2019届秋季上学期高二语文8月月考试题(含解析) (333)
2019届秋季上学期高二语文8月月考试题(含解析) (805)
专题十四英语标识语的使用1.[2019原创]Which of the following public signs is correct in English?A. B.C. D.2.[2019原创]Which of the following public signs is correct in English?A. B.C. D.3.[2019原创]Which of the following public signs is correct in English?A. B.C. D.4.[2019原创]Which of the following public signs is correct in English?A. B.C. D.5.[2019原创]Which of the following public signs is correct in English?A. B.C. D.6.[2019原创]Which of the following public signs is correct in English?A. B.C. D.7.[2019原创]Which of the following public signs is correct in English?A. B.C. D.8.[2019原创]Which of the following public signs is correct in English?A. B.C. D.9.[2019原创]Which of the following public signs is correct in English?A. B.C. D.10.[2019原创]Which of the following public signs is correct in English?A. B.C. D.【参考答案】1.D 【解析】本题考查公共标识。
2019届秋季上学期高二语文8月月考试题(含解析) (1138)
9大语法难点（1）一、宾语从句1.宾语从句的含义充当主句宾语的从句叫做宾语从句。
如：She knew that the teacher had se en the film.她知道这位老师看过这部电影。
“that the teacher had seen the film”做 knew 的宾语，同时又是由连接词 that 引导的从句，所以它叫做宾语从句。
2. 宾语从句的分类（1）动词宾语从句：顾名思义，它是位于动词后面的宾语从句。
如：He asked whose handwriting was the best in our class．他问我们班上谁的书法最好。
（2）介词宾语从句：顾名思义，它是位于介词后面的宾语从句。
如：I agree with what you said just now.我同意你刚才说的话。
（3）形容词宾语从句：顾名思义，它是位于形容词后面的宾语从句。
如：I am afraid that I will be late. 恐怕我要迟到了。
3. 引导宾语从句的连接词（1）that：没有含义，在宾语从句中不做成分（2）whether/if：表示是否，在宾语从句中不做成分。
I don't know if /whether he still lives h ere after so many years. 我不知道这么多年后，他是否还住在这里。
（3）连接代词：what, which, who, whom, whose（在宾语从句中做主、宾、表和定语）连接副词：where, when, how, why（在宾语从句中做状语）The small children don't know what is in their stockings．（what 在宾语从句中做主语）这些小孩子不知道什么在他们的长筒袜里。
Could you tell me why you were late for the meeting this morning？（why 在宾语从句中做原因状语）你能告诉我为什么你今天早上开会迟到吗？4. 在做宾语从句的题目时应注意两点（1）时态：①当主句是现在时态时，宾语从句可以根据需要使用任何时态。
2019届秋季上学期高二语文8月月考试题(含解析) (308)
河北武邑中学2018-2019学年上学期高二年级第一次月考历史试题一、选择题（本大题共25小题，每小题2分，共50分）1.“商人们通过电报和海底电缆追踪明尼阿波利斯、利物浦、布宜诺斯艾利斯和格但斯克的小麦价格，他们到最便宜的地方去买，到最贵的地方去卖。
这样，世界小麦的供应大体上就按照需求和支付能力来进行供应。
”这一现象说明A. 科技进步促进农产品价格明显下降B. 垄断产生克服了生产的无计划性C. 通讯革新推动了世界市场形成D. 农产品成为世界市场主要商品【答案】C【解析】“电报和海底电缆”是第二次工业革命时期发明，“到最便宜的地方去买，到最贵的地方去卖”说明通讯工具的革新导致世界市场的最终形成，故C项正确；材料说明是世界市场发展问题，农产品价格上升和下降与市场需求有关，故A项错误；垄断组织不是材料体现的主要信息，故B项错误；材料中农产品只是举例子，不能说明农产品成为世界市场主要商品，故D项错误。
2.老舍的著名话剧《茶馆》中有一位秦二爷，他在19世纪末致力于投资近代工业，他的理想是要“顶大顶大的工厂！那才救得了穷人，那才能抵制外货，那才能救国！”他也确实创办了一些实业，1916年前后，他创办的企业最为红火，其原因不包括A. 清政府放宽了对民间设厂的严格限制B. 辛亥革命后为资本主义扫除一些障碍C. 一战期间列强放松了对中国的经济侵略D. 实业救国思潮及反帝爱国运动的推动【答案】A【解析】1916年，清政府已被推翻，民国建立，中国民族工业处于发展的黄金时期，A项说法错误，符合题意。
其他三项均符合本阶段民族资本主义发展的原因。
故答案选A。
3.有西方学者认为：“近代世界赖以建立的种种发明与发现可能有一半来源于中国”。
传入欧洲并对“近代世界”的到来产生了重大影响的中国科技成就是A. 地动仪B. 造纸术C. 雕版印刷术D. 罗盘针【答案】D【解析】【详解】根据材料可知，宋朝时指南针用于航海，它传入欧洲以后，促进新航路开辟，加强了世界各地之间的联系，D项正确。
2019届秋季上学期高二语文8月月考试题(含解析) (502)
河南省滑县2019届高三数学第二次联考试题文（扫描版）2018—2019学年高三年级调研考试（二）数学（文科）参考答案1.【答案】B【解析】依题意，{}{}232,1,0,1,2Z A x x =∈-≤<=--，故{}0,2A B =，故选B.2.【答案】A 【解析】依题意，()()()()24i 13i 24i 26i 4i 121010i1i 13i 13i 13i 1010--------====--++-，故选A. 3.【答案】D【解析】依题意，131********n n ⎡⎤⎛⎫-⎢⎥⎪⎝⎭-⎢⎥⎣⎦=--，化简可得2log 6n =，故[]2n =，则第2日蒲生长的长度为D. 4.【答案】C【解析】运行该程序，第一次，999,2S k ==；第二次，995,4S k ==；第三次，979,6S k ==；第四次，915,8S k ==；第五次，659,10S k ==，第六次365,12S k =-=，此时0S <，故输出的k 的值为12，故选C. 5.【答案】B【解析】A 班学生的分数多集中在[70,80]之间，B 班学生的分数集中在[50,70]之间，故A B x x >；相对两个班级的成绩分布来说，A 班学生的分数更加集中，B 班学生的分数更加离散，故22A B s s <，故选B.6.【答案】A【解析】依题意，()()()()55255550550mn m n m n n m n ->-⇔--->⇔-->5,5,5,5,m m n n ><⎧⎧⇔⎨⎨><⎩⎩或故“2216m n +<”⇒“5525mn m n ->-”，反之不成立，例如6m n ==；故“2216m n +<”是“5525mn m n ->-”的充分不必要条件，故选A. 7.【答案】C【解析】作出该几何体1111ABCD A B C D -的直观图，旋转一定的角度后，得到的图形如下图所示，观察可知，1CA =1A D =，1A B = C.8.【答案】B【解析】依题意，不妨设点M （x,y ）在第一象限，联立225,,x y by x a ⎧+=⎪⎨=⎪⎩解得,x c y ⎧=⎪⎪⎨⎪=⎪⎩（其中222b a c +=），可知四边形MNPQ为矩形，且根据双曲线的对称性，2c c ⋅=，即225c ab =，解得12b a =（2b a=舍去），故所求渐近线方程为12y x =±，故选B. 9.【答案】D【解析】依题意，函数()f x 为偶函数，故1k =-，则()()320g k x g x ++-+=即为()()132g x g x -++-=-，故函数()g x 的图象的对称中心为()1,1-，故选D.10.【答案】A【解析】依题意，()()()3sin 32sin 33f x x x x πϕϕϕ⎛⎫=-+-=-+ ⎪⎝⎭，则()333Z k k ππϕπ⨯-+=∈，则()43Z k k πϕπ=-∈；因为2πϕ<，故3πϕ=，故()2sin 3f x x =，则将函数()f x 的图象向右平移6π个单位长度 后得到函数()2cos3g x x =-的图象，故选A. 11.【答案】B【解析】依题意，当0x ≥时，()()2'1212121f x x x x x =-=-，故当()0,1x ∈时，()'0f x <，当()1,x ∈+∞时，()'0f x >，且()11f =-，作出函数()f x 的大致图象如下所示；令()()()22320g x f x f x =--=⎡⎤⎣⎦，解得()()122f x f x ==-或，观察可知，函数()g x 共有3个零点，故选B.12.【答案】A【解析】设()00,M x y ，()11,N x y ，则直线MA 1的斜率为1003MA y k x -=，由11NA MA ⊥，所以直线NA 1的斜率为1003NA x k y =--．于是直线NA 1的方程为：0033x y x y =-+-．同理，NA 2的方程为：0033x y x y =--+．联立两直线方程，消去y ，得20109y x x -=． 因为()00,M x y 在椭圆221189y x +=上，所以22001189x y +=，从而2292x y -=-．所以012x x =-． 所以1212012MA A NA A S x S x ∆∆==，故选A. 13.【答案】322-或【解析】依题意，()4212m m +⋅=，解得322m =-或. 14.【答案】5【解析】作出不等式组所表示的平面区域如下图阴影部分所示，观察可知，当直线2z x y =-过点55,33A ⎛⎫- ⎪⎝⎭时，2z x y =-取最大值，最大值为5.15.【答案】108【解析】依题意，不妨设2AB =，故所求概率22224P ππ⨯⨯+⨯⨯==.16.【解析】因为()sin sin 4sin sin ABC b a A b B B S bc C ∆+=⋅+，故2sin sin 4sin sin ABC ab A b B B S bc C ∆+=⋅+，即222sin sin 4sin sin ABC a B b B B S c B ∆+=⋅+，即2224ABC a b c S ∆+-=，故cos sin ab C ab C =，故4C π=，则△ABC的外接圆半径为2sin c C ==.17.【解析】（1）依题意，设BD x =，则AD =，3BC x =,又,43B AB π==.在△ABD 中，由余弦定理得3cos4216322π⋅⋅-+=x x x ，即2280x x +-=，解得2x =，或4-=x （舍去）. 则36BC x ==；（5分）（2） 在△ ABC 中，设A,B,C 所对的边分别为a,b,c ， 由正弦定理sin sin b c B C=，得sin sin c B C b ==又AC b AB c =>=，所以B C >，则C为锐角，所以cos 3C =则()1sin sin sin cos cos sin 2BAC B C B C B C ∠=+=++=.（10分） 18.【解析】（1）依题意，设等差数列{}n a 的公差为d ，则4224d a a =-=，解得2d =，故11a =，21n a n =-，而236m mS S +=+，则214436m m a a m +++=+=，解得8m =，故32424232425762m S S ⨯==+⨯=；（6分）（2）因为21n a n =-，故()()+1211111212322123n n a a n n n n +⎛⎫==- ⎪++++⎝⎭，故()111111111...23557792123323n nT n n n ⎛⎫=-+-+-++-= ⎪+++⎝⎭.（12分） 19.【解析】（1）依题意 ，所求平均数为20.260.36100.28140.12180.04⨯+⨯+⨯+⨯+⨯ 0.4 2.16 2.8 1.680.727.76=++++=；（3分） （2）依题意，完善表中的数据如下所示：故()222000800600200400333.3310.828100010001200800K ⨯⨯-⨯=≈>⨯⨯⨯；故有99.9%的把握认为“愿意购买该款电视机”与“市民的年龄”有关；（7分）（3）依题意，使用时间在[)0,4内的有1台，记为A ，使用时间在[]4,20内的有4台，记为a,b,c,d ，则随机抽取2台，所有的情况为（A ，a ），（A ，b ），（A ，c ），（A ，d ），（a ，b ），（a ，c ），（a ，d ），（b ，c ），（b ，d ），（c ，d ），共10种，其中满足条件的为（a ，b ），（a ，c ），（a ，d ），（b ，c ），（b ，d ），（c ，d ），共6种，故所求概率63105P==.（12分）20.【解析】（1）作出平面EFG 的图形如下所示，点G 为线段SB 上靠近B 点的三等分点；C（5分）（2）依题意， 因为0090,45SDA SAD ∠=∠=，故SD AD ==而2SA SB ==，所以222SB SD BD =+， 所以SD BD ⊥，又因为DADB D =，所以SD ABCD ⊥平面；因为SD ⊂平面SCD，所以平面SCD ABCD ⊥平面． 作'EE CD ⊥于'E ，因为平面=SCDABCD CD 平面，所以'EE ⊥平面SCD ；又因为//EF SCD 平面，所以'EE 即为F 到平面SCD 的距离．在△ABD 中，设AB 边上的高为h ，则h =，因为23ED EC BD AC ==，所以2'3EE h ==，即F 到平面SCD（12分）21.【解析】（1）依题意，直线l ：28y x =+，联立22,28,x y y x ⎧=⎨=+⎩故24160x x --=，设11(,)M x y ，22(,)N x y ，则124x x +=，1216x x =-，故1220MN x =-==；（5分）（2）联立0,40,x y x y -=⎧⎨+-=⎩解得2x y ==，故()2,2A ，设直线l 的方程为：4(2)y k x -=+，11(,)M x y ，22(,)N x y ， 则11112(2)222AM y k x k x x -++==--，22222(2)222AN y k x k x x -++==--， 212121212121212[(2)2][(2)2][2()4]2(4)4(2)(2)2()4AM ANk x k x k x x x x k x x k k x x x x x x +++++++++++==---++， 联立抛物线22x y =与直线4(2)y k x -=+的方程消去y 得22480x kx k ---=，可得122x x k +=，1248x x k =--，代入AM AN k k ⋅可得1AM AN k k ⋅=-.（12分）22.【解析】（1）依题意，()0,x ∈+∞，()221'222x mx f x x m x x++=++=⋅，若22m -≤≤，则210x mx ++≥，故()'0f x ≥，故函数()f x 在()0,+∞上单调递增；当22m m <->或时，令210x mx ++=，解得12xx ； 若2m >0<0<，故函数()f x 在()0,+∞上单调递增； 若2m <-，则当x ⎛∈⎝⎭时，()'0f x >，当x ∈⎝⎭时，()'0f x <，经典资料经典资料（一）当x ⎫∈+∞⎪⎝⎭时，()'0f x >； 综上所述；当2m ≥-时，函数()f x 在()0,+∞上单调递增；当2m <-时，函数()f x在⎛ ⎝⎭和⎫+∞⎪⎝⎭上单调递增，在⎝⎭上单调递减；（6分） （2）题中不等式等价于2222ln 2e 3x x mx x x ++≤+，即2e ln x x x mx -+≥， 因此2e ln x x x m x -+≥，设()2e ln x x x h x x-+=，∴ ()'10h =，当)1,0(∈x 时，()2e 1ln 10x x x x -++-<，即0)('<x h ，)(x h 单调递减； 当),1(+∞∈x 时，()2e 1ln 10x x x x -++->，即0)('>x h ，)(x h 单调递增； 因此1=x 为)(x h 的极小值点，即1)1()(+=≥e h x h ，故e 1m ≤+， 故实数m 的取值范围为(],e 1-∞+.（12分）。
2019届秋季上学期高二语文8月月考试题(含解析) (533)
淇滨高中2018-2019学年上学期第一次月考高一数学试卷考试时间：120分钟注意事项：1．答题前，先将自己的姓名、准考证号填写在试题卷和答题卡上，并将准考证号条形码粘贴在答题卡上的指定位置。
2．选择题的作答：每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，写在试题卷、草稿纸和答题卡上的非答题区域均无效。
3．非选择题的作答：用签字笔直接答在答题卡上对应的答题区域内。
写在试题卷、草稿纸和答题卡上的非答题区域均无效。
一、单选题（每题5分，共60分）1．已知集合{|20}A x x =-<，{}1,2,3B =，则A B =（ ）A ．{}1,2,3B ．{}1C ．{}3D ．∅2．设集合{}=1,2M ，则满足条件{}=1,2,3,4M N 的集合N 的个数是（ ）A ．1B ．3C ．2D ．43.A B C D4．下列函数中，在()0,2上为增函数的是（ ） A ．32y x =-+B ．3y x=C ．245y x x -=+D ．23810y x x +=- 5．若奇函数()f x 在[]3,7上是增函数，且最小值是1，则它在[7,3]--上是（ ） A ．增函数且最小值是1- B ．增函数且最大值是1- C ．减函数且最大值是1-D ．减函数且最小值是1-6．已知集合{|P x y ==，集合{|Q y y =，则P 与Q 的关系是（ ） A ．P Q = B ．P Q ⊆ C ．P Q ⊇ D ．P Q =∅7.已知()5412-+=-x x x f ，则()x f 的表达式是（ ）A ．()x f =x x 62+ B ．()x f =782++x xC ．()x f =322-+x x D ．()x f =1062-+x x8．已知函数()2f x x bx c =＋＋的图象的对称轴为直线x ＝1，则（ ） A ．()()1(12)f f f <<- B ．()()12()1f f f <<- C ．()())211(f f f -<<D ．()())112(f f f -<<9．图中的图象所表示的函数的解析式为（ ）A ．()10322y x x =-≤≤ B ．()1232032y x x --=≤≤ C ．()10232y x x =-≤≤- D ．()1012y x x =-≤≤-10．已知()()121,2111,2x x x f x f x +≥⎧-<⎪⎪⎨⎪-⎪⎩＝，则1746f f ⎛⎫⎛⎫+= ⎪ ⎪⎝⎭⎝⎭（ ） A ．16-B ．16C ．56 D ．56-11．函数()y f x =是R 上的偶函数，且在(]0-∞，上是增函数，若()()2f a f ≤， 则实数a 的取值范围是（ ）A ．2a ≤B ．2a ≥-C ．22a -≤≤D ．22a a ≤-≥或12．已知()32f x x =－，()22g x x x =－，()()()()()()(),,g x f x g x F x f x f x g x ⎧⎪≥<⎨⎪⎩＝若若，则()F x 的最值是 （ ）A ．最大值为3，最小值1- B．最大值为7- C ．最大值为3，无最小值 D ．既无最大值，又无最小值 二、填空题（每题5分，共20分）13. 已知集合A ＝{0,1,2}，则集合B ＝{x －y |x ∈A ，y ∈A }中元素的个数是_______.14．有15人进家电超市，其中有9人买了电视，有7人买了电脑，两种均买了的有3人，则这两种都没买的有________人．15．若函数()f x 的定义域为[12]-，则函数2(3)f x -的定义域为________．16．函数2y x =+的值域为________．三、解答题（17题10分，18-22题每题12分，共70分）17．（10分）已知全集U =R ，集合{}|4A x x =>，{|66}B x x =-<<． (1)求AB 和A B ；(2)求U B ð；18.（12分）已知集合A ＝{x |－2≤x ≤7}，B ＝{x |m ＋1<x <2m －1}． (1)当m=3时，求AB .(2)若B ⊆A ，求实数m 的取值范围.19．（12分）已知函数()211x f x x ++＝． (1)判断函数()f x 在区间[1,)+∞上的单调性，并用定义证明你的结论； (2)求该函数在区间[1]4，上的最大值与最小值．20.（12分）已知f (x )是一次函数，且满足f (3x )=2 f (x )+2x+1，求(1) f (x )的解析式.(2)若g (x )=x f (x ),求g (x )的最小值.21.（12分）已知函数222,0()0,0,0x x x f x x x mx x ⎧->⎪==⎨⎪-+<⎩是奇函数.(1)求实数m 的值；(2)若函数f (x )在区间[3,2]a a --上单调递增，求实数a 的取值范围.22．（12分）定义在R 上的函数f (x )，满足当x >0时，f (x )>1，且对任意的x ，y ∈R ，有()()()·f x y f x f y +＝，f (1)＝2．(1)求f (0)的值；(2)求证：对任意x ∈R ，都有f (x )>0； (3)解不等式f (3-2x )>4．高一数学答案1-12．B D.C.D. B ．C.A ．B ．B ．A ．D.B13. 5 14. 2 15． 1,22⎡⎤⎢⎥⎣⎦ 16. (]4-∞，17．（1）{|46}A B x x =<<，{}|6AB x x =>-；（2）{|66}U B x x x =≥≤-或ð；18. 解析：(1)当m=3时，B ＝{x |4<x <5}，{|45}A B x x =<< (2)当B ＝∅时，有m ＋1≥2m －1，则m ≤2；当B ≠∅时，∵B ⊆A ，如图．则⎩⎪⎨⎪⎧m ＋1≥－2，2m －1≤7，m ＋1<2m －1，解得2<m ≤4. 综上，m 的取值范围为m ≤4，19．【解析】（1）函数()f x 在[1,)+∞上是增函数． 证明:任取12,[,)1x x ∈+∞，且12x x <,则()()()()121212121221211111x x x x f x f x x x x x ++--=+++=+-． 易知120x x -<，12()11(0)x x ++>，所以()()120f x f x -<，即()()12f x f x <， 所以函数()f x 在[1,)+∞上是增函数．（2）由（1）知函数()f x 在[1]4，上是增函数， 则函数()f x 的最大值为()945f =，最小值为()312f =．20.(1)设，则由，得，即，所以，解得.所以.(2)，则.21. （1）∵函数是奇函数；∴，.（2）由（1）知如图 当时，,∴当时，单调递减；当时，单调递增.当时，，∴当时，单调递减；当时，单调递增. 综上：函数在上单调递增.又函数在区间上单调递增.∴或，解得故实数的取值范围是.22．【解析】（1）对任意x ，y ∈R ，()()()·f x y f x f y +＝． 令x ＝y ＝0，得f (0)＝f (0)·f (0)，即f (0)·[f (0)-1]＝0． 令y ＝0，得f (x )＝f (x )·f (0)，对任意x ∈R 成立， 所以f (0)≠0，因此f (0)＝1．（2）证明：对任意x ∈R ，有2·2222()()02x x x x x f x f f f f ⎡⎤⎛⎫⎛⎫⎛⎫===≥ ⎪ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎝⎭⎣⎦+． 假设存在x 0∈R ,使f (x 0)＝0,则对任意x >0,有f (x )＝f [(x -x 0)＋x 0]＝f (x -x 0)·f (x 0)＝0． 这与已知x >0时，f (x ) >1矛盾．所以，对任意x ∈R ，均有f (x )>0成立． （3）令x ＝y ＝1有f (1+1)＝f (1)·f (1)，f (2)＝2×2＝4．任取x 1，x 2∈R ，且x 1<x 2，则f (x 2)－f (x 1)＝f [(x 2-x 1)＋x 1]-f (x 1)＝f (x 2-x 1)·f (x 1) -f (x 1)＝f (x 1)·[f (x 2-x 1)-1]． ∵x 1<x 2，∴x 2-x 1>0，由已知f (x 2-x 1)>1，∴f (x 2-x 1)-1>0． 由（2）知x 1∈R ，f (x 1)>0．所以f (x 2)-f (x 1)>0，即f (x 1)<f (x 2)． 故函数f (x )在(,)-∞+∞上是增函数．由f (3-2x )>4，得f (3-2x )>f (2)，即3-2x >2．解得x <12． 所以，不等式的解集是1,2⎛∞-⎫ ⎪⎝⎭．经典资料淇滨高中2018-2019学年上学期第一次月考高一数学答题卷考号 ______________ 姓名______________班级______________ 一．选择题（用2B 铅笔涂黑选项每题5分共60分） 考生须知1、 考生答题前，在规定的地方准确填写考号和姓名。
2019届秋季上学期高二语文8月月考试题(含解析) (234)
河北省邢台市内丘中学等五校2017-2018学年高二语文下学期3月月考试题一、现代文阅读（35分）（一）论述类文本阅读（本题共3小题，9分）阅读下面的文字，完成1-3小题。
从“抵制韩流”看消费型民族主义梁文道韩剧风猛烈吹袭大陆后，就有很多人看不过去要出来说话，这种事我们大可以引为茶余饭后的闲谈话题，一笑置之。
但是我们也应认真思索，为什么我们可以这么轻易地把爱韩剧就等于汉奸、看国产片就等于爱国的逻辑理直气壮地宣之于口，而且竟还有市场？很多人之所以能够不假思索地说出这种话，是因为近年有一股更大的潮流，这股潮流就是“消费型民族主义”。
首先，我们要注意它与抵制日货的理路不尽相同。
不管你同意与否，提倡抵制日货的人至少还试图搬出一套罢买日货可以打击日本商界，然后日本企业会抱怨日本政府外交政策的推理。
“消费型民族主义”却是诉诸感情直觉，要大家以抵制某产品的方式直接表达爱国情怀。
当然，实际操作起来，“消费型民族主义”又会和抵制日货运动相混杂，成为后者的指导精神。
其次，“消费型民族主义”不是一种经济政策上的保护主义。
奉行保护主义的国家如韩国，会硬性规定电影院每年要有一定日数放映韩片，以保证电影生产数量的稳定，以阻挡外来电影带来的竞争压力，目的是扶持自己国家的特定产业。
保护政策好还是不好，各有各的观点，但它起码也是套言之成理的说法。
“消费型民族主义”着眼的却不是这么深层次的产业发展问题，它只不过是一种浮浅的情绪表达和标签。
“消费型民族主义”的出现，靠的是两种逻辑。
一个是民族主义本身的空洞，另一个是市场营销的文化转向。
什么叫民族主义的空洞呢？难道民族主义不是很强大很澎湃的一种意识形态吗？的确，它是的。
但它之所以强大，之所以能够把一切事物都纳在民族旗号下，照研究民族主义的人类学家安德森的说法，正是因为它的内涵是空的。
举个例子，由于没有人能够肯定到底某物的民族性是什么，所以我们才能把一件衣服说成是很有民族性的，一部汽车是很民族的，甚至连一种动物也是很能代表某民族的（尽管他在血统上和这一民族无关，也不是这一民族培育出来的品种），没有什么不可以被命名为很民族的。
2019届秋季上学期高二语文8月月考试题(含解析) (1115)
化学部分A卷：7．C 8．D 9．D 10．A 11．B 12． C 13．BB卷：7．B 8．D 9．B 10．A 11．C 12．C 13．B26. (15分)(1)D→B→C→B (2分)(2)硬质玻璃管 (2分)(3) 5NO+3MnO4－+4H+=5NO3－+3Mn2++2H2O (2分)(4)60% (2分)(5)②淀粉溶液 (1分)加入最后一滴液体时，锥形瓶内溶液恰好从蓝色变为无色，且维持半分钟不变色(2分) ③56.6% (2分) ④BD(2分)27．(14分)(1)Bi2S3+6Fe3＋=2Bi3＋+6Fe2＋+3S (2分)抑制溶液中Bi3＋的水解(2分) SiO2(2分)(2)过滤、洗涤、干燥(2分)28. (14分)(1)CO2(g)+3H2(g)=== 1/2C2H4(g)+2H2O ΔH=－(b－a) kJ/mol(2分)(其它合理答案均得分)(2)负 (1分) 4OH――4e－=O2↑+2H2O或2H2O―4e－=O2↑+4H+(2分)(3)①Ir (1分) ②d和e(2分)，＜(2分)③状态a和c均未达到平衡，状态c温度高反应速率快，CO2的转化量大，转化率高；(2分)④62527（或23.15）(2分)35．【化学－物质结构与性质】 (15分)3d4s分) d (1分)(2)①具有孤电子对(或孤对电子) (2分)②sp 3(1分) 8N A (2分) ③CN －或C 22－或NO +(2分)(3)从锰到铼原子序数增大，核对外层电子引力增大，电子层数增多，核对外层电子引力减小，但前者占主导，所以铼中的金属键更强，熔点更高 (2分) (4)6 (1分) 234(3.74×10－8)3×N A(2分)36．【化学——选修5：有机化学基础】(15分) (1)－ CH 3(2分)(2)取代反应(1分) －CHO(1分) (3)乙醛(2分)(4)O － CCH 2CHHOCHCH 222C －OO+ 2H 2O(2分)(5)10 (2分)CHC H 2CHO OH或或HOCH 2CHCHOOHCHCHOHOCH 2 (2分)HCHOH 2Cu/O 2ΔΔ3CH 2OHCH 3CH 3CH 2ClNaOH/H 2 OCH 2－CH 2－CH 2OHOHHOCH 2CH 2 CHO（3分）（6）。
2019届秋季上学期高二语文8月月考试题(含解析) (773)
词汇拓展
1.begin(v.)→(过去式)→(过去分→(adv.)在很大程度上;大量地
3.sudden (adj.)→(adv.)突然;忽然
4.strange (adj.)→(n.)陌生人
5.wind (n.)→(adj.)多风的
6.report (v.& n.)→(n.)记者
7.wood (n.)→(adj.)木制的
8.beat (v.)→(过去式)→(过去分词)敲打;打败
9.sleep (v.)→(adj.)睡着的→(adj.)困倦的;瞌睡的
1.began; begun; beginning2.heavily3.suddenly 4.stranger5.windy6.reporter7.wooden 8.beat; beaten9.asleep; sleepy10.rose; risen 11.fell; fallen; pletely14.silent 15.truth; truly16.weakness17.hid; hidden
15.true(adj.)→(n.)实情;事实→(adv.)真正;确实
16.weak (adj.)→(n.)软弱;弱点;不足
17.hide (v.)→(过去式)→(过去分词)隐藏;隐蔽
18.excite(v.)→(adj.)激动的;兴奋的→(adj.)使人兴奋的,令人激动的→(n.)激动;兴奋
19.marry (v.)→(n.)婚姻;婚礼→(adj.)已婚的
20.shine (v.)→(过去式/过去分词)发光;照耀
21.lead (v.)→(过去式/过去分词)带路;领路→(n.)领导;领袖
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开封市第二十五中学高一年级月考试题（2018年10月）英语（考试时间：120分钟试卷满分：150分）注意事项：1.答题前，考生务必将自己的班级、姓名、考场号和座位号填写在答题卡上的指定位置。
2.回答选择題时，选出每小题答案后，用铅笔把答题卡对应題目的答案标号涂黑。
如需改动，用橡皮檫干净后，再选涂其他答案标号。
回答非选择题时，将答案写在答题卡上。
写在本试卷上无效。
第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。
录音内容结束后，你将有2分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is the shirt?A. £19.15.B. £9. 18.C. £9.15.答案是C。
1. What will the woman do first?A. Walk the dog.B. Surf some websites.C. Buy a new computer.2. What is the weather like during the weekend?A. Cold.B. Hot.C. Warm.3. What are the speakers doing?A. Watching TV.B. Making a film.C. Visiting a zoo.4. What does the woman think the man should listen to?A. Music.B. Study tapes.C. News.5. What are the speakers mainly talking about?A. When to eat.B. Where to eat.C. Whom to eat with.第二节 (共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；读完后，各小题给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6. What does the woman say about the homeless guy?A. He seems to be in need of help.B. He is so careful with money.C. He should find a job to support himself.7. What kind of person is the man probably?A. Kind.B. Careful.C. Hard-working.听第7段材料，回答第8至10题。
8. What does the woman think of the skirt?A. Attractive.B. Out of fashion.C. Too short.9. Why does the man allow the woman to wear the skirt?A. The skirt is really in fashion.B. The woman's friend is wearing the same skirt as hers.C. Her mum agrees to it.10. What is the probable relationship between the speakers?A. Friends.B. Father and daughter.C. Teacher and student.听第8段材料，回答第11至I3题。
11. What will the man do?A. Look for a new job.B. Visit the woman.C. Teach English.12. Which country is the man going to?A. Korea.B. China.C. Australia.13. How will the man spend his Christmas this year?A. By holding a party.B. By putting on a play.C. By practicing singing.听第9段材料，回答第14至17题。
14. What is the good news to the speakers?A. They will join a film club.B. The head teacher will run a club.C. They're allowed to start a club.15. What is the name of the club?A. Film Club.B. Our Super Film Club.C. Super Film Club,16. Who are allowed to join the club?A. Students from Grade 4 and Grade 6.B. Students from Grade 5 and Grade 7.C. Students from Grade 1 to Grade 3.17. What activity will he provided for the club members?A. Seeing films after school.B. Learning to make films.C. Visiting film studios on weekdays.听第10段材料，回答第18至20题。
18. Which competition was held, in the school last year?A. Singing Competition.B. Dancing Competition.C. Reading Competition.19. What is the purpose of the Pet’s Competition?A. To help students select pets.B. To put a love of animals in students with theory.C. To tell students loving animals is important.20. What does the speaker suggest the students do?A. Write down what happens during the competition.B. Take their dogs to the Pet’s Competition.C. Join other educational and funny events.第二部分阅读理解（共两节；满分40分）第一节(共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项，并在答题卡上将该项涂黑。
ASeaside TravellingDate： Sunday, October 29 , 2017Time： 9:30 a.m.—1:30 p.m.Leader ：George Green (0409 …413 - 945)Meet at Rushall Station, North Fitzroy, for 9:30 a.m. leaving on social ride to Port Melbourne ? and back along bike paths, a rail trail and bike lanes. Returning at about 1:30 pm. About 30 km. Newport Lakes Bike PathDate ： Wednesday T November J，2017Time : 9:30 a.m.—3:30 p.m.Leader： Jopie Bodegraven (0423 -151 -767)I discovered the quite new Sunshine to Footscray bike path recently plus a nice part through Newlands Paddock and this ride includes both. Meet at Newport Lakes，lunch at Buckingham Reserve on Kororoit Creek and finally, reach our haunt（地方）in Kensington. About 51 km.Maribyrnong TrailDate： Friday, November 3, 2017Time： 9:30 a.m.—3:00 p.m.Leader： Chris Walsh (0412 -878 -491)A nice flat ride. Travel via Docklands then out along the Maribyrnong for lunch，returning via Kensington. About 40 km.Jells ParkDate： Sunday, October 22 , 2017Time： 8:50 a.m.—3 :50 p.m.Leader： Paul Sierak (0409 - 381 -342)Catch the 8:56 am train from Westgarth for Jolimont then Richmond to Ringwood. From there riding to Jells Park for lunch. After lunch wandering along the Blind Creek bike paths to Boronia station and train back to Camberwell/Richmond/Flinders Street. About 45 km.21. Who discovered a new bike path?A. George Green.B. Chris Walsh.C. Jopie Bodegraven.D. Paul Sierak.22. Which ride will take the longest time?A. Seaside Travelling.B. Newport Lakes Bike Path.C. Maribyrnong Trail.D. Jells Park.23. If you want to do a flat ride, you may go on _______A. Friday, November 3，2017B. Wednesday, November 1, 2017C. Sunday，October 22, 2017D. Sunday, October 29 , 2017BIt all started when I was 11 years old, when I had just got into the school. Everything was all right at the beginning and I even made a few friends.A few months later, however the school decided to organize a completely new class in order to make the classes smaller, because obviously that helped with learning and getting rid of bullying(消除欺凌). Yeah，that’s right !I was chosen to be moved from my old class to the new one. At first it was fine, everyone ignored me, and I was happy to be left alone. Then it started. One day after school a few students from my new class came up to me.“Hi,” a girl called Molly said, “Wanna be friends?”I said "Yes " of course. She laughed and told me that she was sorry but she and her mates couldn’t be friends with " loners " like me.A few more situations like that followed, but soon it turned physical. For a few weeks I was beaten up almost every day after school. When I told the teacher, she said I couldn’t change class and that was final. So I was stuck with those horrible students. I cried myself to sleep every night. But after a few more months of putting up with that, I decided to tell my family. They didn’t do anything at first, but after a while they got tired of me moaning(抱怨)about how I hated school and talked to the head teacher. A week or so after that I was moved to another class. They soon forgot about me.I’m perfectly（完全地；完美的） fine now． I hardly ever cry. And all this happened becauseI told someone who could actually do something.24. The author’s trouble began .A. as soon as she moved into a new schoolB. soon after she moved into a smaller classC. before she got to know a girl called MollyD.when she was about to move into a new school25. What do w e know about the author’s new school?A. It had more girls than boys in the school.B. It had students only from the local area.C. Bullying was common among students in the school.D. It was set up not long before the author moved in.26. What’s the author’s attitude（态度）t owards the school’s decision to make a new class?A. PuzzledB. SupportiveC. DoubtfulD. Unhappy27. When Molly said “Wanna be friends?, she was .A. trying to make fun of the authorB. trying to be friendly with the authorC. interested in making friends with the authorD. trying to get more information about the authorCEven if all goes well for you in high school—you keep your grades up，join in activities and never fall on your face in front of everyone in the dining hall—that time of life still can be hard. There are so many subjects to learn and social activities to join in. But of all different challenges, making good friends might be the most important.Researchers found that those with strong, close relationships with their friends at age 15 were more likely to be healthy and happy later. They have more self-worth(自信）and less anxiety and depressive symptoms (抑郁症状）by early adulthood(人）. Importantly, popularity—explained as lots of people liking you generally, but not closely—wasn't found to have the same advantage as close friends.The researchers followed the 169 teens every year for ten years. They got data in real time from these teens as they grew. Importantly，too, the teens were 58 percent whites, 29 percent African Americans, and 8 percent of different faces, and with families of $40,000 to $59,999 a year.“Our study proves that forming strong close friendships is likely one of the most important pieces of the being well-liked by a large group of teenage social experience,” said Joseph Allen. Why does this matter? Because, as Allen wrote, “For high schoolers, people cannot replace developing deep and supportive friendships. And these experiences stay with us，over and above what happens later. As technology makes it increasingly easy to make many superficial(表面的)friends, spending time and attention in developing close connections（关系）with a few people should be a main concern.”28. According to the study, making good friends at high school will .A. help you believe in yourselfB. help you keep away from anxiety in lifeC. take away your symptoms of depressionD. make you experience more worry29. What do the numbers in paragraph 3 show about the research?A. It costs researchers a lot of money.B. It is scientific.C. It is carried out by teenagers themselves.D. It is made in both America and Africa.30. What can we learn from the last paragraph?A. High schoolers prefer to be liked by strangersB. Friendships have nothing to do with technology.C. True friendship calls for much energy.D. A few people can’t be a social net.31. What might be the best title for the passage?A. Friends Make a Difference to Your LifeB. Close Friendships Can Give You Strength in LifeC. Being Popular at High School Is Really ImportantD. Good High School Friends Add to Your Happiness LaterDDoes handwriting（书写，书法）matter？Not very much，according to many educators. However，scientists say it is far too soon to declare handwriting is not important．New evidence（证据）suggests that the link between handwriting and educational development is deep．Children not only learn to read more quickly when they first learn to write by hand，but they are also better able to create ideas and remember information．In other words，it's not only what we write that matters﹣but how．A study led by Karin James，a psychologist at Indiana University，gave support to that view． A group of children，who had not learned to read and write，were offered a letter or a shape on a card and asked to copy it in one of three ways：draw the image on a page but with a dotted outline （虚线），draw it on a piece of blank white paper，or type it on a computer．Then the researchers put the children in a brain scanner（脑部扫描仪）and showed them the image again．It was found that when children had drawn a letter freehand without a dotted outline or a computer，the activity in three areas of the brain were increased．These three areas work actively in adults when they read and write．By contrast（比较），children who chose the other two ways showed no such effect．Dr．James attributes（把…归于）the differences to the process（过程）of free handwriting：Not only must we first plan and take action in a way but we are also likely to produce a result that is variable．Those are not necessary when we have an outline．It's time for educators to change their mind and pay more attention to children's handwriting．32．What do scientists mean by saying " it is far too soon to declare handwriting is not important"？A．Handwriting is not very important to children．B．Handwriting has nothing to do with education．C．Handwriting should not be ignored at present．D．Handwriting can not be learned in a short time．33．What does "that view" in Para.3 refer to？A．Children read quickly when they write by hand．B．How we write is as important as what we write．C．Children create ideas and remember information．D．A group of students should know what to write．34．In the study led by Karin James, which child’s brain is the most actively?A. The children’s brains were equally active.B. The one who drew the image on a page but with a dotted outline（虚线）.C. The one who typed the image on a computer．D. The one who drew the image on a piece of blank white paper.35. According to the passage，the author obviously giving up handwriting．A．is for B．is against C．is responsible for D．doesn't care about．第二节(共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，并在答题卡上将该项涂黑。