廊坊分校教学A楼A-301(A-301)
河北省廊坊市2024-2025学年八年级上学期11月月考数学试题(含答案)
2024—2025学年度八年级上学期阶段评估（二）数学上册第十一~十四章注意事项：共8页，总分120分，考试时间120分钟．一、选择题（本大题共12个小题，每小题3分，共36分．在每小题给出的四个选项中，只有一项是符合题目要求的）1．计算：（ ）A ．1B ．2C ．3D ．42．下列多边形中，内角和度数与其外角和度数相等的是（ ）A ．B ．C ．D ．3．下列运算正确的是（ ）A ．B ．C ．D ．4．如图，嘉嘉书上的三角形被污染了一部分，很快他就根据所学知识画出一个与书上全等的三角形，则这两个三角形全等的依据是（ ）A ．ASAB ．SASC ．AASD ．SSS5．下列多项式的乘法中，不能运用平方差公式进行计算的是（ ）A ．B ．C ．D ．6．当n 为正整数时，一定能被某个数整除，则该数可能是（ ）A ．5B ．8C ．9D ．127．如图，在中，根据尺规作图的痕迹，下列四个结论中，一定正确的有①；②；③；④．0122+=236a a a ⋅=826a a a -=()326a a =623a a a ÷=()()11x x +-()()22x y x y ---+()()22m n m n -++()()a b a b -+-()()2224n n +--ABC △AF CF =AD BD =AF BF =BAF FBC ∠=∠A ．4个B ．3个C ．2个D ．1个8．若与的乘积中不含x 的一次项，则m 的值为（ ）A ．B ．-3C ．0D ．39．在和中，，，．已知，则（ ）A ．30°B ．C ．或D ．30°或150°10．如图，在长为5m ，宽为3m 的长方形空地上规划一块长方形花园（图中阴影部分），花园的北面和东、西两面都留有宽度为m 的小路（图中空白部分），则花园的面积为（ ）A ．m 2B ．m 2C ．m 2D ．m 211．如图，在中，，D ，E ，F 分别是，，上的点，且，，若，则的度数为（ ）A ．94°B ．96°C ．104°D ．138°12．如图，点E 在等边的边上，，射线于点C ，P 是射线上一动点，F 是线段上一动点，当的和最小时，，则的长为（ ）A ．14B ．13C ．12D ．10二、填空题（本大题共4个小题，每小题3分，共12分）13．蝴蝶颜色炫丽，翩翩起舞时非常美丽，深受人们喜爱，它的图案具有对称美．如图，蝴蝶图案关于y x m +23x +32-ABC △A B C '''△30C C '∠=∠=︒8AC A C ''==5AB A B ''==B m ∠=︒B '∠=m ︒m ︒()180m -︒()01x x <<()221115x x -+()24106x x -+()24106x x +-()2276x x -+ABC △CA CB =AB AC BC AE BD =AD BF =42EDF ∠=︒C ∠ABC △BC 6BE =CD BC ⊥CD AB EF PF +7PF =AC轴对称，点P 的对应点为，若点P 的坐标为，则点的坐标为______．第13题图14．在中，，，，在的延长线上取一点D ，使，则C ，D 两点之间的距离为______．15．如图，是等边三角形，D 为边上一点，以为边作等边，连接．若，则的度数是______．第15题图16．已知甲、乙都是长方形，它们的边长如图所示（a 为正整数），甲、乙的面积分别为，．若满足条件的整数n 有且只有2个，则a 的值为______．三、解答题（本大题共8个小题，共72分．解答应写出文字说明、证明过程或演算步骤）17．（本小题满分7分）（1）计算：．（2）分解因式：．18．（本小题满分8分）先化简，再求值：，其中．19．（本小题满分8分）已知如图所示：P '()1,2-P 'ABC △90C ∠=︒30B ∠=︒2AC =CA AD AB =ABC △AC BD BDE △CE 20DEC ∠=︒CDB ∠1S 2S 122025S S n -<≤2202520242026-⨯22882x xy y -+()()()22221311x x x +-+--+12x =ABC △（1）尺规作图：作的角平分线AD （不写作法，保留作图痕迹）．（2）在（1）的条件下，若，，的面积为16，点E 在边上，且，连接，求的面积．20．（本小题满分8分）将幂的运算逆向思维可以得到，，，在解题过程中，根据算式的结构特征，逆向运用幂的运算法则，常可化繁为简，化难为易，使问题巧妙获解．（1）若，，求的值．（2）若，求x 的值．21．（本小题满分9分）我国数学家华罗庚曾用诗词表达了“数形结合”的思想，其中谈到“数缺形时少直观，形少数时难入微．数形结合百般好，隔离分家万事休．”请利用“数形结合”的思想解决以下问题．图1是一个长为4b ，宽为的长方形，沿图中虚线用剪刀平均分成四块小长方形，然后按如图2所示的形状拼得一个大正方形．（1）观察图1，图2，请写出，，ab 之间的等量关系：______．（2）如图3，正方形的边长为a ，正方形的边长b ，点E ，G 分别在，边上．若，，求图中阴影部分的面积．22．（本小题满分9分）【提出问题】某数学活动小组对多项式乘法进行如下探究：①；②；③．我们发现，形如的两个多项式相乘，其结果一定为（p ，q 为整数）．因式分解是与整式乘法是方向相反的变形，故有即可将形如ABC △8AB =10AC =ABD △AC AE AB =DE CDE △m n m n a a a +=⋅()nmn m a a =()n n n a b ab =2m a =3n a =32m n a+162482x x ⨯⨯=()a a b >()2a b +()2a b -ABCD CEFG CD BC 13a b +=32ab =()()21565x x x x ++=++()()23256x x x x --=-+()()24228y y y y +-=+-()()x p x q ++()2x p q x pq +++()()()2x p q x pq x p x q +++=++的多项式因式分解成（p ，q 为整数）．例如：．【初步应用】（1）用上面的方法分解因式：______．【类比应用】（2）规律应用：若可用以上方法进行因式分解，则整数m 的所有可能值是______．【拓展应用】（3）分解因式：．23．（本小题满分11分）如图，在中，，E 是的中点，交AC 于点D ，点F 在上，，交于点G ，若，．（1）求的长．（2）求的长．（3）求证：为等边三角形．24．（本小题满分12分）中线是三角形中的重要线段之一．在利用中线解决几何问题时，当条件中出现“中点”“中线”等条件时，可以考虑作辅助线，即把中线延长一倍，通过构造全等三角形，把分散的已知条件和所要求的结论集中到同一个三角形中，从而运用全等三角形的有关知识来解决问题，这种作辅助线的方法称为“倍长中线法”．（1）如图1，在中，，，D 是的中点，求边上的中线的取值范围．嘉淇在组内经过合作交流，得到了如下的解决方法：延长到点H ，使，连接．可以判定，从而得到．这样就能把线段，，集中在中，利用三角形三边的关系，可得中线AD 的取值范围是______．()2x p q x pq +++()()x p x q ++()()()22710252525y y y y y y ++=+++⨯=++2718y y +-=()236x m x +--()()2318a b a b +-+-ABC △30A ∠=︒AB DE AB ⊥DE BF CF =FG AC ⊥AC 2EF =4DF =DG CD BCF △ABC △6AB =4AC =BC BC AD AD DH AD =BH ADC HDB ≌△△4AC HB ==AB AC 2AD ABH △（2）如图2，在中，，D 为边的中点，求证：．（3）如图3，在中，，为角平分线，E 为边的中点，过点E 作的平行线，交于点F ，交的延长线于点P ．①判断和的数量关系，并说明理由；②若，，，则的长为______．2024—2025学年度八年级上学期阶段评估（二）数学参考答案1．C 2．B 3．C 4．A 5．D 6．D 7．B 8．A 9．C 10．A 11．B12．D 提示：如图，作点E 关于直线的对称点G ，过点G 作，垂足为P ，交于点F ，交于点H ，此时的值最小．∵，∴，∴，∴为等边三角形，．∵，∴，∴，∴．∵，∴为等边三角形，∴．∵和都是等边三角形，∴，，∴．在中，，∴．∵PF =7，∴FH =4，∴AC =AH +CH =4+6=10．故选D ．13． 14．6 15．100° 16．101217．（1）解：原式．3分（2）解：原式．4分18．解：原式 (3)分Rt ABC △90ACB ∠=︒AB 12CD AB =ABC △AB AC >AD BC AD AB CA BF CP 90BAC ∠=︒30ABC S =△8BF =AP AB GP CD ⊥AB AC EF PF +CD BC ⊥GP BC ∥60AFH B GFB ∠=∠=∠=︒AFH △30G ∠=︒GF EF =30FEG G ∠=∠=︒60EFP ∠=︒60BFE ∠=︒60B ∠=︒BEF △6BF BE ==ABC △AFH △AB AC =AF AH =6CH BF ==Rt CPH △30PCH ∠=︒132PH CH ==()1,2--()()220252025120251=--+()222222025202512025202511=--=-+=()()22222442222x xy y x x y y ⎡⎤=-+=-⨯⋅+⎣⎦()222x y =-()()22244169211x x x x x x =++-++--++．…5分当时，原式．…8分19．解：（1）如图1，即所求，…3分（2）如图2，过点D 作，垂足为P ，作，垂足为Q ．∵是的角平分线，∴．…5分∵，，∴，∴．答：的面积为4．…8分20．解：（1）∵，，∴．…4分（2）∵，…5分∴，解得．…8分21．解：（1）．3分（2）． (9)分22224416921128x x x x x x x =++----+-+=-12x =21152822⎛⎫=⨯-=- ⎪⎝⎭AD DP AB ⊥DQ AC ⊥AD ABC △DP DQ =1162ABD S AB DP =⋅=△8AB =4DP DQ ==()()11110844222CDE S CE DQ AC AE DQ =⋅=-⋅=⨯-⨯=△CDE △2m a =3n a =()()32323232238972m n m n mn a a a a a +=⋅=⋅=⨯=⨯=()()231231624822222x xx x x x ++⨯⨯=⨯⨯==12316x x ++=3x =()()224a b a b ab +=-+()()222111222S a a b b a ab b =-+=-+阴影部分()()221173313332222a b ab ⎡⎤=+-=-⨯=⎣⎦22．解：（1）．…2分（2）-2或2或4或8．…6分（3）．……9分23．解：（1）∵，∴．∵，∴．∵，∴，∴．∵，∴．…3分（2）如图，连接．∵，，∴．∵，，∴，∴．…5分∵E 是的中点，，∴．∵，∴，…6分∵，∴，∴，∴．…7分（3）证明：由（2）得，∴，．∵，∴，∴．…9分在中，．∵，∴为等边三角形．…11分24．解：（1）．2分（2）证明：如图1，延长到点E ，使，连接．图1∵D 为的中点，∴．()()29y y -+()()()()()()223186363a b a b a b a b +-+-=++-+++-⨯()()63a b a b =+-++DE AB ⊥90DEA ∠=︒30BAC ∠=︒60ADE ∠=︒FG AC ⊥90DGF ∠=︒30DFG ∠=︒4DF =2DG =AF 2EF =4DF =6DE =90DEA ∠=︒30BAC ∠=︒12AD =12210AG AD DG =-=-=AB DE AB ⊥AF BF =CF BF =AF CF =FG AC ⊥10CG AG ==20AC =20128CD AC AD =-=-=AF BF CF ==FAC FCA ∠=∠FAB FBA ∠=∠30BAC FAC FAB ∠=∠+∠=︒30FCA FBA ∠+∠=︒()180********BCF CBF FAC FAB FCA FBA ∠+∠=︒-∠+∠+∠+∠=︒-︒=︒BCF △()180********BFC BCF CBF ∠=︒-∠+∠=︒-︒=︒BF CF =BCF △15AD <<CD DE CD =AE AB AD BD =在和中，∴（SAS ），∴，．∵，∴，∴，即．在和中，，∴（SAS ），∴．∵，∴．…6分（3）①．…7分理由：如图2，延长到点G ，使，连接．图2∵E 为的中点，∴．在和中，，∴（SAS ），∴，．∵平分，∴．∵，∴，，∴，∴，∴，∴．…10分②2．……12分提示：∵，，∴，∴．设，∵，∴，ADE △BDC △AD BD ADE BDCED CD =⎧⎪∠=∠⎨⎪=⎩ADE BDC ≌△△AE CB =DAE B ∠=∠90ACB ∠=︒90CAB B ∠+∠=︒90CAB DAE ∠+∠=︒90CAE ∠=︒AEC △CBA △AE CB CAE ACB AC CA =⎧⎪∠=∠⎨⎪=⎩AEC CBA ≌△△CE AB =12CD CE =12CD AB =BF CP =PE EG PE =BG BC BE CE =BEG △CEP △BE CE BEG CEP EG EP =⎧⎪∠=∠⎨⎪=⎩BEG CEP ≌△△BG CP =G P ∠=∠AD BAC ∠BAD CAD ∠=∠EF AD ∥BFE BAD ∠=∠P CAD ∠=∠BFE P ∠=∠G BFE ∠=∠BF BG =BF CP =BFE P ∠=∠BFE AFP ∠=∠P AFP ∠=∠AP AF =AP AF x ==8BF =8AB x =+由①得，∴．∵，∴，∴，∴，即．8CP BF ==8AC x =-90BAC ∠=︒()()()2111886430222ABC S AB AC x x x =⋅=+-=-=△24x =2x =2AP =。
福禄克 Fluke 301A 刀锋系列钳形表 说明书
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2022年-2023年主治医师之全科医学301练习题(一)及答案
2022年-2023年主治医师之全科医学301练习题(一)及答案单选题（共30题）1、下列哪项措施不利于慢性龈缘炎的防治A.洁治术B.餐后漱口C.经常用牙签剔牙D.定期口腔检查E.以上各项都是【答案】 C2、患者女，32岁，幼年曾患麻疹，反复咳嗽、咳痰10年，多于晨起及夜间睡眠时咳大量黄痰，此次受凉后咳嗽加重，咳痰增多，为黄绿色痰，伴发热，间断咯血2次，每次量约30ml。
查体：T 38.2℃，P 100次/分，双肺呼吸音粗，双下肺可闻及粗湿啰音，血常规：WBC 12×10A.慢性支气管炎急性发作B.肺脓肿C.肺结核D.支气管扩张E.肺炎F.肺癌【答案】 D3、阵发性睡眠性血红蛋白尿症（PNH）的诊断要点是A.酸溶血试验阳性B.抗人球蛋白试验阳性C.血红蛋白电泳HbA2及HbF增高D.高铁血红蛋白还原试验异常E.小球形红细胞增多【答案】 A4、欲比较单位相同、均数相差悬殊资料的变异程度宜用A.标准差B.百分位数C.变异系数D.方差E.四分位数间距【答案】 C5、女性，35岁，今晨突然恶心，呕吐，伴眩晕，视物旋转。
查体：双眼球震颤，最可能的诊断是A.脑炎B.青光眼C.急性迷路炎D.癫痫E.尿毒症【答案】 C6、烧伤侵袭性感染中最主要的病原菌侵入途径是A.呼吸道感染B.静脉导管感染C.肠源性感染D.烧伤创面感染E.尿路感染（留置导尿所致）【答案】 D7、"人人享有卫生保健"战略目标是在何时提出的A.1977年5月第30届世界卫生大会B.1948年WHO成立时C.1980年第33届世界卫生大会D.1978年国际初级卫生保健大会E.1997年第50届世界卫生大会【答案】 A8、氨基糖苷类抗生素的主要不良反应是A.第八对脑神经损害B.肌痉挛C.肝脏损害D.灰婴综合征E.胃肠道反应【答案】 A9、绝大部分高频电疗的禁忌证A.局部金属异物、植有心脏起搏器B.慢性消化系统疾病C.慢性炎症D.骨关节炎E.伤口愈合迟缓【答案】 A10、肌力增强训练是康复治疗中常用技术之一，理解和掌握肌力增强的理论和方法的正常运用(每种方法各有其优缺点)，常可达到较好治疗效果A.力学、解剖学和生理学条件的综合B.肌肉本身体积的大小C.肌肉收缩的长度D.后负荷的大小E.肌肉的初长【答案】 A11、在体外放射分析中，以标记抗原及其特异性抗体在适当的反应体系中发生免疫反应，形成抗原体复合物为基础的方法是A.免疫放射分析B.放射受体分析C.放射免疫分析D.受体放射分析E.酶免疫分析【答案】 C12、女性，25岁，既往曾因活动时心悸、气短，诊断为风心病，二尖瓣狭窄。
安全生产-高处作业理论考试题及答案(301-400)
安全生产-高处作业理论考试题及答案（301-400）301、固定式平台又称为( )。
A、折叠式B、组合式C、脚手架正确答案：C302、固体物质火灾属于( )类火灾。
A、AB、BC、C正确答案：A303、挂点装置的人员载重量为( )Kg。
A、50B、60C、70正确答案：C304、挂梯的脚踏板间隔应选择( )mm。
A、200至300B、300至400C、400至500正确答案：B305、挂梯的宽度应选择( )mm。
A、400至500B、500至600C、300至400正确答案：A306、挂梯的踏脚间距不宜过大或过小,( )mm间距选择不合理。
A、200B、300C、400正确答案：A307、挂梯顶端应高出楼顶上沿以便于人员上下,其高度不宜过高,也不宜过低,( )mm高度选择不合理。
A、300B、500C、800正确答案：A308、挂梯扶手高度不宜过高过低,( )mm高度选择不合理。
A、100B、200C、300正确答案：A309、挂梯高度不宜过高,( )m高度的挂梯选择不合理。
A、4B、5C、8正确答案：C310、挂梯上方应高出楼房外沿( )mm。
A、500至800B、800至1000C、1000至1500正确答案：C311、挂梯是在高处作业中十分常见,是一种在不适合设置悬吊设备、设施,且使用时间较长的情况下使用的( )设施。
A、攀登B、行走C、攀爬正确答案：C312、管道安装从( )开始,按水流方向将预制加工好的管段按照编号运放至相应的位置上,排列整齐。
A、排气口B、出水口C、进水口正确答案：C313、管道水平安装时,应有( )的坡度坡向泄水处,且管道坡度均匀。
A、2‰至5‰B、2‰至4‰C、4‰至5‰正确答案：A314、管道水平安装时,应有2‰~5‰的坡度坡向泄水处,且管道坡度均匀。
管道翻身处低点应设置泄水装置,对于( )系统最高点还应设有自动放风装置。
A、冷水B、给水C、热水正确答案：C315、贯彻安全责任制,( )各级行政正职人员为安全施工的第一责任者,对安全施工负直接领导责任。
河北省廊坊市六校联考2024年高三第一次适应性测试数学试题
河北省廊坊市六校联考2024年高三第一次适应性测试数学试题注意事项：1． 答题前，考生先将自己的姓名、准考证号填写清楚，将条形码准确粘贴在考生信息条形码粘贴区。
2．选择题必须使用2B 铅笔填涂；非选择题必须使用0．5毫米黑色字迹的签字笔书写，字体工整、笔迹清楚。
3．请按照题号顺序在各题目的答题区域内作答，超出答题区域书写的答案无效；在草稿纸、试题卷上答题无效。
4．保持卡面清洁，不要折叠，不要弄破、弄皱，不准使用涂改液、修正带、刮纸刀。
一、选择题：本题共12小题，每小题5分，共60分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1．如图所示，正方体ABCD -A 1B 1C 1D 1的棱长为1，线段B 1D 1上有两个动点E 、F 且EF =22，则下列结论中错误的是（ ）A ．AC ⊥BEB ．EF //平面ABCDC ．三棱锥A -BEF 的体积为定值D ．异面直线AE ,BF 所成的角为定值2．已知2π()12cos ()(0)3f x x ωω=-+>.给出下列判断： ①若12()1,()1f x f x ==-，且12minπx x -=，则2ω=；②存在(0,2)ω∈使得()f x 的图象向右平移6π个单位长度后得到的图象关于y 轴对称； ③若()f x 在[]0,2π上恰有7个零点，则ω的取值范围为4147,2424⎡⎫⎪⎢⎭⎣； ④若()f x 在ππ,64⎡⎤-⎢⎥⎣⎦上单调递增，则ω的取值范围为20,3⎛⎤ ⎥⎝⎦.其中，判断正确的个数为（ ） A ．1B ．2C ．3D ．43．已知复数168i z =-，2i z =-，则12z z =（ ） A ．86i -B ．86i +C ．86i -+D ．86i --4．已知函数2()ln f x ax x x =-+有两个不同的极值点1x ，2x ，若不等式()()()12122f x f x x x t +>++有解，则t 的取值范围是（ ） A ．(,2ln 2)-∞- B ．(],2ln 2-∞- C ．(,112ln 2)-∞-+D ．(],112ln 2-∞-+5．已知命题P ：x R ∀∈，sin 1x ≤，则p ⌝为( ) A ．0x R ∃∈，0sin 1x ≥ B ．x R ∀∈，sin 1x ≥ C ．0x R ∃∈，0sin 1x >D ．x R ∀∈，sin 1x >6．直线20(0)ax by ab ab ++=>与圆221x y +=的位置关系是（ ） A ．相交B ．相切C ．相离D ．相交或相切7．函数sin ln ||2y x x π⎛⎫=-⋅ ⎪⎝⎭图像可能是（ ） A ． B ． C ．D ．8．三棱锥S ABC -的各个顶点都在求O 的表面上，且ABC ∆是等边三角形，SA ⊥底面ABC ，4SA =，6AB =，若点D 在线段SA 上，且2AD SD =，则过点D 的平面截球O 所得截面的最小面积为（ ） A ．3πB ．4πC ．8πD ．13π9．下列四个结论中正确的个数是（1）对于命题0:p x R ∃∈使得2010x -≤，则:p x R ⌝∃∈都有210x ->；（2）已知2(2,)XN σ，则 (2)0.5P X >=（3）已知回归直线的斜率的估计值是2，样本点的中心为（4,5），则回归直线方程为ˆ23yx =-； （4）“1x ≥”是“12x x+≥”的充分不必要条件. A ．1B ．2C ．3D ．410．执行如图所示的程序框图，输出的结果为（ ）A ．78B ．158C ．3116D ．151611．小张家订了一份报纸，送报人可能在早上6:307:30-之间把报送到小张家，小张离开家去工作的时间在早上7.008:00-之间.用A 表示事件：“小张在离开家前能得到报纸”，设送报人到达的时间为x ，小张离开家的时间为y ，(,)x y 看成平面中的点，则用几何概型的公式得到事件A 的概率()P A 等于（ ）A ．58B ．25C ．35D ．7812．某个命题与自然数n 有关，且已证得“假设()*n k k N =∈时该命题成立，则1n k =+时该命题也成立”．现已知当7n =时，该命题不成立，那么（ ） A ．当8n =时，该命题不成立 B ．当8n =时，该命题成立 C ．当6n =时，该命题不成立D ．当6n =时，该命题成立二、填空题：本题共4小题，每小题5分，共20分。
NOVATEK-ELECTRO LTD 产品说明书：UBZ-301（10-100A）通用感应电机保护
NOVATEK-ELECTRO LTDResearch-and-Manufacture CompanyUBZ-301 (10-100A)UNIVERSAL INDUCTIONMOTOR PROTECTION UNITUSERS MANUALCONTROLS DESCRIPTION AND DIMENSIONS DIAGRAM 4151. Control for nominal current setting, Inom;2. Control for operating current setting, Iop (% Inom);3. Control for T2 (double overload trip) delay setting;4. Combined trip adjustment control for Umin/Umax;5. Control for phase imbalance adjustment, PI;6. Control for trip threshold for the minimum current, Imin (%Inom);7. Control for automatic reset delay setting, Ton;8. Green LED indicating for the mains voltage presence;9,10,11. Red LEDs indicating faults for insulation, overload and U fault respectively;12. Green LED indicating for load energization;13. Output terminals;14. Input terminals (10,11,12 are used for the connection with the BO-01 exchange unit);15. Insulation monitoring terminal.1 APPLICATIONSThe UBZ-301(10-100A)universal induction motor protection unit is designed for the continuous monitoring of the mains voltage parameters and for RMS phase/line currents of 3-Phase AC 380V/50Hz electrical equipment monitoring, primarily, of induction motors whose power is from 5kW up to 50 kW, isolated neutral system included.The unit provides full and effective protection of electrical equipment by a magnetic starter (contactor) coil control.The unit isolates electrical equipment from the running system and/or disables its start. This is performed in the following cases:1. when the mains voltage is of poor quality (unallowable voltage jumps, phase loss, incorrect phase sequence and phase «coincidence», phase/line voltage imbalance);2. when mechanical overloads (symmetrical phase/line current overload) take place. The unit performs overload protection with a dependent time delay;3. when phase/line current asymmetrical overloads induced by faults inside the motor occur. The unit performs protection from phase current imbalance and further disables an automatic reset;4. when phase current asymmetry without overload occurs that is induced by the insulation fault inside the motor and/or the power cable;5.when motor load is lost(«dry stroke»for pumps).The unit provides the minimum start and/or operating current protection;6. when insulation level to frame is abnormally low. The unit performs insulation level test before start and if the insulation is poor the start is disabled.7.when stator winding ground-to-fault occurs during operation. The unit performs the ground leakage current protection.The UBZ-301 (10-100A) provides:•a simple and accurate electromotor nominal current setting by nominal current standard scale;•the electromotor operating current setting that differs from standard values;•overload tripping with a dependent time delay (the current-time characteristic curve is plotted for a conventionally cold motor). The motor heat balance differential equation is being solved in the operation process. This approach enables to take account of the preceding electromotor status and to make a decision on heat overload presence with the maximum validity. This method also permits to allow for a motor start heating and to restrict (at the customer’s option) amount of starts per unit time;•shift of current-time characteristic curve along the current-axis and along time-axis as well;•setting of trip thresholds for the minimum/the maximum voltage,line voltage&phase current imbalance, and also for automatic reset delay at the personal customer’s discretion;•fault type indication, the mains voltage presence indication, current range indication the unit is adjusted to, and load energization indication;•the data exchange and transfer to the local computer network according to the RS-485 MODBUS record through the BO-01 exchange unit (BO-01 is supplied on order).2 DESCRIPTIONThe unit is a microprocessor-based digital device that provides a high degree of reliability and accuracy. The unit doesn’t need any auxiliary supply because it retrieves it's energy demand out of the measurement signal: it’s self-powered by the voltage to be monitored. Simultaneous isolated independent monitoring for the mains voltage and phase currents permits to detect the type of occurring fault and to provide a different decision-making logic for each fault type. When the mains voltage faults occur the unit performs automatic load reset on return voltage parameters to normal operating conditions. If a fault is induced by abnormal condition inside the motor(phase current imbalance at the symmetrical mains voltage,leakage current presence etc.) restart is disabled.The unit is stocked with three toroidal current transducers. Two of them are the phase/line current transducers (TT1, TT2), power phase cables are pulled through them. The third transducer is the differential current transducer(DCT)that has an enlarged diameter,because three power phase cables are pulled through it. By the 6, 7, 8, 9 terminals the unit is connected in parallel to the mains supply to be monitored. The unit output is provided with N.O. and N. C. contacts (the 1, 2, 3, 4 terminals). The output 3-4 terminals are connected in series with the starter coil power supply (with control circuit). The5terminal is designed to monitor the insulation level. The unit wiring diagram is shown below.When the unit trips the load is de-energized by a break in the magnetic starter coil power circuit through the N. C. 3-4 contacts.Table 1 - The 1-2-3-4 output contacts specificationMax. current for~ 250 V A. C.Max. powerMax sustained safevoltage ~Max. current for U = 30V D.C.Cosφ = 0.43A 2000VA 460V 3ACosφ = 1.05ANominal parameters and trip thresholds are set by front-panel screwdriver potentiometers.Nominal current setting. Nominal current is set by № 1 potentiometer. There are eleven positions of the potentiometer. Each position corresponds to the specific standard nominal current scale value (see below Table of Nominal Currents). Each position is characterized by the specific number of blinks that the green «On» LED makes. To set the nominal current one needs to bring out potentiometer control arm to a corresponding position; when the unit is energized the number of blinks «On» LED must correspond to the Table below. One needs to take into account that there are «dead bands» between the positions where «On» LED glows without blinks and where the nominal current is indefinite.In order to set operating value which is different from the nominal one that is specified in the nominal current table, it’s recommended the № 1 potentiometer to set to the position corresponding to the nearest value from the nominal current scale, and by the № 2 potentiometer one can increase or decrease the necessary value in % from the set value.Table 2 - Nominal current tablePotentiometer №1 devisionsNom. current, АGreen LED «On» blink1101bl.- pause 212,52bl.- pause 3163bl.- pause 4204bl.- pause 5255bl.- pause 6326bl.- pause 7407bl.- pause 8508bl.- pause 9639bl.- pause 108010bl.- pause 1110011bl.- pauseNOTE S:1.Continuous green «On» LED glow means that the potentiometer is set in «dead band». One needs to set the potentiometer so as the green LED blinked and the number of blinks corresponded to the set nominal current.2.Nominal currents setting is to be performed correcting for load connections (Wye/Delta), according to ratings of engine.Controls and adjustmentsThe unit has seven independent controls. For user’s convenience screwdriver slots of adjusting potentiometers are brought out to the unit front panel.•№1 – «Inom» - nominal current setting; there are eleven positions and each position corresponds to the specific current from the nominal currents table;•№2 – «Iop» - operating current; it is set in ± 15 percent of nominal current, it has ten scale marks;•№3 – «T2» - overload trip delay when there is double overload for operating current set; in the central position T2 ≈ 58-60 seconds The minimum time delay is 10 seconds, the maximum time delay is 100 seconds. The control shifts current-time characteristic dependence along time axis;•№4 – «Unom(%)» - combined control for Umax/Umin threshold in percent of the nominal voltage; according to this setting before the load energization the unit is checking the mains voltage level and, depending on its value, permits or forbids the load energization; after the load has been energized the voltage monitoring is going on but the load de-energization decision is made for currents;•№5 – «PI%» - trip threshold control for line voltage imbalance and RMS phase current imbalance; it has ten scale marks. The parameter is calculated as the difference between the maximum and the minimum values, in percent of the maximum value. If current imbalance percentage is twice as much as voltage imbalance percentage then it’s supposed that the imbalance is induced by fault conditions inside the motor. The automatic reset is forbidden and the unit is disabled;•№6 – «Imin» - trip threshold control for the minimum operating current, in percent of operating current set. It has ten scale marks from 0% to 75%: in «0» position this control is off;•№7 – «Ton» - automatic reset delay, it is within 0 – 600 seconds range; the scale is logarithmic.Indication•the green «ON» LED indicates that voltage exists in the mains. In the blink mode of glow the blink number between pauses corresponds to the specific nominal current from the nominal current table; there is a continuous glow in a «dead band». One needs to set a nominal current in the blink mode of operation;•the green «Load» LED indicates that the load is energized (the 3-4 terminals are closed);•the red «Insulation» LED lights up with continuous glow before the start if the stator/ power cable winding insulation level is abnormally low (less than 500 kOhms), and also during operation when there is a tripping for differential current; the unit is disabled;•the red «U Fault» LED glows when the mains voltage fault has occurred. The blink mode of operation switches on when there is undervoltage/overvoltage, phase imbalance for the mains voltage, voltage is not present on all three phases;•incorrect phase sequence or phase coincidence induces the mode of operation when all three red LEDs are blinking in turn;•the red «Overload» LED blinks when the average phase current exceeds the nominal one. After the unit has tripped for overload this LED comes to glow during 0.9 AR (automatic reset) delay.4 TECHNICAL BRIEFNominal line voltage, V380Mains frequency, Hz45-55Nominal current range in UBZ-301 10-100, А10-100Operating current setting range, % of nominal±15Double overload delay adjustment range, sec10-100Voltage threshold adjustment range, % of nominal±(5-20)Phase imbalance adjustment range, %5-20Trip threshold adjustment range for the minimum current, % of nominal0-75Automatic reset delay adjustment range ( Тon), sec0-600First energization load delay when Тon= 0, sec2-3Trip delay for current overload According to current-time characteristic curveTrip delay for voltage fault, sec2Trip delay for current fault (overload excluded), sec2 Fixed trip point for leakage current, А 1.0 Insulation resistance threshold, kОhms500±20 Voltage hysteresis, V10/17 Heat hysteresis, % of stored-up heat after load de-energization33Trip threshold accuracy for current, % of nominal current, not more than2-3 Trip threshold accuracy for voltage, V, not more than3 Phase imbalance accuracy, %, not more than 1.5 Operating voltage range, % of nominal one50-150 Power consumption (under load), VA, not more than 3.0 Maximum switched current of output contacts, A5 Output contact life:- under 5A load , operations, no less than - under 1A load , operations, no less than 100 000 1 000 000Enclosure:- apparatus- terminal block IP40 IP20Operating temperature range, °C from -35 to +55 Storage temperature, °C from -45 to +70 Weight, kg, not more than0.200Case dimensions 4 modules of S-typeMounting standard 35 mm DIN-railMounting position arbitrary5 OPERATION1. After supply voltage has been applied to the unit and before the output relay is energized the unit checks:•a stator winding insulation level to frame. If insulation resistance is below 500±20 kOhms, the load is not energized. The red «Insulation» LED glows;•the mains voltage quality,i.e.if voltage is present on all three phases,if the mains voltage is symmetrical, what the RMS line voltage value is like. When any of inhibit factors is present, the load is not energized, the red «U Fault» LED blinks;•a correct phase sequence, and phase «non-coincidence». When any of inhibit factors is present, the load is not energized, all red LEDs are blinking in turn; If all the parameters are normal, the outlet relay will be energized after Ton delay has expired (the 3-4 contacts are being closed and the 1-2 contacts are being opened) - the green «Load» LED glows. If load currents are absent (there are no less 2% of nominal one) the reason is that the load is de-energized. Voltage monitoring and insulation level is going. Output relay of unit is de-energized if inhibit factors are present in pause without currents;2. After the load is energized the unit performs voltage and current monitoring. The decision on load de-energization is made according to the following factors:•RMS current exceeds the nominal (operating) current (set by №№ 1, 2, 3 potentiometers); if there is current overload without heat overload the red «Overload» LED blinks but the load is not de-energized. If current overload induces heat overload the load is de-energized. The red «Overload»LED glows and is ON during 0.9Ton. The automatic reset is permitted;•current imbalance (set by №5 potentiometer) is twice exceeds the mains voltage imbalance; the load is de-energized, all red LEDs glow, the unit is disabled, the automatic reset is forbidden. To enable the unit one needs to remove supply voltage from the unit. It’s supposed that this type of fault is induced by abnormal conditions inside the motor;•current imbalance (set by №5 potentiometer) is less than twice exceeds voltage imbalance; the load is de-energized, the red «U Fault» LED glows, the automatic reset is permitted;•current imbalance (set by №5 potentiometer) is less than voltage imbalance; the load is de-energized, the red «U Fault» LED blinks, the automatic reset is permitted;•the average current value is less than Imin (set by №6 potentiometer); the load is de-energized, all red LEDs blink simultaneously, the unit is disabled, the automatic reset is forbidden. To enable the unit one needs to remove the supply voltage from the unit.Electromotor protection against heat overloadThe electromotor heat balance equation is being solved as the work advances. It’s supposed that:•the motor was cold before start;•during operation the motor releases the heat which is proportional to the current square;•after the stop the motor cools down exponentially.Below is the current-time characteristic curve with different T2 values (set by №3 potentiometer), where:•I/In – current ratio relative to the nominal current;•T/T2 -- actual trip delay relative to T2 (set by № 3 potentiometer).Current-time characteristic dependenceThe current-time characteristic dependence shown in the tables below is given for the standard recommended T2 value (the №3 potentiometer middle position corresponds to 60 seconds when double overload occurs):I/Inom 1.1 1.2 1.4 1.72 2.73456781015Тsec36524714888.66036.424.613.58.5 5.9 4.3 3.3 2.10.9After the load has been de-energized owing to the heat overload it will automatically be energized again:•according to heat hysteresis if time delay Ton=0, i. e. the motor must cool down 33% of the stored up heat;•according time delay Ton (№ 7 potentiometer) if Ton isn’t equal 0.By suitable selection of different Ton values, heat hysteresis considered, one can reduce number of starts per time unit because in the intermittent cycle the unit stores heat quantity released at the start of the motor.6 PRELIMINARY STARTING PROCEDURE AND SERVICE MANUALThe unit produced is completely ready for operation and needs no special pre-starting procedure measures. Owing to digital technology all the unit settings are aligned quite accurate, so no control devices are needed to adjust them. Use of the unit according to specifications above and the present service manual, continuous work included, relieves of preventive maintenance during service life. To put the unit in operation one must follow operating instructions given below:1.To set nominal (operating) current, trip thresholds, trip delays and reset delay by potentiometer's contact arms.2.To connect the unit according to the wire diagram given below:•by the 6(L1), 7(L2), 8(L3), 9(N) terminals the unit is connected in parallel to the mains supply to be monitored;•two current transducers (each one of them is put on two power phase wires that carry the load) are connected to the 13, 14, 15, 16 terminals; in connecting one has to consider the transducers grading;1st transducer– the beginning – the 13 terminal, the end – the 14 terminal;2nd transducer– the beginning – the 15 terminal, the end – the 15 terminal;•a differential current transducer that is put on the three power phase wires must be connected to the 17, 18 terminals (the connection grading is unimportant);•the 5 insulation monitoring terminal is connected to one of the MS output contacts;•output contacts (the 3-4 terminals) are connected to the MS coil power supply circuit (control circuit);•the BO-01 exhange and date transfer unit is connected to the 10, 11, 12 terminals (this unit is supplied on order).3.To apply a voltage to the unit. The correct setting of nominal current is checked by the number of blinks that the green LED makes. After Ton has expired (if there are no factors that can forbid energizing) the output relay of the unit is energized. If Ton=0, the first energizing will occur after 2-3 sec delay has expired.NOTE - The unit must be connected subject to the safety regulations. To set settings is recommended in «off» state. To set settings alive is permitted in the test conditions subject to the safety regulations.ATTENTION!If immediately after the load has been energized the unit de-energizes it and disables it for current imbalance,the incorrect polarity of the current transducers TT1or TT2 connection may be a reason. Then it’s recommended to change one of the transducers connection by reversing the places“the beginning-the end”of the13-16terminals.If the effect pointed above repeats when the load is re-energized it means that the transducers were connected correctly and the imbalance arose from EM and/or power cable fault.NOTES:1 Transducers are mounted by plastic clamps (they are component parts of supplies).2 The phase wires which are passing through the differential transducer to try to symmetrize in the centerof the transducer.WIRING DIAGRAMDT–differential current transducer (differential current transformer);CT1,CT2–current--transducers;BO-01– exchange and date transfer unit (on order)NOTE:1 “START”-button and “STOP”-button can be connected to MSC power supply circuit if necessary;2 The 220V MSC connection is shown here. The 380V MSC power supply circuit is analogous, coil power is applied from different phases through the 3-4 contacts;3 If BO-01 is absent the 10, 11, 12 terminals are not used.7 STORAGE AND SHIPPING CONDITIONSThe unit in manufacturer package should be stored in enclosed rooms at –45 to +70 °C and exposed to no more than 80% of relative humidity when there are no fumes in the air that exert a deleterious effect on package and the unit material. The Buyer must provide the protection of the unit against mechanical damages in transit.8 WARRANTYNovatek-Electro LTD. Company warrants a trouble-free operation of the UBZ-301 (10-100A) unit manufactured by it within 36 months from the date of sale, provided:•the proper installation;•the safety of the inspection quality control department seal;•the integrity of the case, no traces of an opening, cracks, spalls etc.。
河北省廊坊市英语初一上册同步考试试卷及答案
河北省廊坊市英语初一上册同步考试试卷班级：________________ 学号：________________ 姓名：______________一、听力题（每题3分）Question 1:Listen to the recording and choose the correct picture that matches the conversation.Recording: (A picture of a book and a picture of a pen are shown.)Speaker: “I’m looking for a pen to write with. Do you know where I can find one?”Answer: Picture of a pen.Question 2:Listen to the dialogue and answer the question.Recording:Speaker 1: “What’s your favorite subject in school?”Speaker 2: “My favorite subject is science. It’s so interesting!”Question: What’s Speaker 2’s favorite subject?Answer: Science.Question 3:Listen to the short passage and fill in the blank with the missing word.Recording:“This weekend, I plan to go hiking with my family in the mountains. We will pack some food and water, and wear comfortable shoes. It’s going to be a great way to relax andenjoy _______.”Question: Fill in the blank: enjoy _______.Answer: natureQuestion 4:Listen to the conversation and select the correct answer to the question.Recording:Speaker 1: “How often do you go to the library?”Speaker 2: “I usually go there twice a week, on Tuesdays and Thursdays.”Question: How often does Speaker 2 go to the library?Answer: Twice a week.Question 5:Listen to the instructions and then repeat the sequence of actions in the correct order.Recording:“First, put on your shoes. Then, grab your backpack. After that, open the front door.Finally, lock it behind you before leaving.”Question: Repeat the sequence of actions in the correct order.Answer: Put on shoes, grab backpack, open front door, lock door behind you.二、单选题（每题3分）1.Which of the following is NOT a family member?A. FatherB. TeacherC. MotherD. SisterAnswer: B2.How do you say “What’s your name?” in English?A. My name is…B. Hello!C. What’s your name?D. Nice to meet you.Answer: C3.Which preposition should be used to complete the sentence “The book is____thetable.”?A. onB. inC. underD. atAnswer: A4.What’s the opposite of “big”?A. smallB. tallC. longD. wideAnswer: A5.Which sentence is grammatically correct?A. I have a dog, it’s name is Max.B. I have a dog, his name is Max.C. I have a dog, its name is Max.D. I have a dog, it name is Max.Answer: C三、多选题（每题4分）Question 1:Which of the following words can be used to describe a person who is always willing to help others?A. SelfishB. GenerousC. StubbornD. Kind-heartedAnswer: D. Kind-heartedQuestion 2:The book “The Adventures of Tom Sawyer” was written by _______.A. Jane AustenB. Mark TwainC. Charles DickensD. William ShakespeareAnswer: B. Mark TwainQuestion 3:“I_______have finished my homework before dinner, but I watched TV instead.”A. shouldB. mightC. couldD. mustAnswer: A. shouldQuestion 4:The sentence “She is not only beautiful but also intelligent.” can be rewritten as:A. She is intelligent, not beautiful.B. She is neither beautiful nor intelligent.C. She is both beautiful and intelligent.D. She is intelligent, although she is not beautiful.Answer: C. She is both beautiful and intelligent.Question 5:Which of the following sentences is in the future tense?A. I am studying English now.B. I have studied English for five years.C. I will study English next year.D. I studied English last semester.Answer: C. I will study English next year.四、阅读理解（每题4分）Title: Exploring Ancient Suzhou: Gardens and HistorySuzhou, known as the “Venice of the East”, boasts a rich cultural heritage, with itsancient gardens standing as testament to centuries of artistic and architecturalbrilliance. The city’s gardens, such as the Humble Administrator’s Garden and the Lion Grove Garden, are not merely landscapes but intricate masterpieces of Chinese garden design, incorporating elements of poetry, painting, and philosophy.Walking through these gardens, one is greeted by meticulously arranged rocks, ponds reflecting the sky and surrounding scenery, and winding paths that lead to hiddenpavilions and serene bridges. Each turn reveals a new perspective, inviting visitors to slow down and savor the tranquility.Suzhou’s history is equally fascinating, with its roots dating back over 2,500 years. The city played a pivotal role in China’s economic and cultural development, especiallyduring the Song and Ming dynasties, when it flourished as a center of silk production and scholarly pursuits. Today, relics from these bygone eras can still be foundthroughout the city, from ancient temples to historic streets lined with traditionalarchitecture.Questions:1.What is Suzhou commonly known as, and why? (4 points)Answer: Suzhou is commonly known as the “Venice of the East” due to its intricate network of canals and waterways that crisscross the city,reminiscent of Venice in Italy. two famous gardens in Suzhou mentioned in the passage. (4 points)Answer: The Humble Administrator’s Garden and the Lion Grove Garden are two famous gardens mentioned in the passage.3.How do Suzhou’s gardens reflect Chinese garden design principles? (4points)Answer: Suzhou’s gardens reflect Chinese garden design principles by incorporating elements of poetry, painting, and philosophy into their landscapes. They feature meticulously arranged rocks, ponds, winding paths, pavilions, and bridges, creating intricate masterpieces thatinvite visitors to slow down and savor the tranquility.4.During which dynasties did Suzhou flourish as a center of silk productionand scholarly pursuits? (4 points)Answer: Suzhou flourished as a center of silk production and scholarly pursuits during the Song and Ming dynasties.5.What can visitors still find throughout Suzhou that relates to itshistorical past? (4 points)Answer: Visitors can still find relics from Suzhou’s hi storical past throughout the city, including ancient temples and historic streets lined with traditional architecture.五、作文（30分）Title: My Favorite Teacher in Junior ThreeInstructions: Write a short essay about your favorite teacher in your junior year ofmiddle school. In your essay, please describe the teacher’s appearance, personality traits, and one specific incident that made you admire or appreciate them the most. Remember to use proper grammar, spelling, and punctuation. Your essay should be approximately 100-120 words.My Favorite Teacher in Junior ThreeAmong the many dedicated educators who have guided me through my junior year of middle school, Mrs. Li, my English teacher, stands out as my absolute favorite. With her warm smile framed by gentle eyes, she embodies a sense of kindness and understanding that instantly puts students at ease. Her medium height and neatly tied hair add to her elegant appearance, making her a sight to behold whenever she enters the classroom.What truly sets Mrs. Li apart, however, is her passion for teaching and her genuine concern for each student’s growth. She possesses an incredible ability to make complex grammatical rules and literary concepts come alive through interactive lessons and engaging activities. Her patience is unparalleled; she never hesitates to spend extra time explaining a concept or offering personalized feedback to help students overcome challenges. One incident that solidified Mrs. Li’s position as my favorite teacher occurred during a particularly difficult chapter in English literature. I was struggling to grasp the themes and symbolism within a classic novel, feeling overwhelmed and discouraged. It was Mrs. Li who, after class, sat down with me one-on-one, breaking down each concept step by step until I finally saw the beauty in the text. Her encouragement and unwavering beliefin my abilities lifted my spirits and ignited a spark of interest in literature that continues to burn brightly today.Beyond academics, Mrs. Li is a mentor and a friend. She listens attentively, offers wise advice, and celebrates our successes with equal enthusiasm. Her positive influence has not only improved my English proficiency but also shaped me into a more confident and resilient individual. For these reasons and countless more, Mrs. Li will always hold a special place in my heart as my favorite teacher in junior three.。
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2025届河北省廊坊市三河市八年级物理第一学期期末学业水平测试试题含解析
2025届河北省廊坊市三河市八年级物理第一学期期末学业水平测试试题注意事项1．考试结束后，请将本试卷和答题卡一并交回．2．答题前，请务必将自己的姓名、准考证号用0．5毫米黑色墨水的签字笔填写在试卷及答题卡的规定位置．3．请认真核对监考员在答题卡上所粘贴的条形码上的姓名、准考证号与本人是否相符．4．作答选择题，必须用2B 铅笔将答题卡上对应选项的方框涂满、涂黑；如需改动，请用橡皮擦干净后，再选涂其他答案．作答非选择题，必须用05毫米黑色墨水的签字笔在答题卡上的指定位置作答，在其他位置作答一律无效．5．如需作图，须用2B 铅笔绘、写清楚，线条、符号等须加黑、加粗．一、单选题1．如图所示是用斜面和小车做“测物体的平均速度”的实验,则下列说法不正确的是( )A ．小车下滑过程在做变速运动B ．测量下半程平均速度时要让小车从中点处静止滑下C ．为了延长小车在斜面运动时间，可以减小倾斜程度D ．实验时小车过了中点才停止计时，将会导致上半段平均速度偏小2．下列说法中正确的是( )A ．登月舱从地球到月球，质量变小B ．1 kg 铁比1 kg 棉花的质量大C ．把钢棒轧成一张薄钢板，形状发生了变化，但质量不变D ．一杯水凝固成冰后，质量变大3．透镜在我们的生活、学习中应用广泛，下列说法正确的是（ ）A ．近视眼镜利用了凹透镜对光的发散作用B ．照相时，被照者应站在离镜头二倍焦距以内C ．凸透镜成像和小孔成像都是由于光的折射而形成的实像D ．借助放大镜看地图时，放大镜到地图的距离应大于一倍焦距4．下列说法正确的是A ．体积越大的物体，质量一定越大B ．固体的密度总是大于液体的密度C ．同一物质，质量越大，比热容越大D ．晶体都有固定的熔点5．将质量和体积都相同的空心铁球和铝球分别注满水（ρρ>铁铝），再比较它们的质量，则（）A ．铁球质量大B ．铝球质量大C ．两球质量一样大D ．无法判断6．在要光屏上得到与物体大小相等的像，应当使用（ ）A ．凹透镜B ．平面镜C ．凸透镜D ．三种都可以7．下列现象中，与月食的形成原因相同的是（ ）A ．平面镜中的像B ．手影C ．用凸面镜扩大视野D ．海市蜃楼8．如图所示，自行车的零部件设计或骑行过程的操作中主要为了减小摩擦的是（ ）A ． 轮胎上制有花纹B ． 车轴处装有滚珠轴承C ． 刹车时用力捏闸D ．脚蹬表面凸凹不平二、多选题9．小明同学打乒乓球时，不小心将球踩瘪了，但没有破裂。
廊坊市第十二中学_企业报告(业主版)
2023-06-13
（8）房地产开发经营（1）
重点项目
项目名称
中标单位
中标金额（万元） 公告时间
TOP1
河北省廊坊市第十二中学宿舍管 理服务项目竞争性磋商中标公告
廊坊橘子物业服务 有限公司
15.8
*按近 1 年项目金额排序，最多展示前 10 记录。
2022-10-10
（9）纺织原料、毛皮、被服装具（1）
39.8
*按近 1 年项目金额排序，最多展示前 10 记录。
2023-03-28
（6）工程监理服务（1）中标金额（万元） 公告时间
本报告于 2023 年 08 月 22 日 生成
4/17
重点项目
项目名称
中标单位
中标金额（万元） 公告时间
TOP1
河北省廊坊市第十二中学建设项 目-监理竞争性磋商成交公告
中标金额（万元） 公告时间
TOP2 TOP3
廊坊市第十二中学建设项目设备 购置及安装项目公开招标 B 包
廊坊市今实文化发 展有限公司
廊坊市第十二中学理化生实验室 设备采购项目成交公告
廊坊市奥都教育科 技有限公司
*按近 1 年项目金额排序，最多展示前 10 记录。
328.6 28.9
2022-08-29 2023-03-28
目录
企业基本信息 .................................................................................................................................1 一、采购需求 .................................................................................................................................1