湖北省武汉市2019-2020学年高一下学期期中英语试题(解析版)

矿产资源开发利用方案编写内容要求及审查大纲
矿产资源开发利用方案编写内容要求及《矿产资源开发利用方案》审查大纲一、概述
㈠矿区位置、隶属关系和企业性质。

如为改扩建矿山, 应说明矿山现状、
特点及存在的主要问题。

㈡编制依据
(1简述项目前期工作进展情况及与有关方面对项目的意向性协议情况。

(2 列出开发利用方案编制所依据的主要基础性资料的名称。

如经储量管理部门认定的矿区地质勘探报告、选矿试验报告、加工利用试验报告、工程地质初评资料、矿区水文资料和供水资料等。

对改、扩建矿山应有生产实际资料, 如矿山总平面现状图、矿床开拓系统图、采场现状图和主要采选设备清单等。

二、矿产品需求现状和预测
㈠该矿产在国内需求情况和市场供应情况
1、矿产品现状及加工利用趋向。

2、国内近、远期的需求量及主要销向预测。

㈡产品价格分析
1、国内矿产品价格现状。

2、矿产品价格稳定性及变化趋势。

三、矿产资源概况
㈠矿区总体概况
1、矿区总体规划情况。

2、矿区矿产资源概况。

3、该设计与矿区总体开发的关系。

㈡该设计项目的资源概况
1、矿床地质及构造特征。

2、矿床开采技术条件及水文地质条件。

合集下载

2019-2020学年下学期高二期中备考精编金卷英语(C卷)解析版

1绝密 ★ 启用前 2019-2020学年下学期高二期中备考精编金卷英语（C ）注意事项：1.答题前，先将自己的姓名、准考证号填写在试题卷和答题卡上，并将准考证号条形码粘贴在答题卡上的指定位置。

用2B 铅笔将答题卡上试卷类型C 后的方框涂黑。

2.选择题的作答：每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答：用签字笔直接答在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后，请将本试题卷和答题卡一并上交。

第Ⅰ卷第一部分听力（略）第二部分阅读理解（共两节，满分60分）第一节（共15小题，每小题3分，满分45分）阅读下列短文，从每题所给的A 、B 、C 和D 四个选项中，选出最佳选项。

AVisiting museums during this pandemic is going to be a no-go, but you can still get much of the experience of some of American greatest institutions in your own living room. As museums adapt to our current state of widespread isolation, they’re offering online prog rams and virtual tours that are second only to being there in person. Click to join us and read on for our top picks. The National Gallery of ArtThe NGA’s website has 53,000 images to download, and they recommend using them as backdrops for your Zoom meetings. The D.C. museum also offers plenty of virtual programming for the whole family. You can find videos and activities that center around the gallery’s collection .Online: Price: $58/Flexible Guest Adult; $38/Named Adult; $19/Child; Under 6 Free National Women’s History MuseumThe National Women’s History Museum is uploading new stories and videos daily all month thatcelebrate women throughout history, and they encourage you to take a woma n’s history break each daywhile working from home to learn about important women. You can browse their extensive collection of stories and online exhibits.Online: Price: $148/Household; $100/Two adults; $30/Child Museum of FlightSeattle’s Museum of Flight may be sitting empty of guests right now, but virtually it’s open for business. On the website of the world’s bi ggest aviation museum, you can tour an Air Force One model or a NASA Space Shuttle Trainer, view a huge collection of digitized photos and documents, and listen to the Flight Deck podcast.Online: Annual Membership: $150/Family; $115/Two Adults 1. What do these places have in common? A. They all are museums in the USA. B. Kids can listen to stories. C. They all have outdoor activities. D. Members can get free admission. 2. Which place is favored by aircraft lovers? A. The National Gallery of Art. B. National Women’s History Museum . C. Museum of Flight.D. The National Gallery of Art & Museum of Flight.3. How much does it cost for a family with 2 children to visit National Women’s History Museum online? A. $148. B. $160. C. $208. D. $260. 【答案】1-3 ACA【解析】这是一篇广告应用文，文章主要介绍了一些美国博物馆在疫情期间也能提供在线项目和虚拟旅游。

2019-2020学年武汉市第十九中学高三英语下学期期中考试试题及答案

2019-2020学年武汉市第十九中学高三英语下学期期中考试试题及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AMany workers have had no choice but to adapt to working from home in recent months since offices shut down due to the COVID-19 pandemic (新冠疫情). And the noisy situation and endless housework may result in a terrible emotion. A new option is waiting foryou. That is WFH: work from a hotel.Hotel FigueroA special program titled Work Perks aims to reposition some of 94-year-old Hotel Figuero’s 268 rooms as day-use offices.According to Managing Director Connie Wang, the set-up launched in June and is a great opportunity to get out of their houses with high-speed Wi-Fi, unlimited printing privileges and free parking. The 350-square-foot rooms sell for $ 129 per day, with an option to extend to an overnight stay for an additional $ 20.The WytheA boutique hotel in Brooklyn. The hotel recently announced a partnership with co-working office space company Industrious through which it is recycling 13 second-story guest rooms to serve as offices for up to four people.Each of the rooms has a small outdoor platform, and dogs are welcome. Pricing starts at $ 200 and goes up to $ 275, depending on how many people use the space.The SawyerThe Sawyer, in Sacramento, California, is offering pool cabanas (更衣室) for use as outdoor offices, complete with fast Wi-Fi, free parking and catered lunch for $ 150 per day.HotelsByDayYannis Moati founded HotelsByDay back in 2015. That company has grown to include more than 1,500 hotels, and has seen a significant increase in the number of inquiries for day-use bookings lately.Moati said the current situation will force hotels to upgrade themselves to stay alive, and he predicted that offering rooms for day-use only is one of the directions they will go.1.How much should one pay for a 24-hour stay in Hotel Figuero?A.$ 129.B.$ 149.C.$ 150.D.$ 200.2.Which hotel allows pets in?A.The Wythe.B.The Sawyer.C.HotelsByDay.D.Hotel Figuero.3.What do we know about Yannis Moati?A.He started a program titledWork Perks.B.He has upgraded at least 1,500 rooms.C.He usually predicts everything correctly.D.He is optimistic about the WFH trend.BAvi Loeb, a scientist, believes that we are not alone in the universe. The belief fits withLoeb's alien spaceship theory that at least one alien spaceship might be flying over the orbit of Jupiter, which won the international attention last year.Astronomers inHawaiifound the first known interstellar object in late 2017. It was a bit of light moving so fast past the sun that it could only have come from another star. Almost every astronomer on the planet was trying to figure out how the object, called “Oumuamua” got to our far-away part of the Milky way galaxy. “One possibility is that ‘Oumuamua’ is debris from an advanced technological equipment,” Loeb said. “Technology comes from another solar system just showed up at our door. ”“‘Oumuamua’ is not an alien spaceship,” Paul Sutter, another scientist wrote. He suggested Loeb was seeking publicity. Most scientists think “Oumuamua” is some sort of rock. They think it could be an icy wandering comet.Loeb says that “Oumuamua's” behavior means it can't be a block of rock shaped like a long photo. He thinks it's more likely an object that's very long and thin, perhaps like a long pancake or a ship's sail. Loeb says that if someone shows him evidence thatcontradictshis beliefs, he will immediately give in.Loeb believes himself a truth-teller and risk-taker in an age of very safe, too-quiet scientists. “The worst thing that can happen to me is that I would be relieved of my management duties, and that would give me even more time to focus on science,” Loeb says. He said he wouldn't mind giving up all the titles he had and returning to the Israeli farming village where he grew up.4. What does Loeb say about “Oumuamua”?A. It is an icy comet.B. It looks like a long photo.C. It is actually some sort of rock.D. It may come from another alien civilization.5. What does the underlined word “contradicts” in paragraph 4 probably mean?A.Goes against.B. Relies on.C. Turns to.D. Searches for.6. What do you think of Loeb?A. He is foolish.B. He is unsatisfied with his titles.C. He is a firm believer in scientific truth.D. He is uncertain about his career future.7. What's the best title for the text?A. Have Aliens Paid a Visit in Spaceships?B. Do We Really Know about Space Theory?C. Scientists Are Working on High TechnologyD. Astronomers Are Encouraging Space TravelCThe idea of low material desire, low consumption and refusing to work, marry and have children, concluded as a “lying down” lifestyle, recentlystruck a chord withmany young Chinese who are eager to take pause to breathe in this fast-paced and highly-competitive society.Many millennials (千禧一代) and generation Zs complained to the Global Times that burdens, including work stress, family disputes (纷争) and financial strains, have pushed them “against the wall”. They said they hate the “involution (内卷),” joking that they would rather give up some of what they have than get trapped in an endless competition against peers.“Instead of always following the ‘virtues’ of struggle, endure and sacrifice to bear the stresses, they prefer a temporary lying down as catharsis (宣泄) and adjustment,” said a scholar. “It is no wonder that some young people, under the growing pressures from child-raising to paying the mortgage (按揭) today, would try to live in a simple way and leave the worries behind.”Interestingly, the majority of millennials and Gen Zs reached by the Global Times, who claim to be big fans of the lying down philosophy, acknowledged that they only accept a temporary lying down as a short rest. It is true that with the great improvement of living conditions, some Chinese youth have partially lost the spirit of hardship and are not willing to bear too much hard work. But in fact, lying down is not entirely comfortable. Young people who lie down always feel guilty about their constant loss of morale (士气) far beyond their reach.“Young people on campus have both aspirations and confusion about their future, but most of us have rejected setting ourselves up in chains to waste opportunities and challenges,” a postgraduate student told the Global Times. “It’s no use running away. I have to ‘stand up’ and face the reality sooner or later.”8. What does the underlined phrase in paragraph 1 mean?A. Warned.B. Criticized.C. Touched.D. Amused.9. What might have caused the “lying down” lifestyle among the young?A. Improvements in living conditions.B. Growing pressure from family and social life.C. Increasing material possessions from families.D. Temporary adjustment to failure in competitions.10. What’s the scholar’s attitude toward the “lying down” group?A. Understanding.B. Intolerant.C.Supportive.D. Unclear.11. What can be inferred about the young generation from the text?A. They never really drop their responsibilities.B. They really enjoy the “lying down” lifestyle.C. They find their dreams far beyond their reach.D. They would rather escape than take challenges.DDogs are often referred to as “man's best friend”. But MacKenzie, a four-pound Chihuahua (奇瓦瓦狗), who was named winner of the 2020 American Hero Dog competition, is making the world a better place for humans and animals alike. Often called the “Oscars for dogs”, the award recognizes dogs who make great contributions to society.This year's competition attracted over 400 competitors from across the country. While all were impressive, it was tiny MacKenzie who won the judges' hearts. Born at a rescue shelter in Hilton, New York, in 2013, she had a cleft palate (腭裂) that required her to be tube fed for the first year of her life. A life-saving operation, performed in 2014, gave her the ability to eat and drink independently, enabling the tiny dog to focus on doing what she loved most: taking care of others.The seven-year-old Chihuahua is now gainfully “employed” by the Mid Foundation, a Rochester, New York-based non-profit organization that shelters and cares for animals born with disabilities. MacKenzie's official job is “to provide love and care for baby rescue animals born with birth defects”. The Chihuahua is good at her job and hasnurturedmany different species-from puppies to kittens to turkeys, squirrels, birds and even a goat. She acts as their mother and teaches them how to socialize, play, and have good manners.In addition to her role as an animal caretaker, MacKenzie also has the important job of greeting thefoundation's volunteers and friends. The incredible dog, who has lost her ability to bark, also visits area schools to help children understand physical disabilities in both animals and people. Her heart-warming and inspiring story makes MacKenzie worthy of America's top dog honor!12. What made MacKenzie American Hero Dog?A. Being man's best friend.B. Her struggle with disabilities.C. Rescuing animals with disabilities.D. Her contributions to a better world.13. What can we infer about MacKenzie from Paragraph 2?A. Her growth path was not easy.B. She was deserted by her owner.C. She was operated on at two years old.D. She still needs taking care of by others.14. What does the underlined word “nurtured” in Paragraph 3 mean?A. Trained.B. Comforted.C. Tended.D. Abused.15. Which can be a suitable title for the text?A. MacKenzie—The Most Hard-working DogB. MacKenzie—America's “Most Heroic Dog”C. Chihuahua—Inspiration of Positive EnergyD. Chihuahua—Appeal for Animals' Protection第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

湖北省武汉市部分重点中学2019-2020学年高一下学期期中考试数学试题含解析

武汉市部分重点中学2019-2020学年度下学期高一期中测试
数学试卷
全卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分.共150分，考试时间120分钟.
第Ⅰ卷（选择题共80分）
一、选择题：本大题共12小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.
1.在数列中，，，则的值为（）
【解析】
【分析】
由，都有，可得，再根据等差数列的性质即可判断.
【详解】等差数列的公差，，都有，
，
.
故选： .
【点睛】本题考查等差数列的性质，属于基础题.
12.给定两个单位向量，，且，点在以为圆心的圆弧上运动，，则的最小值为（）
A. B. C. D.
【答案】B
【解析】
试题解析：（Ⅰ）由
又所以 .
（Ⅱ）由余弦定理有，解得，所以
点睛：在利用余弦定理进行求解时，往往利用整体思想，可减少计算量，若本题中的
.
19.设为等差数列的前项和，， .
（1）求数列的通项公式；
（2）求的最大值及此时的值.
【答案】（1）；（2）当时，有最大值为
【解析】
【分析】
【点睛】本题考查等差数列通项公式以及前项和的综合应用，难度较易.其中第二问还可以先将的表达式求解出来，然后根据二次函数的对称轴以及开口方向亦可确定出的最大值以及取最大值时的值.
20.已知向量，且 .
（1）求及；
（2）若，求的最大值和最小值.
【答案】（1）（2）；
【解析】
试题分析：
②化角：通过三角恒等变形，得出内角的关系，从而判断三角形的形状，此时要注意应用这个结论．

湖北省2019-2020学年高二下学期期中英语试卷精选汇编：应用文写作专题

书面表达专题湖北省武汉市2019-2020学年高二英语下学期期中联考试题第一节：应用文（满分15分）假定你是李华，想邀请外教Henry一起参观中国剪纸( paper-cutting)艺术展。

请给他写封邮件，内容包括：1.展览时间、地点。

2.展览内容。

注意：1.词数80左右；2.可以适当增加细节，以使行文连贯。

Dear Henry,Yours sincerely, Li Hua书面表达(共25分)第一节Dear Henry,I am writing to invite you to attend the Chinese paper-cutting art exhibition to be held in the art gallery from 8:00 am to 5: 00 pm next Sunday in our city center.Paper-cutting is a traditional art form in China, which has a history of more than 1, 500 years. People often beautify their home with paper-cutting during festivals as well as weddings. In this exhibition, you can seepaper-cutting with a wide variety of patterns. In addition, there are well-known artists who will perform how to cut paper on the spot. I wish that you could grasp this opportunity to learn traditional Chinese culture further.Looking forward to your reply.Yours sincerely,湖北省武汉市蔡甸区汉阳一中2019-2020学年高二英语下学期期中联考试题假设你是李华，2022年北京冬奥会正面向全国学生招募志愿者，你希望成为其中一员。

专题01 平面向量的概念(解析版)

专题01 平面向量的概念一、单选题1．下列说法正确的是A ．单位向量都相等B ．若a b ≠，则a b ≠C ．若a b ＝，则//a bD ．若a b ≠，则a b ≠ 【试题来源】山西省忻州市第一中学北校2019-2020学年高一下学期3月月考【答案】D【分析】根据向量的概念，向量的两个要素：大小和方向性，即可判断各选项．【解析】对于A ，单位向量的大小都相等，但方向不一定相同，所以单位向量不一定都相等，所以A 错误；对于B ，两个向量不相等，可以大小相等，方向不同，因而当a b ≠时可能a b ＝，所以B 错误；对于C ，两个向量的模相等，但方向可以不同，因而当a b ＝时a 和b 不一定平行，所以C 错误；对于D ，若两个向量的模不相等，则两个向量一定不相同，所以若a b ≠，则a b ≠成立，所以D 正确．综上可知，D 为正确选项，故选D 【名师点睛】本题考查了向量的概念，向量的两个要素：大小和方向性，属于基础题． 2．给出下列四个说法：①若||0a =，则0a =；②若||||a b =，则a b =或a b =-；③若//a b ，则||||a b =；④若//a b ，//b c ，则//a c ．其中错误的说法有A ．1B ．2C ．3D ．4【试题来源】安徽省六安市第一中学2019-2020学年高一上学期期末（文）【答案】D【解析】①只有零向量的模是0，因此应有0a =，不是0，错；②模相等的向量方向不确定，不一定相同或相反，错；③两向量平行，只要方向相同或相反或有一个为零向量，模不作要求，错；④当0b =时，,a c 不一定共线，错．故选D ．【名师点睛】本题考查向量的概念，掌握向量的定义是解题关键．3．下列关于向量的命题正确的是A ．若||||a b =，则a b =B ．若||||a b =，则//a bC ．若a b =，b c =，则a c =D ．若//a b ，//b c ，则//a c【试题来源】2020-2021学年高一数学十分钟同步课堂专练（人教A 版必修4）【答案】C【分析】利用向量的知识对每一个选项逐一分析判断得解．【解析】A ．若||||a b =，则,a b 不一定相等，因为向量是既有大小，又有方向的，||||a b =只能说明向量的大小相等，不能说明方向相同，所以该选项错误；B ．若||||a b =，则,a b 不一定平行，所以该选项错误；C ．若a b =，b c =，则a c =，所以该选项是正确的；D ．若//a b ，//b c ，则//a c 错误，如：=0b ，,a c 都是非零向量，显然满足已知，但是不一定满足//a c ，所以该选项错误．故选C【名师点睛】本题主要考查平面向量的概念，意在考查学生对这些知识的理解掌握水平，属于基础题．4．下列命题正确的是A ．若||0a =，则0a =B ．若||||a b =，则a b =C ．若||||a b =，则//a bD ．若//a b ，则a b =【试题来源】2020-2021学年【补习教材寒假作业】高一数学（人教A 版2019）【答案】A【分析】根据零向量的定义，可判断A 项正确；根据共线向量和相等向量的定义，可判断B ，C ，D 项均错．【解析】模为零的向量是零向量，所以A 项正确；||||=时，只说明向,a b的长度相等，无法确定方向，a b所以B，C均错；a b 时，只说明,a b方向相同或相反，没有长度关系，不能确定相等，所以D错．故选A．【名师点睛】本题考查有关向量的基本概念的辨析，属于基础题．5．下列说法中，正确的个数是①时间、摩擦力、重力都是向量；②向量的模是一个正实数；③相等向量一定是平行向量；④向量a→与b→不共线，则a→与b→都是非零向量A．1B．2C．3D．4【试题来源】湖北省武汉市第六中学2018-2019学年高一下学期2月月考【答案】B【分析】根据向量的相关概念，逐项判定，即可得出结果．【解析】①时间没有方向，不是向量，摩擦力，重力都是向量，故①错误；②零向量的模为零，故②错；③相等向量的方向相同，模相等，所以一定是平行向量，故③正确；④零向量与任意向量都共线，因此若向量a→与b→不共线，则a→与b→都是非零向量，即④正确．故选B．【名师点睛】本题主要考查向量有关命题的判定，熟记向量的相关概念即可，属于基础题型．6．下列说法中正确的是A．平行向量就是向量所在的直线平行的向量B．长度相等的向量叫相等向量C．零向量的长度为零D．共线向量是在一条直线上的向量【试题来源】吉林省长春市第二十九中学2019-2020学年高一下学期线上检测数学试卷【答案】C【分析】直接根据共线向量、相等向量、零向量的概念判断即可．【解析】平行向量也叫共线向量，是指方向相同或相反的两个向量，另外规定零向量与任意向量平行，故A，D错；相等向量是指长度相等、方向相同的向量，故B错；长度为零的向量叫零向量，故C对；故选C．【名师点睛】本题主要考查平面向量的有关概念，属于基础题．7．下列命题正确的是A．若,a b都是单位向量，则a b=B．两个向量相等的充要条件是它们的起点和终点都相同C．向量AB与BA是两个平行向量A B C D四点是平行四边形的四个顶点D．若AB DC=，则,,,【试题来源】2021年新高考数学一轮复习讲练测【答案】C【分析】利用单位向量的定义可判断A；利用向量相等的定义可判断B；利用平行向量的定义可判断C；利用向量相等的定义可判断D．【解析】对于A，单位长度为1的向量为单位向量，,a b都是单位向量，但方向可能不同，故A不正确；对于B，模相等，方向相同的向量为相等向量，故B不正确；对于C，向量AB与BA为相反向量，所以两个为平行向量，故C正确；A B C D四点在同一条直线上，对于D，AB DC=，若,,,A B C D 不能构成平行四边形，故D不正确；故选C,,,【名师点睛】本题考查了向量的基本概念，需理解单位向量、相等向量、共线向量的概念，属于基础题．8．下列说法错误的是A．向量OA的长度与向量AO的长度相等B．零向量与任意非零向量平行C．长度相等方向相反的向量共线D．方向相反的向量可能相等【试题来源】2021年新高考数学一轮复习讲练测【答案】D【分析】向量有方向、有大小，平行包含同向与反向两种情况．向量相等意味着模相等且方向相同，根据定义判断选项．【解析】A．向量OA与向量AO的方向相反，长度相等，故A正确；B ．规定零向量与任意非零向量平行，故B 正确；C ．能平移到同一条直线的向量是共线向量，所以长度相等，方向相反的向量是共线向量，故C 正确；D ．长度相等，方向相同的向量才是相等向量，所以方向相反的向量不可能相等，故D 不正确．【名师点睛】本题主要考查向量的基本概念及共线（平行）向量和相等向量的概念，属于基础概念题型．9．有下列命题：①若向量a 与b 同向，且||||a b >，则a b >；②若四边形ABCD 是平行四边形，则AB CD =；③若m n =，n k =，则m k =；④零向量都相等．其中假命题的个数是A ．1B ．2C ．3D ．4【试题来源】2021年高考数学复习一轮复习笔记【答案】C【分析】分别根据每个命题的条件推论即可判断．【解析】对于①，因为向量是既有大小又有方向的量，不能比较大小，故①是假命题；对于②，在平行四边形ABCD 中，,C AB D 是大小相等，方向相反的向量，即AB CD =-，故②是假命题；对于③，显然若m n =，n k =，则m k =，故③是真命题；对于④，因为大小相等，方向相同的向量是相等向量，而零向量的方向任意，故④是假命题．故选C ．【名师点睛】本题主要考查平面向量的概念，意在考查学生对这些知识的理解掌握水平，属于基础题．10．下列说法中正确的是．A ．零向量没有方向B ．平行向量不一定是共线向量C ．若向量a 与b 同向且a b =，则a b =D ．若向量a ，b 满足a b >且a 与b 同向，则a b >【试题来源】吉林省松原市扶余市第一中学2019-2020学年高一下学期期中考试【答案】C【分析】由零向量，平行向量，相等向量的定义逐一判断可得选项．【解析】对于A ，零向量的方向是任意的，故A 错误；对于B ，平行向量就是共线向量，故B 错误；对于C ，由相等向量的定义：两向量的方向相同，大小相等可知，C 正确；对于D ，两个向量不能比较大小，故D 错误．故选C ．【名师点睛】本题考查向量的基本定义，在判断关于向量的命题时注意向量的方向，属于基础题．11．以下说法正确的是A ．若两个向量相等，则它们的起点和终点分别重合B ．零向量没有方向C ．共线向量又叫平行向量D ．若a 和b 都是单位向量，则a b =【试题来源】2020-2021学年高一数学十分钟同步课堂专练（人教A 版必修4）【答案】C【分析】根据向量的基本概念逐一判断即可．【解析】只要两个向量的方向相同，模长相等，这两个向量就是相等向量，故A 错误，零向量是没有方向的向量，B 错误；共线向量是方向相同或相反的向量，也叫平行向量，C 正确；若a ，b 都是单位向量，两向量的方向不定，D 错误；故选C ．12．给出下列命题：①零向量的长度为零，方向是任意的；②若,a b 都是单位向量，则a b =；③向量AB 与BA 相等．则所有正确命题的序号是A ．①B ．③C ．①③D ．①②【试题来源】2020-2021学年高一数学单元测试定心卷（人教B 版2019必修第二册）【答案】A【分析】根据零向量和单位向量的概念可以判定①②，注意相等向量不仅要长度相等，方向要相同，可否定③．【解析】根据零向量的定义可知①正确；根据单位向量的定义可知，单位向量的模相等，但方向不一定相同，故两个单位向量不一定相等，故②错误；向AB 与BA 互为相反向量，故③错误．故选A ．【名师点睛】本题考查零向量和单位向量的概念，相等向量的概念，属概念辨析，正确掌握概念即可．13．下列关于平面向量的命题中，正确命题的个数是（1）长度相等、方向相同的两个向量是相等向量；（2）平行且模相等的两个向量是相等向量；（3）若a b ≠，则a b →→≠；（4）两个向量相等，则它们的起点与终点相同．A ．0B ．1C ．2D ．3 【答案】B【分析】根据相等向量的有关概念判断．【解析】由相等向量的定义知（1）正确；平行且模相等的两个向量也可能是相反向量，（2）错；方向不相同且长度相等的两个是不相等向量，（3）错；相等向量只要求长度相等、方向相同，而表示两个向量的有向线段的起点不要求相同，（4）错，所以正确答案只有一个．故选B ．14．下列命题中，正确命题的个数是①单位向量都共线；②长度相等的向量都相等；③共线的单位向量必相等；④与非零向量a 共线的单位向量是||a a ．A ．0B ．1C ．2D ．3【试题来源】天津市和平区耀华中学2019-2020学年高一下学期期中【答案】A【分析】根据单位向量，相等向量，共线向量的定义进行判断即可．【解析】因为不同的单位向量的方向可能不相同，所以①错误；相反向量的长度相等，但方向相反，则②错误；因为共线的单位向量方向可能相反，所以它们不一定相等，则③错误；与非零向量a 共线的单位向量是||a a 或||a a -，则④错误；故选A 【名师点睛】本题主要考查了对单位向量，相等向量，共线向量的辨析，属于基础题． 15．有下列命题：①若a b →→=，则a b →→=；②若AB DC →→=，则四边形ABCD 是平行四边形；③若m n →→=，n k →→=，则m k →→=；④若//a b →→，//b c →→，则//a c →→．其中，假命题的个数是A ．1B ．2C ．3D ．4 【试题来源】宁夏育才中学2019-2020学年高一5月教学质量检测【答案】C 【分析】根据平面向量的概念及向量平行的相关知识逐个判断即可．【解析】a b →→=，则a b →→，的方向不确定，则a b →→，不一定相等， ①错误；若AB DC →→=，则,AB DC →→的方向不一定相同，所以四边形ABCD 不一定是平行四边形，②错误；若m n →→=，n k →→=，则m k →→=，③正确；若//a b →→，//b c →→，则0b →→=时，//a c →→不一定成立，所以④错误．综上，假命题的是①②④，共3个．故选C ．【名师点睛】本题主要考查平面向量的概念，意在考查学生对这些知识的理解掌握水平，属于基础题．16．下列说法不正确的是A ．平行向量也叫共线向量B ．两非零向量平行，则它们所在的直线平行或重合C ．若a 为非零向量，则a a是一个与a 同向的单位向量 D ．两个有共同起点且模相等的向量，其终点必相同【试题来源】安徽省六安市第一中学2019-2020学年高一上学期期末（理）【答案】D【分析】根据共线向量的定义判断AB ；由a a 的模长为1，10a >得出a a是一个与a 同向的单位向量；举例排除D ．【解析】由于任一组平行向量都可以平移到一条直线上，则平行向量也叫共线向量，A 正确；两非零向量平行，则它们所在的直线平行或重合，由共线向量的定义可知，B 正确； a a 的模长为1，10a >，则a a是一个与a 同向的单位向量，C 正确；从同一点出发的两个相反向量，有共同的起点且模长相等，但终点不同，D 错误；故选D【名师点睛】本题主要考查了共线向量概念的辨析，属于基础题．17．下列四个命题正确的是A ．两个单位向量一定相等B ．若a 与b 不共线，则a 与b 都是非零向量C ．共线的单位向量必相等D ．两个相等的向量起点、方向、长度必须都相同【试题来源】辽宁省阜新市第二高级中学2019-2020学年高一下学期第一次学考【答案】B【分析】由相等向量、共线向量的概念逐一核对四个选项得答案．【解析】两个单位向量一定相等错误，可能方向不同；若a与b不共线，则a与b都是非零向量正确，原因是零向量与任意向量共线；共线的单位向量必相等错误，可能是相反向量；两个相等的向量的起点、方向、长度必须相同错误，原因是向量可以平移．故选B．【名师点睛】本题考查命题的真假判断与运用，考查了平行向量、向量相等的概念，属于基础题．18．有下列说法：①若两个向量不相等，则它们一定不共线；②若四边形ABCD是平行四边形，则AB CD=；③若//a c；b c，则//a b，//AB CD．④若AB CD=，则AB CD且//其中正确说法的个数是A．0B．1C．2D．3【试题来源】2021年新高考数学一轮专题复习（新高考专版）【答案】A【分析】对于①，根据向量相等的定义以及向量共线的定义可知结论不正确；对于②，根据向量相等的定义可知结论不正确；对于③，找特殊向量，当0b=时，可知结论不正确；对于④，AB与CD不一定平行，AB与CD可能在一条直线上，可知结论不正确．【解析】对于①，当两个向量不相等时，可能方向相反，所以可能共线，故①不正确；对于②，若四边形ABCD是平行四边形，则AB DC=，故②不正确；对于③，当0b=时，a与c可以不共线，故③不正确；AB CD或AB与CD在一条直线上”，故④不对于④，“若AB CD=，则AB CD且//正确．故选A．【名师点睛】本题考查了向量相等的定义，考查了向量共线的定义，属于基础题．19．下列说法正确的是A ．单位向量都相等B ．若//a b ，则a b =C ．若a b =，则a b =D ．若λa b ，（0b ≠），则a 与b 是平行向量【试题来源】山西省大同市灵丘县豪洋中学2019-2020学年高一下学期期中【答案】D 【分析】根据相等向量，共线向量的定义判断可得；【解析】对于A ，单位向量的模长相等，但方向不一定相同，所以A 错误；对于B ，当//a b 时，其模长a 与b 可能相等或a b λ=0λ≥，或b a λ=0λ≥，所以B 错误；对于C ，当a b =时，不一定有a b =，因为a b =要a b =且a 与b 同向，所以C 错误；对于D ，λa b ，（0b ≠），则a 与b 是平行向量，D 正确．故选D ．【名师点睛】本题考查了平面向量的基本概念应用问题，属于基础题．20．如图所示，在正ABC 中，D ，E ，F 均为所在边的中点，则以下向量中与ED 相等的是A ．EFB ．BEC ．FBD ．FC【试题来源】2020-2021学年【补习教材寒假作业】高一数学（人教A 版2019）【答案】D【分析】由题意先证明//DE CB 且12DE CB =，再利用中点找出所有与向量ED 相等的向量【解析】DE 是ABC 的中位线，//DE CB ∴且12DE CB =，则与向量ED 相等的有BF ，FC ．故选D ．【名师点睛】本题考查了相等向量的定义，利用中点和中位线找出符合条件的所求的向量，属于基础题．21．已知a 、b 是平面向量，下列命题正确的是A ．若||||1a b ==，则a b =B ．若||||a b <，则a b <C ．若0a b +=，则//a bD ．零向量与任何非零向量都不共线【试题来源】备战2021年新高考数学一轮复习考点微专题【答案】C【分析】A ，根据向量的定义判断；B ．向量不能比较大小判断；C ，若0a b +=，则b a =-，由共线向量定理判断；D ，由零向量与任一向量共线判断．【解析】对于A ，向量方向不相同则向量不相等，选项A 错误；对于B ．向量不能比较大小，选项B 错误；对于C ，若0a b +=，则b a =-，//b a ∴，选项C 正确；对于D ，零向量与任一向量共线，选项D 错误．故选C ．【名师点睛】本题主要考查平面向量的概念及线性运算，还考查了理解辨析的能力，属于基础题．22．下列命题中正确的是A ．若||a b |=|，则a b =B ．若a b ≠，则a b ≠C ．若||a b |=|，则a 与b 可能共线D ．若a b ≠，则a 一定不与b 共线【试题来源】考点18 平面向量的概念及其线性运算-备战2021年高考数学（理）一轮复习考点一遍过【答案】C【分析】利用共线向量、模的计算公式，即可得出．【解析】因为向量既有大小又有方向，所以只有方向相同､大小(长度)相等的两个向量才相等，因此A 错误；两个向量不相等，但它们的模可以相等，故B 错误；无论两个向量的模是否相等，这两个向量都可能共线，故C正确，D错误．故选C【名师点睛】本题考查了共线向量、模的计算公式，考查了理解能力，属于基础题．23．下列关于向量的概念叙述正确的是A．方向相同或相反的向量是共线向量B．若//a ca b，//b c，则//C．若a和b都是单位向量，则a b=D．若两个向量相等，则它们的起点和终点分别重合【试题来源】山西省2019-2020学年高一下学期期末（理）【答案】A【分析】由向量共线的定义，可知A正确；当0b=时，可知B不正确；单位向量，方向不定，不相等；向量相等即大小和方向相同即可．【解析】由向量共线的定义可知，A正确；当0b=时，可知B不正确；单位向量，方向不确定，故C不正确；向量是自由的，向量相等，只需大小和方向相同即可，不需起点终点重合，故D不正确．故选A【名师点睛】本题考查了向量的定义和基本性质，考查了理解辨析能力，属于基础题目．24．已知向量a与b共线，下列说法正确的是A．a b=或a b=-B．a与b平行C．a与b方向相同或相反D．存在实数λ，使得λa b【试题来源】安徽省合肥市庐江县2019-2020学年高一下学期期末【答案】B【分析】根据向量共线的概念，以及向量共线定理，逐项判断，即可得出结果．【解析】向量a与b共线，不能判定向量模之间的关系，故A错；向量a与b共线，则a与b平行，故B正确；a为零向量，则满足a与b共线，方向不一定相同或相反；故C错；当0a ≠，0b =时，满足a 与b 共线，但不存在实数λ，使得λa b ，故D 错．故选B ．【名师点睛】本题主要考查向量共线的有关判定，属于基础题型．25．下列关于平面向量的命题中，正确命题的个数是①任一向量与它的相反向量都不相等；②长度相等、方向相同的两个向量是相等向量；③平行且模相等的两个向量是相等向量；④若a b ≠，则||||a b ≠；⑤两个向量相等，则它们的起点与终点相同．A ．0B ．1C ．2D ．3【答案】B【分析】根据平面向量的基本概念，对选项中的命题进行分析、判断正误即可．【解析】零向量与它的相反向量相等，①错；由相等向量的定义知，②正确；两个向量平行且模相等，方向不一定相同，故不一定是相等向量，例如，在平行四边形ABCD 中，//AB CD ，且=AB CD ，但AB CD ≠，故③错； a b ≠，可能两个向量模相等而方向不同，④错；两个向量相等，是指它们方向相同，大小相等，向量可以自由移动，故起点和终点不一定相同，⑤错．故选B ．26．判断下列命题：①两个有共同起点而且相等的非零向量，其终点必相同； ②若//a b ，则a 与b 的方向相同或相反； ③若//a b 且//b c ，则//a c ； ④若a b =，则2a b >．其中正确的命题个数为A ．0B ．1C ．2D ．3【试题来源】四川省凉山州2019-2020学年高一下学期期末考试（文）【答案】B【分析】根据相等向量、共线向量、零向量等知识确定正确命题的个数．【解析】①，两个有共同起点而且相等的非零向量，其终点必相同，根据相等向量的知识可知①是正确的．②，若//a b ，则可能b 为零向量，方向任意，所以②错误．③，若//a b 且//b c ，则可能b 为零向量，此时,a c 不一定平行，所以③错误．④，向量既有长度又有方向，所以向量不能比较大小，所以④错误．故正确的命题有1个．故选B【名师点睛】本题主要考查相等向量、共线向量、零向量等知识，属于基础题． 27．设,a b 是非零向量，则“2a b =”是“a a b b =” 成立的 A ．充要条件B ．充分不必要条件C ．必要不充分条件D ．既不充分也不必要条件【试题来源】山东省济南市莱芜第一中学2020-2021学年高三上学期11月月考【答案】B 【分析】结合共线向量、单位向量的知识，以及充分、必要条件的概念，判断出正确选项．【解析】依题意,a b 是非零向量，a a 表示与a 同向的单位向量，b b 表示与b 同向的单位向量，当2a b =时，,a b 的方向相同，所以a a b b =，当a a b b =时，,a b 的方向相同，但不一定有2a b =，如3a b =也符合，所以“2a b =”是“a a b b=” 成立的充分不必要条件．故选B【名师点睛】本题主要考查共线向量的知识、单位向量的知识，考查充分、必要条件的判断，属于基础题．28．若四边形ABCD 是矩形，则下列说法不正确的是A ．AB →与CD →共线B ．AC →与BD →共线 C ．AD →与CB →模相等，方向相反 D ．AB →与CD →模相等【试题来源】2020-2021学年【补习教材寒假作业】高一数学（苏教版）【答案】B【分析】根据向量的共线及模的概念即可求解．【解析】因为四边形ABCD 是矩形，所以AB →与CD →共线，AD →与CB →模相等，方向相反，AB →与CD →模相等正确， AC →与BD →共线错误，故选B29．设,a b →→是两个平面向量，则“a b →→=”是“||||a b →→=”的A ．充分而不必要条件B ．必要而不充分条件C ．充要条件D ．既不充分也不必要条件【试题来源】浙江省金华市曙光学校2020-2021学年高二上学期期中【答案】A【分析】根据充分条件、必要条件的定义及向量的概念判断即可．【解析】因为a b →→=，则一定有||||a b →→=，而||||a b →→=推不出a b →→=，所以“a b →→=”是“||||a b →→=”的充分不必要条件，故选A30．下列关于向量的结论：（1）若||||a b =，则a b =或a b =-；（2）向量a 与b 平行，则a 与b 的方向相同或相反；（3）起点不同，但方向相同且模相等的向量是相等向量；（4）若向量a 与b 同向，且||||a b >，则a b >．其中正确的序号为A ．（1）（2）B ．（2）（3）C ．（4）D ．（3）【试题来源】专题07 平面向量的实际背景及基本概念（重点练）-2020-2021学年高一数学十分钟同步课堂专练（人教A 版必修4）【答案】D【分析】根据向量的定义可判断（1）（4）错误，向量,a b 都是零向量时，由向量,a b 平行得不出方向相同或相反，从而判断（2）错误，根据相等向量的定义可判断（3）正确．【解析】（1）若||||a b =，由于,a b 的方向不清楚，故不能得出a b =或a b =-，故（1）不正确．（2）由零向量与任何向量平行，当向量a 与b 平行时，不能得出a 与b 的方向相同或相反，故（2）不正确．（3）由向量的相等的定义，起点不同，但方向相同且模相等的向量是相等向量；故（3）正确．（4）向量不能比较大小，故（4）不正确．故选D ．二、多选题1．下面的命题正确的有．A ．方向相反的两个非零向量一定共线B ．单位向量都相等C ．若a ，b 满足a b >且a 与b 同向，则a b >D ．“若A 、B 、C 、D 是不共线的四点，且AB DC =”⇔“四边形ABCD 是平行四边形”【试题来源】备战2021年新高考数学一轮复习考点一遍过【答案】AD【分析】根据向量的概念：方向相反或相同的非零向量共线，模相等且方向相同的向量相等，向量除了相等的情况不能比较大小，即可判断选项正误；【解析】方向相反的两个非零向量必定平行，所以方向相反的两个非零向量一定共线，故A 正确；单位向量的大小相等，但方向不一定相同，故B 错误；向量是有方向的量，不能比较大小，故C 错误；A 、B 、C 、D 是不共线的点，AB DC =，即模相等且方向相同，即平行四边形ABCD 对边平行且相等，反之也成立，故D 正确．故选AD【名师点睛】本题考查了向量的基本概念，需要理解向量共线、相等的条件，属于简单题；2．若四边形ABCD 是矩形，则下列命题中正确的是A ．,AD CB 共线B ．,AC BD 相等 C ．,AD CB 模相等，方向相反 D ．,AC BD 模相等【试题来源】2020-2021学年高一数学单元测试定心卷（人教B 版2019必修第二册）【答案】ACD【分析】根据向量的加法和减法的几何意义（平行四边形法则)，结合矩形的判定与性质进行分析可解．【解析】因为四边形ABCD 是矩形，,ADBC AC BD ∴=‖，所以,AD CB 共线，,AC BD 模相等，故A 、D 正确；因为矩形的对角线相等，所以|AC|=|BD|，,AC BD 模相等，但的方向不同，故B 不正确；|AD|=|CB|且AD ∥CB ，所以,AD CB 的模相等，方向相反，故C 正确．【名师点睛】本题考查向量的共线，相等，模，向量的加减法的几何意义，属基础题，根据向量的加减法的平行四边形法则和矩形的性质综合判定是关键．3．在下列结论中，正确的有A ．若两个向量相等，则它们的起点和终点分别重合B ．平行向量又称为共线向量C ．两个相等向量的模相等D ．两个相反向量的模相等【试题来源】江苏省淮安市涟水县第一中学2019-2020学年高一上学期第二次月考【答案】BCD【分析】根据向量的定义和性质依次判断每个选项得到答案．【解析】A ．若两个向量相等，它们的起点和终点不一定不重合，故错误； B ．平行向量又称为共线向量，根据平行向量定义知正确；C ．相等向量方向相同，模相等，正确；。

2019-2020学年湖北省荆州市石首城南高级中学高一英语下学期期末试题含解析

2019-2020学年湖北省荆州市石首城南高级中学高一英语下学期期末试题含解析一、选择题1. Don’t reply to any e-mails _____ personal information, no matter who sends it to you.A. requestingB. searchingC. askingD. ruining参考答案：A2. Death is universal, but life is not. , everyone dies, but not everyone really lives.A. In other wordsB. As a resultC. What’s moreD. In short参考答案：A考查固定短语。

A. In other words换句话说；B. As a result结果；C. What’s more另外；D. In short总之，简言之。

句意：死亡是普遍的，但生命不是。

换句话说，每个人都会死亡，但不是每个人都真正的活着。

根据句意选A.3. _______ himself ______ clearly, he raised his voice.A. So as to make; heardB. In order to make; hearC. To make; heardD. In order that make; hear参考答案：C4. He was sentenced to death what he has stolen from the bank.A. thatB. sinceC.because D. because of参考答案：D5. The volcano erupted and the lava poured down the mountain, several villages.A. buriedB. to buryC. buryingD. being buried参考答案：C【详解】考查非谓语动词。

湖北省武汉市青山区2019-2022学年高一上学期期末英语质量检测语法填空汇编(共三年)(含答案)

武汉市青山区2019—2022学年度第一学期期末高一质量检测英语试题语法填空汇编（共三年）2021-2022第一学期期末考试第二节(共10小题，每小题1.5分，满分15分)阅读下面材料，在空白处填入适当的内容（1个单词）或括号内单词的正确形式。

China has built a high-speed passenger rail network in recent years and will continue to enlarge ___51___ (rapid). By the end of 2017, China's railway mileage ___52___ (reach) 127, 000 kilometers, and 25,000 km of it are high-speed rail, ___53___ makes China's high-speed system the world's ___54___ (large) high-speed network.China’s high-speed trains are similar to those of France's TGV, Germany’s ICE and Japan's Shinkansen. The fast trains with ___55___ top speed of 250 - 350km/h are called CRH, China Railway High-speed.If you want to travel around China, the high-speed trains will be your ideal vehicle since they are clean, comfortable and modern. Unlike the traditional trains in China, no smoking___56___ (allow) on high-speed trains, not even between carriages.To meet the ___57___ (require) of different passengers, the high-speed railway operators have divided CRH tickets into three types. They are business, first class and second class. There's never a mad crowd with many people ___58___ (sit) in the aisles as well as in seats.The ticket prices for China's high-speed trains are reasonable ___59___, on most routes, the frequency of departure is very high, so it's quite convenient for people ____60____ (buy) tickets.2020-2021学年第一学期期末考试第二节（共10小题;每小题1.5分，满分15分)阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。

湖北省2019-2020学年高一下学期期中英语试卷精选汇编：读后续写(概要写作)专题

读后续写（概要写作）专题湖北省武汉市2019-2020学年高一英语下学期期中联考试题第二节（满分25分）阅读下面短文,根据所给情节进行续写,使之构成一个完整的故事。

To celebrate his girlfriend’s birthday,Luke Fortune drove from a small town in Central Oregon to Portland, where he parked his car in a paid garage overnight. The next morning, he discovered that the car’s window had been broken, along with his dreams for the future: His backpack and computer were gone.“Everything important to me was on that computer,” said Fortune, 21, who is studying to become a paramedic (护理人员).” My classwork, every paper I’d written, and all the programs I needed for my paramedic tests. Every letter I was working on for job applications. I felt sick.”Two days after the theft, another young man was standing outside his apartment, also in Portland. Masoud Almazrouei ,29, was an exchange student from the United Arab Emirates. A man came up to him, saying he had a computer for sale. Only $200.Almazrouei,who had been in the United States for only a year, admits now that he was naive (天真).But he needed a computer, so he bought it, took it home, and turned it on. Within seconds, he saw files and photographs.“I wondered who would sell a computer with all of this on it,” he said.” I realized it could be stolen.” Amarone found what appeared to be the owner’s cell phone number and called it.“This guy with a thick accent told me he had my computer,” Fortune said.” He told me the story and said it was his fault. I thought it was a trick. I told him if he really had the computer, he should take it to the police.”Soon after, a police officer called Fortune to say that a man had dropped the computer off and had said he was sorry. He passed along the man’s number.注意：1. 所续写短文的词数应为150左右;2. 至少使用5个短文中标有下划线的关键词语;3. 续写部分分为两段,每段的开头语已为你写好;4. 续写完成后,请用下划线标出你所使用的关键词语。

湖北省武汉市洪山区高级中学2019-2020学年高一下学期线上期中考试英语试题+Word版含答案

洪山高级中学 2019-2020 学年度下学期高一期中考试高一英语试卷考试时间：2020 年4 月23 日上午10:10-12:10 试卷满分：150 分选择题部分第一部分听力（共两节，满分 30 分）第一节（共 5 小题；每小题 1.5 分，满分 7.5 分）听下面 5 段对话。

每段对话后有一小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What helps the man study?A. Having the TV on.B. Staying in a quiet place.C. Listening to music.2.Why does Anne need help?A.She's carrying something. B . Her bag is full. C. It is hard to close her drawer.3.How often does the man work out now?A. Twice a week.B. Once a week.C. Every other day.4.What is the probable relationship between the speakers?A.Mother and son.B. Teacher and student.C. Monitor and classmate.5.How does the man feel about the idea?A. Relaxed.B. Excited.C. Unsure.第二节（共 15 小题；每小题 1.5 分，满分 22.5 分）听下面 5 段对话或独白。

每段对话或独白后有几个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

湖北省宜昌市协作体2024-2025学年高一上学期期中考试英语试题(含答案,无听力音频无听力原文)

宜昌市协作体高一期中考试英语考生注意：1. 本试卷分选择题和非选择题两部分。

满分150分，考试时间120分钟。

2. 答题前，考生务必用直径0.5毫米黑色墨水签字笔将密封线内项目填写清楚。

3. 考生作答时，请将答案答在答题卡上。

选择题每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑；非选择题请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答，超出答题区域书写的答案无效，在试题卷、草稿纸上作答无效。

4. 本卷命题范围：人教版必修第一册Welcome Unit至Unit 2。

第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。