《C++程序设计教程 第2版》教学素材习题08答案

习题8答案1．参考答案#include <iostream.h>#include <iomanip.h>#include <string.h>#define N 4struct student{char num[10];char name[20];int sc;};void main(){void Input(student studs[],int n);void Output(student studs[],int n);int Max(student studs[],int n);int i;student studs[N];Input(studs,N);i=Max(studs,N);Output(studs,N);cout<<"×î¸ß·ÖѧÉúµÄѧÉúÐÅϢΪ£º"<<endl;cout<<setw(10)<<studs[i].num<<setw(10);cout<<studs[i].name<<setw(10);cout<<studs[i].sc<<setw(10)<<endl;}void Input(student studs[],int n){int i;for(i=0;i<n;i++){cout<<"ÇëÊäÈëµÚ"<<i+1<<"¸öѧÉúµÄѧºÅ:";cin>>studs[i].num;cout<<"ÇëÊäÈëµÚ"<<i+1<<"¸öѧÉúµÄÐÕÃû:";cin>>studs[i].name;cout<<"ÇëÊäÈëµÚ"<<i+1<<"¸öѧÉúµÄ³É¼¨:";cin>>studs[i].sc;}}void Output(student studs[],int n)//×¢Ò⺯Êý¶¨ÒåµÄ·½·¨,Êä³ö½á¹ûÒªÕûÆë»®Ò»{int i;cout<<setw(10)<<"ѧºÅ"<<setw(10)<<"ÐÕÃû"<<setw(10)<<"³É¼¨"<<en dl;for(i=0;i<n;i++){cout<<setw(10)<<studs[i].num<<setw(10);cout<<studs[i].name<<setw(10);cout<<studs[i].sc<<setw(10)<<endl;}}int Max(student studs[],int n){int i,k;k=0;for(i=1;i<n-1;i++)if(studs[k].sc<studs[i].sc)k=i;return k;}2．参考答案#include <iostream.h>#include <ctype.h>int daytab[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};struct data{int year,month,day;}dt;int day_of_year(int year,int month,int day){int i,leap;leap=((year%4==0&&year%100!=0)||year%400==0);for(i=1;i<month;i++)day+=daytab[leap][i];return day;}void inver(char s[],int &year,int &month,int &day){int i=0;while(isdigit(s[i])){year=year*10+s[i]-'0';i++;}i++;while(isdigit(s[i])){month=month*10+s[i]-'0';i++;}i++;while(isdigit(s[i])&&s[i]){day=day*10+s[i]-'0';i++;}}void main(){char s[20];cout<<"输入日期（年-月-日）：";cin>>s;dt.year=0;dt.month=0;dt.day=0;inver(s,dt.year,dt.month,dt.day);cout<<s<<"是"<<dt.year<<"年的第"<<day_of_year(dt.year,dt.month,dt.day)<<"天"<<endl;}3．参考答案#include <iostream.h>#include <iomanip.h>#include <string.h>#define N 4struct student{char num[10];char name[20];int sc[5];int aver;};void main(){void Input(student studs[],int n);void Output(student studs[],int n);student studs[N];Input(studs,N);Output(studs,N);}void Input(student studs[],int n){int i,j;for(i=0;i<n;i++){cout<<"请输入第"<<i+1<<"个学生的学号:";cin>>studs[i].num;cout<<"请输入第"<<i+1<<"个学生的姓名:";cin>>studs[i].name;cout<<"请输入第"<<i+1<<"个学生的五门成绩:";for(j=0;j<5;j++)cin>>studs[i].sc[j];}}void Output(student studs[],int n){int i,j;cout<<setw(10)<<"学号"<<setw(10)<<"姓名"<<setw(10)<<"课程1";cout<<setw(10)<<"课程2"<<setw(10)<<"课程3"<<setw(10)<<"课程4"<<setw(10)<<"课程5"<<endl;for(i=0;i<n;i++){cout<<setw(10)<<studs[i].num<<setw(10);cout<<studs[i].name<<setw(10);for(j=0;j<5;j++)cout<<studs[i].sc[j]<<setw(10);cout<<endl;}}4．#include <iostream.h>#include <iomanip.h>#include <string.h>#define N 4struct address_list{char num[10];char name[20];char addr[80];int phonenum;char mobilenum[10];char email[30];};void main(){void Input(address_list studs[],int n);void Output(address_list studs[],int n);address_list studs[N];Input(studs,N);Output(studs,N);}void Input(address_list studs[],int n){int i;for(i=0;i<n;i++){cout<<"请输入第"<<i+1<<"个学生的学号:";cin>>studs[i].num;cout<<"请输入第"<<i+1<<"个学生的姓名:";cin>>studs[i].name;cout<<"请输入第"<<i+1<<"个学生的地址:";cin>>studs[i].addr;cout<<"请输入第"<<i+1<<"个学生的电话号码:";cin>>studs[i].phonenum;cout<<"请输入第"<<i+1<<"个学生的手机号码:";cin>>studs[i].mobilenum;cout<<"请输入第"<<i+1<<"个学生的E-mail地址:";cin>>studs[i].email;}}void Output(address_list studs[],int n){int i;cout<<setw(10)<<"学号"<<setw(10)<<"姓名"<<setw(10)<<"地址";cout<<setw(10)<<"电话号码"<<setw(10)<<"手机号码"<<setw(10)<<"E-mail地址"<<endl;for(i=0;i<n;i++){cout<<setw(10)<<studs[i].num<<setw(10)<<studs[i].name<<setw(10);cout<<studs[i].addr<<setw(10)<<studs[i].phonenum<<setw(10);cout<<studs[i].mobilenum<<setw(10)<<studs[i].email;cout<<endl;}}5．#include <iostream.h>#include <math.h>struct coordinate{double x;double y;double z;};void main(){void Print(coordinate x);coordinate Input();double distance(coordinate x,coordinate y);coordinate a,b;double dist;cout<<"请输入第1个点的坐标:"<<endl;a=Input();cout<<"请输入第2个点的坐标:"<<endl;b=Input();dist=distance(a, b);cout<<"第1个点的坐标:";Print(a);cout<<"第2个点的坐标:";Print(b);cout<<"这两点的距离为:"<<dist<<endl;}coordinate Input(){coordinate a;cout<<"请输入该坐标的x点:";cin>>a.x;cout<<"请输入该坐标的y点:";cin>>a.y;cout<<"请输入该坐标的z点:";cin>>a.z;return a;}void Print(coordinate a){cout<<"("<<a.x<<","<<a.y<<","<<a.z<<")"<<endl;}double distance(coordinate a,coordinate b){double dist;dist=sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)+(a.z-b.z)*(a.z-b.z));return dist;}6．参考答案#include <iostream.h>#include <iostream.h>struct complex{double real;double imag;};void main(){void Print(complex& x);void Input(complex& x);complex add(complex x,complex y);complex sub(complex x,complex y);complex x,y,z;cout<<"请输入第1个复数:"<<endl;Input(x);cout<<"请输入第2个复数:"<<endl;Input(y);cout<<"第1个复数为:";Print(x);cout<<"第2个复数为:";Print(y);z=add(x, y);cout<<"相加后的复数为:";Print(z);z=sub(x, y);cout<<"相减后的复数为:";Print(z);}void Input(complex& x){cout<<"请输入复数的实部:";cin>>x.real;cout<<"请输入复数的虚部:";cin>>x.imag;}void Print(complex& x){cout<<x.real;if (x.imag>0) cout<<'+';cout<<x.imag<<'i'<<endl;}complex add(complex x,complex y){complex z;z.real=x.real+y.real;z.imag=x.imag+y.imag;return z;}complex sub(complex x,complex y){complex z;z.real=x.real-y.real;z.imag=x.imag-y.imag;return z;}7．参考答案#include <iostream.h>void main(){int n;enum {sun,mon,tue,wed,thu,fri,sat}day;char weekday[7][7]={"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};cout<<"输入间隔天数：";cin>>n;day=sun;cout<<"今天是"<<weekday[day]<<","<<n<<"天后是"<<weekday[(day+n)%7];}8．#include <iostream.h>#include <iomanip.h>void main(){enum color {Red,Blue,Green};color i,j,k,pri;int n,loop;n=0;for(i=Red;i<=Green;i=color(int(i)+1))for(j=Red;j<=Green;j=color(int(j)+1))if(i!=j){for (k=Red;k<=Green;k=color(int(k)+1))if((k!=i)&&(k!=j)){n=n+1;cout<<setw(4)<<n;for(loop=1;loop<=3;loop++){switch(loop){case 1 : pri=i;break;case 2 : pri=j;break;case 3 : pri=k;break;default:break;}switch (pri){case Red: cout<<setw(10)<<"Red";break;case Blue: cout<<setw(10)<<"Blue";break;case Green: cout<<setw(10)<<"Green";break;default:break;}}cout<<endl;}}cout<<setw(5)<<n;}。