四川省成都市第七中学2020-2021学年第一学期高一期中考试数学试题
2020-2021学年成都市第七中学高三英语期中考试试题及答案

2020-2021学年成都市第七中学高三英语期中考试试题及答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AMy mother and her best friend Martha were in their mid-80s when they saw each other for the last time.They had been friends since they were 18, both of them students atWesleyanCollegeinMacon,Georgia. My mother was the dreamy one, who loved to read and dream herself as an actress. Martha, however, was more practical. I’m not sure what they had in common except that they trusted each other, helped each other, and stayed in touch even when life separated them.Martha spent most of her adulthood inAtlanta, where she raised three kids. My mother, meanwhile, raised eight children, and moved many times during her financially and emotionally troubled marriage, which included several months living with her family inseedymotels.I sensed my mother hid her troubles from most people, but not from Martha, and I knew from my mother that Martha carried her own sorrows. Their willingness to share sorrow without judgment was part of what bond them.The best friendships can also withstand (抵挡) periods without communication. They didn’t communicate a lot — this was before the ease of emails and texts and yet I knew they were always in each other’s minds.One day in 2008, 1 drove my mother to Martha’s house for their final visit. The moment my mother hobbled (蹒跚) into Martha’s house, they threw their arms around each other and went to sit out in the garden, laughing until they were dizzy. I snapped a photo, and spotted something joyous, young and free on my mom, which existed only in the presence of her best friend.Two years later, my mother died. Of all the people I had to tell, Martha was the hardest because I felt it erased her past. After that, we lost touch. But I still think of her and how that friendship strengthened my mother.1. What does the underlined word “seedy” in Paragraph 3 probably mean?A. largeB. dirtyC. urbanD. bright2. The author’s mother and Martha had a lasting friendship partly because they________.A. were willing to shareB. were constantly in touchC. had much in commonD. had a likeness in personality3. What is the author’s purpose in writing the text?A. To tell the importance of friendship.B. To express his gratitude to his mother.C. To share his standard of choosing a friend.D. To praise the friendship between Martha and his mother.BWhere do you find beauty? Fashion Magazines? Music Videos? One American photographer is finding beauty in unexpected places. And a new documentary about his work might help change the traditional standards of “who” is beautiful.Rick Guidotti put aside his career as a fashion photographer to turn his lens to people living with genetic, physical and behavioral differences. He says what changed his perception of beauty was a chance encounter with an albino (白化病)girl.“I was just tired of people telling me who was beautiful. Every season that face would change but I was always told who was beautiful. As an artist, I don't see beauty just on covers of magazines. I see it everywhere. So it was my initial intention that opened my eyes a little wider and wider.” Said Guidotti.Guidotti has created Positive Exposure, a not-for-profit organization that uses photography and video to transform public views and promote a world where differences are celebrated. Guidotti and Positive Exposure are featured in a new documentary called On Beauty.The cast and crew recently hosted a screening at Georgetown University in Washington. One of the women featured in the film is Jayne Waithera. “I never thought I was beautiful because nobody said that to me, but meeting him was my profound moment. I remember that particular day he took my picture and I felt so good like I felt there's somebody who, really loves me and sees me for who I am and who sees me more than my condition.” said Waithera.The documentary is the idea of producer Joanna Rudnick. After seeing Guidotti's photos, she decided to tell his story. Joanna and Guidotti are traveling from city to city to promote On Beauty. “As I travel from community to community, I'm taking photographs and I'm encouraging individuals with a positive sense of who they are. They're seeing beauty in their reflection but I'm also encouraging their families and they in turn are encouraging their communities as well. All is based on the philosophy of change how you see,see how you change.”4. What made Rick change his understanding of beauty?A. A girl diagnosed with albino.B. His job as a fashion photographer.C. The beauty on the covers of magazines.D. Influence from the people working with him.5. What can we infer about Jayne Waithera?A. She showed great interest in taking photos.B. She used to be disappointed at her work and life.C. She was greatly influenced by the experience with Rick.D. She believed Rick was the best photographer in the world.6. Which of the following words can best describe On Beauty?A. abstract and differentB. traditional and academicC. tolerant and encouragingD. creative and interesting7. What's the best title of the text?A. True Beauty In The Eye Of A PhotographerB. Beautiful Or Not Beautiful,That's A QuestionC. Be Who You Are Not Who You Want To BeD. A Different photographer, A Different MagazineCThe China International Search and Rescue Team(CISAR) was formed in 2001 and is now made up of several hundred rescue workers and about 20 police dogs. The team brings help and hope to those whose lives are changed by astorm, flood, earthquake, or any other natural disasters.After long and careful training, the team went on its first international rescue tasks in 2003. That year, the Chinese team helped save lives after earthquakes inAlgeriaandIran. It was the first time that a Chinese team had worked outsideChinawhose members won high praise for bravery and skill.Since then, the CISAR has completed many tasks. The list of people to whom help has been given is long. The team treated more than 3,000 people who were wounded in the 2006 earthquake inIndonesia, helped 2,500 wounded people after the earthquake that hitHaitiin 2010, and spent several months giving aid to over 25,000 people suffering from the 2010 floods inPakistan. On April 26, 2015, a group of 62 people from CISAR went toNepalafter the 8.1 magnitude earthquake that happened there.Rescue workers are trained to find people, treat wounds, and hand out food, water, and other supplies. They have to be able to do work that is difficult under conditions which can be very dangerous. After a disaster, there is usually no electricity or water, and there may be diseases and other dangers. Rescue workers get to save lives, butthey must also bury the dead. That means they have to be strong in both body and mind.Rescue workers must have big hearts, too. It takes a lot of love and courage to risk one’s own life to save someone else’s. The members of the CISAR have plenty of both and are always ready to go wherever help is needed.8. What is the function of the numbers in Paragraph 3?A. To advertise for the CISAR.B. To add some basic information.C. To praise Recue Workers’ contributions.D. To stress the dangers Rescue Workers face.9. What is the author’s attitude towards Rescue Workers?A. Hopeful.B. Respectful.C. Curious.D. Supportive.10. What are the last two paragraphs mainly about?A. The duty rescue workers must perform.B. The qualities rescue workers must own.C. The difficulties rescue workers must go through.D. The willingness rescue workers should require.11. What may be the best title of the passage?A. China to the RescueB. How to train CISARC. Welcome to CISARD. Rescue on requestDBeing an Olympian (奥运会选手) demands focus, determination, and a competitive spirit. Plus, representing your country is a lot of pressure. However, two athletes recently showed the world another quality that is definitely worth championing.Qatar's Mutaz Essa Barshim and Italy's Gianmarco Tamberi were competing in the high jump on Sunday when they reached a stalemate (僵局). Both men had managed to jump over a surprising 2.37 meters with no faults along the way. However, after three attempts neither managed the next level of 2.39 meters.An Olympic official suggested ajump-offbetween the two friends and rivals (竞争对手) to determine who would get the gold medal. But Barshim had another plan to reward their efforts.“Can we have two golds?” he asked the official.The official agreed and the two men jumped for joy. This was the first time a gold medal had been shared since 1912. “He is one of my best friends, not only on the track, but outside the track. We work together. This is a dream come true.” shared Barshim.The decision to share the medal was particularly meaningful to Tamberi. The Italian had suffered an ankle injury that prevented him from competing in the Rio Olympics in 2016, and it nearly put an end to his career altogether. So this year he brought along his cast to this year's Olympics with “Road to Tokyo 2021” to inspire him along the way.For Barshim, the gold has topped off his already impressive medal collection, having received a bronze and a silver medal in 2012 and 2016 respectively.Despite all the glory of receiving a gold medal for their countries, their achievement means so much more. These two individuals, trying to do their very best for their countries, have provided a wonderful example to all those competing in sports. They've summed up exactly what it means to take part in a global event with a generous and compassionate (有同情心的) spirit.12. What happened to Barshim and Tamberi in the competition?A. They ended in a tie.B. They quit the competition.C. They set a new record.D. They ran out of strength.13. What does the underlined word “jump-off” in Paragraph 3 refer to?A. Debate.B. Vote.C. Celebration.D. Extra round.14. Why was the gold medal particularly meaningful to Tamberi?A. It could bring him a lot of money.B. It may make up for his regret in 2016.C. It was a glory for his country.D. It could complete his medal collection.15. What does the author mainly want to convey in the text?A. The importance of sharing.B. The glory of winning gold medals.C. The valuable and special team spirit.D. The considerate and sharing Olympic spirit.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。
四川省成都市第七中学2020-2021学年高一英语下学期期末试卷含解析

四川省成都市第七中学2020-2021学年高一英语下学期期末试卷含解析一、选择题1. Rather than ________ at home, she preferred ________ with us.A. to stay; to goB. stay; to goC. staying; goingD. stay; go参考答案:B【详解】考查固定短语。
句意:她宁愿和我们一起去也不愿待在家里。
这里使用prefer to do…rather than do…意为“宁愿做……而不愿做……”。
故选B。
【点睛】考生在平时的学习中应注意积累相应的词汇和搭配,并牢记其意思。
在做题时,将词义和题干相结合,从语法、句子结构尤其是句意上去判断,句意通顺,符合逻辑,即正确答案。
2. –I have seen the film The Artists.- .It’s really wonderful.A. Neither have IB. Neither I haveC. So have ID. So I have参考答案:C3. Instead of ________sights, Edison would spend the time ________in the public library.A. seeing, to readB. see, readC. to see, to readD. seeing , reading参考答案:D4. Studying English lies not so much in we learn by heart as in we really understand.A. that; whatB. what; whatC. that; thatD. what; that参考答案:B5. is no possibility Bob can win the first prize in the match.A. There; thatB. It; thatC. There; whetherD. It; whether参考答案:A 6. It was quite ___accident that I met him; he was homeless and ___rags at that time.A. at; byB. on; inC. by; inD. in; in参考答案:C略7. We congratulated her on her ________ by Beijing University.A. acceptB. being acceptedC. acceptedD. to accept参考答案:B8. I go to work by _____car and I usually drive at ______speed of 50 kilometers an hour.A. a; \B. a; aC.\; aD.\; \参考答案:C9. When they got there, they found the people suffering from the storm were food and water supplies.A. in want ofB. in praise ofC. in honor ofD. in place of参考答案:A考查词组。
四川省成都市第七中学2020-2021学年高二上学期期中考试语文试题 Word版含答案

Evaluation Only. Created with Aspose.Words. Copyright 2003-2016 Aspose Pty Ltd.成都七中2020—2021学年度上期高2022届高二半期考试语文试题一、现代文阅读(一)论述类文本阅读(本题共3小题)阅读下面的文字,完成1~3题。
陈寅恪说:“所谓真了解者,必神游冥想,与立说之古人,处于同一境界,始能批评其学说之是非得失,而无隔阂肤廓之论。
”这表明学术研究还需借助于历史的想象力。
但历史想象与艺术想象有所不同。
我们切不可拿“想象”作“证据”,“误认天上的浮云为天际的树林”。
这也是治学者应当牢记的“信条”。
治学须以历史学为根基。
李大钊说:“纵观人间的过去者便是历史,横观人间的现在者便是社会。
”也就是说,要洞察现实的社会,就不能不研究过去的历史。
胡适则把这种认识的思路,比作“祖孙的方法”,这一方法从来不把事物看作一个孤立的东西,而把它视为“历史”的一个“中段”:“上头有他的祖父,下头有他的孙子。
捉住了这两头,他再也逃不出去了。
”但历史也不是单纯事件的条块铺陈,它的背后还有“思想”,“有一个思想的过程所构成的内在方面”。
因此,我们只有通过“想象”,才能把握它内在的“思想”,才能从一堆枯燥无生命的原材料中发现有血有肉的生命。
事实上,对许多研究者来说,研究对象与他个人经历并无直接关系。
研究政治史的人,并不一定就是政治家,如果没有历史想象力的参与,他们的研究工作可以说是难以开展的。
历史想象应是“构造性”的。
这一点和艺术想象确有相似之处,钱锺书也认为,“史学家追叙真人真事,每须遥体人情,悬想事势,设身局中,潜心腔内,忖之度之,以揣以摩,庶几入情合理。
盖与小说剧本之臆造人物、虚构境地,不尽同而可相通。
”这很容易让人联想到司马迁,他在《史记》中创立的记史方法,比如刘邦之母大泽遇蛇、韩信下拜遇黄石公等,就颇具艺术想象的意味。
这仅是问题的一个方面。
2020-2021学年四川省成都市第七中学高一上学期期中考试地理试题

四川省成都市第七中学2020-2021学年高一上学期期中考试第Ⅰ卷选择题本卷共35个小题,每个小题有四个选项,只有一个选项最符合题意。
“一闪一闪亮晶晶,满天都是小星星,挂在天空放光明,好像许多小眼睛……”是一首大家耳熟能详的童谣。
据此回答1~2题。
1.童谣中所说的“星星”大多属于A.行星 B.恒星 C.流星 D.星云2.下列属于上题所述天体类型的是A.太阳 B.月球 C.木星 D.陨星1月31日晚间,2018年第一场天文大戏如约登场,“超级月亮”“血月”“蓝月亮”三合一亮相夜空,而上一次见到如此奇景还是152年前的1866年。
下图为“月全食形成示意图”。
据此回答3~4题。
3.“月全食”天文景观涉及的三个天体,月球、地球、太阳分别属于A.恒星、行星、行星 B.恒星、行星、卫星C.卫星、行星、恒星 D.恒星、卫星、行星4.图示天体A.均位于地月系 B.太阳质量最大 C.均位于河外星系 D.地球质量最小“It’s not just a planet(行星),It’s home(家园)。
”是对地球在太阳系中地位的恰如其分的评价。
据此完成5~6题。
5.地球的特殊性表现在A.质量在八颗行星中最小 B.既有自转运动,又有公转运动C.是唯一有水存在的行星 D.是太阳系中唯一有生命的行星6.地球表面有大气层,主要原因是A.与太阳的距离适中 B.生物进行光合作用或呼吸作用C.其体积和质量适中 D.八大行星各行其道、互不干扰下图为“我国年太阳辐射总量分布图”。
据此回答7~8题。
7.据图可知我国年太阳辐射总量的分布特点是A.由南向北逐渐增加 B.由东南向西北逐渐增加C.整体分布较均衡 D.西多东少,北多南少8.图中a区域较b区域年太阳辐射总量大的主要影响因素是A.正午太阳高度 B.地势 C.距海远近 D.纬度2020年“最关金边日食”发生于2020年6月21日,这次日食非常接近“全食”,太阳被月球遮盖达到了99.7%。
【英语】四川省成都市第七中学2020-2021学年高一上学期期中考试试题

四川省成都市第七中学2020-2021学年高一上学期期中考试英语试题第Ⅰ卷第一部分听力(共两节,满分20 分)第一节(共5 小题;每小题1 分,满分5 分)听下面5 段对话。
每段对话后有一个小题,从题中所给的A、B、C 三个选项中选出最佳选项。
听完每段对话后,你都有10 秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What will the woman do this afternoon?A. Do some exercise.B. Go shopping.C. Wash her clothes.2. Why does the woman call the man?A. To cancel a flight.B. To make an apology.C. To put off a meeting.3. How much more does David need for the car?A. $5,000.B. $20,000.C. $25,000.4. What is Jane doing?A. Planning a tour.B. Calling her father.C. Asking for leave.5. How does the man feel?A. Tired.B. Dizzy.C. Thirsty.第二节(共15小题)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6、7题。
6. What does Jack want to do?A. Watch TV.B. Play outside.C. Go to the zoo.7. Where does the conversation probably take place?A. At home.B. In a cinema.C. In a supermarket.听第7段材料,回答第8至10题。
第四关 以立体几何为背景的新颖问题为背景的填空题-(原卷版)

压轴填空题第四关 以立体几何为背景的新颖问题为背景的填空题【名师综述】以立体几何为背景的新颖问题常见的有折叠问题,与函数图象相结合问题、最值问题,探索性问题等. 对探索、开放、存在型问题的考查,探索性试题使问题具有不确定性、探究性和开放性,对学生的能力要求较高,有利于考查学生的探究能力以及思维的创造性,是新课程下高考命题改革的重要方向之一;开放性问题,一般将平面几何问题类比推广到立体几何的中,不过并非所有平面几何中的性质都可以类比推广到立体几何中,这需要具有较好的基础知识和敏锐的洞察力;对折叠、展开问题的考查,图形的折叠与展开问题(三视图问题可看作是特殊的图形变换)蕴涵了“二维——三维——二维” 的维数升降变化,求解时须对变化前后的图形作“同中求异、异中求同”的思辩,考查空间想象能力和分析辨别能力,是立几解答题的重要题型.类型一 几何体在变化过程中体积的最值问题典例1.如图,等腰直角三角形ABE 的斜边AB 为正四面体A BCD -的侧棱,2AB =,直角边AE 绕斜边AB 旋转一周,在旋转的过程中,三棱锥E BCD -体积的取值范围是___________.【来源】山东省菏泽市2021-2022学年高三上学期期末数学试题【举一反三】如果一个棱锥底面为正多边形,且顶点在底面的射影是底面的中心,这样的棱锥称为正棱锥.已知正四棱锥P ABCD -内接于半径为1的球,则当此正四棱锥的体积最大时,其高为_____类型二 几何体的外接球或者内切球问题典例2.已知正三棱锥S ABC -的底面边长为32P ,Q ,R 分别是棱SA ,AB ,AC 的中点,若PQR 是等腰直角三角形,则该三棱锥的外接球的表面积为______.【来源】陕西省宝鸡市2022届高三上学期高考模拟检测(一)文科数学试题【举一反三】已知菱形ABCD 中,对角线23BD =,将ABD △沿着BD 折叠,使得二面角A BD C --为120°,AC 33= ,则三棱锥A BCD -的外接球的表面积为________. 【来源】江西宜春市2021届高三上学期数学(理)期末试题类型三 立体几何与函数的结合典例3. 已知正方体1111ABCD A B C D -的棱长为1,E 为线段11A D 上的点,过点E 作垂直于1B D 的平面截正方体,其截面图形为M ,下列命题中正确的是______. ①M 在平面ABCD 上投影的面积取值范围是17,28⎡⎤⎢⎥⎣⎦;②M 的面积最大值为334; ③M 的周长为定值.【来源】江西省九江市2022届高三第一次高考模拟统一考试数学(理)试题【举一反三】如图,点C 在以AB 为直径的圆周上运动(C 点与A ,B 不重合),P 是平面ABC 外一点,且PA ⊥平面ABC ,2PA AB ==,过C 点分别作直线AB ,PB 的垂线,垂足分别为M ,N ,则三棱锥B CMN -体积的最大值为______.【来源】百校联盟2020-2021学年高三教育教学质量监测考试12月全国卷(新高考)数学试题类型四 立体几何中的轨迹问题典例4. 已知P 为正方体1111ABCD A B C D -表面上的一动点,且满足2,2PA PB AB ==,则动点P 运动轨迹的周长为__________.【来源】福建省莆田市2022届高三第一次教学质量检测数学试题【举一反三】在棱长为2的正方体1111ABCD A B C D -中,棱1BB ,11B C 的中点分别为E ,F ,点P 在平面11BCC B 内,作PQ ⊥平面1ACD ,垂足为Q .当点P 在1EFB △内(包含边界)运动时,点Q 的轨迹所组成的图形的面积等于_____________.【来源】浙江省杭州市2020-2021学年高三上学期期末教学质量检测数学试题【精选名校模拟】1.已知在圆柱12O O 内有一个球O ,该球与圆柱的上、下底面及母线均相切.过直线12O O 的平面截圆柱得到四边形ABCD ,其面积为8.若P 为圆柱底面圆弧CD 的中点,则平面PAB 与球O 的交线长为___________. 【来源】江苏省南通市2020-2021高三下学期一模试卷2.已知二面角PAB C 的大小为120°,且90PAB ABC ∠=∠=︒,AB AP =,6AB BC +=.若点P 、A 、B 、C 都在同一个球面上,则该球的表面积的最小值为______.【来源】山东省枣庄市滕州市2020-2021学年高三上学期期中数学试题3.四面体A BCD -中,AB BC ⊥,CD BC ⊥,2BC =,且异面直线AB 和CD 所成的角为60︒,若四面体ABCD 的外接球半径为5,则四面体A BCD -的体积的最大值为_________. 【来源】浙江省宁波市镇海中学2020-2021学年高三上学期11月期中数学试题4.我国古代《九章算术》中将上,下两面为平行矩形的六面体称为刍童,如图的刍童ABCD EFGH -有外接球,且43,4,26,62AB AD EH EF ====,点E 到平面ABCD 距离为4,则该刍童外接球的表面积为__________.【来源】江苏省苏州市张家港市2020-2021学年高三上学期12月阶段性调研测试数学试题5.已知正三棱柱111ABC A B C -的外接球表面积为40π,则正三棱柱111ABC A B C -的所有棱长之和的最大值为______.【来源】河南省中原名校2020-2021学年高三第一学期数学理科质量考评二6.已知体积为72的长方体1111ABCD A B C D -的底面ABCD 为正方形,且13BC BB =,点M 是线段BC 的中点,点N 在矩形11DCC D 内运动(含边界),且满足AND CNM ∠=∠,则点N 的轨迹的长度为______. 【来源】百校联盟2021届普通高中教育教学质量监测考试(全国卷11月)文科数学试卷7.矩形ABCD 中,3,1AB BC ==,现将ACD △沿对角线AC 向上翻折,得到四面体D ABC -,则该四面体外接球的表面积为______;若翻折过程中BD 的长度在710,22⎡⎤⎢⎥⎣⎦范围内变化,则点D 的运动轨迹的长度是______.【来源】江苏省无锡市江阴市青阳中学2020-2021学年高三上学期1月阶段检测数学试题8.如图,在四面体ABCD 中,AB ⊥BC ,CD ⊥BC ,BC =2,AB =CD =23,且异面直线AB 与CD 所成的角为60,则四面体ABCD 的外接球的表面积为_________.【来源】山东省新高考2020-2021学年高三上学期联考数学试题9.已知三棱锥P ABC -外接球的表面积为100π,PB ⊥平面ABC ,8PB =,120BAC ∠=︒,则三棱锥体积的最大值为________.【来源】江苏省徐州市三校联考2020-2021学年高三上学期期末数学试题10.已知直三棱柱111ABC A B C -的底面为直角三角形,且内接于球O ,若此三棱柱111ABC A B C -的高为2,体积是1,则球O 的半径的最小值为___________.【来源】广西普通高中2021届高三高考精准备考原创模拟卷(一)数学(理)试题11.如图,已知长方体1111ABCD A B C D -的底面ABCD 为正方形,P 为棱11A D 的中点,且6PA AB ==,则四棱锥P ABCD -的外接球的体积为______.【来源】2021年届国著名重点中学新高考冲刺数学试题(7)12.如图所示,在三棱锥B ACD -中,3ABC ABD DBC π∠=∠=∠=,3AB =,2BC BD ==,则三棱锥B ACD -的外接球的表面积为______.【来源】江西省南昌市八一中学、洪都中学、十七中三校2021届高三上学期期末联考数学(理)试题13.在三棱锥P ABC -中,平面PAB 垂直平面ABC ,23PA PB AB AC ====120BAC ∠=︒,则三棱锥P ABC -外接球的表面积为_________.【来源】福建省福州市八县(市)一中2021届高三上学期期中联考数学试题14.已知A ,B ,C ,D 205的球体表面上四点,若4AB =,2AC =,23BC =且三棱维A BCD -的体积为23CD 长度的最大值为________.【来源】福建省四地市2022届高三第一次质量检测数学试题15.如图,在四棱锥P ABCD -中,PA ⊥平面ABCD ,底面ABCD 是直角梯形,//AB CD ,AB ⊥AD ,22CD AD AB ===,3PA =,若动点Q 在PAD △内及边上运动,使得CQD BQA ∠=∠,则三棱锥Q ABC -的体积最大值为______.【来源】八省市2021届高三新高考统一适应性考试江苏省无锡市天一中学考前热身模拟数学试题16.已知正三棱锥A BCD -的底面是边长为23其内切球的表面积为π,且和各侧面分别相切于点F 、M 、N 三点,则FMN 的周长为______.【来源】湖南省常德市2021-2022学年高三上学期期末数学试题17.在三棱锥P ABC -中,PA ⊥平面ABC ,AC CB ⊥,4===PA AC BC .以A 为球心,表面积为36π的球面与侧面PBC 的交线长为______.【来源】山东省威海市2021-2022学年高三上学期期末数学试题18.在棱长为1的正方体1111ABCD A B C D -中,过点A 的平面α分别与棱1BB ,1CC ,1DD 交于点E ,F ,G ,记四边形AEFG 在平面11BCC B 上的正投影的面积为1S ,四边形AEFG 在平面11ABB A 上的正投影的面积为2S .给出下面四个结论:①四边形AEFG 是平行四边形; ②12S S +的最大值为2; ③12S S 的最大值为14;④四边形AEFG 6则其中所有正确结论的序号是___________.【来源】北京西城区2022届高三上学期期末数学试题196,在该圆柱内放置一个棱长为a 的正四面体,并且正四面体在该圆柱内可以任意转动,则a 的最大值为__________.【来源】河南省郑州市2021-2022学年高三上学期高中毕业班第一次质量预测数学(文)试题20.在三棱锥P -ABC 中,P A =PB =PC =2,二面角A -PB -C 为直二面角,∠APB =2∠BPC (∠BPC <4π),M ,N 分别为侧棱P A ,PC 上的动点,设直线MN 与平面P AB 所成的角为α.当tan α的最大值为2532时,则三棱锥P -ABC 的体积为__________.【来源】湖南省长沙市长郡中学2020-2021学年高三上学期入学摸底考试数学试题21.体积为8的四棱锥P ABCD -的底面是边长为22底面ABCD 的中心为1O ,四棱锥P ABCD -的外接球球心O 到底面ABCD 的距离为1,则点P 的轨迹长度为_______________________.22.如图,在ABC 中,2BC AC =,120ACB ∠=︒,CD 是ACB ∠的角平分线,沿CD 将ACD △折起到A CD'△的位置,使得平面A CD '⊥平面BCD .若63A B '=,则三棱锥A BCD '-外接球的表面积是________.【来源】河南省2021-2022学年高三下学期开学考试数学理科试题23.在三棱锥P ABC -中,4AB BC ==,8PC =,异面直线P A ,BC 所成角为π3,AB PA ⊥,AB BC ⊥,则该三棱锥外接球的表面积为______.【来源】辽宁省营口市2021-2022学年高三上学期期末数学试题24.在棱长为2的正方体1111ABCD A B C D -中,E 是CD 的中点,F 是1CC 上的动点,则三棱锥A DEF -外接球表面积的最小值为_______.【来源】安徽省淮北市2020-2021学年高三上学期第一次模拟考试理科数学试题25.如图,在正方体1111ABCD A B C D -中,点M ,N 分别为棱11,B C CD 上的动点(包含端点),则下列说法正确的是___________.①当M 为棱11B C 的中点时,则在棱CD 上存在点N 使得MN AC ⊥;②当M ,N 分别为棱11,B C CD 的中点时,则在正方体中存在棱与平面1A MN 平行;③当M ,N 分别为棱11,B C CD 的中点时,则过1A ,M ,N 三点作正方体的截面,所得截面为五边形; ④直线MN 与平面ABCD 2;⑤若正方体的棱长为2,点1D 到平面1A MN 2.【来源】四川省成都市第七中学2021-2022学年高三上学期1月阶段性考试理科数学试题11。
四川成都第七中学2020-2021高二上学期10月测试语文试题(含答案)

成都七中2020—2021学年度上学期高2022届高二10月阶段性测试语文试题一、现代文阅读(一)论述类文本阅读阅读下面的文字,完成1~3题。
白居易的诗歌影响广泛而深远,晚唐张为称白居易为“广大教化主”,白氏获得这样的称号,一个最重要的原因,就是他坚持“文章合为时而著,歌诗合为事而作”。
这一原则回应了当时文艺创作遇到的挑战,符合社会发展的现实需要,获得了后世广泛共鸣。
我国在魏晋时进入“文学的自觉时代”,对文体、内容等的研究使文艺开拓出新的天地。
但过犹不及,片面重视形式、忽视内容的倾向一直存在。
如六朝骄文讲求对偶、声律,脱离生活;中唐“大历十才子”追求丽辞、精于雕琢,反映的生活较为狭隘。
而唐自安史之乱后,进入藩镇割据、民不聊生的阶段,文人们罔顾现实而空玩文字,背离了士人的责任,也扭曲了文艺的主要功用。
于是韩愈、柳宗元等发起“古文运动”,务求恢复文章质朴自由、言之有物的传统;白居易、元稹等发起“新乐府运动”,倡导诗歌承续《诗经》和汉魏乐府补察时政、泄导人情的功能。
除了“文章合为时而著,歌诗合为事而作”,白居易还提出一些相关的主张,如诗歌应“救济人病、裨补时阙”,诗人应“志在兼济、行在独善”。
“为君、为臣、为民、为物、为事而作,不为文而作”,白居易的诗文创作忠实地践行了他的上述理念。
不论他在入仕初期,还是在朝为左拾遗,抑或被贬地方,都有许多作品深刻地反映社会现实,如《新制布袭》言:“安得万里裘,盖裹周四垠。
稳暖皆如我,天下无寒人。
”悲悯情怀与杜甫一脉相承。
白居易的讽谕诗是他现实主义精神的杰出代表,其中《观刈麦》《卖炭翁》等,都是广为人知的名篇。
而其讽谕之作中却绝无怨毒,只是“愿得天子知”,以达到辅助君王革新天下的目的。
与“文章合为时而著,歌诗合为事而作”的原则相关,他在诗歌创作中力避艰涩,追求平易,形成了朴素的美学风格。
关注现实、语言平易并不意味着艺术性减弱,他认为“韵协则言顺,言顺则声易入”,他非常重视以和谐的韵律连缀诗章,《琵琶行》《长恨歌》等作品皆为平易而美的佳作。
四川省成都市第七中学2020-2021学年高一化学上学期期中试题

四川省成都市第七中学2020-2021学年高一化学上学期期中试题年级:姓名:四川省成都市第七中学2020-2021学年高一化学上学期期中试题(无答案)可能用到的原子量:H-1 He-4 C-12 N-14 O-16 Na-23 Mg-24 Cl-35.5 Fe-56第Ⅰ卷(选择题)选择题(每小题只有1个选项符合题意)1.下列物质的分类错误的是A .纯碱——钠盐B .H 2SO 4——强电解质C .氢氧化铁胶体——无色分散系D .H 2O 2——氧化物2.将wgNaCl 固体完全溶于1L 水中,溶解和电离过程如图所示。
下列说法正确的是A .a 离子为Na +,b 离子为Cl -B .溶解和电离过程中,水分子与晶体不存在相互作用C .所得溶液中c (Na +)等于w/58.5mol/LD .若再加入NaCl 固体至离子浓度不再变化时,则所得为饱和溶液3.常温下,下列各组离子一定能在指定溶液中大量共存的是A .与Zn 反应能放出H 2的溶液中:3HCO -、K +、3NO -、24SO - B .能使石蕊试液变红的溶液中:Ba 2+、Cu 2+、3NO -、Cl -C .含大量NaHSO4的溶液中:Na +、Ba 2+、OH -、3NO - D .溶液呈强碱性的溶液中:K +、Mg 2+、Cl -、23SO - 4.人们可从钛铁矿(主要成分FeTiO 3)制取金属钛(Ti ),其在一定条件下的主要反应有:①FeTiO 3+H 2 高温Fe +TiO 2+H 2O ;②TiO 2+2C +2Cl 2高温TiCl 4+2CO ; ③TiCl 4+2Mg 高温2MgCl 2+Ti下列叙述错误的是A .反应①中的H 2是还原剂B .反应②中钛元素失电子C .反应③是置换反应D .反应②中TiCl 4不是氧化产物5.设N A 为阿伏加德罗常数的值。
下列叙述正确的是A.0.1mol FeCl3完全转化为氢氧化铁胶体,生成0.1N A个胶粒B.5.6g铁与足量高温水蒸气完全转化为Fe3O4,转移电子数为0.3N AC.28g C2H4和CO的混合气体中含有的原子数为N AD.常温常压下,11.2L CO2所含的质子数小于11N A6.下列说法一定正确的是A.HCl和NH3的水溶液能导电,则HCl和NH3·H2O为电解质B.25℃时,醋酸溶液比醋酸钠溶液的导电能力弱C.NaHCO3的电离方程式为NaHCO3=Na++H++23CO-;D.CaCO3的水溶液不易导电,故CaCO3是弱电解质7.某溶液仅由Na+、Cu2+、Ba2+、Fe3+、CO32-、SO42-、Cl-中的若干种离子组成,取适量该溶液进行如下实验:根据以上实验判断,下列推断错误的是A.气体1通入澄清石灰水中,溶液变浑浊B.白色沉淀2中加稀硝酸,沉淀不溶解C.原溶液中一定存在Na+,一定不存在Cl-D.滤液2中加入碳酸钠溶液一定会产生白色沉淀8.用等体积的0.10mol·L-1 BaCl2溶液,可使相同体积的Al2(SO4)3、NH4Al(SO4)2、Na2SO4三种溶液中的24SO-恰好完全沉淀,则三种硫酸盐的物质的量浓度之比为A.3:2:3 B.2:3:6 C.2:6:3 D.1:1:19.下列说法正确的是A.NaHSO4溶液与过量Ba(OH)2溶液反应时,发生中和的OH-与未反应的OH-之比为1:1B.PbO2+4HCl=PbCl2+Cl2↑+2H2O中,氧化剂和还原剂物质的量之比为1:2 C.3S+6KOH△K2SO3+2K2S+3H2O中,被氧化的S和被还原的S质量比为2:1 D.3(NH4)2SO4△3SO2↑+N2↑+6H2O+4NH3↑中,发生氧化反应和未发生氧化反应的氮元素物质的量之比为2:1操作目的用分液漏斗分离水和酒精利用密度不同,使两者混合物分离加入新制生石灰,后经过滤得到乙醇制备饮用级高度酒将混合气体通入饱和Na2CO3溶液中洗气除去CO2中混有的HCl11.已知酸性:H2SO3>CH3COOH>H2CO3>HClO。
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成都七中高2023届高一上期半期考试
数 学
本试卷分选择题和非选择题两部分. 第Ⅰ卷(选择题)1至2页,第Ⅱ卷 (非选择题)3至4页,共4页,满分150分,考试时间120分钟.
注意事项:
1.答题前,务必将自己的姓名、考籍号填写在答题卡规定的位置上.
2.答选择题时,必须使用2B 铅笔将答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦擦干净后,再选涂其它答案标号.
3.答非选择题时,必须使用0.5毫米黑色签字笔,将答案书写在答题卡规定位置上.
4.所有题目必须在答题卡上作答,在试题卷上答题无效.
5.考试结束后,只将答题卡交回.
第Ⅰ卷 (选择题,共60分)
一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.
1.已知集合{}{}
212,,210,,M x x x Z N x x x x Z =−<<∈=−−<∈则M N =()
(A){}0,1 (B) {}1,0− (C){}0 (D) {}1−
2.函数()ln f x x =()
(A)[0,2] (B)(]0,2 (C)(0,+)∞ (D)(2,)+∞ 3.下列函数是偶函数的为()
(A)33,0(),0
x x f x x x ⎧≥=⎨−<⎩ (B)1()f x x x =−
(C) ())f x x = (D)1
()22x
x
f x =−
4.若函数2
2x y a +=+(0,a >且1a ≠)的图象恒过一定点P ,则P 的坐标为() (A)(0,1) (B)(2,1)− (C)(2,2)− (D)(2,3)−
5.已知3log 0.3,a =0.13,b =30.1c =,则()
(A)a b c << (B)c a b << (C)a c b << (D)b c a <<
6.下列结论正确的是()
1=− (B)lg(25)1+= (C)1383
()272
− = (D)24log 3log 6=
7.若幂函数222()()m
f x m m x =−−⋅在0(,)+∞单调递减,则2()f =()
(A)8 (B)3 (C)1−
(D)
1
2
8.Logistic 模型是常用的数学模型之一,可应用于流行病学领域,有学者根据公布的数据建立某地区流感累计确诊病例数()R t (t 的单位:天)的模型:601−=+()
()N t K
R t e ,其中K 为
最大确诊病例数, N 为非零常数,当1
2
=
*
()R t K 时,*t 的值为() (A)53 (B)60 (C)63 (D)66
9.函数1122
−
=
+()x x
x x f x 的大致图象为()
(A) (B)
(C) (D)
10.关于x 的方程210−++=()x a x a 的两个不等根12,x x 都在02(,)之内,则实数a 的取值范围为() (A)(0,2) (B)(0,1) (C)(1,2) (D)(0,1)(1,2)
11.若函数2
13
45()log ()f x x x =−++,则()f x 的单调递增区间为 ()
(A)(2,5) (B) (1,2)− (C)(2,)+∞
(D) (,2)−∞
12.已知定义在[)0,+∞上的函数()f x ,满足当[]0,2x ∈时,2,01
()42,12
x x f x x x ≤≤⎧=⎨−<≤⎩.
当2x >时,满足()(2)f x mf x =−,(m R m ∈为常数),则下列叙述中正确为()
①当1
2
m =时,(3)1;f = 01<<m ②时,函数()f x 的图象与直线1*
2,−=∈n y m n N []0,2n 在上的交点个数为21;n −③当1m >时,24()x m mf x ≥在[)0,+∞上恒成立.
(A)①②
(B)②③ (C)①③
(D)①②③
第Ⅱ卷 (非选择题,共90分)
二、填空题:本大题共4小题,每小题5分,共20分.把答案填在答题卡上.
13. 若1
3,x x
−+=则22x x −+的值为 .
14. 已知函数4log ,0()3,0
x x x f x x −>⎧=⎨≤⎩,则1
[()]4f f =___________.
15.函数()(8),(0,8)f x x x x =−∈的最大值为 .
16. 已知函数()(),,f x x x m m R =−∈若()f x 在区间[]12,上的最大值为3,则
=m .
三、解答题:本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.
17.(本小题满分10分)
已知集合{}
{}2
|12200,|2A x x x B x m x m =−+≤=≤≤+.
(1)若[]2,11B A =,求实数m 的值;
(2)若(),R B
A =∅求实数m 的取值范围.
18.(本小题满分12分) 计算下列各式的值:
(1)0
2)+ (2)92log 266
3log 4log 3.2
++
19.(本小题满分12分)
声强级1L (单位dB )由公式112
1010
−=lg(
)I
L 给出,其中I 为声强(单位2/W m ). (1)若航天飞机发射时的最大声强是2
10000/W m ,求其声强级;
(2)一般正常人的听觉声强级的范围为[]
0120,(单位dB ), 求其声强的取值范围.
20.(本小题满分12分) 已知函数()f x 是定义在00(,)
(,)−∞+∞上的偶函数,当0x >时2
32,(),
f x ax ax =−+()∈a R .
(1)求()f x 的函数解析式;
(2)当1a =时,求满足不等式21log ()f x >的实数x 的取值范围.
21.(本小题满分12分)
已知函数()f x 为偶函数,()g x 为奇函数,且1
−=()().x f x g x e
(1)求函数()f x 和()g x 的解析式;
(2)若2()()f x ag x >在1∈+∞(,)x 恒成立,求实数a 的取值范围; (3)记111+=++()
(),()
g x H x f x 若∈,,a b R 且1+=,a b 求41−+++()()H a H b 的值.
22. (本小题满分12分)
已知函数=())g x x 若()g x 是定义在R 上的奇函数. (1)求a 的值;
(2)判断函数的单调性,并给出证明,若2
221+>+()()g bx g x 在[]23,上有解,求实数b
的取值范围;
(3)若函数1
()122
f x x =−−,判断函数[]()()y f f x
g x =−−在区间[]0,1上的零点个数,并说明理由.。