材料专业英语课后习题答案
材料科学与工程专业英语第三版翻译以及答案
UNIT 1一、材料根深蒂固于我们生活的程度可能远远的超过了我们的想象，交通、装修、制衣、通信、娱乐（recreation）和食品生产，事实上（virtually），我们生活中的方方面面或多或少受到了材料的影响。
历史上，社会的发展和进步和生产材料的能力以及操纵材料来实现他们的需求密切（intimately）相关，事实上，早期的文明就是通过材料发展的能力来命名的（石器时代、青铜时代、铁器时代）。
二、早期的人类仅仅使用（access）了非常有限数量的材料，比如自然的石头、木头、粘土（clay）、兽皮等等。
随着时间的发展，通过使用技术来生产获得的材料比自然的材料具有更加优秀的性能。
这些性材料包括了陶瓷（pottery）以及各种各样的金属，而且他们还发现通过添加其他物质和改变加热温度可以改变材料的性能。
此时，材料的应用（utilization）完全就是一个选择的过程，也就是说，在一系列有限的材料中，根据材料的优点来选择最合适的材料，直到最近的时间内，科学家才理解了材料的基本结构以及它们的性能的关系。
在过去的100年间对这些知识的获得，使对材料性质的研究变得非常时髦起来。
因此，为了满足我们现代而且复杂的社会，成千上万具有不同性质的材料被研发出来，包括了金属、塑料、玻璃和纤维。
三、由于很多新的技术的发展，使我们获得了合适的材料并且使得我们的存在变得更为舒适。
对一种材料性质的理解的进步往往是技术的发展的先兆，例如：如果没有合适并且没有不昂贵的钢材，或者没有其他可以替代（substitute）的东西，汽车就不可能被生产，在现代、复杂的（sophisticated）电子设备依赖于半导体（semiconducting）材料四、有时，将材料科学与工程划分为材料科学和材料工程这两个副学科（subdiscipline）是非常有用的，严格的来说，材料科学是研究材料的性能以及结构的关系，与此相反，材料工程则是基于材料结构和性能的关系，来设计和生产具有预定性能的材料，基于预期的性能。
专业英语课后习题参考答案
Unit 7 P56I、Translate the following words into Chinese1、Reinforced concrete钢筋混凝土2、Rolled-steel轧制钢3、Weldability可焊性4、Aggregate骨料5、Mortar砂浆6、Deformation变形II、Translate the following words into English1、冲击荷载shock loading2、软钢，低碳钢mild steel/low carbon steel3、冷拉hard drawn4、黏土砖clay brick5、收缩shrinkageIII、Translate the following sentence into Chinese1、The modern civil engineer needs to deal with a variety of materials that are oftenintegrated in the same structure , such as steel and concrete , or are used separatelyfor construction projects , such as pavement form asphalt and Portland cementconcrete.现代土木工程师需要处理大量建筑材料。
有时多种材料使用在同一结构中，如钢筋和混凝土；有时建筑材料被分别使用在单独的建筑项目中，例如沥青路面和硅酸盐水泥混凝土。
2、The useful engineering properties of both unalloyed and allyed aluminum are lowspecific gravity , resistance to corrosion , high electrical conductivity and excellentforming properties.铝和铝合金的有用的工程特性都是低比重，耐腐蚀，导电性能高和成型性能好。
苏州大学高分子材料专业英语课后习题(汇总)
高分子材料专业英语【P4.There has been long been a need for a definitivepublication on the engineering aspects of plastics processing.（塑料加工）长期以来，有着在塑料加工工程方面权威出版物的需求。
The society of Plastics Engineers is pleased to sponsor and endorse this new ,Plastics Process Engineering ,as the publication which serves this long-standing need.塑料工程师协会很高兴赞助和支持这个新的变化，以满足“塑料加工工程”作为出版物长期存在的需要。
2.Crystallization is only one aspect of orientation. Molecular orientation may not always result in crystallization but in enhancement of order when the various types of bonds such as hydrogen bonds and other weak interatomic forces can contribute to property enhancement.结晶只是取向的一个方面。
分子取向可能并不总是导致结晶，而是排列有序性的提高，同时，各种类型的化学键如氢键和其它弱原子间力有助于提高性能。
T wo important thermal transitions in a semi-crystalline polymer are the glass transition and melting. The temperatures of these transitions are donated by Tg ,which is characteristics of the amorphous phase, and Tm which is【P9】There are two basic types of polymerization:(1)addition, which occurs when active chains(活性链) and/or monomer units interact without a by-product（副产物(2)condensation ,which occurs when a Lewis polyacidand a Lewis polybase react to form a chain with the splitting out of a by-product molecule ,such as water or CO2.有两种基本的聚合反应类型：（1）加成聚合反应，活性连和单体单元之间相互反应，没有副产物产生（2）缩合聚合反应，路易斯聚酸和路易斯聚碱形成分子链。
《材料科学与工程基础》英文影印版习题及思考题及答案
《材料科学与⼯程基础》英⽂影印版习题及思考题及答案《材料科学与⼯程基础》英⽂习题及思考题及答案第⼆章习题和思考题Questions and Problems2.6 Allowed values for the quantum numbers ofelectrons are as follows:The relationships between n and the shell designationsare noted in Table 2.1.Relative tothe subshells,l ＝0 corresponds to an s subshelll ＝1 corresponds to a p subshelll ＝2 corresponds to a d subshelll ＝3 corresponds to an f subshellFor the K shell, the four quantum numbersfor each of the two electrons in the 1s state, inthe order of nlmlms , are 100(1/2 ) and 100(-1/2 ).Write the four quantum numbers for allof the electrons inthe L and M shells, and notewhich correspond to the s, p, and d subshells.2.7 Give the electron configurations for the followingions: Fe2+, Fe3+, Cu+, Ba2+,Br-, andS2-.2.17 (a) Briefly cite the main differences betweenionic, covalent, and metallicbonding.(b) State the Pauli exclusion principle.2.18 Offer an explanation as to why covalently bonded materials are generally lessdense than ionically or metallically bonded ones.2.19 Compute the percents ionic character of the interatomic bonds for the followingcompounds: TiO2 , ZnTe, CsCl, InSb, and MgCl2 .2.21 Using Table 2.2, determine the number of covalent bonds that are possible foratoms of the following elements: germanium, phosphorus, selenium, and chlorine.2.24 On the basis of the hydrogen bond, explain the anomalous behavior of waterwhen it freezes. That is, why is there volume expansion upon solidification?3.1 What is the difference between atomic structure and crystal structure?3.2 What is the difference between a crystal structure and a crystal system?3.4Show for the body-centered cubic crystal structure that the unit cell edge lengtha and the atomic radius R are related through a =4R/√3.3.6 Show that the atomic packing factor for BCC is 0.68. .3.27* Show that the minimum cation-to-anion radius ratio for a coordinationnumber of 6 is 0.414. Hint: Use the NaCl crystal structure (Figure 3.5), and assume that anions and cations are just touching along cube edges and across face diagonals.3.48 Draw an orthorhombic unit cell, and within that cell a [121] direction and a(210) plane.3.50 Here are unit cells for two hypothetical metals:(a)What are the indices for the directions indicated by the two vectors in sketch(a)?(b) What are the indices for the two planes drawn in sketch (b)?3.51* Within a cubic unit cell, sketch the following directions:.3.53 Determine the indices for the directions shown in the following cubic unit cell:3.57 Determine the Miller indices for the planesshown in the following unit cell:3.58Determine the Miller indices for the planes shown in the following unit cell:3.61* Sketch within a cubic unit cell the following planes:3.62 Sketch the atomic packing of (a) the (100)plane for the FCC crystal structure, and (b) the (111) plane for the BCC crystal structure (similar to Figures 3.24b and 3.25b).3.77 Explain why the properties of polycrystalline materials are most oftenisotropic.5.1 Calculate the fraction of atom sites that are vacant for lead at its meltingtemperature of 327_C. Assume an energy for vacancy formation of 0.55eV/atom.5.7 If cupric oxide (CuO) is exposed to reducing atmospheres at elevatedtemperatures, some of the Cu2_ ions will become Cu_.(a) Under these conditions, name one crystalline defect that you would expect toform in order to maintain charge neutrality.(b) How many Cu_ ions are required for the creation of each defect?5.8 Below, atomic radius, crystal structure, electronegativity, and the most commonvalence are tabulated, for several elements; for those that are nonmetals, only atomic radii are indicated.Which of these elements would you expect to form the following with copper:(a) A substitutional solid solution having complete solubility?(b) A substitutional solid solution of incomplete solubility?(c) An interstitial solid solution?5.9 For both FCC and BCC crystal structures, there are two different types ofinterstitial sites. In each case, one site is larger than the other, which site isnormally occupied by impurity atoms. For FCC, this larger one is located at the center of each edge of the unit cell; it is termed an octahedral interstitial site. On the other hand, with BCC the larger site type is found at 0, __, __ positions—that is, lying on _100_ faces, and situated midway between two unit cell edges on this face and one-quarter of the distance between the other two unit cell edges; it is termed a tetrahedral interstitial site. For both FCC and BCC crystalstructures, compute the radius r of an impurity atom that will just fit into one of these sites in terms of the atomic radius R of the host atom.5.10 (a) Suppose that Li2O is added as an impurity to CaO. If the Li_ substitutes forCa2_, what kind of vacancies would you expect to form? How many of thesevacancies are created for every Li_ added?(b) Suppose that CaCl2 is added as an impurity to CaO. If the Cl_ substitutes forO2_, what kind of vacancies would you expect to form? How many of thevacancies are created for every Cl_ added?5.28 Copper and platinum both have the FCC crystal structure and Cu forms asubstitutional solid solution for concentrations up to approximately 6 wt% Cu at room temperature. Compute the unit cell edge length for a 95 wt% Pt-5 wt% Cu alloy.5.29 Cite the relative Burgers vector–dislocation line orientations for edge, screw, andmixed dislocations.6.1 Briefly explain the difference between selfdiffusion and interdiffusion.6.3 (a) Compare interstitial and vacancy atomic mechanisms for diffusion.(b) Cite two reasons why interstitial diffusion is normally more rapid thanvacancy diffusion.6.4 Briefly explain the concept of steady state as it applies to diffusion.6.5 (a) Briefly explain the concept of a driving force.(b) What is the driving force for steadystate diffusion?6.6Compute the number of kilograms of hydrogen that pass per hour through a5-mm thick sheet of palladium having an area of 0.20 m2at 500℃. Assume a diffusion coefficient of 1.0×10- 8 m2/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.6.7 A sheet of steel 1.5 mm thick has nitrogen atmospheres on both sides at 1200℃and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 6×10-11m2/s, and the diffusion flux is found to be 1.2×10- 7kg/m2-s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4 kg/m3. How far into the sheet from this high-pressure side will the concentration be 2.0 kg/m3?Assume a linear concentration profile.6.24. Carbon is allowed to diffuse through a steel plate 15 mm thick. Theconcentrations of carbon at the two faces are 0.65 and 0.30 kg C/m3 Fe, whichare maintained constant. If the preexponential and activation energy are 6.2 _10_7 m2/s and 80,000 J/mol, respectively, compute the temperature at which the diffusion flux is 1.43 _ 10_9 kg/m2-s.6.25 The steady-state diffusion flux through a metal plate is 5.4_10_10 kg/m2-s at atemperature of 727_C (1000 K) and when the concentration gradient is _350kg/m4. Calculate the diffusion flux at 1027_C (1300 K) for the sameconcentration gradient and assuming an activation energy for diffusion of125,000 J/mol.10.2 What thermodynamic condition must be met for a state of equilibrium to exist? 10.4 What is the difference between the states of phase equilibrium and metastability?10.5 Cite the phases that are present and the phase compositions for the followingalloys:(a) 90 wt% Zn–10 wt% Cu at 400℃(b) 75 wt% Sn–25wt%Pb at 175℃(c) 55 wt% Ag–45 wt% Cu at 900℃(d) 30 wt% Pb–70 wt% Mg at 425℃(e) 2.12 kg Zn and 1.88 kg Cu at 500℃(f ) 37 lbm Pb and 6.5 lbm Mg at 400℃(g) 8.2 mol Ni and 4.3 mol Cu at 1250℃.(h) 4.5 mol Sn and 0.45 mol Pb at 200℃10.6 For an alloy of composition 74 wt% Zn–26 wt% Cu, cite the phases presentand their compositions at the following temperatures: 850℃, 750℃, 680℃, 600℃, and 500℃.10.7 Determine the relative amounts (in terms of mass fractions) of the phases forthe alloys and temperatures given inProblem 10.5.10.9 Determine the relative amounts (interms of volume fractions) of the phases forthe alloys and temperatures given inProblem 10.5a, b, and c. Below are given theapproximate densities of the various metalsat the alloy temperatures:10.18 Is it possible to have a copper–silveralloy that, at equilibrium, consists of a _ phase of composition 92 wt% Ag–8。
高分子材料与工程专业英语答案
高分子材料与工程专业英语答案【篇一：高分子材料专业英语第二版部分答案2】t all polymers are built up from bonding together a single kindof repeating unit. at the other extreme ,protein molecules are polyamides in which n amino acide repeat units are bonded together. although we might still call n the degree of polymerization in this case, it is less usefull,since an aminoacid unit might be any one of some 20-odd molecules that are found in proteins. in this case the molecular weightitself,rather than the degree of the polymerization ,is generally used to describe the molecule. when the actual content of individual amino acids is known,it is their sequence that is of special interest to biochemists and molecular biologists.并不是所有的聚合物都是由一个重复单元链接在一起而形成的。
在另一个极端的情形中，蛋白质分子是由n个氨基酸重复单元链接在一起形成的聚酰胺。
尽管在这个例子中，我们也许仍然把n称为聚合度，但是没有意义，因为一个氨基酸单元也许是在蛋白质中找到的20多个分子中的任意一个。
高分子材料专业英语第二版部分答案
unit1all polymers are built up from bonding together a single kind of repeating unit. At the other extreme ,protein molecules are polyamides in which n amino acide repeat units are bonded together. Although we might still call n the degree of polymerization in this case, it is less usefull,since an amino acid unit might be any one of some 20-odd molecules that are found in proteins. In this case the molecular weight itself,rather than the degree of the polymerization ,is generally used to describe the molecule. When the actual content of individual amino acids is known,it is their sequence that is of special interest to biochemists and molecular biologists.并不是所有的聚合物都是由一个重复单元链接在一起而形成的。
在另一个极端的情形中，蛋白质分子是由n个氨基酸重复单元链接在一起形成的聚酰胺。
尽管在这个例子中，我们也许仍然把n称为聚合度，但是没有意义，因为一个氨基酸单元也许是在蛋白质中找到的20多个分子中的任意一个。
在这种情况下，一般是分子量本身而不是聚合度被用来描述这个分子。
(完整版)材料科学与工程专业英语第三版-翻译以及问题详解
UNIT 1一、材料根深蒂固于我们生活的程度可能远远的超过了我们的想象，交通、装修、制衣、通信、娱乐（recreation）和食品生产，事实上（virtually），我们生活中的方方面面或多或少受到了材料的影响。
历史上，社会的发展和进步和生产材料的能力以及操纵材料来实现他们的需求密切(intimately)相关,事实上，早期的文明就是通过材料发展的能力来命名的（石器时代、青铜时代、铁器时代).二、早期的人类仅仅使用（access）了非常有限数量的材料，比如自然的石头、木头、粘土（clay)、兽皮等等.随着时间的发展，通过使用技术来生产获得的材料比自然的材料具有更加优秀的性能.这些性材料包括了陶瓷（pottery）以及各种各样的金属，而且他们还发现通过添加其他物质和改变加热温度可以改变材料的性能。
此时，材料的应用（utilization）完全就是一个选择的过程，也就是说，在一系列有限的材料中，根据材料的优点来选择最合适的材料，直到最近的时间内，科学家才理解了材料的基本结构以及它们的性能的关系。
在过去的100年间对这些知识的获得，使对材料性质的研究变得非常时髦起来.因此，为了满足我们现代而且复杂的社会，成千上万具有不同性质的材料被研发出来，包括了金属、塑料、玻璃和纤维.三、由于很多新的技术的发展，使我们获得了合适的材料并且使得我们的存在变得更为舒适。
对一种材料性质的理解的进步往往是技术的发展的先兆，例如：如果没有合适并且没有不昂贵的钢材，或者没有其他可以替代（substitute）的东西，汽车就不可能被生产，在现代、复杂的（sophisticated）电子设备依赖于半导体(semiconducting）材料四、有时，将材料科学与工程划分为材料科学和材料工程这两个副学科(subdiscipline）是非常有用的,严格的来说,材料科学是研究材料的性能以及结构的关系，与此相反，材料工程则是基于材料结构和性能的关系，来设计和生产具有预定性能的材料，基于预期的性能。
材料科学与工程专业英语第三版-翻译以及答案
UNIT 1一、材料根深蒂固于我们生活的程度可能远远的超过了我们的想象，交通、装修、制衣、通信、娱乐（recreation）和食品生产，事实上（virtually），我们生活中的方方面面或多或少受到了材料的影响。
历史上，社会的发展和进步和生产材料的能力以及操纵材料来实现他们的需求密切（intimately）相关，事实上，早期的文明就是通过材料发展的能力来命名的（石器时代、青铜时代、铁器时代）。
二、早期的人类仅仅使用（access）了非常有限数量的材料，比如自然的石头、木头、粘土（clay）、兽皮等等。
随着时间的发展，通过使用技术来生产获得的材料比自然的材料具有更加优秀的性能。
这些性材料包括了陶瓷（pottery）以及各种各样的金属，而且他们还发现通过添加其他物质和改变加热温度可以改变材料的性能。
此时，材料的应用（utilization）完全就是一个选择的过程，也就是说，在一系列有限的材料中，根据材料的优点来选择最合适的材料，直到最近的时间内，科学家才理解了材料的基本结构以及它们的性能的关系。
在过去的100年间对这些知识的获得，使对材料性质的研究变得非常时髦起来。
因此，为了满足我们现代而且复杂的社会，成千上万具有不同性质的材料被研发出来，包括了金属、塑料、玻璃和纤维。
三、由于很多新的技术的发展，使我们获得了合适的材料并且使得我们的存在变得更为舒适。
对一种材料性质的理解的进步往往是技术的发展的先兆，例如：如果没有合适并且没有不昂贵的钢材，或者没有其他可以替代（substitute）的东西，汽车就不可能被生产，在现代、复杂的（sophisticated）电子设备依赖于半导体（semiconducting）材料四、有时，将材料科学与工程划分为材料科学和材料工程这两个副学科（subdiscipline）是非常有用的，严格的来说，材料科学是研究材料的性能以及结构的关系，与此相反，材料工程则是基于材料结构和性能的关系，来设计和生产具有预定性能的材料，基于预期的性能。
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材料专业英语课后习题答案材料专业英语课后习题答案在学习材料专业英语的过程中，课后习题是非常重要的一部分，它能够帮助我们巩固所学的知识，并检验我们的理解和掌握程度。
下面是一些常见的材料专业英语课后习题及其答案，希望对大家的学习有所帮助。
一、单项选择题1. The ________ of a material refers to its ability to be drawn into a wire.A. malleabilityB. ductilityC. strengthD. hardness答案：B. ductility2. The ________ of a material refers to its ability to resist deformation under stress.A. malleabilityB. ductilityC. strengthD. hardness答案：C. strength3. The ________ of a material refers to its ability to resist scratching or indentation.A. malleabilityB. ductilityC. strengthD. hardness答案：D. hardness4. The process of changing a metal's properties by heating and cooling it is called ________.A. annealingB. temperingC. quenchingD. forging答案：A. annealing5. The process of heating a material to a high temperature and then cooling it quickly to make it hard is called ________.A. annealingB. temperingC. quenchingD. forging答案：C. quenching二、填空题1. The ________ of a material is its ability to return to its original shape after being deformed.答案：elasticity2. The ________ of a material is the maximum stress it can withstand before breaking.答案：tensile strength3. The ________ of a material is its ability to conduct electricity.答案：electrical conductivity4. The ________ of a material is its ability to conduct heat.答案：thermal conductivity5. The ________ of a material is its ability to absorb energy without breaking.答案：toughness三、阅读理解题材料科学与工程专业的学生需要学习并掌握英语，因为这门学科涉及到许多国际合作和交流。
通过学习材料专业英语，学生可以更好地理解和应用材料科学与工程的知识。
同时，材料专业英语也是学生未来就业的一项重要技能。
阅读下面的短文，回答问题：Materials science and engineering is a multidisciplinary field that combines principles from physics, chemistry, and engineering to study the properties and behavior of materials. It involves the development, processing, and characterization of materials, as well as the design and manufacturing of materials-based products.English plays a crucial role in materials science and engineering. Many scientific papers, research articles, and technical documents in this field are written in English. Therefore, students in this major need to have a good command of English in order to access and understand the latest research findings and technological advancements. Moreover, English proficiency is essential foreffective communication with international colleagues and collaborators.In addition to language skills, materials science and engineering students also need to learn specialized terminology and concepts in English. This includes understanding the different types of materials, their properties, and the various processes involved in their production and application. By mastering the language of materials science and engineering, students can effectively communicate their ideas, conduct experiments, and analyze data. Furthermore, learning materials-specific English can enhance students' employability. Many multinational companies and research institutions in the field of materials science and engineering require employees who are proficient in English. Being able to read and write technical documents, give presentations, and participate in international conferences are highly valued skills in this industry.In conclusion, studying materials-specific English is essential for students in the field of materials science and engineering. It not only facilitates their understanding and application of knowledge, but also enhances their career prospects. Therefore, students should take their materials specialty English courses seriously and strive to improve their language skills.问题：1. What does materials science and engineering involve?答案：Materials science and engineering involves the development, processing, and characterization of materials, as well as the design and manufacturing ofmaterials-based products.2. Why is English important in materials science and engineering?答案：English is important in materials science and engineering because many scientific papers, research articles, and technical documents in this field are written in English. English proficiency is essential for accessing and understanding the latest research findings and for effective communication with international colleagues and collaborators.3. How can learning materials-specific English enhance students' employability? 答案：Learning materials-specific English can enhance students' employability by providing them with the skills to read and write technical documents, give presentations, and participate in international conferences. These skills are highly valued by multinational companies and research institutions in the field of materials science and engineering.希望以上的材料专业英语课后习题及其答案能够帮助大家更好地学习和掌握这门学科。