上海市控江中学2014届高三月考考试卷(含答案)
上海市控江中学高三化学月考试卷含解析

上海市控江中学高三化学月考试卷含解析一、单选题(本大题共15个小题,每小题4分。
在每小题给出的四个选项中,只有一项符合题目要求,共60分。
)1. 下列实验对应的结论不正确的是A.①能组成Zn-Cu原电池 B.②能证明非金属性Cl>C>SiC.③能说明2NO2N2O4 △H<0 D.④中自色沉淀为BaSO4参考答案:B试题分析:A、该装置可以构成Zn、Cu、硫酸铜原电池,故A正确;B、根据实验可以得出酸的酸性顺序是:盐酸>碳酸>硅酸,可以证明非金属性C>Si,但是不能证明Cl>C,因为不是氯元素的最高价含氧酸,故B错误;C、把盛有二氧化氮气体的圆底烧瓶放在冷水浴中,颜色变浅,则平衡正向移动,放在热水中,颜色加深,则平衡逆向移动,说明2NO2N2O4△H<0,故C正确;D、硝酸钡中通入二氧化硫后,存在的硝酸可以将亚硫酸根氧化为硫酸根而产生硫酸钡白色沉淀,故D正确,故选B。
考点:考查化学实验方案的评价2. 运用有关概念判断下列说法正确的是A.NH4Cl中有离子键,是离子化合物B.46g C2H5OH燃烧放出的热量为乙醇的燃烧热C.互为同系物D.绿色化学的核心是应用化学原理对环境污染进行治理参考答案:A46g C2H5OH燃烧时的产物是否是最稳定的物质,未作说明,故B不正确;是酚类,是烃类,两者不是同系物,C错误;绿色化学核心是从源头控制,避免产生污染,D错误。
3. 下列实验操作能够达到实验目的的是A.从溴水中提纯单质溴的方法是:先用CCl4萃取,分液后再蒸馏B.取少量溶液X,向其中加入适量新制氯水,再加几滴KSCN溶液,溶液变红,说明X 溶液中一定含有Fe2+C.用盛NaOH溶液的洗气瓶除去CO2中混有的HCl气体D.在实验室里,用澄清的石灰水和氯化铵溶液混合制取氨气参考答案:A略4. 下列画有横线的物质在反应中不能完全消耗的是A.将含少量CO2的CO气体通入盛有足量Na2O2的密闭容器中,并不断用电火花引燃B.将l mol Mg置于10 L空气(标况)中,使之在高温下反应C.标准状况下,将11.2L H2S与22.4L O2混合点燃D.在强光持续照射下,向过量的Ca(ClO)2的悬浊液中通入少量CO2参考答案:D略5. 复印机实际上是一种静电印刷电器,它通过可重复使用的光感器进行工作,在复印机附近会闻到一种特殊气味,离复印机越近气味越浓,若用湿润的KI淀粉试纸检验,则试纸变成蓝色,该气体可能为A、 B、 C、 D、参考答案:B6. 实验室用酸碱中和滴定的方法测定某未知浓度的NaOH溶液的浓度,实验数据如下表:滴定次数待测NaOH溶液的体积(mL)0.1000mol/L标准盐酸的体积(mL)滴定前刻度V1滴定后刻度V2120.000.2121.72 220.000.0221.74 320.000.2221.73下列说法中不正确的是A.滴定曲线可用右图中的曲线b来表示B.该NaOH溶液的物质的量浓度为0.1079mol/LC.该滴定实验可选用酚酞作指示剂D.若量取NaOH溶液时开始仰视,后来平视,则测定结果会偏高参考答案:B7. 下列有关胶体的说法错误的是()A.实验室常用渗析的方法对胶体提纯B.硅酸胶体中逐滴加入氢氧化钠溶液,先有沉淀生成再看到沉淀溶解C.所有的胶体均能发生电泳D.由于土壤胶粒带负电,因此使用NH4+的肥效比NO3-高参考答案:略8. 天然气和液化石油气(主要成分为C3~C5的烷烃)燃烧的化学方程式分别为: CH4+ 2O2CO2+ 2H2O,C 3H8+ 5O2 3CO2+4H2O现有一套以天然气为燃料的灶具,今改用液化石油气,应采取的正确措施是() A.增大空气进入量或减小石油气进入量B.减小空气进入量,增大石油气进入量C.减小空气进入量,减小石油气进入量D.减小空气进入量或增大石油气进入量参考答案:A略9. 已知:2KMnO4+16HCl===2KCl+2MnCl2+5Cl2↑+8H2O;Cl2+2FeCl2===2FeCl3;2KI+2FeCl3===2KCl+I2+2FeCl2。
上海市控江中学2024届高三上学期9月月考数学试题

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上海市高三化学月考试卷(附答案)[整理].docx
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上海市高三化学月考试卷(附答案)(时间:120分钟,满分:150分)本卷可能用到的相对原子质量:H—1 B—10.8 C—12 0—16 S—32 Na—23 K—39 Cu—64 Ba—137 N—14第I卷(共66分)一、选择题(本题共10分,每小题2分,只有一个正确选项)1.引起现代家庭装饰室内空气质量下降的有毒物质是()A.—氧化碳B.甲烷C.甲醇D.甲醛2.人体内的微量元素共有20多种,这些总和虽不足人体质量的千分之一,但对机体的生理作用却不可忽视,碘元素就是其中的一种。
人类日常食用的加碘盐是指在食盐中加入了()A.单质碘B.碘化钾3.下列物质用途错误的是()A.天然气用于民用燃料C.碘酸钾 D.含碘有机物B.纯酒精用作医用消毒D.福尔马林用于浸制生物标本4.光缆通讯能同时传输大量信息,一条光缆通路可同时容纳十亿人通话,也可以同时传送多套电视节目,是一种现代化通讯手段。
制造电缆主要材料是()A.光导纤维B.氧化铝陶瓷C.合成纤维D.天然有机高分了材料5.下列表达式中错误的是()A.氨分子的电子式:B.氧化钠的电子式:Na+[ : O : ]2_Na+C.氯离子的离子结构示意图:D.硫离子的核外电子排布式:ls^s^p^s^pA ©A" 7丿77二、选择题(本题共36分,每小题3分,只有一个正确选项)6.对于右图所示装置的叙述正确的是()A.Z n为正极,电极上有氢气放出B.C u为负极,电极上有氢气放出C.这是一个原电池的装置,Cu为正极,Zu为负极D.这是电解稀硫酸的装置,Cu为阳极,Zn为阴极A.CU2\ K\ S2、crC.Na+、HC(V、Ba2+, NO3B.NH4+、Na+、SO42、A1O2D.H+、Ba2+, NO3—、I&为了确定某物质是否变质,所选试剂(括号内物质)达不到实验要求的是(A.K2SO3是否被氧化(BaCl2)C.KI是否被氧化(淀粉溶B.FeSO4是否被氧化(KSCN)D.漂粉精是否变质(盐酸)9. 可逆反应:(I)2A(g) + B(g) =2C(g) + Q (Q>0) ,(II)3A(g 尸 D(g) + E(g) + Q (Q<0),下列条件均能使反应(I )、(II)中A 的转化率增大的是( ) ① 增大压强②升高温度③增加A 的浓度11.在25°C 时,浓度均为 lmol/L 的(NH 4)2SO 4^ (NH^CCh 、(NH 4)2Fe(SO 4)2 (硫酸亚铁钱) 三种溶液中,测得其中C (NH 4+)分别为a 、b 、c (mol/L),则下列判断正确的是( )12. “绿色化学”对化学反应提出了 “原子经济性”(即节约原子)的新概念,理想的原子经 济性反应是原料分子中原子全部转化在所要得到的产物中,不产生副反应,实现零排放。
2014年上海市高中毕业统一学业考试化学试卷(word解析版)

2014年全国普通高等学校招生统一考试上海化学试卷考生注意:1.本试卷满分l50分,考试时问120分钟·2.本考试设试卷和答题纸两部分,试卷包括试题与答题要求;所有答题必须涂(选择 题)或写(非选择题)在答题纸上;做在试卷上一律不得分。
3.答题前,考生务必在答题纸上用钢笔或圆珠笔清楚填写姓名、准考证号,并将核对后的条形码贴在指定位置上。
4.答题纸与试卷在试题编号上是一一对应的,答题时应特别注意,不能错位。
相对原子质量: H-1 C-12 O-16 Na-23 S-32 Cl-35.5 Zn-65 As-75一、 选择题(本题共10分,每小题2分,每小题只有一个正确选项) 1.“玉兔”号月球车用Pu 23894作为热源材料,下列关于Pu 23894的说法正确的是A .Pu 23894与U 23892互为同位素B .Pu 23894与Pu 23994互为同素异形体C .Pu 23894与U 23892具有完全相同的化学性质D .Pu 23894与Pu 23994具有相同的最外层电子2.下列试剂不会因为空气中的氧气而变质的是A .过氧化钠B .氢硫酸C .硫酸亚铁D .苯酚3.结构为…—CH=CH —CH=CH —CH=CH —CH=CH-…的高分子化合物用碘蒸气处理后,其导电能力大幅度提高。
上述高分子化合物的单体是A .乙炔B .乙烯C .丙烯D .1,3-丁二烯4.在“石蜡→液体石蜡→石蜡蒸气→裂化气”的变化过程中,被破坏的作用力依次是A .范德华力、范德华力、范德华力B .范德华力、范德华力、共价键C .范德华力、共价键、共价键D .共价键、共价键、共价键5.下列分离方法中,和物质的溶解度无关的是A .升华B .萃取C .纸上层析D .重结晶二、 选择题(本题共36分,每小题3分,每题只有一个正确选项) 6.今年是门捷列夫诞辰180周年,下列事实不能用元素周期律解释的只有A.碱性:KOH > NaOH B.相对原子质量:Ar > KC.酸性HClO4 > H2SO4D.元素的金属性:Mg > Al7.下列各组中两种微粒所含电子数不相等的是A.H3O+和OH―B.CO和N2C.HNO2和NO2―D.CH3+和NH4+8.BeCl2熔点较低,易升华,溶于醇和醚,其化学性质与AlCl3相似。
上海市2014届高三普通高等学校招生全国统一模拟考试化学试题 Word版含答案.pdf

26.上述元素中有两种元素是同一主族,可以作为判断两者非金属性强弱的依据的是
(填编号)。
.两种形成共价中的偏向
.最高价氧化物熔沸点高低
.最高价氧化物水化物的酸性
d.
五(本题共8分)
用钛铁矿(FeTiO3)提取钛主要过程如下:
步骤1:在加热条件下,用硫酸溶解10.0g钛铁矿,将TiO32转化为TiO2+,生成FeSO4;
淀生成,小试管中发生反应的化学方程式是__________________。
38.为了检验M的组成,进行下列实验。
① M能被磁铁吸引;加入足量稀硫酸,振荡,固体全部溶解,未观察到有气体生成;
31.在一定条件下将2 mol CO和6 mol H2充入2 L的密闭容器中发生反应,5分钟后测得c(H2)=1.5 mol/L,则此段
时间内的反应速率(用CH3OH表达)________ mol/(L·min)。
32.由表中数据分析可知,Q
0(填“>”、“<”或“=”)。其它条件不变的情况下,若压缩容器的体
步骤2:利用降温结晶法,使得绿矾析出,滤出绿矾后,加热滤液水解得到钛酸(H2TiO3),将钛酸进行焙烧制得
TiO2。
步骤3:TiO2 + C + Cl2
TiCl4 + CO (未配平)
步骤4:TiCl4(g)+ Mg(g) → Ti(s) + MgCl2(l) (未配平)
请结合上述信息完成下列问题:
结合上述反应完成下列填空:
23.上述反应所涉及的元素中,原子核外电子运动状态最多的元素在周期表中位
________________,其氧化物属于
晶体。
24.上述元素中有三种元素处于相邻位置,其原子半径从大到小的顺序为
2014年上海市普通高中学业水平考试化学试卷 Word版含

2014年上海市普通高中学生学业水平考试化学试卷(考试时间90分钟,满分100分)相对原子质量:H—1,O—16,Na—23,Mg—24,S—32,Cl—35.5,Fe—56,Ba—137一、选择题(本题共40分,每小题2分。
每小题只有一个正确答案)1.可以用电子式表示的微粒是A. HeB. NeC. Na+D. S2-2.下列物质中只存在共价键的是A. 金刚石B. 铝C. 氩气D. 硫酸钾3.关于146C的叙述错误的是A. 质子数为6B. 电子数为6C. 中子数为6D. 质量数为144.大多数有机化合物不具有的性质是A. 熔、沸点高B. 易燃烧C. 热稳定性差D. 反应慢且副反应多5.下列各组物质组成相同的是A. 乙炔、电石气B. 乙酸、食醋C. 乙醇、消毒酒精D. 甲醛、福尔马林6. 0.10mol/L的NH4Cl溶液中,离子浓度最小的是A. NH4+B. H+C. Cl-D. OH-7.在下列物质的溶液中滴入AgNO3溶液,产生淡黄色沉淀,加入稀HNO3后沉淀不消失的是A. NaClB. NaBrC. KID. K2CO38.既能由单质间通过化合反应制得,又能在溶液中通过复分解反应制得的物质是A. FeSB. Fe(OH)2C. FeOD. Fe3O49.下图是Cu-Zn原电池的装置示意图,下列叙述正确的是A.Zn片是阳极B.H+在铜片上得电子C.反应过程中电能转变为化学能D.电子从锌片通过硫酸溶液流向铜片10.下列电离方程式正确的是A.NaOH →Na++O2-+ H+B.H2O →H+ +OH-C.HClO ClO-+ H+D.CH3COONH4CH3COO- + NH4+11.下列关于实验室制取NH3的叙述正确的是A.用N2和H2作反应物 B.用碱石灰干燥C.用向上排空气法收集 D.用湿润的蓝色石蕊试纸验满12.某古玩爱好者收藏的“商代铝碗”在“鉴宝”时被专家当场否定,其理由是A.铝的导热性较强,不易做碗B.铝的质地较软,易变形,不易做碗C.铝元素易导致老年痴呆,不易盛放食物D.铝的性质较活泼,难提炼,商代不可能有铝制品13.粗盐提纯的实验中,不需要进行的操作是14.某无色溶液中存在大量的Ba+、NH4+、Cl-,该溶液中还可能大量存在的离子是A. Fe3+B. CO3-C. Mg2+D. OH-15.已知热化学方程式H2 (g)+Br2 (l) → 2HBr(g)+72.8kJ。
2014年高考物理上海卷试卷及答案word版

(A) A的示数增大
(C) △V3与△I的比值大于r
(B) V2的示数增大
(D) △V1大于△V2
19、静电场在x轴上的场强E随x的变化关系如图所示,x轴正向为场强正方向,带正电的点电荷沿x轴运动,则点电荷
(A)A体积增大 (B)A体积减小
(C) △FA △FB(D)△pA<△pB
21、牛顿第一定律表明,力是物体发生变化的原因;该定律引出的一个重要概念是。
22、动能相等的两物体A、B在光滑水平面上沿同一直线相向而行,它们的速度大小之比vA:vB=2: 1,则动量大小之比PA:PB=;两者碰后粘在一起运动,其总动量与A原来动量大小之比P:PA=。
(1)求箱子加速阶段的加速度大小a'。
(2)若a>g tan ,求减速阶段球受到箱子左壁和顶部的作用力。
评卷人
得分
四、综合题
33、如图,一对平行金属板水平放置,板间距为d,上极板始终接地。长度为d/2、质量均匀的绝缘杆,上端可绕上板中央的固定轴0在竖直平面内转动,下端固定一带正电的轻质小球,其电荷量为q。当两板间电压为U1时,杆静止在与竖直方向00′夹角 =300的位置;若两金属板在竖直平面内同时绕O、O′顺时针旋转 =150至图中虚线位置时,为使杆仍在原位置静止,需改变两板间电压。假定两板间始终为匀强电场。求:
(A)在x2和x4处电势能相等
(B)由x1运动到x3的过程中电势能增大
(C)由x1运动到x4的过程中电场力先增大后减小
(D)由x1运动到x4的过程中电场力先减小后增大
上海市六校联考2014届高三上学期12月月考化学试题(Word版 含解析)

2013-2014学年上海市六校联考高三(上)月考化学试卷(12月份)一、选择题(本题共10分,每小题2分,只有一个正确选项)1.(2分)(2014•九江二模)下列说法正确的是()A.“雾霾”与“风雨雷电”一样属于一种自然现象B.塑化剂是一种应用很广的化工塑料软化剂,可大量添加到婴幼儿玩具中C.利用潮汐能发电能达到节能减排的目的D.P M2.5的产生与人类活动无关2.(2分)(2013秋•上海月考)硫化氢分子中,形成共价键的原子轨道是()A.硫原子的2p轨道和氢原子的1s轨道B.硫原子的2p轨道和氢原子的2p轨道C.硫原子的3p轨道和氢原子的1s轨道D.硫原子的2p轨道和氢原子的3p轨道3.(2分)(2013秋•越城区校级期末)用酸性KMnO4溶液不能达到预目的是()A.区别苯和甲苯B.检验硫酸铁溶液中是否有硫酸亚铁C.检验CH2=CHCHO中含碳碳双键D.区别SO2和CO24.(2分)(2013秋•上海月考)下列推断正确的是()A.N a2O和Na2O2组成元素相同,与CO2反应产物也相同B.SO2和CO2都是酸性氧化物,都能与NaOH溶液反应C.N O和NO2的密度均比空气大,都可用向上排空气法收集D.C3H8和CH3CH2OH相对分子质量相近,分子间作用力相近,二者沸点也相近5.(2分)(2013•淇县校级模拟)氧化还原反应中,水的作用可以是氧化剂、还原剂、既是氧化剂又是还原剂、既非氧化剂又非还原剂等.下列反应与Br2+SO2+2H2O=H2SO4+2HBr相比较,水的作用不相同的是()①2Na2O2+2H2O=4NaOH+O2↑②4Fe(OH)2+O2+2H2O=4Fe(OH)3③2F2+H2O=4HF+O2④2Al+2NaOH+2H2O=2NaAlO2+3H2.A ①②B.③④C.①③.②④二、选择题(本题共36分,每小题3分,只有一个正确选项)6.(3分)(2013秋•天心区校级月考)向溶液X中持续通人气体Y,会产生“澄清一浑浊一澄清”现象的是()A.X:漂白粉溶液Y:二氧化硫B.X:硝酸钡溶液Y:二氧化硫C.X:氯化铝溶液Y:氨气D.X:偏铝酸钠溶液Y:二氧化氮7.(3分)(2013秋•上海月考)如图集气瓶中用滤纸折成的纸蝴蝶上喷洒了一种溶液,通入某种气体后,实验结果与预测的纸蝴蝶颜色变化不一致的是()A B C D喷洒液酚酞黄色甲基橙紫色石蕊酸化的KI﹣淀粉通入的气体NH3Cl2SO2O2预测的颜色变化变为红色先橙后褪色先红后褪色变为蓝色A.A B.B C.C D.D8.(3分)(2015•吉林校级二模)在两个密闭容器中,分别充有质量相同的甲、乙两种气体,若它们的温度和密度均相同,试根据甲、乙的摩尔质量(M)关系,判断下列说法正确的是()A.若M(甲)>M(乙),则气体体积:甲<乙B.若M(甲)<M(乙),则气体的压强:甲>乙C.若M(甲)>M(乙),则气体的摩尔体积:甲<乙D.若M(甲)<M(乙),则的分子数:甲<乙9.(3分)(2013秋•上海月考)一定条件下,碳钢腐蚀与溶液pH的关系如下:pH 2 4 6 6.5 8 13.5 14腐蚀快慢较快慢较快主要产物Fe2+Fe3O4Fe2O3FeO2﹣下列说法不正确的是()A.在煮沸除氧气后的碱性溶液中,碳钢腐蚀速率会减缓B.在pH>6溶液中,碳钢主要发生吸氧腐蚀C.在pH>7溶液中,碳钢腐蚀的正极反应为O2+4H++4e→2H2OD.在pH<4溶液中,碳钢主要发生析氢腐蚀10.(3分)(2013秋•上海月考)25℃时,下列溶液中水的电离程度最小的是()A.0.01mol/L NaHSO4B.0.1mol/L Na2CO3溶液C.p H=4盐酸溶液D.p H=11氨水11.(3分)(2013秋•上海月考)N A表示阿伏加德罗常数的值,常温下,抽去如图所示装置中的玻璃片,使两种气体充分反应.下列说法正确的是()A.反应前气体的总体积为0.448LB.生成物中含有0.01N A个分子C.装置中氢元素的总质量为0.04gD.生成物完全溶于水后所得溶液含有0.01N A个NH4+12.(3分)(2014•晋中模拟)药物贝诺酯可由乙酰水杨酸和对乙酰氨其酚在一定条件下反应制得:下列有关叙述正确的是()A.1mol贝诺酯分子可与9mol H2完全反应B.可用FeCl3溶液区别乙酰水杨酸和对乙酰氨基酚C.贝诺酯与足量NaOH溶液共热,最终生成乙酰水杨酸钠和对乙酰氨基酚钠D.乙酰水杨酸和乙酰氨基酚均可与NaHCO3溶液反应13.(3分)(2013秋•上海月考)元素R、X、T、Z、Q在元素周期表中的相对位置如图所示,其中R单质在暗处与H2剧烈化合并发生爆炸.则下列判断正确的是()A.非金属性:T<X<RB.气态氢化物稳定性:R<T<QC.R与Q的电子数相差16D.X与Q最高价氧化物的水化物的质子数相差1814.(3分)(2014•青浦区一模)根据表中信息判断,下列选项不正确的是()序号反应物产物①KMnO4、H2O2、H2SO4K2SO4、MnSO4②Cl2、FeBr2FeCl3、FeBr3③MnO4﹣Cl2、Mn2+A.第①组反应的其余产物为H2O和O2B.第②组反应中参加反应的Cl2与FeBr2的物质的量之比为1:2C.第③组反应中生成1mol Cl2,转移电子2molD.氧化性由强到弱顺序为MnO4﹣>Cl2>Fe3+>Br215.(3分)(2012•桃城区校级三模)在200mL某硫酸盐溶液中含有1.5N A个硫酸根离子(N A表示阿伏加德罗常数),同时含有N A个金属阳离子,则该硫酸盐的物质的量浓度为()A.1mol•L﹣1B.2.5mol•L﹣1C.5mol•L﹣1D.2mol•L﹣116.(3分)(2014•黄浦区一模)人们在自然界中找到了组成为Al63Cu24Fe13的天然准晶体,将100g的此准晶体分别与足量的盐酸、烧碱和稀硝酸反应,产生气体的物质的量关系为()A.n(稀硝酸)<n(烧碱)<n(盐酸)B.n(烧碱)<n(盐酸)<n(稀硝酸)C.n(烧碱)<n(稀硝酸)<n(盐酸)D.n(盐酸)<n(稀硝酸)<n(烧碱)17.(3分)(2014秋•奉贤区期末)某废水含有下列离子中的5种(忽略水的电离及离子的水解),K+、Cu2+、Al3+、Fe2+、Cl﹣、CO32﹣、NO3﹣、SO42﹣,测得各种离子的物质的量浓度相等.为探究废水的组成,某同学进行了如下实验:①用铂丝蘸取少量溶液,在火焰上灼烧,透过蓝色钴玻璃观察无紫色火焰.②另取溶液加入足量稀盐酸,有无色气体生成,该无色气体遇空气变成红棕色,此时溶液依然澄清,且溶液中阴离子种类不变.③另取溶液加入BaCl2溶液,有白色沉淀生成.根据上述实验,以下推测正确的是()A.溶液中无法确定Al3+的存在与否B.原溶液中不含的离子为:K+、Al3+、CO32﹣C.步骤②中可以确定Fe2+、NO3﹣的存在D.步骤③中共有2种钡盐沉淀三、选择题:(本题共20分),每小题4分,每小题有一个或两个正确选项.只有一个正确选项的,多选不给分;有两个正确选项的,选对一个给2分,选错一个该小题不给分.18.(4分)(2013秋•上海月考)在5.6g Fe粉中加入过量的稀硫酸溶液,待反应完全后,再加入1mol•L﹣1KNO3溶液25mL,恰好反应完全.该反应的方程式为:FeSO4+KNO3+H2SO4→K2SO4+Fe2(SO4)3+N x O y+H2O(未配平),则对该反应的下列说法正确的是()A.化学方程式中按物质顺序的计量数是:8、2、5、1、4、1、5B.反应中氧化产物是N2OC.反应过程中转移的电子数为8mol电子D.氧化产物和还原产物的物质的量之比为4:119.(4分)(2013•盐城一模)在常温下,0.1000mol•L﹣1 Na2CO3溶液25mL用0.1000mol•L﹣1盐酸滴定,滴定曲线如图.对滴定过程中所得溶液中相关离子浓度间的关系,下列说法正确的是()A.a点:c(CO32﹣)>c(HCO3﹣)>c(OH﹣)B.b点:5c(Cl﹣)>4c(HCO3﹣)+4c(CO32﹣)C.c点:c(OH﹣)=c(H+)+c(HCO3﹣)+2c(H2CO3)D.d点:c(H+)=2c(CO32﹣)+c(HCO3﹣)+c(OH﹣)20.(4分)(2013秋•上海月考)N2(g)+3H2(g)═2NH3(g)+92.4kJ.恒容时,体系中各物质浓度随时间变化的曲线如图示.下列说法错误的是()A.前20分钟反应内放出的热量为46.2kJB.第25分钟改变的条件是将NH3从反应体系中分离出去C.若第60分钟时反应又达到了平衡,则时段Ⅲ改变的条件是增大压强D.时段Ⅰ仅将初始投放的物质浓度增至原来的2倍,则反应物的转化率增大,平衡常数不变21.(4分)(2014春•金牛区校级期末)为了证明硫酸亚铁铵[(NH4)2Fe(SO4)26H2O]晶体的成分中含有NH4+、Fe2+、SO42﹣和H2O,下列实验叙述中不正确的是()A.取少量硫酸亚铁铵晶体放入试管中,加热,试管口有液体生成,则可证明晶体的成分中含有结晶水B.取少量硫酸亚铁铵晶体放入试管,加浓NaOH溶液,加热,试管口湿润的蓝色石蕊试纸变红,则可证明晶体的成分中含有NH4+C.取适量硫酸亚铁铵晶体溶于水,加少量稀盐酸,无现象,再滴入几滴BaCl2溶液,有白色沉淀生成,则可证明晶体的成分中含有SO42﹣D.取适量硫酸亚铁铵晶体溶于水,得浅绿色溶液,滴入2滴KSCN溶液,溶液不显血红色,再滴入几滴新制氯水,溶液变为血红色,则可证明晶体的成分中含有Fe2+22.(4分)(2013秋•上海月考)将Cu、Cu2O和CuO均匀混合物分成两等份,其中一份用足量的CO还原,测得反应后固体质量减少6.4g,另一份中加入150mL某浓度的硝酸,固体恰好完全溶解,且同时收集到标准状况下NO X气体6.72L,则所用硝酸的物质的量浓度可能为()A.8.0mol•L﹣1B.9.0mol•L﹣1C.10.0mol•L﹣1D.11.0mol•L﹣1四、解答题(共7小题,满分84分)23.(12分)(2013秋•上海月考)X、Y、Z、M、N是五种短周期元素,原子序数依次增大.X原子中没有中子,Y元素最高正价与最低负价之和为0;M与X同主族;Z、N分别是地壳中含量最高的非金属元素和金属元素.请回答下列问题:(1)五种元素原子半径由大到小的顺序是(写元素符号).(2)X与Y能形成多种化合物,其中既含极性键又含非极性键,且相对分子质量最小的物质(写分子式),M离子的电子排布式为.由以上某些元素组成的化合物A、B、C、D有如下转化关系A B(在水溶液中进行)其中C是溶于水显酸性的气体;D是淡黄色固体.(3)写出C的结构式;D的电子式(4)如果A、B均由三种元素组成,B为两性不溶物,写出由A转化为B的离子方程式(5)如果A由三种元素组成,B由四种元素组成,A、B溶液均显碱性.用离子方程式表示A溶液显碱性的原因.(6)如果将27题中A、B浓度均为0.1mol/L的溶液混合,混合溶液中离子浓度由大到小的顺序是.24.(12分)(2013秋•上海月考)氮气及含氮的化合物在国民经济中占有重要地位.合成氨工业中,合成塔中每产生2mol NH3,放出92.4kJ热量.(1)若起始时向容器内放入2mol N2和6mol H2,达平衡后放出的热量为Q,则Q 184.8kJ(填“>”、“<”或“=”).一定条件下,在密闭恒容的容器中,能表示反应达到化学平衡状态的是.a.3v逆(N2)=v正(H2)b.2v正(H2)=v正(NH3)c.混合气体密度保持不变d.c(N2):c(H2):c(NH3)=1:3:2工业生产尿素的原理是以NH3和CO2为原料合成尿素[CO(NH2)2],反应的化学方程式为2NH3(g)+CO2(g)⇌CO (NH2)2(l)+H2O(l).(2)在一定温度和压强下,若原料气中的NH3和CO2的物质的量之比(氨碳比),如图是氨碳比(x)与CO2平衡转化率(α)的关系.α随着x增大而增大的原因是.(3)如图中的B点处,NH3的平衡转化率为.已知:3Cl2+2NH3→N2+6HCl ①3Cl2+8NH3→N2+6NH4Cl ②(4)完成并配平下列氧化还原反应方程式,再标出电子转移的方向和数目:12Cl2+15NH3→(5)反应③中的还原剂是,还原产物是.(6)若按③反应后产生气体9.408L(标准状况),则被氧化的气体的物质的量是mol.25.(12分)(2013秋•上海月考)根据要求完成下列实验.(a、b 为弹簧夹,其他装置略去)Ⅰ、验证酸性的相对强弱:碳酸>苯酚.(已知酸性:亚硫酸>碳酸)(1)铜与浓硫酸反应的化学方程式是,装置A中的足量的试剂是.(2)连接仪器、、加药品后,打开a关闭b,然后滴入浓硫酸,加热.能说明碳酸的酸性比苯酚酸性强的实验现象是:.Ⅱ、验证SO2具有氧化性、还原性和酸性氧化物的通性.(3)打开b,关闭a.能验证SO2具有氧化性的化学方程式是.(4)若过量的SO2通入NaOH溶液中,其化学方程式是:.(5)BaCl2溶液中无任何现象,将其分成两份,分别滴加氨水和氯水,均产生白色沉淀,沉淀化学式分别是,.(6)写出其中SO2显示还原性并生成白色沉淀的总的离子方程式.26.(12分)(2012•徐州模拟)二氧化氯(ClO2)是一种黄绿色有刺激性气味的气体,其熔点为﹣59℃,沸点为11.0℃,易溶于水.工业上用稍潮湿的KClO3和草酸(H2C2O4)在60℃时反应制得.某学生拟用如图所示装置模拟工业制取并收集ClO2.(1)A中反应产物有K2CO3、ClO2和CO2等,请写出该反应的化学方程式:.(2)A必须添加温度控制装置,除酒精灯外,还需要的玻璃仪器有烧杯、;B也必须添加温度控制装置,应该是(填“冰水浴”或“热水浴”)装置.(3)反应后在装置C中可得NaClO2溶液.已知NaClO2饱和溶液中在温度低于38℃时析出晶体是NaClO2•3H2O,在温度高于38℃时析出晶体是NaClO2.根据如图所示的NaClO2的溶解度曲线,请补充从NaClO2溶液中制得NaClO2的操作步骤:①;②;③洗涤;④干燥.(4)ClO2很不稳定,需随用随制,产物用水吸收得到ClO2溶液.为测定所得溶液中ClO2的含量,进行了下列实验:步骤1:准确量取ClO2溶液10.00mL,稀释成100.00mL试样;量取V1mL试样加入到锥形瓶中;步骤2:调节试样的pH≤2.0,加入足量的KI晶体,静置片刻;步骤3:加入淀粉指示剂,用c mol•L﹣1Na2S2O3溶液滴定至终点,消耗Na2S2O3溶液V2mL.(已知2Na2S2O3+I2═Na2S4O6+2NaI)①滴定过程中,至少须进行两次平行测定的原因是.②原ClO2溶液的浓度为g•L﹣1(用步骤中的字母代数式表示).27.(10分)(2013秋•上海月考)二茂铁(如图)是一种有机过渡金属化合物,不溶于水,易溶于苯、乙醚等有机溶剂.由烃A可制备二茂铁.A分子是一种没有侧链的环状结构,其一氯取代物有三种,1molA最多可与2molBr2加成,其与Br2的1:1加成只得两种产物.(1)A的结构简式为.(2)下列说法正确的是.A.烃A具有烯烃的性质B.烃A具有苯的性质C.烃A分子中所有的碳原子可能在同一平面D.烃A不可能发生取代反应(3)写出A的1,4﹣加成聚合反应的化学方程式二茂铁氯乙酰是有机合成的中间体,下面是其合成路线:(4)写出有关物质的化学式:试剂A ,C (结构简式).(5)B→C的反应类型是,最终合成二茂铁乙酰氯的反应类型是.(6)写出C与足量NaOH溶液反应的化学方程式:.28.(12分)(2013•江苏)化合物A(分子式为C6H6O)是一种有机化工原料,在空气中易被氧化.A 的有关转化反应如下(部分反应条件略去):已知:①②(R表示烃基,R′和R″表示烃基或氢)(1)写出A的结构简式:.(2)G是常用指示剂酚酞.写出G中含氧官能团的名称:和.(3)某化合物是E的同分异构体,且分子中只有两种不同化学环境的氢.写出该化合物的结构简式:(任写一种).(4)F和D互为同分异构体.写出反应E→F的化学方程式:.(5)根据已有知识并结合相关信息,写出以A和HCHO为原料制备的合成路线流程图(无机试剂任用).合成路线流程图示例如下:H2C═CH2CH3CH2Br CH3CH2OH.29.(14分)(2013秋•上海月考)在50mL a mol•L﹣1的硝酸溶液中,加入6.4g Cu,全部溶解,假设硝酸的还原产物只有NO2和NO,将反应后溶液用蒸馏水稀释至100mL时测得c(NO3﹣)=3mol•L﹣1.(1)求稀释后的溶液的pH= .(2)若生成的气体中NO2的物质的量为0.125mol,则a= .(3)治理氮氧化物污染的方法之一是用NaOH溶液进行吸收,反应原理如下:NO2+NO+2NaOH→2NaNO2+H2O 2NO2+2NaOH→NaNO2+NaNO3+H2O若将上述(2)中的NO2和NO的混合气体通入2mol•L﹣1的NaOH恰好被吸收,求NaOH溶液的体积为mL.生成的NaNO2为mol.(4)治理氮氧化物污染的另一种方法,可用氨氧混合气进行选择性催化还原处理.其主要反应原理如下:4NO+4NH3+O24N2+6H2O 6NO2+8NH37N2+12H2O某硝酸厂排放的尾气中氮氧化合物的含量为2490mg/m3(体积已折算至标准状况),其中NO与NO2物质的量比为4:1.设尾气中氮氧化物与氨氧混合气恰好完全反应.①氨氧混合气的平均相对分子质量为(精确到0.01).②要处理5m3的尾气,需要氨氧混合气的体积为L.2013-2014学年上海市六校联考高三(上)月考化学试卷(12月份)参考答案与试题解析一、选择题(本题共10分,每小题2分,只有一个正确选项)1.(2分)(2014•九江二模)下列说法正确的是()A.“雾霾”与“风雨雷电”一样属于一种自然现象B.塑化剂是一种应用很广的化工塑料软化剂,可大量添加到婴幼儿玩具中C.利用潮汐能发电能达到节能减排的目的D.P M2.5的产生与人类活动无关考点:常见的生活环境的污染及治理.专题:化学应用.分析:A.根据雾霾的成因分析;B.塑化剂可导致人慢性中毒;C.潮汐能属于清洁能源,利用潮汐能发电能减少化石燃料的燃烧;D.PM2.5的产生主要人类生活生产等活动造成的.解答:解:A.雾霾是雾和霾的混合物,其中雾是自然天气现象,霾的核心物质是悬浮在空气中的烟、灰尘等物质,主要是人类活动造成的,不是自然现象,故A错误;B.塑化剂可导致人慢性中毒,故不可大量添加到婴幼儿玩具中,故B错误;C.潮汐能属于清洁能源,利用潮汐能发电能减少化石燃料的燃烧,减少有害气体的排放,达到节能减排的目的,故C正确;D.PM2.5的产生主要人类生活生产等活动造成的,故D错误;故选C.点评:本题考查了常见生活环境的污染与治理、能源问题等,难度不大.2.(2分)(2013秋•上海月考)硫化氢分子中,形成共价键的原子轨道是()A.硫原子的2p轨道和氢原子的1s轨道B.硫原子的2p轨道和氢原子的2p轨道C.硫原子的3p轨道和氢原子的1s轨道D.硫原子的2p轨道和氢原子的3p轨道考点:原子核外电子排布.专题:原子组成与结构专题;化学键与晶体结构.分析:H的1s轨道上只有1个电子,S原子的价电子排布式为3s23p4,3个3p原子轨道中两个含有单电子,2个H的1s轨道分别与S的两个3p轨道电子形成共价键,以此来解答.解答:解:H只有1个电子,占据1s轨道,S原子的价电子排布式为3s23p4,3个3p原子轨道中两个含有单电子,2个H的1s轨道分别与S的两个3p轨道电子形成共价键,故选C.点评:本题考查共价键的形成,明确原子的最外层电子占据的能级是解答本题的关键,题目较简单.3.(2分)(2013秋•越城区校级期末)用酸性KMnO4溶液不能达到预期目的是()A.区别苯和甲苯B.检验硫酸铁溶液中是否有硫酸亚铁C.检验CH2=CHCHO中含碳碳双键D.区别SO2和CO2考点:物质的检验和鉴别的实验方案设计.专题:物质检验鉴别题.分析:酸性KMnO4溶液具有强氧化性,可与具有还原性的SO2、硫酸亚铁等物质发生氧化还原反应,可与甲苯、碳碳双键、醛基等基团发生氧化还原反应,以此解答该题.解答:解;A.甲苯可与酸性高锰酸钾溶液发生氧化还原反应,可鉴别,故A不选;B.硫酸亚铁具有还原性,可与酸性KMnO4溶液发生氧化还原反应,可鉴别,故B不选;C.CH2=CHCHO中碳碳双键和醛基都可与酸性高锰酸钾溶液发生氧化还原反应,不能检验是否含有碳碳双键,故C选;D.SO2具有还原性,可与酸性KMnO4溶液发生氧化还原反应,可鉴别,故D不选.故选C.点评:本题考查较为综合,涉及高锰酸钾的性质、常见还原性物质以及有机物官能团的结构和性质,题目难度不大,注意物质的鉴别方法的实验方案的设计.4.(2分)(2013秋•上海月考)下列推断正确的是()A.N a2O和Na2O2组成元素相同,与CO2反应产物也相同B.SO2和CO2都是酸性氧化物,都能与NaOH溶液反应C.N O和NO2的密度均比空气大,都可用向上排空气法收集D.C3H8和CH3CH2OH相对分子质量相近,分子间作用力相近,二者沸点也相近考点:钠的重要化合物;氮的氧化物的性质及其对环境的影响;二氧化硫的化学性质.专题:元素及其化合物.分析:A.Na2O与CO2反应产物是碳酸钠;Na2O2与CO2反应产物为碳酸钠和氧气;B.能够与碱反应只生成盐和水的氧化物属于酸性氧化物;C.NO与空气密度相差不大,不能用排气法收集;D.CH3CH2OH中存在氢键,氢键的存在物质的沸点显著升高.解答:解:A.Na2O和Na2O2组成元素相同,与CO2反应产物不同,故A错误;B.SO2和CO2都能够与NaOH溶液反应,且都只生成盐和水,故B正确;C.NO与空气密度相差不大,不能用排气法收集,故C错误;D.C3H8和CH3CH2OH相对分子质量相近,分子间作用力相近,但是因为乙醇中存在氢键,所以其沸点高于C3H8,故D错误;故选:B.点评:本题考查了物质的性质,明确物质的性质、酸性氧化物的概念,氢键对物质性质的影响是解题关键,注意氢键只影响物质的物理性质.5.(2分)(2013•淇县校级模拟)氧化还原反应中,水的作用可以是氧化剂、还原剂、既是氧化剂又是还原剂、既非氧化剂又非还原剂等.下列反应与Br2+SO2+2H2O=H2SO4+2HBr相比较,水的作用不相同的是()①2Na2O2+2H2O=4NaOH+O2↑②4Fe(OH)2+O2+2H2O=4Fe(OH)3③2F2+H2O=4HF+O2④2Al+2NaOH+2H2O=2NaAlO2+3H2.A.①②B.③④C.①③D.②④考点:氧化还原反应.专题:氧化还原反应专题.分析:应Br2+SO2+2H2O=H2SO4+2HBr中,水中的氢氧元素的化合价都不变,所以水既非氧化剂又非还原剂,据此分析解答.解答:解:①该反应中水中氢、氧元素化合价都不变,所以水既不是氧化剂又不是还原剂,故不选;②该反应中水中氢、氧元素化合价都不变,所以水既不是氧化剂又不是还原剂,故不选;③该反应中水中氧元素失电子作还原剂,故选;④该反应中水中氢元素得电子作氧化剂,故选;故选B.点评:本题考查氧化还原反应,根据水中各元素化合价是否变化来分析解答,难度不大.二、选择题(本题共36分,每小题3分,只有一个正确选项)6.(3分)(2013秋•天心区校级月考)向溶液X中持续通人气体Y,会产生“澄清一浑浊一澄清”现象的是()A.X:漂白粉溶液Y:二氧化硫B.X:硝酸钡溶液Y:二氧化硫C.X:氯化铝溶液Y:氨气D.X:偏铝酸钠溶液Y:二氧化氮考点:二氧化硫的化学性质;氨的化学性质;氮的氧化物的性质及其对环境的影响.专题:元素及其化合物.分析:A.发生氧化还原反应生成硫酸钙;B.发生氧化还原反应生成硫酸钡;C.生成的氢氧化铝,不能溶解在氨水中;D.开始生成氢氧化铝,然后溶解在硝酸中.解答:解:A.漂白粉溶液中通入二氧化硫,发生氧化还原反应生成硫酸钙,溶液变浑浊,不会变澄清,故A错误;B.硝酸钡溶液中通入二氧化硫,发生氧化还原反应生成硫酸钡,溶液变浑浊,不会变澄清,故B错误;C.氯化铝溶液中通入氨气,生成的氢氧化铝,不能溶解在氨水中,溶液变浑浊,不会变澄清,故C错误;D.偏铝酸钠溶液中通入二氧化氮,二氧化氮与水反应生成硝酸,与偏铝酸钠反应生成氢氧化铝,然后溶解在硝酸中生成硝酸铝,则会产生“浑浊→澄清”现象,故D正确;故选D.点评:本题考查物质的性质,为高频考点,综合考查元素化合物知识,把握发生的氧化还原反应、复分解反应为解答的关键,注意物质的溶解性及氢氧化铝的两性,题目难度不大.7.(3分)(2013秋•上海月考)如图集气瓶中用滤纸折成的纸蝴蝶上喷洒了一种溶液,通入某种气体后,实验结果与预测的纸蝴蝶颜色变化不一致的是()A B C D喷洒液酚酞黄色甲基橙紫色石蕊酸化的KI﹣淀粉通入的气体NH3Cl2SO2O2预测的颜色变化变为红色先橙后褪色先红后褪色变为蓝色A.A B.B C.C D.D考点:实验装置综合;氯气的化学性质;氨的化学性质;二氧化硫的化学性质.专题:元素及其化合物.分析:A.氨水能使酚酞试液变红;B.次氯酸有漂白性,能使石蕊试液褪色;C.SO2不能漂白酸碱指示剂;D.淀粉遇碘变蓝色.解答:解:A.氨气溶于水得到氨水,氨水电离出氢氧根离子而使氨水呈碱性,酚酞遇碱变红色,故A不选;B.氯气溶于水生成盐酸和次氯酸,盐酸有酸性而使紫色石蕊试液变红,次氯酸有漂白性而使石蕊试液最终褪色,故B不选;C.SO2不能漂白酸碱指示剂,可使紫色石蕊试液呈红色,故C选;D.氧气能氧化酸化的碘化钾生成碘单质,淀粉遇碘变蓝色,故D不选;故选C.点评:本题考查元素化合物的性质,注意次氯酸能使酸碱指示剂褪色,而二氧化硫不能使酸碱指示剂褪色,为易错点,难度不大.8.(3分)(2015•吉林校级二模)在两个密闭容器中,分别充有质量相同的甲、乙两种气体,若它们的温度和密度均相同,试根据甲、乙的摩尔质量(M)关系,判断下列说法正确的是()A.若M(甲)>M(乙),则气体体积:甲<乙B.若M(甲)<M(乙),则气体的压强:甲>乙C.若M(甲)>M(乙),则气体的摩尔体积:甲<乙D.若M(甲)<M(乙),则的分子数:甲<乙考点:阿伏加德罗定律及推论.专题:阿伏加德罗常数和阿伏加德罗定律.分析:相同温度下,在两个密闭容器中,分别充有等质量、等密度的甲、乙两种气体,根据ρ=可知气体的体积相等,结合n=以及PV=nRT比较压强大小,根据Vm=比较气体摩尔体积大小,根据n=判断气体的物质的量,气体物质的量越大,气体分子数越多.解答:解:A.两个密闭容器中,分别充有等质量、等密度的甲、乙两种气体,根据ρ=可知气体的体积相等,故A错误;B.若M(甲)<M(乙),根据n=,则气体的物质的量:甲>乙,由PV=nRT可知,气体的压强:甲>乙,故B正确;C.根据n=,若M(甲)>M(乙),则气体的物质的量:甲<乙,根据Vm=,故则气体的摩尔体积:甲>乙,故C错误;D.根据n=,若M(甲)<M(乙),则n(甲)>n(乙),则气体的分子数:甲>乙,故D错误;故选B.点评:本题考查阿伏加德罗定律及推论,题目难度不大,本题注意相关计算公式的运用,为解答该题的关键,易错点为D,注意根据密度的计算公式推导.9.(3分)(2013秋•上海月考)一定条件下,碳钢腐蚀与溶液pH的关系如下:pH 2 4 6 6.5 8 13.5 14腐蚀快慢较快慢较快。
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控江中学2014届高三月考考试卷II. Grammar and Vocabulary(26’)Section ADirections: After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that fits each blank.(16’)(A)It is a particularly useful time for America to reflect on those who 25_____ (sacrifice)so much for our freedom.When I first 26____ (speak )at West Point in 2009, we still had more than 100,000 troops in Iraq. We ____27___(prepare)to surge in Afghanistan. Our counterterrorism efforts 28____( focus)on al-Qaida’s core leadership -- those who had carried out the 9/11 attacks. And our nation was just beginning a long climb out of the worst economic crisis .Four and a half years later, as you graduate, the landscape has changed. We29____(remove)our troops from Iraq. We are winding down our war in Afghanistan. Al-Qaida’s leadership on the border region between Pakistan and Afg hanistan has been decimated, and Osama bin Laden is no more.Meanwhile, our economy30_____( remain) the most dynamic on Earth, our businesses the most innovative. Each year, we grow more energy independent.But the world 31____(change)with accelerating speed. This presents opportunity, but also new dangers.It will be your generation’s task to respond to this new world. The question we face, the question each of you will face, is not whether America__32___ (lead )but how we will lead, not just to secure our peace and prosperity but also extend peace and prosperity around the globe.(B)Many kinds of music can stir the imagination and produce strong feeling. For some people, romantic composers such as Chopin and Tchaikovsky enhance feelings of love and sympathy. Religious and spiritual music ___33___ help some people feel peace or lessen their pain. But one musician seems to have a unique ability of healing(治愈) the human body – Wolfgang Amadeus Mozart. Scientists have found Mozart’s music to be remarkable i n its ability 34____ (calm) its listeners. It can also increase their perceptions, and help them express themselves more clearly.Many amazing cases have been documented using Mozart 35____ a healing aid. For example, a tiny premature baby 36______ (name) Krissy, who weighed just 1.5 pounds at birth, was on total life support. Doctors thought she had little chance of survival. Her mother insisted on playing Mozart for Krissy, andthought 37_____ saved her daughter’s life. Krissy lived, __38___ she was very small for her age and slower than the average child. At the age of four, she showed an interest in music and her parents gave her violin lessons.39_____ their astonishment, Krissy was able to play musical pieces from memory that were far beyond the ability of an average four-year-old. __40___ (play) music helped her improve in all areas of her life.Section BDirections: complete the following passage by using the words in the box. Each word can only be used once. Note that th ere is one word more than you need.(10’)Genes are found in every plant or animal cell. They are the basic units of life that are capable of passing specific 72____ from one generation to another. For example, whether you are tall or short depends upon the genes that you 73____ from your parents. Cloning plants or animals is a process that 74____ the production of a new organism that is genetically identical to the organism from which cells were taken. Although this 75_____ has aroused great interest around the world over the last ten years or so, cloning is not something new in nature. Most mothers give birth to just one child at a time; however, on rare 76___ a mother may give birth to a set of twins. If these two children are identical twins, then they are in fact naturally 77___ clones of each other, although not of the parents. The reason for them being clones is that the two children originated from one 78___ egg and consequently they are genetically identical. Twins that develop from two79___ eggs are not clones of each other.Cloning also occurs naturally in plants. Strawberry plants reproduce themselves by sending out runners, or modified stems, and these runners take root a short distance from the 80_____ plant and start to grow, and to produce fruit. In time, this plant sends out runners of its own that also take root. This is known as asexual reproduction; in other words, reproduction that does not involve the fusion (融合) of male and female cells. The newly 81____ plants are clones of the original. In addition to strawberry plants, certain types of flowers and grasses reproduce themselves in the same way. Throughout history, people have also facilitated cloning by taking small cuttings from plants and then growing them into new plants. This form of cloning is called vegetative propagation.III. Reading Comprehension(47’)Section ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.(15’)Robert Frank, an economist at Cornell, believes that his profession is restricting cooperation and generosity. In the U.S., economics professors give __51__ money to charity than professors in other fields. Economics students in Germany are more likely than those from other majors to recommend an overpriced plumber (水管工) when they are __52__ to do it. Economics majors tend to rate __53_ as “generally good,” “correct,” and “moral” more than their peers.Does studying economics change people? Maybe not. It could be self-selection: students who already believe inself-interest are __54__ to economics. But this doesn't exclude the possibility that studying economics pushes people further toward the selfish extreme. By spending time with like-minded people, economics students may become __55__ that selfishness is widespread and reasonable -- or at least that giving is rare and foolish.“As a business school professor, these effe cts worry me, as economics,__56__ every aspect of our lives, is taught widely in business schools, providing a__57__ for courses in management, finan ce, and accounting.” says Frank.If economics can __58_ pro-social behavior, which is central to the well-being of people or society, what should we do about it? A change in economics and business __59__ is suggested. Courses in behavioral economics, which considers the role o f “social preferences” like __60__, fairness and cooperation, are required for students of economics major. In fact, economics courses not involving some behavioral economics are considered both an inadequate education and a poor preparation to be a practising economist. Also, __61_ width, economics majors are required to take courses in social sciences like sociology and psychology, which place considerable emphasis on how people are __62__ about others, not only themselves. __63__, within economics courses, we should do a better job __64__ the principle ofself-interest, which involves anything a person values -- including helping others.Not until then may the prophecy (预言) by Nobel Prize-winning economist and philosopher Amartya Sen be __65__. Calling economists “rational fools,” he observed: “The purely economic man is indeed close to being a social fool.”51. A. fewer B. less C. smaller D. more52. A. encouraged B. requested C. assigned D. paid53. A. teamwork B. greed C. desire D. economics54. A. opposed B. entitled C. drawn D. attached55. A. convinced B. depressed C. relaxed D. doubtful56. A. depending on B. adapting to C. differing from D. doubtful57. A. potential B. judgment C. foundation D. doubtful58. A. assess B. research C. discourage D. reason59. A. education B. standard C. approach D. cause60. A. competition B. evaluation C. community D. application61. A. in case of B. in terms of C. in relation to D. generosity62. A. concerned B. anxious C. curious D. in need of63. A. However B. Therefore C. Furthermore D. enthusiastic64. A. claiming B. defining C. overlooking D. recalling65. A. broken B. predicted C. challenged D. fulfilled Section BDirections: Read the following four passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.AI used to think of myself as a fairly cosmopolitan(全球的)sort of person, but my bookshelves told a different story as my literature collection mainly consisted of British and American titles. Worse still, I hardly ever read anything in translation. My reading was limited to stories by English-speaking authors.So, at the start of 2012, I set myself the challenge of trying to read a book from every country in a year to find out what I was missing.With no idea how to go about this, thinking that I was unlikely to find books from nearly 200 nations from my loc al bookshop, I decided to ask the planet’s readers for help. I created a blog called A Year of Reading the World, appealing for suggestions of titles that I could read in English.The response was amazing. Before I knew it, people all over the world were getting in touch with ideas and offers of help. Some posted me books from their home countries.Others did hours of research on my behalf. In addition, several writers sent me unpublished translations of their novels, giving me a rare opportunity to read works otherwise unavailable to the 62% of British people who only speak English. Even with such support, however, sourcing books was no easy task.Tracking down stories in some unfamiliar places even took as much time as the reading and blogging. It was hard to fit it all in around work and many were the nights when I sat bleary-eyed (睡眼惺忪的) into the small hours to make sure I stuck to my target of reading one book every 1.87 days.Still,one by one, the country names on the list made at the start of the year transformed into vital, exciting places filled with laughter, love, anger, hope and fear. Lands that had once seemed exotic became familiar to me – places I could identify with. At its best, I learned, fiction makes the world real.66. What help did the writer receive to achieve his goal?A. Some writers sent him their original works.B. The local bookstore provided books from 200 nations even if it was unlikely.C. Some writers did research work on what books are popular.D. Some people mailed books from their own countries.67. In order to accomplish his goal, the writer did the following except ______.A. asking for help from all over the worldB. making full use of his leisure time after workC. reading until early next morningD. appealing to writers to send him new books68. What does the word "exotic" in the last paragraph most probably mean?A. Unrealistic.B. Uncivilized.C. Strange.D. Unimaginable.69. Which of the following best describe the writer’s experience in the year?A. Original but tiringB. Hard but relaxingC. Busy but fruitfulD. Helpful but challengingBVilla d'Este, Tivoli (Italy) - Official Site Useful InformationCall Center 199766166Number to dial from all of Italy for pre-sales and reservations for: tickets, guided tours, school groups, instructional visits.Bookings from abroad:email: villadestetivoli@ fax: 0039 0412770747 telephone: 0039 0412719036 Visiting Hours:Opening 8.30 – closed one hour before sunset.The ticket office closes one hour before the closing of the monument.The hydraulic organ of the Organ Fountain is active daily, from 10.30 am, every two hours.The Fontana della Civetta functions daily, from 10.00 am, every two hours. Ticket Prices:(from May 17 to October 20, 2013)Full ticket (exhibition + villa and gardens, not divisible): € 11. Reduced ticket: € 7.These prices will be valid during the daytime openings of the Villa until the closure of theexhibition, due on the 20th of October, 2013 (From the 22nd of October, 2013) Full ticket: € 8Reduced ticket: € 4These fares may vary in conjunction with exhibitions set inside the Villa.The right to purchase reduced price tickets belongs to all citizens of the European Unionbetween the ages of 18 and 24 as well as permanent teachers of state schools (uponpresentation of identity documents).School Visits:Reservations are required. The management of Villa d'Este, in the aim of preserving themonument and better distributing the flow of students, has limited the number of studentsallowed into the Villa to 100 students per hour. Should any school group arrive at the Villawithout having made a reservation, it will be admitted to the Villa according to spaceavailability at a particular time and asked to wait until such space becomes available. Rightof Reservation cost: € 1,00.Notices:Certain areas of the villa may be closed for restoration: for information inquire at the ticketoffice.Please pay particular attention to the areas marked with signs indicating danger (in Italian:pericolo).70.which of the following statement is not true?A. Villa d'Este is closed at night.B. Ticket prices are usually higher than usual when there happens to be an exhibition.C.Tourist are not allowed to enter areas marked with signs “pericolo”D.Visitors can buy reduced tickets as long as they take a reservation.71. The receptionist at the ticket office may recommend you to see ______ first, if you arrive at 10.25 am.A. the exhibition inside the villaB. the Organ FountainC. the gardensD. the Fontana della Civetta72. How can a visiting Chinese professor of architecture in Rome make a booking?A. By dialing 199766166.B. By writing an email to villadestetivoli@.C. By calling 0039 0412719036.D. By sending a fax to 0039 0412770747.73.Why are reservations essential for school visits?A. Reservations are more economical.B. Reservations enable as many students as possible to visit the monument.C. Reservations ensure a pleasant visit for students and a manageable one for the Villa.D. Reservation fees can help preserve the site.CHave you ever seen harmful robots refuse to die, no matter how fiercely people fight back? As is known, it is always the case in some of the scariest science fiction.Now, science fiction has changed into sciencefact. For the first time, researchers have created a robotic machine that can stand a beating and keep on walking. Developed by scientists from CornellUniversity and the University of Vermont, the new robot looks like a spider with four legs.Until now, even the most advanced robot was almost certain to break down when damaged.That’s because its inside computer simply doesn’t know how to operate the machine after its shape has changed.To get around this problem, the spidery robot’s developers equipped their invention witheight motors and two sensors that read how the machine is tilting(倾斜). The motors and sensors all provide electrical signals to the machine’s software.Using this information, the system follows a new procedure to figure out the machine’s shapeat any given moment. The program chooses from among 100,000 possible arrangements of parts.From there, the computer considers a wide variety of possible next steps, and it calculateshow best to move the robot forward the longest possible distance, before trying to move again.“The new strategy is a major advance in robotics”, Professor Skehan, a scientist in CornellUniversity says, “and it’s far from scary.” The technology may someday help researchers create better artificial arms and legs that give new freedom to people who lack them. The new knowledge might also help scientists understand how people and animals figure out their own sense of place in space.“Designing robots that can adapt to changing environments and can compensate(补偿) fordamage has been a difficult problem,” says neuroscientist Olaf Sporns of In diana University in Bloomington. “This work provides a new way toward solving this important problem.”74.The purpose of the author to write this article is to ________.A. introduce a new robot that will not dieB. discuss science fiction and new inventionC. recommend the latest inventionD. explain the relationship between robot and medicine75.It can be learnt from the passage that ________.A. animals have no sense of place in spaceB. people have difficulty in figuring out how to get to his destinationC. scientists don’t understand people’s ability of locationD. scientists want to know where people and animals are going76. What’s the most important characteristic of the new rob ot?A. Its shape is like a spider with four legs.B. It can repair itself and move again after damaged.C. It is operated by its inside computer.D. It is certain to change the direction when damaged.77.We can infer from the view of Professor Skehan that ________.A. the new technology will help people have a better sense of spaceB. the new technology will help people grow new arms and legsC. designing robots can help to be adaptable to the changing of the environmentD. the new technology will have some medical benefitsSection CDirections: Read the passage carefully. Then answer the questions or complete the statements in NO MORE THAN TEN WORDS.With 26 British prime ministers, 58 Nobel prize winners, over 150 Olympic medals and a "notable alumni" list that reads like a historical hall of fame, the institutions of Oxford and Cambridge – collectively known as Oxbridge – are seen, by many, as the dream alma mater(母校).However, as admission season dawns, and the October 15 deadline for Oxbridge inches ever closer, many students may wonder what makes the UK's top two institutions so special. Why does Oxbridge symbolize the academic dream for so many? Do the universities deserve the reputation they hold in the minds of so many teenagers, parents and academics?There is no doubt that both Oxford and Cambridge have a long standing history of academia. Yet, what is often overlooked is the strong reputation of countless other universities in the UK.A simple click on Google can tell students that the London School of Economics and Political Sciences, for example, has over 18 Nobel Prize winners and 50 world leaders. University College London attracts students from 150 countries and has exchange and research links with nearly 300 overseas universities. Manchester University has thelargest student union of all UK universities and boasts alumni such as Niels Bohr and James Chadwick.I suddenly realized the Oxbridge effect when I was out in London with friends. I met some new people and was surprised by their reaction when I told them I was going to study at Cambridge. One person even got down on one knee and kissed my hand. From then on, I told people I was going on a gap year. Although I knew that Oxbridge provides a good education, I had never expected to get such extreme reactions. It was this that made me start to feel uncomfortable about the way that Oxbridge is viewed. The Cambridge Tab, the university's student newspaper, has argued that what makes Cambridge special is the fact that the students are told that they are unique and a cut above the rest, so they believe it. Ron Weasley never took the Felix Felicis potion that Harry Potter pretended to give him – all he had to do to win the Quidditch match was to believe he was great.For students applying now, yes, you will receive a world class education at Oxbridge, but you will find the same at numerous other universities throughout the country. Every time you hear about the brilliance of Oxbridge, consider that just because many believe, it does not have to be so.78. The examples of the London School of Economics and Political Sciences, University College London and Manchester University serve to illustrate the point that _________________________________in the UK.79.According to the passage, we can find that people ___________________ the students at the Oxbridge.80. How did the writer avoid over-reaction from people to her admission into Cambridge?_____________________________________________________________________ _81. What is the writer’s suggestion to students applying to universities?_____________________________________________________________________ __I.TranslationDirections: Translate the following sentences into English, using the word given in the brackets.82.要不了多久,他们就会同意我们出版这本针对年龄为6-12岁孩子的书了。