河北省邯郸市2016-2017学年高一上学期期末考试英语试题含答案
注意事项：1.本试卷分第I 卷（选择题）和第II 卷（非选择题）两部分。
2.考试时间120分钟，满分150分。
3.答题前，考生务必将自己的姓名、准考证号填写在答题卡相应的位置。
4．全部答案在答题卡上完成，答在试卷上无效。
第I 卷第一部分：听力（共两节，满分30分）做题时，先将答案标在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is he shirt?A. $19.15B. $9.18C. $9.15答案是C.1. What sport is the man best at?A. BasketballB. Football.C. Tennis.2. What time is it now?A. 7:10.B.7:30.C. 7:40.3. How much should the woman pay for the oranges?A. $1B. $3C. $54. What does the woman think of herself?A. She needs a free lunch.B. Her pay is not high.C. She works hard.5. What is the man doing?A. Giving a suggestion.B. Starting a discussion.C. Stopping a fight.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有2至4个小题，从题中做给的A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有5秒钟的时间阅读各个小题；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6. What’s the relationship between Tom and Dick?A. Friends.B. Brothers.C. Workmates.7. Why was Tom knocked down by a car?A. He was drunk.B. He drove too fast.C. His cars were deaf.听第7段材料，回答第8至第10题。
8. Who might the man be?A. Bill’s teacher.B. The headmaster.C. Bill’s classmate.9. What kind of student is Bill?A. A clever student.B. A hard-working student.C. A stubborn student.10. What does the woman wish Bill to do?A. Help her do the housework.B. Work hard to make greater progress.C. Go out and enjoy himself regularly.听第8段材料，回答第11至13小题。
11. Where does the conversation take place?A. In a store.B. In the hospital.C. On the street.12. What will the man do next?A. Buy something.B. Wait for the woman.C. Go back home.13. What does the woman think of the man?A. Handsome.B. Healthy.C. Helpful.听第9段材料，回答第14至16题。
14. Who would cook?A. Vicky.B. Peter.C. Anna.15. What did Vicky ask the speakers to bring?A. A bottle of wine.B. A surprise gift.C. A dish of fish.16. How will the woman go home after dinner?A. On foot.B. By taxi.C. By car.听第10段材料，回答第17至20题。
17.When did the movie win the Grand Jury Prize?A. In 1939.B. In 1997.C. In 1998.18. What was Dora’s job?A. A doctor.B. A teacher.C. A soldier.19. Whom did Guido save?A. His uncle.B. His wife.C. His son.20. What is the movie about?A. War.B. Game.C. Love.第二部分阅读理解（共两节，满分40分）第一节（共12小题；每小题2分，满分24分）阅读下列短文，从每题所给的四个选项（A、B、C、D）中，选出最佳选项，并在答题卡上将该项涂黑。
AHere are four of the best soccer movies, chosen after considering their ratings(排名) from IMDb and Rotten Tomatoes.Looking for EricThe 2009 movie is a comedy-drama that shows the friendship between a postman and the former soccer player Eric Cantona, who gives life advice to his fan. Steve Evets played the role of the postman, Eric Bishop, while Cantona played himself.Shaolin SoccerThe 2001 film is a sports comedy that tells the story of a Shaolin follower who forms a soccer team with his brothers. The whole team gains popularity for the players’ martial arts(武术) skills. Stephen Chow, Ng Man-tat, and Wong Yat-fei played the leading roles of the movie.The Damned UnitedThe movie, produced in 2009, tells the story of Brian Clough, a coach of the English soccer team, Leeds Untied, in 1974. Michael Sheen starred as manager Clough.Gregory’s GirlBeing one of the first movies about soccer, Gregory’s Girl tells the story of a teenage couple who fall in love while playing on the same team. It is a comedy movie produced in 1981, which starred John Gordon Sinclair, Dee Hepburn, and Clare Grogan.21. Who played the role of the soccer player Eric Cantona?A. Steve Evets.B. Eric Bishop.C. Eric Cantona.D. Michael Sheen.22. The players on Shaolin soccer team became popular because of their .A. gift for soccerB. friendshipC. love storiesD. martial arts skills23. When was the movie telling the story of a soccer coach produced?A. In 2009.B. In 2001.C. In 1974.D. In 1981.24. Which of the following is among the first movies about soccer?A. Looking for Eric.B. Shaolin Soccer.C. The Damned United.D. Gregory’s Girl.BIt's not right for an adult to leave a child locked in a parked car in the burning heat while they chat with a friend or do anything else without supervising their child. This kind of behavior is so wrong that states have even carried out laws allowing good citizens to rescue trapped kids. Unluckily one Georgia man learned that these laws aren’t true to pets after he decided to save a dog and was arrested(逮捕)。
According to a story from USA Today, Michael Hammons, used his wife’s wheelchair leg to break the window of a parked car after hearing from bystanders that there was a dog inside.One witness(目击者)told reporters that “if it is 80 degrees outside, within 30 minutes, it will be 114 degrees inside a car, even with the windows broken.” Bystanders had reportedly already phoned 911before and were waiting for police to arrive, but for Hammons there was no time to lose.Police were forced to take action after the owner of both the dog and car came out of the store and requested police arrest Hammons. Oconee County Chief Deputy Lee Weems told USA Today, “We would not have made those charges on our own.” But the owner of the car insistedthat Hammons be charged with criminal trespassing(非法入侵).The dog’s owner said that she had only been gone five minutes, even though bystanders said it was actually much longer. No matter how long it actually was, the decision to leave her dog locked in a car in 80 degree weather wasn’t a bright one on her part. Interestingly enough, USA Today reports that Georgia state law does allow a person to break a window to save a child in a hot or cold car, just not a pet.25. What does the underlined word “supervising” in Paragraph 1 probably mean?A. Watching.B. Raising.C. Feeding .D. Helping.26. The police arrested Hammons according to .A. the car owner’s evidenceB. a witness’ wordsC. their own judgmentD. the Georgia state law27. What do we know about Hammons?A. He was praised by his wife.B. He knew the law well before the rescue.C. He saved the dog at the request of bystanders.D. He used a wheelchair to break the car window.28. What’s the main idea of the text?A. A man saved a dog but got arrested.B. A man saved a dog but got arrested.C. A dog was saved from a hot car.D. A woman found her car broken.CIn 1991 British computer scientist Tim Berners-Lee published the first-ever website while working at CERN, a huge physics lab in Switzerland. Within ten years, sites such as eBay, Amazon and Google had appeared and the Web was changing society by changing how people communicate, shop and get information.Berners-Lee was born in 1955 and studied physics at Oxford. While employed at CERN in the 1980s, Berners-Lee noticed how hard it was to keep track of the projects and computer systems of the organization’s thousands of researchers, who were spread around the world. As he later stated, “In those days, there was different information on different computers, but you had to logon (登陆) to different computers to get at it. Also, sometimes you had to learn a different program on each computer.”In March 1989, Berners-Lee gave managers at CERN a suggestion for an information management system that linked documents on different computers that were connected to the Internet. In 1990 the Englishman’s boss gave him time to work on the project. After first calling the project Information Management, Berners-Lee tried out names such as Mine of Information and Information Mesh before settling on World Wide Web.The beginning of the Web as a publicly available(可用的) service on the Internet arrived on August 6, 1991, when Berners-Lee published the first-ever website. Fittingly, the site was about the World Wide Web project, describing the Web and how to use it.Berners-Lee didn’t try to cash in on his invention and turned down CERN’s call to patent(申请专利) his Web technology. He wanted the Web to be open and free so it could be used as widely as possible.29. What caused Berners-Lee to invent the Web?A. His love for invention.B. The managers’ command.C. The need to manage information.D. The necessity of learning different programs.30. What was Berners-Lee’s project first called?A. Information Management.B. Mine of Information.C. Information Mesh.D. World Wide Web.31. After the Web was invented, Berners-Lee .A. made money on his inventionB. patented his Web technologyC. allowed it to be used for freeD. used it to make himself popular32. Which of the following can best describe Berners-Lee?A. Brave and gifted.B. Patient and kind.C. Hard-working and attractive.D. Creative and generous.第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
江西省南昌市实验中学2016-2017学年高一第一学期期末考试英语试卷
2016-2017学年度上学期高一英语学科期末考试试卷说明：1本卷共有四大题，共81小题,全卷满分150分,考试时间为120分钟.2本卷分为试题卷和答题卷，答案要求写在答题卷上．不得在试题卷上作答．否则不给分.一、听力测试听下面5段对话。
每段对话后有一个小题，从题中所给A,B,C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.What is the man going to do ?A.Swim in the seaB. Go runningC. Take part in a competition2.What does the man like about the new restaurant ?A.The serviceB. The foodC. The atmosphere3.What colour is the dress?A.BlueB. YellowC. Green4.Where could the speakers most likely be?A.At homeB. At a hotelC. At a train station5.What is the conversation mainly about?A.When the party will be heldB.How many people will attend the partyC.Whether the man was invited to the party听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给A,B,C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话或独白前，你都将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
读第6段材料，回答第6，7题。
6.When did the woman see the film Oliver Twist?st SaturdayB. Last SundayC. On Monday7.What is the wo man’s opinion about the film?A.It was very badB.It was true to the novelC.It made her think of the world听第7段材料，回答第8，9题。
河北省邯郸市2023-2024学年高一上学期期末质量检测试题 数学(含答案)
邯郸市2023-2024学年第一学期期末质量检测高一数学（答案在最后）注意事项：1．答卷前，考生务必将自己的姓名、班级和考号填写在答题卡上．2．回答选择题时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号．回答非选择题时，将答案写在答题卡上．写在本试卷上无效．3．考试结束后，将本试卷和答题卡一并交回．一、选择题：本题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一项是符合题目要求的．1.已知集合{}1,0,1,2A =-，{}1B x x =≥，则()RB A ⋂=ð（）A.{}1 B.{}1,0- C.{}1,1- D.{}1,22.命题“()0,x ∀∈+∞，e ln x x >”的否定为（）A.()0,x ∃∈+∞，e ln x x >B.()0,x ∀∈+∞，e ln x x <C.()0,x ∀∈+∞，e ln x x ≤D.()0,x ∃∈+∞，e ln x x≤3.已知函数()sin f x x =，则“π6x =”是“()12f x =”的（）A .充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件4.已知正实数x ，y 满足22x y +=，则81y x+的最小值为（）A.7B.8C.9D.105.已知角α的终边经过点()3,4tan P α-，则cos α=（）A.2B.2-C.2±D.2±6.已知函数()πsin 2f x x ⎛⎫=+⎪⎝⎭，将函数()f x 的图象先向右平移个ϕ单位长度，再将所得函数图象上的所有点保持纵坐标不变，横坐标变为原来的12，得到函数()g x 的图象，若函数()g x 的图象关于原点对称，则ϕ的一个可能取值是（）A.π4 B.π2C.πD.2π7.已知函数()f x =在区间[]1,2-上单调递增，则实数a 的取值范围为（）A.(),0∞- B.[)1,0-C.1,2⎛⎤-∞ ⎥⎝⎦D.10,2⎛⎤ ⎥⎝⎦8.已知函数()21213221xxf k k x +=-+---有三个不同的零点，则实数k 的取值范围为（）A.4,9⎛⎫-∞- ⎪⎝⎭ B.1,2⎛⎫-+∞ ⎪⎝⎭C.()0,∞+ D.1,2⎡⎫+∞⎪⎢⎣⎭二、选择题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求，全部选对的得5分，部分选对的得2分，有选错的得0分．9.下列各组函数中，表示同一个函数的是（）A.()f x =()g x x= B.()23f x x x =-与()23g t t t=-C .()xf x x =与()1,01,0x g x x >⎧=⎨-<⎩ D.()0f x x =与()1g x =10.已知0a b c d >>>>，则下列不等关系成立的是（）A.22ac bc >B.a d b c ->-C.ad bc< D.11a cb c>--11.已知函数()()tan f x A x ωϕ=+（0ω>，π2ϕ<）的部分图象如图所示，则下列说法正确的是（）A.()f x 的最小正周期为πB.()f x 的定义域为ππ{|,Z}28k x x k ≠+∈C.点3π,08⎛⎫-⎪⎝⎭是函数()f x 图象的一个对称中心D.()f x 在3π,π4x ⎡⎤∈⎢⎥⎣⎦上的值域为[]1,1-12.已知定义在R 上的偶函数()f x 满足()()2121f x f x --=--，且当1224x x <<<时，()()21210f x f x x x ->-恒成立．则下列说法正确的是（）A.函数()1f x -为奇函数B.()()202310f f +-=C.()520232f f ⎛⎫-> ⎪⎝⎭D.函数()f x 的图象关于点()3,0对称三、填空题：本题共4小题，每小题5分，共20分．13.函数()213log 12xx xf x -=+++的定义域为_____________．14.已知幂函数()2133m y m m x+=+-的图象不经过原点，则实数m =_____________．15.已知函数()2xf x =，则()()223f x f x ->+的解集为_____________．16.某市规划局计划对一个扇形公园进行改造，经过对公园AOB 区域（如图所示）测量得知，其半径为2km ，圆心角为弯，规划局工作人员在 AB 上取一点C ，作CD ∥OA ，交线段OB 于点D ，作CE ⊥OA ，垂足为E ，形成三角形CDE 健步跑道，则跑道CD 长度的最大值为_____________km ．四、解答题：本题共6小题，共70分．解答应写出文字说明、证明过程或演算步骤．17.求解下列问题：（1）计算：10381272023π-⎛⎫⎛⎫+- ⎪ ⎪-⎝⎭⎝⎭（2）若e 2a =，e 3b =，求32a b +的值．18.已知()()()()()3πsin πcos cos 2π23πsin sin cos 14π2f ααααααα⎛⎫+--- ⎪⎝⎭=⎛⎫--+ ⎪⎝⎭．（1）化简()f α；（2）若()2fα=-，求212sin sin 212αα+-的值．19.已知定义在R 上的函数()21x b f x a =++，是奇函数，且()3210f =-．（1）求实数a ，b 的值；（2）判断函数()f x 在R 上的单调性，并用函数单调性的定义证明．20.已知函数()2π4cos cos 4sin 33f x x x x ωωω⎛⎫=-+- ⎪⎝⎭（0ω>）的最小正周期为π．（1）求()f x ；（2）已知π2π33α<<，()65f α=，求cos 2α．21.2023年10月20日，国务院新闻办举办了2023年三季度工业和信息化发展情况新闻发布会工业和信息化部表示，2023年前三季度，我国新能源汽车产业发展保持强劲的发展势头．在这个重要的乘用车型升级时期，某公司科研人员努力攻克了动力电池单体能量密度达到300Wh/kg 的关键技术，在技术水平上使得纯电动乘用车平均续驶里程超过460公里．该公司通过市场分析得出，每生产1千块动力电池，将收入()f x 万元，且()2120,05240330,5101x x f x x x x ⎧+<≤⎪=⎨-<≤⎪-⎩该公司每年最多生产1万块此种动力电池，预计2024年全年成本总投入2.5x 万元，全年利润为()F x 万元．由市场调研知，该种动力电池供不应求．（利润＝收入－成本总投入）（1）求函数()F x 的解析式；（2）当2024年动力电池的产量为多少块时，该企业利润最大？最大利润是多少？22.已知不等式20x mx n ++<的解集为{}21x x -<<-，函数()1xg x n λλ=--（0n >，且1n ≠），()()()2log 1log m m x x h x λ=-++（0m >，且1m ≠）．（1）求不等式20mx x n +-≥的解集；（2）若对于任意的[]11,1x ∈-，均存在2x ⎤∈⎦，满足()()12g x h x ≤，求实数λ的取值范围．邯郸市2023-2024学年第一学期期末质量检测高一数学注意事项：1．答卷前，考生务必将自己的姓名、班级和考号填写在答题卡上．2．回答选择题时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号．回答非选择题时，将答案写在答题卡上．写在本试卷上无效．3．考试结束后，将本试卷和答题卡一并交回．一、选择题：本题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一项是符合题目要求的．1.已知集合{}1,0,1,2A =-，{}1B x x =≥，则()RB A ⋂=ð（）A.{}1 B.{}1,0- C.{}1,1- D.{}1,2【答案】B 【解析】【分析】根据集合的交集，补集的概念运算求解即可.【详解】 {}1,0,1,2A =-，{}1B x x =≥∴{}R 1B x x =<ð，(){}R 1,0B A ⋂=-ð.故选：B ．2.命题“()0,x ∀∈+∞，e ln x x >”的否定为（）A.()0,x ∃∈+∞，e ln x x >B.()0,x ∀∈+∞，e ln x x <C.()0,x ∀∈+∞，e ln x x ≤D.()0,x ∃∈+∞，e ln x x≤【答案】D 【解析】【分析】根据全称命题与存在性命题的关系，准确改写，即可求解.【详解】根据全称命题与存在性命题的关系，可得：命题“()0,x ∀∈+∞，e ln x x >”的否定为“()0,x ∃∈+∞，e ln x x ≤”.故选：D ．3.已知函数()sin f x x =，则“π6x =”是“()12f x =”的（）A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件【答案】A 【解析】【分析】根据已知条件进行判断充分条件与必要条件，确定选项.【详解】因为ππ1sin 662f ⎛⎫== ⎪⎝⎭，当1sin 2x =时，π2π6x k =+或5π2π6x k =+，k ∈Z ，所以“π6x =”是“()12f x =”的充分不必要条件.故选：A ．4.已知正实数x ，y 满足22x y +=，则81y x+的最小值为（）A.7B.8C.9D.10【答案】C 【解析】【分析】利用“乘1法”与基本不等式的性质即可得出.【详解】由22x y +=，得212x y+=，所以81812116110109222x y y xy x y x x y ⎛⎫⎛⎫⎛⎫++=+⋅=+++= ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭≥，当且仅当16y x x y =即43y =，13x =时，等号成立，所以81y x+的最小值为9，故选：C ．5.已知角α的终边经过点()3,4tan P α-，则cos α=（）A.2B.22-C.22±D.32±【答案】A 【解析】【分析】由已知条件利用任意角的三角函数的定义即可求解.【详解】角α的终边经过点()3,4tan P α-，则4tan tan 3αα-=，解得tan 1α=，则点P 坐标为()3,3，则cos 2α==.故选：A ．6.已知函数()πsin 2f x x ⎛⎫=+⎪⎝⎭，将函数()f x 的图象先向右平移个ϕ单位长度，再将所得函数图象上的所有点保持纵坐标不变，横坐标变为原来的12，得到函数()g x 的图象，若函数()g x 的图象关于原点对称，则ϕ的一个可能取值是（）A.π4 B.π2C.πD.2π【答案】B 【解析】【分析】写出变换后的函数解析式，利用正弦型函数函数的对称性得出ϕ的表达式再判断各选项．【详解】函数()πsin 2f x x ⎛⎫=+⎪⎝⎭，将函数()f x 的图象先向右平移ϕ个单位长度，再将所得函数图象上的所有点保持纵坐标不变，横坐标变为原来的12，得到函数()πsin 22g x x ϕ⎛⎫=+- ⎪⎝⎭的图象，由题知，()g x 为奇函数，ππ2k ϕ=+，Z k ∈，B 选项满足条件，故选：B7.已知函数()f x =在区间[]1,2-上单调递增，则实数a 的取值范围为（）A.(),0∞- B.[)1,0-C.1,2⎛⎤-∞ ⎥⎝⎦D.10,2⎛⎤ ⎥⎝⎦【答案】B 【解析】【分析】利用换元法求出定义域后求解参数即可.【详解】根据题意，设1t ax =-，则y ，因为y =在[)0,t ∞∈+上单调递增，所以1t ax =-在区间[]1,2-上单调递增，则有010a a ->⎧⎨+≥⎩，解得10a -≤<，故选：B ．8.已知函数()21213221xxf k k x +=-+---有三个不同的零点，则实数k 的取值范围为（）A.4,9⎛⎫-∞- ⎪⎝⎭ B.1,2⎛⎫-+∞ ⎪⎝⎭C.()0,∞+ D.1,2⎡⎫+∞⎪⎢⎣⎭【答案】C 【解析】【分析】根据题意，令210xt =-≠，转化为方程()232120t k t k -+++=有两个不等实根1t ，2t ，零()()23221h t t k t k =-+++，结合二次函数的图象与性质，列出不等式组，即可求解.【详解】由函数()21213221xxf k k x +=-+---，令210xt =-≠，则0x ≠，则()2132g k t k t t+=+--，令()0g t =，可得()232210t k t k -+++=，函数21(0)x tx =-≠的图象，如图所示，由题意，方程()232120t k t k -+++=有两个不等实根1t ，2t ，不妨设12t t <，则101t <<，21t ≥，令()()23221h t t k t k =-+++，则()()021010h k h k ⎧=+>⎪⎨=-<⎪⎩，此时解得0k >，或()()02101023012h k h k k⎧⎪=+>⎪=-=⎨⎪+⎪<<⎩，此时无解，综上所述，实数k 的取值范围是()0,∞+.故选：C ．二、选择题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求，全部选对的得5分，部分选对的得2分，有选错的得0分．9.下列各组函数中，表示同一个函数的是（）A.()f x =()g x x= B.()23f x x x =-与()23g t t t=-C.()xf x x =与()1,01,0x g x x >⎧=⎨-<⎩ D.()0f x x =与()1g x =【答案】BC 【解析】【分析】逐一判断选项中的两个函数的三要素是否都相同即得结果.【详解】A 选项中：()f x x ==与()g x x =对应关系不同，故不是同一函数，故A 不正确；B 选项中：()23f x x x =-与()23g t t t =-定义域都为R ，且对应关系相同，故是同一函数，故B 正确；C 选项中：当0x >时，()1x f x x ==，当0x <时，()1xf x x-==-，所以()1,01,0x x f x x x >⎧==⎨-<⎩，故()x f x x=与()1,01,0x g x x >⎧=⎨-<⎩是同一函数，故C 正确；D 选项中：函数()0f x x =的定义域为{}0x x ≠，函数()1g x =的定义域为R ，两个函数定义域不同，故不是同一函数，故D 不正确.故选：BC ．10.已知0a b c d >>>>，则下列不等关系成立的是（）A.22ac bc >B.a d b c ->-C.ad bc <D.11a cb c>--【答案】ABC 【解析】【分析】利用不等式的性质逐一分析判断ABC ，再举反例排除D 即可得解.【详解】对于A ，因为0a b c d >>>>，所以20c >，0a b >>，则22ac bc >，故A 正确；对于B ，因为c d >，所以d c ->-，又a b >，所以a d b c ->-，故B 正确；对于C ，因为0d c <<，所以0d c ->->，又0a b >>，所以ad bc ->-，故ad bc <，故C 正确；对于D ，取2,1,1a b c ===-，则111132a c b c=<=--，故D 错误，故选：ABC.11.已知函数()()tan f x A x ωϕ=+（0ω>，π2ϕ<）的部分图象如图所示，则下列说法正确的是（）A.()f x 的最小正周期为πB.()f x 的定义域为ππ{|,Z}28k x x k ≠+∈C.点3π,08⎛⎫-⎪⎝⎭是函数()f x 图象的一个对称中心D.()f x 在3π,π4x ⎡⎤∈⎢⎥⎣⎦上的值域为[]1,1-【答案】BCD 【解析】【分析】根据题意，结合正切函数的图象与性质，逐项判定，即可求解.【详解】由图象知3πππ2884T =-=，所以函数()f x 的最小正周期为2π，故A 不正确；因为函数的最小正周期ππ2T ω==，可得2ω=，所以3π3πtan 2088f A ϕ⎛⎫⎛⎫=⨯+= ⎪ ⎪⎝⎭⎝⎭，则3ππ4k ϕ+=，k ∈Z ，即34πφkπ=-，k ∈Z ，因为π2ϕ<，所以当1k =时，3ππ44ϕπ=-=，则()tan 24f x A x π⎛⎫=+ ⎪⎝⎭，又因为()01f =，所以()0f A =πtan 14=，则1A =，所以()tan 24f x x π⎛⎫=+ ⎪⎝⎭，由ππ242x k π+≠+，Z k ∈，可得ππ28k x ≠+，k ∈Z ，所以()f x 的定义域为ππ{|,}28k x x k ≠+∈Z ，所以B 正确；因为3πππ2842⎛⎫⨯-+=- ⎪⎝⎭，可得点3π,08⎛⎫- ⎪⎝⎭是函数()f x 图象的一个对称中心，所以C 正确；当3π,π4x ⎡⎤∈⎢⎥⎣⎦时，π7π9π2,444x ⎡⎤+∈⎢⎥⎣⎦，可得[]πtan 21,14x ⎛⎫+∈- ⎪⎝⎭，所以D 正确.故选：BCD ．12.已知定义在R 上的偶函数()f x 满足()()2121f x f x --=--，且当1224x x <<<时，()()21210f x f x x x ->-恒成立．则下列说法正确的是（）A.函数()1f x -为奇函数B.()()202310f f +-=C.()520232f f ⎛⎫-> ⎪⎝⎭D.函数()f x 的图象关于点()3,0对称【答案】ABD 【解析】【分析】利用函数的奇偶性、对称性与周期性以及单调性对选项逐一分析即可.【详解】∵()()2121f x f x --=--，可得()()11f x f x --=--，∴函数()1f x -为奇函数，故A 正确；∵()()2121f x f x --=--，当0x =时，()()11f f -=--，()10f -=，又函数()f x 为偶函数，()()f x f x -=，由A 知()()11f x f x --=--，∴()()11f x f x +=--，可得()()2f x f x +=--()f x =-，则()()4f x f x +=，函数()f x 的周期为4，且()()110f f -==，∴()()202345053f f =⨯+()()310f f ==-=，∴()()202310f f +-=，故B 正确；∵1224x x <<<时，()()21210f x f x x x ->-恒成立，∴函数()f x 在()2,4上单调递增，由()520232f f ⎛⎫-> ⎪⎝⎭，可得()532f f ⎛⎫> ⎪⎝⎭，矛盾，故C 不正确；因为()1f x --()1f x =--，∴函数()f x 的图象关于点()1,0-对称，∵函数()f x 的周期为4，函数()f x 的图象关于点()3,0对称，故D 正确，故选：ABD ．三、填空题：本题共4小题，每小题5分，共20分．13.函数()213log 12x x xf x -=+++的定义域为_____________．【答案】()()2,11,3--⋃-【解析】【分析】依据对数型复合函数定义域求解即可.【详解】由题意可得10302x x x+≠⎧⎪-⎨>⎪+⎩，则123x x ≠-⎧⎨-<<⎩，即23x -<<且1x ≠-，所以函数()f x 的定义域为()()2,11,3--⋃-．故答案为：()()2,11,3--⋃-14.已知幂函数()2133m y m m x +=+-的图象不经过原点，则实数m =_____________．【答案】4-【解析】【分析】根据幂函数的定义求出m 的值，再由幂函数图象性质，判断m 的值.【详解】根据幂函数的定义可得2331m m +-=，解得4m =-或1m =，当4m =-时，3y x -=不经过原点，符合题意；当1m =时，2y x =过原点，不符合题意，故4m =-．故答案为：4-15.已知函数()2xf x =，则()()223f x f x ->+的解集为_____________．【答案】15,3⎛⎫-- ⎪⎝⎭【解析】【分析】根据题意，求得函数()f x 的单调性与奇偶性，把不等式转化为223x x ->+，即可求解.【详解】由函数()2xf x =，可得其定义域为R ，且()()||22xx f x f x --===，所以()2xf x =为偶函数，当[)0,x ∈+∞时，()2xf x =，可得()2xf x =在[)0,∞+上单调递增，根据偶函数的性质，不等式()()223f x f x ->+，即为()()223fx f x ->+，可得223x x ->+，整理得231650x x ++<，解得153x -<<-，所以()()223f x f x ->+的解集为15,3⎛⎫-- ⎪⎝⎭．故答案为：15,3⎛⎫-- ⎪⎝⎭．16.某市规划局计划对一个扇形公园进行改造，经过对公园AOB 区域（如图所示）测量得知，其半径为2km ，圆心角为弯，规划局工作人员在 AB 上取一点C ，作CD ∥OA ，交线段OB 于点D ，作CE ⊥OA ，垂足为E ，形成三角形CDE 健步跑道，则跑道CD 长度的最大值为_____________km ．【答案】3【解析】【分析】过点O 作CD 的垂线，连接OC ，设COA θ∠=，分别求得2sin CE OF θ==，2cos OE CF θ==，且23sin 3DF θ=，求得πsin 33CD CF DF θ⎛⎫=+=+ ⎪⎝⎭，结合三角函数的性质，即可求解.【详解】如图所示，过点O 作CD 的垂线，垂足为F ，连接OC ，设COA θ∠=（π0θ3<<），则2sin CE OF θ==，2cos OE CF θ==，又tansin 63DF OF πθ==，所以1π2cos sin sin cos sin 332233CD CF DF θθθθθ⎛⎫⎛⎫=+=+=+=+ ⎪ ⎪ ⎪⎝⎭⎝⎭，因为π0θ3<<，所以ππ2π333θ<+<，当ππ32θ+=，即π6θ=时，CD取到最大值km 3．故答案为：433.四、解答题：本题共6小题，共70分．解答应写出文字说明、证明过程或演算步骤．17.求解下列问题：（1）计算：10381272023π-⎛⎫⎛⎫+- ⎪ ⎪-⎝⎭⎝⎭（2）若e 2a =，e 3b =，求32a b +的值．【答案】17.1418.ln 72【解析】【分析】（1）根据指数幂运算求解;（2）指对互化求解【小问1详解】11033381239111272023π3244--⎡⎤⎛⎫⎛⎫⎛⎫+-+-+-=⎢⎥ ⎪ ⎪ ⎪-⎝⎭⎝⎭⎝⎭⎢⎥⎣⎦【小问2详解】∵e 2a =，e 3b =，∴ln 2a =，ln 3b =，∴323ln 22ln 3ln 8ln 9ln 72a b +=+=+=．18.已知()()()()()3πsin πcos cos 2π23πsin sin cos 14π2f ααααααα⎛⎫+--- ⎪⎝⎭=⎛⎫--+ ⎪⎝⎭．（1）化简()f α；（2）若()2fα=-，求212sin sin 212αα+-的值．【答案】（1）()tan f αα=-（2）1【解析】【分析】（1）根据诱导公式以及sin tan cos ααα=对其化简即可；（2）应用二倍角公式对212sin sin 212αα+-化简，将弦转换成切求解即可.【小问1详解】()()()()()()()()3πsin πcos cos 2πsin sin cos 2tan 3πcos sin cos sin sin cos 14π2f αααααααααααααα⎛⎫+--- ⎪--⎝⎭===--⎛⎫--+ ⎪⎝⎭；【小问2详解】由（1）得tan 2α=，所以22222221sin sin cos cos 2sin sin 21sin sin cos cos 2sin cos αααααααααααα+-+-=+-=+22tan tan 142111tan 14ααα+-+-===++．19.已知定义在R 上的函数()21xb f x a =++，是奇函数，且()3210f =-．（1）求实数a ，b 的值；（2）判断函数()f x 在R 上的单调性，并用函数单调性的定义证明．【答案】（1）实数a 的值为12-，实数b 的值为1（2）函数()f x 在R 上单调递减，证明见解析【解析】【分析】（1）根据题意，结合()00f =和()3210f =-，联立方程组，即可求解；（2）根据题意，利用函数单调性的定义和判定方法，即可得证.【小问1详解】解：因为定义在R 上的函数()21x bf x a =++是奇函数，可得()00f =，即02b a +=，又因为()3210f =-，所以3510b a +=-，联立方程组，可得12a =-，1b =，所以()()1112221221x x x f x -=-+=++，又由()()()()2121221212x x x xf x f x ---+--===-++，符合题意，所以,a b 的值分别为12-和1.【小问2详解】解：函数()f x 在R 上单调递减，证明：在R 上任取12x x <，则()()()()21121212121111112222122121212121x x x x x x x x f x f x -⎛⎫-=-+--+=-= ⎪++++++⎝⎭，因为12x x <，所以21220x x ->，又2210x +>，1210x +>，所以()()120f x f x ->，即()()12f x f x >，所以函数()f x 在R 上单调递减．20.已知函数()2π4cos cos 4sin 33f x x x x ωωω⎛⎫=-+- ⎪⎝⎭（0ω>）的最小正周期为π．（1）求()f x ；（2）已知π2π33α<<，()65f α=，求cos 2α．【答案】（1）()2sin 26f x x π⎛⎫=-⎪⎝⎭（2）310-【解析】【分析】（1）根据三角恒等变换的公式，化简得到()π2sin 26f x x ω⎛⎫=- ⎪⎝⎭，再结合三角函数的性质，即可求解；（2）根据题意，求得π3sin 265α⎛⎫-= ⎪⎝⎭，进而得到π4cos 265α⎛⎫-=- ⎪⎝⎭，结合两角和的余弦公式，即可求解.【小问1详解】由函数()()41cos 214cos cos sin 3222x f x x x x ωωωω⎛⎫-=++- ⎪⎪⎝⎭222cos 22cos 23x x x ωωω=++--π2cos 21232sin 26x x x ωωω⎛⎫=-++-=- ⎪⎝⎭，因为0ω>，函数()f x 的最小正周期2ππ2T ω==，可得1ω=，所以()π2sin 26f x x ⎛⎫=- ⎪⎝⎭．【小问2详解】由()π62sin 265f αα⎛⎫=-= ⎪⎝⎭，可得π3sin 265α⎛⎫-= ⎪⎝⎭，因为π2π33α<<，所以ππ7π2,626α⎛⎫-∈ ⎪⎝⎭，所以πcos 206α⎛⎫-< ⎪⎝⎭，所以π4cos 265α⎛⎫-=- ⎪⎝⎭，所以ππππππcos 2cos 2cos 2cos sin 2sin 666666αααα⎡⎤⎛⎫⎛⎫⎛⎫=-+=-- ⎪ ⎪⎢⎥⎝⎭⎝⎭⎝⎭⎣⎦4313525210-=-⨯-⨯=．21.2023年10月20日，国务院新闻办举办了2023年三季度工业和信息化发展情况新闻发布会工业和信息化部表示，2023年前三季度，我国新能源汽车产业发展保持强劲的发展势头．在这个重要的乘用车型升级时期，某公司科研人员努力攻克了动力电池单体能量密度达到300Wh/kg 的关键技术，在技术水平上使得纯电动乘用车平均续驶里程超过460公里．该公司通过市场分析得出，每生产1千块动力电池，将收入()f x 万元，且()2120,05240330,5101x x f x x x x ⎧+<≤⎪=⎨-<≤⎪-⎩该公司每年最多生产1万块此种动力电池，预计2024年全年成本总投入2.5x 万元，全年利润为()F x 万元．由市场调研知，该种动力电池供不应求．（利润＝收入－成本总投入）（1）求函数()F x 的解析式；（2）当2024年动力电池的产量为多少块时，该企业利润最大？最大利润是多少？【答案】（1）()25120,052905240,51012x x x F x x x x ⎧-+<≤⎪⎪=⎨⎪--<≤⎪-⎩（2）当2024年动力电池的产量为7000块时，该企业利润最大，最大利润是207.5万元．【解析】【分析】（1）根据已知函数模型得出函数解析式；（2）分别利用二次函数性质和基本不等式求出分段函数两段的最大值，然后比较可得．【小问1详解】由题意得()() 2.5F x f x x =-，∵()2120,05240330,5101x x f x x x x ⎧+<≤⎪=⎨-<≤⎪-⎩，∴当05x <≤时，()225120 2.51202F x x x x x =+-=-+，当510x <≤时，()2403309052.5240112x F x x x x x -=-=----，综上所述，函数()F x 的解析式为()25120,052905240,51012x x x F x x x x ⎧-+<≤⎪⎪=⎨⎪--<≤⎪-⎩．【小问2详解】由（1）得()25120,052905240,51012x x x F x x x x ⎧-+<≤⎪⎪=⎨⎪--<≤⎪-⎩，当05x <≤时，()2255251201202416F x x x x ⎛⎫=-+=-+- ⎪⎝⎭，∴()F x 在50,4⎛⎤ ⎥⎝⎦上单调递减，在5,54⎛⎤⎥⎝⎦上单调递增，∴()()max 225255120132.51616F x F ==+-=；当510x <≤时，()()905905552402401240207.5121222F x x x x x ⎡⎤⎡⎤=--=-+-+≤-+=⎢⎥⎢⎥--⎣⎦⎣⎦，当且仅当()905112x x =--，即7x =时，()max 207.5F x =，∵132.5207.5<，∴()F x 的最大值为207.5，故当2024年动力电池的产量为7000块时，该企业利润最大，最大利润是207.5万元．22.已知不等式20x mx n ++<的解集为{}21x x -<<-，函数()1xg x n λλ=--（0n >，且1n ≠），()()()2log 1log m m x x h x λ=-++（0m >，且1m ≠）．（1）求不等式20mx x n +-≥的解集；（2）若对于任意的[]11,1x∈-，均存在2x ⎤∈⎦，满足()()12g x h x ≤，求实数λ的取值范围．【答案】（1）{|1x x ≤-或2}3x ≥；（2）5,4⎡⎫-+∞⎪⎢⎣⎭【解析】【分析】（1）根据一元二次不等式与方程的关系及一元二次不等式的解法，求出解集;（2）由函数恒成立问题和存在性问题，得到()()max max g x h x ≤，利用换元转化进行分类讨论求解λ的范围.【小问1详解】不等式20x mx n ++<的解集为{}21x x -<<-，即2,1--是20x mx n ++=的两个根，故3m =，2n =，∴20mx x n +-≥，即为2320x x +-≥，解得1x ≤-或23x ≥，∴不等式20mx x n +-≥的解集为{|1x x ≤-或2}3x ≥．【小问2详解】由题意可知()()max max g x h x ≤，()()()233log 1log h x x x λ=-++，x ⎤∈⎦，令3log t x =，则()21y t t λ=-++，1,22t ⎡⎤∈⎢⎥⎣⎦，对称轴方程为12t λ+=，①若1122λ+<，即0λ<时，当12t =时，max 1124y λ=+，即()max 1124h x λ=+，此时()21x g x λλ=--在[]1,1-上单调递减，()()max 1111122g x g λλλ=-=--=--，由11112240λλλ⎧--≤+⎪⎨⎪<⎩，得504λ-≤≤；②若11222λ+≤≤，即03λ≤≤时，当12t λ+=时，()2max 114y λ=+，即()()2max 114h x λ=+，此时()21x g x λλ=--在[]1,1-上单调递增，()()max 11g x g λ==-，由()2111403λλλ⎧-≤+⎪⎨⎪≤≤⎩，得03λ≤≤；③若122λ+>，即3λ>时，当2t =时，max 22y λ=-，即()max 22h x λ=-，此时()21x g x λλ=--在[]1,1-上单调递增，()()max 11g x g λ==-，由1223λλλ-≤-⎧⎨>⎩，得3λ>，综合①②③可知54λ-≥，即实数λ的取值范围是5,4⎡⎫-+∞⎪⎢⎣⎭．。
甘肃省兰州一中2016-2017-2学期期末考试高一英语试题(含详细答案)
甘肃省兰州一中2016-2017-2学期期末考试高一英语试题说明：本试卷分为第I卷（选择题卷）和第II卷（非选择题卷）。
满分120分，考试时间100分钟。
答案写在答题卡上，交卷时只交答题卡。
第I卷选择题（共三节，满分60分）第一节（共10小题；每小题2分，满分20分）阅读下列短文，从每题所给的A、B、C和D中选出最佳选项。
AI was born and raised in the tiny town of Lafayette, Georgia. It’s a rather boring town, but luckily my mom loved traveling so we hit the road pretty frequently. I was diagnosed with spinalmuscular atrophy (脊肌萎缩症) at the age of two and have been in a wheelchair ever since. Mywheelchair and I have been to 14 countries and have plans to visit many more. Since graduatingfrom the University of West Georgia with a degree in marketing last year, I’ve put all of myenergy into growing my website. Aside from traveling and working on my blog, I love going toconcerts and trying new foods.My mom was a teacher so she was off work every summer. We used that time to travellocally and took a lot of road trips along the East Coast. Disney World was a popular choice.When I turned 15, we tried our hand at traveling internationally and went to the Bahamas. Thesetrips made me fall in love with travel and showed me that there’s so much out there in the world.My mom always told me “If you can’t stand up, stand out” a nd I try to live by thatmentality daily. I might not be able to stand physically, but I can stand. I can stand for anythingthat I desire, like traveling. A disability is not going to limit me from seeing the world. I refuse toeven entertain the thought that my disability could have that sort of power.It is much more difficult to travel as a wheelchair user. Over my life, I have met numbers ofchallenges, especially when I was younger. But I’ve learned to be positive no matter when trouble comes to me.1. What do we know about the author?A. He dislikes living in his town.B. He was born with a severe illness.C. He began travelling abroad at 15.D. He was poorly educated due to his illness.2. How does the author sound in the passage?A. UnfortunateB. OptimisticC. IndependentD. Warm-hearted3. What does the underlined part mean?A. You must stand up by yourself.B. You should accept your disability.C. You must learn how to use a wheelchair.D. You should have will and great character.BIt was a cold and wet night, I had just left a local club to travel home when I lost control ofmy car. I crashed into a car, then hit a tree. The force was so great that is knocked the parked carseveral meters forwards. I was knocked out cold. Worse still, I had no idea that a fire had startedunder the engine of my car. It then set the tree on fire.Driving behind me was a young man, who I later found out was called Jared. He saw theaccident occur and stopped to help me out of the burning car. He put his own life in danger whenhe got into the back seat to try to undo my seat belt. This wasn’t easy because I’d hit the操纵台).driver’s side and my seat belt was squeezed into the console (With my seat belt undone, Jared then hit open the driver’s window to drag me out as I hadstill not regained consciousness (意识). He bravely did this while my car and the tree wereburning. Woken by the crash, the homeowners came out to investigate. Jared told them to ringemergency services. I was rushed to the Royal Adelaide Hospital in a serious condition. Ieventually woke up a day later.I owe my life to Jared and I consider him a friend due to the special bound. Jared says thatalthough the events of that night initially shocked him, he never once hesitated to help. In addition,he doesn’t believe that he did anything special.4.What happened to the author in the crash?A. He was knocked out of his car.B. He was knocked unconscious.C. He felt cold because of bleeding.D. He climbed on the tree to escape fire.5.Why did Jared get into the back seat?A. To unfasten the author’s seat belt.B. To get the author out of the car.C. To help the author drive the car safely.D. To put out the burning fire in the car.6. Which is the best title for the passage?A. A narrow escape from deathB. A courageous crash rescueC. Jared, my best friendD. A frightening car fireCThe World Health Organization says the widespread use of sugar in food products and drinksis a major concern in many areas. So WHO officials are calling on governments to require taxeson sugary drinks in an effort to limit their usage and popularity. The officials believe the taxes also would reduce the risk of health problems resulting from obesity.Obesity is a condition in which the body stores large, unhealthy amounts of fat. Obese individuals are considered overweight. A new report says that in 2014 more than one-third of the adults in the world were overweight, and 500 million were considered obese. The United Nations agency estimates that in 2015, 42 million children under age 5 were either overweight or obese. It says that number represents an increase of about 11 million during the past 15 years. Almost halfof these boys and girls live in Asia and one-fourth in Africa.The U.N. agency blames unhealthy diets for a rise in diabetes cases. There are 422 million cases of the disease worldwide. WHO says 1.5 million people die from it every year. It says theuse of sugar in food products, like sugary drinks, is a major reason for the increase in rates of obesity and diabetes.Temo Waqanivalu is with the agency’s Department for the Prevention on Non-Communicable Diseases. He told VOA hat taxing sugary drinks would reduce consumptionand save lives. Waganivalu noted that Mexico enacted a 10 percent tax on sugary drinks in 2014. He said by the end of the year, there was a 6 percent drop in the consumption of such drinks. Among poor people, the number of people who consumed sugary drinks dropped by 17 percent.The WHO says people should limit the amount of sugar they consume. It says they should。
河北省邯郸市2017年中考一模英语试卷及答案
2017 年邯郸市初中毕业生升学文化课模拟考试英语试卷( 一)卷 I( 选择题，共80 分)听力部分 ( 第一节 )I. 听句子，选出句子中所包括的信息。
( 共 5 小题，每题1分，计 5分)1. A. weak B. week C. wake2. A. fourth B. fourteenth C. fortieth3. A. show up B. speed up C. stay up4. A. Tom likes playing games, and so does Jerry.B. Jerry likes playing games, but Tom doesn ’ t.C. Tom likes playing games, but Jerry doesn ’ t.5.A. Lucy can draw well, for she is old enough.B.Lucy can ’t draw well becaus she is young.C.Lucy can draw well, although she is young.II.听句子，选出该句的最正确答语。
( 共 5 小题，每题 1 分，计 5 分 )6. A. Good idea! B. It ’ s too long. C. You are beautiful.7. A. How great! B. Th at ’s all. C. Not at all.8. A. That ’ s a pity! B. Here you are. C. Sorry to hear that.9. A. Near the park. B. By bike. C. Three days ago.10. A. The same to you. B. Congratulations! C. Thank you.III. 听对话和问题，选择正确的选项。
2016-2017学年八年级上学期第一次学情调研考试英语试题(含答案)
2016-2017学年上学期第一次学情调研初二英语试卷（考试时间：100分钟考试形式：闭卷考试总分：100分）第Ⅰ卷（选择题，共45 分）一、单项选择（共15 小题，每小题 1 分，计15 分）从A 、B 、C、D 四个选项中选出一个可以填入句中空白处的最佳答案。
1. Tom is _______ honest boy, and he has ______ good sense of humour.A. a, aB. an, /C. a, /D. an, a2. My best friend Jack looks happy, and he always _____ a smile ________ his face.A. wears, onB. put, inC. wear, onD. wears, in3.I didn’t have breakfast this morning. Do you have _____________?A. anything eatB. something eatingC. anything to eatD. something eat4. They young man wears glasses because he spends too much time _____ the computer games.A. to playB. playingC. to workD. working5. — Health is money.— But I think it is money.A. as important asB. more important thanC. so important thanD. the same as6. There is a big cake. ____________ share it.A. May be we canB. We may beC. Maybe we canD. Maybe can we7.We all think he is one of the _____________ in our school.A. good teacherB. best teachersC. better teachersD. best teacher8. —Peter is _______ than you, right?—Yes, but he is ________ runner in our class.A. heavier, the bestB. heavier, bestC. heavyer, the bestD. heavy, better9. —What is your brother like? —_______________.A. He likes watching TV.B. He is a worker in a factory.C. He is very helpful and friendly.D. He works on a farm.10. “_________” is another way of saying “cookie”.A. BiscuitB. EraserC. HolidayD. Maths11.Times seems __________ when we are playing computer games.A. go fasterB. to go fasterC. to going fastD. go fast12.Why don’t you _________ an English Club to practice _________English?A. to join, speakingB. to join, to speakC. join, to speakD. join, speaking13. I have __________ money than you, but I have __________ friends than you.A. more, moreB. less, moreC. fewer, moreD. more, less14. The Changjiang River is ________ river in China.A. the longestB. the longerC. the second longerD. the second longest15. —Would you like some bread？—______________. I’m hungry now.A. Yes, I would.B. No, I don’tC. Yes, please.D.No, thanks.二、完形填空（共10 小题，每小题 1 分，计10 分）阅读下面短文，掌握其大意，然后从各题所给的四个选项中选出一个最佳答案。
河北省邯郸市武安市第一中学2024-2025学年高一上学期10月期中考试英语试题
河北省邯郸市武安市第一中学2024-2025学年高一上学期10月期中考试英语试题一、听力选择题1．What kind of dance does the man like now?A．Modern dance.B．Folk dance.C．Ballet.2．What does the man suggest the woman do?A．Read a novel.B．See a movie.C．Watch a TV program. 3．What will the woman probably do today?A．Clean the house.B．Have a party.C．Get some food. 4．Where are the speakers probably now?A．In a car.B．At the airport.C．At the train station. 5．What are the speakers mainly talking about?A．The activities after school.B．The problem of a computer.C．The story of a writer.听下面一段较长对话，回答以下小题。
6．Who is the man probably?A．A policeman.B．A driver.C．A judge.7．What will the woman get?A．A ticket.B．A warning.C．A driver’s license.听下面一段较长对话，回答以下小题。
8．Why does the man find it hard to study at home?A．He needs a teacher’s help.B．There is too much noise.C．Online classes are boring.9．What do the speakers plan to do after the coronavirus is over?A．Have a party.B．Go for a trip.C．Play loud music.听下面一段较长对话，回答以下小题。
【精准解析】河北省邯郸市永年一中2019-2020学年高一下学期期末考试英语试题
- 1 - 永年一中2019-2020学年高一下学期期末考试 英语 第一部分：听力（共两节，满分30分） 第一节 (共 5 小题；每小题 1.5 分，满分 7.5 分) 听下面 5 段对话。每段对话后有一个小题，从题中所给的 A、B、C 三个选项中选出最佳选项。听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 例：How much is the shirt? A. ￡19.15. B. ￡9.15. C. ￡9.18. 答案是B。 1. When was the woman born? A. In 1984. B. In 1982. C. In 1980. 2. What are the speakers probably doing? A. Looking for John’s new apartment. B. Visiting John’s old house. C. Helping John move house. 3. Why does the woman refuse to go to the beach? A. It’s hot there. B. She can’t swim. C. She isn’t free. 4. What are the speakers talking about? A. A news report. B. A driving test. C. A car accident. 5. What does the man mean? A. He doesn’t have a computer. B. He doesn’t know how much a new computer costs. C. He thinks the price of the new computer is reasonable. 第二节(共 15 小题；每小题 1.5 分，满分 22.5 分) 听下面5段对话或独白。每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。听每段对话或独白前，你将有时间阅读各个小题，每 - 1 -
内蒙古准格尔旗世纪中学2016-2017学年高一上学期期末考试英语试题缺答案
2016-2017学年第一学期高一期末考试英语试题命题人：周睿第一部分：阅读理解（共15小题,每小题2分）第一节:阅读下列短文，从每题所给的四个选项(A、B、C和D）中,选出最佳选项. AIn the late 1990s，a family visited the school where I taught deaf students. They said they would be moving here and planned to send their deaf daughter to my school as a first grader. They were upset that their child’s kindergarten teacher told them not to have high hopes for her. The teacher painted a bleak （暗淡的）picture for their little girl’s future. Standing behind them was Katherine, a beautiful five-year—old with long hair and dark eyes。
The whole time her parents were there she didn’t make a sound or use sign language，even when her parents asked her to do so。
After a few weeks with Katherine, I discovered I was dealing with a very bright child。
Although I was able to make her join in different learning activities, writing was always a struggle。
河北省邯郸市2023-2024学年高一上学期期末质量检测试题 语文(含答案)
绝密★启用前邯郸市2023—2024学年第一学期期末质量检测高一语文（答案在最后）班级____________姓名____________注意事项：1．答卷前．考生务必将自己的姓名、班级和考号填写在答题卡上。
2．回答选择题时，选出每小题答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
回答非选择题时，将答案写在答题卡上，写在本试卷上无效。
3．考试结束后，将本试卷和答题卡一并交回。
一、现代文阅读（35分）（一）现代文阅读Ⅰ（本题共5小题，19分）阅读下面的文字，完成1～5题。
表面上，种子拥有致命毒素似乎是很合理的，这是一种自然的适应性改变。
毕竟，为了保护种子。
有什么办法比杀死任何想要吃掉它们的东西更好呢？但实际上，从令人讨厌到真正致命的这个进化步骤要复杂得多。
当一粒种子受到攻击时，植物的当务之急就是让攻击者停下来，这也是苦味、辣味和灼烧感很常见的原因。
直接的生理不适赶走了种子掠食者，并告诫它们不要再来。
它们甚至可以将这个教训传递给其他同类。
相反，毒素可能需要过几个小时或几天才能发挥效力，这样就无法阻止正在掠食种子的攻击者了。
理论上说，像蓖麻毒蛋白这样无味的毒素可能会让一只动物吃光一棵蓖麻植株的所有种子，然后离开，并在不知道原因的情况下死去。
因此，引发不适感的化学物质可以阻止各类种子掠食者，而致命的毒素只能消灭单独的掠食者，这是一场持久战。
这引发了一个问题，是什么进化诱因促使一些毒素不断变强，导致像蓖麻毒蛋白这样的化合物具有几乎令人难以理解的强大效力？“似乎没有明显的答案。
”当我提出这个问题的时候，德里克·比利告诉我。
我有段时间没联系他了，但当我遇到无法解决的难题时，这位种子研究方面的“神”总是慷慨地帮助我。
他解释说．种子的毒素往往以不同的方式影响不同的攻击者。
为了使一只动物感到轻微胃痛，并警告它不要再吃这种种子，而进化出来的物质，也许对另一只动物来说是完全致命的。
河南省郑州市2016-2017学年高一上学期期末考试数学试题 Word版含答案
河南省郑州市2016-2017学年高一上学期期末考试数学试题 Word版含答案数学试题第Ⅰ卷（共60分）一、选择题：本大题共12个小题，每小题5分，共60分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1.若$\{1,2\}\subset A\subset\{1,2,3,4,5\}$，则满足条件的集合$A$的个数是（）A。
6B。
8C。
7D。
92.设$a,b\in\mathbb{R}$，集合$A=\{1,a+b,a\},B=\{0,\frac{b}{a},b\}$，若$A=B$，则$b-a=$（）A。
2B。
$-1$C。
1D。
$-2$3.下列各组函数中$f(x)$与$g(x)$的图象相同的是（）A。
$f(x)=x,g(x)=|x|$B。
$f(x)=x^2,g(x)=\begin{cases}x,&(x\geq 0)\\-x,&(x<0)\end{cases}$C。
$f(x)=1,g(x)=x$D。
$f(x)=x,g(x)=\begin{cases}x,&(x\geq0)\\0,&(x<0)\end{cases}$4.下列函数中，既是偶函数又在$(-\infty,0)$内为增函数的是（）A。
$y=-\frac{1}{2}$B。
$y=x^2$C。
$y=x+1$D。
$y=\log_3(-x)^2$5.三个数$a=0.32,b=\log_2 0.3,c=2^0.3$之间的大小关系为（）A。
$a<c<b$B。
$a<b<c$C。
$b<a<c$D。
$b<c<a$6.下列叙述中错误的是（）A。
若点$P\in\alpha,P\in\beta$且$\alpha\cap\beta=l$，则$P\in l$B。
三点$A,B,C$能确定一个平面C。
若直线$a\parallel b$，则直线$a$与$b$能够确定一个平面D。
若点$A\in l,B\in l$且$A\in\alpha,B\in\alpha$，则$l\subset\alpha$7.方程$\log_3 x+x=3$的解所在区间是（）A。