江苏省扬州市2020届高三第二次模拟考试(5月)物理(含答案)

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江苏省2020届高三第二次模拟考试地理 Word版含答案1

2020届高三模拟考试试卷地理2020.4本试卷包括第Ⅰ卷(选择题)和第Ⅱ卷(综合题)两部分。

满分120分，考试时间100分钟。

第Ⅰ卷(选择题共60分)一、选择题(共60分)(一) 单项选择题：本大题共18小题，每小题2分，共36分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

图1、图2分别为某日同一时刻太阳高度沿某经线和某纬线分布图。

读图回答1～2题。

1. 此时()A. 北京时间为2时B. a＋c＝90°C. 图1经线为90°WD. 图2纬线为23°26′N2. 下列叙述正确的是()A. 该日北极圈上出现极昼B. 该日后太阳直射点将向南移C. 次日图2纬线昼长夜短D. 次日南京日出东北方向2020年1月6日～7日，全国迎来了冬至后的首次大范围降水，图3为1月6日～7日全国降水量分布图。

读图回答3～5题。

图33. 贵阳和西安两地降水量的差值最大可能是()A. 5 mmB. 14 mmC. 22 mmD. 24 mm4. 昆明可能发布()A. 洪涝预警B. 低温冻害预警C. 滑坡、泥石流预警D. 森林火灾预警5. 太原未来两天的天气状况可能是()A. 天气转晴，气温升高B. 气压下降，降雪变为降雨C. 降雪后，气温降低，空气质量改善D. 风速减小，出现连续性降水图4示意我国南方某地区等坡度线(地表坡度值相等的点连成的线)，图中数字代表坡度(坡面与水平面的夹角)。

图5表示图4区域内一次局地暴雨后甲、乙两个水文站观测到的河流流量变化。

据此回答6～7题。

6. 该次暴雨发生的局部地点最可能是()A. ①地B. ②地C. ③地D. ④地7. 据图判断，该河流()A. 干流由西南流向东北B. 流量②地比③地小C. ①地水流较平稳D. ④地以侵蚀作用为主海漂植物是通过海水漂流进行传播的植物。

椰树广泛分布于热带滨海地区，是海漂植物的典型代表。

椰树是海南省的省树，但并非海南岛的“土著”，其种子最初是借助海水运动从其他国家“偷渡”而来的。

2020届山东省日照市高三(下)5月校际联合考试二模物理试题

2020届山东省日照市高三（下)5月校际联合考试二模物理试题
学校:___________姓名：___________班级：___________考号：___________
1．下列说法中正确的有（）
A．医院用的“CT”的工作原理是利用超声波的多普勒效应
B．将单摆从赤道移到北极，单摆周期将变大
C．光导纤维传递光信号是利用光的衍射原理
故选C。
3．A
【解析】
【分析】
【详解】
以第1块石块为研究对象，分析受力情况：重力G、第2块石块的弹力N1和第3块石块的弹力N2，如图，由平衡条件得
故选A。
4．C
【解析】
【分析】
【详解】
因粒子受周围气体的阻力作用，则速率减小，根据可知，粒子的速率减小，半径不变，则磁感应强度B的值减小，可知粒子从A点射入，由左手定则可知，粒子带正电，故选项ABD错误，C正确。
解得
故B错误；
A．球在室内充气前与在室外相比，压强发生变化，气体体积不变，球内壁单位面积上受到气体分子的撞击力发生变化，故A错误；
C．在室内，蹦蹦球充气过程温度不变，但气体质量发生变化，所以球内气体内能发生变化故C错误；
D．设至少充气n次可使球内气体压强达到4atm以上，以蹦蹦球内部气体和所充气体的整体为研究对象
A． B． C． D．
4．一不计重力的带电粒子垂直射入自左向右逐渐增强的磁场中，由于周围气体的阻碍作用，其运动轨迹恰为一段圆弧，则从图中可以判断（）
A．粒子从B点射入，速率逐渐减小
B．粒子从A点射入，速率逐渐增大
C．粒子带正电荷
D．粒子带负电荷
5．如图所示，在网球的网前截击练习中，若练习者在球网正上方距地面H处，将质量为m的球以速度v沿垂直球网的方向击出，球刚好落在底线上。已知底线到网的距离为L，重力加速度取g，将球的运动视作平抛运动，球落在底线上时速度方向的偏角为α。下列判断正确的是（）

2020届江苏省扬州市高三第四次模拟考试：数学模拟试卷(有答案)

Read x If x≤5 Then y←10x Else y←+5End If扬州市高三第四次模拟测试数学试题Ⅰ（全卷满分160分，考试时间120分钟）注意事项：1．答卷前，请考生务必将自己的学校、姓名、考试号等信息填写在答卷规定的地方．2．试题答案均写在答题卷相应位置，答在其它地方无效．一、填空题（本大题共14小题，每小题5分，共70分，请将答案填写在答题卷相应位置）1．已知集合{|12}A x x =-<<，Z 是整数集，则A Z =I ▲ ． 2．若复数z 满足1iz i =+（i 为虚数单位），则z = ▲ ． 3．命题“2,10x R x x ∃∈++=”的否定 ▲ ． 4．已知ABC ∆中，21,2,3a b C π===，则边c 的长度为 ▲ ． 5．下面是一个算法的伪代码．如果输出的y 值是20，则输入的x 值是 ▲ ．6．在区间]2,1[-内随机选取一个实数，则该数为正数的概率是 ▲ ．7．在三棱锥P ABC -中，PA 、PB 、PC 两两垂直，且3,2,1PA PB PC ===，则三棱锥P ABC -的体积为 ▲ ．8．已知tan 2α=且α为锐角，则cos2α= ▲ ．9．在平面直角坐标系xOy 中，如果直线l 将圆22420x y x y +--=平分，且不经过第四象限，那么l 的斜率的取值范围是 ▲ ．10．已知等边ABC ∆中，若1()3AP AB AC =+u u u r u u u r u u u r ，AQ AP t AB =+u u ur u u u r u u u r ，且AP AQ ⊥u u u r u u u r ，则实数t 的值为 ▲ ．11．设双曲线)0,0(12222>>=-b a by a x 的右焦点为F ，右准线l 与两条渐近线交于P 、Q 两点，如果PQF∆是等边三角形，则双曲线的离心率是 ▲ ．（第5题图）12．设函数2log ()(0)()2(0)x x x f x x -<⎧=⎨≥⎩，若关于x 的方程2()()0f x af x -=恰有三个不同的实数解，则实数a 的取值范围为 ▲ ．13．已知数列{}n a 是各项均不为零的等差数列，n S 为其前n项和，且n a =n *∈Ν）．若不等式2016n n S a λ≥-对任意n *∈Ν恒成立，则实数λ的最小值为 ▲ ．14．已知函数32()f x ax bx cx d =+++在O 、A 两点处取得极值，其中O 是坐标原点，A 在曲线2sin ([,])33y x x x ππ=∈上，则曲线()y f x =的切线斜率的最大值为 ▲ ．二、解答题（本大题共6小题，计90分．解答应写出必要的文字说明、证明过程或演算步骤） 15．（本小题满分14分）已知向量(sin(),1)2a x ωϕ=+r ，(1,cos())2b x ωϕ=+r (0,0)4πωϕ><<，记函数()()()f x a b a b =+⋅-r r r r ．若函数()y f x =的周期为4，且经过点1(1,)2M ．（1）求ω的值；（2）当11x -≤≤时，求函数()f x 的最值． 16．（本小题满分14分）在三棱锥P －S BC 中，A ，D 分别为边SB ，SC 的中点，且3,8, 5.AB BC CD ===PA ⊥BC ．（1）求证：平面PSB ⊥平面ABCD ；（2）若平面PAD I 平面PBC l =，求证：//l BC ．PSDCBA（第16题图）17．（本小题满分14分）某工厂生产某种黑色水笔，每百支水笔的成本为30元，并且每百支水笔的加工费为m 元（其中m 为常数，且36m ≤≤）．设该工厂黑色水笔的出厂价为x 元/百支（3540x ≤≤），根据市场调查，日销售量与x e 成反比例，当每百支水笔的出厂价为40元时，日销售量为10万支．（1）当每百支水笔的日售价为多少元时，该工厂的利润y 最大，并求y 的最大值．（2）已知工厂日利润达到1000元才能保证工厂的盈利．若该工厂在出厂价规定的范围内，总能盈利，则每百支水笔的加工费m 最多为多少元（精确到0.1元） 18．（本小题满分16分）已知椭圆22221(0)x y a b a b+=>>的长轴长为4，椭圆的离心率为32．设点M 是椭圆上不在坐标轴上的任意一点，过点M 的直线分别交x 轴、y 轴于A 、B 两点上，且满足13AM AB =u u u u r u u u r．（1）求证：线段AB 的长是一定值；（2）若点N 是点M 关于原点的对称点，一过原点O 且与直线AB 平行的直线与椭圆交于P 、Q 两点（如图），求四边形MPNQ 面积的最大值，并求出此时直线MN 的斜率．yQPNMB A Ox （第18题图）19．（本小题满分16分）数列{}n a 是公差为d (0)d ≠的等差数列，它的前n 项和记为n A ，数列{}n b 是公比为q (1)q ≠的等比数列，它的前n 项和记为n B ．若110a b =≠，且存在不小于3的正整数,k m ，使k m a b =．（1）若11a =，2d =，3q =，4m =，求k A ．（2）若11a =，2d =，试比较2k A 与2m B 的大小，并说明理由；（3）若2q =，是否存在整数,m k ，使86k m A B =，若存在，求出,m k 的值；若不存在，说明理由．20．（本小题满分16分）已知函数()f x =1ln ,a x a x+∈R ．（1）求函数()f x 的单调递减区间；（2）当[]1,2x ∈时，()f x 的最小值是0，求实数a 的值；（3）试问过点(02)P ，可作多少条直线与曲线()y f x =相切并说明理由．扬州市高三第四次模拟测试数学试题Ⅱ（全卷满分40分，考试时间30分钟）21（B ）．（本小题满分10分）已知矩阵21a A b ⎡⎤=⎢⎥⎣⎦，若矩阵A 属于特征值3的一个特征向量为11α⎡⎤=⎢⎥⎣⎦u r ，求该矩阵的另一个特征值．21（C ）．（本小题满分10分）在直角坐标系xOy 中，直线l 的参数方程为12x ty a t =+⎧⎨=-⎩（t 为参数）在极坐标系(与直角坐标系xOy 取相同的长度单位，且以原点O 为极点，极轴与x 轴的非负半轴重合）中，圆C 的方程为4cos ρθ=．若直线l 被圆C 截得的弦长为11，求实数a 的值．22．（本小题满分10分）长时间上网严重影响着学生的健康，某校为了解甲、乙两班学生上网的时长，分别从这两个班中随机抽取6名同学进行调查，将他们平均每周上网时长作为样本，统计数据如下：甲班 10 12 15 18 24 36 乙班121622262838如果学生平均每周上网的时长超过19小时，则称为“过度上网”．（1）从甲班的样本中有放回地抽取3个数据，求恰有1个数据为“过度上网”的概率；（2）从甲班、乙班的样本中各随机抽取2名学生的数据，记“过度上网”的学生人数为X ，写出X 的分布列和数学期望()E X ． 23．（本小题满分10分）已知*0()()nkk n nk f x Cx n N ==∈∑．（1）若456()()2()3()g x f x f x f x =++，求)(x g 中含4x 项的系数；（2）证明：012121231(2)123[]3n m m m m m n m n m n C C C nC C m -+++++++++++++=+L ．高三第四次模拟测试数学试题Ⅰ参考答案一、填空题1．{0,1} 2．1i - 3．“2,10x R x x ∀∈++≠” 4．7 5．2或6 6．23 7．1 8．35- 9．1[0,]2 10．23- 11．2 12．[1,)+∞ 13．12017 14．32二、解答题（本大题共6小题，计90分．解答应写出必要的文字说明、证明过程或演算步骤）15．解：（1）2222()()()sin ()cos ()cos(2)22f x a b a b a b x x x ωωϕϕωϕ=+⋅-=-=+-+=-+r r r r r r………………………4分由题意得：周期24T πω==，故2πω=……………………6分（2）∵图象过点1(1,)2M ，1cos(2)22πϕ∴-+=即1sin 22ϕ=，而04πϕ<<，故26πϕ=，则()cos()26f x x ππ=-+． ……………………10分当11x -≤≤时，23263x ππππ-≤+≤1cos()1226x ππ∴-≤+≤ ∴当13x =-时，min ()1f x =-，当1x =时，max 1()2f x =． ……………………14分16．证：（1）Q A ，D 分别为边SB ，SC 的中点，且8BC = //AD BC ∴且4AD =3,AB SA ==Q 5CD SD ==222SA AD SD ∴+=90SAD ∴∠=︒即SA AD ⊥BC SB ∴⊥ ……………………3分PA BC ⊥Q ，PA SB A =I ，PA 、SB ⊂平面PSB BC ∴⊥平面PSBBC ⊂Q 平面ABCD ∴平面PSB ⊥平面ABCD ……………………7分（2）//AD BC Q ，AD ⊂平面PAD ，BC ⊄平面PAD//BC ∴平面PAD ……………………10分BC ⊂Q 平面PBC ，平面PAD I 平面PBC l =//l BC ∴ ……………………14分17．解：（1）设日销量为x k e ，则401000ke=401000k e ∴=．则日售量为401000x e e ∴日利润401000(30)xe y x m e =--⋅．即 401000(30)xe x m y e --=，其中3540x ≤≤． ………………3分令'0y =得31x m =+．① 当34m ≤<时，343135m ≤+< ∴当3540x ≤≤时，'0y ≤．∴当35x =时，y 取最大值，最大值为51000(5)m e -． ………………5分② 当46m ≤≤时，353137m ≤+≤，函数y 在[35,31]m +上单调递增，在[31,40]m +上单调递减． ∴当31x m =+时，y 取最大值91000m e -． ………………7分 ∴当34m ≤<时，35x =时，日利润最大值为51000(5)m e -元当46m ≤≤时，31x m =+时，日利润最大值为91000m e -元． ………………8分（2）由题意得：401000(30)1000xe x m e --≥对[35,40]x ∀∈恒成立 ………………10分则4030xe m x e≤--对[35,40]x ∀∈恒成立设40()30x e h x x e =--，[35,40]x ∈ 404040'()1x xe e e h x e e -∴=-= 则()h x 在[35,40]上单调增，则min 51()(35)5h x h e ==-，即515m e≤- 5.0≈ ∴每百支水笔的加工费m 最多约为4.9元答：每百支水笔的加工费m 最多约为4.9元． ………………14分18．解：（1）由题意得：24a c e a =⎧⎪⎨==⎪⎩2a c =⎧⎪⎨=⎪⎩1b ∴= ∴椭圆方程为：2214x y += ……………………3分设00(,)M x y ，则220014x y +=13AM AB =u u u u r u u u r Q 且A 、B 分别在x 轴、y 轴上 003(,0),(0,3)2A xB y ∴222220000999()944x AB x y y ∴=+=+= 3AB ∴=为定值 ……………………7分（2）方法（一）设11(,)P x y //AB PQ Q 02PQ AB y k k x ∴==-，220044x y += 则直线PQ 的方程为：02y y x x =-…………………9分∵0022214y y x x x y ⎧=-⎪⎪⎨⎪+=⎪⎩ 22012200220122004161616x x x y y y x y ⎧=⎪+⎪∴⎨⎪=⎪+⎩2222002222000041664441616x y PQ OP x y x y +∴==⋅=++ 点M 到直线00:20PQ y x x y +=的距离：0000002200|3|24x y d y x ==+ ………12分 22220000002222220000003||(44)12212122216441616四边形MPQMPNQ x y x y y y S S PQ d x y y y x y ∆-∴==⨯⋅=⋅==+-++4200201231y y y -+=+，令231,1t y t =+≥，则242002011()14133(5)3199t t y y t y t t ---+-+==-+-≤+ 当且仅当2t =时，取等号；即20312y +=时，max ()4四边形MPNQ S =，此时220018,33y x ==2MN k ∴=±………16分方法（二）设直线MN 的斜率为k ，则003232PQ AB y k k k x -===-，则直线MN 方程为y kx =，直线PQ 方程为2y kx =-， …………………9分解方程组22,1,4y kx x y =⎧⎪⎨+=⎪⎩ 214M x k =±+，用2k -代k 得，2116P x k =±+，由椭圆的对称性知222002221||M MN OM x y k x ==+=+，点P 到直线MN 的距离222|||(2)|3||111kx y kx kx kx d kkk---===+++， ………12分由椭圆的对称性知，四边形MPNQ 的面积1226||||2PMN M P S S MN d x kx ∆==⋅⋅=⋅＝ 2222222224,114116(14)(116)1642026420k kk k k k kk k==≤=+⋅+++++⨯+当且仅当22164k k=，即2k =±时取等号，所以，四边形MPNQ 的面积的最大值为4，此时直线MN 的斜率24k =±． ………16分 19．解：（1）34327k a b ===，即2127k -=，14k =，14196A =． ………3分（2）依题意，224k A k =，且121m q k -=-，显然1q >．又222211[(21)1]11m mq B k q q q -==----，所以222221[(21)1]41m k B A k q k q -=---- 22221[(21)4(41)]1k q k q k q =--+--， ………6分设2222()(21)4(41)f x k x k x k =--+-，2(1)(21)10f k =--> 它是关于x 的二次函数，它的图象的开口向上，它的对称轴方程22412(21)k x k =<-，故()f x 是(1,)+∞上的增函数，所以当1x >时()(1)0f x f >>，即220m k B A ->，所以22k m A B <． ………9分（3）依题意：112m k m a b a -==⋅，由86k m A B =得：118621k ma a a qa k q+-⨯=⨯-，即111112286212m m a a a a k --+⋅⨯=⨯-， 4862128622486486m k k k⨯+⨯==-⨯-⨯-， ………12分所以151634421m k --=+，因为92512=，故19m -≤，且51641294343=⨯=⨯⨯，且121m -+为奇数则其中121129m -+=时，151621m -+是整数，故17m -=，8m =且340k =． ………16分 20．解：（1）2211'()a ax f x x x x-=-+=， 0a ≤时，'()0f x <在(0,)+∞上恒成立，则()f x 的单调递减区间(0,)+∞，0a >时，令10ax -<则1x a <，即10x a<<时，'()0f x <，则()f x 的单调递减区间1(0,)a ． ………3分（2）①12a ≤，()f x 在[1,2]上单调递减，min 1()(2)ln 202f x f a ∴==+=，解得：112ln 22a =-≤，适合题意；②1a ≥，()f x 在[1,2]上单调递增，min ()(1)10f x f ∴==≠，无解；③112a <<，()f x 在1[1,]a 上单调递减，1[,2]a 上单调递增，min 11()()ln 0f x f a a a a∴==+=，解得：a e =，舍去；综上可得：12ln 2a =-． ………8分（3）0a ≤时，有1条切线；0a >时，有2条切线．设切点坐标是00(,())x f x ，依题意：00200()210f x ax x x --=- 即00011ln 2a x a x x +-=-，化简得：002ln 20a x a x +--= 设2()ln 2F x a x a x=+--，0x > 故函数()F x 在(0,)+∞上零点个数，即是曲线切线的条数． ………10分2222'()a ax F x x x x -=-+=①当0a =时，2()2F x x=-，在(0,)+∞上恰有一个零点1； ………11分③ 当0a <时，22'()0ax F x x -=<在(0,)+∞上恒成立， ()F x 在(0,)+∞上单调递减，且(1)0F a =->，2()20F e e=-< 故()F x 在(1,)e 上有且只有一个零点，当0a <时，()F x 在(0,)+∞上恰有一个零点； ………12分③0a >时，()F x 在2(0,)a 上递减，在2(,)a+∞上递增，故()F x 在(0,)+∞上至多有两个零点，且(1)220F a a =--=-< 又函数ln y x =在(1,)+∞单调递增，且值域是(0,)+∞，故对任意实数a ，必存在0(1,)x ∈+∞，使02ln a x a+>，此时 00000222()ln 2(ln )0a F x a x a a x x x a+=+--=+-> 由于21a a+>，即函数()F x 在0(1,)x 上必有一零点； ………14分111(1)1121()2(1)22(23)a a a aaa F eea a a e a a a-++++++=-++--=-++先证明当0a >时，112(2)a aea ++≥+，即证112ln(2)a a a++≥+ 若(0,2)a ∈，113a a++≥，而2ln(2)2ln 4a +≤，由于2ln 4ln163=< 若[2,)a ∈+∞，构建函数1()12ln(2)x x x xϕ=++-+，32222122(1)2'()102(2)(2)x x x x x x x x x x x ϕ----=--==>+++ ()x ϕ在[2,)+∞为增函数，1()(2)32ln 402a ϕϕ≥=+->综上0a >时，112(2)a aea ++≥+，所以11222222(2)23(25)23a aea a a a a a a ++≥+=+++++>++，故1(1)()0a aF e-++>又1(1)(1)0,1a aF e -++<<，所以在1(1)(,1)a ae-++必有一零点．∴当0a >时，()F x 在(0,)+∞上有两个零点∴综上：0a ≤时，有1条切线；0a >时，有2条切线． ………16分数学试题Ⅱ参考答案21（B ）．解：因为2113111a b ⎡⎤⎡⎤⎡⎤=⎢⎥⎢⎥⎢⎥⎣⎦⎣⎦⎣⎦，则2313a b +=⎧⎨+=⎩ ，解得12a b =⎧⎨=⎩所以1221A ⎡⎤=⎢⎥⎣⎦ …5分由212()(1)4021f λλλλ--==--=--，所以(1)(3)0λλ+-= 211,3λλ=-= 1λ=-所以另一个特征值是． ………………………………10分 21（C ）．解：直线l 的参数方程为12x ty a t =+⎧⎨=-⎩（t 为参数）所以直线的直角坐标系方程是：220x y a +--= ………………………………2分圆的直角坐标系方程是：2224x y -+=（），圆心（2，0），半径2r =……………………4分设圆心到直线的距离为d ，221142d ⎛⎫+= ⎪ ⎪⎝⎭，所以52d = ……………………………7分又4225255a a d ---===所以9122a =-或 ………………………………10分 22．解：（1）设“恰有一个数据为过度上网”为事件A ，则213124()()339P A C ⎛⎫== ⎪⎝⎭ ……3分（2）甲组六人中有两人过度上网，乙组六人中有四人过度上网，则224222666(0)225C C P X C C === 112112422244226656(1)225C C C C C C P X C C +===11112222424244222266101(2)225C C C C C C C C P X C C ++===211211242442226656(3)225C C C C C C P X C C +=== 222422666(4)225C C P X C C === ……………8分()2342225225225225E X ∴=+⨯+⨯+⨯= 答：数学期望为2 …………………………10分 23．解：（1）00110()(1)nk k n nn n n n n n k f x C x C x C x C x x ===+++=+∑L …………………………1分456456()()2()3()(1)2(1)3(1)g x f x f x f x x x x =++=+++++()g x 中4x 项的系数为4444562356C C C ++=； …………………………3分（2） 012111111231232323n m m m m m m m m n m m m m nC C C nC C C C nC -++++++++++++++++=++++L L设12()(1)2(1)(1)m m m nh x x x n x +++=++++++L ①则函数()h x 中含1m x +项的系数为111112323m m m m m m m m n C C C nC ++++++++++++L ……5分由错位相减法得：1231()(1)(1)(1)(1)(1)m m m m n m n xh x x x x x n x ++++++-=++++++++-+L ② 11(1)1(1)()(1)1(1)m nm n x x xh x n x x +++⎡⎤+-+⎣⎦-=-+-+2111()(1)(1)(1)m m n m n x h x x x n x +++++=+-+++，()h x 中含1m x +项的系数，即是等式左边含3m x +项的系数，等式右边含3m x +项的系数为3211m m m n m n C nC ++++++-+ …………………………7分3211m m m n m n C nC ++++++-+21(1)!(3)!(2)!m m n m n nC m n +++++=-++-221113m m m n m n n C nC m ++++++-=-++21(3)(1)3m m n m n n C m ++++--=+21(2)13m m n m n C m +++++=+所以012121231(2)123[]3n m m m m m nm n m n C C C nC C m -+++++++++++++=+L………………10分。

江苏省南通市2020届高三第二学期阶段性模拟考试(附答案)

开始输出n 输入p结束n ←1, S ←0S < pn ←n + 1S ←S + 2n NY（第5题）江苏省南通市2020届高三第二学期阶段性模拟考试数学试题2020.05(总分160分，考试时间120分钟)一、填空题（本大题共14小题，每小题5分，计70分. 不需写出解答过程，请把答案写在答题纸的指定位置上）1．已知集合{}1,2,3,4A =，{}2log (1)2B x x =-<，则A B =I ▲ ． 2．设复数2(2i)z =+（i 为虚数单位），则z 的共轭复数为 ▲ ．3．若以连续掷两次骰子分别得到的点数m ，n 作为点P 的横、纵坐标，则点P 在直线2x ﹣y ﹣1＝0上方的概率为．4．在平面直角坐标系xOy 中，若抛物线22(0)x py p =>上纵坐标为1的一点到焦点的距离为4，则该抛物线的焦点到准线的距离为 ▲ ． 5．执行右边的程序框图，若p ＝14，则输出的n 的值为 ▲ ．6．函数22log (32)y x x =--的值域为 ▲ ．7．等差数列}{n a 中，若100119753=++++a a a a a ，则=-1393a a ▲ ．8．现用一半径为10 cm ，面积为80π cm 2的扇形铁皮制作一个无盖的圆锥形容器（假定衔接部分及铁皮厚度忽略不计，且无损耗），则该容器的容积为 ▲ cm 3．9．已知() 0 αβ∈π，，，且()1tan 2αβ-=，1tan 5β=-，则tan α的值为 ▲ ．10．已知实数,x y 满足40210440x y x y x y +-⎧⎪-+⎨⎪+-⎩≤≥≥，则3z x y =+-的取值范围是 ▲ ．11．若函数()()ππ()sin 63f x a x x =++-是偶函数，则实数a 的值为 ▲ ．12．在△ABC 中，cos 2sin sin A B C =，tan tan 2B C +=-，则tan A 的值为 ▲ ． 13．已知函数2210()0xx mx x e f x e mx x ⎧+<⎪=⎨⎪+>⎩，，，，若函数()f x 有四个不同的零点，则实数m 的取值范围是 ▲ ．14．已知[)0,2θπ∈，若关于k ()33sin cos k θθ-在(],2-∞-上恒成立，则θ的取值范围为 ▲ ．二、解答题（本大题共6小题，计90分. 解答应写出必要的文字说明，证明过程或演算步骤，请把答案写在答题纸的指定区域内） 15．(本小题满分14分)已知sin cos θθ+=，ππ44θ⎛⎫∈- ⎪⎝⎭，．（1）求θ的值；（2）设函数()22()sin sin f x x x θ=-+，x ∈R ，求函数()f x 的单调增区间．16．(本小题满分14分)如图，在四棱锥P ABCD -中，底面ABCD 为梯形，//CD AB ，2AB CD =， AC 交BD 于O ，锐角PAD ∆所在平面PAD ⊥底面ABCD ，PA BD ⊥，点Q 在侧棱PC 上，且2PQ QC =．（1）求证：//PA 平面QBD ；（2）求证：BD AD ⊥．17．(本小题满分14分)在平面直角坐标系xOy 中，圆O ：224x y +=，直线l ：43200x y +-=．43()55A ，为圆O 内一点，弦MN 过点A ，过点O 作MN 的垂线交l 于点P ．（1）若MN ∥l ，求△PMN 的面积．（2）判断直线PM 与圆O 的位置关系，并证明．18．(本小题满分16分)如图，有一正三角形铁皮余料，欲利用余料剪裁出一个矩形(矩形的一个边在三角形的边上)，并以该矩形制作一铁皮圆柱的侧面。

2020届高三第二学期英语模拟卷(含答案)

2020届高三第二学期英语模拟试卷第一部分听力(满分30)1.What is the cause of the woman’s quietness?A. The violent film.B. Her tiredness.C. The crowded theater.2.How does the man know about animals?A. From books.B. On TVC. Through the Internet.3.What does the man ask the woman to do?A. Give her ID card to him.B. Move a table.C. Sign for a parcel.4.Why doesn’t the man want to eat?A.He’s feeling a little sick.B.He doesn’t like the food.C. He ate something just now.5.What are the speakers mainly talking about?A. A picnic.B. The weather.C. A forecast.听第 6 段材料，回答第6、7 题。

6.Why doesn’t the man want the telephone sales job?A.It needs working long hours.B.It is not suitable for him.C.It doesn’t pay well.7.What does the man think of the job on the ship?A. Attractive.B. Boring.C. Tiring.听第7 段材料，回答第8、9 题。

8.What does the woman advise the man to focus on?A. The price.B. The quality.C. The model.9.What will the speakers do next?A. Continue to shop.B. Visit a gym.C. Go to the cashier.听第8 段材料，回答第10 至12 题。

2020届高三二模英语试题(含答案)

高三英语试卷（2020.05）(满分140分，考试时间120分钟)I Listening ComprehensionSection ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A Supermarket. B. Tailors shop. C. Department store. D. Convenience store.2. A. 200 pound. B. 600 pounds. C. 300 pounds. D. 700 pounds.3. A. Call the ticket office later. B. Order the tickets onlineC. Not to buy the ticket on the Internet.D. Order the tickets when it's not busy.4.A. Borrowing money from a business company. B Lending some money to a student.C. Asking for some financial aid. D Reading students’ application.5. A. The bed is to blame for his not falling asleep. B. He can fall asleep if he stops drinking.C. He can drink more to fall asleep easily.D. Drinking is good for sleeping.6. A. He is satisfied with the content. B. He feels sorry for it.C. He thinks it is valueless.D. He thinks it is valuable.7. A Professor Smith spoke Greek when he explained the maths problem.B. The woman still didn’t understand the maths problem.C. Unfortunately, she didn’t hear Professor Smiths explanation.D. Professor Smith didn't explain the problem clearly.8. A. Collect papers for the man. B. Do the typing once again.C. Check the paper for typing errors.D. Read the whole newspaper.9.A. Proceed in his own way. B. Stick to the original plan.C. Negotiate with his colleague.D. Try to change his colleagues mind.10. A. His project proved to be unsuccessful. B. He was unable to get sufficient money.C. Lack of land prevented his success.D. He was successful with his project.Section BDirections: In Section B, you will hear several longer conversation(s)and short passage(s), and you will be asked several questions on each of the conversation(s)and the passage(s). The conversation(s)and the passage (s) will beread twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one is the best answer to the question you have heard.Questions 11 through 13 are based on the following talk.11. A. To guide and help children's play. B. To give children an opportunity to play.C. To make children excited. D To keep children company.12. A. It determines the standard a child can reach.B. It is the happiest period during one's life.C. It is the most important time to shape one’s character.D. It is the best time for children to learn new thing.13. A. The relationship between play and learning.B. The way to help children develop both physically and mentally.C. The importance of children’s play.D. Different stages of children’s development.Questions 14 through 16 are based on the following passage.14. A. It tends to wander towards unpleasant experiences.B. It wanders for almost half of their waking time.C. It has trouble concentrating after a brain injuryD. It tends to be affected by their negative feelings.15. A. To find how happiness relates to daydreaming.B. To observe how one’s mind affects one’s behavior.C. To see why daydreaming impacts what one is doing.D. To study the relation between health and daydreaming.16. A. Participants with clear goals in mind outperformed those without clear goals.B. The difference in performance between the two groups was insignificant.C. Non-daydreamers were more confused on their tasks than daydreamers.D. Daydreamers did better than non-daydreamers in task performance.Questions 17 through 20 are based on the following conversation.17. A. Their average lifespan was less than 50 years.B. It was very common for them to have 12 children.C. They retired from work much earlier than today.D. They were quite optimistic about their future.18. A. Get ready for ecological changes.B. Adapt to the new environment.C. Learn to use new technology.D. Explore ways to stay young.19. A. When all women go out to work.B. When family planning is enforced.C. When a world government is set up.D. When all people become wealthier.20. A. Eliminate poverty and injustice.B. Migrate to other planets.C. Control the environment.D. Find inexhaustible resources.Ⅱ. Grammar and VocabularySection ADirections: After reading the passage below, fill in the blanks to make the passage coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word: for the other blanks. use one word that best fits each blank.Plants Scream in the Face of StressFor the first time, researchers appear to have evidence that like animals, those plants deprived of water or (21)__________(force)to endure bodily harm can let out their pain. The study. (22)_________ has yet to be published in a scientific Journal, adds another dimension to scientists(23)________ (grow)understanding of how plants detect and interact with their surroundings.In recent years, it has become very clear that plants are more sensitive than researchers (24)_________ (think). They respond when touched by insects and turn toward sources of light. “Plants are not just robotic stimulus-response devices,” said Frantisek Baluska of the University of Bonn in Germany. “They’re living organisms which have their own problems.”Actually making their suffering hearable, however, is another matter entirely.(25)________(test) that possibility, a team led by Itzhak Khait, a plant scientist at Tel Aviv University in Israel, placed microphones capable of detecting ultrasonic frequencies(超声波频率) four inches from tomato and tobacco plants. The researcher then either stopped watering them or cut their stems.Measuring in the range of 20 to 150 kilohertz (千赫) the researchers found that even happy healthy plants madethe occasional noise. But when cut, tobacco plants emitted (26)_________average of 15 sounds within an hour of being cut, (27)_________tomato plants produced 25 sounds.(28)_______researchers aren’t yet sure how plants produce these sounds, Khait and his colleagues proposed one possibility in their paper (29)____________as water travels through the plants' tubes, air bubbles will form and explode, producing small vibrations.All this “screaming” caused by stress wasn’t in a range detectable by human ears. But organisms that can hear ultrasonic frequencies like mice, bats or perhaps other plants (30)________possibly hear the plants cries from as far away as 15 feet.Section BDirections: Fill in each blank with a proper word chosen from the box. Each word can be used only once. Note that there is one word more than you need.Italians find “Moments of Joy in this Moment of Anxiety”It started with the national anthem. Then came the piano chords, trumpet blasts, violin serenades(小夜曲) and even the clanging of pots and pans--all of it (31)_________from people’s homes, out of windows and from balconies, and resounding across rooftops.Finally, on Saturday afternoon, a nationwide (32)__________of applause broke out for the doctors on the medical front lines fighting the spread of Europe’s worst coronavirus outbreak.Italians remain (33)_________under house arrest as the nation, the European front in the global fight against the coronavirus, has ordered extraordinary restrictions on their movement to prevent infection.But the music and noise erupting over the streets, from people (34)_________in their homes, reflects the spirit, resilience and humor of a nation facing its worst national emergency since the Second World War.To the extent that this is a virus that tries people' s souls, it has also demonstrated the (35)__________of those national characters.In China, patriotic truck drivers risked infection to bring(36)_________needed food to the people of Wuhan, the epicenter of the outbreak. In Iran, videos show doctors in full combat dress and masks dancing to keep (37)_______up. And in Italy, the gestures of gratitude and music ring out above the country’s empty streets, while social media feeds fill with (38)___________, sentimental and humorous web videos.Images of nurses collapsed from exhaustion or their faces bruised(使受瘀伤) from tightly(39)________maskshave also spread across the web in recent days. Parents posted pictures of unicorns and rainbows drawn by young children with the title “It will all be OK.”“We’re Italians, and loving singing is part of our culture,” said Giorgio Albertini, 51, an archaeology professor who clapped from his apartment balcony in the university district of Milan, calling it a way “to feel a community, and to have the (40)_________grief.”Ⅲ Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Making choices is hard. That would be why researcher Moran Cerf has (41)_________it from his life. As a rule, he always chooses the second menu item at a restaurant.This is (42)___________by his research in neuroeconomics(神经经济学)( a somewhat new, divisive field) at Northwestern University. As Business Insider describes, Cerf has extended his ideas which draw on some controversial ideas in psychology, including ego depletion out into a piece of advice that, to (43)_________happiness, people should "build a life that requires (44)________decisions by surrounding themselves with people who possess traits they prefer.On an instinctive level, Cerf’s idea (45)_____________: Many choices people make are the product of social pressures and the inputs of (46)___________people around them. One example Cerf furnishes is that, (47)________consistently ordering the second menu item. he never picks where to eat. Rather, he (48)________his decision to his dining partner which friend he plans to eat with, probably one he trusts and always lets them pick.While it's (49)__________what, if any, scientific principles underlie those pieces of advice, there is no shortage of research showing that choices can sometimes feel more(50)_______than liberating. An example from Quanta poits (假设): If you have a clear love of Snickers(士力架), choosing that over an Almond Joy(杏仁巧克力) or a Milky Way(牛奶巧克力) should be a(51)________. And, as an experiment conducted by neuroscientist Paul Glimcher at NYU shows, most of the time it is, (52)_________you introduce more choices. When the participants were offered three candy bars (Snickers, Milky Way, and Almond Joy) they had no problem picking their favorite, but when they were given the option of one among 20, including Snickers, they would sometimes drift away from their (53)_____. When the choices were taken away in later trials. the participants would wonder what caused them to make such a bad decision.As Quanta details, according to a model called" 'divisive normalization(分裂归一化), which has gained some popularity, the way the brain encodes choices has a lot to do with how it values all its options. So, if you have twothings that are clearly (54)___________, brain areas involved in decision-making fire in a pattern that makes the decision clear. When the choices are comparable. the brain does its best to focus on the distinctions between the two, but more choices (55)_________ that ability out.41. A. relieved B. released C. eliminated D. liberated42. A. influenced B. inherited C. implemented D. informed43. A. maximize B. balance C. cherish D. seek44. A safer B. fewer C. better D. sounder45. A. stands out B comes into force C makes sense D. play a part46. A. distinguished B. trusted C. authorized D. honored47. A. in addition to B. instead of C. in spite of D. regardless of48. A. conveys B. relates C. submits D. limitsA. evidentB. unclearC. criticalD. inevitable50. A. confusing B. Inspiring C. worrying D. appealing51. A. stressor B. no-brainer C. challenge D. headache52. A. after B. before C. when D. until53. A. preference B. struggle C. status D. directionA. impressiveB. insignificantC. uniqueD. distinct55. A. crowd B. figure C. sort D. putSection BDirections: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A. B. C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)One spring day, once the flowers have begun to open, a bee will hover (盘旋)and zip through your yard and dive-bomb your picnic table. While you're thinking about avoiding an attack, that bee is focused on something else entirely: me.A honeybee has about six weeks to live. Today, like most days, her task is to fly as many as three miles from home. stick her long. straw like tongue into a hundred or so flowers. When the bee has had her fill. she’ll fly home. There the bee will deposit what she has got into the mouth of one of her co-workers, who will relay it to another, and so on for about 20 minutes, until the mixture is ready to be placed into the comb. Then she and her 50.000 or so mates will hover in the dark all night every night, flapping their wings to create hot, breezy conditions to remove the waterfrom the mixture. Several sunrises later, they will seal me off in a golden cell of beeswax. In her lifetime, our bee may visit 4,000 flowers, and yet will produce only one-twelfth a tea spoon of me.The average American consumes nearly a pound and a half of me every year, in tea, on toast, and beyond. If I do say so myself, I am a timeless treasure. Literally I never go bad.Unfortunately, my good health is not guaranteed. The problem lies in the growth of industrial agriculture and the use of pest control chemicals, as well as changes in weather patterns, all of which reduce the number of flowers bees have to visit. I’d appreciate your letting your own garden grow just a little wild. My future depends on all of us fostering spring and summers wild flowers, thus helping the bees, who give so much to you, to me without ever asking for anything in return.56. What does “me” refer to in the passage?A. The flower.B. The bee.C. Water. D Honey.57. What is the 2nd paragraph mainly about?A. Bees’ special talent.B. Bees’ hard work.C. Bees’ living environment.D. Bees’ social behavior.58. Which one of the following is true according to the passage?A. A bee will always prioritize attacking picnic lovers.B. Before “me” is sealed off in beeswax, the drying process can take a few nights.C. The lifework of a bee satisfies the average demand of an American consumer annually.D. Bees are more likely to visit those deliberately pest-controlled gardens59. What is the purpose of the passage?A. To appeal for help for honeybees.B. To talk about the history of a treasure.C. To put forward techniques for gardeners.D. To argue against the control of chemicals.(B)Get Your Unlimited Card at Cineworld CinemasEnjoy Unlimited FilmsWatch all the films you want at any Cineworld for just one monthly price.Being an Unlimited card holder gives you access to all the 2D films you canhandle for one monthly price. Watch what you want, when you want as manytimes as you want. Plus, save money when watching films in 3D and others.After you've been with us for more than I year we'll upgrade you to a Premium Card and you' ll get into 3D films completely free too! Start enjoying today by using a temporary pass while you wait for your card to arrive in the post.Save On Snacks And DrinksGet 10% off all in-cinema food and drink. Plus get 10% off atCineworld Starbucks licensed stores. First year card holders get 10%o off,whilst Premium card holders get 25% off Cineworld's in-cinema food anddrinks including, all drinks, popcorn, nachos, hotdogs, ice cream, pick nmix and much more. Plus all card holders get 10% discounts at Cineworld Starbucks licensed stores. All you need to do is show your card at the counter and your discount will be applied.Recommend A FriendUnlimited members can get free months of membership when theyrecommend Unlimited to their friends!Recommend Unlimited to your friends and well give you free monthsof membership to say thank you. For every friend that signs up using yourunique Recommend a Friend code you will both receive one month’s free membership once they have been an active Unlimited member for 90 days. The free month will be automatically added to the end of your current subscription. You can earn a maximum of 12 Free Months with your Recommend a Friend code, so recommend Unlimited to 12 friends and you could get a full year of free Unlimited cinema!60. The cinema names its membership card “Unlimited” because__________.A. one can have the benefits for good upon joining the membership.B. Cineworld members can enjoy as many 2D and 3D films as they like for free.C. it frees a member from any regular payment to the movie tickets at Cineworld.D. card holders can share limitless discounts and offers with friends and relatives.61. Which of the statement is TRUE according to the passage?A. The benefits above are not available until the card is delivered.B. Premium card holders can have 25%o off at a licensed Starbucks.C. Whoever persuades 6 friends into Unlimited can enjoy a half year of free membership.D. A second year of investment is worthwhile if you are a cinema goer.62. This passage is probably written to____________.A. secure the loyalty of potential customers.B. introduce the latest movies and discounts.C promote the popularity of Cineworld cinemas.D. give away movie cards to readers for free.(C)A rare hole has opened up in the ozone layer above the Arctic, in what scientists say is the result of unusually low temperatures in the atmosphere above the north pole.The hole, which has been tracked from space and the ground over the past few days, has reached record dimensions, but is not expected to pose any danger to humans unless it moves further south. If it extends further south overpopulated areas, such as southern Greenland, people would be at increased risk of sunburn. However, on current trends the hole is expected to disappear altogether in a few weeks.Low temperatures in the northern polar regions led to an unusual stable polar vortex(极地漩涡) and the presence of ozone-destroying chemicals such as chlorine(氯)in the atmosphere-from human activities caused the hole to form.“The hole is principally a geophysical curiosity.” said Vincent-Henri Peuch, director of the Copernicus Atmosphere Monitoring Service. “We monitored unusual dynamic(动态的)conditions, which drive the process of chemical depletion of ozone. Those dynamics allowed for lower temperatures and a more stable vortex than usual over the Arctic, which then triggered the formation of polar stratospheric(平流层的)clouds and the catalytic(催化的) destruction of ozone.”The hole is not related to the Covid-19 shutdowns that have dramatically cut air pollution and reduced greenhouse gas emissions. It is also too early to say whether the unusually stable Arctic polar vortex conditions are linked with the climate crisis, or part of normal stratospheric weather variability.Peuch said there were no direct implications for the climate crisis. Temperatures in the region are already increasing, slowing the depletion of ozone, and the hole will start to recover as polar air mixes with ozone rich air from lower latitudes. The last time similar conditions were observed was in spring 2011.While a hole over the Arctic is a rare event, the much larger hole in the ozone layer over the Antarctic has been a major cause for concern for more than four decades. The production of ozone depleting chemicals has been dramatically reduced, under the1987 Montreal Protocol(蒙特利尔协议), but some sources appear still to be functioning in 2018unauthorized emissions were detected from some areas.New sources of ozone depleting chemicals were not a factor in the hole observed in the Arctic, said Peuch. “However, this is a reminder that one should not take the Montreal Protocol measures for granted and that observations from the ground and from satellites are central to avoid a situation where the ozone destroying chemical level in the stratosphere could increase again.”63. What is the possible meaning of the underlined word “depletion”?A. replacement.B. consumption.C. increase.D. production.64. According to the passage, scientists are concerned about the hole because____________.A. it is expected to be a threat to the mankind.B. the new hole is caused by air pollution and greenhouse gas emissions.C. it may encourage further scientific research and environmental awareness.D. it wars us of an oncoming climate crisis.65. What can be learned from the last two paragraphs?A. The hole over the Arctic shares the same causes as the one over the Antarctic.B. Human activities are highly responsible for producing ozone-destroying chemicals.C. The Montreal Protocol has successfully prevented new emissions.D. Some new illegal emissions are to blame for the hole over the Arctic.66. The best title for the passage is probably_________.A. Record-size Hole Opens in Ozone Layer above the Arctic.B Actions Urgently Needed for a New Hole in Ozone Layer.C Environmental Disaster and International Cooperation.D. How a Hole in Ozone Affects our Life on Earth.Section CDirections: Read the following passage. Fill in each blank with a proper sentence given in the box. Each sentence can be used only once. Note that there are two more sentences than you need.People like to post their selfies(自拍照)on social media. To know more about it, scientists at Syracuse University in New York recently did a research and came up with some surprising findings.People who post selfies and use editing software to make themselves look better show behaviors connected to narcissism, the researchers said. (67)_________Makana Chock, a professor from Syracuse University. said because social media is mostly used by people to share unimportant information about their lives, it is a good place for people to “work towards satisfying their own vanity.” Those “likes” under their Facebook selfies make them feel good.(68)_________Some people feel “peer pressure” to post selfies and some follow the popular belief that if there is no picture of an event or experience. it did not really happen. “Anyway, it shouldn’t be seen as negative. People get sense of satisfaction especially when they get likes. And it does no harm,” Chock said.Other findings from the study include: There are no major differences on how often men and women post selfies and how often they use editing software. (69)_______Chock said posting selfies on social media is not all that different from what people have done for many years. On trips and special events, our parents and grandparents used cameras instead of phones to take photos. They would bring back photos to show friends and family. You had no choice but to look at them. You probably commented about how nice everyone in the photos looked, especially children and the person showing the photos. They were happy to hear your comments. (70)__________On social media, however, people can decide not to look at photos even if they click “like”.TV. Summary WritingDirections: Read the following passage, Summarize the main idea and the main point(s)of the passage in no more than 60 words. Use your own words as far as possible.It's natural to feel the need to control something when everything around you feels out of control, and you feel helpless. When a friend of mine first heard about the coronavirus outbreak. she got down on her hand. and knees and cleaned her kitchen floor. She told me, “My floor wasn’t even dirty, but doing something constructive made me feel in control and that I was holding on to my power, despite the desperate circumstances.”Your most powerful weapon against uncertainty is your perspective because nobody and no situation can take that from you unless you give it away. Your perspective can victimize or empower you. When you look for the upside in a downside situation and figure out what you can control and what you can't, it's easier to accept whatever is beyond your control.高三英语调研测试（试卷参考答案）I Listening ComprehensionSection A1-5 BDBCB6-10 CBCCDSection B11-13 AAC14-16 BAD17-20 ACDCII. Grammar and V ocabularySection A21. forced22 which23. growing 24. thought25. To test27. while28. Although/While/Thou29. that30 could/canSection B31-40 IBACG FDEKJIII Reading ComprehensionSection A41-55 CDABC BADBA BDADASection B56-59 DBBA60-62CDA63-66 BCBASection C67-70 CBFDTV. Summary WritingFor reference:Strengthening or retrieving a sense of control is a natural demand. First, good perspective is of the greatest help, for evaluating the situation properly brings a clearer picture. Second, kind behaviors during tough times can secure you a sense of control as well. Third, actions and thoughts of positivity also help as they may create hope and optimism.It's essential to feel you can control something in a crisis or emergency. Positive perspective is the most important, since it will ensure you confidence and power to pull through the difficult situation. Then doing small good deeds can free you from worry temporarily by helping others. Lastly. take some positive action to arouse the hope within you.V. Translation72. Never before have we been so eager/keen to go to school as we are now.73. Why not do something you love but don’t have time to do since you can only stay at home?74. In Europe many coffee houses which serve as ideal places for social interaction have to close their stores to respond to the public health crisis.75. It turns out that when our country is facing difficulties, every Chinese, whether at home or abroad is willing to make contributions to their motherland.。

2020届高三绵阳二诊物理试题(含解析)

2020届高三绵阳二诊物理试题二、选择题：本题共8小题，每小题6分，共48分。

在每小题给出的四个选项中，第14~18题只有一项符合题目要求，第19~21题有多项符合题目要求。

全部选对的得6分，选对但不全的得3分，有选错的得0分。

1.关于安培力和洛伦兹力，下列说法正确的是（）A. 运动电荷在磁场中一定受到洛伦兹力作用B. 通电导线在磁场中一定受到安培力作用C. 洛伦兹力一定对运动电荷不做功D. 安培力一定对通电导线不做功【答案】C【详解】A．运动电荷在磁场中运动，若速度方向与磁场方向平行，则不受洛伦兹力作用，选项A错误；B．通电导线在磁场中，若电流方向与磁场方向平行，则不受安培力作用，选项B错误；C．由于洛伦兹力方向垂直于运动电荷的速度方向，根据功的定义可知，洛伦兹力对运动电荷不做功，选项C正确；D．安培力方向与通电导线垂直，可以对通电导线做功，从而把电能转化为机械能，选项D错误。

故选C。

v沿斜面向上运动，又返回底端。

能够描述物块速度v随时间t变2.一物块在固定的粗糙斜面底端以初速度化关系的图像是（）A. B.C. D.【答案】C详解】根据牛顿第二定律：上滑过程：mgsinθ+μmgcosθ=ma1，下滑过程：mgsinθ-μmgcosθ=ma2，比较可知：a1＞a2，则物块上滑过程v-t图象的斜率比下滑过程的大。

由速度-时间公式得：上滑过程有v0=a1t0，下滑过程有v0=a2t1，可得：t1＞t0，故C正确，ABD错误。

故选C。

3.质量为m 的篮球从某一高处从静止下落，经过时间1t 与地面接触，经过时间2t 弹离地面，经过时间3t 达到最高点。

重力加速度为g ，忽略空气阻力。

地面对篮球作用力冲量大小为（） A. 123++mgt mgt mgt B. 123+-mgt mgt mgt C. 123-+mgt mgt mgt D. 123--mgt mgt mgt 【答案】A【详解】选向下为正，运动全程由动量定理得：mg （t 1+t 2+t 3）+I 地=0，则有：I 地=-（mgt l +mgt 2十mgt 3），负号表方向。

2024届江苏省高三二模语文语言文字运用题汇编含答案

2024届江苏省高三二模语文语言文字运用题汇编（一）语言文字运用I（本题共3小题，10分）阅读下面的文字，完成18～20题。

木星恐怖地上升着，渐渐占据了半个天空。

这时，我们可以清楚地看到它云层中的风暴，那风暴把云层搅动成 A 的线条。

我知道，那厚厚的云层下是沸腾的液氢和液氦的大洋。

著名的大红斑出现了，这个在木星表面维持了几十万年的大旋涡大得可以吞下整整三个地球。

这时木星已占满了整个天空，地球仿佛是浮在木星沸腾的暗红色云海上的一只气球！而木星的大红斑就处在天空正中，如一只红色的巨眼盯着我们的世界，大地笼罩在它那阴森的红光中……小小的地球能逃出这巨大怪物的引力场，真是令人_ B __。

从地面上看，地球甚至连成为木星的卫星都不可能。

我们似乎就要掉进那无边云海覆盖着的地狱中去了！但领航工程师的计算是精确的。

暗红色的迷乱的天空继续缓缓移动，不知过了多长时间，西方的天边露出了黑色的一角，那黑色迅速扩大，其中有星星在闪烁——地球正在冲出木星的引力魔掌。

我们的星球在木星表面拉起了如山的液氢和液氦的巨浪。

木星巨大的引力把地球加速甩向外太空。

离开木星时，地球已达到了逃逸速度，它不再需要返回潜藏着死亡的太阳系，而是向 C 的外太空飞去。

漫长的流浪时代开始了。

18.请在文中横线处填入恰当的成语。

（3分）19.下列句子中的“似乎”和文段中加点的“似乎”，表意相同的一项是（3分）A.实验进行到一半，他们似乎就要找到突破点了，可惜结局并不令人如意。

B.他看到前方四五十米处似乎躺着一个人，便跑回车里，告诉班长。

C.他望了我一眼，轻声地说：“时间不早了，我们似乎该启程了。

”D.这一双眼睛似乎是娇嫩的矢车菊的蓝色，眼神柔和而又温暖。

20.画波浪线句子中作者将地球比作“气球”，将木星的大红斑比作“巨眼”，请分析其语意效果。

（4分）18.A.乱七八糟B.不可置信/难以置信C.无边无际/广阔无垠（评分建议：一空一分，如有其它成语，言之成理即可。

【市级联考】江苏省扬州市2024届高三第一次模拟考试物理试题

【市级联考】江苏省扬州市2024届高三第一次模拟考试物理试题一、单项选择题（本题包含8小题，每小题4分，共32分。

在每小题给出的四个选项中，只有一项是符合题目要求的）(共8题)第(1)题如图是一种电加热装置，当把一铁块放入线圈中且不接触线圈，稍等片刻，铁块就会烧得通红，小明同学由此做出了以下一些猜想，其中正确的是（）A ．若把一干燥的木棍伸入线圈中，木棍会被烧着B ．线圈内部一定通有随时间变化的电流C ．线圈内部一定通有强度很大的恒定直流D ．铁块是否会变红与线圈中电流是否变化无关第(2)题如图所示，一束平行于等边三棱镜截面ABC 的单色光从空气射向点，在三棱镜内偏折到点。

已知入射方向与AB 的夹角为，、分别为AB 、AC 边的中点，则光第一次到达点后的传播大致是下图中的（）A ．B ．C ．D ．第(3)题用同一束单色光，在同一条件下先后照射锌板和银板，都能产生光电效应。

已知锌的极限频率为8.1×1014Hz ，银的极限频率为1.2×1015 Hz 。

关于以上两次实验，下列说法正确的是（）A ．入射单色光的频率可能为9.0×1014HzB ．锌板产生的光电子的初动能一定较大C ．银板产生的光电子的逸出功一定较小D ．锌板产生的光电子的动量可能较小第(4)题两条通电的直导线互相垂直，如图所示，但两导线相隔一小段距离，其中导线AB 是固定的，另一条导线CD 能自由转动或平动。

它们通以图示方向的直流电流时，CD 导线将（）A ．逆时针方向转动，同时靠近导线ABB ．顺时针方向转动，同时靠近导线ABC ．逆时针方向转动，同时离开导线ABD ．顺时针方向转动，同时离开导线AB第(5)题太赫兹辐射通常指频率在0.1-10THz （1THz=1012Hz ），太赫兹波对人体无危害，多用于国家安全、信息技术领域，被誉为“改变未来世界十大技术”之一、通过和电磁波谱对比，下列关于太赫兹波说法正确的是（）A．太赫兹波光子能量比红外线光子能量更大B．太赫兹波比紫外线更难使金属发生光电效应C．太赫兹波比微波更容易发生衍射D．太赫兹波比X射线穿透能力更强第(6)题2019年12月17日，我国第一艘国产航空母舰“山东舰”正式交付海军，“山东舰”发动机最大输出功率为P，最大航行速度为，其航行时所受的阻力随速度增大而增大，某次直线航行过程中，下列说法中正确的是（）A．若“山东舰”匀加速启动，则在匀加速阶段，发动机提供的牵引力大小恒定B．若“山东舰”以恒定功率P启动，经时间t后速度达，则有C．若“山东舰”以匀速航行时，发动机输出功率为D．若“山东舰”以匀速航行时，发动机输出功率小于第(7)题物理学中有很多关于圆盘的实验，第一个是法拉第圆盘，圆盘全部处于磁场区域，可绕中心轴转动，通过导线将圆盘圆心和边缘与外面电阻相连。

2020届湖南省衡阳市普通高中高三毕业班下学期第二次联考(二模)理综物理试题及答案

绝密★启用前湖南省衡阳市普通高中2020届高三毕业班下学期第二次联考(二模)理综-物理试题注意事项：1.本试卷分第I卷(选择题)和第II卷(非选择题)两部分。

答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答第I卷时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其它答案标号。

写在本试卷上无效。

3.回答第II卷时，将答案写在答题卡上。

写在本试卷上无效。

4.考试结束后,将本试题卷和答题卡一并交回。

第I卷二、选择题：本题共8小题,每小题6分。

共48分。

在每小题给出的四个选项中,第14～18题只有一项符合题目要求；第19～21题有多项符合题目要求,全部选对的得6分,选对但不全的得3分,有选错的得0分。

14.用如图甲所示的电路研究光电效应中光电流与照射光的强弱、频率等物理量的关系。

图中A、K两极间的电压大小可调,电源的正负极也可以对调,分别用a、b、c三束单色光照射,调节A、K间的电压U,得到光电流I与电压U的关系如图乙所示,由图可知A.由欧姆定律可知,甲图中电压表的示数为零时,电流表的示数也为零B.由能量守恒定律可知,光电子的最大初动能等于入射光子的能量C.单色光a和c的频率相同,a光强度比c光的大,b光的频率最大D.若用a、b、c三束单色光分别照射某种金属,若b光能使该金属发生光电效应,则a 光也一定能使该金属发生光电效应15.2019年“山东舰”正式服役,标志着我国进入双航母时代,如图,“山东舰”正在沿直线航行,其质量为m,发动机的输出功率恒为P,所受阻力大小恒为f,某时刻速度为v 1、加速度为a 1,一段时间t 后速度变为v 2(v 2>v 1),在这段时间内位移为x 。

下列关系式正确的是A.x ＝212v v +B.11v P f a m m =-C.1P f v >D.22211122Pt mv mv =- 16.为了阻止宇宙中的小行星撞击地球,科学家们提出在大气层外的地球同步轨道上放一个质量为m 的超级核弹,当外来小行星飞近地球时将其摧毁,以减少小行星对地球造成的伤害.已知地球半径为R,自转周期为T,万有引力常量为C,地球同步轨道离地面高度为h 。

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1 / 15 江苏省扬州市2020届高三模拟考试试卷物理本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分．满分120分，考试时间100分钟．第Ⅰ卷(选择题共31分) 一、单项选择题：本题共5小题，每小题3分，共15分．每小题只有一个选项符合题意． 1. 某水电站输电给远处的用户，其输电功率为P，输电电压为U，输电电流为I，输电线总电阻为r，则下列表达式正确的是 ( ) A. U＝Ir B. P＝UI C. P＝I2r D. P＝U2r 2. 在如图所示的装置中，A、B两物块的质量分别为4 kg、1 kg，不计弹簧和细绳质量以及一切摩擦，重力加速度g＝10 m/s2，先固定物块A使系统处于静止状态．释放A的瞬间，下列说法正确的是( ) A. 弹簧的弹力大小为30 N B. 弹簧的弹力大小为40 N C. A的加速度大小为10 m/s2 D. B的加速度大小为0 3. 如图所示，两墙壁平行竖直，小球从P点以垂直于墙面的初速度v0抛出，打在右侧墙壁上的Q点．已知小球与墙壁碰撞前后竖直分速度不变，水平分速度大小不变、方向相反，不计空气阻力．若只改变初速度大小，小球仍能击中Q点，则初速度大小可能为( ) A. v02 B. 2v0 C. 3v0 D. 4v0 4. 如图所示，木板上右端放一小物块，木板可以绕转轴在竖直面内转动，现让木板以恒定角速度从图示位置转到水平位置，在此过程中，物块相对木板静止，则物块所受支持力的瞬时功率( ) A. 逐渐增大 B. 保持不变 C. 先增大，后减小 D. 先减小，后增大 2 / 15

5. 如图所示，水平面内有一平行金属导轨，导轨光滑且电阻不计．电源电动势为E，匀强磁场与导轨平面垂直．阻值为R的导体棒垂直于导轨静止放置，且与导轨接触良好．t＝0时刻，闭合开关S，棒的速度v随时间t变化的图象可能正确的是( )

二、多项选择题：本题共4小题，每小题4分，共16分．每小题有多个选项符合题意，全部选对的得4分，选对但不全的得2分，错选或不答的得0分． 6. 2019年12月31日晚，我国重量最重、技术含量最高的高轨卫星“实践20号”成功实施了第四次变轨．如图所示，实线1、虚线2分别是卫星变轨前后的轨道，则卫星( ) A. 在轨道1的A点处应点火加速 B. 在轨道1的A点处的速度比在轨道1的B点处小 C. 在轨道1的A点处的加速度比在轨道2的A点处小 D. 在轨道1的运行周期比在轨道2的运行周期大 7. 在真空中某点电荷的电场中，将等量异种的检验电荷分别置于M、N 两点，两检验电荷所受电场力方向如图所示，且F2＞F1(不计检验电荷间相互作用)，已知M点处检验电荷带负电，下列说法正确的是( ) A. 场源点电荷带负电 B. M点电场强度大于N点电场强度 3 / 15

C. M点电势高于N点电势 D. 若将M点处检验电荷沿 MN 连线从M点移到N点，其电势能一定先增大后减小 8. 在如图所示的电路中，R1为定值电阻，R2为热敏电阻(温度升高，电阻减小)，电源的电动势为E，内阻为r.闭合开关，当环境温度升高时，下列说法正确的是( ) A. 电压表示数增大 B. 电流表示数减小 C. 有电流向下流过A点 D. 电压表和电流表示数变化量之比ΔUΔI保持不变 9. 如图甲所示，光滑斜面上有固定挡板A，斜面上叠放着小物块B和薄木板C，木板下端位于挡板A处，整体处于静止状态．木板C受到逐渐增大的沿斜面向上的拉力F作用时，木板C的加速度a与拉力F的关系图象如图乙所示．

已知最大静摩擦力等于滑动摩擦力，重力加速度为g＝10 m/s2，则由图象可知( ) A. 10 NB. F＞15 N时物块B和木板C相对滑动 C. 木板C的质量 D. 木板和物块两者间的动摩擦因数 4 / 15

第Ⅱ卷(非选择题共89分) 三、简答题：本题分必做题(第10、11、12题)和选做题(第13题)两部分，共42分．请将解答填写在相应的位置．【必做题】 10. (8分)某同学利用如图所示的实验装置验证机械能守恒定律．将气垫导轨固定在水平桌面上，调节旋钮使其水平．在气垫导轨的左端固定一光滑的定滑轮，在B处固定一光电门，测出滑块及遮光条的总质量为M，将质量为m的钩码通过细线与滑块连接．打开气源，滑块从A处由静止释放，宽度为d的遮光条经过光电门遮光时间为t，取遮光时间t内的平均速度作为滑块经过B处的速度，A、B之间的距离为x，钩码离地面足够高，重力加速度为g. (1) 关于实验操作和注意事项，下列说法正确的是________． A. 必须满足m远小于M B. 调整定滑轮高度，使细线水平 C. 用手向上托稳钩码，由静止开始释放钩码 D. 不开气源，平衡滑块与导轨之间的摩擦力后，也能验证系统机械能守恒

(2) 滑块由A运动到B的过程中，系统重力势能的减小量ΔEp为________，系统动能的增加量ΔEk为____________(以上结果均用题中所给字母表示). (3) 改变x重复实验得到多组数据，用图象法处理数据，为了形象直观，应该画________． 5 / 15

A. tx图象 B. t2x图象 C. 1t2x图象 11. (10分)某兴趣小组通过实验测量一个标准电池组的电动势和内阻，实验原理图如图甲所示，定值电阻R0的标称值为4.0 Ω.

(1) 闭合开关S，调节滑动变阻器R，发现电压表有读数，而电流表读数为0.用多用电表排查故障，在使用多用电表前，发现指针不在左边“0”刻度线处，应先调整图乙中多用电表的________(选填“A”“ B” 或“C”)． (2) 将红、黑表笔分别插入“＋”、“－”插孔，选直流电压10 V挡检测故障．在图甲中，将多用电表的________(选填“红”或 “黑”)表笔接入a端，另一表笔接入b端，发现指针偏转，说明 a、b间________(选填“短路”或 “断路”)． (3) 排除故障后，某次实验的数据如下表所示：测量次数 1 2 3 4 5 6 电压表读数U/V 5.26 5.16 5.04 4.94 4.83 4.71 电流表读数I/mA 20 40 60 80 100 120 根据表中的数据，在如图丙所示的方格纸上作出了UI图象，由图象求得电动势E＝________V，内阻r＝________Ω.(结果保留三位有效数字) 6 / 15

(4) 将测量结果与标准电池组说明书中给出的参数比较发现：电动势的测量值与已知值几乎相同，但内阻的测量值偏大．若测量过程无误，则内阻测量值偏大的原因可能是________． A. 电压表内阻的影响 B. 电流表内阻的影响 C. 滑动变阻器R的最大值偏小 D. R0的标称值比实际阻值偏小 12. [选修3－5](12分) (1) 下列现象中，与原子核内部变化有关的是________． A. α粒子散射现象 B. 天然放射现象 C. 光电效应现象 D. 原子发光现象 (2) 为了做好疫情防控工作，小区物业利用红外测温仪对出入人员进行体温检测．红外测温仪的原理是：被测物体辐射的光线只有红外线可被捕捉，并转变成电信号．如图所示为氢原子能级示意图，已知红外线单个光子能量的最大值为1.62 eV.若有一群处于n＝4激发态的氢原子最多能辐射________种频率的光子，其中可被红外测温仪捕捉到的有________种． (3) 如图所示，在足够长的光滑水平面上，用质量分别为2 kg和1 kg的甲、乙两滑块，将轻弹簧压紧后处于静止状态，轻弹簧仅与甲拴接，乙的右侧有一挡板P.现将两滑块由静止释放，当弹簧恢复原长时，甲的速度大小为2 m/s，此时乙尚未与P相撞． ①求弹簧恢复原长时乙的速度大小； ②若乙与挡板P碰撞反弹后不能再与弹簧发生碰撞，求挡板P对乙的冲量的最大值． 7 / 15

【选做题】 13. 本题包括A、B两小题，请选定其中一题作答．若都作答则按A小题评分． A. [选修33](12分) (1) 关于内能，下列说法正确的是________． A. 物体的内能包括物体运动的动能 B. 0 ℃的水结冰过程中温度不变，内能减小

C. 提起重物，因为提力做正功，所以物体内能增大 D. 摩擦冰块使其融化是采用热传递的方式改变物体的内能 8 / 15

(2) 一定质量的理想气体由状态A经状态B变化到状态C的pV图象如图所示．气体分子在单位时间内撞击容器壁上单位面积的次数用N表示，则NA________NB.气体在A→B过程中放出的热量________在B→C过程中吸收的热量．(均选填“大于”“小于”或“等于”). (3) 题(2)中，已知气体在状态C时的温度为27 ℃，阿伏加德罗常数为6.0×1023 mol－1，在标准状态(压强p0＝1.0×105 Pa、温度t0＝0 ℃)下理想气体的摩尔体积都为22.4 L，求该气体的分子数．(结果保留一位有效数字)

B. [选修34](12分) (1) 下列说法正确的是________． A. 医学上检查人体内部器官的“CT”，使用的是γ射线 B. 雨后公路积水表面漂浮的油膜阳光下呈现彩色，这是光的折射现象 C. 利用多普勒效应原理，可以测量运动物体的速度 D. 考虑相对论效应，静止的人测量沿自身长度方向高速运动的杆比静止时的杆长

(2) 如图所示，一直线上有振动情况完全相同的波源S1、S2，已知振动频率为5 Hz，波速为10 m/s，则该波的波长为________m．若S1、S2间距离为2 m，S1、A、B、C、S2间等间距，A、B、C三点中振动加强的点是________． (3) 半圆环形透明薄件截面如图所示，内径为r，材料折射率n＝2，点光源放在P点，射向A点