2019学年宁波市高一上九校联考
浙江省宁波市2019-2020学年高一下学期九校联考英语试题含答案
宁波市2019学年第二学期九校联考高一英语试题第Ⅰ卷第一部分：听力（共两节，满分30分）第一节：（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.Where does the conversation probably take place?A.In a restaurant.B.In a bookstore.C.In a library.2.What does the woman do?A.A designer.B.A writer.C.A sales agent.3.What might the man be doing now?A.Washing dishes.B.Setting the table.C.Doing some cooking.4.When will the speakers make some preparations?A.Tuesday.B.Wednesday.C.Thursday.5.What happened to the man?A.He lost his bike.B.He failed the exam again.C.He was scolded by his dad.第二节：（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6.What are the speakers mainly talking about?A.The umbrella.B.The shop.C.The weather.7.What was the weather like yesterday morning?A.Rainy.B.Sunny.C.Cloudy.听第7段材料，回答第8至10题。
2019学年第一学期浙江省宁波市九校联考高二语文参考答案
宁波市九校联考高二语文参考答案 第1页 共4页 宁波市一9201学年第学期期末九校联考 高二语文参考答案一、语言文字运用（共23分）1．D 【解析】A 项，岗-冈。
B 项，抉-决，浸j ìn 。
C 项，合-和，岐q í。
2．A 【解析】五湖四海，指全国各地，这里应为“江河湖海”。
3．C 【解析】冒号使用“一冒到底”，这里可以把冒号去掉。
（另：冒号可以用在“是”“即”等字后面以提起下文，但不可用在这些字前。
）4．B 【解析】A 项，句式杂糅，“应该”和“有……的必要”杂糅，把“应该”改成“有”。
C 项，成分残缺，“采取”缺少宾语，在“音视频”后加上“的形式”。
D 项，“食品安全对于公众”主客颠倒，“传播和编造”语序不当。
5．C 【解析】浪漫主义爱国诗人，《九辩》是宋玉的作品。
6．D 【解析】宋荣子和列子达到了“无功”和“无名”的状态。
7．（1）如：垃圾分类人人动手，干湿分离家家行动。
（16字）/众人分类一条心，垃圾也能变成金。
（14字）（2分）（2）如：垃圾分类是人类可持续发展的必然选择，所以实行生活垃圾分类势在必行，但是目前不宜过快的一步到位。
（1分）眼下推进垃圾分类，首先应该加强科普教育，普及垃圾分类的知识，需要增强民众的参与意识。
（1分）同时，也要充分考虑我国国情，不应过分追求极致的垃圾分类，或完全沿用其他国家的分类方式。
（1分）垃圾分类标志着时代和观念的进步，也将经历一个漫长的过程。
（1分）（注意答题的切入口是垃圾分类的实施角度：肯定实施垃圾分类的必要性1分；指出目前实施垃圾分类所面临的最主要的困境1分；垃圾分类需要注意的问题1分；普及垃圾分类将是一个漫长的过程，不可操之过急1分。
言之成理即可。
）二、现代文阅读（26分）（一）（6分）8．C 【解析】原文是“基本上”。
9．A 【解析】“旨在表达水墨画正在成为一种惹人瞩目的文化现象”错。
（二）（20分）10．（1）玉温柔无价；（2）玉可以直接做成戒指镯子和簪笄（或者“玉无须刻意雕琢”）；（3）玉可供把玩，含意丰富；（4）玉无瑕难得、有瑕亦坦荡；（5）玉是中国传统文化的象征。
2019-2020学年浙江省宁波市九校联考高一下学期期末数学试卷 (解析版)
2019-2020学年浙江宁波市九校联考高一第二学期期末数学试卷一、选择题（共10小题）.1．设集合M＝{x|x2+x﹣6＜0}，N＝{x|1≤x≤3}，则M∩N＝（）A．[1，2）B．[1，2]C．（2，3]D．[2，3]2．直线6x+8y﹣2＝0与6x+8y﹣3＝0间的距离为（）A．1B．3C．D．3．如果实数a，b满足：a＜b＜0，则下列不等式中不成立的是（）A．|a|+b＞0B．C．a3﹣b3＜0D．4．圆C是以直线l：（2m+1）x+（m+1）y+2m＝0的定点为圆心，半径为4的圆，则圆C 的方程为（）A．（x+2）2+（y﹣2）2＝16B．（x﹣2）2+（y﹣2）2＝16C．（x﹣2）2+（y+2）2＝16D．（x+2）2+（y+2）2＝165．已知sin2θ＝﹣，则tanθ+＝（）A．B．﹣C．D．﹣6．已知数列{a n}是等差数列，数列{b n}是等比数列，若a2+a6+a10＝2π，b2b5b8＝8，则的值是（）A．B．C．D．7．在△ABC中，若sin（B+C）sin（B﹣C）＝sin2A，则△ABC是（）A．等腰三角形B．锐角三角形C．直角三角形D．钝角三角形8．已知圆C1：x2+y2＝1和圆C2：x2+y2﹣2x﹣y＝0的公共弦过点（a，b），则4a2+b2的最小值为（）A．B．C．1D．29．已知函数，若函数g（x）＝f（x）﹣kx﹣1恰有三个零点，则实数k的取值范围为（）A．B．C．D．10．已知函数，若关于x的方程|f（x）﹣a|+|f（x）﹣a﹣1|＝1，有且仅有三个不同的整数解，则实数a的取值范围是（）A．B．[0，8]C．D．二、填空题（共7小题，每小题3分，满分21分）11．已知直线l1：ax﹣y+a+1＝0，直线l2：3x+（a﹣4）y+3＝0，若l1∥l2，则实数a的值为．12．设α，β∈（0，π），，则cosα＝，tan（α+β）＝．13．已知数列{a n}的前n项和S n＝2a n﹣2，则数列{a n}满足a n＝，若b n＝log2a n，数列的前n项和为T n，则T n＝．14．已知实数x，y满足约束条件，则z＝x+2y的最大值为．15．过点P（0，2）的直线l与圆C：x2+y2＝32相交于M，N两点，且圆上一点Q到直线l的距离的最大值为5，则直线l的方程是．16．已知正实数x，y满足x+y＝1，则的最小值为．17．已知△ABC中，角A，B，C所对的边分别是a，b，c，AB边上的高为CD，且2CD ＝AB，则的取值范围是．三、解答题（共5小题，满分0分）18．已知等差数列{a n}的公差不为0，S3＝15，a1，a4，a13成等比数列．（1）求数列{a n}的通项公式；（2）若数列{c n}满足，求数列{c n}的前n项和T n．19．已知函数．（1）求函数f（x）的周期和单调递增区间；（2）在△ABC中，角A，B，C所对的边分别是a，b，c，且满足，求f（B）的取值范围．20．已知函数．（1）若区间[1，6]上存在一个x0，使得|f（x0）|≥a成立，求实数a的取值范围；（2）若不等式f（e x）≥me x在x∈（﹣∞，0]上恒成立，求实数m的取值范围．21．如图，在平面直角坐标系xOy中，已知点P（2，4），圆O：x2+y2＝4与x轴的正半轴的交点是Q，过点P的直线l与圆O交于不同的两点A，B．（1）求AB的中点M的轨迹方程；（2）设点，若，求△QAB的面积．22．已知正项数列{a n}满足a1＝1，2a n a n+1+3a n+1＝8a n﹣2．（1）试比较a n与2的大小，并说明理由；（2）设数列{a n}的前n项和为S n，证明：当n∈N*时，S n＞2n﹣5．参考答案一、选择题1．设集合M＝{x|x2+x﹣6＜0}，N＝{x|1≤x≤3}，则M∩N＝（）A．[1，2）B．[1，2]C．（2，3]D．[2，3]【分析】根据已知角一元二次不等式可以求出集合M，将M，N化为区间的形式后，根据集合交集运算的定义，我们即可求出M∩N的结果．解：∵M＝{x|x2+x﹣6＜0}＝{x|﹣3＜x＜2}＝（﹣3，2），N＝{x|1≤x≤3}＝[1，3]，∴M∩N＝[1，2）故选：A．2．直线6x+8y﹣2＝0与6x+8y﹣3＝0间的距离为（）A．1B．3C．D．【分析】由题意利用两条平行直线直线间的距离公式，求得结果．解：直线6x+8y﹣2＝0与6x+8y﹣3＝0间的距离为＝，故选：C．3．如果实数a，b满足：a＜b＜0，则下列不等式中不成立的是（）A．|a|+b＞0B．C．a3﹣b3＜0D．【分析】根据a＜b＜0，取a＝﹣2，b＝﹣1，即可选出答案．解：根据a＜b＜0，取a＝﹣2，b＝﹣1，则D不成立．故选：D．4．圆C是以直线l：（2m+1）x+（m+1）y+2m＝0的定点为圆心，半径为4的圆，则圆C 的方程为（）A．（x+2）2+（y﹣2）2＝16B．（x﹣2）2+（y﹣2）2＝16C．（x﹣2）2+（y+2）2＝16D．（x+2）2+（y+2）2＝16【分析】带有参数的直线，先整理可得恒过定点，由题意可得圆心坐标，由题意进而求出圆的方程．解：由（2m+1）x+（m+1）y+2m＝0，可得（2x+y+2）m+（x+y）＝0，所以直线过的交点，解得：x＝﹣2，y＝2，即直线过定点（﹣2，2），则所求圆的方程为（x+2）2+（y﹣2）2＝16．故选：A．5．已知sin2θ＝﹣，则tanθ+＝（）A．B．﹣C．D．﹣【分析】利用同角三角函数基本关系式，二倍角的正弦函数公式化简所求结合已知即可计算求解．解：sin2θ＝﹣，则tanθ+＝+＝＝＝＝﹣．故选：D．6．已知数列{a n}是等差数列，数列{b n}是等比数列，若a2+a6+a10＝2π，b2b5b8＝8，则的值是（）A．B．C．D．【分析】由已知结合等差数列与等比数列的性质求得a6与b5的值，进一步求得，则答案可求．解：在等差数列{a n}中，由a2+a6+a10＝2π，得3a6＝2π，即；在等比数列{b n}中，由b2b5b8＝8，得，即b5＝2．∴．∴＝sin．故选：C．7．在△ABC中，若sin（B+C）sin（B﹣C）＝sin2A，则△ABC是（）A．等腰三角形B．锐角三角形C．直角三角形D．钝角三角形【分析】由题意利用两角和与差的正弦函数公式，三角形内角和定理化简已知等式，结合sin A≠0，sin C≠0，可得cos B＝0，结合范围B∈（0，π），可求B为直角，即可判断三角形的形状．解：∵sin（B+C）sin（B﹣C）＝sin2A，∴sin A sin（B﹣C）＝sin2A，∵A为三角形内角，sin A≠0，∴sin（B﹣C）＝sin A，∴sin B cos C﹣cos B sin C＝sin B cos C+cos B sin C，∴2cos B sin C＝0，∵C为三角形内角，sin C≠0，∴可得cos B＝0，∵B∈（0，π），∴B＝，△ABC是直角三角形．故选：C．8．已知圆C1：x2+y2＝1和圆C2：x2+y2﹣2x﹣y＝0的公共弦过点（a，b），则4a2+b2的最小值为（）A．B．C．1D．2【分析】根据题意，求出两圆的公共弦的方程，分析可得2a+b＝1，变形可得：（2a+b）2＝4a2+b2+4ab＝1，结合基本不等式的性质可得（4a2+b2）+（4a2+b2）≥1，变形即可得答案．解：根据题意，圆C1：x2+y2＝1和圆C2：x2+y2﹣2x﹣y＝0，则两圆的公共弦的方程为2x+y＝1，又由两圆的公共弦过点（a，b），则有2a+b＝1，变形可得：（2a+b）2＝4a2+b2+4ab＝1，又由4a2+b2≥2＝4ab，则有（4a2+b2）+（4a2+b2）≥1，即有4a2+b2≥，当且仅当2a＝b时等号成立，即4a2+b2的最小值为；故选：B．9．已知函数，若函数g（x）＝f（x）﹣kx﹣1恰有三个零点，则实数k的取值范围为（）A．B．C．D．【分析】作出函数y＝f（x）的图象，则函数y＝g（x）有三个不同的零点，等价于直线y＝kx+1与曲线y＝f（x）的图象有三个不同交点，考查直线y＝kx+1与圆（x﹣3）2+y2＝1相切，且切点位于第三象限时以及直线y＝kx+1过点（4，0）时，对应的k值，数形结合可得出实数k的取值范围．解：当2＜x＜4时，y＝，则y≤0，等式两边平方得y2＝﹣x2+6x﹣8，整理得（x﹣3）2+y2＝1，所以曲线y＝表示圆（x﹣3）2+y2＝1的下半圆，如下图所示，由题意可知，函数y＝g（x）有三个不同的零点，等价于直线y＝kx+1与曲线y＝f（x）的图象有三个不同交点，直线y＝kx+1过定点P（0，1），当直线y＝kx+1过点A（4，0）时，则4k+1＝0，可得k＝；当直线y＝kx+1与圆（x﹣3）2+y2＝1相切，且切点位于第三象限时，k＜0，此时，解得k＝．由图象可知，当时，直线y＝kx+1与曲线y＝f（x）的图象有三个不同交点．因此，实数k取值范围是．故选：B．10．已知函数，若关于x的方程|f（x）﹣a|+|f（x）﹣a﹣1|＝1，有且仅有三个不同的整数解，则实数a的取值范围是（）A．B．[0，8]C．D．【分析】作出函数f（x）的图象，由|f（x）﹣a|+|f（x）﹣a﹣1|＝1可得出a≤f（x）≤a+1，即函数f（x）位于直线y＝a和y＝a+1的图象上有三个横坐标为整数的点，数形结合可得实数a的取值范围．解：∵|f（x）﹣a|+|f（x）﹣a﹣1|＝，∴函数f（x）位于直线y＝a和y＝a+1的图象上有三个横坐标为整数的点，当x＜0时，且f（x）＜0，由双勾函数的单调性可知，函数y＝f（x）在区间（﹣∞，﹣）上单调递减，在区间（﹣，0）上单调递增，于是当x＜0时，，∵f（﹣1）＝，f（﹣2）＝，f（﹣3）＝，f（﹣4）＝，且f（﹣4）＞f （﹣3）＞f（﹣2），如下图所示，要使得函数f（x）位于直线y＝a和y＝a+1的图象上有三个横坐标为整数的点，则f（﹣3）≤a+1＜f（﹣4），即，解得．因此，实数a的取值范围是．故选：A．二、填空题（共7小题，每小题3分，满分21分）11．已知直线l1：ax﹣y+a+1＝0，直线l2：3x+（a﹣4）y+3＝0，若l1∥l2，则实数a的值为1．【分析】由题意利用两条直线平行的条件，求得a的值．解：直线l1：ax﹣y+a+1＝0，直线l2：3x+（a﹣4）y+3＝0，若l1∥l2，显然a≠4，＝≠，解得a＝1，故答案为：1．12．设α，β∈（0，π），，则cosα＝，tan（α+β）＝．【分析】利用余弦的倍角公式以及两角和差的正切公式进行计算即可．解：cosα＝2cos2﹣1＝2×（）2﹣1＝，则α∈（0，），则sinα＝，tanα＝，∵cosβ＝﹣，∴sinβ＝，则tanβ＝﹣，则tan（α+β）＝＝＝＝，故答案为：，13．已知数列{a n}的前n项和S n＝2a n﹣2，则数列{a n}满足a n＝2n，若b n＝log2a n，数列的前n项和为T n，则T n＝．【分析】（1）直接利用数列的递推关系式的应用求出数列的通项公式．（2）利用裂项相消法的应用求出数列的和．解：（1）数列{a n}的前n项和S n＝2a n﹣2①，当n＝1时，解得a1＝2．当n≥2时，S n﹣1＝2a n﹣1﹣2②，①﹣②得a n＝2a n﹣2a n﹣1，整理得a n＝2a n﹣1，所以（常数），所以数列{a n}是以2为首项，2为公比的等比数列．所以．（2）由于，所以b n＝log2a n＝，故，故＝1﹣．14．已知实数x，y满足约束条件，则z＝x+2y的最大值为7．【分析】由约束条件作出可行域，化目标函数为直线方程的斜截式，数形结合得到最优解，把最优解的坐标代入目标函数得答案．解：由约束条件作出可行域如图，联立，解得A（﹣1，4）．化z＝x+2y为y＝．由图可知，当直线y＝过A时，直线在y轴上的截距最大，z有最大值为﹣1+8＝7．故答案为：7．15．过点P（0，2）的直线l与圆C：x2+y2＝32相交于M，N两点，且圆上一点Q到直线l的距离的最大值为5，则直线l的方程是y＝±x+2．【分析】由题意画出图形，可知所求直线的斜率存在，设出直线方程，再由圆心到直线的距离等于列式求得k，则答案可求．解：如图，圆C：x2+y2＝32的半径为，所求直线过点（0，2），当直线l的斜率不存在时，圆上一点Q到直线l的距离的最大值为4，不合题意；则直线l的斜率存在，设直线方程为y＝kx+2，即kx﹣y+2＝0．要使圆上一点Q到直线l的距离的最大值为5，则O到l的距离为．∴，解得k＝±1．∴直线l的方程是y＝±x+2．故答案为：y＝±x+2．16．已知正实数x，y满足x+y＝1，则的最小值为．【分析】利用“乘1法”与基本不等式的性质即可得出．解：因为x+y＝1，所以x+1+y+2＝4，则＝（）[（x+1）+（y+2）]＝[5++]＝+[+]≥+×2＝，当且仅当＝，即x＝，y＝时取“＝”，故答案为：．17．已知△ABC中，角A，B，C所对的边分别是a，b，c，AB边上的高为CD，且2CD ＝AB，则的取值范围是[2，]．【分析】由AB及AB边上的高CD，联想到三角形的面积公式，然后结合余弦定理构造出＝sin C+cos C的函数，转化为函数的值域问题．解：由已知A，B，C所对的边分别是a，b，c，设CD＝h．因为AB边上的高为CD，且2CD＝AB，所以2h＝c．所以．所以，即c2＝2ab sin C＝a2+b2﹣2ab cos C，两边同除以ab得：，当且仅当时取等号，又，当且仅当a＝b时取等号．所以．故答案为：[2，]．三、解答题（共5小题，满分0分）18．已知等差数列{a n}的公差不为0，S3＝15，a1，a4，a13成等比数列．（1）求数列{a n}的通项公式；（2）若数列{c n}满足，求数列{c n}的前n项和T n．【分析】（1）直接利用等差数列的定义求出数列的通项公式．（2）利用（1）的结论，进一步利用分组法求出数列的和．解：（1）设等差数列{a n}的公差d≠0，S3＝15，a1，a4，a13成等比数列．所以，整理得，解得，所以a n＝a1+2（n﹣1）＝2n+1，（2）由（1）得数列{c n}满足＝2n+1+22n+1，所以＝2n+3+n2+2n﹣8．19．已知函数．（1）求函数f（x）的周期和单调递增区间；（2）在△ABC中，角A，B，C所对的边分别是a，b，c，且满足，求f（B）的取值范围．【分析】（1）利用两角和与差的三角函数，化简函数为一个角的一个三角函数的形式，然后求该函数的周期和单调区间即可；（2）结合条件，利用余弦定理求出cos B的取值范围，进而得到B的取值范围，即可求解f（B）的取值范围．解：＝sin x﹣（cos x+1）+＝sin x﹣cos x＝sin（x﹣），（1）根据f（x）的解析式可得T＝＝2π，令﹣+2kπ≤x﹣≤+2kπ，解得x∈[﹣+2kπ，+2kπ]（k∈Z），即f（x）的单调递增区间为：[﹣+2kπ，+2kπ]（k∈Z）；（2）因为，即c2+a2﹣b2≥c，则由余弦定理cos B＝，因为B∈（0，π），所以≤cos B＜1，则0＜B≤，所以﹣＜B﹣≤﹣，则sin（B﹣）∈（﹣，﹣]，即f（B）的值域为：（﹣，﹣]．20．已知函数．（1）若区间[1，6]上存在一个x0，使得|f（x0）|≥a成立，求实数a的取值范围；（2）若不等式f（e x）≥me x在x∈（﹣∞，0]上恒成立，求实数m的取值范围．【分析】（1）由f（x）在[1，2]递减，在[2，6]递增，求得f（x）的值域，可得|f（x）|的最大值，由题意知只需|f（x0）|max≥a成立，然后求出a的范围；（2）由题意可得m≤1+﹣在x∈（﹣∞，0]上恒成立，只需求得1+﹣在x∈（﹣∞，0]上的最小值，结合指数函数的单调性，可得所求最小值，进而得到所求范围．解：（1）函数在[1，2]递减，可得f（x）∈[﹣2，﹣1]，在[2，6]递增，可得f（x）∈[﹣2，]，则|f（x）|在[1，6]的最大值为2，由题意可得|f（x0）|max≥a成立，即a≤2，所以a的取值范围为（﹣∞，2]；（2）不等式f（e x）≥me x在x∈（﹣∞，0]上恒成立，可得e x+﹣6≥me x在x∈（﹣∞，0]上恒成立，化为m≤1+﹣在x∈（﹣∞，0]上恒成立，由y＝e x，（0＜y≤1），可得≥1，1+﹣＝4（﹣）2﹣的最小值为4（1﹣）2﹣＝﹣1，则m≤，即m的取值范围是（﹣∞，﹣1]．21．如图，在平面直角坐标系xOy中，已知点P（2，4），圆O：x2+y2＝4与x轴的正半轴的交点是Q，过点P的直线l与圆O交于不同的两点A，B．（1）求AB的中点M的轨迹方程；（2）设点，若，求△QAB的面积．【分析】（1）设弦AB的中点为M，可得OM⊥MP，由数量积＝0，可得M的轨迹方程；（2）由题意可知，直线l的斜率存在，设直线方程为y﹣4＝k（x﹣2），联立直线方程与圆的方程，利用根与系数的关系及中点坐标公式求得M的坐标，代入|MN|＝|OM|，构造关于k的方程，解出k的值，进一步求得|AB|与Q到直线的距离，则△QAB的面积可求．解：（1）设点M（x，y），∵M是弦AB的中点，∴MO⊥MP，又∵＝（x，y），＝（x﹣2，y﹣4），∴x（x﹣2）+y（y﹣4）＝0，即x2+y2﹣2x﹣4y＝0，联立，解得或，又∵M在圆O的内部，∴点M的轨迹方程是x2+y2﹣2x﹣4y＝0（﹣＜x＜2）；（2）由题意可知，直线l的斜率存在，设直线方程为y﹣4＝k（x﹣2），联立，得（1+k2）x2﹣4k（k﹣2）x+（2k﹣4）2﹣4＝0．设A（x1，y1），B（x2，y2），则．设中点M（x0，y0），则，①代入直线l的方程得，②又由|MN|＝|OM|，得，化简得，将①②代入得k＝3．∵圆心到直线l的距离d＝＝，∴|AB|＝，Q到直线l的距离h＝．∴，即△QAB的面积为．22．已知正项数列{a n}满足a1＝1，2a n a n+1+3a n+1＝8a n﹣2．（1）试比较a n与2的大小，并说明理由；（2）设数列{a n}的前n项和为S n，证明：当n∈N*时，S n＞2n﹣5．【分析】（1）推导出，从而a n+1﹣2＝，从而a n+1﹣2与a n﹣2同号，进而a n﹣2与a1﹣2同号，由此能求出a n＜2．（2）由，得1≤a n＜2，从而2﹣a n≤（2﹣a1）（）n﹣1＝（）n﹣1，由此能证明S n＞2n﹣5．解：（1）解：∵正项数列{a n}满足a1＝1，2a n a n+1+3a n+1＝8a n﹣2．∴，∴﹣2＝＝，∵正项数列{a n}中，a n＞0，∴2a n+3＞0，∴a n+1﹣2与a n﹣2同号，∴a n﹣2与a1﹣2同号，∵a1﹣2＝﹣1＜0，∴a n﹣2＜0，∴a n＜2．（2）证明：由（1）知，∴﹣＝，∴与同号，也与同号，∴1≤a n＜2，∴＝＝≤，∴2﹣a n≤（2﹣a1）（）n﹣1＝（）n﹣1，∴2n﹣S n＝≤5[1﹣（）n]＜5，∴S n＞2n﹣5．。
精品解析：浙江省宁波市九校2019-2020学年高一上期期末英语试题(解析版)
2019学年第一学期宁波市九校联考高一英语试题选择题部分第一部分听力（共两节，满分30分）第一节（共5小题；每小题 1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.What color are Julie’s shoes?A.Black.B.Brown.C.Dark blue.2.Who dies in the story?A.The dragon.B.The soldier.C.The princess.3.Which animal is in the field?A.A sheep.B.A cow.C.A horse.4.What is the woman going to do this evening?A.Go on a trip.B.Attend a concert.C.Look after her brother.5.What is the homework for next Tuesday?A.Writing an essay.B.Reading the textbook.C.Listening to some radio programs.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6.How long will school be canceled according to Martin?A.For three days.B.For six days.C.For seven days.7.What do the speakers want to do tomorrow?A.Visit their friends.B.Skate on a pond.C.Make a snowman with their father.听第7段材料，回答第8至10题。
宁波市九校2019-2020学年上学期高一数学期末联考卷附答案解析
宁波市九校2019-2020学年上学期期末联考高一数学试卷一、单选题1．已知集合{}0A x x =>,集合{}16B x x =-<≤,则A B =I ( )A ．()10-， B ．(]06，C ．()06， D ．(]16-， 2．函数tan 43y x x ππ⎛⎫=-<< ⎪⎝⎭的值域是( )A ．()11-，B ．3⎛⎫ ⎪ ⎪⎝⎭-1，C．(-D．⎡-⎣3．已知∈，x y R ,且0x y >>,则( )A ．110x y ->B ．cos cos 0x y ->C ．11022x y⎛⎫⎛⎫-< ⎪ ⎪⎝⎭⎝⎭D ．ln ln 0x y +> 4．已知向量122a ⎛⎫= ⎪ ⎪⎝⎭r ，,2b =r ,且a b ⋅=r r 则a r 与b r的夹角为( ) A ．6πB ．2π C ．4π D ．3π 5．已知半径为2的扇形AOB 中,»AB 的长为3π,扇形的面积为ω,圆心角AOB 的大小为ϕ弧度,函数()sin h x x x πϕω⎛⎫=+ ⎪⎝⎭,则下列结论正确的是( )A ．函数()h x 是奇函数B ．函数()h x 在区间[]20π-，上是增函数 C ．函数()hx 图象关于()30π，对称 D ．函数()hx 图象关于直线3x π=-对称6．已知7log 2a =，0.7log 0.2b =，0.20.7c =，则a ，b ，c 的大小关系为（ ） A ．a c b <<B ．a b c <<C ．b c a <<D ．c a b <<7．已知4个函数:①sin y x x =;②cos y x x =;③2=x x y e;④4cos xy x e =-的图象如图所示,但是图象顺序被打乱,则按照图象从左到右的顺序,对应的函数序号正确的为( )A ．①④②③B ．③②④①C ．①④③②D ．③①④②8．在ABC V 中,102BA AC AC BC BC BA AB BC BC BA ⋅⋅+=⋅=u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r ，,则ABC V 为( ) A ．直角三角形 B ．三边均不相等的三角形 C ．等边三角形 D ．等腰非等边三角形9．若()()()()2202022020log 2019log 2log 2019log 2xyy x--+<+,则( )A ．0x y +<B ．0x y +>C ．0x y -<D ．0x y ->10．设函数()()(]()1222112f x x f x x x ⎧+∈-∞-⎪=⎨⎪+-∈-+∞⎩，，，，,则方程()()21610f x x x ++-=根的个数为( )A ．2B ．3C ．4D ．5二、填空题11．已知函数()()1lg 31x f x x +=+,则()0f =____________函数定义域是____________. 12．已知12e e u r u u r ，是单位向量,12e e ⊥u r u u r ,122AB e e =+u u u r u r u u r ,123BC e e =-+u u u r u r u u r ,12CD e e λ=-u u u r u r u u r ,若AB CD ⊥uu u r uu u r,则实数λ=____________;若A B D ，，三点共线,则实数λ=____________.13．己知函数()()2tan 06f x a x a ππ⎛⎫=+> ⎪⎝⎭的最小正周期是3.则a =___________()f x 的对称中心为____________.14．已知a b R ∈，,定义运算“⊗”:a a b a b b a b ≥⎧⊗⎨<⎩，，,设函数()()()2221log xf x x =⊗-⊗,()02x ∈，,则()1f =___________;()f x 的值域为__________.15．已知函数()()29a f x m x =-为幂函数,且其图象过点(3,则函数()()2log 6a g x x mx =-+的单调递增区间为___________.16．已知a b c r r r ，，，是平面向量,且2c =r ,若24a c b c ⋅=⋅=r r r r，,则a b +r r 的取值范围是__________.17．函数()()25sin f x x g x x =--=，,若1202n x x x π⎡⎤∈⎢⎥⎣⎦，，……，，,使得()()12f x f x ++…()()()()()()1121n n n n f x g x g x g x g x f x --++=++++…,则正整数n 的最大值为___________.三、解答题18．已知向量()()()sin 1cos 10a x b x c m =-=r r r ，，=，，，,其中04x π⎡⎤∈⎢⎥⎣⎦，.(1)若的35a b ⋅=-r r ,求tan x 的值;(2)若a c +r r 与a c -r r垂直,求实数m 的取值范围.19．已知集合{()121A x y B a a ===-+，，,()(){}110C x x m x m m R =--++≤∈，.(1)若()RA B =∅Ið,求a 的取值范围;(2)若A C C =I ,求m 的取值范围.20．已知()f x 为偶函数,当0x ≥时,()()2lg 1f x x =+.(1)求()f x 的解析式;(2)若对于任意的()0x ∈-∞，,关于x 的不等式()()lg kx f x <恒成立,求k 的取值范围.21．已知函数()sin 26f x x π⎛⎫+ ⎝=⎪⎭,()()sin 002g x A x A πωϕωϕ⎛⎫=+>>< ⎪⎝⎭，，的部分图象如图所示.(1)求()gx 的解析式,并说明()f x 的图象怎样经过2次变换得到()g x 的图象;(2)若对于任意的46x ππ⎡⎤∈-⎢⎥⎣⎦，,不等式()2f x m -<恒成立,求实数m 的取值范围.22．在函数定义域内,若存在区间[]m n ，,使得函数值域为[]m k n k ++，,则称此函数为“k 档类正方形函数”,已知函数()()3log 29132x xf x k k k ⎡⎤=⋅--++⎣⎦.(1)当0k=时,求函数()y f x =的值域;(2)若函数()y f x =的最大值是1,求实数k 的值;(3)当0x >时,是否存在()01k ∈，,使得函数()f x 为“1档类正方形函数”?若存在,求出实数k 的取值范围,若不存在,请说明理由.解析宁波市九校2019-2020学年上学期期末联考高一数学试卷一、单选题 1．已知集合{}0A x x =>,集合{}16B x x =-<≤,则A B =I( )A ．()10-， B ．(]06，C ．()06， D ．(]16-， 【答案】B【解析】进行交集的运算即可.解：∵{}0A x x =>，{}16B x x =-<≤，∴(]06A B =I ，. 故选：B.【点睛】本题考查交集的定义及运算，属于基础题.2．函数tan 43y x x ππ⎛⎫=-<< ⎪⎝⎭的值域是( )A ．()11-，B ．⎛ ⎝⎭- C ．(-D ．⎡-⎣【答案】C【解析】先判断出函数tan y x =在,43ππ⎛⎫- ⎪⎝⎭单调递增，分别求出特殊值，再写出函数的值域即可.【详解】解：因为函数tan y x =在,43ππ⎛⎫- ⎪⎝⎭单调递增，且tan tan 134ππ⎛⎫=-=- ⎪⎝⎭，则所求的函数的值域是(-. 故选：C.【点睛】本题考查正切函数的单调性，以及特殊角的正切值，属于基础题. 3．已知∈，x y R ,且0x y >>,则( ) A ．110x y-> B ．cos cos 0x y ->C ．11022xy⎛⎫⎛⎫-< ⎪ ⎪⎝⎭⎝⎭D ．ln ln 0x y +>【答案】C【解析】利用不等式的基本性质、函数的单调性即可判断出结论. 【详解】解：0x y >>，则11x y <，即110x y->，故A 错误； 函数cos y x =在()0,∞+上不是单调函数，故cos cos 0x y ->不一定成立，故B 错误；函数12xy ⎛⎫= ⎪⎝⎭在()0,∞+上是单调减函数，则1122x y⎛⎫⎛⎫< ⎪ ⎪⎝⎭⎝⎭，故C 正确；当11,x y e==时，ln ln 10x y +=-<，故D 错误. 故选：C. 【点睛】本题考查了不等式的基本性质、函数的单调性，考查了推理能力与计算能力，属于基础题.4．已知向量122a ⎛⎫= ⎪ ⎪⎝⎭r ，,2b =r ,且a b ⋅=r r 则a r 与b r的夹角为( ) A ．6πB ．2π C ．4π D ．3π 【答案】A【解析】分别求出向量的模长，代入向量的数量积即可求解，注意夹角的范围. 【详解】解：设a r 与b r的夹角为θ,122a ⎛⎫= ⎪ ⎪⎝⎭r Q ，，1a ∴=r ,||||cos cos a b a b θθ∴⋅=⨯==r r r r ,[0,]θπ∈Q ,6πθ∴=.故选：A.【点睛】本题考查向量的数量积及其夹角，是基础题.5．已知半径为2的扇形AOB 中,»AB 的长为3π,扇形的面积为ω,圆心角AOB 的大小为ϕ弧度,函数()sin h x x x πϕω⎛⎫=+ ⎪⎝⎭,则下列结论正确的是( )A ．函数()h x 是奇函数B ．函数()h x 在区间[]20π-，上是增函数 C ．函数()hx 图象关于()30π，对称 D ．函数()hx 图象关于直线3x π=-对称【答案】D【解析】先通过扇形的弧长和面积公式表示出ω和ϕ，并代入函数()h x 的解析式，整理得1()cos 3h x x =-，再结合余弦函数的图象与性质逐一判断每个选项的正误即可. 【详解】解：∵扇形弧长¶323,2AB ϕπϕπ==∴=， 又∵扇形面积13232ωππ=⋅⋅=， 31()sin sin cos 323h x x x x ππϕπωπ⎛⎫⎛⎫∴=+=+=- ⎪ ⎪⎝⎭⎝⎭，对于A 选项，函数()h x 为偶函数，即A 错误；对于B 选项，令1[2,2],3x k k k Z πππ∈+∈，则[6,36],x k k k Z πππ∈+∈， 而[2,0][6,36],k k k Z ππππ-+∈Ú，即B 错误； 对于C 选项，令1,32x k k Z ππ=+∈，则33,2x k k Z ππ=+∈， ∴函数的对称中心为33,0,2k k Z ππ⎛⎫+∈ ⎪⎝⎭，即C 错误； 对于D 选项，令1,3x k k Z π=∈，则3,k x k Z π=∈， ∴函数的对称轴为3,k x k Z π=∈，当1k =-时，有3x π=-，即D 正确.故选：D. 【点睛】本题考查了扇形的弧长和面积公式，余弦函数的奇偶性、单调性和对称性，属于基础题. 6．已知7log 2a =，0.7log 0.2b =，0.20.7c =，则a ，b ，c 的大小关系为（ ）A ．a c b <<B ．a b c <<C ．b c a <<D ．c a b <<【答案】A【解析】771log 2log 2<= ，0.70.7log 0.2log 0.71>=，0.20.70.71<<，再比较,,a b c 的大小.【详解】71log 22a =<，0.70.7log 0.2log 0.71b =>=，0.20.70.71c <=<，a c b <<，故选A. 【点睛】本题考查了指对数比较大小，属于简单题型，同底的对数，指数可利用单调性比较大小，同指数不同底数，按照幂函数的单调性比较大小，或是和中间值比较大小.7．已知4个函数:①sin y x x =;②cos y x x =;③2=x x y e;④4cos xy x e =-的图象如图所示,但是图象顺序被打乱,则按照图象从左到右的顺序,对应的函数序号正确的为( )A ．①④②③B ．③②④①C ．①④③②D ．③①④②【答案】B【解析】分别判断函数的奇偶性，对称性，利用函数值的特点进行判断即可. 【详解】 解：①sin y x x =是奇函数，图象关于原点对称；当0x >时，0y ≥恒成立；②cosy x x =是奇函数，图象关于原点对称；③2=xx y e为非奇非偶函数，图象关于原点和y 轴不对称，且0y ≥恒成立； ④4cos xy x e =-是偶函数，图象关于y 轴对称；则第一个图象为③，第三个图象为④，第四个图象为①，第二个图象为②. 即对应函数序号为③②④①. 故选：B. 【点睛】本题主要考查函数图象的识别和判断，利用函数的奇偶性和对称性是解决本题的关键，难度不大.8．在ABC V 中,102BA AC AC BC BC BA AB BC BC BA ⋅⋅+=⋅=u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r ，,则ABC V 为( ) A ．直角三角形 B ．三边均不相等的三角形 C ．等边三角形D ．等腰非等边三角形【答案】C【解析】直接代入数量积的计算公式第一个条件求出A C =，第二个条件得到B 即可求出结论. 【详解】解：因为在ABC V 中，,,(0,)A B C π∈10,2||||||||BA AC AC BC BC BA AB BC BC BA ⋅⋅+=⋅=u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r u u u r ， ||||cos ||||cos 0||cos ||cos 0||||AB AC A CA CB CCA A AC C AB BC -⨯⨯⨯⨯∴+=⇒-=u u u u r u u u r u u u r u u u ru u u r u u u r u u u r u u u r cos cos A C A C ∴=⇒=，11||||cos ||||cos 223BC BA BC BA B BC BA B B π⋅=⨯⨯=⨯⇒=⇒=u u u r u u u r u u u r u u u r u u u r u u u r Q ，∴ABC V 为等边三角形.故选：C. 【点睛】本题考查了数量积运算性质以及特殊角的三角函数值，考查了推理能力与计算能力，属于中档题. 9．若()()()()2202022020log 2019log 2log 2019log 2xyy x--+<+,则( )A ．0x y +<B ．0x y +>C ．0x y -<D ．0x y ->【答案】A【解析】令，然后结合函数的单调性即可判断. 【详解】解：结合已知不等式的特点，考虑构造函数,令()()22()log 2019log 2020x xf x -=-，则易得()f x 在R 上单调递增，()()()()2202022020log 2019log 2log 2019log 2yxy x--+<-Q ，()()()()2222log 2019log 2020log 2019log 2020x x y y--∴-<-，即()()f x f y <-，所以x y <-， 故0x y +<. 故选：A. 【点睛】本题主要考查了利用函数的单调性比较大小，解题的关键是由已知不等式的特点构造函数.10．设函数()()(]()1222112f x x f x x x ⎧+∈-∞-⎪=⎨⎪+-∈-+∞⎩，，，，,则方程()()21610f x x x ++-=根的个数为( )A ．2B ．3C ．4D ．5【答案】C【解析】方程()()21610fx x x ++-=根的个数等价于函数()f x 与函数()21()116g x x x =-+-的交点个数，画出两个函数的大致图象，观察交点个数即可. 【详解】 解：方程()()21610fx x x ++-=根的个数等价于函数()f x 与函数()21()116g x x x =-+-的交点个数，画出两个函数的大致图象，如图所示：1(0)(0)016g f =>=Q ， ∴在(0,)+∞内有1个交点，191(5)(5)164g f -=-<-=-Q ，51(3)(3)162g f -=->-=-， 11(2)(2)0,(1)(1)1616g f g f -=-<-=-=>-， ∴两个函数在(,0)-∞内有3个交点，综上所述，函数()f x 与函数()g x 共有4个交点，所以方程()()21610f x x x ++-=根的个数是4个，故选：C. 【点睛】本题主要考查了函数与方程的关系，关键是要画出函数图像，并且确定关键点的高低，是一道难度较大的题目.二、填空题11．已知函数()()1lg 31x f x x +=+,则()0f =____________函数定义域是____________. 【答案】2 113⎛⎫- ⎪⎝⎭，【解析】直接在函数解析式中取0x =求得()0f ；由对数式的真数大于0，分母中根式内部的代数式大于0联立不等式组求解函数定义域.【详解】解：由()()1lg 31x f x x +=++，得(0)lg12f ==； 由10310x x ->⎧⎨+>⎩，解得113-<<x ，∴函数定义域是113⎛⎫- ⎪⎝⎭，. 故答案为：2；113⎛⎫- ⎪⎝⎭，. 【点睛】本题考查函数的定义域及其求法，是基础的计算题.12．已知12e e u r u u r ，是单位向量,12e e ⊥u r u u r ,122AB e e =+u u u r u r u u r ,123BC e e =-+u u u r u r u u r ,12CD e e λ=-u u u r u r u u r ,若AB CD ⊥uu u r uu u r,则实数λ=____________;若A B D ，，三点共线,则实数λ=____________.【答案】125 【解析】利用向量垂直和向量平行的性质直接求解. 【详解】解：由已知可得1212(2)()210AB CD e e e e λλ⋅=+⋅-=-=u u u r u u u r u r u u r u r u u r，解得实数12λ=；∵A B D ，，三点共线，又()12122,12AB e e BD BC CD e e λ=+=+=-+u u u r u r u u r u u u r u u u r u u u r u r u u r ，2112λ∴=- 解得实数5λ=. 故答案为：12；5.【点睛】本题考查实数值的求法，考查向量垂直和向量平行的性质等基础知识，考查运算求解能力，是基础题. 13．己知函数()()2tan 06f x a x a ππ⎛⎫=+> ⎪⎝⎭的最小正周期是3.则a =___________()f x 的对称中心为____________. 【答案】13 31022k k Z ⎛⎫-∈ ⎪⎝⎭，， 【解析】根据正切的周期求出a ，利用整体法求出对称中心即可. 【详解】解：函数()()2tan 06f x a x a ππ⎛⎫=+> ⎪⎝⎭的最小正周期是3， 则3a ππ=，得13a =， 所以函数1()2tan 36f x x ππ⎛⎫=+ ⎪⎝⎭，由11,362x k k Z πππ+=∈，得3122x k =-，k Z ∈， 故对称中心为31022k k Z ⎛⎫-∈ ⎪⎝⎭，，. 故答案为：13；31022k k Z ⎛⎫-∈ ⎪⎝⎭，，. 【点睛】考查正切函数的周期，正切函数的对称性，基础题.14．已知a b R ∈，,定义运算“⊗”:a a b a b b a b ≥⎧⊗⎨<⎩，，,设函数()()()2221log xf x x =⊗-⊗,()02x ∈，,则()1f =___________;()f x 的值域为__________.【答案】1[)13， 【解析】由所给的函数定义求出分段函数()f x 的解析式，进而求出结果.【详解】解：由题意1(0,1]()?21(1,2)xx f x x ∈⎧=⎨-∈⎩ 所以(1)1,f = 当(1,2)x ∈时，()f x 是单调递增函数，则()(1,3)f x ∈，则()f x 的值域为[)13，.故答案分别为：1；[)13，. 【点睛】考查分段函数的解析式及函数的值域，属于基础题. 15．已知函数()()29a f x m x =-为幂函数,且其图象过点(3,则函数()()2log 6a g x x mx =-+的单调递增区间为___________. 【答案】()2-∞，【解析】根据函数()f x 是幂函数求出m 的值，再根据()f x 的图象过点(3，求出a 的值；由此得出函数()gx 的解析式，根据复合函数的单调性：同增异减，求出()g x 的单调递增区间.【详解】 解：函数函数()()29a f x m x =-为幂函数，291m -=，解得5m =，且其图象过点(3，所以3a =，解得12a =， 所以函数()()2log 6a g x x mx =-+即函数()()212log 56g x x x =-+， 令2560x x -+>，解得2x <或3x >,所以函数()g x 的单调递增区间为()2-∞，. 故答案为：()2-∞，. 【点睛】本题考查了函数的定义与性质的应用问题，复合函数的单调性的判断，是基础题.16．已知a b c r r r ，，，是平面向量,且2c =r ,若24a c b c ⋅=⋅=r r r r，,则a b +r r 的取值范围是__________.【答案】[)3+∞，【解析】先根据()6a b c a c b c +⋅=⋅+⋅=r r r r r r r得到cos 3a b θ⨯=+r r ；进而表示出a b +r r 即可求解.【详解】解：设a b +rr与c r的夹角为θ，()6||||cos a b c a c b c a b c θ+⋅=⋅+⋅==+⨯⨯r r r r r r r r r rQ ， ||cos 3a b θ∴+⨯=rr ，0cos 1θ∴<≤，3||3cos a b θ+=≥rr .故答案为：[3,)+∞. 【点睛】本题主要考察平面向量的数量积以及三角函数的性质应用，属于基础题. 17．函数()()25sin f x x g x x =--=，,若1202n x x x π⎡⎤∈⎢⎥⎣⎦，，……，，,使得()()12f x f x ++…()()()()()()1121n n n n f x g x g x g x g x f x --++=++++…,则正整数n 的最大值为___________.【答案】6【解析】由题意可得()()sin 52g x f x x x -=++，由正弦函数和一次函数的单调性可得()()2sin 5g x f x x x --=+的范围是50,12π⎡⎤+⎢⎥⎣⎦，将已知等式整理变形，结合不等式的性质，可得所求最大值n .【详解】解：函数()25=--f x x ，()sin g x x =，可得()()sin 52g x f x x x -=++，由0,2x π⎡⎤∈⎢⎥⎣⎦，可得sin ,5y x y x ==递增， 则()()2sin 5g x f x x x --=+的范围是50,12π⎡⎤+⎢⎥⎣⎦，()()()()()()()()121121n n n n f x f x f x g x g x g x g x f x --++++=++++……，即为()()()()(()()()112211)n n n n g x f x g x f x g x f x g x f x --⎡⎤⎡⎤⎡⎤-+-+⋯+-=-⎣⎦⎣⎦⎣⎦， 即()()()112211sin 5sin 5sin 52(1)sin 52n n n n x x x x x x n x x --++++⋯+++-=++，即()()(112211sin 5sin 5sin 5)2(2)sin 5n n n n x x x x x x n x x --++++⋯+++-=+，由5sin 50,12n n x x π⎡⎤+∈+⎢⎥⎣⎦，可得52(2)12n π-≤+， 即5524n π≤+，而55(6,7)24π+∈， 可得n 的最大值为6. 故答案为：6. 【点睛】本题考查函数的单调性和应用，考查转化思想和运算能力、推理能力，属于中档题.三、解答题18．已知向量()()()sin 1cos 10a x b x c m =-=r r r ，，=，，，,其中04x π⎡⎤∈⎢⎥⎣⎦，.(1)若的35a b ⋅=-r r ,求tan x 的值;(2)若a c +r r 与a c -r r垂直,求实数m 的取值范围.【答案】(1)12;(2) 11⎡⎤⎡-⋃⎢⎥⎢⎣⎦⎣⎦. 【解析】(1)根据平面向量的数量积列方程求出tan x 的值，再根据x 的范围确定tan x 的值；(2)根据平面向量的数量积和模长公式求出m 的解析式，再求m 的取值范围.(1)因为3sin cos 15a b x x ⋅=⋅-=-r r ,即2sin cos 5x x ⋅=, 所以222sin cos tan 2sin cos tan 15x x x x x x ⋅==++, 所以22tan 5tan 20x x -+=,即tan 2x =或1tan 2x =. 因为04x π⎡⎤∈⎢⎥⎣⎦，,所以[]tan 01x ∈，,即1tan 2x =；(2)因为a c +r r 与a c -r r垂直,()()220a c a c a c ∴+⋅-=-=r r r r r r ，a c ∴=r r ,所以221sin m x =+,因为04x π⎡⎤∈⎢⎥⎣⎦，,所以2231sin 12m x ⎡⎤=+∈⎢⎥⎣⎦，,即11m ⎡⎤⎡∈-⋃⎢⎥⎢⎣⎦⎣⎦. 【点睛】本题考查了平面向量的数量积与模长应用问题，也考查了三角函数的应用问题，是中档题.19．已知集合{()121A x y B a a ===-+，，,()(){}110C x x m x m m R =--++≤∈，.(1)若()RA B =∅Ið,求a 的取值范围;(2)若A C C =I ,求m 的取值范围.【答案】(1)20a -<≤;(2)20m -≤≤【解析】（1）可以求出[]31A =-，，从而可得出A R ð，根据()RA B =∅Ið得121a a -<+，并且13211a a -≥-⎧⎨+≤⎩，解出a 的范围即可； （2）根据A C C =I 即可得出C A ⊆，然后可讨论1m +与1m --大小关系，从而得出集合C ，根据C A ⊆即可得出m 的范围.(1)因为{[]31A x y ===-，,所以()()31,R A =-∞-+∞U ，ð, 因为()121B a a =-+，,即121a a -<+.即2a >-, 由()RA B =∅Ið得,13211a a -≥-⎧⎨+≤⎩,解得20a -≤≤, 所以20a -<≤； (2)因为A C C =I,即C A ⊆,[]()(){}31|110A C x x m x m =-=--++≤，，,①11m m +≤--时,即1m ≤-时,{}11C x m x m m R =+≤≤--∈，, C A ⊆,所以1311m m +≥-⎧⎨--≤⎩,解得2m -≤,所以21m -≤≤-.②11m m +>--时,即1m >-时,{}11C x m x m m R =--≤≤+∈，, C A ⊆,所以1113m m +≤⎧⎨--≥-⎩,解得0m ≤,所以10m -<≤. 综上所述:20m -≤≤. 【点睛】本题考查了描述法、区间的定义，一元二次不等式的解法，补集、交集的定义及运算，子集的定义，分类讨论的思想，考查了计算能力，属于基础题. 20．已知()f x 为偶函数,当0x ≥时,()()2lg 1f x x =+.(1)求()f x 的解析式;(2)若对于任意的()0x ∈-∞，,关于x 的不等式()()lg kx f x <恒成立,求k 的取值范围.【答案】(1)()()()2lg 102lg 10x x f x x x ⎧-+<⎪=⎨+≥⎪⎩，，;(2)40k -<<.【解析】（1）设0x <，则0x ->，()()()2lg 1f x f x x =-=-+，再求出()f x 的解析式；（2）当0x <时，因为0kx >，所以k 0<，结合分离参数法求出k 的范围.【详解】(1)设0x <,则0x ->,()()()2lg 1f x f x x =-=-+,所以()()()2lg 102lg 10x x f x x x ⎧-+<⎪=⎨+≥⎪⎩，，；(2)当0x <时,因为0kx >,所以k 0<, 所以()()lg2lg 1kx x <-+,即()()2lg lg 1kx x <-+,即()21kx x <-+.因为0x <,所以()2112x k x xx-+>=+-恒成立,当0x <时,1224x x +-≤-=-最大值为-4,所以4k >-, 所以40k -<<.【点睛】本题考查分段函数求解析式，函数求含参恒成立问题，转化为最值问题即可，中档题. 21．已知函数()sin 26f x x π⎛⎫+ ⎝=⎪⎭,()()sin 002g x A x A πωϕωϕ⎛⎫=+>>< ⎪⎝⎭，，的部分图象如图所示.(1)求()gx 的解析式,并说明()f x 的图象怎样经过2次变换得到()g x 的图象;(2)若对于任意的46x ππ⎡⎤∈-⎢⎥⎣⎦，,不等式()2f x m -<恒成立,求实数m 的取值范围. 【答案】(1)()1sin 23g x x π⎛⎫=+ ⎪⎝⎭,变换见解析;(2)12⎛- ⎝⎭，. 【解析】（1）先根据图象求出()g x 的解析式；再结合图象变化规律说明()f x 的图象怎样经过2次变换得到()gx 的图象；（2）先结合正弦函数的性质求出()f x 的范围；再结合恒成立问题即可求解.【详解】(1)由图得112A ω==，, 因为203π⎛⎫-⎪⎝⎭，为函数递增区间上的零点,所以21232k k Z πϕπ-⋅+=∈，,即23k k Z πϕπ=+∈，. 因为2πϕ<,所以3πϕ=,即()1sin 23g x x π⎛⎫=+⎪⎝⎭，将函数()f x 的图象上所有点的横坐标伸长到原来的4倍(纵坐标不变),再将所得图象向左平移3π个单位长度可得()gx ；(2)因为46x ππ⎡⎤∈-⎢⎥⎣⎦，,所以2632x πππ⎡⎤+∈-⎢⎥⎣⎦，,所以当263x ππ+=-时,()f x取最小值,当262x ππ+=时,()f x 取最大值1,因为()2f x m -<恒成立,即()22m f x m -+<<+恒成立,所以212m m ⎧-+<⎪⎨⎪<+⎩即122m ⎛∈-- ⎝⎭，. 【点睛】本题主要考查由函数sin()y A x ωϕ=+的部分图象求解析式，诱导公式，函数sin()y A x ωϕ=+的图象变换规律，以及恒成立问题，属于中档题. 22．在函数定义域内,若存在区间[]m n ，,使得函数值域为[]m k n k ++，,则称此函数为“k 档类正方形函数”,已知函数()()3log 29132x xf x k k k ⎡⎤=⋅--++⎣⎦.(1)当0k=时,求函数()y f x =的值域;(2)若函数()y f x =的最大值是1,求实数k 的值;(3)当0x >时,是否存在()01k ∈，,使得函数()f x 为“1档类正方形函数”?若存在,求出实数k 的取值范围,若不存在,请说明理由. 【答案】(1)()3log 2+∞，;(2)1k =或17k =-;(3)存在,207k <<. 【解析】（1）根据指数函数的性质和对数函数想性质可得到函数()y f x =的值域；（2）利用换元法设30x t t =>，，然后对参数k 进行分类讨论，分0k ≥和k 0<两种情况进行讨论函数()g t 的最大值，根据最大值取得的情况计算出k 的取值；（3）继续利用换元法设30x t t =>，，设真数为()()2212g t k t k t k =⋅--++，根据二次函数的性质可得()f x 在()1+∞，上为增函数，则()()()()min max f x f m f x f n ==，，将问题转化为方程()3log 291321x xk k k x ⎡⎤⋅--++=+⎣⎦在()0+∞，上有两个不同实根进行思考，再次利用换元法转化为一元二次方程，根据>0∆，及韦达定理可计算出实数k 的取值范围. 【详解】 (1)0k=时,()()3log 32xf x =+,因为322x +>. 所以()()33log 32log 2x f x =+>,所以函数()y f x =的值域为()3log 2+∞，(2)设30x t t =>，,则()()23log 212f t k t k t k ⎡⎤=⋅--++⎣⎦,若0k ≥,则函数()()2212g t k t k t k =⋅--++无最大值,即()f t 无最大值,不合题意;故k 0<,因此()()2212gt k t k t k =⋅--++最大值在104k t k-=>时取到, 且114k f k -⎛⎫= ⎪⎝⎭,所以()211212344k k k k k k k --⎛⎫--++= ⎪⎝⎭, 解得1k=或17k =-,由k 0<,所以17k =-.(3)因为01k <<时,设()31x t t =>.设真数为()()2212g t k t k t k =⋅--++.此时对称轴104k t k-=<, 所以当1t >时,()g t 为增函数,且()()1230g t g k >=+>,即()f x 在()1+∞，上为增函数.所以,()()()()min max 11f x f m m f x f n n ==+==+，,即方程()3log 291321xx k k k x ⎡⎤⋅--++=+⎣⎦在()0+∞，上有两个不同实根,即()1291323xx x k k k -⋅--++=,设()31x t t =>.所以()22123k tk t k t ⋅--++=.即方程()22220k t k t k ⋅-+++=有两个大于l 的不等实根,因为01k<<,所以()()()228202142220k k k k k k k k ⎧∆=+-+>⎪+⎪>⎨⎪-+++>⎪⎩, 解得207k<<, 即存在m n ，,使得函数()f x 为“1档类正方形函数”,且207k <<.【点睛】本题主要考查函数的值域问题，最值问题，考查了换元法的应用，分类讨论思想和转化思想的应用，不等式的计算能力，本题属综合性较强的中档题.。
精品解析：浙江省宁波市九校2019-2020学年高一上期期末英语试题(解析版)
2019学年第一学期宁波市九校联考高一英语试题选择题部分第一部分听力（共两节，满分30 分）第一节（共5 小题；每小题1.5 分，满分7.5 分）听下面5 段对话。
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听完每段对话后，你都有10 秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What color are Julie’s shoes?A. Black.B. Brown.C. Dark blue.2. Who dies in the story?A. The dragon.B. The soldier.C. The princess.3. Which animal is in the field?A. A sheep.B. A cow.C. A horse.4. What is the woman going to do this evening?A. Go on a trip.B. Attend a concert.C. Look after her brother.5. What is the homework for next Tuesday?A.Writing an essay.B. Reading the textbook.C. Listening to some radio programs. 第二节（共15小题；每小题1.5 分，满分22.5 分）听下面5 段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5 秒钟；听完后，各小题将给出5 秒钟的作答时间。
每段对话或独白读两遍。
听第6 段材料，回答第6、7 题。
6. How long will school be canceled according to Martin?A. For three days.B. For six days.C. For seven days.7. What do the speakers want to do tomorrow?A. Visit their friends.B. Skate on a pond.C. Make a snowman with their father.听第7段材料，回答第8至10题。
2018-2019学年浙江省宁波市九校联考高一(上)期末英语试卷-解析版
2018-2019学年浙江省宁波市九校联考高一（上）期末英语试卷一、阅读理解（本大题共10小题，共25.0分）AI was used to carrying a penknife in my pocket，and over the years I moved up in size from a small single knife to a Swiss Army knife and then eventually to a Leatherman multi-tool （多刃刀具）．This wasn't a problem for many years．However，after the 9/11，the world changed．I was traveling from JFK to LAX，so I took the knife out of my pocket and put it in my bag．But when I got to the airport，I had completely forgotten about it，so I just quickly went through safety check．This was not long after 9/11，so safety check was extremely strict．But somehow，the X-ray screener missed the knife in the bag，and I walked on through．I was sitting in the gate area waiting for boarding，when I noticed a second security screening process right next to the gate，with another X-ray machine and what looked like anti-terrorist soldiers．I suddenly remembered that I had this knife in my bag!I really didn't know what I should do．If I did nothing and they caught the knife during the second security screening，I'd be dead；if I told them I accidentally got the knife through the first screening，they would certainly re-screen every passenger on the plane；if I dropped it in a garbage can，it would be found by a cleaner in a secure area （警戒区），and probably result in something scary! I was anxious and like a cat on hot bricks．Suddenly，I noticed a skycap，someone whose job is to carrypassengers' bags at an airport．I had an idea．I then began to ask every skycap I saw，"Hey，how would you like a ﹩60multi-tool as a present"Finally，a guy looking happy but confused took it off my hands．I then went through the second safety check with no knife．1.The author carried a knife in his pocket ______ ．A. out of habitB. B．as a presentC. out of self-protectionD. as a souvenir （纪念品）2.In the end，how did the author deal with the knife？______A. He put it in the bag．B. He gave it to others．C. He threw it away secretly．D. He handed it to a policeman．3.The passage is mainly about ______ ．A. the history of penknivesB. the strict safety check in JFKC. a meaningful gift from the airportD. an embarrassing experience in the airportBNovember 11th，also known as the "bare sticks holiday"，and a day originally meant for young people to celebrate being single，has become the world's largest 24-hour online shopping carnival．Forum （论坛）readers share their opinions．Blonde Amber （Ireland）There is nothing to be proud of to be in a country that spends so much online on a particular day．It does nothing more than show the superficiality （肤浅）of the temporary pleasure of shopping，and produces nothing more than a mountain of environmental waste．I bet there is plenty of "buyers' remorse" after this day．Vivian （US）Since it is Singles' Day，I guess only the single population of China should buy something to relieve social pressure．The married might be excluded （排除）from the festival．Alex （US）Singles' Day was initiated （创始）by a group of college students to celebrate being single，or not having a girlfriend or boyfriend．They think poor guys should buy something on the day to entertain themselves．But Jack Ma got hold of the opportunity，hit the jackpot and successfully made it a yearly shopping spree （狂欢）．George （Canada）I work in Shanghai．Many of my young female colleagues are still single．They simply haven't time to date，as they tend to work long hours and travel two hours by subway to get to and from work．Singles' Day is a day when they spoil themselves with online shopping．Patrick （Australia）I don't care if it is Singles' Day or a shopping spree．It sounds fair enough to me．Just a click and I can get the best deals I have ever seen delivered to my door，and save money and time．4.What does the underlined word "remorse" in Paragraph 2 mean？______A. Surprise．B. Joy．C. Regret．D. Excitement．5.What's the best title for the passage？______A. To Buy or Not to Buy？B. A Global Shopping SpreeC. Jack Ma and the Double ElevenD. Singles' Day or Shopping Spree？6.Where can we most probably find this passage？______A. From a taxtbook．B. From a poster．C. From a website．D. From an advertisement．CRobyn Rihanna Fenty has rocked the entertainment world with her contributions to pop music．She was born on February 20，1988，in Saint Michael，Barbados．In her early teens，Rihanna was greatly inspired by reggae （雷盖音乐）singer Bob Marley and pop singer Madonna．She was lucky enough to get her first opportunity at the age of 15，when her friend introduced her to an experienced music composer Evan Rogers from New York．Rihanna moved to US to start a career in music，and recorded under the guidance of Rogers and his partner Carl Sturken．Later，Shane Carter recognized her talent and had her sign a contract with Def Jam Recordings．Rihanna has been musically influenced by famous artists，such as Beyonce Knowles，Madonna，Mariah Carey，Alicia Keys，and Bob Marley．In 2005，Rihanna released her debut album （首张专辑）"Music of the Sun''，which included the single hit "Pon de Replay"．This single broke all records and peaked at No．2 on the US Billboard Hot 100 charts，as well as the UK charts．Her second single "If It's Lovin' That You Want" was at No．36 on the Billboard Hot 100 charts，and No．11 on the UK charts．Rihanna released her second album，"A Girl Like Me" in 2006，which included the hit song and lead single "S．O．S" （Rescue Me）．This single peaked at the number one position on the Billboard Hot 100．In 2006，Rihanna also tried her luck in films，and made her acting debut playing a role in "Bring It On：All or Nothing"．The next year，she released her third album "Good Girl Gone Bad''，which had hit tracks like "Umbrella"，"Hate That I Love You"，and "Don't Stop the Music''，among others．In the same year，at the MTV Video Music Awards，Rihanna won two awards for the hit single "Umbrella"．In 2008，Rihanna won her first Grammy Award for her hit single "Umbrella"．So far，Rihanna has won 45awards in various categories．7.What plays an important role in Rihanna's success？______A. The support of her friends．B. The encouragement of her family．C. The education she received at school．D. The help and influence of successful musicians．8.What happened to Rihanna when she was eighteen years old？______A. She started a career in music．B. She began to act in films．A．She began to release albums．D．She won her first Grammy Award．9.What do we know about Rihanna's second single "If It's Lovin' That You Want"？______A. It was released in 2006．B. It was included in her third album．C. It was not as successful as her first single．D. It was more successful than her third single．10.Which song earned rewards for Rihanna for two years in a row？______A. Umbrella．B. Pon de Replay．C. Hate That I Love You．D. Don't Stop the Music．二、阅读七选五（本大题共5小题，共10.0分）Many students have already chosen whether or not to apply for Early Decision （ED）．The official deadline for most colleges and universities with an ED application is Nov 1st at 11：59 p．m．Early Decision has risks．(1) However，ED comes with some nice perks （好处）．The two biggest advantages are：1．Early notification （通知）．Students apply early and are notified early - usually by December 15．2．A boost （提高）in acceptance．With just a little bit of research，you can find out the acceptance rate for students who apply normally and those who apply through ED．You might be surprised．(2)What questions do you need to ask before you make the ED choice？First，consider academic fit．Are you satisfied with the amount of research you've done to make a four-year commitment （承诺）to this school？Have you spent enough time on die college's website to understand the academic offerings？(3) Do you think you'd struggle to keep up with the other students in class(4) Are you sure you'll like the climate？Is it the right size （not too big，not too small）？Is the emphasis on sports，arts，culture，etc．right for you？Do you like the surrounding area？Is it enough to keep you entertained，or is it too overwhelming （难应付的）？(5) If you apply for Early Decision and are accepted，will you be able to attend if you are not offered any financial aid？If the answer is "no" then you probably should reconsider applying through ED，because you will need to withdraw （撤回）your other applications if you are accepted．A．Look at the social fit，too．B．Also look at your finances．C．Turn to your teachers for advice，too．D．Do you think you're competitive academically？E．Are you sure you can adapt to the new surroundings？F．ED acceptance rates at some schools can be twice as high as the regular acceptance rates．G．It means the student has agreed that if he or she is accepted to a school，he or she must attend it．11. A. A B. B C. C D. D E. E F. F G. G12. A. A B. B C. C D. D E. E F. F G. G13. A. A B. B C. C D. D E. E F. F G. G14. A. A B. B C. C D. D E. E F. F G. G15. A. A B. B C. C D. D E. E F. F G. G三、完形填空（本大题共20小题，共30.0分）Four months into her pregnancy （孕期），my mother learned that my brother would be born with Down syndrome （唐氏综合症）．Never having dealt with anyone with the disease，the entire family began to (16)．Would he learn to walk and talk(17)like the other kids？Would he be liked by others？Would he have some(18)？All these thoughts and every detail (19)us，though we knew we would (20)him exactly the way he is．Thankfully，after birth，Lipe was (21)than we expected，with no heart problems in general connected with Down syndrome．He is the most (22)person I have ever met．Anything is a reason for him to flash a smile．Even if it took him some extra(23)to learn new things，he always did extremely well．Although we were glad to see that，we still(24)what others would say about him．In order to (25)him．I kept his condition a secret．I was also afraid of being treated (26)by others because of his condition．But I soon realized(27)I truly loved him，I shouldn't be (28)of him．The first time I told a friend about Lipe's disease，she just reminded me that all that my brother needed was my love and (29)．It was my friend's understanding that (30)me to be proud of Lipe．Because of my brother，I have learned the meaning of(31)．Before his birth，if I saw someone who acted or looked differently，I simply thought it to be (32)and started laughing．I am now glad that I have changed in these ways．I now consider what they could possibly be (33)in life，and the many reasons why they could be behaving like that．We may live in a world in which the society coldly (34)every inch of you，but we can at least treat others with (35)．Only in this way can we expect to createa better society．16. A. practice B. worry C. complain D. understand17. A. quickly B. easily C. quietly D. normally18. A. friends B. classmates C. teachers D. students19. A. left B. troubled C. helped D. inspired20. A. change B. shock C. accept D. remember21. A. younger B. happier C. calmer D. healthier22. A. curious B. cheerful C. suitable D. confident23. A. luck B. praise C. effort D. power24. A. gave up B. believed in C. learned from D. cared about25. A. care B. protect C. follow D. comfort26. A. badly B. excitedly C. seriously D. politely27. A. if B. although C. because D. unless28. A. proud B. afraid C. scared D. ashamed29. A. hope B. peace C. support D. interest30. A. made B. encouraged C. required D. attracted31. A. pride B. honesty C. patience D. respect32. A. poor B. troublesome C. strange D. difficult33. A. achieving B. choosing C. enjoying D. experiencing34. A. judges B. refuses C. improves D. discovers35. A. pleasure B. difference C. kindness D. determination四、语法填空（本大题共1小题，共15.0分）36.Do you judge people by their appearance？This week I was talking to some guys at Planet Fitness，(1) told me about their boss' experience of buying a new car．The salesmen didn't know that this man had a lot of money．It was because he often dressed (2) （he）in worn-out clothes，just like a homeless man on the street．When the boss arrived at the first shop，the salesmen (3) （total）ignored him and treated him like he wasn't worth their time．He (4) （leave）the shop with a smile on his face．Later that day，he walked into another shop，(5) （wear）the same clothes as usual．The salesmen greeted him with kindness andrespect．Then this man paid almost ﹩20 million (6) new car!There's a Bible text that tells us how (7) （treat）people that you learn little about．It says，"Don't forget to show (8) （warm）to strangers，because anyone who does it may entertain angels without realizing it!" Don't judge (9) book by its cover! The boss was not an angel (10) you never know who just might be．五、书面表达（本大题共2小题，共40.0分）37.假定你是李华，新落成的外文书店为增加访客量现向市民征求建议，请给书店经理Mr． Bowie 写一封建议信，内容包括：1．拥有宽敞的空间以提供良好的阅读体验；2．提供公益讲座（public lecture）等服务；3．其他建议（至少一条）．注意：1．词数80左右；2．可适当增加细节，以使行文连贯．38.It was a cold December day．After saying goodbye to his neighbor，David，Tom set out for a run with his dog，Taz．Asa professional athlete，Tom often went for training runs by himself，and had done this particular route many times before，but that day something unusual happened to him．About an hour later，Tom hit some black ice．He found himself slipping down the rock face，which became steeper and steeper （陡峭的）until suddenly he was in free fall．He fell 60 feet into the canyon （峡谷），landing on grass and dry branches．If he'd missed them，there was no way he would have survived．He could feel his legs，so he knew he wasn't paralyzed （瘫痪的），but he was in great pain．Taz had managed to find his way back to Tom，so Tom knew there must be a way out of the canyon，but he couldn't stand or even crawl （爬行）．He later learned that he had broken his pelvis （骨盆）．Tom shouted for help，and tried to pull himself forward．Every inch was an effort．It took him five hours to go a quarter of a mile．Eventually it got so dark that he couldn't see where he was going．He decided to stay next to a river which he could drink some water from．All he had on him were his jogging clothes，a water bottle，two boxes of medicine，a bar of chocolate，and a shower cap which adventure racers often wear to prevent heat loss．At night，the temperature dropped below freezing．Tom couldn't go to sleep or he would die，so he stayed awake lifting his head a few inches，over and over．Throughout the night，Taz curled up next to him and kept him company．The next morning，he couldn't move any more．He tried to stay positive．He was sure somebody would find he was missing or hear him screaming for help．But there was nobody around．注意：1．所续写短文的词数应为150左右；2．应使用5个以上短文中标有下划线的关键词语；3．续写部分分为两段，每段的开头语已为你写好；4．续写完成后，请用下划线标出你所使用的关键词语．Paragraph 1：As time went by， Tom felt himself growing weaker and he knew he must take action，__________Paragraph 2：About three hours later， Taz returned and Tom heard an engine in the distance．答案和解析1.【答案】【小题1】A 【小题2】B 【小题3】D【解析】1．A．细节理解题．根据第一段I was used to carrying a penknife in my pocket， and over the years I moved up in size from a small single kni fe to a Swiss Army knife and then eventually to a Leatherman multi-tool （多刃刀具）．可知，作者携带一把刀是出于习惯．故选A．2．B．细节理解题．根据最后一段Finally， a guy looking happy but confused took it off my hands．可知，作者最终把刀给了别人．故选B．3．D．主旨大意题．阅读全文，根据文章内容可知，本文主要讲述了我习惯随身携带一把刀，但是由于第一次安检没有检测到，在第二次安检前，我很焦虑，最终想了个办法，把刀给了机场行李搬运工，这是一个在机场的尴尬经历．故选D．本文主要讲述了我习惯随身携带一把刀，但是由于第一次安检没有检测到，在第二次安检前，我很焦虑，最终想了个办法，把刀给了机场行李搬运工．本文是一个人物故事类阅读理解，题目涉及多道细节理解题，做题时结合原文和题目有针对性的找出相关语句进行仔细分析，结合选项选出正确答案．推理判断题也是要在抓住关键句子的基础上合理的分析才能得出正确答案，切忌胡乱猜测，一定要做到有理有据．4.【答案】【小题1】C 【小题2】D 【小题3】C【解析】1．C．词义猜测题．根据前面的句子It does nothing more than show the superficiality （肤浅）of the temporary pleasure of shopping以及本句I bet…after this day说明，在双十一这一天的购物许多都是跟风，无任何意思，过了这天后就会后悔，所以由此推断remorse等同于regret；故选C．2．D．标题归纳题．根据本文的内容以及最后一段的I don't care if it is Singles' Day or a shopping spree． It sounds fair enough to me．可知，Singles' Day or a shopping spree作为文章的标题最合适，故选D．3．C．文章出处题．本文属于社会现象类的短文阅读．主要介绍了双十一作为传统的"单身节"已经演变成了购物节了，并且列举了一些网民的观点，所以应该是出自网站上的文章；故选C．本文属于社会现象类的短文阅读．主要介绍了双十一作为传统的"单身节"已经演变成了购物节了，并且列举了一些网民的观点．本文是一个人物故事类阅读理解，题目涉及多道细节理解题，做题时结合原文和题目有针对性的找出相关语句进行仔细分析，结合选项选出正确答案．推理判断题也是要在抓住关键句子的基础上合理的分析才能得出正确答案，切忌胡乱猜测，一定要做到有理有据．7.【答案】【小题1】D 【小题2】B 【小题3】C 【小题4】A【解析】1．D．细节理解题．根据文章第三段第一句Rihanna has been musically influenced by famous artists，such as Beyonce Knowles，Madonna，Mariah Carey，Alicia Keys，and Bob Marley 可知，Rihanna 在音乐上深受著名艺术家Beyonce Knowles，Madonna，Mariah Carey，Alicia Keys 和Bob Marley 的影响．故正确答案为D．2．B．细节理解题．根据文章第一段第二句She was born on February 20，1988，in Saint Michael，Barbados 可知，她在1988年出生，因此2006年时她18岁；又根据文章最后一段第一句In 2006，Rihanna also tried her luck in films 可知，在2006年，她拍摄了电影．故正确答案为B．3．C．推理判断题．A项，"它在2006年发行"．文中未提及．故A项错误．B项，"它被包含在她的第二个专辑里"．文中未提及．故B项错误．C项，"它不如她的第一首单曲成功"，根据文章第四段第一句Her second single "If it's Lovin That You Want" was at No．36 on the Billboard Hot 100 charts，and No．11 on the UK charts 可知，她的第二首单曲《If it's Lovin That You Want》在美国公告牌单曲榜排行36名，在英国排行11名．根据文章第三段最后一句This single broke all records and peaked（达到最高水平）atNo．2 on the US Billboard Hot 100 charts（排行榜），as well as the UK charts 可知，她的第一首单曲打破所有纪录，在美国公告牌百强单曲榜和英国排行榜上登顶．故C项正确．D项，"它比她的第三首单曲成功"，文章没有提及第三首单曲的排名，无法比较．故D项错误．故正确答案为C．4．A．细节理解题．根据文章最后一段第三句In the same year，at the MTV Video Music Awards，Rihanna won two awards for the hit single "Umbrella" 和文章最后一段倒数第二句In 2008，Rihanna won her first Grammy Award for her hit single "Umbrella" 可知，在2006年，Rihanna 因为她的单曲《Umbrella》得了两次奖；在2008年，因为这首单曲获得了格莱美奖．故正确答案为A．本文属于人物故事类的短文阅读．主要介绍了Robyn Rihanna Fenty在流行音乐界做出的巨大贡献，她的单曲及在电影方面的影响颇深．阅读理解考察学生的细节理解和推理判断能力，做细节理解题时一定要找到文章中的原句，和题干进行比较，再做出正确的选择．在做推理判断题不要以个人的主观想象代替文章的事实，要根据文章事实进行合乎逻辑的推理判断．11.【答案】【小题1】G 【小题2】F 【小题3】A 【小题4】E 【小题5】B【解析】1．G．考查上下文逻辑关系．根据上文Early Decision has risks早期决策有风险，可知这里是：It means the student has agreed that if he or she is accepted to a school， he or she must attend it．这意味着学生已经同意，如果他或她被学校录取，他或她必须参加．故选G．2．F．考查上下文逻辑关系．根据上文With just a little bit of research， you can find out the acceptance rate for students who apply normally and tho se who apply through ED．只要做一点调查，你就能知道那些申请正常的学生和那些通过教育部申请的学生的录取率．可知这里是：ED acceptance rates at some schools can be twice as high as the regular acceptance rates有些学校的教育入学率可能是正常入学率的两倍．故选F．3．A．考查上下文逻辑关系．根据上文consider academic fit．看看学习适应度．可知这里是：Look at the social fit， too看看社会适应度．故选A．4．E．考查上下文逻辑关系．根据下文Are you sure you'll like the climate？你确定喜欢这里的气候吗？可知这里是：Are you sure you can adapt to the new surroundings？你确定能适应新环境吗？故选E．5．B．考查上下文逻辑关系．根据下文If you apply for Early Decision and are accepted， will you be able to attend if you are not offered any financi al aid如果你申请提前决定并被接受，如果你没有得到任何经济援助，你能参加吗？可知这里是：Also look at your finances看看你的经济情况．故选B．许多学生已经选择是否申请早期决策（ED），文章介绍早期决策的好处．答题前先快速浏览一遍七个备选答案，先确定哪个选项适合放在文章的什么位置．通常有三个四个位置：标题，句首，句中，句尾．不同位置的句子有不同的特征．确定文章体裁，抓住文章结构．分析篇章结构，找出各段的主题句或主旨大意．16.【答案】【小题1】B 【小题2】D 【小题3】A 【小题4】B 【小题5】C【小题6】D 【小题7】B 【小题8】C 【小题9】D 【小题10】B【小题11】A 【小题12】A 【小题13】D 【小题14】C 【小题15】B【小题16】D 【小题17】C 【小题18】D 【小题19】A 【小题20】C【解析】1-20 BDABC DBCDB AADCB DCDAC1．B．动词的辨析，practice练习，worry担忧，complain抱怨，understand理解，从来没有人得过这种疾病，整个家庭开始担忧起来，故答案为B．2．D．副词的辨析，quickly迅速地，easily容易地，quietly安静地，normally正常地，他能像其他孩子那样正常地走路和说话吗，故答案为D．3．A．名词的辨析，friends朋友，classmates同学，teachers教师，students学生，他会有朋友吗，故答案为A．4．B．动词的辨析，left留下，troubled困扰，helped帮助，inspired鼓舞，所有的这些想法都让我们困扰，故答案为B．5．C．动词的辨析，change改变，shock震惊，accept接受，remember记住，我们知道无论他是什么样，我们都会接受他，故答案为C．6．D．形容词的辨析，younger更年轻的，happier更高兴的，calmer更冷静的，healthier更健康，根据下文的with no heart problems in general connected with Down syndrome可知，Lipe比我们想象中更健康，故答案为D．7．B．形容词的辨析，curious好奇的，cheerful欢呼的，suitable合适的，confident自信的，根据想下文的Anything is a reason for him to flash a smile可知，他是我见过的最高兴的人，故答案为B．8．C．名词的辨析，luck幸运，praise表扬，effort努力，power力量，即使他学习新事物需要付出更多的努力，故答案为C．9．D．短语的辨析，gave up放弃，believed in相信，learned from学习，cared about关心，我们仍然关系别人会怎么说他，故答案为D．10．B．动词的辨析，care关心，protect保护，follow跟随，comfort安慰，为了保护他，我把他的情况当成一个秘密，故答案为B．11．A．副词的辨析，badly不好地，excitedly兴奋地，seriously严重地，politely礼貌地，我也怕由于他的情况被别人不好地对待，故答案为A．12．A．连词的辨析，if如果，although尽管，because因为，unless除非，如果我是真地爱他，我不应该因他感到羞愧，故答案为A．13．D．形容词的辨析，proud自豪的，afraid害怕的，scared害怕的，ashamed羞愧的，如果我是真地爱他，我不应该因他感到羞愧，故答案为D．14．C．名词的辨析，hope希望，peace和平，support支持，interest兴趣，她提醒我弟弟需要的是我的爱和支持，故答案为C．15．B．动词的辨析，made使，encouraged鼓励，required要求，attracted吸引，是我朋友的理解鼓励了我为Lipe感到自豪，故答案为B．16．D．名词的辨析，pride自豪，honesty诚实，patience耐心，respect尊重，因为我弟弟，我学会了尊重的意义，故答案为D．17．C．形容词的辨析，poor贫穷的，troublesome令人讨厌的，strange奇怪的，difficult困难的，以前我看到有人行为或长得不一样，我只会想他们是奇怪的，并开始笑，故答案为C．18．D．动名词的辨析，achieving获得，choosing选择，enjoying享受，experiencing经历，我现在会想他们在生活中可能经历了什么，故答案为D．19．A．动词的辨析，judges评价，refuses拒绝，improves提高，discovers发现，虽然社会会冷漠地评价你的每一分寸，故答案为A．20．C．名词的辨析，pleasure乐趣，difference不同，kindness善良，determination决心，至少我们要善良地对待其他人，故答案为C．短文主要讲了作者的弟弟出生带有唐氏综合症，在作者对弟弟的爱和支持下，作者也明白了现在社会也有很多人经历着这些疾病，我们不能嘲笑别人，而要平等地尊重他们．在做完形填空时，首先需要快速的浏览全文，把握文章的主旨大意；其次要学会带着问题到文中相应的地方，通过细节阅读来寻找或概括答案；最后理清作者的写作思路也非常重要；做此类题时，要多注意一些形容词或动词的搭配，在平时多积累一些固定搭配．36.【答案】【小题1】who【小题2】himself【小题3】totally【小题4】left【小题5】wearing【小题6】for【小题7】to treat【小题8】warmth【小题9】a【小题10】but【解析】1．who．考查连词，who引导非限定性定语从句，先行词是guys，在定语从句中做主语，故填关系代词who．2．himself．考查代词，dress oneself in：穿…的衣服，固定搭配，故填himself．3．totally．考查副词，副词修饰动词ignore，故填totally．4．left．考查动词，他离开了这个商店，一般过去时，故填left．5．wearing．考查非谓语，he与wear是主动关系，故填现在分词做状语，故填wearing．6．for．考查介词，pay for：为…付钱，固定搭配，故填介词for．7．to treat．考查不定式，how to do sth：如何做某事，如何对待别人，故填to treat．8．warmth．考查名词，放在动词后面作宾语，展现温暖，故填warmth．9．a．考查冠词，这里表示泛指，不要以貌取人，故填a．10．but．考查连词，但是你永远不知道谁会是天使，表示转折，故填but．文章通过一则故事告诉读者不要以貌取人．在一篇200词左右的语篇（短文或对话）中留出10处空白，部分空白的后面给出单词的基本形式，要求考生根据上下文填写空白处所需的内容或所提供单词的正确形式，所填写词语不得多于3个单词．要做好语法填空题，理解短文是解题的前提，扎实的词汇、句型和语法知识是基础，英语国家的背景知识是必要的补充．考生须灵活运用语法知识，如单词词性、单词时态、名词单复数、连接词、代词、冠词等判断各空白处应填写的内容．答完后，还要通读全文，核对所填单词形式是否正确，是否符合语境．37.【答案】Dear Mr．Bowie，I know that new-built Foreign Language Bookstores are now seeking advice from the public to increase the number of visitors．As a book fan，I would like to offer some advice．（写信目的）First，the book store should have enough space to provide good reading experience for our readers．Second，public lectures should be included in the activities to raise the readers' interest．Third，the book store can donate some books to the poor students so as to attract them to the book store．【高分句型一】（建议）Hopefully，the book store will be the one where we can enrich our knowledge and relax．【高分句型二】（希望）Yours，Li Hua【解析】高分句型一：Third，the book store can donate some books to the poor students so as to attract them to the book store．译文：第三，书店可以捐出一些书给贫困学生，以吸引他们到书店．分析：这句话使用so as to表示目的．高分句型二：Hopefully，the book store will be the one where we can enrich our knowledge and relax译文：希望书店能让我们丰富知识，放松心情．分析：这句话使用where引导定语从句．提纲类写作是近年高考英语书面表达的热点题型，命题人通常以提纲作文的形式考查书信、报道、通知、日记、发言稿、对某人或某物的介绍、欢迎词等．提纲作文的选材范围很广，内容简单易懂，且多是考生熟悉的话题．这类题型的主要特点是要点明确，范围具体．但考生也容易受中文提纲的制约，将书面表达变成了翻译，造成语法结构和词汇上的单调，甚至写出结构不完整的句子．38.【答案】Paragraph 1：As time went by， Tom felt himself growing weaker and he knew he must take action，so he thought of David．He attached the shower cap to Taz and signalled the direction to his house to Tit and Taz went out of the canyon．Soon Taz went back to his house and knocked at David's door．Seeing the shower cap，David realized that Tom was in danger．He called the rescue workers and drove his car to the canyon with Taz in it．【高分句型一】（Taz回去求救）Paragraph 2：About three hours later， Taz returned and Tom heard an engine in the distance．He was glad that someone could help him．After a short while，David came with two rescue workers，and they carried Tom out of the canyon together．Luckily，Tom was not seriously injured．He pulled through after staying in bed for two weeks．He owed his survival to his devoted dog and caring neighbour．【高分句型二】（David带着救援人员来救Tom）【解析】高分句型一：He called the rescue workers and drove his car to the canyon with Taz in it．译文：他打电话给救援人员，开着他的车去峡谷，车上有塔兹．分析：这句话使用with复合结构．高分句型二：He owed his survival to his devoted dog and caring neighbour．译文：他生还归功于他忠诚的狗和有爱心的邻居．分析：这句话使用owe sth to sb将…归功于读写任务型写作是将阅读与写作有机结合，要求考生既能读懂文章信息，又要依据要求规范连贯地表达内容，其中准确概括很有挑战且十分重要，根据记叙文、议论文、说明文等不同文体作相应概括，总的来说，遵循以下步骤：确定主题句；寻找关键词；重构主题句；重组支持句．写作时注意准确运用时态，上下文意思连贯，符合逻辑关系，尽量使用自己熟悉的单词句式，同时也要注意使用高级词汇和高级句型使文章显得更有档次，平时需注意积累短语和重要句型．。
浙江省宁波市九校联考2018-2019学年高一上学期期末考试英语试题及答案解析
浙江省宁波市九校联考2018~2019学年高一上学期期末考试英语试题注意事项：1．答题前填写好自己的姓名、班级、考号等信息；2．请将答案正确填写在答题卡上。
第I卷（选择题）一、阅读理解I was used to carrying a penknife in my pocket，and over the years I moved up in size from a small single knife to a Swiss Army knife and then eventually to a Leatherman multi-tool （多刃刀具）．This wasn't a problem for many years．However，after the 9/11，the world changed．I was traveling from JFK to LAX，so I took the knife out of my pocket and put it in my bag．But when I got to the airport，I had completely forgotten about it，so I just quickly went through safety check．This was not long after 9/11，so safety check was extremely strict．But somehow，the X-ray screener missed the knife in the bag，and I walked on through．I was sitting in the gate area waiting for boarding，when I noticed a second security screening process right next to the gate，with another X-ray machine and what looked like anti-terrorist soldiers．I suddenly remembered that I had this knife in my bag! I really didn't know what I should do．If I did nothing and they caught the knife during the second security screening，I'd be dead；if I told them I accidentally got the knife through the first screening，they would certainly re-screen every passenger on the plane；if I dropped it in a garbage can，it would be found by a cleaner in a secure area （警戒区），and probably result in something scary! I was anxious and like a cat on hot bricks．Suddenly，I noticed a skycap，someone whose job is to carry passengers' bags at an airport．I had an idea．I then began to ask every skycap I saw，"Hey，how would you like a ﹩60 multi-tool as a present？"Finally，a guy looking happy but confused took it off my hands．I then went through the second safety check with no knife．1．The author carried a knife in his pocket ______ ．A．out of habit B．B．as a presentC．out of self-protection D．as a souvenir （纪念品）2．In the end，how did the author deal with the knife？______A．He put it in the bag．B．He gave it to others．C．He threw it away secretly．D．He handed it to a policeman．3．The passage is mainly about ______ ．A．the history of penknivesB．the strict safety check in JFKC．a meaningful gift from the airportD．an embarrassing experience in the airportNovember 11th, also known as the “bare sticks holiday”, and a day originally meant for young people to celebrate being single, has become the world’s largest 24-hour online shopping carnival. Forum (论坛) readers share their opinions.Blonde Amber (Ireland)There is nothing to be proud of to be in a country that spends so much online on a particular day. It does nothing more than show the superficiality (肤浅) of the temporary pleasure of shopping, and produces nothing more than a mountain of environmental waste. I bet there is plenty of “buyers’ remorse” after this day.Vivian (US)Since it is Singles’ Day, I guess only the single population of China should buy something to relieve social pressure. The married might be excluded (排除) from the festival.Alex (US)Singles’ Day was initiat ed (创始) by a group of college students to celebrate being single, or not having a girlfriend or boyfriend. They think poor guys should buy something on the day to entertain themselves. But Jack Ma got hold of the opportunity, hit the jackpot and successfully made it a yearly shopping spree(狂欢).George (Canada)I work in Shanghai. Many of my young female colleagues are still single. They simply haven’t time to date, as they tend to work long hours and travel two hours by subway to get to and from work. Singl es’ Day is a day when they spoil themselves with online shopping.Patrick (Australia)I don’t care if it is Singles’ Day or a shopping spree. It sounds fair enough to me. Just a click and I can get the best deals I have ever seen delivered to my door, and save money and time.4．What does the underlined word “remorse” in Paragraph 2 mean?A．Surprise. B．Joy.C．Regret. D．Excitement.5．What’s the best title for the passage?A．To Buy or Not to Buy? B．A Global Shopping SpreeC．Jack Ma and the Double Eleven D．Singles’ Day or Shopping Spree? 6．Where can we most probably find this passage?A．From a taxtbook. B．From a poster.C．From a website. D．From an advertisement.Robyn Rihanna Fenty has rocked the entertainment world with her contributions to pop music. She was born on February 20, 1988, in Saint Michael, Barbados. In her early teens, Rihanna was greatly inspired by reggae (雷盖音乐) singer Bob Marley and pop singer Madonna. She was lucky enough to get her first opportunity at the age of 15, when her friend introduced her to an experienced music composer Evan Rogers from New York.Rihanna moved to US to start a career in music, and recorded under the guidance of Rogers and his partner Carl Sturken. Later, Shane Carter recognized her talent and had her sign a contract with Def Jam Recordings.Rihanna has been musically influenced by famous artists, such as Beyonce Knowles, Madonna, Mariah Carey, Alicia Keys, and Bob Marley. In 2005,Rihanna released her debut album (首张专辑) “Music of the Sun'”, which included the single hit “Pon de Replay”. This single broke all records and peaked at No. 2 on the US Billboard Hot 100 charts, as well as the UK charts. Her second single “If It’s Lovin’ That You Want” was at No. 36 on the Billboard Hot 100 charts, and No. 11 on the UK charts.Rihanna released her second album, “A Girl Like Me” in 2006, which included the hit song and lead single “S.O.S” (Rescue Me). This single peaked at the number one position on the Billboard Hot 100.In 2006, Rihanna also tried her luck in films, and made her acting debut playing a role in “Bring It On: All or Nothing”. The next year, she released her third album “Good Girl GoneBad”',which had hit tracks like “Umbrella”, “Hate That I Love You”,and “Don’t Stop the Music'”, among others. In the same year, at the MTV Video Music Awards, Rihanna won two awards for the hit single “Umbrella”. In 2008, Rihanna won her first Grammy Award for her hit single “Umbrella”. So far, Rihanna has won 45 awards in various categories.7．What plays an important role in Rihanna’s success?A．The support of her friends.B．The encouragement of her family.C．The education she received at school.D．The help and influence of successful musicians.8．What happened to Rihanna when she was eighteen years old?A．She started a career in music.B．She began to act in films.C．She began to release albums.D．She won her first Grammy Award.9．What do we know about Rihanna’s second single “If It’s Lovin’ That You Want”?A．It was released in 2006.B．It was included in her third album.C．It was not as successful as her first single.D．It was more successful than her third single.10．Which song earned rewards for Rihanna for two years in a row?A．Umbrella. B．Pon de Replay.C．Hate That I Love You. D．Don't Stop the Music.二、完形填空Four months into her pregnancy （孕期），my mother learned that my brother would be born with Down syndrome （唐氏综合症）．Never having dealt with anyone with the disease，the entire family began to 11 ．Would he learn to walk and talk 12 like the other kids？Would he be liked by others？Would he have some 13 ？All these thoughts and every detail 14 us，though we knew we would 15 him exactly the way he is．Thankfully，after birth，Lipe was 16 than we expected，with no heart problemsin general connected with Down syndrome．He is the most 17 person I have ever met．Anything is a reason for him to flash a smile．Even if it took him some extra 18 to learn new things，he always did extremely well．Although we were glad to see that，we still 19 what others would say about him．In order to 20 him．I kept his condition a secret．I was also afraid of being treated 21 by others because of his condition．But I soon realized 22 I truly loved him，I shouldn't be 23 of him．The first time I told a friend about Lipe's disease，she just reminded me that all that my brother needed was my love and 24 ．It was my friend's understanding that 25 me to be proud of Lipe．Because of my brother，I have learned the meaning of 26 ．Before his birth，if I saw someone who acted or looked differently，I simply thought it to be 27 and started laughing．I am now glad that I have changed in these ways．I now consider what they could possibly be 28 in life，and the many reasons why they could be behaving like that．We may live in a world in which the society coldly 29 every inch of you，but we can at least treat others with 30 ．Only in this way can we expect to create a better society．11．A．practice B．worry C．complain D．understand 12．A．quickly B．easily C．quietly D．normally 13．A．friends B．classmates C．teachers D．students 14．A．left B．troubled C．helped D．inspired 15．A．change B．shock C．accept D．remember 16．A．younger B．happier C．calmer D．healthier 17．A．curious B．cheerful C．suitable D．confident 18．A．luck B．praise C．effort D．power 19．A．gave up B．believed in C．learned from D．cared about 20．A．care B．protect C．follow D．comfort 21．A．badly B．excitedly C．seriously D．politely 22．A．if B．although C．because D．unless 23．A．proud B．afraid C．scared D．ashamed 24．A．hope B．peace C．support D．interest 25．A．made B．encouraged C．required D．attracted 26．A．pride B．honesty C．patience D．respect 27．A．poor B．troublesome C．strange D．difficult28．A．achieving B．choosing C．enjoying D．experiencing 29．A．judges B．refuses C．improves D．discovers 30．A．pleasure B．difference C．kindness D．determination第II卷（非选择题）三、七选五Many students have already chosen whether or not to apply for Early Decision (ED). The official deadline for most colleges and universities with an ED application is Nov 1st at 11:59 p.m.Early Decision has risks. 31．However, ED comes with some nice perks(好处). The two biggest advantages are:1.Early notification (通知). Students apply early and are notified early—usually by December 15.2.A boost (提高) in acceptance. With just a little bit of research, you can find out the acceptance rate for students who apply normally and those who apply through ED．You might be surprised. 32．What questions do you need to ask before you make the ED choice?First, consider academic fit. Are you satisfied with the amount of research you’ve done to make a four-year commitment(承诺) to this school? Have you spent enough time on the colle ge’s website to understand the academic offerings? 33．Do you think you’d struggle to keep up with the other students in class?34．Are you sure you’ll like the climate? Is it the right size (not too big, not too small)? Is the emphasis on sports, arts, culture, etc. right for you? Do you like the surrounding area? Is it enough to keep you entertained, or is it too overwhelming (难应付的)?35．If you apply for Early Decision and are accepted, will you be able to attend if you are not offered any financial aid? If the answer is “no” then you probably should reconsider applying through ED, because you will need to withdraw (撤回) your other applications if you are accepted.A．Look at the social fit, too.B．Also look at your finances.C．Turn to your teachers for advice, too.D．Do you think you’re competitive academically？E．Are you sure you can adapt to the new surroundings？F．ED acceptance rates at some schools can be twice as high as the regular acceptance rates. G．It means the student has agreed that if he or she is accepted to a school, he or she must attend it.四、语法填空Do you judge people by their appearance?This week I was talking to some guys at Planet Fitness, 36．told me about their boss’ experience of buying a new car. The salesmen didn’t know t hat this man had a lot of money. It was because he often dressed 37．(he) in worn-out clothes, just like a homeless man on the street. When the boss arrived at the first shop, the salesmen 38．(total) ignored him and treated him like he wasn’t worth their ti me. He 39．(leave) the shop with a smile on his face. Later that day,he walked into another shop, 40．(wear) the same clothes as usual. The salesmen greeted him with kindness and respect. Then this man paid almost $20 million 41．new car!There’s a Bible tex t that tells us how 42．(treat) people that you learn little about. It says, “Don’t forget to show 43．(warm) to strangers, because anyone who does it may entertain angels without realizing it!” Don’t judge 44．book by its cover! The boss was not an angel 45．you never know who just might be.五、提纲类作文46．假定你是李华，新落成的外文书店为增加访客量现向市民征求建议，请给书店经理Mr. Bowie写一封建议信，内容包括：1．拥有宽敞的空间以提供良好的阅读体验；2．提供公益讲座（public lecture）等服务；3．其他建议（至少一条）。