山东省济宁市2017-2018学年高一上学期期末考试英语试题

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2017-2018年山东省济宁市高三上学期数学期末试卷(理科)与解析

2017-2018年山东省济宁市高三上学期数学期末试卷(理科)与解析

2017-2018学年山东省济宁市高三(上)期末数学试卷(理科)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.(5分)集合A={x|x2﹣3x≤0},B={x|y=lg(2﹣x)},则A∩B=()A.{x|0≤x<2}B.{x|1≤x<3}C.{x|2<x≤3}D.{x|0<x≤2}2.(5分)已知,,且,则m=()A.﹣3B.﹣1C.1D.33.(5分)已知函数g(x)=log a(x﹣3)+2(a>0,a≠1)的图象经过定点M,若幂函数f(x)=xα的图象过点M,则α的值等于()A.﹣1B.C.2D.34.(5分)命题p:若a<b,则∀c∈R,ac2<bc2;命题q:∃x0>0,使得lnx0=1﹣x0,则下列命题中为真命题的是()A.p∧q B.p∨(¬q)C.(¬p)∧q D.(¬p)∧(¬q)5.(5分)中国古代数学著作《算法统宗》中记载了这样的一个问题:“三百七十八里关,初行健步不为难,次日脚痛减一半,六朝才得到其关,要见次日行里数,请公仔细算相还”,其大意为:有一个人走了378里路,第一天健步行走,从第二天其因脚痛每天走的路程为前一天的一半,走了6天后到达了目的地,问此人第二天走的路程里数为()A.76B.96C.146D.1886.(5分)已知实数x,y满足条件,则的最大值为()A.B.﹣1C.1D.7.(5分)已知,,则=()A.B.C.D.8.(5分)已知a>0,b>0,并且,,成等差数列,则a+9b的最小值为()A.16B.9C.5D.49.(5分)函数y=﹣2cos2x+cosx+1,x∈[﹣,]的图象大致为()A.B.C.D.10.(5分)“a=﹣1”是函数为奇函数”的()A.充分不必要条件B.必要不充分条件C.充分必要条件D.既不充分也不必要条件11.(5分)已知抛物线C1:y2=2px(p>0)的焦点为F,准线与x轴的交点为E,线段EF被双曲线C2:的顶点三等分,且两曲线C1,C2的交点连线过曲线C1的焦点F,曲线C2的焦距为2,则曲线C2的离心率为()A.B.C.D.12.(5分)设f(x)=|lnx|,若函数g(x)=f(x)﹣ax在区间(0,e2)上有三个零点,则实数a的取值范围是()A.B.C.D.二、填空题(每题5分,满分20分,将答案填在答题纸上)13.(5分)直线l过抛物线C:x2=4y的焦点且与y轴垂直,则l与抛物线C所围成的图形的面积等于.14.(5分)函数f(x)=Asin(ωx+φ)的部分图象如图所示,则将y=f(x)的图象向右平移个单位后,得到的图象对应的函数解析式为.15.(5分)某多面体的三视图,如图所示,则该几何体的外接球的表面积为.16.(5分)设函数,则方程f n (x)=0的根为.三、解答题(本大题共7小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.(12分)△ABC的内角A,B,C所对的边分别是a,b,c,且.(1)求角A的大小;(2)若b+c=5,,求a的值.18.(12分)已知S n为数列{a n}的前n项和,且3S n=1﹣a n.(1)求数列{a n}的通项公式;(2)设,求数列{b n}的前n项和T n.19.(12分)如图,三棱柱ABC﹣A1B1C1中,侧棱AA1⊥平面ABC,△ABC为等腰直角三角形,∠BAC=90°,且AB=AA1=2,E,F分别是CC1,BC的中点.(1)若D是AA1的中点,求证:BD∥平面AEF;(2)若M是线段AE上的任意一点,求直线B1M与平面AEF所成角正弦的最大值.20.(12分)如图,点是圆内的一个定点,点P 是圆A上的任意一点,线段BP的垂直平分线l和半径AP相交于点Q,当点P 在圆A上运动时,点Q的轨迹为曲线C.(1)求曲线C的方程;(2)点E(2,0),F(0,1),直线QE与y轴交于点M,直线QF与x轴交于点N,求|EN|•|FM|的值.21.(12分)设函数f(x)=x+lnx﹣.(1)讨论函数f(x)的单词性;(2)当a=1时,记g(x)=xf(x),是否存在整数t,使得关于x的不等式t≥g (x)有解?若存在,请求出t的最小值;若不存在,请说明理由.22.在直角坐标系xOy中,以坐标原点O为极点,x轴的正半轴为极轴,建立极坐标系,已知直线l的参数方程为(t为参数),曲线C的极坐标方程是ρcos2θ=2sinθ.(1)写出直线l的普通方程和曲线C的直角坐标方程;(2)设直线l与曲线C相交于A,B两点,点M为AB的中点,点P的极坐标为,求|PM|的值.23.(10分)设函数f(x)=|x﹣a|+2x.(1)当a=﹣1时,求不等式f(x)≤0的解集;(2)若x≥﹣1时,恒有f(x)≥0成立,求a的取值范围.2017-2018学年山东省济宁市高三(上)期末数学试卷(理科)参考答案与试题解析一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.(5分)集合A={x|x2﹣3x≤0},B={x|y=lg(2﹣x)},则A∩B=()A.{x|0≤x<2}B.{x|1≤x<3}C.{x|2<x≤3}D.{x|0<x≤2}【解答】解:A={x|x2﹣3x≤0}={x|0≤x≤3},B={x|y=lg(2﹣x)}═{x|2﹣x>0}={x|x<2},则A∩B={x|0≤x<2},故选:A.2.(5分)已知,,且,则m=()A.﹣3B.﹣1C.1D.3【解答】解:∵,,∴﹣=(m+2,1),∵,∴=,即m+2=﹣1,得m=﹣3,故选:A.3.(5分)已知函数g(x)=log a(x﹣3)+2(a>0,a≠1)的图象经过定点M,若幂函数f(x)=xα的图象过点M,则α的值等于()A.﹣1B.C.2D.3【解答】解:∵y=log a(x﹣3)+2(a>0,a≠1)的图象过定点M,∴M(4,2),∵点M(4,2)也在幂函数f(x)=xα的图象上,∴f(4)=4α=2,解得α=,故选:B.4.(5分)命题p:若a<b,则∀c∈R,ac2<bc2;命题q:∃x0>0,使得lnx0=1﹣x0,则下列命题中为真命题的是()A.p∧q B.p∨(¬q)C.(¬p)∧q D.(¬p)∧(¬q)【解答】解:当c=0时,ac2<bc2不成立,则命题p为假命题,当x=1时,ln1=1﹣1=0,则命题q为真命题,则(¬p)∧q为真命题,其余为假命题,故选:C.5.(5分)中国古代数学著作《算法统宗》中记载了这样的一个问题:“三百七十八里关,初行健步不为难,次日脚痛减一半,六朝才得到其关,要见次日行里数,请公仔细算相还”,其大意为:有一个人走了378里路,第一天健步行走,从第二天其因脚痛每天走的路程为前一天的一半,走了6天后到达了目的地,问此人第二天走的路程里数为()A.76B.96C.146D.188【解答】解:根据题意,记每天走的路程里数为{a n},可知{a n}是公比q=的等比数列,由S6=378,得S6==378,解可得a1=192,则a2=a1×q=192×=96;即此人第二天走的路程里数为96;故选:B.6.(5分)已知实数x,y满足条件,则的最大值为()A.B.﹣1C.1D.【解答】解:作出不等式组对应的平面区域,设,即y=()x+z,平移曲线y=()x+z,由图象可知当曲线y=()x+z经过点A时,此时z取得最大值,由,解得A(1,1),此时z=1﹣()1=,故选:D.7.(5分)已知,,则=()A.B.C.D.【解答】解:∵,∴,即.∵,∴.∴==.故选:A.8.(5分)已知a>0,b>0,并且,,成等差数列,则a+9b的最小值为()A.16B.9C.5D.4【解答】解:根据题意,a>0,b>0,且,,成等差数列,则+=2×=1;则a+9b=(a+9b)(+)=10++≥10+2=16;即则a+9b的最小值为16;故选:A.9.(5分)函数y=﹣2cos2x+cosx+1,x∈[﹣,]的图象大致为()A.B.C.D.【解答】解:因为函数y=﹣2cos2x+cosx+1,x∈[﹣,],所以函数为偶函数,故排除A,Dy=﹣2cos2x+cosx+1=﹣2(cosx﹣)2+,x∈[﹣,],因为cosx≤1,所以当cosx=时,y max=,当cosx=1时,y min=0,故排除C,故选:B.10.(5分)“a=﹣1”是函数为奇函数”的()A.充分不必要条件B.必要不充分条件C.充分必要条件D.既不充分也不必要条件【解答】解:若函数为奇函数,则f(﹣x)=﹣f(x),即f(﹣x)+f(x)=0,则ln(+a)+ln(+a)=0,即ln(+a)(+a)=0,则(+a)(+a)=1,即•=1,则=1即a2﹣(a+2)2x2=1﹣x2,则,得a=﹣1,则“a=﹣1”是函数为奇函数”的充要条件,故选:C.11.(5分)已知抛物线C1:y2=2px(p>0)的焦点为F,准线与x轴的交点为E,线段EF被双曲线C2:的顶点三等分,且两曲线C1,C2的交点连线过曲线C1的焦点F,曲线C2的焦距为2,则曲线C2的离心率为()A.B.C.D.【解答】解:如图,由可线段EF被双曲线C2:的顶点三等分,得2a=,即p=6a∵两曲线C1,C2的交点A连线过曲线C1的焦点,∴A(3a,6a)在双曲线C2:上,∴⇒.∴曲线C2的离心率e满足:e2=,可得e=故选:D.12.(5分)设f(x)=|lnx|,若函数g(x)=f(x)﹣ax在区间(0,e2)上有三个零点,则实数a的取值范围是()A.B.C.D.【解答】解:∵函数g(x)=f(x)﹣ax在区间(0,e2)上有三个零点,∴y=f(x)与y=ax在区间(0,e2)上有三个交点;由函数y=f(x)与y=ax的图象可知,k1==;f(x)=lnx,(x>1),f′(x)=,设切点坐标为(t,lnt),则=,解得:t=e.∴k2=.则直线y=ax的斜率a∈(,).故选:D.二、填空题(每题5分,满分20分,将答案填在答题纸上)13.(5分)直线l过抛物线C:x2=4y的焦点且与y轴垂直,则l与抛物线C所围成的图形的面积等于.【解答】解:方法一:抛物线C:x2=4y的焦点(0,1),直线l过抛物线C:x2=4y 的焦点且与y轴垂直,直线与抛物线的交点(﹣2,1),(2,1),直线l的方程为y=1,如图所示,可知l与C围成的图形的面积等于矩形OABF的面积与函数y=x2的图象和x轴正半轴及直线x﹣=2围成的图形的面积的差的2倍(图中阴影部分的2倍).即l与C所围成的图形的面积S=4﹣2x2dx=4﹣2×x3=4﹣=.故答案为:.方法二:抛物线C:x2=4y的焦点(0,1),直线l过抛物线C:x2=4y的焦点且与y轴垂直,直线与抛物线的交点(﹣2,1),(2,1),则l与抛物线C所围成的图形的面积等于S=2×2dy=2×2×=,∴l与C所围成的图形的面积为,故答案为:.14.(5分)函数f(x)=Asin(ωx+φ)的部分图象如图所示,则将y=f(x)的图象向右平移个单位后,得到的图象对应的函数解析式为.【解答】解:由函数f(x)=Asin(ωx+φ)的部分图象知,A=1,=﹣=,∴T=π,即=π,解得ω=2;由五点法画图知,sin(2×+φ)=1,解得φ=﹣=,∴f(x)=sin(2x+);将y=f(x)的图象向右平移个单位,得到的图象对应的函数解析式为y=sin[2(x﹣)+]=sin(2x﹣).故答案为:y=sin(2x﹣).15.(5分)某多面体的三视图,如图所示,则该几何体的外接球的表面积为.【解答】解:由三视图还原原几何体如图:该几何体是正三棱柱,底面是边长为4的等边三角形,正三棱柱的高是.如图,设底面等腰三角形ABC的外心为G,则CG=,∴直三棱柱外接球的半径R=.∴该几何体的外接球的表面积为4πR2=4π×=.故答案为:.16.(5分)设函数,则方程f n (x)=0的根为﹣1,﹣2,﹣3,…,﹣n.【解答】解:f1(x)=1+x,f2(x)=1+x+=(x+1)(1+),f3(x)=f2(x)+=(x+1)(1+)+=(x+1)[1++]=(x+1)(1+)(1+).…同理可得:f n(x)=(x+1)(1+)(1+)…(1+).∴f n(x)=0解为﹣1,﹣2,﹣3,…,﹣n.故答案为:﹣1,﹣2,﹣3,…,﹣n.三、解答题(本大题共7小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.(12分)△ABC的内角A,B,C所对的边分别是a,b,c,且.(1)求角A的大小;(2)若b+c=5,,求a的值.【解答】(1)由,得,∵sinC≠0,∴,∴,∴,∵,∴,即.(2)由,∴bc=4,∵,∴.18.(12分)已知S n为数列{a n}的前n项和,且3S n=1﹣a n.(1)求数列{a n}的通项公式;(2)设,求数列{b n}的前n项和T n.【解答】解:(1)当n=1时,3S1=1﹣a1,∴3a1=1﹣a1,∴,当n≥2时,因为3S n=1﹣a n①所以3S n=1﹣a n﹣1②﹣1①﹣②得3a n=a n﹣1﹣a n,∴4a n=a n﹣1,∴.所以数列{a n}是首项为,公比为的等比数列.∴;(2),=,∴,=.19.(12分)如图,三棱柱ABC﹣A1B1C1中,侧棱AA1⊥平面ABC,△ABC为等腰直角三角形,∠BAC=90°,且AB=AA1=2,E,F分别是CC1,BC的中点.(1)若D是AA1的中点,求证:BD∥平面AEF;(2)若M是线段AE上的任意一点,求直线B1M与平面AEF所成角正弦的最大值.【解答】(1)证明:连接DC1,BC1,∵D,E分别是AA1,CC1的中点,∵AD=C1E,AD∥C1E,∴四边形ADCE是平行四边形,∴AE∥DC,∵E,F分别是CC1,BC的中点,∴EF∥BC1,∴平面AEF∥平面BDC1,又BD⊂平面BDC1,∴BD∥平面AEF.(2)解:以A为坐标原点,AB,AC,AA1分别为x,y,z轴,建立空间直角坐标系,如图所示:可知:A(0,0,0),B1(2,0,2),E(0,2,1),F(1,1,0),∴,,=(﹣2,0,﹣2),设平面AEF的法向量为,由,得,令z=2,得x=1,y=﹣1,即,设,则=+=+λ=(﹣2,0,﹣2)+λ(0,2,1)=(﹣2,2λ,λ﹣2).设直线B1M与平面AEF所成角为θ,则=∴当时,.20.(12分)如图,点是圆内的一个定点,点P 是圆A上的任意一点,线段BP的垂直平分线l和半径AP相交于点Q,当点P在圆A上运动时,点Q的轨迹为曲线C.(1)求曲线C的方程;(2)点E(2,0),F(0,1),直线QE与y轴交于点M,直线QF与x轴交于点N,求|EN|•|FM|的值.【解答】解:(1)因为点Q在BP的垂直平分线上,所以|QB|=|QP|,∴|QA|+|QB|=|QA|+|QP|=4,从而点Q的轨迹是以A,B为焦点的椭圆,这时,a=2,,∴b=1,所以曲线C的方程为.(2)由题设知,直线的斜率存在.设直线QE的方程为y=k(x﹣2),Q(x1,y1),E(x2,y2),由,得(1+4k2)x2﹣16k2x+16k2﹣4=0,因为,x2=2,所以,所以,因为点F,N,Q共线,k FN=k FQ,所以,即,又直线QE与y轴的交点纵坐标为y M=﹣2k,所以,|FM|=|1﹣y M|=|1+2k|,所以|EN|•|FM|=4.21.(12分)设函数f(x)=x+lnx﹣.(1)讨论函数f(x)的单词性;(2)当a=1时,记g(x)=xf(x),是否存在整数t,使得关于x的不等式t≥g (x)有解?若存在,请求出t的最小值;若不存在,请说明理由.【解答】解:(1)f′(x)=当a<0时,x∈(0,﹣a)时,f'(x)<0;x∈(﹣a,+∞)时,f'(x)>0;当0≤a≤1时,x∈(0,+∞)时,f'(x)>0;当a>1时,x∈(0,a﹣1)时,f'(x)<0;x∈(a﹣1,+∞)时,f'(x)>0;综上,当a<0时,函数f(x)的单调减区间是(0,﹣a);单调增区间是(﹣a,+∞);当0≤a≤1时,函数f(x)的单调增区间是(0,+∞);无单调减区间;当a>1时,函数f(x)的单调减区间是(0,a﹣1);单调增区间是(a﹣1,+∞).(2)当a=1时,g(x)=xf(x)=x2+xlnx,g'(x)=2x+lnx+1,可知函数g'(x)单调递增,,,所以存在唯一,使得g'(x0)=0,即g'(x0)=2x0+lnx0+1=0,当x∈(0,x0)时,g'(x)<0;x∈(x0,+∞)时,g'(x)>0;所以,记函数,φ(x0)在上递减.所以,即.由,且t为整数,得t≥0.所以存在整数t满足题意,且t的最小值为0.22.在直角坐标系xOy中,以坐标原点O为极点,x轴的正半轴为极轴,建立极坐标系,已知直线l的参数方程为(t为参数),曲线C的极坐标方程是ρcos2θ=2sinθ.(1)写出直线l的普通方程和曲线C的直角坐标方程;(2)设直线l与曲线C相交于A,B两点,点M为AB的中点,点P的极坐标为,求|PM|的值.【解答】解:(1)由,得y=3x+1,由曲线C的极坐标方程ρcos2θ=2sinθ,得ρ2cos2θ=2ρsinθ,所以曲线C的直角坐标方程为x2=2y.(2)由,得x2﹣6x﹣2=0,设A(x1,y1),B(x2,y2),所以x1+x2=6,AB的中点是,所以M (3,10), 点P 的极坐标为,所以点P 的直角坐标为. 则:|PM |=.23.(10分)设函数f (x )=|x ﹣a |+2x .(1)当a=﹣1时,求不等式f (x )≤0的解集;(2)若x ≥﹣1时,恒有f (x )≥0成立,求a 的取值范围.【解答】解:(1)因为|x +1|+2x ≤0, 所以或,即或x <﹣1,则不等式f (x )≤0的解集是 .(2)因为为增函数,当a ≤﹣1时,3×(﹣1)﹣a ≥0,从而a ≤﹣3, 当a ≥﹣1时,﹣1+a ≥0,从而a ≥1, 综上,a ≤﹣3,或a ≥1.赠送—高中数学知识点【2.1.1】指数与指数幂的运算 (1)根式的概念①如果,,,1nx a a R x R n =∈∈>,且n N +∈,那么x 叫做a 的n 次方根.当n 是奇数时,a 的n n a n 是偶数时,正数a 的正的n n a 表示,负的n 次方根用符号n a -0的n 次方根是0;负数a 没有n 次方根.n a n 叫做根指数,a 叫做被开方数.当n 为奇数时,a 为任意实数;当n 为偶数时,0a ≥.③根式的性质:()n n a a =;当n 为奇数时,nn a a =;当n 为偶数时,(0)|| (0)nn a a a a a a ≥⎧==⎨-<⎩. (2)分数指数幂的概念①正数的正分数指数幂的意义是:(0,,,m n m na a a m n N +=>∈且1)n >.0的正分数指数幂等于0.②正数的负分数指数幂的意义是: 11()()0,,,m m m nn n aa m n N a a-+==>∈且1)n >.0的负分数指数幂没有意义. 注意口诀:底数取倒数,指数取相反数.(3)分数指数幂的运算性质①(0,,)rsr sa a aa r s R +⋅=>∈ ②()(0,,)r s rs a a a r s R =>∈③()(0,0,)r r rab a b a b r R =>>∈【2.1.2】指数函数及其性质 函数名称指数函数定义函数(0xy a a =>且1)a ≠叫做指数函数图象1a >01a <<xa y =xy(0,1)O1y =xa y =xy (0,1)O 1y =定义域R值域 (0,)+∞过定点 图象过定点(0,1),即当0x =时,1y =.奇偶性 非奇非偶单调性在R 上是增函数在R 上是减函数函数值的 变化情况1(0)1(0)1(0)x x x a x a x a x >>==<< 1(0)1(0)1(0)x x x a x a x a x <>==>< a 变化对 图象的影响 在第一象限内,a 越大图象越高;在第二象限内,a 越大图象越低.〖2.2〗对数函数【2.2.1】对数与对数运算(1)对数的定义①若(0,1)xa N a a =>≠且,则x 叫做以a 为底N 的对数,记作log a x N =,其中a 叫做底数,N 叫做真数.②负数和零没有对数.③对数式与指数式的互化:log (0,1,0)x a x N a N a a N =⇔=>≠>. (2)几个重要的对数恒等式log 10a =,log 1a a =,log b a a b =.(3)常用对数与自然对数常用对数:lg N ,即10log N ;自然对数:ln N ,即log e N (其中 2.71828e =…). (4)对数的运算性质 如果0,1,0,0a a M N >≠>>,那么①加法:log log log ()a a a M N MN += ②减法:log log log a a a MM N N-= ③数乘:log log ()n a a n M M n R =∈ ④log a Na N =⑤log log (0,)b n a a nM M b n R b=≠∈ ⑥换底公式:log log (0,1)log b a b NN b b a=>≠且【2.2.2】对数函数及其性质函数 名称 对数函数定义函数log (0a y x a =>且1)a ≠叫做对数函数图象1a >01a <<定义域 (0,)+∞ 值域 R过定点 图象过定点(1,0),即当1x =时,0y =.奇偶性 非奇非偶单调性在(0,)+∞上是增函数在(0,)+∞上是减函数函数值的 变化情况log 0(1)log 0(1)log 0(01)a a a x x x x x x >>==<<<log 0(1)log 0(1)log 0(01)a a a x x x x x x <>==><<a 变化对 图象的影响在第一象限内,a 越大图象越靠低;在第四象限内,a 越大图象越靠高.x yO(1,0)1x =log a y x=xyO (1,0)1x =log a y x=。

山东省2020-2021学年高一下学期各校英语3月月考试题汇编 语法填空专题 Word版含答案

山东省2020-2021学年高一下学期各校英语3月月考试题汇编 语法填空专题 Word版含答案

山山山2020-2021山山山山山山山山3山山山山山山山-山山山山山山山东省菏泽市郓城县第一中学2020-2021学年高一下学期第一次月考英语试题阅读下面短文, 在空白处填入1个适当的单词或括号内单词的正确形式。

What we eat every day does affect our health. Therefore, we should try our best to change our bad eating habits and have a 56___________ (balance) diet. As we all know, fried food 57___________(taste) delicious, but eating too much will probably lead to some illnesses. Worse still, a lot of money 58______________ (waste) on some junk food, which is not healthy at all. As a matter of fact, our eating habits are changing for the worse. We used 59___________ (eat) more grains and vegetables, but less meat, 60__________ is a good eating habit. However, things are 61_____________ (extreme) different now. With our life 62_______________(become) better and better, we are now eating a lot of food that is high in both sugar and fat. Some young people even make it 63_________ rule to eat out every month without considering the balance of our diet. The food we eat has a great effect 64_________ our health, so in order to have a healthy life, we must make right 65__________ (choose) and keep in mind that we are what we eat.【答案】56.balanced 57. tastes 58. is wasted 59. to eat 60. which61. extremely 62. becoming 63. a 64. on 65. choices山东省济南市长清区第一中学2020-2021学年高一下学期第一次质量检测英语试题第二节(共10小题;每小题1.5分,满分15分)阅读下面材料,在空白处填入适当的内容(1个单词)或括号内单词的正确形式。

山东省各校2020-2021学年高一下学期英语4月月考试题精选汇编 语法填空专题 Word版含答案

山东省各校2020-2021学年高一下学期英语4月月考试题精选汇编 语法填空专题 Word版含答案

山山山山山2020-2021山山山山山山山山4山山山山山山山山山-山山山山山山山东省枣庄市滕州第一中学2020-2021学年高一下学期4月月考英语试题第二节(共10小题;每小题1.5分,满分15分)阅读下面材料,在空白处填入1个适当的单词或括号内单词的正确形式。

The giant panda, also ___56___(know) as panda bear or simply panda, is a bear native ___57___ south central China. In the past many years, the giant panda ___58___(drive) out of the lowland areas where it once lived as a result of farming, deforestation (森林砍伐) and other __59___(develop). Wild population estimates (评估) vary:one estimate shows that there are about 1,590 individuals ___60___(1ive) in the wild, while a 2016 study estimated that this figure could be as high as 2,000 to 3,000. Some reports also show that ___61___ number of giant pandas in the wild is on the rise.The West first learned of the giant panda on March 11, 1869, ___62__ the French missionary (传教士) Armand David received a panda skin from a hunter. In 1936, Ruth Harkness became the first Westerner to bring a live giant panda named Su Lin to the Brookfield Zoo in Chicago. To protect the pandas, in 2012, Earthwatch Institute, a global nonprofit that teams volunteers with scientists to conduct important ___63___(science) research, launched (发起) a program called “On the Trail of Giant Panda”. This program, based in the Wolong National Nature Reserve, allows ___64__(volunteer) to work up close with pandas cared for in captivity (圈养), and help them ___65___(gradual) adapt to life in the wild.【答案】【答案】56. known 57. to 58. has been driven 59. development 60. living 61. the62. when 63. scientific 64. volunteers 65. gradually【解析】这是一篇说明文。

最新山东省济宁市-2017学年高一上学期期末考试英语试题-word版含答案

最新山东省济宁市-2017学年高一上学期期末考试英语试题-word版含答案

第Ⅰ卷第一部分听力(共两节,满分30分)做题时,建议先将答案标在试卷上,录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What’s the weather like in the woman’s country now?A. Cold.B. Warm.C. Hot.2. Where does the man want to go?A. A library.B. A bookstore.C. A cinema.3. How does Jenny look now?A. Happy.B. ExcitedC. Sad.4. How much was the boy given yesterday?A. $20.B. $30.C. $50.5. What will the speakers do next?A. Rest in the park.B. Walk in the park.C. Do their homework.第二节(共15小题,每小题1.5分,满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6. What time is it now?A. 9:00.B. 9 :10. C 9 :30.7. How will the man go to the meeting?A. By car.B. By bus.C. By air.听第7段材料,回答第8至10题。

济宁市2017-2018学年高一英语上学期期末考试试题

济宁市2017-2018学年高一英语上学期期末考试试题

山东省济宁市2017-2018学年高一英语上学期期末考试试题本试卷分第Ⅰ卷和第Ⅱ卷两部分,共10页.满分150分。

考试用时120分钟。

考试结束后,将本试卷和答题卡一并交回。

注意事项:1答题前,考生务必用0.5毫米黑色签字笔将自己的姓名、座号、考生号、县区和科类填写到答题卡和试卷規定的位置上。

2第Ⅰ卷每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;如需改动,用橡皮擦干净后,再选涂其他答案标号。

3第Ⅱ卷必須用0.5毫米黑色签字笔作答,答案必须写在答题卡各题目指定区域内相应的位置;如需改动,先划掉原来的答案,然后再写上新的答案;不能使用涂改液、胶带纸、修正带。

不按以上要求作答的答案无效。

第Ⅰ卷第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1。

5分,满分7。

5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置.听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt?A。

£19。

15 B。

£9。

18 C.£9.151。

What will the woman do about the dress?A. she'll change it. B。

She’ll return it。

C. She'll buy it。

2。

What are the speakers talking about?A。

Buying DVDs。

B。

Borrowing DVDs. C。

Sharing DVDs。

3. What did the woman think of Dana ’s speech?A。

Boring. B。

Important. C. well—prepared. 4。

2022-2023学年山东省济宁市高一上学期期末考试英语试题 (解析版)

2022-2023学年山东省济宁市高一上学期期末考试英语试题 (解析版)
Kiln Theatre
Located in the heart of Kilburn, Kiln Theatre opened in the Forester’s Hall in 1980. In 1987 the theatre was almost totally destroyed by a fire which started in a neighbouring yard. Two years later it was rebuilt. After undergoing a major redevelopment, the theatre reopened as the Kiln Theatre under the artistic leadership of Indhu Rubasingham in 2018.
3. What are the speakers talking about?
A. Their study plans.
B. Their exam results.
C. Their favorite subjects.
4. What happened to Jennifer?
A. She did poorly in practice.
A. She stayed at home.
B. She worked on a farm.
C. She went to the cinema.
9. What does the man want to do most today?
A, Ride a horse B. Pick apples. C. Go fishing.
2022—2023学年度第一学期质量检测
高一英语试题
注意事项:

高一上学期期末考试英语试题(含听力)

高一上学期期末考试英语试题(含听力)

2016—2017学年高一上学期期末英语试卷(含听力)第一部分听力(共两节,满分30分)第一节(听下面5段对话,每段对话后有一个小题,从题中所给的A,B,C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话前,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How will the woman travel?A. By planeB. By carC. By train2. What do we know about Ann?A. She loves all kinds of musicB. She enjoys rock musicC. She likes classic music3. Where did the conversation most probably take place?A. In a liftB. In an officeC. On a bus4. How much will the woman pay?A. $20B. $18C. $85. What did the girl do on Sunday evening?A. She studied a littleB. She took an evening walkC. She enjoyed a movie 第二节(共15小题;每小题1.5分,) 听下面5段对话或独白,每段对话或独白后有一个小题,从题中所给的A,B,C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话或独白前,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话或独白读两遍。

听第6段材料,回答第6至7题。

6. Where did the woman hear about the weather information?A. From the radio.B. From the woman’s friendC. On the Internet7. What is the man going to do tomorrow?A. To give up the planB. To put off the planC. To go as planned听第7段材料,回答第8至10题。

山东省烟台市2017-2018学年高一上学期期末考试英语试题Word版含答案

山东省烟台市2017-2018学年高一上学期期末考试英语试题Word版含答案

第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后; 你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5 小题; 每小题1.5分, 满分7.5 分)听下面5 段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. When does the train leave for Chicago?A. At 9:10 a. m.B. At 9:20 a. m.C. At 9:40 a. m.2. What sport does the man like most?A. Baseball.B. Swimming.C. Basketball3. Why is the woman going to bring her friend?A. They can make five.B. She can’t play poker well.C. Her friend loves playing poker.4. What is the man going to do?A. Talk to more soldiers.B. Organize the information.C. Read a book about the war.5. How many people are there in the speakers’family?A. Two.B. Three.C. Four.第二节(共15小题; 每小题1.5分,满分22.5分)听下面5 段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听每段对话或独白前;你将有时间阅读各个小题,每小题5秒钟; 听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

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山东省济宁市2017-2018学年高一上学期期末考试英语试题2018.02第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)AInstead of asking to go to summer camp or on a vacation, 10-year-old Liam Hannon asked his dad, Scott Hannon, if he could make bagged lunches and hand them out to the homeless all around Cambridge. "Liam has a huge heart, Hannon said about his son. “Plus, it was something nice we could do together as father and son and with my wife and baby.”Soon after telling his father his plans, Liam started "Liam's Lunches of Love,” and started handing out 20 lunches each week. "Many of the people we help are actually really nice and just a little kindness matters in their lives," Liam said. "It just feels really good help.”After seeing how passionate Liam was about his project, Hannon started a GoFundMe to raise money so they could make 60 lunches each week. "It makes me really proud as a dad," Hannon added, So far, Liam has handed out 300 lunches and even though summer is over, he has continued his community service on the weekends.“What Scott and Liam have done has really given the homeless self-respect and kindness in a really tough circumstance," said Krystal Kelly, director of development at the Hildebrand Family Help Center where Liam also collects school things for homeless children, "it's the first time that any of those people has been looked at in the eye or anyone has noticed their presence, To think that a 10-year-old can be that selfless, it's atrazine.”21 What do we know about “Liam’s Lunches of love”?A. It was star ted by Liam’s father.B. 300 lunches in all will be made.C. The project got more people's help.D. It will be stopped with the summer over.22. What else does Liam do to help homeless children?A. Provide shelters for them to live in. B Offer free dinners to them every day.C. Look after them himself.D. Try to help with their study.23. According to Kelly, what do Liam's lunches mean to the homeless?A. They can live on the lunches every day.B. They no longer feel hungry at noon.C. They feel respected and recognized.D. They live an excellent life now.BMy first tip is to prepare yourself for revising(复习). During the term, you must have gone to the lectures and taken a lot of notes. These are the first steps in learning. Now, at the end of the term, gather all the notes you took and run through them quickly. While doing this, keep asking yourself, "Do I understand what I am reading?" If yes, great. If not, you have to spend some time understanding them before the exams take place.My second tip is to plan different types of revision in order to study more efficiently. Even if you are interested, everyone gets bored after a couple of hours of studying. Something that really helps is to plan different types of active studying while revising. You switch between useful study methods so you won't get bored and it's easier to study for longer period of time.One thing that can really help you to memorize your study material more easily is to make the facts more connected. Th ere are many different ways to do so, I’m going to gi ve you two examples and the first one is to create pictures in your mind while studying. This can be really helpful for studying history, for example. The second method, especially for learning new words:Try to make yourself familiar with new words by looking for the ones that look alike.24. According to Paragraph 1, what is the first step for revising?A. Going to lectures.B. Taking notes.C. Keeping asking yourself.D. Understanding your notes.25. What should you do after reading notes for an hour?A. Go on reading.B. Do some exercises.C. Listen to music.D. Go to sleep.26. Which word may the author think helps learn the new word "arise "more easily?A. Rise.B. Happen.C. Appear.D. Create.27. Which of the following can be the best title?A. How to Survive the Exam SeasonB. How to Memorise New WordsC. How to Prepare for Future Study.D. How to Keep Interested in StudyCOn this program we explore common expressions in American English. Today, we talk about expressions that began behind the wheels of automobiles. Now they are common expressions that we use in everyday conversations.Well, let's not delay any longer. Let’s get ' thi s show on the road!“To get the show on the road" means to begin something as soon as possible. It's a casual expression that we use when we want to start something, anything an activity or project or an actual road trip.Well, not any activity. You would not likely use this expression to begin something sad, such as a funeral. It is a lighthearted expression.So, the person who says "hey, let's get this show on the road in is taking charge. They want to start things. They want to get things going. You could say they are in the driver's seat. Just as the driver is in control of their vehicle, the person in the driver's seat of an activity, event or project is also in control, Feel free to use this phrase in any situation, formal of informal.Speaking free, most rides are not. They cost money. When you take a taxi you must pay for it. If you drive a car, you must pay for gas, repairs and insurance. It is great when you get a free ride to where you are going.However, in life, to get a free ride means to gain from something without having to do anything in exchange. It can be annoying to have a friend or co-worker who is always trying to get a free ride. They do not give. They just take, take, take!Now, when we are actually driving, the phrage go down that road simply means to drive down a road, We would say this when we give directions. “Go down that road for about a mile and you’ll see your destination on the right." But in conversations, it has an interesting meaning. To go down that road means to make a decision. But it is more than that. It also means that this decision may bring trouble or leave you in a difficult place. We often more use this phrase as a warning.28. The underlined word "lighthearted" in Paragraph 4 is closest in meaning to ___.A. amazingB. humourousC. cheerfulD. heartbreaking29. What can we learn from the passage?A. "To get this show on the road" can be used to start anything.B. The person “in the driver’s seat” is the one in charge.C. Someone who likes getting a free ride is always welcome.D. We can use "go down that road" as an encouragement.30. What do the four expressions have in common?A. They all have something to do with transport.B. They all can be used in any situation.C. They are not used when we're actually travelling.D. They are all used to talk about driving cars.31. Where probably is the text from?A. A radio broadcast.B. A guide book.C. A travel journal.D. A newspaper.DWe humans spend about one-third of our lives asleep. This may sound like a lot of time, but it is not wasted. Sleep not only helps us stay healthy but it also helps our brains remember. Our brains need good sleep to remember what we do and learn during the other two thirds of our lives when we are awake.Researchers at the University of Wisconsin-Madison have found that sleep helps improve brain performance by shrinking(收缩)synapses in the brain. A synapse is the area where cells pass messages to other cells.Scientist Chiara Cirelli is a leader at the school 's Center for Sleep and Consciousness. She told the reporter that sleep is when the human brain mixes information it has learned while awake into its general collection of knowledge. Meanwhile, the brain forgets unimportant details. This forgetting is important. It makes space for new learning and new memories.Cirelli said that the Centers research began with this hypothesis(假设): We sleep so that our brain can repair and refresh itself, She said the idea seems simple and reasonable. However, testing and discovering how it works has been extremely difficult.Synapses are only about 20-40 nanometers wide. The team began their study by measuring(测量)the size of the synapses to look for changes in these already tiny spaces between nerve cells. Cirelli says the process(过程)is difficult because "all the actual measurements of the synapses have to be done by hand.” The team had to wait until improvements in laboratory technology made it possible to see these tiny changes. A University of Wisconsin press release called the research a "huge job.” Many research specialists worked for four years to photograph, rebuild and study certain areas of a mouse brain. The report also said the scientists measured 6,920 synapses.Cirelli says they found that our synapses shrink as our brains clean themselves during sleep. We wake up refreshed and ready to fill those synapses with new information. The research findings are the result of years of hard work at the University of Wisconsin Madison. The researchers published their findings in the journal Science.32. How does the brain help improve our memory while we are sleep?A. By not forgetting any learnt knowledge.B. By keeping learning new information.C. By repeating information learnt before.D. By adding new knowledge to its old collection.33. What is the fifth paragraph mainly about?A. The size for the synapses.B. The preparations for the measuring work.C. The difficulties in the measuring work.D. The result of the measuring work.34. What can we infer about the research work?A. The synapses were found bigger after a good night’s sleep.B. The researchers carried out their work with a human brain.C. The team began their research as soon as they decided to.D. The findings proved their hypothesis was right.35. What is the result of the research?A. Sleep helps us keep healthy.B. Sleep helps us learn better.C. Sleep helps the brain shrink.D. Sleep takes one-third of our lifetime第二节(共5小题,每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

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