杨浦新王牌-徐汇区高二卷
徐汇新王牌高中补习班之第四周高二学案题

高二英语精品学案(第三周)com高考英语词汇过关测试(P111-120)Class_________Name__________Number__________Score__________ I请写出下列单词的词性和词义(2*10=20分)单词词性词义1.explosive2.intensive3.fertilize4.facilities5.fascinate6.fantastic7.feasible8.flexible9.exploit10.unfavorableII请写出所给短语的中文/英文意思(4*10=40%)1.__________________ 1.百感交集2.be fed up with 2.__________________3.__________________ 3.挑......的毛病4.__________________ 4.以牙还牙5.In the field\area of 5.__________________6.__________________ 6.在很大程度上7.__________________7.勇敢面对8.__________________8.激烈的竞争9.feel one’s way9.__________________10.__________________10.赶时髦III请用所给短语的适当形式填空(5*8=40%)catch one’s eye be fascinated by\at failure to do far fromfor fear of\that fetch sth for sb fall on be faced with1.His performance in the speech competition is satisfactory.2.It will the headmaster to make the decision.3.After a rain,they found themselves a serious flood.4.I the sight that I could not take my eyes off it.5.think in English has made him make little progress in English.6.An interesting article in the newspaper.7.He went into the room on tiptoe waking up the sleeping boy.8.If it is convenient to you,please the parcel me.IV用所给词汇翻译下面句子(5*10=50%)1.他作为一个杰出的科学家而闻名,但他却淡泊名利。
杨浦高中补习机构新王牌高二期末复习一

高二期末复习一(一)阅读下文,完成1—6题。
(17分)艺术世界的空筐结构(节选)(1)艺术世界之所以具有永久的魅力,原因之一,就在于它象纯粹数学一样,具有“空筐”结构的性质。
(2)大家知道,数学是2 + 3 =5这样一门抽象的科学。
例如:“两头牛加三头牛等于五头牛”,“两棵树加三棵树等于五棵树”。
人类第一个伟大的数学家正是从这类具体的事实概括出了这样一个达四海亘古今、囊括宇宙万物的伟大的抽象公式:2 + 3 =5。
它好比是说:“两只空筐加三只空筐等于五只空筐。
”筐子的“空”,是为了能随意装进天地间万物。
如果只能装一样东西,倒不出来,那数学的用处就极有限了。
(3)有趣的是,艺术魅力的源泉之一,也在于它向我们提供了一种“空筐”,其中尤以音乐最为典型。
就是说在一切艺术中,当推音乐“空筐”最“空”,最具有弹性。
如果说,牛顿和爱因斯坦的成就之一,在于他们分别提供了两个伟大的“空筐”:F=mA和E =mC2,那末,贝多芬的成就却在于他向人类文化宝库提供了好几个雄视百代、卓然独立于千古的音乐“空筐”:《英雄》《命运》《田园》和《第九》这四部交响曲。
这些“筐”竟是如此的“空”,它们要求乐队指挥、演奏家和广大听众把各自的内外阅历统统放进去。
因此,有海菲茨的贝多芬,也有梅纽因和小泽征尔的贝多芬,同时还有张三、李四的贝多芬。
(4)20岁欣赏《命运交响曲》,同40岁重聆这部作品时的感受是很不同的——如果你在这20年间,饱受事变,经历了坎坷人生的话——之所以有这种效果,正是因为音乐艺术具有“空筐”性质。
这种性质的音乐心理学基础,便是自由联想。
所谓“空筐”,正是艺术家为万千观众提供的发挥想象力的空间。
爱因斯坦一再强调想象力比知识更重要,这不仅是指理论物理学和数学研究而言,而且也是人们欣赏艺术作品时最重要的素质。
可以说“空筐”是为想象力而设臵的,“空筐”要求万千听众用自己的想象力去进行再创作。
(5)诗歌的“空筐”的性质也是很显著的。
2022-2023学年上海市徐汇区高二上学期期末数学质量检测试题(含解析)

2022-2023学年上海市徐汇区高二上册期末数学质量检测试题一、填空题1.三条互相平行的直线最多可确定____个平面.【正确答案】3【分析】讨论三条直线的位置关系即可得到答案.【详解】解:若三条直线在同一个平面内,则此时三条直线只能确定一个平面,若三条直线不在同一个平面内,则此时三条直线能确定三个平面,所以三条互相平行的直线最多可确定3个平面.故3.2.过点()1,2A 且与直线2310x y -+=平行的直线方程为______.(用一般式表示)【正确答案】2340x y -+=【分析】根据平行关系可设直线方程为230x y D -+=,将点()1,2A 代入求得D ,即得.【详解】设与直线2310x y -+=平行的直线为230x y D -+=,又()1,2A 在直线230x y D -+=上,所以2320D -⨯+=,即4D =,所以所求直线方程为2340x y -+=.故答案为.2340x y -+=3.古希腊数学家阿基米德早在2200多年前利用“逼近法”得到椭圆的面积除以圆周率π等于椭圆的长半轴长与短半轴长的乘积,已知椭圆221273x y +=,则该椭圆的面积为______.【正确答案】9π【分析】根据椭圆方程求出a 、b ,依题意椭圆的面积πS ab =,从而计算可得.【详解】对于椭圆221273x y +=,则a =、b =所以椭圆的面积π9πS ab ==;故9π4.若直线2y x m =+是圆2220x y x y ++-=的一条对称轴,则m =______.【正确答案】2【分析】根据圆的方程求得圆心坐标,代入直线方程,即可求解.【详解】由题意,圆2220x y x y ++-=,可得圆心坐标为1(,1)2-,把圆心1(,1)2-代入直线2y x m =+,可得112()2m =⨯-+,解得2m =.故答案为.25.已知圆柱的底面直径和高都等于球的直径,圆柱的体积为16π,则球的表面积为______.【正确答案】16π【分析】设球的半径为r ,根据圆柱的体积可求得r ,利用球的表面积公式即可求得答案.【详解】设球的半径为r ,则圆柱的底面直径和高皆为2r ,故圆柱的体积为2π216π,2r r r ⨯=∴=,故球的表面积为24π16πr =,故16π6.如图,在长方体1111ABCD A B C D -中,设11AA =,2AB =,3AD =,则11CC BD -=______.【分析】根据长方体的结构特征,结合空间向量减法的几何意义及已知条件,求目标向量的模即可.【详解】由111111CC BD BB BD D B DB -=-====7.一条沿直线传播的光线经过点()2,6P -和()1,4Q -,然后被直线10x y +-=反射,则反射光线所在直线方程为______(用一般式表示)【正确答案】210x y +-=【分析】根据题意,先得到PQ 所在直线方程,然后联立两直线方程得到入射点M 坐标,再求得点()1,4Q -关于直线10x y +-=的对称点N 的坐标,即可得到反射光线MN 的直线方程.【详解】由题意可得PQ 所在直线方程为:()644121y x --=+-+,即220x y +-=,联立直线方程22010x y x y +-=⎧⎨+-=⎩,解得入射点()1,0M ,设点()1,4Q -关于直线10x y +-=的对称点为(),N x y 则()4111141022y x x y -⎧⨯-=-⎪⎪+⎨-++⎪+-=⎪⎩,解得32x y =-⎧⎨=⎩,所以()3,2N -,即反射光线MN 方程为:()2131y x =---,即210x y +-=故答案为:210x y +-=8.直线10x y ++=分别与x 轴,y 轴交于A ,B 两点,点P 在圆()2222x y -+=上,则ABP 面积的取值范围是______.【正确答案】15,22⎡⎤⎢⎥⎣⎦【分析】首先由直线方程求得,A B 坐标,得到AB ;利用点到直线距离公式求得圆心到直线AB 的距离1d ,从而得到点P 到直线距离2d 的范围,利用三角形面积公式可求得结果.【详解】由题意得:()1,0A -,()0,1B-AB ∴=由圆()2222x y -+=知:圆心()2,0,半径r =∴圆心到直线10x y ++=距离12d ==P ∴到直线10x y ++=距离[]211,d d r d r ∈-+,即222d ∈⎣⎦2115,222ABP S AB d ⎡⎤∴=⋅∈⎢⎥⎣⎦故15,22⎡⎤⎢⎥⎣⎦9.直线y x b =+与曲线x =b 的取值范围是__________.【正确答案】11b -<≤或b =【分析】根据曲线方程得曲线的轨迹是个半圆,数形结合分析得两种情况:(1)直线与半圆相切有一个交点;(2)直线与半圆相交于一个点,综合两种情况可得答案.【详解】由曲线x =221(0)x y x +=≥,表示以原点为圆心,半径为1的右半圆,y x b =+是倾斜角为4π的直线与曲线x =(1)直线与半圆相切,根据d r =,所以1d =,结合图像可得b =;(2)直线与半圆的上半部分相交于一个交点,由图可知11b -<≤.故11b -<≤或b =.方法点睛:处理直线与圆的位置关系时,若两方程已知或圆心到直线的距离易表达,则用几何法;若方程中含有参数,或圆心到直线的距离的表达较繁琐,则用代数法;如果x 或y 有限制,需要数形结合进行分析.10.一动圆与圆2240x y x ++=外切,同时与圆224600x y x +--=内切,则动圆圆心的轨迹方程为______.【正确答案】2212521x y +=【分析】根据两圆位置关系得动圆圆心到两已知圆心距离和为定值,再根据椭圆的定义即得.【详解】圆2240x y x ++=,即()2224x y ++=,圆心为(2,0)A -,1=2r ,圆224600x y x +--=,即()22264x y -+=,圆心为(2,0)B ,28r =,设动圆的圆心为P ,半径为r ,由题意得||2PA r =+,||8PB r =-,则104PA PB AB +=>=,所以动圆的圆心为P 的轨迹是以,A B 为焦点的椭圆,可设方程为22221(0)x y a b a b+=>>,则210a =,2c =,所以5a =,221b =,所以动圆圆心的轨迹方程为2212521x y +=.故答案为.2212521x y +=11.已知圆柱底面半径为2,一个与底面成45°角的平面截这个圆柱,则截面上的椭圆离心率为______.【正确答案】2【分析】由题意作出图像,结合图像和椭圆的性质,求得,,a b c 的值,利用离心率的定义,即可求解.【详解】如图所示,圆柱的底面直径为4,所以椭圆的短轴长24b CD ==,即2b =,又因为椭圆所在的平面与圆柱底面所成的角为45 ,所以4c s4542oAB a == ,解得a ==2c ,所以椭圆的离心率为2c e a ==.故212.在棱长为1的正方体1111ABCD A B C D -中,BD AC O ⋂=,M 是线段1D O 上的动点,过M 作平面1ACD 的垂线交平面1111D C B A 于点N ,则点N 到点A 的距离最小值是___________.【正确答案】2【详解】连结11B D ,易知面1ACD ⊥面11BDD B ,而1MN ACD ⊥,即1NM D O ⊥,NM 在面11BDD B 内,且点N 的轨迹是线段11B D ,连结1AB ,易知11AB D 是等边三角形,则当N 为11B D 中点时,NA 62二、单选题13.下列说法正确的是()A .直线的倾斜角越大,它的斜率越大;B .两直线的倾斜角相等,则它们的斜率也相等;C .任何一条直线都有唯一的斜率;D .任何一条直线都有唯一的倾斜角.【正确答案】D【分析】根据直线的倾斜角和斜率概念分别判断即可.【详解】对于A :直线的倾斜角2ππ,,33αβαβ==>,1212tan 0,tan 0,k k k k αβ=<=><,所以A 错误;对于B :两直线的倾斜角相等为π2,斜率不存在,所以B 错误;对于C :当直线的倾斜角为π2时直线斜率不存在,所以C 错误;对于D :任何一条直线都有唯一的倾斜角.所以D 正确.故选.D14.已知平面αβγ、、两两垂直,直线a b c 、、满足:,,a b c αβγ⊆⊆⊆,则直线a b c 、、不可能满足以下哪种关系A .两两垂直B .两两平行C .两两相交D .两两异面【正确答案】B【分析】通过假设//a b ,可得,a b 平行于,αβ的交线,由此可得c 与交线相交或异面,由此不可能存在////a b c ,可得正确结果.【详解】设l αβ= ,且l 与,a b 均不重合假设:////a b c ,由//a b 可得://a β,//b α又l αβ= ,可知//a l ,//b l又////a b c ,可得://c l因为,,αβγ两两互相垂直,可知l 与γ相交,即l 与c 相交或异面若l 与a 或b 重合,同理可得l 与c 相交或异面可知假设错误,由此可知三条直线不能两两平行本题正确选项:B本题考查空间中的直线、平面之间的位置关系,关键在于能够通过线面关系得到第三条直线与前两条线之间的位置关系,从而得到正确结果.1512=,化简的结果是()A .221364x y +=B .2213632x y +=C .2213616x y +=D .2213616y x +=【正确答案】B 【分析】由条件利用椭圆的定义、标准方程,即得.12=,可得点(),M x y 到定点()12,0F ,()22,0F -的距离之和等于12,即1212124MF MF F F +=>=,所以动点(),M x y 的轨迹是焦点在x 轴上的椭圆,设其方程为22221(0)x y a b a b+=>>,则212a =,2c =,所以6a =,b =故方程为2213632x y +=.故选:B.16.对于圆()()()2220x a y b r r -+-=>上任意一点(),P x y ,当m n ≠时,22x y m x y n -++-+的值与x ,y 无关,有下列结论:①点(),a b 的轨迹是一个圆;②点(),a b 的轨迹是一条直线;③当4m n -=时,r ;④当r =,1m =时,[)11,n ∈+∞.其中正确的个数是()A .1B .2C .3D .4【正确答案】A【分析】由d =,将已知条件看作(,)P x y 到直线20x y m -+=、20x y n -+=且已知圆在平行线20x y m -+=、20x y n -+=2r ≥,再结合各项描述分析正误.【详解】令d =,可看作(,)P x y 到直线20x y m -+=、20x y n -+=由()22x y m x y n m n -++-+≠的值与,x y 无关,所以距离之和与P 在圆上的位置无关,故已知圆在平行线20x y m -+=、20x y n -+=之间,2r ≥,2r =时,(),a b 的轨迹是平行于20x y m -+=、20x y n -+=直线,①错误;2r >时,(),a b 的轨迹不是直线,②错误③4m n -=时,5r ≤=,正确;④1r m ==时r =≤,则|1|10n -≥,故][(),911,n ∈-∞-⋃+∞,④错误.所以正确的有③.故选:A三、解答题17.已知()1,3A ,()5,7B (1)求线段AB 垂直平分线所在直线方程(2)若直线l 过()1,0-,且A 、B 到直线l 距离相等,求l 方程【正确答案】(1)80x y +-=;(2)10x y -+=或5450x y -+=.【分析】(1)由题可得AB 的中点坐标,再根据互相垂直的直线斜率之间的关系及点斜式方程即得;(2)根据点到直线距离公式结合条件即得.【详解】(1)因为点()1,3A ,()5,7B .所以线段AB 的中点坐标为()3,5,直线AB 的斜率为73151-=-,因此直线AB 的中垂线的斜率为1-,因此线段AB 的垂直平分线所在直线方程为()53y x -=--,即80x y +-=;(2)因为直线l 过点()1,0-,()1,3A ,()5,7B ,当直线l 的斜率不存在时,显然不合题意,设直线l 的方程为()1y k x =+,即0kx y k -+=,=1k =或54k =,所以直线l 的方程为10x y -+=或5450x y -+=.18.已知()1,0A -,()10B ,,C BC =.(1)求点C 的轨迹方程;(2)设直线l 经过点()2,2-,且l 与点C 的轨迹相交所得弦长为,求直线l 的方程;【正确答案】(1)()223+8x y +=(2)34140x y -+=或20x +=【分析】(1)根据两点间距离公式应用已知条件化简即可得轨迹方程;(2)设直线方程,把半径,弦长和圆心到直线距离转化为关于k 的方程求解即可.【详解】(1)设(),C x y 因为()1,0A -,()10B ,BC =化简得()()22222121x y x y ++=-+,即得22+610x y x ++=点C 的轨迹方程为()223+8x y +=(2)因为点C 的轨迹方程为()223+8x y +=,圆心为()3,0C -,半径r =设l 的方程为()22y k x -=+或2x =-又因为l 与点C 的轨迹相交所得弦长为所以圆心()3,0C -到直线l 的距离1d =1d =,即得22441k k k -+=+解得34k =,且2x =-符合题意.l 的方程为()3224y x -=+或2x =-所以l 的方程为34140x y -+=或20x +=19.如图,在正方体1111ABCD A B C D -中,E 为1BB 的中点.(1)求:异面直线1BC 与AE 所成角的大小;(2)求:直线1AA 与平面1AD E 所成角的正弦值.【正确答案】(1)arccos10;(2)23.【分析】(1)利用坐标法,求出1BC 和AE 的坐标,由空间向量夹角公式即可求解;(2)求出平面1AD E 的法向量和1AA 的坐标,由空间向量夹角公式即得.【详解】(1)以点A 为坐标原点,AD 、AB 、1AA 所在直线分别为x 、y 、z 轴建立如图所示的空间直角坐标系A xyz -,设正方体棱长为2,则()0,0,0A ,()0,2,0B ,()12,2,2C ,()12,0,2D ,()0,2,1E ,所以()12,0,2BC = ,()0,2,1AE = ,所以111,10o c s BC AEBC AEBC AE⋅=,所以直线1BC与1D E所成的角为arccos10;(2)由题可知()0,0,0A、()10,0,2A、()12,0,2D、()0,2,1E,所以()12,0,2AD=,()0,2,1AE=,()10,0,2AA=,设平面1AD E的法向量为(),,n x y z=,由122020n AD x zn AE y z⎧⋅=+=⎪⎨⋅=+=⎪⎩,令1y=,则()2,1,2n=-,设直线1AA与平面1AD E所成角为α,则sinα11142cos,323n AAn AAn AA⋅===-=⨯⋅,因此直线1AA与平面1AD E所成角的正弦值为23.20.已知椭圆()2222:10x yC a ba b+=>>的长轴长为8,O是坐标原点,1F,2F分别为椭圆C的左、右焦点,点(),2M x在椭圆C上,且12MF F△的面积为4.(1)求椭圆C的方程;(2)设直线():0,0l y kx m k m=+>>与椭圆C交于E,F两点,且直线OE,OF的斜率之和为2k-.①求直线l经过的定点的坐标;②求OEF的面积的最大值.【正确答案】(1)2211612x y+=(2)①(0,;②【分析】(1)根据长轴长为8可求出a,再根据12MF F△的面积公式可求出c,进而确定椭圆的方程;(2)①设出直线方程与椭圆进行联立,标准设而不求的步骤后,将韦达定理代入斜率和为2-的表达式中可得定点;②将①中求出的参数代入韦达定理,表示出OEF的面积,求此表达式的最大值即可.【详解】(1)由题意可知121228,2MF MF a F F c +===,所以有121211222422MF F M S F F y c c =⨯=⨯⨯== ,所以2c =,因为22212b a c =-=,所以椭圆C 的方程为2211612x y +=.(2)①设()()1122,,,E x y F x y ,联立22,1,1612y kx m x y =+⎧⎪⎨+=⎪⎩整理,得()2223484480k x kmx m +++-=,所以()()2222Δ644344480k m k m =-+->,可得221216m k <+,21212228448,3434km m x x x x k k -+=-=++,设直线,OE OF 的斜率分别为12,k k ,因为直线,OE OF 的斜率之和为2k -,所以122k k k +=-,即()()2121212221212122242224401212k m m x x y y kx m kx m km k k k k m x x x x x x m m -+++-++=++=+=+⋅==--,所以224m =,又0m >,所以m =,所以直线l经过的定点的坐标为(0,.②设直线l经过的定点为(0,N ,则1212OEF OEN OFN S S S x =-=⨯-==,设0>t,则2166OEF t S t t t==≤=++ 当且仅当6tt =时,即t =294k =时取等号,此时0∆>,所以OEF S ≤OEF 的面积的最大值为。
徐汇新王牌高中补习班之高二化学上海理工大学附属中学期中试卷2

徐汇新王牌高中补习班之高二化学上海理工大学附属中学期中试卷2上海理工大学附属中高二下学期期中考试化学试题相对原子质量:H—1 C—12 N—14 O—16 Na—23 Mg—24Al—27 S—32 Cl—35.5 Fe—56 Cu—64第?卷 (共54分)一、选择题(本题共24分,每小题只有一个正确选项)1、已知天然气的主要成分CH是一种会产生温室效应的气体,等物质的量的CH 和CO442产生的温室效应前者大。
下面是有关天然气的几种叙述:?天然气与煤、柴油相比是较洁净的能源;?等质量的CH和CO产生的温室效应也是前者大;?燃烧天然气也是酸雨的成42因之一。
其中正确的是 ( )A( B.只有? C.?和? D(只有? 2、下列物质的沸点按由高到低顺序正确排列的是 ( )丁烷;? 2-甲基丙烷;? 戊烷;? 乙烷;? 丙烷A、?、?、?、?、?B、?、?、?、?、?C、?、?、?、?、?D、?、?、?、?、? 3、下列说法中错误的是( )A 原子及其阴离子的核外电子层数等于该元素所在的周期数B 元素周期表中从IIIB族到IIB族10个纵行的元素都是金属元素C 除氦外的稀有气体原子的最外层电子数都是8D 同一元素的各种同位素的物理性质、化学性质均相同4、CHCH(CH)CH(CH)的名称是( ) 32532A(1,3,二甲基戊烷 B(2,甲基,3,乙基丁烷C(2,3,二甲基戊烷 D(3,4,二甲基戊烷5、由乙烯推测丙烯的结构或性质正确的是( )A(分子中所有原子都在同一平面上 B(能发生水解反应C(与HCl加成只生成一种产物 D(能发生加聚反应6、砹是原子序数最大的卤族元素,推测砹或砹的化合物最不可能具有的性质是( ) ?砹化氢很稳定 ?砹单质与水反应,使砹全部转化成氢砹酸和次砹酸 ?砹是黑色固体 ?砹化银难溶于水 ?砹易溶于某些有机溶剂A(只有?? B(只有 C(只有?? D(只有?? 7、下列叙述中正确的是 ( )A 含金属元素的离子一定都是阳离子B 在氧化还原反应中,非金属单质一定是氧化剂C 某元素从化合态变成游离态时,该元素一定被还原D 金属阳离子被还原不一定得到金属单质8、下列各组化合物中,不论二者以任何比例混合,只要总质量一定,则完全燃烧时消耗O2的质量和生成水的质量不变的是(( )A.CH、CHB.CH、CHC.CH、CHD.CH、CH 4262636243624349、下列反应中,属于取代反应的是 ( )A、在催化剂存在条件下乙烯与溴反应制1,2—二溴乙烷B、苯与浓硝酸、浓硫酸混合共热制取硝基苯第1页C、甲苯使酸性高锰酸钾溶液褪色D、在一定条件下苯与氢气反应制取环己烷10、丙烯醇(CH=CH-CHOH)可发生的化学反应有 ( ) 22加成 ?氧化 ?燃烧 ?加聚 ?取代A.只有 B(只有 C(? D(只有 11、下列说法中错误的是 ( )化学性质相似的有机物是同系物分子组成相差一个或几个CH原子团的有机物是同系物 2若烃中碳、氢元素的质量分数相同,它们必定是同系物互为同分异构体的两种有机物的物理性质有差别,但化学性质必定相似A. B. 只有?? C. 只有?? D. 只有 12、a、b、c、d、e分别是Cu、Ag、Fe、Al、Mg 5种金属中的一种。
新王牌杨浦暑期补习班高二数学练习题

1.已知,向量AB 的方向是东南方向,且5AB =,那么向量2AB - 的方向是;2BA -=.2.如图,在平行四边形ABCD 中,E 、F 、G 、H 分别为各边的中点.设CG a = ,CH b = ,试用a 、b表示向量DC 、FH 和BD .3.下列说法正确的有()个(1)零向量是没有方向的向量; (2)零向量的方向是任意的; (3)零向量与任意向量共线;(4)零向量只能与零向量共线.(A )1(B )2(C )3(D )以上都不对4.已知不平行的两个向量a 、b,求作向量()51222a b a b ⎛⎫+-- ⎪⎝⎭ .5.下列结论中,正确的是()(A )2004厘米长的有向线段不可以表示单位向量(B )若AB 是单位向量,则BA不是单位向量(C )若O 是直线l 上一点,单位长度已选定,则l 上只有两点A 、B ,使得OA 、OB是单位向量(D )计算向量的模与单位长度无关A BCDEF G H OABCDPQRABCDEFM6.若31122202245p q m q p m ⎛⎫⎛⎫---++= ⎪ ⎪⎝⎭⎝⎭,其中p 、q 为已知向量,求未知向量m .7.如图,四边形ABCD 中,点P 、Q 、R 分别是对角线AC 、BD 和边AB 的中点.设AD a = ,BC b =,试用a 、b表示向量PQ .8.已知ABC ∆中,点M 在A B 上,点N 在AC 上,13AM AB = ,13AN AC = .求证:13MN BC =.9.如图,点M 是的重心,则MA MB MC +-为()(A )0(B )4ME(C )4MD(D )4MF10.如图,已知a(提示:利用勾股定理).。
杨浦初中补习班杨浦高考补习班新王牌新模式选择多样化高二化学试卷(10份)

上海市浦东新区2013-2014学年高二第一学期期末质量测试化学试卷(完卷时间:90分钟,满分:100+20分)说明:本试卷分为试题与答卷两部分,请考生将学校、班级、姓名、学号和答案写在答卷上。
附加题供学有余力的学生做。
相对原子质量:H-1 N-14 O-16 S-32 Cu-64 Ba-137一、选择题(每题2分,共40分,每题只有1个正确答案)1.属于短周期元素的是A.K B.Ca C.I D.P2.我国使用最早的合金是A.青铜B.生铁C.锰钢D.硬铝3.下列化合物不是黑色的是A.FeO B.FeS C.Fe3O4 D.Fe2O34.下列各组反应属于铝热反应的是A.Al2O3+NaOH B.Al+Fe3O4C.Al+CuSO4D.Al+HCl5.分类是常用的学习方法,对于反应2Al+2NaOH+2H2O→2Na AlO2+3H2↑的分类错误的是A.化合反应B.氧化还原反应 C.离子反应D.放热反应6.Fe2O3和Al2O3都A.是两性氧化物B.可与氢氧化钠溶液反应C.可与盐酸反应D.可溶于水7.属于定量仪器的是A.试管B.烧杯C.量筒D.锥形瓶8.在标有“20℃,25 mL”的滴定管内装溶液至刻度“0”时,管内液体的体积A.约为5mL B.大于25 mL C.等于25 mL D.小于25 mL9.以下因素中,不会影响气体体积大小的是A.分子个数B.原子半径C.温度D.压强10.不同元素的原子间最本质的区别是A.中子数不同B.相对原子质量不同C.质子数不同D.最外层电子数不同11.由短周期元素和长周期元素共同组成的族可能是A.主族B.副族C.Ⅷ族D.Ⅶ族12.关于元素周期表的说法正确的是A .元素周期表中有8个主族B .元素周期表中有7个周期C .周期表中的主族都有金属元素D .IA 族中的元素全部是金属元素13.右图表示1~18号元素原子的结构或性质随核电荷数递增的变化。
图中纵坐标表示 A .电子层数 B .原子半径 C .最高化合价D .最外层电子数14.Y 元素最高正价与负价的绝对值之差为4,Y 元素与M 元素可形成离子化合物,该物质能溶于水并在水中电离出电子层结构相同的离子,该化合物是 A .硫化钾B .硫化钠C .氯化钠D .氧化铝15.门捷列夫制作元素周期表时,许多元素尚未发现,他在铝的下面留了空位给“类铝”,并对“类铝”的性质进行了预测, “类铝”与后来发现的镓的性质一致,从而验证了元素周期表的正确性。
上海徐汇高二数学月考试题.doc

上海徐汇高二数学月考试题.填空L已知各项均为正数的等比数列{a"}的首项句=1,公比为q ,前n项和为咒,若slim-^ = 1,则公比为q的取值范围是。
"Too \ n2.若0 E R,贝埴线y = sin。
・x +1的倾斜角的取值范围是.3.已知直线经过点A(0,4)和点B (1, 2),则直线AB的斜率为.4.已知点A.(2,3),3(-3,-2),若直线/过点P(l,l),且与线段AB相交,则直线/的斜率k的取值范围是5.过点(-1,3)且平行于直线x - 2y + 3 = 0的直线方程为.6.若直线x+ay+2=0和2x+3y+l= 0互相垂直,贝U a=.7.已知向量a = (cos仇sin0),向量Z = (、/!,-1)则\2a-b\的最大值是8.已知8,5均为单位向量,它们的夹角为60°,那么\a + 3b\ =9.若a =(2,3). » = (—4,7),则«在«上的投影为.( \ 110.已知等比数列危}的公比为q ,贝有lim ----------- q n =—,贝首项xi的取值范围是()H—>00、1 + 0 ) 2.解答题11.设O是直角坐标原点,OA = 2i + 3j,OB = 44-J ,在x轴上求一点P,使芬•畚最小,并求此时ZAF3的大小.12.若。
= (cosa,sins), 5 = (cos",sin”),且1上。
+方1=右也一位I (k〉0, b 6 R), 求Q 3的最小值,并求此时Q与方的夹角。
rt h -4- h +•••/?3.设数列{&}, {如}均为等差数列,(公差都不为零),则lim ~= --------------------------- ?‘is b n n • a3,114.知4 = (1,2), Z = (—3,2),当k为何值时,(1)ka + B与a - 3习垂直?(2)+ Z与4-3Z平行?平行时它们是同向还是反向?15.证明:对于任意的a,b,c,d eR,恒有不等式(ac + W)2 < (a2+Z?2)(c2+J2)16.平面向量S = (J5,-1),5 = (?,¥),若存在不同时为0的实数*和L使x = a + (t2- 3)片,y = -ka + tb,Kx ly ,试求函数关系式k = f(t)。
上海市徐汇区市级名校2025届化学高二下期末考试模拟试题含解析

上海市徐汇区市级名校2025届化学高二下期末考试模拟试题请考生注意:1.请用2B铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
写在试题卷、草稿纸上均无效。
2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。
一、选择题(每题只有一个选项符合题意)1、下列实验操作、实验现象和实验结论均正确的是A.A B.B C.C D.D2、下列说法正确的是A.冶铝工业中,采用铁作阳极,碳作阴极B.硫酸工业中,采用低温条件来提高SO2的转化率C.合成氨工业中,将氨气液化分离来增大正反应速率D.氯碱工业中,采用阳离子交换膜防止OH-与阳极产物Cl2反应3、下列有关钠及其化合物说法正确是的A.将一小块金属钠投入到硫酸铜溶液中,有红色物质析出B.实验室中的NaOH溶液用带有玻璃塞的试剂瓶盛装C.Na2O2和Na2O中阴、阳离子的个数比均为1:2D.某无色溶液进行焰色反应实验,直接观察时,火焰呈黄色,则该溶液中阳离子只有Na+4、下列化合物分子中一定既含σ键又含π键的是()A.N2 B.CO2C.C2H6O D.H2O25、以下实验:其中可能失败的实验是()①为检验RX是碘代烷,将RX与NaOH水溶液混合后再加入AgNO3溶液;②鉴别己烯、甲苯、丙醛三种无色液体,可以使用银氨溶液和KMnO4酸性溶液③用锌与稀硝酸反应制取氢气,用排水法收集氢气;④在试管中加入2mL 10%的CuSO4溶液,滴入2%的NaOH溶液4~6滴,振荡后加入乙醛溶液0.5mL,加热至沸腾来检验醛基⑤为检验淀粉已水解,将淀粉与少量稀硫酸加热一段时间后再加入银氨溶液,水浴加热。
⑥用浓溴水除去混在苯中的苯酚,过滤得到纯净的苯⑦乙醇和1:1的硫酸共热到170℃制乙烯A.①②③④⑤⑥⑦B.①④⑤⑥C.①③④⑤D.③⑤⑥⑦6、室温时10 mL某气态烃与过量的氧气混合,完全燃烧后的产物通过浓硫酸,再恢复至室温,气体体积减少了30 mL ,剩余气体再通过氢氧化钠溶液,体积又减少了40 mL ,则该气态烃的分子式为A.C4H6B.C2H4C.C3H8D.C4H87、石油加工的各种处理过程中,属于裂化过程的是()A.分离出汽油和煤油B.原油脱盐、脱水C.十六烷变为辛烷和辛烯D.将直链烃变为芳香烃8、将a L(标准状况)CO2通入100mL 3mol·L-1 NaOH溶液中,下列各项为通入CO2过程中溶液内发生反应的离子方程式,其中不正确的是 ( )A.a =6.72时,CO2+OH- = HCO3-B.a =3.36时,CO2+2OH- = CO32-+H2OC.a =4.48时,2CO2+3OH- = CO32-+HCO3-+H2OD.a =8.96时,3CO2+4OH- = CO32-+2HCO3-+H2O9、向Na2CO3、NaHCO3混合溶液中逐滴加入稀盐酸,生成气体的量随盐酸加入量的变化关系如图所示,则下列离子组在对应的溶液中一定能大量共存的是A.a点对应的溶液中:Na+、OH-、SO42-、NO3-B.b点对应的溶液中:K+、Al3+、MnO4-、Cl-C.c点对应的溶液中:Na+、Ca2+、NO3-、Cl-D.d点对应的溶液中:K+、Fe2+、NO3-、SO42-10、下列说法正确的是A.冰和水晶都是分子晶体B.原子晶体一定是共价化合物C.某物质固态时不导电但在熔融状态下能导电,则该物质中一定含有离子键D.干冰是分子晶体,其溶于水生成碳酸的过程只需克服分子间作用力11、以下关于化学实验中“先与后”的说法中正确的是()①蒸馏时,先点燃酒精灯,再通冷凝水②加热氯酸钾和二氧化锰的混合物制备氧气,用排水法收集气体后,先移出导管后撤酒精灯③实验室制取某气体时,先检查装置气密性后装药品④分液时,先打开分液漏斗上口的塞子,后打开分液漏斗的旋塞⑤H2还原CuO实验时,先检验气体纯度后点燃酒精灯⑥使用托盘天平称盘物体质量时,先放质量较小的砝码,后放质量较大的砝码⑦蒸馏时加热一段时间,发现忘记加沸石,应迅速补加沸石后继续加热A.②③④⑤⑦B.①②③④⑦C.②③④⑤D.全部12、下列叙述中正确的是A.NH3、CO、CO2都是极性分子B.CH4、CCl4都是含有极性键的非极性分子C.HF、HCl、HBr、HI 的稳定性依次增强D.CS2、H2O、C2H2都是直线形分子13、现有①浓硫酸、②硝酸铵、③氰化钾、④苯、⑤浓硝酸、⑥双氧水⑦氨水、⑧汞8种化学药品,下列有关在瓶上应贴的危险化学品标志正确的是()A.贴标签a的可以是:②④⑥B.贴标签b的可以是:②⑥⑦C.贴标签c的可以是:③⑧D.贴标签d的只有:①⑤14、下列实验操作、现象和结论均正确的是选项实验操作现象结论将光亮的镁条放入盛有NH4Cl溶液的试管有大量气泡产生反应中有NH3产生A中更难溶的物质无法转化为难溶的B 向AgI悬浊液中滴加NaCl溶液不出现白色沉淀物质向KI溶液中滴入少量氯水和苯,振荡、静溶液上层呈紫色I-还原性强于Cl-C置D 向某溶液中滴加氯水后再加入KSCN溶液溶液呈红色溶液中一定含有Fe2+A.A B.B C.C D.D15、下列实验操作或方法中,不合理的是()A.用丁达尔现象区分氯化钠溶液和淀粉溶液B.用重结晶法来提纯含有少量氯化钾杂质的硝酸钾晶体C.分别将SO2和Cl2通入滴有酚酞的氢氧化钠溶液中,验证两者的漂白性D.通过饱和碳酸氢钠溶液除去CO2中的HCl气体16、聚丙烯酸酯的结构简式可表示如图所示,可以由丙烯酸酯加聚得到。
- 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
- 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
- 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。
徐汇区II. Grammar(15%)Section ADirections: After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.ADating from 1971 and directed by Francis Ford Coppola, The Godfather won three Oscars.(18)__________(last) almost three hours, the film is Shakespearean in its scope and ambition. It is the story of a New York mafia family headed by Marlon Brando as “the Godfather”.(19)__________ Brando has the title role,it is Al Pacino playing his troubled son Michael(20)_________ steals the show in a masterly performance.(21)__________(achieve) his aim of taking the audience on an emotional rollercoaster tide,the director intersperses(点缀) long scenes of family life with shorter sequences of extreme violence. Having been shot in explicit detail, this violence may shock some viewers. But anyone (22)__________(prepare) to put up with this will enjoy (23)_________ unique dramatic experience. In fact, for many people The Godfather is the greatest American film made in the 1970s.BI have taught many children who held the belief that their self-worth relied (24)_________ how well they performed at tennis and other skills. For them, playing well and (25)___________ (win) are often life-and-death affairs. However, while some seem to be lost in the desire to succeed, (26)_________ take an opposite attitude. In a culture (27)__________ values only the winner and pays no attention to the ordinary players, they strongly blame competition. Among the most vocal are the youngsters who have suffered under competitive pressure from their parents or society. While teaching these young people, I often observe in them a desire to fail. They seem to seek failure by not trying to win or achieve success. By not trying, they always have an excuse: “I may have lost, (28)____________ it doesn't matter because I really didn't try. ” (29)__________ is not usually admitted by themselves is the belief that if they had really tried and lost, that would mean a lot. (30)________(clear), this belief is the same as that of the true competitors who try to prove themselves. Both are based on the mistaken belief (31)____________ one's self-respect relies on how well one performs in comparison with others. Both are afraid of not being valued. Only when this basic and often troublesome fear begins to dissolve (32) __________ we discover a new meaning in competition.III. Reading ComprehensionSection A (10%)Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Dear Sunday Globe,I am writing to you about your article in last Sunday’s newspaper, “Cell phones Makes Life Easier.”You did an excellent job explaining the good points of cell phones; they are ___33_____, we feel safer always being able to call someone, and they are very helpful in business. ____34____ you didn’t talk about their bad points at all. Thus I hope you’ll let me give your readers some advice on cell phone etiquette.The first point I’d like to address is ____35_____. When talking face to face in public, you wouldn’t shout. Likewise, don’t shout when you talk in public on your cell phone. In fact, the microphones in cell phones are so _____36_____ that you can be heard even if you speak quietly. Furthermore, keep you ringer nice and quiet -and don’t let it ring in meetings, at the movies, etc.Another point that needs to be made has to do with personal space. I think it is very impolite to make calls in small spaces or ___37_____ rooms. This makes others ____38_____ and forces them to listen to your personal business. ____39_____, it stops many face-to-face conversations from very beginning; that’s why I never use my cell phone within 3 meters of other people except in emergencies, and only after asking ____40_____.Lastly, let me draw your readers’ attention to the dangers of doing two things at the same time. For instance, cell phones and driving are a bad _____41_____. Pay attention to the road! Likewise, cell phones can cause you to neglect good friends. Give friends who are with you your full attention. Turn off your cell phone and enjoy their ___42_____!Sincerely,Amber Jala33. A. expensive B. convenient C. affordable D. developed34. A. On the other hand B. As a result C. In short D. On the contrary35. A. carelessness B. loudness C. passion D. limit36. A. tiny B. virtual C. fashionable D. sensitive37. A. crowded B. empty C. smooth D. brand-new38. A. concerned B. competitive C. uncomfortable D. patient39. A. However B. Occasionally C. Additionally D. Therefore40. A. support B. permission C. appreciation D. performance41. A. absorption B. solution C. involvement D. combination42. A. company B. custom C. flavor D. claimSection B(14%)Directions: Read the following two passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)Good nutrition and a balanced diet will help your children grow up healthily. No matter how old your kids are,you can take steps to improve nutrition and to encourage smart eating habits. Here are some suggestions.Family MealsFamily meals are comforting for both parents and kids. Children like to guess what they are going to have and parents get the chance to introduce new foods to children and to find out which foods they like and which ones they don't.Teens may turn up their noses at your plan of a family meal. It is not surprising because they're trying to establish independence. Yet studies find that teens still want their parents' advice,so they use the mealtime as a chance to reconnect.Stocking Up on Healthy FoodsKids,especially younger ones,will eat mostly what they can get at home. That's why it's important to control the supply lines—the foods which you serve for meals and have on hand for snacks. You should have enough fruits,vegetables,lean meat and other good sources of protein,such as eggs and nuts,and healthy snacks,such as yogurt,peanut butter and whole—grain biscuits.Being a Good ExampleThe best way for you to encourage healthy eating is to eat well yourself. Kids will follow the lead of the adults they see every day. By eating fruits and vegetables and avoiding fast food and sugary drinks,you'll be sending the right message.No Conflicts over FoodsParents might find themselves shouting at children to get them to have healthy foods in front of them. This in fact can make children dislike what they are asked to eat.Get Kids IncludedMost kids will enjoy making the decision about what to make for dinner. Talk to them about making choices and planning a balanced meal. It can help prepare them to make good decisions on their own about the foods they want to eat.43. The underlined sentence in the third paragraph probably means that teenagers may _______.A. look forward to your plan of a family mealB. help you to make a plan of a family mealC. show no interest in your plan of a family mealD. refuse to help with the plan of a family meal44.According to the article,which should NOT be done by parents?A. Forming a healthy eating habit.B. Forcing kids to have vegetables.C. Stocking up on some fruits at home.D. Making meal plans with kids.45. What's the best title for the passage?A. How to Eat HealthilyB. How to Prepare for a Family MealC. Help Kids Form Healthy Eating HabitsD. Help Kids Make the Right Choices(B)Navigation computers, now sold by most car makers, cost $ 2000 and up. No surprise, then, that they are most often found in luxury cars. But it is a developing technology ─meaning prices should eventually drop ─and the market does seem to be growing.Even at current prices, a navigation computer is impressive. It can guide you from point to point in most major cities with precise turn-by-turn directions ─spoken by a clear human sounding voice, and written on a screen in front of the driver.The computer works with an antenna(天线)that takes signals from no fewer than three of the 24 Global Positioning System (GPS) satellites. By measuring the time required for a signal to travel between the satellites and the antenna, the car's location can be pinned down within 100 meters.The satellite signals, along with inputs on speed from a wheel-speed sensor and direction from a meter, determine the car's position even as it moves. This information is combined with a map database. Streets, landmarks and points of interest are included.Most systems are basically identical. The differences come in hardware--the way the computer accepts the driver's request for directions and the way it presents the driving instructions. On most systems, a driver enters a desired address or point of interest via a touch screen or disc. But the Lexus screen goes a step further: you can point to any spot on the map screen and get directions to it.BMW's system offers a set of cross hairs(瞄准器上的十字纹) that can be moved across the map (you have several choices of map scale) to pick a point you'd like to get to. Audi's screen can be switched to TV reception.Even the voices that recite the directions can differ, with better systems like BMW's and Lexus's having a wider vocabulary. The instructions are available in French, German, Spanish, Dutch and, Italian, as well as English. The driver can also choose parameters for determining the route: fastest, shortest or no freeways, for example.46. We learn from the passage that navigation computers ______.A. will greatly promote sales of automobilesB. may help solve potential traffic problemsC. are likely to be accepted by more driversD. will soon be viewed as a symbol of luxury47. With a navigation computer, a driver will easily find the best route to his destination _________.A. by inputting the exact addressB. by indicating the location of his carC. by checking his computer databaseD. by giving orders to the computer48. The navigation computer functions ____________.A. by means of a direction finder and a speed detectorB. basically on satellite signals and a map databaseC. mainly through the reception of turn-by-turn directionsD. by using a screen to display satellite signals49. The navigation systems in cars like Lexus, BMW and Audi are mentioned to show __________.A. the immaturity of the new technologyB. the superiority of the global positioning systemC. the cause of price fluctuations in car equipmentD. the different ways of providing guidance to the driverSection C (6%)Directions: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words.A tsunami(海啸) is a giant wave that can do huge amounts of damage when it hits land. To see how one starts, throw a stone into a pond or lake, and watch the ripples(涟漪) spread out on the surface of the water. A tsunami starts in a similar way to one of these ripples, except that it is not caused by a stone, but by something much bigger, such as an earthquake occurring under the sea.Once it has started, a tsunami can move across the ocean for huge distances. An earthquake off the coast of South America generated (引起) a tsunami that travelled west for over 15,000 kilometres and caused enormous damage when it hit the coast of Japan 22 hours later.Tsunamis can be caused by volcanic eruptions as well as by earthquakes. The most deadly tsunami in recorded history was the one that followed the eruption of Indonesia’s Krakatoa volcano in 1883. About 36,000 people died, and what actually killed most of them was the tsunami rather than the eruption itself.It is not only events on Earth that cause tsunamis. They can also be generated by a comet (彗星) or meteor(流星) hitting the Earth. No one has actually seen this happen, except on screen in Hollywood films such as Deep Impact. But the giant tsunamis produced by special effects in such films, big enough to cover the skyscrapers of New York, are theoretically possible, and computer simulations (模拟研究) show that they have almost certainly happened in the distant past.In the open ocean, a tsunami wave is difficult to see, because most of it is below the surface. The part of the wave that is actually visible may be just one or two metres high. But the wave has enormous power, and can travel at the speed of a jet plane —almost 800 kph. As it eventually approaches land, the wave slows down, and this causes a dramatic increase in its height. By the time it actually reaches the land, it can be up to 30 metres high.Tsunamis occur in all the major oceans of the world, although they are most common in the Pacific area around Japan. Here, there is a complex and detailed system for monitoring the waves and providing warning for those who live in the area.(Note: Answer the questions or complete the statements in NO MORE THAN TWELVE WORDS.)50. Which tsunami was the most deadly one in history according to the passage?51. Apart from being generated by a comet or meteor hitting the Earth, a tsunami can also be caused by ____________________________________________.52. Why is a tsunami difficult to see in the open ocean?I.Vocabulary (10%)Directions: Complete the sentences with the words in the box. Each word can only be used53.During the Mid-autumn Festival, people usually eat moon-cakes which _________ a happyreunion.54.He suggests that we should wear something white in the desert because it can ________ heat.55.When people ___________ financial crimes they actually steal money from the country.56.The company proudly announced the ________ of its new range of cars.57.Terry can't ___________ in the match because he has hurt his foot.58.The fact is that most people ___________ far more protein than they actually need.59.It takes 15 minutes to __________ the plane into a car by removing the wings and the tail.60.There are not enough trained younger men and women ready to ___________ from olderexperts.61.People who cannot __________ between colours are said to be colour-blind.62.Customers find the 24 - hour service very ___________.II.Translation (15%)Section A (共4分, 每小题2分)Directions:Complete the following sentences by translating the Chinese in the brackets into English.1. 探险家们首次试图抵达北极,但因为恶劣的天气不得不半路折返。