山西大学附中学年高三第一学期12月月考.docx
山西大学附中学年高三第一学期12月月考.docx

高中数学学习材料鼎尚图文*整理制作山西大学附中2015—2016学年高三第一学期12月月考数学试题(文)考试时间:120分钟 满分:150分一.选择题(本大题共12题,每小题5分,共60分.)1.若bi i ai -=+1)21(,其中R b a ∈,,i 是虚数单位,则=+||bi a ( ) A.i +21B.5C.52D.542.已知{}2R y y x M =∈=,{}22R 2x x y N =∈+=,则M N =( )A .()(){}1,1,1,1- B .{}1 C .[]0,1 D .0,2⎡⎤⎣⎦3.下列说法中正确的是( )A .“()00f =”是“函数()f x 是奇函数”的充要条件B .若:p 0R x ∃∈,20010x x -->,则:p ⌝R x ∀∈,210x x --< C .若p q ∧为假命题,则p ,q 均为假命题 D .“若6πα=,则1sin 2α=”的否命题是“若6πα≠,则1sin 2α≠4.若0,2πα⎛⎫∈ ⎪⎝⎭,且23cos cos 2tan 210πααα⎛⎫++==⎪⎝⎭,则( )A .12 B .13 C .14 D .155.执行如图所示的程序框图,输出20152016s =,那么判断框内应填( ) A .2015?k ≤ B .2016?k ≤ C .2015?k ≥ D .2016?k ≥6.一个几何体的三视图如右图所示,则该几何体的表面积为( ) A .32B .6262++C .12D .3262++7 . 已知变量,x y 满足240220x y x x y -+≥⎧⎪≤⎨⎪+-≥⎩,则32x y x +++的取值范围是( )(A )52,2⎡⎤⎢⎥⎣⎦ (B )55,42⎡⎤⎢⎥⎣⎦ (C )45,52⎡⎤⎢⎥⎣⎦ (D )5,24⎡⎤⎢⎥⎣⎦8.对具有线性相关关系的变量x ,y ,测得一组数据如下表:根据上表,利用最小二乘法得它们的回归直线方程为10.5y x a =+,则a 的值等于( ) A .1 B .1.5 C .2 D .2.5 9.已知函数()f x 是定义在[]1,2a a -上的偶函数,且当0x >时,()f x 单调递增, 则关于x 的不等式(1)()f x f a ->的解集为( ) A .45[,)33 B .]35,34()32,31[⋃ C .)32,31[]31,32(⋃--D .随a 的值而变化 10.三棱锥P ABC -中,PA ⊥平面ABC ,AC BC ⊥,1AC BC ==,3PA =,则该三棱锥外接球的表面积为( )A .π5B .π2C .π20D .π411. 如图,1F 、2F 是双曲线22221x y a b-=(0a >,0b >)的左、右焦点,过1F 的直线l 与双曲线的左右两支分别交于点A 、B .若2F ∆AB 为等边三角形,则双曲线的离心率为( )A .4B .7C .233D .3 12.等差数列{}n a 的前n 项和为*()n S n N ∈,且满足150S >,160S <,则11S a ,22S a ,... ,1515S a 中最大的项为( ) A .66S a B .77S a C .99S a D .88Sa 二.填空题(本大题共4小题,每小题5分,共20分.)13.等比数列{}n a 的前n 项和=2+2nn S a a ⋅-,则a =_______.14.记集合(){}22,|16A x y xy =+≤,集合()(){},|40,,B x y x y x y A =+-≤∈表示的平面区域分别为12,ΩΩ.若在区域1Ω内任取一点(),P x y ,则点P 落在区域2Ω中的概率为_ __15.已知菱形ABCD 的边长为2,120BAD ∠=︒,点E ,F 分别在边BC 、DC 上,3BC BE =,DC DF λ=.若1,AE AF ⋅=,则λ的值为16.已知函数()f x (R x ∈)满足()11f =,且()f x 的导数()12f x '<,则不等式()22122x f x <+的解集为三.解答题(本大题共6小题,共70分.) 17.(本小题满分12分)已知函数()()2cos 3cos sin 222xx x f x =-.(1)设ππ22θ⎡⎤∈-⎢⎥⎣⎦,,且()31f θ=+,求θ的值; (2)在△ABC 中,AB=1,()31f C =+,且△ABC 的面积为32,求sinA+sinB 的值.18.如图,直四棱柱1111ABCD A B C D -的底面ABCD 是菱形,∠ADC =0120,11AA AB ==,点1O O 、分别是上下底菱形对角线的交点. (1)求证:1A O ∥平面11CB D ;(2)求点O 到平面11CB D 的距离.19.(本小题满分12分)某工厂甲、乙两个车间包装同一种产品,在自动包装传送带上每隔一小时抽一包产品,称其重量(单位:克)是否合格,分别记录抽查数据,获得重量数据茎叶图(如右).(Ⅰ)根据样本数据,计算甲、乙两个车间产品重量的均值与方差,并说明哪个车间的产品的重量相对稳定;(Ⅱ)若从乙车间6件样品中随机抽取两件,求所抽取两件样品重量之差不超过2克的概率.20.(本小题满分12分)已知椭圆C 的对称中心为原点O ,焦点在x 轴上,左右焦点分别为1F 和2F ,且122F F =,点31,2⎛⎫⎪⎝⎭在该椭圆上.(Ⅰ)求椭圆C 的方程;(Ⅱ)过1F 的直线l 与椭圆C 相交于A ,B 两点,若△2AF B 的面积为1227,求以2F 为圆心且与直线l 相切圆的方程.21.(本小题满分12分设函数()22ln f x x x a x =-+(1)当2a =时,求函数()f x 在点()()1,1f 处切的切线方程;(2)若函数()f x 存在两个极值点()1212x x x x <、,①求实数a 的范围;②证明:()123ln 22f x x >--请考生在第22、23二题中任选一题作答(在答题卡相应位置填涂),如果多做,则按所做的第一题记分 22.(本小题满分10分)选修4-4:坐标系统与参数方程 在直角坐标系xOy 中,半圆C 的参数方程为1cos sin x y ϕϕ=+⎧⎨=⎩(ϕ为参数,0ϕπ≤≤),以O 为极点,x 轴的非负半轴为极轴建立极坐标系. (Ⅰ)求C 的极坐标方程;(Ⅱ)直线l 的极坐标方程是(sin 3cos )53ρθθ+=,射线OM :3πθ=与半圆C 的交点为O 、P ,与直线l 的交点为Q ,求线段PQ 的长.23.(本题小满分10分)选修4—5:不等式选讲 已知函数()212f x x x a =-++,()3g x x =+. (Ⅰ)当2a =-时,求不等式()()f x g x <的解集; (Ⅱ)设1a >-,且当1[,)22a x ∈-时,()()f x g x ≤,求a 的取值范围.。
山西省山西大学附属中学高三化学上学期12月月考试题

山西大学附中2015—2016学年第一学期高三12月考试化学试卷考试时间90分钟满分100分可能用到的相对原子质量: H:1 N:14 C:12 O:16 S:32 Cu:64 Fe:56Mg:24 Ba:137 Cl:35.5 P:31 Na:23 Br:80 F:19 Si:28 Al:27 Zn:65一、单项选择题(每小题2分共34分)1.下列措施不合理的是()A.用SO2漂白纸浆和草帽B.用硫酸清洗锅炉中的水垢C.高温下用焦炭还原SiO2制取粗硅D.用Na2S做沉淀剂,除去废水中的Cu2+和Hg2+2.设N A为阿伏加德罗常数的值,下列说法中正确的是()A.30g甲醛(HCHO)和醋酸的混合物中含碳原子数目为N AB.1mol Cl2与足量的NaOH溶液反应,转移的电子数为2N AC.100mL0.2mol·L-1的AlCl3溶液中,含Al3+数为0.02N AD.标准状况下,将22.4L氯化氢溶于足量水中,溶液中含有的HCl分子数为N A3. 下列实验可实现鉴别目的是()A.用KOH溶液鉴别SO3(g)和SO2B.用湿润的碘化钾淀粉试纸鉴别Br2(g)和NO2C.用CO2鉴别NaAlO2溶液和CH3COONa溶液D.用BaCl2溶液鉴别AgNO3溶液和K2SO4溶液4. 可逆反应mA(g)+nB(g) pC(g)+qD(g)的v-t图像如图甲所示,若其他条件都不变,只是在反应前加入合适的催化剂,则其v-t图像如图乙所示。
①a1=a2②a1<a2③b1=b2④b1<b2⑤t1>t2⑥t1=t2⑦两图中阴影部分面积相等⑧图Ⅱ中阴影部分面积更大以上所述正确的为( )A.②④⑤⑦ B.②④⑥⑧ C.②③⑤⑦ D.②③⑥⑧5. 如图是第三周期11~17号元素某些性质变化趋势的柱形图,下列有关说法中正确的是( ).A. y轴表示的可能是基态的原子失去一个电子所需要的最小能量;B. y 轴表示的可能是原子在化合物中吸引电子的能力标度;C. y 轴表示的可能是原子半径;D. y 轴表示的可能是形成基态离子转移的电子数6. a molNa 2O 2和b molNaHCO 3固体混合后,在密闭容器中加热到250℃,使其充分反应,当排出气体为两种气体时, a:b 不可能为A .3:4B .4:5C .2:3D .3:27. 某研究性学习小组讨论甲、乙、丙、丁四种仪器装置的有关用法,其中不合理的是()A .甲装置:可用来证明碳的非金属性比硅强B .乙装置:橡皮管的作用是能使水顺利流下C .丙装置:用图示的方法不能检查此装置的气密性D .丁装置:先从①口进气集满二氧化碳,再从②口进气,可收集氢气8. 某同学采用硫铁矿焙烧取硫后的烧渣(主要成分为Fe 2O 3、SiO 2、Al 2O 3,不考虑其他杂质) 制取七水合硫酸亚铁(FeSO 4·7H 2O) ,设计了如下流程: 下列说法不正确的是 ( )A .溶解烧渣选用足量硫酸,试剂X 选用铁粉B .固体1中一定含有SiO 2,控制pH 是为了使Al 3+转化为Al(OH)3,进入固体2C .从溶液2得到FeSO 4·7H 2O 产品的过程中,须控制条件防止其氧化和分解D .若改变方案,在溶液1中直接加NaOH 至过量,得到的沉淀用硫酸溶解,其溶液经结晶分离也可得到FeSO 4·7H 2O9. 对于合成氨反应,达到平衡后,以下分析正确的是( )A . 升高温度,对正反应的反应速率影响更大B . 增大压强,对正反应的反应速率影响更大C . 减小反应物浓度,对逆反应的反应速率影响更大D . 加入催化剂,对逆反应的反应速率影响更大10. 一般情况下,前者无法决定后者的是( )A . 原子核外电子排布﹣﹣元素在周期表中的位置B . 弱电解质的相对强弱﹣﹣电离常数的大小NaOH 溶液 控制pH 试剂X 足量酸 烧渣 固体溶液固体FeSO 4·7H 2O 溶液C.分子间作用力的大小﹣﹣分子稳定性的高低D.物质内部储存的能量﹣﹣化学反应的热效应11. 工业上将Na2CO3和Na2S以1:2的物质的量之比配成溶液,再通入SO2,可制取Na2S2O3,同时放出CO2.在该反应中()A.硫元素被氧化B.氧化剂与还原剂的物质的量之比为1:2C.每生成1molNa2S2O3,转移4mol电子D.相同条件下,每吸收10m3SO2就会放出2.5m3CO212. 短周期元素甲、乙、丙、丁的原子序数依次增大,甲和丁的原子核外均有两个未成对电子,乙、丙、丁最高价氧化物对应的水化物两两之间能相互反应.下列说法错误的是()A.元素丙的单质可用于冶炼金属B.甲与丁形成的分子中有非极性分子C.简单离子半径:丁>乙>丙D.甲与乙形成的化合物均有氧化性13. 羰基硫(COS)可作为一种粮食熏蒸剂,能防止某些昆虫、线虫和真菌的危害.在恒容密闭容器中,将CO和H2S混合加热并达到下列平衡:CO(g)+H2S(g)⇌ COS(g)+H2(g) K=0.1反应前CO的物质的量为10mol,平衡后CO物质的量为8mol,下列说法正确的是()A.升高温度,H2S浓度增加,表明该反应是吸热反应B.通入CO后,正反应速率逐渐增大C.反应前H2S物质的量为7molD.CO的平衡转化率为80%14. 已知热化学方程式如下:CaSO 4(s)+CO(g) CaO(s) + SO2(g) + CO2(g) △H1= +218.4k J·mol-1(反应Ⅰ) CaSO 4(s)+4CO(g)CaS(s) + 4CO2(g) △H2= -175.6k J·mol-1(反应Ⅱ)假设某温度下,反应Ⅰ的速率(v1)大于反应Ⅱ的速率(v2),则下列反应过程能量变化示意图正确的是()A B C D15、某钠盐溶液中可能含有2222433NO SO SO CO Cl I------、、、、、等阴离子。
山西省山西大学附属中学高三12月月考(英语)

山西省山西大学附属中学高三12月月考英语试题(满分:150分时间:1 )第一部分听力理解(共10分)第一节(共5题)请听下面5段对话,选出最佳选项1.Where does the conversation take place?A. At the post officeB. At the restaurantC. At the bus stop2. What does the man probably do?A. A teacherB. A dentistC. A waiter3. Why does the woman plan to go to town?A. To pay her bills in the bank.B. To buy bookd in the bookstore.C. To get some money from the bank.4. Who is the man probably?A. A friend of the woman’s father’sB. The woman’s brotherC. The woman’s father5. How much did the man’s wife pay for the coat?A. $80 B $240 C $1二节(共10题)请听下面5段对话或独白,选出最佳选项请听第6段材料,回答6至8题6. Why does the man make the phone call?A. To book some tickets for the show.B. To get some information about the garden.C. To know when the box office is open7. How much will one pay for two tickets now?A. 26 dollars.B. 30 dollarsC. 60 dollars8. How long will the show last?A. For about two hoursB. For about three hoursC. For about four hours请听第7段材料,回答9至11题9. When should one arrive if the dinner time is 7 pm according to the woman?A. At 6:mB. At 6:50 pmC. At 7:40 pm10. What should be done during the dinner?A. Praising the host or hostess for the meal.B. Expressing thanks to the host or hostess for the dinner.C. Talking to the host or hostess as much as possible.11. What can we know about the woman?A. She comes from America.B. She likes holding parties.C. She knows American custom very well.请听第8段材料,回答12至14题12. What do Tasty Fish and Something Fishy have in common?A. A lot of cooking instructions.B. A lot of texts.C. A lot of colorful pictures.13. Which book is the cheapest one?A. Tasty FishB. Worldwide FishC. Something Fishy14. Which book does the woman decide to buy?A. Something FishyB. Worldwide FishC. Tasty Fish请听第9段材料,回答15至17题15. Where did the woman speaker talk to Sherry Palmer?A. In her house.B. In Sherry Palmer’s houseC. In her office.16.What did Sherry Palmer do when she saw Allen?A. She returned his mobile phone.B. She shouted at him.C. She wanted to catch him.17. What can we learn from the conversation?A. Allen was actually innocent.B. Allen died of heart trouble.C. The man speaker will arrest Sherry Palmer.请听第10段材料,回答18至18. What clothes does the speaker’s sister like?A. Clothes in fashion.B. Cheap clothesC. Ordinary clothes.19. What does the speaker think of going to the nightclubs?A. It’s a waste of money and time.B. It’s really a passion with her.C. It gives her a headache.Why did the speaker fail to live with her sister?A. Her sister often brings friends home and makes too much noise.B. The speaker likes to keep things neat while her siste r doesn’t.C. They always can’t agree on the color they like best.第二部分英语知识运用第一节:单项选择(共15小题;每小题1分,满分15分)21.---So you are running __ clothing shop?---Yes, but I don’t want to make it ___ shop only for rich people.A. the, theB. a, aC. a, theD. /, the22. John ___ such a thing about you. He never speaks ill of you behind your back.A. can't have saidB. might not have saidC. couldn't sayD. mustn't have said23.It was seven o'clock ____I got to school this morning, ____ made our teacher very angry.A. when; thatB. that; thatC. that; whenD. when; which24.Her husband earns ____ she while they do the same amount of work.A. twice as many asB. as twice much asC. twice more money asD. twice as much money as25.This dictionary is _____ to me, but that one is _____ .A. great help; helpfulB.a great help; of little useC.important; of few importanceD. very helpful; of no any use26.The students discussed the experiment that they would like to see ____ next year.A. carry outB. carrying outC. carried outD. to carry out27.Not until I was standing on the edge of death ____ how much I wanted to live.A. I realizedB. did I realizeC. I had realizedD. had I realized28. we must ___ to the public the simple fact that drug are dangerous.A. get acrossB.get awayC.get backD.get behind29. his composition was so confusing that I could hardly make any ____ of it.A.meaningB.messagermationD.sense30. Road accidents victims____ almost a quarter of the hospital patients.A. make offB. make upC. make outD. make for31. Everything he _____ to his country.A. had was contrbutedB. had been contributedC. had to be contributedD. had contributed32.The army has _____ grain. They are in a very difficult situation.A. run downB. run out ofC. run offD. run into33.____ the factors already referred to, people sometimes feel insecure because their motives are misunderstood by others.A. But forB. ExceptC. Apart fromD. Except that34. I hope my teacher will take my recent illness into ___ when judging my examination.A. regardB.countingC.accountD.observation35.Jack, as well as his friends who ____ football games, ____ traveled with the team.A. likes; hasB. like; haveC. like; hasD. likes; have第二节完形填空(共;每小题2分,满分40分)Charles and I used to hang out all the time , together with a few other guys , but he seemed too cool for us lately . We couldn’t understand the 36 , and we didn’t ask him for an explanation . 37 , we decided to 38 him a lesson in the way he treated us .Once we started giving Charles the 39 shoulder , almost everybody was taking no notice of him . He looked so 40 , especially at lunchtime when he sat alone in the cafeteria . Now and then he nodded and said , “Hey!” when 41 passed his table , but all he got 42 return were mean looks and silence .At first I was glad my plan had 43 , but Charles’ unhappiness made me upset . I only wanted him to know 44 it felt like to be blown off , but I hadn’t thought about how badly my “lesson”would 45 him .During one lunch period, I 46 as Charles repeatedly glanced at his watch , obviously 47 the minutes until he could leave the cafeteria . I suddenly realized I had done wrong .“Hey ! man . I’m terribly sorry.” I called out .Charles turned around 48 , clearly wanting to avoid eye contact .“Oh, so you are talking to me now ?” he asked .“I’m so sorry , 49 I had thought that you wanted to end our friendship.” I said .“What?” he nearly shouted , looking much 50 . “I’ve left you alone because I thought that was what you wanted.”“Oh, my God ! Why would I want 51 ?” I shouted , completely puzzled .Clearly , we both had been 52 each other wrong .At first Charles couldn’t accept my 53 . I knew he needed time to 54 all the hurt I’d caused him . But eventually , he did forgive me . We even started hanging out together 55 . And our friendship wasn’t destroyed at all .36.A.situation B.change C.action D.appearance37.A.Besides B.Therefore C.Instead D.Opposite38.A.take B.teach C.give D.attend39.A.serious B.friendly C.warm D.cold40.A.sad B.angry C.happy D.high41.A.nobody B.anyone C.they D.someone42.A.at B.in C.on D.by43.A.helped B.operated C.worked D.done44.A.what B.that C.as D.how45.A.worry B.touch C.hurt D.disappoint46.A.imagined B.listened C.recalled D.watched47.A.counting B.guessing C.waiting D.checking48.A.immediately B.slowly C.finally D.willingly49.A.and B.so C.thus D.but50.A.interested B.pleased C.surprised D.moved51.A.it B.those C.that D.such52.A.understanding B.regarding C.knowing D.treating53.A.explanation B.attitude C.suggestion D.apology54.A.get through B.get over C.get across D.get along55.A.seldom B.once C.again D.also第三部分:阅读理解(共,每小题2.5分,共50分)AAmericans are proud of their variety and individuality, yet they love and respect few things more than a uniform, whether it is the uniform of an elevator operator or the uniform of a five-star general.Why are uniforms so popular in the United States?Among the arguments for uniforms, one of the first is that in the eyes of most people they look more professional than civilian(百姓的)clothes.People have become conditioned to expect superior quality from a man who wears a uniform.The television repairman who wears uniform tends to inspire more trust than one who appears in civilian clothes.Faith in the skill of a garage mechanic is increased by a uniform.What easier way is there for a nurse, a policeman, a barber, or a waiter to lose professional identity(身份)than to step out of uniform?Uniforms also have many practical benefits.They save on other clothes.They save on laundry bills.They aretax-deductible(可减税的).They are often more comfortable and more durable than civilian clothes.Primary among the arguments against uniforms is their lack of variety and the consequent loss of individuality experienced by people who must wear them.Though there are many types of uniforms, the wearer of any particular type is generally stuck with it, without change, until retirement.When people look alike, they tend to think, speak, and act similarly, on the job at least.Uniforms also give rise to some practical problems.Though they are long-lasting, often their initial expense is greater than the cost of civilian clothes.Some uniforms are also expensive to maintain, requiring professional dry cleaning rather than the home laundering possible with many types of civilian clothes.56.It is surprising that Americans who worship variety and individuality _______.A.still judge a man by his clothesB.hold the uniform in such high regardC.enjoy having a professional identityD.will respect an elevator operator as much as a general in uniform57.People are accustomed to think that a man in uniform _______.A.suggests quality workB.discards his social identityC.appears to be more practicalD.looks superior to a person in civilian clothes58.The chief function of a uniform is to _______.A.provide practical benefits to the wearerB.make the wearer catch the public eyeC.inspire the wearer’s confidence in himselfD.provide the wearer with a professional identity59.The best title for this passage would be _______.A.Uniforms and SocietyB.The Importance of Wearing a UniformC.Practical Benefits of Wearing a UniformD.Advantages and Disadvantages of UniformsBTUESDAY, July11SHANGHAI---The 12th International Processing, Packaging & End-Line Printing Exhibition opens atShanghai New International Expo Centre ( to July 13)Tel: 021 65 HONGKONG---The Hong Kong International Textile and Garment Machinery and Technology Fair opens at Hong Kong Convention and Exhibition Centre ( to July 14).Tel: +852 2584 4333THURSDAY, July 13SHANGHAI---The China(Shanghai) International Wedding Photographic Equipment Exhibition (Autumn) opens at Shanghai Mart ( to July16 ).Tel: 021 6272 2828HARBIN, Heilongjiang Province---The Ninth Harbin International Automobile Industry Exhibition and Sports Centre ( to July 17 ).Tel : 0451 5363 5464FRIDAY, July 14HONG KONG---The Hong Kong Wedding, Banquet & Wedding Accessories Expo opens at Hong Kong Convention and Exhibition Centre ( to July 16 ).Tel: +852 2367 8385WEDNESDAY, July 19SHANGHAI---The 14th Shanghai International Advertising Technology & Equipment Exhibition / Shanghai International Media Technology & Equipment opens at Shanghai New International Expo Centre ( to July 22 ).Tel: 021 6328 8899SHANGHAI---The Shanghai International Outdoor AD Illuminating Technology & Equipment Exhibition, Outdoor Media Promotion Exhibition opens at Shanghai New International Expo Centre ( to July 22 ).Tel: 021 6321 7522SHANGHAI---PAPERTECH Shanghai opens at Shanghai New International Expo Centre ( to July 22 ).Tel: 021 6328 889960.More exhibitions are held in _______A.Shanghai New International Expo CentreB.Hong Kong Convention and Exhibition CentreC.Shanghai MartD.Harbin International conference, Exhibition and Sports Centre61.How many exhibitions can you attend on July 15______A.one B.two C.three D.four62.The text is likely to be a (an)________A.business diaryB.product advertisementC.private timetableD.magazineCAnimals are more like us than we ever imagined.They feel pain, they experience stress, they show affection, excitement and love.All these findings have been made by scientists in recent years---and such results are beginning to change how we view animals.Strangely enough, some of this research was sponsored by fast food companies like McDonald’s and KFC.Pressured by animal rights groups , these companies felt they had to fund scientists researching the emotional and mental states of animals.McDonald’s, for instance, funded studies on pig behavior at Purdue University, Indiana.This research found that pigs seek affection and easily become depressed if left alone or prevented from playing with each other.If they become depressed, they soon become physically ill.Because of this, and other similar studies, the European Union has banned the use of isolating pig stalls from .In Germany, the government is encouraging pig farmers to give each pig econds of human contact a day, and to provide them with toys to prevent them from fighting Other scientists have shown that animals think and behave like humans.Koko, the 300-pound gorilla at the Gorilla Foundation in Northern California, for instance, has been taught sign language.Koko can now understand several thousand English words, more than many humans who speak English as a second language.On human IQ tests, she scores between 70 and 95.Before such experiments, humans thought language skills were absent from the animal kingdom.Other myths are also being overturned, like the belief that animals lack self-awareness.Studies have also shown that animals mourn their dead, and that they play for pleasure.These striking similarities between animal and human behavior have led some to ask a question: “If you believe in evolution, how can’t you believe that animals have feelings that human beings have?”Until recently, scientists believed that animals behaved by instinct and that what appeared to be learned behavior was merely genetically-programmed activity.But as Koko the Gorilla shows, this is not the case.In fact, learning is passed from parent to offspring far more often than not in the animal kingdom.So what implications does this knowledge have for humans? Because of this, should we ban hunting and animal testing? Should we close zoos? Such questions are being raised by many academics andpoliticians.Harvard and 25 other American law schools have introduced courses on animal rights.Germany meanwhile, recently guaranteed animal rights in its constitution---the first country to do so.63.McDonald’s and KFC give money to support scientist to do research on animals, because_____ A.they are international big companies.B.they love animals.C.they are pressured by animal right groups.D.they earn a large amount of money and want to do some good deeds.64.The research on pigs at Purdue University shows that______A.pigs love being alone.B.pigs easily become physically ill.C.pigs need affection.D.pigs don’t like to play with each other.65.Which of the following statements is NOT true?A.Animals behave by instinct.B.Animals have self-awareness.C.Animals have feelings and love.D.Animals do not have language skills.66.Should we ban hunting and animal testing?A.Yes.B.NoC.Not certainD.Not mentionedDEven facts “forgotten”by people during a busy day may be retrieved if this is followed by a good night’s sleep.Researchers from the University of Chicago asked volunteers to remember simple words.Many found their memories letting them down towards the end of the day, but the following morning, those who had slept well could recall much more.Researchers, writing in the journal Nature, said the brain could “rescue” lost memories during the night.When the brain is first asked to remember something that memory is laid down in an “unstable”state, meaning that it is possible that it could be lost.At some point, the brain consolidates those it deems important intoa “stable”, more permanent state.However, the Chicago researchers suggested that it was possible for a “stable”memory to be made “unstable” again.This would mean that memories could be modified then filed away again in the face of new experiences.The 12 volunteers tested in the experiment were played words created through a speech synthesizer which were purposely difficult to understand.Initially, the written version of the word from the audio version only.Tests revealed that the ability to recall the right word tended to tail off as the day ended.However, when the volunteers were retested after a good night’s sleep, they were able to recall some words that they had “ forgotten” the previous evening.Dr Daniel, one of the study authors, said: “Sleep consolidates memories, protecting them against subsequent interference or decay.Sleep also appears to “recover” or restore memories.” He said: “If performance is reduced by decay, sleep might actively recover what has been lost.”Dr Karim Nader, from the Department of Psychology in McGill University in Montreal, said: “Memory research is undergoing a transformation---no longer is memory thought to be a hard-writing of the brain, instead it seems to be a process of storage and restorage.”Sleep helps some memories “mature” and also prunes out unimportant memories.67.What does the first paragraph implies?A.A busy day makes people forget things easily.B.People need a good night’s sleep after a busy day.C.A good night’s sleep helps memories.D.A good night’s sleep helps people forget a busy day.68.The words the 12 volunteers played in the experiment were not ____A.created through a speech synthesizerB.hard to understandC.available at the beginningD.designed to test people’s ability of understanding69.According to the passage, memory_____A.is a hard-writing of the brainB.is not a process of storageC.is not a process of restorageD.will be mature with the help of sleep70.Which of the following is NOT true?A.When people first remember something, the memory is in an “unstable state”.B.The brain will change those important unstable memories into stable.C.Once the memory become stable, it will never become unstable again.D.Sleep can protect memories from being harmed.EThe need for love is deeply rooted in the human psyche(灵魂). __71___ Separateness, according to psychologists, means to be cut off, helpless and alone in the world. It is the source of all anxiety._72____ It can be selfish and possessive, or unselfish and giving. Abraham Maslow distinguishes between two kinds of love: B-love or “being love” means love for another person: unselfish love not dependent upon your own needs. D-love or “deficiency-love” is a selfish possessive love which is based upon someone else’s ability to satisfy your needs.D-love is conditional. It depends upon whether personal needs continue to be met…But B-love is unconditional. __73___ Furthermore, as it depends upon who you are, it is possible only when you allow yourself to be known to the other person.The psychologist Erich Fromm also distinguished between two types of love.__74__ Symbiotic union is an immature love based upon the satisfaction of needs and is similar to Maslow’s concept of D-love.Mature love, on the other hand, is a relationship that allows individuals to retain(保持) their independence, their identity, and their integrity. In mature love people can overcome their sense of separateness yet continue to be themselves. The mature lover wo uld say , “I love you because I need you,” but the mature one: “__75__”A.There are two types of love.B.I need you because I love you.C.Love is a way of overcoming the feelingD.Every one of us needs love.E.It depends not upon what you do, but who you are.F.They are immature love, called by him symbiotic union(共同体), and mature love.G.These two types are quite different from each other.第四部分写作第一节短文改错(10分)错误涉及一个单词的增加、删除或修改增加:在缺词出加一个漏字符号(^),并在其下面写出该加的词。
山西省太原市山西大学附中2024届高三上学期12月月考(总第七次)数学试题

山西省太原市山西大学附中2024届高三上学期12月月考(总第七次)数学试题学校:___________姓名:___________班级:___________考号:___________一、单选题..C.D.年的五一劳动节是疫情后的第一个小长假,公司筹备优秀员工假期免费旅游.常见的五个旅游热门地北京、上海、广州、深圳、成都外,淄博烧烤火爆全国,山东也成为备选地之一.若每个部门从六个旅游地中选择一个旅游地,则甲、乙、丙、丁四个部门至少有三个部门所选旅游地全不相同的方法种数共有()1800B.1080C.720D.360 2020年12月17日凌晨,嫦娥五号返回器携带月球样品在内蒙古四子王旗预定区域安全着陆-嫦娥五号返回:舱之所以能达到如此高的再入精度,主要是因为它采用弹跳式返回弹道,实现了减速和再入阶段弹道调整,这与“打水漂”原理类似(如图所示A .4B .57.已知函数21()sinsin 22xf x x ωω=+-点,则ω的取值范围是A .10,8⎛⎤⎥⎝⎦B .150,,148⎛⎤⎡⋃ ⎥⎢⎝⎦⎣8.设函数()(21)xf x e x ax a =--+,其中则a 的取值范围是()A .3,12e ⎡⎫-⎪⎢⎣⎭B .33,2e 4⎡⎫-⎪⎢⎣⎭二、多选题三、填空题(1)当//AB 平面PCD 时,求PC 的长;(2)当三棱锥P COD -体积最大时,求二面角D PC -20.抽屉中装有5双规格相同的筷子,其中2双是一次性筷子,每次使用筷子时,从抽屉中随机取出1双,若取出的是一次性筷子,若取出的是非一次性筷子,则使用后经过清洗再次放入抽屉中,求:(1)在第2次取出的是非一次性筷子的条件下,第1次取出的是一次性筷子的概率;(2)取了3次后,取出的一次性筷子的个数(双)的分布列及数学期望;(3)取了(2,3,4n n =,…)次后,所有一次性筷子刚好全部取出的概率.21.已知直线l 经过椭圆()2222:10x y E a b a b +=>>的右焦点,A B ,当直线l 分别与x 轴、y 轴垂直时,线段AB 的长分别为(1)求椭圆E 的标准方程;(2)过点B 作x 轴的垂线交椭圆E 于点C (异于点,A B ADF △面积的最大值.22.已知函数()ln ,R f x ax x a =-∈.(1)讨论函数()f x 的单调性;(2)当1a =时,设()()()21x g x f x -=,求证:函数()g x 存在极大值点。
山西省山大附中高三数学12月月考试题 文

山西大学附中2011——2012第一学期高三12月月考数学试题(文)考试时间:120分钟 满分:150分一.选择题(本大题共12小题,每小题5分,共60分)1.设集合}log ,3{2a P =,{}b a Q ,=,若}0{=Q P ,则=Q PA.{}0,3B.{}2,0,3C.{}1,0,3D.{}2,1,0,32.复数31i i +(i 为虚数单位)的虚部是A .12iB .12-iC .12-D .123.已知p :20<<x ,q :11≥x,则p 是q 的A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件 4.已知等比数列{}n a 的前n 项和为112,6n n S a -=⋅+则a 的值为A .13-B .13C .12-D .125.一个体积为柱的侧(左)视图的面积为A . 12B .8C ..6.将函数)3cos(π-=x y 的图像上各点的横坐标伸长到原来的2倍(纵坐标不变),再向左平移6π个单位,所得图像的一条对称轴方程为A.9π=x B. 8π=x C. 2π=x D. π=x 7.已知函数()|lg |f x x =,若0a b <<,且()()f a f b =,则2a b +的取值范围是A.)+∞B.)+∞C.[3,)+∞D.(3,)+∞8.从某小学随机抽取100名同学,将他们的身高(单位:厘米)数据绘制成频率分布直方图(如图).若要从身高在[ 120 , 130),[130 ,140) , [140 , 150]三组内的学生中,用分层抽样的方法选取18人参加一项活动,则从身高在[140 ,150]内的学生中选取的人数应为 A .2 B .3 C .4 D .5 9.ABC ∆的外接圆的圆心为O ,半径为1,若AO AC AB 2=+,且||||AC OA =,则向量BA 在向量BC 方向上的射影为A.B.C.3D.10.对于数25,规定第1次操作为3325133+=,第2次操作为33313355++=,如此 反复操作,则第2011次操作后得到的数是A.25B.250C.55D.13311.已知椭圆2214x y +=的焦点为1F ,2F ,在长轴12A A 上任取一点M ,过M 作垂直于12A A 的直线交椭圆于点P ,则使得120PF PF ⋅<的点M 的概率为A .3 B .3. 3D .1212.定义方程()()f x f x '=的实数根0x 叫做函数()f x 的“新驻点”,如果函数()g x x =,()ln(1)h x x =+,()cos x x ϕ=(()x π∈π2,)的“新驻点”分别为α,β,γ,那么α,β,γ的大小关系是A .γβα<<B .βγα<<C .βαγ<<D .γαβ<<二、填空题(本大题共4小题,每小题5分,共20分)13.经过圆0222=++y x x 的圆心,且与直线0=+y x 垂直的直线方程是14.已知(cos23,cos67)AB =︒︒ ,(2cos68,2cos22)BC =︒︒,则ABC ∆的面积为15.若命题“∃a ∈[1,3],使02)2(2>--+x a ax ”为真命题,则实数x 的取值范围是________.16.已知函数()x f 是定义在R 上的奇函数,()()x f x f -=+4,且在[]2,0上()x f 是增函数,则下列结论:①若4021<<<x x 且421=+x x ,则()()021>+x f x f ; ②若5,402121=+<<<x x x x 且,则()()21x f x f >;③若方程()[]8,8-=在m x f 内恰有四个不同的解4321,,,x x x x ,则84321±=+++x x x x 。
山西省山大附中2015届高三12月月考化学试卷 Word版含答案.pdf

(1)在处理粗盐水的过程中,可加入石灰乳和纯碱作为沉淀剂,则所得滤渣的成分除过量的沉淀剂外还有
。
(2)将CaO投入含有大量的NH4Cl的母液中,能生成可循环使用的NH3,该反应的化学方程式是
。
(3)向饱和食盐水中首先通入的气体是
,过程Ⅲ中生成NaHCO3晶体的反应的化学方程式是
。
(4)碳酸钠晶体失水的能量变化示意图如下:
(4)已知O2-半径为140pm,计算Ba2+半径
Ⅰ(11分)
(1)CaCO3、Mg(OH)2(漏写得1分,错答得0分)
(2)2NH4Cl+CaO=CaCl2+2NH3↑+H2O
(3)NH3(1分) NH3+H2O+CO2+NaCl=NaHCO3↓+NH4Cl
(4)Na2CO3·H2O(s)=Na2CO3(s) +H2O(g) ΔH=+ 58.73 kJ·mol-1
(5)106(b-a)/11a
Ⅱ(1)Cl2 (1分)SO2+Br2+2H2O2HBr+HSO4(2分)
(2)Mg(OH)2沉淀的质量(2分)
(3) 97.7 mol(2分)
Ⅰ(6分)
CO(或一氧化碳)CH3OH(或甲醇)
(1)1/3 (0.33或33%) (2)C
Ⅱ(1)0.7
C
C
稀硫酸
粗盐
海水
Mg(OH)2 Br2 K+、Mg2+等 苦卤(K+、Mg2+、Br-等) H2SO4 Cl2 试剂1
。
(2)NaCl、KCl、MgCl2、MgSO4等物质。用沉淀法测定苦卤中镁元素的含量(g/L),实验过程中应测定的数据有
。
(3)电解200kg 25%的饱和食盐水,当浓度下降到20%时,收集到氯气的物质的量
山西省山西大学附属中学高三数学12月模块诊断试题 理
山西大学附属中学2016-2017学年高三第一学期12月(总第六次)模块诊断数学试题(理)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设集合2{40}A x x =->,124x B x ⎧⎫=⎨⎬⎩⎭<,则AB =( )A .{}2x x > B. {}2x x <- C. {}22或x x x <-> D. 12x x ⎧⎫<⎨⎬⎩⎭2.复数z 满足(1)|1|z =+,则z 等于( )A .1B .1C .12- D 12i - 3.已知,p q 是简单命题,则“p q ∧是真命题”是“p ⌝是假命题”的( ) A .充分而不必要条件 B .必要而不充分条件 C .充分必要条件 D .既不充分也不必要条件 4.下列结论正确的是( )A .若直线l ⊥平面α,直线l ⊥平面β,则//αβB .若直线//l 平面α,直线//l 平面β,则//αβC .若两直线12l l 、与平面α所成的角相等,则12//l lD .若直线l 上两个不同的点A B 、到平面α的距离相等,则//l α5.中国古代数学著作《算法统宗》中有这样一个问题:“三百七十八里关,初行健步不为难,次日脚痛减一半,六朝才得到其关,要见次日行里数,请公仔细算相还.”其意思为:有一个人走378里路,第一天健步行走,从第二天起脚痛每天走的路程为前一天的一半,走了6天后到达目的地,请问第二天走了( )A .24里B .48里C .96里D .192里6.已知数列{}n a 为等差数列,满足32013OA a OB a OC =+ ,其中,,A B C 在一条直线上, O 为直线AB 外一点,记数列{}n a 的前n 项和为n S ,则2015S 的值为( ) A .20152B . 2015C .2016D .20137.若直线4:=+ny mx l 和圆4:22=+y x O 没有交点,则过点),(n m 的直线与椭圆14922=+y x 的交点个数为( )A.0个B.至多一个C.1个D.2个 8.定义在R 上的函数()f x 满足:'()1()f x f x >-,(0)6f =,'()f x 是()f x 的导函数,则不等式()5x x e f x e >+(其中e 为自然对数的底数)的解集为( )A .(,0)(1,)-∞+∞B .(,0)(3,)-∞+∞ C .(0,)+∞ D .(3,)+∞9.已知01a <<,01b <<,则函数2()log 2log 8a b f x x b x a =++的图象恒在x 轴上方的概率为( ) A10.已知三棱锥ABC O -,,,A B C 三点均在球心为O 的球表面上,1AB BC == ,120ABC ∠= ,三棱锥ABC O -的体积为45,则球O 的表面积是( ) A .π16 B .π64 C .π332D .π54411. 设双曲线()2222:10,b 0x y C a a b-=>>左,右焦点为12,,F F P 是双曲线C 上的一点,1PF 与x 轴垂直,12PF F ∆的内切圆方程为()()22111x y ++-=,则双曲线方程为( )A .22123x y -= B .2212y x -= C .2212x y -= D .2213y x -= 12.已知函数()21,g x a x x e e e ⎛⎫=-≤≤ ⎪⎝⎭为自然对数的底数与()2ln h x x =的图象上存在关于x 轴对称的点,则实数a 的取值范围是( )A .211,2e ⎡⎤+⎢⎥⎣⎦B .21,2e ⎡⎤-⎣⎦C .2212,2e e ⎡⎤+-⎢⎥⎣⎦D .)22,e ⎡-+∞⎣ 第Ⅱ卷(共90分) 二、填空题(每题5分,满分20分,将答案填在答题纸上)13. 若88221083)1()1()1()2()1(-+⋅⋅⋅+-+-+=-++x a x a x a a x x ,则______6=a .14.如图在圆O 中,O 为圆心,AB 为圆的一条弦,4=AB ,则=⋅AB AO .ABO 14题图15.在直线2-=y 上任取一点Q ,过Q 作抛物线y x 42=的切线,切点分别为A 、B ,则直线AB 恒过的点是 . 16.函数()()2sin 2,cos 223(0)36f x x g x m x m m ππ⎛⎫⎛⎫=+=--+> ⎪ ⎪⎝⎭⎝⎭,对任意10,4x π⎡⎤∈⎢⎥⎣⎦,存在20,4x π⎡⎤∈⎢⎥⎣⎦,使得()()12g x f x =成立, 则实数m 的取值范围是 .三、解答题 (本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.) 17.(本小题满分12分)在成且已知的对边分别为角中c b a B c b a C B A ABC ,,,135sin ,,,,,,=∆等比数列. (Ⅰ)求CA tan 1tan 1+的值;(Ⅱ)若c a B ac +=求,12cos 的值.18.(本小题满分12分)某市文化馆在春节期间举行高中生“蓝天海洋杯”象棋比赛,规则如下:两名选手比赛时,每局胜者得1分,负者得0分,比赛进行到有一人比对方多2分或打满6局时结束.假设选手甲与选手乙比赛时,甲每局获胜的概率皆为23,且各局比赛胜负互不影响. (Ⅰ)求比赛进行4局结束,且乙比甲多得2分的概率;(Ⅱ)设ξ表示比赛停止时已比赛的局数,求随机变量ξ的分布列和数学期望.19.(本小题满分12分)在如图所示的空间几何体中,平面⊥ACD 平面ABC ,ACD ∆与ACB ∆是边长为2的等边三角形,2=BE ,BE 和平面ABC 所成的角为 60,且点E 在平面ABC 上的射影落在ABC ∠的平分线上. (Ⅰ)求证:∥DE 平面ABC ; (Ⅱ)求二面角A BC E --的余弦值.20.(本小题满分12分)已知椭圆2222:1(0)x y C a b a b+=>>,其左,右焦点分别为1F ,2F ,点P 是坐标平面内一点,且7OP =1234PF PF ⋅=,其中O 为坐标原点. (Ⅰ)求椭圆C 的方程;(Ⅱ)过点1(0,)3S -,且斜率为k 的动直线l 交椭圆于,A B 两点,在y 轴上是否存在定点M ,使以,A B 为直径的圆恒过这个定点?若存在,求出点M 的坐标;若不存在,请说明理由.21. (本小题满分12分)已知函数x x x x f +-=2ln )(.(Ⅰ)若关于x 的不等式112)(2-+⎪⎭⎫ ⎝⎛-≤ax x a x f 恒成立,求整数a 的最小值;(Ⅱ)若正实数21,x x 满足+)(1x f 0)(2)(2122212=+++x x x x x f ,证明:21521-≥+x x .请在第22、23题中任选一题作答,如果多做,则按所做的第一题记分. 22. (本小题满分10分) 选修4-4:坐标系与参数方程在直角坐标系xOy 中, 过点)23,23(P 作倾斜角为α的直线l 与曲线1:22=+y x C 相交于不同的两点N M ,.(I)写出直线l 的参数方程; (II)求PNPM 11+ 的取值范围.23. (本小题满分10分) 选修4-5:不等式选讲已知函数1)(-=x x f(I)求不等式01)(2>-+x x f 的解集;(II)设m x x g ++-=3)(,若关于x 的不等式)()(x g x f <的解集非空,求实数m 的取值范围.山西大学附属中学2016~2017学年高三第一学期12月(总第六次)模块诊断数学评分细则一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.二、填空题(每题5分,满分20分,将答案填在答题纸上) 13.(理)28(文)30x y --=.14.815.(0,2)16.41,3⎡⎤⎢⎥⎣⎦三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.) 17. (1)依题意,ac b =2 由正弦定理及.16925sin sin sin ,135sin 2===B C A B 得-------------------3分 .51325169135sin sin sin sin sin )sin(sin cos sin cos tan 1tan 1=⨯==+=+=+C A B C A C A C C A A C A --6分 (2)由.0cos 12cos >=B B ac 知由.1312cos ,135sin ±==B B 得(舍去负值)-------------------------------8分 从而,.13cos 122===Bac b --------------------------------------------9分由余弦定理,得.cos 22)(22B ac ac c a b --+=代入数值,得).13121(132)(132+⨯⨯-+=c a 解得:.73=+c a --12分 理科18.解(Ⅰ)由题意知,乙每局获胜的概率皆为21133-=.…………1分比赛进行4局结束,且乙比甲多得2分即头两局乙胜一局,3,4局连胜,则12212114333381P C =⋅⋅⋅=. (Ⅱ)由题意知,ξ的取值为2,4,6.………5分 则22215(2)()()339P ξ==+=…………6分12122212212120(4)()()33333381P C C ξ==+=…………7分 1221216(6)()3381P C ξ===…………9分所以随机变量ξ的分布列为ξ246P5920811681………10分则520162662469818181Eξ=⨯+⨯+⨯= (12)文科18.解:(1)由已知得,抽取的100名学生中,男生60名,女生40名,分数小于等于110分的学生中,男生人有60×0.05=3(人),记为A1,A2,A3;女生有40×0.05=2(人),记为B1,B2;…从中随机抽取2名学生,所有的可能结果共有10种,它们是:(A1,A2),(A1,A3),(A2,A3),(A1,B1),(A1,B2),(A2,B1),(A2,B2),(A3,B1),(A3,B2),(B1,B2);其中,两名学生恰好为一男一女的可能结果共有6种,它们是:(A1,B1),(A1,B2),(A2,B1),(A2,B2),(A3,B1),(A3,B2);故所求的概率为P==(2)由频率分布直方图可知,在抽取的100名学生中,男生 60×0.25=15(人),女生40×0.375=15(人);…据此可得2×2列联表如下:所以得K2==≈1.79;…因为1.79<2.706,所以没有90%的把握认为“数学尖子生与性别有关”(理科)19.解析:(1)由题意知,ABC ∆,ACD ∆都是边长为2的等边三角形,取AC 中点O ,连接BO ,DO , 则AC BO ⊥,AC DO ⊥,又∵平面⊥ACD 平面ABC ,∴⊥DO 平面ABC ,作⊥EF 平面ABC , 那么DO BF ∥,根据题意,点F 落在BO 上,∵BE 和平面ABC 所成的角为 60,∴ 60=∠EBF , ∵2=BE ,∴3==DO EF ,∴四边形DEFO 是平行四边形,∴OF DE ∥, ∵DE 不包含于平面ABC ,⊂OF 平面ABC ,∴∥DE 平面ABC .(2)解法一:作BC FG ⊥,垂足为G ,连接EG ,∵⊥EF 平面ABC ,∴BC EF ⊥,又F FG EF = ,∴⊥BC 平面EFG ,∴BC EG ⊥,∴EGF ∠就是二面角A BC E --的平面角.EFG RT ∆中,3,2130sin ==⋅=EF FB FG ,213=EG ,∴1313cos ==∠EG FG EGF , 即二面角A BC E --的余弦值为1313. 解法二:建立如图所示的空间直角坐标系xyz O -,)3,13,0(),0,0,1(),0,3,0(--E C E,∴(1,3,0),(0,BC BE =--=-,平面ABC 的一个法向量为)1,0,0(1=n ,设平面BCE 的一个法向量为2(,,)n x y z =,则2200n BC n BE ⎧⋅=⎪⎨⋅=⎪⎩,∴00x y ⎧--=⎪⎨--=⎪⎩,∴2(n =-. 所以12121213cos ,13n n n n n n ⋅<>==⋅, 又由图知,所求二面角的平面角是锐角,二面角A BC E --的余弦值为1313.(文科)19.解析:(1)设O 为AB 的中点,连结1A O ,∵14AF AB =,O 为AB 的中点,∴F 为AO 的中点,又∵E 为1AA 的中点,∴1//EF A O ,又∵D 为11A B 的中点,O 为AB 的中点,∴1A D OB =,又∵1//A D OB ,∴四边形1A DBO 为平行四边形,∴1//A O BD ,又∵1//EF A O ,∴//EF BD ,又∵EF ⊄平面1DBC ,BD ⊂平面1DBC ,∴//EF 平面1DBC ;(2)∵12AB BC CA AA ====, D ,E 分别为11A B ,1AA 的中点,14AF AB =,∴1C D ⊥面11ABB A ,而11D BEC C BDE V V --=, 1111BDE ABA B BDB ABE A DES S S S S ∆∆∆∆=---1113222121112222=⨯-⨯⨯-⨯⨯-⨯⨯=,∵1C D =111113332D BEC C BDE BDE V V S C D --∆==⋅=⨯=. 20. 解:(1)22222122c e a c a ==→=,设(,)P m n ,又1(,0)F c -,2(,0)F c ,2274m n +=,2223(,)(,)4c m n c m n m c n ---⋅--=-+=,2273144c c -=→=,从而222, 1.a b == 椭圆C 的方程为22 1.2x y += …………4分 (2)设1:3AB l y kx =-代入椭圆整理得22416(21)039k x kx +--=,0∆>成立. 记11(,)A x y ,22(,)B x y ,则12243(21)k x x k +=+,122169(21)x x k =-+, 设存在定点(0,)M m ,0MA MB ⋅=11221212(,m)(,m)(m)(m)0x y x y x x y y -⋅-=+--=121222121211(m )(m )0,3311(1)()()()033x x kx kx k x x k m x x m +----=+-++++=222216141(1)()()09(21)33(21)3k k k m m k k -+⋅-⋅+++=++222212116(1)12()9(21)()0,339k k m k m m -+-+++++=22218(1)(9m 6m 15)0k m -++-=,22101.96150m m m m ⎧-=⇒=⎨+-=⎩ 存在定点(01)M 满足要求. …………12分 21.解析:(Ⅰ))0(12121)(2>++-=+-='x xx x x x x f ,由0)(<'x f ,得0122>--x x ,又0>x ,所以1>x .所以)(x f 的单调减区间为),1(+∞. (Ⅱ)令1)1(21ln ]1)12[()()(22+-+-=-+--=x a ax x ax x a x f x g , 所以xx a ax a ax x x g 1)1()1(1)(2+-+-=-+-='.当0≤a 时,因为0>x ,所以0)(>'x g .所以)(x g 在),0(+∞上是递增函数,又因为02231)1(1211ln )1(2>+-=+-+⨯-=a a a g ,所以关于x 的不等式1)12()(2-+-≤ax x ax f 不能恒成立. 当0>a 时,xx a x a x x a ax x g )1)(1(1)1()(2+--=+-+-=', 令0)(='x g ,得ax 1=.所以当)1,0(a x ∈时,0)(>'x g ;当),1(+∞∈a x 时,0)(<'x g ,因此函数)(x g 在)1,0(ax ∈是增函数,在),1(+∞∈a x 是减函数.故函数)(x g 的最大值为a a a a a a a a g ln 2111)1()1(211ln )1(2-=+⨯-+⨯-=.令a a a h ln 21)(-=,因为021)1(>=h ,02ln 41)2(<-=h ,又因为)(a h 在),0(+∞∈a 是减函数.所以当2≥a 时,0)(<a h .所以整数a 的最小值为2. (Ⅲ)由0)(2)()(21222121=++++x x x x x f x f ,即0ln ln 2122221211=++++++x x x x x x x x ,从而)l n ()()(212121221x x x x x x x x ⋅-⋅=+++ 令21x x t ⋅=,则由t t t ln )(-=ϕ得,tt t 1)(-='ϕ,可知,)(t ϕ在区间)1,0(上单调递减,在区间),1(+∞上单调递增.所以1)1()(=≥ϕϕt , 所以1)()(21221≥+++x x x x ,又021>+x x , 因此21521-≥+x x 成立 请在第22、23题中任选一题作答,如果多做,则按所做的第一题记分。
山西省山大附中高三数学12月月考试题 文(含解析)
山西省山大附中高三12月月考数学试题(文科)考试时间:120分钟 满分:150分【试卷综析】本试卷是高三文科试卷,以基础知识和基本技能为载体,以能力测试为主导,在注重考查学科核心知识的同时,突出考查考纲要求的基本能力,重视学生科学素养的考查.知识考查注重基础、注重常规、注重主干知识,兼顾覆盖面.试题重点考查:不等式、函数的性质及图象、三角函数、解三角形、数列、平面向量、立体几何、导数的应用、圆锥曲线、复数、集合、程序框图、参数方程、不等式选讲等;考查学生解决实际问题的综合能力,是份较好的试卷.【题文】一、选择题(本大题共12题,每小题5分,共60分.)【题文】1.设不等式02≤-x x 的解集为M ,函数()x x f -=1lg )(的定义域为N ,则=⋂N MA.(]0,1-B.[)1,0C.()1,0D.[]1,0【知识点】集合的运算A1 【答案】【解析】B解析:由02≤-x x 得0≤x ≤1,所以M=[0,1],由10x ->得-1<x <1,所以N=(-1,1),则[)0,1M N =I ,所以选B.【思路点拨】可先解不等式得M ,求函数的定义域得N ,再求交集即可. 【题文】2.若复数z 满足()i z i 21-2+=,则z 的虚部位为 A.55 B.i 55C.1D.i 【知识点】复数的运算L4 【答案】【解析】A解析:因为()1222555i z i i +==+=+-,所以虚部为5,则选A. 【思路点拨】可先由已知条件计算出复数z 再判断其虚部,即可解答.【题文】3.命题“若b a ,都是偶数,则b a +是偶数”的逆否命题是A.若b a +不是偶数,则b a ,都不是偶数B.若b a +不是偶数,则b a ,不都是偶数C.若b a ,都不是偶数,则b a +不是偶数D.若b a ,不都是偶数,则b a +不是偶数 【知识点】命题及其关系A2 【答案】【解析】B解析:由命题的逆否命题的含义可知选B.【思路点拨】写一个命题的逆否命题,可先写出其否命题,再对条件和结论同时否定即可. 【题文】4.已知等差数列{}n a 且()()48231310753=++++a a a a a ,则数列{}n a 的前13项和为A.24B.39C.52D.104 【知识点】等差数列的性质D2 【答案】【解析】C解析:因为()()3571013410732661248a a a a a a a a ++++=+==,所以74a =,则1371352S a ==,所以选C.【思路点拨】一般遇到等差数列时,可先观察项的项数是否有性质特征,有性质特征的可用性质转化求解.【题文】5.若抛物线2ax y =的焦点坐标是(0,1),则=aA.1B.21 C.2 D.41【知识点】抛物线的性质H7【答案】【解析】D 解析:因为抛物线方程为21x y a =,所以其焦点坐标为10,4a ⎛⎫⎪⎝⎭,则有111,44a a ==,所以选D.【思路点拨】本题主要考查的是抛物线的性质,由抛物线的方程求其焦点坐标时应先把方程化成标准方程再进行求值.【题文】6.已知函数),0(cos sin )(R x ab x b x a x f ∈≠-=在4π=x 处取得最大值,则函数⎪⎭⎫⎝⎛-=x f y 4π是 A.偶函数且它的图像关于点()0,π对称B.偶函数且它的图像关于点⎪⎭⎫⎝⎛023,π对称 C.奇函数且它的图像关于点⎪⎭⎫⎝⎛023,π对称D.奇函数且它的图像关于点()0,π对称 【知识点】三角函数的图象与性质C3【答案】【解析】B解析:因为函数),0(cos sin )(R x ab x b x a x f ∈≠-=在4π=x 处取得最大值,所以-=,b=-a ,所以()()sin cos sin cos sin 4f x a x b x a x x x π⎛⎫=-=+=+ ⎪⎝⎭(a>0),则sin cos 42y f x x x ππ⎛⎫⎛⎫=-=-= ⎪ ⎪⎝⎭⎝⎭,所以为偶函数,且它的图像关于点⎪⎭⎫⎝⎛023,π对称,则选B.【思路点拨】可先结合最大值点得出a,b 关系,再把函数f(x)化成一个角的三角函数进行解答判断即可.【题文】7.已知A,B,C 三点是某球的一个截面的内接三角形的三个顶点,其中30,24,18===AC BC AB ,球心到这个截面的距离为球半径的一半,则该球的表面积为 A.π1200 B.π1400 C.π1600 D.π1800 【知识点】球的截面性质G8 【答案】【解析】A解析:因为222AB BC AC +=,所以三角形ABC 外接圆圆心在AC 中点处,半径为15,设球半径为R ,由球的截面性质得222152R R ⎛⎫-= ⎪⎝⎭,得2300R =,所以该球的表面积为241200R ππ=,则选A.【思路点拨】一般遇到球的截面问题时,通常利用球的截面性质寻求截面与球半径的关系进行解答.【题文】8.已知以下三视图中有三个同时表示某一个三棱锥,则不是该三棱锥的三视图是【知识点】三视图G2 【答案】【解析】D解析:三棱锥的三视图均为三角形,四个答案均满足;且四个三视图均表示一个高为3,底面为两直角边分别为1,2的棱锥;A 与C 中俯视图正好旋转180°,故应是从相反方向进行观察,而其正视图和侧视图中三角形斜边倾斜方向相反,满足实际情况,故A ,C 表示同一棱锥;设A 中观察的正方向为标准正方向,以C 表示从后面观察该棱锥;B 与D 中俯视图正好旋转180°,故应是从相反方向进行观察,但侧视图中三角形斜边倾斜方向相同,不满足实际情况,故B ,D 中有一个不与其它三个一样表示同一个棱锥,根据B 中正视图与A 中侧视图相同,侧视图与C 中正视图相同,可判断B 是从左边观察该棱锥,综上可知选D. 【思路点拨】由已知中的四个三视图,可知四个三视图,分别表示从前、后、左、右四个方向观察同一个棱锥,但其中有一个是错误的,根据A 与C 中俯视图正好旋转180°,故应是从相反方向进行观察,而其正视图和侧视图中三角形斜边倾斜方向相反,满足实际情况,可得A ,C 均正确,而根据AC 可判断B 正确,D 错误.【题文】9.执行如图所示的程序框图,若13)(2-=x x f ,取101=ε,则输出的值为 A.3219 B.169 C.85 D.43【知识点】程序框图 二分法求方程近似解B9 L1 【答案】【解析】A解析:因为()()010,120f f =-<=>,第一次执行循环体时13110244f ⎛⎫=-=-<⎪⎝⎭,,12a =,11112210b a -=-=>;第二次执行循环体327111041616f ⎛⎫=-=> ⎪⎝⎭,311,4410b b a =-=>;第三次执行循环体5751151110,,864648810f b b a ⎛⎫=-=>=-=> ⎪⎝⎭,第四次执行循环体9139110.,16256161610f a b a ⎛⎫=-<=-=< ⎪⎝⎭,所以输出9519168232+=,则选A.【思路点拨】遇到循环结构的程序框图时,可依次执行循环体,直到跳出循环再进行判断即可.【题文】10.已知约束条件⎪⎩⎪⎨⎧≤≥-≤+-10012x y ax y x 表示的平面区域为D ,若区域D 内至少有一个点在函数xe y =的图像上,那么实数a 的取值范围为A.[)4,eB.[)+∞,eC.[)3,1D.[)∞+,2 【知识点】简单的线性规划E5【答案】【解析】B解析:由题意作出其平面区域及函数y=e x 的图象,结合函数图象知,当x=1时,y=e x=e ; 故实数a 的取值范围为[e ,+∞),所以选B..【思路点拨】可先作出指数函数xe y =的图象,再由不等式表示的平面区域数形结合得出实数a 满足的条件即可.【题文】11.已知函数x x x g kx x f ln )(,)(==,若关于x 的方程)()(x g x f =在区间⎥⎦⎤⎢⎣⎡e e ,1内有两个实数解,则实数k 的取值范围是 A.⎪⎭⎫⎢⎣⎡e e 21,12 B.⎥⎦⎤ ⎝⎛e e 1,21 C.⎪⎭⎫ ⎝⎛210e , D.⎪⎭⎫⎝⎛+∞,1e 【知识点】函数与方程B9【答案】【解析】A 解析:由)()(x g x f =得2ln x k x =,令()2ln x t x x =,由()312ln '0xt x x -==得x e =得函数t(x)在1e e ⎡⎢⎣上单调递增,在,e e ⎤⎦上单调递减,又()22111,,2te t e t e e e e ⎛⎫==-= ⎪⎝⎭,所以若关于x 的方程)()(x g xf =在区间⎥⎦⎤⎢⎣⎡e e ,1内有两个实数解,则实数k 的取值范围是⎪⎭⎫⎢⎣⎡e e 21,12,则选A. 【思路点拨】一般遇到方程的解的个数问题通常转化为函数的图象的交点个数问题;通过导数研究函数的单调性及极值;通过对k 与函数h (x )的极值的大小关系的讨论得到结论.【题文】12.已知椭圆C:)0(12222>>=+b a by a x 的左右焦点为21,F F ,若椭圆C 上恰好有6个不同的点P ,使得P F F 21∆为等腰三角形,则椭圆C 的离心率的取值范围是A.⎪⎭⎫ ⎝⎛3231, B.⎪⎭⎫ ⎝⎛121, C.⎪⎭⎫⎝⎛132, D.⎪⎭⎫ ⎝⎛⋃⎪⎭⎫ ⎝⎛1212131,, 【知识点】椭圆的几何性质H5【答案】【解析】D解析:6个不同的点有两个为短轴的两个端点,另外4个分别在第一、二、三、四象限,且上下对称左右对称。
山西省山大附中高三12月月考语文试题.pdf
山西大学附中 2012~2013学年第一学期高三(12月)月考 语文试题 考试时间 130分钟 本试卷分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分。
满分150分。
注意事项: 1.答题前,考生务必将自己的姓名、准考证号、 班级填写在答题卡上。
2.全部答案在答题卡上完成,答在本试题上无效。
第Ⅰ卷 阅读题 一、现代文阅读(9分,每小题3分) 阅读下面的文字,完成1~3题。
形具快乐生 张保振 一个时期以来,谈论快乐的话题愈来愈多。
工作上有“快乐工作”说,生活上有“快乐生活”说,竞技场上有“快乐足球”说,学校有“快乐学习”说,研究领域有“快乐经济学”说,等等。
人生来具有趋乐避苦的本性。
追求快乐,享受快乐,为人之常情。
问题是什么叫快乐,怎样才能求得快乐。
快乐是感觉,如何求之呢?马克思主义者对快乐有着自己的感受。
谢觉哉在谈到长征中的艰苦与快乐时说,“不可能有从天上掉下来一个快乐来给你享受”,“只有经过劳作、经过奋斗得来的快乐,才是真正的快乐”,这就告诉我们,形具快乐才生。
形具快乐生,首要在“形”。
形是一种载体,是一种形体。
无“形”,快乐就成了无本之木。
毫无疑问,凡变化者,在天成象,在地成形。
无形难变,更难转化为快乐。
这种形,具体到日常的生活工作中,就是大量的、琐碎的、不起眼的一件一件的具体工作。
这些工作,或决策,或管理,或科研,或操作等,都是对建设小康社会的参与,对创造新生活的奉献。
这些工作,因我参与、我奉献而快乐。
因为说到底,形为快乐之质,快乐为形器之用。
形与快乐,犹如刀之刃、山之峰,形存快乐存,形谢快乐灭。
形具快乐生,重要在“具”。
具是一种状态,这种状态的潜台词叫“足”,同义语为“办”。
一件事情与工作之“形”,做起来会有难易,论起会有高下,但不论是非凡或是平凡,只有全身心地投入进去,专心致志,精益求精,不畏劳苦,百折不回,才有可能困难脚下踩,快乐心头生。
如果是言语的巨人,行动的矮子,对事不“具”不“办”,或是三心二意,少“具”缺“足”,东一榔头西一棒,又怎么能享受经过劳作、奋斗、拼搏而取得成功后的快乐呢? 形具快乐生,关键在“生”。
解析山西大学附中最新高三12月月考生物试题
word版高中生物山西大学附中2021~2021学年第一学期高三(12月)月考ﻭ生物试题ﻭ(考查时间:90min满分:90分)【试卷综析】本卷为山西大学附中2021~2021学年第一学期高三(12月)月考生物试题,考查的知识点有:细胞的物质基础、细胞的结构功能,细胞代谢、细胞增殖及细胞生命历程、生物的遗传变异、生物进化以及动物生命活动调节等,重点考查了光合作用、呼吸作用、遗传变异和生命活动调节的有关内容.本卷试题难度中等,符合高三一轮模拟考试要求。
ﻭ一、选择题(共40小题,每小题1分,共40分,每小题只有一个选项最符合题意)【题文】1. 下图表示胰岛素分子中一条多肽链,其中有3个甘氨酸(结构式:NH2—CH2—COOH)且位于第1、8、23位.下列叙述正确的是( )ﻫINCLUDEPICTURE".。
/Application%20Data/Tencent/Users/1312838645/QQ/WinTemp/RichOle/7G%60QR@X4P3_G1Q21YWU%60Z(K.png" \* MERGE FORMAT ﻭﻵﻡA.图中多肽至少含有一个羧基(位于第1位)和一个氨基(位于第30位)ﻭB.用特殊水解酶除去图中3个甘氨酸,形成的产物比原多肽多5个氧原子ﻭC.用特殊的水解酶选择性除去图中3个甘氨酸,形成的产物中有4条多肽ﻭD.该多肽释放到细胞外需要经过两种细胞器的加工ﻭ【答案】【知识点】A2蛋白质和核酸ﻭ【答案解析】D解析:一条多肽链至少含一个羧基和一个氨基,但不能确定哪一端是氨基,哪一端是羧基,A错;除去1号位甘氨酸会破坏一个肽键,除去第8位和第23位甘氨基各会破坏两个肽键,破坏肽键时产生的羧基会增加一个氧原子,但同时去除甘氨酸会带走一个氧原子,因此新形成的产物中氧原子数和原多肽的氧原子数相等,B错;用特殊的水解酶选择性除去图中3个甘氨酸,形成的产物中有3条多肽,C错;该多肽释放到细胞外需要经过内质网和高尔基体这两种细胞器的加工,D正确。
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山西大学附中2015—2016学年高三第一学期12月月考
数学试题(文)
考试时间:120分钟 满分:150分
一.选择题(本大题共12题,每小题5分,共60分.)
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B .若:p 0R x ∃∈,2
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D .“若6
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5.执行如图所示的程序框图,输出2015
2016
s =
,那么判断框内应填( ) A .2015?k ≤ B .2016?k ≤ C .2015?k ≥ D .2016?k ≥
6.一个几何体的三视图如右图所示,则该几何体的表面积为( ) A .
3
2
B .6262++
C .
1
2
D .3262++
7 . 已知变量,x y 满足240
220
x y x x y -+≥⎧⎪≤⎨⎪+-≥⎩
,则3
2x y x +++的取值范围是
( )
(A )52,2⎡⎤
⎢⎥⎣⎦ (B )55,42⎡⎤
⎢⎥⎣⎦ (C )45,52⎡⎤
⎢⎥⎣⎦ (D )5
,24⎡⎤⎢⎥⎣⎦
8.对具
有线性相关关系的变量x ,y ,测
得一组数据如下表:
根据上表,利用最小二乘法得它们的回归直线方程为10.5y x a =+,则a 的值等于( ) A .1 B .1.5 C .2 D .2.5 9.已知函数()f x 是定义在[]1,2a a -上的偶函数,且当0x >时,()f x 单调递增, 则关于x 的不等式(1)()f x f a ->的解集为( ) A .45[,)33 B .]35,34()32,31[⋃ C .)3
2
,31[]31,32(⋃--
D .随a 的值而变化 10.三棱锥P ABC -中,PA ⊥平面ABC ,AC BC ⊥,1AC BC ==,3PA =
,则该三棱锥外接球
的表面积为( )
A .π5
B .π2
C .π20
D .π4
11. 如图,1F 、2F 是双曲线22
221x y a b
-=(0a >,0b >)的左、
右焦点,过1F 的直线l 与双曲线的左右两支分别交于点A 、B .若2F ∆AB 为等边
三角形,则双
曲线的离心率为( )
A .4
B .7
C .
23
3
D .3 12.等差数列{}n a 的前n 项和为*
()n S n N ∈,且满足150S >,160S <,
则
11S a ,2
2
S a ,... ,1515S a 中最大的项为( ) A .
66S a B .77S a C .99S a D .88
S
a 二.填空题(本大题共4小题,每小题5分,共20分.)
13.等比数列{}n a 的前n 项和=2+2n
n S a a ⋅-,则a =_______.
14.记集合(){}2
2,|16A x y x
y =
+≤,集合()(){},|40,,B x y x y x y A =+-≤∈表示的平面区域分别为
12,ΩΩ.若在区域1Ω内任取一点(),P x y ,则点P 落在区域2Ω中的概率为_ __
15.已知菱形ABCD 的边长为2,120BAD ∠=︒,点E ,F 分别在边BC 、DC 上,3BC BE =,
DC DF λ=.若1,AE AF ⋅=,则λ的值为
16.已知函数()f x (R x ∈)满足()11f =,且()f x 的导数()12
f x '<,则不等式()
22
122x f x <
+的解集为
三.解答题(本大题共6小题,共70分.) 17.(本小题满分12分)已知函数(
)
()2cos 3cos sin 2
22
x
x x f x =-.
(1)设ππ22θ⎡⎤∈-⎢⎥⎣⎦
,,且()31f θ=+,求θ的值; (2)在△ABC 中,AB=1,()31f C =+,且△ABC 的面积为3
2
,求sinA+sinB 的值.
18.如图,直四棱柱1111ABCD A B C D -的底面ABCD 是菱形,∠ADC =0120,11AA AB ==,点1O O 、分别是上下底菱形对角线的交点.
(1)求证:1A O ∥平面11CB D ; (2)求点O 到平面11CB D 的距离.
19.(本小题满分12分)某工厂甲、乙两个车间包装同一种产品,在自动包装传送带上每隔一小时抽一包产品,称其重量(单位:克)是否合格,分别记录抽查数据,获得重量数据茎叶图(如右).
(Ⅰ)根据样本数据,计算甲、乙两个车间产品重量的均值与方差,并说明哪个车间的产品的重量相对稳定;
(Ⅱ)若从乙车间6件样品中随机抽取两件,求所抽取两件样品重量之
差不超过2克的概率.
20.(本小题满分12分)已知椭圆C 的对称中心为原点O ,焦点在x 轴上,左右焦点分别为1F 和2F ,且
122F F =,点31,2⎛⎫
⎪⎝⎭
在该椭圆上.
(Ⅰ)求椭圆C 的方程;
(Ⅱ)过1F 的直线l 与椭圆C 相交于A ,B 两点,若△2AF B 的面积为122
7
,求以2F 为圆心且与直线l 相切圆的方程.
21.(本小题满分12分设函数()2
2ln f x x x a x =-+
(1)当2a =时,求函数()f x 在点()()
1,1f 处切的切线方程;
(2)若函数()f x 存在两个极值点()1212x x x x <、,①求实数a 的范围;
②证明:()123
ln 22
f x x >--
请考生在第22、23二题中任选一题作答(在答题卡相应位置填涂),如果多做,则按所做的第一题记分 22.(本小题满分10分)选修4-4:坐标系统与参数方程 在直角坐标系xOy 中,半圆C 的参数方程为1cos sin x y ϕ
ϕ=+⎧⎨=⎩
(ϕ为参数,0ϕπ≤≤),以O 为极点,x 轴的
非负半轴为极轴建立极坐标系. (Ⅰ)求C 的极坐标方程;
(Ⅱ)直线l 的极坐标方程是(sin 3cos )53ρθθ+=,射线OM :3
π
θ=与半圆C 的交点为O 、P ,与直
线l 的交点为Q ,求线段PQ 的长.
23.(本题小满分10分)选修4—5:不等式选讲 已知函数()212f x x x a =-++,()3g x x =+. (Ⅰ)当2a =-时,求不等式()()f x g x <的解集; (Ⅱ)设1a >-,且当1
[,)22
a x ∈-
时,()()f x g x ≤,求a 的取值范围.。