【答案版】2019-2020学年广东省北京师范大学东莞石竹附属学校高一10月月考化学试题
2020高考一轮复习广东省2019届高三10月英语试卷精选汇编：书面表达
书面表达北京师范大学东莞石竹附属学校第二节书面表达(满分25分)美国某中学拟邀请中国学生开展“手拉手”交流活动（The Hand-in-Hand Program）, 正在其网站上招募参加者。
假设你是新华中学的学生李华，对该活动很感兴趣。
请你用英语给对方写一封申请信，内容应包含下列要点：1 表示有意参加；2 简述自身条件（如性格，兴趣，特长等）；3 说明你能为美国伙伴做些什么。
注意：1．词数100左右;2．可适当增加细节，以使行文连贯;Dear Sir or Madam,____________________________________________________________________________________________________________________________________________________ _________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ __________________________________________________________________________________________________________________________________________ ___________________________________________________________Yours,Li HuaDear Sir or Madam,I am Li Hua, a student from China. I have read your Hand-in-Hand Program on your website. I think the idea is very appealing to me, and now I am writing to apply to join in it.I am a boy with an outgoing personality. Thus, I am good at dealing with strangers and making new friends. I have a wide range of hobbies, such as reading and doing sports. Besides, I devote large amount of spare time to photography.If I am accepted, I will act as a bridge between American and Chinese students. I would like to invite my American friends to our school and I will spare no effort to be a perfect guide for them.Thanks for your consideration. I am looking forward to your favorable reply.肇庆市香山中学第二节书面表达（满分25分）假如你叫李华，是一名高中生。
广东省北京师范大学东莞石竹附属学校高三10月月考英语试题 Word缺答案
2018--2019学年度上学期高三10月月考英语试题*本试题卷共5页。
全卷满分120分，折合分135分，考试用时120分钟。
第二部分阅读理解 (共两节, 满分40分)第一节 (共15小题; 每小题2分, 满分30分)阅读下面短文, 从每题所给的A、B、C、和D四个选项中, 选出最佳选项, 并在答题卡上将该项涂黑。
AAND ENJOY A FREE * FLIGHT TO ANY DESTINATION IN ASI A!With a registration fee of just $50 per child, children under the age of 12 can join Eagle Airways' FLY* Child must be accompanied by two paying adults.** Terms and conditions apply.21. One of the benefits mentioned in the advertisement is ____.A. a free flight to any destination in the worldB.30% off any book purchased at Ruby BookstoreC. a free bowl of dessert at any restaurant at the airportD. a discount on any course at Tanya Language School22. Which of the following bookings may receive the most benefits?23. Which of the following is TRUE according to the advertisement?A. You need to pay $50 to sign up a child for the club.B. Club members enjoy free travel insurance for any flight.C. The advertisement is intended for students of all ages.D. Any child must be accompanied by at least one paying adult.BI've loved my mother's desk since I was just tall enough to sit above the top of it. Mother sat writing letters. Standing by her chair, looking at the ink bottle, pens, and white paper, I decided that the act of writing must be a most wonderful thing in the world.Years later, during her final illness, Mother kept different things for mysisterand brother. "But the desk," she said again, "is for Elizabeth."I never saw her angry, never saw her cry. I knew she loved me; she showed in action. But as a young girl, I wanted to have heart-to-heart talks between mother and daughter.They never happened. And a gulf opened between us. I was "too emotional". But she lived "on the surface".As years passed and I had my own family. I loved my mother and thanked her for our happy family. I wrote to her in careful words and asked her to let me know in any way she chose that she did forgive me.My hope turned to disappointment, then little interest and, finally, peace - it seemed that nothing happened. I couldn't be sure that the letter had even got to Mother.I only knew that I had written it, and I could stop trying to make her into someone she was not.But the present of her desk told me, as she'd never been able to, that she was pleased that writing was my chosen work. I cleaned the desk carefully and found some papers inside - a photo of my father and a one-paper letter, folded and refolded many times. It was my letter."In any way you choose, Mother, you always chose the act that speaks louder than words."24. When did the writer begin to love her mother's desk?A. After Mother died.B. Before she became a writer.C. When she was a child.D. When Mother gave it to her.25. What does the passage want to show?A. Mother was actually kind in her heart to her daughter.B. Mother was too serious about her daughter in words.C. Mother wrote to her daughter in careless words.D. Mother wrote to her daughter in careful words.26. What does the underlined word "gulf" in the passage mean?A. Deep understanding between the old and the young.B. Different ideas between mother and daughter.C. Free talks between mother and daughter.D. Part of the sea going far in land.27. What did Mother do with her daughter's letter asking for forgiveness?A. She had never received the letter.B. For years, she often talked about the letter.C. She read the letter again and again till she died.D. She didn't forgive her daughter at all in all her life.CThe production of coffee beans is a huge, profitable business, but, unfortunately, full-sun production is taking over the industry and bringing about a lot of damage. The change in how coffee is grown from shade-grown production to full-sun production endangers the very existence of certain animals and birds, and even disturbs the worl d’s ecological balance.On a local level, the damage of the forest required by full-sun fields affects the area’s birds and animals. The shade of the forest trees provides a home for birds and other species that depend on the trees’ flowers and fruits. Ful l-sun coffee growers destroy this forest home. As a result, many species are quickly dying out.On a more global level, the destruction of the rainforest for full-sun coffee fields also threatens (威胁) human life. Medical research often makes use of the forests' plant and animal life, and the destruction of such species could prevent researchers from finding cures for certain diseases. In addition, new coffee-growing techniques are poisoning the water locally, and eventually the world's groundwater.Both locally and globally, the continued spread of full-sun coffee plantations (种植园) could mean the destruction of the rainforest ecology. The loss of shade trees is already causing a slight change in the world's climate, and studies show that loss of oxygen-giving trees also leads to air pollution and global warming. Moreover, the new growing techniques are contributing to acidic (酸性的) soil conditions.It is obvious that the way much coffee is grown affects many aspects of life, from the local environment to the global ecology. But consumers do have a choice.They can purchase shade-grown coffee whenever possible, although at a higher cost. The future health of the planet and mankind is surely worth more than an inexpensive cup of coffee.28. What can we learn about full-sun coffee production from Paragraph 4?A. It limits the spread of new growing techniques.B. It leads to air pollution and global warming.C. It slows down the loss of shade trees.D. It improves local soil conditions.29. The purpose of the text is to________.A. entertainB. advertiseC. instructD. persuade30. Where does this text probably come from?A. An agricultural magazine.B. A medical journal.C. An engineering textbook.D. A tourist guide.31. Which of the following shows the structure of the whole text?(P：Paragraph)DEvery year more people recognize that it is wrong to kill wildlife for "sport." Progress in this direction is slow because shooting is not a sport for watching, and only those few who take part realize the cruelty and destruction.The number of gunners, however, grows rapidly. Children too young to develop proper judgments through independent thought are led a long way away by their gunning parents. They are subjected to advertisements of gun producers who describe shooting as good for their health and gun carrying as a way of putting redder blood in the veins (血管). They are persuaded by gunner magazines with stories honoring the chase and the kill. In school they view motion pictures which are supposedly meant to teach them how to deal with arms safely but which are actually designed to stimulate a desire to own a gun. Wildlife is disappearing because of shooting and because of the loss of wild land habitat. Habitat loss will continue with our increasing population, but can we slow the loss of wildlife caused by shooting? There doesn't seem to be any chance if the serious condition of our birds is not improved.Wildlife belongs to everyone and not to the gunners alone. Although most people do not shoot, they seem to forgive shooting for sport because they know little or nothing about it. The only answer, then, is to bring the truth about sport shooting to the great majority of people.Now, it is time to realize that animals have the same right to life as we do and that there is nothing fair or right about a person with a gun shooting the harmless and beautiful creatures. The gunners like to describe what they do as character-building, but we know that to wound an animal and watch it go through the agony of dying can make nobody happy. If, as they would have you believe, gun-carrying and killing improve human-character, then perhaps we should encourage war.32. According to the text, the films children watch at school actually_______.A. teach them how to deal with guns safelyB. praise hunting as character-huntingC. describe hunting as exerciseD. encourage them to have guns of their own33. Most people do not seem to be against hunting because_____.A. it helps to build human characterB. they have little knowledge of itC. it is too costly to stop killing wildlifeD. they want to keep wildlife under control34. The underlined word “agony” in the last paragraph probably means_____.A. formB. conditionC. painD. sadness35. It can be inferred from the text that the author seems to ______.A. worry about the existence of wildlifeB. blame the majority of peopleC. be in favor of warD. be in support of hunting第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
广东省北京师范大学东莞石竹附属学校2019-2020学年高一英语10月月考试题[含答案].doc
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广东省北京师范大学东莞石竹附属学校2019-2020学年高一英语10月月考试题注意事项：l. 本试卷分第Ⅰ卷和第Ⅱ卷。
第Ⅰ卷15分，第Ⅱ卷135分，全卷满分150分。
考试时间120分钟。
2．考生务必将所有的答案涂/写在答题卷上各题目指定区域内的相应位置；否则不得分。
3. 考生务必用黑色字迹的钢笔或签字笔做答。
第I卷 (满分15分)听力（共两节, 满分15分）第一节听力理解（共5小题；每小题2分，满分10分）请听第 1 段对话回答第 1 至 2 题1.Where does the conversation happen?A.In a bookstoreB.In a shopC.In an office2.Why does the father buy a gift for his son?A.For his birthdayB.For his graduationC.For his success请听第 2 段对话回答第 3 至 5 题.3.What is the woman’s favorite enjoyment?A.Watching TVB.Listening to musicC.Playing games4.What is the man’s favorite program?A.AdvertisementsB.International news serials5.What does the woman think of the man’s opinion?A.She agrees with it completely.B.She agrees with part of it.C.She feels disappointed at it.第二节：听取信息(共 5 小题；每小题 1 分，满分 5 分).请听下面一段独白，请根据题目要求，从所听到的内容中获取必要的信息，然后填入标号为6—10 题的空格中。
广东省东莞市-北京师范大学东莞石竹附属学校2019-2020学年高一10月月考语文试题(word无答案)
广东省东莞市-北京师范大学东莞石竹附属学校2019-2020学年高一10月月考语文试题(word无答案)一、情景默写(★) 1 . 古诗文默写⑴《荆轲刺秦王》“易水诀别”中，荆轲悲壮的唱词是：_____________，_____________⑵《荆轲刺秦王》“易水诀别”中，通过众宾客的穿戴来表现出送行气氛的句子是：_____________，_____________。
⑶《沁园春·长沙》一诗中，诗人旧地重游，引发对往昔生活的回忆过渡句是：____________，________________。
⑷“家事国事天下事事事关心”，《沁园春·长沙》一诗中表现革命者关注国家大事的言行的句子是：_____，_____。
二、文言文阅读(★★★★) 2 . 阅读下面的课内文段，完成下面小题。
秦将王翦破赵，虏赵王，尽收其地，进兵北略地，至燕南界。
太子丹恐惧，乃请荆卿曰：“秦兵旦暮渡易水，则虽欲长侍足下，岂可得哉？”荆卿曰：“微太子言，臣愿得谒之。
今行而无信，则秦未可亲也。
夫今樊将军，秦王购之金千斤，邑万家。
诚能得樊将军首，与燕督亢之地图献秦王，秦王必说见臣，臣乃得有以报太子。
”太子曰：“樊将军以穷困来归丹，丹不忍以己之私，而伤长者之意，愿足下更虑之！”荆轲知太子不忍，乃遂私见樊於期，曰：“秦之遇将军，可谓深．矣。
父母宗族，皆为．戮没。
今闻购将军之首，金千斤，邑万家，将奈何？”樊将军仰天太息流涕曰：“吾每念，常痛于骨髓，顾计不知所出耳！”轲曰：“今有一言，可以解燕国之患，而报将军之仇者，何如？”樊於期乃前曰：“为之奈何？”荆轲曰：“愿得将军之首以．献秦，秦王必喜而善见臣。
臣左手把其．袖，而右手揕其胸，然则将军之仇报，而燕国见陵之耻除矣。
将军岂有意乎？”樊於期偏袒扼腕而进曰：“此臣日夜切齿拊心也，乃今得闻教！”遂自刎。
太子闻之，驰往，伏尸而．哭，极哀。
既已，无可奈何，乃遂收盛樊於期之首，函封之。
2019-2020学年广东省东莞市北京师范大学石竹附属学校新高考化学模拟试卷含解析
5．下列物质属于碱的是
A．CH3OHB．Cu2(OH)2CO3C．NH3·H2OD．Na2CO3
【答案】C
【解析】
【详解】
A.CH3OH为非电解质，溶于水时不能电离出OH－，A项错误；
B.Cu2(OH)2CO3难溶于水，且电离出的阴离子不全是OH－，属于碱式盐，B项错误；
C.NH3·H2O在水溶液中电离方程式为 NH4++OH－，阴离子全是OH－，C项正确；
B．Fe2+的还原性大于Br-，将少量氯水滴入FeBr2溶液中，首先氧化Fe2+，则无法比较Cl2、Br2的氧化性强弱，故B错误；
C．将SO2通入酸性高锰酸钾溶液中，溶液褪色，体现SO2的还原性，不是漂白性，故C错误；
D．测得同浓度的Na2CO3溶液的pH大于Na2SO3溶液，说明CO32-的水解能力大于SO32-，则电离能力HSO3->HCO3-，即电离常数Ka:HSO3->HCO3-，故D正确；
A．原子半径：Y＞Z＞X
B．X元素的族序数是Y元素的2倍
C．工业上电解融Y2X3化合物制备单质Y
D．W与X形成的所有化合物都只含极性共价键
【答案】D
【解析】
【分析】
W、X、Y、Z是原子序数依次增大的短周期主族元素，且占据三个不同周期，则W为第一周期主族元素，W为H，Z应为第三周期主族元素，根据化合物M的结构简式可知，Z可形成3个单键和1个双键，因此，Z原子最外层有5个电子，Z为P，W与Z的质子数之和是X的2倍，X的质子数= =8，则X为O，根据化合物M的结构简式，Y可形成+3价阳离子，则Y为Al，以此解答。
2．常温下，下列各组离子一定能在指定溶液中大量共存的是
A．使酚酞变红色的溶液：K+、Fe3+、SO42-、Cl-
【精准解析】广东省北京师范大学东莞石竹附属学校2019-2020学年高一10月月考地理试题+Word版含解析byde
①扰乱地球大气层，使地面的无线电短波通讯受到影响，甚至会出现短暂的中断。
②高能带电粒子扰动地球磁场，产生“磁暴”现象，使磁针剧烈颤动，不能正确指示方向。
③当高能带电粒子流高速冲进两极地区的高空大气层时，会产生极光现象。
④引发自然灾害，比如地震、水旱灾害
【4 题详解】
卫星发射中心的区位条件主要包括纬度、气候气象条件、地形条件、交通条件等。相对于海
2019-2020 学年度第一学期高一年级第一次月考地理试卷 考试时间：90 分钟 总分：100 分
一、单项选择题（共 30 题，每题 2 分，共 60 分） 下面是四幅经纬网图，读图回答下列各题。
高中学习讲义
1. 图中位于北半球、西半球的区域是（
）
A. ①
B. ②
C. ③
D. ④
2. 图中①在③的什么方向（
10°S—20°S，可知该点位于西半球、南半球，故 D 错误。所以选 B。
【2 题详解】
由 第 1 题 的 解 析可 知 ① 位 于 120°E—130°E，10°S—20°S， ③点 位 于 10°E—20°E，
0°—10°S，由①点和③点所处的纬度范围可知①点位于③点的南方，①点和③点所处的经
度范围可知①点位于③点东方，可知图中①在③的东南方向，可知 ACD 错误，故 B 正确。
故选 A。
7.读地球表面某区域的经纬网示意图，分析，若某人从 M 点出发，依次向正南、正东、正北
和正西方向分别前进 100 千米，则其最终位置是( )
只要坚持 梦想终会实现
-3-
高中学习讲义
A. 回到 M 点
B. 在 M 点正西方
C. 在 M 点正东方
D. 在 M 点东南方
2024届广东省东莞市北京师范大学石竹附属学校数学高一下期末教学质量检测试题含解析
2024届广东省东莞市北京师范大学石竹附属学校数学高一下期末教学质量检测试题注意事项1．考生要认真填写考场号和座位序号。
2．试题所有答案必须填涂或书写在答题卡上，在试卷上作答无效。
第一部分必须用2B 铅笔作答；第二部分必须用黑色字迹的签字笔作答。
3．考试结束后，考生须将试卷和答题卡放在桌面上，待监考员收回。
一、选择题：本大题共10小题，每小题5分，共50分。
在每个小题给出的四个选项中，恰有一项是符合题目要求的1．已知在ABC 中，()sin sin cos cos sin A B A B C +=+⋅，则ABC 的形状是 A ．锐角三角形 B ．钝角三角形 C ．等腰三角形D ．直角三角形2．在长为12cm 的线段AB 上任取一点C ．现作一矩形，邻边长分别等于线段AC ，CB 的长，则该矩形面积大于20cm 2的概率为 A ．16B ．13C ．23D ．453．下列说法正确的是（ ） A ．小于90︒的角是锐角B ．钝角是第二象限的角C ．第二象限的角大于第一象限的角D ．若角α与角β的终边相同，则,απβ=+∈k k Z4．下列关于极限的计算，错误的是（ ）A ．2227lim57n n n n →∞++=+221722lim 755n n n n→∞++=+ B ．222242lim n n n n n →∞⎛⎫+++⎪⎝⎭222242lim lim limn n n nn n n →∞→∞→∞=+++0000=+++=C ．)lim limn n n →∞=12n == D ．已知2,3,n n n n a n --⎧=⎨⎩为奇数为偶数，则()12lim n n a a a →∞+++= 12222319121324----+=-- 5．将两个长、宽、高分别为5，4，3的长方体垒在一起，使其中两个面完全重合，组成一个大长方体，则大长方体的外接球表面积的最大值为（ ）A ．150πB ．125πC ．98πD ．77π6．已知点(),P x y 是直线()400kx y k ++=>上一动点PA 、PB 是圆22:20C x y y +-=的两条切线，A 、B 是切点，若四边形PACB 的最小面积是2，则k 的值为（ ） A ．3B ．212C ．22D ．27．如图，网格纸上小正方形的边长为1，粗实线画出的是某多面体的三视图，则该多面体的体积为（ ）A ．54B ．54185+C ．90D ．818．等差数列中，若，，则（ ） A ．2019B ．1C ．1009D ．10109．某空间几何体的三视图如图所示，则这个几何体的体积等于（ ）A ．1B ．2C ．4D ．610．已知圆柱的轴截面为正方形，且该圆柱的侧面积为36π，则该圆柱的体积为 A ．27πB ．36πC ．54πD ．81π二、填空题：本大题共6小题，每小题5分，共30分。
2019-2020学年广东省东莞市北京师范大学石竹附属中学新高考化学模拟试卷含解析
2019-2020学年广东省东莞市北京师范大学石竹附属中学新高考化学模拟试卷一、单选题（本题包括15个小题，每小题4分，共60分．每小题只有一个选项符合题意）1．大海航行中的海轮船壳上连接了锌块，说法错误的是A．船体作正极B．属牺牲阳极的阴极保护法C．船体发生氧化反应D．锌块的反应：Zn－2e-→Zn2+【答案】C【解析】【详解】A. 在海轮的船壳上连接锌块，则船体、锌和海水构成原电池，船体做正极，锌块做负极，海水做电解质溶液，故A正确；B. 在海轮的船壳上连接锌块是形成原电池来保护船体，锌做负极被腐蚀，船体做正极被保护，是牺牲阳极的阴极保护法，故B正确；C. 船体做正极被保护,溶于海水的氧气放电：O2+4e−+2H2O=4OH−，故C错误；D. 锌做负极被腐蚀：Zn－2e-→Zn2+，故D正确。
故选:C。
2．下列有关物质性质的叙述一定不正确的是A．向FeCl2溶液中滴加NH4SCN溶液，溶液显红色B．KAl(SO4) 2·12H2O溶于水可形成Al(OH)3胶体C．NH4Cl与Ca(OH)2混合加热可生成NH3D．Cu与FeCl3溶液反应可生成CuCl2【答案】A【解析】【详解】A项，FeCl2溶液中含Fe2+，NH4SCN用于检验Fe3+，向FeCl2溶液中滴加NH4SCN溶液，溶液不会显红色，A 项错误；B项，KAl（SO 4）2·12H2O溶于水电离出的Al3+水解形成Al（OH）3胶体，离子方程式为Al3++3H2O Al （OH）3（胶体）+3H+，B项正确；C项，实验室可用NH4Cl和Ca（OH）2混合共热制NH3，反应的化学方程式为2NH4Cl+Ca（OH）2ΔCaCl2+2NH3↑+2H2O，C项正确；D项，Cu与FeCl3溶液反应生成CuCl2和FeCl2，反应的化学方程式为Cu+2FeCl3=CuCl2+2FeCl2，D项正确；答案选A。
3．已知：Br＋H2 HBr＋H，其反应的历程与能量变化如图所示，以下叙述正确的是A．该反应是放热反应B．加入催化剂，E1－E2的差值减小C．H－H的键能大于H－Br的键能D．因为E1>E2，所以反应物的总能量高于生成物的总能量【答案】C【解析】【分析】根据反应物的总能量和生成物的总能量的相对大小来判断反应的热效应。
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2019-2020学年广东省北京师范大学东莞石竹附属学校高一10月月考化学试题考生须知：考生答题时，将答案写在专用答题卡上。
选择题答案请用2B铅笔将答题卡上对应题目的答案涂黑；非选择题答案请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内规范作答，凡是答题不规范一律无．．．．．．．．．．效．。
可能用到的相对原子质量：H：1 C：12 N：14 O：16 Na：23 Mg：24 S：32Cl：35.5 K：39 Ca：40第I卷（选择题共60分）一、选择题：每小题3分，共60分。
每小题给出的四个选项中，只有一项是符合题目要求的。
1.对下列实验事故或废弃药品的处理方法正确的是A. 当有大量毒气泄漏时，人应沿顺风方向疏散B. 金属钠意外着火时，应用干燥的沙土盖灭C. 当少量浓硫酸沾皮肤上，应立即用氢氧化钠溶液冲洗D. 酒精失火用水浇灭2.下列基本实验操作不正确的是( )编号①②③④操作示意图操作名称倾倒液体取用块状固体稀释浓硫酸检查气密性A. ①③B. ①②C. ③④D. ②④3.下列图示的四种实验操作名称从左到右依次是( )A. 过滤、蒸发、蒸馏、分液B. 过滤、蒸馏、蒸发、分液C. 蒸发、蒸馏、过滤、分液D. 分液、蒸馏、蒸发、过滤4.根据下表信息，将乙二醇和丙三醇分离的最佳方法是密度物质分子式熔点/℃沸点/℃溶解性/g·cm–3乙二醇C2H4O2–11.5 198 1.11 易溶于水和乙醇丙三醇C3H8O317.9 290 1.26 能跟水、酒精以任意比互溶A. 分液B. 蒸馏C. 加水萃取D. 冷却至0℃后过滤5.下列有关物质的量的说法，错误的是A. 1摩尔任何气体都含有6．02×1023个分子B. 0.012Kg12C中含有6.02×1023个碳原子C. 1摩尔水中含有2mol氢和1mol氧D. 1molH2O中含有3 mol原子6.偏二甲肼(C2H8N2)是一种高能燃料，燃烧产生的巨大能量可作为航天运载火箭的推动力。
下列叙述正确的是A. 偏二甲肼的摩尔质量为60 gB. 6.02×1023个偏二甲肼分子的质量约为60 gC. 1 mol偏二甲肼的质量为60 g·mol－1D. 6 g偏二甲肼含有N A个偏二甲肼分子7.两份质量相同的CH4和NH3比较，下列结论错误的是A. 分子个数比为17∶16B. 同温同压下两种气体的体积之比是17∶16C. 氢原子个数比为17∶12D. 原子个数比为17∶168.配制一定物质的量浓度的NaOH溶液，下列操作正确的是A. 称量时，应将NaOH固体放在称量纸上称量B. 将称量的NaOH固体置于小烧杯中溶解，待溶液冷却至室温再转移C. 定容时若加水超过了刻度线，可用胶头滴管直接将多余溶液吸出D. 为减小误差，容量瓶必须干燥才可使用9.在配制溶液过程中正确的是（）A. 配制盐酸溶液用量筒量取盐酸时量筒必须先润洗B. 配制盐酸溶液时，容量瓶中少量的水不影响最终的浓度C. 定容时观察液面俯视会造成所配溶液浓度偏低D. 浓H2SO4稀释后即可注入容量瓶配制10.下列物质中所含分子物质的量最多的是（）A. 88g CO2 B. 3.5 mol H2C. 标准状况下33.6L SO2D. 3.01×1023个硫酸分子11.下列叙述正确的是A. 标准状况下，22.4L CO所含原子的物质的量为1molB. 33.6LNH3气体所含分子的物质的量为1.5molC. 同温同压下，相同体积的物质，其物质的量一定相等D. 同温同压下，一氧化碳气体和氮气，若体积相等，则质量一定相等12.下列溶液中的Cl−浓度与50 mL 1 mol/L MgCl2溶液中的Cl−浓度相等的是A. 150 mL 1 mol/L NaCl溶液B. 75 mL 2 mol/L CaCl2溶液C. 150 mL 2 mol/L KCl溶液D. 50 mL2 mol/L KClO3溶液模拟试卷13.等物质的量浓度的KCl、MgCl2、AlCl3三种溶液。
现欲完全沉淀其中的Cl—，消耗相同物质的量浓度的AgNO3溶液的体积比为3:2:1，则上述三种溶液的体积比为A. 1:1:1B. 9:3:1C. 3:2:1D. 9:3:214.三种正盐的混合溶液1L中含有0.2 molNa+、0.25 molMg2+、0.4 molCl－ ,则SO42－的物质的量浓度( )A. .0.15 mol/LB. 0.3 mol/LC. 0.1 mol/LD. 0.5 mol/L15.下列实验操作：①过滤②溶解③蒸馏④取用药品⑤萃取⑥配制一定浓度的溶液，一定要用到玻璃棒的是A.①②⑥ B. ②③⑥ C. ③④⑥ D. ④⑤⑥16.已知300 mL某浓度的NaOH溶液中含60 g溶质。
现欲配制1 mol/L 的NaOH溶液，应取原溶液与蒸馏水的体积比约为（忽略稀释时体积的变化）A. 1︰4B. 1︰5C. 2︰1D. 2︰317.饮茶是中国人的传统饮食文化之一。
为方便饮用，可通过以下方法制取罐装饮料茶，上述过程涉及的实验方法、实验操作和物质作用说法不正确的是A. ①操作利用了物质的溶解性B. ③操作为分液C. ②操作为过滤D. 加入抗氧化剂是为了延长饮料茶的保质期18.已知3.01×1023个X气体分子质量为16 g，则X气体的摩尔质量是A. 16 gB. 32 gC. 64 g /molD. 32 g /mol19.三个密闭容器中分别充入N2、H2、O2三种气体，以下各种情况下排序正确的是( )A. 当它们的温度和压强均相同时，三种气体的密度：ρ(H2)>ρ(N2)>ρ(O2)B. 当它们的温度和密度都相同时，三种气体的压强：p(H2)>p(N2)>p(O2)C. 当它们的质量和温度、压强均相同时，三种气体的体积：V(O2)>V(N2)>V(H2)D. 当它们的压强和体积、温度均相同时，三种气体的质量：m(H2)>m(N2)>m(O2)20.80 g 密度为 ρ g·cm −3的CaCl 2溶液里含2 g Ca 2+，从中再取出一半的溶液中Cl −的浓度是 A.800ρmol·L −1B. 1.25ρ mol·L −1C.1600ρ mol·L −1D. 0.63 mol·L −1第Ⅱ卷（非选择题 共40分）21.（1）6.02×1023个氢氧根离子的物质的量是________mol ，其摩尔质量为________。
（2）在标准状况下，0.01 mol 某气体的质量为0.44 g ，则该气体的密度为________g·L −1（保留小数点后两位），该气体的相对分子质量为________。
（3）在标准状况下，由CO 和CO 2组成的混合气体为6.72 L ，质量为12 g ，此混合物中CO 和CO 2物质的量之比是________，CO 的体积分数是________，CO 的质量分数是________，C 和O 原子个数比是________，混合气体的平均相对分子质量是________，密度是________g·L −1。
22.现有NaCl 、Na 2SO 4和NaNO 3的混合物，选择适当的试剂除去杂质，从而得到纯净的NaNO 3晶体，相应的实验流程如图所示。
请回答下列问题：（1）写出实验流程中下列物质的化学式：试剂X___，沉淀A____。
（2）上述实验流程中①②③步均要进行的实验操作是___（填操作名称）。
（3）上述实验流程中加入过量Na 2CO 3溶液的目的是______________________________。
（4）按此实验方案得到的溶液3中肯定含有______（填化学式）杂质。
为了解决这个问题，可以向溶液3中加入适量的___（填化学式），之后若要获得NaNO 3晶体，需进行的实验操作是____（填操作名称）。
23.今有下列六组仪器：①牛角管、②锥形瓶、③温度计、④冷凝管、⑤已组装固定好的铁架台、酒精灯和带塞(有孔)蒸馏烧瓶(垫有石棉网)、⑥带铁夹的铁架台。
现要进行酒精和水混合物的分离实验。
试回答下列问题：(1)按仪器的安装先后顺序排列以上提供的各组仪器(填序号)：⑤→______→______→______→①→②。
(2)冷凝管中冷凝水应从下口______(填“进”或“出”，下同)，上口________。
(3)蒸馏时，温度计水银球应位于_________。
(4)在蒸馏烧瓶中注入液体混合物后，加几片碎瓷片的目的是________。
(5)蒸馏后在锥形瓶中收集到的液体是________，烧瓶中剩下的液体主要是_________。
24.“84消毒液”能有效杀灭甲型H1N1病毒，某同学购买了一瓶“威露士”牌“84消毒液”，并查阅相关资料和消毒液包装说明得到如下信息：“84消毒液”：含25%NaClO、1000mL、密度1.192g·cm−3，稀释100倍（体积比）后使用。
请根据以上信息和相关知识回答下列问题：（1）该“84消毒液”的物质的量浓度为_____mol·L−1。
（2）该同学取100 mL“威露士”牌“84消毒液”稀释后用于消毒，稀释后的溶液中c（Na+）=____mol·L −1。
（3）一瓶“威露士”牌“84消毒液”能吸收空气中____L的CO2（标准状况）而变质。
（已知：CO2+2NaClO+H2O=Na2CO3+2HClO）（4）该同学参阅“威露士”牌“84消毒液”的配方，欲用NaClO固体配制480mL含25%NaClO的消毒液。
下列说法正确的是____。
A．如上图所示的仪器中，有四种是不需要的，还需一种玻璃仪器B．容量瓶用蒸馏水洗净后，应烘干才能用于溶液配制C．利用购买的商品NaClO来配制可能导致结果偏低D．需要称量的NaClO固体质量为143g参考答案一、选择题1. B2. B3. A4. B5.C6.B7.D8.B9.B 10.B11.D 12.C 13. B 14.A 15. A 16.A 17.B 18. D 19.B 20. B21. (1). 1 (2). 17 g/mol (3). 1.96 (4). 44 (5). 1∶3 (6). 25% (7). 17.5% (8). 4∶7 (9). 40 (10). 1.7922. (1). AgNO3 (2). BaSO4 (3). 过滤 (4). 除去过量的Ba2+和Ag+ (5). Na2CO3 (6). HNO3 (7). 蒸发浓缩、冷却结晶、过滤23. (1). ③ (2). ⑥ (3). ④ (4). 进 (5). 出 (6). 蒸馏烧瓶支管口处 (7). 防止加热时液体暴沸 (8). 酒精 (9). 水24. (1). 4.0 (2). 0.04 (3). 89.6 (4). C。