黑龙江省大兴安岭漠河县第一中学2019-2020学年高一上学期11月月考英语试卷
黑龙江省大兴安岭漠河县第一中学2018_2019学年高二英语上学期第一次月考试题
黑龙江省大兴安岭漠河县第一中学2018-2019学年高二英语上学期第一次月考试题时间90分钟满分120分第三部分：阅读理解(共20小题；每小题2分，满分40分)第一节：(共15小题，每小题2分，满分30分)阅读下列短文，从每题所给的四个选项(A、B、C和D)中，选出最佳选项AYour_body ,which_has_close_relations_with_the_food_you_eat，is the most important thing you own，so it needs proper treatment and proper nourishment (食物). The old saying “An apple a day keeps the doctor away.” is not as silly as some people think. The body needs fruit and vegetables because they contain vitamins. Many people take extra vitamins in pill form(丸剂), believing that these will make them healthy. But a good diet is made up of nutritive food and this gives all the vitamins you need. The body doesn't need or use extra vitamins, so why they waste money on them?In the modern Western world，many people are too busy to bother about eating properly. They throw anything into their stomachs，eating hurriedly and carelessly. The list of illnesses caused or made worse by bad eating habits is frightening.1．The sentence “Your body, which has close relations with the food you eat” really means ________.A. all kinds of food you eat can be made into your bodyB. your body is made up of the food you eatC. what you eat has a great effect on your healthD. the more you eat，the fitter you'll feel2．The old saying referred to in the passage tells us that______.A. eating apples regularly does lots of good to our healthB．the apple is the best among all kinds of fruitsC．apples can take the place of doctorsD．an apple is a sure cure for illness3．In the second paragraph, the writer tries to let us know________.A. our bodies need food，or we can't liveB．often eating apples is a good habitC．taking extra vitamin pills is completely uselessD．a good diet is of great importance to our health4．In the modern Western countries ________.A. people won't want to pay more attention to their eatingB．a list of people's illness are caused or made worse by bad eating habits C．people throw everything into their stomachs without chewing(咀嚼)D．people are only too busy to cook meals for themselvesBGetting a good education is more important today than ever before. It is the best thing you can do to build a better future for your children and yourself.Most children in Canada attend public schools. Public schools are completely founded by governments through tax (税收)income. Boys and girls attend the same school and share the same courses and classes. Schooling in Canada is provided in English and in French.The rest of Canadian children attend private schools, which are supported mainly by fees(费)paid directly by parents. Some private schools enroll (招收) only boys or girls.By law, children must attend school from age 5 to 16. Children are usually in school between 8:30 or 9:00 a. m. ，and 3:30 or 4:00 p. m. ，Monday through Friday, from September to the middle of June. There are several different levels in the Canadian education system. The first is called elementary schools. In most provinces elementary schools include kindergarten through Grade 7 or 8.From Grade 8 or 9 through 12 or 13，children go to secondary school or high school. High school students must take certain courses for several years, such as English or French and mathematics. Some courses help students get a job after they graduate from school. Other courses prepare students for college or university. In Canada，teenagers usually make these choices for themselves，with the advice of their teachers, guidance counselor (指导教师) and parents.Schools usually offer extra activities at the end of the normal school day. These include sports, games, music and clubs.Most elementary and high schools encourage parents to take part in school activities. Parents' nights are organized from time to time. These are chances for parents to discuss their children's progress with teachers. You may wish to bring a friend with you. After graduating from high school，many young adults continue their studies through postsecondary education.5．According to the passage，students in Canada can get education for free in ________.A. private schoolsB. universitiesC. public schoolsD. community(社区) college6．Which of the following statements is TRUE according to the passage?A. Most high school students choose their courses against their wills.B. The students do their afterclass activities all the afternoon.C. Parents are allowed to take part in school activities in the morning.D. If you don't send your fiveyearold child to school in Canada，you will break the law in Canada.7．Which of the following is NOT true according to the passage?A. There are only boys in some private schools.B．There are only boys in some public schools.C．There are both boys and girls in some private schools.D．There are both boys and girls in all public schools.CWe often hear people talking about a generation gap (代沟). The name is new, butthe idea isold. Young people and their parents don’t understand each other. The world has always kept changing. During the second century after Christ a wise man said, “Bury me on my face because in a little while everything will be turned upside down.”There has always been a gap between generations, but more people talk about it now. Old Mr. Ellis thinks he understands what has happened.“When I was a boy, I thought the world was a beautiful place. My life was very pleasant. But when I was older, I learned about people who were treated badly, people who didn’t have enough to eat. I wanted to help them, and I married a girl who wanted to help them, too. We went to meetings and talked a lot, but it didn’t seem to make much difference. ”“Our children grew up in a world at war. They didn’t know when the fighting would stop. They wanted their children to have nice clothes and toys. They didn’t want to think about the future. They thought nothing could be done about it.”“Now I have grandchildren, and they have their own ideas. They are trying to make the world better. They are trying to help other people. They’re making people listen to them. I am proud of their generation.”8. The wise man mentioned in the text told people to bury him on his face so that when everything is turned upside down he will _____.A. lie on his stomachB. lie on his backC. stand quietlyD. sit in peace9. Which generation did NOT want to do anything to make the world a better one?A. Mr. Ellis’ generationB. His c hildren’s generationC. His grandchildren’s generationD. None of the above.10. Which generation is/was more efficient in making the world better one?A. Mr. Ellis’ generation.B. His children’s generation.C. His grandchildren’s generati on.D. None of the above.11. What is the writer’s attitude towards the generation gap?A. Unacceptable.B. Awful.C. Funny.D. Common.DOnce there was a poor farmer and his farm belonged to(属于) a rich man. One day he brought a basket of apples to the rich man’s house. On the doorsteps, he met two monkeys dressed like children. They jumped onto the basket to eat the apples and threw some on the ground. The farmer politely took off his hat and asked the monkeys to get off. They obeyed(服从) and the farmer went into the house. He asked to see the rich man. A servant took him to the room where the rich man was sitting."I have brought you the basket of apples you asked for," he said."But why have you brought a half-empty basket?" the rich man asked."I met your children outside, and they stole(偷) some of the apples."12. Why did the farmer bring apples to the rich man? BecauseA. he was poorB. he liked the rich manC. his farm belonged to the rich manD. the rich man’s children liked apples13. What did the monkeys do when the farmer was on the doorsteps?A. They jumped and jumped.B. They played.C. They ran away.D. They ate some of the apples.14. The monkeys left the basket becauseA. they had thrown apples on the groundB. the farmer had politely asked them to get offC. they were afraid of the hatD. the farmer wa s angry wit h them15. How did the rich man feel when he saw the basket? He feltA. pleasedB. unhappyC. excitedD. moved第二节：(共5小题，每小题2分，满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
黑龙江省大兴安岭漠河县第一中学2019-2020学年高一语文下学期期末考试试题【含答案】
黑龙江省大兴安岭漠河县第一中学2019-2020学年高一语文下学期期末考试试题一、现代文阅读（36分）（一）论述类文本阅读（本题共3小题，9分）阅读下面的文字，完成1～3题。
文学批评大概是最勇于自我革新的文类。
一段时间以来，这一文类将革新重点放在“文体”上。
批评家们热衷于谈论“文章之道”，试图将文学批评从学术阵营拉到文学阵营中来。
因为，倘若没有风格，批评断然是不可能成为文学而只是文学的附属品，因而无法战胜时间。
在我刚刚开始学习批评写作的时候，就接受了诸如此类的教诲。
如果还不能写得好一点，就写得漂亮一点吧。
我叹服于别林斯基的气盛言宜，激动于桑塔格的锐利精致，感佩于李健吾的才华横溢。
对于我来说，他们都显示了“文章”的典范，展示了文学批评之美是多么迷人。
时至今日，在漫长试笔和不断试错之后，我终于认识到，“写得好”与“写得漂亮”之间，还是有着不言自明的距离。
倘若没有深邃思想，所有“漂亮”都不过是虚妄。
就好像好看的皮囊与有趣的灵魂并不一定永远合体，如果让我选择，我肯定会选择有趣的灵魂。
无法想象，别林斯基、桑塔格、李健吾们只擅长遣词造句，只提供空洞无物的“美文”，他们大约无法穿越时间和空间，投递到我们的文学生活中来。
是的，思想是文学批评的盐，是灵魂，是普罗米修斯盗来的火，也是文学批评赖以存续下去并诱使一代又一代杰出头脑投身其中的理由。
那么，思想又是什么呢？思想是对文学作为一门艺术的不断重新定义与发现。
思想还包括认识生活的能力，辨别现实生活与文学世界的关联与差别的能力以及将知识、情感与智慧结合在一起的能力。
由是，文学批评摆脱对他人文本的依附地位，获得了与他所评论的对象携手前行的资格，共同在这广袤的人世间探险，共同探究人类生活新的可能。
接下来需要追问的是，思想从何而来？思想需要广博的知识，需要披荆斩棘认识生活的勇气和能力，也需要理解言辞的智慧，特别是，它需要理论视野。
滥用理论固然是错误的，但如果完全放弃理论训练，丢掉理论透镜，文学批评可能沦为仅仅抒发个人情感的读后感。
黑龙江省大兴安岭漠河一中高一上学期11月月考数学试题(解析版)
2019-2020学年黑龙江省大兴安岭漠河一中高一上学期11月月考数学试题一、单选题 1．在中与终边相同的角有( )A ．个B ．个C ．个D ．个【答案】D 【解析】先写出与终边相同的角的表达式，然后对赋值，求得在范围内角的个数. 【详解】 与终边相同的角为.当时，，故在中与终边相同的角有个，所以选D.【点睛】本小题主要考查终边相同的角，考查任意角的概念以及周期性，属于基础题. 2．若α角与β的终边垂直，则α与β的关系是（ ） A ．90βα︒=+B ．90βα︒=±C ．90360()k k Z βα︒︒=++⋅∈D ．90360()k k Z βα︒︒=±+⋅∈【答案】D【解析】利用终边相同的角的关系直接求解 【详解】若角α与β的终边垂直，则90360()k k Z βα︒︒-=±+⋅∈，90360()k k Z βα︒︒∴=±+⋅∈.故选：D 【点睛】本题考查终边相同的角，是基本概念的考查 3．函数的单调增区间为（ ）A ．，B ．，C ．，D ．，【答案】C【解析】先将函数解析式化简整理，得到，再由，求解，即可得出结果.【详解】 因为，由可得， 即函数的单调递增区间为，.故选C 【点睛】本题主要考查正弦型函数的单调区间，熟记正弦函数的单调区间即可，属于常考题型.4．若cos()2πα+=cos2=α（ ） A ．23-B ．13-C ．13D ．23【答案】C【解析】本道题化简式子,计算出sin α,结合2cos 212sin αα=-,即可. 【详解】cos sin 2παα⎛⎫+=-= ⎪⎝⎭,得到sin α=,所以 211cos 212sin 1233αα=-=-⋅=,故选C.【点睛】本道题考查了二倍角公式,难度较小. 5．将函数1cos()26y x π=-图象向左平移3π个长度单位，再把所得图象上各点的横坐标缩短到原来的一半（纵坐标不变），所得图象的函数解析式是（ ）A ．cos(+)6y x π= B ．1cos 4y x = C ．cos y x = D ．1cos()43y x π=-【答案】C【解析】试题分析：函数1cos()26y x π=-图象向左平移3π个长度单位，得到11cos +=cos 2362y x x ππ⎡⎤⎛⎫=- ⎪⎢⎥⎝⎭⎣⎦，再把所得图象上各点的横坐标缩短到原来的一半（纵坐标不变）得到1cos 2cos 2y x x ==. 【考点】三角函数图象变换.【易错点晴】三角函数图象变换，关键在于不管怎么变，都是变x ，其它系数保留；熟记左加右减，并且要看清题意到底是谁变换成谁.本题中，平移的时候12是没有变到的，所以必须提取出来.另外，如果既平移，又伸缩，就必须确保每一次都是变x . 6．若(cos )cos3f x x =，则(sin 30)f ︒的值为（ ） A ．1 B ．－1C ．0D ．【答案】B【解析】试题分析：由已知可得(sin30)(cos60)cos1801f f ︒=︒=︒=-.【考点】本小题主要考查诱导公式的应用和函数值的求法，考查学生灵活的转化能力和运算求解能力.点评：解决本题的关键在于把sin30︒化成cos60︒，然后直接代入求解即可，如果先求函数解析式就会变得非常麻烦.7．在平面直角坐标系中，角的顶点与原点重合，始边与x 轴的非负半轴重合，终边过点，则（ ）A ．B ．C ．D ．【答案】A【解析】试题分析：由已知得，，所以，所以.【考点】三角函数的定义与求值.8．下列函数中，在其定义域内既是偶函数又在(,0)-∞上单调递增的函数是 （ ）A ．2()f x x =B ．||()2x f x =C ．21()log f x x= D ．()sin f x x = 【答案】C【解析】试题分析：A ：函数2y x =为偶函数，在(),0-∞上单调递减，B ：函数2x y =为偶函数，在(),0-∞上单调递减，C ：函数21log y x=为偶函数，在(),0-∞上单调递增， D ：函数sin y x =为奇函数． 所以综上可得：C 正确．【考点】函数奇偶性、函数的单调性．9．定义在R 上的奇函数()f x 满足()()2f x f x +=-，且当[]0,1x ∈时，()2cos x f x x =-，则下列结论正确的是（ ）A ．()20202019201832f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭B ．()20202019201832f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭C ．()20192020201823f f f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭D ．()20192020201823f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭【答案】C【解析】根据f （x ）是奇函数，以及f （x+2）=f （-x ）即可得出f （x+4）=f （x ），即得出f （x ）的周期为4，从而可得出f （2018）=f （0），2019122f f ⎛⎫⎛⎫=⎪ ⎪⎝⎭⎝⎭，20207312f f ⎛⎫⎛⎫= ⎪ ⎪⎝⎭⎝⎭然后可根据f （x ）在[0，1]上的解析式可判断f （x ）在[0，1]上单调递增，从而可得出结果. 【详解】∵f （x ）是奇函数；∴f （x+2）=f （-x ）=-f （x ）；∴f （x+4）=-f （x+2）=f （x ）； ∴f （x ）的周期为4；∴f （2018）=f （2+4×504）=f （2）=f （0），2019122f f⎛⎫⎛⎫= ⎪ ⎪⎝⎭⎝⎭,20207 312f f ⎛⎫⎛⎫=⎪ ⎪⎝⎭⎝⎭ ∵x ∈[0，1]时，f （x ）=2x-cosx 单调递增；∴f(0)＜12f ⎛⎫⎪⎝⎭＜712f ⎛⎫⎪⎝⎭∴()20192020201823f f f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭,故选C.【点睛】本题考查奇函数，周期函数的定义，指数函数和余弦函数的单调性，以及增函数的定义，属于中档题.10．已知4cos()cos sin()sin ,5αβααβα-+-=-3,2πβπ⎛⎫∈ ⎪⎝⎭，则sin β的值是（ ） A ．45B ．45-C ．35-D ．35【答案】C【解析】逆用两角差的余弦公式求得4cos 5β=-，再利用平方关系求解sin β 【详解】cos()cos sin()sin αβααβα-+-cos()αβα=--4cos 5β==-，3,2πβπ⎛⎫∈ ⎪⎝⎭，3sin 5β∴==-.故选：C 【点睛】本题考查两角差的余弦公式，考查同角三角函数基本关系，是基础题11．已知sin cos 1sin cos 3αααα-=+，则44cos cos 36ππαα⎛⎫⎛⎫+-- ⎪ ⎪⎝⎭⎝⎭的值为（ ） A．310+ B．410+ CD【答案】C【解析】先求tan 2α=，利用平方差公式结合同角三角函数基本关系化简所求为221tan 31tan 3παπα⎛⎫-+ ⎪⎝⎭⎛⎫++ ⎪⎝⎭，利用两角和的正切求tan 3πα⎛⎫+ ⎪⎝⎭即可求解【详解】由已知得tan 2α=， 则44cos cos 36ππαα⎛⎫⎛⎫+--⎪ ⎪⎝⎭⎝⎭44cos sin 33ππαα⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭22cos sin 33ππαα⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭2222cos sin 33cos sin 33ππααππαα⎛⎫⎛⎫+-+ ⎪ ⎪⎝⎭⎝⎭=⎛⎫⎛⎫+++ ⎪ ⎪⎝⎭⎝⎭ 221tan 31tan 3παπα⎛⎫-+ ⎪⎝⎭=⎛⎫++ ⎪⎝⎭，又tantan 3tan 31tan tan 3παπαπα+⎛⎫+= ⎪⎝⎭-=，24421cos cos 361ππαα-⎛⎫⎛⎫⎝⎭∴+--= ⎪ ⎪⎝⎭⎝⎭⎛⎫+.= 故选C . 【点睛】本题考查三角变换，考查两角和的正切公式，考查齐次式化简求值，意在考查计算能力，是中档题12．如果2弧度的圆心角所对的弦长为4，那么这个圆心所对的弧长为（ ） A ．2 B ．2sin1C ．2sin1D ．4sin1【答案】D【解析】利用半弦长，弦心距，半径组成直角三角形得半径长度，再利用弧长公式求解 【详解】连接圆心与弦的中点，则以弦心距，弦长的一半和半径长为长度的线段构成一个直角三角形，半弦长为2，其所对的圆心角也为2，故半径长为2sin1.这个圆心角所对弧长为242sin1sin1⨯=. 故选：D 【点睛】本题考查扇形弧长公式，灵活运用勾股定理得半径长度是关键，是基础题二、填空题 13．已知方程1sin 10x x =，其在区间[]10,10-内解的个数为__________. 【答案】7个【解析】画出函数()sin f x x =，1()10g x x =的图像，数形结合求解 【详解】构造函数()sin f x x =，1()10g x x =，并作出它们的图象，如图：由图象得函数()sin f x x =与1()10g x x =在区间[10,10]-上共有7个交点，故方程1sin 10x x =在区间[10,10]-上有7个解. 故答案为：7【点睛】本题考查函数与方程的应用，考查数形结合思想的应用，熟记基本函数图像是关键14．已知304παβ∈，（，），3sin()5αβ+=-，12sin()413πβ-=，则cos()4πα-=________【答案】3365【解析】由诱导公式将cos 4πα⎛⎫-⎪⎝⎭化为sin 4πα⎛⎫+⎪⎝⎭，再由()44ππααββ⎛⎫+=+-- ⎪⎝⎭，根据两角差的正弦公式，即可求出结果. 【详解】因为304παβ⎛⎫∈ ⎪⎝⎭，，，所以302παβ⎛⎫+∈ ⎪⎝⎭，，442πππβ⎛⎫-∈- ⎪⎝⎭，， 又()3sin 5αβ+=-，12sin 413πβ⎛⎫-= ⎪⎝⎭，所以32，παβπ⎛⎫+∈ ⎪⎝⎭，042ππβ⎛⎫-∈ ⎪⎝⎭，，所以()4cos 5αβ+=-，5cos 413πβ⎛⎫-= ⎪⎝⎭，所以()()()3541233cos sin sin cos cos sin 4444451351365sin πππππαααββαββαββ⎡⎤⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫-=+=+--=+--+-=-⨯--⨯=⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎣⎦. 故答案为3365【点睛】本题主要考查简单的三角恒等变换，熟记两角差的正弦公式以及诱导公式，即可求解，属于常考题型.15．已知函数()sin f x x ω=在区间0,6π⎛⎫⎪⎝⎭上是增函数，则下列结论正确的是__________（将所有符合题意的序号填在横线上）． ①函数()sin f x x ω=在区间,06π⎛⎫-⎪⎝⎭上是增函数； ②满足条件的正整数ω的最大值为3； ③412f f ππ⎛⎫⎛⎫≥⎪ ⎪⎝⎭⎝⎭. 【答案】①②③ 【解析】!由题函数()sin f x x ω=在区间π06（，）上是增函数，则由f x sin x sin x f x ωω-=-=-=-（）（）（），可得f x （）为奇函数，则①函数()sin f x x ω=在区间(π6-,0)上是增函数，正确； 由 62，ππω≤可得3ω≤ ，即有满足条件的正整数ω的最大值为3，故②正确；由于 212436ππππ+==⨯， 由题意可得对称轴6x π≥ ，即有ππ412f f ⎛⎫⎛⎫≥ ⎪ ⎪⎝⎭⎝⎭.，故③正确．故答案为①②③．【点睛】本题考查正弦函数的图象和性质，重点是对称性和单调性的运用，考查运算能力，属于中档题．16．设函数π()sin()3f x x ω=+，其中0>ω．若函数()f x 在[]0,2π上恰有2个零点，则ω的取值范围是________．【答案】54,63⎡⎫⎪⎢⎣⎭【解析】求出函数的零点，对大于0的零点按从小到大排序，第二个在[0,2]π上，第三个大于2π，由此可求得ω的范围． 【详解】()f x 取零点时x 满足条件()3k x k Z ππωω=-+∈，当0x >时的零点从小到大依次为 123258,,333x x x πππωωω===，所以满足523823ππωππω⎧≤⎪⎪⎨⎪>⎪⎩ ，解得：54,63ω⎡⎫∈⎪⎢⎣⎭ 【点睛】本题考查三角函数零点个数问题，属于中等题，解题时只要求出零点，按题设条件列出不等关系即可求解参数范围．三、解答题 17．化简下列各式： （1）tan α是第二象限角）； （2【答案】（1）-1；（2）1.【解析】（1）根据三角函数值在各个象限符号及同角基本关系式，直接化简表达式，求出最简结果．（2）利用平方关系及诱导公式，以及三角函数在象限的符号，去掉根号和绝对值符号，化简即可． 【详解】（1）原式＝=tansin cos αα=|cos sin αα|， ∵α是第二象限角，∴sinα＞0，cosα＜0， ∴原式sin cos αα=|cos sin αα|sin cos αα=•cos sin αα-=-1． （2）原式=808080801010101010101010sin cos sin cos cos sin cos sin cos sin cos sin ︒-︒︒-︒︒-︒====︒-︒︒-︒︒-︒1．【点睛】本题考查同角三角函数基本关系式的应用，考查诱导公式的应用，是基础题． 18．已知函数()sin f x a x b =+（,R a b ∈）．（1）若0a <，函数()f x 的最大值为0，最小值为4-，求,a b 的值； （2）当1b = 时，函数2()()cos g x f x x =+的最大值为2，求a 的值．【答案】（1）22a b =-⎧⎨=-⎩；（2）0.【解析】（1）由题意可得04a b a b -+=⎧⎨+=-⎩，由此求得a ，b 的值．（2）利用整体换元法将()g x 化为二次型函数，分类讨论求得最大值，即可求得a 值. 【详解】（1）由题意0a <，所以sin 1x =-时，()f x 最大，sin 1x =时，()f x 最小，可得04a b a b -+=⎧⎨+=-⎩，∴22a b =-⎧⎨=-⎩；（2）∴g （x ）＝f （x ）+cos 2x ＝1+a sin x +cos 2x ＝2+a sin x ﹣sin 2x24a =+2﹣（sin x-2a ）2，令t ＝sin x ，g （t ）24a =+2﹣（t 2a -）2，∵t ∈[1-，1]，分类讨论： 若12a-＜，即a <-2， g max ＝g （1-）21a =--＝2，故a 1=-；（舍去）； 若12a-≤≤1即﹣2≤a ≤2， g max ＝g （2a ）24a =+2＝2，得a ＝0（舍去）；若2a ＞1，即a >2，g max ＝g （1）=2+a-1＝2，得a ＝1（舍去）∴可得：a ＝0．【点睛】本题主要考查了正弦函数的图象和性质，同角三角函数基本关系式的应用，考查了二次函数求最值的方法，考查了分类讨论思想，属于中档题．19．已知函数2()log |cos |f x x =，（1）求其定义域和值域；（2）判断奇偶性；（3）判断其周期性，若是周期函数，求其最小正周期；（4）写出其单调减区间.【答案】（1）|,,2x x k k Z ππ⎧⎫≠+∈⎨⎬⎩⎭()(,0]f x ∈-∞； （2）偶函数；（3）是周期函数，π；（4）,()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭. 【解析】（1）利用真数大于0列不等式求解定义域，求得真数的范围得值域 （2）利用奇偶性定义判断（3）利用周期定义求解（4）利用复合函数及余弦函数单调性求解【详解】（1）cos 0,x ≠2x k ππ∴≠+，k Z ∈，∴定义域为|,2x x k k Z ππ⎧⎫≠+∈⎨⎬⎩⎭. 0|cos |1x ∴<≤，()(,0]f x ∴∈-∞；（2）()2x k k Z ππ≠+∈，∴定义域关于原点对称.又()()f x f x =-，()f x ∴为偶函数；（3）令()|cos |g x x =，则()|cos()|g x x ππ+=+|cos |()x g x ==，()f x ∴是周期函数，且π为最小正周期；（4）()|cos |g x x =的单调递减区间为,()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭，又2()l o g f x x =单调递增()f x ∴的单调递减区间为,()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭. 【点睛】本题考查对数函数的基本性质，考查余弦函数的性质，灵活运用复合函数解题是关键，是中档题20．已知函数()22sin sin 44f x x x x ππ⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭. （1）求函数()f x 图象的对称轴方程；（2）求函数()f x 在区间,122ππ⎡⎤-⎢⎥⎣⎦上的值域.【答案】（1）()23k x k Z ππ=+∈（2）[2] 【解析】（1）化简()f x 2sin 26x π⎛⎫=- ⎪⎝⎭，令2()62x k k Z πππ-=+∈得对称轴方程；（2）求52,636x πππ⎡⎤-∈-⎢⎥⎣⎦，利用三角函数性质求值域 【详解】（1）函数()22sin sin 44f x x x x ππ⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭2(sin cos )(sin cos )x x x x x =+-+222sin cos x x x =+-2cos 2x x =-2sin 26x π⎛⎫=- ⎪⎝⎭，由2()62x k k Z πππ-=+∈，得()23k x k Z ππ=+∈， ∴函数图象的对称轴方程为()23k x k Z ππ=+∈. （2）,122x ππ⎡⎤∈-⎢⎥⎣⎦，52,636x πππ⎡⎤-∈-⎢⎥⎣⎦. ()2sin 26f x x π⎛⎫=- ⎪⎝⎭在区间,123ππ⎡⎤-⎢⎥⎣⎦上单调递增，在区间,32ππ⎡⎤⎢⎥⎣⎦上单调递减，∴当3x π=时，()f x 取得最大值2.又1122f f ππ⎛⎫⎛⎫-=<= ⎪ ⎪⎝⎭⎝⎭，故函数的最小值为，故函数的值域为[2].【点睛】本题考查三角恒等变换，考查三角函数的对称性，考查图像性质，意在考查计算能力，是基础题21．已知函数:()sin (0)f x x x ωωω=+>的周期为π.（1）求ω的值；（2）求函数()y f x =的单调递增区间；（3）当0,6x π⎡⎤∈⎢⎥⎣⎦时，求函数()f x 的值域.【答案】（1）2ω=（2）单调递增区间为5,()1212k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦（3）2] 【解析】（1）化简()2sin 3f x x πω⎛⎫=+⎪⎝⎭，利用周期公式求解； （2）令222,232k x k πππππ-+≤+≤+求解单调区间即可、（3）22,333x πππ⎡⎤+∈⎢⎥⎣⎦，利用函数的图像及性质求解 【详解】 ()2sin 3f x x πω⎛⎫=+ ⎪⎝⎭. （1）22T ππωω==⇒=.（2）令222,232k x k πππππ-+≤+≤+k Z ∈，得5,1212k x k ππππ-+≤≤+k Z ∈， 所求单调递增区间为5,()1212k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦.（3）0,6x π⎡⎤∈⎢⎥⎣⎦，22,333x πππ⎡⎤+∈⎢⎥⎣⎦，sin 2,132x π⎤⎛⎫+∈⎥ ⎪⎝⎭⎣⎦，所以函数()y f x =在0,6x π⎡⎤∈⎢⎥⎣⎦上的值域为2]. 【点睛】本题考查考查三角函数的单调性，周期性，考查图像性质，意在考查计算能力，是基础题22．弹簧挂着的小球作上下运动，它在t 秒时相对于平衡位置的高度h 厘米由下列关系式确定：2sin 4h t π⎛⎫=+ ⎪⎝⎭.以t 为横坐标，h 为纵坐标，作出这个函数在一个周期的闭区间上的图象，并回答下列问题.（1）小球在开始振动时（即0t =）的位置在哪里？（2）小球的最高点和最低点与平衡位置的距离分别是多少？（3）经过多少时间小球往复振动一次？（4）每秒钟小球能往复振动多少次？【答案】（1）（2）见解析；（3）经过2π秒往复运动一次（4）12π次 【解析】（1）0t =代入解析式求解（2）利用图像直接求解（3）利用图像得周期（4）利用112f T π==求解 【详解】 函数2sin 4h t π⎛⎫=+ ⎪⎝⎭在[0,2]π上的图象如图：（1）0t =时，2sin )4h cm π==，即小球在开始振动时的位置.（2）小球的最高点和最低点与平衡位置的距离都是2cm .（3）小球往复运动一次，就是一个周期，2T π=秒，即经过2π秒往复运动一次. （4）每秒钟往复运动的次数112f T π==. 【点睛】本题考查三角函数图像的实际应用，考查读题转化能力，是基础题。
黑龙江省大兴安岭漠河县第一中学2019-2020学年高一上学期11月月考物理试卷
v ／（m·s －1） t ／s 0 10 30 36 1物理试题一、选择题：本题共12小题，每小题4分。
共48分。
在每小题的四个选项中，第1～7题只有一项符合题目要求，第8～12题有多项符合题目要求。
全部选对的得4分，选对但不全的得2分，有选错的得0分。
1.下列说法正确的个数有( )（1）长度是国际单位制中的基本单位（2）想要马拉车加速前进，马拉车的力必须大于车拉马的力（3）光滑水平面的两个物体，受到相同的水平推力，加速度大的惯性大（4）小球做竖直上抛运动时，由于速度竖直向上，是超重现象（5）三个力的大小分别是3N 、7N 、9N 他们合成的最大值和最小值是19N 和1NA.0个B.1个C.2个D.3个2．关于合力与它的两个分力的关系，下列叙述正确的是( )A ．合力一定大于其中任意一个分力B ．合力可能小于其中任意一个分力C ．两个分力的大小不变，若夹角在0～180º之间变化，则夹角越大其合力也越大D ．两个分力F 1和F 2的夹角θ不变，F 1大小不变，若F 2增大，则合力F 一定增大3．如图所示为一物体被吊车用钢索竖直向上提升过程的运动图象。
下列判断正确的是( )A.0～36 s 内物体被吊起的高度为25 mB.0～10 s 内物体的平均速度大于30～36 s 内物体的平均速度C.30～36 s 内物体处于超重状态D.0～10 s 内钢索最容易发生断裂 4．一物体在多个力的作用下处于静止状态，如果仅使其中某个力的大小逐渐减小到零，然后又逐渐从零恢复到原来大小（在上述过程中，此力的方向一直保持不变），那么如图所示的v-t 图象中，符合此过程中物体运动情况的图象可能是( )5．在平直公路上，自行车与同方向行驶的一辆汽车在t=0时同时经过某一个路标，它们的位移x （m ）随时间t （s ）变化的规律为：汽车为x=10t-0.25t 2，自行车为x=6t ，则下列说法正确的是：( )A ．汽车作匀减速直线运动，其加速度大小为0.25m/s 2B ．在t=8s 时两车速度相等，自行车第一次追上了汽车C ．当自行车追上汽车时，它们距路标96mFA BD ．在t=0至t=16s 时间内，两车间距离先减小后增大6.如图所示，在水平光滑桌面上放有m 1和m 2两个小物块，它们中间有细线连接。
黑龙江省大兴安岭漠河县第一中学2020学年高二英语教学质量检测试题
黑龙江省大兴安岭漠河县第一中学2020学年高二英语教学质量检测试题第一部分阅读理解(共两节,满分35分)第一节(共10小题;每小题2.5分,满分25分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AClaudie Dubreuil, a Canadian woman, has built a very special house out of four sea containers (集装箱) that cost only 3,000 euro per container. What she made out of them is absolutely beautiful. And what she managed to make out of four simple sea containers is exceptional! We’d definitely like a home like this, how about you?As a general contractor (总承包人), Canadian Claudie Dubreuil makes a nice living out of building apartments and traditional wood houses. Unfortunately, building these types of houses didn’t provide her with enough of a creative challenge. So, when it came to designing and building her own house, she didn’t choose the familiar option. Instead, she picked a very special and creative approach to her new home.Claudie decided to design a home based on metal sea containers. With this decision, she didn’t choose the easiest route. In fact, she met with a lot of obstacles during building her house. For example, it was very difficult to find an engineer who had the resources and abilities to cut through the sea containers and to install doors and windows in them. She was turned down by four different engineers before finding one that was willing to work with her. Luckily, she did find someone who dared to take on the project in theend. And the result is amazing! Her home turned out absolutely beautiful and it’s eco-friendly as well.We love what Claudie did with her home! It looks so modern that you can hardly recognise the sea containers, though she left some special pieces of wall the way they were.21.How much does the special house cost at least?A.3,000 euro.B.12,000 euro.C.6,000 euro.D.9,000 euro.22.Why did Claudie decide to design a sea-container house?A.She was on a tight budget.B.She was skilled at it.C.She wanted a special and creative house.D.She couldn’t find other building materials.23.Which of the following can replace the underlined word “obstacles” in paragraph 3?A.difficultiesB.differencesC.pleasureD.puzzlementBA dog found swimming more than 220 kilometers off the coast of Thailand has been returned safely to land.Late last week, workers on an oil rig (石油钻塔) noticed the animal, all alone in the water. He began swimming toward the side of the structure. The dog was able to get himself onto a solid area.He appeared cold, tired and fearful. The workers lowered a rope and secured it around the dog. Then, they worked together to pull the animal up to safety.The crew that found the dog quickly gave their new friend a name: Boonrod. The name means something similar to “survivor” in the Thai language.One of those workers was Vitisak Payalaw. He has been providing updates on Boonrod on his Facebook page. He said it was lucky that the crew noticed the dog in the water. If there had been waves, he said, the animal likely would not have been seen.No one knows how Boonrod ended up all alone at sea, or how long he had been out there. But Vitisak and others suggested the animal might have fallen off a fishing boat.On Monday, Boonrod arrived on dry land. A team of animal doctors were waiting for him in the southern Thai province of Songkhla. Workers at the Songkhla po rt also welcomed the dog with a special “welcome” necklace made of yellow flowers. Many people took pictures with Boonrod.Vitisak wrote on Facebook, “Today (April 15), Boonrod’s overall condition has improved. He is getting stronger.”The dog is now in the care of an animal doctor in Songkhla. The animal protection group Watchdog Thailand said,“He is in good condition and getting stronger.” On Tuesday, the group published pictures of Boonrod getting washed—and getting plenty of love and attention.Vitisak says that if no one claims Boonrod as their pet, he will take him to his home in northeast Thailand.24.What was the dog like when he was found?A.He was cold, tired and fearful.B.He was already in a safe place.C.He was hopeful but lonely.D.He was in good state.25.What can we learn about the dog from the text?A.He is homeless again.B.His original name is “Boonrod”.C.He has been taken home by Vitisak.D.He was rescued by the workers on an oil rig.26.How is the dog at present?A.He is found by his owner.B.He is getting much care.C.He is badly injured.D.He is treated badly.CStatistics show that most toddlers (刚学走路的小孩) learn how to say about 20 words by 18 months. Talking is easy. If you ask anyone, none will remember how they started doing it, it just comes naturally.But what might not flow as smoothly as words, is body language. It’s a whole different deal when you’re using your hands, eyes or head instead of your tongue. And what makes it misunderstood is the fact that body language differs all around the world because of different cultures.I find it shockingly amazing how just a small finger gesture could mean one thing in the east and the completely opposite in the west. For instance, in Japan bowing is the most common greeting. It shows respect and Japanese pay a lot of attention to the details like the timing, posture and movement.A bow in Japan represents sincerity, respect and graciousness. While in New Zealand Maori, the pressing of noses and foreheads is the traditional greeting. They call it “hongi”, which is regarded as the breath of life.For most of us, nodding our head up and down often means agreement, but not for the Bulgarians or Greeks. In both cultures, nodding one’s head up and down actually means “no”. The American goodbye wave could actually be interpreted (领会) as a “no” in many parts of Europe and Latin America. And the Italian goodbye wave would be understood in America as a “come here” and the American “come here” gesture would actually be seen as an insult (侮辱) in most of Asia.So before you travel to explore a different culture, make sure you’re aware of alternate meanings for body language. We live in a world with manydifferent cultures, so don’t forget how differently one hand gesture can be interpreted!27.What makes body language misunderstood often?A.Its difficulties in understanding.B.Its smooth flowing.C.Different cultures.D.Its wide uses.28.What does the pressing of noses and foreheads mean in New Zealand?A.Respect.B.Greeting.C.Tradition.D.Breath.29.In which country does nodding mean “no”?A.Greece.B.America.C.New Zealand.D.Japan.30.What can be a suitable title for the text?A.The Origin of Body LanguageB.The Difference of Culture Around the WorldC.The Limitation of CultureD.Body Language Around the World第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
黑龙江省大兴安岭漠河县第一中学2019_2020学年高一物理上学期11月月考试题
黑龙江省大兴安岭漠河县第一中学2019-2020学年高一物理上学期11月月考试题一、选择题：本题共12小题，每小题4分。
共48分。
在每小题的四个选项中，第1～7题只有一项符合题目要求，第8～12题有多项符合题目要求。
全部选对的得4分，选对但不全的得2分，有选错的得0分。
1.下列说法正确的个数有( )（1）长度是国际单位制中的基本单位（2）想要马拉车加速前进，马拉车的力必须大于车拉马的力（3）光滑水平面的两个物体，受到相同的水平推力，加速度大的惯性大（4）小球做竖直上抛运动时，由于速度竖直向上，是超重现象（5）三个力的大小分别是3N 、7N 、9N 他们合成的最大值和最小值是19N 和1NA.0个B.1个C.2个D.3个2．关于合力与它的两个分力的关系，下列叙述正确的是( )A ．合力一定大于其中任意一个分力B ．合力可能小于其中任意一个分力C ．两个分力的大小不变，若夹角在0～180º之间变化，则夹角越大其合力也越大D ．两个分力F 1和F 2的夹角θ不变，F 1大小不变，若F 2增大，则合力F 一定增大3．如图所示为一物体被吊车用钢索竖直向上提升过程的运动图象。
下列判断正确的是( )A.0～36 s 内物体被吊起的高度为25 mB.0～10 s 内物体的平均速度大于30～36 s 内物体的平均速度C.30～36 s 内物体处于超重状态D.0～10 s 内钢索最容易发生断裂 4．一物体在多个力的作用下处于静止状态，如果仅使其中某个力的大小逐渐减小到零，然后又逐渐从零恢复到原来大小（在上述过程中，此力的方向一直保持不变），那么如图所示的v-t 图象中，符合此过程中物体运动情况的图象可能是( )5．在平直公路上，自行车与同方向行驶的一辆汽车在t=0时同时经过某一个路标，它们的位移x （m ）随时间t （s ）变化的规律为：汽车为x=10t-0.25t 2，自行车为x=6t ，则下列说法正确的是：( )A ．汽车作匀减速直线运动，其加速度大小为0.25m/s 2B ．在t=8s 时两车速度相等，自行车第一次追上了汽车FA BC ．当自行车追上汽车时，它们距路标96mD ．在t=0至t=16s 时间内，两车间距离先减小后增大6.如图所示，在水平光滑桌面上放有m 1和m 2两个小物块，它们中间有细线连接。
2019～2020学年度学年度黑龙江省大兴安岭漠河一中高一第1学期11月月考数学试题及参考答案解析
2019～2020学年度黑龙江省大兴安岭漠河一中高一第一学期11月月考数学试题一、单选题 1.在中与终边相同的角有( )A.个B.个C.个D.个【试题答案】D 【试题解答】先写出与终边相同的角的表达式,然后对赋值,求得在范围内角的个数. 与终边相同的角为.当时,,故在中与终边相同的角有个,所以选D.本小题主要考查终边相同的角,考查任意角的概念以及周期性,属于基础题. 2.若α角与β的终边垂直,则α与β的关系是( ) A.90βα︒=+B.90βα︒=±C.90360()k k Z βα︒︒=++⋅∈D.90360()k k Z βα︒︒=±+⋅∈【试题答案】D【试题解答】利用终边相同的角的关系直接求解若角α与β的终边垂直,则90360()k k Z βα︒︒-=±+⋅∈,90360()k k Z βα︒︒∴=±+⋅∈.故选:D本题考查终边相同的角,是基本概念的考查 3.函数的单调增区间为( )A.,B.,C.,D.,【试题答案】C【试题解答】先将函数解析式化简整理,得到,再由,求解,即可得出结果.因为,由可得, 即函数的单调递增区间为,. 故选C本题主要考查正弦型函数的单调区间,熟记正弦函数的单调区间即可,属于常考题型. 4.若3cos()2πα+=则cos2=α( ) A.23-B.13-C.13D.23【试题答案】C【试题解答】本道题化简式子,计算出sin α,结合2cos 212sin αα=-,即可.3cos sin 2παα⎛⎫+=-= ⎪⎝⎭,得到3sin α=,所以 211cos 212sin 1233αα=-=-⋅=,故选C.本道题考查了二倍角公式,难度较小. 5.将函数1cos()26y x π=-图象向左平移3π个长度单位,再把所得图象上各点的横坐标缩短到原来的一半(纵坐标不变),所得图象的函数解析式是( )A.cos(+)6y x π= B.1cos 4y x = C.cos y x = D.1cos()43y x π=-【试题答案】C【试题解答】试题分析:函数1cos()26y x π=-图象向左平移3π个长度单位,得到11cos +=cos 2362y x x ππ⎡⎤⎛⎫=- ⎪⎢⎥⎝⎭⎣⎦,再把所得图象上各点的横坐标缩短到原来的一半(纵坐标不变)得到1cos 2cos 2y x x ==g . 三角函数图象变换.【易错点晴】三角函数图象变换,关键在于不管怎么变,都是变x ,其它系数保留；熟记左加右减,并且要看清题意到底是谁变换成谁.本题中,平移的时候12是没有变到的,所以必须提取出来.另外,如果既平移,又伸缩,就必须确保每一次都是变x . 6.若(cos )cos3f x x =,则(sin 30)f ︒的值为( ) A.1B.－1C.0D.【试题答案】B【试题解答】试题分析:由已知可得(sin30)(cos60)cos1801f f ︒=︒=︒=-. 本小题主要考查诱导公式的应用和函数值的求法,考查学生灵活的转化能力和运算求解能力.点评:解决本题的关键在于把sin30︒化成cos60︒,然后直接代入求解即可,如果先求函数解析式就会变得非常麻烦.7.在平面直角坐标系中,角的顶点与原点重合,始边与x 轴的非负半轴重合,终边过点,则( )A. B.C. D.【试题答案】A【试题解答】试题分析:由已知得,,所以,所以.三角函数的定义与求值.8.下列函数中,在其定义域内既是偶函数又在(,0)-∞上单调递增的函数是 ( )A.2()f x x =B.||()2x f x =C.21()log f x x= D.()sin f x x =【试题答案】C【试题解答】试题分析:A:函数2y x =为偶函数,在(),0-∞上单调递减,B:函数2x y =为偶函数,在(),0-∞上单调递减, C:函数21log y x=为偶函数,在(),0-∞上单调递增, D:函数sin y x =为奇函数. 所以综上可得:C 正确. 函数奇偶性、函数的单调性.9.定义在R 上的奇函数()f x 满足()()2f x f x +=-,且当[]0,1x ∈时,()2cos xf x x =-,则下列结论正确的是( )A.()20202019201832f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭B.()20202019201832f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭C.()20192020201823f f f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭D.()20192020201823f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭【试题答案】C【试题解答】根据f(x)是奇函数,以及f(x+2)=f(-x)即可得出f(x+4)=f(x),即得出f(x)的周期为4,从而可得出f(2018)=f(0),2019122f f ⎛⎫⎛⎫=⎪ ⎪⎝⎭⎝⎭,20207312f f ⎛⎫⎛⎫= ⎪ ⎪⎝⎭⎝⎭然后可根据f(x)在[0,1]上的解析式可判断f(x)在[0,1]上单调递增,从而可得出结果.∵f(x)是奇函数；∴f(x+2)=f(-x)=-f(x)；∴f(x+4)=-f(x+2)=f(x)； ∴f(x)的周期为4；∴f(2018)=f(2+4×504)=f(2)=f(0),2019122f f ⎛⎫⎛⎫=⎪ ⎪⎝⎭⎝⎭,20207 312f f ⎛⎫⎛⎫=⎪ ⎪⎝⎭⎝⎭ ∵x ∈[0,1]时,f(x)=2x -cosx 单调递增；∴f(0)＜12f ⎛⎫⎪⎝⎭＜712f ⎛⎫⎪⎝⎭∴()20192020201823f f f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭,故选C.本题考查奇函数,周期函数的定义,指数函数和余弦函数的单调性,以及增函数的定义,属于中档题.10.已知4cos()cos sin()sin ,5αβααβα-+-=-3,2πβπ⎛⎫∈ ⎪⎝⎭,则sin β的值是( ) A.45B.45-C.35-D.35【试题答案】C【试题解答】逆用两角差的余弦公式求得4cos 5β=-,再利用平方关系求解sin βcos()cos sin()sin αβααβα-+-Q cos()αβα=--4cos 5β==-,3,2πβπ⎛⎫∈ ⎪⎝⎭, 3sin 5β∴==-.故选:C本题考查两角差的余弦公式,考查同角三角函数基本关系,是基础题 11.已知sin cos 1sin cos 3αααα-=+,则44cos cos 36ππαα⎛⎫⎛⎫+-- ⎪ ⎪⎝⎭⎝⎭的值为( )【试题答案】C【试题解答】先求tan 2α=,利用平方差公式结合同角三角函数基本关系化简所求为221tan 31tan 3παπα⎛⎫-+ ⎪⎝⎭⎛⎫++ ⎪⎝⎭,利用两角和的正切求tan 3πα⎛⎫+ ⎪⎝⎭即可求解由已知得tan 2α=, 则44cos cos 36ππαα⎛⎫⎛⎫+--⎪ ⎪⎝⎭⎝⎭44cos sin 33ππαα⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭22cos sin 33ππαα⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭2222cos sin 33cos sin 33ππααππαα⎛⎫⎛⎫+-+ ⎪ ⎪⎝⎭⎝⎭=⎛⎫⎛⎫+++ ⎪ ⎪⎝⎭⎝⎭ 221tan 31tan 3παπα⎛⎫-+ ⎪⎝⎭=⎛⎫++ ⎪⎝⎭,又tantan 3tan 31tan tan 3παπαπα+⎛⎫+= ⎪⎝⎭-Q =, 24421cos cos 361ππαα-⎛⎫⎛⎫⎝⎭∴+--= ⎪ ⎪⎝⎭⎝⎭⎛⎫+.=故选C .本题考查三角变换,考查两角和的正切公式,考查齐次式化简求值,意在考查计算能力,是中档题12.如果2弧度的圆心角所对的弦长为4,那么这个圆心所对的弧长为( ) A.2B.2sin1C.2sin1D.4sin1【试题答案】D【试题解答】利用半弦长,弦心距,半径组成直角三角形得半径长度,再利用弧长公式求解连接圆心与弦的中点,则以弦心距,弦长的一半和半径长为长度的线段构成一个直角三角形,半弦长为2,其所对的圆心角也为2,故半径长为2sin1.这个圆心角所对弧长为242sin1sin1⨯=. 故选:D本题考查扇形弧长公式,灵活运用勾股定理得半径长度是关键,是基础题二、填空题 13.已知方程1sin 10x x =,其在区间[]10,10-内解的个数为__________. 【试题答案】7个【试题解答】画出函数()sin f x x =,1()10g x x =的图像,数形结合求解构造函数()sin f x x =,1()10g x x =,并作出它们的图象,如图:由图象得函数()sin f x x =与1()10g x x =在区间[10,10]-上共有7个交点,故方程1sin 10x x =在区间[10,10]-上有7个解. 故答案为:7本题考查函数与方程的应用,考查数形结合思想的应用,熟记基本函数图像是关键14.已知304παβ∈，（，）,3sin()5αβ+=-,12sin()413πβ-=,则cos()4πα-=________【试题答案】3365【试题解答】由诱导公式将cos 4πα⎛⎫-⎪⎝⎭化为sin 4πα⎛⎫+⎪⎝⎭,再由()44ππααββ⎛⎫+=+-- ⎪⎝⎭,根据两角差的正弦公式,即可求出结果.因为304παβ⎛⎫∈ ⎪⎝⎭，，,所以302παβ⎛⎫+∈ ⎪⎝⎭，,442πππβ⎛⎫-∈- ⎪⎝⎭，, 又()3sin 5αβ+=-,12sin 413πβ⎛⎫-= ⎪⎝⎭,所以32，παβπ⎛⎫+∈ ⎪⎝⎭,042ππβ⎛⎫-∈ ⎪⎝⎭，,所以()4cos 5αβ+=-,5cos 413πβ⎛⎫-= ⎪⎝⎭,所以()()()3541233cos sin sin cos cos sin 4444451351365sin πππππαααββαββαββ⎡⎤⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫-=+=+--=+--+-=-⨯--⨯=⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⎣⎦. 故答案为3365本题主要考查简单的三角恒等变换,熟记两角差的正弦公式以及诱导公式,即可求解,属于常考题型.15.已知函数()sin f x x ω=在区间0,6π⎛⎫⎪⎝⎭上是增函数,则下列结论正确的是__________(将所有符合题意的序号填在横线上). ①函数()sin f x x ω=在区间,06π⎛⎫-⎪⎝⎭上是增函数； ②满足条件的正整数ω的最大值为3； ③412f f ππ⎛⎫⎛⎫≥⎪ ⎪⎝⎭⎝⎭. 【试题答案】①②③ 【试题解答】!由题函数()sin f x x ω=在区间π06（，）上是增函数,则由f x sin x sin x f x ωω-=-=-=-（）（）（），可得f x （）为奇函数,则①函数()sin f x x ω=在区间(π6-,0)上是增函数,正确； 由 62，ππω≤可得3ω≤ ,即有满足条件的正整数ω的最大值为3,故②正确； 由于 212436ππππ+==⨯， 由题意可得对称轴6x π≥ ,即有ππ412f f ⎛⎫⎛⎫≥ ⎪ ⎪⎝⎭⎝⎭.,故③正确.故答案为①②③.本题考查正弦函数的图象和性质,重点是对称性和单调性的运用,考查运算能力,属于中档题.16.设函数π()sin()3f x x ω=+,其中0>ω.若函数()f x 在[]0,2π上恰有2个零点,则ω的取值范围是________.【试题答案】54,63⎡⎫⎪⎢⎣⎭【试题解答】求出函数的零点,对大于0的零点按从小到大排序,第二个在[0,2]π上,第三个大于2π,由此可求得ω的范围.()f x 取零点时x 满足条件()3k x k Z ππωω=-+∈,当0x >时的零点从小到大依次为 123258,,333x x x πππωωω===,所以满足523823ππωππω⎧≤⎪⎪⎨⎪>⎪⎩ ,解得:54,63ω⎡⎫∈⎪⎢⎣⎭本题考查三角函数零点个数问题,属于中等题,解题时只要求出零点,按题设条件列出不等关系即可求解参数范围.三、解答题 17.化简下列各式:(1)tan α是第二象限角)；【试题答案】(1)-1；(2)1.【试题解答】(1)根据三角函数值在各个象限符号及同角基本关系式,直接化简表达式,求出最简结果.(2)利用平方关系及诱导公式,以及三角函数在象限的符号,去掉根号和绝对值符号,化简即可.(1)原式＝=sin cos αα=|cos sin αα|, ∵α是第二象限角,∴sinα＞0,cosα＜0, ∴原式sin cos αα=|cos sin αα|sin cos αα=•cos sin αα-=-1. (2)原式=808080801010101010101010sin cos sin cos cos sin cos sin cos sin cos sin ︒-︒︒-︒︒-︒====︒-︒︒-︒︒-︒1.本题考查同角三角函数基本关系式的应用,考查诱导公式的应用,是基础题. 18.已知函数()sin f x a x b =+(,R a b ∈).(1)若0a <,函数()f x 的最大值为0,最小值为4-,求,a b 的值； (2)当1b = 时,函数2()()cos g x f x x =+的最大值为2,求a 的值.【试题答案】(1)22a b =-⎧⎨=-⎩；(2)0.【试题解答】(1)由题意可得04a b a b -+=⎧⎨+=-⎩,由此求得a ,b 的值.(2)利用整体换元法将()g x 化为二次型函数,分类讨论求得最大值,即可求得a 值.(1)由题意0a <,所以sin 1x =-时,()f x 最大,sin 1x =时,()f x 最小, 可得04a b a b -+=⎧⎨+=-⎩,∴22a b =-⎧⎨=-⎩；(2)∴g (x )＝f (x )+cos 2x ＝1+a sin x +cos 2x ＝2+a sin x ﹣sin 2x24a =+2﹣(sin x-2a )2,令t ＝sin x ,g (t )24a =+2﹣(t 2a -)2,∵t ∈[1-,1],分类讨论: 若12a-＜,即a <-2, g max ＝g (1-)21a =--＝2,故a 1=-；(舍去)； 若12a-≤≤1即﹣2≤a ≤2, g max ＝g (2a )24a =+2＝2,得a ＝0(舍去)；若2a ＞1,即a >2,g max ＝g (1)=2+a-1＝2,得a ＝1(舍去)∴可得:a ＝0.本题主要考查了正弦函数的图象和性质,同角三角函数基本关系式的应用,考查了二次函数求最值的方法,考查了分类讨论思想,属于中档题.19.已知函数2()log |cos |f x x =,(1)求其定义域和值域；(2)判断奇偶性；(3)判断其周期性,若是周期函数,求其最小正周期；(4)写出其单调减区间.【试题答案】(1)|,,2x x k k Z ππ⎧⎫≠+∈⎨⎬⎩⎭()(,0]f x ∈-∞；(2)偶函数；(3)是周期函数,π； (4),()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭.【试题解答】(1)利用真数大于0列不等式求解定义域,求得真数的范围得值域(2)利用奇偶性定义判断(3)利用周期定义求解(4)利用复合函数及余弦函数单调性求解(1)cos 0,x ≠Q 2x k ππ∴≠+,k Z ∈,∴定义域为|,2x x k k Z ππ⎧⎫≠+∈⎨⎬⎩⎭.0|cos |1x ∴<≤,()(,0]f x ∴∈-∞； (2)()2x k k Z ππ≠+∈Q ,∴定义域关于原点对称.又()()f x f x =-Q ,()f x ∴为偶函数；(3)令()|cos |g x x =,则()|cos()|g x x ππ+=+|cos |()x g x ==,()f x ∴是周期函数,且π为最小正周期；(4)()|cos |g x x =的单调递减区间为,()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭,又2()log f x x =单调递增 ()f x ∴的单调递减区间为,()2k k k Z πππ⎡⎫+∈⎪⎢⎣⎭.本题考查对数函数的基本性质,考查余弦函数的性质,灵活运用复合函数解题是关键,是中档题20.已知函数()22sin sin 44f x x x x ππ⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭. (1)求函数()f x 图象的对称轴方程；(2)求函数()f x 在区间,122ππ⎡⎤-⎢⎥⎣⎦上的值域.【试题答案】(1)()23k x k Z ππ=+∈(2)[2] 【试题解答】(1)化简()f x 2sin 26x π⎛⎫=-⎪⎝⎭,令2()62x k k Z πππ-=+∈得对称轴方程；(2)求52,636x πππ⎡⎤-∈-⎢⎥⎣⎦,利用三角函数性质求值域(1)函数()22sin sin 44f x x x x ππ⎛⎫⎛⎫=+-+ ⎪ ⎪⎝⎭⎝⎭2(sin cos )(sin cos )x x x x x =+-+222sin cos x x x =+-2cos 2x x =-2sin 26x π⎛⎫=- ⎪⎝⎭,由2()62x k k Z πππ-=+∈,得()23k x k Z ππ=+∈, ∴函数图象的对称轴方程为()23k x k Z ππ=+∈. (2),122x ππ⎡⎤∈-⎢⎥⎣⎦Q ,52,636x πππ⎡⎤-∈-⎢⎥⎣⎦. ()2sin 26f x x π⎛⎫=- ⎪⎝⎭Q 在区间,123ππ⎡⎤-⎢⎥⎣⎦上单调递增,在区间,32ππ⎡⎤⎢⎥⎣⎦上单调递减,∴当3x π=时,()f x 取得最大值2.又1122f f ππ⎛⎫⎛⎫-=<= ⎪ ⎪⎝⎭⎝⎭,故函数的最小值为,故函数的值域为[2].本题考查三角恒等变换,考查三角函数的对称性,考查图像性质,意在考查计算能力,是基础题21.已知函数:()sin (0)f x x x ωωω=+>的周期为π.(1)求ω的值；(2)求函数()y f x =的单调递增区间；(3)当0,6x π⎡⎤∈⎢⎥⎣⎦时,求函数()f x 的值域.【试题答案】(1)2ω=(2)单调递增区间为5,()1212k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦(3)2] 【试题解答】(1)化简()2sin 3f x x πω⎛⎫=+⎪⎝⎭,利用周期公式求解； (2)令222,232k x k πππππ-+≤+≤+求解单调区间即可、 (3)22,333x πππ⎡⎤+∈⎢⎥⎣⎦,利用函数的图像及性质求解 ()2sin 3f x x πω⎛⎫=+ ⎪⎝⎭. (1)22T ππωω==⇒=.(2)令222,232k x k πππππ-+≤+≤+k Z ∈,得5,1212k x k ππππ-+≤≤+k Z ∈, 所求单调递增区间为5,()1212k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦. (3)0,6x π⎡⎤∈⎢⎥⎣⎦,22,333x πππ⎡⎤+∈⎢⎥⎣⎦,3sin 2,132x π⎡⎤⎛⎫+∈⎢⎥ ⎪⎝⎭⎣⎦, 所以函数()y f x =在0,6x π⎡⎤∈⎢⎥⎣⎦上的值域为[3,2].本题考查考查三角函数的单调性,周期性,考查图像性质,意在考查计算能力,是基础题 22.弹簧挂着的小球作上下运动,它在t 秒时相对于平衡位置的高度h 厘米由下列关系式确定:2sin 4h t π⎛⎫=+ ⎪⎝⎭.以t 为横坐标,h 为纵坐标,作出这个函数在一个周期的闭区间上的图象,并回答下列问题.(1)小球在开始振动时(即0t =)的位置在哪里？(2)小球的最高点和最低点与平衡位置的距离分别是多少？(3)经过多少时间小球往复振动一次？(4)每秒钟小球能往复振动多少次？【试题答案】(1)2)(2)见解析；(3)经过2π秒往复运动一次(4)12π次 【试题解答】(1)0t =代入解析式求解(2)利用图像直接求解(3)利用图像得周期(4)利用112f T π==求解函数2sin 4h t π⎛⎫=+ ⎪⎝⎭在[0,2]π上的图象如图:(1)0t =时,2sin 2()4h cm π==,即小球在开始振动时的位置2).(2)小球的最高点和最低点与平衡位置的距离都是2cm .(3)小球往复运动一次,就是一个周期,2T π=秒,即经过2π秒往复运动一次. (4)每秒钟往复运动的次数112f T π==.本题考查三角函数图像的实际应用,考查读题转化能力,是基础题。
黑龙江省大兴安岭漠河县第一中学2019_2020学年高一物理上学期11月月考试题
v ／（m·s －1） t ／s 0 10 30 36 1黑龙江省大兴安岭漠河县第一中学2019-2020学年高一物理上学期11月月考试题一、选择题：本题共12小题,每小题4分。
共48分。
在每小题的四个选项中,第1～7题只有一项符合题目要求,第8～12题有多项符合题目要求。
全部选对的得4分,选对但不全的得2分,有选错的得0分。
1.下列说法正确的个数有( )（1）长度是国际单位制中的基本单位（2）想要马拉车加速前进,马拉车的力必须大于车拉马的力（3）光滑水平面的两个物体,受到相同的水平推力,加速度大的惯性大（4）小球做竖直上抛运动时,由于速度竖直向上,是超重现象（5）三个力的大小分别是3N 、7N 、9N 他们合成的最大值和最小值是19N 和1NA.0个B.1个C.2个D.3个2．关于合力与它的两个分力的关系,下列叙述正确的是( )A ．合力一定大于其中任意一个分力B ．合力可能小于其中任意一个分力C ．两个分力的大小不变,若夹角在0～180º之间变化,则夹角越大其合力也越大D ．两个分力F 1和F 2的夹角θ不变,F 1大小不变,若F 2增大,则合力F 一定增大3．如图所示为一物体被吊车用钢索竖直向上提升过程的运动图象。
下列判断正确的是( )A.0～36 s 内物体被吊起的高度为25 mB.0～10 s 内物体的平均速度大于30～36 s 内物体的平均速度C.30～36 s 内物体处于超重状态D.0～10 s 内钢索最容易发生断裂 4．一物体在多个力的作用下处于静止状态,如果仅使其中某个力的大小逐渐减小到零,然后又逐渐从零恢复到原来大小（在上述过程中,此力的方向一直保持不变）,那么如图所示的v-t 图象中,符合此过程中物体运动情况的图象可能是( )5．在平直公路上,自行车与同方向行驶的一辆汽车在t=0时同时经过某一个路标,它们的位移x （m ）随时间t （s ）变化的规律为：汽车为x=10t-0.25t 2,自行车为x=6t,则下列说法正确的是：( )A ．汽车作匀减速直线运动,其加速度大小为0.25m/s 2B ．在t=8s 时两车速度相等,自行车第一次追上了汽车FA BC ．当自行车追上汽车时,它们距路标96mD ．在t=0至t=16s 时间内,两车间距离先减小后增大6.如图所示,在水平光滑桌面上放有m 1和m 2两个小物块,它们中间有细线连接。
黑龙江省大兴安岭漠河县第一中学2019_2020学年高一语文上学期第一次阶段性考试试题201912250124
黑龙江省大兴安岭漠河县第一中学2019-2020学年高一语文上学期第一次阶段性考试试题时间：150分钟总分：150分一、现代文阅读（36分）（一）论述类文本阅读（本题共3小题，9分）阅读下面的文字，完成下面1-3小题《诗经》作为我国古代第一部诗集，表现出鲜明的以人为本的民族文化特色。
《诗经》三百零五篇作品中，除了《大雅·生民》和《商颂·玄鸟》这两首诗在写到商周祖先降生时略具有神话因素外，其他作品都没有任何神秘色彩。
在这里我们看不到众神的足迹，也看不到神对人事的判决和预言。
对国家的兴亡从人事上寻找最终的原因，并且把它诉诸诗的创作，这是周人以人为本的哲学、政治思想在文学中的最鲜明体现。
以人为本而不是以神为本，这使中国人很早就摆脱了原始社会的巫术宗教观念，也使诗这种文学体裁很早就从巫术宗教中脱离出来。
如果说，在中国的原始诗歌中，像伊耆氏的《蜡辞》乃至甲骨卜辞中的乞雨词，还带有鲜明的宗教意味的话，那么到了周代，这种原始宗教神学观念已经被周人的实践理性精神逐步取代。
所以在《诗经》中，除了颂诗这种“美盛德之形容，以其成功告于神明”的祭祀歌之外，在占有作品总数近十分之九的雅诗和风诗中，带有宗教巫术观念的诗作很少。
即使是《周颂》这样的祭祀诗中，面对冥冥中的先祖，周人也并不把自身的一切托付于神，更重要的意义是借此追念先公先王的道德功业，表达自己要“不懈于位”、要敬德保民，以求国家长治久安的想法。
这里没有像古希腊奥林匹斯山上众神存在的场所，他们也不能相信神能主宰自己的命运并决定自己的生活，在这里人就是自己生活的主宰，也是诗歌的全部内容，情感投射的全部指向。
他们是那样肯定自己，信任自己，尽情地表现着自己，并且以自已的创作实践，把“文学是人学”这一在西方近代社会才真正提出的永恒命题，在这里给予了充分的表现，并且奠定了以人为本而不是以神为本的中国诗歌发展的民族心理传统。
它使《诗经》充满了浓郁的人情味，使诗成为表达周人宗族伦理情感和乡土情结的最好形式，凡是他们的念亲、爱国、思旧、怀乡等各种喜怒哀乐之情，都可以在这里得到最好的表达。
2019-2020学年黑龙江省大兴安岭漠河县第一中学高二上学期第二次月考语文试题(解析版)
黑龙江省大兴安岭漠河县第一中学2019-2020学年高二上学期第二次月考语文试题（试卷满分：150分时间：150分钟）一、现代文阅读(36分)（一）论述类文本阅读（本题共3小题，9分）阅读下面的文字，完成1～3题。
无丑不成戏，无丑亦不成班。
然而世人以为丑角不入行，连配角都算不上，不过是插科打诨而已。
其实不然，丑角的唱念做打皆有独到的功夫，且无不有绝妙的特定程式。
至于丑角的意义，司马迁在《史记》中专写《滑稽列传》，并在《太史公自序》中认为俳优“不流世俗，不争势利，上下无所凝滞，人莫之害，以道之用”，故而“谈言微中”“谈笑讽谏”，进而“合于大道”，体现了古之“优谏”精神。
丑角的历史恐怕要比“正角”久远得多。
戏曲的雏形源自西周乐舞和秦汉百戏，其中包括民间杂耍。
所谓秦之“侏儒”，汉之“俳优”，唐之“巷鹘”，元明之“丑”，显现了丑角演变的轨迹。
其中，丑角戏在盛唐才渐至巅峰。
这是因为唐明皇李隆基多才多艺，洒脱好玩，还亲自操刀写曲本，如著名的《霓裳羽衣曲》，即为玄宗对“胡部新声”加以润色而成；他还时常充作鼓手琴师，更喜欢粉墨登场，嗜演丑角。
唐代的“梨园”原为长安光化门北禁苑中与枣园、桃园、樱桃园并存的果园，李隆基常在此请李龟年、雷海青、黄旛绰、公孙大娘、李仙鹤等名伶演戏，剧种有全能戏、歌舞戏、参军戏和傀儡戏，兴之所至少不了也“客串”一把，后来干脆创办“梨园”戏班，开教坊，封伶官，设“坐部伎”“立部伎”，自称梨园“崖公”，“梨园”遂成戏曲的代称并风行起来。
很多人认为唐玄宗喜演丑角，不过是为逗杨贵妃开心罢了。
这未免太小看大唐雄主的气魄。
在笔者来看，唐明皇敢演且擅演与皇上身份完全相反的丑角，源自他不同凡响的喜剧精神和器量，其胸襟、气度，无不与博大包容的盛唐精神相匹配，足可傲视古今。
众所周知，现实世界拥有严酷的、森严的等级秩序，朝廷拥有铁定的无上权力，芸芸草民只能被动地服从权威、教条和禁忌。
然而人类并不满足于铁定的现实世界，仍需要戏仿的、自由的虚拟世界，帝王也不例外：一则想象彼岸世界以寓存死后的灵肉——皇陵不过是它的投影而已；二则纵情艺术世界以欢娱精神——音乐、绘画、舞蹈和戏曲，无不成了他们戏仿的艺术形式。
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英语试题满分：120分；考试时间：100分钟；第一部分阅读理解（共两节，满分40分)第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项。
AWhen asked about happiness, we usually think of something extraordinary, an absolute delight, which seems to get rarer the older we get.For kids, happiness has a magical quality. Their delight at winning a race or getting a new bike is unreserved(毫不掩饰的).In the teenage years the concept of happiness changes. Suddenly it’s conditional on such things as excitement, love and popularity. I can still recall the excitement of being invited to dance with the most attractive boy at the school party.In adulthood the things that bring deep joy-- love, marriage, birth--also bring responsibility and the risk of loss. For adults, happiness is complicated(复杂的).My definition of happiness is “the capacity for enjoyment”. The more we can enjoy what we have, the happier we are. It’s easy to overlook the pleasure we get from the company of friends, the freedom to live where we please, and even good health.I experienced my little moments of pleasure yesterday. First I was overjoyed when I shut the last lunch-box and had the house to myself. Then I spent an uninterrupted morning writing, which I love. When the kids and my husband came home, I enjoyed their noise after the quiet of the day. Psychologists tell us that to be happy we need a mix of enjoyable leisure time and satisfying work. I don’t think that my grandmother, who raised 14 children, had much of either. She did have a network of close friends and family, and maybe this is what satisfied her.We, however, with so many choices and such pressure to succeed in every area, have turned happiness into one more thing we’ve got to have. We’ve so self-conscious about our “right” to it that it’s maki ng us miserable. So we chase it and equal it with wealth and success, without noticing that the people who have those things aren’t necessarily happier.Happiness isn’t about what happens to us--it’s about how we see what happens to us. It’s the skillful w ay of finding a positive for every negative. It’s not wishing for what we don’t have, but enjoying what we do possess.1. As people grow older, they ____.A. feel it harder to experience happinessB. associate their happiness less with othersC. will take fewer risks in pursuing happinessD. tend to believe responsibility means happiness2. What can we learn about the author from Paragraph 5 and 6?A. She cares little about her own healthB. She enjoys the freedom of travelingC. She is easily pleased by things in daily lifeD. She prefers getting pleasure from housework3. People who equal happiness with wealth and success ____.A. consider pressure something blocking their wayB. stress their right to happiness too muchC. are at a loss to make correct choicesD. are more likely to be happy4. What can be concluded from the passage?A. Happiness lies between the positive and the negative.B. Each man is the master of his own fate.C. Success leads to happiness.D. Happy is he who is content.BAs I was walking home，a boy seemed to be singing a song in a very low voice，walking in front of me and carrying some of the same high school books I had with me.I caught up to him，and said “Hello”．I could tell he was startled，and dropped one of his books.I picked it up and as I handed it to him，he said “Thank you.” in a strange way，like with a strong accent.We soon began walking together and talking.It turns out he was in my science class，and I didn’t even know it!His name was Ahmad，and his family had just moved here this school year.He invited me into his house，and his family treated me like a special guest，which made me feel very welcome.He said hospitality (好客) is very basic to his culture，and strangers were always treated verykindly.His mom brought out some great food，and offered me some tea.Ahmad’s father and two sisters wanted to hear all about me and my family，and my schooling.Ahmad’s whole family had to leave their lifelong ho me because war had broken out，and it wasn’t safe there anymore.They left with only what they could carry.His family was happy to feel safe，and they got used to American culture quickly.They seemed pleased that Ahmad had brought a friend home to meet them.And as my friendship with Ahmad has continued，I now realize that the world is so much bigger than I thought！I also realize that your friends don’t have to be just like you.Differences make the world go round.5．What does the underlined word “startled” in P aragraph 1 mean?A．Excited. B．Moved.C．Surprised. D．Interested.6．Why was the writer treated like a special guest by Ahmad’s family?A．They liked strangers who came to their home for help.B．They wanted to know more information about the writer.C．Strangers were always treated very kindly in their culture.D．The writer was an American and knew much about their culture.7．Where does the writer probably come from?A．Canada. B．America.C．China. D．Australia.8．What can we learn from the passage?A．People from different countries can be good friends.B．Friends need different cultures and different accents.C．Your friends should have a lot of things the same with you.D．You can’t make friends with people from other countries.CThe Winter Olympics is also called the White Olympics. At this time, many colorful stamps are published to mark the great Games. The first stamps marking the opening came out on January 25, 1932 in the United States for the 3rd White Olympics. From then on, publishing stamps during the White Olympics became a rule. During the 4th Winter Olympic Games a group of stamps werepublished in Germany in November 1936. The five rings of Olympics were drawn on the front of the sportswear. It was the first time that the rings appeared on the stamps of the White Olympics. In the 1950’s, the stamps of this kind became more colorful.When the White Olympics came, the host countries(东道国) as well as the non-host countries published stamps to mark those Games. China also published four stamps in February 1980, when the Chinese sports men began to take part in the White Olympics. Japan is the only Asian country that has ever held the White Olympics. Altogether 14,500 million stamps were sold to raise money for this sports meet. Different kinds of sports were drawn on these small stamps. People can enjoy the beauty of the wonderful movements of some sportsmen.9．The White Olympics and the Winter Olympics _______.A．are the same thing B．are different gamesC．are not held in winter D．are held in summer10．The world made it a rule to publish stamps to mark the great world games _______. A．after the year 1936 B．after the 3rd White OlympicsC．before the 3rd White Olympics D．before the year 193211．The Winter Olympics is held once _______.A．every two years B．every three yearsC．every four years D．every five years12．Which of the following is true?A．Only the host countries can publish stamps to mark those Games.B．Only the non-host countries can publish stamps to mark those Games.C．All the countries can publish stamps to mark those Games.D．Japan can’t publish stamps to mark those GamesDEP Portable HeaterWe all know that the cost of heating our homes will continue to be a significant burden on the family budget. Now millions of people are saving on their heating bills with the EP Portable Heater. With over one million satisfied customers around the world, the new EP heats better and faster, saves more on heating bills, and runs almost silent.The EP has no exposed heating parts that can cause a fire. The outside of the EP only gets warm to the touch so that it will not burn children or pets.The EP will not reduce oxygen in the room. With other heaters, you’ll notice that you get sleepy when the heat comes on because they are burning up oxygen.The advanced EP also heats the room evenly, wall to wall and floor to ceiling. It comfortably covers an area up to 350 square feet. Other heaters heat rooms unevenly with most of the heat concentrated to the center of the room. And they only heat an area a few feet around the heater. With the EP, the temperature will not vary in any part of the room.The EP comes with a 3-year warranty(保修) and a 60-day, no questions asked, satisfaction guarantee. If you are not totally satisfied, return it at our expense and your money will be given back to you.Now we have a special offer for 10 days, during which you can enjoy a half price discount and a free delivery. If you order after that, we reserve the right to either accept or reject order requests at the discounted price.Take action right now!13. From the passage, we can learn that the EP ___ .A. doesn’t burn up oxygenB. runs without any noiseC. makes people get sleepyD. is unsuitable for children and pets14. The underlined word “evenly” in paragraph 4 probably means ___.A. continuouslyB. separatelyC. quicklyD. equally15. The main purpose of the passage is to___.A. persuade people to buy the productB. advise people to save on heating billsC. report the new development of portable heatersD. compare the functions of different heater brands第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。