完整版反激变压器设计
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参数要求
INPUT MIN
90VAC INPUT MAX 265VAC OUTPUT 1
19VDC I 3.16A Po
60.04W OUTPUT 2
12VDC I 0.1A Po
1.2W OUTPUT 3
0VDC I 0A Po
0W NVcc
12VDC I 0A Po
0W 工作频率Fs
70KHz Dmax=0.5Ae 70.3步骤1求CORE 137.79
0.2T
AP=0.62cm4
步骤2 估算臨界電流 IOB ( DCM / CCM BOUNDARY )
IOB = 80%*Io(max)
IoB = 2.528
步骤3求匝數比 n
N = [VIN(min) / (Vo + Vf)] * [Dmax / (1-Dmax)]
107.26
N= 5.4447*1= 5.44
步骤4求CCM / DCM臨界狀態之副邊峰值電流ΔISB.
ΔIsb = 2Iob / (1-Dmax)=10.112A
步骤5計算次級電感 Ls 及原邊電感 Lp.
Ls = (Vo + Vf)(1-Dmax) * Ts / ΔISB =0.14070.013916
=13.916uH
Lp = n2 Ls =412.5193uH
步骤6求CCM時副邊峰值電流ΔIsp.
Io(max) = (2ΔIs + ΔISB) * (1- Dmax) / 2
ΔIs = Io(max) / (1-Dmax) - (ΔISB / 2 )
ΔIsp = ΔISB +ΔIs = Io(max) / (1-Dmax) + (ΔISB / 2 )
=11.376A
步骤7求CCM時原邊峰值電流ΔIpp.
ΔIpp = ΔIcp / n = 2.089383A
步骤8
確定Np、Ns
1> Np Np = Lp * ΔIpp / (ΔB* Ae)=61.302T 2> Ns Ns = Np / n =11.259T 3> Nvcc
求每匝伏特數Va Va = (Vo + Vf) / Ns= 1.7497V/Ts Nvcc = (Vcc + Vf) / Va =7.0298T 本文介绍了设计反激变压器的步骤及公式,在红色框内输入数据即可.....
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AP= AW*Ae=(Pt*100000)/(2ΔB*fs*J*Ku)
VIN(min)=△B = 0.6 * (390 - 60) = 198mT ≒传递功率Pt = Po /η +Po = J : 電流密度 A / cm2 (300~500)
Ku: 繞組系數 0.2 ~ 0.5