2024届云南省部分名校高考备考实用性联考卷(一)英语试题
2024年新高考一卷英语试题
2024年新高考一卷英语试题一、The new policy will have a significant _______ on the country's economic development.A. effectB. affectC. effortD. affectation（答案：A）二、She _______ her homework before going to bed every day.A. finishesB. is finishingC. has finishedD. had finished（答案：A）三、The book is written in such a way that it is easy for children to _______.A. understandB. be understoodC. understandingD. understood（答案：A）四、He _______ his hometown for twenty years. He really misses it!A. has leftB. has been away fromC. leftD. is away from（答案：B）五、_______ is known to all, knowledge is power.A. ThatB. AsC. ItD. What（答案：B）六、The teacher asked the students _______ carefully in class.A. listenB. to listenC. listeningD. listened（答案：B）七、He _______ a lot of money on books every year.A. spendsB. takesC. costsD. pays（答案：A）八、_______ the help of my teacher, I made great progress in English.A. WithB. UnderC. InD. By（答案：B）九、She _______ a beautiful dress when she attended the party last night.A. woreB. put onC. dressedD. was wearing（答案：A）十、The doctor advised him _______ more vegetables and fruit.A. eatB. to eatC. eatingD. eats（答案：B）。
2024届云南省部分名校高三上学期备考实用性联考卷(一)物理试题
2024届云南省部分名校高三上学期备考实用性联考卷（一）物理试题一、单选题 (共6题)第(1)题如图所示，和是竖直放置的两根平行光滑金属导轨，导轨足够长，间接定值电阻，金属杆保持与导轨垂直且接触良好。
杆由静止开始下落并计时，杆两端的电压、杆所受安培力的大小随时间变化的图像，以及通过杆的电流、杆加速度的大小随杆的速率变化的图像，合理的是（ ）A．B．C．D．第(2)题静电透镜被广泛应用于电子器件中，如图所示是阴极射线示波管的聚焦电场，其中虚线为等势线，任意两条相邻等势线间电势差相等，z轴为该电场的中心轴线。
一电子从其左侧进入聚焦电场，实线为电子运动的轨迹，P、Q、R为其轨迹上的三点，电子仅在电场力作用下从P点运动到R点，在此过程中，下列说法正确的是（）A．P点的电势高于Q点的电势B．电子在P点的加速度小于在R点的加速度C．从P至R的运动过程中，电子的电势能减小D．从P至R的运动过程中，电子的动能先减小后增大第(3)题如图所示，质量为m的小球A从地面上斜抛，抛出时的速度大小为25m/s，方向与水平方向夹角为53°角，在A抛出的同时有一质量为3m的黏性小球B从某高处自由下落，当A上升到最高点时恰能击中竖直下落中的黏性小球B，A、B两球碰撞时间极短，碰后A、B两球粘在一起落回地面，不计空气阻力，，g取。
以下说法正确的是（ ）A．小球B下落时离地面的高度是20mB．小球A上升至最高处时离地面40mC．小球A从抛出到落回地面的时间为3sD．小球A从抛出到落回地面的水平距离为60m第(4)题如图所示，两个相同的半球A和B放置在一直角墙角处，A放在水平地面上，B放在半球A上并与竖直墙壁接触，球面与竖直墙壁均光滑，两半球处于静止状态。
半球A的球心离竖直墙面的距离为球半径的1.2倍，最大静摩擦力等于滑动摩擦力。
则半球A 与水平地面间的动摩擦因数最小值为（ ）A．B．C．D．第(5)题如图，轻弹簧的下端固定在水平桌面上，上端放有物块P，系统处于静止状态，现用一竖直向上的力F作用在P上，使其向上做匀加速直线运动，以x表示P离开静止位置的位移，在弹簧恢复原长前，下列表示F和x之间关系的图像可能正确的是（ ）A．B．C．D．第(6)题高空坠物极易对行人造成伤害．若一个50 g的鸡蛋从一居民楼的25层坠下，与地面的撞击时间约为2 ms，则该鸡蛋对地面产生的冲击力约为（）A．10 N B．102 N C．103 N D．104 N二、多选题 (共4题)第(1)题如图所示，正方形单匝铝质线圈和放在光滑绝缘水平桌面上，分别在外力作用下以速度向右匀速进入同一匀强磁场中。
2024届云南省部分名校高三上学期备考实用性联考卷(一)物理核心考点试题
2024届云南省部分名校高三上学期备考实用性联考卷（一）物理核心考点试题一、单项选择题：本题共8小题，每小题3分，共24分，在每小题给出的答案中，只有一个符合题目要求。
(共8题)第(1)题光的偏振现象说明光是横波.下列现象中不能反映光的偏振特性的是( )A．一束自然光相继通过两个偏振片,以光束为轴旋转其中一个偏振片,透射光的强度发生变化B．一束自然光入射到两种介质的分界面上,当反射光线与折射光线之间的夹角恰好是90°时,反射光是偏振光C．日落时分,拍摄水面下的景物,在照相机镜头前装上偏振滤光片可以使景像更清D．通过手指间的缝隙观察日光灯,可以看到彩色条纹第(2)题地球表面重力加速度为，地球的第一宇宙速度为，万有引力恒量为，下式关于地球密度的估算式正确的是（ ）A．B．C．D．第(3)题某质量为2kg的遥控汽车（可视为质点）沿如图所示的路径进行性能测试，半径为3m的半圆弧BC与长8m的直线路径AB相切于B点，与半径为4m的半圆弧CD相切于C点。
若小车从A点由静止开始，以1m/s2的加速度驶入路径，到达B点后保持速率不变依次经过BC和CD，则（ ）A．小车到达B点时的速度大小为2m/s B．小车从A到D所需时间为C．小车在BC段的向心加速度大小为D．小车在CD段所受向心力大小为4N第(4)题如图所示是研究光电效应的实验原理图，某实验小组用光强相同（即单位时间照射到单位面积的光的能量相等）的红光和紫光分别照射阴极K，移动滑片P分别得到红光和紫光照射时，光电管的光电流I与电势差的关系图像可能正确的是（ ）A．B．C．D．第(5)题太阳系八大行星中，金星离地球最近，且到太阳的距离小于地球到太阳的距离。
认为金星与地球均绕太阳做匀速圆周运动。
下列说法正确的是（ ）A．金星的线速度小于地球的线速度B．金星的周期小于地球的周期C．金星的角速度小于地球的角速度D．金星的向心加速度小于地球的向心加速度第(6)题如图所示为双缝干涉实验原理图，单缝S0、双缝中点O、屏上的点位于双缝S1和S2的中垂线上，当双缝距光屏距离为时，屏上P处为中央亮纹一侧的第3条亮纹，现将光屏靠近双缝，观察到P处依旧为亮纹，则光屏移动的最小距离为（ ）A．B．C．D．第(7)题如图所示，“天宫二号”在距离地面393 km的近圆轨道运行．已知万有引力常量G＝6.67×10－11 N·m2/kg2，地球质量M＝6.0×1024 kg，地球半径R＝6.4×103 km.由以上数据可估算( )A．“天宫二号”的质量B．“天宫二号”的运行速度C．“天宫二号”受到的向心力D．地球对“天宫二号”的引力第(8)题某同学对着墙壁练习打网球，假定球在墙面上以25 m/s的速度沿水平方向反弹，落地点到墙面的距离在10 m至15 m之间，忽略空气阻力，取g＝10 m/s2，球在墙面上反弹点的高度范围是 ( )A．0.8 m至1.8 m B．0.8 m至1.6 mC．1.0 m至1.6 m D．1.0 m至1.8 m二、多项选择题：本题共4小题，每小题4分，共16分。
2024届云南省三校联考备考高三上学期实用性联考(五)英语试卷及答案
2024届云南三校高芳备考实用性联考卷（五）英语注意事项：1. 答题前，考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚。
2. 每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
在试题卷上作答无效。
3. 考试结束后，请将本试卷和答题卡一并交回。
满分150分，考试用时120分钟。
第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What do the speakers mainly talk about?A. Flowers.B. Birthday presents.C. Clothes.2. How many cans of Coke has Rowan drunk?A. Three.B. Nine.C. Twelve.3. Where does the conversation take place?A. At home.B. At a bus station.C. In a school.4. What is the probable relationship between the speakers?A. Workmates.B. Boss and employee.C. Interviewer and interviewee.5. Who helped the woman practice speaking French?A. The man.B. Her sister.C. Her neighbor.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。
2024届“3+3+3”高考备考诊断性联考卷(三)英语-答案
2024届“3+3+3”高考备考诊断性联考卷（三）英语参考答案第一部分阅读（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）1~5 BDACC 6~10 DBDCA 11~15 BABCD第二节（共5小题；每小题2.5分，满分12.5分）16~20GDFAB第二部分语言运用（共两节，满分30分）第一节（共15小题；每小题1分，满分15分）21~25 BADCD 26~30 BDCAB 31~35 DCADB第二节（共10小题；每小题1.5分，满分15分）36．Originating 37．has gone 38．to 39．but 40．which42．to use 43．creatively 44．an 45．traditional 41．cleanness语法填空评分原则1．有拼写或大小写错误的作答不给分。
2．除所列答案外，若试评过程中发现其他可接受答案，经评卷专家组讨论确认后也可给分。
第三部分写作（共两节，满分40分）第一节（满分15分）【参考范文】Dear Carl，How delighted to know that you’re interested in our performance of the play Thunderstorm at the Art Festival to be held next month in our school! You’re welcome to join us!As you know，we haven’t decided on the actors．You can choose a role you would like to playand tell me about it．As for the rehearsal，we’ll do it in the rehearsal hall from 7：00 — 9：30 everyFriday evening．Is it convenient for you?Very glad to have you with us in the performance and anticipating your early reply．Yours sincerely，Li Hua英语参考答案·第1页（共9页）写作第一节评分原则一、评分原则1．本题总分为15分，按五个档次进行评分。
2024年云南省三校高考备考联考卷(一)数学试题及答案
２０２５届云南三校高考备考实用性联考卷(一)数㊀学注意事项:１ 答题前ꎬ考生务必用黑色碳素笔将自己的姓名㊁准考证号㊁考场号㊁座位号在答题卡上填写清楚.２ 每小题选出答案后ꎬ用２Ｂ铅笔把答题卡上对应题目的答案标号涂黑.如需改动ꎬ用橡皮擦干净后ꎬ再选涂其他答案标号.在试题卷上作答无效.３ 考试结束后ꎬ请将本试卷和答题卡一并交回.满分１５０分ꎬ考试用时１２０分钟.一㊁单项选择题(本大题共８小题ꎬ每小题５分ꎬ共４０分.在每小题给出的四个选项中ꎬ只有一项是符合题目要求的)１.已知集合Ａ＝{ｘｘ２－２ｘ－３>０}ꎬＢ＝{ｘ０<ｘ<４}ꎬ则(∁ＲＡ)ɘＢ＝Ａ.(３ꎬ４)Ｂ.(０ꎬ３]Ｃ.(－ɕꎬ３)ɣ(１ꎬ４)Ｄ.(－ɕꎬ－１)２.已知复数ｚ＝２ｉ１＋ｉꎬ则下列说法正确的是Ａ.ｚ＝１－ｉＢ.ｚ＝２Ｃ.ｚ－＝１＋ｉＤ.ｚ的虚部为ｉ㊀图１３.如图１ꎬαꎬβ是九个相同的正方形拼接而成的九宫格中的两个角ꎬ则ｔａｎ(α＋β)＝Ａ.－３Ｂ.３３Ｃ.３Ｄ.１４.假设ＡꎬＢ是两个事件ꎬ且Ｐ(Ａ)>０ꎬＰ(Ｂ)>０ꎬ则下列结论一定成立的是Ａ.Ｐ(ＡＢ)ɤＰ(ＢＡ)Ｂ.Ｐ(ＡＢ)＝Ｐ(Ａ)Ｐ(Ｂ)Ｃ.Ｐ(ＢＡ)＝Ｐ(ＡＢ)Ｄ.Ｐ(ＡＢ)＝Ｐ(Ｂ)Ｐ(ＢＡ)５.已知ａ＝ｌｏｇ５２ꎬｂ＝ｌｏｇ７３ꎬｃ＝１２ꎬ则下列判断正确的是Ａ.ｃ<ｂ<ａＢ.ｂ<ａ<ｃＣ.ａ<ｂ<ｃＤ.ａ<ｃ<ｂ６.在前ｎ项和为Ｓｎ的正项等比数列{ａｎ}中ꎬ设公比为ｑꎬ{ａｎ}满足ａ１ａ４＝８ꎬａ３＝ａ２＋２ꎬｂｎ＝ｌｏｇ２ａｎＳｎ＋１ꎬ则Ａ.ｑ＝１２Ｂ.Ｓｎ＝２ａｎ＋１Ｃ.ｂｎ＝ｎ－１２ｎＤ.数列{ｂｎ}的最大项为ｂ３７.在正方体ＡＢＣＤ－Ａ１Ｂ１Ｃ１Ｄ１中ꎬＭ是线段Ｃ１Ｄ１(不含端点)上的动点ꎬＮ为ＢＣ的中点ꎬ则Ａ.ＣＭʊ平面Ａ１ＢＤＢ.ＢＤʅＡＭＣ.ＭＮʊ平面Ａ１ＢＤＤ.平面Ａ１ＢＤʅ平面ＡＤ１Ｍ８.已知Ｆ为双曲线Ｃ:ｘ２ａ２－ｙ２ｂ２＝１(ａ>０ꎬｂ>０)的左焦点ꎬＡ是Ｃ的右顶点ꎬ点Ｐ在过点Ｆ且斜率为２－３的直线上ꎬøＯＡＰ＝２π３且线段ＯＰ的垂直平分线经过点Ａꎬ则Ｃ的离心率为Ａ.３－２Ｂ.３－１Ｃ.３Ｄ.６二㊁多项选择题(本大题共３小题ꎬ每小题６分ꎬ共１８分ꎬ在每小题给出的四个选项中ꎬ有多项是符合题目要求的.全部选对的得６分ꎬ部分选对的得部分分ꎬ有选错的得０分)９.已知函数ｆ(ｘ)＝ｘ３－３ｘ＋２ꎬ则Ａ.ｆ(ｘ)有两个极值点Ｂ.点(０ꎬ２)是曲线ｙ＝ｆ(ｘ)的对称中心Ｃ.ｆ(ｘ)有三个零点Ｄ.直线ｙ＝０是曲线ｙ＝ｆ(ｘ)的一条切线１０.设函数ｆ(ｘ)＝ｓｉｎ(ωｘ＋φ)＋ｃｏｓ(ωｘ＋φ)ω>０ꎬφɤπ２æèçöø÷的最小正周期为πꎬ且过点(０ꎬ２)ꎬ则Ａ.ｆ(ｘ)在０ꎬπ２æèçöø÷单调递增Ｂ.ｆ(ｘ)的一条对称轴为ｘ＝π２Ｃ.ｆ(ｘ)的周期为π２Ｄ.把函数ｆ(ｘ)的图象向左平移π６个长度单位得到函数ｇ(ｘ)的解析式为ｇ(ｘ)＝２ｃｏｓ２ｘ＋π３æèçöø÷１１.已知ａｎ＝２ｎ和ｂｎ＝３ｎ－１ꎬ数列{ａｎ}和{ｂｎ}的公共项由小到大组成数列{Ｃｎ}ꎬ则Ａ.Ｃ３＝３２Ｂ.{Ｃｎ}不是等比数列Ｃ.数列１ｂｎｂｎ＋１{}的前ｎ项和Ｔｎ＝１２－１３ｎ＋２Ｄ.数列ｂｎａｎ{}的前ｎ项和Ｓｎɪ[１ꎬ５)三㊁填空题(本大题共３小题ꎬ每小题５分ꎬ共１５分)１２.若函数ｆ(ｘ)＝(２ｘ＋ａ)ｌｎ３ｘ－１３ｘ＋１为偶函数ꎬ则ａ＝㊀㊀㊀㊀.１３.正四棱锥的顶点都在同一球面上ꎬ若该棱锥的高为２ꎬ底面边长为１ꎬ则该球的表面积为㊀㊀㊀㊀.１４.已知抛物线Ｃ:ｙ２＝４ｘꎬ焦点为Ｆꎬ不过点Ｆ的直线ｌ交抛物线Ｃ于ＡꎬＢ两点ꎬＤ为ＡＢ的中点ꎬＤ到抛物线Ｃ的准线的距离为ｄꎬøＡＦＢ＝１２０ʎꎬ则ＡＢｄ的最小值为㊀㊀㊀㊀㊀.四㊁解答题(共７７分ꎬ解答应写出文字说明ꎬ证明过程或演算步骤)１５.(本小题满分１３分)已知在әＡＢＣ中ꎬ三边ａꎬｂꎬｃ所对的角分别为ＡꎬＢꎬＣꎬａ(ｃｏｓＡ＋ｃｏｓＢｃｏｓＣ)＝３ｂｓｉｎＡｃｏｓＣ.(１)求Ｃꎻ(２)若ａ＋ｂ＝２ｃꎬәＡＢＣ外接圆的直径为４ꎬ求әＡＢＣ的面积.１６.(本小题满分１５分)如图２ꎬ在四棱锥Ｐ－ＡＢＣＤ中ꎬＰＤʅ底面ＡＢＣＤꎬＣＤʊＡＢꎬＡＤ＝ＤＣ＝ＣＢ＝２ꎬＡＢ＝４ꎬＤＰ＝３.(１)证明:ＢＤʅＰＡꎻ㊀图２(２)求平面ＡＢＤ与平面ＰＡＢ的夹角.１７.(本小题满分１５分)已知椭圆Ｃ１:ｘ２２ａ２＋ｙ２２ｂ２＝１(ａ>ｂ>０)左右焦点Ｆ１ꎬＦ２分别为椭圆Ｃ２:ｘ２ａ２＋ｙ２ｂ２＝１(ａ>ｂ>０)的左右顶点ꎬ过点Ｆ１且斜率不为零的直线与椭圆Ｃ１相交于ＡꎬＢ两点ꎬ交椭圆Ｃ２于点Ｍꎬ且әＡＢＦ２与әＢＦ１Ｆ２的周长之差为４－２２.(１)求椭圆Ｃ１与椭圆Ｃ２的方程ꎻ(２)若直线ＭＦ２与椭圆Ｃ１相交于ＤꎬＥ两点ꎬ记直线ＭＦ１的斜率为ｋ１ꎬ直线ＭＦ２的斜率为ｋ２ꎬ求证:ｋ１ｋ２为定值.１８.(本小题满分１７分)绿色已成为当今世界主题ꎬ绿色动力已成为时代的驱动力ꎬ绿色能源是未来新能源行业的主导.某汽车公司顺应时代潮流ꎬ最新研发了一款新能源汽车ꎬ并在出厂前对该批次汽车随机抽取１００辆进行了单次最大续航里程(理论上是指新能源汽车所装载的燃料或电池所能够提供给车行驶的最远里程)的测试.现对测试数据进行分析ꎬ得到如图３所示的频率分布直方图.㊀图３(１)估计这１００辆汽车的单次最大续航里程的平均值ｘ－(同一组中的数据用该组区间的中点值代表)ꎻ(２)若单次最大续航里程在３３０ｋｍ到４３０ｋｍ的汽车为 Ａ类汽车 ꎬ以抽样检测的频率作为实际情况的概率ꎬ从该汽车公司最新研发的新能源汽车中随机抽取１０辆ꎬ设这１０辆汽车中为 Ａ类汽车 的数量为Ｙꎬ求Ｅ(Ｙ).(３)某汽车销售公司为推广此款新能源汽车ꎬ现面向意向客户推出 玩游戏ꎬ送大奖 活动ꎬ客户可根据抛掷硬币的结果ꎬ操控微型遥控车在方格图上行进ꎬ若遥控车最终停在 胜利大本营 ꎬ则可获得购车优惠券.已知硬币出现正㊁反面的概率都是１２ꎬ方格图上标有第０格㊁第１格㊁第２格㊁ ㊁第３０格.遥控车开始在第０格ꎬ客户每掷一次硬币ꎬ遥控车向前移动一次ꎬ若掷出正面ꎬ遥控车向前移动一格(从ｋ到ｋ＋１)ꎬ若掷出反面ꎬ遥控车向前移动两格(从ｋ到ｋ＋２)ꎬ直到遥控车移到第２９格(胜利大本营)或第３０格(失败大本营)时ꎬ游戏结束.已知遥控车在第０格的概率为Ｐ０＝１ꎬ设遥控车移到第ｎ格的概率为Ｐｎ(ｎ＝１ꎬ２ꎬ ꎬ３０)ꎬ试证明:数列{Ｐｎ－Ｐｎ－１}(ｎ＝１ꎬ２ꎬ ꎬ２９)是等比数列ꎬ并解释此方案能否成功吸引顾客购买该款新能源汽车?１９.(本小题满分１７分)(１)证明:当０<ｘ<１时ꎬｘ－ｘ２<ｓｉｎｘ<ｘꎻ(２)已知函数ｆ(ｘ)＝ｃｏｓａｘ－ｌｎ(１－ｘ２)ꎬ若ｘ＝０是ｆ(ｘ)的极小值点ꎬ求ａ的取值范围.数学参考答案·第1页（共11页）2025届云南三校高考备考实用性联考卷（一）数学参考答案一、单项选择题（本大题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一项符合题目要求）题号 1 2 3 4 5 6 7 8 答案 B B D A D C D C 【解析】1．2230x x -->，(3)(1)0x x -+>，得x >3或x <−1，∴{|31}A x x x =><-或，{|04}B x x =<<， ∴{|13}A x x =-R ≤≤ ，∴(03]A B =R ， ，故选B.3．由题意及图得，1tan 3α=，1tan 2β=，∴11tan tan 23tan()11tan tan 11123αβαβαβ+++==⨯=-+-，∵π02α⎛⎫∈ ⎪⎝⎭，，π02β⎛⎫∈ ⎪⎝⎭，，∴π4αβ+=，∴tan()1αβ+=，故选D.5．55771log 2log log log 32a b =<==<=，即a c b <<，故选D. 6．A ．∵148a a =，322a a =+，23223332824422a a a a a a a a ===-⎧⎧⎧⇒⎨⎨⎨==--=⎩⎩⎩或（舍去）∴，∴322.aq a ==11a =∴； B. 1112n n n a a q --== ，112112n n n a a q a S q --==-- ，∴12n n S a -=-，∴21n n S a =-；C ．1221log log 21112222n n n n n n n a n n b S a ----====+ ；D ．1122n nn nb b ++--=，∵12345b b b b b <=>>…， ∴2314b b ==，∴23{}n b b b 的最大项为和，故选C. 7．如图1，以D 为原点，分别以DA ，DC ，DD 1，所在直线为x 轴，y轴、z 轴建立空间直角坐标系. 设2AB =，则B (2，2，0)，A 1 (2，0，2)，A (2，0，0)，C (0，2，0)，N (1，2，0)，设M (0，y ，2)(02y <<)，则(220)DB = ，，，1(202)DA =，，，设平面1A BD 的法向量为图1数学参考答案·第2页（共11页）111()n x y z = ，，，则11111220220n DA x z n DB x y ⎧=+=⎪⎨=+=⎪⎩ ，可取11x =，得(111)n =-- ，，， (022)CM y =- ，，∵，∴ (111)(022)0n CM y y =---=-≠ ，，，，，故A 不正确； (22)AM y =- ，，∵，∴(220)(22)240DB AM y y =-=-≠，，，，，故B 不正确；(122)MN y =-- ，，∵，∴(111)(122)10n MN y y =----=+≠，，，，，故C 不正确；∵11A D AD ⊥，111A D C D ⊥，111 AD C D D = ，1AD ，111C D AD M ⊂平面，∴11 A D AD M ⊥平面.又11A D A BD ⊂平面，∴平面11A BD AD M ⊥平面，故D 正确，故选D.8．因为2π3OAP ∠=且OP 的垂直平分线经过点A ，所以OPA △为等腰三角形且OA PA a ==，所以在三角形FPA △中tan tan(60)1FPA PFA ∠=-∠== ，∴45FPA ∠= ，从而在三角形FPA △由正弦定理可知：sin sin AF AP FPA PFA =∠∠，即：sin sin a c aFPA PFA+=∠∠，24=，解得e =，故选C ．二、多项选择题（本大题共3小题，每小题6分，共18分．在每小题给出的四个选项中，有多项是符合题目要求的．全部选对的得6分，部分选对的得部分分，有选错的得0分）题号 9 10 11 答案 ABD BD AD【解析】9．由题，2()33f x x '=-，令()0f x '>得1x >或1x <-，令()0f x '<得11x -<<，所以()f x 在(1)-∞-，，(1)+∞，上单调递增，(11)-，上单调递减，所以1x =±是极值点，故A 正确；令3()3h x x x =-，该函数的定义域为R ，33()()(3)3()h x x x x x h x -=---=-+=-，则()h x 是奇函数，(00)，是()h x 的对称中心，将()h x 的图象向上移动两个单位得到()f x 的图象，所以点(02)，是曲线()y f x =的对称中心，故B 正确；因为(1)40f -=>，(1)0f =，(2)0f -=，所以，函数()f x 在(1)-∞-，上有一个零点，当1x >时，()(1)0x f f >=，即函数()f x 在数学参考答案·第3页（共11页）(1+)∞，上无零点，综上所述，函数()f x 有两个零点，故C 错误；令2()330f x x '=-=，可得1x =±，又(1)0(1)4f f =-=，，当切点为(10)，时，切线方程为0y =，当切点为(14)-，时，切线方程为4y =，故D 正确，故选ABD.10．根据辅助角公式得πsin()cos()n 4)i (x f x x x ωϕωϕωϕ⎛⎫=+++=++ ⎪⎝⎭．∵最小正周期为π，0ω>， 2π2π2πT ω===∴，即π()24f x x ϕ⎛⎫=++ ⎪⎝⎭．∵函数()f x过点(0，π||2ϕ≤，(0)πin 4f ϕ⎛⎫=+= ⎪⎝⎭∴，则ππ2π42k k ϕ+=+∈Z ，．当0k =时π4ϕ=．即π()222f x x x ⎛⎫=+= ⎪⎝⎭．令2(2ππ2π)x k k k ∈+∈Z ，，，则πππ2x k k ⎛⎫∈+ ⎪⎝⎭，，k ∈Z ，当0k =时，()f x 在π02⎛⎫⎪⎝⎭，单调递减，故A 错误；令2πx k k =∈Z ，，则π2k x k =∈Z ，当1k =时，()f x 的一条对称轴为π2x =，故B 正确；因为()2f x x =为偶函数，所以(||)2|)2f x x x ==，则(||)f x 的周期为πk k ∈Z ，且0k ≠，故C 错误；函数()f x 的图象向左平移π6个长度单位得到函数()g x 的解析式为ππ()2263g x x x ⎡⎤⎛⎫⎛⎫=+=+ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦，故D 正确，故选BD ．11．∵2n n a =，31n b n =-，∴C n 是以2为首领，4为公比的等比数列，∴12n n C q -==1222124222n n n ---== ，∴61532232C -===， A 正确B 不正确；311(31)22n n n n b n n a -==- ；35552n nn S +=-<， 而1 1n S S =≥，∴15n S <≤，D 正确；C. 1111(31)(32)3n n b b n n +==-+ (32)(31)(31)(32)n n n n +----+11133132n n ⎛⎫=- ⎪-+⎝⎭，∴13n T =111111125588113132n n ⎛⎫-+-+-+- ⎪-+⎝⎭1…1113232n ⎛⎫=- ⎪+⎝⎭11696n =-+，∴C 选项错误，正确选项为AD ，故选AD.数学参考答案·第4页（共11页）三、填空题（本大题共3小题，每小题5分，共15分）【解析】12．因为()f x 为偶函数，则1(1)(1)(2)ln (2)ln 22f f a a =-+=-+，∴，解得0a =，当0a =时，31ln31()2f x x x x =-+，(31)(31)0x x -+>，解得13x >或13x <-，则其定义域为1|3x x ⎧>⎨⎩或13x ⎫<-⎬⎭，关于原点对称.13()13131ln ln ln 3()13()(2)(2)(1)132x x f x x x x x x x x ---+-⎛⎫== ⎪-+-+⎝--⎭=-- 312ln31()x x x f x -==+，故此时()f x 为偶函数. 13．正四棱锥P −ABCD 的外接球的球心在它的高PO1上，记为O ，如图2，则 PO =AO =R ， 12PO =，12OO R =-， 在Rt △AOO 1中，1 2AO =， 由勾股定理：222 (2)2R R ⎛⎫=-+ ⎪ ⎪⎝⎭， 得98R =， 所以球的表面积 281π4π16S R ==. 14．过点AB ，作抛物线C ：24y x =的准线的垂线，垂足为M N ，，设AM λ=，BNμ=，则由梯形的中位线可知2d λμ+=，在AFB △中由余弦定理可知：||AB =所以||AB d =又因||AB d====，当且仅当λμ=时，等号成立，所以||AB d 图2数学参考答案·第5页（共11页）四、解答题（共77分．解答应写出文字说明，证明过程或演算步骤）15．（本小题满分13分）解：（1）因为(cos cos cos )sin cos a A B C A C +=，由正弦定理得，sin (cos cos cos )sin cos A A B C B A C +=， 因为(0π)sin 0A A ∈≠，，，所以cos cos cos cos A B C B C +，……………………………………（2分）因为cos cos()A B C =-+sin sin cos cos B C B C =-．……………………………………（4分）所以sin sin cos B C B C =， 又sin 0B ≠，则tan C =， 因为(0π)C ∈，，所以π3C =． ……………………………………（6分）（2）由正弦定理，4sin cC=，则4sin c C ==，………………………………（8分）由余弦定理：22222121cos 222a b c a b C ab ab +-+-===，∴2()212a b ab ab +--=， 2()123a b ab +-=，∴a b +=∵， ………………………………（11分）12ab =，∴1sin 2ABC S ab C ==故△的面积 ………………………………（13分）16．（本小题满分15分） （1）证明：在四边形ABCD 中作DE ⊥AB 于E ，CF ⊥AB 于F ，如图3， ∵CD AB ，2CD AD CB ===，4AB =， ∴四边形ABCD 为等腰梯形，1AE BF ==∴，故 DE BD ==.……………………（2分）数学参考答案·第6页（共11页）∴222AD BD AB +=， ∴AD BD ⊥.又∵PD ⊥平面ABCD ，BD ABCD ⊂平面， ∴PD BD ⊥， 又∵PD AD D = , ∴BD ⊥平面P AD. ……………………（5分）又 PA PAD ⊂平面， ∴BD PA ⊥．……………………………（7分）（2）解：如图4，以D 为原点建立空间直角坐标系. 由（1）可得BD =，则A (2，0，0)，B (0，，0)， P (0，0)，则(20AP =- ，，(0BP =-，， ……………………………（9分）设平面P AB 的法向量()n x y z =，，，则有20n AP x n BP ⎧=-+=⎪⎨=-+=⎪⎩，可取12)n = ，， …………………（12分）又平面ABD 的一个法向量 (001)m = ，，，……………………（13分）∴||cos 2||||m n m n m n 〈〉==，，…………………（14分）即平面ABD 与平面P AB所成夹角的余弦值为2， 所以，平面ABD 与平面P AB 的夹角为π4. …………………（15分）17．（本小题满分15分） （1）解：设椭圆1C 的半焦距为c ，由椭圆的定义可知2ABF △的周长为，12BF F △的周长为2c +，又2ABF △与12BF F △的周长之差为4-……………………………………（2分）所以24c -=-，图3图4数学参考答案·第7页（共11页）又因椭圆1C 左右焦点12F F ，分别为椭圆2C 的左右顶点.c a =∴，……………………………………（4分）联立解得，a =从而有c a == ……………………………………（5分）所以222222a b c -==，解得21b =，所以所求椭圆1C 的方程为22142x y +=，椭圆2C 的方程为2212x y +=．……………………………………（6分）（2）①证明：由（1）可知椭圆1C 的方程为22142x y +=，12(0)0)F F ，，设000()(0)M x y y ≠，，则有220012x y +=，于是12kk 2020122y x ===--.……………………………………（10分）②解：因为1212k k =-，所以21k =-，所以直线DE的方程为：y x =-联立y x =-与22142x y +=，消去y得：230x -=,……………………………………（11分）则有：1203x x ==，所以(033D E ⎛- ⎝⎭，，……………………………………（14分）83DE ==． ……………………………………（15分） 附注：本题也可由椭圆的焦半径公式可知：122()DE a e x x =-+22224412k k =-+． 也可以利用弦长公式直接求. 18．（本小题满分17分）解：（1）x =0.002×50×205+0.004×50×255+0.009×50×305+0.004×50×355+0.001×50×405 =300(km)．……………………………………（3分）数学参考答案·第8页（共11页）（2）由题意可知任取一辆汽车为“A 类汽车”的概率为(0.0040.001)500.25+⨯=，……………………………………（4分） 经分析Y ~(100.25)B ，，……………………………………（6分） ()100.25 2.5E Y =⨯=．……………………………………（8分）（3）第一次掷硬币出现正面，遥控车移到第一格，其概率为12，即112P =. 遥控车移到第(229)n n ≤≤格的情况是下面两种，而且只有两种： ①遥控车先到第n −2格，又掷出反面，其概率为212n P -；②遥控车先到第n −1格，又掷出正面，其概率为112n P -.所以211122n n n P P P --=+， ……………………………………（10分） 所以1121()2n n n n P P P P ----=--，……………………………………（11分）因为1012P P -=-， 所以129n ≤≤时，数列{P n −P n −1}是等比数列，首项为1012P P -=-，公比为12-的等比数列.所以1112P -=-，22112P P ⎛⎫-=- ⎪⎝⎭，33212P P ⎛⎫-=- ⎪⎝⎭， (112)n n P P -⎛⎫-=- ⎪⎝⎭.所以112100()()()n n n n n P P P P P P P P ---=-+-+⋯+-+=1111...1222n n -⎛⎫⎛⎫⎛⎫-+-++-+ ⎪ ⎪⎪⎝⎭⎝⎭⎝⎭1111212113212n n ++⎛⎫-- ⎪⎡⎤⎛⎫⎝⎭==--⎢⎥ ⎪⎛⎫⎝⎭⎢⎥⎣⎦+ ⎪⎝⎭， 01P =也满足上式，故1211(0129)32n n P n +⎡⎤⎛⎫=--=⋯⎢⎥ ⎪⎝⎭⎢⎥⎣⎦，，，，……………………………………（14分）所以获胜的概率302921132P ⎡⎤⎛⎫=--⎢⎥ ⎪⎝⎭⎢⎥⎣⎦，数学参考答案·第9页（共11页）失败的概率2929302811211111223232P P ⎡⎤⎡⎤⎛⎫⎛⎫==⨯--=--⎢⎥⎢⎥ ⎪ ⎪⎝⎭⎝⎭⎢⎥⎢⎥⎣⎦⎣⎦，……………………………………（16分）所以30292829302111111110323232P P ⎡⎤⎡⎤⎡⎤⎛⎫⎛⎫⎛⎫-=-----=-->⎢⎥⎢⎥⎢⎥ ⎪⎪ ⎪⎝⎭⎝⎭⎝⎭⎢⎥⎢⎥⎢⎥⎣⎦⎣⎦⎣⎦， 所以获胜的概率大.所以此方案能成功吸引顾客购买该款新能源汽车．……………………………………（17分）19．（本小题满分17分）（1）证明：构建()sin (01)F x x x x =-∈，，， ……………………………………（1分） 则()1cos 0F x x '=->对(01)x ∀∈，恒成立， ……………………………………（2分）则()F x 在(01)，上单调递增，可得()(0)0F x F >=， 所以sin (01)x x x >∈，，； ……………………………………（3分）构建22()sin ()sin (01)G x x x x x x x x =--=-+∈，，，………………………………（4分） 则()21cos (01)G x x x x '=-+∈，，， ……………………………………（5分）构建()()(01)g x G x x '=∈，，，则()2sin 0g x x '=->对(01)x ∀∈，恒成立，……………………………………（6分）则()g x 在(01)，上单调递增，可得()(0)0g x g >=， 即()0G x '>对(01)x ∀∈，恒成立， ……………………………………（7分）则()G x 在(01)，上单调递增，可得()(0)0G x G >=， 所以2sin (01)x x x x >-∈，，； 综上所述：sin x x x x 2-<<． ……………………………………（8分）（2）解：令210x ->，解得11x -<<，即函数()f x 的定义域为(11)-，， 若0a =，则21ln(1)(11)()f x x x =--∈-，，，令21u x =-， 因为1ln y u =-在定义域内单调递减，21u x =-在(10)-，上单调递增，在(01)，上单调递减，则21ln(1)()x x f =--在(10)-，上单调递减，在(01)，上单调递增，数学参考答案·第10页（共11页）故0x =是()f x 的极小值点，符合题意. ……………………………………（10分）当0a ≠时，令||0b a =>，因为222()cos ln(1)cos(||)ln(1)cos ln(1)x ax x a x x bx f x =--=--=--， 且22()cos()ln[1()]cos ln(1)()x f f x bx x bx x -=----=--=， 所以函数()f x 在定义域内为偶函数，…………………………………………………………（11分）由题意可得：22()sin (11)1xf x b bx x x '=--∈--，， （i ）当202b <≤时，取1min 1m b ⎧⎫=⎨⎬⎩⎭，，(0)x m ∈，，则(01)bx ∈，， 由（1）可得222222222(2)()sin()111x x x b x b f x b bx b x x x x +-'=-->--=---， 且222202010b x b x >-->，≥，， 所以2222(2)()01x b x b f x x +-'>>-， ……………………………………（13分）即当(0)(01)x m ∈⊆，，时，()0f x '>，则()f x 在(0)m ，上单调递增， 结合偶函数的对称性可知：()f x 在(0)m -，上单调递减，所以0x =是()f x 的极小值点，符合题意； ……………………………………（14分）（ⅱ）当22b >时，取10(01)x b ⎛⎫∈⊆ ⎪⎝⎭，，，则(01)bx ∈，， 由（1）可得2233223222222()sin ()(2)111x x x f x b bx b bx b x b x b x b x b x x x'=--<---=-+++----， 构建3322321()20h x b x b x b x b x b ⎛⎫=-+++-∈ ⎪⎝⎭，，， …………………………………（15分）则32231()320h x b x b x b x b ⎛⎫'=-++∈ ⎪⎝⎭，，，且331(0)00h b h b b b ⎛⎫''=>=-> ⎪⎝⎭，，则()0h x '>对10x b ⎛⎫∀∈ ⎪⎝⎭，恒成立，可知()h x 在10b ⎛⎫ ⎪⎝⎭，上单调递增，且21(0)2020h b h b ⎛⎫=-<=> ⎪⎝⎭，，数学参考答案·第11页（共11页）所以()h x 在10b ⎛⎫ ⎪⎝⎭，内存在唯一的零点10n b ⎛⎫∈ ⎪⎝⎭，，当(0)x n ∈，时，则()0h x <，且2010x x >->，， 则3322322()(2)01xf x b x b x b x b x'<-+++-<-，……………………………………（16分）即当(0)(01)x n ∈⊆，，时，()0f x '<，则()f x 在(0)n ，上单调递减， 结合偶函数的对称性可知：()f x 在(0)n -，上单调递增， 所以0x =是()f x 的极大值点，不符合题意； 综上所述：22b ≤，即22a ≤，解得a ， 故a的取值范围为a .……………………………………（17分）。
2024届云南省三校联高考备考实用性联考卷(四)英语试题
2024届云南省三校联高考备考实用性联考卷（四）英语试题1. Who did the woman go hiking with?A．Her classmate. B．Her cousin. C．Her parents.2. Where are the speakers?A．On the train. B．At the airport. C．In the car.3. What is Mary probably doing according to the woman?A．Attending a meeting. B．Doing some training. C．Going on holiday.4. How much will the woman probably pay for the skirt?A．$ 30. B．$70. C．$100.5. What did the boy buy yesterday?A．Something to read. B．Something to eat. C．Something to wear.听下面一段较长对话，回答以下小题。
6. Why does the man choose to learn Spanish?A．His boss asked him to learn it.B．He plans to have a vacation in Spain.C．He wants to meet the needs of his job.7. What will NOT be included in beginner Spanish?A．Conversation. B．Grammar. C．Phrases.听下面一段较长对话，回答以下小题。
8. Whose birthday was it yesterday?A．Mary’s.B．Jane’s.C．Mary’s sister’s.9. Why does Mary look tired?A．She stayed up typing a paper.B．She had the party for a whole night.C．She was too nervous to sleep last night.听下面一段较长对话，回答以下小题。
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2024届云南省部分名校高考备考实用性联考卷（一）英语试题学校:___________姓名：___________班级：___________考号：___________一、短对话1．What color was the jacket the man wore yesterday?A．Blue.B．Black.C．Green.2．How much does a bus ticket cost today?A．£1.50.B．£3.00.C．£4.00.3．What is the probable relationship between the speakers?A．Husband and wife.B．Nurse and patient.C．Teacher and student. 4．Where did the speakers probably meet last time?A．At a conference.B．At a restaurant.C．At the sales department. 5．What did the woman drop?A．A bus ticket.B．Her mobile phone.C．Some money.二、长对话听下面一段较长对话，回答以下小题。
6．What are the speakers trying to do?A．Have a meeting.B．Plan a holiday.C．Arrange for a dinner. 7．What will the woman do next?A．Call her secretary.B．Check her time.C．Fly to Italy.听下面一段较长对话，回答以下小题。
8．What are the speakers talking about?A．Visiting neighbor’s home.B．Taking up a new hobby.C．Planning a new home.9．What is probably the man’s hobby?A．Skateboarding.B．Playing the guitar.C．Running.听下面一段较长对话，回答以下小题。
10．What does the woman want to do?A．Change a new TV.B．Cancel the TV service.C．Add more TV channels. 11．What does the man suggest doing?A．Watching less TV.B．Keeping more channels.C．Trying a cheaperpackage.12．What do we know about the woman’s husband?A．He has lost his job.B．He seldom watches TV.C．He works in a firestation.听下面一段较长对话，回答以下小题。
13．What is the conversation mainly about?A．Why to buy a used car.B．How to select a used car.C．Where to buy a used car. 14．How did the man get his last used car?A．On the eBay.B．From a friend.C．In a car market. 15．Where will the woman find the largest selection of cars in one place?A．Craigslist.B．CarMax.C．eBay.16．What is the best time to check car information on the noticeboard?A．Winter vacation.B．Spring vacation.C．Graduation season.三、短文听下面一段独白，回答以下小题。
17．Who is probably introducing the museum?A．A guide.B．An AI robot.C．A pilot.18．What special activity is provided this year?A．A flying experience.B．A free museum tour.C．A lecture on planes. 19．What does the speaker advise visitors to do?A．Fly planes on weekdays.B．Go to the countryside.C．Book plane trips in advance.20．What can we learn about the museum?A．It’s not far from a village.B．It only opens on weekends.C．It’s the smallest museum in Europe.四、阅读理解Four Hotels That Will Make Your Life EasierMarriott Detroit AirportIt’s such an ideal option for business travelers in a hurry. Here is the basic idea: You download the iPhone or Android app. The night before, you can “check-in” virtually. When you arrive you get a message that the room is ready and your key, which is already tied to your reservation, is waiting for you at the desk.Yotel New YorkThe self-service kiosks (一体机) at this high-tech New York hotel are open 24x7 and work just like the ones you’d see at an airport. There are just five-steps to register and obtain your room card. There’s even a luggage robot. You tap in the number of bags you’re carrying, then wait for a robot arm to swing down and store your luggage in a locker.Hyatt Regency MinneapolisBusiness travelers like the fast kiosk check-in works. Like the Yotel, the kiosk asks you to put in your credit card. The whole process takes about three minutes. When travelers leave, they can be equally impressed with the fast check-out. You never have to wait in line. Radisson LaCrosseThe Radisson is trying to make the kiosk process even faster, you use a mobile app to register and then receive a password by email or text. When you get to the kiosk, you can scan the password to get your key without any other steps required. It’s incredibly fast. 21．Which hotel has the self-service luggage locker?A．Marriott Detroit Airport.B．Yotel New York.C．Hyatt Regency Minneapolis.D．Radisson LaCrosse.22．What do Marriott Detroit Airport and Radisson LaCrosse have in common?A．They provide key-free service.B．They both have the fastest check-in process.C．Travelers need to check in with a credit card.D．Travelers can check in with their mobile phones.23．What’s the main purpose of the text?A．To assess the service of the hotels.B．To criticize the service of the hotels.C．To recommend hotels with fast service.D．To help customers check in and check out.As a child, Liu Wenwen didn’t like the suona, a “loud” traditional Chinese musical instrument, also an ancestral treasure of her family that was to become her career.Liu says she felt ashamed. In the 1990s, people admired things that were modern and international. The suona was considered out of date. Her father’s family has performed with the suona for seven generations, while the tradition on her mother’s side of the family can be traced back to the early Qing Dynasty. Despite her unwillingness, she followed her parents to play the suona as early as 3 years old. Besides it, Liu has also learned traditional Chinese vocal music and dancing—skills that have improved her oral muscles and sense of rhyme, helping equip her to be a professional musician.It wasn’t until 2008 that she first found suona music beautiful. That was when she entered the Shanghai Conservatory of Music to learn the instrument more systematically from Liu Ying, a professor and top player. “The music played by the professor is just amazing, and different from what I had heard before,” she says.She loves exchanging ideas about suona playing techniques with her students. “It’s wonderful to see the younger generation carrying on this cultural tradition.” Liu Wenwen said she is pleased to see the suona regain popularity among young people, sometimes combined with jazz, opera and other art forms. This has stopped its decline in the 1990s. Her name, when mentioned on China’s social media platforms, often is followed by a video of her live performance at a concert in Sydney, Australia. Westerners were amazed by the loud, unfamiliar instrument and its colorful music. “I felt my hard work had paid off. I trained for over 20 years, probably just to win cheers and applause for traditional Chinese music on the international stage”.24．What urged Liu Wenwen to learn to play the suona?A．Family tradition.B．Personal interest.C．Her professor.D．Her ambition.25．Apart from daily training, what did Liu do to be a professional musician?A．Follow her parents to play the suona.B．Learn music history at an early age.C．Play the suona with her parents on the stage.D．Better her oral muscles and sense of rhyme.26．How did Liu first find suona music beautiful?A．By learning from the famous professor Liu.B．By visiting Shanghai Conservatory of Music.C．By performing the suona music in Sydney.D．By hearing her family playing the suona.27．What can we learn from Liu’s last words in the last paragraph?A．She learned the value of her performance.B．She earned a fortune after 20 years’ training.C．She worked hard and became an international professor.D．She surprised many westerners with a video of her performance.Antony Aumann, a religious studies and philosophy professor at Northern Michigan University told Insider he had caught his student submitting essays written by the AI chatbot, and Aumann had his student rewrite the essay.It’s not just his struggling with the rise of AI chatbots like ChatGPT. As a result of these tools becoming accessible to anybody with an Internet connection, education departments across the entire country are adjusting work process and redesigning entire courses, according to the NYT, forcing students to submit handwritten essays or introducing oral exams. The New York City and Seattle public school systems have already banned ChatGPT on their own networks and devices. “I think the consideration behind the ban is reasonable,” Aumann said. “They want to make sure that their students are learning the critical thinking skills that are part of learning how to write.”But universities aren’t likely to follow the ban. After all, going around these restrictions is quite easy. Even tools designed to assist teachers in catching students secretly making use of AI tools like ChatGPT will probably be of little use, because students can change a few words from what ChatGPT produced, add some grammatical mistakes on purpose, and the detectors no longer think it’s written by a chatbot.Besides, some professors including Aumann argued that the cat is already out of the bag. Once students are captured by ChatGPT’s convenience and efficiency, it’d be pointless to fight ChatGPT in the classroom.Instead of absolute prohibition, Aumann suggested encouraging their students to react to ChatGPT in the same way they react to learning source—they will be asked to evaluate its reasons and arguments.28．Why did the author mention Aumann’s case in paragraph 1?A．To spread a tool of AI chatbots.B．To start a discussion on ChatGPT.C．To introduce ChatGPT technology.D．To share a public concern on college education.29．Why is ChatGPT banned by some school systems?A．Teachers can have easy access to ChatGPT.B．Teachers can catch students cheating easily.C．ChatGPT fails to develop learners’ competence.D．ChatGPT blocks the improvement of education systems.30．What does “the cat is already out of the bag” really mean in paragraph 4?A．Students will be caught cheating through ChatGPT.B．It cannot be avoided that ChatGPT attracts students.C．Teachers decide to lake action to address the problem.D．The cat manages to escape from being caught eventually.31．What’s Aumann’s attitude to ChatGPT?A．Worried.B．Subjective.C．Objective.D．Indifferent.Florida wildlife officials say manatees (海牛) facing starvation are benefitting from a program that feeds them on tons of donated lettuce (生菜). The program aims to save as many of the large animals as possible as water pollution has led to shortages of their favorite food, seagrass.The effort has provided the manatees with more than 25 tons of lettuce. The feedings usually draw about 300 to 350 manatees per day. Sometimes, there are as many as 800 manatees. Normally, wildlife experts advise against people feeding wild animals. This is because it can lead the animals to make an unhealthy connection between humans and food. It is a crime in Florida for a person to feed manatees on their own, even though officials say many people want to do so. Experts believe the best way people can help is to donate money through an official institution (机构).In 2021, 1101 manatee deaths were reported, largely from starvation. The normal five-year average is about 625 deaths. State wildlife officials say that so far this year, 164 manatee deaths have been recorded. Tom Reinert, the local director of state’s Fish and Wildlife Conservation Commission, said the feeding program has helped to reduce the rising death rates. Officials estimate there are about 8800 manatees in Florida waters. That is a big improvement from about 2000 that existed in the 1990s. The increased numbers were responsible for manatees being removed from the endangered species list.The most important element for supporting the remaining population will be restoring seagrass beds. So far, Florida has set aside $8 million to deal with that problem. “You can’t just go out and plant a bunch of seagrass,” Reinert said. But he added, “Projects are getting started and are in the planning stages.”32．What is the program intended to do?A．To reduce food waste.B．To study manatees’ eating habits.C．To rescue large animals from starvation.D．To solve the problem of water pollution. 33．What do experts advise the public to do for manatees?A．Feed healthy food to them.B．Set up special rescue groups.C．Pay more visits to wildlife reserves.D．Offer financial aid to officialorganizations.34．Which of the following can best describe the feeding program?A．Impractical.B．Significant.C．Complicated.D．Time-consuming.35．What’s the best title for the text?A．Manatee Saving Program B．Ocean Protecting ProgramC．Manatee Feeding Program D．Seagrass Beds Restoring Program五、七选五Are you someone who easily gets tired and doesn’t feel like doing anything? Do you label this kind of behavior as mere laziness? 36Feel disconnected from everything.People experiencing exhaustion most commonly don’t feel like themselves anymore, don’t feel engaged by anything and constantly struggle with the sense of helplessness andinability to take back control of their lives.Used to be motivated and passionate.A clear difference between someone who’s worn out and someone who’s lazy is that the tired people used to have things they were passionate about. 37 And even hate doing anything because of how much they overworked themselves.Become moody and annoyed.Do you suddenly find yourself easily angry? 38 If you start to have trouble controlling your emotions, especially when it never used to be a problem for you, this might be the reason why.39One of the warning signs is that you start neglecting your self-care and socially keep away from others. You stop making an effort to dress up yourself or look good and you tend to spend most of your time by yourself doing nothing.Changes happen gradually.Studies show that exhaustion develops in five major stages, according to degrees of severity. The honeymoon phase, the onset of stress, chronic stress, exhaustion and habitual exhaustion. By the time you reach the final stage, exhaustion will make you suffer from depression and anxiety. 40A．Ignore your self-care.B．Focus on warning signs.C．Do you often feel emotionally out of control?D．So it’s important to raise awareness about exhaustion.E．But the lazy people don’t ever devote themselves to things.F．However, they may now be struggling to find interest in anything.G．Here are five signs to show you’re experiencing exhaustion rather than laziness.六、完形填空your true 44 , the things you are good at, and the things that you are bad at.In my early years al school, I had 45 with some subjects and I used to get really bad grades. Sometimes I would get an F and that would make me really 46 . I used to think: “What will I show my parents?” So what I used to do was 47 those grades, I would turn the F into a B just to 48 my parents, and eventually, I was caught doing that. I realized a lot after that. I knew that I had to accept that failure and 49 it. Then with a series of trials, something 50 actually came from it. I started doing better with my grades. That F turned into a B 51 , and that B turned into an A．Whenever you face a failure, 52 think that you are not going to recover from this, you must think of 53 to better yourself. Did you know that it took Thomas Edison 10,000 attempts to 54 the light bulb? This is the 55 that we must learn from our failures, not run from them!41．A．succeed B．fail C．depress D．achieve 42．A．diligent B．innocent C．mature D．sensitive 43．A．inform B．warn C．announce D．discourage 44．A．interests B．abilities C．facts D．hobbies 45．A．trouble B．inspiration C．experience D．fun 46．A．silly B．surprised C．scared D．satisfied 47．A．give up B．add up C．dig up D．cover up 48．A．ease B．tease C．please D．treat 49．A．result from B．learn from C．suffer from D．conclude from 50．A．beneficial B．sensible C．negative D．forgettable 51．A．precisely B．consequently C．generally D．naturally 52．A．seldom B．never C．hardly D．often 53．A．skills B．trends C．schedules D．ways 54．A．get B．abandon C．perfect D．change 55．A．proof B．reason C．result D．response七、用单词的适当形式完成短文阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。