【英语】山东省淄博市2013届高三第二次模拟考试30
山东省淄博市2013届高三第一次模拟考试 英语 Word版无答案
绝密★启用并使用完毕前淄博市2012—2013学年度高三模拟考试试题英语本试卷分第I卷和第II卷两部分，共14页。
满分l 50分。
考试用时l 20分钟。
考试结束后，将本试卷和答题卡一并交回。
注意事项：1．答题前，考生务必用0．5毫米黑色签字笔将自己的姓名、座号、准考证号、县区和科类填写在答题卡和试卷规定的位置上。
2．第I卷每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑；如需改动，用橡皮擦干净后，再选涂其他答案标号。
3．第II卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置；如需改动，先划掉原来的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带。
不按以上要求作答的答案无效。
第I卷(共105分)第一部分：听力(共两节，满分30分)该部分分为第一、第二两节。
注意：回答听力部分时，请先将答案标在试卷上。
听力部分结束前，你将有两分钟的时间将你的答案转涂到客观题答题卡上。
第一节(共5小题：每小题l．5分，满分7．5分)听下面5段对话。
每段对话后有一个小题．从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is the shirt?A．￡l 9．15．B．￡9．15．C．￡9．18．答案是B。
1．Wh at do we know about Aim?A．She is good at singing．B．She is interested in listening to music．C．She likes to play musical instruments．2. What does the man mean?A．The bag is expensive．B．The woman shouldn't buy a new bag．C．He can’t lend any money to the woman．3．Which course is the woman not interested in? A．English．B．Maths．C．History4．What does the woman think of the furniture show?A．It’s a waste of money．B．It’s a waste of time．C．It’s worth visiting．5．What will the woman probably do next Saturday?A．To watch a play．B．To stay at home．C．To have dinner with the man．第二节(共15小题；每小题l．5分，满分22．5分)听下面5段对话。
山东省淄博市2014届高三下学期第二次模拟考试英语试题(word版)
山东省淄博市2014届高三下学期第二次模拟考试英语试题（word版）本试卷分第I卷和第II卷两部分，共14页。
满分I50分。
考试用时120分钟。
考试结束后，将本试卷和答题卡一并交回。
注意事项：1．答题前，考生务必用0．5毫米黑色签字笔将自己的姓名、座号、准考证号、县区和科类填写在答题卡和试卷规定的位置上。
2．第I卷每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑；如需改动，用橡皮擦干净后，再选涂其他答案标号。
3．第II卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置；如需改动，先划掉原的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带。
不按以上要求作答的答案无效。
第I卷（共105分）第一部分：英语知识运用（共两节，满分55分）第一节单项填空（共10小题；每小题1．5分，满分15分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
1．The new president has been doing everything he can, with or without Congress, opportunity for more people．A．to expand B．expanding C．expanded D．expand 2．—Doctor, need I go on taking medicine?—No．You've fully recovered, _ I said you would．A．though ; B．because C．if D．as 3．—Has Mr．Gilbert completed the report?—I don't know．But I saw he it．A．wrote B．has been writing C．was writing D．had written 4．Knowing his classmates who have gone to college are all successful, he wishes he harder at school．A．worked ' B．had worked C．has worked D．works 5．—How are you prepared for the new project?—We have done much but a lot of equipment ．A．is remained to buy B．are remained to buyC．remains to be bought D．remain to be bought6．We should thank our teachers and friends, with help our effort has paid off．A．that B．which C．whom D．whose 7．Before you make a decision you have to figure out you care for．A．what B．that C．why D．whether 8．—Our family are going to Hawaii for a holiday．—．Its beach is very attractive．A．You're crazy B．It's all right C．You're lucky D．Ws surprising9．There is great need for clean water in city where the river has been polluted．A．不填; the B．a；the C．不填；a D．a；a10．I can't remember when you．told me the story but I clearly remember where it was you told me．A．when B．what C．if D．that第二节完形填空（两篇共30小题；满分40分．A篇10小题；每题1分，满分10分．B篇20小题；每题1．5分，满分30分）阅读下面短文，从短文后各题所给的四个选项（A、B、C、D）中，选出最佳选项。
山东省淄博市2013届高三第二次模拟考试 数学理 Word版含答案
高三复习阶段性检测试题理 科 数 学本试卷分第I 卷和第II 卷两部分，共5页．满分150分．考试用时120分钟，考试结束后，将试卷和答题卡一并上交． 注意事项：1．答题前，考生务必用0．5毫米黑色签字笔将自己的姓名、座号、考生号、县区和科类填写在答题卡和试卷规定的位置上．2．第1卷每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，答案不能答在试卷上．3．第II 卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置，不能写在试卷上；如需改动，先划掉原来的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带．不按以上要求作答的答案无效．4．填空题请直接填写答案，解答题应写出文字说明、证明过程或演算步骤． 参考公式： 锥体的体积公式：13V Sh =，其中S 是锥体的底面积，h 是锥体的高.如果事件A,B 互斥，那么()()()P A B P A P B +=+；如果事件A,B 独立，那么()()()P A B P A P B =⋅.第I 卷（选择题 共60分）一、选择题：本大题共12小题，每小题5分，共60分，在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合{}{}1,0,1,,x A B y y e x A =-==∈，则A B ⋂= A.{}0 B.{}1C.{}0,1D.{}1,0,1-2.复数11i i+-（i 是虚数单位）的共轭复数的虚部为 A.1-B.0C.1D.23.已知等差数列{}n a 的前n 项和为n S ，满足1313113a S a ===，则 A.14- B.13- C.12- D.11-4.一个四棱锥的底面为正方形，其三视图如图所示，则这个四棱锥的体积是 A.1 B.2C.3D.45.函数()2tan 22f x x x ππ⎛⎫=-- ⎪⎝⎭在，上的图象大致为6.在A B C ∆中，“sin 2A >”是“3A π∠>”的A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件 7.如图，平行四边形ABCD 中，2,1,AB A D A ==∠=，点M 在AB 边上，且13A M AB D M D B =⋅，则等于A.2-B.2C.1-D.18.市内某公共汽车站6个候车位（成一排），现有3名乘客随便坐在某个座位上候车，则恰好有2个连续空座位的候车方式的种数是 A.48B.54C.72D.849.已知x,y 满足条件020x y x x y k ≥⎧⎪≤⎨⎪++≤⎩（k 为常数），若目标函数3z x y =+的最大值为8，则k= A.16-B.6-C.83-D.610.已知A B C ∆中，三个内角A ，B ，C 的对边分别为a,b,c ，若A B C ∆的面积为S ，且()222,t a n S a b c C =+-则等于A.34B.43C.43-D.34-11.在平面直角坐标系xo y 中，圆C 的方程为228150x y x +-+=，若直线2y kx =+上至少存在一点，使得以该点为圆心，半径为1的圆与圆C 有公共点，则k 的最小值是 A.43-B.54-C.35-D.53-12.定义域为[],a b 的函数()y f x =的图象的两个端点为A,B,M ()(),x y x 是f 图象上任意一点，其中()()()1,1x a b R ON OA OB λλλλλ=+-∈=+- 向量，若不等式M N k ≤恒成立，则称函数()[],f x a b 在上“k 阶线性近似”.若函数[]112y x x=+在，上“k 阶线性近似”，则实数k 的取值范围为A.[)0+∞，B.[)1+∞，C.32⎡⎫-+∞⎪⎢⎣⎭D.32⎡⎫++∞⎪⎢⎣⎭第II 卷（共90分）二、填空题：本大题共4小题，每小题4分，共16分13.执行如图所示的程序框图，若输出的结果是8，则输入的数是______. 14.若双曲线()222210x y a b ab-=>>的左、右焦点分别为F 1,F 2，线段F 1F 2被抛物线22y bx =的焦点分成5：3两段，则此双曲线的离心率为______.15.已知函数()f x 在实数集R 上具有下列性质：①直线1x =是函数()f x 的一条对称轴;②()()2f x f x +=-;③当1213x x ≤<≤时，()()()21f x f x -⋅()210,xx -<则()2012f 、()2013f 从大到小的顺序为_______.16.如图，一个类似杨辉三角的数阵，请写出第()2n n ≥行的第2个数为______.三、解答题：本大题共6个小题，共74分. 17.（本小题满分12分）已知函数()()21cos cos 02f x x x x ωωωω=+-> ，其最小正周期为.2π（I ）求()f x 的表达式；（II ）将函数()f x 的图象向右平移8π个单位，再将图象上各点的横坐标伸长到原来的2倍（纵坐标不变），得到函数()y g x =的图象，若关于x 的方程()0g x k +=，在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个实数解，求实数k 的取值范围.18.（本小题满分12分）袋中有8个大小相同的小球，其中1个黑球，3个白球，4个红球. （I ）若从袋中一次摸出2个小球，求恰为异色球的概率；（II ）若从袋中一次摸出3个小球，且3个球中，黑球与白球的个数都没有超过红球的个数，记此时红球的个数为ξ，求ξ的分布列及数学期望E ξ.19.（本小题满分12分）等比数列．．．．{}n c 满足(){}1*1104,n n n n c c n N a -++=⋅∈数列的前n 项和为n S ，且2l o g .n na c = （I ）求,n n a S ；（II ）数列{}{}1,41n n n n n b b T b S =-满足为数列的前n 项和，是否存在正整数m ，()1k m k <<，使得1,,m k T T T 成等比数列？若存在，求出所有,m k 的值；若不存在，请说明理由.20.（本小题满分12分）在如图所示的几何体中，A B C ∆是边长为2的正三角形，1,AE AE >⊥平面ABC ，平面B C D ⊥平面ABC,BD=CD ，且.BD CD ⊥（I ）若AE=2，求证：AC 、、平面BDE ； （II ）若二面角A —DE —B 为60°，求AE 的长.21.（本小题满分13分）已知抛物线24y x =的焦点为F 2，点F 1与F 2关于坐标原点对称，直线m 垂直于x 轴（垂足为T ），与抛物线交于不同的两点P ,Q 且125F P F Q ⋅=-.（I ）求点T 的横坐标0x ；（II ）若以F 1,F 2为焦点的椭圆C 过点1,2⎛⎫⎪ ⎪⎝⎭. ①求椭圆C 的标准方程；②过点F 2作直线l 与椭圆C 交于A,B 两点，设22F A F B λ=，若[]2,1,T A T Bλ∈--+求的取值范围.22.（本小题满分13分）已知(),P x y 为函数1ln y x =+图象上一点，O 为坐标原点，记直线OP 的斜率()k f x =. （I ）若函数()f x 在区间1,3m m ⎛⎫+⎪⎝⎭()0m >上存在极值，求实数m 的取值范围； （II ）当 1x ≥时，不等式()1t f x x ≥+恒成立，求实数t 的取值范围；（III ）求证()()()22*1!1n n n e n N -+>+∈⎡⎤⎣⎦.高三复习阶段性检测试题理科数学参考答案及评分标准一、 选择题1-5 B A D B C 6-10 A D C B C 11-12 A C 二、填空题: 本大题共4小题，每小题4分，共16分． (13) 2,22- (14)332(15) )2013(f ,)2012(f ,)2011(f (16)223n n -+ 三、解答题：本大题共6小题，共74分． (17)（本小题满分12分）解：（I ）21()cos cos 2f x x x x ωωω=⋅+-c o s 211i n 2s i n (2)2226x x x ωπωω+=+-=+ ……………3分 由题意知)(x f 的最小正周期2T π=，222T πωπωπ=== 所以2=ω……………………………………………………………………5分所以()sin 46f x x π⎛⎫=+⎪⎝⎭ …………………………………………………6分（Ⅱ）将()f x 的图象向右平移个8π个单位后，得到)34sin(π-=x y 的图象，再将所得图象所有点的横坐标伸长到原来的2倍，纵坐标不变，得到)32sin(π-=x y 的图象.所以)32sin()(π-=x x g …………………………9分 因为02x π≤≤,所以22333x πππ-≤-≤.()0g x k +=在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个实数解，即函数()y g x =与y k =-在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个交点，由正弦函数的图象可知22k -≤-<或1k -=所以22k -<≤1k =-. …………………………12分(18)（本小题满分12分）解: （Ⅰ）摸出的2个小球为异色球的种数为11C 11173419C C C += ………2分从8个球中摸出2个小球的种数为2828C =………………3分故所求概率为1928P =………………………………4 分（Ⅱ）符合条件的摸法包括以下三种：一种是有1个红球，1个黑球，1个白球，共有11C 114312C C =种 ………………………………5分一种是有2个红球，1个其它颜色球，共有214424C C =种， ………………………………6分 一种是所摸得的3小球均为红球，共有344C =种不同摸法，故符合条件的不同摸法共有40种. ………………………………8分由题意知，随机变量ξ的取值为1，2，3.其分布列为：………………………11分 3319123105105E ξ=⨯+⨯+⨯= ……………………12分(19)（本小题满分12分） 解: （Ⅰ）40,103221=+=+c c c c ，所以公比4=q ……………………2分10411=+c c 得21=c121242--=⋅=n n n c ……………………4分所以212log 221n n a n -==- ……………………5分 21()[1(21)]22n n n a a n n S n ++-=== ……………………6分（Ⅱ）由（Ⅰ）知211114122121n b n n n ⎛⎫==- ⎪--+⎝⎭于是11111112335212121n n T n n n ⎡⎤⎛⎫⎛⎫⎛⎫=-+-++-= ⎪ ⎪ ⎪⎢⎥-++⎝⎭⎝⎭⎝⎭⎣⎦ …………9分 假设存在正整数(),1m k m k <<，使得1,,m k T T T 成等比数列，则2121321m k m k ⎛⎫=⨯ ⎪++⎝⎭， 可得2232410m m km-++=>， 所以22410m m -++>从而有，1122m -<<+，由,1m N m *∈>，得2m = …………………… 11分此时12k =.当且仅当2m =，12k =时，1,,m k T T T 成等比数列. ……………………12分 (20)（本小题满分12分） 解: （Ⅰ）分别取B C B A B E ，， 的中点M N P ，，,连接D M M N NP D P ，，，,则M N ∥A C ,N P ∥A E ,且1=12N P A E =因为B D C D =，2B C =,M 为B C 的中点, 所以D M B C ⊥,1D M = 又因为平面BC D ⊥平面ABC ,所以D M ⊥平面ABC ……………2分 又A E ⊥平面ABC ,BEDCANP所以D M ∥A E ……………………4分所以D M ∥N P ，且D M N P =,因此四边形D M N P 为平行四边形，所以M N ∥D P ,所以A C ∥D P ，又A C ⊄平面BD E ，D P ⊂平面BDE ， 所以A C ∥平面BD E .……………………6分（或者建立空间直角坐标系，求出平面BD E 的法向量1n ，计算10AC ⋅=n 即证） （Ⅱ）解法一:过M 作M N ⊥E D 的延长线于N ,连接B N . 因为B C A M ⊥,B C D M ⊥,所以B C ⊥平面D M A E ,ED ⊂平面D M A E 则有BC ED ⊥.所以E D ⊥平面B M N ,B N ⊂平面B M N , 所以E D B N ⊥.所以M N B ∠为二面角A ED B --的平面角，即=60MNB ︒∠. ……………………9分在R t B M N ∆中，=1BM，则=M N,=BN .在Rt M N D ∆中，=3D N .设1A E h =+，则DE =所以3N E =，又BE =在R t B N E ∆中,222BE BN NE =+,即()2212h ++=223⎛⎛+ ⎪⎝⎝⎭解得h=，所以1AE = ………………12分解法二:由（Ⅰ）知D M ⊥平面ABC ，A M M B ⊥, 建立如图所示的空间直角坐标系M xyz -.设A E h =，则()0,0,0M ,()1,0,0B , ()0,0,1D ()0A ,()E h ， ()1,0,1BD =-,()BE h =-.设平面BD E 的法向量1(,,)x y z =n则110,0.B D B E ⎧⋅=⎪⎨⋅=⎪⎩ n n所以0,0.x z x zh -+=⎧⎪⎨-++=⎪⎩令1x =,所以1=n ……………………9分又平面A D E 的法向量2(1,0,0)=n 所以1212121cos ,2⋅<>===⋅n n n n n nEzMBED CAN解得1h =,即1AE = ……………………12分 (21)（本小题满分13分） 解：（Ⅰ）由题意得)0,1(2F ，)0,1(1-F ，设),(00y x P ，),(00y x Q -，则),1(001y x P F +=，),1(002y x Q F --=.由521-=⋅Q F P F ，得512020-=--y x 即42020-=-y x ，①…………………2分 又),(00y x P 在抛物线上，则0204x y =，②联立①、②易得20=x ……………………4分 （Ⅱ）（ⅰ）设椭圆的半焦距为c ，由题意得1=c ，设椭圆C 的标准方程为)0(12222>>=+b a by ax ，则121122=+ba ③122+=b a ④…………………5分 将④代入③，解得12=b 或212-=b （舍去）所以2122=+=b a ……………………6分 故椭圆C 的标准方程为1222=+y x……………………7分（ⅱ）方法一：容易验证直线l 的斜率不为0，设直线l 的方程为1x ky =+将直线l 的方程代入2212xy +=中得：22(2)210k y ky ++-=.…………………8分设112212(,),(,),00A x y B x y y y ≠≠且，则由根与系数的关系，可得：12222k y y k +=-+ ⑤12212y y k =-+ ⑥ …………………9分因为B F A F 22λ=，所以12y y λ=，且0λ<.将⑤式平方除以⑥式，得：221222214142222y y kky y k k λλ++=-⇒++=-++由[]51112,1+22022λλλλλ∈--⇒-≤≤-⇒-≤++≤2214022kk ⇒-≤-≤+所以 7202≤≤k ……………………………………………………………11分因为1122(2,),(2,)TA x y TB x y =-=- ，所以1212(4,)TA TB x x y y +=+-+， 又12222k y y k +=-+，所以2121224(1)4()22k x x k y y k ++-=+-=-+，故2222221212222216(1)4||(4)()(2)(2)k k TA TB x x y y k k ++=+-++=+++2222222216(2)28(2)828816(2)2(2)k k k k k +-++==-++++， 令212t k =+，所以2207k ≤≤所以27111622k ≤≤+，即71[,]162t ∈， 所以222717||()828168()42T A T B f t t t t +==-+=-- .而71[,]162t ∈，所以169()[4,]32f t ∈.所以||[2,]8TA TB +∈ . ………………………………………………13分方法二：1）当直线l 的斜率不存在时，即1-=λ时，)22,1(A ，)22,1(-B ，又T )0,2(，所以(1,(1,222TA TB +=-+--=…………8分2）当直线l 的斜率存在时，即[)1,2--∈λ时，设直线l 的方程为)1(-=x k y由⎪⎩⎪⎨⎧=+-=1222y x k kx y 得0224)21(2222=-+-+k x k x k设()()1122,,,A x y B x y ，显然120,0y y ≠≠，则由根与系数的关系，可得：2221214kkx x +=+，22212122kk x x +-=⋅ ……………………9分221212122)(kk k x x k y y +-=-+=+ ⑤ 22212122121)1)((kkx x x x k y y +-=++-=⋅ ⑥因为B F A F 22λ=，所以12y y λ=，且0λ<.将⑤式平方除以⑥式得： 221421k+-=++λλ由[)1,2--∈λ得⎪⎭⎫⎢⎣⎡--∈+2,251λλ即⎪⎭⎫⎢⎣⎡-∈++0,2121λλ 故0214212<+-≤-k ，解得272≥k ………………………………………10分 因为1122(2,),(2,)TA x y TB x y =-=-，所以1212(4,)TA TB x x y y +=+-+，又222121)1(44kk x x ++-=-+，故2222222221221)21(4)21()1(16)()4(k kk k y y x x ++++=++-+=+22222222)21(221104)21(2)21(10)21(4k kk k k ++++=+++++=…………………11分令2211kt +=，因为272≥k 所以8121102≤+<k ，即⎥⎦⎤ ⎝⎛∈81,0t ， 所以22251721042()22TA TBt t t +=++=+-1694,32⎛⎤∈ ⎥⎝⎦.⎥⎦⎤⎝⎛+8213,2 ……………………12分综上所述：||8TA TB +∈. ……………………13分(22)（本小题满分13分） 解：（Ⅰ）由题意()1ln xk f x x+==，0x > ……………………………………1分所以()21ln ln x x f x x x '+⎛⎫'==- ⎪⎝⎭…………………………………………2分 当01x <<时，()0f x '>；当1x >时，()0f x '<. 所以()f x 在()0,1上单调递增，在()1,+∞上单调递减.故()f x 在1x =处取得极大值. …………………………………………3分 因为函数()f x 在区间1,3m m ⎛⎫+⎪⎝⎭（其中0m >）上存在极值， 所以01113m m <<⎧⎪⎨+>⎪⎩得213m <<. 即实数m 的取值范围是213⎛⎫⎪⎝⎭，. …………………………………………4分（Ⅱ）由()1t f x x ≥+得()()11ln x x t x++≤令()()()11ln x x g x x ++=则()2ln x xg x x-'=. ……………………………………………………6分令()ln h x x x =- 则()111=x h x x x-'=-因为1,x ≥所以()0h x '≥,故()h x 在[)1+∞，上单调递增.……………………7分 所以()()110h x h ≥=>,从而()0g x '>()g x 在[)1+∞，上单调递增, ()()12g x g ≥=所以实数t 的取值范围是(],2-∞. …………………………………………9分 （Ⅲ）由(Ⅱ) 知()21f x x ≥+恒成立,即1ln 2122ln 11111xx x xx x x x+-≥⇔≥=->-+++ ……………………10分令()1,x n n =+则()()2ln 111n n n n +>-+所以()2ln 12112⨯>-⨯,()2ln 23123⨯>-⨯, ……,()()2ln 111n n n n +>-+.所以()()222111ln 1231212231n n n n n ⎡⎤⎡⎤⨯⨯⨯⋅⋅⋅⨯⨯+>-++⋅⋅⋅+⎢⎥⎣⎦⨯⨯+⎣⎦12121n n n ⎛⎫=-->- ⎪+⎝⎭………………………………12分所以()22221231n n n e-⨯⨯⨯⋅⋅⋅⨯⨯+>所以()()()221!1n n n en -*+>+⋅∈⎡⎤⎣⎦N . ………………………………13分。
高中英语真题-2013第二次高考科目教学质量检测
高中英语真题:2013第二次高考科目教学质量检测考生须知：本试卷分选择题和非选择题两部分。
满分120分，考试用时120分钟。
选择题部分（共80分）注意事项：1．答题前，考生在答题卡上务必用直径0.5毫米黑色墨水签字笔将自己的姓名、准考证号填写清楚，并贴好条形码。
请认真核准条形码上的准考证号、姓名和科目。
2．每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，不能答在试题卷上。
第一部分：英语知识运用（共两节，满分30分）第一节：单项填空（共20小题；每小题0.5分，满分10分）从A、B、C、D四个选项中，选出可双填入空白处的最佳选项，并在答题纸上将该选项标号涂黑。
1．--- Can I really get a mountain bicycle as a reward if I win the rac e?--- Absolutely! .A．It all depends B．I mean it C．You’ve got me D．So will you2．I can’t remember when turning point occurred exactly, but it might be summer morning when I was in New York.A．不填；a B．a; a C．the; a D．a; the 3．You needn’t have apologized for your absence - , it’s ha rdly your fault.A．therefore B．however C．meanwhile D．besides4．Every morning Jack’s wife will stand before the mirror, carefully until she has to go to work.A．dressed B．dressing C．to dressD．having dressed5．One split second later your life or someone else’s life could be gone you are just glancing at your phone to check a text message.A．every though B．in that C．only if D．as if6．If I your advice then, I think that the crops could be gro wing better.A．took B．would have taken C．had taken D．have taken7．The knowledge that his friends have deserted him is a (n) pill for Mr. Smith to swallow.A．extra B．bitter C．common D．effective 8．Our waste recycling project a lot of investigation and p aperwork had been done by the end of last term.A．involved B．to involve C．being involved D．involving9．Richardson joins a list of young stars whose careers and pe rsonal lives have been spoiled after early .A．experience B．promise C．impression D．failure10．Many grownups challenging conversations with their c hildren later this month to help them recover from the panic.A．have had B．have C．will be havingD．will have had11．Have you ever dreamed of staging a concert, thousand s of people are applauding and appreciation your music?A．at which B．when C．for which D．which12．During the flood many students volunteered through th e weekend, giving out food and water for the victims.A．working B．to work C．to have worked D．having worked13．--- How soon will the candidates get their university admissions? --- It may take three weeks for all the applications to be .A．withdrawn B．delivered C．edited D．processed14．I don’t like football; as for me, would be more fun than w atching a 90 minutes’ boring match.A．everything B．something C．anything D．nothing15．Just a month before the earthquake the school practiced a n emergency drill showing the children how tofind their “safe place”.A．calmly B．regularly C．automatically D．specially16．Not having promoted the new digital camera successfully, t he company should its original marketing methods.A．account for B．reflect on C．work outD．call up17．Only may cousin has chosen to apply for a job in Africa the majority of this year’s graduates working in Britain.A．in common with B．as well as C．in contrast to D．by reason of18．Statistics indicate that women are shoppers in Europe, contributing to four – fifths of annual online shopping sales.A．enthusiastic B．potential C．traditional D．intelligent19．The actress readily the fact that her unbalanced diet wa s a majothinfluence on her expanding figure.A．considered B．consulted C．acknowledged D．reviewed20．---Do you need the electric dryer?--- .A．No way B．My pleasure C．No problem D．After you第二节：完形填空（共20小题，每小题1分，满分20分）阅读下面短文，掌握其大意，然后从21—40题所给的四个选项（A、B、C、D）中，选出最佳选项，并在答题纸上将该选项标号涂黑。
2023届山东省淄博市部分学校高考二模英语试题答案
部分学校高三阶段性诊断考试试题英语参考答案（202304）第一部分阅读（共两节，满分50分）1-3 BDC4-7 ACDB8-11 ACBA12-15 DABD16-20 CEFGD第二部分语言知识运用（共两节，满分30分）第一节（共15小题；每小题1分，满分15分）21-25 BDCAC26-30 DABCD31-35 ABCDA第二节（共10小题；每小题1.5分，满分15分）36.which37.a38.lower39.or40.Normally41.intelligence42. are involved43.made44.with45.to create第三部分写作（共两节，满分40分）第一节（满分15分）参考范文My Favorite Chinese IdiomGood morning, everyone!Frankly speaking, the Chinese idiom “Qie Er Bu She”is one of my favorite expressions, which has helped me go through many tough days.It conveys the meaning of “the persistence instead of giving up”'. Four charac-ters combined, this idiom denotes the determination to explore despite being confronted with difficulties. The reason why I appreciate the proverb is that it lifts me up both academically and physically.I would be obliged if this idiom can illuminate others of my age.That's all. Thank you.第二节（满分25分）参考范文Then appeared a rescue boat with a pole attached to it. Frank supported the back of the old man whom the other two pushed upward the boat with great efforts. At the same time, someone on the boat pulled the old man up, making it in the end. Then, the three in the water grasped the pole on the boat, with which they climbed aboard, to safety. The three men sat on the boat, looking pale and exhausted, out of breath. Within ten minutes, the group was back on land.The old man was rushed to hospital. Luckily, the details on his condition proved there was nothing wrong with him and he recovered in a short time. “Thank you for saving my life,” he said, showing his sincere gratitude to Frank and the two men, who left the hospital in relief after ensuring the old man was safe. Frank returned to work, obviously late. “I was a bit late, but I had a good excuse. It is worth enough," he thought.。
山东省淄博市2013届高三复习阶段性检测(二模)理科综合试题.pdf
8．下列说法正确的是 A．相同物质的量的O2和O3，体积相同 B．离子化合物一定含有离子键，可能含有共价键 C．由盐酸的酸性强于氢硫酸的酸性，可推知氧化性：Cl2>S D．常温下，等体积、pH均为3的醋酸和硫酸分别与完全相同的镁条反应，硫酸产生氢气速率快 9．下列关于常见有机化合物的说法中正确的是 A．分子式为C4H10的物质具有三种分子结构 B．甲烷、苯、乙酸在一定条件下都能发生取代反应 C．丝绸和棉花的组成元素相同，分子结构不同，因而性质不同 D．用氢氧化钠溶液与乙酸乙酯充分混合并振荡，以除去其中的乙酸 10．下列说法正确的是 A．金属元素不可能形成含氧酸根离子 B．元素R的含氧酸的化学式是H2RO3，则其气态氢化物的化学式就是RH4 C．金属与非金属元素分界线附近的元素是过渡元素 D．形成化合物种类最多的元素在IVA族 11．下列实验方案可行或结论正确的是 A．用饱和Na2CO3溶液除去CO2中的HCl B．可用加热氯化铵的方法制取氨气 C．用加热的方法可除去碳酸钠粉末中的碳酸氢钠 D．在酸碱中和滴定实验中，当锥形瓶中溶液的颜色发生突变时即达到滴定终点 12．下列说法正确的是 A．0．1mol氯气与足量氢氧化钠溶液(常温)反应，转移电子0．1NA B．常温下将醋酸钠、盐酸两溶液混合后溶液呈中性，则混合溶液中：（Cl-） C．某溶液中水电离出的，则此溶液中K+、、Cl—、可以大量共存 D．常温下物质的量浓度相等的① (NH4)2CO3溶液、②(NH4)2SO4溶液和③NH4Cl溶液 中，水的电离程度 ：①>③>② 13．一定质量的某铁的氧化物FexOy，与足量4 mol/L稀硝酸溶液充分反应，消耗硝酸700mL，放出2．24LNO气体(标 准状况)。则该铁的氧化物的化学式为 A．FeO B．Fe2O3 C．Fe3O4 D．Fe8O10 二、选择题(本题包括7小题，每小题给出的四个选项中，有的只有一个选项正确，有的 有多个选项正确，全部选对的得5分，选对但不全的得3分，有选错的得0分) 14．用比值法定义物理量是物理学中一种很重要的思想方法，下列物理量由比值法定义正确的是 A．加速度 B．磁感应强度 C．电容 D．电流强度 15．空间站是科学家进行天文探测和科学实验的特殊而又重要的场所。假设空间站正在地球赤道平面内的圆周轨道 上运行，其离地球表面的高度为同步卫星离地球表面高度的十分之一，且运行方向与地球自转方向一致。下列说法正确 的是 A．空间站运行的加速度等于其所在高度处的重力加速度 B．空间站运行的速度等于同步卫星运行速度的倍 C．在空间站工作的宇航员因受到平衡力作用而在舱中悬浮或静止 D．站在地球赤道上的人观察到空间站向东运动 16．一理想变压器原、副线圈的匝数比为10：l，原线圈输入电压的变化规律如图甲所示。副线圈所接电路如图乙 所示，P为滑动变阻器的触头。下列说法正确的是 A．副线圈输出电压的频率为50Hz B．副线圈输出电压的有效值为3lV C．P向右移动时，电阻R消耗的功率增大 D．P向右移动时，原、副线圈的电流比增大 17．如图所示，A、B为两个等量正点电荷，D为A、B连线的中点。以O为坐标原点、垂直AB向右为正方向建立Ox轴。 下列四幅图分别反映了在x轴上各点的电势 (取无穷远处电势为零)和电场强度E的大小随坐标x的变化关系，其中正确的 是
【数学】山东省淄博市2013届高三第二次模拟考试(理)
山东省淄博市2013届高三第二次模拟考试（理）本试卷分第I 卷和第II 卷两部分，共5页．满分150分．考试用时120分钟，考试结束后，将试卷和答题卡一并上交． 注意事项：1．答题前，考生务必用0．5毫米黑色签字笔将自己的姓名、座号、考生号、县区和科类填写在答题卡和试卷规定的位置上．2．第1卷每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，答案不能答在试卷上．3．第II 卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置，不能写在试卷上；如需改动，先划掉原来的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带．不按以上要求作答的答案无效．4．填空题请直接填写答案，解答题应写出文字说明、证明过程或演算步骤． 参考公式： 锥体的体积公式：13V Sh =，其中S 是锥体的底面积，h 是锥体的高.如果事件A,B 互斥，那么()()()P A B P A P B +=+；如果事件A,B 独立，那么()()()P AB P A P B =⋅.第I 卷（选择题 共60分）一、选择题：本大题共12小题，每小题5分，共60分，在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合{}{}1,0,1,,xA B y y e x A =-==∈，则A B ⋂=A.{}0B.{}1C.{}0,1D.{}1,0,1-2.复数11ii+-（i 是虚数单位）的共轭复数的虚部为 A.1-B.0C.1D.23.已知等差数列{}n a 的前n 项和为n S ，满足1313113a S a ===，则 A.14- B.13- C.12- D.11-4.一个四棱锥的底面为正方形，其三视图如图所示，则这个四棱锥的体积是 A.1 B.2 C.3 D.45.函数()2tan 22f x x x ππ⎛⎫=--⎪⎝⎭在，上的图象大致为6.在ABC ∆中，“sin 2A >”是“3A π∠>”的A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件7.如图，平行四边形ABCD 中，2,1,60AB AD A ==∠=，点M 在AB 边上，且13AM AB DM DB =⋅，则等于A.C.1-D.18.市内某公共汽车站6个候车位（成一排），现有3名乘客随便坐在某个座位上候车，则恰好有2个连续空座位的候车方式的种数是 A.48 B.54 C.72 D.849.已知x,y 满足条件020x y x x y k ≥⎧⎪≤⎨⎪++≤⎩（k 为常数），若目标函数3z x y =+的最大值为8，则k= A.16-B.6-C.83-D.610.已知ABC ∆中，三个内角A ，B ，C 的对边分别为a,b,c ，若ABC ∆的面积为S ，且()222,tan S a b c C =+-则等于A.34B.43C.43-D.34-11.在平面直角坐标系xoy 中，圆C 的方程为228150x y x +-+=，若直线2y kx =+上至少存在一点，使得以该点为圆心，半径为1的圆与圆C 有公共点，则k 的最小值是 A.43-B.54-C.35-D.53-12.定义域为[],a b 的函数()y f x =的图象的两个端点为A,B,M ()(),x y x 是f 图象上任意一点，其中()()()1,1x a b R ON OA OB λλλλλ=+-∈=+-向量，若不等式MN k≤恒成立，则称函数()[],f x a b 在上“k 阶线性近似”.若函数[]112y x x=+在，上“k 阶线性近似”，则实数k 的取值范围为A.[)0+∞，B.[)1+∞，C.32⎡⎫-+∞⎪⎢⎣⎭D.32⎡⎫+∞⎪⎢⎣⎭第II 卷（共90分）二、填空题：本大题共4小题，每小题4分，共16分13.执行如图所示的程序框图，若输出的结果是8，则输入的数是______.14.若双曲线()222210x y a b a b-=>>的左、右焦点分别为F 1,F 2，线段F 1F 2被抛物线22y bx =的焦点分成5：3两段，则此双曲线的离心率为______.15.已知函数()f x 在实数集R 上具有下列性质：①直线1x =是函数()f x 的一条对称轴;②()()2f x f x +=-;③当1213x x ≤<≤时，()()()21f x f x -⋅()210,xx -<则()2012f 、()2013f 从大到小的顺序为_______.16.如图，一个类似杨辉三角的数阵，请写出第()2n n ≥行的第2个数为______.三、解答题：本大题共6个小题，共74分. 17.（本小题满分12分）已知函数()()21cos cos 02f x x x x ωωωω=+->，其最小正周期为.2π （I ）求()f x 的表达式；（II ）将函数()f x 的图象向右平移8π个单位，再将图象上各点的横坐标伸长到原来的2倍（纵坐标不变），得到函数()y g x =的图象，若关于x 的方程()0g x k +=，在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个实数解，求实数k 的取值范围.袋中有8个大小相同的小球，其中1个黑球，3个白球，4个红球. （I ）若从袋中一次摸出2个小球，求恰为异色球的概率； （II ）若从袋中一次摸出3个小球，且3个球中，黑球与白球的个数都没有超过红球的个数，记此时红球的个数为ξ，求ξ的分布列及数学期望E ξ.19.（本小题满分12分）等比数列．．．．{}n c 满足(){}1*1104,n n n n c c n N a -++=⋅∈数列的前n 项和为n S ，且2l o g .n n a c = （I ）求,n n a S ；（II ）数列{}{}1,41n n n n n b b T b S =-满足为数列的前n 项和，是否存在正整数m ，()1k m k <<，使得1,,m k T T T 成等比数列？若存在，求出所有,m k 的值；若不存在，请说明理由.20.（本小题满分12分）在如图所示的几何体中，ABC ∆是边长为2的正三角形，1,AE AE >⊥平面ABC ，平面BCD ⊥平面ABC,BD=CD ，且.BD CD ⊥（I ）若AE=2，求证：AC 、、平面BDE ；（II ）若二面角A —DE —B 为60°，求AE 的长.21.（本小题满分13分）已知抛物线24y x =的焦点为F 2，点F 1与F 2关于坐标原点对称，直线m 垂直于x 轴（垂足为T ），与抛物线交于不同的两点P,Q 且125F P F Q ⋅=-. （I ）求点T 的横坐标0x ；（II ）若以F 1,F 2为焦点的椭圆C 过点1,2⎛ ⎝⎭.①求椭圆C 的标准方程；②过点F 2作直线l 与椭圆C 交于A,B 两点，设22F A F B λ=，若[]2,1,TA TB λ∈--+求的取值范围.已知(),P x y 为函数1ln y x =+图象上一点，O 为坐标原点，记直线OP 的斜率()k f x =. （I ）若函数()f x 在区间1,3m m ⎛⎫+ ⎪⎝⎭()0m >上存在极值，求实数m 的取值范围； （II ）当 1x ≥时，不等式()1tf x x ≥+恒成立，求实数t 的取值范围； （III ）求证()()()22*1!1n n n e n N -+>+∈⎡⎤⎣⎦.理科数学参考答案及评分标准一、 选择题1-5 B A D B C 6-10 A D C B C 11-12 A C 二、填空题: 本大题共4小题，每小题4分，共16分．(13) 2,22- (14)332 (15) )2013(f ,)2012(f ,)2011(f (16)223n n -+ 三、解答题：本大题共6小题，共74分．解：（I ）21()cos cos 2f x x x x ωωω=⋅+-cos2112sin(2)2226x x x ωπωω+=+-=+ ……………3分由题意知)(x f 的最小正周期2T π=，222T πωπωπ===所以2=ω……………………………………………………………………5分所以()sin 46f x x π⎛⎫=+⎪⎝⎭…………………………………………………6分 （Ⅱ）将()f x 的图象向右平移个8π个单位后，得到)34sin(π-=x y 的图象，再将所得图象所有点的横坐标伸长到原来的2倍，纵坐标不变，得到)32sin(π-=x y 的图象.所以)32sin()(π-=x x g …………………………9分因为02x π≤≤,所以22333x πππ-≤-≤.()0g x k +=在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个实数解，即函数()y g x =与y k =-在区间0,2π⎡⎤⎢⎥⎣⎦上有且只有一个交点，由正弦函数的图象可知22k -≤-<或1k -=所以k <≤或1k =-. …………………………12分 (18)（本小题满分12分）解: （Ⅰ）摸出的2个小球为异色球的种数为11C 11173419C C C += ………2分从8个球中摸出2个小球的种数为2828C = ………………3分 故所求概率为1928P =………………………………4 分 （Ⅱ）符合条件的摸法包括以下三种：一种是有1个红球，1个黑球，1个白球，共有11C 114312C C =种 ………………………………5分一种是有2个红球，1个其它颜色球，共有214424C C =种， ………………………………6分 一种是所摸得的3小球均为红球，共有344C =种不同摸法，故符合条件的不同摸法共有40种. ………………………………8分由题意知，随机变量ξ的取值为1，2，3.其分布列为：………………………11分3319123105105E ξ=⨯+⨯+⨯= ……………………12分 (19)（本小题满分12分）解: （Ⅰ）40,103221=+=+c c c c ，所以公比4=q ……………………2分10411=+c c 得21=c121242--=⋅=n n n c ……………………4分所以212log 221n n a n -==- ……………………5分21()[1(21)]22n n n a a n n S n ++-=== ……………………6分 （Ⅱ）由（Ⅰ）知211114122121n b n n n ⎛⎫==- ⎪--+⎝⎭于是11111112335212121n n T n n n ⎡⎤⎛⎫⎛⎫⎛⎫=-+-++-= ⎪ ⎪ ⎪⎢⎥-++⎝⎭⎝⎭⎝⎭⎣⎦ …………9分 假设存在正整数(),1m k m k <<，使得1,,m k T T T 成等比数列，则2121321m k m k ⎛⎫=⨯ ⎪++⎝⎭， 可得2232410m m k m-++=>， 所以22410m m -++> 从而有，11m <<， 由,1m N m *∈>，得2m = …………………… 11分 此时12k =.当且仅当2m =，12k =时，1,,m k T T T 成等比数列. ……………………12分(20)（本小题满分12分）解: （Ⅰ）分别取BC BABE ，， 的中点M N P ，，,连接DM MN NP DP ，，，,则MN ∥AC ,NP ∥AE ,且1=12NP AE =因为BD CD =，2BC =,M 为BC 的中点,所以DM BC ⊥,1DM =又因为平面BCD ⊥平面ABC , 所以DM ⊥平面ABC ……………2分 又AE ⊥平面ABC ,所以DM ∥AE ……………………4分所以DM ∥NP ，且DM NP =,因此四边形DMNP 为平行四边形，所以MN ∥DP ,所以AC ∥DP ，又AC ⊄平面BDE ，DP ⊂平面BDE ， 所以AC ∥平面BDE .……………………6分（或者建立空间直角坐标系，求出平面BDE 的法向量1n ，计算10AC ⋅=n 即证）（Ⅱ）解法一:过M 作MN ⊥ED 的延长线于N ,连接BN . 因为BC AM ⊥,BC DM ⊥,所以BC ⊥平面DMAE ,ED ⊂平面DMAE 则有BC ED ⊥.BEDC A MNPEDA N所以ED ⊥平面BMN ,BN ⊂平面BMN , 所以ED BN ⊥.所以MNB ∠为二面角A ED B --的平面角， 即=60MNB ︒∠. ……………………9分 在Rt BMN ∆中，=1BM，则MN,BN 在Rt MND ∆中，=3DN . 设1AE h =+，则DE所以3NE =BE =在Rt BNE ∆中,222BE BN NE =+,即()2212h ++=22+⎭解得h=所以1AE ………………12分解法二:由（Ⅰ）知DM ⊥平面ABC ，AM MB ⊥, 建立如图所示的空间直角坐标系M xyz -.设AE h =，则()0,0,0M ,()1,0,0B ,()0,0,1D ()A ,()E h ，()1,0,1BD =-,()BE h =-.设平面BDE 的法向量1(,,)x y z =n则110,0.BD BE ⎧⋅=⎪⎨⋅=⎪⎩n n所以0,0.x z x zh -+=⎧⎪⎨-++=⎪⎩令1x =,所以1=n ……………………9分又平面ADE 的法向量2(1,0,0)=n所以1212121cos ,2⋅<>===⋅n n n nn n 解得1h =, 即1AE = ……………………12分(21)（本小题满分13分）解：（Ⅰ）由题意得)0,1(2F ，)0,1(1-F ，设),(00y x P ，),(00y x Q -，则),1(001y x F +=，),1(002y x F --=. 由521-=⋅Q F P F ，得512020-=--y x 即42020-=-y x ，①…………………2分 又),(00y x P 在抛物线上，则0204x y =，②联立①、②易得20=x ……………………4分 （Ⅱ）（ⅰ）设椭圆的半焦距为c ，由题意得1=c ，Ez设椭圆C 的标准方程为)0(12222>>=+b a by a x ，则121122=+ba ③ 122+=b a ④ …………………5分将④代入③，解得12=b 或212-=b （舍去）所以2122=+=b a ……………………6分故椭圆C 的标准方程为1222=+y x ……………………7分 （ⅱ）方法一：容易验证直线l 的斜率不为0，设直线l 的方程为1x ky =+将直线l 的方程代入2212x y +=中得：22(2)210k y ky ++-=.…………………8分 设112212(,),(,),00A x y B x y y y ≠≠且，则由根与系数的关系，可得：12222ky y k +=-+ ⑤12212y y k =-+ ⑥ …………………9分因为F F 22λ=，所以12yy λ=，且0λ<.将⑤式平方除以⑥式，得：221222214142222y y k k y y k k λλ++=-⇒++=-++ 由[]51112,1+22022λλλλλ∈--⇒-≤≤-⇒-≤++≤2214022k k ⇒-≤-≤+ 所以 7202≤≤k ……………………………………………………………11分因为1122(2,),(2,)TA x y TB x y =-=-，所以1212(4,)TA TB x x y y +=+-+， 又12222k y y k +=-+，所以2121224(1)4()22k x x k y y k ++-=+-=-+，故2222221212222216(1)4||(4)()(2)(2)k k TA TB x x y y k k ++=+-++=+++ 2222222216(2)28(2)828816(2)2(2)k k k k k +-++==-++++， 令212t k =+，所以2207k ≤≤ 所以27111622k ≤≤+，即71[,]162t ∈， 所以222717||()828168()42TA TB f t t t t +==-+=--.而71[,]162t ∈，所以169()[4,]32f t ∈.所以||[2,8TA TB +∈. ………………………………………………13分 方法二：1）当直线l 的斜率不存在时，即1-=λ时，)22,1(A ，)22,1(-B ， 又T )0,2(，所以(1,(1,)222TA TB +=-+--= …………8分 2）当直线l 的斜率存在时，即[)1,2--∈λ时，设直线l 的方程为)1(-=x k y由⎪⎩⎪⎨⎧=+-=1222y x kkx y 得0224)21(2222=-+-+k x k x k设()()1122,,,A x y B x y ，显然120,0y y ≠≠，则由根与系数的关系，可得：2221214k k x x +=+，22212122kk x x +-=⋅ ……………………9分 221212122)(k kk x x k y y +-=-+=+ ⑤22212122121)1)((kk x x x x k y y +-=++-=⋅ ⑥ 因为B F A F 22λ=，所以12yy λ=，且0λ<.将⑤式平方除以⑥式得：221421k +-=++λλ由[)1,2--∈λ得⎪⎭⎫⎢⎣⎡--∈+2,251λλ即⎪⎭⎫⎢⎣⎡-∈++0,2121λλ 故0214212<+-≤-k ，解得272≥k ………………………………………10分 因为1122(2,),(2,)TA x y TB x y =-=-，所以1212(4,)TA TB x x y y +=+-+，又222121)1(44k k x x ++-=-+，2222222221221)21(4)21()1(16)()4(k k k k y y x x ++++=++-+=+ 22222222)21(221104)21(2)21(10)21(4k k k k k ++++=+++++=…………………11分 令2211k t +=，因为272≥k 所以8121102≤+<k ，即⎥⎦⎤ ⎝⎛∈81,0t ，所以22251721042()22TA TB t t t +=++=+-1694,32⎛⎤∈ ⎥⎝⎦.⎥⎦⎤ ⎝⎛+8213,2TB ……………………12分 综上所述：||[2,]8TA TB +∈. ……………………13分 (22)（本小题满分13分）解：（Ⅰ）由题意()1ln x k f x x+==，0x > ……………………………………1分 所以()21ln ln x x f x x x '+⎛⎫'==- ⎪⎝⎭…………………………………………2分 当01x <<时，()0f x '>；当1x >时，()0f x '<.所以()f x 在()0,1上单调递增，在()1,+∞上单调递减.故()f x 在1x =处取得极大值. …………………………………………3分 因为函数()f x 在区间1,3m m ⎛⎫+ ⎪⎝⎭（其中0m >）上存在极值， 所以01113m m <<⎧⎪⎨+>⎪⎩得213m <<. 即实数m 的取值范围是213⎛⎫ ⎪⎝⎭，. …………………………………………4分 （Ⅱ）由()1t f x x ≥+得()()11ln x x t x++≤ 令()()()11ln x x g x x++= 则()2ln x x g x x -'=. ……………………………………………………6分 令()ln h x x x =- 则()111=x h x x x-'=- 因为1,x ≥所以()0h x '≥,故()h x 在[)1+∞，上单调递增.……………………7分 所以()()110h x h ≥=>,从而()0g x '>()g x 在[)1+∞，上单调递增, ()()12g x g ≥=所以实数t 的取值范围是(],2-∞. …………………………………………9分（Ⅲ）由(Ⅱ) 知()21f x x ≥+恒成立, 即 1ln 2122ln 11111x x x x x x x x+-≥⇔≥=->-+++ ……………………10分 令()1,x n n =+则()()2ln 111n n n n +>-+ 所以()2ln 12112⨯>-⨯,()2ln 23123⨯>-⨯, ……, ()()2ln 111n n n n +>-+. 所以()()222111ln 1231212231n n n n n ⎡⎤⎡⎤⨯⨯⨯⋅⋅⋅⨯⨯+>-++⋅⋅⋅+⎢⎥⎣⎦⨯⨯+⎣⎦ 12121n n n ⎛⎫=-->- ⎪+⎝⎭………………………………12分 所以()22221231n n n e -⨯⨯⨯⋅⋅⋅⨯⨯+> 所以()()()221!1n n n e n -*+>+⋅∈⎡⎤⎣⎦N .………………………………13分。
2020年淄博市高三第二次模拟英语试题(含答案)
按秘密级事项管理★启用前高三第二次线上检测试题英语注意事项:1. 答卷前，考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上。
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第一部分阅读(共两节，满分50 分)第一节（共15 小题；每小题2.5 分，满分37.5 分）阅读下列短文，从每题所给的A、B、C、D 四个选项中选出最佳选项。
ASome of Our New ProgramsSTEM Inventions with LittleBitsIn this invention workshop, students enhance their skills with a great new system of discovery called LittleBits. It’s a platform of easy-to-use electronic building blocks that empower you to invent anything, from your own remote controlled car, to a smart home device. Students will begin with several inventions designed to let them figure out how the components go together, and then they will design and create their own inventions. Ages 7—12. Introduction to Computer AnimationIn this new program, you will have fun designing and creating your own videos. Students will learn the basic skills needed to create and animate. Whether you are making a LEGO brick film, animating in claymation（黏土动画）or capturing a flower bloom, you can bring anything to life with computer animation. Ages 7—12.Computer Programming with OzobotIn this exciting new program, robotics and coding will become elementary! Have fun expanding your horizons with the help of Ozobot—the tiny smart robot. There is no end to the possibilities, as you create a different landscape of adventures, games and coding with Ozobot. Students will use markers, tablets and laptops for coding. Ages 7—12.Super Science STEM ChallengesIn this engineering camp, you will have fun integrating Science, Technology, Engineering, and Mathematics by building and designing a wide range of gadgets(小装置), inventive machines, towers and more. Projects include: the Great Tower Challenge, the Standing Cup Pyramid Challenge, Egg Drop Challenge and a host of other fun contests designed to bring out the engineer in you! Ages 7—12.1.What do students acquire with LittleBits?A.The chances to have fun.B.The skills in inventing.C.The power to think.D.The permit for designing.2.What can we know about Ozobot?A.It is of similar size to humans.B.It functions as a computer.C.It can assist children to code.D.It can use markers, tablets and laptops.3.Which program is suitable if a kid is competitive?A.STEM Inventions with LittleBits.B.Introduction to Computer Animation.puter Programming with Ozobot.D.Super Science STEM Challenges.BI have come to southern Florida to see how licensed local snake hunters are helping the government cope with the recent explosion of invasive Burmese pythons (缅甸蟒蛇) that is destroying the region’s wildlife by eating almost everything—from squirrels to rabbits to foxes—in their path.Thirty years ago, there were no Burmese pythons in Florida. Now most experts agree there ma y be as many as 100,000 to 200,000. And they’re reproducing at an alarming rate. The government has to pay to catch and kill the powerful snakes, which can grow to be 20 feet long, as thick as a telephone pole, and weigh over 200 pounds.I’m with Tom Rahil l, a python hunter, who has caught over 500 of the snakes over the last decade and become known as “the snake whisperer” for his success. As we walk along theriver bank, I watch Rahill occasionally push a stick into the thick grass. As he looks for more signs, he tells me his stories and about special living habits of snakes.Suddenly Rahill shouts, “SNAKE! There, slowly crossing the limestone road, is a Burmese python.” He rushes to th e snake. It looks like a five-to-six-footer. Its thick, full belly indicates it must have killed and eaten recently.Expertly, Rahill moves around the snake as it strikes out at him. He then grabs it with one hand firmly behind its head. I grab its tail firmly as the snake tries hard to wrestle itself away from me. Then, just as Rahill predicted, it poops (排便) all over me.My pants are covered with smelly Burmese python poop. But I don’t care. We’ve finally bagged our python. Rahill and I high-five each other. He asks me if I want to keep hunting. I quickly tell him, “Let’s go!” As Rahill puts it, there are a lot more pythons out there.4.Why does the government pay to catch and kill Burmese pythons?A.Because few people dare to catch Burmese pythons.B.Because Burmese pythons break the region’s ecological balance.C.Because Burmese pythons are difficult to catch.D.Because Burmese pythons are dangerous to people.5.What do we know about Tom Rahill?A.He is a licensed python hunter.B.He is good at telling stories.C.He knows how to speak to snakes.D.He caught 500 pythons last year.6.How does the author feel about hunting pythons with Rahill?A. Guilty.B. Disappointed.C. Funny.D. Excited.7.What does the author mainly tell us in this text?A.The dangerous situation of the wildlife in southern Florida.B.The endangered Burmese python in southern Florida.C.An experience of hunting the ecology-threatening Burmese pythons.D.An experienced python hunter —Tom Rahill.CYou’ve probably heard that brick-and-mortar retail (实体零售) is in trouble. Even industry giants are closing hundreds of stores. Given retail’s gradual change to mobile ande-commerce (电子商务), you may be wondering, “What will retail look like in the future?” Nobody knows. But here are a few things you can expect to see based on current technology.Ultrafast delivery is coming. Today, the normal practice is two-day delivery. But if you’ve been paying attention, you know that’s changing. In fact, a surprisingly high 25% of consumers said that they would abandon their orders if one-day delivery wasn’t available. Of course, that’s just the beginning. Two-hour delivery is coming in the foreseeable future, and Amazon has already been trying 30-minute delivery.Your kitchen will resupply itself. You won’t have to worry about running out of essentials like coffee, pet food or snacks because your containers will sense stock ( 库存) levels and replace those items without you having to lift a finger. No more waking up to find your coffee store is empty or last-minute trips to the grocery store because you forgot to buy pet food.Know exactly what’s in stock and where. Have you ever gone to a store hoping to buy something, only to learn that they were out of stock? A new feature from Google Home allows people to ask Google Assistants to find in-stock products at the closest store. For example: “Google, where can I find the Nintendo Switch console?” An assistant will tell you how many stores have it right then and how close they are. Of course, it isn’t currently a vailable for all stores in all locations, but you can already see a future when it has become standard.Convenience, experience, and options—retail will take on a new look.8.How does the author develop the passage?A.By asking and answering.B.By clarifying and describing.C.By analyzing and commenting.D.By comparing and concluding.9.What can we know from paragraph 2?A.Consumers can’t get their orders in one day now.B.It is possible to deliver goods within two hours in the future.C.The delivery will be in two days in the future.D.Superfast delivery has widely been used now.10.According to the passage, what will happen in the future?A.Retail will disappear gradually.B.Industrial giants will rule the whole retail trade.C.Shopping will be more convenient and effective.D.People will ask Google Assistants to purchase goods.11.What’s the best title of the passage?A.What will retail be like in the future?B.How will new technology change the world?C.How will we run the retail trade in the future?D.What benefits will high-tech bring in the future?DScientists have discovered a new material that can hold the key to unlocking the potential of hydrogen-powered(氢动力) vehicles.As the world looks towards a gradual move away from fossil-fuel-powered cars and trucks, greener alternative technologies are being explored, such as electric-battery-powered vehicles. Another “green” technology with great potential is hydrogen power. However, the major obstacles have been the size, complexity, and expense of the fuel systems—until now.An international team of researchers, led by Professor David Antonelli of Lancaster University, has discovered a new material that offers a solution. The new material would be used to make molecular sieves(分子过滤器) within fuel tanks—which can store the hydrogen and work alongside fuel cells in a hydrogen-powered “system”. It makes the design of tanks far smaller, cheaper, more convenient and energy-denser than existing hydrogen fuel technologies, and significantly outperform battery-powered vehicles.The cost of manufacturing this new material is so low, and the energy density it can store is so much higher, that the hydrogen fuel cell systems cost five times less than ordinary batteries as well as providing a much longer range—potentially enabling journeys up to around four or five times longer between fill-ups.The new material makes the cooling system unnecessary. This is crucial because it means cooling equipment does not need to be used in vehicles, resulting in systems with the potential to be far more efficient than existing designs.Although vehicles, including cars and heavy goods vehicles, are the most obvious application, this material can also be used in portable devices such as drones or within mobile chargers so people could go on week-long camping trips without having to recharge their devices. It could also be used to run a house or a remote neighborhood off a fuel cell.12.What can we infer from paragraph 2?A.Fossil fuel will soon run out.B.It is impossible to conserve fossil fuel.C.Electric cars will replace gasoline cars.D.It is not economical to use hydrogen power now.13.Which of the following best explains the underlined word “outperform” in paragraph 3?A. Lose control of.B. Take the place of.C. Be less successful than.D. Perform better than.14.What do we know about the new material?A.It’s too complex to make.B.It simplifies the cooling system.C.It’s cheaper and more efficient.D.It can be used only for vehicles.15.In which section of the Internet can you probably find this text?A. Education.B. Science.C. Life.D. Biology.第二节(共5 小题；每小题2.5 分，满分12.5 分)阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
2024年淄博市高三一模英语高考模拟试卷试题(含答案详解)
淄博市2023-2024学年度高三模拟考试英语2024年3月第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳答案。
AGood evening everyone!I hope to pick your brain on potential advertising strategies and gaining new customers for my boyfriend’s car repair shop.He has been in business for3years and is fairly successful,but we are trying to increase the number of chargeable hours.While he was doing repair work,I took over all the administrative duties.The first thing on my to-do list was to get him on social media.I was floored that he had no social media presence,which is not surprising considering he is old school.Now,he has a business Facebook page and an Instagram account,although it may not be worth much yet.We are working on a weekly“feature”for both platforms in order to create some interest.He doesn’t want to do coupons(优惠券)or discounts or anything like that,and I understand why.His labor rate is already significantly lower than anyone else in the area,and his overall costs are lower as well.This is where I am a bit lost——how can we effectively attract more customers without a hook?My guess would be focusing on the value,but I’m not sure how well that will work out.We are considering sending postcards as well since he already cooperates with a few local shops who send their large jobs to him and such.However,I am unsure about Facebook marketing, but definitely open.1．What was scheduled first to promote business?A．Working out a weekly feature.B．Increasing chargeable hours. C．Establishing his presence online.D．Visiting his old school.2．How might they attract new clients?A．By raising labor rates.B．By offering discounts and coupons.C．By cutting overall costs.D．By highlighting the value of services. 3．What is the purpose of the text?A．To offer information.B．To seek advice.C．To show advantages.D．To find cooperation.BThere was no way to escape when they spotted a polar bear.Verena Mohaupt and a handful of colleagues were trapped on a floating sea ice while the bear gazed at them,smelling the air,a dangerous sign.“That’s when everything kicks in,”Mohaupt says,“and you focus on what’s important.”As a colleague fired into the sky as a warning shot,Mohaupt radioed their research ship a few kilometres away,whose helicopter luckily arrived quickly and Mohaupt didn’t have to use the gun that was hanging over her shoulder.Keeping a lookout for bears was a regular duty for Mohaupt,the logistics coordinator(后勤协调员)for a year-long mission known as the MOSAiC——the largest Arctic research exploration in history.The project,consisting of roughly300scientists,led by scientist MarkusRex,has collected massive measurements that will help better forecast how warming will transform the globe in the coming decades.For months,the exploration operated in constant darkness while polar bears wandered nearby,storms rocked the ship and the ice shifted and cracked.Then,when the Sun returned,the ice began to melt,creating a life-threatening risk and a nightmare for researchers who needed to keep their instruments from sinking.Tasked with the security of the mission,Mohaupt designed an extensive training course for the participants in which they learnt how to avoid the danger,like storm-rocking and ice-cracking. They jumped into a Norwegian channel in their survival suits and climbed out of the freezing waters using only their ice picks.They learnt how to escape from a crashed helicopter.And they discussed the psychological effects of being far from home.Mohaupt brought knitting equipment, yoga mats and a violin for their men tal health——although having been prepared for the isolation.Mohaupt didn’t expect a career in polar regions,but says she has always been drawn to the north.“She was there to make sure that we were protected,”says Markus Rex,“Mohaupt iscertainly the champion in the field.”4．Why does the author mention a polar bear in the beginning?A．To show the threat of bears.B．To tell an interesting story.C．To introduce Mohaupt’s job.D．To describe the polar scenery.5．What can we know from paragraph3?A．The working conditions were tough.B．Mohaupt helped to collect massive data. C．The exploration went on in total darkness.D．Mohaupt’s duty was to protect polar bears. 6．Which of the following best describes Mohaupt?A．Ambitious and brave.B．Passionate and dependent. C．Considerate and modest.D．Professional and responsible.7．What is a suitable title for the text?A．A Potential Danger in the Exploration.B．A Guardian Angel of Polar Researchers. C．A Great Scientific Exploration in History.D．A Great Female Scientist in Polar Research.CChances are you’ve heard the phrase“like a moth to a flame”——and probably seen it in action at a nighttime fire or barbecue,too.It turns out,however,this age-old saying may not be quite right.Rather than being attracted to light,moths’tendency to fly toward brightness is a behavioral response to help them determine which way is up,suggests a new study published in the journal Nature Communications.To avoid falling down to the ground,insects need to know which way is up,says study coauthor Yash Sondhi,a National Geographic Explorer.Without systems to maintain spatial(空间的)orientation,the brightness of the sky,even at night,has always been a strong indicator of “up”——until artificial lights came along.If they mess that up,they start plummeting.Sondhi and a team of researchers set up experiments to investigate how different lights influence flight behavior.First,the researchers suspended a light bulb from a rope between two trees——resembling a typical downward-pointing light——and in a separate test,they turned the light upward by mounting it on a tripod(三脚架).In both cases,insects leaned their winged backs to the bulb.But when the light was pointed up,the insects often bumped to the ground.What if the light is spread over a wide area?The researchers stretched a large white sheetacross the tree and projected a UV light on it.If the insects were truly“attracted”to the light,they should fly up toward it.Instead,the insects cruised(巡航)straight through this illuminated corridor,flying how they would during the day.The team then placed the sheet on the ground and shined the light on it,which is when something truly odd happened:All these moths flying over it turned upside down and crashed out of the sky.Directionality of light is a huge factor in the pattern we have seen,not just brightness or color.“Artificial lights may cause a mismatch between the insect’s sense of which way is up and true direction of gravity,which spells trouble for insects population.”says Sondhi.8．What can be inferred about“like a moth to a flame”in the new study?A．A moth is generally attracted by a flame.B．Artificial lights are valuable for a moth. C．Brightness indicates up for a moth.D．A moth has a sense of direction. 9．What does the underlined word“plummeting”in paragraph2mean?A．Crashing.B．Speeding.C．Freezing.D．Suspending. 10．What lights influence insects most in the experiments?A．UV lights on the tree.B．Upward-pointing lights. C．Downward-pointing lights.D．Lights of different colors.11．What is Sondhi’s attitude toward artificial lights?A．Concerned.B．Dismissive.C．Doubtful.D．Neutral.DWould you rather watch a new movie,or an old favorite?Would you rather try a dish you’ve never had at a restaurant,or stick with something you know you’ll like?Researchers studying the “mere exposure effect”have found that we often prefer the familiar over the novel.People didn’t need to experience a reward or positive outcome while around the object—simply being exposed to the object would be enough to make people like it.To test this, social psychologist Robert Zajonc had participants read words in a foreign language out loud and varied how often participants read each word(up to25repetitions).Next,after reading the words, participants were asked to guess at the meaning of each word by filling out a rating scale (indicating how positive or negative they thought the meaning of the word was).He found that participants liked words that they had said more often,while words thatparticipants hadn’t read at all were rated more negatively,and words that had been read25times were rated highest.Just the me re exposure to the word was enough to make participant s like it more.One place where the me re exposure effect occurs is in advertising.It explains why seeing the same advertisement multiple times could be more convincing than just seeing it once.Of course, there’s a caution here:the me re exposure effect doesn’t happen for things we initially dislike. Researchers have found that our liking for a variety of things(including pictures,sounds,foods, and smells)can be increased with repeated exposure,suggesting that the mere exposure effect isn’t limited to just one of our senses.Additionally,researchers have found that the me re exposure effect occurs in studies with human research participants as well as in studies with non-human animals.Another key finding from this analysis was that participants eventually started to like object s less after many repeated exposures.In other words,a smaller number of repeated exposures will make you like something more——but,if the repeated exposures continue,you could eventually get tired of it.12．What is the key factor in Robert Zajonc’s test?A．Frequency.B．Preference.C．Originality.D．Achievement. 13．Which of the following is an example of mere-exposure effect?A．We favor an advertisement at the first sight.B．A student joined in the club because of love.C．We are more convinced of what we met before.D．A student read as many English words as possible.14．What can we learn about“mere exposure effect”according to paragraph4?A．It is the result of advertising.B．It has nothing to do with animals.C．It is true of what we dislike at first.D．It can be applied to multiple senses. 15．What is the text mainly about?A．More love because of more exposures.B．The study on mere exposure effect. C．Better results from the earlier exposures.D．The application of mere exposure effect.第二节(共5小题;每小题2.5分,满分12.5分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
【Word版解析】【2013淄博二模】山东省淄博市2013届高三第二次模拟考试 数学文
高三复习阶段性检测试题文 科 数 学本试卷分第I 卷和第II 卷两部分，共5页．满分150分．考试用时120分钟，考试结束后，将试卷和答题卡一并上交． 注意事项：1．答题前，考生务必用0．5毫米黑色签字笔将自己的姓名、座号、考生号、县区和科类填写在答题卡和试卷规定的位置上．2．第1卷每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，答案不能答在试卷上．3．第II 卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置，不能写在试卷上；如需改动，先划掉原来的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带．不按以上要求作答的答案无效．4．填空题请直接填写答案，解答题应写出文字说明、证明过程或演算步骤． 参考公式： 锥体的体积公式：13V Sh =，其中S 是锥体的底面积，h 是锥体的高.如果事件A,B 互斥，那么()()()P A B P A P B +=+；如果事件A,B 独立，那么()()()P AB P A P B =⋅.第I 卷（选择题 共60分）一、选择题：本大题共12小题，每小题5分，共60分，在每小题给出的四个选项中，只有一项是符合题目要求的.1.集合{}{}1,0,1,,xA B y y e x A =-==∈，则A B ⋂=A.{}0B.{}1C.{}0,1D.{}1,0,1-【答案】B{}1,{1,,}x B y y e x A e e==∈=，所以{1}A B ⋂=，选B.2.复数11ii+-（i 是虚数单位）的共轭复数的虚部为 A.1-B.0C.1D.2【答案】A21(1)21(1)(1)2i i i i i i i ++===--+，所以11ii+-的共轭复数是i -，所以共轭复数的虚部为1-，选A.3.已知等差数列{}n a 的前n 项和为n S ，满足1313113a S a ===，则 A.14- B.13-C.12-D.11-【答案】D在等差数列中，1131313()132a a S +==，所以1132a a +=，即113221311a a =-=-=-，选D. 4.一个四棱锥的底面为正方形，其三视图如图所示，则这个四棱锥的体积是 A.1B.2C.3D.4【答案】B由题设及图知，此几何体为一个四棱锥，其底面为一个对角线长为2的正方形，故其底面积为141122⨯⨯⨯=。
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高三复习阶段性检测试题英语本试卷分第I卷和第II卷两部分，共15页。
满分150分。
考试用时120分钟。
考试结束后，将本席卷和答题卡一并交回。
注意事项：1、答题前，考生务必用0.5毫米黑色签字笔将自己的姓名、座号、准考证号、县区和科类填写在答题卡和试卷规定的位置上。
2、第I卷每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑；如需改动，用橡皮擦干净后，再选涂其他答案标号。
3、I卷必须用0.5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域内相应的位置；如需改动，先划掉原来的答案，然后再写上新的答案；不能使用涂改液、胶带纸、修正带。
不按以上要求作答的答案无效。
第I卷（共105分）第一部分：听力（共两节，满分30分）该部分分为第一、第二两节。
注意：回答听力部分时，请先将答案标在试卷上。
听力部分结束前，你将有两分钟的时间将你的答案转涂到客观题答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is the shirt?A.￡19.15B.￡9.15C.￡9.18答案是B。
1.What does the man like doing on holidays?A.Swimming.B.Staying at home.C.Relaxing on the beach.2.How will the speakers deal with the problem of their children?A.They will take to the movies.B.They will leave them at home.C.They will leave them at their grandma’s house.3.Where is the bar?A.On the right of the lift.B.Next to the restaurant.C.Beside the performance stage.4.What colour was the woman’s bedroom before?A.PinkB.Blue.C.Green.5.What are the speakers mainly talking about?A.A lab.B.A professor.C. An experiment.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段话。
每段话后有几个小题，从题中所给出的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话读两遍。
听下面一段对话，回答第6和第7两个小题。
6.Where does this conversation take place?A.At an airport.B.Aat a hotel.C.Aag a railwany station.7.How many bags does the man have in total?A.One.B.Two.C.Three.8.What are the speakers mainly talking about?A.How to use a pay phone.B.When to use a pay phone.C.Where to find a pay phone.9.What do we know about the woman?A.She works here as a teacher.B.She wants to make a local call.C.She has no money to make a call.听下面一段对话，回答第10至第12三个小题。
10．Where did the man go last night?A.To a theatre.B.To a concert.C.To a restaurant.11.What did the two girls in front of the man do ?A.They argude.B.They talked lound.C.They callde in the manager.12.What did the man do in the end?A.He left halfway.B.He quieted down.C.He watchde the movie till the end.听下面一段对话，回答第13至第16四个小题。
13.How much does the special travel card for six months cost?A. ￡6.B. ￡8.C. ￡12.14.Where did the man have his photos taken?A.In a libray.B.In a photographer’sC.In a post office.15.What does the woman need to show to get a special travel card?A.Her passport.B.Her driving license.C.A letter from her college.16.What will the woman do next?A.Go to the tourist office.B.Visit the travel agency.C.Ask her teacher for a letter.听下面一段对话，回答第17至第20四个小题。
17．How much will the speakers give the director in total?A.＄200.B.＄500.C. ＄1000.18.What does the man guggest doing?A.Decorating the stage.B.Buying some cosumes.C.Getting a tape recorder.19.What are the speakers talking about?A.A performance.B.A meeting.C.A party.20.What is the relationship between the speakers?A.Colleagues.B.Classmates.C.Neighbours.第二部分英语知识运用（共两节，满分35分）第一节语法和词汇知识（共15小题；每小题1分，满分15分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
21．—I’m afraid I couldn’t go to your birthday party.—Oh,_______!you’re my best fridne and I do wish you woule be there!A.go aheadB.of courseC.you needn’tD.what a pity22.Just one more block down this way,and you’ll find the post office_______the road.A.overB.acrossC.onD.through23.We do have_______Bob here,but he is not that Bob,_______chairman of our company.A.th;aB.the;theC.the;不填D. a;不填24．A team of experts coming to China soon________whether the H7N9 virus can be spread between people.A. are examiningB.examinedC.will examineD. examines25.One_______take it as a sign of weakness to ask for help from others,because no one is perfect.A.mustn’tB.couldn’tC.wouldn’tD.needn’t26.Margaret Thatcher,_______people call the “Iron Lady”,always said what she meant and meantwhat she said and did what she said she would do.A.whoB.whichC.thatD.whose27.________ a new library is to be built has not been decided yet,because the project will cost a lot of money.A.ThatB.WhetherC.WhereD.How28.Three people were killed and at least 130 were injured,including several children,_______bombs exploded near the finish line of Boston Marathon last week.A.whereB.whenC.becauseD.before29.Together with the whole team,Jeremy Lin_______ready to experience the NBA paly off game this weekend.A.isB.wasC.areD.were30.—We’d better go downstairs right now for lunch.—________They serve food 24 hours a day.A.Hurry up!B.NO way!C.Take your time.D.It doesn’t matter.31.The key________the problem is to meet the demand of the passengers and help them go home as soon as possible.A.to solveB.to solvingC.solvingD.solves32.Although the design is not perfect,the quality of this kind of engine________.A.has been improvedB.would be improvedC.was improvedD.is improved33. Thest homeowners fully understand that no other dhoices are_______ to them that could help them save their homes.A.capableB.availableC.suitableD.possible34.There were a lot of cars parking along the street and the fire trucks couldn’t pass through,_____it more difficult for the firemen to conrtol the fire.A.makeB.madeC.makingD.to make35.—I do want to see the movie.—Okay,if the rain________now,we________ to the theatre.A.stops;goB.could stop;willgoC.stopped; would goD.would stop;would to第二节完形填空（共20小题；每小题1分，满分20分）阅读下面短文，从短文后各题所给的四个选项（A、B、C、D）中，选出最佳选项。