【英语】吉林省东北师大附中2015届高三上学期第三次摸底考试
东北师大附中高三第三次摸底考试(英语)
2009—2010学年“拼搏一年·成就梦想”高三年级第三次摸底考试英语学科试卷此试卷分第I卷（选择题）和第II卷（非选择题）两部分。
满分150分时间120分钟第I卷（选择题，共105分）第一部分听力理解（共两节，满分20分）该试题分为第一、第二两节。
注意：回答听力部分时，请先将答案标在试卷上，听力部分结束前，你将有时间将你的答案转涂到客观题答题卡上。
第一节（共5小题；每题1分，满分5分）听下面五段对话，每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. When will Susan arrive?A. At 4:30.B. At 4:45.C. At 5:20.2. Why can’t the woman go to see the film today?A. Because she is not feeling well.B. Because she doesn’t like the film.C. Because she has another plan.3. How much is the jacket?A. 600 US dollars.B. 100 Hong Kong dollars.C. 600 Hong Kong dollars.4. What does the man have for this meal?A. Soup, noodles and iced coffee.B. A sandwich, noodles and hot coffee.C. Soup, noodles and hot coffee.5. Who is Mr. Smith?A. A friend of the girl’s father’s.B. The girl’s brother.C. The girl’s father.第二节（共15小题；每题1分，满分15分）听下面五段对话或独白，每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
等差数列的基本性质
等差数列一、等差数列的定义以及证明方法：1、定义：若数列{a n }中，对于任意两项a n ，a n -1均有：a n -a n -1=d （d 为常数），则数列{a n }为等差数列.注意一些等差数列的变形形式，如：111n n d a a +-=（d 为常数，此时，数列{1na }为等差数列）d =(d为常数，此时，数列⎧⎫为等差数列) ……2、证明方法：（1）定义法：若数列{a n }中，对于任意两项a n ，a n -1均有：a n -a n -1=d （d 为常数），则数列{a n }为等差数列.（2）等差中项法：2a n+1=a n +a n+2（3）通项公式法：若数列{a n }的通项公式为a n =pn+q 的一次函数，则数列{a n }为等差数列. （4）若数列{a n }的前n 项和为S n =An 2+Bn ，则数列{a n }为等差数列.【例题1】【2013年，北京高考（文）】给定数列a 1，a 2，a 3，……，a n ，……，对i =1，2，……，n-1，该数列的前i 项的最大值记为A i ，后n –i 项a i+1，a i +2，……，a n 的最小值记为B i ，d i =A i –B i .(I)设数列{a n }为3，4，7，1，求d 1，d 2，d 3的值.(II)设d 1，d 2，……，d n -1是公差大于0的等差数列，且d 1>0，证明：a 1，a 2，a 3，……，a n -1是等差数列.3、等差数列的通项公式：（1）等差数列的通项公式：a n =a 1+(n-1)d 累加法和逐项法：对于形如1nna a f n 的形式，我们一般情况下，可以考虑使用逐项法或者累加法，从而达到求a n 的目的.变形形式： a n =a m +(n-m )d由以上公式可以得到：n ma a d n m-=-（2）等差数列通项公式的一些性质：①若实数m,n,p,q 满足：m+n=p+q ，则：n m p q a a a a +=+；特别的，若m+n=2p ，则：2n m p a a a +=；②若数列{a n }为等差数列，则下标成等差数列的新数列仍然成等差数列；③若数列{a n }为等差数列，数列{b n }为等差数列，则数列{pa n +qb n }还是等差数列； ④当d >0时，{a n }为递增数列；当d =0时，数列{a n }为常数列；当d <0时，数列{a n }为递减数列；【例题1】【2015届黑龙江省双鸭山一中高三上学期期末考试，3】在等差数列{}n a 中,首项01=a ,公差,0≠d 若7321a a a a a k ++++= ,则k =（ ）A . 22B . 23C . 24 D. 25【变式训练】【2015届吉林省东北师大附中高三上学期第三次摸底考试，3】设等差数列{}n a 的前n 项和为n S ，若151,15a S ==，则6a 等于 （ ） A .8 B .7 C .6 D .5 4、等差数列的求和问题：——方法：倒序相加()()()111111222n n n n n nS a a a a n d na d -=+=++-=+⎡⎤⎣⎦ （1）在等差数列{a n }中，k S ，2k k S S -，32k k S S -成等差数列；或者：()233k k k S S S -=； （2）奇偶项问题：在等差数列中，若项数为偶数项，即：当n=2m （n,m ∈N*）时，有：S 偶-S 奇=md ，1=mm S a S a +奇偶；如果项数为奇数，即当n=2m+1时，此时，()()121121212m m m S a a m a +++=+=+⋅； 1=S m S m +奇偶，项数n=+-S S S S 奇偶奇偶. （3）若两个数列{a n }和{b n }均为等差数列，其前n 项和和前m 项和分别为S n 和T m ，则有：21212121n n m m a S m b n T ---=⋅-，当m=n 时，则：2121n n n n a S b T --= （4）等差数列前n 项和的最值问题： 由()2111222n n n d d S na d n a n -⎛⎫=+=+- ⎪⎝⎭以及二次函数的知识可知，当d >0时，抛物线的开口向上，此时有最小值；当d <0时，抛物线的开口向下，此时函数有最大值。
吉林省东北师大附中2015届高三上学期第三次摸底考试数学(理)试题 Word版含解析
吉林省东北师大附中2015届高三上学期第三次摸底考试数学（理科）试卷【试卷综述】本试卷是高三理科试卷，以基础知识和基本技能为载体，以能力测试为主导，在注重考查学科核心知识的同时，突出考查考纲要求的基本能力，重视学生科学素养的考查.知识考查注重基础、注重常规、注重主干知识，兼顾覆盖面.试题重点考查：集合、不等式、向量、导数、数列、充要条件等；考查学生解决实际问题的综合能力，是份较好的试卷。
说明：本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，总分150分，考试时间120分钟.注意事项：1. 答题前，考生在答题卡上务必用直径0.5毫米黑色墨水签字笔将自己的姓名、准考证号填写清楚，并贴好条形码，请认真核准该条形码上的准考证号、姓名和科目.2. 每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其它答案标号，在试卷上作答无效.第Ⅰ卷（选择题，共60分）【题文】一．选择题：本大题共12小题，每小题5分，共60分．在每小题给出的四个选项中，只有一项是符合题目要求的．【题文】（1）设集合{||1|2}A x x =-<，1{|24}x B x +=≥，则AB = （ ）（A ） [0,2] （B ）(1,3) （C ）[1,3) （D ）(1,4) 【知识点】集合的运算A1【答案】【解析】C 解析：{|13}A x x =-<<，{|1}B x x =≥，{|13}A B x x ∴=≤< 故选C.【思路点拨】化简集合A ，B ，直接计算即可.【题文】（2）若命题:p 2000,13x R x x ∃∈+>，则p ⌝是 ( )（A ）2000,13x R x x ∃∈+≤ （B ）2,13x R x x ∀∈+≤（C ）2,13x R x x ∀∈+< （D ）2,13x R x x ∀∈+> 【知识点】特称命题的否定A3【答案】【解析】B 解析：由定义可得p ⌝为2,13x R x x ∀∈+≤，故选B. 【思路点拨】特称命题的否定是全称命题.【题文】（3）设等差数列{}n a 的前n 项和为n S ，若151,15a S ==，则6a 等于 （ ）（A ） 8 （B ）7 （C ）6 （D ）5【知识点】等差数列D2 【答案】【解析】C 解析：155551552a a S a +=⨯=∴=，公差1d =，所以66a =， 故选C.【思路点拨】由等差数列性质计算可得，也可由515S =直接求公差.【题文】（4）“1<λ”是数列“)(22*∈-=N n n n a n λ为递增数列”的 （ ）（A ）充分不必要条件 （B ）必要不充分条件 （C ）充要条件 （D ）既不充分也不必要条件 【知识点】充分必要条件A2 【答案】【解析】A 解析：由“1<λ”可得][221[] 12122210n n a a n n n n n λλλ+-=+-+--=-+（）（）＞，故可推出“数列)(22*∈-=N n n n a n λ为递增数列”，故充分性成立．由“数列)(22*∈-=N n n n a n λ为递增数列”可得][221[]12122210n n a a n n n n n λλλ+-=+-+--=-+（）（）＞，故212n λ+＜， 即32λ＜，不能推出“1<λ”，故必要性不成立．因此“1<λ”是“数列)(22*∈-=N n n n a n λ为递增数列”的充分不必要条件，故选A. 【思路点拨】由“1<λ”可得1 0n n a a +-＞，推出“数列)(22*∈-=N n n n a n λ为递增数列”．由“数列)(22*∈-=N n n n a n λ为递增数列”，不能推出“1<λ”，由此得出结论．【题文】（5）在等比数列{}n a 中，若452,5a a ==，则数列{lg }n a 的前8项和等于 （ ） （A ） 6 （B ）5 （C ）4 （D ）3【知识点】等比数列 D3【答案】【解析】C 解析：因为452,5a a ==，4510a a ∴⋅=，4412781281845lg lg lg lg lg()lg()lg()4lg104a a a a a a a a a a a +++++=====，故选C.【思路点拨】4518a a a a ⋅=⋅，结合对数运算性质得4412781845lg lg lg lg lg()lg()a a a a a a a a +++++==即可求解.【题文】（6）设α，β都是锐角，且55cos =α，10sin()10αβ-=，则=βcos （ ） （A ）22 （B ）210- （C ）22或210- （D ）22或210【知识点】两角和与差的余弦公式C5【答案】【解析】A 解析：cos cos[()]cos cos()sin sin()βααβααβααβ=--=-+-，由题意可得25310sin ,cos()510ααβ=-=，代入得2cos 2β=，故选A. 【思路点拨】注意到角的变换()βααβ=--，再利用两角差的余弦公式计算可得结果. 【题文】（7）已知函数2()2sin 222cos f x x x =-，则()f x 的最小正周期T 和其图像的一条对称轴方程是 ( ) （A ）2,8x ππ=（B ）32,8x ππ=（C ）,8x ππ= （D ）3,8x ππ= 【知识点】三角函数图像与性质C3 【答案】【解析】D 解析：2()2sin 222cos 2sin 22(1cos 2)f x x x x x =-=-+2sin(2)24x π=--，T π∴=，对称轴32,4228k x k x πππππ-=+∴=+，当0k =时，38x π=，故选D.【思路点拨】先化简()2sin(2)24f x x π=--即可求周期与对称轴方程.【题文】（8）已知函数2()ln 3,f x x x x =+-则其导函数'()f x 的图像与x 轴所围成的封闭 图形的面积为 （ ）（A ）ln 2 （B ）3ln 24- （C ）3ln 24+ （D ）32 【知识点】定积分的应用B13【答案】【解析】B 解析：()1'23f x x x =+-令()'0f x =,得：12x =或1, 所以'()f x 的图像与x 轴所围成的封闭图形的面积为：1'111221()()|()(1)2f x dx f x f f -=-=-⎰1133(ln )(ln113)ln 22424=+--+-=-,故选B.【思路点拨】由题可得'()f x 的图像与x 轴所围成的封闭图形的面积为：1'111221()()|()(1)2f x dx f x f f -=-=-⎰，代入计算可得结果.【题文】（9）已知0,0,lg 2lg8lg 2x yx y >>+=，则113x y+的最小值是 ( ) （A ）4 （B ）3 (C) 2 (D) 1 【知识点】基本不等式E6【答案】【解析】A 解析：由题得333y lg2lg2lg(22)lg2lg2x y x y x ++=⨯==，所以31x y +=，11113(3y)()(2)333y x x x y x y x y+=++=++224≥+=，当且仅当33y xx y=，即22(3)x y =，11,26x y ==时等号成立，故选A. 【思路点拨】】由题得31x y +=，做变换11113(3y)()(2)333y x x x y x y x y+=++=++即可利用基本不等式求解.【题文】（10）若函数)(x f 的定义域为R ，2)(>'x f 恒成立，2)1(=-f ，则42)(+>x x f 解集为（ ）（A ）(,1)-∞- （B ）(,1)-∞ （C ）(1,1)- （D ）(1)-+∞， 【知识点】导数的应用B12【答案】【解析】D 解析：令()()(24)g x f x x =-+，要求42)(+>x x f ，就是求()0g x >，g'()()20x f x '=->，所以函数()g x 在R 上单调递增，而(1)(1)20g f -=--=，()0(1)g x g >=-，即1x >-，故选D.【思路点拨】构造函数()()(24)g x f x x =-+，得g'()()20x f x '=->，得函数()g x 在R 上单调递增，又(1)0g -=，所以()0(1)g x g >=-，可求其解集. 【题文】（11）设01a <≤，函数x x x g xax x f ln )(,)(-=+=，若对任意的12,[1,]x x e ∈，都有12()()f x g x ≥成立，则a 的取值范围为 （ ）（A ）(0,1] （B ）(0,2]e - （C ）[2,1]e - （D ）1[1,1]e- 【知识点】函数综合B14【答案】【解析】C 解析：令222'()1a x af x x x-=-=，11'()1x g x x x -=-=， [1,e]x ∈，01a <≤，'()0,'()0f x g x ∴>>，即(),()f x g x 在[1,e]x ∈时单调递增，由对任意的12,[1,]x x e ∈，都有12()()f x g x ≥成立，所以min max ()()f x g x ≥，即(1)()f g e ≥，112a e a e ∴+≥-∴≥-，又01a <≤，得21e a -≤≤，故选C.【思路点拨】由题意可得(),()f x g x 在[1,e]x ∈时单调递增，要使对任意的12,[1,]x x e ∈，都有12()()f x g x ≥成立，只需min max ()()f x g x ≥.【题文】（12）定义函数348,12,2()1(), 2.22x x f x x f x ⎧--⎪⎪=⎨⎪>⎪⎩≤≤，则函数()()6g x xf x =-在区间[1,2](n n *)∈N 内的所有零点的和为 ( )（A ）31(1)42n - （B ）31(1)22n - （C ）3(21)4n - （D ）3(21)2n -【知识点】根的存在性及根的个数判断 B5【答案】【解析】D 解析：当312x ≤≤时，88f x x =-（）， 所以()2(82)18g x x =--，此时当32x =时，0max g x =（）；当322x ≤＜时，168f x x =-（），所以28120g x x =--+（）（）＜；由此可得12x ≤≤时，0max g x =（）． 下面考虑122n n x -≤≤且2n ≥时，g x （）的最大值的情况．当12232n n x --≤≤⋅时，由函数f x （）的定义知()11112()2)(22n n xf x f f x --==⋯=, 因为13122n x -≤≤，所以()2225(1282)n n g x x --=--， 此时当232n x -=⋅时，0max g x =（）；当2322n n x -⋅≤≤时，同理可知()1225(182)20n n g x x --=--+，＜．由此可得122n n x -≤≤且2n ≥时，0max g x =（）．综上可得：对于一切的*n N ∈，函数g x （）在区间12]2[n n-，上有1个零点，从而g （x ）在区间[1]2n ，上有n 个零点，且这些零点为232n n x -=⋅，因此，所有这些零点的和为3(221)n-．故选D. 【思路点拨】函数f x （）是分段函数，要分区间进行讨论，当12x f x ≤≤，（）是二次函数，当2x ＞时，对应的函数很复杂，找出其中的规律，最后作和求出．第Ⅱ卷（非选择题 共90分）【题文】二、填空题（本大题共4小题, 每小题5分, 共20分） 【题文】（13）函数221()(0)41x f x x x +=>+的最大值为 ；【知识点】函数的最值B3 【答案】【解析】212+解析：令21t x =+（1t >），原式222t t t =-+122t t=+-，（1） 222t t +≥，（1）式1212222+≤=-，故最大值为212+. 【思路点拨】令21t x =+（1t >），原式222tt t =-+122t t=+-，利用基本不等式即可 求解.【题文】（14）在ABC △中，内角A B C 、、所对的边的长分别为a b c 、、，且2()a b b c =+，则BA= ； 【知识点】余弦定理C8【答案】【解析】12解析：2a b b c =+（），即222a a b bc b c b=++=，，∴由正弦、余弦定理化简得：2222222a c b c bc b c cosB ac ac a +-++===2222a a sinAab b sinB===，则2sinA sin B =，即2A B =或2A B π+=，2222a b c bccosA =+-，且22a b b c b bc =+=+（），22222222b c a b c b bccosA bc bc +-+--∴== ()02c c b bc -=＞ ，即2c b C B A B C A B ππ∴++=∴+＞，＞，，＜，故2A B π+=不成立，舍去，2A B ∴=，则12B A =．故答案为12. 【思路点拨】利用余弦定理列出关系式，将已知等式变形为22a b bc =+代入，约分后再将2a b c b+=代入，利用正弦定理化简得到22sinA sinBcosB sin B ==，进而得到2A B =，即可求出所求式子的值．【题文】（15）函数()ln()(0)f x x ax a =<的递增区间是 ； 【知识点】函数的单调性B3【答案】【解析】1(,)ae-∞解析：0a <，∴ 定义域为(,0)-∞，'()ln()1f x ax =+，当'()0f x >时，函数()f x 递增，此时110ax x e ae >∴<<，故递增区间为1(,)ae -∞.【思路点拨】求单调区间先求定义域，再根据'()0f x >解出x 的范围即可.【题文】（16）已知数列}{n a 中，12122,5,23(3)n n n a a a a a n --===+≥，则20193a a -= .【知识点】递推公式D5【答案】【解析】1- 解析：由1223n n n a a a --=+，得112333n n n n a a a a n ----=--≥（）（）， 122125353210a a a a ==∴-=-⨯=-≠，，，∴数列{}13n n a a --是以1-为首项，以1-为公比的等比数列，20193a a -是这个数列的第19项，18201931(1)1a a -=-⨯-=-， 故答案为1-.【思路点拨】把给出的数列递推式变形，得到等比数列{}13n n a a --，求出其通项公式即可. 【题文】三、解答题（本题共6小题, 共70分.解答应写出文字说明、证明过程或演算步骤） 【题文】（17）（本小题满分10分） 已知ABC ∆是斜三角形，内角A B C 、、所对的边的长分别为a b c 、、．己知C a A c cos 3sin =．（I ）求角C ；（II ）若c =21，且sin sin()5sin 2,C B A A +-= 求ABC ∆的面积. 【知识点】余弦定理 正弦定理C8 【答案】【解析】（I ）3C π=（II ）534解析：（I ）根据正弦定理a csinA sinC= ，可得csin A asinC =， sinA 3cos ,sin 3cos c a C a C a C =∴=，可得sin 3cos C C =，得3sinC tanC cosC ==,03C C ππ∈∴=（，），； （II ）sin sin(B A)5sin 2A,C 3C π+-==sin sin()C A B ∴=+sin(A B)sin(B A)5sin 2A ∴++-=，2sin cosA 25sin cos B A A ∴=⨯ A B C 、、为斜三角形，cos 0A ∴≠，sinB 5sinA ∴=，由正弦定理可知5b a = (1)由余弦定理2222cos c a b ab C =+-2212122a b ab ∴=+-⨯ (2)由（1）（2）解得5,1a b ==11353sin 152224ABCSab C ∴==⨯⨯⨯=. 【思路点拨】（I ）根据正弦定理算出csin A asinC =，与题中等式比较可得3tanC =，结合C 为三角形内角，可得C 的大小；（II ）余弦定理2222cos c a b ab C =+-的式子，列式解出5,1a b ==，再利用三角形的面积公式加以计算，即可得到ABC 的面积．【题文】（18）（本小题满分12分）已知等比数列{}n a 为递增数列，且251021,2()5n n n a a a a a ++=+=，N n *∈.（Ⅰ）求n a ；（Ⅱ）令1(1)n n n c a =--，不等式2014(1100,N )k c k k *≥≤≤∈的解集为M ，求所有()k a k M ∈的和.【知识点】数列递推式；等比数列的通项公式；数列的求和D5 D3 D4【答案】【解析】（I ）2nn a =（II ）11451012142204814()3--=-解析：. （Ⅰ）设{}n a 的首项为1a ，公比为q ，42911()a q a q ∴=，解得1a q =， 又221(2525)n n n n n n a a a a a q a q +++=∴+=（），,则2215q q +=（），22520q q -+=解得12q =（舍）或2q =．1222n n n a -∴=⨯=． （Ⅱ）由（I ）可得：()()1112nnn n c a =--=--，当n 为偶数，122014n n c =-≥，即22013n≤-，不成立． 当n 为奇数122014n n c =+≥，即22013n≥，1011210242204821549n m m ==∴=+≤≤，，，，{}k a k M ∴∈（）组成首项为112，公比为4的等比数列． 则所有k a k M ∈（）的和11451012142204814()3--=-． 【思路点拨】（Ⅰ）设{}n a 的首项为1a ，公比为q ，由2510a a =，可得42911()a q a q =，解得1a q =．再利用2125n n n a a a +++=（），可得q ，即可得出n a ．（II ）由（I ）可得()()1112n nn n c a =--=--．当n 为偶数，不成立．当n 为奇数，122014n n c =+≥，可得21n m =+，得到m 的取值范围．可知k a k M ∈（）组成首项为211，公比为4的等比数列,求出即可． 【题文】(19)（本小题满分12分）某高中数学竞赛培训在某学段共开设有初等代数、平面几何、初等数论和微积分初步共四门课程，要求初等数论、平面几何都要合格，且初等代数和微积分初步至少有一门合格，则能取得参加数学竞赛复赛的资格.现有甲、乙、丙三位同学报名参加数学竞赛培训，每一位同学对这四门课程考试是否合格相互独立，其合格的概率均相同（见下表），且每一门课程是否合格相互独立. 课 程来初等代数 平面几何 初等数论 微积分初步合格的概率3243 32 21 （Ⅰ）求乙同学取得参加数学竞赛复赛的资格的概率；（Ⅱ）记ξ表示三位同学中取得参加数学竞赛复赛的资格的人数，求ξ的分布列及期望ξE ． 【知识点】二项分布与n 次独立重复试验的模型；古典概型及其概率计算公式；离散型随机变量的期望与方差K6 K2 K8 【答案】【解析】（I ）512（II ）54解析：（1）分别记甲对这四门课程考试合格为事件A ，B ，C ，D ，且事件A ，B ，C ，D 相互独立，“甲能能取得参加数学竞赛复赛的资格”的概率为：P ABCD P ABCD P ABCD ++=（）（）（）322132213211543324332433212⋅⋅⋅+⋅⋅⋅+⋅⋅⋅= ． （2）由题设知ξ的所有可能取值为0，1，2，3，5312B ξ～（，），03373430121728()PC ξ===（），213577351()()12121728P C ξ===（），223575252()()12121728P C ξ===（）， 33351253()121728P C ξ===（） ，ξ∴的分布列为：5312B ξ～（，）,512534E ξ∴=⨯=． 【思路点拨】（I ）分别记甲对这四门课程考试合格为事件A ，B ，C ，D ，“甲能能取得参加数学竞赛复赛的资格”的概率为P ABCD P ABCD P ABCD ++（）（）（），由事件A ，B ，C ，D 相互独立能求出结果．（II ）由题设知ξ的所有可能取值为0，1，2，3，5312B ξ～（，），由此能求出ξ的分布列和数学期望．【题文】(20) （本小题满分12分）如图，在三棱柱111ABC A B C -中，1A A ⊥平面ABC ，90BAC ︒∠=，F 为棱1AA 上的动点，14,2A A AB AC ===．（Ⅰ）当F 为1A A 的中点，求直线BC 与平面1BFC 所成角的正弦值； （Ⅱ）当1AFFA 的值为多少时，二面角1B FC C --的大小是45︒．【知识点】与二面角有关的立体几何综合题；异面直线及其所成的角G12 G10 【答案】【解析】（I ）63（II ）153AF FA = 解析：（1）如图，以点A 为原点建立空间直角坐标系，依题意得11000200020004024A B C A C （，，），（，，），（，，），（，，），（，，），F 为1AA 中点，02(0)F ∴，，，1()()(202224220)BF BC BC =-=-=-，，，，，，，，，设()n x y z =，，是平面1BFC 的一个法向量，则12202240n BF x z BC x y z n ⎧⎪⎨⎪⎩=-+==-++= ，得x y z =-=, 取1x =，得1)1(1n =-，，， 设直线BC 与平面1BFC 的法向量1)1(1n =-，，的夹角为θ， 则463||||223BC n cos BC n θ-===-⋅⋅， ∴直线BC 与平面BFC 1所成角的正弦值为63．…（5分） （2）设()0,0(,04)F t t ≤≤，1()2,0,4()22BF t BC =-=-，，，， 设()n x y z =，，是平面1BFC 的一个法向量，则1•20•2240n BF x tz n BC x y z ⎧⎪=-+==-+⎨⎩=⎪+， 取2z =，得4)2(n t t =-，，,(2)00AB =，，是平面1BFC 的一个法向量，||||n ABcos n AB n AB =＜，＞()22222244t t t =+-+=，得52t =， 即15322AF FA ==，， ∴当153AF FA =时，二面角1B FC C --的大小是45︒．…（10分） 【思路点拨】（I ）以点A 为原点建立空间直角坐标系，利用向量法能求出直线BC 与平面1BFC 所成角的正弦值．（II ）求出平面1BFC 的一个法向量，利用向量法能求出当153AF FA =时，二面角1B FC C --的大小是45︒.【题文】(21) （本小题满分12分）已知双曲线C 的中心在坐标原点，焦点在x 轴上，离心率5,2e =虚轴长为2. （Ⅰ）求双曲线C 的标准方程；（Ⅱ）若直线:l y kx m =+与双曲线C 相交于A ，B 两点（A B ，均异于左、右顶点），且以AB 为直径的圆过双曲线C 的左顶点D ，求证：直线l 过定点，并求出该定点的坐标．【知识点】直线与双曲线H8【答案】【解析】（Ⅰ）2214x y -=（Ⅱ）直线l 过定点，定点坐标为1003⎛⎫- ⎪⎝⎭， 解析：（Ⅰ）由题设双曲线的标准方程为22221(0,b 0)x y a a b -=>>，由已知得：52c a =，22b =，又222a b c +=，解得2,1a b ==，∴双曲线的标准方程为2214x y -=.（Ⅱ）设1122(x ,y ),(x ,y )A B ，联立2214y kx m x y =+⎧⎪⎨-=⎪⎩ ，得 222(14k )84(m 1)0x mkx ---+=，有2222212221221406416(14k )(m 1)08014k 4(m 1)014kk m k mk x x x x ⎧->⎪∆=+-+>⎪⎪⎨+=<-⎪⎪-+⎪=>⎩- ， 22221212121224(k )(k )k ()14m k y y x m x m x x mk x x m k-=++=+++=- ，以AB 为直径的圆过双曲线C 的左顶点(2,0)D -，1AD BD k k ∴=-，即1212122y yx x ⋅=-++， 1212122()40y y x x x x ∴++++=22222244(1)1640141414m k m mk k k k--+∴+++=---，22316200m mk k ∴-+=．解得：12m k =，2103km =. 当12m k =时，l 的方程为(2)y k x =+，直线过定点(20)-，，与已知矛盾； 当2103k m =时，l 的方程为103y k x ⎛⎫=+ ⎪⎝⎭，直线过定点1003⎛⎫- ⎪⎝⎭，，经检验符合已知条件． 所以，直线l 过定点，定点坐标为1003⎛⎫-⎪⎝⎭，．【思路点拨】（Ⅰ）由已知得：52c a =，22b =，易得双曲线标准方程； （Ⅱ））设1122(x ,y ),(x ,y )A B ，联立2214y kx mx y =+⎧⎪⎨-=⎪⎩ ，得 222(14k )84(m 1)0x mkx ---+=，以AB 为直径的圆过双曲线C 的左顶点(2,0)D -，1AD BD k k ∴=-，即1212122y yx x ⋅=-++，代入即可求解. 【题文】 (22)（本小题满分12分） 已知函数()()2ln(1)af x x a R x=-+∈ （Ⅰ）求函数)(x f 的单调区间； （Ⅱ）设,m n 是正数，且m n ≠，求证：ln ln 2m n m nm n -+<-. 【知识点】利用导数研究函数的单调性B12【答案】【解析】（I ）当02a ≤≤时，()f x 的递增区间为(1,)+∞；当0a <或2a >时，()f x 的递增区间为22(1,2),(2,)a a a a a a --+-+∞，减区间为22(2,2)a a a a a a --+-.（II ）略解析：（I ）函数)(x f 的定义域为(1,)+∞，22212221(1)a x ax af x x x x x -+'=-=--（）， 令2()22h x x ax a =-+，由题意得2(1)0x x ->，则2484(2)a a a a ∆=-=-，对称轴为x a =，（1）当02a ≤≤时，()0h x ≥，即0f x '≥（），()f x 在(1,)+∞上递增； （2）当0a <或2a >时，()0h x =的两根为212x a a a =--，222x a a a =+-，由(1)12210h a a =-+=>，2a >，得121x x <<，当12(,)x x x ∈时，()0h x <，0f x '<（），()f x 递减；当12(1,)(,)x x x ∈+∞时，()0h x >，0f x '>（），()f x 递增，所以()f x 的递增区间为22(1,2),(2,)a a a a a a --+-+∞，减区间为22(2,2)a a a a a a --+-.（II ）要证2m n m nlnm lnn -+-＜，只需证112m m n nm nln -+＜， 即21()1m m n l n n m n -+＞ ，即()2101m n n l mn m n--+＞，设()211x g x lnx x -=-+（）， 由题知g x （）在1+∞（，）上是单调增函数，又1m n ＞， 所以10mg g n=（）＞（）， 即()2101m n n l mn m n--+＞ 成立，得到2m n m n lnm lnn -+-＜． 【思路点拨】（I ）求出函数的导数，对a 分情况讨论，（1）当02a ≤≤时，（2）当0a <或2a >时，求出导数为0的根，即可得到单调区间；（II ）把所证的式子利用对数的运算法则及不等式的基本性质变形，即要证()2101m n n l m n m n--+＞，根据题意得到g x （）在1x ≥时单调递增，且1m n ＞，利用函数的单调性可得证．。
英语高考模拟卷-吉林市2015届高三第三次模拟考试英语试题及答案
吉林省吉林市2015届高三第三次模拟考试英语试题本试卷分第I卷（选择题）和第II卷（非选择题）。
第I卷1至10页，第II卷10至12页。
共150分。
考试时间120分钟。
注意事项：请按照题号顺序在答题纸上各题目的答题区域内作答，超出答题区域书写的答案无效；在草稿纸、试题卷上答题无效。
第I卷第一部分：听力（共两节, 满分30分）第一节（共5小题；每小题1.5分, 满分7.5分）听下面5段对话。
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听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What have they decided to do?A. Visit an exhibition.B. Study about planes and satellites.C. Fly in a plane.2. Where does the conversation probably take place?A. In a bookstore.B. In a lab.C. In a library.3. How long does it take the man to drive home after 5 p.m.?A. 35 minutes.B. 20 minutes.C. 15 minutes.4. What does the woman think of the piano lessons?A. They are very boring.B. They are too expensive.C. They are very interesting.5. What did the woman suggest?A. Finding a new place for the typewriter.B. Finding a better typist.C. Buying a new typewriter.第二节(共15小题;每小题1.5分, 满分22.5分)听下面5段对话或独白。
东北师大附中—上学期高三英语第三次摸底考试
东北师大附中2007—2008学年度上学期高三第三次摸底考试英语试题本试卷分第一卷（选择题）和第二卷（非选择题）两部分第Ⅰ卷注意事项：1．答第一卷前，考生务必将自己的姓名、准考证号、考试科目涂写在答题卡上。
2．每小题选出答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
不能答在试题卷上。
请将补全对话及主观题部分答到答题页上。
第一部分英语知识运用（共三节，满分50分）第一节语音知识（共5小题；每小题1分，满分5分）从A、B、C、D四个选项中，找出其划线部分与所给单词的划线部分读音相同的选项，并在答题卡上将该项涂黑。
例：have A．gave B．save C．hat D．made 答案是C。
1．vital A．strict B．evident C．violent D．combination 2．tension A．division B．comprehension C．television D．persuasion 3．smooth A．goose B．blood C．childhood D．footprint 4．charity A．schedule B．machine C．choir D．bachelor 5．expectation A．experience B．example C．expand D．extra第二节语法和词汇知识（共15小题；每小题1分，满分15分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
例：We last night, but we went to the concert instead．A．must have studied B．might studyC．should have studied D．would study答案是C。
6．With _____ computer, seeing a free movie is _____ practical reality for some families.A．/, a B．the, the C．a, a D．a, /7．—What makes life ________ in your opinion?—To love and to be loved.A．worth B．worthy C．worthwhile D．worthy of 8．Professor Hawking is ____ as one of the world's greatest living physicists.A．proved B．clarified C．acknowledged D．admitted9．It was two years ______ he came back from abroad.A．since B．that C．when D．before10．________, scientists are still working hard to try to find other forms of energy to make use of.A．Limitless as the solar energy is B．Limitless is the solar energyC．As the solar energy is limitless D．Limitless as the solar energy11．David Beckham has ________ it takes to be a professional footballer.A．who B．what C．which D．that12．China has made _____ progress in taking action to ensure safety of toys and other products exported to Europe.A．considerable B．considering C．considerate D．considered 13．This year’s fall in profits was not unexpecte d. _____, it is very disappointing.A．Yet B．But C．Also D．Nevertheless 14．Tom ______ quiet and no one else would have known about the mistake.A．could have kept B．could keepC．should keep D．must have kept15．—Is Danny going abroad?—I think so. He _____ for a better job, but he didn’t get it.A．hopes B．had hoped C．was hoped D．has hoped 16．Make ______ a habit to put whole-grain biscuits and nuts in your backpack.A．/ B．this C．that D．it17．_____ one can control his/her body movement in the air is a decisive factor _____ one wants to be a really good skateboarder.A．How well; if B．How soon; unlessC．How often; until D．How high; till18．The boy spent as much time watching TV as he _____ studying.A．would B．was C．had D．did 19．Teleworking means people save time previously _____ to work, and _____ them to be more flexible in working hours.A．spent in traveling; allows B．spent traveling; allowsC．spends traveling; allow D．spent traveling; allowing20．Everyone should keep on getting himself educated so as to be _____ modern technology.A．good at B．successful inC．up to date with D．interested in第三节完形填空（共20小题；每小题1.5分，满分30分）阅读下面短文，从短文后所给各题的四个选项（A、B、C和D）中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
2017高三英语北师大版一轮语法专题7 非谓语动词
语法专题七非谓语动词1.(2015课标全国Ⅰ,语法填空)A study of travelers (conduct) by the website TripAdvisor names Yangshuo as one of the top 10 destinations in the world.2.(2015课标全国Ⅱ,语法填空)When a new day breaks,the walls have given up their heat and are now cold enough (cool) the house during the hot day. 〚导学号03730016〛3.(2015重庆)(raise) in the poorest area of Glasgow,he had a long,hard road to becoming a football star. 〚导学号03730017〛4.(2015湖南)Video games can be a poor influence if (leave) in the wrong hands.5.(2015河南洛阳12月统考)In a single moment I felt the heaviness of the day (transform) into lightness of a feather.6.(2015山西四校联考)So she developed her love of (read).7.(2015四川宜宾一诊)(bury) in heavy schoolwork,most senior three students have no free time to do what they want.8.(2015广州调研)The officer,after (recover) from the shock,began yelling at Sam.9.(2015安徽黄山第二次质检)(compete) more effectively with others,more and more people equip themselves with higher education.10.(2015吉林省实验中学第四次模拟)(ask) why he studied the language,Mr.Zuckerberg said his wife Priscilla Chan’s family members speak Chinese. 11.(2015甘肃部分普通高中联考)(encourage),the team conducted another experiment.12.(2015北京东城下学期综合测试)—Good news!There’s a supermarket(build) in this area next month! 〚导学号03730018〛—Cool!It will be convenient for us when it’s open.13.(2015成都二诊)(determine) to make his fortune in South America,Mark Twain set off from his home for New Orleans in his teens.14.(2015安徽江南十校联考)There he was,standing still where I had left him and opening his mouth as if (say) something.15.(2015河南洛阳12月统考)I can’t remember her face now but(recall)the incident makes me happy.16.(2015吉林东北师大附中第三次摸底)I knew she needed my help,and her smile was enough(make) my day.17.(2015重庆巴蜀中学模拟)People tend to love agricultural products (grow) without the use of fertilizers,pesticides or chemical additives.18.(2014江西)When it comes to (speak) in public,no one can match him.19.(2014浙江)Amie Salmon,disabled,is attended throughout her school days by a nurse (appoint) to guard her.20.(2014山东)There’s a note pinned to the door (say) when the shop will open again.21.(2014山东)It’s standard practice for a company like this one(employ) a security officer.22.(2014陕西)It’s quite hot today.Do you feel like (go) for a swim?23.(2014湖南)Children,when (accompany) by their parents,are allowed to enter the stadium.24.(2014湖南)(understand) your own needs and styles of communication is as important as learning to convey your affection and emotions.25.(2014四川)The manager was satisfied to see many new products(develop) after great effort.26.(2014天津)Anxiously,she took the dress out of the package and tried it on,only(find) it didn’t fit.27.(2014安徽)While waiting for the opportunity to get (promote),Henry did his best to perform his duty.Ⅱ.完成句子1.失败了三次,他不想再试了。
吉林省长春市普通高中2015届高三第三次模拟考试英语试题(含解析)
长春市普通高中2015届高三质量监测（三）英语本试卷分第I卷（选择题）和第II卷（非选择题）两部分。
考试结束后，将本试卷和答题卡一并交回。
第I卷注意事项：1. 答第I卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2. 选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
不能答在本试卷上，否则无效。
第一部分听力（1—20小题）在笔试结束后进行。
第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该项涂黑。
ARaised in a fatherless home, my father was extremely tightfisted towards us children. His attitude didn’t soften as I grew into adulthood and went to college. I had to ride the bus whenever I came home. Though the bus stopped about two miles from home, Dad never met me, even in severe weather. If I grumbled, he’d say in his loudest father-voice, “That’s what your legs are for!”The walk didn’t bother me as much as the fe ar of walking alone along the highway and country roads. I also felt less than valued that my father didn’t seem concerned about my safety. But that feeling was canceled one spring evening.It had been a particularly difficult week at college after long hours in labs. I longed for home. When the bus reached the stop, I stepped off and dragged my suitcase to begin the long journey home.A row of hedge（树篱）edged the driveway that climbed the hill to our house. Once I had turned off the highway to start the last lap of my journey, I always had a sense of relief to see thehedge because it meant that I was almost home. On that particular evening, the hedge had just come into view when I saw something gray moving along the top of the hedge, moving toward the house. Upon closer observation, I realized it was the top of my father’s head. Then I knew, each time I’d come home, he had stood behind the hedge, watching, until he knew I had arrived safely.I swallowed hard against the tears. He did care, after all.On later visits, that spot of gray became my watchtower. I could hardly wait until I was close enough to watch for its secret movement above the greenery. Upon reaching home, I would find my father sitting innocently in his chair. “So! My son, it’s you!” he’d say, his face lengthening into pretended surprise.I replied, “Yes, Dad, it’s me. I’m home.”本文是亲情类小故事阅读。
2021届吉林省东北师大附中高三下学期3月第三次摸底考试英语试卷及答案
2021届吉林省东北师大附中高三下学期3月第三次摸底考试英语试卷★祝考试顺利★(含答案)本试卷满分150分，考试用时120分钟。
第Ⅰ卷选择题（共90分）第一部分听力 (共两节，满分20分)第一节 (共5小题；每小题1分，满分5分)听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What’s John doing now?A. Playing football.B. Watching TV.C. Studying.2. What can the man do?A. Swim.B. Play soccer.C. Play basketball.3. When will the meeting be over?A. At 11:00.B. At 10:00.C. At 9:30.4. What does the woman think of the play?A. Terrible.B. Just so-so.C. Great.5. What’s the weather like now?A. Snowy.B. Rainy.C. Sunny.第二节 (共15小题；每小题1分，满分15分)听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C 三个选项中选出最佳选项。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6. Where does the man want to go?A. The library.B. The lab.C. The café.7. What’s the man’s major?A. Psychology.B. Physics.C. Chemistry.听第7段材料，回答第8至10题。
2015年高考模拟试题_吉林省实验中学高三上学期第三次阶段检测英语卷
2015年吉林省实验中学高三上学期第三次阶段检测英语试题第I卷第一部分：听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.What is the height of the man?A.Five feet six inches.B. Five feet seven inches.C. Four feet seveninches.2.Why will the woman treat the man?A.To thank him for informing him of the meeting.B.To introduce him some new friends.C.To talk with him about the new work plan.3.What are the two speakers talking about?A.The written part of a driving test.B.The written part of an English test.C.The spoken part of a driving test.4.Why doesn‟t the man agree to turn down this road?A.He has to buy some fruits now.B.The shopping center has closed.C.The traffic is too busy now.5.What is the man‟s mother?A. She is a professor.B. She is a doctor.C. She is a director.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
吉林省长春市东北师范大学附中2021-2022学年高三上学期第三次摸底考试英语试题及答案
东北师大附中2022届高三年级第三次摸底考试（英语）科试卷第一部分听力（共两节，满分20分）做题时，先将答案标在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1分，满分5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does the man mean?A. He doesn't know the woman.B. He has met the woman before.C. He mistook the woman for someone else.2. Where might the speakers be?A. In a supermarket.B. In a restaurant.C.At home.3. What will the woman probably do next?A.Get some medicine for the man.B. Send the man to the hospital.C.Check out of the hotel.4. What does the woman suggest the man do?A. Get a better job.B. Get his car repaired.C.Get a new car.5. Why did the girl apologize to the man?A. She didn't know where she was going.B. She took the man's phone by mistake.C. She bumped into the man carelessly.第二节（共15小题：每小题1分，满分15分）听下面5段对话或独白。
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吉林省东北师大附中2015届高三上学期第三次摸底考试英语试题试卷总评：整套试卷突出了语言运用能力的考查。
阅读难度不高，且试题以细节理解题为主，阅读理解题阅读量不大。
完形填空内容比较简单、易懂，比较容易定位关键词，语法填空选择的材料也比较简单，所填空设计到了，名词、冠词、代词、从句、非谓语动词，可以说考查比较基础、全面。
改错部分所涉及的错误比较明显，学生比较容易确认、改正。
总的来说，整套试卷的难度小，属偏易范畴，比较有利于提升高三学子的自信心。
5. What happened to Tom?A. He‘s sick.B. He fell while running.C. He has been out of work for a long time.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题, 每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话，回答第6和第7两个小题。
6. Where are the speakers probably?A. At a radio station.B. At home.C. On their journey.7. What hit the US Midwest?A. A snowslide (雪崩).B. A blizzard (暴风雪).C. An earthquake.听下面一段对话，回答第8和第9两个小题。
8. What is the relationship between the speakers?A. Friends.B. Salesman and customer.C. Strangers.9. Why does the woman refuse to try some ice cream?A. There aren‘t her favorite flavors.B. She prefers to drink some milk.C. She is on a diet.听下面一段对话，回答第10至第12三个小题。
10. What are listed on the paper?A. Home numbers.B. Office numbers.C. Cellphone numbers.11. What does the man ask the woman to do?A. Correct the numbers on the paper.B. Confirm the e-mail addresses.C. Check the class schedule.12. How many people does the woman need to call?A. 23.B. 24.C. 25.听下面一段对话，回答第13至第16四个小题。
13. Why was the boy asked to see the woman?A. He doesn‘t like her class.B. He disturbs his classmates.C. He is always complaining.14. What‘s the boy talking about during the class?A. The lecture.B. His trips.C. His neighbor.15. How does the boy feel when asking the woman questions during the class?A. Excited.B. Confident.C. Uncomfortable.16. What does the woman advise the boy to do?A. Ask her questions after class.B. Talk with his classmates after class.C. Write down all the points of the lecture.听下面一段独白，回答第17至第20四个小题。
17. What is the survey about?A. British culture.B. Necessities to survive.C. Ideal (理想的) lifestyles.18. What is Baloo?A. A fictional character.B. The author of a book.C. A bear in the zoo.19. What is the most necessary thing for women?A. The Internet.B. Chocolate.C. Hugs.20. What don‘t most people in London realize?A. The importance of love and friendship.B. Their dependence on mobile phones.C. The essence (本质) of happiness.第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该项涂黑。
【题文】AWHAT can help you make a fortune in the future? Graduating from a top university might not be enough. A new study from the University of Essex in Britain has shown that the more friends you have in school, the more money you‘ll earn later.The idea that popularity could have a serious influence on one‘s earning potential shouldn‘t come as too much of a surprise. The researchers noted that if you want to get ahead in life, social skills and networking are easily as powerful as talent and hard work.―If a person has lots of friends, it means that he or she has the ability to get along with others in all kinds of different situations,‖ said Xu Yanchun, 17, from Nantou High School in Shenzhen, who totally agreed with the recent finding. ―Also, friends always help each other. They not only create wider social circles for you but lift your mood when you are occasionally in low spirits,‖ said Xu. She believed that all this helps you ―earn a higher salary.‖Maybe that‘s why some people think the younger generations are in the age of Friendalholism (交友狂症). A woman even complained that the networking website Facebook‘s 5,000-friend limit was too low for her large reserve of social contacts.But what does a friend mean? Should friends be regarded as a form of currency?―Call me uncool, but I think of a friend as an actual person with whom I have an actual history and whom I enjoy actually seeing. It seems, however, that this is no longer the definition of friend‖, said Meghan Daum, who works with The Los Angeles Times in the US.Daum dislikes the idea that quantity trumps quality in the age of Friendaholism. She thought the idea of friendship, at least among the growing population of Internet social networkers, was to get as many of not-really-friends as possible. For example, a friend might be someone you might know personally but who could just as easily be the friend of a friend of some other Facebook friend you don‘t actually know. Although she agreed that social ties grease (润滑) the wheels of life, she also warned. ―Too bad one thing money can‘t buy is a real friend.‖21. What will be needed if you are to achieve success according to the researchers?A. Social skills, friends, good mood and fortune.B. Social skills, networking, talent and hard work.C. Social skills, networking, potential and fortune.D. Social skills, talent, hard work and the facebook.22. What can friends do in the eyes of Xu Yanchun?A. They can help you with your schoolwork.B. They teach you how to make more money.C. They help you get rid of sadness and cheer up.D. They always get on well with you.23. We learn that Meghan Daum‘s attitude towards friends is somewhat _______.A. up-to-dateB. optimisticC. confusedD. traditional24. What does the word ―trumps‖ in the last paragraph mean?A. is better thanB. is equal toC. is worse thanD. is similar to【题文】BA few years ago, pop poets such as Murray Lachlan Young began to set poetry to rock musicwith some surprising results. People thought that poetry was the new rock ‗n‘ roll. However, despite the brief popularity of a few pop poets, poetry and pop m usic didn‘t seem to mix. But are they really so different?If you look back at the origins of poetry, there is a strong connection between poems and popular music. In Greek mythology, for example, the muse (女神) Erato is pictured with a lyre (里拉琴) in her hand, and looks just like the ancestor of the modern rock star with his electric guitar. In addition, the poets Shelley and Byron were as famous in the nineteenth century as the pop stars of today.But despite their common origins, there are many differences between poetry and pop music. Pop songs are always written for a public performance, whereas poetry often isn‘t. And the lyrics in pop songs sometimes have less rhythm than those in poetry. This is because the music provides the rhythm rather than the words. Pop lyrics are also simpler and often keep on saying the same thing. This repetition works well in a performance and means that pop songs are easier for people to sing and learn by heart.Both songs and poems tell a story or talk about feelings. Songs in particular deal with the different stages in a relationship, such as falling in love or breaking up. The words and ideas in songs are usually easier to understand than those in ―serious‖ poetry. However, talented performers like Paul McCartney, or newer stars like Robbe Williams, often give simple songs more expression when they perform them. And some of the best lines from pop lyrics are as beautiful as poetry.So although pop music and poetry have many differences, they do have one important thing in common: the power to make us think about how we feel.25. What did Murray Lachlan Young do a few years ago?A. He had poems and rock music combined.B. He surprised people with his beautiful style of writing.C. He wrote beautiful music for some famous poems.D. He invented a new kind of poem for his fans.26. According to the article, the difference between poetry and pop songs is that _______.A. there is more rhythm in pop songs than poetryB. pop songs are more difficult to understand than poetryC. some words in pop songs are repeated over and over againD. pop songs are not always performed before audience27. According to Paragraph 4, which of the following statements is TRUE?A. Songs and poems are equally beautiful.B. The main theme of songs is about relationship.C. Songs tell stories but poems tell about feelings.D. Songs and poems express a similar message.28. What does the writer say about talented performers today?A. They look at poetry to find ideas for their songs.B. They think their songs are more serious than poetry.C. They give songs more meaning when they sing them.D. They consider themselves to be more popular than poets.【题文】CTODAY, Friday, November 12JAZZ with the Mike Thomas Jazz Band at The Derby Arms. Upper Richmond Road West, Sheen.DISCO Satin Sounds Disco. Free at The Lord Napier, Mort lake High St., from 8 a. m. to 8 p. m. Tel: 682—1158.SATURDAY, November 13JAZZ Lysis at The Bull‘s Head, Barnes. Admission ￡60.MUSICAL HALL at The Star and Garter, Lower Richmond Road, Putney, provided by the Aba Daba Music Hall company. Good food and entertainment fair price. Tel: 789—6749.FAMIL Y night out? Join the sing-along at The Black Horse. Sheen Road, Richmond.JAZZ The John Bennett Big Band at The Bull‘s Head, Barnes. Admission ￡80.THE DERBY ARMS, Upper Richmond Road West, give you Joe on the electric accordion (手风琴). Tel: 789—4536.SUNDAY, November 14DISCO Satin Sounds Disco. Free at The Lord Napier, Mort Lake High Street, from 8 a.m. to 8 p.m.FOLK MUSIC at The Derby Arms. The Short Stuff and residents the Norman Chop Trio. Non-members ￡70. Tel: 688—4626.HEA VY MUSIC with Tony Simon at The Bull. Upper Richmond Road West, East Sheen.THE DERBY ARMS, Upper Richmond Road West, give you Joe on the electric accordion. 29. If you want to enjoy the electric accordion on Saturday, you should ring _______ to find out atwhat time it starts.A. 789—6749.B. 789—4536.C. 682—1158.D. 688—4626.30. You want to spend the Saturday by joining the entertainment with your family. Where shouldyou go?A. Jazz at The Bull‘s Head.B. Disco at The Lord Napier.C. The sing-along at The Black Horse.D. The electric accordion at The Derby Arms.31. Where and when can you hear the Norman Chop Trio?A. At the Bull on Saturday.B. At the Derby Arms on Sunday.C. At the Bull‘s Head on Sunday.D. At the Black Horse on Saturday.【题文】DIn modern society there is a great deal of argument about competition. Some value it highly, believing that it is responsible for social progress and prosperity (繁荣). Others say that competition is bad; that it sets one person against another; that it leads to unfriendly relationship between people.I have taught many children who held the belief that their self-worth relied on how well they performed at tennis and other skills. For them, playing well and winning are often life-and-death affairs. In their single-minded pursuit (追求) of success, the development of many other human qualities is sadly forgotten.However, while some seem to be lost in the desire to succeed, others take an opposite attitude. In a culture which only values the winner and pays no attention to the ordinary players, theystrongly blame competition. Among those who are against competition are young people who have suffered under competitive pressures from their parents or society. Teaching these young people, I often observe in them a desire to fail. They seem to seek failure by not trying to win or achieve success. By not trying, they always have an excuse: ―I may have lost, but it doesn‘t matter because I really didn‘t try.‖ What is not usually admitted by them is the belief that if they had really tried and lost, that would mean a lot.Such a loss would be a measure of their worth. Clearly, this belief is the same as that of true competitors who try to prove themselves. Both are based on the mistaken belief that one‘s self-respect relies on how well one performs in comparison with others. Both are afraid of not being valued. Only as this basic and often troublesome fear begins to disappear can we discover a new meaning in competition.32.What does this passage mainly talk about?A．Competition helps to set up self – respect.B．Competition is harmful to personal quality development.C．Failures are necessary experiences in competitionD．Opinions about competition are different among people.33.Why do some people favor competition according to the passage?A．It improves personal abilities. B．It builds up a sense of duty.C．It pushes society forward. D．It encourages individual efforts.34The underlined phrase ―the most vocal‖ in Paragraph 3 means ___________.A．those who try their best to winB．those who value competition most highlyC．those who are against competition most strongly.D．those who rely on others most for success35.Which point of view may the author agree to?A．Fear of failure should be removed in competition.B．Competition should be encouraged.C．Winning should be a life – and – death matter.D．Every effort should be paid back.【题文】第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。