A study on the law of oxidation rate in GaAs-based VCSELs
氯气氧化分解草酸钴沉淀母液中的草酸

氯气氧化分解草酸钴沉淀母液中的草酸田庆华;易宇;郭学益【摘要】为有效去除草酸沉钴母液中残留的大量草酸,采用氯气作为氧化剂探索氧化分解母液中草酸的可行性.考察反应温度、反应时间、氯气用量、搅拌速度和钴离子浓度等因素对氧化效果的影响.确定了优化工艺条件:反应温度50℃,搅拌速度700 r/min,次氯酸钙150 g,6 mol/L盐酸550 mL,反应时间3h.在此条件下,草酸的氧化率可达97.9%,母液中残留的草酸质量浓度仅为0.42 g/L,处理后的母液可直接返回含钴物料的浸出,实现了工艺流程的闭路循环.%In order to remove the oxalic acid left in the mother-liquor originated from the precipitation of cobalt by oxalic acid, a novel method of using chlorine as the oxidant to decompose the oxalic acid was proposed. The main factors affecting the oxidation rate such as the solution temperature, reaction time, quantity of chlorine, stirring speed and Co2* concentration were investigated. The optimal conditions are as follows: 700 r/min of stirring speed, 150 g calcium hypochlorite, 550 mL of hydrochloric acid with concentration of 6 mol/L and 5 h of reaction time at 70 °C. Under these conditions, the oxidation rate of oxalic acid is 97.9% and the concentration of residual oxalic acid in mother liquor is only 0.42 g/L. The treated mother liquor can be returned directly for leaching cobalt. There is a closed circulation in the whole process.【期刊名称】《中南大学学报(自然科学版)》【年(卷),期】2011(042)009【总页数】5页(P2558-2562)【关键词】氯气;氧化;草酸;草酸钴【作者】田庆华;易宇;郭学益【作者单位】中南大学冶金科学与工程学院,湖南长沙,410083;中南大学冶金工程博士后流动站,湖南长沙,410083;中南大学冶金科学与工程学院,湖南长沙,410083;中南大学冶金科学与工程学院,湖南长沙,410083【正文语种】中文【中图分类】TF803.22目前,国内外草酸钴的生产主要采用草酸铵沉钴法,即在氯化钴溶液体系中,加入沉淀剂草酸铵,生成草酸钴沉淀,经过滤干燥得到产品[1]。
(完整版)药学英语第五版原文翻译

Introduction to PhysiologyIntroductionPhysiology is the study of the functions of living matter. It is concerned with how an organism performs its varied activities: how it feeds, how it moves, how it adapts to changing circumstances, how it spawns new generations. The subject is vast and embraces the whole of life. The success of physiology in explaining how organisms perform their daily tasks is based on the notion that they are intricate and exquisite machines whose operation is governed by the laws of physics and chemistry.Although some processes are similar across the whole spectrum of biology—the replication of the genetic code for or example—many are specific to particular groups of organisms. For this reason it is necessary to divide the subject into various parts such as bacterial physiology, plant physiology, and animal physiology.To study how an animal works it is first necessary to know how it is built. A full appreciation of the physiology of an organism must therefore be based on a sound knowledge of its anatomy. Experiments can then be carried out to establish how particular parts perform their functions. Although there have been many important physiological investigations on human volunteers, the need for precise control over the experimental conditions has meant that much of our present physiological knowledge has been derived from studies on other animals such as frogs, rabbits, cats, and dogs. When it is clear that a specific physiological process has a common basis in a wide variety of animal species, it is reasonable to assume that the same principles will apply to humans. The knowledge gained from this approach has given us a great insight into human physiology and endowed us with a solid foundation for the effective treatment of many diseases.The building blocks of the body are the cells, which are grouped together to form tissues. The principal types of tissue are epithelial, connective, nervous, and muscular, each with its own characteristics. Many connective tissues have relatively few cells but have an extensive extracellular matrix. In contrast, smooth muscle consists of densely packed layers of muscle cells linked together via specific cell junctions. Organs such as the brain, the heart, the lungs, the intestines, and the liver are formed by the aggregation of different kinds of tissues. The organs are themselves parts of distinct physiological systems. The heart and blood vessels form the cardiovascular system; the lungs, trachea, and bronchi together with the chest wall and diaphragm form the respiratory system; the skeleton and skeletal muscles form the musculoskeletal system; the brain, spinal cord, autonomic nerves and ganglia, and peripheral somatic nerves form the nervous system, and so on.Cells differ widely in form and function but they all have certain common characteristics. Firstly, they are bounded by a limiting membrane, the plasma membrane. Secondly, they have the ability to break down large molecules to smaller ones to liberate energy for their activities.生理学简介介绍生理学是研究生物体功能的科学。
A-level-A2化学unit4部分内容整理

A-level-A2化学unit4部分内容整理Rate of reaction=change in concentration/rate , orrate=K[A]x[B]yK:the rate constant at a particular temperature[A]&[B]:the concentration of substances A & Bx:the order with respect to A, and y is the order for BThe overall order of reaction:the sun of the individual orders,x+yColorimetry measures the intensity of a color in a reaction mixture with time, such as in the oxidation of iodide ion to give brown iodine.In clock reaction the reaction is timed until a sudden color change happens when a certain amount of product is formed.Mass change is used when a gas is produced.Volume change is an alternative to mass changed for gases.Titrimetric analysis uses titrations to measure changing concentration of a reactant or product.HALF_LIFE:the time needed for any reactant concentration to fall to half of its.The diagram shows that the reaction is:*Exothermic- the products are at lower energy level than the reactants*Subject to an energy barrier, the activation energy in route 1*Able to follow an alternative pathway in route 2,with lower barrierA catalyst increase the reaction rate by proving an alternative reaction pathway with a lower activation energy.Catalyst and reactants can be in the same physical state, called homogenous.in different way,called heterogeneous.Process Reactants Catalyst Type of catalyst Haber synthesis Nitrogen,hydrogen Iron Heterogeneous Catalyst converter in carExhaust gases Platinum HeterogeneousConstant process,sulfuric acid manufacture Sulfur dioxide,oxygen gasesVanadiun(V) oxide HeterogeneousEsterification Solutions ofacid,alcoholHydrogen ions homogeneouslnK=-Ea/RT + a constantEa:the activate energy for the reactionR:the gas constant and has the value 8.31 JK-1mol-1T:the kelvin temperature (absolute temperature)Gradient=-Ea/Rrate=K[A][C]2the reaction is first order with respect to A- so A is involved in the rate-determining step the reaction is second order with respect to substance C-so moles of C are involved in the rate-determining stepR--I + OH-1*****R--OH + I-1S N2 mechanism,meaning substitution/nucleophilic/second orderThe slow step involves only one species and does not spend on the concentration of hydroxide ions.Rate=K[RI]The mechanism must be consistent with the evidence:*if the reaction is second order overall it must involve 2 different species.*if the reaction is first order overall (only 1 species in the rate equation) then this is the rate-determining step and it must be a 2-step reactionEntropy (symbol S) is a measure of disorder in a system.As the temperature of a material increases,the particles gain energy and their motion also increase.Higher temperatures, therefore,increase the disorder of the particles.Entropy increases with change of state to grater distance between particles and consequent increased disorderThe ions in solid sodium chloride are more ordered than the same ions dissolved in water.Dissolving sodium chloride causes the entropy to increase.Change Example Change in theentropy Reason for the changeReaction releasing a gas Zinc with sulfuricacid releasinghydrogenpositive (increasingentropy)Gas molecules aremore disorderedthan particles in thesolutionGas reaction where molecules combine,reducing the total number Haber process formaking ammoniaNegative Fewer productmolecules thanreactantmolecules,reducingthe disorderA standard entropy S is the entropy of a substance at standard temperature and pressure,and is expressed per mole of substance.The standard entropy change for physical or chemical processes is the difference in the entropies of the products and reactants measured under standard conditions:S[system]=S[product] - s[reactant]Spontaneous processes are often exothermic.Exothermic reactions give out heat(negative H),which increase the disorder of the surrounding particles.Some endothermic reactions are also spontaneous at room temperature.They have positive value for HWhether reactions occur spontaneously or not cannot be explained in terms of enthalpy changes alone.S[total]=S[system] +S[surrounding]For any spontaneous change S[total] must have a positive value.Total disorder must increase.S[surroundings]=-H/T (exothermic reactions have negative H but transfer energy to the surroundings,which increase their entropy.Change Exo/endothermic S[surroundings]S[system] S[total] why is thechangespontaneousDissolving sodium nitrite in water Endothermic Decrease Increasebecause thecrystallinelattice isdestroyed+ S[system] islargerSodium metal burning in Cl Exothermic Increase Decreasebecause acrystallinelattice isformed+ S[surroundings] is largerAmmonia gas and hydrogen chloride gas combine t give solid ammonium chloride Exothermic Increase decrease because alattice forms+ S[surroundings] is largerA feasible reaction has S[total]=S[system]- H/T*The entropy change in the system*The temperature measured in kelvin*The enthalpy change with the surroundings,HSpontaneous reactions can only happen for Stotal more than 0.A chemical reaction is feasible when S total has a positive value.Energy must first be provided to start such reactions*a spark*heat(as in the decomposition of CaCo3 above)*light (visible or UV)*lattice energy-the solid must separated into individual ions to dissolve (an endothermic change)*hydration enthalpy- the separated ions interact with the surrounding polar solvent,such as water (an exothermic change)H(solution)=-H(lattice energy) + H(hydration)A positive H(solution) corresponds to an overall endothermic change-dissolving is not favoured. It may still be favoured by an increase in entropy.Solid sodium chloride is a highly ordered 3-D lattice with a low entropy value.On dissolving,the ions separate and move independently,the entropy of the system therefore increases,favouring the change.A negative H(solution) corresponds to an overall exothermic change and so dissolving is favoured in term of enthalpy.The products have less energy than the reactants in general,although dissolving is regarded as a physical not a chemicalchange.The lattice enthalpy (or energy) of a compound is a affected by:1.the change on the ions---larger charges increase the force of attraction between oppositely charged ions2.the size of ions---smaller ions fit closer and this increase the force of attraction3.the degree of covalency in the ionic bonding---whether the bonding is 100% ionic and the ions completely separate, as the ionic model assumes.4.ionic radius---small ions have a great density5.ionic charge---larger charges increase the charge densityDynamic equilibrium:When both forward and reverse reaction in a reversible reaction continue but the rate of the forward reaction is equal to the rate of the reverse reaction:H2(s)+I2(s)=2HI(g)when hydrogen and iodine gases are first mixed in a closed system,the forward reaction alone begins since there are no products present.As the amounts of reactants fall,the forward rate decreases.Physical changes can also result in dynamic equilibria:I2(s)=I2(g)Important industrial reactions that are reversible include:*the Haber process for ammonia-N2(g)+3H2(g)=2NH3(g)*the contact process for sulfric acid-2SO2 (g) +O2 (g) =2SO3(g)*esterification -for example CH3COOH(I)+C2H5OH(I)=CH3COOC2H5(I)+H2O(I) Equilibrium law:There is a relationship between the reactant and the product equilibrium concentrations at a particular temperature.K c:the equilibrium constantHomogeneous:all liquids or all gases.Hetergeneous:more than 1 physical state is present.K c>>1:the products are favored,and the position of equilibrium lies well over to the product side.K c<<1:the reactant are favored,and the position of equilibrium lies well over to the reactant side.K c is very large indeed,such as 1×1010:the reaction has one to completion. K c is tiny,such as 1×10-10:NO reaction has occurred.。
小学上册第十五次英语第一单元真题试卷

小学上册英语第一单元真题试卷英语试题一、综合题(本题有100小题,每小题1分,共100分.每小题不选、错误,均不给分)1.The _____ (植物领域) is a rich area for exploration and learning.2.What is the name of the famous clock tower in London?A. Big BenB. Tower BridgeC. London EyeD. Buckingham PalaceA3.What is the capital of France?A. BerlinB. LondonC. ParisD. MadridC4. A __________ is a small, furry animal that hops around.5.They are _______ (playing/studying) in the classroom.6.The children are ______ (happy) at the zoo.7.What color is the grass?A. BlueB. GreenC. RedD. Yellow8. A lever can help lift heavy ______.9.I enjoy going to the ______.10.The _____ (ocean) is vast.11. A compound that can act as both an acid and a base is called ______.12.What is the name of the largest land animal?A. LionB. ElephantC. RhinoD. GiraffeB13.The _____ (海星) can be found in tidal pools.14.The Earth’s crust is constantly being renewed through ______ activity.15.What do you call the person who flies an airplane?A. PilotB. DriverC. CaptainD. Engineer16.How many days are in February during a leap year?A. 28B. 29C. 30D. 31B17.My dad loves to cook __________. (晚餐)18.Which fruit is yellow?A. AppleB. BananaC. CherryD. Grape19.What is the capital city of the Maldives?A. MaléB. Addu CityC. FuvahmulahD. Kulhudhuffushi20.What do we call the place where books are kept?A. SchoolB. LibraryC. BankD. Store21.She has a pretty ________.22.The _______ of sound is measured in decibels.23.My uncle is a skilled ____ (potter).24.I saw a _______ flying in the garden (我在花园看到一只_______在飞).25.How many wheels does a bicycle have?A. TwoB. FourC. ThreeD. SixA26.We have a toy ____ that we can control with a remote. (玩具名称)27.What do you call the winter sport of sliding down snow-covered hills?A. SkiingB. SurfingC. SkatingD. Snowboarding28.I love to sit by the __________ when it’s sunny. (河)29. A catalyst helps a reaction occur at a ________ rate.30.The _____ (火车站) is crowded.31.The capital of the Republic of the Congo is ________ (布拉柴维尔).32.I like to play ___. (cards)33. A lion roars fiercely in the _______ as it prowls.34.Salt is an example of a ______ formed from an acid and a base.35.The __________ (历史的留下) contributes to legacy.36.How many days are there in a week?A. 5B. 6C. 7D. 8C37.What do we call the solid part of the Earth?A. AtmosphereB. HydrosphereC. LithosphereD. BiosphereC38.The __________ (历史的启示) sparks creativity.39.I have a ________ in my backpack.40.The process of oxidation involves __________ losing electrons.41.What do we call the movement of the Earth around the sun?A. RotationB. RevolutionC. OrbitD. Spin42.The fire is _____ (hot/cold).43.The chemical formula for iron sulfate is _______.44.What do you call the event where people come together to celebrate a holiday?A. GatheringB. CelebrationC. PartyD. EventB45. A ______ (蜥蜴) can be quite colorful and fascinating.46.Playing with my toy ____ helps me relax. (玩具名称)47.Which insect can produce honey?A. AntB. ButterflyC. BeeD. FlyC48.I enjoy storytelling sessions at the library. The librarian has the best ________ (故事).49.What do we call a person who studies ancient civilizations?A. ArchaeologistB. HistorianC. AnthropologistD. Paleontologist50.The island nation of Japan is made up of ________ (岛国日本由________组成).51.The first telephone was invented by _______. (贝尔)52.The __________ is known for its vast empire and military prowess. (罗马帝国)53.I like to ________ (experiment) with ideas.54.What is the process of plants making their food called?A. DigestionB. PhotosynthesisC. RespirationD. Evaporation55.What do we call the animal that is often kept in cages and can talk?A. DogB. ParrotC. CatD. Hamster56.His name is . (他的名字是。
2024年统编版小学4年级第15次英语第6单元期末试卷[含答案]
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2024年统编版小学4年级英语第6单元期末试卷[含答案]考试时间:80分钟(总分:110)A卷考试人:_________题号一二三四五总分得分一、综合题(共计100题)1、f Exploration began in the ________ (15世纪). 填空题:The Age2、填空题:I can ______ (保持) positive relationships with others.3、Which of these is a popular fruit?A. SpinachB. CarrotC. StrawberryD. Broccoli答案:C4、What color is the sky on a clear day?A. GreenB. BlueC. RedD. Yellow答案:B. Blue5、听力题:My aunt is a ______. She loves to travel.6、填空题:__________ (化学平衡点) indicates when reactants and products are in balance.7、填空题:__________ (温度) affects the rate of chemical reactions.8、填空题:My _____ (外公) loves gardening.The __________ (历史的纵深挖掘) reveals complexities.10、填空题:Julius Caesar was a famous Roman _______. (统治者)11、听力题:Inertia is the tendency of an object to resist ______.12、填空题:The ancient Romans used ________ (法律) to maintain order.13、What is the process of taking in oxygen and expelling carbon dioxide?A. PhotosynthesisB. RespirationC. DigestionD. Circulation答案: B14、填空题:I enjoy visiting the __________ with my family. (博物馆)15、听力题:Photosynthesis converts sunlight into ______ energy.16、填空题:I love to ______ (阅读) books.17、填空题:A kangaroo carries its baby in a ______ (袋子).18、听力填空题:I think learning about different cultures is fascinating. It broadens our understanding of the world. I want to learn more about __________ and its traditions.19、Which of these is a type of tree?A. RoseB. OakC. TulipD. Daisy答案:B20、听力题:The Moon orbits the Earth and is its ______.A _____ (青蛙) jumps into the pond.22、填空题:A kitten loves to chase ________________ (玩具).23、听力题:My uncle is a fantastic ____ (gardener).24、填空题:Birds can _________ in the sky. (飞)25、填空题:I enjoy baking ______ (饼干) to share with my friends.26、听力题:The _____ of a solution tells us how much solute is dissolved in a given amount of solvent.27、听力题:The __________ is known for its scenic drives.28、填空题:The ________ likes to play hide-and-seek.29、填空题:The flower petals are ______.30、听力题:The _______ of light can be affected by its speed.31、What is the capital of the Dominican Republic?A. Santo DomingoB. SantiagoC. La RomanaD. Puerto Plata答案:A32、听力题:The ______ helps transport oxygen in the blood.33、What is the name of our galaxy?A. AndromedaB. Milky WayC. WhirlpoolD. SombreroOne of the reasons I love this animal is because it is very ______. It can run very ______ and climb trees easily. I enjoy watching videos of it ______ in the wild. They are also very ______ and often play with each other.35、听力题:My dad is a _____ (医生).36、填空题:My favorite toy is a ________ (机器人) that moves.37、听力题:The ______ studies the stars and planets.38、听力题:__________ are often used to treat infections.39、听力题:My sister is a ______. She loves painting landscapes.40、填空题:The explorer traveled to many _____ (国家).41、填空题:The capital of Libya is _____.42、听力题:Asteroids are remnants from the early solar system that never formed into ______.43、听力题:They are _____ (riding) their bikes.44、听力题:The party is at my ________.45、填空题:My mom loves to __________. (旅行)46、填空题:The ancient Greeks held _______ to celebrate their gods. (运动会)47、填空题:The ________ was a defining moment in the struggle for rights.48、填空题:The __________ (历史的细节) can be overlooked.49、What do you call a person who teaches?A. StudentB. TeacherC. DoctorD. Farmer50、听力题:A ________ is a region that has a specific type of climate.51、听力题:I need to ________ my homework.52、听力题:I like to wear ___ (shirts/pants).53、How many planets are in our solar system?A. EightB. NineC. TenD. Seven答案:A54、填空题:I like to play dress-up with my toy ____. (玩具名称)55、填空题:The ______ (猴子) is known for its cleverness.56、What is the opposite of high?A. LowB. TallC. ShortD. Narrow答案:A57、填空题:A deer uses its keen sense of smell to detect ________________ (危险).58、填空题:A _____ (野生植物) grows naturally without human care.59、What is the name of the famous American football team based in New England?A. Dallas CowboysB. New York GiantsC. Green Bay PackersD. New England Patriots答案:D60、What is the name of the famous American holiday celebrated on July 4th?A. Independence DayB. ThanksgivingC. Memorial DayD. Labor Day答案: A. Independence Day61、听力题:We like to ________ together.62、填空题:The __________ (全球视野) broadens perspectives.63、填空题:My ________ (玩具) is a source of inspiration and joy.64、填空题:I love to take my _________ (玩具车) to the park and race it.65、填空题:I can create my own game with my ________ (玩具名称).66、What do we call the first meal of the day?A. LunchB. DinnerC. BreakfastD. Snack67、听力题:A chemical equation must be _____ to follow the law of conservation of mass.68、填空题:The __________ (历史学校教育) helps students learn about their heritage.69、What is the name of our nearest star?A. Alpha CentauriB. Proxima CentauriC. SiriusD. Betelgeuse70、What is the term for an animal that only eats plants?A. CarnivoreB. OmnivoreC. HerbivoreD. Insectivore答案: C71、填空题:The ancient Greeks engaged in ________ to celebrate athletic prowess.72、听力题:The ______ tells the body how to grow and develop.73、听力题:The capital of India is __________.74、听力题:The sun is ______ (bright) during the day.75、填空题:The __________ (历史的交错) illustrates complexity.76、What is the name of the famous American singer known for "Born This Way"?A. Katy PerryB. Lady GagaC. RihannaD. Taylor Swift答案:B77、What is the capital of the USA?A. Los AngelesB. Washington D.C.C. New YorkD. Chicago答案:B78、听力填空题:I enjoy playing chess because it challenges my __________.79、听力题:Electrons are found outside the _____ (nucleus) of an atom.80、填空题:A _____ (盆栽) can add charm to any room.81、听力题:The process of oxidation can lead to ______ of metals.82、What is the capital city of Japan?A. BeijingB. TokyoC. SeoulD. Bangkok答案: B83、填空题:The ancient Egyptians practiced ______ (宗教) rituals to honor their gods.84、What is the largest organ in the human body?A. HeartB. BrainC. SkinD. Liver答案:C. Skin85、填空题:My friend has a ___ (小宠物), which is a cute rabbit.86、听力题:The _______ is known for its beautiful colors.87、选择题:What is the main color of a fire truck?A. RedB. BlueC. YellowD. Green88、What do we call the act of planting seeds in the ground?A. HarvestingB. SowingC. WateringD. Weeding答案:B89、填空题:I can ______ (理解) the importance of empathy.90、选择题:What do we call a large animal with antlers?A. DeerB. MooseC. ElkD. All of the above91、填空题:A _____ (植物影响研究) can explore ecological relationships.92、填空题:A ferret loves to dig and ______ (探索).93、What is the color of snow?A. BlackB. WhiteC. GreenD. Blue答案:B94、填空题:The __________ (历史的启迪) enlightens minds.95、What is the name of the process in which plants release oxygen?A. PhotosynthesisB. RespirationC. TranspirationD. Digestion答案:A96、听力题:A substance that speeds up a chemical reaction without being consumed is called a _______.97、填空题:I have a ________ that brings me joy.98、听力题:She wears a ___ (dress).99、填空题:I have a pet ______ (狗).100、What do we call the study of plants?A. ZoologyB. BotanyC. EcologyD. Geology答案: B。
对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估

生态毒理学报Asian Journal of Ecotoxicology第18卷第4期2023年8月V ol.18,No.4Aug.2023㊀㊀基金项目:中国科学院大连化学物理研究所创新基金(DICP I202219);国家自然科学基金重点项目(22036006)㊀㊀第一作者:张钰莹(1997 ),女,硕士研究生,研究方向为新型污染物环境行为与健康效应,E -mail:**************.cn ㊀㊀*通信作者(Corresponding author ),E -mail:*****************㊀㊀#共同通信作者(Co -corresponding author),E -mail:******************.cnDOI:10.7524/AJE.1673-5897.20230319001张钰莹,耿柠波,闫雷,等.对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估[J].生态毒理学报,2023,18(4):253-264Zhang Y Y ,Geng N B,Yan L,et al.Distribution characteristics and human exposure assessment of p -phenylenediamine (PPD)antioxidants and their oxi -dation products in road dust and nearby topsoil [J].Asian Journal of Ecotoxicology,2023,18(4):253-264(in Chinese)对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估张钰莹1,2,耿柠波2,#,闫雷1,*,王龙星2,张海军2,陈吉平21.东北农业大学资源与环境学院,哈尔滨1500302.中国科学院大连化学物理研究所,中国科学院分析化学分离科学重点实验室,大连116023收稿日期:2023-03-19㊀㊀录用日期:2023-04-12摘要:N ,N -取代对苯二胺(PPD)是一类广泛添加在橡胶轮胎中的抗氧化剂,能够随着橡胶轮胎的磨损,不断释放并积聚在道路尘土中㊂6PPD -Q(6PPD -quinone)是N -(1,3-二甲基丁基)-N -苯基对苯二胺(6PPD)的臭氧化产物,近期由于其对银鲑鱼表现出的高毒性而备受人们关注㊂目前对于该类污染物的环境行为研究十分有限,给健康风险评估带来了极大的不确定性㊂本研究采集了大连市5个区域的尘土样品和表层土样品,研究了6种PPDs 和6PPD -Q 在不同区域样品中的分布特征㊂结果表明,6PPD ㊁6PPD -Q ㊁N,N -二-2-萘基对苯二胺(DNPD)和N,N -(1,4-二甲基戊基)-对苯二胺(77PD)在道路尘土样品中的检出率均为100%;而在表层土壤样品中,仅6PPD ㊁6PPD -Q 和77PD 在70%以上的样品中有检出,所有样品中均未检测到N -苯基-N -环己基-对苯二胺(CPPD)㊂6PPD -Q 在大多数道路尘土中处于较高污染水平,浓度范围为0.12~52.21ng ㊃g -1(中值:7.18ng ㊃g -1)约占总质量浓度的34.10%,其次是DNPD 和6PPD ,二者浓度范围分别为0.61~113.83ng ㊃g -1(中值:2.54ng ㊃g -1)和0.21~27.26ng ㊃g -1(中值:1.83ng ㊃g -1)㊂6种PPDs 总和(ΣPPDs)浓度范围为3.59~131.37ng ㊃g -1(中值:11.24ng ㊃g -1)㊂城市主干道尘土中ΣPPDs 和6PPD -Q 的浓度显著高于居民区尘土和居民广场尘土㊂居民区绿化带表层土中目标化合物检出率较低,农田表层土由于距离污染源较近,污染水平高于居民区绿化带㊂对3种尘土样品进行人体暴露评估,6种检测到的化合物中,6PPD -Q 的暴露量最高;ΣPPDs 和6PPD -Q 经口摄入量远大于经皮肤摄入,ΣPPDs 和6PPD -Q 通过道路尘土的摄入量均表现为主干道>居民区道路>居民广场,其中,主干道尘土摄入量占70%以上㊂主干道㊁居民区道路和广场尘土样品中ΣPPDs 的日摄入量分别为0.13㊁0.02㊁0.01ng ㊃kg -1㊃d -1,6PPD -Q 的日摄入量分别为0.06㊁0.02㊁0.01ng ㊃kg -1㊃d -1㊂儿童对于ΣPPDs 和6PPD -Q 的日摄入量为0.20ng ㊃kg -1㊃d -1和0.11ng ㊃kg -1㊃d -1,约为成人的2倍㊂由于本研究选择的5个采样区域均与居民生活密切相关,道路尘土中6PPD -Q 具有较高浓度可能会造成潜在的人体健康风险㊂关键词:PPDs ;6PPD -Q ;道路尘土;暴露评估文章编号:1673-5897(2023)4-253-12㊀㊀中图分类号:X171.5㊀㊀文献标识码:ADistribution Characteristics and Human Exposure Assessment of p -pheny-lenediamine (PPD )Antioxidants and Their Oxidation Products in Road Dust and Nearby TopsoilZhang Yuying 1,2,Geng Ningbo 2,#,Yan Lei 1,*,Wang Longxing 2,Zhang Haijun 2,Chen Jiping 2254㊀生态毒理学报第18卷1.College of Resources and Environment,Northeast Agriculture University,Harbin150030,China2.CAS Key Laboratory of Separation Sciences for Analytical Chemistry,Dalian Institute of Chemical Physics,Chinese Academy of Sciences,Dalian116023,ChinaReceived19March2023㊀㊀accepted12April2023Abstract:N,N -substituted p-phenylenediamine(PPD)is widely used antioxidant in rubber tire,which may con-tinuously release and accumulate in road dust with the tire wear.As an ozonation product of N-(1,3-dimethylbutyl)-N -phenyl-p-phenylenediamine(6PPD),6PPD-quinone(6PPD-Q)have attracted much attention currently due to the high toxicity to coho salmon.However,information on the environmental behavior of PPDs and6PPD-Q re-mains limited.The present study collected dust and topsoil samples from five different urban areas in Dalian to in-vestigate the distribution characteristics of six PPDs and6PPD-Q.The results indicated that6PPD,6PPD-Q,N,N -di-2-naphthyl-p-phenylenediamine(DNPD)and N,N -(1,4-dimethylpentyl)-p-phenylenediamine(77PD)were de-tected in100%of road dust samples.While,in topsoil samples,only6PPD,6PPD-Q,and77PD were detected in more than70%samples,N-phenyl-N -cyclohexyl-p-phenylenediamine(CPPD)was not detected in all samples. 6PPD-Q was detected at higher level in most road dust samples,the concentrations ranged from0.12to52.21ng㊃g-1(median:7.18ng㊃g-1),which account for34.10%of the total concentration,followed by DNPD and6PPD,the concentrations ranged from0.61to113.83ng㊃g-1(median:2.54ng㊃g-1)and0.21to27.26ng㊃g-1(median:1.83ng ㊃g-1),respectively.Total PPDs concentration(ΣPPDs)ranged from3.59to131.37ng㊃g-1with the median concen-tration of11.24ng㊃g-1.ΣPPDs and6PPD-Q in urban trunk dust were significantly higher than that in residential dust and residential plaza dust.A lower detection rate of each compound was observed in the topsoil collected from the residential green belt.However,the topsoil collected from agricultural land exhibited a higher level than that collected in the residential green belt due to its proximity to the source.The daily intake of each compound was calculated and the results showed that6PPD-Q was at the highest exposure amount.Oral intake ofΣPPDs and 6PPD-Q was much greater than dermal intake.The intake ofΣPPDs and6PPD-Q exhibited the same trend:trunk road>residential road>residential pared with residential road and residential square road dust,expo-sure to urban trunk road dust accounting for more than70%of the intake forΣPPDs and6PPD-Q.The daily in-takes ofΣPPDs were0.13,0.02and0.01ng㊃kg-1㊃d-1and6PPD-Q were0.06,0.02and0.01ng㊃kg-1㊃d-1for the main road,residential road and square dust samples,respectively.The intakes ofΣPPDs and6PPD-Q for children was0.20ng㊃kg-1㊃d-1and0.11ng㊃kg-1㊃d-1,which is nearly twice that of adults.The present study selected five sampling areas closely-related with resident life,and the high concentrations of6PPD-Q in road dust may pose a potential human health risk.Keywords:PPDs;6PPD-Q;road dust;exposure assessment㊀㊀N,N -取代对苯二胺(PPD)是橡胶中广泛使用的抗氧化剂[1],人们将常见的对苯二胺类抗氧化剂统一称为PPDs㊂据估计,全球每年生产近31亿条轮胎[2],对PPDs有较高的需求㊂仅在中国,2009年PPDs消耗量超过10万t[3]㊂N-异丙基-N -苯基-1, 4-苯二胺(IPPD)㊁N-苯基-N -环己基对苯二胺(CP-PD)㊁N,N -二苯基对苯二胺(DPPD)㊁N-(1,3-二甲基丁基)-N -苯基对苯二胺(6PPD)㊁N,N -二-2-萘基对苯二胺(DNPD)和N,N -(1,4-二甲基戊基)-对苯二胺(77PD)是常见的对苯二胺类抗氧化剂[4]㊂其中, 6PPD对淡水生物具有急性和慢性毒性[5],并可能引起人类皮肤过敏反应㊂IPPD对人胚胎肺成纤维细胞有一定的毒性[6]㊂DPPD对大鼠具有生殖和发育毒性[7]㊂近年来,人们发现6PPD的臭氧转化产物, 6PPD-quinone(6PPD-Q)对银大马哈鱼(coho salmon)具有急性致死效应(半数致死浓度LC50<95ng㊃L-1)㊂进而开始关注PPDs及其衍生物的环境水平和健康风险㊂橡胶制品的广泛使用导致PPDs及其衍生物大量释放到环境中㊂PPDs作为抗氧化剂应用于橡胶产品,特别是用于生产轮胎㊁管道㊁皮带和鞋底的橡胶材料[8],还可能被应用于制备染发剂[9]㊁指甲油染料[10]㊁润滑剂[11]等㊂越来越多的研究表明第4期张钰莹等:对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估255㊀PPDs和6PPD-Q在尘土[8,12-15]㊁大气颗粒物[16-18]㊁地表径流[19-22]㊁沉积物[23-24]㊁食品[25]以及人类尿液[26]中广泛存在㊂道路尘土是PPDs和6PPD-Q主要的赋存介质,可以直接随着雨水进入地表径流进而对水生生物带来危害,因此全面开展PPDs和6PPD-Q在道路尘土中的污染特征研究至关重要㊂目前为止,有关尘土及土壤中PPDs和6PPD-Q的数据十分有限㊂Huang等[8]报道了中国广州地区道路尘土中6种PPDs(ΣPPDs)的总浓度为20.3~543ng㊃g-1,其中IPPD浓度为3.0~88.1ng㊃g-1,77PD浓度为<LOQ ~38.5ng㊃g-1,DPPD浓度为5.8~126ng㊃g-1,DN-PD浓度为1.5~35.9ng㊃g-1,6PPD浓度为4.1~238 ng㊃g-1,而6PPD-Q浓度为3.0~88.1ng㊃g-1㊂在中国香港收集的道路尘土样本中,6PPD和6PPD-Q的浓度分别为31.4~831ng㊃g-1(中值:309ng㊃g-1)和9.50~936ng㊃g-1(中值:234ng㊃g-1)[27]㊂Huang等[8]对中国广州市4个不同功能区尘土中的PPDs和6PPD-Q进行分析,结果表明,地下停车场中ΣPPDs 浓度最高(35.8~1481ng㊃g-1;中值:232ng㊃g-1),道路尘土中为20.3~543ng㊃g-1(中值:226ng㊃g-1),车辆内粉尘中为56.6~604ng㊃g-1(中值:156ng㊃g-1),房屋粉尘中浓度最低为<LOQ~207ng㊃g-1(中值:14 ng㊃g-1);6PPD-Q浓度由大到小依次为:车辆粉尘(中值:80.9ng㊃g-1)>地下停车场尘土(中值:41.8ng ㊃g-1)>道路尘土(中值:32.2ng㊃g-1)>房屋粉尘(中值:<LOQ)㊂Hiki和Yamamoto[28]报道了日本东京道路尘土中6PPD和6PPD-Q的水平分别为45~1175 ng㊃g-1(中值:329ng㊃g-1)和116~1238ng㊃g-1(中值:809ng㊃g-1);与住宅道路相比,主干道尘土中的6PPD-Q浓度更高㊂综上,不同城市功能区尘土中PPDs和6PPD-Q的污染水平差异很大,但目前仅有2篇文章开展了相关研究工作,使其健康风险评估存在很大的不确定性,有待进一步开展系统的研究工作㊂为探讨PPDs和6PPD-Q的区域污染特征,以大连市为研究对象开展试验,从与居民日常生活密切相关的不同区域采集样品,包括主干道㊁居民区道路和居民广场的尘土样品,以及居民区绿化带㊁农田表层的土壤样品,采用高效液相色谱串联质谱法(HPLC-MS/MS)对样品中的6种PPDs以及6PPD-Q 进行定量分析,并对比了尘土与土壤样品中目标物质的污染特征,进一步根据美国环境保护局(US EPA)的风险评估模型,估计了道路源尘土中目标化合物对儿童及成人的暴露量,以期为保护人群健康提供基础数据㊂1㊀材料与方法(Materials and methods)1.1㊀试剂与仪器材料与试剂:PPDs抗氧化剂标准品(IPPD㊁DP-PD㊁CPPD㊁6PPD㊁77PD㊁DNPD)和6PPD-Q分别购自阿拉丁(中国上海)㊁玛雅试剂(中国上海)㊁凯为化学(中国上海)㊁百灵威(中国北京)㊁TCI化学(日本东京)和加拿大多伦多研究化学(加拿大多伦多)㊂2个内标苯胺-d5和6PPD-Q-d5分别购自加拿大多伦多研究化学和上海安谱实验科技股份有限公司(中国)㊂试验所用试剂丙酮(农残级)购自美国Fisher公司,二氯甲烷(农残级)购自美国J.T.Baker公司,乙腈(HPLC-MS级)购自美国默克公司,超纯水由Millipore 超纯水设备制备而成(Millipore,Billerica,MA,USA)㊂仪器:土壤玛瑙研磨机(中国长沙米淇公司, MITR-TRXQM-1L),超声波清洗仪(美国Branson公司,B5200S),氮气吹干仪(中国北京八方世纪科技有限公司,BF2000),旋转蒸发仪(瑞士Buchi公司,Ro-tavapor R-205),电子天平(中国上海精密仪器仪表有限公司,JA-2003型),移液器(德国艾本德公司,Ep-pendorf Research®plus),Milli-Q超纯水(美国,Milli-pore),高效液相色谱-三重四极杆质谱联用仪(美国Thermo公司,HPLC-MS/MS,TSQ Quantum Access),台式低速离心机(中国上海力辰仪器科技有限公司, LC-LX-L40B),氮气吹扫仪(中国上海安谱实验科技股份有限公司,DC12H),凝胶渗透色谱仪(中国大连依利特分析仪器有限公司,GPC-P230)㊂1.2㊀样品采集2022年9月 2023年3月,在大连市共采集样品39份:其中尘土样品19份,包括城市主干道(ur-ban trunk dust,UD;N=7)㊁居民区道路(residential dust,CD;N=7)以及居民广场(residential plaza dust, SQ;N=5);表层土样品20份,采集于高速公路两侧10m范围内农田(agricultural land,FS;N=13)以及居民区绿化带(residential green belt,CS;N=7),将表面杂草等杂质去除后,采集表层土㊂使用预先清洗过的毛刷采集道路尘土和表层土样品,为减少交叉污染,每个采样点使用一个新的刷子,然后用铝箔纸包裹放入聚乙烯密封袋,运入实验室在-20ħ下储存至提取和分析㊂采样点地理信息如表1所示㊂256㊀生态毒理学报第18卷表1㊀试验采样点地理信息Table1㊀Geographical information of test sampling sites注:UD表示城市主干道尘土,CD表示居民区道路尘土,SQ表示居民广场尘土;FS表示高速公路两侧10m范围内农田表层土,CS表示居民区绿化带表层土㊂Note:UD indicates urban trunk road dust,CD indicates residential road dust,SQ indicates residential square dust;FS indicates farmland topsoil within10 m on both sides of the highway,and CS indicates residential green belt topsoil.1.3㊀样品前处理尘土与土壤样品去除石块㊁树枝等杂质后自然风干,然后用球磨机磨碎至完全通过150μm孔径铜质标准筛㊂取0.5g样品放入15mL玻璃离心管内,加入20ng提取内标(6PPD-Q-d5),10mL丙酮,超声15minˑ3次,合并提取液并在3000r㊃min-1离心力下离心5min,上清液转移至100mL平底烧瓶中㊂经旋转蒸发后氮吹浓缩至近干,加入2mL二氯甲烷复溶,将溶液通过0.22μm PTFE滤膜后通过GPC进一步去除提取液中的脂质,GPC流动相为二氯甲烷,检测器波长为254nm,设置流速为5mL㊃min-1,收集22~38min的流出组分,旋转蒸发后氮吹浓缩至近干,加入20ng进样内标苯胺-d5,用乙腈定容至1mL,过0.22μm PTFE滤膜后储存至棕色液相小瓶中待上机分析㊂1.4㊀仪器分析采用HPLC-MS/MS对目标化合物进行定量分析㊂液相参数:色谱分离采用C8液相色谱柱(100 mmˑ2.1mm,1.7μm,ACQUITY UPLC,美国Wa-ters)㊂流动相A为含0.8%(mʒm)乙酸铵的水(pH= 3),流动相B为乙腈,流速为0.18mL㊃min-1㊂流动相梯度为:0~20min:40%B~92%B;20~20.2 min:92%B~100%B;20.2~30min:100%B~40% B㊂进样量为10μL,色谱柱温度设定为25ħ㊂质谱参数:电喷雾离子源,正离子电离模式(ESI+);电离电压:3.5kV;辅助气压力:7.0ˑ104Pa;鞘气压力:2.8ˑ105Pa,传输毛细管温度为300ħ,鞘气温度为340ħ,碰撞气压力为0.2Pa㊂采集数据模式:多反应监测(MRM)㊂7种目标物质的质谱参数如表2所示㊂1.5㊀质量保证和质量控制为保证样品测定的准确性与可靠性,开展了一系列质控实验㊂目标污染物采用内标法定量分析,混合标准溶液浓度梯度为0.5~200ng㊃mL-1,进样内标在标准溶液中的浓度为20ng㊃mL-1,其线性回归系数R2ȡ0.99㊂为评估实验室分析过程中的潜在污染,本研究分析了3个全程空白样品(仅添加溶剂与内标),采用与样品完全相同的方法进行前处理和仪器分析,包括:丙酮超声提取3次,氮吹浓缩,二氯甲烷复溶,GPC脱脂,氮吹浓缩,复溶于乙腈中过滤并进行上机分析㊂在空白样品中均未检出目标物质㊂将6个混合样品中加入100μL混合标准溶液第4期张钰莹等:对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估257㊀表2㊀目标化合物的HPLC-MS /MS 参数Table 2㊀HPLC -MS/MS parameters of target compounds目标物质Target compounds保留时间/min Retention time/min母离子(m /z )Parent ion (m /z )子离子(m /z )Product ion (m /z )碰撞能/V Collision energy/V透镜管电压/V Lens tube voltage/VIPPD2.85227.1107.13470184.12070CPPD 4.89267.0107.13776184.12376DPPD 9.16261.0107.14270184.124706PPD 6.68269.1107.14270184.1217077PD 8.99305.1135.22977206.21677DNPD 11.34361.1219.12590234.028906PPD -Q 8.23299.1187.12284241.02784注:IPPD 表示N -异丙基-N -苯基-1,4-苯二胺,77PD 表示N,N -(1,4-二甲基戊基)-对苯二胺,DPPD 表示N,N -二苯基对苯二胺;DNPD 表示N,N -二-2-萘基对苯二胺,6PPD 表示N -(1,3-二甲基丁基)-N -苯基对苯二胺,6PPD -Q 表示6PPD -quinone ,ΣPPDs 表示6种PPDs 总和㊂Note:IPPD indicates N -isopropyl -N -phenyl -1,4-phenylenediamine,77PD indicates N ,N -(1,4-dimethylpentyl)-p -phenylenediamine,DPPD indicates N ,N -diphenyl -p -phenylenediamine,DNPD indicates N ,N -di -2-naphthyl -p -phenylenediamine,6PPD indicates N -(1,3-dimethylbutyl)-N -phenyl -p -pheny -lenediamine ,6PPD -Q indicates 6PPD -quinone,and ΣPPDs indicates the sum of the six PPDs.(10ng ㊃mL -1),采用与样品完全相同的方法进行前处理和仪器分析,得出目标化合物的方法检出限(method detection limit,MDL)为IPPD :1.47ng ㊃g -1㊁CPPD :2.29ng ㊃g -1㊁77PD :0.34ng ㊃g -1㊁DPPD :1.46ng ㊃g -1㊁DNPD :1.23ng ㊃g -1㊁6PPD :0.43ng ㊃g -1㊁6PPD -Q :0.24ng ㊃g -1㊂加标回收率实验则是将6个混合尘土样品中加入100μL 混合标准溶液(100ng ㊃mL -1),采用与样品完全相同的方法进行前处理和仪器分析㊂6种目标物质的回收率为82.87%~100.57%㊂6种PPDs 总和(ΣPPDs)和6PPD -Q 基质效应(ME)参考文献报道的方法进行评估[12,29];使用混合尘土样品采用与样品相同的前处理方法进行提取与净化,将最终提取液溶解在1mL 乙腈中,然后取出2个相同体积(0.2mL)的子样品㊂子样品A 加入0.2mL 混合标准溶液,子样品B 中加入0.2mL 乙腈,外标S 为0.2mL 混合标准溶液+0.2mL 乙腈㊂ME 值的计算方法是:ME %()=(A i -B i )S iˑ100式中:A i ㊁B i 和S i 分别为子样品A 和B 以及外标溶液中被分析物(i )的色谱峰面积㊂在6次测量中,7个目标分析物的基质效应值在88.29%到108.13%之间,表明基质效应较低㊂因此,本试验在后续的数据分析中忽略了尘土基质对6种PPDs 和6PPD -Q 分析的基质效应干扰㊂1.6㊀人体暴露评估不同环境介质中的PPDs 及6PPD -Q 会通过不同的暴露途径进入人体并带来健康风险㊂尘土中的PPDs 及6PPD -Q 可以通过经口摄入和皮肤接触这2种途径进入人体㊂因此,本研究在暴露评估中计算了成人与儿童的日摄入量,计算公式如下:DI der =C RS ˑCF ˑSA ˑAF ˑABS ˑEF ˑEDBW ˑATDI ing =C RS ˑIR ing ˑCF ˑEF ˑED BW ˑAT式中:DI der 和DI ing 表示通过尘土经皮肤吸收和经口摄入途径的每日摄入量;C RS 代表尘土中ΣPPDs 的总浓度以及6PPD -Q 的浓度(ng ㊃kg -1);IR ing 代表尘土的摄入率(mg ㊃d -1);EF 代表暴露频率(d ㊃a -1);ED 代表暴露持续时间(a);BW 代表体质量(kg);AT 代表平均暴露时间(d);CF 代表转换因子(10-6kg ㊃mg -1);SA 代表可接触皮肤表面积(cm 2);AF 代表尘258㊀生态毒理学报第18卷土对毛皮的附着系数(mg ㊃cm -2);ABS 代表吸收系数(量纲为1)㊂用于评估儿童和成人日摄入量的参数如表3所示,符合美国国家环境保护局风险评估指南和相关研究[27,30-31]㊂2㊀结果(Results )2.1㊀道路尘土和附近表层土中PPDs 和6PPD -Q 的污染水平㊀㊀7种目标化合物中,所有样品中均未检出CP -PD ,后续仅对检出的6种化合物进行统计分析㊂不同区域样品中ΣPPDs 和6PPD -Q 浓度的统计结果如图1所示,6种目标化合物总浓度为2.58~175.75ng ㊃g -1(中值:15.27ng ㊃g -1),其中ΣPPDs 浓度为2.46~130.22ng ㊃g -1(中值:10.09ng ㊃g -1),6PPD -Q 浓度为<MDL ~52.21ng ㊃g -1(中值:7.18ng ㊃g -1)㊂与其他PPDs 相比,6PPD -Q 的污染水平较高,与ΣPPDs 浓度处于同一水平,表明PPDs 以及6PPD -Q 广泛存在于交通区域和居民生活区域的尘土中㊂表3㊀评估儿童及成人暴露于PPDs 和6PPD-Q 的日摄入量参数Table 3㊀Parameters used to estimate human exposure to PPDs and 6PPD -Q参数Parameter 单位Unit 儿童Children 成人Adult 尘土摄入率(IR ing )Ingestion rate (IR ing )mg ㊃d -1200100暴露频率(EF)Exposure frequency (EF)d ㊃a -1365365暴露持续时间(ED)Exposure duration (ED)a624体质量(BW)Body weight (BW)kg 16.5858.55平均暴露时间(AT)Average time during exposure (AT)d 365ˑ70365ˑ70转换因子(CF)Conversion factor (CF)kg ㊃mg -110-610-6可接触皮肤表面积(SA)Skin surface area available for contact (SA)cm 211502145尘土对毛皮的附着系数(AF)Soil to skin adherence factor (AF)mg ㊃cm -20.20.07吸收系数(ABS)Adsorption factor (ABS)%1313图1㊀道路尘土和附近表层土中ΣPPDs 和6PPD-Q 浓度水平Fig.1㊀Concentrations of ΣPPDs and 6PPD -Q in road dust and nearby topsoil第4期张钰莹等:对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估259㊀图2 道路尘土和附近表层土中目标化合物的浓度Fig.2㊀Concentration of each target compound in road dust and nearby topsoil㊀㊀本研究中,道路尘土和表层土的污染水平差别较大㊂如图2所示,在19份尘土样品6PPD -Q ㊁6PPD ㊁DNPD 以及77PD 的检出率均为100%;而IPPD 和DPPD 检出率较低,均为42.10%,主干道尘土中的6PPD ㊁DNPD 和6PPD -Q 浓度分别为1.61~27.26ng ㊃g -1(中值:3.52ng ㊃g -1)㊁10.84~113.83ng ㊃g -1(中值:19.08ng ㊃g -1)和42.33~52.21ng ㊃g -1(中值:47.35ng ㊃g -1),显著高于居民区道路尘土(6PPD :0.89~3.69ng ㊃g -1,中值1.95ng ㊃g -1;DNPD :2.13~20.33ng ㊃g -1,中值3.78ng ㊃g -1;6PPD -Q :5.32~44.54ng ㊃g -1,中值10.07ng ㊃g -1)(P <0.05)和广场尘土(6PPD :1.42~1.84ng ㊃g -1,中值1.48ng ㊃g -1;DNPD :1.79~12.39ng ㊃g -1,中值3.23ng ㊃g -1;6PPD -Q :1.99~14.45ng ㊃g -1,中值5.85ng ㊃g -1)(P <0.05)㊂77PD 在主干道㊁居民区和广场尘土中含量没有显著差异(P >0.1),浓度范围为1.65~7.57ng ㊃g -1㊂仅在主干道尘土中检测到DPPD ,浓度为1.64~27.55ng ㊃g -1(中值:9.79ng ㊃g -1)㊂IPPD 在主干道和居民区仅有一个样品检出,浓度分别为15.29ng ㊃g -1和2.23ng ㊃g -1,居民广场尘土中检出率为100%,浓度为1.52~20.33ng ㊃g -1㊂农田表层土样品中77PD ㊁6PPD 和6PPD -Q 的检出率均为100%,浓度范围分别为0.68~3.95ng ㊃g -1(中值:1.12ng ㊃g -1)㊁0.94~4.48ng ㊃g -1(中值:2.14ng ㊃g -1)和0.39~18.61ng ㊃g -1(中值:5.72ng ㊃g -1);DNPD 的检出率为46.15%,浓度范围为<MDL ~18.40ng ㊃g -1(中值:<MDL),IPPD 和DPPD 均未检出㊂在居民区绿化带表层土中6种目标物质的检出率均低于50%,未检出IPPD 和DPPD ,DNPD 检出率为28.57%,浓度范围为1.77~5.07ng ㊃g -1;77PD 和6PPD -Q 的检出率均为42.86%,其中,77PD 浓度范围为0.61~4.19ng ㊃g -1,6PPD -Q 浓度范围为0.37~2.42ng ㊃g -1;仅在样品CS1中检测到6PPD ,浓度为0.66ng ㊃g -1㊂2.2㊀道路尘土和附近表层土中ΣPPDs 和6PPD -Q 的分布特征㊀㊀不同区域样品中各目标化合物的分布特征存在差异,由于PPDs 类化合物容易降解[32],而不同化合物降解速率不同,导致距离排放源较远的土壤样品中化合物的分布特征不同㊂在UD ㊁CD ㊁SQ 以及FS 这4个区域中,6PPD -Q 是含量最高的组分,占ΣPPDs 和6PPD -Q 总浓度的34.54%~53.63%(平均值43.84%),其次是DNPD ,占ΣPPDs 和6PPD -Q 总浓度的17.87%~37.06%(平均值27.48%)㊂由于居民区绿化带表层土(CS)中各化合物检出率较低,去掉6个化合物均未检出的CS4㊁CS5㊁CS6和CS7,其余3个样品中DNPD 和77PD 占比较高(图3)㊂主干道尘土中6PPD -Q 与DNPD 占ΣPPDs 和6PPD -Q 总浓度的79.54%;其次为DPPD 和6PPD ,占比分别为9.28%和6.63%;IPPD 和77PD 仅占总浓度的4.54%㊂居民区道路的6PPD -Q 与DNPD 占总浓度的78.42%,77PD 占比为11.06%,6PPD 占比为5.69%,IPPD 和DPPD 仅占总浓度的4.82%㊂居民广场中6PPD -Q 与DNPD 占总浓度的64.72%,260㊀生态毒理学报第18卷77PD 占比为13.63%,IPPD 占比较高(9.44%),其次为6PPD(7.47%),DPPD 的占比最低为4.74%㊂高速公路两侧农田表层土样品中各组分占比6PPD -Q (44.73%)>DNPD (17.87%)>6PPD (15.89%)>77PD(10.21%)>IPPD (6.40%)>DPPD (4.91%),77PD ㊁DNPD 和6PPD 是农田表层土PPDs 的主要成分,尽管三者占ΣPPDs 和6PPD -Q 总浓度的16.49%~70.92%,但对ΣPPDs 含量的贡献在70%以上,说明这3种抗氧化剂广泛应用于橡胶及其相关制品的制造中[33-35]㊂图3㊀道路尘土和附近表层土中目标化合物的组成Fig.3㊀Composition of target compounds in road dust and nearbytopsoil图4㊀PPDs 和6PPD-Q 的浓度相关性注:(a)5种PPDs 和6PPD -Q 的Pearson 相关性;(b)6PPD 和6PPD -Q 的相关性拟合㊂Fig.4㊀Correlation between the concentration of PPD and 6PPD -Q in the sampleNote:(a)Pearson s rank correlation for PPDs and 6PPD -Q;(b)Correlation between 6PPD and 6PPD -Q concentrations.第4期张钰莹等:对苯二胺类抗氧化剂及其氧化产物在道路尘土和附近表层土中的分布特征及人体暴露评估261㊀图5㊀儿童和成人ΣPPDs 和6PPD-Q 日摄入量分析注:DI 表示目标化合物的日摄入量,DI ing 表示经口摄入量,DI der 表示经皮肤摄入量Fig.5㊀Daily intakes of ΣPPDs and 6PPD -Q in children and adultsNote:DI indicates daily intake of the target compound,DI ing indicates oral intake and DI der indicates dermal intake.2.3㊀PPDs 与6PPD -Q 浓度相关性分析采用Pearson 相关分析法检验了不同区域尘土样品及表层土样品中ΣPPDs 和6PPD -Q 浓度之间的相关性㊂除77PD 外,所有PPDs 和6PPD -Q 的浓度均呈显著正相关㊂常用抗氧化剂6PPD 浓度与DPPD(ρ=0.80)和DNPD(ρ=0.83)的浓度呈强相关(P ɤ0.001),表明三者具有相似的来源㊂6PPD 是商用轮胎配方中添加量最大的一种对苯二胺类抗氧化剂,添加量约为1%~4%[33-35],另外DPPD 和DNPD 也是常用的抗氧化剂[36]㊂本研究的39个道路尘土以及土壤样品中,6PPD 与6PPD -Q 的浓度之间存在着强烈的线性相关(r =0.78,P <0.01),由于6PPD -Q 是6PPD 与臭氧反应的产物,其高相关性表明6PPD -Q 的累积对6PPD 在尘土中的环境存量有明显的依赖性㊂2.4㊀ΣPPDs 和6PPD -Q 的人体暴露评估道路尘土中PPDs 及氧化产物6PPD -Q 可能经口和皮肤进入人体,根据本研究在不同环境尘土中测得的目标化合物浓度,我们估算了该类污染物的成人和儿童的每日摄入量,以初步评估其人体健康风险㊂在此评估中,经口摄入和皮肤吸收被认为是平行进行的㊂儿童与成人通过尘土经皮肤吸收和经口摄入的5种PPDs 以及6PPD -Q 每日摄入量如图5所示㊂结果表明,无论成人还是儿童,ΣPPDs 和6PPD -Q 的经口摄入量均大于皮肤吸收量,对于儿童而言,ΣPPDs 和6PPD -Q 经口摄入量分别为0.10ng ㊃kg -1㊃d -1和0.08ng ㊃kg -1㊃d -1;对于成人而言,ΣPPDs 和6PPD -Q 经口摄入量分别为0.06ng ㊃kg -1㊃d -1和0.04ng ㊃kg -1㊃d -1㊂ΣPPDs 和6PPD -Q 在3种不同尘土环境中的摄入量呈现相同的趋势,均为主干道尘土>>居民区道路尘土>居民广场道路尘土,3种尘土样品中ΣPPDs 的日摄入量分别为0.12㊁0.03㊁0.02ng ㊃kg -1㊃d -1,6PPD -Q 的日摄入量分别为0.09㊁0.04㊁0.01ng ㊃kg -1㊃d -1㊂儿童与成人的日摄入量存在差异,儿童对于ΣPPDs 的总摄入量为0.12ng ㊃kg -1㊃d -1,成人摄入量仅为儿童的近50%;对于6PPD -Q ,儿童的摄入量为0.09ng ㊃kg -1㊃d -1,而成人仅为0.05ng ㊃kg -1㊃d -1,表明该类化合物的儿童暴露量显著高于成人㊂3㊀讨论(Discussion )本研究对与居民生活密切相关的不同环境中尘土以及表层土中的PPDs 和6PPD -Q 进行了污染特征分析和暴露评估,阐明了不同环境中PPDs 和6PPD -Q 的复合污染概况,将不同区域尘土以及表层土样品中的PPDs 和6PPD -Q 的存在水平进行对比,并进一步分析其不同的污染特征㊂结果表明,6PPD ㊁6PPD -Q ㊁DNPD 和77PD 在道路尘土样品中的检出率均为100%;农田表层土样品中77PD ㊁6PPD 和6PPD -Q 的检出率均为100%;在居民区绿化带表层土中6种目标物质的检出率均低于50%,CPPD 在所有样品中均未检到㊂6PPD -Q 浓度最高,和ΣPPDs 具有相同的浓度分布趋势,即主干道尘土>居民区道路尘土>居民广场尘土>农田表层土>绿化带表层土,ΣPPDs 和6PPD -Q 在道路尘土中的含量远高于表层土㊂将主干道尘土作为ΣPPDs 和6PPD -Q 的主要来源介质,我们可以看出,ΣPPDs 和262㊀生态毒理学报第18卷6PPD-Q能够随着 主干道尘土-居民区道路尘土-居民广场尘土-绿化带表层土 的路径迁移而浓度水平和检出率逐渐降低㊂本研究不同环境尘土中PPDs组成存在较大差异,车流量较大的城市主干道中,DPPD㊁DNPD㊁6PPD含量最高,这可能由于这3种物质被广泛用于商用车轮胎配方中[32-33]㊂另外,除了主干道尘土,居民区道路尘土中77PD检出率也为100%,这可能由于77PD可用于居民区内电线的橡胶涂层[37]㊂农田表层土中的77PD㊁6PPD和6PPD-Q含量及检出率均高于绿化带表层土㊂本研究绿化带表层土均选自无汽车通行居民小区,目标化合物浓度偏低且检出率均低于50%,而农田表层土均采集自高速公路两侧10m内的农田㊂不同环境之间的浓度的差异表明,汽车通行乃至橡胶轮胎的使用对PPDs和6PPD-Q污染情况有很大影响,轮胎在道路上摩擦形成的磨损颗粒可能是这些橡胶添加剂释放的主要途径[38]㊂此外,PPDs还可能被应用于染发剂[9]㊁指甲油染料[10]㊁润滑剂[11]等的制备,这些均与居民生活息息相关,所以,居民区道路尘土㊁居民广场尘土以及居民区绿化带表层土中的PPDs 可能并不仅来源于橡胶轮胎磨损,而是多种因素综合作用㊂本研究中主干道尘土中ΣPPDs浓度水平(中值:62.64ng㊃g-1)低于日本东京主干道(中值:329ng ㊃g-1)[28]和中国广州市道路尘土(中值:156ng㊃g-1)[8],高于中国南方某电子垃圾拆解区周边家庭客厅尘土(中值:14ng㊃g-1)[8]㊂本研究中主干道尘土中6PPD-Q的检出水平(中值:42.33ng㊃g-1)远低于日本东京主干道(中值:809ng㊃g-1)[28]㊁中国香港新界和九龙地区交通密集道路(中值:234ng㊃g-1)[27]和广州市主干道(中值:122ng㊃g-1)[8]㊂推测单位时间内车流量可能是引起PPDs和6PPD-Q浓度差异的主要原因㊂健康风险评估表明,经口摄入是人体接触PPDs和6PPD-Q的主要途径㊂儿童与成年人经皮肤吸收占经口摄入量的14.95%~19.52%㊂儿童6PPD-Q的总摄入量估计为0.09ng㊃kg-1㊃d-1,低于其母体化合物的剂量(0.12ng㊃kg-1㊃d-1);成人6PPD-Q的总摄入量估计为0.05ng㊃kg-1㊃d-1,略低于其母体化合物的剂量(0.07ng㊃kg-1㊃d-1)㊂儿童暴露于尘土中ΣPPDs及6PPD-Q的健康风险大于成人的主要原因是:儿童单位体质量的摄入比成人多,且具有相对频繁的手对口的行为㊂鉴于对苯二胺类抗氧化剂的广泛使用以及橡胶轮胎磨损颗粒的持续产生,道路尘土中6PPD-Q的高水平存在对成年人及儿童具有潜在的健康风险㊂成人对于3种尘土样品中6PPD的日摄入量分别为0.005㊁0.001㊁0.001ng㊃kg-1㊃d-1,儿童对于3种尘土样品中6PPD的日摄入量分别为0.005㊁0.002㊁0.002ng㊃kg-1㊃d-1㊂Liu等[39]的研究中,儿童对于室内尘土㊁操场尘土中6PPD的每日摄入量中值分别为0.04ng㊃kg-1㊃d-1和0.11ng㊃kg-1㊃d-1,成人对于室内尘土中6PPD的日摄入量中值为0.008ng㊃kg-1㊃d-1㊂本研究所得6PPD日摄入量远低于Liu等的研究㊂就6PPD-Q而言,作为新出现的污染物,我们无法获得它的允许日摄入量值㊂然而,尘土中6PPD-Q的日摄入量与尘土中全氟和多氟烷基物质(PFAS)[40]处于同一水平,但低于有机磷酸酯(OPEs)[41]的日摄入量㊂通信作者简介:闫雷(1974 ),女,博士,教授,主要研究方向为生态毒理学㊂共同通信作者简介:耿柠波(1985 ),女,博士,副研究员,主要研究方向为生态毒理学㊂参考文献(References):[1]㊀Huntink N M,Datta R N,Noordermeer J W M.Address-ing durability of rubber compounds[J].Rubber Chemistryand Technology,2004,77(3):476-511[2]㊀Tian Z Y,Zhao H Q,Peter K T,et al.A ubiquitous tirerubber-derived chemical induces acute mortality in cohosalmon[J].Science,2021,371(6525):185-189[3]㊀吕咏梅.对苯二胺类橡胶防老剂技术进展及市场需求分析[J].橡胶科技市场,2010,8(21):1-5[4]㊀Datta R N,Huntink N M,Datta S,et al.Rubber vulcani-zates degradation and stabilization[J].Rubber Chemistryand Technology,2007,80(3):436-480[5]㊀Klauschies T,Isanta-Navarro J.The joint effects of saltand6PPD contamination on a freshwater herbivore[J].Science of the Total Environment,2022,829:154675 [6]㊀朱勇,丁璐,徐艳琼.橡胶防老剂4020㊁4010NA对人胚肺成纤维细胞的毒性对比[J].职业与健康,2016,32(14):1991-1992,1996Zhu Y,Ding L,Xu Y Q.A comparative study of toxicityof rubber antioxidant4020and4010NA on human em-bryonic lung fibroblast cells[J].Occupation and Health,2016,32(14):1991-1992,1996(in Chinese)[7]㊀Matsumoto M,Yamaguchi M,Yoshida Y,et al.An an-tioxidant,N,N -diphenyl-p-phenylenediamine(DPPD),affects labor and delivery in rats:A28-day repeated dose。
高锰酸钾降解土霉素的研究
摘要抗生素的使用为我们的生活带来了便利,但是抗生素的滥用会造成环境污染问题。
目前我国土霉素(Oxytetracycline,OTC)的污染现象十分严重。
当土霉素进入环境中,会诱导细菌等微生物产生抗性基因,成为耐药菌。
耐药菌的产生会对环境与人体健康产生很大危害,因此去除这类抗生素十分有必要。
因为土霉素的生物特性和结构特征导致传统的生物法氯化法无法有效降解土霉素,需要采用高级氧化技术对其处理。
由于高锰酸钾具有很强的氧化性,而且价格低廉,本研究采用高锰酸钾降解土霉素这一经济高效的处理方法。
探索了高锰酸钾降解土霉素的影响因素和反应中生成物二氧化锰的作用,检测了该条件下反应后溶液的总有机碳去除情况与生物毒性,研究了土霉素降解机理与路径。
实验结果表明,最佳反应条件为:高锰酸钾与OTC摩尔比为10:1、温度为30 ℃、初始pH为4.0,OTC的初始浓度为50 mg/L。
该工艺条件同时适用于低浓度和高浓度的土霉素废水。
在最佳反应条件下反应1 h,土霉素降解率达到93.3%,溶液总有机碳去除率达到91.9%,取此时的溶液进行抑菌圈实验,发现反应1 h后溶液中生物毒性已经消失。
通过对反应过程中生成的二氧化锰MnO2-1与实验室由高锰酸钾和水合硫酸锰制备的二氧化锰MnO2-2进行FTIR、BET和XRD表征对比分析,解释了反应过程中沉淀产生原因,并对MnO2-2单独降解土霉素、MnO2-2联合高锰酸钾降解土霉素以及单独高锰酸钾降解土霉素进行了效果对比,解释了MnO2-1在反应中起到的作用,发现在酸性条件下,该产物没有表现出氧化、吸附和催化作用。
对反应后溶液做LC-MS检测推断土霉素的中间产物,并推出了可能的降解路径:M/Z(461)-M/Z(447)-M/Z(227),最后被降解为二氧化碳和水等无毒物质。
关键词:高锰酸钾;降解;土霉素ABSTRACTThe wide spread use of antibiotics has brought much benefits to human and production, but it also caused the pollution of the environment problem. At present the oxytetracycline pollution phenomenon in our country is very serious. OTC occurrence in natural environment can affect the selection of genetic variants of microorganisms resulting in the development of drug resistant bacteria or pathogens, which may subsequently induce a risk to the ecosystem and human health. It is thus important to remove such a compound from contaminated water. Conventional water treatment methods, such as biodegradation and chlorination, cannot remove OTC efficiently due to its bio-resistant property and chemical stability. Advanced oxidation technologies were needed to process OTC. Potassium permanganate(KMnO4) is a kind of oxidant which has low cost and high oxidation. Potassium permanganate was used to treat OTC solution for researching a kind of more economical and efficient water treatment method. Study on the influence factors of the degradation rate of oxytetracycline, products detected after degradation, degradation pathways and mechanism of oxytetracycline, the removal rate of OTC and biological toxicity of OTC.The study showed that the optimal conditions were: mole ratio of KMnO4 and OTC was 10:1 (K/O = 10), T = 30 ℃, pH = 4.0, OTC initial concentration 50 mg/L. The process conditions could be applied to both low concentration and high concentration OTC solution. The degradation rate of OTC reached 93.3% at 1 h and the removal rate of TOC reached 91.9% at 1 hour in the optimal conditions. Bacteriostatic ring was test and found that the biological toxicity has gone after 1 h. FTIR, BET and XRD were used to analysis the differences between the newly situ formed manganese dioxide (MnO2-1) in degrading process and MnO2-2 formed by KMnO4 and MnSO4·H2O and the cause of MnO2-1. And then three methods of degradation results were contrasted and the function of MnO2-1 was explained. We found that the product MnO2-1 did not show the function of oxidation, adsorption and catalytic. The degradation products were analyzed by TOC and LC-MS. The possible degradation pathway was M/Z(461)-M/Z(447)-M/Z(227) and the final products were non-toxic substances such as Carbon dioxide and water.Keywords:potassium permanganate;degradation;oxytetracycline目录摘要 (I)ABSTRACT (II)第一章绪论 (1)1.1引言 (1)1.2抗生素污染物的来源和危害 (2)1.2.1抗生素污染物的来源 (2)1.2.2四环素类抗生素简介 (3)1.2.3抗生素污染的危害 (5)1.3处理抗生素等污染物方法 (6)1.3.1物理法 (6)1.3.2生物法 (8)1.3.3化学法 (10)1.4高锰酸钾降解抗生素类污染物的研究进展 (14)1.5本课题的研究内容和意义 (15)1.5.1研究内容 (15)1.5.1意义 (16)第二章高锰酸钾降解土霉素的研究 (17)2.1实验试剂及仪器 (17)2.2实验过程 (18)2.2.1实验前期准备 (18)2.2.2实验步骤 (20)2.3 检测方法及表征方法 (21)2.3.1土霉素紫外特征吸收峰的选择 (21)2.3.2高效液相色谱(HPLC)法及标准曲线的制作 (22)2.3.3 BET比表面积检测法 (23)2.3.4傅立叶变换红外光谱检测方法(FTIR) (23)2.3.5 X射线衍射分析(XRD) (24)2.3.6总有机碳分析仪分析方法 (24)2.3.7抑菌圈法检测OTC生物毒性 (24)2.4高锰酸钾单独降解土霉素的研究 (25)2.4.1高锰酸钾用量对降解土霉素的影响 (25)2.4.2土霉素初始浓度对反应的影响 (27)2.4.3 PH对土霉素降解效率的影响 (29)2.4.4温度对土霉素降解效率的影响 (29)2.4.5高锰酸钾对土霉素生物毒性的影响 (30)2.5实验中生成的二氧化锰的作用探讨 (32)2.5.1回收产物与新制备二氧化锰 (32)2.5.2反应中生成和实验室新制备的二氧化锰的表征分析 (33)2.5.3 MnO2-2单独处理OTC溶液以及MnO2-2联合高锰酸钾处理OTC溶液 (35)2.6本章小结 (38)第三章高锰酸钾降解土霉素的机理分析 (40)3.1最优条件下TOC检测结果分析 (40)3.2生成中间产物的分析 (41)3.3高锰酸钾降解OTC的路径分析 (44)3.4本章小结 (45)结论 (46)参考文献 (47)攻读硕士学位期间取得的研究成果 (56)致谢 (57)第一章绪论第一章绪论1.1 引言近年来我国环境污染问题越来越严重,上到大气污染,下至土壤和水资源的污染,环境和资源问题将会是限制未来发展的两大难题。
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To remind people of those Chinese poems and to promote cultural heritage, China Central Television (CCTV) has produced a TV show-Chinese Poetry Competition. The final of the hit show’s second season was shown on Feb7.Wu Yishu, 16, who studies at the High School attached to Fudan University in Shanghai, came out on top. “I really admire her knowledge of poems”, said Huang Zijin, 16, a senior 2 student from Ningbo High School in Zhejiang province. “The first time I saw her wearing traditional Han clothing on TV, I was very impressed by her classical looks. She fulfills all my fantasies for classic Chinese women’s talents. What’s more, she always appears especially calm throughout the show, which is very unusual for her age. ”“Learning poems isn’t about winning or losing. The power of poetry lies in shaping ơne’s view of life and developing one’s inner world,” said Li Bo, an expert at the Chinese Poetry Competition’s second season.When it comes to teaching people about poetry, Li Dingguang, the show’s academic advisor, suggested that teachers should explain more about the beauty of the poetry from both the aesthetie (审美的) and emotional sides, and guide the student to lose themselves in the poems’ rhythmic and rhyming lines.“Although the proportion (比例) of ancient Chinese poems in the textbooks of primary ant secondary schools has increased, many students still learn them for exams,” Li Dingguang told China. org. cn. “Therefore, it’s important to help students truly appreciate the artistry and fun of poetry.”1.China Central Television (CCTV) HOSTS Chinese Poetry Competition aiming at_______.A.enriching Chinese history and literature B.learning poems from ancient peopleC.giving people a chance to compete D.spreading Chinese traditional culture2.Wu Yishu won the first place in the final because of______ .A.Her rich knowledge of poems B.Her wearing traditional Han clothingC.Her rich knowledge of poems and calmness D.Her classical looks3.According to LiBo, why do people learn poetry?A.To get good marks in examination B.To help build up their inner world.C.To win the Chinese Poetry Competition D.To appreciate the beauty of rhythm and rhyme. 4.What is Li Dingguang’s attitude to poetry teaching?A.doubtful B.supportive C.critical D.causal5.What can be inferred from the last paragraph?A.Few Chinese learn poems just for exams.B.Most Chinese learn poems just for exams.C.Poems are now learned by more and more Chinese.D.Not all the students are truly appreciating and learning poems.Beer and eggs are commonly seen in the kitchen. However, scientists recently found that they were used in historic paintings, too.To preserve Danish paintings, a group of researchers studied what was the composition of ancient paint or what it was made of. They did experiments on small pieces of paintings that had already been cut off from the original artwork.According to their paper published in Science-Advances, grains and yeast (酵母) were foundon the base of the paintings. Beer was the most common drink in the 19th century in Denmark, and its by-products were spent (用过已废的) grains and yeast.The study showed that they were used to provide a stable painting surface. Researchers also pointed out that beer by-product was used as a “glue” because it had a lot of sugar. With beer added, the paint can also dry faster.Apart from beer, egg has long been found in oil-based paints used by artists in the 15th century, such as Italian painter Leonardo da Vinci. A recent study published in Nature Communications may have “cracked” the secret of how eggs can help preserve artworks.The researchers re-created the ancient paint by adding egg yolks (蛋黄) to oil paint. They then looked into how it changed over time. The findings showed that the proteins in the yolk helped to slow down the oxidation (氧化) of the paint and reduce wrinkling (皱褶) as the egg makes the paint more smooth.However, the oil paint with added egg usually takes longer to dry. It seemed fine for artists. They were willing to accept that their work would be preserved for a longer period.The more we understand how artists choose and use their materials, the more we can “appreciate what they’re doing”, Ken Sutherland, an expert at the Art Institute of Chicago, US, told Science News. Sutherland added that research like this could help people have a deeper understanding of the artworks.6.What is the main purpose of the research mentioned in the passage?A.To find out how eggs can help to protect the artworks.B.To study the history of beer and egg consumption in Denmark.C.To explore the benefits of beer and egg consumption for artists.D.To research the composition of ancient paint for protecting Danish paintings.7.Why were beer by-products used in historic Danish paintings?A.To keep the paintings clean.B.To help the colors stick better.C.To give the painting a different look.D.To make the paintings more colorful.8.What does the underlined word in Paragraph 5 mean?A.Kept.B.Shared.C.Controlled.D.Discovered.9.How did yolk’s proteins help preserve artworks?A.By adding color to the paint.B.By making the paint dry faster.C.By wrinkling the paint with oil.D.By slowing down the oxidation of the paint.10.According to Ken Sutherland, the research like this provides .A.preservation techniques for paintingsB.deeper understanding of the artworksC.more appreciation for artists’ materialsD.insights into the history of art materialsWhen you are a kid, gaining a best friend forever can happen in a single play date. But when you grow up to be an adult, making and maintaining friendships gets harder. So how much quality time (优质时光) do you need before that stranger becomes your friend? A new study recently found that, on average, it takes about 50 hours with someone before you consider them a casual (感情不深的) friend, about 90 hours before you become real friends, and about 200 hours to become close friends.The study’s author Jeffrey Hall, a communications professor, invited adults who are eager to make friends to take part in two experiments — people who had just moved to a new city in the past six months and college freshmen. He asked them to rate and track the degree of closeness and time spent together with a new person. “Results suggest that the chance of changing from casual friend to real friend is greater than 50% after around 80-100 hours together,” said Hall.The study found that the amount of time spent talking together, or the fact that you spent time at school or work with them, was unrelated to friendship closeness. “It is really easy to spend a lot of time with people as they are routinely in the same place at the same time as you,” Hall said. “However, my study shows you can have workmates you spend hundreds and hundreds of hours with and still not develop a friendship.”You do not need to become best friends with your workmates to develop meaningful relationships with them. But for those of us hoping to change from “girl who I eat lunch at work with” to “friend I can depend on,” Hall suggests that you need to take the relationship out of the workplace for it to become a friendship. The participants who did activities outside of work with someone, such as being invited to have lunch in their home, were more likely to develop deeper relationships with them.11.What is the new study mainly about?A.Ways of making friends in a new environment.B.Why people need to make different friends.C.Different levels of friendship.D.How long it takes to develop a friendship.12.What do we know about the participants in the study?A.They knew each other before.B.They had difficulty in making new friends.C.They were in great need of friends.D.They started their new life in the same city.13.What does Hall want to tell us in paragraph 3?A.It is easy to get along well with classmates.B.Friendship closeness is related to communication.C.It is unnecessary to become best friends with workmates.D.Just spending enough time together doesn’t result in friendship.14.What does the underlined word “routinely” probably mean in paragraph 3?A.Usually.B.Impressive.C.Seldom.D.Confidently.15.Which can help people build deeper relationships with workmates according to Hall?A.Joining the same work team.B.Having lunch at work with them.C.Inviting them to your home after work.D.Sharing work experience with each other.Everybody hates rats. But in the areas where there are many earthquakes, rats will soon be man’s friends.What happens after an earthquake? We send in rescue (营救) dogs. Why? Because they can smell people. Dogs save lives. They help rescuers to find living people. But dogs are big and they can’t get into small spaces. So now a new research project is using a smaller animal to save lives: the rat.How does it work? First, the rat is trained to smell people. When this happens, the rat’s brain gives a signal (信号). This is sent to a small radio on its back, and then the rescuers follow the radiosignals. When the rat’s brain activity jumps, the rescuers know that someone is alive. Although there are already robots which can do this job, rats are better. Christian Linster at Cornel University, New York says, “Robots’ noses don’t work well when there are other smells around. Rats are good at that.” Rats can also see in the dark. They are cheaper and quicker to train than dogs, and unlike robots, they don’t need electricity!The “rat project” is not finished, but Julie Ryan of International Rescue Corps in Scotland says, “It would be fantastic. A rat could get into spaces we couldn’t get to and a rat would get out if it wasn’t safe.” Perhaps for the first time in history, people will be happy to see a rat in a building (but only after an earthquake, of course).16.Why are rats used in the new research project?A.They are smarter than dogs.B.They are more curious.C.They can reach smaller spaces.D.They are more popular than dogs.17.What is the purpose of the new research project?A.To make a comparison.B.To help rescue people.C.To reduce the work of rescuers.D.To charge robots.18.What’s the main reason why rats are better than robots to find survivors?A.Rats have a better sense of smell to find survivors.B.Robots can’t judge the smell of living survivors.C.Rats have natural ability to find survivors.D.Rats can get to spaces unreachable for robots.19.What’s Julie Ryan’s attitude towards “rat project”?A.Negative B.Neutral C.Positive D.Opposed20.What is the main idea of the text?A.The ways to rescue survivors.B.Rats are man’s new best friends.C.Rats can be trained to help find survivors after the earthquake.D.Man will be happy to see a rat in the building.A few weeks ago, my teenage daughter failed a test. She was embarrassed, angry, anxious and there were tears in her eyes. This grade might prevent her from qualifying for the next key class she wanted to take.She took some time to complain to me. Then I saw something interesting. She calmed herself down by making a joke. She expressed thankfulness that she didn’t have bigger problems. Then she made a plan to talk to her teacher to improve her skills. This was a great change from the kid I was watching deal with disappointment a few years ago,the one who once was unwilling to take responsibility and blamed others, which shows she has grown up and understood the good in the bad.We expect our kids to learn and grow, but many of them will also grow through adversity (逆境), and even thrive (茁壮成长) after trauma (创伤). Psychologists call it post-traumatic growth. Trauma, defined as an emotional response to a terrible event like an accident, attack, natural disaster, or other life-changing happenings, is painful and even can be harmful. Trauma does leave its mark, but the mark may not be all bad and there can also be growth.In one study, researchers surveyed nearly 385 people who experienced financial adversity, even while working full-time. These people are also the parents or primary caregivers or young children in education. And those surveyed had either been sick with an illness or had a loved one who’s been in bad health. Despite all of this adversity, 88 percent of the people surveyed said they now have stronger family relationships and a greater appreciation for life. Some said they experienced spiritual growth and 11 percent reported they discovered new opportunities.Hardship makes us adapt, respond, and find other ways to solve it. When we do, we become not only able to heal the trauma associated with it but also thrive again. We build up confidence and experience that will help us the next time we face adversity.21.How did the author’s daughter react after failing the test?A.She blamed other people for her failure.B.She felt grateful and meant to improve.C.She became more anxious and angrier.D.She refused to take responsibility.22.What positive change did the author observe in their daughter?A.She became more frighted of difficulties in life.B.She developed a stronger support system.C.She became more negative and disappointed.D.She grew up and understood the value of hardships.23.What did the study mentioned in the article tell about surveyed people?A.They became more disconnected from others.B.They developed responsible attitude towards their families.C.They had a better family and increased appreciation for life.D.They experienced a decline in their overall well-being.24.How does hardship contribute to personal growth according to the article?A.It prevents a person from healing from trauma.B.It limits personal ability to adapt to adversity.C.It encourages a person to find different solutions and develops confidence.D.It results in long-term negative effects on a person’s emotional well-being.25.What is the main message of the article regarding adversity and growth?A.Hardship can lead to personal growth.B.Traumatic events leave only harmful effects.C.Adversity always leads to negative outcomes.D.People who face trauma are unable to heal from it.Forget drinking countless glasses of water or getting your beauty sleep. The secret of looking young is simply to stay out of sun.A study of hundreds of women has revealed that those who avoided the sun’s rays looked up to20 years younger than they actually are. However, other supposed rules for a youthful complexion (肤色), from drinking lots of water to sleeping well and exercising regularly, failed to hold back the hands of time.Only keeping out of the sun, and wearing sunscreen when this wasn’t possible, made a difference, the American Academy of Dermatology’s annual conference will hear today.The finding comes from a study of 231 women of all ages who were quizzed about (调查) their lives, including whether they were sun-loves. When researchers from Massachusetts General Hospital in the US guessed how old the women were, they found those who took care in the sun tended to have aged more slowly.Researcher Dr. Alexa Kimball said the popular belief that we drink lots of water to stay healthy is false and previous research by the British Nutrition Foundation reached a similar conclusion.It isn’t clear why the women who slept well didn’t have younger-looking skin. But it may be that the question they were asked was too narrow and didn’t consider their long-term sleep patterns. 26.Which way can help women stay younger according to the study?A.Drinking plenty of water.B.Having a good sleep.C.Taking exercise regularly.D.Keeping out of the sun.27.How did the researcher get the finding?A.By interviewing 231 women face to face.B.By comparing the new research with the previous ones.C.From the results of some quizzes.D.Through the result of different games.28.Why does sleeping well fail to make people look young?A.Because most people don’t sleep long enough.B.Because most people have wrong sleep patterns.C.Because most people lack of sleep.D.It’s unknown yet now.29.What is the main idea of the passage?A.To introduce a good way to make women look younger.B.To explain how scientists carried out the research.C.To prove people’s previous ideas are true.D.To persuade women to change their long-term sleep patterns.30.The passage is most probably taken from ______.A.a school textbook B.a reference bookC.a science fiction D.a science paperIt’s school time again! You’re probably feeling excited and maybe a little sad for the vacation is over. Some kids feel nervous or a little scared on the first day of school because of all the new things: new teachers, new friends, and maybe even a new school. Luckily, these “new” worries only stick around for a little while. Let’s find out more about going back to school.Most teachers kick off the school year by introducing themselves and talking about what you’ll be doing that year. Some teachers give students a chance to tell something about themselves to the rest of the class. When teachers do the talking on the first day, they often go over classroom rules so you’ll know what’s allowed and what’s not. Pay close attention so you’ll know if you need to raise your hand to ask a question and what the rules are about visiting the restroom.You might already know a lot of people in your class on the first day. But it’s a great day to make a new friend, so try to say “hello” to kids you know and new ones that you don’t. Make the first move and you’ll be glad about what you did and so will your new friend!Most teachers let you pick your own seat on the first day, but by the second or third morning, they’ll have mapped out a seating plan. It’s a good idea to write down where your seat is in your notebook so you don’t forget.Seeing friends you haven’t seen for a while can make the first day a good one. You can make the day feel special by wearing clothes that you really like. Maybe you got a great T-shirt on one of your vacations, or a pair of sneakers (运动鞋). It also can make you feel good to be prepared and have all the things you need, such as pencils, folders, and whatever else you’ll be needing. But make sure that you pack them the night before in case you don’t have time in the morning. 31.The underlined words “kick off” in the second paragraph probably mean ________.A.teach B.study C.find D.start32.According to the writer, you can make the day feel special by ________.A.wearing your favorite clothes B.getting up earlyC.having a good breakfast D.bringing a new school bag33.According to the passage you usually do everything on the first day of school except ________.A.introduce yourself B.learn about the school rulesC.go over your new lessons D.make new friends34.If you happen to see an old friend on the first day of school, from the passage we know that youwill feel ________.A.nervous B.lucky C.happy D.strange35.The last paragraph mainly tells us about ________.A.what to know about a new school B.how to prepare for a new schoolC.what to do on your first day of school D.how to spend your first day of schoolRising temperatures driven by the climate crisis are cutting the sleep of people across the world, the largest study to date has found.The researchers used data from sleep-tracking wristbands (手环) used by 47,000 people over 7 months and across 68 countries. The analysis revealed that due to increasing night-time temperatures, the average global citizen is losing 44 hours of sleep a year.However, lost sleep affects some groups much more than others. The sleep loss per degree of warming is about a quarter higher for women than men, twice as high for those over 65 years old and three times higher for those in less affluent nations, where people have less access to cooling features.Previous studies have shown that rising temperatures damage health, including increasing heart attacks, mental health crises, and accidents and injuries. Poor sleep has also been shown to have these effects, and the researchers say their new study suggests that disturbed sleep may be a key mechanism by which heat causes these health impacts. The researchers say their data shows no signs of people being able to adapt to hotter nights.“In this study, we provide the first planetary-scale (世界范围的) evidence that warmer than average temperatures cut human sleep,” said Kelton Minor, who led the research. “It’s very likely the effect is more serious.” Minor added that the research had important implications for policymakers, who need to ensure cities, towns and buildings are well adapted to heat in order to reduce the health impacts.The data used in the study came mainly from richer nations. The wristbands also tended to be worn by people less prone (易于遭受) to sleep disturbance by warmer temperatures. “Lower-income people are underrepresented in the data and we’re well aware of that,” said Minor. He said more research was needed, particularly in places that are already among the hottest in the world.36.Which is NOT mentioned about the study in paragraph 2?A.How the data was collected.B.How many respondents were involved.C.The duration of the study.D.The purpose of the study.37.What does the underlined word “affluent” in paragraph 3 probably mean?A.Thickly populated.B.Badly polluted.C.Wealthy.D.Equal.38.How do increasing temperatures harm people?A.They cause car accidents.B.They reduce people’s sleep time.C.They result in extreme weather events.D.They limit people’s adaptation ability.39.What can be learned from Kelton Minor’s words in paragraph 5?A.The study adopted a new research method.B.Some cities have taken firmer action to fight the heat.C.Policymakers have doubts about the study.D.Heat’s impacts may be worse than estimated.40.What does the last paragraph mainly tell us about the study?A.Its findings.B.Its limitations.C.Its applications.D.Its significance.Teens are now less likely to do part-time jobs, drink alcohol or go out without their parents than teens 10 or 20 years ago. This generation of teens is delaying (推迟) the responsibilities and pleasures of adulthood. Some people think that today’s teens are more responsible. Others have suggested that today’s teens aren’t working because they are simply lazy.To figure out what’s really going on, we should look at these trends (趋势) with “life history theory” taken into consideration. A “fast life method” was the most common parenting approach in the mid-20th century, when fewer high technology devices were available and the average woman had four children. The parents needed to focus on day-to-day survival. As a result, kids needed to take care of themselves sooner. A “slow life method” on the other hand is more common in times and places where families have fewer children and spend more time on each child’s growth and development. When an average family has two children, preparing for college can begin as early as primary schools. There is a clear difference between the two methods. The two methods are adaptations to a particular cultural background, so each isn’t naturally “good”or “bad”.Delaying exposure (接触) to alcohol, then, could make young adults less prepared to deal with drinking in college. One study found teens who rapidly increased their binge-drinking (酗酒) were more at risk of alcohol dependence than those who learned to drink over a longer period of time. The same might be true for teens who don’t work, drive or go out much in high school. College teachers describe students who can’t do anything without calling their parents.However, the “slow-life method” is also likely beneficial as teens are spending more time developing socially and emotionally before they drive, drink alcohol and work for pay. The key is to make sure that teens eventually get the opportunity to develop the skills they will need as adults: independence, along with social and decision making skills. For parents, this might mean pushing their teenagers out of the house more.41.Compared with teens nowadays, which can best describe teens in the past?A.Believable.B.Outgoing.C.Intelligent.D.Independent.42.What plays a key role in the trend of teens growing up more slowly?A.Social comments.B.Cultural changes.C.Educational development.D.Methods of education.43.What does the author advise parents to do?A.Spend less time in taking care of their children.B.Force their children to leave home at an early age.C.Encourage their children to take part in social activities.D.Help their children to get to adulthood as soon as possible.44.Which of the following can be the best title for the text?A.How teens develop skills they need in future.B.Teens take no responsibility for what they do.C.Why today’s teens aren’t in any hurry to grow up.D.Nowadays teens can’t make decisions by themselves.45.In which part of a magazine can we read this passage?A.Society.B.Education.C.Business.D.Entertainment.Abby Bell loves her job at Haley House, a soup kitchen in Boston’s South End. On a recentweekday morning she was busy greeting guests, helping volunteers, preparing pots of fresh coffee, and answering endless questions. “Butter? We have tons.” “Cups? I’ll grab some for you.”“Without this place there would be no me. These people are angels,” says Linda, a regular guest at Haley House’s free morning breakfast.That feeling is created by Haley House, a program that for five decades has approached social issues facing Boston’s South End community through its soup kitchen, cheap housing, urban gardens, and education programs. The organization welcomes homeless people or those living in low-income housing as a valuable part of the larger community. “It’s really important to know people as people,” says Ms.Federici, who also works for the organization while serving in the kitchen.Instead of relying on volunteers or drive-by helpers to work in its soup kitchen, Haley House seeks out people of all ages and backgrounds who are interested in staying there for two years to help solve the social problems in South End. In exchange, they receive room and board, running its kitchen and caring for its guests.The biggest offering that Haley House has to Boston is, it’s an example of how all these pieces are linked — food, training, jobs, housing. “We couldn’t solve that whole problem of housing homeless people. We couldn’t give jobs to everybody. But what we did was we created models,” says Ms. McKenna, who is now retired from Haley House.“There is that strong connection to the community that Haley House workers are able to develop over their time here,” says Sean, who delivers food to Haley House. “They are really passionate about food, but more importantly, about people.”46.Which of the following best describes Abby Bell?A.Warm-hearted.B.Sharp-minded.C.Generous.D.Intelligent.47.What is Haley House intended for?A.Popularizing local soup culture.B.Educating South End neighbors.C.Helping build a better community.D.Stressing the importance of people.48.What does the underlined sentence in Paragraph 3 mean?A.It’s important to know people.B.It’s important to respect people equally.C.It’s important to know people you are familiar with.D.It’s important to know more people.49.What do we know about Haley House workers?A.They are talented cooks.B.They do the job for free.C.They live in Haley House.D.They come from Boston.50.What is the best title for the text?A.From Haley to Boston: A Popular ModelB.Haley House: A Developing OrganizationC.Abby Bell: A Worker at Haley HouseD.Haley House: Full of Hope。
二氧化锰催化氧化甲醛的研究进展
二氧化锰催化氧化甲醛的研究进展发布时间:2022-06-15T07:58:50.865Z 来源:《科学与技术》2022年2月4期作者:顾辉子[导读] 随着人们在室内停留时间的增加,室内甲醛污染逐渐成为一个对人体健康很重要的影响因素顾辉子浙江新火原新材料科技有限公司浙江绍兴 312030摘要:随着人们在室内停留时间的增加,室内甲醛污染逐渐成为一个对人体健康很重要的影响因素。
二氧化锰因其高催化活性、热稳定性、原材料易得、成本低、晶型丰富,引起了很大的关注。
本综述总结了近几年以二氧化锰为主的催化材料在甲醛催化氧化上的应用,特别是甲醛低温催化领域的研究进展。
介绍了二氧化锰的晶型、形貌对催化性能的影响并对甲醛催化机理进行分析。
关键词:氧化锰;催化氧化;甲醛;室内污染随着社会的发展,居民生活水平的提高,人们在室内活动时间明显增加。
城市大环境的空气污染导致部分地区室外环境也不理想,因此室内外环境的交换频率也逐渐降低。
而室内装饰、家具、人体本身,办公用品等各种生活用品,都在不断的产生各种室内空气污染物。
在这些污染物种,VOC因其特有的难闻、刺激性的气味和致癌性正受到日益广泛的关注。
其中,甲醛释放周期长,难彻底清除成为最受关注的室内大气污染物之一。
2004年,IARC将甲醛认定为致癌物质[3]。
2000年,WHO将室内甲醛浓度限定在0.1mg/m3。
因此,提高室内空气质量并发展室内甲醛处理技术是十分必要。
控制甲醛的策略主要有三方面,源头控制,通风和末端治理。
源头控制可以减少甲醛的释放,比如控制建筑板材中含醛胶水的用量。
尿醛树脂作为主要的粘结剂用在板材中,将在几个月甚至几年的时间内持续释放甲醛。
加强通风被证明是非常有效的手段,而且是必要手段。
但是如果室外环境欠佳,通风会带来PM2.5和臭氧的污染[4]。
末端治理包括吸附,光催化氧化,等离子催化,和热催化或室温催化。
物理吸附比如活性炭吸附的有效性局限于他的吸附能力。
另外,吸附饱和后的材料会脱附,引起二次污染[5]。
路易斯酸调控双核铁配合物催化氧化反应的研究
摘要在催化反应中,金属酶催化剂在温和的条件下就可以体现出高的催化活性及高的产物选择性。
以甲烷单加氧酶为模型,探索其仿生化合物的结构和功能一直以来是人们追求的目标。
由于天然酶分子纯化困难稳定性差,而人工合成的仿生化合物可塑性强,更能清晰地了解酶的结构和功能。
所以人们更加注重对仿生酶的性能研究,同时也为仿生化学、酶化学等相关领域的发展提供了重要支撑和推动作用。
本文以甲烷单加氧酶简单的仿生化合物双核铁金属配合物为模型,以非卟啉类化合物(TPA:三[2-甲基吡啶]胺和TPMA:三[{4-甲氧基-2、5-二甲基}-2-甲基吡啶]胺)为有机配体,研究了非氧化还原性金属离子作为路易斯酸对双核铁催化剂的催化氧化反应性能的影响。
结果表明,路易斯酸Sc3+能够显著地提高双核铁配合物催化氧化环己烷和烯烃环氧化的反应速率,且路易斯酸的酸性越强,反应速率的提高越明显。
进一步的研究机理表明:低价的双核铁在过量的氧化剂TBHP的作用下生成高价的diamond core结构的惰性物种[Fe III(μ-O)2Fe IV], 该物种对于C-H键活化及烯烃环氧化反应体限了极差的催化活性,非氧化还原性金属离子的加入会解离该结构,形成开环的活性物种, 从而大幅度提高反应速率。
本文揭示了非氧化还原性金属离子作为路易斯酸对双核铁配合物催化氧化反应性能影响的规律及其机理,该工作的开展对于调控现有的惰性催化剂体系以及开发新的催化氧化技术具有重要的指导意义,也为研究甲烷单加氧酶催化氧化机理提供新的线索。
关键词:甲烷单加氧酶;双核铁配合物;路易斯酸;C-H键活化AbstractThe metal enzyme catalysts are well known for their ability to carry out catalytic reactions with the high efficiency, high selectivity under mild conditions. It is the goal to explore the applications of methane in the organic synthesis and industry by studying the biomimetic materials of metal enzymes like soluble methane monooxygenase(sMMO). Due to the complicated structure of the enzymes and the poor stability, the synthetic small molecular model complexes have the strong advantage in plasticity, and it is better to understand the structures, functions, activity differences and mechanisms of the enzymes. Therefore, the study of simple complexes of enzymes has become one of the most popular topics in science and catalytic chemistry. It promotes the development of enzyme chemistry, biomimetic chemistry and other related fields.In this paper, the influences of Lewis acids on the catalytic oxidation reactions by diiron complexes with TPA or TPMA ligand. The results showed that Lewis acid like Sc3 + could significantly accelerate the reaction rate of cyclohexane and olefin epoxidation by diiron complexs. In the absence of Lewis acid, oxidation of diiron(III) complex by TBHP would generate a well known di-μ-oxo-bridged dinuclear Fe (III)Fe(IV) core which is very sluggish for C-H acitivation and olefin epoxidation. Adding non redox metal ions would cause the dissociation of the dinuclear core which sharply improves the rates of reaction. This work may offer a novel strategy to improve the catalytic reactivity of a variety of inert redox metal catalysts, and may provide new clues to understand theirs roles in catalytic oxidation mechanism of soluble methane monooxygenase.Key words: soluble methane monooxygenase; diiron complex; Lewis acids; C-H activation目录摘要 (1)Abstract (2)1 绪论 (5)1.1甲烷单加氧酶的组成及存在形式 (5)1.2 甲烷单加氧酶的催化氧化循环机理 (7)1.3 甲烷单加氧酶的活化机理 (9)1.3.1分子氧活化机理 (9)1.3.2烷烃的活化机理 (10)1.4 生物酶中间体活性差异的研究 (11)1.5 非氧化还原性金属离子在均相催化反应中的应用 (14)1.6 选题的意义及思路 (16)2 实验部分 (19)2.1 实验试剂 (19)2.2 实验仪器及实验设备 (21)2. 3 双核铁配合物及配体的合成方法 (21)2.4 实验说明 (24)2.4.1 TON和TOF计算方法 (24)2.4.2催化氧化反应中的色谱条件 (25)2. 5催化氧化反应及动力学实验的操作步骤 (25)2.5.1烯烃环氧化体系的操作步骤 (25)2.5.2环己烷体系催化氧化实验的操作步骤 (25)2.5.3环己烷体系催化氧化动力学操作步骤 (26)2.5.4 Lewis acid调控双核铁催化氧化底物扩展的操作步骤 (26)2.6.机理的光谱学表征 (26)2.6.1 UV-Vis测试的操作步骤 (26)2.6.2 EPR测试操作步骤 (27)2.6.3同步辐射(EXAFS)测试操作步骤 (27)3实验结果与讨论 (28)3.1 Lewis acid调控双核铁催化剂催化氧化环辛烯的反应体系 (28)3.2 Lewis acid调控双核铁催化剂催化氧化环己烷体系条件的筛选 (30)3.3 Lewis acid 调控双核铁催化剂催化氧化环己烷体系空白实验 (36)3.4 Lewis acid调控双核铁催化剂(L = TPA和TPMA)催化氧化环己烷动力学实验 (37)3.5 路易斯酸调控双核铁催化剂(L=TPA)催化氧化底物扩展实验 (39)3.6. 双核铁催化剂/Sc(OTf)3/TBHP体系光谱表征 (43)3.7双核铁催化剂/Sc(OTf)3 /TBHP体系机理讨论 (47)4 结论 (49)致谢 (50)参考文献 (51)附录1 作者攻读硕士期间发表的论文 (58)附录2 (59)1 绪论金属酶作为一种生物催化剂,相比于其它催化剂具有选择性、高效性和反应条件温和的特征。
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Contents lists available at ScienceDirect
Optik
journal homepage: www.elsevier.de/ijleo
A study on the law of oxidation rate in GaAs-based VCSELs
∗ Corresponding author. E-mail address: fengyuan 1224@ (Y. Feng). /10.1016/j.ijleo.2014.04.078 0030-4026/© 2014 Elsevier GmbH. All rights reserved.
mainly by the diffusion reaction, the oxidation rate decreased to a given value and basically stabilized. 3. Results and analyses In the process of oxidation reaction, the chemical reactions are as follows [10]:
a r t i c l e
i n f o
a b s t r a c t
In order to accurately control the oxidation aperture in high power vertical cavity surface emitting lasers (VCSELs), the selective oxidation process is studied with experiments. Selective oxidation experiments are carried out upon the simulate wafer of VCSELs at different temperature. Oxidation products are examined at different oxidation depths of oxidation layer and each component content is analyzed. The results of the experiments are analyzed with the kinetics of thermal diffusion. The analyzed results show that the concentration of oxidant is e exponentially declined with increasing depth of oxidation in highpower VCSELs. The oxidation depth stability and precision can be improved by lowering the oxidation temperature and prolonging the oxidation time. © 2014 Elsevier GmbH. All rights reserved.
Y. Feng ∗ , G.J. Liu, C.L. Yan, Y.Q. Hao, Y. Wang, Z.J. Li, P. Lu
National Key Laboratory of High-Power Semiconductor Lasers, Changchun University of Science and Technology, Weixing Rd. 708t al. / Optik 125 (2014) 5124–5127
5125
Fig. 1. Cross-section SEM photograph of an oxided sample.
Fig. 4. Oxidation content vs. oxidation depth.
Article history: Received 5 September 2013 Accepted 26 April 2014 Keywords: VCSEL Selective oxidation Oxidation rate Kinetics of thermal diffusion e-Exponential law
1. Introduction High-power vertical-cavity surface-emitting lasers have widely been applied to data communication, data storage, optical sensors, printing industry, especially in the military applications [1–4], where using VCSEL array devices to pump solid state lasers has special tempting prospects [5]. In recent years, the development of high power VCSEL has become a research hotspot to domestic and international semiconductor lasers. Selective oxidation in the preparation of high-power VCSEL, the extensive use of technology to form a current injection window, to achieve electro-optical limit and the refractive index-guided. Selective oxidation process has become a key process of the preparation of the VCSEL [6,7]. Due to the fact that precise control of the oxidation depth and the thermal stability of the oxidation process, the VCSEL output power and electro-optical conversion efficiency are essential [8,9], so one of the difficulties in the selective oxidation is the controllability of the oxidation depth and accuracy. Thus, we adopted the oxidation of the same sample under different conditions and measured the content of each component in the reaction products. By using diffusion kinetics of the oxidation rate law of mathematical analysis and suggesting that oxidation time is shorter, the linear law of oxidant concentration is shown. When the oxidation time is longer where it is mainly controlled by diffusion, the oxidant concentration shows an e exponential attenuation.
2. Experiments The epitaxial wafer of VCSEL was grown on N-type GaAs substrate by using MBE and the active layer contains three GaAsAlGaAs quantum wells. The bottom Bragg reflector consists of 41 pairs of Al0.22 Ga0.78 As/GaAs and the top Bragg reflector consists of 22 pairs of Al0.22 Ga0.78 As/GaAs. There is a 35 nm thick Al0.98 Ga0.02 As layer located at the first pair in P-DBR in order to form buried AlGaAs/Alx Oy . The top layer is GaAs contact layer. The whole epitaxial wafer thickness is about 650 m and the center wavelength of DBR reflection spectrum is at 800 nm. The photolithographic technique and wet chemical etching are used to form the oxidation window as Fig. 1. The lateral oxidation of Al0.98 Ga0.02 As in N2 /H2 O atmosphere is characterized with respect to oxidation temperature, N2 carrier gas flow, and the geometry of the mesa structures. The selective oxidation setup was shown in Fig. 2. The exposed Al0.98 Ga0.02 As layer was oxidized at 420 ◦ C, 440 ◦ C and 460 ◦ C in N2 /H2 O atmosphere. Dry N2 with a constant flow of 1 L/min was used as carrier gas for H2 O vapor. The water temperature was maintained at 90 ◦ C. The oxidation time was maintained in 40 min. The Cross-section of the oxided samples was SEM observed and the oxidation depth of samples was measured. In order to explore the oxidation law of the samples under different temperatures, we use SEM microanalysis of samples per 1 distance and measure the oxidation depth, corresponding to the various elements of the point oxidation layer X-ray energy spectrum (Fig. 3) and element composition analysis table (Table 1). According to X-ray energy spectra, we can qualitatively describe the resultant content of each point of the oxidation layer, and element