志。
《现代》杂志成了三十年代现代诗派诗歌创作的重要阵地,汇聚了沪、京、津等许多大城市的诗人,也集中刊发了一大批具有现代主义倾向的诗作。
戴望舒是现代诗派诗歌领袖,1932年诗坛刮起“戴望舒旋风”,其诗论被现代诗派奉为金科玉律。
主要代表人物都以各自意象新颖、想象独特的诗作,推进现代诗派诗歌的发展。
现代诗派诗歌是民族化与现代化的结晶,它标志着中国新诗的成熟。
在二十世纪三十年代阶级对垒的社会历史背景下,现代诗派诗人们大多是游离于政党与政治派别之外的边缘人;同时,许多人来自乡土,在都市中感受着传统与现代双重文明的挤压,又成为乡土和都市夹缝中的边缘人。
现代诗派诗人是都市的漂泊者,又是一代寻梦者。
他们深受法国象征派诗人的影响,濡染了波德莱尔式的对现代都市的疏离感和陌生感及魏尔伦式的世纪末颓废情绪。
而五四运动的退潮和大革命的失败,更摧毁了年青诗人的纯真信念,辽远的国土由此成为一代诗人的精神寄托。
戴望舒的《雨巷》典型地表达了一代青年普遍的理想幻灭的忧郁情绪。
作为理想象征的“丁香一样的姑娘”,像梦飘过一样,在面前一闪,转瞬即逝了。
就这样用暗示象征的手法,表达了追求美好理想而不得的那种孤苦心情。
这点深受法国象征派诗人魏尔伦的影响,魏尔伦的《无言的歌集》表达了巴黎公社失败后不知所措的知识分子苦闷沮丧的情绪,其基调是对于诗人的理想与他周围的肮脏生活相脱节的悲剧感。
在诗艺上,现代诗派诗人注重暗示的技巧,很少直接呈示主观感受,采用意象隐喻、通感、象征来间接传达情调和意绪,这使得现代诗派诗歌大多含蓄、朦胧,既避免了狂叫、直说,又纠正了初期象征派晦涩难懂的弊病,创造性地转化了波德莱尔、魏尔伦的象征主义诗艺,很好地实践着戴望舒所主张的“诗是由真实经过想象而出来的,不单是真实亦不单是想象”。
XXX2014-2015学年下学期高二年级期末考试语文试卷后有答案
XXX2014-2015学年下学期高二年级期末考试语文试卷后有答案XXX2014-2015学年下学期高二年级期末考试语文试卷后有答案本试卷满分为150分，考试时间150分钟。
第I卷50分一、基础与阅读（17分）材料一古人云“冒之以衣服，旌之以章旗，所以重其威也”，通过服饰表明贵贱在夏商时期当已形成。
我们通过《孝经》对服饰的论述片段，便能了解到古代“不僭上逼下”的着装要求。
穿错颜色，不但会受到惩罚，甚至还会招来杀身之祸。
清朝XXX 赐死年羹尧时，列举的罪状有几条就跟着装用色有关——用鹅黄色的荷包。
用黄布包裹衣服。
中国历代的服饰色彩与五行思想有着密切的关系。
从历代的服饰色彩演变中不难发现，古代服饰色彩始终以正色为尊，注重衣色之纯，五种正色白、青、黑、赤、黄源于五行金、木、水、火、土。
而历代所崇尚的颜色各异，《檀弓》有云“夏后氏尚黑，XXX尚白，XXX”，《史记·殷本纪》也记述XXX“易服色。
尚白”。
《礼记·王藻》云：“衣杂色，裳间色，非列采不入公门。
”个中的“列采”就是杂色服饰，也就是说，没有穿着杂色衣服是不能进入公门的。
作为封建社会初步的秦朝尚水德，于是黑色便成为打扮的首要颜色，“郊祀之服皆以袀玄”。
皇帝也经常是“玄衣绛裳”，即黑色上衣和深红色下衣，同样是以黑色为主调。
普通百姓单调的服色与礼制限制有关，“散民不敢服杂彩”（《春秋繁露·服制》）的描述正反映了这一现实。
《汉书·五行志》也曾记录，XXX微服私行，为了不引起人们的注意.遂穿着“白衣”。
封建社会中期当前，关于打扮颜色和等级的划定越发明确具体。
XXX虽然划定“贵贱异等，杂用五色”，但没有特别划定皇帝常服的服色。
而到了唐初，以黄袍衫等为皇帝常服，厥后逐渐用赤黄，“遂禁XXX不得以XXX为衣服杂饰”。
今后当前，黄色就成为了皇帝御用的颜色，成为皇帝王权的象征。
据《清史稿》记录：“龙袍，色用明黄。
领、袖俱石青，片金缘。
浙江省金华市金东区2024年十校联考最后英语试题含答案
浙江省金华市金东区2024年十校联考最后英语试题含答案注意事项：1．答卷前，考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。
用2B铅笔将试卷类型（B）填涂在答题卡相应位置上。
将条形码粘贴在答题卡右上角"条形码粘贴处"。
2．作答选择题时，选出每小题答案后，用2B铅笔把答题卡上对应题目选项的答案信息点涂黑；如需改动，用橡皮擦干净后，再选涂其他答案。
答案不能答在试题卷上。
3．非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新答案；不准使用铅笔和涂改液。
不按以上要求作答无效。
4．考生必须保证答题卡的整洁。
考试结束后，请将本试卷和答题卡一并交回。
Ⅰ. 单项选择1、The boy explains the important problem ______，so that everyone can understand him.A．carefully B．clear C．quickly D．carelessly2、―What a terrible experience I had just now. ―_____, you are safe now. That’s the main thing.A．Anyway B．Exactly C．Otherwise D．Moreover3、—Dad, it’s a long way from our home to the park!—You mean it’s ________ to take a taxi?A．popular B．possible C．important D．necessary4、—Tommy, there are so many mistakes in your chemistry paper, what will you do with it?—Oh, I am sorry, Miss Lee. , I'll do more exercises and learn from the mistakes to make progress.A．In case that B．In case C．In that case5、Teenagers would rather______phone calls while businessmen prefer_____e-mails to communicatewith each other.A．make; to write B．making; writing C．to make; to write D．make; writing6、— ____ do you go to the library?— Once a week.A．How often B．How farC．How much D．How long7、Most boys _______ blue to pink while most girls _______ wear pink than blue.A．would rather, prefer B．prefer, would ratherC．would rather, would rather D．prefer, prefer8、---Will Jim come to Yangzhou for a holiday?---He________ come and it depends on how much homework he will have.A．may B．should C．must D．need9、--How was your last weekend? -- ______.A．It’s good B．It’s great C．It was interesting D．I am happy10、our parents, we should let them be healthy and happy when we grow up .A．Return B．To return C．Returning D．ReturnedⅡ. 完形填空11、On June 2, 886, a German threw a message in a bottle into the water while his ship crossed the Indian Ocean. Around 32 years later in January, the bottle was 1 on the Australian coast, making it the oldest-known message in a bottle in the world.The bottle was thrown into the water to study ocean currents（洋流）. But throwing messages in bottles into the ocean is not just for 2 . People send out such messages for many reasons. Some people write information about themselves in 3 of finding a pen friend. 4 write down secrets, hoping that waves will 5 those secrets. And still other people just write down some jokes, songs or anything else they think might be 6 .The reasons and ways might be different, but the 7 is always the same: to reach out and try to connect 8 someone. This kind of shared feeling might be 9 this tradition has remained popular for so long. In 989, the British band The Police wrote a song called Message in A Bottle that described this 10 : A hundred billion bottles washed up on the beach. “Seems I’m not alone at being alone,” the singer said.1．A．sold B．showed C．found D．made2．A．scientists B．tourists C．friends D．families3．A．fears B．hopes C．worries D．cares4．A．Another B．Other C．All D．Others5．A．put off B．wash away C．pick up D．call at6．A．fun B．dangerous C．terrible D．boring7．A．price B．speed C．plan D．goal8．A．with B．by C．into D．on9．A．what B．why C．how D．when10．A．result B．feeling C．situation D．accidentⅢ. 语法填空12、Tyler was a troublesome student. He sat in the back row. Every time I called him to answer questions, he’d r1．with a flip(轻率的) answer. If he got it wrong, he would get very angry.Usually kids could sit q2．in class. However, Tyler was just loud. One day, Tyler was talking while I was teaching. I said to him, “Tyler, why not join in our discussion i3．of having one of your own?” He got up from his chair, pushed it over, and s4．somet hing I can’t remember. I sent him to the office and he received a week’s out-of-school punishment.The week was a wonderful time for me, but when it came to an e5．, I began to feel worried. So I came up with a plan. On the day of his r6．, I told him I wanted to start over with him. If he felt like he was going to lose control(控制) in class, he could step o7．the door for a moment.From then on, Tyler was a changed s8．in my classroom. In fact he was a smart child and he even stopped a fight between two students one day. And he never used the privilege(特权) to leave the class for a moment. I believe that just letting him decide for h9．made all the difference.When the year was over, he wrote me a thank-you note about h10．good the year had been for him. I still have it today and find it very moving to reread when I get stressed(有压力的) about teaching.Ⅳ. 阅读理解A13、 A passenger told an air hostess that he needed a cup of water to take his medicine when the plane just took off. She told him that she would bring him the water in ten minutes.The air hostess was so busy that she forgot to give him the water. As a result, the passenger couldn’t take his medicine in time. Thirty minutes later, when the passenger’s ring for service sounded, she hurried over to him wit h a smile whether he needed help or not. But the passenger never answered a word.When he was going to get off the plane, the passenger asked the air hostess to hand him the passenger’s booklet（意见簿）. She was very sad. She knew that he would write down sharp words, which might result in the loss of her job. But with a smile she handed it to him.Off the plane, she opened the booklet, and smiled, for the passenger put it, “On the flight, you asked me whether I needed help or not for twelve times in all. How can I refuse your twelve sincere smiles?”That’s right! Who can refuse twelve smiles from a person?1．What did the passenger need when the plane just took off?A．A booklet to write something . B．A cup of water to take his medicine.C．The air hostess to make an apologize. D．To get off the plane at once.2．Why did the air hostess forget to give the passenger the water?A．Because the passenger was angry.B．Because it’s not allowed to take medicine during the flight.C．Because she was very busy.D．Because there wasn’t enough water on the plane.3．Why was the air hostess very sad ?A．She thought the passenger would write down bad words.B．She thought she couldn’t give the passenger any help.C．She thought the passenger would tell her manager.D．She thought she should say sorry to the passenger again.4．The Chinese meaning of the word “sincere” is “”.A．自豪的B．婉转的C．真诚的D．委屈的5．Which is the best title for the passage?A．The Air Hostess B．A Cup of Water C．On the plane D．Twelve SmilesB14、1．We can learn that students probably do better in exams______.A．in very hot weatherB．on low-pressure daysC．when a strong wind comes2．Who may have a hard time in winter?A．Thin girls. B．Fat men. C．Little children.3．At what temperature do people feel best ?A．About 12℃B．About 18℃. C．About 24℃.C15、My sister Alli and I have been trying to get people to stop dropping cigarette butts(烟蒂) for seven years. One day, we were walking in our hometown and saw hundreds of cigarette butts on the ground. They made the town look so ugly that we decided to start a group to mak e people stop dropping butts. We called it “No Butts About It”. At first, we drew pictures with “The Earth is Not Your Ashtray(烟灰缸)” written on them. We put the pictures around our hometown---in parks, by beaches, and along roads. We wanted to make people understand that dropping butts hurts the environment. Most smokers don’t think that dropping butts hurts the earth. But it does! All rubbish does. Later, we wrote to companies and asked them for money to help us. We used the money to buy ashtrays to give smokers. We wanted smokers to carry the ashtrays with them so they didn’t have to drop butts. At the moment, we are trying to get cigarette companies to put an ashtray in each pack of cigarettes. Some companies want to do it.Many people have started to joi n our group since it began. Today there are 45 other “No Butts About It” groups in America. And there are even groups in England, Australia and India! Many newspapers have written about my sisterand I over the last seven years. And we have won many prizes for our good work.But we are not interested in prizes. We just want to make the earth a better and cleaner place for animals, plants and people. One day it will be.1．（小题1）“No Butts About It” started___________A．seventeen years ago. B．seven years ago.C．seventy years ago D．It’s not mentioned.2．（小题2）Why did they start the group?A．Because they don’t like cigarette.B．Because they want to make money.C．Because they want people to know them.D．Because they want to protect the environment.3．（小题3）How many “No Butts About It” groups are there in America?A．7 B．45 C．46 D．49.4．（小题4）The writer lives in_________A．America. B．England. C．Australia. D．India.5．（小题5）What did the writer do the following EXCEPT__________?A．starting a group cal led “No Butts About It”B．writing to companies to ask them for helpC．asking newspapers to write about her sister and herD．managing to get some cigarette companies to put an ashtray in each cigarette packD16、Y esterday my son，daughter and I went to the grocery store. In front of us in line was a little girl with her mother. The little girl was asking her mother for a box of Smarties. The polite way she was asking almost broke the mother’s heart，“I’m sorry，Honey，but we have no money to buy it.”My son was watching that dialogue. By the way，he had been raking(用耙子耙)leaves our garden to raise himself some money to buy a bike. As he watched the mother and daughter leave the store，he ran to the candy counter(柜台)and bought a box of Smarties with the money .He turned to look at me and I just nodded. He ran out after the little girl and her mother and he gave them the box. He came back and told me what he told them. “Every kid should have a pack of Smarties because they can make you smart.”I was so excited that I bought a pack of Smarties for my son. I told him that I was proud of him，and that was for hisact of generosity because he gave his own Smarties to others. Quickly，he replied，“But you do nice things for people and you never get anything for it.”I explained，“When you do something nice for someone，you shouldn’t expect to get anything. When you get something you should be very thankful.”1．When the writer and her children went to the grocery store，they saw a little girl asking ____.A．her mother for a nice toyB．her mother for a box of SmartiesC．where she could find a box of SmartiesD．her mother if she could had enough money2．From the passage we know Smarties are ____.A．a nice electric toyB．an interesting story bookC．a kind of candyD．some leaves of a nice tree3．The writer was ____ to see her son buy a pack of Smarties for the little girl.A．sad B．excited C．angry D．proud4．The writer still bought the pack of Smarties to ______ .A．praise her son’s good deed.B．give it to the little girl some dayC．have them with her husband.D．give it to other children.5．What can we learn from the story above?A．Every kid should have a pack of Smarties.B．Everyone should have a good mother.C．Everyone should do nice things for others.D．Every mother should often do something for her children.E17、Mrs. Smith has a bottle of medicine named 666 POWDER FOR COLD at home. Here is the instruction of it.1．What kind of patients mustn’t take 666 POWDER FOR COLD ?A．The patients who have got a fever.B．The patients who have got a cough.C．The patients who have got a sore throat.D．The patients who have got a heart disease.2．How many days can a bottle of 666 POWDER FOR COLD last for an adult patient at least?A．One day B．Two days.C．Three days D．Six days.3．Mrs. Smith’s baby, John, six months old, has got a cold. What do you think she should do ?A．She should feed him 1/2 spoon of 666 POWDER FOR COLD three times a dayB．She should feed him 1 spoon of 666 POWDER FOR COLD three times a day.C．She should tak e him to see a doctor and get to know what’s wrong with her son.D．She should feed him 1/2 spoon of 666 POWDER FOR COLD only once4．Which of the following is NOT true?A．Patients can take the 666 POWDER FOR COLD in February , 2015.B．If patients take more than one spoon at a time, they need to see a doctor.C．If patients don’t feel well after taking, they need to see a doctor.D．Patients can’t use 666 POWDER FOR COLD for more than seven days.F18、阅读下列短文，从每题A、B、C、D四个选项中，选出一个能回答所提问题或完成所给句子的最佳答案。
浙江省金华十校2014届高三上学期期末调研考试数学(理)试题
金华十校2013-2014学年第一学期期末调研考试高三数学（理科）试题卷本试卷分第Ⅰ卷和第Ⅱ卷两部分．考试时间120分钟． 试卷总分为150分．请考生按规定用笔将所有试题的答案涂、写在答题纸上．参考公式：球的表面积公式 棱柱的体积公式 S =4πR 2 V =Sh球的体积公式其中S 表示棱柱的底面积，h 表示棱柱的高． V =43πR 3棱台的体积公式其中R 表示球的半径 V =13h (S 1S 2)棱锥的体积公式其中S 1、S 2表示棱台的上、下底面积，h 表示棱 V =13Sh 台的高．其中S 表示棱锥的底面积，h 表示棱锥的高． 如果事件A 、B 互斥，那么P (A +B )= P (A )+ P (B )第Ⅰ卷一、选择题：本大题共10小题，每小题5分，共50分．在每小题给出的四个选项中，只有一项是符合题目要求的．1． 已知集合M ={x |2x >1}，N ={x | x ≥1}，则)M N =R （ðA ．[1,+∞)B ．(0,1)C ．(-∞,0)D ． (0,+∞)2． 复数2i1i--（i 为虚数单位）在复平面上对应的点所在的象限为 A ．第一象限 B ．第二象限 C ．第三象限 D ．第四象限3． 已知a ，b 是实数，则“|a -b |≥|a |+|b |”是“ab <0”的 A ．充分不必要条件 B ．必要不充分条件C ．充分必要条件D ．既不充分也不必要条件 4． 若某程序框图如右图所示，则该程序运行后输出的值是A ．4B ．5C ．6D ．75． 在空间中，若m ,n 是两条不同的直线，α,β是两个不同的平面，则下列命题中正确的是A ．α∥β, m ⊂α, n ⊂β⇒ m ∥nB ．α⊥β, n ∥α, m ⊥β⇒n ⊥mC ． m ∥n , m ⊥α⇒n ⊥αD ．m ∥n , m ∥α⇒ n ∥α6. 若数列{a n }的前n 项和S n 满足S n = 4-a n (n ∈N *)，则a 5=（第4题）A ．1B ．12 C ．14 D ． 187． 有4名优秀学生A 、B 、C 、D 全部被保送到甲、乙、丙3所学校，每所学校至少去一名，且A 生不去甲学校，则不同的保送方案有 A ．24种B ．30种C ．36种D ．48种8． 若实数x ,y满足不等式组40,,20,x y x x y k -⎧⎪⎨⎪++⎩≥≤≤且z =x +3y 的最大值为12，则实数k =A ．-12B ． 323-C ．-9D ． 143-9． 已知A ，B ，C 是单位圆O 上任意的不同三点，若2OA OB xOC =+，则正实数x 的取值范围为A ．(0,2]B ．[1,3]C ．[2,4]D ．[3,5]10．对于项数都为m 的数列{a n }和{b n }，记b k 为a 1,a 2,…,a k (k =1,2,…,m )中的最小值，给出下列命题：①若数列{b n }的前5项依次为5，5，3，3，1，则a 4=3； ②若数列{b n }是递减数列，则数列{a n }也是递减数列； ③数列{b n }可能是先递减后递增的数列； ④若数列{a n }是递增数列，则数列{b n }是常数列． 其中，是真命题的为A ．①④B ． ①③C ．②③D ． ②④第Ⅱ卷二、填空题：本大题有7小题，每小题4分，共2811．等差数列{a n }中，a 2=3，S 512．62)x 的展开式中，常数项为 ▲ ．13．已知函数y =A sin(ωx +ϕ)（A >0,ω>0所示，则此函数的最小正周期为 ▲ ．14．某几何体的三视图（单位：cm ）如图所示，则该几何 体最长的一条侧棱长度是 ▲ cm ．15．已知向量a ，b ，c 满足a +b +c =0，| c |=，且c 与a -b 所 成的角为120°，则当t ∈R 时，|t a +(1-t )b |的取值范围是 ▲ ．16．已知点F ( c >0)是双曲线22221x y a b-=的左焦点，过F 且平行于双曲线渐近线与抛物线y =2362x +相切，则该双曲线的离心率为 ▲ ．17．若函数21()lg 1x ax f x x x ++=⋅-的值域为(0,)+∞，则实数a 的最小值为 ▲ ．三、解答题：本大题共5小题，共72分，解答应写出文字说明、证明过程或演算步骤． 18．（本题满分14分） 在△ABC 中，角A ,B ,C 所对的边分别是a ,b ,c ，已知c =1，6C π=． (Ⅰ)若ab 的值；(Ⅱ)求cos A cos B 的取值范围．19．（本题满分14分）袋中装有黑球和白球共7个，从中任取2个球都是白球的概率为17。
浙 江金华市重点十校2012--2013学年第一学期期末考试高三语文
2013届高三上学期期末考试语文试题命题学校：鞍山一中命题人、校对人：齐次倪玉虹第Ⅰ卷阅读题甲必考题一、现代文阅读（9分，每小题3分）阅读下面的文字，完成1～3题。
中国传统文化中的“蛟”陈桂权中国传统文化中的“蛟”到底是何种动物?翻检史籍我们发现，古人所说的蛟应是在综合鳄鱼、大鱼、蟒蛇、牛等动物特点的基础上组合而成的一种具有神化色彩的动物。
许慎《说文解字》卷十三云:“蛟，龙之属也。
池鱼满三千六百，蛟来为之长，能率鱼飞，臵笱水中即蛟。
”三国时训诂学家张揖在《广雅》卷十中说蛟云:“蛟状鱼身而蛇尾，皮有珠鼍，似蜥蜴而大身，有甲皮，可作鼓。
”晋郭璞《山海经传》对“虎蛟”的解释是“蛟似蛇，四足龙属，其状鱼身而蛇尾，其音如鸳鸯，食者不肿，可以已痔”（《山海经•南山经》）。
郭璞不仅从形态学的角度对蛟做了一番描绘，还谈到其药用价值。
而唐代经学大师颜师古在《汉书注》卷五七中引郭璞对蛟所做的另一更为详细的解释是:“其状云似蛇，而四脚细颈，颈有白婴，大者数围，卵生子如一二斛瓮，能吞人也。
”行文至此，我们对于蛟的原始意象似乎已有一模糊的轮廓。
从诸位学者对蛟的特点的描述中，我们可以归纳出蛟的两个显著特征:其一，蛟的体形兼具鱼、蛇之形，正所谓“鱼身而蛇尾”，且拥有四足;其二，蛟为性情暴烈的食肉动物，攻击性强。
这两大特点，不禁使人联想到另一水中猛兽——鳄鱼。
而宋代文人彭乘在《墨客挥犀》卷三中对蛟的形态、生活习性及危害性的生动描述，则为这一猜想提供了又一佐证:“蛟之状如蛇，其首如虎，长者数丈。
多居溪潭石穴，声如牛鸣。
岸行或溪行者，时遭其害。
见人先腥涎绕之，即于腰下吮其血，血尽乃止。
”因此，有学者认为“两项对照，蛟龙特征与鳄鱼一一对应，可见古人视鳄为蛟龙，蛟龙是以鳄鱼为原型的神灵”（向柏松《中国水神崇拜》138页）。
应该说“鳄鱼为蛟之原型”这一观点符合古人早期对蛟的描述，但蛟作为一虚构组合之物，其特征绝非任何一种动物所能兼具。
对于“蛟为鳄鱼”这一观点最早质疑的人是颜师古。
浙江省金华市十校2023-2024学年高二下学期6月期末调研考试数学试题(含答案)
金华十校2023-2024学年第二学期期末调研考试高二数学试题卷本试卷分选择题和非选择题两部分.考试时间120分钟.试卷总分为150分.请考生按规定用笔将所有试题的答案涂､写在答题纸上.选择题部分（共58分）一､单选题：本题共8小题，每小题5分，共40分在每小题给出的四个选项中，只有一项是符合题目要求的.1.已知复数，则在复平面内对应的点位于（ ）A.第一象限B.第二象限C.第三象限D.第四象限2.已知向量，且，则（ ）A.11B.-11C.D.3.已知是实数，则“”是“”的（ ）A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件4.已知函数的对称中心为，则能使函数单调递增的区间为（）A.B. C. D.5.函数的图象为（）A. B.C. D.122i,12i z z =+=-+12z z -()()1,2,3,a b x x ==-()2a a b ⊥+ x =112112-x 152x x +…2x …()()πcos 202f x x ϕϕ⎛⎫=+<< ⎪⎝⎭π,06⎛⎫ ⎪⎝⎭()f x π0,4⎡⎤⎢⎥⎣⎦ππ,42⎡⎤⎢⎥⎣⎦π3π,24⎡⎤⎢⎥⎣⎦3π,π4⎡⎤⎢⎥⎣⎦()ln cos x xf x x=6.已知随机变量，且，则（ ）A.0.4B.0.2C.0.8D.0.17.高二某班男生20人，女生30人，男､女生身高平均数分别为，方差分别为170､160，记该班全体同学身高的平均数为，方差为，则（ ）A. B.C.D.8.已知当时，，若函数的定义域为，且有为奇函数，为偶函数，则所在的区间是（ ）A.B. C. D.二､多选题：本题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项符合题目要求.全部选对的得6分，有选错的得0分，部分选对的得部分分.9.在正方体中，（ ）A.B.直线与所成角为C.平面D.直线与平面所成角为10.投掷一枚质地均匀的硬币两次，记“第一次正面向上”为事件，“第二次正面向上”为事件，“至少有一次正面向上”为事件，则下列判断正确的是（ ）A.与相互独立B.与互斥C..D.11.在中，已知，则（ ）A.B.C.的外接圆直径为10D.的面积为非选择题部分（共92分）三､填空题：本题共3小题，每小题5分，共15分.()1,4X N ~()()0.20.1P X a P X ==……19a P X ⎛⎫<<= ⎪⎝⎭170cm 160cm ､X 2s 2165,165X s >>2165,165X s <>2165,165X s ><2165,165X s <<[)0,1x ∈()33xf x =-()f x R ()1f x +()2f x +()3log 300f (),0∞-10,2⎛⎫ ⎪⎝⎭1,12⎛⎫ ⎪⎝⎭()1,∞+1111ABCD A B C D -1AC BD ⊥1BD CD π411A C ∥1AB C1BC 11BB D D π6A B C A B A B ()23P BC =∣()()()()P C P A P B P AB =+-ABC ()4cos 3sin 4sin 9,6B B C A AC ++-==A B >2AB BC=ABC ABC I212.已知集合，集合，则__________.13.若，则__________.14.在三棱锥中，，且，若三棱锥的外接球表面积的取值范围为，则三棱锥体积的取值范围为__________.四､解答题：本题共5小题，共77分.解答应写出文字说明､证明过程或演算步骤.15.（本题满分13分）某校开展一项名为“书香致远，阅读润心”的读书活动，为了更好地服务全校学生，需要对全校学生的周平均阅读时间进行调查，现从该校学生中随机抽取200名学生，将他们的周平均阅读时间（单位：小时）数据分成5组：，根据分组数据制成了如图所示的频率分布直方图.（1）求的值，并估计全校学生周平均阅读时间的平均数；（2）用分层抽样的方法从周平均阅读时间不小于6小时的学生中抽出6人，从这6人中随机选出2人作为该活动的形象大使，求这2人都来自这组的概率.16.（本题满分15分）如图，在四棱锥中，四边形为正方形，为等边三角形，分别为的中点，，垂足为.（1）证明：平面；（2）若，求平面与平面形成的锐二面角的余弦值.17.（本题满分15分）已知分别为三个内角的对边，且.（1）证明：；{}1,2,3,4,5,6A ={14}B x x =∈-<<R∣A B ⋂=5250125(21)x a a x a x a x +=+++⋯+2a =A BCD -,AC AB BD AB ⊥⊥10,3AC BD AB ===A BCD -661π,409π4⎡⎤⎢⎥⎣⎦A BCD -[)[)[)[)[]2,4,4,6,6,8,8,10,10,12a [)6,8P ABCD -ABCD PAD 2,AB E F =､AD BC ､EG PF ⊥G EG ⊥PBC 3cos 4PAB ∠=-PAB PCD ,,a b c ABC ,,A B C ()()sin 22cos sin A B a cA B Ab++-+=22b a ac -=（2）求的最小值.18.（本题满分17分）已知函数.（1）若，求函数在点处的切线方程；（2）求函数在区间上的最大值的表达式；（3）若函数有两个零点，求实数的取值范围.19.（本题满分17分）二项分布是离散型随机变量重要的概率模型.我们已经知道，若，则.多项分布是二项分布的推广，同样是重复次试验，不同的是每次试验的结果不止2种，而有种，记这种结果为事件，它们的概率分别为，则.现考虑某厂生产的产品分成一等品､二等品､三等品和不合格品，它们出现的概率分别为，从该厂产品中抽出个，研究各类产品出现的次数的情况，就是一个多项分布.由于产品很多，每次抽取可以看作是独立重复的.（1）若从该厂产品中抽出4个，且和分别为和0.05，求抽出一等品1个､二等品2个，三等品1个的概率；（2）现从该厂中抽出个产品，记事件出现的次数为随机变量.为了定出这一多项分布的分布列，只需求出事件的概率，其中为非负整数，.（i ）求；（ii ）对于上述多项分布，求在给定的条件下，随机变量的数学期望.cos aA b+()1eln x f x ax x x -=--2a =()f x ()()1,1M f ()f x []1,3()g a ()f x a (),X B n p ~()C (1)k k n kn P X k p p -==-n m m 12,,,m A A A 12,,,m p p p 120,1i m p p p p +++= …1A 2A 3A 4A 1234,,,p p p p n 123,,p p p 4p 0.15,0.70,0.10n i A ,1,2,3,4i X i ={}11223344,,,B X k X k X k X k =====()1,2,3,4i k i =1233k k k k n +++=()P B 22X k =1X金华十校2023-2024学年第二学期调研考试高二数学卷评分标准与参考答案一､单选题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的题号12345678答案D D B C C A B C二､多选题：本题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项符合题目要求.全部选对的得6分，有选错的得0分，部分选对的得部分分.题号91011答案ACD ACD BCD三､填空题：本题共3小题，每小题5分，共15分.12.13.4014.四､解答题：本题共5小题，共77分.解答应写出文字说明､证明过程或演算步骤.15.解：（1）依题意可得，解得又，即估计全校学生周平均阅读时间的平均数为6.92小时.（2）由频率分布直方图可知和三组的频率的比为所以利用分层抽样的方法抽取6人，这三组被抽取的人数分别为记中的3人为中的2人为中的2人为，从这6人中随机选出2人，则样本空间共15个样本点；设事件选出的2人都来自，则共3个样本点，所以.16.解：（1）如图，连接，在中，，在正方形中，，又因为平面，所以平面.又因为，所以平面，而平面，所以.因为平面，所以平面.{}1,2,3⎡⎤⎣⎦()0.020.050.10.1821a ++++⨯=0.15a =()30.0250.1870.1590.1110.052 6.92⨯+⨯+⨯+⨯+⨯⨯=[)[)6,88,10､[]10,120.15:0.1:0.053:2:1=3,2,1,[)6,8[)123,,,8,10a a a []12,,10,12b b 1c {}121311121123212221313231121121Ω,,,,,,,,,,,,,,a a a a a b a b a c a a a b a b a c a b a b a c b b b c b c =:A [)6,8{}121323,,A a a a a a a =()31155P A ==,PE EF PAD PE AD ⊥ABCD EF AD ⊥PE EF ⊂､,PEF PE EF E ⋂=AD ⊥PEF BC ∥AD BC ⊥PEF EG ⊂PEF EG BC ⊥BC PF ⊂､,PBC BC PF F ⋂=EG ⊥PBC（2）因为，所以，则，则如图以为原点，分别为轴，过且垂直为轴建系，则，则，设为平面的法向量，则，取，同理平面的法向量.所以，故平面与平面形成的锐二面角的余弦值.17.解：（1）因为所以，即；（2）因为，又，所以，因此，于是，3cos 4PAB ∠=-PB ==PF ==cos PEF ∠==E ,EA EF ,x y E ABCD z ()()1,0,0,1,2,0A B ()()31,0,0,1,2,0,0,2G C P ⎛--- ⎝()30,2,0,1,,2AB PA ⎛== ⎝ ()1111,,n x y z = PAB 11110,230,y x y =⎧⎪⎨+=⎪⎩)12n =PCD )22n =-12341cos ,77n n -==-PAB PCD 17()()sin 22cos sin A B A B A+-+()()()sin 2cos sin sin sin sin A B A A B AB AA++-+==sin sin B b a cA a b+==22b a ac -=222cos 2b c a A bc+-=22b a ac -=cos 2c a A b +=2cos b A a c =+()2sin cos sin sin sin sin B A C A A B A =+=++即，故，因为，所以，即，所以，当且仅当时，“=”成立.故.18.解：（1）易知函数的定义域为.当时，.，所以在点处的切线斜率，又，即点坐标为，所以点处的切线方程为.（2）因为.所以，当时，易知在上恒成立，所以在上单调递减，故函数在区间上的最大值为.当时，令，则在上单调递增，且当时，，当时，，所以在上有唯一的一个零点.令，则该方程有且只有一个正根，记为，则可得()sin sin B A A -=2B A =ππ3C A B A =--=-π03A <<1cos 12A <<sin 1cos cos cos sin 2cos a A A A A b B A+=+=+…cos A =cos aA b+()f x ()0,∞+2a =()12eln ,0x f x x x x x -=-->()()111112e 2e 112e x x x f x x x x x ---⎛⎫=+--=+- ⎪⎝⎭'M ()()011112e 21k f ⎛⎫==+-⎝'= ⎪⎭()012e 101f =--=M ()1,1M ()21121y x x =-+=-()1e ln ,0xf x ax x x x -=-->()()11111ee 11e x x xf x a ax x a x x ---⎛⎫=+--=+- ⎪⎝⎭'0a …()0f x '<()0,∞+()f x ()0,∞+()f x []1,3()01e 101f a a =--=-0a >()11e,0x g x a x x-=->()g x ()0,∞+0x →()g x ∞→-x ∞→+()g x ∞→+()0g x =()0,∞+11e0x a x--=()000x x >-+单调递减单调递增所以函数在区间上的最大值为，由，有：当时，；当时，.故（3）由（2）可知，当时，在上单调递减，故此时函数至多有一个零点，不符合题意.当时，在时，单调递减，在时，单调递增；且，所以，①又时，，当时，为了满足有两个零点，则有.②对①两边取对数可得，③将①③代入②可得，解得.所以实数的取值范围为19.解：（1）记从该厂产品中抽出4个，且恰好抽出一等品1个､二等品2个，三等品1个为事件，则，（2）（i ），x()00,x ()0,x ∞+()f x '()f x ()f x []1,3()(){}max 1,3f f ()()211,33e 3ln3f a f a =-=--22ln303e 1a +<<-()()11g a f a ==-22ln33e 1a +-…()()233e 3ln3g a f a ==--()2222ln31,3e 12ln33e 3ln3,.3e 1a a g a a a +⎧-<⎪⎪-=⎨+⎪--⎪-⎩…0a …()f x ()0,∞+()f x 0a >()00,x ()f x ()0,x ∞+()f x 0101e0x a x --=0101e x a x -=0x →()f x ∞→+x ∞→+()f x ∞→+()f x ()010000e ln 0x f x ax x x -=--<00ln 1ln a x x =--()010000eln ln 0x f x ax x x a -=--=<1a <a 01a <<M ()12212413213C C C 40.1530.710.10.0882P M p p p ==⨯⨯⨯⨯⨯=(){}()11223344,,,P B PXk X k X k X k =====331122441121231234C C C C k k k k k k k k n n k n k k n k k k p p p p ------=⋅⋅⋅（ii ）若把事件作为一方，则作为另一方，那么随机变量分布列为，即服从二项分布列为，同理可知：.所以.所以在给定的条件下，随机变量服从二项分布，即所以此时，随机变量的数学期望为()()()()()()312411212312341112212334!!!!!!!!!!0!!k k k k n k n k k n k k k n p p p p n k k n k k k n k k k k k ------=⋅⋅⋅⋅-⋅-----⋅331241241234123412341234!111!!!!!!!!!k k k k k k k k n n p p p p p p p p k k k k k k k k =⋅⋅⋅⋅=⋅⋅⋅⋅⋅1A 1234A A A A =++1X ()112341,P X k X X X n k =++=-1X ()()()1111111!1!!n kk n P X k p p k n k -==⋅-⋅-()()()22222222!1!!n k k n P X k p p k n k -==⋅-⋅-()()()1212112212121212!,1!!!n k k k k n P X k X k p p p p k k n k k --===⋅⋅--⋅⋅--()()()1122112222,P X k X k P X k X k P X k ======∣()()()()122122121222121222!!1/1!!!!!n k k n k k k k n n p p p p p p k k n k k k n k ---=⋅⋅--⋅-⋅--⋅-()()11221111222!1!!11k n k k n k p p k n k k p p ---⎛⎫⎛⎫=- ⎪ ⎪⋅----⎝⎭⎝⎭22X k =1X 1122,1p X B n k p ⎛⎫~- ⎪-⎝⎭1X ()1221p n k p -⋅-。