云南师大附中2021届高考适应性月考卷(一)英语参考答案

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云南师大附中2015届高考适应性月考卷(一)英语-试卷

云南师大附中2015届高考适应性月考卷(一)英语-试卷
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云南师大附中2013届高考适应性月考卷(五)高三(五)英语_答案

云南师大附中2013届高考适应性月考卷(五)高三(五)英语_答案

云南师大附中2013届高考适应性月考卷(五)英语参考答案第一部分听力(共两节,20小题;每小题1.5分,满分30分)1~5 BBCCA 6~10 CACAC 11~15 BBCCA 16~20 BAABC第二部分英语知识运用(共两节,满分45分)第一节:单项填空(共15小题;每小题1分,满分15分)21~25 BDACB 26~30 CDBCA 31~35 CADBD第二节:完形填空(共20小题;每小题1.5分,满分30分)36~40 CACCA 41~45 DBDBD 46~50 AACCD 51~55 BADBC第三部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)A篇:56~58 ACD B篇:59~62 BDBA C篇:63~66 BCAD D篇:67~70 BDBA第二节(共5小题;每小题2分,满分10分)71~75 BCADF第四部分写作(满分35分)第一节:短文改错(满分10分)Shirley and I have been to ∧quiet beach in southwestern Florida on holidays for most of① aour married life. If that beach could talk, it will tell our happy visits over the years. But one day I② wouldrealized that I had ever expressed my gratitude to my wife who had lived those year with me. I③ never ④ yearsasked to myself how about act on it. On our 40th wedding anniversary, Shirley and I walked again⑤⑥actingby the familiar sea. Then I told her how thankful I am for she had shared my life. Say thanks to⑦ was ⑧ Sayingher brightened not only her world, but also me. Receiving my thanks, my wife won’t feel unloved⑨ mineand unappreciated.⑩ or第二节:书面表达(满分25分)【参考范文】Dear Mr. Smith,I want to express my thanks to your warm reception during the time I was in America. I appreciate greatly what you have done for me.I will never forget your warm hospitality. First of all, with your patient explanation of the英语参考答案·第1页(共8页)culture experiences, I gained abundant experience which would provide support for my future. Furthermore, at the expense of your own time, you accompanied me to visit places of interest. Last but not the least, the comfortable place you provided for me to stay made a deep impression on me. Thus, I really appreciate your dedicated help, and I am looking forward to your visit to Kunming in the future.Thank you for your kindness again.Sincerely yours,Wang Lin【解析】第二部分英语知识运用第一节:单项填空21.B考查交际用语。

云南师大附中2023届高考适应性月考卷(四)英语(云南版)-答案

云南师大附中2023届高考适应性月考卷(四)英语(云南版)-答案

英语参考答案第一部分听力(共两节,满分30分)1~5 CBCBA 6~10 BACBB 11~15 CABCA 16~20 CCABC第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)21~25 ABBAB 26~30 DACCA 31~35 BBACD第二节(共5小题;每小题2分,满分10分)36~40 EFBDA第三部分语言知识运用(共两节,满分45分)第一节完形填空(共20小题;每小题1.5分,满分30分)41~45 CBADC 46~50 BCADB 51~55 DBACA 56~60 DADBC第二节(共10小题;每小题1.5分,满分15分)61.was delivered 62.Calls 63.and 64.nestled 65.who 66.happiest 67.when/as 68.across 69.a 70.guessing 第四部分写作(共两节,满分35分)第一节短文改错(共10小题;每小题1分,满分10分)Years ago,I was a volunteer English teacher in a village in Cameroon,which I befriended one①whereof my young students,Dick.He was very helpful to me and spent much evenings at my home,②manyassisting me with chores in exchange for meal,and teaching me the ins and outs of life in the village.③mealsHe never asked me for something,but I would regular buy him school supplies or clothing,as he was④anything ⑤regularlyvery poor but said he was motherless.At one point,I left him money∧care for my dog while I was英语参考答案·第1页(共9页)英语参考答案·第2页(共9页)⑥and ⑦toaway on a extended trip .After I leftlost in touch with Dick .I feel guilty for “abandoning⑧an⑨ ⑩felthim ”— guilt that haunted me for years .第二节 书面表达(满分25分)【参考范文】Dear Harrison ,I am writing to share with you an exciting experience .In order to broaden the students’ horizon and encourage them to structure their career planning well ,our school invited some professors to deliver a series of lectures about the major construction of the university relating to 14 academic disciplines from July 20th to 22nd in our auditorium .With their vivid and informative lectures ,the experts provided us with a lot of enlightenment and helped us figure out some puzzles we might encounter about our future major choosing .I do benefit a lot from those lectures .With those positive suggestions and useful information ,which helped further clarify the puzzles we might have in our future careers ,I am convinced that my following college life will be full of excitement and fruits .Yours ,Li Hua【解析】第二部分 阅读理解第一节A主题语境:人与自然——自然生态【语篇导读】本文是应用文。

云南师大附中2024届高考适应性月考卷(一)理综(云南版)-答案

云南师大附中2024届高考适应性月考卷(一)理综(云南版)-答案

理科综合参考答案一、选择题:本题共13小题,每小题6分。

题号1234567 8 9 10 11 12 13答案 C C B B A D A B D C C D B 二、选择题:本题共8小题,每小题6分。

在每小题给出的四个选项中,第14~17题只有一项符合题目要求;第18~21题有多项符合题目要求,全部选对的给6分,选对但不全的给3分,有选错的给0分。

题号14 15 16 17 18 19 20 21 答案 B D C A AC CD AC BCD 【解析】1.少部分酶的化学本质是RNA,部分激素的化学本质不是蛋白质,如性激素,A错误。

葡萄糖不能进入线粒体,线粒体膜上没有运输葡萄糖的转运蛋白,B错误。

变性蛋白质仍能与双缩脲试剂发生紫色反应,D错误。

2.在光学显微镜下只能观察到叶绿体的形态,用电子显微镜才能观察到叶绿体的结构,C错误。

3.②过程表示转录,该过程中RNA聚合酶结合到DNA上发挥作用,而起始密码子位于mRNA上,B错误。

4.NAA是人工合成的物质,属于植物生长调节剂,不是植物激素,A错误。

促进枝条生根的最适NAA浓度应在100~500mg/L之间,C错误。

表中每个NAA浓度均表现出对枝条生根的促进作用,D错误。

5.北极冻原生态系统动植物稀少,营养结构简单,抵抗力稳定性和恢复力稳定性均较低,A 错误。

6.若用Eco RⅠ、BclⅠ进行切割,则氨苄青霉素抗性基因被破坏,含重组质粒的大肠杆菌无法在含氨苄青霉素的培养基中生长,A错误。

若用Eco RⅠ、BclⅠ进行切割,在含X−gal 的培养基中呈现蓝色的菌落也可能是导入了空质粒的大肠杆菌,B错误。

若用XmaⅠ、NheⅠ进行切割,在含X−gal的培养基中呈现白色的菌落也可能是未导入质粒的大肠杆菌,C错误。

7.2B铅笔芯的成分为石墨,A错误。

理科综合参考答案·第1页(共8页)理科综合参考答案·第2页(共8页)8.碳碳双键能发生加聚反应,A 错误。

云南师范大学附属中学2021届高三高考适应性月考卷(二)文科数学试题

云南师范大学附属中学2021届高三高考适应性月考卷(二)文科数学试题

文科数学试卷注意事项:1.答题前,考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚.2.每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其他答案标号.在试题卷上作答无效.3.考试结束后,请将本试卷和答题卡一并交回.满分150分,考试用时120分钟.一、选择题(本大题共12小题,每小题5分,共6分在每小题给出的四个选项中,只有一项是符合题目要求的)1.已知集合305x A x x ⎧-⎫=<⎨⎬-⎩⎭,集合{}46B x x =<<,则A B = ()A .()3,6B .[)3,6C .[)4,5D .()4,52.瑞士数学家欧拉在1748年得到复数的三角方程:i e cos isin θθθ=+(i 为虚数单位),根据此公式可知,若i e 10θ+=,则θ的一个可能值为()A .0B .π2C .πD .3π23.cos 45cos15sin 45sin15+︒︒︒︒的值为()A .32B .32-C .12D .12-4.已知双曲线的方程为22143x y -=,双曲线右焦点F 到双曲线渐近线的距离为()A .1B C D .25.我国古代数学名著《增删算法统宗》中有如下问题:“一个公公九个儿,若问生年总不知,知长排来争三岁,其年二百七岁期.借问长儿多少岁,各儿岁数要详推.”大致意思是:一个公公九个儿子,若问他们的生年是不知道的,但从老大的开始排列,后面儿子比前面儿子小3岁,九个儿子共207岁。

问老大是多少岁?()A .38B .35C .32D .296.为了更好地配合我市“文明城市”的创建工作,我校开展了“文明行为进班级”的评比活动,现对甲,乙两个年级进行评比,从甲、乙两个年级中随机选出10个班级进行评比打分,每个班级成绩满分为100分,评分后得到如图所示的茎叶图,通过茎叶图比较甲、乙两个年级成绩的平均数及方差大小()A .x x <甲乙,22s s <甲乙B .x x >甲乙,22s s <甲乙C .x x <甲乙,22s s >甲乙D .x x >甲乙,22s s >甲乙7.若AB 是以O 为圆心,半径为1的圆的直径,C 为圆外一点,且2OC =,则CA CB ⋅=()A .3B .3-C .0D .不确定,随着直径AB 的变化而变化8.已知圆M 的方程为22680x y x y +--=,过点()0,4P 的直线l 与圆M 相交的所有弦中,弦长最短的弦为AC ,弦长量长的弦为BD ,则四边形ABCD 的面积为()A .30B .40C .60D .809.正四面体ABCD 的储视图为边长为1的正方形,则正四面体ABCD 的外接球的表面积为()A .3π2B .3π2C .3πD .12π10.已知()2sin cos f x x x =,下列结论中错误的是()A .()f x 即是奇函数也是周期函数B .()f x 的最大值为33C .()f x 的图象关于直线π2x =对称D .()f x 的图象关于点()π,0中心对称11.已卸抛物线()2:20C y px p =>,F 为C 的焦点,过焦点F 且倾斜角为α的直线l 与C 交于()11,A x y ,()22,B x y 两点,则下面陈述不正确的为()A .2121234x x y y p +=-B .22sin p AB α=C .112AF BF p+=D .记原点为O ,则2sin AOBp S α=12.下列四个命题:①1ln 22>,②2ln 2e>,③0.22.22log 0.4log 0.4log 0.4log 0.4a +=⋅,④1331log 7log 13<,其中真命题的个数为()A .1个B .2个C .3个D .4个二、填空题(本大题共4小题,每小题5分,共20分)13.若x ,y 满足约束条件10,10,24,x y x y x y --≥⎧⎪+-≥⎨⎪-≤⎩,则32x y +的最大值为________.14.ABC 的内角A ,B ,C 的对边分别为a ,b ,c ,若sin 2sin A C =,且三条边a ,b ,c 成等比数列,则cos A 的值为________.15.已知函数()ln 2f x x ax =-恰有三个零点,则实数a 的取值范围为________.16.边长为1的正方体ABCD A B C D ''''-,点FP 为面对角线CD '上一点,则AP BP +的最小值为________.三、解答题(共70分.解答应写出文字说明,证明过程或演算步骤)17.(本小题满分12分)记n S 为正项数列{}n a 的前n 项和,且满足()241n n S a =+.(1)求数列{}n a 的通项;(2)求证:1223111112n n a a a a a a ++++< .18.(本小题满分12分)如图,在等腰梯形ABCD 中,AB CD ,222AB CD AD ===,将ADC 沿着AC 翻折,使得点D 到点P ,且AP BC ⊥.(1)求证:平面APC ⊥平面ABC ;(2)求点C 到平面APB 的距离.19.(本小题满分12分)为了调查高中生文理科偏向情况是否与性别有关,设计了“更擅长理科,理科文科无差异,更擅长文科三个选项的调在问卷”,并从我校随机选择了55名男生,45名女生进行问卷调查,问卷调查的统计情况为:男生选择更擅长理科的人数占25,选择文科理科无显著差异的人数占15,选择更擅长文科的人数占25;女生选择更擅长理科的人数占15,选择文科理科无显著差异的人数占35,选择更擅长文科的人数占15.根据调查结果制作了如下22⨯列联表.更擅长理科其他合计男生女生合计(1)请将22⨯的列联表补充完整,并判断能否有95%的把握认为文理科偏向与性别有关;(2)从55名男生中,根据问卷答题结果为标准,采取分层抽样的方法随机抽取5人,再从这5人中随机选取2人,求所选的2人中恰有1人更擅长理科的概率.附:()()()()()22n ad bc K a b c d a c b d -=++++,其中n a b c d =+++.()20P K k ≥0.0500.0250.0100.0010k 3.8415.0246.63510.82820.(本小题满分12分)已知点()2,0M -,()2,0N ,点P 满足:直线PM 的斜率为1k ,直线PN 的斜率为2k ,且1234k k ⋅=-.(1)求点(),P x y 的轨迹C 的方程;(2)过点()1,0F 的直线l 交曲线C 于A ,B 两点,问在x 轴上是否存在点Q ,使得QA QB ⋅为定值?若存在,求出点Q 的坐标;若不存在,请说明理由.21.(本小题满分12分)已知()22ln f x ax x x =-+.(1)若12a =-,求()f x 的最大值;(2)若()f x 有两个不同的极值点1x ,2x ,证明:()()()121214ln 543f x f x x x +++<-.请考生在第22、23两题中任选一题作答,并用2B 铅笔在答题卡上把所选题目的题号涂黑.注意所做题目的题号必须与所涂题目的题号一致,在答题卡选答区域指定位置答题.如果多做,则按所做的第一题计分.22.(本小题满分10分)【选修4-4:坐标系与参数方程】在平面直角坐标系中,以坐标原点为极点,以x 轴的正半轴为极轴,曲线C 的极坐标方程为2ρ=,直线l的参数方程为2,,x t y =--⎧⎪⎨=⎪⎩(t 为参数).(1)求曲线C 和直线l 的直角坐标方程;(2)设点(P -,直线l 与曲线C 有不同的两个交点分别为A ,B ,求11PA PB+的值.23.(本小题满分10分)【选修4-5:不等式选讲】已知函数()123f x x x =-+-.(1)求函数()f x 的最小值M ;(2)若0a >,0b >,且a b M +=,证明:22111a b a b +≥++.云南师大附中2021届高考适应性月考卷(二)文科数学参考答案一、选择题(本大题共12小题,每小题5分,共60分)题号123456789101112答案DCACBAABCBDB【解析】1.由题意知,()3,5A =,()4,6B =,所以()4,5A B =,故选D .2.由题意知,iπe 1cos πisin π10+=++=,故选C .3.原式()3cos4515cos302︒==︒︒-=,故选A .4.由题意知,双曲线的右焦点为)F,双曲线的渐近线方程为2y x =±,即20y -=,所以点)F到渐近线的距离d ==,故选C .5.由题意可知,九个儿子的年龄可以看成以老大的年龄1a 为首项,公差为3-的等差数列,所以()198932072a ⨯+⨯-=,解得135a =,故选B .6.由茎叶图可知,甲年级的平均分主要集中在70多分,而且比较集中,而乙主要集中在80分以上,但是比较分散,故选A .7.如图,()()()g g CA CB CO OA CO OB CO OA =++=+,A .8.圆M 的标准方程为()()223425x y -+-=,即圆是以()3,4M 为圆心,5为半径的圆,且由()()220344925-+-=<,即点()0,4P 在圆内,则最短的弦是以()0,4P 为中点的弦,所以22592AC ⎛⎫=+ ⎪⎝⎭,所以8AC =,过()0,4P 最长的弦BD 为直径,所以10BD =,且AC BD ⊥,故而1g g 402ABCD S AC BD ==,故选B .9.如图,该正四面体可以看成边长为1的正方体六个面对角线组成的正四面体ABCD ,所以正四面体ABCD 的外接球,即为边长为1的正方体的外接球,所以外接球的半径为32,则24π3π2S ⎛⎫== ⎪ ⎪⎝⎭,故选C .10.由()2sin cos f x x x =,所以()()()()22sin cossin cos f x x x x x f x -=--=-=-,所以()f x 是奇函数;()()()()222πsin 2πcos2πsin cos f x x x x x f x +=++==,所以()f x 又是周期函数;()()()()22πsin πcos πsin cos f x x x x x f x -=--==,所以()f x 关于直线π2x =对称;()()()()222πsin 2πcos 2πsin cos f x x x x x f x -=--=-=-,所以()f x 关于点()π,0对称,即选项A ,C ,D 正确;又()()()()222222sin cos sin 1sin 1sin f x x x x x x ==--()()22232sin 1sin 1sin 12422327x x x --⎛⎫=≤=⎪⎝⎭,当且仅当3sin 3x =,()max 239f x =,故B 选项错误,故选B .11.由题意知,令直线2px my =+,()11,A x y ,()22,B x y ,与抛物线2:2C y px =联立方程,消去x 得2220y pmy p --=,所以122y y pm +=,212y y p =-,所以21212224p p p x x my my ⎛⎫⎛⎫=++=⎪⎪⎝⎭⎝⎭,则2121234x gx y y p +=-,故A 正确;由1πtan 2m αα⎛⎫=≠ ⎪⎝⎭,所以12AB AF BF x x p =+=++()212222m y y p pm p =++=+=()222122121tan sin p p m p αα⎛⎫+=+= ⎪⎝⎭,当π2α=时,经检验22sin p AB α=亦成立,故B 确;所以12121211112222x x p p p p p AF BF x x x x +++=+=⎛⎫⎛⎫++++ ⎪⎪⎝⎭⎝⎭()122121224x x pp p x x x x ++==+++()()121222121222424x x p x x p p p p p p x x p x x ++++==+++++,故C 正确.如图,作OE 垂直AB 于E ,则22112g g g sin 22sin 22sin AOBp p p S AB OE ααα=== ,当π2α=时,经检验22sin AOB p S α= 亦成立,故D 错误,故选D.12.由2ln 2ln 4ln e 1=>=,故①正确;由2ln 2ln e ln 2e 2e >⇔>,考察函数ln x y x =,21ln x y x -'=,所以当()0,e x ∈时,0y '>,即y 在()0,e 上单调递增,当()e,x ∈+∞时,0y '<,即y 在()e,+∞上单调递减,所以e x =时,y 取到最大值1e ,所以ln 2ln e2e<,故②错误;令0.2log 0.4a =,2log 0.4b =,所以0.40.40.411log 0.2log 2log 0.41a b+=+==,所以a b ab +=,即0.220.22log 0.4log 0.4log 0.4glog 0.4+=,故③正确;由4372401219713=>=,所以133log 74>,由4313285612979131=<=,所以313log 134<,故④错误,故选B .二、填空题(本大题共4小题,每小题5分,共20分)【解析】13.约束条件所表示的线性区域,如图所示,又有题意知:32x y +在点()3,2A 处取得最大值,所以32x y +的最大值为13.14.由正弦定理知:sin 2sin a A c C==,又2b ac =,所以::2:1a b c =,从而由余弦定理得22222212cos 24b c aA bc+-+-===-.15.如图,函数()f x 恰有三个零点,等价于方程ln 2x ax =,有三个解,即函数ln y x =与函数2y ax =的图象有三个交点,又有2y ax =为过原点的直线,由图可知,当且仅当2y ax =为ln y x =切线的时候,方程ln 2x ax =恰有两个解,故而,令2y ax =为ln y x =的切线,设切点为()00,ln A x x ,则线的方程为()0001ln y x x x x -=-,由于切线过原点,所以0ln 1x =,即0e x =,此时直线的斜率为1e,由题意知,102e a <<,即10,2e a ⎛⎫∈ ⎪⎝⎭.16.如图甲,将等边ACD ' 沿CD '向后旋转到与面A BCD ''共面,得到等边1A CD ' ,则AP BP +的最小值即为图乙中线段1A B 的长,取A B '的中点I ,由题意知:等边ACD ' 的边长为,A BCD ''是以1BC =,A B '=1A B ===.甲乙三、解答题(共70分.解答应写出文字说明,证明过程或演算步骤)17.(本小题满分12分)(1)解:当1n =时,由11S a =,所以()21141a a =+,解得11a =,当2n ≥时,由()241n n S a =+①,则()21141n n S a --=+②,由①式减去②式得()()221411n n n a a a -=+-+,即()()()2211112n n n n n n n n a a a a a a a a ----+=-=+-,由题意知,10n n a a -+>,所以12n n a a --=,则数列{}n a 为11a =,公差为2的等差数列,所以21n a n =-.(6分)(2)证明:由(1)知,()()111111212122121n n a a n n n n +⎛⎫==- ⎪-+-+⎝⎭,所以122311111111111213352121n n a a a a a a n n +⎛⎫+++=-+-++- ⎪-+⎝⎭11112212n ⎛⎫=-< ⎪+⎝⎭,证毕.(12分)18.(本小题满分12分)(1)证明:由等腰梯形222AB CD AD ===,则60ABC ∠=︒,又2AB BC =,所以AC BC ⊥①,又BC AP ⊥②又 AC AP A =③,由①②③知,BC ⊥平面APC ,所以平面,APC ⊥平面ABC .(6分)(2)解:如图,取AB 的中点E ,连接DE ,CE ,AC ,则AECD 为菱形,且60DAE ∠=︒,则AC DE ⊥,记垂足为O ,则12DO =,AC =,由(1)知,平面APC ⊥平面ABC,如图,又DO AC ⊥,所以DO ⊥平面ABC ,由(1)知,BC ⊥平面APC ,即BC CP ⊥,又1BC CP ==,所以BP =,所以13g 22ACB S AC CB ==,在ABP 中,由2AB =,1AP =,BP =所以2223cos 2g 4PA AB PB PAB AB AP +-∠==,所以sin 4PAB ∠=,则17g gsin 24PAB S AP AB PAB =∠=.设点C 到平面APB 的距离为h ,由P ACB C ABP V V --=,得11g g 33ACB ABP PO S h S = ,即217ACB ABP POgS h S == .(12分)19.(本小题满分12分)解:(1)补充22⨯的列联表如下:更擅长理科其他合计男生223355女生93645合计3169100所以()221002236933100334.628 3.841554531693123K ⨯⨯-⨯⨯==≈>⨯⨯⨯⨯,所以有95%的把握认为文理科偏向与性别有关.(6分)(2)由题意可知,选取的5人中,有2人更擅长理科,3人不更擅长理科,用1A ,2A 表示更擅长理科的两人,用1B ,2B ,3B 表示其他三人,则从这5人中,任取2人共有以下10种情况:()12,A A ,()11,A B ,()12,A B ,()13,A B ,()21,A B ,()22,A B ,()23,A B ,()12,B B ,()13,B B ,()23,B B ,满足条件的有()11,A B ,()12,A B ,()13,A B ,()21,A B ,()22,A B ,()23,A B ,共6种情况,所以所选的2人中恰有1人更擅长理科的概率为35.(12分)20.(本小题满分12分)解:(1)由题意知:()122y k x x =≠-+,()222y k x x =≠-,由123gk 4k =-,即()32224y y g x x x =-≠±+-,整理得点(),P x y 的轨迹C 的方程为()221243x y x +=≠±.(4分)(2)假设在x 轴上存在点()0,0Q x ,使得g QA QB 为定值.当直线l 的斜率存在时,设直线l 的方程为()()10y k x k =-≠,联立方程()221,431,x y y k x ⎧+=⎪⎨⎪=-⎩消去y 得()22223484120k x k x k +-+-=,令()11,A x y ,()22,B x y ,则2122834k x x k +=+,212241234k x gx k-=+,由()101,QA x x y =-,()202,QB x x y =-,所以()()()()()()2102012102012g 11QA QB x x x x y y x x x x kx x =--+=--+--()()()22221201201k x x x k x x k x =+-++++()2022581234x k x k-+-=++,将0x 看成常数,要使得上式为定值,需满足05816x +=,即0118x =,此时135g 64QA QB =-;当直线l 的斜率不存在时,可得31,2A ⎛⎫ ⎪⎝⎭,31,2B ⎛⎫- ⎪⎝⎭,11,08Q ⎛⎫⎪⎝⎭,所以33,82QA ⎛⎫=- ⎪⎝⎭,33,82QB ⎛⎫=-- ⎪⎝⎭,135g 64OA QB =-,综上所迷,存在11,08Q ⎛⎫ ⎪⎝⎭,得g QA QB 为定值.(12分)21.(本小题满分12分)(1)解:当12a =-时,()212ln 2f x x x x =--+,所以()21f x x x'=--+,则()f x '在()0,+∞上是单调递减函数,且有()10f '=,当()0,1x ∈时,()0f x '>,即()f x 为()0,1上的增函数,当()1,x ∈+∞时,()0f x '<,即()f x 为()1,+∞上的减函数,所以()()max 312f x f ==-.(6分)(2)证明:由题意知:由()222ax x f x x-+'=则1x ,2x 即为方程2220ax x -+=的两个不同的正根,故而需满足:12121160,10,210,a x x a x x a ⎧⎪∆=->⎪⎪+=>⎨⎪⎪=>⎪⎩解得116a >,所以()()()()22121211122212112ln 2ln 33f x f x x x ax x x ax x x x x +++=-++-+++()()211212*********ln 2ln 2312a a x x x x x x x x g a ⎛⎫⎡⎤=+-+-+=-+- ⎪⎣⎦⎝⎭,令116t a =>,()()()1212112ln 2312f x f x x x t t +++=-+-,令()12ln 212g t t t =-+-,所以()1212g t t'=-+,则()g t '为()16,+∞上的减函数,且()240g '=所以当()16,24t ∈时,()0g t '>,即()g t 为()16,24上的增函数;当()24,t ∈+∞时,()0g t '<,即()g t 为()24,+∞上的减函数,所以()()max 242ln 244g t g ==-,所以()()()121212ln 2442ln 2544ln 543f x f x x x +++≤-<-=-,证毕.(12分)22.(本小题满分10分)【选修4-4:坐标系与参数方程】解:(1)由222x y ρ=+,所以曲线C 的直角坐标方程为224x y +=,由2,,x t y =--⎧⎪⎨=⎪⎩(t 为参数),消去t 得直线l的直角坐标方程为0y +=.(5分)(2)由题意知,关于点(P -的直线l的参数方2,23,2t x y ⎧=--⎪⎪⎨⎪=+⎪⎩(t 为参数),代入曲线C 的直角坐标方程得211270t t ++=,又121108130∆=-=>,所以方程有两个不同的解1t ,2t ,又12110t t +=-<,12g 270t t =>,所以10t <,20t <,有1t ,2t 的几何意义可知,121212121111111127t t PA PB t t t t t t ⎛⎫++=+=-+=-= ⎪⎝⎭.(10分)23.(本小题满分10分)【选修4-5:不等式选讲】(1)解:由绝对值三角不等式可知:()12313132f x x x x x x x =-+-≥-+-≥-+-=,当且仅当3x =时,两个不等式同时取等号,所以()f x 的最小值2M =.(5分)(2)证明:由(1)知,2a b +=,则()()114a b +++=,所以()()()()2211111112121111a b a b a b a b +-+-+=+-+++-+++++()111111144a b a b ⎛⎫++++ ⎪++⎝⎭⎝⎭=≥=当且仅当1a b ==,不等式取等号,所以22111a b a b +≥++.(10分)。

云南师大附中2013届高考适应性月考卷(一)英语答案

云南师大附中2013届高考适应性月考卷(一)英语答案

云南师大附中2013届高考适应性月考卷(一)英语参考答案第一部分:听力(共两节,20小题;每小题1.5分,满分30分)11~15ABBCB 16~20CBABCABABC 6~101~5CABCB第二部分:英语知识运用第一节:单项填空(共15小题;每小题1分,满分15分)21~25 ACDCB 26~30 BCCBA 31~35 AABCB第二节:完形填空(共20小题;每小题1.5分,满分30分)36~40 BCDAB 41~45 CDBAD 46~50 ABCBD 51~55 AABDB第三部分:阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)64~66ABACCDBCDBC 67~7060~6356~59CDBC第二节(共5小题;每小题2分,满分10分)71~75 DABFE第四部分:写作(共两节,满分35分)第一节:短文改错(满分10分)Welcome to Happy Restaurant! In our restaurant, you will enjoy a better taste and abetter atmosphere. The cook,who are invited from Spain and Italy,brought us a lot of localcooks bringfood for the guests from different places. With a variety of delicious food choices,westrong believe that you will not have other food bought out of your restaurant. As you canstronly oursee, all the guests enjoy the environment as well∧the tasty food because everybody doesn’tasforget to talking in a low voice. W e believe that a quieter place is a better place for you totalktaste the food. If you are interesting in the recipe of our dishes, our cooks are ready to askinterested answeryour questions. The dinner sets are not one-time-used,but because you want to takeifanything in our restaurant for memory,please tell our waiters or waitresses. They arewilling to help to you.英语参考答案·第1页(共6页)第二节:书面表达(满分25分)【参考范文】Hi Lucille,We’re throwing a surprise party for Andrew’s birthday, who has been here for more than 2 months from France. We’d like to invite you to the party. We want to give him a surprise, so please keep quiet about it. We’ll gather at Room 505 in the teaching building at 8:30 p.m. this Saturday. Don’t forget it will be after the evening classes. And it’s going to last about one hour and a half. We each will prepare a little present. When he comes, we’ll light the candles and sing “Happy Birthday” together for him. Then the cake will be cut and we’ll sing songs and play games. It’ll be nice to see how excited he will be. I’m sure you’ll have a good time at the party, too.Yours,Xiao Hua 【解析】第二部分:英语知识运用第一节:单项填空21. A 考查状语从句的连接词。

云南师大附中2015届高考适应性月考卷(五)英语-答案

英语参考答案·第1页(共10页)云南师大附中2015届高考适应性月考卷(五)英语参考答案第一部分:听力(共两节,满分30分)1~5 BCABA 6~10 ABBAA 11~15 CBBBA 16~20 ABAAC第二部分:阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)21~ 25 ADDBA 26~30 CDCBC 31~35 DDBAB第二节(共5小题;每小题2分,满分10分)36~40 CGBFD第三部分:英语知识运用(共两节,满分45分)第一节:完形填空(共20小题;每小题1.5分,满分30分)41~45 CDABC 46~50 DCBDA 51~55 BBCAC 56~60 DABDA第二节:语法填空(共10小题;每小题1.5分,满分15分)61.safety62.staying 63.unlocked 64.may/might/will 65.or66.(should )be employed 67.where/in which68.risky 69.that 70.It 第四部分:写作(共两节,满分35分)第一节:短文改错(满分10分)In some cartoons elephants seem to be afraid of mice. Are we really giant cowards (胆小鬼)?①they Some scientists decided to confirm it. They conducted a experiment in South Africa. The mice ∧ ②an ③were placed in the small holes in the ground and covered with balls of elephant waste. While the ④When/Aselephants got close ,the scientists pulled away the waste balls to reveal the mice. Much to the scientists surprise ,seeing the mice ,the elephants stopped immediately and back away. The scientists ⑤scientists’ ⑥backedthought it might have been the “moving ”waste balls what scared the elephants. So they did the ⑦that英语参考答案·第2页(共10页) experiment again with any mice in the holes ,but this time the elephants didn ’t stop. Thus it was⑧without 或把any 改为no ⑨turned out that elephants true fear little mice.⑩truly第二节:书面表达(满分25分)【参考范文】In the picture ,the girl regrets not starting her work sooner. By no means can she finish so muchwork before the deadline. This phenomenon is called “procrastination ”.Nowadays ,frequently exposed to smartphones and computers ,some students are more likely todistract their attention ,leaving their schoolwork untouched. Others fail to get things done simply because of laziness. As a result ,they are stressed out as the deadline approaches. Procrastination eventually does harm to health both physically and mentally.How can you handle it ?For one thing ,turn off those things that may affect your work ,such asQQ and Wechat. For another ,don’t allow yourself any excuse ,because the longer you wait ,the worse it gets.【解析】第二部分:阅读理解第一节A【语篇导读】本文夹叙夹议。

云南省云南师大附中2023届高考适应性月考卷(七)英语含答案

秘密★启用前英语试卷注意事项:1.答题前,考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚。

2.每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦干净后,再选涂其他答案标号。

在试题卷上作答无效。

3.考试结束后,请将本试卷和答题卡一并交回。

满分150分,考试用时120分钟。

第一部分听力(共两节,满分30分)注意,听力部分答题时,请先将答案标在试卷上。

听力部分结束前,你将有两分钟的时间将答案转涂到答题卡上。

第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.Where are probably the speakers?A. In a car.B. On a boat.C. On a plane.2.What does Jenny want Brant to do?A. Go shopping with her.B. Buy something for her.C. Cook supper with her.3.What is the probable relationship between the speakers?A. Husband and wife.B. Interviewer and interviewee.C. Employer and employee.4.What day is it today?A. Sunday.B. Saturday.C. Friday.5.Why does the woman want a later appointment?A.Her flight was delayed.B.She needs to pick up someone.C.She has to take her mother to the hospital.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。

云南师大附中2023届高考适应性月考卷(四)英语(云南版)答案

云南师大附中2023届高考适应性月考卷(四)(云南版)英语参考答案第一部分听力(共两节,满分30分)1~5 CBCBA 6~10 BACBB 11~15 CABCA 16~20 CCABC第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)21~25 ABBAB 26~30 DACCA 31~35 BBACD第二节(共5小题;每小题2分,满分10分)36~40 EFBDA第三部分语言知识运用(共两节,满分45分)第一节完形填空(共20小题;每小题1.5分,满分30分)41~45 CBADC 46~50 BCADB 51~55 DBACA 56~60 DADBC第二节(共10小题;每小题1.5分,满分15分)61.was delivered 62.Calls 63.and 64.nestled 65.who 66.happiest 67.when/as 68.across 69.a 70.guessing第四部分写作(共两节,满分35分)第一节短文改错(共10小题;每小题1分,满分10分)Years ago,I was a volunteer English teacher in a village in Cameroon,which I befriended one①whereof my young students,Dick.He was very helpful to me and spent much evenings at my home,②manyassisting me with chores in exchange for meal,and teaching me the ins and outs of life in the village.③mealsHe never asked me for something,but I would regular buy him school supplies or clothing,as he was④anything ⑤regularlyvery poor but said he was motherless.At one point,I left him money∧care for my dog while I was⑥and ⑦toaway on a extended trip.After I left Cameroon,I lost in touch with Dick.I feel guilty for “abandoning英语参考答案·第1页(共1页)⑧an ⑨⑩felthim”—guilt that haunted me for years.第二节书面表达(满分25分)【参考范文】Dear Harrison,I am writing to share with you an exciting experience.In order to broaden the students’ horizon and encourage them to structure their career planning well,our school invited some professors to deliver a series of lectures about the major construction of the university relating to 14 academic disciplines from July 20th to 22nd in our auditorium.With their vivid and informative lectures,the experts provided us with a lot of enlightenment and helped us figure out some puzzles we might encounter about our future major choosing.I do benefit a lot from those lectures.With those positive suggestions and useful information,which helped further clarify the puzzles we might have in our future careers,I am convinced that my following college life will be full of excitement and fruits.Yours,Li Hua【解析】第二部分阅读理解第一节A主题语境:人与自然——自然生态【语篇导读】本文是应用文。

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云南师大附中2021届高考适应性月考卷(一)英语参考答案第一部分听力(共两节,满分30分)1~5 CABAC 6~10 BCACB 11~15 ABCCB 16~20 CABAA第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)21~25 CCBBC 26~30 DBDAC 31~35 BADDA第二节(共5小题;每小题2分,满分10分)36~40 DEGBF第三部分语言知识运用(共两节,满分45分)第一节(共20小题;每小题1.5分,满分30分)41~45 CABDA 46~50 CBDAB 51~55 CDBDA 56~60 CCBAD第二节(共10小题;每小题1.5分,满分15分)61.is located 62.attraction 63.got 64.pools 65.which 66.various/varied 67.mainly 68.wandering 69.to go 70.to第四部分写作(共两节,满分35分)第一节短文改错(共10小题;每小题1分,满分10分)Dear Mary,How have you been recently? I am very delighted to tell you a piece of good news∧a tennis match①thatwill be hold in our school on 29th of this month.The competition welcomed anyone who is interested②held ③welcomesin a sport.You’re talented in tennis,since why not participate? Uncertainly,this is a chance to show ④the ⑤so ⑥Certainlyhis talent and make friends.The top tenth players will be awarded a prize.May successes be in your ⑦your ⑧ten ⑨successfavor.I’m looking forward to your reply.Don’t hesitate to contact with me if you need any help.⑩Yours,英语参考答案·第1页(共10页)Li Hua 第二节书面表达(满分25分)【参考范文】Dear Jason,I’m writing to apply to be a member of your volunteer group,whose aim is to raise students’awareness of fighting against the novel coronavirus.Due to the urgent epidemic situation,everyone should spare no effort to prevent the disease from harming more people.I sincerely hope that I can make a contribution.As a student of nursing major,I have not only the enthusiasm but professional knowledge to help spread related tips and skills.It’s also a priceless chance for me to put my expertise into use.Moreover,I’m fluent in English and easygoing as well.I’d appreciate it if you could take my application into consideration.Thanks a lot!Yours,Li Hua【解析】第二部分阅读理解A【语篇导读】本文是说明书类应用文。

介绍了双筒望远镜的使用、清洁和保存方法。

21.C 细节理解题。

根据第一部分(HOW TO USE YOUR BINOCULAR)的A(EYE DISTANCE ADJUSTMENT)结尾处的“Note the setting for later use.”可知调好双眼距离后可以记下来方便以后使用,故选C。

22.C 细节理解题。

根据第三部分(VERY IMPORTANT)的提示“Never attempt to clean your binocular from inside or try to take it apart.”可知拆开望远镜进行清洁的操作是错误的,故选C。

23.B 文章出处题。

此文介绍了双筒望远镜的使用、清洁和保存方法,是产品说明书,故选B。

B【语篇导读】本文是记叙文。

作者在海边租的度假小屋中得到充分休息,为人生充电。

24.B 细节理解题。

根据第一段内容可知作者身兼数职,以及第一段第二句尾的“…had英语参考答案·第2页(共10页)burned me out”,可知作者觉得很疲惫,需要假期,故选B。

25.C 细节理解题。

根据第三段第三句和第四句“Inspecting it,the first thing I noticed was the same small carpet in the kitchen as in my own.It felt like a good sign.”可知厨房里的小地毯和作者家的一样,是一个好预兆,故选C。

26.D 细节理解题。

根据第四段第四句和第五句“Another year,during a beach walk,a woman stopped me because she thought she knew me.It turned out we have a friend in common inAtlanta.”可知该女子与作者攀谈是因为她认识她,她们有共同的朋友,故选D。

27.B 标题归纳题。

文章描写了作者因为工作劳累来到海边小屋度假,得到充分休息后感觉又充满活力,标题中的“shelter”与文中多次出现的“rental/house”相呼应,故选B。

C【语篇导读】本文是说明文。

介绍了内华达地震实验室对新型桥梁设计进行测试的成果。

28.D 细节理解题。

根据第一段最后一句“The designs were created to better stand violent earthquakes and speed reconstruction efforts after major quake damage.”可知该设计是为了让桥梁经受住剧烈地震以及震后迅速修复桥梁,故选D。

29.A 观点态度题。

根据第二段第六句“The bridge has done better than we expected,”可知Saiid Saiidi教授对这个实验的结果很满意,故选A。

30.C 细节理解题。

根据第三段第三句“He said the tested designs used special types of connectors to link pre-made bridge parts.”可知试验中使用连接器连接桥梁部件,故选C。

31.B 写作目的题。

本文的写作目的是介绍内华达地震实验室对新型桥梁进行试验的成果,故选B。

D【语篇导读】本文是调查报告。

通过对资深留学中介的采访,报道了目前很多去往英美等国家的中国留学生年轻化的趋势和引发的一些相关问题。

32.A 细节理解题。

根据文章第一段和第二段大意,尤其是第一段结尾“…and the current group of Chinese overseas students is younger than those in the past years.”可知近年来英语参考答案·第3页(共10页)去往英美等国家的中国留学生年轻化,故选A。

33.D 推理判断题。

根据文章第三段提到的有些中国留学生无法自律,无法毕业的问题,以及最后一段第三句“But she does think both students and parents should be responsiblefor their own investment of both time and money.”可知杜认为,孩子和家长都应该对出国留学的投资负责,应该更谨慎地做决定,故选D。

34.D 细节理解题。

根据文章第二段第四句“…most of them are not ready to put themselves ina completely different context at such a young age.”和倒数第二句“…and there isanother group who did not do very well in their college entrance exams,so they seek tostudy abroad as a solution to their troubles.”以及第三段提到中国留学生缺乏自律的问题,可知有些中国留学生没有能力独立适应国外的生活和学习,故选D。

35.A 词义猜测题。

根据文章最后一段第一句和第二句“As to the dismissal issue,Du said it’s inevitable due to the large number of students crowding abroad.It’s just not easy to ensurequality.”可知杜说由于学生数量多,难以保证质量,所以被大学开除的问题是“难以避免的”,故选A。

第二节【语篇导读】本文是说明文。

文章介绍了应该如何设置适合自己的人生目标。

36.D 考查文章总分关系。

第一段总起全文,下文叙述了几点设立目标的注意事项,此句用于再强调目标的重要性及引出下文,故选D。

37.E 考查句间承接关系。

根据空后句子“Try to suit your goals to your strengths.”可知要先了解自己的长项和弱项再设定相应目标,与E选项中的“strengths”相呼应,故选E。

38.G 考查句间并列关系。

根据空前一句“…if you are good at drawing,think about careers in visual design.”可知如果善于画画可以考虑设计工作,G项的意思是:如果你善于写作,就考虑如何把它利用到事业当中,两句话并列举例,互相呼应,故选G。

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