CLAD模拟试题
大学生英语竞赛D类智力测试专项强化真题试卷4(题后含答案及解析)
大学生英语竞赛D类智力测试专项强化真题试卷4(题后含答案及解析)题型有：1.1．This bar chart shows how many times a class of children hit a target with a set of ten beanbags. How many children hit the target fewer than 7 times?A．21.B．22.C．23D．24正确答案：B解析：本题要求的是撞击在7次以下的人数，由图表可知7次以下的为22人。
2．Balbir wants to guide a robot along the white squares through this maze.The robot starts on the square marked “Entrance”, and must finish on the square marked”Exit”.It can only move FORWARD, TURN RIGHT 90°and TURN LEFT 90°.Which instructions will guide the robot through the maze?A．FORWARD 4, TURN LEFT 90°, FORWARD 2, TURN RIGHT 90 , FORWARD 3, TURN RIGHT 90 , FORWARD 5.B．FORWARD 3, TURN RIGHT 90 , FORWARD 1, TURN RIGHT 90 , FORWARD 3, TURN LEFT 90 , FORWARD 3.C．FORWARD 3, TURN LEFT 90 , FORWARD 1, TURN RIGHT 90 , FORWARD 2, TURN RIGHT 90 , FORWARD 4.D．FORWARD 3, TURN RIGHT 90 , FORWARD 1, TURN LEFT 90 , FORWARD 2, TURN LEFT 90 , FORWARD 4.正确答案：C解析：前移三个格，左转90度，再前移一个格，右转90度，再前移两个格，右转90度，前移四个格就可以出去了，但每前移一格都不包括机器人所站的那一格。
专业英语八级(阅读)模拟试卷150(题后含答案及解析)
专业英语八级（阅读）模拟试卷150(题后含答案及解析)题型有： 2. READING COMPREHENSIONPART II READING COMPREHENSIONSECTION A MULTIPLE-CHOICE QUESTIONSIn this section there are several passages followed by fourteen multiple-choice questions. For each multiple-choice question, there are four suggested answers marked [A] , [B], [C] and [D]. Choose the one that you think is the best answer.(1)So Roger Chillingworth—a deformed old figure, with a face that haunted men’s memories longer than they liked—took leave of Hester Prynne, and went stooping away along the earth. He gathered here and there an herb, or grubbed up a root, and put it into the basket on his arm. His grey beard almost touched the ground, as he crept onward. Hester gazed after him a little while, looking with a half fantastic curiosity to see whether the tender grass of early spring would not be blighted beneath him, and show the wavering track of his footsteps, sere and brown, across its cheerful verdure. She wondered what sort of herbs they were, which the old man was so sedulous to gather. Would not the earth, quickened to by the sympathy of his eye, greet him with poisonous shrubs, of species hitherto unknown, that would start up under his fingers? Or might it suffice him, that every wholesome growth should be converted into something deleterious and malignant at his touch? Did the sun, which shone so brightly everywhere else, really fall upon him? Or was there, as it rather seemed, a circle of ominous shadow moving along with his deformity, whichever way he turned himself? And whither was he now going? Would he not suddenly sink into the earth, leaving a barren and blasted spot, where, in due course of time, would be seen deadly nightshade(颠茄), dogwood(山茱萸), henbane(天仙子), and whatever else of vegetable wickedness the climate could produce, all flourishing with hideous luxuriance? Or would he spread bat’s wings and flee away, looking so much the uglier, the higher he rose towards heaven? (2)”Be it sin or no,”said Hester Prynne bitterly, as she still gazed after him, “I hate the man!”(3)She upbraided herself for the sentiment, but could not overcome or lessen it. Attempting to do so, she thought of those long-past days, in a distant land, when he used to emerge at eventide(黄昏)from the seclusion of his study, and sit down in the firelight of their home, and in the light of her nuptial smile. He needed to bask himself in that smile, he said, in order that the chill of so many lonely hours among his books might be taken off the scholar’s heart. Such scenes had once appeared not otherwise than happy, but now, as viewed through the dismal medium of her subsequent life, they classed themselves among her ugliest remembrances. She marvelled how such scenes could have been! She marvelled how she could ever have been wrought upon to marry him! She deemed it her crime most to be repented of, that she had ever endured, and reciprocated, the lukewarm grasp of his hand, and had suffered the smile of her lipsand eyes to mingle and melt into his own. And it seemed a fouler offence committed by Roger Chillingworth, than any which had since been done him, that, in the time when her heart knew no better, he had persuaded her to fancy herself happy by his side. (4)”Yes, I hate him!”repeated Hester, more bitterly than before. “He betrayed me! He has done me worse wrong than I did him!”(5)Let men tremble to win the hand of woman, unless they win along with it the utmost passion of her heart! Else it may be their miserable fortune, as it was Roger Chillingworth’s, when some mightier touch than their own may have awakened all her sensibilities, to be reproached even for the calm content, the marble image of happiness, which they will have imposed upon her as the warm reality. But Hester ought long ago to have done with this injustice. What did it betoken? Had seven long years, under the torture of the scarlet letter, inflicted so much of misery, and wrought out no repentance? (6)The emotions of that brief space, while she stood gazing after the crooked figure of old Roger Chillingworth, threw a dark light on Hester’s state of mind, revealing much that she might not otherwise have acknowledged to herself. (7)He being gone, she summoned back her child. (8)”Pearl! Little Pearl! Where are you?”(9)Pearl, whose activity of spirit never flagged, had been at no loss for amusement while her mother talked with the old gatherer of herbs. At first, as already told, she had flirted fancifully with her own image in a pool of water, beckoning the phantom forth, and—as it declined to venture—seeking a passage for herself into its sphere of impalpable earth and unattainable sky. Soon finding, however, that either she or the image was unreal, she turned elsewhere for better pastime. She made little boats out of birch-bark(桦树皮), and freighted them with snail-shells , and sent out more ventures on the mighty deep than any merchant in New England: but the larger part of them foundered near the shore. She seized a live horse-shoe(鲎)by the tail, and made prize of several five-fingers(海星), and laid out a jelly-fish to melt in the warm sun. Then she took up the white foam, that streaked the line of the advancing tide, and threw it upon the breeze, scampering after it, with winged footsteps, to catch the great snowflakes ere they fell. Perceiving a flock of beach-birds, that fed and fluttered along the shore, the naughty child picked up her apron full of pebbles, and, creeping from rock to rock after these small sea-fowl, displayed remarkable dexterity in pelting them. One Utile grey bird, with a white breast, Pearl was almost sure, had been hit by a pebble, and fluttered away with a broken wing. But then the elf-child sighed, and gave up her sport: because it grieved her to have done harm to a Utile being that was as wild as the sea-breeze, or as wUd as Pearl herself. (10)Her final employment was to gather sea-weed, of various kinds, and make herself a scarf, or mantle, and a head-dress, and thus assume the aspect of a Utile mermaid. She inherited her mother’s gift for devising drapery and costume. As the last touch to her mermaid garb, Pearl took some eel-grass, and imitated, as best she could, on her own bosom, the decoration with which she was so familiar on her mother’s. A letter—the letter A—but freshly green, instead of scarlet! The child bent her chin upon her breast, and contemplated this device with strange interest: even as if the one only thing for which she had been sent into the world was to make out its hidden import.1．According to Para. 1, people are most impressed by ChilUngworth’s______.A．spiritB．figureC．ageD．appearance正确答案：A解析：推断题。
NI CLAD 试题 2
LabVIEW助理开发工程师考试为了快速找到问题，可将答案记录在本页答题纸上。
撕下该页用于记录答案。
实际的CLAD考试中并无该页，仅供模拟题使用。
答案页在模拟题的最后。
1._____2._____3._____4._____5._____6._____7._____8._____9._____10._____11._____12._____13._____14._____15._____16._____17._____18._____19._____20._____21._____22._____23._____24._____25._____26._____27._____28._____29._____30._____31._____32._____33._____34._____35._____36._____37._____38._____39._____40._____1.下列关于代码执行的陈述，正确的是？a.循环执行51次。
b.循环执行50次。
c.循环执行49次。
d.连接50至For循环的总数接线端，与本题代码的执行一致。
2.下列哪项将生成一个LabVIEW事件结构可捕捉到的事件？a.通过鼠标单击改变前面板控件的值b.通过属性节点更新前面板控件c.通过控件引用以编程方式更新前面板控件d.通过VI服务器更新前面板控件3.下列代码执行后，结果显示多少？a.子VI执行消耗的毫秒数b.零c.自1970年1月1日以来经历的秒数d.顺序结构执行消耗的毫秒数4.要在运行时修改前面板控件的一个属性。
下列哪种方法最适合？a.创建一个隐式属性节点，选择要修改的属性b.创建一个控件引用，将引用传递至属性节点并选择要修改的属性c.创建一个链接的共享变量，并选择要修改的属性d.创建一个局部变量，并选择要修改的属性5.创建数组最快捷的方式是：a.在While循环中放置一个“创建数组”函数b.初始化一个数组，然后在While循环中替换数组元素c.使用启用了自动索引的For循环d.使用启用了自动索引的While循环6.在运行周期较长的应用程序中，时间控制最好使用下列哪个定时函数/VI？a.b.c.d.7.在下列程序框图所示的VI中，自动错误处理已禁用。
专业英语四级模拟试卷76(题后含答案及解析)
专业英语四级模拟试卷76(题后含答案及解析)题型有：1. DICTATION 2. LISTENING COMPREHENSION 3. CLOZE 4. GRAMMAR & VOCABULARY 5. READING COMPREHENSION 6. WRITINGPART I DICTATION (15 MIN)Directions: Listen to the following passage. Altogether the passage will be read to you four times. During the first reading, which will be read at normal speed, listen and try to understand the meaning. For the second and third readings, the passage will be read sentence by sentence, or phrase by phrase, with intervals of 15 seconds. The last reading will be read at normal speed again and during this time you should check your work. You will then be given 2 minute 1．正确答案：Robert Edwards Robert Edwards was blinded/in an automobile accident nine years ago./Last week, he was walking near his home/when a thunderstorm approached./ He took refuge under a tree and was struck by lightning./He was knocked to the ground/and woke up some 20 minutes later,/lying face down in water below a tree. / He went into the house and ]ay clown in bed. / When he opened his eyes a short time later,/he could see the clock across the room/fading in and out in front of him. / When his wife entered ,/he saw her for the first time in nine years. / Doctors confirm that he has regained his sight/apparently from the flash of lightning,/but they are unable to explain the happening. / The only possible explanation offered by one doctor was that,/since Edward lost his sight/as a result of a trauma in a terrible accident,/perhaps the only way it would be restored was by another trauma.PART II LISTENING COMPREHENSION (20 MIN)Directions: In Sections A, B and C you will hear everything ONCE ONLY. Listen carefully and then answer the questions that follow. Mark the correct answer to each question on your answer sheet.SECTION A CONVERSATIONSDirections: In this section you will hear several conversations. Listen to the conversations carefully and then answer the questions that follow.听力原文：M: Do you happen to know where the movie theater is downtown7 The one near the hospital.W: Yeah. Why do you ask?M: Well, on Monday, I asked Jennifer out on a date for this coming Saturday night.W: Wow. You’ve really been seeing a lot of her lately. Sounds great. Okay, write down these directions so you don’t get lost.M: Okay, go ahead.W: First, drive down 1st street going west, cross the river, and keep going straight until Pine Street. Then turn left, and the movie theater isthe second building on the right. It’s next to the church.M: Got it. Now, can you recommend any nice restaurants?W: Yeah. The Pink Flamingo serves excellent Spanish food.M: Well where’s that?W: Well, starting from the movie theater, go south on Pine Street, cross 2nd Street, and drive to 3rd Street. You’ll see a parking lot on the left side of the street.M: Okay. Then what?W: Then turn left on 3rd Street and drive east. The Pink Flamingo is the building just before the river on the left side. I think it’s open weekdays from 10:30 in the morning to 11:30 at night, but it stays open until midnight on the weekends.M: Okay, I think I’ve driven by there before. Great. Thanks a lot.2．When is the man going out with Jennifer?A．Friday.B．Saturday.C．Sunday.D．Monday.正确答案：B解析：本题测试对细节内容的理解能力。
CLAD考试题目
bVIEW.hlp文件中b.文件»VI属性»说明信息bVIEW.ini文件中d.帮助»关于VI2) 通过LabVIEW中的哪个功能可使用常用的VI架构进行快速编程？a.VI向导b.VI起步c.VI模板d.VI模式3) LabVIEW按照哪种编程结构执行程序框图代码？a.控制流，程序的执行顺序由编程元素的顺序确定b.从上至下，程序从程序框图的顶部开始执行，一直往下c.从左至右，程序从程序框图的左边开始执行，一直往右d. 数据流模型，程序框图根据数据流向执行4) 创建大型应用程序时，子VI的说明信息：a. 与顶层VI同等重要b. 顶层VI更加重要c. 完全不重要并且非必须d. 仅用于大型的应用程序5) 下图是哪种常见的VI架构？a.多条件结构VIb.通用VIc.状态机VId.并行循环VI6) 程序功能注释应包含在：a. 程序框图b. 连线板c. LabVIEW.hlp文件d. 以上均不正确，图形化编程中无需添加注释7)下列哪种方法不适用于添加LabVIEW程序的文档说明信息a.选择VI属性>>说明信息b.选择前面板对象的属性页c.双击子VI图标并选择说明信息d.右键单击前面板对象并选择说明和提示8) 哪种VI架构允许用户同时运行多个任务？a.多条件结构VIb.并行循环VIc.状态机VId.以上均不正确9) 对一系列函数或计算进行编程时，以下哪种方式可获得最佳性能？a. 层叠式顺序结构b. 平铺式顺序结构c. A和B可获得相同的性能10) 以下答案中匹配VI架构类型和对应程序框图是？A. B.a. A - 状态机VI；B - 简单VIb. A - 通用VI；B - 状态机VIc. A - 通用VI；B - 简单VId. A - 简单VI；B - 状态机VI11) 以下哪种VI架构类型最适合在大型应用程序中将执行功能（例如，计算、转换和数据修改）保存为子VI？a.简单VIb.UI事件处理器c.队列消息处理器d.以上均不正确12) 程序框图中添加的注释：a. 用于添加VI中控件属性的说明信息b. 用于添加程序框图中所有函数/子VI的说明信息c. 用于添加代码功能的说明信息d. 无需添加注释，LabVIEW可自动添加13) 以下关于顺序结构的表述，不正确的是：a.尽可能将顺序结构替换为包含条件结构的While循环b.顺序结构可确保执行顺序c.在VI中使用单个顺序结构将禁止并行操作d.顺序结构的某一帧发生错误时将停止执行14) VI模板通过哪种方式减少编程时间？a.为常用VI类型提供起始编程信息b.为用户自动生成代码c.允许用户保存部分代码并用于后期应用程序开发d.A和Be.A和C15) 以下哪种情况必须使数据连线通过结构？a. 使连线更简单b. 节省空间c. 在结构中使用该数据d. 以上均正确16) 状态机VI架构的缺点是？a.状态机VI只能按顺序执行状态b.如果两个事件同时发生，只处理第一个事件，第二个事件将丢失c.通用架构转换为状态机架构后，程序框图将显著增大d.状态机不能采集数据或使用DAQ函数17) 以下关于强制转换点的表述，正确的是？a.强制转换点可提高程序的性能b.强制转换点表示数据类型的转换c.强制转换点可提高内存的使用效率d.A和Be.B和C18) 在While循环中添加定时函数可：a. 释放内存b. 保留内存c. 释放CPUd. 保留CPU19) 在同一VI中传递数据的最佳方法是？a.连线b.全局变量c.局部变量d.以上均正确20) 动作2中的代码何时执行？a.执行动作1的代码之后b.动作1和动作2布尔值为TRUE时c.动作2的布尔值为TRUE时d.每次循环时1)下列关于数组的表述哪项有误？a.数组可用于保存由循环生成的数据b.数组元素无索引c.数组可包含输入控件或显示控件，但无法同时包含两种控件d.数组可组合相同类型的数据元素2)以下哪种方法不适用于创建一维数组：a.在前面板上放置数组外框，并将控件拖曳至该外框b.使用While循环，禁用自动索引c.使用For循环，启用自动索引d.使用初始化数组函数3)簇控件的优点是？a.通过簇按照逻辑组合相关数据元素b.簇可增加子VI连线板接线端的数量c.簇可减少程序框图上的连线混乱d.A和Be.A和C4)执行下列代码后，最大值和最大索引分别是多少？a.7, 3b.7, 4c.1, 5d.6, 05)下列哪个函数按照元素的自有标签组合簇元素？a.按名称解除捆绑b.解除捆绑c.按名称捆绑d.捆绑6)下图显示的函数是？a.解除捆绑b.按名称解除捆绑c.捆绑d.按名称捆绑7)下图中“数组大小”的输出是？a.一维数组{2, 3}b.一维数组{3, 2}c. 2d.以上均不正确8)选择连接输入时，程序框图上“创建数组”函数的输出是？a.一维数组{1, -4, 3, 7, -2, 6}b.一维数组{1, 7, -4, -2, 3, 6}c.二维数组{{1, -4, 3, 0}, {7, -2, 6}}d.二维数组{{1, -4, 3}, {7, -2, 6}}9)未选择连接输入时，程序框图上“创建数组”函数的输出是？a.一维数组{2, 4, 7, 6, 3}b.一维数组{6, 3, 2, 4, 7}c.二维数组{{2, 4}, {6, 3}}d.二维数组{{2, 4, 7}, {6, 3, 0}}10)减法运算的结果是？a.一维数组{5, 7, 1, 5}b.一维数组{5, 12, 1, 14}c. 一维数组{14}d. 一维数组{14, 7, 1, 14}11)关于下图的表述，正确的是？a.自动索引已禁用b.For循环仅输出生成的第10个值c.For循环的输出为包含10个元素的一维数组d.A和Be.A和C12)执行下列代码后，最小值和最小索引分别是多少？a.0, 5b.0, 7c.10, 5d.0, 613)关于下图的表述，不正确的是？a.由于已启用自动索引，无需连接总数(N)接线端b.输入数组元素中每次有一个元素进入循环c.输出数组与输入数组的大小相同d.如在For循环右侧禁用自动索引，输出仍为一维数组e.以上均正确14)加法运算的结果是？a.一维数组{20, 4, 7}b.一维数组{20, 12, 15}c. 一维数组{12, 4, 15}d. 一维数组{20}15)允许同时包含输入控件和显示控件的是？a.数组b.簇c.A和Bd.以上均不正确16)以下关于数组索引的表述，不正确的是：a.索引可用于访问数组中特定元素b.二维数组包含列索引和行索引c.索引范围为0至n-1d.索引范围为1至n17)以下关于数组常量的表述，不正确的是：a.程序框图中创建的数组常量，在前面板中不可见b.无法调整数组常量的大小以包含多个元素c.允许复制并拖曳前面板上的现有数组至程序框图，以创建相同类型的常量d.数组常量可执行所有的数组操作18)数组传递至循环结构时，使用For循环的优势是？a.For循环允许在结构边框调整数组大小b.For循环允许在结构边框自动初始化数组c.遍历数组时For循环可获取最佳性能d.默认情况下For循环允许自动索引数组19)关于数组和簇区别的表述，正确的是？a.无法通过簇将数据传递至子VI，但可以使用数组b.数组无法包含显示控件和输入控件，但簇可包含两种控件c.数组元素为有序，而簇的元素为无序d. 簇可包含多种数据类型，而数组仅允许包含一种数据类型20)以下哪个簇函数的输出接线端数量仅取决于输入簇的元素数量？a.按名称解除捆绑b.解除捆绑c.按名称捆绑d.捆绑21)“索引数组”函数：a.返回单个元素或从指定索引开始的n维数组的子数组b.返回数组中各个维度的元素个数c.连接多个数组或将元素添加至n维数组d.查找元素并返回元素索引22)执行下列代码后，子数组中的结果是？a.一维数组{8, 5, 7}b.一维数组{10, 8, 5}c.一维数组{10, 8, 5, 7}d.一维数组{7, 10, 8, 5}23)“数组大小”函数：a.仅支持一维数组并返回该数组大小b.支持n维数组并返回每个维度的大小c.支持空的一维数组并允许用户设置数组大小d.支持空的n维数组并允许用户设置每个维度的大小24)执行下列代码后，输出数组中的结果是？a.一维数组{6, 3, 5, 7, 9, 1}b.一维数组{6, 7, 9, 1}c.一维数组{4, 6, 3, 5, 7, 9, 1}d.一维数组{4, 7, 9, 1}25)执行下列代码后，输出数组中的结果是？a.一维数组{2, 4}b.一维数组{5, 3}c.一维数组{2, 5, 1}d.一维数组{4, 3, 0}26)执行下列代码后，初始化数组中的结果是？a.一维数组{3, 3, 3, 3}b.一维数组{4, 4, 4}c.一维数组{3, 4}d.一维数组{4, 3}27)簇函数：a.允许将多种数据类型组合为逻辑结构b.在前面板中通过图表或图形表示数据c.用于在程序框图中区分数据类型d.在前面板中按数据类型区分数据对象28)关于簇的表述，正确的是？a.簇中放置的第一个对象为元素0b.簇中放置的第一个对象为元素1c.如在簇中删除一个元素，必须手动调整元素的顺序d.簇元素的顺序取决于外框中的物理位置29)执行下列代码后，“索引数组”输出的数据类型是？a.双精度数组b.双精度c.整型(I32)数组d.整型(I32)30)以下哪种方法不适用于创建二维数组：a.在前面板中右键单击现有一维数组，在快捷菜单中选择添加维度b.使用两个嵌套的For循环并启用自动索引c.使用定位工具调整索引显示的大小d.在前面板上放置数组，并将另一个数组拖放至该数组31)簇中元素顺序未知时，通过以下哪个函数可替换现有簇中的元素？a.按名称解除捆绑b.解除捆绑c.按名称捆绑d. 捆绑32)下列数组相加后，得到的结果是？a.一维数组{80, 20, 40, 10, -60}b.一维数组{120, 30, -60}c.一维数组{120, 30}d.二维数组{{120, 90, 20}, {60, 30, -40}}33)下列数组相减后，得到的结果是？a.一维数组{-25, 25, 50}b.一维数组{-25, 25}c.二维数组{{-25, -50, -50}, {50, 25, 25}}d.一维数组{75, -50, 25}34)以下表述不正确的是？a. 允许创建包含簇的簇b. 允许创建包含数组的数组c. 允许创建包含数组的簇d. 允许创建包含簇的数组e. 以上均正确35)执行下列代码后，“创建数组”函数的输出是？a.一维数组{4, 8, 3, 3, 6, 4}b.一维数组{4, 2, 3, 6, 4}c.二维数组{{4, 8, 3}, {3, 6, 4}}d.二维数组{{4, 2, 0}, {3, 6, 4}}1)下列哪种图表更新方式用垂直线分割新旧数据进行比较（类似于心电图仪EKG）？a.带状图表b.示波器图表c.扫描图表d.分步图表2)下列哪种图表更新方式从左至右绘制数据，然后清除图表的历史数据并绘制新的数据？a.带状图表b.示波器图表c.扫描图表d.分步图表3)下列哪种图表更新方式从左至右在图表中滚动显示运行数据？a.带状图表b.示波器图表c.扫描图表d.分步图表4)哪种组合适用于下列表述？__________可显示最新写入的值数组， ___________ 周期性更新历史数据。
CLAD模拟试题.doc
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Q1:關於LabVIEW 程式執行程序，下列何者正確？(請選出所有正確的敘述)A.程式執行順序由控制元件的流程(Control Flow) 所決定B.程式各元件須等到所有資料輸入節點後，才會執行並將資料輸出至端點C.程式執行順序由程式框圖的左邊依序執行到右邊D.通過程式各元件節點的資料流將決定程式執行順序Q2:下列For Loop 將循環幾次？A.3B.4C.5D.6Q3:使用者產生了共100 個資料點，且不平均放置於一段時間之內。
若維持此不平均的擷取點，則下列何項指示元最適於顯示資料？A.Waveform ChartB.Waveform GraphC.XY GraphD.Intensity GraphQ4:下列何項函式可以將浮點數的數值轉換為帶有小數點的字串？A.B.C.D.Q5:若下列程式一開始執行時Random 不更新，當使用者按下Start 按鍵，Random 才開始每1 秒更新一筆亂數，則Initial Time 跟Start Time 應設定成何值，程式執行才會有上述功能？A.Initial Timeout = 1000, Start Timeout = -1B.Initial Timeout = -1, Start Timeout = 1000C.Initial Timeout = 1000, Start Timeout = 0D.Initial Timeout = 0, Start Timeout = 1000Q6:針對下列Producer/Consumer 程式架構，何者敘述正確？A.Consumer Loop的迴圈更新時間為Producer Loop的兩倍B.兩個迴圈之間以Wait Time 函數的數值來同步化C.兩個迴圈之間以Dequeue Element 的Timeout 的數值來同步化D.兩個迴圈之間以LabVIEW 內部時序來進行同步化Q7:將Numeric 設為10 並執行下列程式碼，則程式結束後Numeric 和Result 分別顯示何值？A.Numeric = 2 , Result = 2B.Numeric = 2 , Result = 1C.Numeric = 12 , Result = 12D.Numeric = 12 , Result = 11Q8:執行程式5 秒後按下Latch When Release 按鍵，等待3 秒放開Latch When Release 按鍵，接著經過2 秒後按下Switch When Pressed 按鍵，等待 5 秒放開Switch When Pressed 按鍵，請問Boolean 顯示器於執行程式後7 秒和12 秒時分別顯示何值？A.False, FalseB.False, TrueC.True, FalseD.True, TrueQ9:下列何者變數的使用可避免因程式事件時序的不確定而導致的競賽狀態(Race Condition)？A.區域變數(Local Variable)B.全域變數(Global Variable)C.共用變數(Shared Variable)D.功能型全域變數(Functional Global Variable)Q10:何項方程式等於下列程式碼？A.x=√a×((a+b)2−(c−1))B.x=√a×((c−1)−(a+b)2)C.x=√a×((a+b2)−(c−1))D.x=√a2×((a+b)2−(c−1))Q11:假設啟動了自動錯誤處理(Automatic error handling) 功能，則LabVIEW 是否會於執行下列程式碼結束時顯示錯誤?A.否，此VI 將不會停止B.否，因為Simple Error Handler.vi 將會繼續記錄後續錯誤C.是，因為Merge Errors 函式將只會顯示首次錯誤D.是，但因為Merge Error 函式會收集全部錯誤，所以LabVIEW 將顯示錯誤對話框達2 次Q12:執行下列VI 之後，Data指示元將顯示何值？A.(Data x 5) + 2B.(Data + 2) x 5C.Data + 2D.無法確認Q13:「Wait (ms)」與「Wait Until Next ms Multiple」函式行為的差異是？A.首次呼叫「Wait Until Next ms Multiple」的時間延遲,可能短於接至函式輸入端點的特定ms 秒數B.除非完成該程式碼區段的其他所有函式,「Wait (ms)」函式才會開始計時作業C.若某架構已包含「Wait Until Next ms Multiple Function」函式,則可於獨立執行緒中執行D.「Wait (ms)」函式可讓迴圈不致佔用100% 的CPU 資源;「Wait Until Next ms Multiple」則無此項功能Q14:執行下列程式碼而發生錯誤的原因為何？A.檔案路徑並未接至Open/Create/Replace File 函式的輸入B.未將函式間的錯誤叢集接線C.以錯誤存取而開啟檔案File opened with the incorrect accessD.以上皆是Q15:Q15:將Boolean 控制元設定為Latching When Released。
2015年硕士学位研究生入学资格考试GCT英语模拟试题及详解（一）（二）【圣才出品】
2015年硕⼠学位研究⽣⼊学资格考试GCT英语模拟试题及详解（⼀）（⼆）【圣才出品】第三部分模拟试题及详解2015年硕⼠学位研究⽣⼊学资格考试GCT英语模拟试题及详解（⼀）第四部分：外语运⽤能⼒测试（英语）(50题, 每⼩题2分, 满分100分)Part I Vocabulary and StructureDirections: There are ten incomplete sentences in this part. For each sentence there are four choices marked A, B, C and D. Choose the one that bestcompletes the sentence. Mark your answer on the ANSWER SHEET with asingle line through the center.1. If you disagree with her, she is ______ to get annoyed.A. liableB. reliableC. memorableD. moral【答案】A【解析】句意：如果你不同意她，她很容易变得恼怒的。
liable易于的；reliable可靠的；memorable难忘的；moral道德的。
2. Though they disagreed on details, they were in ______ agreement over the plan.B. steadyC. stableD. sticky【答案】A【解析】句意：虽然他们在细节上有分歧，但对该计划达成了实质性的⼀致。
因此，应选择substantial。
3. The hole was so large that water poured in much faster than it could be ______ out.A. dumpedB. jumpedC. lumpedD. pumped【答案】D【解析】句意：这个洞如此⼤，以致于⽔注⼊的速度远⼤于抽出的速度。
CLAD Sample Exam-1
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1._____2._____3._____4._____5._____6._____7._____8._____9._____10._____11._____12._____13._____14._____15._____16._____17._____18._____19._____20._____21._____22._____23._____24._____25._____26._____27._____28._____29._____30._____31._____32._____33._____34._____35._____36._____37._____38._____39._____40._____1.如要考虑状态图应用程序的扩展性，基本结构的最佳选择是？a.顺序结构b.条件结构c.公式节点d.面向对象的结构2.单击_________按钮可跳过程序框图上的节点，而不单步执行该节点。
a.单步步入b.单步步过c.单步步出d.单步调试3.下列关于属性节点的描述，正确的选项有哪些？（选择所有正确的选项）a.属性节点使用户可通过程序方式操控前面板对象。
b.属性节点可用于更新前面板的值。
c.一个前面板对象可有多个属性节点。
d.子VI中包含的属性节点使前面板始终加载至内存。
4.必须从子VI中控制顶层VI的一个前面板控件。
必须传递什么到子VI？a.控件的属性b.控件的方法c.控件的引用d.控件的数据类型5.VI执行后，值输出显示控件显示的值是多少？a.0b. 4c. 5d. 66.在条件结构的假(FALSE)分支的代码中设置断点。
如执行条件结构的真(TRUE)分支，VI执行会暂停吗？a.会b.不会7.哪个属性节点改变子VI中数字数值控件的文本颜色属性？a.b.c.d.8.哪种图表更新模式适合从左到右连续显示数据？a.带状图b.示波器图c.扫描图d.步骤图9.下列哪项不符合数据流编程模型？a.移位寄存器b.隧道c.子VId.局部变量10.如有需要，可将顺序结构替换为下列哪项？a.事件结构b.For循环c.状态机d.While循环11.关于下列代码的陈述，正确的是？a.循环执行1次，循环显示控件显示值1b.循环执行1次，循环显示控件显示值0c.循环无限执行，程序必须中止d.循环不执行，循环显示控件显示值012.与下列代码等价的公式是？a.b.c.d.13.某VI启用了自动错误处理，并调用了一个未启用自动错误处理的子VI。
大学英语六级模拟试卷812(题后含答案及解析)
大学英语六级模拟试卷812(题后含答案及解析)题型有：1. Writing 2. Reading Comprehension (Skimming and Scanning) 3. Listening Comprehension 4. Reading Comprehension (Reading in Depth) 5. Cloze 8. TranslationPart I Writing (30 minutes)1．For this part, you are allowed 30 minutes to write a short essay entitled Be a Child’s Slave? You should write at least 150 words following the outline given below：1．养孩子的压力越来越大，很多人成为“孩奴”2．有些父母坚持为孩子投资一掷千金，也有很多人对此不以为然3．我的看法Be a Child’s Slave?正确答案：Be a Child’s Slave? Many parents say that a child is a blessing, but the cost of raising one can be a curse. They list the imported milk powder and diapers, luxurious private kindergartens, after-school courses such as piano and drawing, and even overseas further education. It is undeniable that the rising strain has made some parents become children’s slaves. These parents take it for granted that to bring up a child is to offer him the best environment for growth. They never hesitate to spend money on their children so that their offspring would not lose at the starting line. Not having enough time to accompany their children, they hope to compensate them with expensive commodities. However, many people argue that parents should not always consider the child as their first priority. What’s more, it is sensible to keep expenses within our financial capacity. In my opinion, parents who have become slaves to their children are harboring unrealistic expectations on their children and pursuing unreasonable consumption concepts. As a matter of fact, what a child needs most and what matters most to his growth are nothing but parents’love.Part II Reading Comprehension (Skimming and Scanning) (15 minutes)Directions: In this part, you will have 15 minutes to go over the passage quickly and answer the questions attached to the passage. For questions 1-4, mark：Y (for YES) if the statement agrees with the information given in the passage;N (for NO) if the statement contradicts the information given in the passage;NG (for NOT GIVEN)if the information is not given in the passage.Intellectual Property The phrase intellectual property (IP)refers to the bundle of legal rights that arise from the creative genius of the human mind. IP rights play an important role in the economic prosperity of a country and serve as a motivating force for creative individuals to share their genius with society. Like real and personal property rights protect one’s ownership interest in tangible (有形的)objects, such as land and automobiles, IP rights protect one’s ownership interest in intangible objects, such as the idea behind an invention, the music score for aBroadway play and the name or logo used to brand a product. Without enforcement of these rights in the law, it would be difficult for society to prosper and grow. In this article, you will learn what intellectual property rights are and the differences between its various forms. General Introduction When most people think of intellectual property rights, patents, trademarks and copyrights come to mind. This core set of IP rights reward and protect the creative works of inventors, authors, owners and sellers of goods and services in the marketplace. While the legal principles that underlie each of these rights are distinct, they each share a common set of principles. An award of patent, trademark or copyright protection requires a delicate balance between the interests of the inventor or author and the interest of society as a whole. This balance is very much like the tradeoff required by zoning laws, which attempt to protect the ownership interest and exclusive right to use that a land owner has with society’s interest in the limited use of the owner’s land for society’s greater good. Public utility easements and right of ways are examples of this balance. The grant of a patent on an important invention of a lifesaving drug represents a similar set of tradeoffs. Is it fair to the inventor to allow society free access to the patented drug? Is it fair to society to be denied access for its greater good? It is the role of intellectual property law to harmonize these seemingly conflicting interests. Intellectual property rights also foster a competitive marketplace. They do so by encouraging disclosure of innovation through protecting the fruits of that innovation for a period of time. Disclosure allows others to build and improve upon prior innovation so that the state of the art continues to evolve and develop. Without the benefits provided by intellectual property protection, the marketplace would not operate effectively. Imagine what the world would be like if every competitor had to continuously “reinvent the wheel” rather than being able to refine and improve upon the works of others. Finally, intellectual property rights are regional in nature and the conditions of their grant and enforceability are governed by the laws of each jurisdiction (管辖区域). A US patent can be only granted and enforced in accordance with the laws of the United States. A trademark can only be registered and enforced in Canada in accordance with the laws of Canada, and a copyright can only be registered and enforced in Mexico in accordance with its laws. While there is a desire to be somewhat uniform and consistent, countries have different approaches to intellectual property rights protection. Variations in the procedure for obtaining IP rights account for a large percentage of these difference, rather than the differences in the substantive rights granted in each country. The words “patent”and “trademark”are often used interchangeably. Many times, we hear that a patent is used to protect a logo and that a trademark is used to protect an invention, and vice versa. While patents and trademarks may be associated with the same product, the two words have very different meanings and refer to very different forms of intellectual property rights. They can seldom be used interchangeably, as the underlying rights that each protects is quite different in nature. “What Is a Patent? In general, a patent is used to protect the intellectual property rights associated with the design of a product or process. US patents are issued by the United States Patent and ‘Trademark Office and are enforceable only within the US and its possession. A US patent has no effectoutside the US. A patent gives the patent owner the “exclusive right”to stop others from making, using, selling or offering for sale the product, or process of making the product, that is described by the. patent claims.; It is important to note that a patent does not give the patent owner the right to exploit the patented invention himself. The patent owner has only the “exclusive right” to stop others from doing so.. In other words, just because you obtain a patent on your product does not mean jthat you can actually use the product. You may be blocked by an earlier patent owner who exercises the “exclusive right” granted to, him under his patent. This is an important distinction and the following example will help to explain it. Suppose that the invention covered by your patent is a chair with four legs, a seat, a back and a pair, of rockers—a rocking chair. Under your patent, you have the exclusive right to, stop others from makings using, selling or offering for sale your patented rocking chair. Let’s assume, however, that the rockers on your rocking chair are unique and are covered by an earlier patent to someone else. The rocker patent,owner has the exclusive right under his patent to stop others (including you)from using his patented.rockers. Your use of the patented rockers on your rocking chair would constitute infringement (侵权)of the rocker patent. So while you received a patent for your rocking chair, you will not be able to actually make, use, sell or offer for sale the chair without first obtaining permission from the rocker patent owner. The rocker patent owner is not required to give you permission, however, and can keep your rocking chair off the market if he chooses to do so. It might make better sense, of course, for the rocker patent owner to participate in your success by giving his permission in exchange for a licensing fee. The term for a patent is 20 years from the filing date of the patent application from which leads to the patent. What Are Trademarks? Like patents, trademark registrations in the US are issued by the United States Patent and Trademark Office. While a patent protects a product from unauthorized copying through the patent owner’s exclusive right to stop others from making, using, selling or offering for sale the patented product, a trademark addresses the need for product identification, or branding, among consumers of the product. Thus, a trademark has nothing to do with preventing a product from being copied. That is the role of a patent. The United States Patent and Trademark Office defines a trademark as any word, name, symbol, or devipe, or any combination, used, or intended to be used, in commerce to identify and distinguish the goods of one manufacturer or seller from goods manufactured or sold by others, and to indicate the source of the goods. In short, a trademark is a brand name. What Is a Copyright?A copyright protects the expression of an idea. Unlike a patent which protects the idea itself, the copyright protects only the expression. The idea of the chair with four legs discussed above can be protected by a patent. The expression of that idea through drawings, pictures and words can be protected by a copyright. In order to qualify for copyright protection, a work must be original to the author. To be original, the work: (1)must have been independently created by the author rather than being copied from other work(s)and, (2)must have at least a minimal degree of creativity. If these two conditions are not met, the work will not qualify as being original and is not entitled to copyright protection. However, a work still qualifies for copyright protection evenif it includes non-original elements. For example, if an author rearranges non-original elements in an original way, the compilation will be considered to be original and qualified for copyright protection. Depending on when the work was created, the period of copyright protection begins when the work is created and terminates 70 years after the death of the author.2．Which of the following do IP rights protect?A．Land.B．Automobile.C．Broadway.D．Logo.正确答案：D解析：细节辨认题。
专业英语四级(完形填空)模拟试卷22(题后含答案及解析)
专业英语四级（完形填空）模拟试卷22(题后含答案及解析)题型有： 3. CLOZEPART III CLOZE (15 MIN)Directions: There are 20 blanks in the following passage. Decide which of the choices given below would best complete the passage if inserted in the corresponding blanks.Crime plagues our society, almost all around us in our daily lives. Daily we hear many instances of【C1】______crimes such as murders, robberies, and rapes. However, there is another【C2】______ of crime known as “white collar” crime. A common conclusion has been【C3】______ that both street and white collar crime have severe consequences. Street crime tends to inflict more【C4】______ harm upon people, while white collar crime is financially more【C5】______. All the【C6】______is given to street crime. Our politicians tend to spend more money on the【C7】______system to solve street crime. There are more cops, more judges, and definitely more jails and prisons.【C8】______is white collar crime heard of through the media. The fact that people are murdered by unsafe working conditions and products is acceptable, 【C9】______it’s unacceptable when people are murdered with a gun, knife, or weapon. As well as supporting isolation from other people, such policies cause【C10】______and stereotyping. Pictures of “criminals”police have in their minds are male people of【C11】______, ages 14-25. Other government programs beside justice system are also【C12】______ with all funding spent on street crime such as the U. S. education system. Kids tend to 【C13】______ from school for life on the streets. With social services being 【C14】______ and massive prisons being constructed, many Americans have no other option but to stay in【C15】______ and what is more, no healthcare as well. Though white collar crime is 90 【C16】______more costly, no one seems to be concerned about how to【C17】______ the problem, because many of the ones who【C18】______white collar crimes have the power to decide whether law 【C19】______ will deal with white collar crime. The decaying of our country’s structure is inevitable when the【C20】______ have the power and “ justice” in America is only a farce(闹剧).1．【C1】A．roomB．streetC．horribleD．fatal正确答案：B解析：语义衔接题。
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Q1:關於 LabVIEW 程式執行程序，下列何者正確(請選出所有正確的敘述)A.程式執行順序由控制元件的流程 (Control Flow) 所決定B.程式各元件須等到所有資料輸入節點後，才會執行並將資料輸出至端點C.程式執行順序由程式框圖的左邊依序執行到右邊D.通過程式各元件節點的資料流將決定程式執行順序Q2:下列 For Loop 將循環幾次A.3B.4C.5D.6Q3:使用者產生了共 100 個資料點，且不平均放置於一段時間之內。
若維持此不平均的擷取點，則下列何項指示元最適於顯示資料A.Waveform ChartB.Waveform GraphC.XY GraphD.Intensity GraphQ4:下列何項函式可以將浮點數的數值轉換為帶有小數點的字串A.B.C.D.Q5:若下列程式一開始執行時 Random 不更新，當使用者按下 Start 按鍵， Random 才開始每 1 秒更新一筆亂數，則 Initial Time 跟 Start Time 應設定成何值，程式執行才會有上述功能A.Initial Timeout = 1000, Start Timeout = -1B.Initial Timeout = -1, Start Timeout = 1000C.Initial Timeout = 1000, Start Timeout = 0D.Initial Timeout = 0, Start Timeout = 1000Q6:針對下列 Producer/Consumer 程式架構，何者敘述正確A.Consumer Loop的迴圈更新時間為Producer Loop的兩倍B.兩個迴圈之間以 Wait Time 函數的數值來同步化C.兩個迴圈之間以 Dequeue Element 的 Timeout 的數值來同步化D.兩個迴圈之間以 LabVIEW 內部時序來進行同步化Q7:將 Numeric 設為 10 並執行下列程式碼，則程式結束後 Numeric 和 Result 分別顯示何值A.Numeric = 2 , Result = 2B.Numeric = 2 , Result = 1C.Numeric = 12 , Result = 12D.Numeric = 12 , Result = 11Q8:執行程式 5 秒後按下 Latch When Release 按鍵，等待 3 秒放開Latch When Release 按鍵，接著經過 2 秒後按下 Switch When Pressed 按鍵，等待 5 秒放開 Switch When Pressed 按鍵，請問 Boolean 顯示器於執行程式後 7 秒和 12 秒時分別顯示何值A.False, FalseB.False, TrueC.True, FalseD.True, TrueQ9:下列何者變數的使用可避免因程式事件時序的不確定而導致的競賽狀態 (Race Condition)A.區域變數 (Local Variable)B.全域變數 (Global Variable)C.共用變數 (Shared Variable)D.功能型全域變數 (Functional Global Variable)Q10:何項方程式等於下列程式碼A.B.C.D.Q11:假設啟動了自動錯誤處理 (Automatic error handling) 功能，則 LabVIEW 是否會於執行下列程式碼結束時顯示錯誤A.否，此 VI 將不會停止B.否，因為 Simple Error 將會繼續記錄後續錯誤C.是，因為 Merge Errors 函式將只會顯示首次錯誤D.是，但因為 Merge Error 函式會收集全部錯誤，所以 LabVIEW 將顯示錯誤對話框達 2 次Q12:執行下列 VI 之後，Data指示元將顯示何值A.(Data x 5) + 2B.(Data + 2) x 5C.Data + 2D.無法確認Q13:「Wait (ms)」與「Wait Until Next ms Multiple」函式行為的差異是A.首次呼叫「Wait Until Next ms Multiple」的時間延遲,可能短於接至函式輸入端點的特定 ms 秒數B.除非完成該程式碼區段的其他所有函式,「Wait (ms)」函式才會開始計時作業C.若某架構已包含「Wait Until Next ms Multiple Function」函式,則可於獨立執行緒中執行D.「Wait (ms)」函式可讓迴圈不致佔用 100% 的 CPU 資源;「Wait Until Next ms Multiple」則無此項功能Q14:執行下列程式碼而發生錯誤的原因為何A.檔案路徑並未接至 Open/Create/Replace File 函式的輸入B.未將函式間的錯誤叢集接線C.以錯誤存取而開啟檔案 File opened with the incorrect accessD.以上皆是Q15:Q15: 將Boolean 控制元設定為 Latching When Released。
若使用者按下 Boolean 控制元，則下列何項程式碼片段 (Snippet) 所回傳的Count 將顯示次數A.B.C.D.Q16:下列何項敘述錯誤A.subVI 的接頭面板 (Connector pane) 將定義輸入/出的接線處B.subVI 接頭面板 (Connector pane) 端點的顏色,即對應其連接的資料型態C.subVI 必具備 1 組圖示與接頭面板 (Connector pane)D.可透過 Functions Palette 而編輯 SubVI 圖示Q17:建置功能型全域變數 (Functional Global Variable) 時，下列何者為非必要A.只執行一次的迴圈 (While Loop)B.為初始化的移位暫存器 (Shift Register)C.條件結構 (Case Structure)D.枚舉型數值控制元 (Enumerated Type Control)Q18:對 subVI 而言，若「Context Help」視窗中的輸入名稱是以粗體顯示，則下列何項條件正確（請選出所有適用的敘述）A.輸入值必為純數 (Scalar)B.此輸入為建議使用,並非必要輸入C.此輸入為必要輸入D.若此輸入並未接線,則原 VI (Calling VI) 將中斷Q19:下列何者為 Dequeue Element 函式的輸出A.[0 1 2 3 4]B.[4 3 2 1 0]C.0D.4v1.0 可编辑可修改Q20:若 START UP VI 回報錯誤,則狀態機的行為是A.轉為關機 (Shutdown) 狀態B.轉為待機 (Idle) 狀態C.停止並顯示錯誤對話框D.重新執行開機 (Startup) 狀態Q21:執行下列程式碼之後， Array Out 顯示為何A.[]312B.[]123C.[]3 1D.[]1 3Q22:在頂層 VI 上有 1 組人機介面控制元，且必須透過 subVI 才能控制之。
則必須將何項傳送至此subVIA.控制元的屬性 (Property)B.控制元的方法 (Method)C.控制元的參考 (Reference)D.控制元的資料型態 (Data Type)Q23:針對屬性節點 (Property Nodes) 的預設行為，下列何項正確 (請選出所有適用的敘述)A.屬性節點 (Property Nodes) 可讓使用者透過程式設計的方式,進而設定人機介面物件的屬性B.屬性節點 (Property Nodes) 可更新人機介面物件中的數值C.單一人機介面的物件可使用超過 1 組的屬性節點 (Property Nodes)D.若屬性發生錯誤，則 LabVIEW 將處理其他屬性，並回報第一個發生的錯誤Q24:下列選項中，何時可使用 Probe 工具取代 BreakpointsA.要減緩 VI 速度,並於接線中顯示數值B.呈現資料的流向C.不需暫停執行，亦可檢查接線上的資料D.於執行程序期間觀看 SubVIv1.0 可编辑可修改Q25:下列何項可令人機介面上的 LED 指示元顯示紅黃綠三種顏色A.屬性節點 (Property Node)B.呼叫節點 (Invoke Node)C.區域變數 (Local Variable)D.全域變數 (Global Variable)Q26:執行下列 VI 之後，人機介面上的 Array 指示元顯示為何A.⎥⎦⎤⎢⎣⎡4332B.⎥⎥⎥⎦⎤⎢⎢⎢⎣⎡543432C.⎥⎦⎤⎢⎣⎡544332D.⎥⎥⎥⎦⎤⎢⎢⎢⎣⎡654543432Q27:__________ 所顯示的完整波形將覆寫已儲存的資料;而 ___________ 將定期更新資料,並保有先前已儲存資料的歷史記錄。
A.Graphs; ChartsB.Charts; PlotsC.Plots; GraphsD.Charts; Graphsv1.0 可编辑可修改Q28:VI 是透過接頭面板 (Connector pane) 上的「Error In」與「Error Out」端點而呼叫 subVI。
若已啟動自動錯誤處理 (Automatic error handling) 功能，且 subVI 回傳錯誤，則應如何避免 LabVIEW 顯示錯誤對話框A.點選 Tools » Options 功能表，並從 Block Diagram 分類中取消勾選Enable automatic errorhandling in new VIsB.在 VI Properties 中找到 Category Execution，取消勾選Allow DebuggingC.將 subVI 的「Error Out」端點,連至原 VI (Calling VI) 中的通道 (Tunnel)、端點 (Terminal),或指示元 (Indicator)D.對 subVI 按下滑鼠右鍵，再勾選Disable automatic error handlingQ29:下列程式圖中的 While Loop 將循環幾次A.0B.1C.2D.無限次Q30:下列何項不是 LabVIEW 既有的除錯功能A.停止值 (Stop Values)B.執行標示 (Highlight Execution)C.單步執行 (Single stepping)D.中斷點 (Breakpoint)Q31:下列何項程式碼片段 (Snippet) 的功能等於此序列架構A.B.C.D.Q32:下列程式碼的 While Loop 將執行幾次A.0B.1C.2D.無限次Q33:應如何記載程式碼說明 (Document) VI，才能讓滑鼠游標移至 VI 圖示上方時，可於「Context Help」視窗中顯示該 VI 的說明A.在 VI Properties 對話框中設定 VI Description 欄位B.在「Show Context Help」視窗中鍵入訊息C.於人機介面上建立名為「VI Description」的自由標籤 (Free label)D.編輯 LabVIEW 的輔助說明檔案Q34:當選定「Concatenate Inputs」的設定，則 Build Array 輸出的結果為何A.B.C. D.Q35:在執行下列程式碼之後，Result 指示元將顯示何字串A.12345B.01234C.123456D.012345Q36:在執行下列程式碼之後，Result 顯示元將顯示何值A.0B.3C.4D.迴圈將不會停止Q37:下列三種資料型態不相同的數值相乘後的輸出結果資料型態為何v1.0 可编辑可修改A.Double Precision Floating Point, DBLB.Long Integer, I32C.Unsigned Long Integer, U32D.Unsigned Long Long Integer, U64Q38:執行下列 VI 之後，Result 指示元將顯示何值A.5B.7C.12D.36Q39:何時透過設置全域變數 (Global Variable) 來傳送資料最為適當A.不同電腦執行的 VI 之間B.主要 VI 與 subVI 之間C.平行的 While Loop 之間D.序列架構 (Sequence Structure) 的框架 (Frame) 之間v1.0 可编辑可修改Q40:若要定時監控使用者介面的更新，應於迴圈中使用下列何項時序函式A.B.C.D.解答1.B, DA, C : 程式執行順序由資料流決定2. B此For Loop設置有Conditional Terminal，當執行到第四次時輸入迴圈的4 > i(3)，未滿足繼續迴圈的條件故即停止迴圈3. C均勻分布資料用Waveform Chart或Waveform Graph顯示；不均勻分布資料只能用XY Graph來顯示4. DFormat Into String可將任意類型資料轉換為字串5. BTimeout設為 -1 時，不會發生Timeout事件；當觸發Start按鍵開關事件將Timeout設為1000時，每隔1000ms會觸發Timeout事件來更新亂數6. D由於Producer每100ms丟入一筆資料，故Consumer不會發生200ms的Timeout，而是依LabVIEW內部時序同步每100ms接收一筆資料7. DProperty Node由最上層開始依序執行，第一個Property Node會先將Numeric預設的10讀出，然後將0寫進Numeric；第二個Property Node會先將前面讀出的10加1寫入Numeric，接著Result再讀出Numeric 的數值為11，最後將11再加1寫入Numeric中，故程式執行後的Numeric讀值為128. BLatch When Released需等到按下按鍵後放開，其狀態才會轉為True，並在程式讀取後回復至False。