河南省实验中学2019年中招模拟大联考答案

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2019年河南省联考中考物理模拟试卷(解析版)

2019年河南省联考中考物理模拟试卷(解析版)

2019年河南省联考中考物理模拟试卷一、填空题(本题共6小题,每空1分,共14分)1.根据你对物理学发展史的判断,在对应的空格内填入相应学者的名字:提出了“日心说”的是,而通过“斜面实验”推翻亚里士多德观点,并提出:物体的运动并不需要力来维持的科学家是。

2.如图所示,是周末的早晨小红在小区拍下的露珠照片,露珠是由于空气中的水蒸气在温度(选填“升高”或“降低”)时,发生了(填物态变化名称);透过露珠能观察到更加清晰的叶脉形状,此时露珠相当于(选填“照相机”“投影仪”或“放大镜”)的作用。

3.萍萍是位音乐爱好者,钢琴独奏或手风琴独奏她一听便能分辨,她的区分依据是这两种乐器发出声音的不同;她用不同的力弹琴时,发出声音的不同。

4.如图所示为一种手摇升降晾衣架示意图,它由4个定滑轮和两个动滑轮组成,绳子的尾端绕在一个固定在墙壁的旋轮上,旋转摇柄可以使晾衣架升降。

假设在升降过程中衣架横梁保持水平,假设衣服和晾衣架(含动滑轮)等的总重是50N,则静止时绳子拉力是N(各种摩擦力忽略不计);要使衣架横梁上升1m,则绕进旋轮上的绳子长度是m。

5.在如图1所示的电路中,电源电压保持不变,小灯泡的额定电压为12V.闭合开关S后,当滑片P从最右端滑到最左端的过程中,小灯泡的I一U关系图象如图2所示。

则小灯泡发光时的最小功率为W,滑动变阻器的最大阻值为Ω,整个电路的最大电功率为W。

6.用手掷出的铅球仍能继续向前运动,是因为铅球;铅球在飞行过程中运动的方向、快慢不断改变,最终要落到地面,是因为铅球。

二、选择题(本题共8小题,每小题2分,共16分.第7~12题每小题只有一个选项符合题目要求,第13~14题每小题有两个选项符合题目要求,全部选对的得2分,选对但不全的得1分,有选错的得0分)7.下列物品中,通常情况下属于绝缘体的是()A.实验室的烧杯B.泡腌菜坛里的盐水C.石墨炸弹中的石墨D.家里炒菜的铁锅8.如图中使用的工具,属于费力杠杆的是()A.食品夹B.瓶起子C.羊角锤D.钢丝钳9.用被毛皮摩擦过的橡胶棒接触验电器的金属球,可发现验电器的两个金属箔会因排斥而张开,对这一现象理解正确的是()A.金属球和金属箔都带正电B.金属球不带电,金属箔带负电C.金属球和金属箔都带负电D.金属球带负电,金属箔带正电10.人工智能使得人们的生活越来越方便,华人青年王孟秋发明了一款功能强大的便携式家用“无人机相机”,相机内装有多种高科技传感器,底部装有镜头和声呐(发射超声,同时能接受超声的装置),机身只有240克。

河南省2019年中考模拟考试试卷数学试卷(河南中招命题研究组编)(含答案)

河南省2019年中考模拟考试试卷数学试卷(河南中招命题研究组编)(含答案)

绝密★启用前2019年河南中招命题研究组2019年河南省普通高中招生考试模拟试卷数学试卷(考试时间:100分钟试卷满分:120分)第Ⅰ卷一、选择题(本大题共10小题,每小题3分,共30分.在每小题给出的四个选项中,只有一个选项是符合题目要求的)1.(-3)-2的平方根是()A.±B.±C.D.±32.据对全国规模以上文化及相关产业5.9万家企业调查,2018年上半年,上述企业实现营业收入42 227亿元,比上年同期增长9.9%,继续保持较快增长.其中42 227亿用科学记数法可表示为()A. 4.2227×10¹ºB. 4.2227×10¹¹C. 4.222 7×10¹²D. 4.22 27×10¹³3.下列分解因式正确的是()A.-x+4x=-x(x+4)B.x²+xy+x=x(x+y)C.x(x-y)+y(y-x)=(x-y)²D.x²-4x+4=(x+2)(x-2)4.如图是由几个小立方块搭成的几何体的俯视图,小正方形中的数字表示在该位置小立方块的个数,则这个几何体的左视图为()A B C D 5.将一把直尺和一块含30°和60°角的三角板ABC按如图所示的位置放置,如果∠CDE=40°,那么∠BAF的大小为()A.10°B.15°C.20°D.25°6.2019年河南中考某市实验操作考试,要求每名学生从物理、化学、生物三个学科中随机抽取一科参加测试.小华和小强都抽到物理学科的概率是()A. B. C. D.7.如图,在△ABC中,AD平分∠BAC,按如下步骤作图.第一步:分别以点A,D为圆心,大于AD的长为半径画弧,交于M,N两点;第二步:作直线MN分别交AB,AD,AC于点E,O,F;第三步:连接DE,DF.若BD=6,AF=4,CD=3,则BE的长是()A.2B.4C.6D.88.如图,在☉O中,AB是直径,CD是弦,AB⊥CD,垂足为点E,连接CO,AD,∠BAD=20°,则下列说法中正确的是()A.AD=2OBB.CE=EOC.∠OCE=40°D.∠BOC=2∠BAD9.如图,在Rt△ABC中,∠ACB=90°,将△ABC绕点C逆时针旋转得到△A'B'C,M是BC的中点,P是A'B'的中点,连接PM.若BC=2,∠BAC=30°,则线段PM长度的最大值是()A.1B.2C.3D.410.如图,点A的坐标为(0,1),点B是x轴正半轴上的一动点,以AB为边作Rt△ABC,使∠BAC=90°,∠ACB=30°,设点B的横坐标为x,点C的纵坐标为y,能表示y与x 的函数关系的图象大致是()第Ⅱ卷二、填空题(本大题共5小题,每小题3分,共15分)11.计算:--(1-)º+sin 45°+()▔³=__________.12.关于x的一元二次方程x(x+1)+ax=0(a≠-1)的根的情况是为__________.13.如图,在▱ABCD中,BC=20cm,CD=20 cm,∠A=45°,动点P从点B出发,沿BC向点C运动,同时动点Q从点D出发,沿DB向点B运动,点P和点Q的运动速度分别为3cm/s和2 cm/s,其中一点到达终点时,另一点也随之停止运动.设运动时间为t s,当△BPQ是直角三角形时,t的__________.14.如图所示的图形是由若干条圆心相同的圆弧组成,其圆心角为90°,最小的扇形半径为1.若每两个相邻圆弧的半径之差为1,由里往外的阴影部分的面积依次记为S1,S2,S3,…,S20,则S1+S2+S3+…+S20=.15.如图,在矩形纸片ABCD中,AB=2,AD=3,点E是AB的中点,点F是AD边上的一个动点,将△AEF沿EF所在直线翻折,得到△A'EF,则A'C的长的最小值是.三、解答题(本大题共8小题,共75分.解答应写出文字说明、证明过程或演算步骤)16.(本小题满分8分)先化简,再求值:-÷(m+2-),其中m是方程x²+2x-3=0的根.17.(本小题满分9分)适当的午休可以使下午学习时精力充沛.思源学校(非寄宿制)对该校学生周一到周五平均每天午休时间x(单位:min)进行抽样调查后分组整理,并绘制了如下不完整的统计图表.根据图中提供的信息,解答下列问题:(1)本次调查共抽取名学生;(2)统计表中,a=,b=;(3)将频数分布直方图补充完整;(4)若全校共有1 800名学生,请估计周一到周五平均每天午休时间不少于45 min的有多少人.18.(本小题满分9分)如图,在平面直角坐标系中,O为坐标原点,△ABO的边AB 垂直于x轴,垂足为点B,反比例函数y=(x<0)的图象经过AO的中点C,交AB于点D.若点D的坐标为(-4,n),且AD=3.(1)求反比例函数的解析式;(2)求经过C,D两点的直线的解析式;(3)设点E是线段CD上的动点(不与点C,D重合),过点E且平行于y轴的直线l 与反比例函数的图象交于点F,求△OEF面积的最大值.19.(本小题满分9分)如图,AB是☉O的直径,且AB=6,点M为☉O外一点,且MA,MC分别切☉O于点A,C.点D是直线BC与AM延长线的交点.(1)求证:DM=AM;(2)填空:①当CM=时,四边形AOCM是正方形;②当CM=时,△CDM为等边三角形.20.(本小题满分9分)图(1)是太阳能热水器装置的示意图,利用玻璃吸热管可以把太阳能转化为热能,玻璃吸热管与太阳光线垂直时,吸收太阳能的效果最好.假设某用户要求根据本地区冬至正午时刻太阳光线与地面水平线的夹角(θ)确定玻璃吸热管的倾斜角(太阳光线与玻璃吸热管垂直).请完成以下计算:如图(2),AB⊥BC,垂足为点B,CD∥AB,FG⊥DE,垂足为点G.若θ=37°50',FG=30 cm,CD=10 cm,求CF的长.(结果取整数,参考数据:sin37°50'≈0. 1,cos 37°50'≈0.79,tan37°50'≈0.78)图(1)图(2) 21.(本小题满分10分)为了“创建文明城市,建设美丽家园”,我市某社区将辖区内面积为1 000 m²的空地进行绿化,一部分种草,剩余部分栽花,设种草部分的面积为x(m²),种草所需费用y₁(元)与x(m²)的函数关系式为y₁=其图象如图所示;栽花所需费用y₂(元)与x(m²)的函数关系式为y₂=-0.01x²-20x+30 000(0≤x≤1 000).(1)请直接写出k₁,k₂和b的值;(2)设这块1 000 m²空地的绿化总费用为W(元),请利用W与x的函数关系式,求出绿化总费用W的最大值;(3)若种草部分的面积不少于700 m²,栽花部分的面积不少于100 m²,请求出绿化总费用W的最小值.22.(本小题满分10分))已知,在菱形ABCD中,∠ADC=120°,点P是直线CD上一动点(不与点C,D重合),连接AP,平移△ADP,使点D移动到点C处,得到△BCQ,点H是直线BD上一点,且∠QHD=60°,连接PH.(1)探索发现:如图(1),若点P在线段CD上,试判断∠APH的度数及P A,PH的数量关系,并说明理由.(2)问题拓展如图(2),若点P在线段CD的延长线上,其他条件不变,填空:①∠APH=°;②P A,PH的数量关系为.(3)解决问题如图(3),点P在线段DC的延长线上,连接AH,若△APH的面积为16,菱形ABCD 的边长为4,求DP的长.图(1)图(2) 图(3)解:(1)∠APH=60°,P A=PH.(2分)理由:连接AH,∵四边形ABCD是菱形,∠ADC=120°,∴AD=AB,∠DAB=60°,∴△ABD是等边三角形,∴∠ABD=60°,∴∠ABH=120°=∠ADP.∵∠QHD=∠CBD=60°,∴BC∥HQ,∴∠HQD=∠BCD=60°,∴△DHQ是等边三角形,∴DH=DQ, 又DB=DC,∴BH=CQ.由平移的性质可知CQ=DP,∴DP=BH,∴△ADP≌△ABH,∴AP=AH,∠DAP=∠BAH,∴∠P AH=∠P AB+∠BAH=∠P AB+∠DAP=60°, ∴△APH是等边三角形,∴P A=PH,∠APH=60°.(4分)(2)①60(5分)②P A=PH(6分)(3)同(1)可证△APH是等边三角形.由等边三角形的面积公式可得AP2=16, 解得AP=8(负值不合题意,已舍去).由平移的性质知:BQ=AP=8.过点B作BG⊥DQ于点G,∵△BDC是等边三角形,∴DG=GC=×4=2,∴BG=-==2,∴GQ=-==2,∴CQ=GQ-GC=2-2,∴DP=CQ=2-2.(10分)23.(本小题满分11分)如图,已知抛物线y=ax2+bx+3经过点A(1,0),与x轴负半轴交于点B,与y轴交于点C,且OC=O B.(1)求抛物线的解析式;(2)点P是直线BC上方的抛物线上的一个动点,过点P作直线l⊥x轴,交直线BC 于点D,当PD的值最大时,求点P的坐标;(3)点M在抛物线上,点N在抛物线的对称轴上,是否存在以点C,B,M,N为顶点的四边形是平行四边形?若存在,请直接写出点M的坐标;若不存在,请说明理由.∴OC=3.∵OC=OB,∴OB=3,∴B(-3,0).把A(1,0),B(-3,0)分别代入y=ax2+bx+3中,得解得故抛物线的解析式为y=-x2-2x+3.(3分)(2)设直线BC的解析式为y=kx+b',-3+' 0,解得将B(-3,0),C(0,3)代入,得故直线AB的解析式为y=x+3.(5分)设P(m,-m2-2m+3),则D(m,m+3),∴PD=(-m2-2m+3)-(m+3)=-m2-3m=-(+)+,∴当m=-时,PD有最大值,此时点P的坐标为(-,).(8分)(3)存在.点M的坐标为(-2,3),(2,-5)或(-4,-5).(11分)。

【100所名校】河南省实验中学2019届高三上学期第三次模拟考试英语试卷+含解析.doc

【100所名校】河南省实验中学2019届高三上学期第三次模拟考试英语试卷+含解析.doc

2019届河南省实验中学高三上学期第三次模拟考试英语注意事项:1.答题前,先将自己的姓名、准考证号填写在试题卷和答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。

2.选择题的作答:每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑,写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用签字笔直接答在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,请将本试题卷和答题卡一并上交。

第I卷(选择题)一、阅读理解As one of our talented remote editors, you'll have the ability to work from home while choosing the types of tasks that Interest you. You will receive free training through online talks and our company newsletters. You will have job security and be paid on time. Working with Scribendi INc. requires a middlle levd of computer and Internet knowledge. You need to be good at downloading and uploading files, attaching files to emails, saving and finding files on your computer, transferring files and renaming files-You should have a good working knowledge of the major document file formats and their associated software programs.Standard qualifications:Editor:•A university degree in a related field•At least three years of experience in editing, writing, document producfion3 or language Aching• A native speaker of the English language•Excellent reading comprehension skills and the ability to follow written instructions and work independently•An average editing or proofreading(校对)speed of 1,000-1,500 words per hour•Micros oft Word 2010 or later on a secure PC (not Mac) computer•Broadband/high-specd Internet access•The ability to accept payments in your own account in US dollars using PayPal; please review PayPals international payment network for more details・Preferred qualifications:•A post-graduate degree in a related field•Access to additional word processing/document production software (e.g、Star/Open Office・ Word Perfect, Open Office, LaTeX. Acrobat, Final Publisher.PageMaker)•ln-depth knowledge of one or more style guides (e.g, Chicago Manual of Style, Turabian,APA)Please note that appplimations for this position are NOT accepted by email. Pleass clo not call or email for more information about a position or to discuss an application・Please note that only applicants selected for evaluation will be contacted. Please visit http:///apply for application. Be careful about meeting deadlines・1 • The remote editor ______ •A.will study the knowledge of type settingB.will receive training that needs to by paid forC- will accept his payments by using PayPalD. can rest on weekends md have good pay2. Who will probably be one of the remote editors?A.All American with a university degree, who worked 3 years for a newspaper.B • A Chinese, with a university,wbo worke d 5 years for a translation—comply・C.An English wish a high school degree, who worked 3 years for a newspaper.D. A Frenchman with a university degree, who has a high level of computer knowledge,3 ・ Which of the following is 1RUE?A.Those applying for the job will be given a job interview.B • One can apply for the job throughout the yearmunication is very important for one to get the job.D.One can apply for the job through the website,Its a little hard to figure out the rules for sure but the baby African buffalo (水牛)seems to have the upper hand ・ The two stand a couple feet apart, staring at each other. Behind them, their mothers look on with the kind of indifference (不关心、)of mothers eveiywhere who see their kids playing a harmless game.The alarm went off about half an hour ago, the second time tonight. Here, one bell means ”elephant M,two Ihino"(犀牛),and three and four, I really can r t remember for what^ because when you' re awoken by bells in the middle of the night, your first thought won't be Animal?, But as soon as I realized it was the rhino alarm. I was running for the stairs•Yet Tm the only one watching the animals stare-down. Either nobody else died of a heart attack when the bells went off, or 1 was the only one in the entire hotel who didn't turn the alarm switch to off before going to bed.The Ark, a hotel shaped like the biblical ark(圣经的方舟),lies in the highlands of Kenya's Aberdare National Park, about 100 kilometers north of Nairobi. At the Ark's prow (船首)are huge windows overlooking a waterhole・ Earlier tonight, Fd watched a pack of wolves, buffalos and elephants・ And now. at Three or so in the mornings Tm down for the round of rhino bells. The first time, 2.5 hours ago. it was a single black rhino, which came down, got a drink, and leftFd have been sorry for the lost sleep・ IPe already arranged with a guide to take me out at sunrise for the so-called M should-never-missed H bird-watching, where well gel to see 30 species, but really, how many times in your life will you get to wake up and say, "Wow! Rhinor? Isn't that the definition of a pretty good right? Last week we went fiom Uganda into Kenya, Before I left home, I thought Fd be happy with ten elephants and five or six giraffes on the whole trip.I didn't dare to dream the rhinor.4. The message that the hoteFs bells sent was _______ ・A. a very wise way the author had never heard ofB ・ hard for the author to remember in detailC. a matter that all visitors had got used toD.like conditioned response training for animals5 - What's the author's attitude toward the bell?A. It's bothering but two bells are welcome.B ・ should be turned off whenever it rings,C.It visitors have a chance to see buffalos・D.It Is a very bad way to wake the guests up.6. What does the underlined part "died of a heart atttack H in paragraph 3 mean ?A. died unexpectedlyB ・ felt extremely excitedC.felt very uncomfortable and tiredD.suffered from a tenible heart attack7- What did the author see at about 3:00 a.m.?A. Two buffalos we me fighting fiercely for food,B ・ A rhino and a buffalo were fighting for water.C・ A rhino and a buffalo were staring at each other.D・ A buffalo was teaching its baby to walk freely.Don't get mad the next time you catch your teenager texting when he promised to be studying・ He simply may not be able to resist. A University of lowa(UI) study found teenagers are far more sensitive than adults to the inunediate effect or reward of their behaviors. The findings may help explain why the initial rush of texting may be more attractive for adolescents than the long-term pay off of studying・n For the teenager, f the rewands are attractive.11 says Professor Jatin Vaidya, an author of the study. 'They draw adolescent. Sometimes, the rewards are a kind of motivation for them・ Even when a behavior is no longer in a teenagers best interest to continue, they will, because the effect of the reward is still there and lasts much longer in adolescents than in adults •”For parents,that means limiting distraction (分心、的事情)so teenagers can make better chokes. Take the homework and social media dilemma: At 9 p.m., shut off everything except a computer that has no access to Facehook or Twitter, the researchers advise. n rm not saying they shouldn't be allowed access to technology/1 Vaidya says. But some help in netting their concentration is necessary for them so they can develop those impulse-control skills:In their study,Vaidya and co-author Shaun Vecera note researchers generally believe teenagers are impulsive (冲动的),make bad decisionsr and engage in risky behavior because the frontal lobes (额叶)of their trains are not fully dweloped・ But the UI researchers wondered・ whether something more fundamental was going on with adolescents to cause behaviors independent of higher-level reasoning・H We wanted to try to understand the brain's reward system how it change from chilhood to adulthood/1 Says Vaidya, who adds the reward character in the human brain is easier than decision-making. “We've been tring to understand the reward process in adolescence and Whether there is more to adolescence hehavior than an under-developed frontal lobe^he adds.For their study ,the researchers persuaded 40 adolescents, aged 13 and 16,and 40 adults, aged 20 and 35 to partiepate・In the future.researchers hope to look into the psychological and neurological (神经学上白勺)aspects of their results-8. What does the passage mainly tell us?A. The initial rush of texting is less attractive for adolescents than the long-term pay off of studying.B • Always, rewards are attractive to teenagers・C.Resistance can be controlled well by adolescents.D.Getting rewards is the greatest motivation for adolescents to study.9・ Which statement agrees with Vaidya^ idea?A・ The influence of the reward is weak In adolescents-B.Parents should help children in making decisions-C- Children should have access to the Internet.D. Children need help in refocusing their attention.10, What result does teenagers1 brain underdevelopment lead to?A・ Doing things after some thought.B • Making good decisions・C.Joining in dangerous actions.D.Escaping risky behavior.11 • How did the researchers carry out their study?A. By making a comparison of brain examinations.B • By examining adults' brain・C. By examining teenage brain.D- By building the train's reward system.Traditional Chinese medicine (TCM) is gaining global popularity. According to a government white paper, TCM has been introduced in 183 countries and regions around the world.Westerners1 understanding of TCM, however, may be limited to acupundurer cupping and massage (针灸,拔罐和按摩).For instance, the purple, injury-like marks left on US.swimmer Michael Phelps* back from cupping for the purpose of relaxing his muscles and reducing pain became the center of attention during the Rio Olympics in 2016.As a matter of fact, Chinese herbs play a more important role in getting rid of diseases and keeping the body in good condition in the TCM treatment system than physical treatment.lt is therefore disheartening to know that-while 103 World Health Organization member countries have given approval to the practice of acupuncture, not many recognize Chinese herbal medicine TCM falls far behind Western medicine owing parity to the slow development of Chinese herbs-Herbs, are made into pills,powder ancl soup, and the kind of herbs uscdl their quality and quantity, and the processing of the ingredients jointly determine the effectiveness of the prescription. Compared with Western medicine, which has standardized drug production processes and treatment methods, TCM lacks standardization, with the chemical composition and functions of its medicines being unclear and their effects being unstable.Fortunately .standardization has improved in recent decades, with an increasing number of factories producing patented TCM drugs.Another factor that has prevented the development of TCM prescription drugs is the lack of creativity, While Western medicine-making companies come up with new products eveiy year, TCM drug producers tend to make medicines according to prescriptions handed down from the past. Chinese chemist Tu Youyoui J s winning the 2015 Nobel Prize in Physiology or Medicine for her rescearch into malaria(疟疾)treatment may drive creativity to some extent in China's TCM industry. However, the current state of affairs cannot be changed within a short time ・12.The author mentions the example of Michael Phelps in order to show ______ .A. he was injured in his swimming.B • cupping is a kind of important TCM treatment・C- westerners know little about TCM・D. westerners attach great importance to TCM.13.Why don't some member countries of WHO recognize Chinese herbal medicine?A.Because Chinese herbs can get rid of diseasesB.Because they only approve the practice of acupunctureC- Because western medicine 15 more effectiveD. Because medicine made out or Chinese herbs develops slowlypared with Western medicine, what is the main weak point of TCM ?A. The methods of processing herbs.B • The effediveness of prescription.C- Lacking in standardization.D. Its unstable functions.15.The lack of creativity in TCM refers to the fact that ____ •A. medidne-making companies lack creativity.B • prescriptions are got from the past.C • Wesiem companies are mom experienced.D. medicine-making companies jack driving force二、七选五Tolerance means tolerating or pulling up with differences・16.This concept means different things to different people, but it is when something is disagreeable that tolerance is expected, and in more politically correct cultures, demanded・There are many different ways to show tolerance・A person might fully disagree with other on any issue,while at the same respecting those with different opinions and treat them with dignity 17・・One problem is the fact this respect is sometimes one-sided. 18. , but some supporters feel reasonable in labeling those who disagree with hateful terms,and vice versa.People on both sides of an issue must be tolerant of each other.19. Jt does not mean that a.person has to accept actions or ideas that are against his or her values or beliefs, it means that each person agrees to respect the other's right to his or her feelings on the matter. When both parties have expressed their opinions, and it is obvious that neither is likely to change position, agreeing to disagree is often the ideal outcome-Some degree of tolerance is necessary in any civilized society<20< Jt goes against human nature. Putting up with differences is a virtue that requires honest effort on the part of every person. It takes time to develop ・A^Therefore, both parties should change their opinions if necessary.B.It is widely accepted that tolerance is a critical step towards a peaceful woild.C.IE refers to showing respect for the race, religion and opinions of other people.D・ Disagreement alone does not equal intolerance・E.However, it is not realistic to believe that all people can achieve it completely on every issue・F.Those who disagree with a particular issue must respect the opinions of those who support it.G・When it conies to controversial issues, tolerance may also represent a let's agree to disagree” altitude.三、完形填空How can I forget the day? On 14 July 1974 1 traveled in an overcrowded bus to an unheard town called Shendurni. The next day. I was to join the faculty of a junior college there. ___________ 21 ___ about my new job, but anxious and fearful too, I was out of my _____ 22 zone ・ Around 7pm .It started Pouring with rain. Wondering about my new cancer in an unknown land, I had _____ 23 ___ in my seat, I woke up with a start to the sound of the conductor , _______ 24__ the name of my bus stop .1 looked out. It was pitch-dark Ah, a power cut, ___ 25 ___ unusual during heavy rainsf Conductor Sahab, can I get a _____ 26 ___ for myself hero? Fm new to the place/ I heard myself ask ____________ 27—.H Ane bhai, get off my bus and let us go. We__ 28 __ to reach the next station on time.^he Shouled back Amid mounting panic, I felt a ________ 29 ___ tap on my shoulders. As I looked back, a warm smile _________________________________________ 30__ m e; °Tm Sawant, from the next town. The bus__ 31 __ there for the night and returns tomorrow morning. Why don't you buy a ticket for the next stop? You can spend the night at my place, and join work tomorrow. H I thanked him from my heart and accepted his 32—, Bythe time the bus reached the final stop, it was 8:30 p.m. The kind soul led me to his house .He and his wife took great __ 33 __ to make my stay comfortable. I was ____________________________ 34 ___ with warm water fora bath, followed by a hot ____ 35 __ and a comfortably bed. All this took place in semi-darkness. No fights yet, I was up early the next morning and my benefactoi•(恩人)came to —36 me off. I could not see his face clearly,as it was —37— dark, I made it 38— the college in time and taught there for almost 11 years, All this while I _39_ him, even asking my new friends and students to help find the kind soul. Rut Mr Sawant remained 40_• Perhaps I had got his name wrong. My only regret: I could not thank him again.21. A. Excited B. Interested C・ Worried D・ Annoyed22. A. home B. school C. comfort D. dilemma23. A. knocked off B • drove off C・ turned off D. dozed off24. A. announcing B • claiming C. screaming D- declaring25. A. Something B ・ Anything C. Everything D・ Noihing26. A. seat B・ room C・ ticket D・ map27. A. sadly B ・ quickly C • nervously D • surprisingly28. A. come B・ get C・ need D. ask29. A. sudden B. soft C. real D・ warm30. A. waved B. welcomed C.greeted D・shook31. A. stops B. arrives C. leaves D・ drives32. A. family B • solution C. invitation D. request33. A. pleasure B・ energy C.(difficulty D. pains34. A. provided B. offered C. given D • blessed35. A. chat B. discussion C. meal D. tea36. A. walk B・ drive C・ show D. see37. A. yet B. still C・ already D. also38. A. to B .in C. fromD.for39. A. sent for B • searched for C. cared for D. waited for40. A. silent B. strange C. unbelievable D. untraceable第II卷(非选择题)四、语法填空阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。

河南省2019届中招考试数学模拟试卷含答案解析

河南省2019届中招考试数学模拟试卷含答案解析

2019年河南省中招考试数学模拟试卷一、选择题(共8小题,每小题3分,共24分)下列各题均有四个选项,其中只有一个是正确的,将正确答案的代号字母填入题后括号内。

1.5的相反数是()A.B.﹣5 C.±5 D.﹣2.2019年12月30日,晋豫鲁铁路正式开通运营,据了解,晋豫鲁铁路是“晋煤外运”的新通道.线路起自山西兴县瓦塘站,终点是山东日照,全线长1260公里,横跨山西、河南、山东三省.总投资941亿元,941亿用科学记数法表示为()A.941×108B.94.1×109C.9.41×1010 D.9.41×10113.不等式组的解集在数轴上表示为()A.B.C.D.4.如图,AB∥CD,点E在BC上,且CD=CE,∠D=74°,则∠B的度数为()A.68°B.32°C.22°D.16°5.下列运算正确的是()A.(2x2)3=6x6B.3a+2b=5ab C.﹣a5•a5=﹣a10D.(a+b)2=a2+b26.一个物体由多个完全相同的小正方体组成,它的三视图如图所示,那么组成这个物体的小正方体的个数为()A.2个B.3个C.5个D.10个7.种植能手李大叔种植了一批新品种黄瓜,为了考察这种黄瓜的生长情况,李大叔抽查了部分黄瓜株上长出的黄瓜根数,得到如图的条形图,则抽查的这部分黄瓜株上所结黄瓜根数的中位数和众数分别是()A.13.5,20 B.15,5 C.13.5,14 D.13,148.如图,二次函数y=ax2+bx+c的图象开口向上,对称轴为直线x=1,图象经过(3,0),下列结论中,正确的一项是()A.abc<0 B.2a+b<0 C.a﹣b+c<0 D.4ac﹣b2<0二、填空题(共7小题,每小题3分,共21分)9.分式方程的解是.10.已知直角三角形ABC的一条直角边AB=8cm,另一条直角边BC=6cm.则以AB为轴旋转一周,所得到的圆锥的表面积是.11.在四张背面完全相同的卡片上分别印有等腰三角形、平行四边形、菱形和圆的图案,现将印有图案的一面朝下,混合后从中随机抽取两张,则抽到卡片上印有图案都是轴对称图形的概率为.12.如图,▱ABCD中,∠ABC=60°,E、F分别在CD和BC的延长线上,AE∥BD,EF⊥BC,EF=,则AB的长是.13.把直线y=﹣x+3向上平移m个单位后,与直线y=2x+4的交点在第一象限,则m的取值范围是.14.如图,在Rt△ABC中,∠C=90°,∠B=60°,点D是BC边上的点,CD=1,将△ABC沿直线AD翻折,使点C落在AB边上的点E处,若点P是直线AD上的动点,则△PEB的周长的最小值是.15.如图,在平面直角坐标系中,一次函数y=kx+b(k≠0)的图象与反比例函数y=(m≠0)的图象交于A、B两点,与x轴交于C点,点A的坐标为(n,6),点C的坐标为(﹣2,0),且tan∠ACO=2,点E在x轴上,若△ACE为直角三角形,则E的坐标是.三、解答题(本大题共8小题,满分75分)16.先化简÷(a+2)+,再求值,a为整数且﹣2≤a≤2.17.如图,在△ABC中,D是BC边上的一点,E是AD的中点,过A点作BC的平行线交CE的延长线于点F,且AF=BD,连接BF.(1)BD与CD有什么数量关系,并说明理由;(2)当△ABC满足什么条件时,四边形AFBD是矩形?并说明理由.(3)在(2)的条件下,△ABC满足条件,矩形AFBD是正方形.18.某中学九(1)班为了了解全班学生喜欢球类活动的情况,采取全面调查的方法,从足球、乒乓球、篮球、排球等四个方面调查了全班学生的兴趣爱好,根据调查的结果组建了4个兴趣小组,并绘制成如图所示的两幅不完整的统计图(如图①,②,要求每位学生只能选择一种自己喜欢的球类),请你根据图中提供的信息解答下列问题:(1)九(1)班的学生人数为,并把条形统计图补充完整;(2)扇形统计图中m=,n=,表示“足球”的扇形的圆心角是度;(3)排球兴趣小组4名学生中有3男1女,现在打算从中随机选出2名学生参加学校的排球队,请用列表或画树状图的方法求选出的2名学生恰好是1男1女的概率.19.一架空客A320﹣200型客机2019年12月28日从印尼泗水飞往新加坡途中失事.我国政府马上派出舰船搜救,我海军一艘潜艇在海面下500米A点处测得仰角为30°正前方的海底有疑似黑匣子信号发出,继续在同一深度直线航行3000米后再次在B点处测得俯角为60°正前方的海底有疑似黑匣子信号发出,求海底疑似黑匣子C点处距离海面的深度?(结果保留根号)20.如图,在平面直角坐标系中,点O为坐标原点,正方形OABC的边OA、OC分别在x轴、y轴上,点B的坐标为(2,2),反比例函数(x>0,k≠0)的图象经过线段BC的中点D.(1)求k的值;(2)若点P(x,y)在该反比例函数的图象上运动(不与点D重合),过点P作PR⊥y轴于点R,作PQ⊥BC所在直线于点Q,记四边形CQPR的面积为S,求S关于x的解析式并写出x的取值范围.21.在圣诞节前夕,几位同学到某文具店调查一种进价为2元的圣诞贺卡的销售情况,每张定价3元,每天能卖出500张,每张售价每上涨0.1元,其每天销售量就减少10个.另外,物价局规定,售价不得超过商品进价的240%.据此,请你解答下面问题:(1)要实现每天800元的利润,应如何定价?(2)800元的利润是否最大?如何定价,才能获得最大利润?22.(1)问题发现如图1,点E、F分别在正方形ABCD的边BC、CD上,∠EAF=45°,连接EF、则EF=BE+DF,试说明理由;(2)类比引申如图2,在四边形ABCD中,AB=AD,∠BAD=90°,点E、F分别在边BC、CD上,∠EAF=45°,若∠B,∠D都不是直角,则当∠B与∠D满足等量关系时,仍有EF=BE+DF;(3)联想拓展如图3,在△ABC中,∠BAC=90°,AB=AC,点D、E均在边BC上,且∠DAE=45°,猜想BD、DE、EC满足的等量关系,并写出推理过程.23.如图,已知抛物线经过A(﹣2,0),B(﹣3,3)及原点O,顶点为C(1)求抛物线的函数解析式.(2)设点D在抛物线上,点E在抛物线的对称轴上,且以AO为边的四边形AODE是平行四边形,求点D的坐标.(3)P是抛物线上第一象限内的动点,过点P作PM⊥x轴,垂足为M,是否存在点P,使得以P、M、A为顶点的三角形与△BOC相似?若存在,求出点P的坐标;若不存在,请说明理由.2019年河南省中招考试数学模拟试卷参考答案与试题解析一、选择题(共8小题,每小题3分,共24分)下列各题均有四个选项,其中只有一个是正确的,将正确答案的代号字母填入题后括号内。

2019年河南省实验中学联考中考化学一模试卷和答案

2019年河南省实验中学联考中考化学一模试卷和答案

A.鉴别 NH4NO3 和 NH4Cl﹣﹣加熟石灰研磨 B.鉴别羊毛线和涤纶线﹣﹣点燃闻气味
C.除去 CuSO4 溶液中的少量 FeSO4﹣﹣加适量铜粉 D.除去 NaCl 中的 KNO3﹣﹣降温结晶 9.(1 分)在一定条件下,将一定质量的 A 与 48g B 按如图所示充分反应,当 B 反应完全
A.大米
B.牛奶
C.水
D.蔬菜
3.(1 分)将物质按不同标准分类是重要的学习方法,下列判断错误的是( )
A.氧化物:冰、干冰、生石灰
B.有机物:葡萄糖、碳酸、淀粉
C.溶液:矿泉水、空气、生理盐水
D.碱:氢氧化钾、熟石灰、烧碱
4.(1 分)化学离不开实验,下列实验操作正确的是( )
A. 性
蒸发
B.
检查装置气密
时,生成 44gC 和 36gD,则下列说法错误的是( )
A.图中所示四种物质均含氧元素
B.生成 C 与 D 的化学计量数之比为 1:1
C.该反应前后原子数目不变
D.物质 A 中碳元素的质量分数为 37.5%
10.(1 分)某同学家中种植的植物比正常的植株矮小瘦弱,叶片发黄,有的叶脉呈淡棕色,
你认为应该施加下列哪一种化肥( )
加过量 BaCl2 溶液;②过滤;③加过量 K2CO3 溶液;④加适量盐酸;⑤加过量 KOH 溶
液。则该操作的合理顺序是
(用序号表示,每个操作限用一次),上述操作中加
入过量 K2CO3 溶液的目的是

20.(3 分)A~E 是初中化学常见的物质,它们之间的关系如图所示。已知 A、D 均是氧化
物且反应①有红色物质生成,C 是胃液的主要成分,B 是密度最小的气体,E 可用作补
A.铝的金属活动性比铁强,则铝制品比铁制品更容易锈蚀

河南省2019年3月2019届九年级第一次模拟大联考(河南卷)数学卷(参考答案)

河南省2019年3月2019届九年级第一次模拟大联考(河南卷)数学卷(参考答案)

数学参考答案 第 1 页(共 7 页)16 11.212.b <913.910 π 14.415.1 或3317.【解析】(1)50.(3 分)参加调查的学生共有 8÷16% =50 人,故答案为:50;(2)“自理星”的人数为 50×30% =15 人, 补全图形如下:(5 分)(3)扇形统计图中“读书星”对应的扇形圆心角度数为 360°× 12 10 =72°.(7 分)50(4)3600×50=864,答:该小学全校 3600 名学生中争当“健康星”的学生人数为 864 人.(9 分)数学参考答案 第 2 页(共 7 页)33 18.【解析】(1)如图,连接 DO .学科&网(2)①3.(6 分)连接 CD ,∵∠ACB =90°,∠B =30°,AC =2 ,∴AB =2AC =4 ,∴BC =6,∵AC 为直径,∴∠BDC =∠ADC =90°, 由(1)得:BE =EC , 1∴DE = 2BC =3,故答案为:3. ②45.(9 分)当∠B =45°时,四边形 ODEC 是正方形,理由如下:数学参考答案 第 3 页(共 7 页)∵∠ACB =90°,∴∠A =45°, ∵OA =OD ,∴∠ADO =45°, ∴∠AOD =90°,∴∠DOC =90°, ∵∠ODE =90°,∴四边形 DECO 是矩形, ∵OD =OC ,∴矩形 DECO 是正方形. 故答案为:45.19.【解析】如图,作 AM ⊥CD 于 M ,作 BF ⊥AM 于 F ,EH ⊥AM 于 H .k 20. 【解析】(1)∵反比例函数 y = x1(k >0)的图象过点 A ,过 A 点作 x 轴的垂线,垂足为 M , ∴ |k |=1,2∵k >0,数学参考答案 第 4 页(共 7 页)⎩ ⎩∴k =2,2 故反比例函数的解析式为:y = x.(3 分)学科.网(2) 如图,作点 A 关于 y 轴的对称点 A ′,连接 A ′B ,交 y 轴于点 P ,则 PA +PB 最小.⎧y = - 1 x + 5 ⎧ x = 4 ⎪ 2 2 ⎧ x = 1 ⎪ 由⎨ 2 ,解得⎨ y = 2 ,或⎨ y = 1 , ⎪ y = ⎩ x⎩ ⎪⎩ 2 1∴A (1,2),B (4, ),221.【解析】(1)设甲组工作一天商店应付 x 元,乙组工作一天商店应付 y 元,⎧8x + 8 y = 3520根据题意得: ⎨6x +12 y = 3480 ,(2 分)⎧x = 300解得: ⎨ y = 140 .答:甲组工作一天商店应付 300 元,乙组工作一天商店应付 140 元.(4 分) (2)单独请甲组所需费用为:300×12=3600(元),数学参考答案 第 5 页(共 7 页)单独请乙组所需费用为:140×24 =3360(元),∵3600>3360,∴单独请乙组所需费用最少.(7 分)(3) 商店请甲乙两组同时装修,才更有利,理由如下:(8 分)单独请甲组完成,损失钱数为:200×12+3600=6000(元), 单独请乙组完成,损失钱数为:200×24+3360=8160(元), 请甲、乙两组同时完成,损失钱数为:200×8+3520 =5120(元).∵8160>6000>5120,∴商店请甲乙两组同时装修,才更有利.(2) 问题解决如图②,过 D 作 DE ⊥AB ,交 BA 的延长线于 E ,由(1)同理得:△ABC ≌△DEA , ∴DE =AB =2,AE =BC =4,Rt △BDE 中,BE =6,学*科网由勾股定理得: BD = 2.(7 分)(3) 拓展延伸10数学参考答案 第 6 页(共 7 页)2 如图③,过 D 作 DE ⊥BC 于 E ,作 DF ⊥AB 于 F ,同理得:△CED ≌△AFD , ∴CE =AF ,ED =DF ,设 AF =x ,DF =y ,⎧x + y = 4 ⎧x = 1 则⎨2 + x = y ,解得: ⎨ y = 3 , ⎩⎩∴BF =2+1=3,DF =3,由勾股定理得: BD == 3 .(10 分)(2)①过点 P 作 PD ⊥x 轴于 D ,交 AB 于点 E ,如图 1 所示.设点 P 的横坐标为 m ,则点 P 的坐标为(m , 1 m 2- 3 m -3),点 E 的坐标为(m , 1m -3),3 22数学参考答案 第 7 页(共 7 页)∴PE = 1 m -3-( 1 m 2- 3 m -3)=- 1m 2+2m ,(5 分)23 23∴S △PAB = 1×PE ×(AD +DO )= 1×(- 1m 2+2m )×6=-m 2+6m =-(m -3)2+9, 22 3∴当 m =3 时,△PAB 的面积最大,最大值是 9.(7 分)学科#网即 9+ 9 +9+(y +3)2=( 9)2+y 2,423 解得:y =- ;2当∠CQB =90°时,有 BQ 2+CQ 2=BC 2, 即( 9 )2+y 2+9+(y +3)2=9+ 9,24方程无解.9 3 综上所述,在直线 PD 上否存在点 Q (3, 4)或(3,- 2),使△QBC 为直角三角形.(11 分)。

河南省2019届中招考试数学模拟试卷含答案解析

河南省2019届中招考试数学模拟试卷含答案解析

2019年河南省中招考试数学模拟试卷一、选择题(共8小题,每小题3分,共24分)下列各题均有四个选项,其中只有一个是正确的,将正确答案的代号字母填入题后括号内。

1.5的相反数是()A.B.﹣5 C.±5 D.﹣2.2019年12月30日,晋豫鲁铁路正式开通运营,据了解,晋豫鲁铁路是“晋煤外运”的新通道.线路起自山西兴县瓦塘站,终点是山东日照,全线长1260公里,横跨山西、河南、山东三省.总投资941亿元,941亿用科学记数法表示为()A.941×108B.94.1×109C.9.41×1010 D.9.41×10113.不等式组的解集在数轴上表示为()A.B.C.D.4.如图,AB∥CD,点E在BC上,且CD=CE,∠D=74°,则∠B的度数为()A.68°B.32°C.22°D.16°5.下列运算正确的是()A.(2x2)3=6x6B.3a+2b=5ab C.﹣a5•a5=﹣a10D.(a+b)2=a2+b26.一个物体由多个完全相同的小正方体组成,它的三视图如图所示,那么组成这个物体的小正方体的个数为()A.2个B.3个C.5个D.10个7.种植能手李大叔种植了一批新品种黄瓜,为了考察这种黄瓜的生长情况,李大叔抽查了部分黄瓜株上长出的黄瓜根数,得到如图的条形图,则抽查的这部分黄瓜株上所结黄瓜根数的中位数和众数分别是()A.13.5,20 B.15,5 C.13.5,14 D.13,148.如图,二次函数y=ax2+bx+c的图象开口向上,对称轴为直线x=1,图象经过(3,0),下列结论中,正确的一项是()A.abc<0 B.2a+b<0 C.a﹣b+c<0 D.4ac﹣b2<0二、填空题(共7小题,每小题3分,共21分)9.分式方程的解是.10.已知直角三角形ABC的一条直角边AB=8cm,另一条直角边BC=6cm.则以AB为轴旋转一周,所得到的圆锥的表面积是.11.在四张背面完全相同的卡片上分别印有等腰三角形、平行四边形、菱形和圆的图案,现将印有图案的一面朝下,混合后从中随机抽取两张,则抽到卡片上印有图案都是轴对称图形的概率为.12.如图,▱ABCD中,∠ABC=60°,E、F分别在CD和BC的延长线上,AE∥BD,EF⊥BC,EF=,则AB的长是.13.把直线y=﹣x+3向上平移m个单位后,与直线y=2x+4的交点在第一象限,则m的取值范围是.14.如图,在Rt△ABC中,∠C=90°,∠B=60°,点D是BC边上的点,CD=1,将△ABC沿直线AD翻折,使点C落在AB边上的点E处,若点P是直线AD上的动点,则△PEB的周长的最小值是.15.如图,在平面直角坐标系中,一次函数y=kx+b(k≠0)的图象与反比例函数y=(m≠0)的图象交于A、B两点,与x轴交于C点,点A的坐标为(n,6),点C的坐标为(﹣2,0),且tan∠ACO=2,点E在x轴上,若△ACE为直角三角形,则E的坐标是.三、解答题(本大题共8小题,满分75分)16.先化简÷(a+2)+,再求值,a为整数且﹣2≤a≤2.17.如图,在△ABC中,D是BC边上的一点,E是AD的中点,过A点作BC的平行线交CE的延长线于点F,且AF=BD,连接BF.(1)BD与CD有什么数量关系,并说明理由;(2)当△ABC满足什么条件时,四边形AFBD是矩形?并说明理由.(3)在(2)的条件下,△ABC满足条件,矩形AFBD是正方形.18.某中学九(1)班为了了解全班学生喜欢球类活动的情况,采取全面调查的方法,从足球、乒乓球、篮球、排球等四个方面调查了全班学生的兴趣爱好,根据调查的结果组建了4个兴趣小组,并绘制成如图所示的两幅不完整的统计图(如图①,②,要求每位学生只能选择一种自己喜欢的球类),请你根据图中提供的信息解答下列问题:(1)九(1)班的学生人数为,并把条形统计图补充完整;(2)扇形统计图中m=,n=,表示“足球”的扇形的圆心角是度;(3)排球兴趣小组4名学生中有3男1女,现在打算从中随机选出2名学生参加学校的排球队,请用列表或画树状图的方法求选出的2名学生恰好是1男1女的概率.19.一架空客A320﹣200型客机2019年12月28日从印尼泗水飞往新加坡途中失事.我国政府马上派出舰船搜救,我海军一艘潜艇在海面下500米A点处测得仰角为30°正前方的海底有疑似黑匣子信号发出,继续在同一深度直线航行3000米后再次在B点处测得俯角为60°正前方的海底有疑似黑匣子信号发出,求海底疑似黑匣子C点处距离海面的深度?(结果保留根号)20.如图,在平面直角坐标系中,点O为坐标原点,正方形OABC的边OA、OC分别在x轴、y轴上,点B的坐标为(2,2),反比例函数(x>0,k≠0)的图象经过线段BC的中点D.(1)求k的值;(2)若点P(x,y)在该反比例函数的图象上运动(不与点D重合),过点P作PR⊥y轴于点R,作PQ⊥BC所在直线于点Q,记四边形CQPR的面积为S,求S关于x的解析式并写出x的取值范围.21.在圣诞节前夕,几位同学到某文具店调查一种进价为2元的圣诞贺卡的销售情况,每张定价3元,每天能卖出500张,每张售价每上涨0.1元,其每天销售量就减少10个.另外,物价局规定,售价不得超过商品进价的240%.据此,请你解答下面问题:(1)要实现每天800元的利润,应如何定价?(2)800元的利润是否最大?如何定价,才能获得最大利润?22.(1)问题发现如图1,点E、F分别在正方形ABCD的边BC、CD上,∠EAF=45°,连接EF、则EF=BE+DF,试说明理由;(2)类比引申如图2,在四边形ABCD中,AB=AD,∠BAD=90°,点E、F分别在边BC、CD上,∠EAF=45°,若∠B,∠D都不是直角,则当∠B与∠D满足等量关系时,仍有EF=BE+DF;(3)联想拓展如图3,在△ABC中,∠BAC=90°,AB=AC,点D、E均在边BC上,且∠DAE=45°,猜想BD、DE、EC满足的等量关系,并写出推理过程.23.如图,已知抛物线经过A(﹣2,0),B(﹣3,3)及原点O,顶点为C(1)求抛物线的函数解析式.(2)设点D在抛物线上,点E在抛物线的对称轴上,且以AO为边的四边形AODE是平行四边形,求点D的坐标.(3)P是抛物线上第一象限内的动点,过点P作PM⊥x轴,垂足为M,是否存在点P,使得以P、M、A为顶点的三角形与△BOC相似?若存在,求出点P的坐标;若不存在,请说明理由.2019年河南省中招考试数学模拟试卷参考答案与试题解析一、选择题(共8小题,每小题3分,共24分)下列各题均有四个选项,其中只有一个是正确的,将正确答案的代号字母填入题后括号内。

2019届中考河南省实验中学2019学年初三语文第三次模拟试卷(含答案)

2019届中考河南省实验中学2019学年初三语文第三次模拟试卷(含答案)

河南省实验中学2019学年初三模拟试卷(时间:120分钟,满分:120分)一、积累与运用(共27分)1.下列词语中加点的字,每对读音都不同的一项是( )(2分)A .拾级∕拾荒 露面∕初露锋芒 疾风劲草∕殊功劲节B .唠叨∕捞取 挨打∕尘埃落定 销声匿迹∕不屑一顾C .投奔∕奔走 应分∕应有尽有 勇冠三军∕冠冕堂皇D .蹿红∕撺掇 剽悍∕虚无缥缈 徇私枉法∕瘦骨嶙峋2.下列词语中没有错别字的一项是( )(2分)A .沉湎 赃物 捅篓子 忠贞不渝 实至名归B .婵联 妖娆 大拇指 以逸待劳 励精图治C .狼藉 羁绊 逻辑学 苦心孤诣 赴汤蹈火D .跻身 爆料 恶作剧 惊慌失错 晨钟暮鼓3.古诗文默写(8分)(1) 事无大小,悉以咨之,然后施行, , 。

(诸葛亮《出师表》)(2)《春江花月夜》中“人生代代无穷已,江月年年只相似”表现美好事物不可阻挡的在消逝,但同时仍有美好事物再现的道理。

晏殊的《浣溪沙》中“ , ”也蕴含了同样的哲理。

(3)古诗中的花可传情达意。

陶渊明在《饮酒》中用“ , ”展现自己寄情山水的闲适自得;杜甫在《春望》中用“ , ”传递自己目睹春城败象的沉痛之情。

4.名著阅读。

(任选一题作答)(4分)(1)阅读《水浒传》连环画中的插图及文字,完成第①~②题。

①鲁智深揪住大王头巾,一下按在床边,那大王刚要挣扎,鲁智深抡起拳头,拳脚齐下,打得大王连叫“救命”。

②只见鲁智深右手向下,把身倒缴着,却把左手拔住上截,把腰一撑,将那棵柳树连根拔起。

③鲁、林二人真是英雄识英雄,好汉识好汉,他们就在菜园中结为兄弟。

④薛霸棍未落下,忽听松树背后雷鸣似的大喝一声,一条铁禅杖飞出来,把水火棍一挡,那棍子早飞了出去。

⑤郑屠挣不来,那把尖刀也丢在了一边。

鲁达抢前一步,踏住他的胸脯,提起拳头,一面打一面喝骂。

⑥长老因鲁智深前番闹了僧堂,这次又大醉,打坏了亭子、金刚……就叫鲁智深到方丈处歇了。

①上面六幅插图及文字是《水浒传》中鲁达的故事,请按照小说的情节发展排列顺序。

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CE=PE=﹣m2+ 11 m , 4
由勾股定理得:CG2+EG2=CE2,
(﹣m2+ 11 m )2=m2+( m)2, 4
解得:m1=4(舍),m2= ,
当 m= 时,y=﹣ +2× +3= ,
∴P( , ), 综上所述,当△CPE 是以 CE 为腰的等腰三角形时, 点 P 的坐标是( , )或( , );…………………………9 分
取 PQ 的中点 G, ∵∠PCQ=90°, ∴CG= PQ,即 PQ=2CG,
当 CG 最小时,PQ 最小, ∴CG⊥PQ,即 CG 与 CB 重合时,CG 最小,
∴CGmin= ,PQmin=2 ,
∴S△PCQ 的最小值=3,S 四边形 PA'B′Q=3﹣
…………………………10 分
23、(11 分) 解:解:(1)把 A(﹣1,0),C(0,3)代入抛物线 y=﹣x2+bx+c 中得: ,
19、(9 分)解:在 Rt△ABD 中,∠ABD=30°,AB=10m, ∴AD=ABsin∠ABD=10×sin30°=5,
BD=ABcos∠ABD=10×cos30°= 5 3 ≈8.65……………………3 分 AD
在 Rt△ACD 中,∠ACD=15°,tan∠ACD= ,
CD ∴CD= 5 ≈18.52,………………………6 分
九年级 数学模拟(二)答案 第 2 页 ( 共 6 页)
∴m= =﹣1,
则点 B 的坐标为(﹣2,﹣1),
由题意得,

解得, ,
则一次函数解析式为:y1=x+1;…………………………3 分 (2)由函数图象可知,当﹣2<x<0 或 x>1 时,y1>y2;…………………………5 分 (3)∵AD⊥BE,AC=2CD, ∴∠DAC=30°, 由题意得,AD=2+1=3, 在 Rt△ADC 中,tan∠DAC= ,即 = ,
∴27 ≤x≤30
∵x 为正整数 ∴有 3 天利润不低于 870 元 ∴综上所述,当天利润不低于 870 元的天数共有 12 天.…………………………10 分
22.(10 分)解:(1)由旋转可得:AC=A'C=2, ∵∠ACB=90°,AB= ,AC=2, ∴BC= , ∵∠ACB=90°,m∥AC, ∴∠A'BC=90°,
∵PC=CE,CG⊥PF, ∴PG=EG,
∴EG= PE=

∵OC=FG=EF+EG,
∴﹣ m+3+
=3,
解得:m1=0,m2= ,
当 m= 时,y=﹣m2+2m+3=﹣( )2+2× +3= ,
∴P( , ),
②当 CE=PE 时,
在 Rt△CEG 中,CG=m,EG=FG﹣EF=3﹣(﹣ m+3)= m,
故答案为:17、20;…………………………2 分 (2)由于共有 50 个数据,其中位数为第 25、26 个数据的平均数, 而第 25、26 个数据均为 2 次, 所以中位数为 2 次, 故答案为:2 次;…………………………4 分 (3)扇形统计图中“3 次”所对应扇形的圆心角的度数为 360°×20%=72°;………6 分 (4)估计该校学生在一周内借阅图书“4 次及以上”的人数为 2000× =120 人.……9 分
18、(9 分) 解:(1)四边形 DEFG 是平行四边形. ∵点 D、E、F、G 分别是 CA、OA、OB、CB 的中点, ∴DG∥AB,DG= AB,EF∥AB,EF= AB, ∴DG∥EF,DG=EF,
九年级 数学模拟(二)答案 第 1 页 ( 共 6 页)
∴四边形 DEFG 是平行四边形;…………………………5 分 (2)①连接 OC. ∵CA=CB, ∴=, ∴DG⊥OC, ∵AD=DC,AE=EO, ∴DE∥OC,DE= OC=2,同理 EF= AB=3, ∴DE⊥DG, ∴四边形 DEFG 是矩形, ∴四边形 DEFG 的面积=6. 故答案为 6;…………………………7 分 ②当 C 是优弧 AB 的中点时,四边形 DEFG 是正方形,此时∠CAB=75°, 当 C 是劣弧 AB 的中点时,四边形 DEFG 是正方形,此时∠CAB=15°, 故答案为 75°或 15°.…………………………9 分
∴PB= BC= , ∵∠BQC=∠BCP=∠A, ∴tan∠BQC=tan∠A= , ∴BQ=BC× =2,
∴PQ=PB+BQ= ;…………………………6 分
(3)∵S 四边形 PA'B′Q=S△PCQ﹣S△A'CB'=S△PCQ﹣ , ∴S 四边形 PA'B′Q 最小,即 S△PCQ 最小, ∴S△PCQ= PQ×BC= PQ,
(3)P 的横坐标为 2 或
.……………………………………11 分
方法 2:第(2)问也可以先求出 CE= 5 m ,PE=﹣m2+ 11 m ,①当 EC=EP 时, 5 m =﹣m2+ 11 m ;
4
4
4
4
②当 CE=CP 时,中点公式.
九年级 数学模拟(二)答案 第 6 页 ( 共 6 页)
34 π
23
4
15、2 或
5
16、(8 分)解:
所以 x=2 +3
原式= x 3 2(x 2) x 2 (x 3)2
2 = x 3 …………………………5 分
当 x=4cos30°+3 时,
原式= …………………………8 分
17、(9 分)解:(1)∵被调查的总人数为 13÷26%=50 人, ∴a=50﹣(7+13+10+3)=17,b%= ×100%=20%,即 b=20,
解得,CD= , 当点 C 在点 D 的左侧时,点 C 的坐标为(1﹣ ,﹣1), 当点 C 在点 D 的右侧时,点 C 的坐标为( +1,﹣1), ∴当点 C 的坐标为(1﹣ ,﹣1)或( +1,﹣1)时,AC=2CD.…………………………9 分
21、(10 分)解:(1)m=﹣ ,n=25…………………………2 分 (2)由(1)第 x 天的销售量为 20+4(x﹣1)=4x+16 当 1≤x<20 时 W=(4x+16)(﹣ x+38﹣18)=﹣2x2+72x+320=﹣2(x﹣18)2+968 ∴当 x=18 时,W 最大=968 当 20≤x≤30 时,W=(4x+16)(25﹣18)=28x+112 ∵28>0
0.27
BC=18.52-8.65=9.87≈9.9………………………8 分 答:改造后的斜坡式自动扶梯水平距离增加的长度约为 9.9 米.………………………9 分
20、(9 分)解:(1)∵点 A(1,2)在反比例函数 y2= 的图象上, ∴k=1×2=2, ∴反比例函数的解析式为 y2= ,
∵点 B(﹣2,m)在反比例函数 y2= 的图象上,
解得: , ∴抛物线的解析式为:y=﹣x2+2x+3;…………………………3 分 (2)把 C(0,3)代入直线 y=﹣ x+m 得: m=3, ∴直线的解析式为:y=﹣ x+3, 设 P(m,﹣m2+2m+3)、E(m,﹣ m+3),
九年级 数学模拟(二)答案 第 5 页 ( 共 6 页)
①当 CE=CP 时,过 C 作 CG⊥PF 于 G, ∴PE=(﹣m2+2m+3)﹣(﹣ m+3)=﹣m2+ m,
九年级 数学模拟(二)答案 第 3 页 ( 共 6 页)
∴W 随 x 的增大而增大 ∴当 x=30 时,W 最大=952 ∵968>952 ∴当 x=18 时,W 最大=968…………………………6 分 (3)当 1≤x<20 时,令﹣2x2+72x+320=870 解得 x1=25,x2=11 ∵抛物线 W=﹣2x2+72x+320 的开口向下 ∴11≤x≤25 时,W≥870 ∴11≤x<20 ∵x 为正整数 ∴有 9 天利润不低于 870 元 当 20≤x≤30 时,令 28x+112≥870 解得 x≥27
∴cos∠A'CB=
=,
∴∠A'CB=30°, ∴∠ACA'=60°;…………………………3 分 (2)∵M 为 A'B'的中点, ∴∠A'CM=∠MA'C, 由旋转可得,∠MA'C=∠A,
九年级 数学模拟(二)答案 第 4 页 ( 共 6 页)
∴∠A=∠A'CM, ∴tan∠PCB=tan∠A= ,
河南省实验中学 2018——2019 学年下期月考 1 试卷
一、选择题(每小题 3 分,共 30 分)ຫໍສະໝຸດ 1——5、 D C A D C
二、填空题(每小题 3 分,共 15 分)
11、0
12、(3,-5)
13、 3
4
三、解答题 (本大题共 8 个小题,满分 75 分)
6——10、 A B A B C
7
14、
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